#help-0
1 messages · Page 699 of 1
(where it says -1)
wait this is linear approximations
lemme find the relevent formula
same answer
in the case of sin it means they have the same height
but please look up linear approximation to learn more
it's not hard, it's just easier to explain with graphs and stuff so a webpage would be better than me
no, you should learn how linear approximations actually work and apply it to your problem
it's basically using the derivative at a point you know (x=2 in this case), and linearly extending that to guess and points that are very close (x = 2.001)
i learned it in calc 1
it's reasonable to know if you know derivatives and have a bit of critical thinking, the topic isn't complex
no
okay
I'm gonna call it theta
instead of x
does ur class use radians or degrees
radians obviously for this I'm dumb
anyways
since theta is in the first quadrant, you know $0\leq \theta \leq \frac\pi2$
bunny
do you agree with this so far?
not you
yours has no theta or pi
clyda please just look it up, i can't explain it as well as a good video or website
you agree?
okay
so now we have
we are doing pi minus theta
so
$\pi-0 \geq \pi-\theta \geq \pi-\frac\pi2$
which is
bunny
sure if you want
what?
do you not see what or not how it's not in the second quadrant?
yes that's the power rule for derivatives
yes that is good
check the inequalities direction
lol yw, hopefully that actually helped
pi minus theta is greater than or equal to pi/2
okay
so what i did
take the original inequality
with the 0 to pi/2
then you want it to be pi - theta
so you can multiple everything by negative 1
then add pi
but either way this is just a proof that it's right
it's not actually understanding
it's basically subtracting the angle from pi, If that makes sense
because we want it to be pi minus theta
each of the three terms
and that's why you have to flip the less than to greater thans
when you multiply inequalities by a negative number
When y’all are done can I get help with smth pls 👩🏽🔬
no not at all
Wait wrong channel I think
$0\leq \theta \leq \frac\pi2$
bunny
start with this one
then do what i said
it'll show that pi-theta is in the second quadrant
Ignorw the sin and cos for now
pick an empty channel
What do I say there
you post your questions
you forgot to flip the inequalities
I have no math equations I need help learning smth
TheMane3
yes, but change the middle one to pi-theta, and simplify the rest, then you can see that (pi-theta) is in quadrant 2
i mean i guess it seems okay, but i wouldn't mention linear approximations unless you know how to do them
TheMane3
look at the last term
pi-pi/2 = pi/2
once you do that, do you agree that angles between pi/2 and pi are in the second quadrant?
i mean if you ever happen to need to prove it, you can do something like that
this worked specifically because you had theta and wanted pi-theta
but you don't really seem to understand why it works
here let me try an easier idea here
let's say you have a number
it's between 0 and 1 inclusive
lets call it x
what range of values could you get if you do 2-x?
what
why is 0.01 the smallest?
what about 0.001?
or 0.0000000000001
I've changed the problem to make it easier
x is now between 0 and 1 inclusive (could be 0 or 1)
now what is the range for 2-x
you what
2 - 0 = 0
would you like you rethink this
no not quite
what's the new range
not 0 to 1
yes fantastic
now let's say our x is between 0 and pi/2 (inclusive again)
what's the range of pi - x?
it's pi
pi is a number
you can do the same work as last time
why is this one so much harder?
well
<=, but yes
who cares
leave it in terms of pi
i don't care
ok
which is?
what's pi - pi/2?
okay
and pi-0 is pi
so the range is pi/2 to pi
right?
so the range is pi/2 to pi
wow this sounds an awful lot like the second quadrant
(it is)
that's why pi - x is in the second quadrant
ok
wait
what
that's a nonsensical statement
perhaps you mean to say (pi+x) is in the first quadrant, or x is in the first quadrant
no stop
sin(something) can't be in a quadrant
sin(something) evaluates to a number
the stuff you put inside the sin can be a quadrant
yes
sin(anything) isn't in a quadrant
uh
i don't think that's true
pi+x is in the third quadrant
pi - x is in the second
sin is positive for values in the second, but negative for values in the third
if x is first quadrant, all of those other ones are true, yes
would be sin(-x)
uhhhhh
well there's a few ways to prove it
but it should intuitively make sense if you can think about it on the unit circle
pi+x is third quadrant, x degrees away from the x-axis
-x is in the 4th quadrant, x degrees away from the x-axis
No but close
it's because the distance from pi+x to the x axis is the same as the length from -x to the x axis
remember sin is the y value, or height, or distance from the x axis
yes
yes
that is true
I'm not sure what that means so glad u got it urself lol
,w -sin(x) = sin(-x)
sin is an odd function so that's why that property works
my bad it's not strictly distance
the sign also matters
sin is positive in quadrant 2 remember
so it can't be equal to the same thing in quadrant 3
what we can say is that sin(pi+x) = - sin(pi-x)
yep
feel free to check both of those in wolfram
oh no
no no no
let's think about this for a second
where is 2pi?
yep
2pi = 0
so...
sin(2pi-x) = sin(-x)
yes
yep
Is the discussion going on here should I ask in another channel
signed distance to the y axis is right
new channel
ok
yes, you can also think of it as the x value
(like cos(0) = 1 because it's the point (1,0) and 1 is the x value)
but continue
uhh
pi + x is in the third quadrant
-x is in the 4th quadrant
cos is positive in one of those and negative in the other, so not quite
hint: ||cos is positive in the 1st and 4th quadrants|| DONT CLICK IF YOU WANT TO FIGURE IT OUT URSELF
yeah ur right anyways tho
,w cos(pi+x) = cos(pi-x)
tangent is sin(x)/cos(x)
yea
uh huh
well
that's true but it's not the intended solution
find another one
those are both in the 4th quadrant
cos is positive in one other quadrant as well
yea
yes
okay but
that's still not the intended solution
despite being true
well let's think about it
what is sin(pi+x) equal to?
wait
this ain't gonna work out like this
okay scratch that
is sin positive or negative for pi+x?
okay
how about cos for pi+x
find the sum of the following APs 2,7,12.......,to 10 terms
yes
so then for tangent
you have tan(pi +x) = negative/negative = positibe
so what other quadrant is tangent positive in?
hint:||it's where both sin and cos are positive||
yes
so tan(???)
,w tan(pi+x) = tan(x)
woah hold on
this ain't true
yes
no
that doesn't exist
you just care about the sign of tangent
yep
you want the other quadrant where tangent is negative
also wrong channel
hold the area near the message
if mobilw
on PC there's a drop-down on the right of the message
well idk what to tell u
just go find a new channel I'm working with mane
speaking of which, what's your answer mane
go ahead and check it with wolfram
go find a document of limit properties
Pleasee help me someone
Can u give me a example of what the answer of a would be
Cuz I’m still kinda confused
@alpine sable yeah thank you, i was overthinking it. It’s so easy and I was just thinking there was something else to it
Please help me know what the right answer is
My teacher said that my answer is wrong
I think 36
but 360/5 divided by 1/2
gives 144
one calculator of mine shows 36 and the other 144
360/5 is 72
Why times?
god use your order of operations
when you divide by faction
(360/5)/2=36
360/5 ÷ 2/1
=360/5 × 1/2
my alevel calculator shows 144 and my gcse shows 36
same
there
then why wold my a level calculator show 144
Help hehehe
oh i see thanks
remember that y=f(x)
Oh I get it, it says relative not absolute
Hey guys I have a question. f(x) has a domain of [-2,4]. What is the domain of f(x+3)
<@&286206848099549185>
@valid bone f(x+3) means the function is shifted 3 units to the left.
So the domain will be shifted 3 units to the left.
So would it be [-5,7]?
No
[-5, 1]?
Yes
Thank you
np
the middle part?
well if you're talking about $\frac{(t+1)-2}{t+1}=1$ part then it's cause -1 can also be represented as +1 - 2
わたし
the same way 3 can be represented as (5 - 2)
Yeah.... my head is so in algebra mode for some reason I saw that as -2(t+1) thank you 🙏🏻
no problem
I tegers
How can i factor this expression fast without foiling all the terms?
$x^2-y^2=(x-y)(x+y)$
G3oG0dly
The big sign? like the one between m=1 and 3?
Yeah that one
Well that's sigma
It's usually used for summation notation
What is summation notation?
a convenient and condensed way of writing out the addition of many terms. for example, $1+2+3+\dots+n=\sum_{k=1}^nk$
coycoy
In simple terms, it is the sum of a sequence
Since it starts at 1 and ends with 3, substitute all (integer) values that is within its range, and add them all up.
For this case, you only have to substitute 1, 2, and 3.
oh so substitute 1,2,and 3 in place of M in (2m + 1)^m-1. And then add the three results together?
That's right.
One example how to do these things:
$\sum_{k=1}^3{2k}\implies 2(1)+2(2)+2(3)\implies2+4+6\implies12$
Callaway
no
in your case $(2m+1)^{(m-1)}$ is the sequence
Ahhh alright alright
Callaway
Oh, okay
So what if we have a sequence of numbers, such as 1,2,3,4,5 and we want to find the sum of the sequence? Are we forced to manually add each integer together or is there a faster way to do it using an equation? @teal epoch
hmm.
well sometimes there some notation that has a faster way than doing it manually and sometimes there are no choices but to manually substitute it to the expression
for this case I don't think there's a faster way
what do you mean sequence of numbers such as 1, 2, 3, 4, 5?
is it 1+2+3+4+5 or the numbers you're going to substitute like this?
$\sum_{k=1}^5{2k+1}$
Callaway
2,4,6,8,10
A sequence
not for substitution @teal epoch
oh i see
welp uh same response ig
ah alright, tysm
Let G be a group of order 315 which has a normal Sylow 3-subgroup. Prove that Z(G) contains a Sylow 3-subgroup of G and deduce that G is Abelian
is the first condition necessary here?
The Sylow 3-subgroup has order 9 so it must be Abelian and be a subgroup of its centralizer
Can someone please help me with the transition matrix
mfw I forgot everything after passing LTAM😆
hello i have a question about fuctions
so when you draw a function
you need x to get f(x) the image
but if x is a none decimal number
how are you going to know where x is
like if x = 0,9999999999999999999999....
well that's x=1
$0.\overline{9}=1$
Mosh
but if you mean something like x=sqrt(2), then just eyeball it w/ a decimal approximation
and if it's a number like Pi how are you gonna knw now
pi ~ 3.14
yes
so put it just after the x=3 mark..
then tracing your function won't be exact right ?
nope
wait what @glass lichen how is that
unless it's trig in the case of pi 
yeah thanks
i like math a lot but i ask to much questions because i wanna know everything
so we just trace what about look like the function so we can study it
asking questions is op 💯
$0.\overline{9}=x \ 9.\overline{9}=10x \ 9+x=10x \ x=1$
i swear my brain is going to kill it self
Mosh
thanks
Thats confusing @glass lichen , how can adding 9's to the end ever make it to 1? that seems very weird
idk
Yeah math isnt suppose to be intuitive 
i guess it's a thing called uncertainty
no
oh
How is it not impossible to get to 1? If I imagine myself writing 9's at the end forever, how will I get to 1
not nine
but
0,999999999.....
to infinity
you are just getting closer to one
but not touching it
yes
yes, a decimal expansion with infinitely many 9's = 1
so saying its equal to one its kinda of confusing
is it just defined as such?
Cause it doesnt make sense that if I write infinite decimal 9's I will get to 1
yeah because a number represents a certain amount of stuff
yeah it doesnt make sense, but by the constructions of R they are the same number
R?
Real numbers
oh ye
and it's just gets to me
like when you are tracing a function you need those two axes
x and y
graphing*
my bad i study math in french so it's kinda hard to tell what i'm talking about in english
samee lol
uh so
I study math in french too
oh
in my country
i'm not french too
me too
I'm from morocco
me too
wait fr?
yeah
2x -3 = 1/2 * (x/3)
Maybe it may seem counterintuitive, but that's because we can't actually comprehend infinity, but it makes sense that if something goes closer and closer to 1 for infinity it equals to 1 itself. It's counterintuitive because infinity doesn't have an end from our point of view , but asking what does 0.99999... equals to , is like asking what it equals to with a "complete" infinity of 9s , so it actually becomes intuitive that it is 1
it would make sense that it gets infinitely closer, but how is that 1
help
The histogram on the left shows the number of hours students in a British Literature class read last week, rounded to the nearest hour. Which of the following statements offers the best description of the median number of hours students in the class read last week?
If we see math as counterintuitive it is because it can rappresent things that we would never understand with our own logic , as i said it is 1 because we consider infinity as a whole , so """"after""""" infinity, or when infinity is reached, it equals to 1
I see where that comes from, but its really counterintuitive
@sullen nova it tells you that b is right, no?
the easiest way to convince yourself imo is what would 1-0.999.... be equal to if not 0
and if you agree it is equal to 0 then they are in fact the same number
0.00...01 I guess
you can't have inf 0's then something after
eyah
so 0.0...1 doesn't make sense
hmmm ye
The problem is that you are treating infinity as something finite
thats true didnt think of that
three times one number added to another is 14. Twice the first number, minus the other number is 1. What are the numbers?
options are: 9 and 5, 10 and 4, 8 and 6, 3 and 5
it is just count how many is in each interval, then use definition of median
namely for odd amount of observations the median is the (n+1)/2th number
how to do
20 is between 0-4
add them all together
then calculate (n+1)/2
and see which interval that corresponds to
3 and 5
you tell me
if first 20 are in 0-4
then next 22 is in 5-9
so clearly 32 is in the interval 5-9
{21,22,23,...,42} is in 5-9
Because 3x+y=14
2x-y =1 , now to eliminate the y terms you multiplicate the second one by -1 , and you get
3x+y=14
-2x+y=-1
You subtract the second equation from the first and you get that x=3
OMG
do parallel lines have the same x-intercept
no
no
okay thanks
well because suppose y = log N (to the base b)
which signifies b^y = N
so now if you take b any negative integer for example -2, and you take y as 1/2
you get sqrt(-2) which leads us to complex numbers and then it becomes to difficult to comprehend [giving wierd irrational values]
because logs to base 1 are nonsensical, as are logs to bases that are zero or negative
yes, exponentials with base 1 or negatives dont make sense as exponentials
I mean I know one would argue that (-2)^3 = 8 and it does makes sense I agree... but then you can't calculate things like sqrt(-2) etc. which leads to many many exceptions, so we avoid the negative values along with 1 and 0 altogether
it's 4/9
you can always approximate a recurring decimal to a fraction
well yeah
but no, .4444.... is just that, 4/9
yeah that'll be the case for any recurring non terminating decimal number
it'll always have a fraction
i made 1 + 2cosx = 0 (x-axis) to show x-cords for A is 2pi/3 already, how do i find x-coordinate for B? Is it by cosine graph or can i use cos x = cos (360 - x)
cos(x)=-1/2 has many many solutions, but there are two general solutions
you can find B from the other general solution
6 × 14/8
Am i could simplify 6 and 8 become 3 and 4?
If yes, why?
and well you can use the identity that cos(x)=cos(2pi-x) but it might not give you B
channel is busy and yes, because 6 and 8 both share a factor of 2
And i Don't need to change 14 become 7 that have factor of 2?
lets move to another channel
Okay
sry for ping 🙏 but whats the other general solution? I solved with cos(2pi-x) and i got the answer shown on the paper
cos(x)=a for -1<=a<=1 have two sets of solutions:
x=a + 2kpi
or
x=-a + 2kpi
for integers k
wow wow nope
?
cos(x) = y (-1<= y <= 1) implies there exists -pi< a < pi such as : cos(x) = cos(a) = y and then x = a + 2kpi or x= -a + 2kpi for k integers
oh right, i forgot the arccos(a)
it's factorial
6! factorial means you need to multiply all natural numbers till 6
so 6! means 1 * 2 * 3 * 4 * 5 * 6
got you
no problem
ehh
that's not the biggest problem
if 0 were included, the factorial would be a dull function
lol yeah
always being equal to 0
it would always result in 0
for the record here the natural numbers include 0
wdym
Here, as it's taught, ℕ = {0,1,2,3,...}
How do you evaluate that
wow ok
Yeah on google it says sometimes natural numbers include 0
that's from the topic of combinatorics, you read it as "8 choose 6". Here is the formula:
then why are whole numbers there
can someone help me for my last question
If we want to exclude it we write ℕ*
what does choose mean here?
yeah see @vagrant rover here there are ! marks which means factorial
ahh alright
so 8 substituted for n and 6 for k?
It's quite a hard topic to explain, I would suggest watching these videos: https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:prob-comb/x9e81a4f98389efdf:combinations/v/introduction-to-combinations
Horrible formula alert!!! Jokes aside, this doesn't explain what this is
ty
"n choose k" is the number of ways to pick k things from a set with n elements
yea
Where you just care about the elements and not their order
Use your intuition and common sense by looking at the time stamps of the most recent messages
mb
What do you mean the number of ways to pick? @vale sapphire
You knw what, I'll just watch the vid
Watched the video, makes sense now. Thanks guys!
Is there a way to rewrite absolute value x
Piecewise
,rccw
No
It looks like this
-(x) and x for absolute value x?
So I should rewrite this equation as piecewise
Absolutely
Because imma tell you, in Calculus, absolute value is SO ANNOYING
We just want piecewise to make everything easier
I don’t understand where this +1 is coming from
It’s just x and -x, like you said
Yes
Would the third term here be 21a^5 b^2 ?
Yes.
ty
so the coefficent of the third term is 21 and the coefficient of the second term is -7, right? @shrewd otter
I'm not sure. It depends on whether the binomial is a sum or difference.
I guess it's true since you can express both as a sum.
Okay thanks 😄
Take (3x - 2)^4 common
Which gives
(3x-2)^4 [ 4(3x-2) + 60x ]
Now the rest is easy to figure out, I suppose
common factor
Yea
I'll give you an example, to make things easier
5 + 10 = 15
Now take 5 common, it becomes
5(1+2) = 15
yup i see now
where i live they dont use perfect english so ive never used the actual term "common"
Ooh I see
I think you can use this rule
actually you can just do this
oh wait b^(logb(x)) = x right
$x^{\textmd{log}_{x}(n)} = n$
(バカ) baka
My friend ane me both couldn't solve this, we are ||morons||
i got the answer with that rule
I mean, the thing @ (バカ) baka sent is not obvious if you dont know that
Still confused
$10^{\log_{10} 8x-3} = 8x-3$
robin
also note that $log_e(x) = ln(x)$
robin
first, factor 6x-49
How tho
$x^2-y^2=(x+y)(x-y)$
G3oG0dly
What do i do next?
G3oG0dly
without touching 6?
yes
channel occupied, maybe try going in an unoccupied one
ok
I got 7root(6x) - 12/3 = 6
um
Did i mess up some where?
G3oG0dly
ye
multiply both sides by 3
why?
to get rid of the denominator
oo
wait i think i found where i messed in previous step
i think i got it
Now if i square both sides i can get 6
wait whats the equation you are now on?
yea
Thanks
i guess, even tho you made me skip more than half of the steps
haha i would fail without u
Hi I have a quick question is there any one that made a multi-use conversion and scale equation? I want to know if I just spent about 2 hours of my life creating a easier method or just stumbled into a worse / equal version of one that is already available.
here are the equations made in notepad
If you spent only 2 hours of your life most likely you did nothing significant
I am not saying it is best of the best. I know it won't change much maybe stream line something but nothing else.
(2a + 1)13
This has 14 terms, right?
is my answer correct?
so what was it
Seemed legit to me
nobody would randomly give out nitro that expires in 361 hrs? I mean people could but thats like hella rare
I clicked it and it brought me to the discord nitro place
and nitro gifts usually have a lifetime of 48 hrs
Anyways, can someone explain this? Wouldn't 5/3 make the fraction bigger?
it would
the values in the sequence get bigger
The best you can do is to see for x = 1
for x=1 it will be f(1)+f(0)=6
$$
\begin{align*}
\frac{\frac{x-1}{x}-1}{\frac{x-1}{x}} &= \frac{1}{1-x} \
\frac{\frac{1}{1-x}-1}{\frac{1}{1-x}} &= x \
\end{align*}
$$
robin
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
not sure if anything useful...
this may not be helpful but I think you should determine what its highest degree of this function
probably it makes things easier
this equation is tricky for real
hmm
consider this 1/(1-x)=x/(x-1)+1
Ah, my bad, I did my calculations wrong
This guy got you ^
inverse function
f(x)+g(x)=1
x+f(g(x))=2x
this does not solve anything yet
but might be a step
I am just thinking out loud here
since f and g are inverse, you can use that to find a function that respects the equation
there's no way to use that and avoid 1/x so its still useless
so we just need to sub x with x-1/x
Is this channel being used?
yes
ye
a
<@&268886789983436800>
@terse oracle Do you have anything meaningful to ask/contribute?
x = h(x)
(x-1)/x= d(x)
f(d(x))=x
f(x)+g(d(x))=1
g(x)+d(x)=1
why am I overcomplicating this lol
1/(1-x) was inerse
xd
but we got 1/x
but if we take the linear
x
we get x+1-1/x
which cancels out the 1/x and gives us a linear function
the problem after taking the inverse turned into a linear functional equation
and we are still missing 2 constant terms
so x+1/x+1/(1-x)+1 should suffice
not sure if this is where I should be asking this question but, any idea what software is used to draw these?
I want to embed such graphs in my latex document
@alpine sable #latex-help
Thank you and sorry for the inconvenience
can someone help walk me through this?
sorry
hm?
well
yeah
so how would 3pi or 4pi be possible
oh wait is 3pi = 2pi and 4pi = 2pi?
no
no
clearly not
but it's just another rotation
0 and 2pi are coterminal angles
pi and 2pi likewise
$\theta +2\pi n, n\in\mathbb{Z}$ will be coterminal with $\theta $
Mosh
no
😦
cause a full rotation isnt pi
a full rotation is 2pi
yes
yes..
and 4pi would be what i drew 3pi as
yes
Hello Guys. How can I resolve a fractional equation?
in use clearly
channel in use
ok so they said to sketch it on the interval, -pi, 4pi
so i get why its sectioned off there
but what do they mean by "partition the interval 0, 2pi into 4 equal parts?
split it into 4 equal parts
No, in the next year, we need this again, but I forgetten this, how I make this.
...?
didnt ask
channel is still in use.
Why, what's the matter?
dude read #❓how-to-get-help
we're using this channel
you need to move to an empty one
Oh, now I unterstand. Sorry, my mistake.
no worries
ok so i see the interval in question
how do i...split it
into 4 equal parts
sure if you feel the need to physically partition
(pi/2, 0)
(pi, -3)
(3pi/2, 0)
but the important values in graphing sines and cosines are the multiples of pi/2
that's cut into four parts right
3
since that's where the points are labeled
oh
well i could use either 0, 3 or 2pi, 3 for my fourth right?
since it's on the period
i think thats the right term
period
yes..
seems like youve got an admirer
hello
@shell heron dont be a pain in the ass.
LOL
There is no need for reaction spam, find something productive to do with your life.
:0
Im clearly helping Mane, thought you were reading.
anyway, i see then, the reason we find 5 points is to plug the x value into that little table
say what
yes
which finds us our y value??? helping us complete the graph???? :000000
yes
YAY
since then you can just repeat the shape
How would you move the y's to the left? Would it just be -3y+y/2^2 = -x+1 ?
I want to move the y's to the left because they want you to put it in a(x-h)^2+k form
is this free?
What
So, what I decided to try and do was complete the square while y is still on the right side. I believe they want you to complete the square while y is in the quadratic, not x.
#help-6 is available
oh
"Complete the square on the right side"
Obviously this is an inverse equation considering x and y are switched. If you attempted to get x alone, it would be impossible to complete the square
Try completing the square with y instead of x
quick question
does this mean tat the output of Q should have the same shape as A
or same number of components basiclly
Use the following data set to answer questions
14, 12, 12, 16, 10, 16, 10, 12, 14, 12, 12, 16, 16, 10, 12, 16
What is the mean rounded to the nearest tenth?
Can someone help me with this?
do you know how to get the mean/average?
No
(sum of all the data)/(number of data)
Ah okay, and when do I have to order it?
Like order the data?
From least to greatest
yeah it is need for the median
but for getting the mode it is optional, but it is easier to get it if it is ordered
And rounding to the nearest tenth is would make 13.125 become 13.1?
@glossy tendon
yes
ty!
😄
10, 10, 10, 12, 12, 12, 12, 12, 12, 14, 14, 16, 16, 16, 16, 16
Would 12 be the median?
I think so
{5, 7, 8, 4, 5, 6, 3, 8, 2, 1, 0, 6, 8, 9, 4, 0}
And how do I find the interquartile range of the above data?
no idea what "interquartile range" is, sorry. I would consider googling, but I have no idea how complicated or simple it is so do whatever you think fits @vagrant rover
Okay thank you : D
You're welcome : ) @vagrant rover
yup khanacadeemy always good 🙏
i recently had a maths exam wanted to check if one of may answers was correct
im only in year nine so it should be easy
What are you trying to work out here?
perimeter of the square
You rounded, but it looks good
thanks you worked that out fast!
np 🙂
Can someone help me with this? What population are they talking about, but most importantly what is a standard deviation of the mean mean?
It means how many scores are within (mean + or - one standard deviation)
^
But what is a standard deviation?
oh
hey guys
whats the name of that one math concept
i hear the word but idk how to spell it because writing it out gives me no results on google
i hear "conn exceptions" or "connexections" or something like that
it has to do with directrix and focus if that helps?
what is 1.5+y2
y=6
the y2 is y to the second power
37.5?
y^2 is how you write y squared
alr
^ means to the power of
$1.5+y^2$
beanz
Hey guys how would I simplify "sin $x$ tan $x$ + cos $x$"
wait
why did you do cos^2(x)/cos(x) and not just cancel out cos(x) from the numerator and denominator? @vernal dragon
oh wait you're not multiplying all the terms
ok
how does cos(x) + cos(x) equal cos(x)?
adding fractions..
yea adding fractions
you dont add the denominators
wait how does $\frac{\sin ^2\left(x\right)+\cos ^2\left(x\right)}{\cos \left(x\right)}=\frac{1}{\cos \left(x\right)}$
TheMane3
moreover how does sin^2(x) + cos^2(x) = 1?
$ sin^2(x) + cos^2(x) = 1$
you added a space
beanz
we don't know what x equals so we can possibly have an answer without x right?
We can prove it by using Pythagorean theorem
Well yes
But its just like every other Diophantine equation, plus Ig you can construct a right-angled triangle based off of the pythagorean theorem
See explanation... Consider a right angled triangle with an internal angle theta: Then: sin theta = a/c cos theta = b/c So: sin^2 theta + cos^2 theta = a^2/c^2+b^2/c^2 = (a^2+b^2)/c^2 By Pythagoras a^2+b^2 = c^2, so (a^2+b^2)/c^2 = 1 So given Pythagoras, that proves the identity for theta in (0, pi/2) For angles outside that range we can use: si...
here's a proof using a right angled triangle and the trigonometric ratios
sure...so sin^2 + cos^2 = 1^2
then what
Damn, that is correct but looks wrong
?
guys, im in an argument with someone
are there any possible solutions for a and b?
channel in use
ok
ok
whats, a^2 + b^2
channel in use, delete your message and crosspost elsewhere please
a^2 + b^2 is a^2 + b^2, also dont post here
if you consider the unit circle, take the sinus and cosinus of an angle x, you will have a right triangle
it's the easiest proof
only in the unit circle, since sinx and cos x are coordinates
hell no
😭
sin²x + cos²x =1
