#help-0
1 messages · Page 726 of 1
wouldn't 3 be equal 55 degrees?
is this a quiz?
how @misty mountain
"Quiz15.pdf"
?
What is marked?
have it memorized lol
Yeah you'd need a calculator
Can you elaborate marked?
as in graded, is it a test?
on the questions it says (1 point)
its just a yes or no question with further detail for explanation
(18+8) * 10 + 8*8 = 324. add the last digit of the second number to the first number, then multiply by 10 and add the product of the two last digits. this works for the product of two numbers under 20
well ima take your words for it, question 3 4 5 are wrong
5 is missing answers
oh nvm, i thought it said 2 pairs of angles, 5 seems correct
Ok I was going to say im confused lol
So if 3 isnt 70 what am I supposed to do?
Is there a formula
I thought it was 180-110
BD bisects ABC
180 -110 implies the angle on the other side of ABC
and nvm, 5 is indeed incorrect, SRO and SRQ are not complementary
they add up to 180 not 90
complementary means 90 though
yeah which is why its wrong
How so?
...
SRO+SRQ=ORQ=180
complementary means they add up to 90
find two angles that add up to either SRO or SRQ?
Okay, how do I solve 3 and 4?
use the information
BD is an angle bisector of ABC
and you know the measure of ABC
Okay?
And what do I do with that information.
I understand that its a bisector
I understand ABC is 110
what property does an angle bisector have?
in question 4 how did you draw the conclusion that QRU=SRU=50 degrees?
What property does it have? I'm confused
can you answer this question then?
yes
@rigid smelt what did I get wrong on 4
I know this is physics but there's a great overlap between people who do physics and math so wondering if anyone can help
is the equation of the axis of the curve for this graph y=1 or is it something else
I do physics, but that's only incidental to the fact that everything IRL counts as physics
I'm guessing the question is solve for resistance for A and B?
it seems that 330 ohm thing will have no current
Of the circuit with current passing through A to B?
Are you able to calculate resistance in parallel? Are you able to do so in serial?
it's 100 | (220 + 470), you just ignore 330
it's essentially not conducting
i may be wrong
i'm probably wrong
Yeah you are lol
LMAOO
@left echo grab an open channel, something that didn't have an active question
can u just answer it’s an easy question
i just wanna make sure
Yeah @left echo
is this channel in use?
tell me how this equates 50
what
again 1/2 * 20 + 10 does not equal 50
so instead what should it be
how can you cancel the 1/2 on the left side?
if it was written as x/2 = 40 would it be more clear what to do?
So would I just divide 40 by 2 then
Use the graph of ƒ to find where ƒ (x) < 0. Assume the entire function is graphed.
(–∞, 0)
[0, ∞)
(0, –∞)
(0, ∞)
help?
so c ?
@vale wigeon
you can divide 40 by 2 if you want
you can also divide 37 by 42069 and add 11.4234
not that it'd be of any relevance to the equation
x/2 = 40 does not become x = 40/2
Yeah, 1
bet thanks
@vale wigeon so x = 20
Okay so qrs = 70?
what is qrs
i gave a nequation u gotta find the channel now
can anyone give me a hint on the setup of this problem?
I've drawn the diagram but I need help proving
<@&286206848099549185> sorry for ping
My brain hurts so much
if someone solves this

have you done it?
is rotation allowed
yes
nope im still trying
only rotation is allowed?
its not possible
can i turn that L piece into a J piece
whats the point of the hints then .-.
im still trying
so
removing the I piece
we must fit the remaining 3 in either 3 x 4 or 4 x 3 rectangle
Yeah
And since you can rotate all, wlog you need to be able to fit the remaining 3 in a 3x4
Does it tell you if you've won?
the hint is kinda useless
i think its not possible
yep
Okay, so why isn't it?
there are only so many combinations with the remaining two
i don’t see any
that work
yep
The hint is actually super useful
is this occupied?
It gives a very precise way to show this is impossible
Ok.... I have a question I need help with, would any of you help me?
Ah
So it’s impossible
And the hint was misleading
And I spent about 2 hours figuring it out
Lmao
The hint isn't a hint that shows "This is how you do it"
Im upto the second line but and Ive put everything in 1/2 x 25 x 18 but im not sure what the height is
The hint is a hint towards the proof of "This is why it can't be done"
Ah ok
36 cl
cm
i dont know how we can prove it
Isn't the height 18 cm tho
other than testing the cases
ah too bad for the pieces in the puzzle there
i actually knew that trick before looking at the hint
missed the convo
whats the trick?
Do you want the answer? I suggest clicking the hint box and investigating the state
Can spoil if you'd like
the hint im guessing it showing where the pieces can go
||number of colored-in squares on the pieces is not the same as colored-in squares in the puzzle area||
answer obviously
What do they mean by internal volume
oh wow
probably just the volume inside the fridge as opposed to outside of it
i imagine it just wants volume
check the units
make em match to what you want then multiply
ok will do
the walls of the fridge have thickness
that's why they used the word internal
to specify
as the internal and external dimensions are different
Im guessing the answer is 907,200 cm3
yeah but you don't know the thickness
yeye but the reason for using the word internal is because unlike abstract solids, a fridge has walls with thickness
you could make it a variable, but i think it would have said if it wanted all that
instead of just area
Where do I check my answer
maybe at the back of the book
There isn't any answers at the book of the book
,w 180 * 60 * 84
back*
👍
what's the amplitude
2
isn't'it stretched vertically by 2
is it
yes
it is
i accidentally selected two of the same answer
ignore the phase shift right pi/2 that ones wrong
yeah were missng one outta these
the frequency
@harsh swallow
what's the frequency compared to the original frequency of cos
can also think about it in terms of period
compare the period of a normal cos
to this one
i think it’s either reflection over the y axis or x axis
but idk which one
could u graph the formula and tell me what u think
f(x)=-2cos(3(x+pi/2))+5
bro what
horizontal stretching
the period of a normal cos is 2pi
and the period of this one is 1/3 * 2pi
so the horizontal stretching is by 1/3
which is one of the options
so there’s a horizontal stretch by 1/3 is right ?
yes
the amplitude ik is 100% 2
period of 2/3 pi
vertical stretching of 2
domain x x in R
horizontal stretching of 1/3
amplitude 2
vertical shift up 5
phase shift left
and then probably one of the reflection ones
Graph it and find out
bro i don’t know
You dont know how to graph that?
so there’s no reflection among any axis?
then what’s the answer
Idk, maybe the range option?
it’s not
That symbol is subset? I forgot this stuff
what that mean
Are u sure its not the range option? I haven't done this sort of thing in a while but isn't the range of this function an element of the real numbers?
yes it’s not the range option
Why though? R u just guessing or do u have reasoning for your answer
Yes
but i thought when dividing binomials, all values have to be divisible by the divisor?
and -15y cant be divided by -4 ??
Why do u think that?
omg is it because of the y...
15/4 is the coefficient of y
so what ure saying is if there was no y in 15, the answer will be as is? -15-20/4 ?
however since 15 has a variable, only -20 can be divided by -4?
15y/4 = 3.75y
I'm struggling understanding this definition of product between polynomials suggested by my linear algebra papers
try to look at the coefficients of each power of x
the coefficient of x^k is determined by the coefficients of x^p and x^q where p+q=k
so the a_p x^p term comes from the left term
They are using indexes in a really weird manner in this definition. That's mainly what is causing me all these doubts
which part
The second part
At this point... can't I just write a single sum putting x^k inside of it?
Instead of nesting two sums?
you need the sum with p+q=k to express the product of the polynomials in terms of the coefficients of the original polynomials
you might find it easier to understand an equivalent way to write it as:
$$\sum_{p+q=k} a_p \cdot b_q = \sum_{p=0}^{k} a_p \cdot b_{k-p} $$
Frosty
Oh, this is not my doubt
My doubt is that i supposed that, since they used k for every sum, that they were having same degree
I think I'm kinda understanding it
hmm yea try writing it out with the full sum notation without the same degree, might help
i got the function f(x) = alnx - bx^2 and its telling me to find the derivative of f for every x that belongs to its domain
well i found the derivative but idk what the next part is 🤦
what next part?
the way i didnt post it sorry
it says find a and b so the tangent line at point A(1, 1) of f will be y = 3x - 2
you need f(x) to go through A, and have the same slope as the line at A
f'(1)=3, yes
yes
since the derivative itself clearly isnt a constant function, but that's one equation for a and b
then use the fact that f goes through A..
yes thats what i was confused abt
3x-2 is tangent to f at (1,1), so that means f(x) has to go through (1,1)
so ||f(1)=1||
is this correct?, the intergal of f(z)=z^2. where f(z) is a complex function
does anyone do physics here? grade 11 and 12
dont ask to ask.
Can anyone explain why 6 . 0,5 = 0,6 . 5? What is the logic behind it?
0.5=5/10
$6\cdot \frac{5}{10}=6\cdot 5\cdot \frac{1}{10}=\frac{6}{10}\cdot 5$
Mosh
@alpine sable just (a/10)b=(b/10)a
I get it now, a new way to think about math, cheers!
re: commutativity and associativity of multiplication
It is one of those things that the book mentions without explaining the logic behind it.
I've never handled inverses in limits and I'm stuck cause i can't compute the inverse of f. Are there other ways to go about it?
@brisk tree Well $f(x) \approx 8x^3$ so $f^{-1}(y) \approx y^{\frac13}/2$. From this you can guess that the limit is $\frac12$.
can someone help me with this please i have no clue
To make this rigorous you can rewrite $\frac{f(x)}{x^3} = 8 + \frac{3}{x^2}$ in terms of $f^{-1}(y)$ to get an expression of the form $\frac{f^{-1}(y)}{y^{\frac13}} = \cdots$ which you can take the limit of easily
Thanks
this is wrong isn't it
yup
do you think subtracting 0.14 from both sides will cancel out the 0.14r?
answer me bubbuh!!
no
im just trying to remember how to do that
wait wait
hold on let me think
no idea
think about how you can undo multiplication
^^
if 0.14 was being added to R, then subtracting 0.14 from each side would be okay
R=100
which is odd
I feel like it should be higher
this is more engineering than maths
Voltage = Current (in amps)/ Resistance
trying to find R
well rather
so
i have a 14v supply at 5A
i want it to be 0.14A

So basically im trying to find the resistance to transform 5A to 0.14
which shouldnt be 100 should it?
Im a bit confused, how do u know the current before hand, isn't is determined by the rest if the circuit?
What does your circuit look like?
I did only start learning electronics a few days ago so i've most likely got this whole thing wrong
Could u post the whole question?
I mean if u have a 14v source and want a current of 0.14A within a circuit, you would want 100 ohm resistance
umno terus mara untuk rakyat malaysia
Imagine you are set designer for Universal Studios movie company. You plan movie sets using
freehand sketches and your computer. In one scene, a banner will hang across a parabolic
archway. To make it look interesting, you have decided to put the banner at an angle along a
line defined by the linear equation y = 0.24x+ 7.2, with x representing the horizontal distance
and y the vertical distance in metres, from the foot of the archway. The archway is modelled by
the quadratic equation y = - 0.48x2+ 4.8x.
hello orang yang nampaknya berasal dari Malaysia
How can you use the equations to determine the points where the banner needs to be
attached to the archway? You can use Technology or the grid below to help with your
explanation.
anyone know this
helo helo
I hate linear equations but I need to practice them again lol
oh lol
,w plot 4/3(x-3)/((x+1)(x-4)), x from -10 to 10
nvm im an idiot you can ignore my question lol
Assume sequence {an} that satisfies |an-a(n+1)/2|≤1,n∈N+
-
Prove that|an|≥2^(n-1)(|a₁|-2)(n∈N*)
-
If |an|≤(3/2)^n,n∈N*, prove that |an|≤2,n∈N*
Help
do they mean the circumradius?
yeah
Is anyone getting help? Can I ask for help?
i think radius of an inscribed circle
depending on what you need help with I'd be happy to help to the best of my ability 🙂
Well okay wait a sec
I have this question
And I can’t prove it, every idea of mine didn’t work
just to reiterate in text form, f(f(x)) = x^2-x+1
im sorry i have no idea how to tackle this 😦
Yea same, I tried proving that f is a 1-1 function but you can’t prove it without knowing f(x)
It’s a 1
Ok
its really annoying because its not factorisable.
Exactly
I don't want to come off as rude but you're sure that is definitely the question?
i dont see how you would go about doing this unless youre dealing with the complex numbers
Yes that’s the question, you’re not rude, I thought about the same thing when I first saw it
The teacher probably didn’t write everything
i mean its 'locked in'
like when i think of questions i cant tackle i picture it and think, is there any room for ambiguity? but it doesnt seem so
its hard to think of why tho
Try F(f(f(x))
my first idea would be to try and differentiate to get something about f', but that doesn't seem right tbh
apply f to both sides
we haven’t been taught about f’ at school yet ,so I basically cannot use it anyways :/
U mean to the normal function or to the f(1)=1?
me, realizing i missed the obvious
f(f(1))= 1
Now f(f(f(x))= f(x)^2-f(x)+1
Put x=1
f(f(f(1)))=f(1)^2-f(1)+1
Procced
It will become f(1) = f(1)^2-f(1)+1
You know now what to do
Wow
How didn’t I think of that
Thank you so much @pearl marlin ❤️
It was that easy after all but I couldn’t think of it🥲
maybe try cubing both sides 🙂
Its okk , sometimes happens
Yea happens a lot these days idk what’s wrong
8x^3 - 60x^2 + 150x - 125 = x
What you want to find?
x
,w solve 8x^3-60x^2+150x-125=x
That looks like a really hefty polynomial to factor. Maybe try substituting u=cbrtx ?
whats u=cbrtx
There is no way you find that by hand
so basically instead of writing the cube root of x, say that instead the cube root of x is some other pronumeral u. Therefore the new equation would be 2u^3+5=u
i think that becomes a lot easier to solve
sorry -5**
,w solve 2x - 5 = cube root (x)
Good

,w 8x^3-60x^2+149x-125=0
could you solve it graphically
solving it graphically would be so much better
Draw in desmos
Guys is there a way to find out sin and cosine of an angle just by myself, without checking any table?

For example, i need to find out cosine of 60° but i want to do that without checking any table
How is that possible?
UNIT CIRCLE
caps
Yes
learn how to calculate trig functions using unit circle
60 is ez but 59.9 not so ez
It's 1/2 ig
Look
desmos graphing calc?
Yes
A really good way to learn trig functions if you can't remember the unit circle is to draw out the triangle it belongs to, and to just remember the qudrant rules like cos(x)=cos(-x)
Or just remember the sine
And cosine is similar to it
I wanted to find it out by myself, without remembering anything
But how do i do that
Can be found by a triangle or something
Like here?
Check where it cut on xaxis
How do you solve 2x - 5 = cube root x
I got no clue
Cubing both sides doesn't help
Sadly
.
OHHHH
thats the line x=3.2398 something
i cant
Thats why wolfram aproximated this
Doesn't help
damn
From where you got this question?
Which one?
hint: 2sinxcosx
I did inverse sin and got 2x = pi/6
how do I find the other solution
so 0 <= 2x <= pi/6 means x can only be in quadrant 1
what does that restriction tell you about 2x?
0 <= 2x <= pi / 3?
0 <= 2x <= pi? Am I supossed to multiply the interval by 2?
yes, multiplying through gets you
0 <= 2x <= pi
now find all solutions to
sin(2x) = 0.5
for 2x
where 0 <=2x<=pi
ok I think im starting to better understand
you can let t=2x to help you
so 2x = pi/6 is one solution and the other solution is on quadrant 2 right?
ok yes ill try that
the other solution for 2x will be in Q2 yes
so t1 = pi/6 and t2 = pi - pi/6 = 5pi/6
and then I would divide t by 2 for x
right?
yeh
ok thank you, the substition makes it easier to understand
anybody have any idea of how to solve this graphically
graph the left side,
graph the right side
identify where they intersect
State the solution to f(x) > g(x) if f(x) is graphed in green and g(x) is graphed in black. Vertical asymptotes are in orange.
i got (-1, -(1/3) and (3,1)
am i correct
they intersect in a very intersting point i can't really define where
wdym you can't define where?
ill just make a approximation
the image pretty much literally shows you
and seeing as some rounding may be involved, -0.333... is probably rounded from -1/3
other question XD
i put it into a calculator to make sure i did it right and they intersect at like x=3.23985238 something like that
this is what happens when people spam 0
yeh, you'll have an approximation
The monthly salary of a person is Rs. 15000 . The central angle of the sector representing his expenses on food and house rent on a pie chart is 60 degrees. The amount he spends on food and house rent is
Rs. 5000
Rs. 2500
Rs. 6000
Rs. 9000
Don't multipost.
read #❓how-to-get-help
ah you got em first
someone help me on question ii. idk how they got to the highlighted answer
they just solved for l by subtracting 2w on both sides then dividing by 2
their answer is fine
wait what
which step are you confused about exaclty?
the whole question
they multiplied top and bottom by 5 if you are confused about the second to last step
the handwriting might be a bit poor, but its all there
did you understand the start?
P = 2l + 2w?
yep perimeter equals that ye
where did you stop understanding
the end goal is to isolate the l
yes
to achieve that they started by subtracting 2w from both sides of the equation
and then they divided both sides of the equation by 2
(this was combined into a single step)
how do u get that equation in the first place
which equation?
P = 2l + 2w is where they started then they substituted
p=4.8
you said you understood the substitution
how do u go from left to right
to achieve that they started by subtracting 2w from both sides of the equation
and then they divided both sides of the equation by 2
(this was combined into a single step)
starting from
4.8 = 2l + 2w,
what do you have if you subtract 2w from both sides?
4.8-2w=2l?
the decimal point may be a bit unclear but its sorta there
ok so then after i get l = 4.8-2w/2
oh yep yeah ok then where do i go from there
or just divide each part of the fraction by 2
ahh ok so 4.8/2 - 2w/2
2w/2 simplifies to w
and they expressed 4.8/2 as a simplified fraction of two integers
what do u mean by that
note that in their end result they had 12/5 instead of 4.8/2
what does the top 2 mean when it says like 52
the 2 little above
i new to matamatics
squared
no im round im fat
first the multiplied the numerator and denominator by 5 to get a fraction of two integers
ugh i got a test in 3 hours its 6am i havent slept
and then they divided the numerator and denominator by 2 to simplify ti
(バカ) baka
you didn't necessarily need to convert it to a fraction like they did
i not so good in english
you could just do 4.8/2 = 2.4
i not understand
and that's enough for what the question is asking for
ahh ok that makes sense now thank u
i got one more short question doe
howd they get that
how do they go from 3.8/4 to 19/20
wait why they multiplying everything by 5
90(1+1)=90(2)=180
i not get it
they wanted to leave their value in a fraction
they also wanted to simplify the fraction
that would mean expressing it as a fraction of two integers
90(1+1) = 90 x (1+1) = 90 x 2
but 1+1 is at end
so in the actual test should i do that
depends on what the question wants
you didn't necessarily need to convert it to a fraction like they did
you could just do 4.8/2 = 2.4
and that's enough for what the question is asking for
hmm ok so rn i could just do 3.8/4?
i have gooder idea for me i gonna dropout
if you're gonna use a fraction, at least try and simplify
bye
otherwise if there's an exact decimal form, give that instead
ok makes sense
then the bottom says calculate the length
and they used the fraction - w
nvm i got it
thank u for ur help guys
wish me luck for test lol
which formula would i use to find x
It's 180-((90-30)+37)
angle sum of triangles...
dont just give answers.
Oh sorry, but how we are meant to make formula if there's no letters?
define them yourself.
In every terrestrial meridian the passage of the Sun occurs at noon, an hour later it will pass through another meridian located 15 ° west of the first and successively until midnight, reaching the antemeridian until returning to the initial point 24 hours later, which is known as time zone; What is the equivalence in radians of those corresponding to each time zone? 15 ° corresponding to each time zone?
Hello, can someone help me with that?
Thanks
help please
perpendicular means opposite reciprocal
so flip the fraction of the slope and apply a negative
Condition: two lines with slope m1 and m2 are perpendicular if m1*m2=-1
does that always work?
Untill your lines are not parallel to axis
oh okay
would it be the last or second awnser
figure it out urself, he/she cant just give u the answer???
lol
this channel is occupied @fathom cosmos
can anyone explain what randomization actually is
can anyone please help me understand how the general solution was found?
i don't see how they got to that from the REF
From the equations:
2x1 - 1x2 + 6x3 = 0
s = x2
t = x3
Give me solutions for x1,x2,x3 in terms of s,t
Or, realize that you can, from the ref, write:
x1 = x2(1/2) + x3(-3)
x2 = x2
x3 = x3
Hey everyone. I dont get why is "- √y" and not "√y". Can anyone help me?
I know its because of the x ∈ [ - ∞, 3], but I still dont know
x^2 = y implies x = plus or minus sqrt (y), and in this case they picked the minus branch because it's the one in the domain, like you pointed out
correct, g inverse could have been 3+root(x) as well, but since the domain has been mentioned, we'll take 3-root(x) only
also note that if an inverse has to exist, the function has to be one-one and onto, so both branches would never be taken together
branches referring to the portion before x=3 and after x=3
is one-one another way to write one to one?
yep
👍
yes
take the image of the graph about the x axis
so it will kinda look like an inverted V with its apex at x=2
Sorry, I dont get what " the function has to be one-one and onto" means... english is not my first language.
those are both math terms not English (not with that meaning at least)
one to one mapping means that a single output value can't have 2 distinct input values
onto means that all values within the co-domain must be mapped to at least 1 value in the domain
meaning if range and co-domain are the same
They're still in English, is not like in Spanish we say "la función es onto" or in French they say "la fonction est one to one" xD
Ahhh ok, so, if the domain was all the real numbers, which of the values (- and +) would I choose?
what (- or +) are you referring to?
I mean that's true, but my general point was 99.9% of English speakers wouldn't have known what it meant anyways
now I'm kinda curious how you say those in french, is it a literal translation?
is the range -inf to +inf
"- √y" and "√y". I would pick both.
no, g(x) = log2 (x+2)
yes, the range is -inf to +inf
welcome
They use the more formal "surjective, injective" or they would say "une fonction est injective / est une injection"
(-) cuz thats what falls withing the domain
Yes! I am portuguese and whose are the formal terms.
did you get it @alpine sable ?
Same in in Spanish :p
If the domain was all the real numbers, it would be (-) then? Sorry, I am still confused, is that something specific about the inverse?
why couldnt I pick the (+) one?
well, the domain for g(x)=(x-3)^2 is all the real numbers. If you take its inverse, you can only consider the portion to the left of x=3 or the right of x=3 at a time..why so? as values of g(x) repeat after x=3 (it's a many to one function). So in accordance with the given domain, you'll consider the branch before x=3 for its inverse
Remember that the inverse function can only map to 1 number
there's nothing as a one to many function
Ahhhh makes sense! Thank youuu!
how does it split into three fractions?
i dont understand how the fraction with x+3 came about
bruh wtf
bro
weirdo
spaz stop
this guy
also test in questions-2
report that fool
and some scammer guy deleted in questions-4
channel in use my guy
o my bad
Look up partial fraction decomposition
Yep, it's standard theory of hiw to decompose such fractions
Write it as A/(x-2) + B/(x-3) + C/(x-3)², and then compare it to find the scalars A,B and C
So here A=4, B=-3 and C=-9
why is it not split as only A/(x+2)+ C/(x+3)²
I'm saying that if you ignore the (x-3) term during decomposition, you'll not be able to equate
So you need (x-2), (x-3) and (x-3)²
the number of factors in denominator determines the number of segments?
I didn't get that
I just meant that you wouldn't be able to do it without the (x-3) term
Try doing without it, you'll not be able to equate
you mean x+3 right?
Yep, so sorry, i didn't catch that +
gotcha, thanks
No problem :)
y = f(x), so the values of f are the y values
A number divided by the infinity is exactly 0?
no
cause you cant divide by infinity
Mosh
I'll give you a weird example, we got infinite possible heights for a person, whats the change of the the person be exactly 1,80cm tall?
Like 1,80000000000...
Exactly 0?
if you have a continuous sample of data, you cant know the probability of a single data value
/ prob of said data value
That's a common misconception, but think about a dart board, the probability that the dart hits any point particular point is 0 but it is certainly possible
relevant
An introduction to probability density functions
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Curious about measure theory? This does require some background in real analysis, but if you want ...
If we want to be formal about it, we're talking about probability density functions, which is a function on an interval and 0 else (skipping details)
When we find the probability we find the area on that sub interval, with an integral of the function
If we want one specific value, then the interval would just be [a,a] if the value we want is a
but integrating from a to a always gives 0
$\int_a^a p(x)\dd{x}=0$
Mosh
I'll check the videos and more content about it because it is hella complex, but turning a long story short, even with infinite possible heights, can a person be exactly 1,80cm tall?
does anyone have any resource for trig integrals?
like
i scoured youtube but i only find those in product form
Omg this integral look so difficult
In this section we will look at integrals (both indefinite and definite) that require the use of a substitutions involving trig functions and how they can be used to simplify certain integrals.
thanks

thats not what you're looking for my bad lol
In this section we look at integrals that involve trig functions. In particular we concentrate integrating products of sines and cosines as well as products of secants and tangents. We will also briefly look at how to modify the work for products of these trig functions for some quotients of trig functions.
this should help tho
yes
$x\to \infty, \frac{1}{x}\to 0$
Stockie
$x\to \infty, \frac{1}{x}\to 0$
Stockie
yep
Hey, I need advices for finding the 4 intersection points of the lemniscate with the circle. I've graphed my problem here:
thanks for announcing your presence and saying you have a question ina question help channel.
lol owned
ok sorry where do i ask this question
not in a math help server...
but this sticker is from this server
Ok so ask in chill or something
Hi
If your question has not been answered for a minimum of 15 minutes, you may use the <@&286206848099549185> tag once
what are the steps to find x if I have the determinant? I multiplied 5 by 3 ,subtracted that from 35 and divided that answer by 4 and got 5. but the answer is -5
First expand the determinant, that is 5(3) - 4x = 35. Then solve for x, you did everything correct except you may have had the formula for the determinant wrong
Just be sure to write it down and be organized and you'll be get it
ok cool ty that makes sense.
looks right
ok what about this
try using the factor theorem to your advantage here 🙂
yeah there you go perfect
the fact it has that ugly remainder means its not a factor
you also could have plugged in -7 to the function and checked if you got 0
might have been easier
do i need to do polynomial long division?
i dont think you need to do long division
the factor theorem states that the remainder of P(x) when divided by (x-a) is equal to P(a)
it works but you didnt need to do it
ok do i need to solve it or does the question ask if x+7 is not a factor of
its just asking for you to show that the remainder when the polynomial is divided by x+7 is non-zero
notice that the remainder of the polynomial when you divide by (x+7) is equal to P(-7) by the factor theorem
ye
but what i did is still right cause i did polynomial long divsion and got
which proves
it
well yes but I think that just subsituting in x=-7 is a bit easier than performing long division. good job tho
ty
yeah... just showing x+7 fails factor theorem would've sufficed
got what?
8
yes
a) "express answer to nearest month"
How do I do "The sum of x and 3x - 2" Is algebraic expressions
yes.
and b good too
yes.
also this isnt a "is this right" server cause any calculator can check for you
you can be my calculator
till then
b^x = 1/(b^x)
1/(b^x) = N/M
b^x = M/N
Take log both sides
xlog b = log M - log N
Am i right
can u check this
its correct
You're close, it would be -xlogb = logM - log N
^
npnp
Usman
Looks good
thanks
hello

