#help-0
1 messages · Page 713 of 1
so it would be 1/3 * (3x+1)^7?
1/3 • ∫u^7 ?
missing the differential
Well he's not wrong if he put a du at the end
Check if a channel is occupied man please
why what he did is allowed, whcih is similar to what i did to my question
It's just strategically substituting things
To simplify the integral
not sure where you are stuck, can you show what you understand?
so basically
uh
nothing
im confusion
okay so just before this you probably were taught the equation of a line, right?
yeah something like that
so y is the dependent variable and x is the independent variable
ok
equation of a line is used to show relationships where something changes at a constant rate
idk where you are stuck, maybe show what you can try from here?
UH
I mean
I did the first part
where I express it as a rate of change
I thik its
yeah okay
32 - 4/9-1
remember your brackets
so you have the equation of a line
that's useful for things changing at a constant rate
identify your variables
Yee
ok
so basically
months is the independant variable
and
height is the dependant variable
so how would I put that in y=mx+b formula
uh
u there
Hey people! I think I can write my question if the channel is unoccupied, isn't it? Btw, sorry about my english I am Portuguese.
Basically, the exercise is asking for the area of the region defined by the given condition.
yeah that's one way to put it
you found the rate of change too that's part of the formula
just declare that x is the number of months and y is the height in cm
hmm maybe sketch it on the complex plane
Yh, I did it! I just dont get how I am going to do with the area.
I tried to find the circular sector area, but i cant because i dont have any angle.
Can you make that complex form in cartision form?
Ok he is using trick
Even if I do that, how would that help me?
There is a square in the circle you see
Ahhh I see
But I still dont get it 😅
how could that help me?
See total area - sqare area will give you those 4 parts area them he divided them with 4 , you will get area you required
What you have tried?
Rate of growth is conatant so
Take dg/dt= k
Solve it you will get
g=kt+c
Now use the constions to solve k and c
( Here g is growth and t is time c is conStant of integration)
uh
Omg, I think I got it! Im going to try myself on paper. Thank you!!!
what is dg/dt
uhm
Hmm okk , velocity is rate of change of distance ,and how you write the velocity?
Rate of change means d/dt( derivative wrt time)
Wait for someone will explain in simple language
it is
your plant goes 4cm in one month right?
so how much does it grow in two months? @alpine sable
uh
because
idk man im just confused here
well lets keep going
1 month is 4cm
2mo 8cm
3 - 12
4- 16
5- 20
6- 24
7 - 28
8 - 32
9- 36
ye
but the problem says its 32 after 9 
THIS IS WHY IM CONFUSION
damn
so our assumption was that the plant starts with 0 height
but thats wrong (since it doesnt work out)
can someone who is good with statistics help me? i am genuinely about to pass out from panicking.
so do you know how to find the slope of a line given two points?
uh
I mean
no
okay
its
$\frac{f(b)-f(a)}{b-a}$, and before you get confused, its the change in the dependent variable divided by the change in the independent variable
bunny
uhh
in your case, growth is the dependent variable because it depends on time
ok
so between 1 and 9 months, whats the change in height?
4cm
whats the height at 9 months?
so whats the change between them (the difference/distance)?
no ideas?
no
whats the distance between 1 and 2?

IDK MAN I DONT LIKE THESE RIDDLES
if i drew a line between them on the number line, how long would it be?
its not supposed to be a riddle, means im doing a bad job showing this
fine we can skip the intuition, but the "change" is going to be the higher number minus the lower number
and the height goes from 4 to 32
so whats the change in height?
28
thank you
im evolving
so the change in height is 28 (cm)
yes
so now what the change in time between 1 and 9?
8
fantastic
IM LEARNING
now remember, the slope (which is the growth rate in this question) is the change in height divided by the change in time
so whats the slope?
yes
The plant grows 3.5 cm/month
you sir are helpful
notice how we did change in height (cm) divided by change in time (months) to get cm/height, which is the units you wanted
do you know how variables work?
okay, lets define one variable to be height, we will call it h
yes y=mx+b works too
3.5=28+8?
so where does the 3.5 fit into here?
m = slope
b = y intercept
do you know the slope?
we have to use a point to solve for it
your points are (1,4) which is 4 height at one month, and (9,32), which is 32 cm at 9 months
you can use either to solve
pick one and put the x and y into the equation we have
Points are in the form (x,y)
uh
(x=1, y=4)
so we have y = 3.5x+b
we need to plug in y and x to solve for b
what are we using for y and x?
28 and 8
i mean
uh
that works, but its not what i was looking for
wait what were u looking for
(x=1, y=4)
youre looking for x =1 and y=4
it just also happens to be true that at four months, the height is 28
but not what i wanted
anyways
we have y = 3.5x+b
can you type it out once you plug in x and y?
im still confused
what is y?
1
4
there we go
yes
so right now we have:
$$y = 3.5x+b$$
but when you plug in $y=4$, you then have
$$4 = 3.5x+b$$
bunny
can you do the same thing for x?
no it doesnt

no you dont
yeah
what did I do?
I have 0 clue
i cant tell if you are just making things up at this point
well stop thinking about plants
we dont need em rn
we are finding the b in this line
the first equation has the letter y, correct?
and the second one no longer has a y, correct?
yes
so what did the y get replaced with?
4
yes
do you see what you can do with x here?
4=3.5/1+b
why did you put a division sign?
you dont
the symbol for multiplication between numbers is a *
now can you rewrite your equation correctly?
4=3.5*1+b
no sir
what is 3.5*1
okay now rewrite it with that simplification please
wait so b = 3.5
.5=b
yep
now we have y = mx+b, and you know that m = 3.5 and b = 0.5
so whats the final equation?
now we have y = mx+b, and you know that m = 3.5 and b = 0.5
b = 0.5 is correct, but its not the full line equation
._.
you were the one who mentioned y = mx+b right?
yes
3.5
yes
and what do you get?
i simply dont have any more hints left
y = mx+b
m = 3.5
b = 0.5
you need to put them in
thats it
I was just confused because
if I write it like
y=3.5x+.5
is that not
incorrect
it is, in fact, the correct answer
we spent like the whole time solving for it
yes
continu
you were saying what?
no distrection
is that the plant grows at 3.5 cm per month, and it started at 0.5 cm
thats what the m and b mean
why do you think its wrong?
in what way?
theres nothing else
for the record, if you come back for help
- if you dont know something, just say that, dont say you know and not know
- feel free to try even if you are wrong, people can correct you
somewhat frustrating because of those
I always askq uestions in class
and look like an idiot
one time I asked what the opposite of square root is...
._.
I got like a 55 in math
so I decided to do summeer schol
ok
fr
im tired
also
Keep grinding
Don’t give up
post a plaintext or latex of your question
U have to send the problem so the helpers can help lol
also accept my friend request please
sorry, not accepting friend requests

you know you arent a very good troll
LOOOOOOOOOOOOOO
@ionic jewel
he likes 6/15 of the activies and 2/3 teams
the chance of both is multiplication
P(A intersect B) = P(A)P(B) // given they are independent
6/15*2/3
12/45
simplify it
yes, you
quit trolling
ok
you have no good history here
goodbye
kicked
wait i guess not
what
i just did
why is it not working

Gottem
Hi how do you do question d)? Answer book says 0.02950 but idk how they got that? It might use combination math. thank u!
(The total number of students is 569)
so imade this into sinx(1-cosx)^-1
i made u = 1-cosx
and what i got finally is du(u)^-1
But i don't know how to change this back
use f'(x)/f(X) integraion
int du/u is one of the easiest integrals to solve if you know a thing or two about logarithms
@vale wigeon I know about natural logs, how would we change this into natural logs?
Ann
oh yes, that is what the differention of log looks like
just remember your substitution
what about for this one?
wouldn't this be 1/ log(cos) + C
if you were to make u = cos
wait nevermind
what??
you suppose to make u be sinx
and the when you find du/dx it would be = cosx
i was thinking of the antiderivative
same principle.
what happens if you get something like u * du
oh right
@tough hatch what happens if i have u *du
if u = 2x^2 + 4
wouldn't i just make it 1/u * du
Where did the 4 come from?
just a made up
Oh
would i just make it 1/u
which would just be 1/2x^2 +4
but
no
Differentiate u dude
yeah and then du/dx would be 4x
this would be the case if u=cos x
and then du = 4x where the dx is cancel out
du = 4x dx
so it would be like 4x/ log(1 / (2x^2 +4) )
so there is u * du
i assume this is different from the (cos x)/(sin x) integrand
can you just tell us the actual integral
You want to make u du into du /u?
not possible
But why
there's no point in "converting"
it's possible to convert udu to du/u?
I'm agreeing that it's not possible 😅
lets just make it this one
Probably use by parts
ez
||easiest way of integration , look at the answer and u-sub the answer 😉||
Let u be the entire integral
wow but you'll be in a pinch if its subjective test
I never said u-sub the options
ohhh then ur ans is legendary
Don't worry, multiple choice questions are easy
hello
Just add in: e. one of the above
is anyone free?
nope
if not I can wait
is this channel in use

It was for a joke...
ikr
so thats a no?
ask
prove that
$\sum_{cyc}{\sqrt{\frac{a}{b+c}+\frac{b}{c+a}}}\ge 3 ~\forall a,b,c>0$
Minh Baka
oh my
theres some inequality of which i forgot the name
u mean am-gm?
nope
wait
sorry bro didnt got anything, im pretty bad at these inequality
i'll try
alrighty so
let's say I have 10 objects
and the one I want has a 4.7% chance of acquiring it
if that's done 20 times
what's the likelihood of getting that one object
after 20 attempts
I hope that makes sense

so u want that obj at the 20th attempt??
At least once
yeah
not just the 20th attempt
hopefully it makes more sense now

okay so, probability= 1- (not getting obj in all 20 attempts)
mhm
so, its 1-(95.3/100)^20
np
hey i'm having a bit of of trouble solving this system of linear equations here
im not exactly sure if its solvable or if there are infinite solutions or what
you have a system of 2 equations with 3 unknowns so there are infinite solutions
z isn't 1
how exactly would i express that for x and y here? Sorry if it's an asinine question im really tired and i want to go to bed
this was fine for x and y
just replace z with t
x = 5 - t
y = 1 - t
z = t
How would I set up this problem?
what have you tried?
simply isolate y on one side
Hey hey hey that kinda looks like a canvas quiz
is this false?
yes, that's false.
It’s not, just practice problems
because the first log is multiplied by 3 right
Good good
Yep
It should be $log_a(b^3c)$
RipeOrange
well, yeah, what would instead be true is that $\3\log_a(b)+{\color{green}{3}}\log_a(c)=3\log_a(bc)$.
Al𝟛dium
ah
since you can factor out a 3, and apply the log property correctly: $$3(\overbrace{\log_a(b)+\log_a(c)}^{\log(x)+\log(y)=\log(xy)})$$ $$3\log_a(ab)$$
Al𝟛dium
does this make sense?
yw
Is this right?
Yes
1 -454 85767 -8629870 487791388 -14685529320 183977791200
How would I simplify it?
First multiply!
mmmmmmmultiply
Or not. Multiplying first is probably a bad idea.
But you could. I would.
Is this helping?
I got this but don’t know where to go from here
where that 12 from deno in right side?
And that 36, frankly.
?
that 12 from denominator $\frac{12.(y-1)}{12}$
Oh right, the guy that said you were correct
Was lying
I should have checked haha
This learn4math fellow seems to know what he's talking about
learn4math
just cancle the 12 out , otherwise it will be complicated
yep
yes you can cancel the 12
it is an expression
nothing really to solve only simplification required
??
Quick Question: What's the difference between $\pm$ and $\mp$? What are their uses?
sorry
Nonexisty
need more context
,, a\pm b = -(a\mp b)
If it stands alone i'm pretty sure they mean the same thing
yep
if they are not used in the same sentence, probably
the third bullet refers to $P((G\cup D)')$
tq
ye outside right?
so yes
and this is just $(G\cup D)'$
yup
Get GUD
that sounds so wrong
not geting the question but , rational numbers are commutative under + and multiply
Guys so I want to buy either maple or mathematica's license, but all I want to do using it is animations in mathematics like this one can anyone help me which of maple and mathematica lets user to make animations like this one or if you guys know any other software then please tell me
I want to make something like this
https://images-ext-1.discordapp.net/external/H_muHAKnvlJBJirXTktVUJLTNo4X_OM8eLrYe9Fp7gs/https/upload.wikimedia.org/wikipedia/commons/4/42/Line_integral_of_scalar_field.gif
Make it like 3/4(2x+7)^(-9) now solve
I'm not sure either tool can do that, I'm willing to bet that was hand animated
:((
You can ask in one of the channels dedicated for software or discussion will probably be of more help
where are they?
oh gotcha
thanks
hey guys so I have problem understanding something
basically if we have the word error and if we wanted to find all the different ways we can order the letters
We would do 7!/3! because there are 3 ways the 3 r's can be arranged
I know its so but i dont get why
like i know it works but just dont understand why doesn't it work if we were to subtract them
why divide?
subtracting makes no sense
also isn't it 5!/3!
it's dividing because for each of the 5! permutations, there's 3! ways to do the r's
could someone explain where the -3x^2 + bx^2 came from
only way you can get terms with x^2 in it are -3(x^2) and bx(x) from the rhs
hence the equation -3x^2+bx^2=-7x^2 (the only term with x^2 in the lhs)
thank you
no worries
After a decrease of 35%, a number becomes 700. Find the original number.
@alpine sable what is free?
i mean no one is clearing there confusion here right now? right
channel does seem free
the other person(fear) posted in like 3 channels
so they have plenty for themself
i have a little confusion i wanna clear
tell
when we do subtraction on algebraic expressions why we have to specially put subtraction sign?
and not with when we do addition?
kinda confuse in this concept rn even if its basic
,rotate
ok so the thing is plus sign doesn't change much
even if we dont put it wont change anything
while minus means sign revelsal
*reversal
okay if we put the addition sign same like how we do on subtraction it will give same answers right
cause i never did that way
yep but we are just too lazy to do that
algebra will never fail u if u go according to the rules
yay thanks for making it a clear to me
np
Negation of the statement "There are integers a and b such that every composite number is divisible by either a or b" is: ∀ a,b ∈ Z, ∃ n ∈ C, ¬ a|n ∧ ¬ b|n
can anyone help me with this question
that is it true or false
so u want the negation of this statement
actually this is the whole question
and it was asked that is it true or false
the answer is true, but I cant exactly understand how is it happening
bro i dont know what those notations mean
and that reverse capital E
it stands for "there exists a"
I think you are not aware of this topic, no worries
i am actually but we dont use these symbols in my country
Actually I am also reading a book from foriegn autthor
and I myself get afraid of these symbols
😆
okay, so let me simplify the question for you,
Find Negation of the statement "There are integers a and b such that every composite number is divisible by either a or b".
this looks good to me
😉
it says a and b are integers, there exits n belonging to composite no., such that a divides n and b divides n.
ya ya, that much is clear
ya its the negation of the statement
well representing the 'and' sign, its true when bot inputs are true
you can use $\nmid$ to make "does not divide" look a little simpler ig
Sneaky
but in the given statement its given 'either or'
so they cant divide both divide n at the same time
thats right, but I think I should prefer using that ¬ symbol otherwise my professor will deduct marks
oh 🤔
last statement cant be true unless both a and b divide n
which is a contradiction to statement (given), since only one of them can divide n
either a or b
So as far I am clear in given statement, it says either divisible by a or b
so in negation it will be that neither by a not by b
right?
yes
wait thats true but in negation given, for it to be true both a and b should divide n
its one of demorgan's laws. $\neg(P \lor Q)= \neg P \land \neg Q$
now even im confused
Sneaky
why both a and b should device n,
actually it is given that either of them divide
thats why its negation
woah, I just figured out it 😆
got it??
okay, thats now clear I think
there was one more
which is really headache
∀x : x^2 > 2
its negation
I am not sure why is it wrong
so means we can not write NOT(x^2>2)
like negation of positive is non-negative
nope x=sqrt(2) will also come
I am a little bit confused,
can you tell me how the correct statement looks like
to get an idea
wait
the negation of the statement "for all t, t<1" is?
t>1 or t=1
hmm wait a minute doesn't for all need to become there exists?
is it right?
yep def
i don't think that's right
because there's a "for all"
you need to change it to "there exists"
that's the other issue with that statement
oh did not see that
but here I am a bit confused,
why (x^2<2) OR (x^2=2) is different from NOT(x^2>2)?
its not
coz not is a negation
the statement in the question isnt x^2>2
yeah so the problem is not that less or equal thing
the statement has the universal quantifier in it'
the problem is that it forgot to convert to there exists
you've kinda ignored it
ohh!!
I think I missed studying this topic
😭
I think that's right 🤔
ya if its that then its not right
okayy
coz the actual negation of positve is non-positive
I think I should whole propostion logic again, more carefully
i know this and i have no idea what weeb is talking about if it helps. You had done the first problem with divisibility pretty well so it doesnt seem like you were lacking knowledge there
Like me and element said, this problem just seems like you didn't register the for all symbol when you were negating
ya but the thing that element118 dude said is correct
negation of for all is there exists
okayy, got that
because if something is true for all, and we just come and say that (there Exists) it is not true for one case, it means its false
I think it like that
yep true
i was thinkin wrong, actually we do not use NOT in my country
so mb i didnt get the question
not is just the negation I think
or many write it as x' , NOT(x) , ~x , etc
well if NOT(x)=-x then what i was sayin is correct....
oh, I think you are confused with these symbols 😅
ya coz we dont use that here lol
I often read different authors, and get confused by the different terminologies they use
there are 5 books in one semester, for one subject
damnnnnnnnn
ur in college???
yup
oh wow im in HS
thats why studying maths
ohh so ur like 4-5 ahead of me coz im also about to go to college
1 -454 85767 -8629870 487791388 -14685529320 183977791200
(transcript)
Hints from creator:
"you see the one at the beginning?"
"it's in it's normal form"
damn
chiil bro
Cryptograph, anyone got an idea?
nope
in its first form
I love cryptohtaphy, but this seems much advanded
I am just doing it
beginner
what is maths IV
idk it has physsics
😅
I have probability and Discrete in college
I am computer science student
Wow
this semster
Next year there will be differential equations
I am afraid beacuse I have forgotten it all
from my school time
anyone able to explain this to me? i am doing the dervative and im just getting x^-1/2
can you show your work?
they used the power rule
and the derivative of 3x/2 cancelled out with the original exponent
@alpine sable
your work hardly makes any sense
you know im asking a question because i dont understand what im doing. so its no big suprise my work doesnt make any sense
i took the 2/3 that is the exponet and i multiplied it by 3/2x
yes i got the negative 1/3
yes since x is 3x/2 you multiply it by 2/3 since thats the exponenet or n
its no different than getting the dervative of 2x^2 which is 4x?
or am i missing something?
well the derv of (3/2)x is just 3/2
wat
thats the -1/3 right?
yep
why dont you multiply the exponent by the fraction)
you do it with 2x^2
but not with this, this makes no sense to me
thats what i did, and i got 6/6
ah i see im dumb
i need to multiply out by x as well
you can write that as (2/3((2/3)*x) so it is 1 * (3/2)*x
yep, with the appropriate exponent.




