#help-0

1 messages · Page 713 of 1

glass lichen
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No... cause you move everything to the u world

rich basin
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so it would be 1/3 * (3x+1)^7?

glass lichen
#

No

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dont put words in my mouth, I told you what it would be

rich basin
#

1/3 • ∫u^7 ?

glass lichen
#

missing the differential

topaz scaffold
#

Check if a channel is occupied man please

rich basin
#

why what he did is allowed, whcih is similar to what i did to my question

alpine sable
#

how would I put this

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into an equation

woeful pulsar
#

using an equation

alpine sable
#

uh

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ok

topaz scaffold
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To simplify the integral

woeful pulsar
alpine sable
#

uh

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nothing

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im confusion

woeful pulsar
#

okay so just before this you probably were taught the equation of a line, right?

alpine sable
#

uh

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y=mx+b?

woeful pulsar
#

yeah something like that

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so y is the dependent variable and x is the independent variable

alpine sable
#

ok

woeful pulsar
#

equation of a line is used to show relationships where something changes at a constant rate

alpine sable
#

yes

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ok

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ok yes

#

uh

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can u continue with the

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help

woeful pulsar
#

idk where you are stuck, maybe show what you can try from here?

alpine sable
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UH

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I mean

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I did the first part

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where I express it as a rate of change

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I thik its

woeful pulsar
#

yeah okay

alpine sable
#

32 - 4/9-1

woeful pulsar
#

remember your brackets

alpine sable
#

uh ok

#

so how would u do it as an equation doe

woeful pulsar
#

so you have the equation of a line

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that's useful for things changing at a constant rate

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identify your variables

alpine sable
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uh

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y is the indepentant variable?

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._.

woeful pulsar
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y is dependent

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x is independent

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typically y depends on x

alpine sable
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Yee

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ok

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so basically

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months is the independant variable

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and

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height is the dependant variable

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so how would I put that in y=mx+b formula

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uh

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u there

alpine sable
#

Hey people! I think I can write my question if the channel is unoccupied, isn't it? Btw, sorry about my english I am Portuguese.

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Basically, the exercise is asking for the area of ​​the region defined by the given condition.

woeful pulsar
#

you found the rate of change too that's part of the formula

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just declare that x is the number of months and y is the height in cm

woeful pulsar
alpine sable
#

Yh, I did it! I just dont get how I am going to do with the area.

#

I tried to find the circular sector area, but i cant because i dont have any angle.

pearl marlin
fast musk
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I am stucked in a question on joint distribution. Anyone please help.

#

May I share?

alpine sable
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im still stuck

pearl marlin
alpine sable
pearl marlin
fast musk
alpine sable
#

But I still dont get it 😅

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how could that help me?

pearl marlin
pearl marlin
alpine sable
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thatsabout it

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I tried

pearl marlin
#

Take dg/dt= constant

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Now solve the differential equation

alpine sable
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uh

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what

pearl marlin
#

Rate of growth is conatant so

Take dg/dt= k

Solve it you will get

g=kt+c
Now use the constions to solve k and c
( Here g is growth and t is time c is conStant of integration)

alpine sable
#

uh

alpine sable
#

what is dg/dt

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uhm

pearl marlin
alpine sable
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bro I dont know why are we doing velocity

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im doing rate of change...

pearl marlin
alpine sable
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uhm

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uh

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this is the question

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uhhh

pearl marlin
alpine sable
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I thought this was slopes

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guess im in the wrong unit

ionic jewel
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your plant goes 4cm in one month right?

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so how much does it grow in two months? @alpine sable

ionic jewel
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yes

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so its rate of growth is how many cm per month?

alpine sable
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4

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uh

ionic jewel
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wait a second

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the problem looks wrong

alpine sable
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uh

ionic jewel
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because

alpine sable
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idk man im just confused here

ionic jewel
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well lets keep going

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1 month is 4cm
2mo 8cm
3 - 12
4- 16
5- 20
6- 24
7 - 28
8 - 32
9- 36

alpine sable
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ye

ionic jewel
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but the problem says its 32 after 9 thinkDerp

alpine sable
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THIS IS WHY IM CONFUSION

ionic jewel
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okay well

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lets do it the hard way

alpine sable
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damn

ionic jewel
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so our assumption was that the plant starts with 0 height

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but thats wrong (since it doesnt work out)

valid yacht
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can someone who is good with statistics help me? i am genuinely about to pass out from panicking.

ionic jewel
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so do you know how to find the slope of a line given two points?

ionic jewel
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okay

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its

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$\frac{f(b)-f(a)}{b-a}$, and before you get confused, its the change in the dependent variable divided by the change in the independent variable

ocean sealBOT
alpine sable
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uhh

ionic jewel
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in your case, growth is the dependent variable because it depends on time

alpine sable
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ok

ionic jewel
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so between 1 and 9 months, whats the change in height?

alpine sable
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uh

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4cm every month?

ionic jewel
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no

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we have determined that doesnt work out

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what is the height at one month?

alpine sable
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4cm

ionic jewel
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whats the height at 9 months?

alpine sable
#

uh

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32

ionic jewel
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so whats the change between them (the difference/distance)?

alpine sable
#

uhm

#

uh

#

uhh

ionic jewel
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no ideas?

alpine sable
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no

ionic jewel
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whats the distance between 1 and 2?

alpine sable
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uh

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wait like

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uh

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2 is an even number?

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uH

ionic jewel
alpine sable
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IDK MAN I DONT LIKE THESE RIDDLES

ionic jewel
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if i drew a line between them on the number line, how long would it be?

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its not supposed to be a riddle, means im doing a bad job showing this

alpine sable
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either ur bad at teaching or im horrible at learning

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or both

ionic jewel
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fine we can skip the intuition, but the "change" is going to be the higher number minus the lower number

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and the height goes from 4 to 32

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so whats the change in height?

alpine sable
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uhm

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4cm every month? ._.

ionic jewel
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you arent reading what i wrote

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what is the higher number minus the lower number?

alpine sable
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28

ionic jewel
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thank you

alpine sable
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im evolving

ionic jewel
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so the change in height is 28 (cm)

alpine sable
#

yes

ionic jewel
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so now what the change in time between 1 and 9?

alpine sable
#

8

ionic jewel
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fantastic

alpine sable
#

IM LEARNING

ionic jewel
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now remember, the slope (which is the growth rate in this question) is the change in height divided by the change in time

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so whats the slope?

alpine sable
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wait

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28 divide 8?

ionic jewel
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yes

alpine sable
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ok

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calculator

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give me a sec

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3.5

ionic jewel
#

The plant grows 3.5 cm/month

alpine sable
#

you sir are helpful

ionic jewel
#

notice how we did change in height (cm) divided by change in time (months) to get cm/height, which is the units you wanted

alpine sable
#

but how would I write that into an equation

ionic jewel
#

do you know how variables work?

alpine sable
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ye

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wait

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y=mx+b

ionic jewel
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okay, lets define one variable to be height, we will call it h

alpine sable
#

so

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des that mean

ionic jewel
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yes y=mx+b works too

alpine sable
#

3.5=28+8?

ionic jewel
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so where does the 3.5 fit into here?

alpine sable
#

uh

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uhhh

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wait I didnt do that right

ionic jewel
#

m = slope
b = y intercept

alpine sable
#

uh

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I remember doing this

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like

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a year ago

ionic jewel
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do you know the slope?

alpine sable
#

uh

#

3.5

ionic jewel
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yes

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so we have y = 3.5x+b, but we still need to solve for b

alpine sable
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uh

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oik

ionic jewel
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we have to use a point to solve for it

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your points are (1,4) which is 4 height at one month, and (9,32), which is 32 cm at 9 months

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you can use either to solve

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pick one and put the x and y into the equation we have

alpine sable
#

yes

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ok

#

uh

ionic jewel
#

Points are in the form (x,y)

alpine sable
#

uh

ionic jewel
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(x=1, y=4)

alpine sable
#

uh ok

#

uh

ionic jewel
#

so we have y = 3.5x+b

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we need to plug in y and x to solve for b

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what are we using for y and x?

alpine sable
#

28 and 8

ionic jewel
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i mean

alpine sable
#

uh

ionic jewel
#

that works, but its not what i was looking for

alpine sable
#

wait what were u looking for

ionic jewel
#

(x=1, y=4)

alpine sable
#

youre looking for x =1 and y=4

ionic jewel
#

sure am

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because at one months, the height is four

alpine sable
#

yes

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I am understanding

ionic jewel
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it just also happens to be true that at four months, the height is 28

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but not what i wanted

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anyways

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we have y = 3.5x+b

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can you type it out once you plug in x and y?

alpine sable
#

im still confused

ionic jewel
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what is y?

alpine sable
#

1

ionic jewel
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no

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try again

alpine sable
#

4

ionic jewel
#

there we go

alpine sable
#

yes

ionic jewel
#

so right now we have:
$$y = 3.5x+b$$
but when you plug in $y=4$, you then have
$$4 = 3.5x+b$$

ocean sealBOT
ionic jewel
#

can you do the same thing for x?

alpine sable
#

uh

#

so

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x=28

ionic jewel
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no it doesnt

alpine sable
#

so

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uh

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Idk man im losing braincells

ionic jewel
#

we have been over what x is

alpine sable
#

uh

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x is 2

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i mean 1

ionic jewel
alpine sable
#

ACCIDENT

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MISCLICK

ionic jewel
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okay

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so you can do the same thing i did

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replace x with 1 in the equation

alpine sable
#

UH

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I need more help

ionic jewel
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no you dont

alpine sable
#

on the help youre giving me

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I do

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trust me

alpine sable
#

yeah

ionic jewel
#

what did I do?

alpine sable
#

I have 0 clue

ionic jewel
#

...

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then why did you say you did

alpine sable
#

4 months the height is 28cm

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so

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Wait

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thats not right

ionic jewel
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i cant tell if you are just making things up at this point

alpine sable
#

bro I dont like math

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always have problems with the letters in this subject

ionic jewel
#

well stop thinking about plants

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we dont need em rn

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we are finding the b in this line

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the first equation has the letter y, correct?

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and the second one no longer has a y, correct?

alpine sable
#

yes

ionic jewel
#

so what did the y get replaced with?

alpine sable
#

4

ionic jewel
#

yes

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that is because y=4, so y and 4 are the same here

alpine sable
#

yes

ionic jewel
#

do you see what you can do with x here?

alpine sable
#

uh

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I dont know if im right on this

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but

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replace it with 1 🤔

ionic jewel
#

yes

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you are

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please write the equation with the 1 in it for me

alpine sable
#

4=3.5/1+b

ionic jewel
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why did you put a division sign?

alpine sable
#

uh

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i thought u ned to

ionic jewel
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you dont

alpine sable
#

oh

#

uh

#

ok

ionic jewel
#

when you see two things pushed together like mx

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it means multiplication

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m times x

alpine sable
#

oh

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ok

ionic jewel
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the symbol for multiplication between numbers is a *

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now can you rewrite your equation correctly?

alpine sable
#

4=3.5*1+b

ionic jewel
#

yes

#

now do you know how to get b by itself?

alpine sable
#

no sir

ionic jewel
#

what is 3.5*1

alpine sable
#

oh

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3.5

ionic jewel
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okay now rewrite it with that simplification please

alpine sable
#

wait so b = 3.5

ionic jewel
#

no

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4=3.5*1+b

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i was talking about this 3.5*1

alpine sable
#

oooh

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4=3.5+b

ionic jewel
#

yes

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now you can subtract 3.5 from each side to get b by itself

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can you do that?

alpine sable
#

.5=b

ionic jewel
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yep

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now we have y = mx+b, and you know that m = 3.5 and b = 0.5

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so whats the final equation?

alpine sable
#

.5=b

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is

#

final

ionic jewel
#

now we have y = mx+b, and you know that m = 3.5 and b = 0.5

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b = 0.5 is correct, but its not the full line equation

alpine sable
#

bruh

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is that not the same thing

ionic jewel
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b=0.5 is not a line

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y=mx+b is a line

alpine sable
#

._.

ionic jewel
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you were the one who mentioned y = mx+b right?

alpine sable
#

yes

ionic jewel
#

and we know what b is now right?

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whats b?

alpine sable
#

yes

#

.5

ionic jewel
#

whats m?

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(the slope)

alpine sable
#

3.5

ionic jewel
#

yes

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now can you plug those into y = mx+b?

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like how we did with x and y before

alpine sable
#

yes

ionic jewel
#

and what do you get?

alpine sable
#

uh

#

wait didnt we just do that

ionic jewel
#

you didnt even know what b was before

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now you do

alpine sable
#

uh

#

ok

ionic jewel
#

i simply dont have any more hints left

#

y = mx+b

m = 3.5
b = 0.5

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you need to put them in

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thats it

alpine sable
#

I was just confused because

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if I write it like

#

y=3.5x+.5

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is that not

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incorrect

ionic jewel
#

it is, in fact, the correct answer

alpine sable
#

how

#

what'

ionic jewel
#

we spent like the whole time solving for it

alpine sable
#

bro

#

no

#

leave

#

be gone

#

im tryna learn math here

#

@ionic jewel

ionic jewel
#

yes

alpine sable
#

continu

ionic jewel
#

you were saying what?

alpine sable
#

no distrection

ionic jewel
#

i was saying it was right

#

what it means

alpine sable
#

just confused because if I write it like tat

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isnt it wrong?

ionic jewel
#

is that the plant grows at 3.5 cm per month, and it started at 0.5 cm

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thats what the m and b mean

ionic jewel
alpine sable
#

but the way u write it

#

y=3.5x+.5

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isnt it written

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incorrectly

ionic jewel
#

in what way?

alpine sable
#

uh

#

im just not going to question your ways

#

continue

ionic jewel
#

theres nothing else

alpine sable
#

oh

#

ok

#

wait

#

then im done

ionic jewel
#

for the record, if you come back for help

  1. if you dont know something, just say that, dont say you know and not know
  2. feel free to try even if you are wrong, people can correct you
#

somewhat frustrating because of those

alpine sable
#

I always askq uestions in class

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and look like an idiot

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one time I asked what the opposite of square root is...

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._.

ionic jewel
#

oh well

#

asking question is how you learn

alpine sable
#

I got like a 55 in math

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so I decided to do summeer schol

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ok

#

fr

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im tired

#

also

#

Keep grinding

#

Don’t give up

alpine sable
#

ok

#

goodnight

ionic jewel
#

post a plaintext or latex of your question

alpine sable
#

U have to send the problem so the helpers can help lol

ionic jewel
#

sorry, not accepting friend requests

alpine sable
#

NOOOOOOOOO

#

U were like the only helpful person

tough hatch
alpine sable
#

I had 94 strokes reading this

#

14

ionic jewel
#

you know you arent a very good troll

alpine sable
#

LOOOOOOOOOOOOOO

alpine sable
ionic jewel
#

he likes 6/15 of the activies and 2/3 teams

#

the chance of both is multiplication

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P(A intersect B) = P(A)P(B) // given they are independent

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6/15*2/3

alpine sable
ionic jewel
#

simplify it

alpine sable
#

4/15

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alr ty

grim shadow
#

what r yall discussing???

#

ok so a troll

tall wing
#

yes, you

#

quit trolling

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ok

#

you have no good history here

#

goodbye

#

kicked

#

wait i guess not

#

what

#

i just did

#

why is it not working

tame falcon
#

Gottem

grim shadow
#

is there a MATH question u guys r discussing?????

#

mb i can help

#

guys???

harsh salmon
#

Hi how do you do question d)? Answer book says 0.02950 but idk how they got that? It might use combination math. thank u!

#

(The total number of students is 569)

rich basin
#

so imade this into sinx(1-cosx)^-1

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i made u = 1-cosx

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and what i got finally is du(u)^-1

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But i don't know how to change this back

topaz scaffold
#

Integrate first

#

Then change it back

pearl marlin
vale wigeon
#

int du/u is one of the easiest integrals to solve if you know a thing or two about logarithms

rich basin
#

@vale wigeon I know about natural logs, how would we change this into natural logs?

vale wigeon
#

my friend

#

literally

#

$\int \frac{\dd{u}}{u} = \log |u| + C$

ocean sealBOT
rich basin
#

oh yes, that is what the differention of log looks like

tough hatch
#

just remember your substitution

rich basin
#

what about for this one?

#

wouldn't this be 1/ log(cos) + C

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if you were to make u = cos

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wait nevermind

grim shadow
#

what??

rich basin
#

you suppose to make u be sinx

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and the when you find du/dx it would be = cosx

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i was thinking of the antiderivative

tough hatch
#

same principle.

rich basin
#

what happens if you get something like u * du

tough hatch
#

oh right

rich basin
#

@tough hatch what happens if i have u *du

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if u = 2x^2 + 4

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wouldn't i just make it 1/u * du

topaz scaffold
#

Where did the 4 come from?

rich basin
#

just a made up

topaz scaffold
#

Oh

rich basin
#

would i just make it 1/u

tough hatch
#

actually

#

ur u-sub is good

rich basin
#

which would just be 1/2x^2 +4

tough hatch
#

but

tough hatch
topaz scaffold
rich basin
#

yeah and then du/dx would be 4x

tough hatch
rich basin
#

and then du = 4x where the dx is cancel out

topaz scaffold
#

du = 4x dx

rich basin
#

so it would be like 4x/ log(1 / (2x^2 +4) )

topaz scaffold
#

I'm lost

#

What are you even subbing here?

rich basin
#

so there is u * du

tough hatch
#

i assume this is different from the (cos x)/(sin x) integrand

rich basin
#

and i want to make it like du/ u

#

yeah they are differnet

tough hatch
#

can you just tell us the actual integral

topaz scaffold
#

You want to make u du into du /u?

tough hatch
topaz scaffold
#

But why

topaz scaffold
#

∫u du is simple enough

tough hatch
#

there's no point in "converting"

tough hatch
rich basin
topaz scaffold
#

I'm agreeing that it's not possible 😅

rich basin
#

lets just make it this one

topaz scaffold
grim shadow
strong furnace
#

||easiest way of integration , look at the answer and u-sub the answer 😉||

topaz scaffold
#

Let u be the entire integral

grim shadow
strong furnace
grim shadow
topaz scaffold
#

Don't worry, multiple choice questions are easy

somber folio
#

hello

topaz scaffold
#

Just add in: e. one of the above

somber folio
#

is anyone free?

somber folio
#

if not I can wait

velvet condor
#

is this channel in use

fringe yoke
topaz scaffold
topaz scaffold
#

...

grim shadow
#

ikr

velvet condor
#

so thats a no?

grim shadow
velvet condor
#

prove that
$\sum_{cyc}{\sqrt{\frac{a}{b+c}+\frac{b}{c+a}}}\ge 3 ~\forall a,b,c>0$

ocean sealBOT
#

Minh Baka

somber folio
#

oh my

grim shadow
velvet condor
#

u mean am-gm?

grim shadow
#

nope

velvet condor
#

bunyakovsky?

#

jensen?

#

holder?

grim shadow
#

wait

grim shadow
somber folio
#

hey man you good at probabilities? @grim shadow

somber folio
#

alrighty so

#

let's say I have 10 objects

#

and the one I want has a 4.7% chance of acquiring it

#

if that's done 20 times

#

what's the likelihood of getting that one object

#

after 20 attempts

#

I hope that makes sense

grim shadow
#

so u want that obj at the 20th attempt??

somber folio
#

At least once

#

yeah

#

not just the 20th attempt

#

hopefully it makes more sense now

grim shadow
#

okay so, probability= 1- (not getting obj in all 20 attempts)

somber folio
#

mhm

grim shadow
#

so, its 1-(95.3/100)^20

somber folio
#

oh

#

mfw binomial

#

I am stupid

#

ty

grim shadow
#

np

alpine sable
#

hey i'm having a bit of of trouble solving this system of linear equations here

#

im not exactly sure if its solvable or if there are infinite solutions or what

novel siren
#

you have a system of 2 equations with 3 unknowns so there are infinite solutions

#

z isn't 1

alpine sable
#

how exactly would i express that for x and y here? Sorry if it's an asinine question im really tired and i want to go to bed

novel siren
#

just replace z with t

#

x = 5 - t
y = 1 - t
z = t

tired hamlet
#

How would I set up this problem?

rigid smelt
#

what have you tried?

tough hatch
topaz scaffold
#

Hey hey hey that kinda looks like a canvas quiz

brave cairn
#

is this false?

alpine sable
#

yes, that's false.

tired hamlet
brave cairn
topaz scaffold
#

Good good

topaz scaffold
#

It should be $log_a(b^3c)$

ocean sealBOT
#

RipeOrange

alpine sable
ocean sealBOT
#

Al𝟛dium

brave cairn
#

ah

alpine sable
#

since you can factor out a 3, and apply the log property correctly: $$3(\overbrace{\log_a(b)+\log_a(c)}^{\log(x)+\log(y)=\log(xy)})$$ $$3\log_a(ab)$$

ocean sealBOT
#

Al𝟛dium

alpine sable
#

does this make sense?

brave cairn
#

yeah

#

thanks

alpine sable
#

yw

tired hamlet
#

Is this right?

topaz scaffold
#

Yes

smoky harness
#

1 -454 85767 -8629870 487791388 -14685529320 183977791200

tired hamlet
#

How would I simplify it?

bold mist
#

First multiply!

#

mmmmmmmultiply

#

Or not. Multiplying first is probably a bad idea.

#

But you could. I would.

#

Is this helping?

tired hamlet
#

I got this but don’t know where to go from here

bold mist
#

Good, good

#

Now those 12s look suspicious to me.

pearl marlin
bold mist
#

And that 36, frankly.

tired hamlet
pearl marlin
#

that 12 from denominator $\frac{12.(y-1)}{12}$

bold mist
#

Oh right, the guy that said you were correct

#

Was lying

#

I should have checked haha

#

This learn4math fellow seems to know what he's talking about

ocean sealBOT
#

learn4math

dry thunder
#

its 12y-12/12

#

idk what exactly ur asking for

#

but ye

pearl marlin
bold mist
#

Seems like (12y-12)/12 could be made simpler

#

Lots of 12s

dry thunder
#

yes you can cancel the 12

#

it is an expression

#

nothing really to solve only simplification required

grim shadow
#

??

teal epoch
#

Quick Question: What's the difference between $\pm$ and $\mp$? What are their uses?

alpine sable
#

sorry

ocean sealBOT
#

Nonexisty

rigid smelt
#

need more context

ocean sealBOT
alpine sable
#

If it stands alone i'm pretty sure they mean the same thing

ocean sealBOT
#

Nonexisty

#

Nonexisty

grim shadow
tough hatch
alpine sable
#

yeah thats what i mean't by stand alone

#

guys how to do b2

tough hatch
#

b2?

#

not a2?

alpine sable
#

ya a sry

#

?

tough hatch
#

the third bullet refers to $P((G\cup D)')$

ocean sealBOT
alpine sable
#

tq

tough hatch
#

do u see where to put the four people in this category?

#

on the Venn diagram?

alpine sable
#

ye outside right?

ocean sealBOT
tough hatch
#

so yes

ocean sealBOT
tough hatch
#

oops, mb

#

mistakenly thought of this as probability

ocean sealBOT
tough hatch
ocean sealBOT
tough hatch
#

moreover G=28 and D=13

#

do u now know what to do with these @alpine sable?

alpine sable
#

yup

thorn kindle
#

Get GUD

exotic marten
#

catus

#

amogus

lapis panther
#

Rational numbers are commutative for___________

#

can somone tell

tough hatch
#

that sounds so wrong

pearl marlin
ionic jewel
#

it was answered in another channel

#

i doubt he knows what commutative means

tough hatch
#

still sounds wrong

#

if its a question they're answering the question is worded wrong

alpine sable
pearl marlin
#

Make it like 3/4(2x+7)^(-9) now solve

ionic jewel
alpine sable
#

:((

ionic jewel
#

maybe look into the python library 3b1b made

#

he does math animations

strong furnace
quaint pond
#

hey guys so I have problem understanding something

#

basically if we have the word error and if we wanted to find all the different ways we can order the letters

#

We would do 7!/3! because there are 3 ways the 3 r's can be arranged

#

I know its so but i dont get why

#

like i know it works but just dont understand why doesn't it work if we were to subtract them

#

why divide?

ionic jewel
#

subtracting makes no sense

#

also isn't it 5!/3!

#

it's dividing because for each of the 5! permutations, there's 3! ways to do the r's

quaint pond
#

Yeah sorry

#

I can't count

gritty cave
#

could someone explain where the -3x^2 + bx^2 came from

minor heath
#

hence the equation -3x^2+bx^2=-7x^2 (the only term with x^2 in the lhs)

gritty cave
#

thank you

minor heath
#

no worries

lost cairn
#

After a decrease of 35%, a number becomes 700. Find the original number.

smoky harness
alpine sable
#

is it free now

#

?

hasty nacelle
#

@alpine sable what is free?

alpine sable
#

i mean no one is clearing there confusion here right now? right

jagged imp
#

channel does seem free

#

the other person(fear) posted in like 3 channels

#

so they have plenty for themself

alpine sable
#

i have a little confusion i wanna clear

grim shadow
#

tell

alpine sable
#

when we do subtraction on algebraic expressions why we have to specially put subtraction sign?
and not with when we do addition?

#

kinda confuse in this concept rn even if its basic

alpine sable
ocean sealBOT
grim shadow
#

ok so the thing is plus sign doesn't change much

#

even if we dont put it wont change anything

#

while minus means sign revelsal

#

*reversal

alpine sable
#

okay if we put the addition sign same like how we do on subtraction it will give same answers right

#

cause i never did that way

grim shadow
#

yep but we are just too lazy to do that

#

algebra will never fail u if u go according to the rules

alpine sable
#

yay thanks for making it a clear to me

grim shadow
#

np

proud sentinel
#

Negation of the statement "There are integers a and b such that every composite number is divisible by either a or b" is: ∀ a,b ∈ Z, ∃ n ∈ C, ¬ a|n ∧ ¬ b|n

#

can anyone help me with this question

#

that is it true or false

grim shadow
#

so u want the negation of this statement

proud sentinel
#

actually this is the whole question
and it was asked that is it true or false

#

the answer is true, but I cant exactly understand how is it happening

grim shadow
#

bro i dont know what those notations mean

proud sentinel
#

its a question from proposition logic

#

a|n means a divides n

grim shadow
#

and that reverse capital E

proud sentinel
#

it stands for "there exists a"

#

I think you are not aware of this topic, no worries

grim shadow
#

i am actually but we dont use these symbols in my country

proud sentinel
#

Actually I am also reading a book from foriegn autthor

#

and I myself get afraid of these symbols

#

😆

grim shadow
#

xd

#

well i understood the question

#

look

proud sentinel
#

okay, so let me simplify the question for you,

Find Negation of the statement "There are integers a and b such that every composite number is divisible by either a or b".

proud sentinel
grim shadow
#

it says a and b are integers, there exits n belonging to composite no., such that a divides n and b divides n.

proud sentinel
grim shadow
#

ya its the negation of the statement

proud sentinel
#

but I am not sure of how to represent its negation

#

in symbols

grim shadow
#

well representing the 'and' sign, its true when bot inputs are true

jagged imp
#

you can use $\nmid$ to make "does not divide" look a little simpler ig

ocean sealBOT
#

Sneaky

grim shadow
#

but in the given statement its given 'either or'

#

so they cant divide both divide n at the same time

proud sentinel
proud sentinel
grim shadow
#

wait

#

i messed up

smoky harness
#

hey can i ake this channel

#

take

grim shadow
#

last statement cant be true unless both a and b divide n

#

which is a contradiction to statement (given), since only one of them can divide n

#

either a or b

proud sentinel
#

So as far I am clear in given statement, it says either divisible by a or b

#

so in negation it will be that neither by a not by b

#

right?

jagged imp
#

yes

placid trellis
#

i need help

#

with math

grim shadow
#

wait thats true but in negation given, for it to be true both a and b should divide n

jagged imp
grim shadow
#

now even im confused

ocean sealBOT
#

Sneaky

proud sentinel
grim shadow
#

thats why its negation

proud sentinel
grim shadow
#

got it??

proud sentinel
#

okay, thats now clear I think

#

there was one more

#

which is really headache

#

∀x : x^2 > 2

#

its negation

#

I am not sure why is it wrong

grim shadow
#

yep it can be equal too

#

negation of 'greater' is 'lesser or equal'

proud sentinel
#

so means we can not write NOT(x^2>2)

grim shadow
#

like negation of positive is non-negative

grim shadow
proud sentinel
#

to get an idea

grim shadow
#

wait

woeful pulsar
#

the negation of the statement "for all t, t<1" is?

proud sentinel
#

(x^2<2) OR (x^2=2)

#

it it that?

grim shadow
#

t>1 or t=1

woeful pulsar
#

hmm wait a minute doesn't for all need to become there exists?

proud sentinel
grim shadow
#

yep def

woeful pulsar
#

i don't think that's right

#

because there's a "for all"

#

you need to change it to "there exists"

#

that's the other issue with that statement

grim shadow
#

oh did not see that

proud sentinel
#

but here I am a bit confused,
why (x^2<2) OR (x^2=2) is different from NOT(x^2>2)?

jagged imp
#

its not

grim shadow
#

coz not is a negation

jagged imp
#

the statement in the question isnt x^2>2

woeful pulsar
#

yeah so the problem is not that less or equal thing

jagged imp
#

the statement has the universal quantifier in it'

woeful pulsar
#

the problem is that it forgot to convert to there exists

jagged imp
#

you've kinda ignored it

proud sentinel
#

I think I missed studying this topic

#

😭

grim shadow
#

wait wait

#

not converts positive to negative right??

proud sentinel
grim shadow
#

ya if its that then its not right

proud sentinel
#

okayy

grim shadow
#

coz the actual negation of positve is non-positive

proud sentinel
jagged imp
#

i know this and i have no idea what weeb is talking about if it helps. You had done the first problem with divisibility pretty well so it doesnt seem like you were lacking knowledge there

#

Like me and element said, this problem just seems like you didn't register the for all symbol when you were negating

grim shadow
#

i myself am confused

#

i dont know the symbols

proud sentinel
#

this seems true

#

XD

grim shadow
#

ya but the thing that element118 dude said is correct

#

negation of for all is there exists

proud sentinel
proud sentinel
#

I think it like that

grim shadow
#

yep true

#

i was thinkin wrong, actually we do not use NOT in my country

#

so mb i didnt get the question

proud sentinel
#

or many write it as x' , NOT(x) , ~x , etc

grim shadow
proud sentinel
grim shadow
#

ya coz we dont use that here lol

proud sentinel
#

all it is the game of symbols

#

XD

proud sentinel
grim shadow
#

yep symbols are confusing

#

ohhhhhhhhh

proud sentinel
grim shadow
#

damnnnnnnnn

proud sentinel
#

so definitely, everyone has diffennt terms

#

for their writing

grim shadow
#

ur in college???

proud sentinel
grim shadow
#

oh wow im in HS

proud sentinel
#

thats why studying maths

proud sentinel
#

this is my first semster

grim shadow
#

ohh so ur like 4-5 ahead of me coz im also about to go to college

smoky harness
#

1 -454 85767 -8629870 487791388 -14685529320 183977791200
(transcript)
Hints from creator:
"you see the one at the beginning?"
"it's in it's normal form"

smoky harness
#

Cryptograph, anyone got an idea?

grim shadow
#

nope

smoky harness
#

in its first form

proud sentinel
#

I am just doing it

#

beginner

smoky harness
#

its question 278/300

#

after maths IV

#

in our challenge

proud sentinel
smoky harness
#

idk it has physsics

proud sentinel
#

I have probability and Discrete in college

#

I am computer science student

smoky harness
#

Wow

proud sentinel
#

Next year there will be differential equations

#

I am afraid beacuse I have forgotten it all

#

from my school time

alpine sable
#

anyone able to explain this to me? i am doing the dervative and im just getting x^-1/2

rigid smelt
#

can you show your work?

tough hatch
#

and the derivative of 3x/2 cancelled out with the original exponent

#

@alpine sable

alpine sable
#

That's what I've tried so far essentially

rigid smelt
#

your work hardly makes any sense

tough hatch
#

nope

#

derivative of 3x/2 is not 3x/2

#

where did the exponent go???

alpine sable
#

you know im asking a question because i dont understand what im doing. so its no big suprise my work doesnt make any sense

#

i took the 2/3 that is the exponet and i multiplied it by 3/2x

ocean sealBOT
alpine sable
#

yes i got the negative 1/3

ocean sealBOT
tough hatch
#

and n=2/3

#

after that multiply to it the derivative of 3x/2

ocean sealBOT
tough hatch
#

for any constant a

#

do u follow @alpine sable

alpine sable
#

yes since x is 3x/2 you multiply it by 2/3 since thats the exponenet or n

#

its no different than getting the dervative of 2x^2 which is 4x?

#

or am i missing something?

tough hatch
#

no u don't multiply 3x/2 by 2/3

#

3x/2 is not the derivative of 3x/2

#

3x/2 = (3/2)x

alpine sable
#

well the derv of (3/2)x is just 3/2

tough hatch
#

wat

ocean sealBOT
tough hatch
#

multiply that

#

to

#

the "outer" derivative of ((3/2)x)^(2/3)

alpine sable
#

thats the -1/3 right?

tough hatch
#

yep

alpine sable
#

why dont you multiply the exponent by the fraction)

#

you do it with 2x^2

#

but not with this, this makes no sense to me

ocean sealBOT
alpine sable
#

thats what i did, and i got 6/6

#

ah i see im dumb

#

i need to multiply out by x as well

#

you can write that as (2/3((2/3)*x) so it is 1 * (3/2)*x

tough hatch
#

yep, with the appropriate exponent.

alpine sable
#

yeah im stupid. i was doing the calculus rightbut screwing up the algebra

#

typical of me! thanks!

harsh swallow
#

Hi

#

If i pick a number between 0 and 1

#

say 31/985

#

the amount of numbers between 0 and it is the same as the amount of numbers between it and 1, right?

#

is that correct?