help-0

[oak chasm]

OK, then the question from @neon igloo is still open.

[hidden turret]

-3, f^-1(-8)

?

[native temple]

why isn’t my latex working?

[oak chasm]

@hidden turret One of the rules is not to just give the answer. See #❓how-to-get-help.

[native temple]

okay how does the conditional probability formula work

If You divide p(a)*p(b) by p(a) or p(b)

you get p(a) or p(b)

but that doesn’t work as the new sample apace of p(a given b) is the sample space of b

the b event becomes the new sample space

[brittle jacinth]

are you guys done

[native temple]

idl

[sly mantle]

contesting channel 'ownership' is rather silly. simply move to an unoccupied channel

[neon igloo]

oh sry n tnxx

[native temple]

who?

me?

[sly mantle]

@native temple i'll say your question is the active one, but note that action will be taken against you if you post on top of other recently asked questions again

[native temple]

okay

[native temple]

So After 15 minutes

I thought I understood the rules

I thought people asked questions over this

and that because they left it wasn’t trailing

[hexed abyss]

i still need help:/

[native temple]

#help-1

[sly mantle]

the time isn't set in stone, rather use common sense to see whether a channel is or has recently been in use for another question

[native temple]

That’s what I did

[sly mantle]

there were definitely lingering questions here, and a helper pointed it out yet you buried them anyway

[native temple]

I thought the other oeople left

[native temple]

i’ll move

[wispy olive]

Can someone please explain the problem to me?

I know the answer.

[native temple]

This miss understing is insane

[wispy olive]

But I need an explanation on how to get the answer.

[harsh swallow]

you find the price of the mixture for 7kg

[wispy olive]

Yeee but it is a fraction.

[harsh swallow]

because that's the total amount you'd get if you did the lowest amount of mixing with whole kgs

and then you divide by 7 to get the price of the mixture

per kg

and compare it

[native temple]

Okay you’re right I didn’t see @neon igloo

[wispy olive]

(450 + 225) ÷ 7 is a fraction.

[native temple]

it was buried

And because of that I assumed it was inactive

[harsh swallow]

(450 * 5 + 225 * 2) / 7

[native temple]

I guess it was almost there

[wispy olive]

Why this?

[native temple]

man

IDK how to judge grey areas

......

[harsh swallow]

because the mix is 5:2

[wispy olive]

Yeah so?

[harsh swallow]

so every 5kg of one it's 2kg of the other

[wispy olive]

Wait.

Okay

I see

[harsh swallow]

so to find the price for 1 kg

you find the price of 7kg

and divide by 7

[wispy olive]

Then what do I do with this fraction?

[harsh swallow]

compare it to the sold price

see how much gain or loss there is

[wispy olive]

Mhm this is a big fraction.

[harsh swallow]

co-prime too

[wispy olive]

?

What is that?

[harsh swallow]

you cannot make it smaller

[wispy olive]

Yee

[harsh swallow]

have you found the value?

[wispy olive]

It is
388 6/7

[harsh swallow]

ye

oh i got 385

385.714285714

[wispy olive]

Let me tey again.

*try

[wispy olive]

Yes

[harsh swallow]

compare that to 405 per kg

[wispy olive]

In fraction from it is 2700/7

[harsh swallow]

yes

and those are co prime

2700 = 2^2 * 5^2 * 3^3

[wispy olive]

Yes

Now what?

[harsh swallow]

you compare

[wispy olive]

405 - 2700/7

[harsh swallow]

find the gain or loss per cent

[wispy olive]

I do this?

[harsh swallow]

i think so

and only look per cent

so anything less than a cent is wasted precision

is how i interpret the sentence

[wispy olive]

That is 450 /7

Bruh.

This is all messed up

What is the C.P. and the S.P.

[harsh swallow]

CP and SP?

[wispy olive]

Cost price and sell price.

[harsh swallow]

2700/7 is how much it costs to make the blend from the two things

and 405 is how much it sells for

[wispy olive]

Yessss

[neon igloo]

help??

[wispy olive]

Thanks A LOT @harsh swallow .

[harsh swallow]

np

[alpine sable]

My question is just this

[sleek elbow]

type it out, hard to read

[alpine sable]

Argghhh

Okay

Just tell me what is 4m^2 + 4m + 1 mod (3)

[sleek elbow]

dont think im ignoring you, but I cant help 😄 already no idea what mod() is

[alpine sable]

[harsh swallow]

modular

[alpine sable]

Okay brother

[harsh swallow]

2 mod(3) is a group of numbers

2, 5, 8 ...

[alpine sable]

This is congruent 2 mod(3)

Right?

@harsh swallow

[harsh swallow]

do you mean the whole expression is mod(3) or just the 1?

[alpine sable]

Whole

Help @harsh swallow

[harsh swallow]

i'm not entirely sure how i would figure out a value for that expression

[alpine sable]

I mean

Not a value

But

Like

The mod

9m^2 + 6m + 1 mod(3) is

1 mod 3

[harsh swallow]

m is in $\mathbb{N}^{0}$ right?

[alpine sable]

[ocean seal]

Katharine

[alpine sable]

Yes

[harsh swallow]

can you explain how you found that out

[alpine sable]

[alpine sable]

This

@harsh swallow

4(m+1) + 1 when divided by 3 leaves 2 as the remainder if I am correct

4/3 is 1 remainder

And then 1 added

Remainder = 2

Is this correct

Or leave it I need help with 107 instead

[harsh swallow]

the ath root of 10000 base a = 10 base a

are the powers of 10 always 10 100 1000 10000 in any base?

if so you can easily find a

[alpine sable]

In base 10

But 10 in base what

4 doesn't fit

[harsh swallow]

10 in base 2 is 2 in base 10

[alpine sable]

3 doesn't

[harsh swallow]

if that makes any sense

[oak chasm]

@harsh swallow Yes, regardless of base. Let's say base is b. 10 in that base is b^1. 100 in that base is b^2. 1000 in that base is b^3.

[harsh swallow]

that would make it super easy to find a wouldn't'it @oak chasm

[alpine sable]

Ok looks like I don't know bases

[alpine sable]

Is this true then 🥺

[ocean seal]

Chai T. Rex

[harsh swallow]

i had a question about that

[oak chasm]

Unless you know m, that's the closest you can get.

[harsh swallow]

can you seperate all the terms

[oak chasm]

Actually, let's see.

[harsh swallow]

can you say 4m^2 + 4m + 1 (mod 3) = 4m^2 (mod 3) + 4m (mod 3) + 1 (mod 3)

[ocean seal]

Chai T. Rex

[oak chasm]

So, the remainder is either 0 or 1 depending on m.

[late scaffold]

anyone here know how to compute profit?

can any one help me for the formula?

[alpine sable]

Im trying to graph this, and i get the limit for both equations. which one should i use? where is the limits for this at?

That's my work so far

[harsh swallow]

seeing as your equations use t as the variable i'm thinking these are parametric equations

[pearl marlin]

You want limit?

Or graph

[alpine sable]

yes its a parametic equation

[harsh swallow]

then both limits are to be used

together

to get a point

that point is the limit

[alpine sable]

okay well i know it matches the line i have for x

the parametic equation

i just dont know how to find the limits

of the parametic equaion

because when i do it on desmos

it gives a different answer than i would get

[harsh swallow]

the limits are written in x limits and y limits

show me?

[keen socket]

did u find the cartesian equation#?

[alpine sable]

thats the bottom right, in quad 1

[harsh swallow]

the equation is a line starting from 6,4

[alpine sable]

its over 5

[keen socket]

show ur input

[keen socket]

i think ur suppose to find the equation of the graph first

to do that u do the Integral of y dx/dt dt

[harsh swallow]

when t goes to infinity the 7e^-2t and 3e^-2t parts go to 0

as it becomes 1/huger and huger numbers

[alpine sable]

i got the x formula already

it lines up perfectly over it

i already have the line, i just need to know where to stop it lol

but i have limits based off the e itself

and if its positive infinity its 1 and 7

[harsh swallow]

i get this on geogebra

although i didn't put in infinity

because it takes too long imo

😄

[alpine sable]

i dont know what that is, lol okay so i should just go with what i got then.

[harsh swallow]

that's the parametric curve

at 1,7 it's t = 0

[alpine sable]

no its no 1 and 7

i did the limit wrong lol

[harsh swallow]

and it goes to infinity on both x and y when t = -infty

and when t = infty it goes to 6,4

[alpine sable]

yep i got them, idk whyd esmos is wrong

i was second guessing myself here for no reason

[harsh swallow]

so the range of x is (-infty,6)

and the range of y is (4, infty)

idk how to write the range of y

whether the infty goes on the left or right

[alpine sable]

its just the limit as t goes to infity

[harsh swallow]

probably the right

[late niche]

Cot = 84/85 right?

[pearl marlin]

Move the triangle in side of angel D

[pearl marlin]

,rotate

[pearl marlin]

Now check

[upper pebble]

cotangent = adjacent/opposite

[late niche]

Ohhhh

[upper pebble]

85 is the hypotenuse

[late niche]

I see

[pearl marlin]

While using angle , that angle should be on your side , then it will be easy to deal

[late niche]

So it would be 84/13

[pearl marlin]

Yup

[upper pebble]

yes

[late niche]

Ohh I get it know thanks

[fading walrus]

what is this notation mean

i dont get it

[sly mantle]

the definition of max is given above

[pearl marlin]

If you can draw both the graph then you can see which is when is max

[fading walrus]

1/x and x doesnt have max

[oak chasm]

Sure it does.

[pearl marlin]

UsE desmos

You will see

[oak chasm]

For example, 1/2 and 2 have a max: 2.

So, when x = 2, x is the max out of x and 1/x.

At each x, one of them will be the max.

[late niche]

So tan is (opp/adj) and it saying that i need to find the S presents it would be 16/63 or it would the other way 63/16 im a little confuse.

[oak chasm]

@late niche Sorry, this channel is currently busy.

[pearl marlin]

,rotate

[oak chasm]

#help-9 is open if you hurry.

[pearl marlin]

Now check

[oak chasm]

@pearl marlin Sorry, this channel is currently busy.

[fading walrus]

oh

i think i get it now

thanks @oak chasm

[oak chasm]

No problem.

[fading walrus]

wait does that mean i have to graph it where 1/x above x and vice versa?

[glass lichen]

when 1/x>x, you graph 1/x

[fading walrus]

yeah

ok

[proud sentinel]

can anyone help me with discrete numebrc functions and generating functions problem!

[alpine sable]

I have a friend that needs help in mandarin

Chinese

I posted some pics

It is math math is universal

No you’re good ! I

Should have been more clear

They need explanation but in mandarin*

,w rotate

,rotate

,rotate

[alpine sable]

How did it go from cosθ = 1/2 - 3/2x to only when x = 2 can θ be an obtuse angle??? Help

Is what they want to know ?

For the question above **

[untold mountain]

help

[jaunty wave]

Sine rule

a/Sin A = b/Sin B

[untold mountain]

so

the answer is

4.41

[jaunty wave]

yez

[untold mountain]

how about cosine rule

?

[jaunty wave]

It depends on if ur trying to find

angle or side

[untold mountain]

uhhh

let me see

give me a sec

[jaunty wave]

side ^2= b^2 +c^2 -2bc*Cos (A)

[jaunty wave]

so

(root 12)^2 + (2)^2

• 2* root 12 * 2 * Cos (30)

I need to know how to use these bots

[untold mountain]

i have a question

so how old are u

are u over 20 ?

[jaunty wave]

No

16

17 soon

[untold mountain]

dang u are smart

:((

:))) i mean

but dude

do u learn calcus

sorry about speeling

[jaunty wave]

Not yet but soon

[untold mountain]

when did you learn the sin and cosine

rule

[jaunty wave]

Like 2 years ago

or 1 and a half

idk

[untold mountain]

tell me some tips

how to get better

at maths

please

[upper pebble]

practice solving problems

[jaunty wave]

uh i just do lots of questions to be honest

ye

[untold mountain]

oke

[jaunty wave]

helps get that muscle memory

[upper pebble]

also try to understand how the math works as opposed to simply memorizing it

[untold mountain]

the problem about myself is that

I sometimes forget about things I learnt before

such as formula

etc

[jaunty wave]

If you do enough questions using the formula even if u forget it one look at it will bring it back to you hopefully

thats how it works for me i guess

[untold mountain]

since you are a few years older than me

give me some math topic

s

that are really important

like mostly used maths

[jaunty wave]

Well it depends on the curriculum at school

[untold mountain]

I am on a break

rn

and I turn year 9 soon

and as u know

we learn basic trigon

in year 9

[jaunty wave]

Do you know what exam boards ur school has

[untold mountain]

for example ?

[jaunty wave]

Edexcel ocr aqa

[untold mountain]

aqa

because its igcse

[jaunty wave]

https://filestore.aqa.org.uk/resources/mathematics/specifications/AQA-8300-SP-2015.PDF this possibly?

I'm not exactly sure btw because I haven't done iGCSE

[untold mountain]

then what have u done ?

[jaunty wave]

I did the normal GCSE

[untold mountain]

ya

its very smae

same

as igcse

but

[jaunty wave]

i had a different exam board as well

[untold mountain]

igcse is little bit more harder

[unborn dome]

hey uh, can anyone help me with this question

im just completely confused....

i got y = aln(-(-3+3)) and I'm pretty sure i messed up a step from there

[untold mountain]

idk

dn

will answer u

he is a smart ass

jkjk

not meant for real

[jaunty wave]

I haven't done logatharims yet lol sorry

[untold mountain]

lol

me too

i don;t even know what that is

[unborn dome]

oooof

[jaunty wave]

I'll stop talking here so someone else can see ur message

[untold mountain]

:))

[fair hamlet]

Hint: this is just the normal logarithm except they have shifted it left by 3 units and then flipped the graph around the x-axis (that is, they’ve negated it). Can you figure out the formula from here?

[unborn dome]

yea that would be nice @fair hamlet

thank you.

im assuming is it maybe like 1/ln-3 (-(x+3)) or

or -1/ln-3

[fair hamlet]

The second thing has no x in it, there is no way it is possible

Look just start with ln(x), shift it 3 units to the left to get ln(x+3) and then negate to get -ln(x+3), now they also want f(-1)=-3, but in our case f(-1)= -ln(2), so all we have to do is multiply our function to get something like -3ln(x+3)/ln(2)

[unborn dome]

I see

Thank you very much @fair hamlet

[untold mountain]

guys

I cannot sleep

pick what I should do

1. just go sleep

2. practise math quesions

[bleak pier]

both?

[untold mountain]

wdym /,, /

[bleak pier]

do math in your dreams

[river glade]

Hi, how should I solve this? I already used the first equation to get A sub 3 and A sub 4 but Idk what to do with that info. Should I just do for example if A sub 3=5, then "5= (1+ x)/t"?

[untold mountain]

what year u on

?

[river glade]

I'm not in high school, but I'm studying for a high school-level math test. I have no idea what level this is as I'm only given practice tests with no syllabus

[untold mountain]

so what year

are u on

[river glade]

I am not on any particular year? lol

[untold mountain]

how old are u

[river glade]

22

[untold mountain]

oh

why are u studying for the high school

test

[alpine sable]

you don't need to know that bro

just respect her man

[untold mountain]

i was just curious

about it

[river glade]

it's for a scholarship

[untold mountain]

umm

i really want to help

but I dont know about this

[river glade]

rip

[untold mountain]

help this man anyone

with this question

[grizzled lion]

What does the notation [1-5] even mean? Is there a number to be inserted?

[vale wigeon]

answer sheet key, most likely

[untold mountain]

I am year 8..

cannot answer that hard questions

[river glade]

what ann said, it's just an indication of where to put in your answer

has nothing to do with the exercise

[grizzled lion]

So what you could try is calculate a_3, a_4, ... with the formula and try to see what regularity you find

[river glade]

I did that and I found that a_3 is 5 and a_4 is 18, but after that I'm stuck... do I need to reason it out or is there anything mathematically that I can do?

[harsh swallow]

@river glade i get 14

[grizzled lion]

same here

[river glade]

oh yeah lol you're right

[harsh swallow]

i used excel

easy fibonacci

[river glade]

-20+6= 14 not 18 haha

but so after this the only possible way to get the answer is by using logic? I don't know how I should proceed

[harsh swallow]

it tends to being 3 times the previous

starts at 2

ends at 3

[velvet pelican]

the formula is ||a_k = (1+3^(k-1))/2|| I think

[light quartz]

ehm so

derivative of xlogy + ylogx = 5

with respect to x

is it -y^2/x^2

[ionic jewel]

,w derivative of xlog(y)+ylog(x) = 5 wrt x

[ocean seal]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[light quartz]

how is that even possible

[harsh swallow]

cuz you first have to make that expression into one where it's y =

[light quartz]

what i did was

oh

[harsh swallow]

that's what it's doing

[ionic jewel]

you can do implicit differentiation

[light quartz]

that's what my teacher told me to do

implicit diff

[ionic jewel]

well you probably did it wrong

[light quartz]

so i used product law

[ionic jewel]

let's just do the first term

[light quartz]

first term

[harsh swallow]

x + something else

[ionic jewel]

x log(y)

what's derivative wrt x

[light quartz]

x times 1/y times dy/dx

[harsh swallow]

log(y) + something else

idk what came over me

[ionic jewel]

don't think that's right

you need product rule

[light quartz]

that's the product rule right?

[ionic jewel]

log(y) + x(1/y)y'

[light quartz]

u times derivative of v + v times derivative of u

[ionic jewel]

you forgot the log(y) from the product rule

[light quartz]

what's y'

[ionic jewel]

dy/dx

just easier notation for me on mobile

[light quartz]

ohh

[ionic jewel]

derivative of ab = a'b + b'a

[harsh swallow]

why product rule?

oh

[light quartz]

yeah

[harsh swallow]

we're not doing partial

[river glade]

like, always? Or how do you know

[light quartz]

and then i got x times 1/y times y'

the first term

[ionic jewel]

and he forgot the x'log(y) = log(y)

in the addition

[light quartz]

and then the second term y times 1/x

[ionic jewel]

bruh your first term is wrong slow down

[river glade]

it is! how did you find it?

[light quartz]

,w derivative x(log(y))

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Π I K#4100

[ionic jewel]

that's wrt y

[harsh swallow]

,w derivative x(log(y)) wrt x

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Katharine#1478

[harsh swallow]

oh

lol

[ionic jewel]

[harsh swallow]

,w derivative x*log(y) wrt x

[light quartz]

[harsh swallow]

ffs

it's stupid

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Katharine#1478

[harsh swallow]

there

are we doing partial or are we not

[ionic jewel]

that ain't eight

[harsh swallow]

cuz if we aren't then this is not the right answer

[ionic jewel]

,w derivative of x*log(y(x)) wrt x

[harsh swallow]

cuz this is partial

[ocean seal]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[ionic jewel]

there we go this is right

@ Russian guy you got the first term of this right, but you didn't apply product rule to get the second one

[light quartz]

the first letter of my username is Russian?

[harsh swallow]

@river glade Bigger k values give a more accurate value of 3. a2/a1 isn't accurate but a20/a19 is very close to 3

[ionic jewel]

idk looks Cyrillic , but either way i can't type it

[light quartz]

oh

[harsh swallow]

capital pi

not cyrillic

[velvet pelican]

The way to solve those is to assume the solution is of the form a_k = c * b^k,
you get a quadratic in terms of b after substituting giving you b=1 or 3
so the general solution is of the form a_k = c1 * 1^k + c2 * 3^k = c1 + c2 * 3^k
then plugging in k=1 and k=2 to solve for c1 and c2 leads you to the answer
search up solving second order linear homogeneous recurrence relations or smth to get a more in depth explanation

[ionic jewel]

my bad

Greek guy then

[alpine sable]

Well the Cyrillic letter Pe was derived from the Greek Pi

[ionic jewel]

but either way you need product rule

(xlog(y))'
= x'log(y) + xlog(y)'
= log(y) = x*1/y*dy/dx

then you do the same idea for the second term you have

then you isolate dy/dx by itself and ur done

obviously the derivative of 5 is 0 too

[ionic jewel]

at this guy

[river glade]

thank you!!

[light quartz]

hmmm yeah

am i the only 12th grader here the math in this server seems beyond what my brain can fathom

[grizzled lion]

Many folks on this server are college students from what I've gathered

[light quartz]

ohh

[grizzled lion]

Either way never feel bad for not yet understanding! :)

[light quartz]

quite honestly I still dont get this question

it's x * logy right

[harsh swallow]

is y a function of x?

[light quartz]

i dont think so

if it were it'd be in brackets right

()

[harsh swallow]

you're still talking about xlogy + ylogx = 5?

[light quartz]

yeah

[harsh swallow]

so if y is a function of x

then x log(y(x))

requires the product rule

if it isn't a function of x

then it is just a constant with regard to x

[ionic jewel]

it is a function of x

y(x) is right

[harsh swallow]

nik hasn't'given a reason to think it is though

[ionic jewel]

it's assumed to be for implicit differentiation

I've done plenty of problems that look like this, it's 100% the assumption

especially since that's how he did it too (notice his dy/dx in his answer) but he just forgot the chain rule

[light quartz]

good point

but what if it's not a function

[ionic jewel]

it's not a partial derivative

[light quartz]

that means?

[harsh swallow]

it means y is not a function of x

they'r independent

that's partial

you can treat it as a constant

as a number

but implicit differentiation

is different

you imply that y = y(x)

and so you have to use chain rule and stuff

[light quartz]

oh

[harsh swallow]

so in this case

you do

x * log(y(x)) + y(x) log(x) = 5

differentiating the first term

is 1 * log(y(x)) + x * 1/y(x) * y'(x)

if i'm not mistaken

[light quartz]

ohh

[harsh swallow]

chain rule

and product rule

i think those are called that

[light quartz]

idk if i was taught chain rule before

[harsh swallow]

a(x)b(x) => a'(x)b(x) + a(x)b'(x)

[light quartz]

thats product rule tho

[harsh swallow]

a(b(x)) => a'(b(x))b'(x)

[light quartz]

wait is it

[harsh swallow]

one is chain rule the other product

i think the multiplying one is product

a(x)b(x) is product

and a(b(x)) is chain

[light quartz]

ah

yeah i've been taught that

My teacher told us to apply product rule for this question actually

[harsh swallow]

so bunny is right

try to do the second part

the first part is

1 * log(y(x)) + x * 1/y(x) * y'(x)

and try to do the second part

y(x) log(x)

differentiate this with the product rule

[light quartz]

y(x) * 1/x ?

[harsh swallow]

yes that's the first one

a(x)b(x) => a'(x)b(x) + a(x)b'(x)

a'(x)b(x)

you did that

you need to do the second one

[light quartz]

x(x) * 1/y * y' ?

[harsh swallow]

not quite

if we do the first part you had it correct

perfect

the second part

the a(x)b'(x) bit

is log(x) y'(x)

maybe if i write it as a whole you can see it better

log(x) y(x) => 1/x y(x) + log(x) y'(x)

a(x)b(x) => a'(x)b(x) + a(x)b'(x)

[light quartz]

i think i sort of get it

[velvet pelican]

divide it into 2 distances

1. The distance covered in the reaction time (just distance = speed * time)
2. The distance covered when braking (easiest is to use v^2 = u^2 + 2as ie. suvat equations)

yea

[unborn dome]

hey uh can anyone help me on this question, not entirely sure what to do for numerator

i get that the denominator is (x+1)(x-4)^2 tho

[velvet pelican]

please use a channel not currently in use

[unborn dome]

o sure

[velvet pelican]

shouldn't it be + v_0t? at the end

[harsh swallow]

fill in the t

and you get the answer

[velvet pelican]

yup

[harsh swallow]

or at least it seems to line up

[velvet pelican]

and add it to the thing for 1.

[harsh swallow]

how

[velvet pelican]

yup that seems correct

you should be able to factor out v_0^2/a

[tired fox]

if you integrate 3/x^2 in the boundary of -4 and 4, you get -1.5. But why is this possible because the areas involved are infinite?

To get -1.5, I did: 3/x^2 = 3x^-2. Integral = 3x^-1/-1 = -3x^-1.
And if you input your boundary values you get -1.5

but at the same time the area should not be negative

[ionic jewel]

the function doesnt exist at 0 so the upper bound - lower bound (fundemental theorem of calculus) doesnt hold if 0 is inside the integral bounds

[tired fox]

ah

I see

so what do you do if the fundamental theorem is broken?

[ionic jewel]

you could split your integral into two parts

but in this case the integral trivially doesnt converge (goes to infinity)

[tired fox]

so can you still define this as an even function?

[ionic jewel]

yes its even

[tired fox]

the areas are the same... although infinite

ok

[ionic jewel]

yes, but they are both positive

[ebon mantle]

Is this channel clear to ask a quick question?

[ionic jewel]

go for it

[ebon mantle]

ok I am having trouble understanding what this question is asking of me

I had no questions like this the whole chapter, I've just been balancing equations, so I'm having trouble understanding how I use those skills to answer this

[ionic jewel]

your answers are wrong

yes this is balancing equations, kind of

okay so you dont actually have to do what im going to show you, but im going to show you what this question really means

do you know how to get the equation of a line?

[ebon mantle]

thank you

[ionic jewel]

the blue line in this case

slope is 2, y intercept is -2

[ebon mantle]

right

[ionic jewel]

so y = 2x-2

do you agree with this?

[ebon mantle]

yes

[ionic jewel]

so the point B is at (2.5, 3)

can you plug that into the equation for the line we get?

x = 2.5, y = 3

[ebon mantle]

ok yea that makes sense

[ionic jewel]

what makes sense?

[ebon mantle]

5-2=3 which is y

[ionic jewel]

yes

5-2 = 3

and is this a "true statement"?

[ebon mantle]

yes

[ionic jewel]

so when the coordinate for point B are put into the line l2, you get a true statement

which actually isnt any of the answer choices

but the moral of the story is that if (and only if) the point is on the line, when you plug it in you will get a true statement

does that make sense? @ebon mantle

[ebon mantle]

yes I think it does. The way you broke it down was incredible

[ionic jewel]

To check for you, the correct answers for this problem are ||1, 2, and 4||

[ebon mantle]

Thank you, I really appreciate everything!

[ionic jewel]

of course, yw

[blazing dock]

original problem: 225 = 2500 + 3600 - 2 * 50 * 60 * cos(x)
my answer: cos(x) = 5875/(-2 * 50 * 60)
expected answer: cos(x) = 5875/(2 * 50 * 60)
What am I doing wrong?

[ionic jewel]

well lets start by subtracting 2500 and 3600 from each side

,calc 225-2500-3600

[ocean seal]

Result:

-5875

[ionic jewel]

now we can divide both sides by $-2\cdot50\cdot60$

[ocean seal]

bunny

[ionic jewel]

so we get $\frac{-5875}{-2\cdot50\cdot60}$

[ocean seal]

bunny

[blazing dock]

OHH

[ionic jewel]

which you can then cancel the negative from the top and bottom to get expected answer

[blazing dock]

i forgot the negative on the 5875

thank you

[ionic jewel]

yw

[blazing dock]

i've been confused on this problem for way too long

[tender geyser]

i have this function and i need to analyze the singularities
could somebody confirm the following results for me?

3 is a pole of 1st order as the denominator has a simple zero at z=3
-3 is an essential singularity as 1/sin(z+3) has infinitely many negative coefficients if we look at the power series
and 2 and -2 are removable singularities because the power series for cos(z) has no negative coefficients

[fathom fossil]

@tender geyser ok

[ionic jewel]

@fathom fossil your answer was wrong, its about 0.85%

[fathom fossil]

Ok

Let me post the question again

I did this using the z score

Formula

12100-9000/1300

and when it says more than you the number for that from 1

[ionic jewel]

isnt -3 also a pole of 1st order because of the 1/(z^2-9)

[tender geyser]

yeah i think its both

but an essential singularity is considered "the stronger type"

so -3 is counted as essential in that case

[ionic jewel]

you have $x^2-2x-8=0$, which factors into $(x-4)(x+2) = 0$, giving you roots of $4, -2$

[ionic jewel]

ah I didnt know that, looks right then

[tender geyser]

awesome ty!

[fathom fossil]

@ionic jewel when you’re finished can you explain what i did wrong?

[ionic jewel]

no i dont know how zscores work lol

[dark granite]

This is wrong

Because 4x-2x isn’t -2x

[fathom fossil]

@ionic jewel so i don’t put 0.85 like you said?

[ionic jewel]

i just dont know how to solve your problem, i just know your answer is wrong

[fathom fossil]

Ok

[ionic jewel]

oh shoot lemme fix it

[ocean seal]

bunny

[alpine sable]

How do u do it

[cinder lily]

i am guessing you just need to write it was linear factors

[ocean seal]

Yes ツ

[alpine sable]

is this right

[sage jacinth]

no

your x coordinate for your vertex is wrong

[fast geyser]

could someone please help me out with this? i've been at it for hours but i keep getting marked wrong. im kinda desperate this point lol. checked on wolfram alpha too. i got (n^(2))!/(2n)!, (n!/(2^(n)+3)), ((n+1)^(2n))/(n+1)!, and e^(n)/(n^(2)).

[jagged raptor]

i havent checked your answers but are you sure you're only choosing the ones where the ratio test gives a ratio > 1

if the series diverges but the ratio test yields a ratio of 1 you should not check that box

[fast geyser]

yup

i feel as though i've made a trivial mistake somewhere but i've spent hours trying to catch it to no avail lol

[glass lichen]

what have you tried..?

[alpine sable]

So I'm making a minecraft plugin that has custom levels that go like this
level 1 to be 10 xp points and level 2 to be 12 so add 2 for every level

what would the equation be to do xp -> levels and levels -> xp?

[placid zinc]

In order to proceed from level n:

f(n) = 10 + 2n

Or would it be 8 + 2n?

[alpine sable]

well the levels are as follows

Level 1: 0-10xp
Level 2: 11-22xp

etc

so its lexelmax +12

I think im so bad at math

[placid zinc]

So yeah to proceed from level n is 8 + 2n

[alpine sable]

wdym by proceed from level

[jagged raptor]

try the 6th option again

[alpine sable]

that wouldn't be right because if im level five that returns 18 when it should be 70

[placid zinc]

To proceed from level 1, you need 11 xp.
To proceed from level 2, you need 23 xp.
So sorry, it is actually 12n - 1

Yeah I had a brain moment there haha

[steady fern]

hi

i have a ask

[alpine sable]

lol let me test it one second

[glass lichen]

in use unless Sage is done.

[alpine sable]

I'm not

[steady fern]

(x + 1) • (x + 2)

i need help plsss

[alpine sable]

@steady fern

[alpine sable]

Idk how long to do the scale

[steady fern]

sure

[alpine sable]

so @placid zinc 12n-1 should return the minimum value for that level?

[steady fern]

how much is plsss

[winter salmon]

bro

[glass lichen]

Still in use. also you have not asked a question.

[placid zinc]

Or, well, I should give a different representation. In order to be at least level n, you need to have 12n - 13 xp

[winter salmon]

[steady fern]

BRUH??

[glass lichen]

#❓how-to-get-help #rules

[winter salmon]

[alpine sable]

okay actually Kay I read the client's request wrong. They want it to be like this

[glass lichen]

@steady fern ignoring the fact you cant read, if you want any amount of help learn how to follow rules.

[alpine sable]

math hurts my brain

[winter salmon]

dude is it that hard to wait? or go to another channel

[alpine sable]

@steady fern x^2+3x+2 now please leave this channel

so @placid zinc say I have 25xp how would I get the level from that

also sorry im pretty bad at math

[placid zinc]

In order to be at least level n, you need to have 12n - 13 xp
We can invert that. If you have x xp, your level is (x + 13)/12 rounded down

[alpine sable]

okay and one more thing

so I also need to get percentage to level up

so is it (12l-13)/x?

[fast geyser]

thank you so much for your help!!! i'll try that, do you know if everything else matches up?

[placid zinc]

Not clear on "percentage to level up". Percentage of what, in terms of what?

[alpine sable]

from their xp to the next level min

Level 1: 0-10xp
They have 8xp
so it should return 80%

[jagged raptor]

i checked everything up to the sixth option

you're right about the first five

the sixth gives a ratio > 1

[full dome]

hello, this is urgent, can someone please check this work for me and tell me if it is correct ?

https://docs.google.com/document/d/13rVWFHGM0RIIdrUIXg9c7i1k1il_mT5YNAf8frJbcjg/edit

[alpine sable]

@placid zinc

Did I do a right

[alpine sable]

yes

[alpine sable]

do you know what it means by show end behaviour

I’m confused

[jagged raptor]

the limits as x-> +/- inf

[alpine sable]

oh ok

[fleet glacier]

I'm not really sure if other people answered your question or not

You want to multiply each element of the first product by the second

so x*x+x *2+1 *x+1 *2

[fleet glacier]

x-h indicates a derivative of 0

at x=h

if you don't know calc, that just means the function goes flat

for x^3, this point is (0,0)

now it's (6,1)

c(x-6)^3+1

now use the second point (10,33) to solve for c

[glass lichen]

or... the parent function was translated 6 units right and 1 up

[fleet glacier]

that too

but the stretching is still done by c

[winter salmon]

whats c im dumb

[fleet glacier]

I think I said that, but really drawn out lmao.

[winter salmon]

like what does c represent

[fleet glacier]

c stretches or squishes the function

[winter salmon]

o

[fleet glacier]

so 5x^3 would be more narrow than x^3 because 5x^3 increases faster than x^3

same case here

[winter salmon]

ah

[fleet glacier]

you have y=c(x-6)^3+1

you need one other point

plug in (10,33)

[glass lichen]

$f(x)\to cf(x)$ means f has been vertically stretched by a factor of c

[ocean seal]

Mosh

[winter salmon]

33=c(10-6)^3+1

[fleet glacier]

yes

I never knew \to was a command

nice

[winter salmon]

c=1/2

[fleet glacier]

I guess, I haven't tried it

lemme see

yeah

it is

[winter salmon]

its telling me to write my answer as y = ...

i havent done graphing/functions in a while jesus

[winter salmon]

how do i write my answer idk really know where to go from here@fleet glacier

[fleet glacier]

wdym

y=c(x-h)^3+k

you know (h,k) is (6,1)

which means h is?

and k is?

you solved for c

[winter salmon]

uh

y=1/2(x-6)^3+1

i get 33

uh

brain work pls

[fleet glacier]

wdym

[warped phoenix]

is this channel in use

[glass lichen]

what have you tried?

[lavish cargo]

hello. i would like help with this question. any help is appreciated. thanks much

[placid zinc]

Σ can be thought of like a linear function

Like a derivative

It splits over addition and lets out constants

[lavish cargo]

sorry what exactly does that mean

and how will that help me find the answer

[placid zinc]

It's the same as:
4(Σ ai) + 18(Σ bi)

Σ splits over addition and lets out constants

[lavish cargo]

I got it wrong (although I am given multiple attempts)

so i substituted "ai" for -16 and it didnt work

[glass lichen]

can you post your working then...?

[lavish cargo]

so i plug "-16" and "7" into equation but it doesnt work

[placid zinc]

,w 4(-16) + 18(7)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Kaynex#7520

[lavish cargo]

wait sorry i had to get a new problem with new numbers to retry it

can you tell me what i need to do to get the answer

[glass lichen]

that was already done....

[lavish cargo]

oh wait i got it

thanks guys for your time

[placid zinc]

I have no idea that's really wrong haha

Step 1 is indeed the mistake

No you can't. They don't really simplify to anything nice

Oh shoot I misread it

Yes you can do xⁿyⁿ = (xy)ⁿ

We say that ⁿ splits over multiplication

(4^-3)(2^-3) = (4×2)^-3

[alpine sable]

What is this?

I don’t understand

[placid zinc]

It works because same exponent yeah. If both the base and exponent are different, stuff doesn't really simplify well

Yes exponents split over division

(x/y)ⁿ = xⁿ/yⁿ

[alpine sable]

so A

[placid zinc]

Yeah np! Feel free to ask if you have any others.

[alpine sable]

How do I do this?

Can someone explain

[rigid smelt]

if i gave you f(x)=x^2 can you determine f(2) for me?

[alpine sable]

no

idk

i dont understand function

[rigid smelt]

then you should revise

i suppose your book has everything you need in it

[alpine sable]

i dont have a book

its online

[rigid smelt]

then you can search it online

search "functions"

[alpine sable]

i try to do the lesson but i dont understand it

so im here

[rigid smelt]

then what dont you understand? there has to be a particular thing about functions that you dont understand

[alpine sable]

like how do u solve it

the lesson kinda azzz

[rigid smelt]

i can just give you like a way to do it but then it would be very mechanical method to study if you want

if f(x)=x^2, then f(a) = a^2

you just replace x with the thing inside the brackets

[alpine sable]

so u put the 2 in a

[rigid smelt]

yes

[alpine sable]

than what

[rigid smelt]

so can you tell me whats f(2)=?

[alpine sable]

4

[rigid smelt]

yeah

it works the same way in the problem

a+h is inside the brackets

[alpine sable]

but its so big

how do i start it

[rigid smelt]

it doesnt matter

can you tell me what f(a+h)=?

[alpine sable]

like crossing stuff out and stuff

3

[rigid smelt]

no

[rigid smelt]

again

[alpine sable]

so its B?

[rigid smelt]

erm no

[alpine sable]

eh

[rigid smelt]

you still havent answered my question

what does f(a+h)=?

[alpine sable]

where the h come form

[rigid smelt]

it doesnt matter

[alpine sable]

4

[rigid smelt]

why did it becomes a numerical value?

we started with a+h

where these two are unnkowns

[alpine sable]

cuz u said a is 2

[rigid smelt]

i never said 2 is a in the problem?

thats just an example i gave you

[alpine sable]

so 0?

[rigid smelt]

no

[alpine sable]

y?

[rigid smelt]

.

ok please just go look at the lesson again

and go online and do more research

because as i said, you are supposed to be the one learning first, you cant just show up and asked a for a lesson about this

this is exactly why i didnt want to straight up show you how to do the problem, because it gets super confusing

[misty mountain]

so I was doing (p+q-2)^2 and got p^2-2p+q^2-4
Can someone explain what I did wrong?

I did the FOIL method btw

[rigid smelt]

i assume you want to expand the thing

can you show the work?

[misty mountain]

ok

FOIL
first
p * p = p^2
outter
p * -2 = -2p
Inner
q * q = q^2
Last
-2 * -2 = 4

[rigid smelt]

use space between the asterisks

[misty mountain]

oh ok

[rigid smelt]

or put `` to create a code block

[misty mountain]

thanks

[alpine sable]

Determine whether the relation is a function: {(–1, –2), (–2, –3), (–3, –1)}.?

[dull oak]

anyone can help me?

[rigid smelt]

channel is busy please move

erm you didnt foil correctly

[misty mountain]

(p+q-2)(p+q-2)

[rigid smelt]

with this one being three terms

[dull oak]

=p(p+q-2) + q(p+q-2) -2(p+q-2)

[rigid smelt]

you have to imagine it as the first term times the whole brackets, second terms times the whole bracket, third term times the whole bracket

dont think it as outer, inner, blah blah, it gets confusing as more and more terms are introduced

[misty mountain]

can you give an example please?

[rigid smelt]

here

[misty mountain]

yeah thats the answer, but I'm asking how to achieve the answer

[dull oak]

wait what

[dull oak]

this is the same as that

[rigid smelt]

or for example, (A + B + C)(D + E)
first term times the whole bracket:
A * (D + E)
second term times whole bracket:
B* (D+E)
etc.

[dull oak]

thats what it is in essence

[misty mountain]

ok let me try that

(p+q-2)^2

(p+q-2)(p+q-2)

p*(p+q-2)

[dull oak]

ok

so

lets say

u wanna do

A(B+C+D)

this equals to AB AC AD right?

now if u sub A = (P+Q-2)

[misty mountain]

p(p+q-2)

[dull oak]

do u see how it multiplies

[misty mountain]

yeah...

[misty mountain]

p*(p+q-2)

q(p+q-2)

[misty mountain]

-2(p+q-2)

so it becomes

p(p+q-2)+q(p+q-2)-2(p+q-2)

right?

[rigid smelt]

you might just as well expand p(p+q-2) and the other terms

and yes

[misty mountain]

ahhh

I see now

thanks

[alpine sable]

Did I do anything wrong here? If so, how do I correct it

[misty mountain]

which one did you get wrong?

[alpine sable]

I'm asking if any of them are wrong