help-0

[pliant crater]

Can Anyone help me out with this?

[noble sinew]

Test?

<@&268886789983436800>

[bright pasture]

... Hmm

[noble sinew]

That is cheating my friend

[ancient creek]

Please read the rules man

[heavy otter]

not here

[merry coral]

solve this and I will give you a cookie

could it be something to do with binomial distibution

also corners have 2 adjcent, side has 3, middle has 4

[native temple]

How is this a function the range repeats

under different out puts

[glass lichen]

so?

You just cant have 2 y values for 1 x value

[night geyser]

f(x) = x^2 is a function

despite f(-1) = f(1)

[since (-1)^2 = 1 = 1^2]

what matters is that each INPUT has one OUTPUT, not that each output has one input

(ie you have it backwards)

[shrewd otter]

Also, there is a class of functions called "injective functions" (one to one functions) which have the property that each output has one input.

[noble sinew]

yes

[clever folio]

Is it not just asking you to use the distance formula for vectors?

Oh wait I see somebody already mentioned the distance formula to you lol.

The distance formula for vectors can be written in terms of crods products.

Sorry dot products

Not cross products

So d(r_a,r_b)=sqrt of some junk to minimize then use max/min procedures from calc 1?

[severe socket]

can anyone help with this?

I dont even understand a(x)=p(x)/x cuz isnt that literally just a(x)=p?

[clever folio]

Pretty sure the euclidean distance in terms of dot prod is d(a,b)=sqrt((a-b) * (a-b)) for your side question.

[ionic jewel]

step 1: go learn function notation

f(x) is not f times x

[severe socket]

i know this

[glass lichen]

You dont

[severe socket]

what

[glass lichen]

given what you just said is completely false

[severe socket]

OOOH its not p multiplied by x its p(x)

my bad im stupid

[glass lichen]

.

[vagrant rover]

What is the difference between a slope and an average rate of change?

[glass lichen]

average rate of change is slope of a secant

slope is.. slope

[vagrant rover]

what is a secant?

[glass lichen]

amazing what google can do

[alpine sable]

anyone able to explain to me how this was gotten?

ive gotten to the end of this integeral, and im going through changing the limits over

and im going on my calc cos^-1(-5/7)

and im getting a different answer

i understand that sec=-1 is pi

[void yoke]

Er what confuses you?

[alpine sable]

i get a different answer on the first limit of -7/5

[void yoke]

What do you get?

[alpine sable]

bruh

im an idiot i had the wrong number in the calc

[void yoke]

Remember if cos < 0 and y < 0, the answer has to be in the 3rd quadrant.

Okay. Well you got the answer!

[alpine sable]

i was going 1/ since its sec, but i just had to switch fraction.

i was doing it wrong, stupid mistake. sorry.

[void yoke]

Ah. I see.

[alpine sable]

typical of me to get everything right and intergrate it right but mess up on this.

[void yoke]

Calculus can be annoying because of the many steps.

[glass lichen]

wait till you hear about householder algorithm

[shut elk]

hi, free?

question is show that ${m \choose n} + {m \choose n-1} = {m+1 \choose n}$. that is, $\frac{m!}{n!(m-n)!}+\frac{m!}{(n-1)!(m-n+1)!}$, they said that this has common denominator $n!(m-n+1)!$

looking at the denominators, I don't see where they

i mean, where did the -1 go?

[void yoke]

Assuming it is a well formed problem, This can be solved by combining fractions.

[shut elk]

i'm interested in understanding how the common denominator makes sense

but yes, absolutely

[ocean seal]

Ee

[lime rain]

this formula take radians or degrees?

[shut elk]

another chat please kuster.

[void yoke]

$$ = \frac{A}{n(n-1)!(m-n)!}+\frac{B}{(n-1)!(m - n +1)(m-n)!} $$
$$ = \frac{A(m-n+1)}{n(n-1)!(m-n)!(m-n+1)}+\frac{Bn}{n(n-1)!(m - n +1)(m-n)!} $$

Lol oops

[shut elk]

i'll grab the text and display it in latex

[ocean seal]

smb3dx

[shut elk]

oh, nice, thanks.

ok

[alpine sable]

Hello yngPaul! Suppose the company stocks $W$ number of widgets. Then the number of widgets sold ($x$) must be an integer in the interval $[0,W]$. Given that the profit function is $p(x)=5x-2-2x^2$ the defining statement for the average profit per widget is [A(x) = 5-2x-\frac{2}{x},] where $x$ in an integer in the half-open interval $(0,W]$; you must exclude $x=0$ since the concept of average profit per widget does not make sense when you haven't sold anything.

[ocean seal]

AndersM

[glass lichen]

Dude. Stop spamming channels from hours old questions

[severe socket]

thanks bro i figured it out but i actually have another question if you could help

[glass lichen]

channel is in use

[shut elk]

ty mosh

[void yoke]

$$ = \frac{A(m - n + 1)}{n!(m-n+1)!}+\frac{Bn}{n!(m - n +1)!} $$. I think …

[ocean seal]

smb3dx

[shut elk]

oh, other way i thought, might be wrong

we needed the (n-1) term on A

or, idk.

[glass lichen]

A already has (n-1)!...

[void yoke]

This is fine.

[shut elk]

i get that like, you're answering the question and stuff

[void yoke]

n! > (n-1)! So you usually want the larger denominator.

[alpine sable]

I don't know if I can, but I can give it a try.

[shut elk]

but i don't understand

what you're showing here

how did we get from (2) to (3)

[void yoke]

Finding common denominators.

[shut elk]

yes, but i don't see (2) to (3)

[void yoke]

Multiply the left by (m-n +1)/(m-n+1)

The right by n/n

Then simplify the ! In the denominators.

[shut elk]

ok thanks.

[limpid scroll]

could someone help me with this question?

[void yoke]

Look up Pythagorean theorem.

[limpid scroll]

nvm im dumb

i was forgetting to square the 3

[void yoke]

Luxury you okay?

[silk coral]

Could I get some help on that question

[void yoke]

Yes

[silk coral]

I know how to do it with triangles but not quadrilaterals

[void yoke]

Er call the 4 arcs r, s, t, and u

[limpid scroll]

which grade math is that?

[silk coral]

Geometry

10th

Well for my school 10th

[void yoke]

R=z, s =120, t and u we don’t know.

Is that clear so far?

[silk coral]

One sec let me write it down

Ok got it

[void yoke]

What is t + u?

(Hint: think about the 70)

[silk coral]

Hmm

Is t 140

[void yoke]

T + u is 140

See only the two segments that make up the 70 angle

[silk coral]

Ohh you use the entire arc

[void yoke]

And the circle.

Yes!

So what is u + r?

[silk coral]

So ur = 100?

Oh wait it would be 160

[void yoke]

160 yes

What is r + s + t + u?

[silk coral]

360

Does y = 20 and x = 10

[void yoke]

Can you find r + s + t + u + u?

[silk coral]

It would be 420 right

[void yoke]

Yes!

Can you find r + s + t + u + u - (r + s + t + u)?

[silk coral]

60

Oh I see so U is 60

[void yoke]

Yup!

[silk coral]

Making z 100

Hm so how do we find x and y

[void yoke]

Look at only the segments that make up “x”

[silk coral]

Oh i got it x = 110 and y = 100

Cause opposites are supplementary

[void yoke]

That is true too or you can use the arcs we completely found.

(Z + 120)/2

[silk coral]

Ahh I see

And (80+120)/2

Is 100 for y

[void yoke]

Yes.

[silk coral]

Ok thank you so much for the help

[void yoke]

Yep. Yw.

[silk coral]

Could I get some help on this one also

<@&286206848099549185>

[limpid scroll]

my geometry class never taught me that ;-;

[silk coral]

Are you still taking it

[limpid scroll]

no it was last year

[topaz scaffold]

I don't understand the labels here

[silk coral]

It’s labeling the arcs and the angles

[topaz scaffold]

Ohhh the angles for the arcs

[silk coral]

Yeah

[topaz scaffold]

Oki give me a minute

[silk coral]

Thanks

[shrewd otter]

What does x represent?

Well, can we make negative sales?

Can we make fractional sales?

The channel is clearly occupied.

It's like you don't care about other people.

[topaz scaffold]

@silk coral Not sure how to explain what I did here

[limpid scroll]

o

sorry

[shrewd otter]

Just apply quadratic formula.

[limpid scroll]

ok

[silk coral]

Thanks that kind of makes sense

[tired hamlet]

How would I set up B?

[topaz scaffold]

How do you know the rotation command?

So the 2 equations you have need to take in H and output A

So your H would be your x and your A would be your y in the normal case

[shrewd otter]

,rotate

[ionic jewel]

the bot is surprisingly good at flipping images the right way

unless people manually do it after

[topaz scaffold]

Does it guess or does it actually have detection?

It always rotates counterclockwise I think

[shrewd otter]

Most people are right handed, so they take photos with the camera on the left.

Leading to clockwise rotation.

[tired hamlet]

Wait so would the formula be 8H+20=10H?

[topaz scaffold]

Yep

[ionic jewel]

yeah i figured it would be the photo direction, makes sense

[topaz scaffold]

For question 2

[alpine sable]

Can we say that the net force on the block = F_BR - f_BS = ma?

So the force on the block from the rubber band is greater at 7 inches than at 6 inches, which implies that the difference would be greater than as well?

[topaz scaffold]

It's asking for the net force

And since the block isn't moving for both 6 and 7 inches, the net force is 0

It's probably best to ask these questions in a physics server

[alpine sable]

So you think it's (b)?

[rugged ermine]

a

hello

[topaz scaffold]

Yes

[alpine sable]

It's not

[topaz scaffold]

Ah rip

What was the answer?

[alpine sable]

Apparently (C)

[topaz scaffold]

Huh

I don't really understand

[alpine sable]

Me neither

[topaz scaffold]

The force from the rubber band should be cancelled by the force from the friction until the rubber band reaches 8 inches right?

Then it moves cause the force from the rubber band is greater

[ionic jewel]

I'd say b too

[alpine sable]

@ionic jewel They can't be equal

The rubber band is not the same length

[ionic jewel]

why not

who cares it's net force

doesn't the friction force equal it

but the other direction

so it all goes away

[topaz scaffold]

The force exerted by the rubber band isn't equal

But the net force is equal

[lilac maple]

Hey, very quick question on permutations:

If I have a set of 13 building blocks and I can arrange them in any order, am I then correct in assuming that the amount of possible orders would be calculatable as permutations? (with both n & r being 13)

Or am I vastly overcomplicating things and the actual result would just be something like 2^13 😅

[topaz scaffold]

Think about it like this

For the first spot, we have all 13 blocks as choices

For the second one, we'll only have 12 left to choose from

And so on

[ionic jewel]

,w 13 permute 13

[topaz scaffold]

So you'll end up getting 13!

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[ionic jewel]

yeah it's the same

didn't know the permute formula off the top of my head

[topaz scaffold]

Same thing as 13!

[ionic jewel]

but 13! is the normal way to think about it, not the permute formula right away

[static fern]

is that

jihyo

[topaz scaffold]

Yea lol

[topaz scaffold]

Right

[static fern]

bow*

[lilac maple]

Perfect, so my assumption was correct 😄

[topaz scaffold]

Cool

[lilac maple]

thanks for the quick help!

[topaz scaffold]

Np

[opal wyvern]

What would be the next step in solving for y'?

I suck at simplification

[velvet condor]

whats the question

y' is a variable rite

[opal wyvern]

it is implicit differentiation

treat it as a variable

solving for y'

[native temple]

if $ \frac{3}{10} = 0.3 $ and $0.3 \times 3 = 0.9$ how does $ \frac{3}{10} = 0.3$?

[ocean seal]

Nerdy_Coder

[velvet condor]

?:)

[opal wyvern]

...what

[undone dock]

$\frac{3}{10}\cdot3=\frac{3\cdot3}{10}=\frac{9}{10}=0.9$

[opal wyvern]

3/10 = 0.3 i dont know how else to put it

[ocean seal]

K.

[native temple]

but how can you get 3/10 to equal 10?

[undone dock]

3/10 doesn't equal 10

Wdym

[opal wyvern]

Multiply it by 33.33 repeating i suppose

[native temple]

why does 33.33 need to be repeated for 3/10 to equal 10?

[opal wyvern]

cause if .33 isnt repeating infinitely it is not equal to 1/3

[native temple]

oh

didn’t know that

I confused 10/3 to 3/10

[opal wyvern]

Homie am I answering your question or are we answering yours

This channel is in use

Solve for y'

[unkempt stream]

Isolate y'

Multiply both sides by 2sqrtxy

Factor it

Bring both y' to 1 side

And the rest on the other

[unkempt stream]

Multiply

The things in the parenthesis

[pastel bobcat]

(-26) + 7 = (-12) = ??

            16

[opal wyvern]

find another channel dude

[unkempt stream]

No

[pastel bobcat]

k sorry

[unkempt stream]

No

Lol

[opal wyvern]

i forgot the minus y on the right side

[unkempt stream]

Multiply the right side

And I'll tell you what to do next

[opal wyvern]

Find another channel dude

<@&286206848099549185>

[unkempt stream]

You're doing the wrong this

Multiply the right side only for mr

Me

Wait

[opal wyvern]

What do you mean by that

[unkempt stream]

Can I see the original thing

So I know what to do

[unkempt stream]

I'll do it

And show your my work

[unkempt stream]

Ok now multiply both side by 2 sqrtxy

Then distribute to bring y'to one side

[opal wyvern]

y' already is on one side

[unkempt stream]

This is what I did

Do you get it

[opal wyvern]

i am attemptin g toio

attempting too

[unkempt stream]

Multiply both sides then distribute so we can bring y'to one side

Then factor out the y'

[opal wyvern]

im so lost

this is what i have

[unkempt stream]

How did you get that y' to one side

[opal wyvern]

frick i did it wrong

[unkempt stream]

You know to cancel out multiplication you use division right?

[opal wyvern]

yep

[unkempt stream]

Yeah lol

So the only way to get it to one side is to subtract which I've been trying to get you to do lol

You were on the right track on the very top of the page

[unkempt stream]

No no no

That's too hard lol

Listen

Multiply x by (2-sqrtxy)

[opal wyvern]

which x in which equation

[unkempt stream]

The one near (2-sqrtxy)

[unkempt stream]

Ok look here

You're over complicating it here

You only have to bring y' to one side

[opal wyvern]

How tf did you get from third from the bottom to second from the bottom

[pastel bobcat]

man maths is fun and hard at the same time

[unkempt stream]

Oh did some in my head

[opal wyvern]

And why do you have an exponent of 3/2 instead of 1/2

[unkempt stream]

You had to distribute

(Xy) times sqrt xy is (xy)^3/2

Since same base you add exponents

Might be wrong though

Haven't done calc in a long time

[velvet condor]

^(3/2)*

[(xy)^3]/2 is a different story

[unkempt stream]

Yh :v

[opal wyvern]

Accurate so far?

[unkempt stream]

Sorry I changed it to 4

This should show that I distributed it

And fuk wait

@opal wyvern

You had it right at one point

But you're not distributing

The thing you multiplied

[opal wyvern]

What do I do next?

[unkempt stream]

Take out the y'

By factoring it out

[opal wyvern]

Don't know how

Ohhh

Nvm

[unkempt stream]

Lol

And then just divide

To isolate y'

[opal wyvern]

Pretty sure I got it, thanks!

[unkempt stream]

Np

[alpine sable]

Hi guys I need help w something

How can I solve this

Corresponding image

[pastel bobcat]

u had the patience to help him solve that big question

man u really are the best

[brave thicket]

does anyone know a faster way of finding the nᵗʰ term in an arithmetic sequence rather than the common formula? -> An = A1 + (n – 1)d

[pastel bobcat]

nah

i havent reached those standards yet

[brave thicket]

ok bhai

[pastel bobcat]

thik behena

[alpine sable]

hi guys

i have another question

this is d and not a right

[flat vale]

Is this working out incorrect?

With CAS, it gives me a non-real result

[flat vale]

what's the problem with this working out?

[fathom pulsar]

Help its urgent

[flat vale]

other channel?

[ancient creek]

it looks correct imo

[wary iron]

Hello everyone i nwws help with a question

[pearl marlin]

How will you find half of 54?

[wary iron]

No clue im struggleing with this question

[pearl marlin]

Like 1/2 of 54 = 54/2
Means you multiply 54 by 1 and Then divide by 2.

[wary iron]

ok

thank y

so in first collem i put 2 then in second collom i put 1?

[ancient creek]

no he was giving you an example with 1/2, you are given 4/9

[wary iron]

oh ok

ok got it thank u

so do i put 4 in first collem and 9 in second sorry im dumb

[pearl marlin]

Relate it with my given example you will see what will come in first box and in second box

[alpine sable]

hi everyone

does anyone have any idea for this problem

[wary iron]

ok thanks man

orrr women

its 2021

[agile berry]

#chill

Posting this here for myself

[limpid scroll]

could someone help me understand how to solve this?

[velvet condor]

bruh

they sum up to?

[limpid scroll]

360?

you mean b and x right

[velvet condor]

yes

so what do they sum up to

[limpid scroll]

is there a property thats supposed to help me here

[velvet condor]

yes

u notice those 2 90° angles?

[limpid scroll]

the rectangles bro?

[velvet condor]

yup

[limpid scroll]

damn

so its 180

[velvet condor]

together with x and β they sum up to 360

yup

so the answer is 180-x

[limpid scroll]

didnt even think of that im so dumb

ty

[twin haven]

they are vertically opposite tho

@velvet condor can you explain

[velvet condor]

90° angle+90°angle+x+β=360°....

[twin haven]

oh i didnt see those rectangles

then yeah

[agile berry]

#chill

[pearl marlin]

Can you take derivative inside that bracket?

[ionic jewel]

$2f'(5) -3g'(5) + 4 = 2-3 =-1$

not sure why it gives you f(5) and g(5)

oh yes

[ocean seal]

bunny

[ionic jewel]

i just forgot how to do math :)

[random flax]

I imagine this is not in use

My question is on calculating weighted averages

(This is the example from google sheets site: https://productivityspot.com/calculate-weighted-average-google-sheets/)

Problem is that I do not get 94.4--> I use summation (price*quant)/summation(qusnt)

And I get 97.4

I am so confused, I am pretty sure I am right but this is on a site so

Can someone confirm?

[random flax]

<@&286206848099549185>

[rancid tendon]

depends on your number system

no plagiarism

you have access to a phone, just use the calculator if you wanna cheat on your test

[snow yoke]

can somebody help me with some math problems?

[pseudo goblet]

you on something

[random flax]

Should I just move my original qn to another room?

[rancid tendon]

this room is taken by @random flax

yall should read #❓how-to-get-help

[ionic jewel]

<@&268886789983436800> ban this guy for like 5 reasons

[random flax]

thanks but I will just move to another room

[snow yoke]

can i dm you?

oof

[ionic jewel]

orlkn is probably a troll as well

really

yeah he is

[tame falcon]

What?

[ionic jewel]

and this one too

and the guy with the gif too probably

[strong furnace]

this guy is racist

[ionic jewel]

raid?

where's the last legit question i came here for math

[ionic jewel]

looks open now, post it

[rancid tendon]

the last legit question is rodian_alxs 's

[pseudo goblet]

think this the guy you looking for maybe?

idk

[tame falcon]

Stop spamming GIFs

[snow yoke]

i'll take a pic then i send here the problem, thanks

[warm granite]

Lets say I have a plot, I want to draw a line and say everything above this line is good and everything below is not. Whats this line called? For reference, I have a plot of correlations and say everything above 0.3 is good?

what should I google to find the code for this?

[rancid tendon]

a cut-off line maybe?

[warm granite]

thats a good idea, im gonna try that

[random flax]

what kind of code are you looking for?

Python?

but yeah, cutoff sounds right

[warm granite]

no in r

[rancid tendon]

@warm granite https://gis.stackexchange.com/questions/267857/selecting-features-above-or-below-a-line-using-r

I googled "plot line select above"

<@&268886789983436800>

[ionic jewel]

<@&268886789983436800>

[fading citrus]

Thanks

[pseudo goblet]

tf

[ionic jewel]

did you get both?

[warm granite]

@rancid tendon Thanks

[rancid tendon]

yw

[fading citrus]

Yes

Well no, it was only one person

They just posted two pics right as I banned them so it came through

[rancid tendon]

there was the repeat offender @restive swan and the new one @stray turtle

[ionic jewel]

yep

although they both are invalid users for me so

[fading citrus]

Oh, they were already banned

I got Hellcat

[rancid tendon]

good

[fading citrus]

Anyway sorry, back on topic

[ionic jewel]

it's been bad tonight

the question here is answered

[rough compass]

can someone help me with calc

[ionic jewel]

post your question

[rough compass]

what is the largest area of a rectangle that can be inscribed in a semicircle of radius 6

[thorn kindle]

18

[rough compass]

how did u do it tho

[thorn kindle]

I am smart

[rancid tendon]

troll?

[thorn kindle]

No.

[ionic jewel]

he's not

but you can express the side lengths of the rectangle as a function of x

then optimize it using the derivative method

[rough compass]

ye i didnt know how to make it a function tho

[ionic jewel]

y = sqrt(36-x^2) is the function of the relevent semicircle

the rectangle will have two dimensions

one of which is the height, the other is the length

the height is going to be the value where the corner hits the semicircle, which is a point on the semicircle

so it's going to be sqrt(36-x^2) for one dimension

then the other is just going be be the distance x, but in both the positive and negative directions, so 2x

then you can go from there

[rough compass]

k ty

[thorn kindle]

Gg

[rough compass]

rip

wasnt 18

[random flax]

Wait its 36?

[rough compass]

yep

[random flax]

here's how i did it

[rough compass]

how did u solve it @random flax

[random flax]

oh let me send a pic

[rough compass]

ok

[random flax]

I used geometry and pythagoras

and derivative

Haven't done this maths in a long time haha

[rough compass]

ye im going into calc next year

just prepping now

[random flax]

Good luck good luck

Calculus is the mother of literally all Uni maths

[rough compass]

ima need it cuz my parents expect an A lmao

[random flax]

not that I would know

[random flax]

xD

wait up I am downloading dc on my phone

to take a pic

[rough compass]

all g

[random flax]

I hope this makes sense and is correct

@ionic jewel @thorn kindle check pls

[ionic jewel]

I'm too lazy to check your math but you did what I suggested so looks good to me

,w max 2x*sqrt(36-x^2)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[ionic jewel]

yep it's 36

[random flax]

Well yep

@rough compass My logic was a bit different at the start from bunny

[ionic jewel]

i appreciate your drawing and work it's done quite a bit better than mine lol

[rough compass]

ye i didnt even think about using trig at all

[random flax]

I didn't remember the formulas so I went straight from pythagoras

Yeah better to use Bunny's method in exam

But yeah my idea is, the corner point will always be hypotenuse=radius of 6, rectangle so x and y can be pythagorized

that's your boundary condition

x will be height on both sides (rectangle opp side= prop) and y is by symmetry 2y

[thorn kindle]

It is easier with the whole circle then just take half of it

[random flax]

Therefore, Area =2xy--> maximize with derivative

[random flax]

Dang that's smart

[ionic jewel]

ah yes this is how i did it very roundabout first before the calc solution

the corner is gonna be at r = 6 theta = pi/4

[random flax]

Yeah AMD's method works well in head but if u had to write it out

[ionic jewel]

which is 6(sqrt(2))/2, then double that for the length of a side for 6sqrt(2), square for area to get 36(2), then divide by 2 since it's a semicircle to get 36

that's how I did it in my head but not sure how to show it's actually the largest besides just already knowing

[random flax]

Its largest cause a circle must be 360 degrees, by circle geom, if u fit a square into circle, you will have 4 equal 90 degrees

and since the radius can go across both edges in a square, can never do this with a rectangle

[snow yoke]

This is with cauchy method

Can somebody help me to solve it?

please?

[pearl marlin]

Can you eliminate two options just by y(0)=0

[snow yoke]

can you please tell me which letter is the answer and the procedure?

[random flax]

yeah b and c can be eliminated with y(0)=0

since sin0=0

you are left with y(0)=1 which is false

d can be eliminated with first derivative

so a is the answer

wait

[snow yoke]

?

[random flax]

it may be the other way around lemme write it

[snow yoke]

okok thanks alot

[random flax]

Yeah a is the correct answer

Try doing derivative of a and d

for b and c just substitute x=0 and you will see y(0) is not 0 since sin(0)=0

for a, do derivative an put in x=0, you get 1-1

for d u should get 1+1

still in head but u should be able to try it in derivative calc if ur derivative game is weak like me

[snow yoke]

thanks 🙂

the following curvilinear integral at arc differentials:

where γ is the arc of the curve of parametric equations

is valid:

@random flax can you help me with this one too?

please

[random flax]

Haha I am no good at differentials, the earlier one was easy substitution

[snow yoke]

oof

do you know somebody that can solve it?

[random flax]

nope, I am new to this serevr

[snow yoke]

oh ok thanks

[random flax]

what is that gamma sign equal to?

[obtuse fox]

You want some help based on your pfp

[snow yoke]

my pfp is fine

[random flax]

I don't understand the language

Wait can u translate the question?

May be doable

[snow yoke]

i translated here

[snow yoke]

.

[random flax]

where??

Ohh nvm haha I need glasses

gotcha

[snow yoke]

ahaha

[random flax]

Nope sorry couldn't do it. I dont remember parametrics anymore

@fading zephyr

he is smart

[ionic jewel]

don't ping me

if i was going to help i would have

[random flax]

ah alr

[random flax]

@snow plaza So there are 3 things here

First you change the order of integration, take out the y terms

Second, you realize the antiderivative of tan inverse by using u substitution

And yeah

[snow plaza]

how can ı do that

[random flax]

Well how to change the order of integration? https://www.youtube.com/watch?v=NETmfwOAKpQ

And I will send u my solution

[random flax]

hope it helps

[snow plaza]

yes thank you

@random flax could you help me ?

[random flax]

no sorry I dk that

[winter linden]

So was at tutions today doing some leniar equations ... so the problem was 3x - 2y = 4 .. so to solve it the tr transposed 3x to the other side but he took 3x 1st then - 4 and aslo on the Lhs
The minus sign is gone... can explain how this works

[winter linden]

Plz help 🙏

[random flax]

um

wait

I am not sure I understood the question properly

Is this what you meant?

@winter linden

for 3x-2y=4 to 2y=3x-4, move 4 from RHS to LHS, and 2y from LHS to RHS

so if you go a+b=1--> this is same as a=1-b

^that logic. Is this the qn?

[winter linden]

Oohhhhhhh ooo ooo o now it makes sense i was just a bit confused cuz the the answer was from lhs to rhs ahh but now it makes sense

Yeah now it makes sense thanks @random flax

[random flax]

lmao, I have been confused with negatives too many times to count

I understand the feeling

[winter linden]

Lowl thanks again

Im really dumb in math

[zenith hemlock]

I need help with b and c. full ans to c is dp/dt=0.024P btw. This is the exponential growth and decay topic!

[arctic mango]

For part b, just find out the fractional change in the population a t = 0 and t = 6

For part c, you have to differentiate P to get dP/dt = P_0 (0.024) e^(0.024t) = 0.024P.

[topaz palm]

Yes exactly this

Use that

[zenith hemlock]

but i dont have P0

[arctic mango]

You don't need it. It gets cancelled when you take the fractional change

Fractional change is ∆P/P_0, multiply it by 100 to get percentage.

∆P = P(t = 6) - P_0.

[zenith hemlock]

alright i got the answer thanks for the insight!

[alpine sable]

Now remote learning sucks and emailing my teacher takes like 3 hours for him to replyy

so how do you even do these?

[zenith hemlock]

actually im still confused how does P_0 (0.024) e^(0.024) suddenly became 0.024P

[torn heron]

Anyone knows how to do? Is there any formula that I could use? Thanks

[arctic mango]

I made a slight mistake.

Check it now. Does it make sense?

d(e^(kt))/dx = ke^(kt)

[pearl marlin]

Area of ellipse - area of rhombus

[pearl marlin]

For OB use pythagorus in triangle AOB

[zenith hemlock]

How does the 2nd line become 3rd? (edit: nevermind, sorry for ping)

[torn heron]

Area of ellipse =pi x OA x OB?

[pearl marlin]

Yes

[torn heron]

Thanks

[prime badge]

the first line says that

[zenith hemlock]

oh my god.... thank you

[chilly panther]

Hi I'm quite confused. I've been asked to find the coefficient of a negative power using binomial theorem... It's something along the lines of

$\left(3x^2-\frac{1}{5x^3}\right)^{13}$

and then I'm asked to find the coefficient of like say x^{-7}

I'd know how to do it if it was positive 7 but I seriously did not think it was possible to do this for negative powers

like you can't do ^{-7}C_13 so I'm confused

[ocean seal]

mcacutt

[noble sinew]

x^(-7)=1/(x^7)

And some of your terms will be with x in denom because you have 1/(5x^3) in your original expression

[chilly panther]

I've just looked up the expansion for the question I've been given and I see it now... So I'd find nChoosek for the positive version which would give me a solution with x on the bottom? Hence the negative power?

[noble sinew]

Yep

[chilly panther]

thank you

[warm cloud]

is this channel busy

[vale wigeon]

not at the moment

but if you're not quick in posting your question, you might get spoken over

[warm cloud]

Help with this question would be appreciated

I'm not sure how I can related the mean to the standard deviation

I did the first part of the question, the new mean is equal to $0.818 or 81.8 cents

[vale wigeon]

,calc 0.787 * 1.04

[ocean seal]

Result:

0.81848

[vale wigeon]

up

yup*

okay

SD(cX) = |c| SD(X) for any random variable X and constant c

here you have c = 1.04 and X is the number of loaves per purchase

[alpine sable]

could someone please show me (with steps) how to solve for x

[warm cloud]

ohh i get it

[vale wigeon]

@alpine sable this channel is busy

[warm cloud]

i didn't know the rule

guess they expected me to derive it myself

thanks

[alpine sable]

sorry

Smh i be ignored like that

[unkempt grail]

would anyone have a godo visualization tool to study this specific function

<x,Ax> where x is a vector and A is a matrix

[night berry]

I have a vague-ish problem to solve that i do not know how to start with.
So, my mentor told me that I have to find out the price of old phones depending on some parameters, and to do that using fourier transform

any ideas how to go about it? or what questions I should ask my mentor

[warm cloud]

Do you have the complete question in written form?

[night berry]

@warm cloud no, he just told me that and then vanished, so I'm really confused

do you have any ideas

[warm cloud]

what are the parameters? do you know how many there are?

[night berry]

parameters are like when the phone was originally bought, etc, that's what I'm guessing

can it be solved using fourier?

[tame coral]

Just a thought, but maybe using fourier transform and having some historical data of prices of older models, you could point out how different parameters/components of phone degrade phone's price over time.

Abstract ideas for abstract question🤔

[night berry]

yes

haha

abstract ideas for abstract question

[warm cloud]

Idk, the question seems very vague. without any limitation/conditions, you can use any function to say anything

[night berry]

but like can you tell me what I should ask him?

about the details

to tell me about

[warm cloud]

like @tame coral pointed out, you could ask for historical data

[tame coral]

What are knowns, and what you want to solve for?

[night berry]

I'll ask him that

[warm cloud]

you could also ask "What am i allowed to ask" and get all the required info

[night berry]

hack

[tame coral]

Jesus I should've asked that today in a job interview

because I worked out, if they say "do you have any questions" and you say "no" you seem quite uninterested, so I was coming up with some semi-relevent questions

[small holly]

how do i simplify √87?

[glass lichen]

cant, it doesnt have any square factors

[small holly]

alright ty

[shell heron]

cant u do this: √87 = √29 * 3 = √29 * √3

well thats not simplifying nvm

[nova widget]

ye because none of them are perfect squares

[small holly]

wait that works for me

[nova widget]

how?

[small holly]

cause i needed to do it for quadratic equation

its

3±√87/-6

[nova widget]

is the -6 directly below the $\sqrt{87}$ or below the entire $3 \pm \sqrt{87}$?

[ocean seal]

g-e-o-m-e-t-r-i-c

[small holly]

the entire thing

[nova widget]

okay

[shell heron]

thats actually good since u could then remove the "√3" im pretty sure

-6 = -√36 = -√12 * √3

[nova widget]

yes but that would be $\frac{3\pm\sqrt{87}}{-(\sqrt{12}\cdot\sqrt{3})}$

[shell heron]

yeah and i wrote before that √87 = √29 * √3

so u could remove √3

[nova widget]

but you also need to divide from the 3, correct?

the 3 on the top

[shell heron]

uh

[ocean seal]

g-e-o-m-e-t-r-i-c

[woeful briar]

how much is 2.44140625E14?

[icy storm]

@woeful briar it is:

[ocean seal]

kyaaa.holo2

[woeful briar]

i do not understand

[icy storm]

Ok, let's start with an example:

[woeful briar]

yes

[icy storm]

When we have a decimal, say 0.5

If we were to describe this in common words this would be "one half". But in terms of place value, we would say that this is "five tenths".

[woeful briar]

yes

[icy storm]

because the decimal digit one place after the decimal point, is the "tenth" place.

[woeful briar]

no i do not get it

[icy storm]

just like how the 0 in the number 50 is in the "tens" place

[woeful briar]

ohhh

[woeful briar]

isnt 5 in the tens place?

[icy storm]

oh yes

I am a buffoon

holy crap

dies from cringe

[spring escarp]

Can I ask just a simple question here I don't have a problem

Can we prove the model of PA in z2?

[icy storm]

@woeful briar ok, anyways so the 5 is in the tens place. Basically, we say things like "tens" and "hundreds" and etc in place value because those numbers of digits corresponds to how many multiples of 10 there are.

[woeful briar]

btw @icy storm so this is about 100 trillion?

[icy storm]

$$50 = 5\times 10 + 0\times 1$$ so there is 5 tens and 0 ones (5 in the tens place, 0 in the ones place). And yeah, that would be 200 trillion.

[ocean seal]

kyaaa.holo2

[icy storm]

forgive my mistake earlier lol, that was bad. But it doesn't change the substance of what I'm trying to teach (I'm just a little tired i guess lol)

My point is that, like how we have tens and hundreds in whole numbers, we also have tenths and hundredths etc with decimal numbers.

[woeful briar]

yea i think i get it

thanks!

[icy storm]

oh- i didn't get to the main point yet, but... if I helped, then no worries 😅

[woeful briar]

yea i think i just work my way up with those numbers

[icy storm]

I guess it's a matter of "explanation vs answer"

[woeful briar]

this

[icy storm]

yeah. Essentially with every positive power of 10, we move the decimal point one place to the right

[woeful briar]

got it!

[alpine sable]

anyone able to explain to me how the limit of 1/2e was dropped? im thinking that would be 1/2 + infinity which would be infinity?

[gray isle]

where's 1/2 + infinity coming from?

[alpine sable]

well 1/2e^-t^2 is inifnity i thought?

[gray isle]

recall your exponent laws

and order of operations

[alpine sable]

okay........

thanks

[spring escarp]

Hey@gray isle

Z2 doesn't succumb to Gödel right so we can prove the consistency of pa in it

I mean it can prove its own consistency

[gray isle]

can't help with that sry

[normal hamlet]

Hell

Hello

[scarlet heath]

how do I find this?

[alpine sable]

Find the unit vector pointing in the direction of u and scale it by the magnitude of v

[scarlet heath]

oh right I forgot the formula

thanks

[vagrant rover]

Is this:

The same thing as this:

[upper pebble]

wouldn't it be 4(xxx)(yyyyy)

$4(xxx)(yyyyy)$

[ocean seal]

cole

[scarlet heath]

how do I find this?

[rigid smelt]

have you heard of/learned logs

[scarlet heath]

yeah

[rigid smelt]

so using your knowledge of log, how do you get rid of the base?

basically try to do something that will either cancel out 3 or 5

[scarlet heath]

isnt it when you raise it to the same base?

[rigid smelt]

yeah

$\log_a(a^b)=b$

[scarlet heath]

so I can do like x+5=3^5^2x-9

[ocean seal]

waler

[rigid smelt]

no...

so lets say you want to cancel out 3

what operation do you do?

[scarlet heath]

do I multiply it by log_3?

[rigid smelt]

not "multiply", you take log_3 on both side

the log is an operation, a function, and the argument is part of it

its not "multiplied" to the log

[scarlet heath]

alright

[rigid smelt]

so what do you have after taking log_3 on both sides?

[scarlet heath]

so it becomes x+5=log_3^5^2x-9?

[rigid smelt]

edgy notation

[scarlet heath]

yeah kinda messy I hsould learn latex

[ocean seal]

waler

[rigid smelt]

did you mean this?

[scarlet heath]

yeah

[rigid smelt]

now what can you do?

[scarlet heath]

uh I can make it

Log(5x-9)/Log(3)

right

[rigid smelt]

no

its the wrong rule to use anyway

[scarlet heath]

a

[rigid smelt]

what rule can we use here?

there is an exponent inside the argument

[scarlet heath]

oh so it becomes 2x-9log_3(5)

[rigid smelt]

missing brackets

but yes

so now its just a linear equation

solve for x

approximate

[scarlet heath]

so x = 18.18?

[rigid smelt]

no

you did something wrong

[scarlet heath]

damn it

[rigid smelt]

also they asked to approx to 3 decimal places

[scarlet heath]

so 18.185

[rigid smelt]

no

again, the answer isnt correct

[scarlet heath]

oh I

ugh how did I mess it up

[rigid smelt]

this is just to say that the representation of your answer isnt correct either

[rigid smelt]

idk

im not psychic

[scarlet heath]

what do I do about the 2x then infront of the log

[rigid smelt]

can you show your work?

like that would make everything much clearer on what you did wrong

[rigid smelt]

this is wrong, very wrong, (2x-9)log_3(5) is not the same as 2x - 9log_3(5)

[scarlet heath]

so the answer was x=9.422

[rigid smelt]

yes

[brisk tree]

How to find the number of solutions of cos(cos(x))=x/10?

[last osprey]

Help mee::::

( 11 )The support lines on the sides of a triangle have the equations r, s and t. Calculate the area of ​​the triangular region bounded by these three straight lines.
r : y = x, s : x + y = 0 e t : y = (15x/100) + 1

( 27 )Let us consider the line r , of the equation x + y − 3 = 0 and the circumference of the equation below. What is the position of the line r with respect to the circumference.
x2 + y2 − 2x − 2y − 3, 75 = 0

( 33 )Determine the coordinates of the points where the line r of the equation y = −x + 5 intersects the circle of the equation below.
x2 + y2 + −2x + −10y + 21 = 0

[alpine sable]

https://cdn.discordapp.com/attachments/775841711812902922/865629439336120330/unknown.png

what is this symbol?

[brisk tree]

Doesn't divide

[brisk tree]

<@&286206848099549185>

[alpine sable]

thanks

[alpine sable]

@scarlet heath that picture made me xd

[pliant bear]

Is there any reasonable way to show that for x in (-2,2), |x| + √(4-x²) ≥2, attaining its minimum on 0?

the plot is obvious

like, I know how to do the symmetry-then-local-extrema-then-boundary-points argument, but that seems rather clumsy and overly complicated

[pliant bear]

oh, wait, does this mean the channel is occupied? sorry, never used the questions channels :/

[ancient creek]

Perhaps consider rewriting this equation as a piecewise equation :P

[pliant bear]

I mean the symmetry argument is the easy part, I was wondering whether the ≥2 would pop up more easily
But I found out that I could minimize the square instead and this works out quite elegantly 🙂

[ancient creek]

Oh ok nice

[austere violet]

If n (A) = x, n (B) = y and n( AUB)= z , express n (A∩B) in terms of x, y and z help someone

[vagrant rover]

Can you write $4x^3y^5$ as $4x^3*y^5$?

[ocean seal]

Dexter is VACCINATED x2

[austere violet]

yes

[vagrant rover]

So 4 is the coefficient for x

and not both y and x

[austere violet]

its for both

[vagrant rover]

Oh

Wait how does that work

can you write it as $4xxxyyyyy$?

[ocean seal]

Dexter is VACCINATED x2

[austere violet]

ahh yaa ig..

[vale sapphire]

yes

[austere violet]

If n (A) = x, n (B) = y and n( AUB)= z , express n (A∩B) in terms of x, y and z help someone

[vagrant rover]

And you would get the same result?

[vale sapphire]

draw a venn diagram

[vale sapphire]

When you're confused when dealing with symbols, switch to numbers

[austere violet]

umm

[vagrant rover]

So you can separate a variable from its coefficient?

[vagrant rover]

Ah okay, yeah that probably helps

[vale sapphire]

Do you really think that 2×3²×3² is equal to (2×3²)(2×3²)

[vagrant rover]

Uhh

No

[vagrant rover]

Wait so you can't write it as ^ this?

[vale sapphire]

yup

[vagrant rover]

k I'm confused

[vale sapphire]

wait no i misread

you can

[vagrant rover]

I thought you said yes

AHH, yes or no xd?

I'm going to go with yes, so can you separate a variable from its coefficient?

[vale sapphire]

Yes

[vagrant rover]

So why do we have coefficients?

[vale sapphire]

When nothing is written between two things it means multiplication

[vagrant rover]

What exactly is a coefficient used for

[vale sapphire]

That's like asking me what the point of multiplying by 2 is

[vagrant rover]

k

I'll just google it

[vale sapphire]

oh wait

[vagrant rover]

waiting

[vale sapphire]

the coefficient of x³ is just the number that multiplies x³ in your expression

that's all a coefficient is

Although, the term is usually reserved for when it's a constant number

[vagrant rover]

So you if you have 4x^3 then that is basically like x^3*x^3*x^3*x^3?

[alpine sable]

😔

[vale sapphire]

no

[vagrant rover]

or is it (4) (x^3)

Ah okay

[vale sapphire]

the latter

[vagrant rover]

it's the latter, I'm guessing

Yeah

alright I think I get it

[vale sapphire]

You're mixing up exponents and multiplication

[vagrant rover]

Right right

[vale sapphire]

4x³ is x³+x³+x³+x³

[vagrant rover]

Oh, I see

[vale sapphire]

like with numbers

4*3 is 3+3+3+3

nobody is changing the rules when going into symbols

[vagrant rover]

So if the coefficient is so important to the variable then how come we can seperate them?

[vagrant rover]

I see

[vale sapphire]

the point of variables is only to be able to make more general statements

[vale sapphire]

wdym "so important to the variable"

[vagrant rover]

Like it determines the value when we simplify

[vale sapphire]

I feel like i'm missing context here

can you explain again?

@vagrant rover

[glass lichen]

Yes you have to multiply by the co-efficient...?

[light mango]

can anybody explain this to me

the integral

[alpine sable]

how do i get the number of people

In this group of archeologists, the ratio of the number of chief archeologists to the number of
senior archeologists must be 3 : 4,
while the ratio of the number of senior archeologists to the number of student archeologists
must be 8 : 3.
Six student archeologists are going on the trip.

[warped phoenix]

i have no idea how i'd do this

the only equation I could come up with is 64 = 2 * w * 8?

<@&286206848099549185>

anyone?

[topaz scaffold]

So you can start by finding your parameters

The volume will be 576*h (in inches)

The time derivative of height will be 8

Assuming that there's no sand at t = 0 so h(t=0) = 0

Using those two we can get that h(t) = 8t

[topaz scaffold]

Plugging in to this we get 576*8t

V = 4608t (in cubic inches)

V = 8t/3 (in cubic feet)

Then you can plug in 64 for V to find t