#help-0

1 messages · Page 705 of 1

shadow edge
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plus im in summer school and the teacher does not give notes

glass lichen
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You make your own notes

shadow edge
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i bought a calculus book so thats my stuff

glass lichen
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then look at the appendix and see if it has implicit....

sour pasture
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@shadow edge
If i were to ask you "Compute d/dx of (x^2) sin(2x) " how would you answer?

shadow edge
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derivate x^2 then sin2x

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so i would do 2x

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  • cos2x d/dx (2x)
sour pasture
#

@shadow edge
Don't worry about it mate.
So we want to take d/dx of (x^2) sin(2x).

You're right in that eventually we'll need to differentiate the little dudes,
but to differentiate a product remember it's not the product of derivatives, it's not the sum of derivatives -- it follows some other logic.

Would you agree it's :
(d/dx of x^2) sin(2x) + x^2 (d/dx of sin(2x)) ?

Then resolving it all gives:
2xsin(2x) + 2x^2cos(2x).

Makes sense?

shadow edge
#

yea

sour pasture
#

@shadow edge Okay cool,
So you now suppose I asked you "Compute d/dx of (x^3) sin(2x) " how would you answer? (give the final answer)

shadow edge
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(x^3)' sin(2x) + x^3 (sin(2x))'

sour pasture
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perfect

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So now what if i give you:

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"Compute d/dx of (y) sin(2x) " how would you answer?
y is some unkown, unspecified, mysterious function of x.
Pretend all the niceities in life.
pretend it can be differentiated.
it's just some other function like x^2, like x^3.
But without knowing its explicit form, knowing only its name how would you respond?

shadow edge
#

so basically i just have to derivate the two sides separate?

ionic jewel
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though that was a question

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mb

sour pasture
#

@shadow edge
When asked the question "Compute d/dx of (x^2) sin(2x) ",
you answered correctly: (d/dx of x^2) sin(2x) + x^2 (d/dx of sin(2x)).

When asked "Compute d/dx of (x^3) sin(2x) ",
you again answered : (d/dx of x^3) sin(2x) + x^3 (d/dx of sin(2x)).

So now when confronted with the unknown "Compute d/dx of (y) sin(2x) ",
fear not. For you have already answered all the questions before it.
Not knowing what y is, but knowing that it's one of the functions for which we have already answered the question, we can safely say (just as Bunny said by product rule) that
the answer is: (d/dx of y) sin(2x) + y (d/dx of sin(2x)).

It's simply dy/dx sin (2x) + 2ycos(2x).
Remember that dy/dx is not a constant wrt differentiation, but the slope of the tangent at (x,y).

shell narwhal
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what is the difference between dy/dx and d/dx ?

sour pasture
shell narwhal
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oh ok

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so almost the same thing

shadow edge
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@sour pasture So from what I understand, I have to derivate both sides separateley and replace the variables with the points from the graph. That will give me the slope so I can find the tangent eqation. Is my thinking ok?

sour pasture
shadow edge
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Thanks so much.

shell narwhal
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so you will end up with something = something ?

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ex: 3 = 3 ?

alpine sable
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whats the formula to work out what p will be

sour pasture
shell narwhal
#

ok thx ur the best

alpine sable
sour pasture
alpine sable
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farewell

warped phoenix
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What do they mean by symmetric about the origin?

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I was told that if it was even, it would be reflecting across the y-axis, and if it was odd, then it would be passing through the origin, and if it was flipped upside down it would "match"

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i wasnt exactly sure what they meant by match

glacial hedge
alpine sable
peak storm
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<@&286206848099549185>

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Pls help me

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Is question 13 up to the far right?

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??

glacial hedge
glacial hedge
rugged ermine
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i have a hoorrible problem

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but 0 idea how to solve it after factoring out

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ill send it rn

glacial tiger
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hey can anyone help?

rugged ermine
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,help

ocean sealBOT
#

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

glass lichen
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not a reflection

neon moss
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what trig identities makes this so

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i can't think of a way sin(x) + cos(x) * ∆t == sin(x + ∆t)

glacial hedge
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wait nvm

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xD

neon moss
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cant be :/

glacial hedge
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that doesn't really make sense ur left with

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$sin(x+\deltat) = sin(x)+\deltatcos(x)$

ocean sealBOT
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Elonmosqito96
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

neon moss
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hmm

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yeah idk

arctic wren
#

So..., most thing thing that humans invented, how humans behave has relation with math and normally what appear is pi, e, the golden ratio or prime numbers. I my experience pi normally appears in periods, the golden ratio with ratios , thus they can't appear, at my point of view on the stock market. Is there a relation between primes or e with the stock market ? If not exist a paper that dive into this though ?

quartz beacon
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aliás, tu é br e isso é mt foda

alpine sable
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math is nature

vague coral
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math is everywhere

alpine sable
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even in my house??

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thats creepy

vague coral
#

yes

arctic umbra
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ya

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n0 is 55572

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the growth rate is 0.05

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111144 is the number of cases that r doubled

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you have 111144=55572(1.05)^t

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solve

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you can simplify to 2=1.05^t

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then use logs

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easiest way is to use logs

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this is occupied rn

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but i can tell u after

golden wharf
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Ok

arctic umbra
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you get log 1.05 (2) = t

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and thats ur answer

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just plug everything in

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if its an equation and you have everything except one variable you just solve

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~isolate the variable~

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ya

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111144=55572(1.05)^t

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when u work with exponential growth

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u should understand the parts

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55572 always represents what u start off with

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logs

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no

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do you know what a log

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like is

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?

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like if u had

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2^x=5

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how would u solve it

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mm

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and u got ur answer

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think of the 1.05 as the base

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log 1.05 (2) = t

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yea

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wdym?

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just see it and u get log 1.05 (2)= t

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like if its 2^x = 5

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i know its the same as log 2 (5)=x

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there r parts of a log

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the base

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the exponent

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the answer (idrk what to call it)

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yea

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u mean after u get the log?

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did u work with logs before?

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thats all u gotta do

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a log is just the inverse of an exponent

alpine sable
#

pls

arctic umbra
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mmk

alpine sable
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I have this formula that gives me the number of years it takes a population to grow

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but each year there is an amount of new inhabitants

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how do I add on to it

arctic umbra
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ok

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what variables r there

alpine sable
arctic umbra
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ok

alpine sable
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thats just an example

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I have to make a function that generates

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a time

arctic umbra
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hmm

alpine sable
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yeah but the part im stuck on is adding on to the new inhabitants

arctic umbra
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i just useed exponents not natural logs but

alpine sable
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ok

arctic umbra
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instead of the one u put

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u could do 1000(1.02)^t

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i was gonna say 1000(1.02)^t+50t but that doesnt work

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wait yes it does

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does the 2 percent include the 50?

alpine sable
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no

arctic umbra
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yea

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mine works

alpine sable
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ok

arctic umbra
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for the second year its 1140.4 not 1141

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so idk if mine isnt

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hold on

alpine sable
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ok

arctic umbra
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yea nvm mine dont work

shut tartan
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hello how would i solve this

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Log2^x=3,7

arctic umbra
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this is taken

shut tartan
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oh ur taken?

arctic umbra
#

this channel -.-

alpine sable
shut tartan
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aww that sucks u kind of cute

arctic umbra
#

🖐️anyways

ionic jewel
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wow his username checks out

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he's down bad

arctic umbra
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right

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my brain isnt working rn @alpine sable

shut tartan
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ok stop bullying me

arctic umbra
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idk im like not getting one

shut tartan
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help me when u guys r done thanks😊

arctic umbra
#

is ur log 2^x in base ten

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or did u mean log 2 (x)

shut tartan
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the answer is 12.906

shut tartan
arctic umbra
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the 3,7 is supposed to be there

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right

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?

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how would u get multiple answers

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@shut tartan

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bruh... you meant to put log 2 (x)= 3.7

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i cant 🖐️

alpine sable
arctic umbra
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its not base 10, 2 is the base

alpine sable
# shut tartan Log2^x=3,7

You can rewrite the variable power od the log as the coefficient then put the log 2 as the base in the right hand side

arctic umbra
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you just do 2^3.7= 12.996

alpine sable
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Yeah

arctic umbra
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😦

alpine sable
#

2 is the base

arctic umbra
#

yea

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the comma got me good

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thought there were 2 solutions like ???

alpine sable
#

I was flummoxed for a while as well haha

arctic umbra
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anyways

alpine sable
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lmao

left echo
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can somebody help me w this cus i’m getting the wrong answer and idk what i’m doing wrong

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the answer is supposed to be 2x^2 - x + 5 - 17/2x+1

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but how am i supposed to get 2x at the start when u just bring down the 4

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when u use synthetic division

dusk hearth
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does anyone know how to solve this (btw it is substituting values into formula)

arctic umbra
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someone already posted above you

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but u need more than that one equation if u have 2 variables

mint urchin
dusk hearth
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ah ok, thanks for the help anyways

proper fern
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@dusk hearth simply the answer is in terms of other variable here for example

5x-4y = 1
x = (1+4y)/5
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thats the solution

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you can then substitute x in equation and get value of y

mint urchin
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wow youre right, i forgot you can solve it like this.

tacit mortar
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hi

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i take channel

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ig

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for this question i got this as my answer $[-1 - \sqrt{3}, 0) \cup [\sqrt{3} - 1, \infty)$

ocean sealBOT
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idkwhatnametoput

tacit mortar
#

Right or wrong

shut tartan
rigid smelt
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,w 1/x - x/2 <=1

quasi venture
#

can someone pls help, i've been stuck for ages

rigid smelt
tacit mortar
#

ty

rigid smelt
quasi venture
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so it would be (25xy^2) ^ 2

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?

rigid smelt
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Yes

quasi venture
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wait wouldn't it be 1/2 not 2?

rigid smelt
#

now apply every single expoenent rule you can remember

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Yesh 1/2

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You wrote

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Oh you wrote 2

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Oops

quasi venture
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alright ill try it ty

peak tiger
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can someone help me with (a)?

rigid smelt
#

What have you tried

peak tiger
#

I've tried subbing in 1 and 1+h into x

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it wasn't the answer though as I got like (-6+2h-2h^2)/h

rigid smelt
#

Thats wrong

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You have to apply the slope formula

peak tiger
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(y2-y1)/(x2-x1)?

rigid smelt
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Yes

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Where x_2 and x_1 is 1 and 1+h

peak tiger
#

that's what i've been doing

quasi venture
rigid smelt
#

Ok someone has to move now

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,w 6(1+h)- 2(1+h)^2

rigid smelt
#

Yeah you didnt expand it correct or something

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You should get -2h^2 +2h +8

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For the numerator

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Check your work again

gaunt magnet
#

the answer i got
The function, F(x), is shown. State the intervals on which F(x) < 0

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correct?

rigid smelt
#

Channel is busy please move

gaunt magnet
#

😭

earnest rover
#

I have the following. I want to write an equation I just don't know how to put my idea down would like some input from yall fr.

So. We have P_1 = R(1-0.5) * 1.75^X
Where X is 2 weeks intervals.
However I want X to also change as this function continues!

I want 2 weeks to now become maybe 3 weeks to then become 4 weeks. And and on and on as P_1 grows.

gaunt magnet
#

LOL

earnest rover
#

Oops

rigid smelt
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Bruh

dark granite
#

@gaunt magnet Your work looks good

gaunt magnet
gaunt magnet
#

ok then thanks

dark granite
#

You're welcome

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This channel is open for questions

glacial hedge
#

Could someone explain a theorem in linear algebra to me it doesn't really make sense

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if Set S is linearly dependant and indexed and v_1 != 0 then there is v_j (j >1) is a linear combination of the preceding vectors

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why does it have to be preceding vectors?

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and why does it have to be indexed?

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<@&286206848099549185> ?

gaunt magnet
#

Hi bunny

ionic jewel
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hi usman

tacit mortar
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channel take

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taken or not?

glacial hedge
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and what that means

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why cant it be the vectors after it in a set>

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?

ionic jewel
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i mean thats probably also true

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just not what the theorem says

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basically if you go left to right on your linearly dependent vectors, eventually you will get to one that's a linear combination of all the previous ones

ionic jewel
glacial hedge
#

wait so we are saying that by using preceding vectors we are limiting the set?

ionic jewel
#

you are limiting what you need to check, yes

glacial hedge
#

Ok i'll aks my teacher xD

tacit mortar
#

i got 6 as the answer just say yes if im correct

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had to round to nearest minute

ionic jewel
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,w -5 = 2t^2/(t+1)-15

glacial hedge
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it should be 6 minutes

tacit mortar
glacial hedge
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oh

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im blind

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i saw 5 xD

ionic jewel
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t = 5.84, so yes

tacit mortar
ionic jewel
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yep

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good job

glacial hedge
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yep deez nutz

tacit mortar
#

Cross multiply
(X-6)²<=(x+2)²
x²+ 36 -12x<=x²+4+4x
32<=16x
2<=x

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got this correct?

ionic jewel
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,w (x-6)/(x+2) <= (x+2)/(x-6)

topaz scaffold
tacit mortar
tacit mortar
upper pebble
#

it doesn't look like Wolfram's answer is the same as yours

topaz scaffold
#

Mmm

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And I trust Wolfram Alpha

upper pebble
#

x^2 - 12x + 36 <= x^2 + 4x + 4
-12x + 36 <= 4x + 4
-16x + 32 <= 0
-16x <= -32
x <= 2

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so we know 2 is greater than or equal to x

tacit mortar
#

yes

upper pebble
#

and -2 would result in a denominator being 0, so we also know x is greater than -2

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same thing with 6

tacit mortar
#

yes

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so the answer is either x>6

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or

pearl marlin
#

Solve taking rhs on lhs

upper pebble
#

idk where those integer solutions come from though

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oh nvm

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because +-1 and 0 are between -2 and 2, and 2 is of course 2

topaz scaffold
pearl marlin
topaz scaffold
#

Ah

upper pebble
#

so doesn't that also mean all integers greater than 6 are solutions

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yes ok

topaz scaffold
#

Should be

pearl marlin
#

it will

pearl marlin
#

$\frac{x-6}{x+2} -\frac{x+2}{x-6} \leq 0$\ $\frac{-16(x-2)}{(x+2)(x-6)} \leq 0$

ocean sealBOT
#

learn4math

tacit mortar
#

ok so do yall get -2< x < 2

pearl marlin
#

see it should be negative or equal to zero , now only posability are $-2 < x\leq 2$ and $x>6$ , you can easly check

ocean sealBOT
#

learn4math

tacit mortar
#

so the answers are either $-2 < x\leq 2$ and $x>6$

ocean sealBOT
#

idkwhatnametoput

pearl marlin
#

yes like $(-2,2] \cup (6, \infty)$

ocean sealBOT
#

learn4math

tacit mortar
#

i get it

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one sec

tacit mortar
#

after solving it all

tacit mortar
opal wyvern
opal wyvern
#

bumpy

rigid smelt
#

you are misunderstanding

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the first derivative is the speed, but the sign of that derivative does not represent if the speed is slowing down or accelerating

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the sign of the second derivative, or the derivative of the speed, shows that

topaz scaffold
#

Looks like a physics 1 question

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Usually people don't know calc then

rigid smelt
#

pretty sure its not physics

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because this is a very typical exercise of calc

topaz scaffold
#

I took physics just last year

rigid smelt
#

trust me but i take physics too

topaz scaffold
rigid smelt
#

physics questions are not this easy

topaz scaffold
#

Hmm

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At the start of the year I got many questions like that

topaz scaffold
# opal wyvern

Anyways it slows down at the right of the bumps and speeds up down on the left I believe

rigid smelt
#

Please dont give out answers

topaz scaffold
#

Oh why?

rigid smelt
#

People are here to learn and not to get spoon-fed

topaz scaffold
#

Welp there's still another question

rigid smelt
#

(Not directed to anyone, just generally speaking)

topaz scaffold
#

Sorry 😅

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To tell if the function is speeding up or slowing down you think about if the second derivative is positive or negative with positive being speeding up and negative being slowing down

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You can find the sign by looking at the concavity of the function

vagrant kayak
#

hellow

dark granite
#

What have you tried so far?

vagrant kayak
#

ok

dark granite
#

@vagrant kayak

vagrant kayak
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i have tried till

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i got the value as

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2(n!)=1152

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and then i dont get it

dark granite
#

That's wrong

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You should have $2(n!)^2=1152$

ocean sealBOT
#

logician_pdx

vagrant kayak
#

yeah

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typo

dark granite
#

kk

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so divide both sides by 2

vagrant kayak
#

ok

dark granite
#

and then square root

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both sides

vagrant kayak
#

ok

dark granite
#

let me know what you get for n!

vagrant kayak
#

ok

#

oh i got it

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n=4

dark granite
#

yes!

vagrant kayak
#

right?

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yay

dark granite
#

nice job

vagrant kayak
#

😄

dark granite
#

Any other questions?

vagrant kayak
#

u good in chemistry?

dark granite
#

nope

vagrant kayak
#

oof

dark granite
#

this is a math server lol

vagrant kayak
#

ik

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ok will u do one thing

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i will send screenshots

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of my homework

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and the answers

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will u check them?

dark granite
#

okay it depends on what kinda questions they are

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but I can take a look

vagrant kayak
#

pnc

dark granite
#

oh I'm good with that

vagrant kayak
#

permutations and combinations

dark granite
#

yes

vagrant kayak
#

omg

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ok

dark granite
#

you gonna dm them to me? or post em here? either is fine

vagrant kayak
#

dm would be better ig

dark granite
#

kk sounds good

vagrant kayak
#

ok

dark granite
#

I'll open up this channel for other questions then

#

This channel is open for questions

opal wyvern
#

Why did my wife leave me

zenith hemlock
#

-ke^(-2k) = -3
e as exponential. find k. Help please.

fallow jasper
#

Lambert W function

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$-2ke^{-2k}=-6$

$-2k=W(-6)$

$k=\frac{-W(-6)}{2}$

ocean sealBOT
#

Blackdeath39

tacit mortar
#

Hi

#

for this question i got this as my answer $[-1 - \sqrt{3}, 0) \cup [\sqrt{3} - 1, \infty)$

ocean sealBOT
#

idkwhatnametoput

tacit mortar
#

right or wrong

cobalt ledge
#

Wew

buoyant edge
#

!!

dull olive
#

I can't solve this for the life of me

tacit mortar
dull olive
#

Oh sorry, I'll post my question somewhere else

tacit mortar
#

its ok 👍

pearl marlin
#

Make quadretic in 2^x

pearl marlin
dull olive
sturdy glen
#

if I already know the eigenvalues of a matrix, how do i find the eigenbases?

pearl marlin
sturdy glen
#

is that just the same as the eigenbases?

tacit mortar
pearl marlin
upper pebble
#

,w 1/x - x/2 <= 1

pearl marlin
ocean sealBOT
#

learn4math

tacit mortar
#

👍

alpine sable
#

How can I get the average value of this graph (positive)?

rich basin
#

i entered 40 into it because it is the highest value, however it is apparantly wrong

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But i don't get why is that the case

rich basin
#

<@&286206848099549185>

acoustic abyss
#

help plz

rich basin
#

sorry this channel si busy

dense rock
#

Boruto look at the question from different perspective - they ask what is the maximum of f(x) - in order to do that you need to differentiate f(x) once, you'll get a quadratic equation to solve

alpine sable
#

what do i have to multiply 2^x by to give 2^-x?

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anyone?

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2^(-2x)

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yes

rich basin
#

@dense rock Yeah that is what i did and when i instert 40 and the local maximun, it is not the global maximun

alpine sable
#

oh ok

#

ty

dense rock
#

(40 is not one of those x's)

rich basin
#

but then 40 is greater than one of the xs

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when plugged into the function

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when i plug 40 in, it gives out 3333.333

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whereas when i plus in 15, the local maximun

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it gives out 2213

low gorge
ocean sealBOT
#

Leopard

rich basin
#

@dense rock but then 40 is greater than one of the x's when plugged into

dense rock
rich basin
#

so the answer is wrong?

dense rock
# acoustic abyss

Please send the full question , it's not understood what needs to be done

dense rock
rich basin
#

@dense rock it is using 15 for the answer

dense rock
#

then the book is wrong, they differentiated the equation, but forgot to check the boundaries👍

acoustic abyss
unborn sleet
#

Hi guys, I have a question that may seem dumb, while I was reading a textbook I found this: "(v^2-9) has no common factors other than 1 and -1", I do understand the 1 but why also the -1?

somber osprey
#

a

nova anvil
#

is the normal riemann/darboux integral $\int_a^b f(x)dx$ by definition only meant to deal with bounded functions?

ocean sealBOT
#

Anticipation

nova anvil
#

ah nvm i think i know why it is true

grand sundial
#

excuse me, may I ask why this is the case?

slim siren
# grand sundial

because if you sub 1 in to that equation there are no values because the number inside the brackets will equal 0, ultimately making 0 = 0 which means that there are no values for y

#

not sure if thats a good explanation but let me know if you want me to elaborate

grand sundial
#

alright, thanks for the explanation, I understand it now, greatly appreciated

tender plinth
#

not sure on how to do (i)

thorn tapir
#

Similar triangles?

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r/R = x/(x + d)

tender plinth
#

Ahh

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aight i got it thanks

#

that was so dumb of me

thorn tapir
#

No problems, always glad to help

tender plinth
#

thank you

thorn tapir
alpine sable
#

is it possible to do this without a calculator?

dawn wraith
#

Take log base 7 on both sides.

#

And from there I suppose it’s impossible.

#

But there must be some kind of way

#

Or an approximation

alpine sable
#

oh ok thankls

dawn wraith
#

Just found a way.

#

@alpine sable
I’ll give you a hint, try using the derivative.

rich basin
#

i need help with (b)

dawn wraith
#

Use the derivative.

#

Take it with respect to r.

thorn tapir
dawn wraith
#

Or just send him the answer, why don’t ya

thorn tapir
#

For why it gives the maximum value, you need to do another derivative of dV/dr

#

to get d^2V/dr^2

#

put the calculated value of r there

#

if the expression is negative, the value is indeed maximum for that r

upper pebble
#

nice fingers

thorn tapir
#

I'm slowly turning into a ghost

dawn wraith
#

He should do it by himself, not just get the answer as if it was free bud.

upper pebble
alpine sable
#

what happened here

#

from first to last line

#

could someone please explain why I have to reject negative for x=plus or min square root 7

#

when finding x

rich basin
#

You can't have negative answers in logs

#

How do you even find for xlnx

thorn tapir
rich basin
#

So there is no other way doing it algebraically

thorn tapir
#

actually wait

#

you know n log x = log x^n

#

?

rich basin
#

yes

thorn tapir
#

Yeah try that

rich basin
#

so you mean x^2 = e^1

thorn tapir
#

no

#

x^x = e

rich basin
#

yeah

#

that is hard as well

manic quail
#

||Use Lambert W function||

thorn tapir
#

Can i see what is the question

alpine sable
#

😭

rich basin
#

This an example question

alpine sable
#

the room was MINE stareFlushed

thorn tapir
#

.... actually true.

jagged raptor
#

newtons method and a couple hours lol

rich basin
thorn tapir
#

you are given the value already

rich basin
#

even if, but how can we use Lambert W function

#

to find the values

thorn tapir
#

you don't need it

rich basin
#

how do we use it though if we don't have the values

alpine sable
#

you don't analytically

manic quail
#

There's no button on your calculator, I presume, so you will need to use a computer.

alpine sable
#

but numerically

thorn tapir
#

You can use some identities but I doubt any numerical value can be done by hand 😂

#

The function is kind of crazy

#

leave it to the computers

rich basin
#

so to use Lambert W function you need a computer?

manic quail
#

You can't compute it otherwise.

rich basin
#

okay

thorn tapir
#

..uhm Yeah

manic quail
#

But in your case, x=e^{W(1)}

rich basin
#

then how do we do d

#

please

#

I got e^x(1-4) = 0

#

and then x = ln(0)k, but that would be an error

thorn tapir
#

derivative

manic quail
#

Take the derivative, and set it equal to 0.

rich basin
#

That is what i used

#

part (a) has the derivative i used

thorn tapir
#

nice

rich basin
#

but then i did not get the answer

thorn tapir
#

you're getting there

rich basin
#

e^t(1-4)

#

and make it 0 to find the stationary point

#

which would mean e^t = 0

#

but then e has no way of becoming a zero

woven crane
#

they aren't both e^t

thorn tapir
#

yeah

plucky sleet
thorn tapir
#

if you did the derivative

#

set it to zero

#

it'll automatically give

#

e^(2t) = 4

#

and then you have e^t

#

put it back on y

rich basin
#

nice i managed to get the answer

#

thanks

thorn tapir
#

welcome 👍

rich basin
#

made a very noob mistake

alpine sable
#

Can anyone help me solving this problem?

glass lichen
#

looks seperable

thorn tapir
#

multiply the whole thing by sec^2 x

#

you'll get it

alpine sable
#

i tried solving it but i think i am wrong somewhere!

glass lichen
#

yeah, it's a seperable DE

#

$\cos^2(x)\dv{y}{x}=1-y$

ocean sealBOT
thorn tapir
#

Just take y and x in different sides

glass lichen
#

yeah... like I said

thorn tapir
#

you don't even need any integrating factors

echo python
#

how can I calculate the angle like this based on 2 coordinate sets?

#

maybe something with arctan?

glass lichen
#

since you can easily get the legs of the corresponding right triangle

sour basin
#

How do I get this help!

glass lichen
sour basin
#

Im not sure how to get the 1-(-1)^n/n

glass lichen
#

$\int \sin(nx)\dd{x}=\frac{1}{n}\int n\sin(nx)\dd{x} =-\frac{1}{n}\cos(nx)$

ocean sealBOT
sour basin
#

where did the (-1)^n come from?

glass lichen
#

plugging in x=pi

#

since cos(integer multiple of pi) will either be 1 or -1

sour basin
#

Oh is it because this has multiple solutions

glass lichen
#

$\cos(n\pi)=1$ if n is even and $\cos(n\pi)=-1$ if n is odd

ocean sealBOT
sour basin
#

Oh

#

Ohh Ok

#

So n accounts for that change

#

(-1)^n

glass lichen
#

yes

#

$n\in\mathbb{Z}\implies \cos(n\pi)=(-1)^n$

ocean sealBOT
sour basin
#

also just a question

#

im kinda confused on whats the point of a fourier series

vale sapphire
#

okay

#

so, especially in physics, a lot of times you submit some system to a given signal, and see how it responds

#

for many systems (electrical, anything that has to do with waves, so really a lot of things), the response is basically linear

#

meaning that the response to a sum of signals is just the sum of the responses to each signal individually

#

As it turns out, sinusoids are rather handy signal shapes

#

they model oscillations which you find all over the place in physics

sour basin
#

Oh

vale sapphire
#

And they're simple enough that you have good tools to calculate the responses to sinusoids in a lot of cases

#

For example with electrical systems

sour basin
#

But it seems that most of the function that I calculate arent really sinosoidal in nature like Lines, then discontinuity

vale sapphire
#

But of course, not everything is a sinusoid

#

the step function is a common example of this

#

What Fourier showed is that any signal can be decomposed into a sum of sinusoids of different amplitudes and frequencies

sour basin
#

Oh

#

And it is given as a function

vale sapphire
#

Since it's a sum, you can use the linearity of your system, and only consider sinusoidal responses

#

And you're then easily able to calculate the response to the actual signal

sour basin
#

So if we have a contuinity would the funciton converge to a point?

vale sapphire
#

a discontinuity?

sour basin
#

Yea

#

How can something converge to a value if its repeated over time

vale sapphire
#

(There are some technicalities : for example, periodic signals have a nice Fourier expansion ; a discrete sum of sinusoids with all frequencies being integer multiples of a base frequency. For non-periodic signals, that becomes an integral)

#

Hang on, there should be some nice animation somewhere out there

woven crane
vale sapphire
#

here, you see a rectangular wave being progressively approximated with sums of sinusoids

vague coral
#

I've seen someone doing animation on Desmos while using Fourier

sour basin
#

Oh Ok

#

Then for all x in the interval (p, p) the Fourier series of f converges to f (x) at a point
of continuity

#

What does this mean

vale sapphire
#

It means that if a function is continuous as a given point, the sum of sinusoids will get arbitrarily close to the function's value at that point

sour basin
#

Oh

#

so like an accurate estimate

vale sapphire
#

yeah, "arbitrarily close" is what a limit is

sour basin
#

Mk

#

Ohhh Okay i get it

#

So like at every x value the function will converge to f(x) but if x is a discontinuty it will converge to f(+x) + f(x-)/2

vale sapphire
#

if x is a discontinuity who knows

acoustic sableBOT
vale sapphire
#

wrong command

echo python
vale sapphire
#

it might converge to some arbitrary value, or it might not

sour basin
#

Kk

vale sapphire
acoustic abyss
#

anyone b bit plz?

acoustic abyss
alpine sable
#

its not -3y

#

u move the 3 to the rhs

#

leaving only the y

sour basin
#

is this integration right?

vale sapphire
#

yes?

glass lichen
#

looks right

sour basin
#

Nvm it is

glass lichen
#

$\frac{2}{L}\left[\frac{x^3}{3}\right]_0^L$

ocean sealBOT
south mesa
#

Can someone explain this please

#

I don’t understand how to do it

acoustic abyss
#

3rd bit?

#

<@&286206848099549185>

tepid crystal
#

Can someone explain how this happened ?

glass lichen
#

$e^{\ln(x)}=x$

ocean sealBOT
glass lichen
#

$n\log_a(x)=\log_a(x^n)$

ocean sealBOT
tepid crystal
glass lichen
#

I mean that's how logs are defined catshrug

tepid crystal
#

I am not taught logs properly yet.

#

was just doing some extra questions

vale ridge
#

the endpoints of a diameter of a cirlce are A(6,-8) and B(-7,-4> What are the coordinates of the centre of the circle.

quartz lark
#

Yo

#

r(t)=(t,9-t,2t)

#

What is the curve of this vector

glass lichen
#

you mean curvature?

south mesa
# vale ridge the endpoints of a diameter of a cirlce are A(6,-8) and B(-7,-4> What are the co...

Use distance formula to find the diameter. Divide it by 2 to get the radius and plug it into the equation of a circle. Then make an equation for both points (ex: (6-h)^2 + (-8-k)^2 = r^2 ). Since they are both equal to r^2, set them equal to each other and simplify. Make one of the variables equal to an expression containing the other so that you can use substitution. Then use substitution to find the value of one variable, and then use that value to find the value of the other variable. Once you know h and k you know the center point.

glass lichen
#

$\kappa (t)=\frac{\abs{T'(t)}}{\abs{r'(t)}}$?

ocean sealBOT
vagrant rover
#
        
0°
        
12.2°
        
17.1°
        
35.0°
        
73.2°

Is this 17.1 deg?

upper pebble
#

also you're not supposed to ping the Helpers role unless your question has been unanswered for 15 minutes according to #❓how-to-get-help

unreal depot
#

can some1 help me out

alpine sable
#

You know there are 3 red, 7 black and 5 green, which is a total of 15 marbles.

vale wigeon
#

or to make that less superfluous, 7 black and 8 not black for a total of 15

alpine sable
#

The probability that the first marbles selected is black is 7/15

#

If there is no replacement, that means that the second time you pick a marble, there will only be 6 that are black.

alpine sable
#

And a total of 14 marbles

shrewd otter
alpine sable
#

Which means that the probability of picking a black marble the second time is 6/14

#

You should do this two more times and multiply all the probabilities you've got

echo python
#

I have 2 vectors, [x, y, z] and [x, y, z]. How can I calculate the 180 degree angle between both y coordinates?

echo python
#

?

alpine sable
echo python
#

only the y values, I can already calculate the angle between x and z with an arctan formula

shrewd otter
#

The angle between two y values is... 0.

#

Since they're colinear.

echo python
#

huh

shrewd otter
#

Well, 0 or 180.

echo python
#

actually I meant, z, my bad. so basically the height degree

#

say one vector is like [0, 0, 30] and the other [0, 0, 45] then the angle would be 45 degrees or so

#

talking about coordinates here^^

thorn tapir
#

they lie in same line

#

the example you provided

echo python
#

wait thats right

#

okay wait let me grab real world vectors, one sec

jagged trout
alpine sable
#

Lau, what are you trying to do aimbot or something?

echo python
#

well yeah and no. I'm trying to make a video game character that shoots the player

alpine sable
#

If you have a direction two direction vectors, turn them into euler angles

#

easier to work like that

echo python
#
83.9572 170.509 11.5``` the vectors for reference; first one is the AI the other one is the player
jagged trout
#

Did you use Unity?

echo python
#

no, I'm challenging myself to code it entirely myself

alpine sable
#

Those are already angles

#

Or is it origin

echo python
#

its x, y, z

#

x for length y for depth z for height

alpine sable
#

So you take the two vectors subtract them from eachother and normalize them

#

Then you negate it, and it will be 180

unreal depot
#

any1 down to help?

shrewd otter
echo python
shrewd otter
#

Actually, this chat is occupied, you dunderhead.

alpine sable
#

Negating a number is just like

#

if you have 2 and you negate it. its -2

unreal depot
shrewd otter
#

Someone is already using this chat to have a question solved.

echo python
#

so basically inverting the number so -2 becomes 2 and 1 becomes -1 or like reverse absolute?

alpine sable
#

I'm only saying it you should negate it, because you mentioned you wanted to turn it 180

shrewd otter
#

You can't bump in and bury their problem.

echo python
#

no

#

I want to calculate the value of the rotation needed

alpine sable
#

So if you have a direction vector, and you negate it - it will point in the opposite direction

echo python
#

for the AI to point at the player

#

based on the coords of the player and those of the ai

#

but only the y value considering I already have the rest

alpine sable
#

Right so

#

You have two player coordinates - p1 and p2

#

if you want p2 to point at p1, you do:

(p2 - p1)

#

Then you have a direction vector that points from p2 to p1

echo python
#

huh, wouldn't that just be the difference between the coords

alpine sable
#

Yes, but that's also a direction

echo python
#

then just multiply the difference of the y value by pi / 180?

#

wait

alpine sable
#

well, that thing

#

is turning the direction vector into euler angles

echo python
#

wait is that what a euler angle is

#

that might actually be what I need

alpine sable
#

atan2( diffVec.y, diffVec.x ) * 180.f / 3.14

#

= y

echo python
#

why x instead of z?

alpine sable
#

what do you mean instead of z

echo python
#

the vector has x, y and z

#

its 3d

alpine sable
#

yea, i understand, but you dont need Z in the angle

echo python
#

but then wouldn't it only work if the ai is next to the player on the x axis?

alpine sable
#

ok, so

#

after calculating p2-p1, u have a direction vector. lets say it could be x 100, y 50, z 20

#

But what u want is an euler angle, so u gotta translate it.

#

U didnt need to do this if the game accepted a direction vector, so it doesn't.

#

This angle kinda looks like a vector, but its not 'x y z', its 'pitch, yaw, roll'

#

the Z component in the angle is the roll, you dont need this

#

like if you change roll, you will 'tilt' your view

#

if you change roll enough, it will make ur player be 'upside down'

#

you cannot be upside down in assault cube, so thats why i say you dont need z

#

roll is good in airplane games, because you can turn your plane upside down, but not in assault cube

echo python
#

ahhh like that

alpine sable
#

so

#

u know how to calculate p2 - p1, and apparently you figured out how to find pitch

#

and i showed u the formula for yaw

#

and roll, you set that to 0

echo python
#

alrightt

#

thanks a lot

alpine sable
#

np

#

@echo python
p2 = 108.778 200.503 5.5
p1 = 83.9572 170.509 11.5

diff = p2 - p1

Normalize(diff);

angle.pitch = atan2( -diff.z, diff.Length2D( ) ) * 180 / 3.14
angle.yaw = atan2( diff.y, diff.x ) * 180 / 3.14;

#

so this

echo python
#

allrightt

#

I had

float nLrRot = std::atan2(target.coords[1] - coords[1], target.coords[0] - coords[0]) * (180 / PI) + 90;
float nUdRot = std::atan2(target.coords[2] - coords[2], target.coords[1] - coords[1]) * (180 / PI);
#

again, thanks a lot

shrewd otter
#

You should really be using tuples or dedicated types.

ivory granite
#

can someone help me with this

thorn tapir
#

Just simply find f'(x)

#

and check where f'(x) is > 0 and where < 0

#

if less than zero, then decreasing

#

and if greater, increasing

#

the question seems to have multiple options correct

ivory granite
#

OOHHH

#

tysmm

shrewd otter
glass lichen
#

yeah it doesnt

thorn tapir
#

maybe, I haven't did the calculations myself so I can't.be sure

shrewd otter
#

Doesn't matter, the given options are all mutually contradictory.

thorn tapir
#

Oh right, they have interchanged the state of the graph in C an D

#

oh, my mistake

rich haven
#

is this a?

shrewd otter
#

No, because those two triangles have the same 3 angles.

rich haven
shrewd otter
#

Ah, right, they don't have to be.

rich haven
#

so its a?

shrewd otter
#

Seems like it.

#

There may be more than one correct answer, though.

echo python
#

thanks for putting me on the right track, tho

alpine sable
#

oh ok

alpine sable
#

@echo python actually, thats exactly the same as i sent u, just written differently xd

echo python
#

oh

serene flame
#

so i'm taking a look at the parametrization method to solve surface integrals. just learned those. and i can't understand why r(u,v) should be <2cos u, 2sin u, v> given S is x^2+y^2 = 4.
Above is the full problem

dry thunder
#

any help?

serene flame
#

sure

#

i'm supposing you're trying to find y

dry thunder
#

ye

ionic jewel
#

the v is a different variable for height, 0<=v =<8

#

i don't know a mathmatical way to show it off the top of my head but it's just the circle parametrization

#

unit circle of radius 2

#

x = 2cos(theta), y = 2sin(theta)

serene flame
#

first off normalize 2y so that it coincides with the other denominators. you can easily do this, just multiply 2 by 3 and divide by 3, and you get 6y/3. Then multiply (4y-1) by 2/3
you get (8y-2)/3. Then distribute the minus sign to the new (6y/3 - (y+1)/3) and you overall get

(8y-2)/3 - 6y/3 + (y+1)/3 -y/3 = 4/3

ebon prism
serene flame
#

now you can straight up cancel the denominators by multiplying both sides by 3 and all that's left to do is sum the y terms and the known terms and get 3y-1 = 4. y is 5/3

ebon prism
#

am i supposed to put arrows on the close circles too

#

?

serene flame
serene flame
dry thunder
#

thanks @serene flame

#

appreciate it!!!

serene flame
#

yw

ebon prism
serene flame
ionic jewel
#

replace x and y as u and v if you care

#

with the restriction that x and y are both larger than 0 and x+y < 1

serene flame
#

oh so it's not obligatory, also, so, z is reformulated. So if i got S = 1+x r(x, y) should be
<x, y, 1+x>

#

having a bit of a hard time with getting r

vagrant rover
#

(A) force x distance 
(B) work x time 
(C) force x acceleration 
(D) force x velocity ```
#

Is this D?

void yoke
#

P = E/t

#

E = 0.5mv^2 or mgh or fd

#

Yes d looks good.

vagrant rover
#

Awesome aweosme

#

thanks!

gray oxide
#

Hello

#

Question:

#

A cylindrical tank contains 20 000L water

#

Through a hole in the tank water runs out

#

Volume V after time t given by the formula

$$V(t) =20 000 - 800t + 8t^2 $$

ocean sealBOT
#

!callidus

gray oxide
#

The tank is empty after 50min

#

That is question A)

#

But question B) is

#

In the interval 0<t<a the speed of the water running through the hole is 600L/min decide a

#

How do I start with this?

glass lichen
#

can you post the question as written?

gray oxide
#

Sure

#

*in the interval of 0<t<a the speed of the water running out is 600Liters/min. Decide a

the formula is
V(t) =20000-800t+8t^2

and water runs out after 50min*

gray oxide
glass lichen
#

I meant a picture of the question

gray oxide
#

Do you read Swedish?

alpine sable
#

A steel ball bearing is dropped from the roof of a building (the initial velocity of the ball is zero). An observer standing in front of a window 120 cm high notes that the ball takes 0.125 s to fall from the top to the bottom of the window. The ball bearing continues to fall, makes a completely elastic col- lision with a horizontal sidewalk, and reappears at the bottom of the window 2.0 s after passing it on the way down. How tall is the building? (The ball will have the same speed at a point going up as it had going down after a completely elastic collision.)

#

What does the second part of the problem mean? Does it mean that it takes 2 seconds for the ball to appear in the window at the top, and then again at the bottom when it comes back up

#

Or does it mean that it will be done passing it, and then come back up after 2 seconds

alpine sable
gray oxide
#

Hope you understand the explanation easily

alpine sable
#

What does part a) and b) ask?

gray oxide
#

I'll try to be clearer srr

#

Part A was

#

"how long time will it take before the tank is empty"

#

I got that question right and it was 50min

#

And I thought that maybe this info will be used in the B answer becuase my textbook does that a lot

#

The B part was

#

"in the interval of 0<t<a the outstream(outflow?) speed is 600liter per min, decide a"

#

Does this make sense or what part is not making sense so I can try and be more clear?

alpine sable
#

Yeah so V'(t) = -800 + 16t, and so you want -800 + 16t = 600, which gives you 1400 = 16t and therefore t = 87.5

gray oxide
#

No I did that and that was wrong sadly :(

#

Do you wanna know the correct time or do you like to keep it mysterious?

glass lichen
#

did you perhaps forget the word average speed...?

#

and that 600L/min is an average?

alpine sable
#

Wait something is wrong

#

It can't be an interval even

glass lichen
#

because as written you cant solve it

gray oxide
#

In the question it says that between 0 and a seconds/min /hours cuz i don't know what a is the speed is 600L/min

glass lichen
#

didnt answer my question

#

at all

gray oxide
#

That means no

glass lichen
#

I asked if 600L/min is an average speed

gray oxide
#

There was no average word or similar word

#

It just said

#

600l/min

glass lichen
#

Ok then talk to your teacher, cause as written you cannot answer it.

alpine sable
#

@gray oxide What is the answer?

gray oxide
#

That's the answer

alpine sable
#

That's the average rate lol

gray oxide
#

I guess I should have assumed so then lol

alpine sable
#

V(a) is the volume at a minutes, and V(0) is the initial volume, divided by the elapsed time a, you get the average speed.

gray oxide
#

Ohhhhh

#

Lol

#

Gimme one sec I wanna solve dis

glass lichen
#

oh wow, average huh

gray oxide
gray oxide
alpine sable
#

I guess it can't be the derivative because the derivative is at a specific time, not an interval

#

So you were supposed to assume it is the average speed, however I don't like that

glass lichen
#

derivative is instantaneous rate of change

alpine sable
#

Yeah

#

So you would be finding the rate of change at a specific time, not an interval in your case

robust phoenix
#

hey guys i need some help

cinder wedge
winged mica
#

can someone check what i sent in #help-2

robust phoenix
# cinder wedge yes?

sinθ<0, m>0, tanθ=2m || find sin θ + cos θ
what should i do here
ik it needs to be a negative number both sinθ and cosθ

#

and i know tan = sin/cos

shrewd otter
#

So since sin < 0, cos must also be < 0.

#

So you know you're in the 3rd quadrant.

robust phoenix
#

yeah i just said it both needs to negative(below zero)

shrewd otter
robust phoenix
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huh

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idk what a bijective is

shrewd otter
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It means you can find θ.

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It's arctan(2m).

robust phoenix
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Hurubon

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I have no idea what you just said

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If you have a video/book that i can read that from

shrewd otter
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Every bijective function has an inverse function.

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So if g is the inverse of f, then if f(x) = y, then g(y) = x.

robust phoenix
shrewd otter
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arctan is the inverse of tan.

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But I don't know how you can use this.

robust phoenix
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well

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here's the answer

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it's 'b' but i have no idea how they got it