https://codeforces.com/contest/1542/problem/C this is the problem i'm trying to solve.
#help-0
1 messages · Page 693 of 1
I though there would be a term for that, thanks anyway, i have to think another way now
yeah basically the idea is calculating it faster than O(1) each
hey that's a currently running contest
no it's finished
oh it's finished
yeah just 10-20 min ago
very recent one lol
it has to be a power of a single prime right?
How are prime numbers used in security fields ?
@next scroll Minimum natural coprime to i. It will be a prime number.
any informative videos related to it?
Ahh.
i brute forced it, there are no. such as 2,3,4,5,7,8,9,...
for odd the ans is always 2
i bet you don't need it to be very fast, just good enough
One application is RSA. Wikipedia has a good article on it, if you know modular arithmetic.
I bet for even n, f(n) = 2 f(n/2).
it seems that f(i) <= 100 for all i up to 10^16
I would pick a target f(i), say 4, and generate all numbers that have that f() in order
f(4) is 3 which is not 2f(4/2)
until n, so you know how many 4s there will be
i was thinking of counting them too, for 2 it is n/2, for 3 it is ... i don't know how to do this part
thanks!
for 4 it becomes remainder mod 12
its in pascals
if you can get the prime factorization start from 2 and the first missing prime would be it
no
why
it's not the first missing prime
it's a power of a prime that's one larger than it already has
how can you disprove what I said ? my argument is the same argument as the sieve thing
f(6) = 4, but 6 is not missing 2.
I misinterpeted the problem my bad
Let me fire up Haskell.
so you just divide n by 12, and that's how many 4s you'll have
First 10 are [6,18,30,42,54,66,78,90,102,114]
Let me check if that holds for the first million.
how long does it take to finish highschool hw
Teach me, master.
yeah, it's all even numbers that aren't divisible by 4
nothing more
uh
what
yeah
no
so 10 is out because it's not divisible by 3
So, the first million equal to 4 are 12n + 6 for sequential ns.
If you insist: ```haskell
let f x = head . filter (\ n -> x
modn /= 0) $ [1 ..]
f 6
4
take 10 . filter ((== 4) . f) $ [1 ..]
[6,18,30,42,54,66,78,90,102,114]
and . take 1000000 . zipWith (==) [6, 18 ..] . filter ((== 4) . f) $ [1 ..]
True
is that haskell
as you go f(5), f(7)... that mutiplier step probably get multiplied by 5 and 7
Yes.
no it's 12,12,60,840
not pretty
f(2) − numbers not divisible by 2
f(3) − numbers not divisible by 3, but divisble by 2
f(4) − numbers not divisible by 4, but divisble by 2 and 3
all we need is how to get the distance between numbers from those
Do you mean f(n) = 2 - numbers not divisible by 2?
f(x) = n are xs not divisible by n, but divisible by 2 through n - 1.
Well, it's the least nondivisor.
No wait.
Yeah, it's the least nondivisor, so it can't be divisible by n, but it has to be divisible by all the other numbers before n or else there's a lower nondivisor.
okay
so if it's divisible by x,y,z,a,b, that's their lcm
not floor or ceil
if lcm doesn;t grow, you're on f(6) for example, you skip it
try that
no, it doesn't add up, why 12,12,60,840
So:
- f(2x + 1) = 2
- f(2(3x + 1)) = f(2(3x + 2)) = 3
- f(6(4x + 1)) = f(6(4x + 2)) = f(6(4x + 3)) = 4
So how do we combine these into, say f(12x + 6) = 4 for the last line?
Hmm, that might not be correct.
https://codeforces.com/contest/1542/status/C you can see submissions here now
well it checks out, the step is lcm, without numbers divisible by n
Right.
Well, let's see.
LCM(2, 3, 4) x + all numbers that 2 and 3 divide but 4 doesn't divide.
12x + 6
f() = 7 : [60,120,180,240,300,360,480,540,600,660]
it skips 420
and it will skip 840
LCM(2, 3, 4, 5, 6, 7) x + all numbers that 2, 3, 4, 5, 6 divide but 7 doesn't.
420x + 1, 420x + 2, 420x + 3, 420x + 4, 420x + 5, 420x + 6.
No, that's not right.
2, 3, 4, 5, 6 divide
LCM(2, 3, 4, 5, 6) = 60
420x + 60, 420x + 120, 420x + 180, 420x + 240, 420x + 300, 420x + 360.
but for example, [2,4,8,10,14,16,20,22,26,28] is f() =3
it doesn't have any excluded numbers
even numbers are alerady not divisible by 3
6x + 6 is excluded.
Looks like you just cross off the x coefficient from the constant terms.
Let's try f(x) = 7.
LCM(1 .. 7) = 420. LCM(1 .. 6) = 60.
420 + 60(1 .. 6)
f(x) = 2.
LCM(1 .. 2) = 2. LCM(1 .. 1) = 1.
2x + 1(1 .. 1).
ok, so N / lcm, and then divide that by current f() and subtract
No, just get the two LCMs.
LCM(1 .. n). LCM(1 .. n - 1).
LCM(1 .. n) x + LCM(1 .. n - 1) (1 .. n - 1).
The length of what?
the length of it, until it reaches n, which is the parameter
so we divide n by lcm
and from that, every 7th number will be excluded
for _ in range(t):
n = int(input())
s = 1
i = 2
ans = n
while s <= n:
ans += n//s
s = i*s//math.gcd(i,s)
i += 1
print(ans%(10**9+7))
this doesn't subtract hmm
Looks like f(x) = 12 has no xs.
moshill1
12 is not a power of prime
Ahh.
same as 6
i don't get this program
oh okay
so like it skips numbers that don;t have xs, one at a time
and adds 1 for each skip, so eventually it reaches the actual f(x) value
idk
some magic
i just don;t understand why it doesn't need to subtract
Got a more efficient version of f:```haskell
let g x = go 1 2 3 x
where
go a b c x = if x mod a == 0 && x mod b /= 0
then c - 1
else go b (lcm b c) (c + 1) x
Uses the LCM stuff.
[2,3,2,3,2,4,2,3,2,3,2,5,2,3,2] f(x) for x in [1..15]
all even numbers are at least 3
the rest are 2
@alpine sable Notice that the second term is the previous first term.
Sorry, the next first term.
Chai T. Rex
@alpine sable ^
hi
Hello.
i wanted to ask how the identity element of an expression is defined; i tried looking it up but i cant figure it out, maybe im phrasing it wrong? i watched a video on this topic but i cant figure out what's happening here
what exactly do you do with an identity in this case? do you replace b with it?
Chai T. Rex
yes but, how do i put it into the "a*b = a+b=3"? do i replace b with it? wouldnt it just always be 1 otherwise?
OH
Chai T. Rex
so a * x would be a + x + 3, and if x = -3 then it would still be a
Right.
got it, thanks, i was confused because i thought its multiplication and u need to find values of a and b to solve that equation
No problem.
@prime badge So, you start n out as 1. You keep track of the LCM of all ns so far as you add 1 to n repeatedly. When the LCM changes, you have a new prime power.
For each new prime power n, you have a certain number of values in your range of that problem that give f(x) = n.
You add n times the number of values in the range to the sum.
You keep doing that until you've covered all the values in the range.
it's... hard to comprehend exactly
Well, remember how we got the forms of the inputs that produce a certain prime power output?
Like LCM(1 .. n) x + LCM(1 .. n - 1) (1 .. n - 1)
So, for each prime power n, you floor divide the maximum input by LCM(1 .. n) to get the maximum value of x.
Then you find out what the maximum constant term is with that x such that the expression is less than or equal to the maximum input.
Like let's say we're at n = 2. Well, LCM(1 .. 2) x + LCM(1 .. 1) (1 .. 1) is just 2x + 1.
So, let's say the maximum input is 2000.
floor of 2000/2 is 1000, so x = 1000.
And then none of the constant terms (1 is the only constant term) work.
So, we have 999 times the number of constant terms plus 0 extra constant terms.
So, 2(999 + 0).
Then we move on to the next prime power, 3.
LCM(1 .. 3) x + LCM(1 .. 2) (1 .. 2) = 6x + 2 and 6x + 4.
,calc floor(2000/6)
Result:
333
Result:
1998
So, 6x + 2 works but 6x + 4 doesn't.
So, 3(333*2 + 1) for a total of 2(999 + 0) + 3(333*2 + 1).
Then we go on to the next prime power, 5, and so forth.
ugh
is that gap at the top of the graph an example of a "hole"?
what's the equation for this graph?
Or is it not given?
If it is a continuous function, then this is most likely an error on the "graphing software" side.

@prime badge https://ideone.com/0WAeAX#stdout
That's my solution to the original problem.
Hello, is does this proof make sense ?
Question: If U is a subspace of V, what is U + U
Answer: U + U is 2U, therefore 2U contains every vector in U times two (eg. if x in u, then 2x in U + U), but because U is closed under scalar multiplication, 1/2 x also exist, and therefore x is in U + U. This shows that every vector in U also exists in U + U. Therefore U + U = U
i need help, whats 34+35?
if your question can be answered with a calculator, it does not belong here

and if this was the setup to a joke (which it might've been, given how the answer is sixty-nine) it was not a very good one
I couldn't agree more
im out
okay let's be real Wolfram could answer like half of the problems here with minimal wording changes
😦 Now my question is buried
this is saying that U and U+U span the same thing
I don't think that U + U is 2U. I think it's any vector in U plus any other vector in U.
Ah okay, thank you very much
the result is still true, but the method would be wrong yes
I havent learned about span yet, ive been going though the book linear algebra done right and this questions is given before that chapter
Thanks a lot for the replies tho, I'll keep trying
Chai T. Rex
Ah yes, thanks
a linear subspace is defined to be closed under addition, so you can use that too
that's quite literally a property of a linear subspace
I got that U+U is a subset of U since its closed under addition, but thats all i got hahah
Thanks a lot for the answers btw
Guys i really need help on this what’s-3
negative three
Thx
f'(x) is the slope of f(x)
as in, when f(x) is decreasing, f'(x) is negative, etc
f''(x) is the concavity of f(x), or the slope of f'(x)
Is this channel open?
I think it is given that there was no reply
Alright thank you
Given f(x) and g(x).
The tangent at the point P(a,g(a)) to the graph of g is perpendicular to the tangent at the point Q(1,f(1)) to the graph of f. Determine g(a)
I found the tangent line of f(x) which is y=x-1 (at point Q(1, f(1))
So the slope of the perpendicular line is -1
but I am not sure how to continue
I got y-g(a) = -x+a
R2?
so isn't Q have to be Q(1,f(1))?
okay making sure
in that case you can find the slope of the tangent at f(1)
read: f'(1)
then find the reciprocal of that slope (for the perpendicular line)
which is -1
then let g'(a) = -1
so what's a?
no clue
what's g'(a)
do we set g'(x) equal to -1?
oh damn
g'(a) = -1
so we get 3/2
whatever this thing is is what confused you
you don't care about the line, just the slope, yeah
yeah thanks!
✅
MEOWBRO 父
if it is 90 degrees then it becomes 0/0 which is undefined
trig proofs are the general case, you could put that it can not equal certain values
but then the proof would only be true if x != 0
well $x \neq \frac{\pi}{2} + \pi n \ \forall \ n \in \mathbb{Z}$
wait lemme show you instead
well that is an extraneous solution i believe
sorry idk what that means lol
I hate how the quantifiers bunch up with the variables instead of giving them some space like the element symbol
"In mathematics, an extraneous solution is a solution, such as that to an equation, that emerges from the process of solving the problem but is not a valid solution to the problem." - Wikipedia
i see, what about the above example i showed then?
Think of it like this:
y = x
Function is defined at x = 0
It is also true that
y = x * (x/x)
y = (x^2) / x
Now the function is no longer defined at 0??
This contradicts our previous statement, meaning that it actually is defined at 0, and us saying it is undefined at 0 is just an extraneous solution
this is why i hate maths, always get stuck on the uneccessary/not so important stuff
ok so in other words
i can just do that
to prove trig identities?
Yes, this statement holds true for all values of x
ok nice
Suggestion: an easier method would be to multiply both sides by cos^2 (x)
You will get 1 = cos^2 (x) + sin^2 (x)
and we know this is true thanks to the Pythagorean identity
Hello why is this the answer
context cardinal of a = m
and x is w/e
from book of proof
thanks
np
How would I start this one?
well if it only has 25% remaining, then you should be able to know how many half lives passed
then you can go from there
that's exactly it
Thank you I’m so slow lol
@sly mantle thanks a lot
uhh, I have a sorta stupid question... The answer to this is false right? because theta can be anything and p just has to be 1?
r u taking a test?
huh usually assignments dont have like a (6 points) (2 points) thing?
lmao
also pretty sure u dont have to justify things on homework till higher level math classes...
Lmao he deleted it
How would I do this one? Would I plug in each option for t until I get 8000?
that isn't really an efficient method especially if you lack a calculator
maybe attempt the problem first and see what you get
I think P = 4000?
is this an examination @tired hamlet
No, practice problems
ok
u just have to plug in the value in yhe formula
it asked for double so just plug in 8000 in P
I just got that now I’m solving for A=8000
just sub then solve for t
u know n, r, and p
btw.
$e = \lim_{x \to \infty} (1+\frac{1}{n})^n$
Moriarty
true
8000 = 4000(1 + (.0075/12)^12t
yes now divide then take the log and solve
I'm actually not sure if it's 12 for monthly compounded but i think so
its 12
I just did that and I got t=ln2/12ln(12.75/12)
ok
that doesn't look correct
Yeah idk what happened
it should be roughly 92
make sure you add more parentheses
so you don't get your order of operations mixed up
I got 0.95 so I think I just messed up my decimals somewhere lol
it should be ln(1.000625) instead of ln(1.0625)
Ok thx that’s why the decimal was shifted over 2 places
,w 8000 = 4000 * e^(0.75 * t)
is what i wrote here true?
first half yes (assuming some defined base) second half no
Instead of 3.84 write 3.8416
Just to be more exact
Why is it not A) Residents of the same city
For D) I could see how the standard deviation would be lower, so there is less variability in the data and therefore a smaller margin of error, but there is a just data from one specific place
you know?
???
they don't care about how accurate your data represents what you are surveying
they just want less deviation
I see
sorry i took so long, i dont have the equation but it was either a logarithmic/exponential function so it was going to be continuous if im not mistaken
not necessarily
the actual mean will be way different
Was the correct answer B?
Nope
has to be D
@tired hamlet
8000 = 4000 * e^(0.75 * t) | :4000
2 = e^(0.75 * t) | ln
ln(2) = 0.75t | : 0.75
ln(2)/0.75 = t
t ~ 0.924196
So it must be minimum 92 months
restaurant has variety
But listen
Sure the standard deviation will be lower in D), but that is a special group of individuals
The actual number of vegetables eaten will not be the same as this group
Or it will be more different
So there is a bigger margin of error
despite the low standard deviation
ohhh
really?
The margin of error determines the confidence interval
And this confidence interval is likely to have the true mean in the interval
Haha, SAT practice test?
What if this group of students who are on a diet eat 20 vegetables everyday each on average
The true national average would probably be like 2 or 3 because they don't care about their health like these diet people
Sure if they all follow the same diet
they have to each have 20 vegetables everyday
it will be a low standard deviation
Where did you get e from?
but it will be a terrible predictor for actual mean
and therefore the interval of confidence will be larger
but that is not what the problem is talking about by margin of error
since it has a definition
does confidence interval have anything to do with accuracy of your survey?
yes
Oh wait
It's the true mean for that population
if he picks the dieters
the confidence interval will be the true mean for that specific population
not the whole country
so if he picks that group
I get it
If the individual picks the dieting group
They will all probably be following the same diet and stuff
eating the same amount of regular veggies
so there will be a low standard deviation
and for the dieters, the mean value from the survey will therefore be an excellent representation of the actual data, so there will be a smaller margin of error
And the interval of confidence will be tight around the mean
This makes sense I think thantk you Sussy
it is not an excellent representation of the actual data
it is just consistent
not accurate
what do you mean?
If you take the dieters
they will all be eating a similar amount of veggies everyday
this dataset does not represent the country's diet practices
just that specific group's
yeah not the country
yeah yeah that's why the answer is D
if it were representative of the whole country, the margin of error would be super big
but it doesn't talk about that in the question
I hope I am understanding this in the right way ://
@lilac snow $e^x = \lim_{x \to \infty} (1 + \frac{x}{n})^n$
sounds about right to me
I will think on this for a bit
Moriarty
Margin of error depends only on your data, not what it's supposed to be representing.
Really?
Is the proof ofthat simple?
Oh wait
does anyone have any idea about this
So if there is a small margin of error
But it's a super specific population
and you want it to represent something more general
what will lower is the percent confidence
right?
not the margin of error?
So we can have a super small margin of error, but we will not be confident at all that the true mean lies within that range
It's really weird that it works this way tbh
The margin of error would be small, but it would be pretty much meaningless
Ye
it will have mega low % confidence for representing the countries mean veggetable consumption
BUt it will be super small margin of error
beacuase they all eating similar amounts
This is great thanks you
By l'hopital's rule, https://www.youtube.com/watch?v=HM-kwHR4VO4
The other def. of e https://www.youtube.com/watch?v=SxJ7X8vE-f0
I call this limit "the fact" with my students, so we can refer to this easily whenever we need to calculate such limit. ,
Limit as x goes to infinite, (1+a/x)^(bx), using definition of e,
Limit of (1+a/n)^(bn) as ...
cuz doesnt choice D just make more sense than any of the other ones?
if you are looking for proof of (1+1/x)^(x) as x->inf , it is defined to be e
No it's statistics
Yeah it made sense to me too
But I was confusing percent confidence with confidence interval with margin of error
the two are completely different
i mean not completely but you get the point
I think you also have a misunderstanding of confidence percent
But if your sample isn't representative of the population, all the confidence interval and moe stuff is meaningless
Can someone help me understand this?
Why does x prime = 1?
If point p can lie anywhere on the circle, x can range anywhere from 0-1 right?
What do you mean?
% confidence in the interval of confidence goes down the less representative your sample is of the general pop.
Well I guess that's good enough for SAT.
If you compute the n% confidence interval of a bunch of random samples, n% of them will contain the population mean. However, the requirement is that these samples are random. Therefore, the confidence interval for a sample consisting of students on a diet is meaningless when you take the population to be Americans.
yes
Yeah
it's meaningless because the % confidence goes down
we can't be confident at all that the true mean falls within that interval
What do you mean exactly?
In the highlighted part
Point p lies on the outer edge of a unit circle
So the x of the point should range from 0-1
I’m so confused where the one comes from in the highlighted part
Maybe because e^(i*x) = cos(x) + i * sin(x)
That seems awfully complex
A song about an awesome number. Lyrics and a higher quality version available at http://danielwedge.com/esong/
I think its not talking about the points
The line from the origin to the points
That makes a bit more sense
Whatever
I’m just accepting what they say as fact
Too difficult
i^2 = -1
Introduction to i and imaginary numbers
Practice this lesson yourself on KhanAcademy.org right now:
https://www.khanacademy.org/math/precalculus/imaginary_complex_precalc/i_precalc/e/imaginary_unit_powers?utm_source=YT&utm_medium=Desc&utm_campaign=Precalculus
Watch the next lesson: https://www.khanacademy.org/math/precalculus/imaginary_comple...
Oh ty
(sorry for the messy work) i included some negatives i feel as though are flawed. did i go through this/approach this right?
OHH
-0 = 0
thanks man lmao
-0 = (-1) (0) = 0
-0 = -124124124(0) = 0
-0 isn't a thing
But it doesn't matter
That wasn't your mistake
btw
When doing long division
Do what i did]
put -( p(x) _
-( p(x) )
when you subtract
In the first line you had 0-(-2x)
And you treated it as 0-(2x)
Do you understand?
OHH
yeah i get it
yeah i put 0-(-2x) and ended up with negative 2 completely ignoring the negative for 2x
thanks man
For the function $A(t) = 2000e^{0.08t}$
TheMane3
T represent time in years, A represents the future value of the investment, 2000 here is the initial investment, and 0.08 is the interest rate
how would I figure out how long in years it would take for the money to double?
TheMane3
what i did was divide both sides by 2000
TheMane3
then i did ln on both sides
TheMane3
TheMane3
$\frac{f(\infty)-f(-\infty)}{\infty-(-\infty)}$
AMD
Difference quotient over R
Is there a name for the following procedure in probability
I flip some coins or otherwise observe some binary outcomes
I then make a probability distribution of "what would be the probability of this particular outcome given this inherent probability"
I then decide what a reasonable range of values for the underlying probability is using the this pdf treating the mode of it as "the mosty likely underlying probability"
likelihood function and maximum likelihood estimation
For (b), i don't get why it is half my answer
So i got my answer through grouping the I's together and calling it as one unit, which makes the total word count 8
And then i calculate the permutation as 8!
,w solve 8!
oh yeah i suppose its just a single variable fit to some data isnt it
thanks!
8!/2! since there are 2 'n' in 'definition'
@alpine sable How did i not see there is an N
Also rather confsued with b as wel
Nevermind i managed to get that
Same with b
so i did 3p2 *8!
3 choose 2 for which the singer is next to the drummer
and then i made it as if the drummer with the singer are like 1 unit
and multiplied by the swapping order
The only thing, is that it might cause some duplicates
Which is very hard to divide out
Why 3 choose 2? If we call the drummer A and the two singers B, C then for each position there is either BAC or CAB (so 2 options)
Also remember you want all options where they aren’t like that, so your answer will be answer from a) minus ways they can sit together
@noble sinew So you are saying that, because there is an option forexample the particular singer B can sit next to the drummer A, for which the drummer A is sitting next to the singer D, which D is an ordinary singer
All you care about is if A is between B and C
Okay thanks, but wouldn't my way would work
If i'd included the cases when one of particular singers sat next to the drummer
Why do you care if only 1 sits next to
Well the question is asking the cases for which the two particular singer does not sit next to the drummer
So therefore you can have one particular singer sitting next to the drummer and one ordinary one, and it would be fine
Do you think, what i did wrong with my way, is that i did not include that
I know that your way is more efficient and better. But just want to know if this would still work
And that my deduction for why it was wrong was correct?
Oh
Do you think this would still work?
Well they don’t have to be a group then so can’t really do it like that so missing a lot of cases
Yeah, i would include the cases for which they are not grouped
so case 1: Non grouped + Case 2: 1 particular singer A sitting next to the drummer + Case 3: 1 particular singer B sitting next to the drumer
Sure can work
And also this would be the last question
I tried doing it by cases
And this kind of looks like a pascal traingle
so i did something like 4! + 4C2 * 3! + 4C3 * 2! + 4 + 4C2 * 2
if you want i could go into the details why i did that
Looks fine
is this not 16 choose 4
If ƒ (x) = |5 − 3x| , then ƒ (2) is:
A. ƒ (−1)
B. ƒ(4/3)
C. ƒ (−2)
D. ƒ (0)
E. ƒ (1)

But the problem is with the answer, i didn't get the correct answer
@noble sinew The answer is 256
Oh just 4^4 lol
B. f(4/3)
Checking for 2 and 3 people that 4^2 and 4^3 is correct is 1 way
The only thing i think I did not cover is that i did not use the 4P3, in which i made the 2 people in one room as one unit
But then i'm confused on how i should writing for which there is only 2 people per room
I was thinking of something like 4C2 * 4P3 * 3!
but that can't be right
I think i should just remove the 3!
Because the 4P3 already apply the ordering for me
That would mean it would be 144
thank u, could u tell me the procedure 
f(2)=1, so find which of A-E equal 1 also
Let me see if i add the part when i made both of them 4C2
So basically the equation i have right now is 4! + 4C2*4P3 + 4C3 * 2! + 4 + 4C2 * 2
which is 192 in total
but how did u f(2)=1? sorry for being really dumb 
The problem is that i still am lower than the actual answer
yo i need help
alva is trying to prove congrounecy with two triangles
but i don't know how to get said triangles or use a certain congruency law to prove it
reply to this with help plz
nvm i got it right 🙂
but i still dumb with this topic
<@&286206848099549185>
f(2)=|5 − 3(2)|=|-1|=1
thank u 
fakuivan
I'm thinking it doesn't, hence why every single symbolic solver I tried fails 
lets say I have data of how two people rated some N movies from 1-10
Cosine Similarity is a good method of finding out how close those two people are right?
also should you replace each of the 1-10s with the z-score instead
I think this is better but the problem is the numbers are very close and due to the nature of how people score things there are a lot more values in the 7-10 range than 1-6
essentially I am asking how would you deal with outliers?
would you calculate standard deviation without the outliers and then use that number instead?
is there a better server I should be asking this in lmao
Someone help me on Linear equations
Mostly Elimination method and Cross Multiplication method
where are you struggling
what step do you not understand
Anyone know what this question is asking? I know curl of a gradient of a function with continuous 2nd partial derivatives is 0. but that doesnt apply to just the funciton??? Im very confused
Divergence of a curl is also 0, and in R³ if it is zero, then the vector field is a curl of another vector field.
it's asking : does there exist any vector field F such that curl F = G, and furthermore, F has all continuous second-order derivatives?
How would i prove that... instead of reverse engineering the curl of G?
???????
how is this related to divergence
If F is a vector field, div(curl(F)) = 0.
If A is a vector field, then div(A) = 0 implies that A = curl(B), where B is another vector field
?
yeah thats the question
the question doesnt even english properly
you gotta learn english man...
dude i know english
im tryn answer ur question...
r u asking how many factors of 2 are there in 50!
yes
well the # of 2 factors in a*b is number of 2 factors in a + number of 2 factors in b
so the question is really asking how many factors of 2 are there in 1-50
hmm,yes.
which is much easier to solve computationally
i.e finding all even numbers, and seeing if they are divisible by 4, 8, etc and adding the sums up
but there is a short way
you divide 50 to 2 continuously
add all denominators
thats how our teachers solve
but I dont know how this works
do you know this method?
can u prove it
uhhh
where exactly did your teacher get 25/2 = 16 or 14 ( i cant tell which number it is)
14*2 = 28
what class are you taking
I dont even know dude education here is fucked up
we are learning numbers and factorials
ok nevermind lets try another question if you are down
sure...
so the answer is false because the div F = y^2+y^2 which isn't 0
?
please ping helpers after a minimum of 15min
you can rewrite 24 as 4*6
thats a hint, the rest is for you to figure out
are you sure its tan(x/x)?
abe
bruh
maybe multiply by cos(x/2) on both sides
on the condition that cos(x/2) != 0
and then apply prod to sum identity
hmm ok ill try that
oh wait
?
actually that might be a terrible idea
xD
i thought about t formula
but that got chaotic
after i expanded double angle
yeah i wouldnt want to apply half angle either
this was a question meant for a graph intersection (graphical)
but i wanted to know how you woud solve this with algebra/trig
how can we just do 4 6
math?
prime factorisation
2 12
of course you can do whatever you want
but you want to factor it into two numbers that are helpful
alr
how to proceed?
i think i've tried all i can think of
im still thinking
there is probably some nice factorisation we can do here
i think algebra might not be possible
we are looking at some series expansion here
what the frick
yeah i think if we want to solve it, we would have to approaching it using some sort of series expansion
i guess, not sure how the system is in your country
australia
yeah i think so
well thats why sometimes graphs are helpful
appreciate <3
why do we need left and right hand limits can anyone explain pls?
imagine a jump discontinuity in a function
ur gonna get different values if u approach from the left or from the right
so
its kind of important to make that distinction
also in general limits do not exist if the left and right hand limits are not equal
like this function for example
if u approach x₀ from the left u get a value and it is NOT the same value as if u approach x₀ from the right
so in that case the limit doesnot exist as u said before
coz both values not same oh both limits not same
yes
yeah because left and right are not the same it is not a limit
or rather the limit does not have a value
thanks for the help man
A school offers three subjects: Mathematics, Art and Science. At least 80% of students study both Mathematics and Art. At least 80% of students study both Mathematics and Science. Prove that at least 80% of students who study both Art and Science, also study Mathematics.
Could someone help with this question please? (ping when you answer)
<@&286206848099549185>
Start with some variables
X = proportion of Art Science no Math
Y = proportion of Art Science Math
Z = proportion of Art no Science Math
W = proportion of no Art Science Math
By modelling you should find the following equations
Y+Z >= 0.8
Y+W >= 0.8
X+Y+Z+W <= 1 (disjoint)
Minimise Y/(X+Y).
how do I minimise y/(x+y)?
well if you want to show it's >= 0.8, you can also minimise Y-0.8(X+Y) and show this value is always positive
and now you have a linear program
which you can solve using linear programming methods
hmm okay I think I get it now
thank you so much! do you mind me pinging you if I need more help on this question?
just ask here ig
whoa i didn't expect this was supposed to be a linear programming question lol
just using methods i know lol
k cool thanks
can someone help in this question its Yr 10
here is the question
<@&286206848099549185>
help
me
wait what, the modelling assumptions are weird lol.
but yeah all you need to do is probably find the vertex and plug in the points A, B relative to that
firstly, realise the value of x (in terms of p) that would minimise y
wait a minute the first 3 parts are missing lol
what did you do for them lol
typically the question tends to continue on stuff you already have
the equation i had at the end was
4! + 4C2*4P3 + 4C3 * 2! + 4 + 4C2 * 2
It was the wrong answer
whats the answer
if i had to wager a guess id say its like 4⁴ = 256?? im probably wrong cause i suck at combinatorics
basically the first guy can go into any of the four rooms
and so can the second guy, and the third guy, and the fourth guy
Yeah
so thats 4 x 4 x 4 x 4
still don't quite get it
Because once the first guy can go in. I know the other people can go in as well, but that does not necessary mean that they will go in
The answer also has another part with an or
yes but they COULD go in
4^4 or 4 + 48 + 36 + 144 + 24 = 256
the question wants you to consider all possibilities
and my answer is quite similar except the number 48 and 36 is not in mine
Which i don't know how the guy even got 48 and 36
i dont know where 4 + 48 + 36 + 144 + 24 comes from ngl
@full wasp Yes but once they get in, there will be less than 4 people to fill in the other rooms
I couple explain how i got my solution if you want
sure
So, basically i took this into cases
First one which is the 24 in the answer
in other words 4!
I got 4! from the case, what if only 1 person goes to each of the room
and with the second case, what if 2 person goes to 1 room and the rest goes to individual rooms
that would be 4C2*4P3
4 choose 2 person, and then i made them into one unit and them order them across the 4 rooms
which corresponds to 144 in the answer
and also the 4, is where everyone goes into one room
but then the question here is, how did they get 48 and 36
and the equation i have right now is
4! + 4C2*4P3 + 4C3 * 2! + 4 + 4C2 * 2
[18:08]
should be c right?
hhh we are busy
im mulling it over
Let me make new calculations
Yes i got the 48
It is 4C3*4P2
4! + 4C2*4P3 + 4C3 *4P2+ 4 + 4C2 * 2
[18:08]
And that could possibly mean that 4C2 is wrong as well
But this time, i'm rather confused with what i should change the 4C2*2
That is the case when they are divided into two rooms
Still stuk with the 4C2 * 2 case
i think that way of going about it is more complicated than it needs to be
just imagine the first person shows up
they can choose any of the 4 rooms so they have 4 choices
the second person also has 4 choices
Yeah
and the third and the fourth so the total number of choices they can make is 4 x 4 x 4 x 4
But what about the ordering though
I'm think it starting to make sense
Just trying to create an image
the ordering is already accounted for in 4 x 4 x 4 x 4
like that covers all the ways u could sort the people and shove them into rooms
But I really want to know what i did wrong with my one
I just don't want to give up, I want to learn stuff through the hard way
i mean im struggling to see where those numbers come from
I know for sure now that 4C2 * 2 is wrong
Because I only accoutned for only 2 rooms
But then when I do soemthing like 4C2 * 4P2, i still got the wrong value
it is 72
However the value is suppose to be 36
i mean 36
So it is basically half the thing i got for the case when i divide the 4 people
into 2 roos
I think i'm starting to see why
Probably should just focus on the case which I am having trobule with
Like, i don't think the other values matter, only this problem is where the issue with my answer derives from
Like why is 36 half my answer
Would anybody be able to please help me?
i do have a second method but it is a bit counterintuitive
so first if u consider treating the people as one large group then you have 4 choices so this is where 4 comes from
But with my one, it is quite similar to the answer. As well as I'm quite close to solving it
just need to find a reasoning behind dividing it by 2
Like something that must of repeated
i dunno sorry
@crisp iron
<@&286206848099549185>
I think I start to get what i did wrong
it is because I had some duplicates
like forexample I would have AB __ CD ___
and i hcan have the same thing
how would i simplify this ><
What does the the denominator read
thats a two
the order makes it very complicated
because it doesn't matter in which order the room contains 2 specific people
it just contains them
if it did matter, then it's 7c4 * 4!
to go from that to the real answer you'd have to divide by 24 in some cases, by 4 in others, by 6 in others
so you think of it as a 4 digit string
1 2 1 4
1 1 1 1
1 1 3 1
just encodes who went where
aw thank u!!
Hi
hello
hi again! not sure if this channel is being used or not but… i have the function f(x) = ax^2
and im being asked to find a so the derivative of f at A(2, f(2)) is equal to 4.. literally sorry if this makes no sense in english, its in greek and im having a hard time translating it
whats the derivative of f(x)?
i found 2xa
yup then i found the derivative of 2
bc it asks for it before it asks for A(2, f(2))
and i found 4a
so you want to find a? or do you want to find f(2)?
ok lets slow down a bit
you are given:
f(x)=ax^2 and thats all?
it says to find a so the derivative of f at A(2, f(2)) is equal to 4.. translating this from greek is hard asf
one sec
is it given that the derivative at x=2 is 4? or is that something you guessed?
also x is an element of R and a is an element of R
nope it says i should find that so its 4
ok so its given that f'(2)=4
and you know that f'(x)=2ax
can you find a from those two information?
no its kot given