#help-0

1 messages · Page 693 of 1

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I though there would be a term for that, thanks anyway, i have to think another way now

woeful pulsar
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yeah basically the idea is calculating it faster than O(1) each

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hey that's a currently running contest

next scroll
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no it's finished

woeful pulsar
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oh it's finished

next scroll
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yeah just 10-20 min ago

woeful pulsar
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very recent one lol

prime badge
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it has to be a power of a single prime right?

strong citrus
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How are prime numbers used in security fields ?

oak chasm
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@next scroll Minimum natural coprime to i. It will be a prime number.

strong citrus
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any informative videos related to it?

prime badge
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no, it won't be a prime number

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like for 6 it's 4

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it's a power of a prime number

oak chasm
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Ahh.

next scroll
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i brute forced it, there are no. such as 2,3,4,5,7,8,9,...

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for odd the ans is always 2

prime badge
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i bet you don't need it to be very fast, just good enough

lavish cypress
oak chasm
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I bet for even n, f(n) = 2 f(n/2).

woeful pulsar
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it seems that f(i) <= 100 for all i up to 10^16

prime badge
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I would pick a target f(i), say 4, and generate all numbers that have that f() in order

woeful pulsar
prime badge
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until n, so you know how many 4s there will be

next scroll
woeful pulsar
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for 3, well it depends on remainder mod 6

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so 2 and 4 mod 6 get counted in

dry thunder
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thanks!

woeful pulsar
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for 4 it becomes remainder mod 12

dry thunder
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its in pascals

strong furnace
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if you can get the prime factorization start from 2 and the first missing prime would be it

prime badge
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no

strong furnace
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why

prime badge
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it's not the first missing prime

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it's a power of a prime that's one larger than it already has

strong furnace
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how can you disprove what I said ? my argument is the same argument as the sieve thing

oak chasm
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f(6) = 4, but 6 is not missing 2.

strong furnace
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I misinterpeted the problem my bad

prime badge
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ok, so what are first numbers that give 4
6, then 18, 30

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maybe they just go by 12

oak chasm
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Let me fire up Haskell.

prime badge
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so you just divide n by 12, and that's how many 4s you'll have

oak chasm
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First 10 are [6,18,30,42,54,66,78,90,102,114]

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Let me check if that holds for the first million.

alpine sable
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how long does it take to finish highschool hw

jagged rapids
prime badge
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nothing more

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uh

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what

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yeah

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no

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so 10 is out because it's not divisible by 3

oak chasm
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So, the first million equal to 4 are 12n + 6 for sequential ns.

oak chasm
# jagged rapids Teach me, master.

If you insist: ```haskell

let f x = head . filter (\ n -> x mod n /= 0) $ [1 ..]
f 6
4
take 10 . filter ((== 4) . f) $ [1 ..]
[6,18,30,42,54,66,78,90,102,114]
and . take 1000000 . zipWith (==) [6, 18 ..] . filter ((== 4) . f) $ [1 ..]
True

vale wigeon
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is that haskell

prime badge
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as you go f(5), f(7)... that mutiplier step probably get multiplied by 5 and 7

oak chasm
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Yes.

prime badge
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no it's 12,12,60,840

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not pretty

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f(2) − numbers not divisible by 2
f(3) − numbers not divisible by 3, but divisble by 2
f(4) − numbers not divisible by 4, but divisble by 2 and 3

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all we need is how to get the distance between numbers from those

oak chasm
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Do you mean f(n) = 2 - numbers not divisible by 2?

prime badge
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yes

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that

oak chasm
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f(x) = n are xs not divisible by n, but divisible by 2 through n - 1.

prime badge
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well not really

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maybe

oak chasm
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Well, it's the least nondivisor.

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No wait.

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Yeah, it's the least nondivisor, so it can't be divisible by n, but it has to be divisible by all the other numbers before n or else there's a lower nondivisor.

prime badge
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okay

next scroll
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well it works for 4

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i have to use round(n/12)

prime badge
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so if it's divisible by x,y,z,a,b, that's their lcm

next scroll
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not floor or ceil

prime badge
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if lcm doesn;t grow, you're on f(6) for example, you skip it

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try that

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no, it doesn't add up, why 12,12,60,840

oak chasm
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So:

  • f(2x + 1) = 2
  • f(2(3x + 1)) = f(2(3x + 2)) = 3
  • f(6(4x + 1)) = f(6(4x + 2)) = f(6(4x + 3)) = 4
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So how do we combine these into, say f(12x + 6) = 4 for the last line?

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Hmm, that might not be correct.

prime badge
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[12,24,36,48,72,84,96,108,132,144] are f() = 7

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it has gaps

oak chasm
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f(36) = 5, I think.

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5 doesn't divide 36, but it's less than 7.

prime badge
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ok

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fix the program

next scroll
prime badge
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no my bad

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that was actually for f() = 5

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sorry

oak chasm
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  • f(2x + 1) = 2
  • f(6x + 2) = f(6x + 4) = 3
  • f(12x + 6) = 4
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Found out.

prime badge
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well it checks out, the step is lcm, without numbers divisible by n

oak chasm
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Right.

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Well, let's see.

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LCM(2, 3, 4) x + all numbers that 2 and 3 divide but 4 doesn't divide.

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12x + 6

prime badge
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f() = 7 : [60,120,180,240,300,360,480,540,600,660]

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it skips 420

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and it will skip 840

oak chasm
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LCM(2, 3, 4, 5, 6, 7) x + all numbers that 2, 3, 4, 5, 6 divide but 7 doesn't.
420x + 1, 420x + 2, 420x + 3, 420x + 4, 420x + 5, 420x + 6.

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No, that's not right.

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2, 3, 4, 5, 6 divide

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LCM(2, 3, 4, 5, 6) = 60

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420x + 60, 420x + 120, 420x + 180, 420x + 240, 420x + 300, 420x + 360.

prime badge
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but for example, [2,4,8,10,14,16,20,22,26,28] is f() =3

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it doesn't have any excluded numbers

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even numbers are alerady not divisible by 3

oak chasm
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6x + 6 is excluded.

prime badge
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no wait 72 is

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right

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and 6 is right from the start

oak chasm
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Looks like you just cross off the x coefficient from the constant terms.

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Let's try f(x) = 7.

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LCM(1 .. 7) = 420. LCM(1 .. 6) = 60.

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420 + 60(1 .. 6)

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f(x) = 2.

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LCM(1 .. 2) = 2. LCM(1 .. 1) = 1.

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2x + 1(1 .. 1).

prime badge
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ok, so N / lcm, and then divide that by current f() and subtract

oak chasm
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No, just get the two LCMs.

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LCM(1 .. n). LCM(1 .. n - 1).

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LCM(1 .. n) x + LCM(1 .. n - 1) (1 .. n - 1).

prime badge
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we don;t need to generate the sequence

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we want the length

oak chasm
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The length of what?

prime badge
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the length of it, until it reaches n, which is the parameter

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so we divide n by lcm

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and from that, every 7th number will be excluded

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for _ in range(t):
    n = int(input())
    s = 1
    i = 2
    ans = n
    while s <= n:
        ans += n//s
        s = i*s//math.gcd(i,s)
        i += 1
    print(ans%(10**9+7))
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this doesn't subtract hmm

oak chasm
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Looks like f(x) = 12 has no xs.

warped phoenix
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moshill1

prime badge
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12 is not a power of prime

oak chasm
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Ahh.

prime badge
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same as 6

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i don't get this program

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oh okay

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so like it skips numbers that don;t have xs, one at a time

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and adds 1 for each skip, so eventually it reaches the actual f(x) value

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idk

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some magic

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i just don;t understand why it doesn't need to subtract

oak chasm
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Got a more efficient version of f:```haskell
let g x = go 1 2 3 x
where
go a b c x = if x mod a == 0 && x mod b /= 0
then c - 1
else go b (lcm b c) (c + 1) x

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Uses the LCM stuff.

alpine sable
prime badge
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[2,3,2,3,2,4,2,3,2,3,2,5,2,3,2] f(x) for x in [1..15]

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all even numbers are at least 3

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the rest are 2

oak chasm
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@alpine sable Notice that the second term is the previous first term.

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Sorry, the next first term.

prime badge
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all numbers divisible by 6 are a t least 4, the rest are 3

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now i see

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i think

ocean sealBOT
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Chai T. Rex

oak chasm
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@alpine sable ^

winged citrus
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hi

oak chasm
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Hello.

winged citrus
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i wanted to ask how the identity element of an expression is defined; i tried looking it up but i cant figure it out, maybe im phrasing it wrong? i watched a video on this topic but i cant figure out what's happening here

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what exactly do you do with an identity in this case? do you replace b with it?

ocean sealBOT
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Chai T. Rex

oak chasm
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So, find some value e such that those equations are true.

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For all values of a.

winged citrus
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yes but, how do i put it into the "a*b = a+b=3"? do i replace b with it? wouldnt it just always be 1 otherwise?

oak chasm
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  • isn't multiplication.
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It's a specially-defined operator.

winged citrus
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OH

ocean sealBOT
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Chai T. Rex

winged citrus
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so a * x would be a + x + 3, and if x = -3 then it would still be a

oak chasm
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Right.

winged citrus
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got it, thanks, i was confused because i thought its multiplication and u need to find values of a and b to solve that equation

oak chasm
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No problem.

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@prime badge So, you start n out as 1. You keep track of the LCM of all ns so far as you add 1 to n repeatedly. When the LCM changes, you have a new prime power.

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For each new prime power n, you have a certain number of values in your range of that problem that give f(x) = n.

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You add n times the number of values in the range to the sum.

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You keep doing that until you've covered all the values in the range.

prime badge
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it's... hard to comprehend exactly

oak chasm
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Well, remember how we got the forms of the inputs that produce a certain prime power output?

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Like LCM(1 .. n) x + LCM(1 .. n - 1) (1 .. n - 1)

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So, for each prime power n, you floor divide the maximum input by LCM(1 .. n) to get the maximum value of x.

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Then you find out what the maximum constant term is with that x such that the expression is less than or equal to the maximum input.

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Like let's say we're at n = 2. Well, LCM(1 .. 2) x + LCM(1 .. 1) (1 .. 1) is just 2x + 1.

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So, let's say the maximum input is 2000.

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floor of 2000/2 is 1000, so x = 1000.

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And then none of the constant terms (1 is the only constant term) work.

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So, we have 999 times the number of constant terms plus 0 extra constant terms.

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So, 2(999 + 0).

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Then we move on to the next prime power, 3.

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LCM(1 .. 3) x + LCM(1 .. 2) (1 .. 2) = 6x + 2 and 6x + 4.

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,calc floor(2000/6)

ocean sealBOT
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Result:

333
oak chasm
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So, x = 333.

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,calc 6*333

ocean sealBOT
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Result:

1998
oak chasm
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So, 6x + 2 works but 6x + 4 doesn't.

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So, 3(333*2 + 1) for a total of 2(999 + 0) + 3(333*2 + 1).

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Then we go on to the next prime power, 5, and so forth.

glacial hedge
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ugh

warped phoenix
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is that gap at the top of the graph an example of a "hole"?

ancient creek
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Or is it not given?

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If it is a continuous function, then this is most likely an error on the "graphing software" side.

ancient creek
oak chasm
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That's my solution to the original problem.

noble jewel
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Hello, is does this proof make sense ?

Question: If U is a subspace of V, what is U + U

Answer: U + U is 2U, therefore 2U contains every vector in U times two (eg. if x in u, then 2x in U + U), but because U is closed under scalar multiplication, 1/2 x also exist, and therefore x is in U + U. This shows that every vector in U also exists in U + U. Therefore U + U = U

blissful musk
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i need help, whats 34+35?

vale wigeon
blissful musk
vale wigeon
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and if this was the setup to a joke (which it might've been, given how the answer is sixty-nine) it was not a very good one

noble jewel
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I couldn't agree more

blissful musk
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im out

ionic jewel
noble jewel
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😦 Now my question is buried

ionic jewel
oak chasm
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I don't think that U + U is 2U. I think it's any vector in U plus any other vector in U.

noble jewel
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Ah okay, thank you very much

ionic jewel
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the result is still true, but the method would be wrong yes

noble jewel
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Thanks a lot for the replies tho, I'll keep trying

ocean sealBOT
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Chai T. Rex

noble jewel
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Ah yes, thanks

ionic jewel
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a linear subspace is defined to be closed under addition, so you can use that too

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that's quite literally a property of a linear subspace

noble jewel
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I got that U+U is a subset of U since its closed under addition, but thats all i got hahah

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Thanks a lot for the answers btw

wind coyote
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Guys i really need help on this what’s-3

ionic jewel
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negative three

wind coyote
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Thx

verbal gull
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trying to figure out this problem

ionic jewel
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f'(x) is the slope of f(x)

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as in, when f(x) is decreasing, f'(x) is negative, etc

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f''(x) is the concavity of f(x), or the slope of f'(x)

spring harbor
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Is this channel open?

noble jewel
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I think it is given that there was no reply

spring harbor
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Alright thank you

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Given f(x) and g(x).
The tangent at the point P(a,g(a)) to the graph of g is perpendicular to the tangent at the point Q(1,f(1)) to the graph of f. Determine g(a)

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I found the tangent line of f(x) which is y=x-1 (at point Q(1, f(1))

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So the slope of the perpendicular line is -1

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but I am not sure how to continue

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I got y-g(a) = -x+a

ionic jewel
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wait

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these are R2 functions

spring harbor
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R2?

ionic jewel
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so isn't Q have to be Q(1,f(1))?

spring harbor
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oh yeah i meant f(1)

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typo my bad

ionic jewel
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okay making sure

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in that case you can find the slope of the tangent at f(1)

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read: f'(1)

spring harbor
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i found it

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it is 1

ionic jewel
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then find the reciprocal of that slope (for the perpendicular line)

spring harbor
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which is -1

ionic jewel
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then let g'(a) = -1

spring harbor
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yes.

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got that as well

ionic jewel
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so what's a?

spring harbor
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no clue

ionic jewel
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what's g'(a)

spring harbor
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i got y-g(a) = -x + a

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oh

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wait

ionic jewel
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why is there a y in there

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or an x for that matter

spring harbor
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do we set g'(x) equal to -1?

ionic jewel
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... yes

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you want the slope of g(x) at the point a to equal -1

spring harbor
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oh damn

ionic jewel
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g'(a) = -1

spring harbor
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so we get 3/2

ionic jewel
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solve for a, then solve for g(a)

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then ur done

spring harbor
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yeahh i missed something simple

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thank you

ionic jewel
spring harbor
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this is tangent line equation

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y-f(a) = f'(a)(x-a)

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I thought i had to use this

ionic jewel
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you don't care about the line, just the slope, yeah

spring harbor
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yeah thanks!

ionic jewel
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ivory otter
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Hi

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$\frac{\cos^2 x}{\cos^2 x} = 1$

ocean sealBOT
#

MEOWBRO 父

ivory otter
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but what if x is 90 ?

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then its 0

elfin snow
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if it is 90 degrees then it becomes 0/0 which is undefined

ivory otter
#

yes

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but thats a problem if im trying to prove a trigonometric identity

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example:

elfin snow
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trig proofs are the general case, you could put that it can not equal certain values

ivory otter
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but then the proof would only be true if x != 0

elfin snow
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well $x \neq \frac{\pi}{2} + \pi n \ \forall \ n \in \mathbb{Z}$

ivory otter
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wait lemme show you instead

ancient creek
ivory otter
elfin snow
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I hate how the quantifiers bunch up with the variables instead of giving them some space like the element symbol

ancient creek
# ivory otter sorry idk what that means lol

"In mathematics, an extraneous solution is a solution, such as that to an equation, that emerges from the process of solving the problem but is not a valid solution to the problem." - Wikipedia

ivory otter
ivory otter
ancient creek
#

Think of it like this:

y = x

Function is defined at x = 0

It is also true that

y = x * (x/x)

y = (x^2) / x

Now the function is no longer defined at 0??

This contradicts our previous statement, meaning that it actually is defined at 0, and us saying it is undefined at 0 is just an extraneous solution

ivory otter
#

this is why i hate maths, always get stuck on the uneccessary/not so important stuff

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ok so in other words

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i can just do that

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to prove trig identities?

ancient creek
ivory otter
#

ok nice

ancient creek
# ivory otter

Suggestion: an easier method would be to multiply both sides by cos^2 (x)

You will get 1 = cos^2 (x) + sin^2 (x)

and we know this is true thanks to the Pythagorean identity

twilit shale
#

Hello why is this the answer

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context cardinal of a = m

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and x is w/e

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from book of proof

ancient creek
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np

twilit shale
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nvm i think i got it

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its m+1 cuz m is the cardinal of a + the void set

tired hamlet
#

How would I start this one?

sage jacinth
#

then you can go from there

sly mantle
twilit shale
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@sly mantle thanks a lot

glacial hedge
#

uhh, I have a sorta stupid question... The answer to this is false right? because theta can be anything and p just has to be 1?

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r u taking a test?

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huh usually assignments dont have like a (6 points) (2 points) thing?

velvet forum
#

lmao

glacial hedge
#

also pretty sure u dont have to justify things on homework till higher level math classes...

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Lmao he deleted it

tired hamlet
#

How would I do this one? Would I plug in each option for t until I get 8000?

sage jacinth
#

that isn't really an efficient method especially if you lack a calculator

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maybe attempt the problem first and see what you get

jagged trout
#

I think P = 4000?

tall wing
#

is this an examination @tired hamlet

tired hamlet
#

No, practice problems

tall wing
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ok

velvet forum
#

u just have to plug in the value in yhe formula

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it asked for double so just plug in 8000 in P

tired hamlet
#

I just got that now I’m solving for A=8000

sage jacinth
#

just sub then solve for t

velvet forum
#

u know n, r, and p

jagged trout
#

btw.
$e = \lim_{x \to \infty} (1+\frac{1}{n})^n$

ocean sealBOT
#

Moriarty

sage jacinth
#

true

velvet forum
#

8000 = 4000(1 + (.0075/12)^12t

sage jacinth
#

yes now divide then take the log and solve

velvet forum
#

I'm actually not sure if it's 12 for monthly compounded but i think so

sage jacinth
#

its 12

tired hamlet
#

I just did that and I got t=ln2/12ln(12.75/12)

velvet forum
#

ok

sage jacinth
#

that doesn't look correct

tired hamlet
#

Yeah idk what happened

velvet forum
#

it should be roughly 92

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make sure you add more parentheses

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so you don't get your order of operations mixed up

sage jacinth
#

yup

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i just got that as well

tired hamlet
#

I got 0.95 so I think I just messed up my decimals somewhere lol

sage jacinth
#

it should be ln(1.000625) instead of ln(1.0625)

tired hamlet
#

Ok thx that’s why the decimal was shifted over 2 places

jagged trout
#

,w 8000 = 4000 * e^(0.75 * t)

warped phoenix
#

is what i wrote here true?

strong furnace
#

first half yes (assuming some defined base) second half no

strong citrus
#

Just to be more exact

fringe yoke
#

Why is it not A) Residents of the same city

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For D) I could see how the standard deviation would be lower, so there is less variability in the data and therefore a smaller margin of error, but there is a just data from one specific place

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you know?

strong furnace
#

accurate data - ❎
error less data 💯

#

thats what this sounds like

fringe yoke
#

???

strong furnace
#

they don't care about how accurate your data represents what you are surveying

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they just want less deviation

fringe yoke
#

I see

warped phoenix
fringe yoke
#

Doesn't less accurate data mean smaller margin of error?

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Tho

strong furnace
#

not necessarily

fringe yoke
#

the actual mean will be way different

tired hamlet
#

Was the correct answer B?

fringe yoke
#

Nope

strong furnace
#

has to be D

jagged trout
#

@tired hamlet
8000 = 4000 * e^(0.75 * t) | :4000
2 = e^(0.75 * t) | ln
ln(2) = 0.75t | : 0.75
ln(2)/0.75 = t
t ~ 0.924196

So it must be minimum 92 months

strong furnace
#

restaurant has variety

fringe yoke
#

But listen

strong furnace
#

but they go into detail

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about how school is same

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daily

fringe yoke
#

Sure the standard deviation will be lower in D), but that is a special group of individuals

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The actual number of vegetables eaten will not be the same as this group

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Or it will be more different

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So there is a bigger margin of error

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despite the low standard deviation

strong furnace
#

margin of error is not based on actual data

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it is based on mean of your own data

fringe yoke
#

ohhh

#

really?

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The margin of error determines the confidence interval

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And this confidence interval is likely to have the true mean in the interval

strong furnace
#

has to do with standard deviation

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so it has to be same dataset

fringe yoke
#

But

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think about it

lilac snow
fringe yoke
#

What if this group of students who are on a diet eat 20 vegetables everyday each on average

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The true national average would probably be like 2 or 3 because they don't care about their health like these diet people

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Sure if they all follow the same diet

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they have to each have 20 vegetables everyday

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it will be a low standard deviation

fringe yoke
#

but it will be a terrible predictor for actual mean

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and therefore the interval of confidence will be larger

strong furnace
#

but that is not what the problem is talking about by margin of error

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since it has a definition

fringe yoke
#

margin of error defines confidence interval

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I guess

#

ugh

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god

strong furnace
#

does confidence interval have anything to do with accuracy of your survey?

fringe yoke
#

yes

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Oh wait

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It's the true mean for that population

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if he picks the dieters

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the confidence interval will be the true mean for that specific population

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not the whole country

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so if he picks that group

strong furnace
#

it has to do with standard deviation and mean of your own dataset

#

yeah

fringe yoke
#

I get it

#

If the individual picks the dieting group

#

They will all probably be following the same diet and stuff

#

eating the same amount of regular veggies

#

so there will be a low standard deviation

#

and for the dieters, the mean value from the survey will therefore be an excellent representation of the actual data, so there will be a smaller margin of error

#

And the interval of confidence will be tight around the mean

#

This makes sense I think thantk you Sussy

strong furnace
#

it is just consistent

#

not accurate

fringe yoke
#

what do you mean?

#

If you take the dieters

#

they will all be eating a similar amount of veggies everyday

strong furnace
#

this dataset does not represent the country's diet practices

#

just that specific group's

fringe yoke
#

yeah not the country

#

yeah yeah that's why the answer is D

#

if it were representative of the whole country, the margin of error would be super big

#

but it doesn't talk about that in the question

#

I hope I am understanding this in the right way ://

jagged trout
#

@lilac snow $e^x = \lim_{x \to \infty} (1 + \frac{x}{n})^n$

strong furnace
#

sounds about right to me

lilac snow
#

Oh okay

#

Thank you

fringe yoke
#

I will think on this for a bit

ocean sealBOT
#

Moriarty

lavish cypress
fringe yoke
#

Really?

lilac snow
#

Is the proof ofthat simple?

fringe yoke
#

Oh wait

alpine sable
#

does anyone have any idea about this

fringe yoke
#

So if there is a small margin of error

#

But it's a super specific population

#

and you want it to represent something more general

#

what will lower is the percent confidence

#

right?

#

not the margin of error?

#

So we can have a super small margin of error, but we will not be confident at all that the true mean lies within that range

#

It's really weird that it works this way tbh

lavish cypress
#

The margin of error would be small, but it would be pretty much meaningless

fringe yoke
#

yeah ok

#

Yes that makes so much sense now

#

So the answer is D)

#

right?

#

yes

lavish cypress
#

Ye

fringe yoke
#

it will have mega low % confidence for representing the countries mean veggetable consumption

#

BUt it will be super small margin of error

#

beacuase they all eating similar amounts

#

This is great thanks you

warped phoenix
#

@fringe yoke what type of question is that?

#

is it logic?

jagged trout
# lilac snow Is the proof ofthat simple?

By l'hopital's rule, https://www.youtube.com/watch?v=HM-kwHR4VO4

The other def. of e https://www.youtube.com/watch?v=SxJ7X8vE-f0

I call this limit "the fact" with my students, so we can refer to this easily whenever we need to calculate such limit. ,
Limit as x goes to infinite, (1+a/x)^(bx), using definition of e,
Limit of (1+a/n)^(bn) as ...

▶ Play video
warped phoenix
#

cuz doesnt choice D just make more sense than any of the other ones?

strong furnace
#

if you are looking for proof of (1+1/x)^(x) as x->inf , it is defined to be e

fringe yoke
#

No it's statistics

#

Yeah it made sense to me too

#

But I was confusing percent confidence with confidence interval with margin of error

#

the two are completely different

#

i mean not completely but you get the point

lavish cypress
#

I think you also have a misunderstanding of confidence percent

#

But if your sample isn't representative of the population, all the confidence interval and moe stuff is meaningless

neat haven
#

Can someone help me understand this?

#

Why does x prime = 1?

#

If point p can lie anywhere on the circle, x can range anywhere from 0-1 right?

fringe yoke
#

% confidence in the interval of confidence goes down the less representative your sample is of the general pop.

lavish cypress
#

Well I guess that's good enough for SAT.

fringe yoke
#

no no

#

tell me more

#

what am I saying wrong

lavish cypress
#

If you compute the n% confidence interval of a bunch of random samples, n% of them will contain the population mean. However, the requirement is that these samples are random. Therefore, the confidence interval for a sample consisting of students on a diet is meaningless when you take the population to be Americans.

fringe yoke
#

yes

#

Yeah

#

it's meaningless because the % confidence goes down

#

we can't be confident at all that the true mean falls within that interval

neat haven
#

Point p lies on the outer edge of a unit circle

#

So the x of the point should range from 0-1

#

I’m so confused where the one comes from in the highlighted part

jagged trout
#

Maybe because e^(i*x) = cos(x) + i * sin(x)

neat haven
#

That seems awfully complex

jagged trout
neat haven
#

I think its not talking about the points

#

The line from the origin to the points

#

That makes a bit more sense

#

Whatever

#

I’m just accepting what they say as fact

#

Too difficult

sullen karma
#

What’s I then

#

Just tying to figure out how e^i Pi plus 1 = 0

jagged trout
#

i^2 = -1

sullen karma
#

Ok

#

I googled it it was the square root of -1

#

Or that

sullen karma
#

Oh ty

nova shard
#

(sorry for the messy work) i included some negatives i feel as though are flawed. did i go through this/approach this right?

fringe yoke
#

@nova shard

nova shard
#

ohh

#

wait, how did you get (x^2+0x)

#

instead of (x^2-0x)

fringe yoke
#

-0x = 0x

#

-0 is not a thing btw

#

I mean it is

#

but 0=0

#

you know?

nova shard
#

OHH

fringe yoke
#

-0 = 0

nova shard
#

thanks man lmao

fringe yoke
#

-0 = (-1) (0) = 0

#

-0 = -124124124(0) = 0

#

-0 isn't a thing

#

But it doesn't matter

#

That wasn't your mistake

#

btw

nova shard
#

oh

#

incredible

fringe yoke
#

When doing long division

#

Do what i did]

#

put -( p(x) _

#

-( p(x) )

#

when you subtract

#

In the first line you had 0-(-2x)

#

And you treated it as 0-(2x)

#

Do you understand?

nova shard
#

OHH

#

yeah i get it

#

yeah i put 0-(-2x) and ended up with negative 2 completely ignoring the negative for 2x

#

thinkies thanks man

fringe yoke
#

Yeah

#

always but a -(what you are subtracting)

#

it makes it more clear

nova shard
#

gotcha

#

wait

#

question

#

why-

#

oh

#

nvm

warped phoenix
#

For the function $A(t) = 2000e^{0.08t}$

ocean sealBOT
#

TheMane3

warped phoenix
#

T represent time in years, A represents the future value of the investment, 2000 here is the initial investment, and 0.08 is the interest rate

#

how would I figure out how long in years it would take for the money to double?

ocean sealBOT
#

TheMane3

warped phoenix
#

what i did was divide both sides by 2000

ocean sealBOT
#

TheMane3

warped phoenix
#

then i did ln on both sides

ocean sealBOT
#

TheMane3

warped phoenix
#

and then i divided both sides by 0.08

#

$\frac{ln2} {0.08} = t$

ocean sealBOT
#

TheMane3

thorn kindle
#

$\frac{f(\infty)-f(-\infty)}{\infty-(-\infty)}$

ocean sealBOT
thorn kindle
#

Difference quotient over R

rocky cloak
#

Is there a name for the following procedure in probability

#

I flip some coins or otherwise observe some binary outcomes

#

I then make a probability distribution of "what would be the probability of this particular outcome given this inherent probability"

#

I then decide what a reasonable range of values for the underlying probability is using the this pdf treating the mode of it as "the mosty likely underlying probability"

noble sinew
#

likelihood function and maximum likelihood estimation

rich basin
#

For (b), i don't get why it is half my answer

#

So i got my answer through grouping the I's together and calling it as one unit, which makes the total word count 8

#

And then i calculate the permutation as 8!

#

,w solve 8!

ocean sealBOT
rocky cloak
#

thanks!

rich basin
#

Woudl anyone be able to help me please?

#

<@&286206848099549185>

alpine sable
rich basin
#

@alpine sable How did i not see there is an N

#

Also rather confsued with b as wel

#

Nevermind i managed to get that

#

Same with b

alpine sable
#

Hm

#

I'll let someone take over since my skills aren't that great

rich basin
#

so i did 3p2 *8!

#

3 choose 2 for which the singer is next to the drummer

#

and then i made it as if the drummer with the singer are like 1 unit

#

and multiplied by the swapping order

#

The only thing, is that it might cause some duplicates

#

Which is very hard to divide out

noble sinew
#

Why 3 choose 2? If we call the drummer A and the two singers B, C then for each position there is either BAC or CAB (so 2 options)

#

Also remember you want all options where they aren’t like that, so your answer will be answer from a) minus ways they can sit together

rich basin
#

@noble sinew So you are saying that, because there is an option forexample the particular singer B can sit next to the drummer A, for which the drummer A is sitting next to the singer D, which D is an ordinary singer

noble sinew
#

All you care about is if A is between B and C

rich basin
#

Okay thanks, but wouldn't my way would work

#

If i'd included the cases when one of particular singers sat next to the drummer

noble sinew
#

Why do you care if only 1 sits next to

rich basin
#

Well the question is asking the cases for which the two particular singer does not sit next to the drummer

#

So therefore you can have one particular singer sitting next to the drummer and one ordinary one, and it would be fine

#

Do you think, what i did wrong with my way, is that i did not include that

#

I know that your way is more efficient and better. But just want to know if this would still work

#

And that my deduction for why it was wrong was correct?

noble sinew
#

Oh

rich basin
#

Do you think this would still work?

noble sinew
#

Well they don’t have to be a group then so can’t really do it like that so missing a lot of cases

rich basin
#

Yeah, i would include the cases for which they are not grouped

#

so case 1: Non grouped + Case 2: 1 particular singer A sitting next to the drummer + Case 3: 1 particular singer B sitting next to the drumer

noble sinew
#

Sure can work

rich basin
#

And also this would be the last question

#

I tried doing it by cases

#

And this kind of looks like a pascal traingle

#

so i did something like 4! + 4C2 * 3! + 4C3 * 2! + 4 + 4C2 * 2

#

if you want i could go into the details why i did that

noble sinew
#

Looks fine

ionic jewel
#

is this not 16 choose 4

molten jungle
#

If ƒ (x) = |5 − 3x| , then ƒ (2) is:
A. ƒ (−1)
B. ƒ(4/3)
C. ƒ (−2)
D. ƒ (0)
E. ƒ (1)

sad

rich basin
#

@noble sinew The answer is 256

noble sinew
#

Oh just 4^4 lol

rich basin
#

Why is it 4&4

#

4^4, i don't get the intution behind it @noble sinew

noble sinew
#

Checking for 2 and 3 people that 4^2 and 4^3 is correct is 1 way

rich basin
#

The only thing i think I did not cover is that i did not use the 4P3, in which i made the 2 people in one room as one unit

#

But then i'm confused on how i should writing for which there is only 2 people per room

#

I was thinking of something like 4C2 * 4P3 * 3!

#

but that can't be right

#

I think i should just remove the 3!

#

Because the 4P3 already apply the ordering for me

#

That would mean it would be 144

molten jungle
rich basin
#

That would together bring the total to 180

#

Which is 76 short

white crown
rich basin
#

Let me see if i add the part when i made both of them 4C2

#

So basically the equation i have right now is 4! + 4C2*4P3 + 4C3 * 2! + 4 + 4C2 * 2

#

which is 192 in total

molten jungle
rich basin
#

The problem is that i still am lower than the actual answer

median hound
#

yo i need help

#

alva is trying to prove congrounecy with two triangles

#

but i don't know how to get said triangles or use a certain congruency law to prove it

#

reply to this with help plz

#

nvm i got it right 🙂

#

but i still dumb with this topic

rich basin
#

<@&286206848099549185>

molten jungle
rich basin
#

I am still sad, still have no idea how to get the answer

worthy grail
#

Hello

#

Does this have a closed form solution for $\tau$?

ocean sealBOT
#

fakuivan

worthy grail
#

I'm thinking it doesn't, hence why every single symbolic solver I tried fails thonkzoom

turbid beacon
#

lets say I have data of how two people rated some N movies from 1-10

#

Cosine Similarity is a good method of finding out how close those two people are right?

#

also should you replace each of the 1-10s with the z-score instead

#

I think this is better but the problem is the numbers are very close and due to the nature of how people score things there are a lot more values in the 7-10 range than 1-6

#

essentially I am asking how would you deal with outliers?

#

would you calculate standard deviation without the outliers and then use that number instead?

#

is there a better server I should be asking this in lmao

late burrow
#

Someone help me on Linear equations

#

Mostly Elimination method and Cross Multiplication method

ember lava
#

what step do you not understand

glacial hedge
#

Anyone know what this question is asking? I know curl of a gradient of a function with continuous 2nd partial derivatives is 0. but that doesnt apply to just the funciton??? Im very confused

lavish cypress
unkempt needle
#

it's asking : does there exist any vector field F such that curl F = G, and furthermore, F has all continuous second-order derivatives?

glacial hedge
glacial hedge
#

how is this related to divergence

lavish cypress
#

If F is a vector field, div(curl(F)) = 0.
If A is a vector field, then div(A) = 0 implies that A = curl(B), where B is another vector field

glacial hedge
#

Ohhhhhhhhhhhhhhhhhhhh

#

ty

indigo minnow
#

hey

#

how do we find how many 2 multipliers in 30!

glacial hedge
#

?

indigo minnow
#

yeah thats the question

glacial hedge
#

the question doesnt even english properly

indigo minnow
#

you gotta learn english man...

glacial hedge
#

dude i know english

indigo minnow
#

just dont distract people from my question

#

stfu

glacial hedge
#

you stfu

#

your question doesnt even make sense

#

Is what im trying to say

indigo minnow
#

dude piss off if your question is done

#

my question aint your business

glacial hedge
#

im tryn answer ur question...

indigo minnow
#

ok let me ask again

#

how many 2 multipliers are there in 50!

#

(fifty factorial)

glacial hedge
#

r u asking how many factors of 2 are there in 50!

indigo minnow
#

yes

glacial hedge
#

well the # of 2 factors in a*b is number of 2 factors in a + number of 2 factors in b

#

so the question is really asking how many factors of 2 are there in 1-50

indigo minnow
#

hmm,yes.

glacial hedge
#

which is much easier to solve computationally

#

i.e finding all even numbers, and seeing if they are divisible by 4, 8, etc and adding the sums up

indigo minnow
#

but there is a short way

#

you divide 50 to 2 continuously

#

add all denominators

#

thats how our teachers solve

#

but I dont know how this works

#

do you know this method?

#

can u prove it

glacial hedge
#

Um

#

what exactly does add all denominators mean

indigo minnow
#

wait let me send an image

#

just like that

glacial hedge
#

uhhh

#

where exactly did your teacher get 25/2 = 16 or 14 ( i cant tell which number it is)

indigo minnow
#

its 14

#

you ignore remainders

#

its not just one teacher

glacial hedge
#

14*2 = 28

indigo minnow
#

all teachers I know did this that way

#

and when I google it

#

I cant find it

glacial hedge
#

what class are you taking

indigo minnow
#

I dont even know dude education here is fucked up

#

we are learning numbers and factorials

#

ok nevermind lets try another question if you are down

glacial hedge
#

yeah sure.

#

i mean your teachers are correct... but their method is... sketchy

indigo minnow
#

lmao idk

#

umm nevermind i cant find question xd

#

but thanks for help lol

glacial hedge
#

sure...

glacial hedge
#

?

alpine sable
#

pls send ans in dm

#

<@&286206848099549185>

rigid smelt
#

please ping helpers after a minimum of 15min

#

you can rewrite 24 as 4*6

#

thats a hint, the rest is for you to figure out

carmine lion
#

how do i solve this equation

#

$2\cos{2x}=\tan{\frac{x}{2}}, 0\leq x\leq2\pi$

rigid smelt
#

are you sure its tan(x/x)?

ocean sealBOT
idle trench
#

then put it outside of the symbol

#

idk

carmine lion
#

bruh

rigid smelt
#

on the condition that cos(x/2) != 0

#

and then apply prod to sum identity

carmine lion
#

hmm ok ill try that

rigid smelt
#

oh wait

carmine lion
#

?

rigid smelt
#

actually that might be a terrible idea

carmine lion
#

xD

#

i thought about t formula

#

but that got chaotic

#

after i expanded double angle

rigid smelt
#

yeah i wouldnt want to apply half angle either

carmine lion
#

this was a question meant for a graph intersection (graphical)

#

but i wanted to know how you woud solve this with algebra/trig

idle trench
#

how can we just do 4 6

rigid smelt
#

math?

idle trench
#

ik

#

but ut could be anything

carmine lion
idle trench
#

2 12

rigid smelt
#

of course you can do whatever you want

#

but you want to factor it into two numbers that are helpful

carmine lion
#

and MOST IMPORTANTLY, looking at the question

#

🥰

carmine lion
#

how to proceed?

#

i think i've tried all i can think of

rigid smelt
#

im still thinking

#

there is probably some nice factorisation we can do here

#

i think algebra might not be possible

#

we are looking at some series expansion here

carmine lion
#

what the frick

rigid smelt
#

yeah i think if we want to solve it, we would have to approaching it using some sort of series expansion

carmine lion
#

lol

#

isn't that Uni level math

rigid smelt
#

i guess, not sure how the system is in your country

carmine lion
#

australia

rigid smelt
#

yeah i think so

carmine lion
#

YIKES

#

whoops caps

#

ok ty for offering help tho

rigid smelt
#

well thats why sometimes graphs are helpful

carmine lion
#

appreciate <3

idle trench
pale summit
#

why do we need left and right hand limits can anyone explain pls?

full wasp
#

imagine a jump discontinuity in a function

#

ur gonna get different values if u approach from the left or from the right

#

so

#

its kind of important to make that distinction

#

also in general limits do not exist if the left and right hand limits are not equal

pale summit
#

i dont get that

#

i mean can u explain it in easy words

full wasp
#

like this function for example

pale summit
#

ye i see

#

its discontinious

full wasp
#

if u approach x₀ from the left u get a value and it is NOT the same value as if u approach x₀ from the right

pale summit
#

so in that case the limit doesnot exist as u said before

#

coz both values not same oh both limits not same

full wasp
#

yes

pale summit
#

u mean its not a limit

#

as left and right are not the same

full wasp
#

yeah because left and right are not the same it is not a limit

#

or rather the limit does not have a value

pale summit
#

thanks for the help man

vast bobcat
#

A school offers three subjects: Mathematics, Art and Science. At least 80% of students study both Mathematics and Art. At least 80% of students study both Mathematics and Science. Prove that at least 80% of students who study both Art and Science, also study Mathematics.

#

Could someone help with this question please? (ping when you answer)

vast bobcat
#

<@&286206848099549185>

woeful pulsar
vast bobcat
#

how do I minimise y/(x+y)?

woeful pulsar
#

well if you want to show it's >= 0.8, you can also minimise Y-0.8(X+Y) and show this value is always positive

#

and now you have a linear program

#

which you can solve using linear programming methods

vast bobcat
#

hmm okay I think I get it now

#

thank you so much! do you mind me pinging you if I need more help on this question?

woeful pulsar
#

just ask here ig

#

whoa i didn't expect this was supposed to be a linear programming question lol

#

just using methods i know lol

vast bobcat
#

k cool thanks

crystal tapir
#

can someone help in this question its Yr 10

#

here is the question

#

<@&286206848099549185>

#

help

#

me

woeful pulsar
crystal tapir
#

can u further explain

#

i am a bit dum

#

soo

woeful pulsar
#

firstly, realise the value of x (in terms of p) that would minimise y

woeful pulsar
#

what did you do for them lol

#

typically the question tends to continue on stuff you already have

rich basin
#

the equation i had at the end was

#

4! + 4C2*4P3 + 4C3 * 2! + 4 + 4C2 * 2

#

It was the wrong answer

full wasp
#

whats the answer

#

if i had to wager a guess id say its like 4⁴ = 256?? im probably wrong cause i suck at combinatorics

rich basin
#

yeah

#

that is the answer

#

How did you get to that

full wasp
#

basically the first guy can go into any of the four rooms

#

and so can the second guy, and the third guy, and the fourth guy

rich basin
#

Yeah

full wasp
#

so thats 4 x 4 x 4 x 4

rich basin
#

still don't quite get it

#

Because once the first guy can go in. I know the other people can go in as well, but that does not necessary mean that they will go in

#

The answer also has another part with an or

full wasp
#

yes but they COULD go in

rich basin
#

4^4 or 4 + 48 + 36 + 144 + 24 = 256

full wasp
#

the question wants you to consider all possibilities

rich basin
#

and my answer is quite similar except the number 48 and 36 is not in mine

#

Which i don't know how the guy even got 48 and 36

full wasp
#

i dont know where 4 + 48 + 36 + 144 + 24 comes from ngl

rich basin
#

@full wasp Yes but once they get in, there will be less than 4 people to fill in the other rooms

#

I couple explain how i got my solution if you want

full wasp
#

sure

rich basin
#

So, basically i took this into cases

#

First one which is the 24 in the answer

#

in other words 4!

#

I got 4! from the case, what if only 1 person goes to each of the room

#

and with the second case, what if 2 person goes to 1 room and the rest goes to individual rooms

#

that would be 4C2*4P3

#

4 choose 2 person, and then i made them into one unit and them order them across the 4 rooms

#

which corresponds to 144 in the answer

#

and also the 4, is where everyone goes into one room

#

but then the question here is, how did they get 48 and 36

#

and the equation i have right now is

#

4! + 4C2*4P3 + 4C3 * 2! + 4 + 4C2 * 2
[18:08]

pallid lance
#

should be c right?

full wasp
#

hhh we are busy

rich basin
#

So i got 4C3 from the case when 3 person goes into one room

#

perhaps 4C3 *2 is wrong

full wasp
#

im mulling it over

rich basin
#

Let me make new calculations

#

Yes i got the 48

#

It is 4C3*4P2

#

4! + 4C2*4P3 + 4C3 *4P2+ 4 + 4C2 * 2
[18:08]

#

And that could possibly mean that 4C2 is wrong as well

#

But this time, i'm rather confused with what i should change the 4C2*2

#

That is the case when they are divided into two rooms

#

Still stuk with the 4C2 * 2 case

full wasp
#

i think that way of going about it is more complicated than it needs to be

#

just imagine the first person shows up

#

they can choose any of the 4 rooms so they have 4 choices

#

the second person also has 4 choices

rich basin
#

Yeah

full wasp
#

and the third and the fourth so the total number of choices they can make is 4 x 4 x 4 x 4

rich basin
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But what about the ordering though

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I'm think it starting to make sense

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Just trying to create an image

full wasp
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the ordering is already accounted for in 4 x 4 x 4 x 4

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like that covers all the ways u could sort the people and shove them into rooms

rich basin
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But I really want to know what i did wrong with my one

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I just don't want to give up, I want to learn stuff through the hard way

full wasp
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i mean im struggling to see where those numbers come from

rich basin
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I know for sure now that 4C2 * 2 is wrong

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Because I only accoutned for only 2 rooms

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But then when I do soemthing like 4C2 * 4P2, i still got the wrong value

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it is 72

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However the value is suppose to be 36

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i mean 36

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So it is basically half the thing i got for the case when i divide the 4 people

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into 2 roos

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I think i'm starting to see why

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Probably should just focus on the case which I am having trobule with

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Like, i don't think the other values matter, only this problem is where the issue with my answer derives from

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Like why is 36 half my answer

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Would anybody be able to please help me?

full wasp
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i do have a second method but it is a bit counterintuitive

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so first if u consider treating the people as one large group then you have 4 choices so this is where 4 comes from

rich basin
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But with my one, it is quite similar to the answer. As well as I'm quite close to solving it

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just need to find a reasoning behind dividing it by 2

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Like something that must of repeated

full wasp
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i dunno sorry

rich basin
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@crisp iron

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<@&286206848099549185>

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I think I start to get what i did wrong

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it is because I had some duplicates

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like forexample I would have AB __ CD ___

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and i hcan have the same thing

dull onyx
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how would i simplify this ><

indigo flint
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What does the the denominator read

dull onyx
#

thats a two

prime badge
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because it doesn't matter in which order the room contains 2 specific people

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it just contains them

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if it did matter, then it's 7c4 * 4!

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to go from that to the real answer you'd have to divide by 24 in some cases, by 4 in others, by 6 in others

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so you think of it as a 4 digit string
1 2 1 4
1 1 1 1
1 1 3 1
just encodes who went where

indigo flint
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@dull onyx

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Idk if u can simplify any further

dull onyx
urban escarp
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can someone assist me with b and c please

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<@&286206848099549185>

ivory otter
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Hi

urban escarp
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hello

dull onyx
#

hi again! not sure if this channel is being used or not but… i have the function f(x) = ax^2
and im being asked to find a so the derivative of f at A(2, f(2)) is equal to 4.. literally sorry if this makes no sense in english, its in greek and im having a hard time translating it

rigid smelt
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whats the derivative of f(x)?

dull onyx
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i found 2xa

rigid smelt
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yes derivative of f is f'(x)=2ax

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now plug in the information you have

dull onyx
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yup then i found the derivative of 2

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bc it asks for it before it asks for A(2, f(2))

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and i found 4a

rigid smelt
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so you want to find a? or do you want to find f(2)?

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ok lets slow down a bit

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you are given:
f(x)=ax^2 and thats all?

dull onyx
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it says to find a so the derivative of f at A(2, f(2)) is equal to 4.. translating this from greek is hard asf

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one sec

rigid smelt
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is it given that the derivative at x=2 is 4? or is that something you guessed?

dull onyx
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also x is an element of R and a is an element of R

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nope it says i should find that so its 4

rigid smelt
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ok so its given that f'(2)=4

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and you know that f'(x)=2ax

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can you find a from those two information?

dull onyx
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no its kot given