help-0

[stable crag]

when is one open and one closed

[worthy tangle]

i guess just plot it? shouldnt be that hard?

[stable crag]

they dont both start at 0, so you start with the offset value of 3cm of 4cm

and the other is at 2cm of 4cm

0.5cm = 1/8th , 3/4 = 3cm

i hope this helps

[visual kernel]

I see

[warped phoenix]

bruh

wtf is this saying

?

[wraith cairn]

When does x+a divide x^n + a^n

[warped phoenix]

wdym @wraith cairn

all i know is that p(x) / x - a = p(a)

[wraith cairn]

when does x+a|x^n+a^n

that's good

so p(x)/x-a = p(a)

[warped phoenix]

right

[wraith cairn]

let p(x) = x^n + a^n

notice if x = -a and n is odd, then x+a divides p(x)

[warped phoenix]

mmmm im not sure i follow

wait

lemme write this down

[wraith cairn]

only when n is odd

if n is even, p(x)>=0 and p(x) = 0 when a = 0, but here , a represents all real > 0, not just 0

[warped phoenix]

so x = -a when n is odd, but x = a when n is even, just to make sure ive got that down right

[wraith cairn]

There are two possibilities
if n is even
Then p(x)>=0 (because a^even >=0 and x^even >=0), p(x) would only equal 0 when a = 0 and x=0. Which gives x + 0 is a factor.
If a is not 0, a^even > 0, p(x)>0 so there will be no factors.
This makes sense because when a = 0, a^n+x^n is just x^n, and x clearly divides x^n
Although this is true, the question probably asks for a value of n so that x+a divides x^n+a^n for all values of a
if n is odd;
p(-a) = -a^n + a^n = 0; meaning x+a is a factor

[warped phoenix]

when you say a^even > = 0 and x^even > = 0 are you say when a and x are even the number is greater than 0 or the # is greater than = 0?

[wraith cairn]

I'm not sure what you mean by that.

any number ^ even exponent >=0

like (-2)^2 >=0

(-5)^2>=0

25^2>=0

[warped phoenix]

why are you putting an equal sign before the 0

wouldnt it be 25^2 > 0

whats 25^2 > = 0

or does it mean the same

[wraith cairn]

it means 25^2 is bigger or equal to 0

[warped phoenix]

ohhh

[wraith cairn]

I need to specify equal because a could be 0. 0^2>=0

[warped phoenix]

i see

so i get that a and x is >=0 when a and x are being raised to the power of an even number, but what about when they're being raised to the power of an odd #?

[queen wigeon]

if n is odd, $P(-a)=(-a)^{n}+a^{n}=(-1)a^{n}+a^{n}=0$

[ocean seal]

mchen10

[queen wigeon]

-1 to the power of an odd number is -1

[warped phoenix]

makes sense but how do we know a is -1

or are you using -1 as an example

ok wait

[alpine sable]

i wanna ask how to do this question

[queen wigeon]

the formula for the surface area of a cylinder is $SA=2\pi r^{2}+2\pi rh$

[ocean seal]

mchen10

[queen wigeon]

plug in the given values of surface area and radius and solve for height

[river glade]

How do I solve this? I tried a few combinatorics formulas but nothing gave me the right answer (96 and 36 respectively)

[lusty pewter]

what is 1+1 @everyone

[polar whale]

69

[alpine sable]

Why is there a 1/7

I dont get why theres a 1/7

And why isnt it just

[queen wigeon]

dt = 7 dx, dx = 1/7 dt

[civic elbow]

Hello, I need some major help with this Geometry puzzle.

[alpine sable]

Ohh damn it makes sense now, thanks!

[wraith cairn]

use SAS, SSS etc

[civic elbow]

ya I got 3 answers so far

[wraith cairn]

tbh you only need to remember the SSS rule, because with SAS you can find the third side with cos law, with ASA you can find the other sides with sin law.

[civic elbow]

could you check if they are correct?

[wraith cairn]

sure.

[alpine sable]

how do i do this question

[wraith cairn]

the last answwer is wrong

make sure you have the triangles listed in the correct order

the triangles are indeed similar, but the letters need to be in order

so it should be CHI ~ INJ instead.

CH/IN = HI/NJ = IC/JI

[civic elbow]

ah ok

What would be CIE?

Alr so what would be wrong here?

@wraith cairn

[wraith cairn]

FiB

pretty sure it's also CBA

you have to list them in the right order

for example ABC ~ EDF iff AB/ED = BC/DF = CA/FE

[minor elbow]

what the heck do i do here?

i feel like im doing something wrong but at the same time idk if im doing it right

[lusty pewter]

i like rick and morty

[minor elbow]

<@&286206848099549185>

[vagrant kayak]

pls help me in this question asap

[minor elbow]

bruh

[vagrant kayak]

<@&286206848099549185>

[minor elbow]

bruhhhhhh

[vagrant kayak]

wut

[minor elbow]

ask a diff channel

i already asked question here

[vagrant kayak]

ok ok

[carmine bronze]

<@&286206848099549185> Hello! Kinda need help with the number thoery terms.

what does 2Z and Z[i] mean?

[remote heron]

are these groups

[jagged imp]

i would assume 2Z is the set of even integers

and Z[i] is {a+bi:a,b in Z}

i as in the imaginary unit

[chrome monolith]

How do i read a and b?

[rigid smelt]

a is the vertical shift, b is the horizontal stretch

you can find a easily by comparing the two graphs

[chrome monolith]

So

[rigid smelt]

b needs some more effort by plugging in coordinates to find

[chrome monolith]

Can i get help

[rigid smelt]

i just told you how you can find either of themm

[chrome monolith]

How do i get a

[queen wigeon]

isn't b the vertical stretch?

[jagged imp]

is b not a vertical dilation

[chrome monolith]

[rigid smelt]

oh wait oops

yeah vertical stretch

[chrome monolith]

So uhhh

[rigid smelt]

either way, you would be plugging in coords to find b

but before that you need to find a

[chrome monolith]

So whats a

[rigid smelt]

comparing the two graphs

[chrome monolith]

2 ?

[rigid smelt]

see how much they are shifted

not really

[chrome monolith]

1 to 3

So 2

Oh

[rigid smelt]

ok

first state a point on sin(x)

[chrome monolith]

1

Pi/2

[rigid smelt]

(pi/2, 1) great

now

look at the second graph

look at x=pi/2

whats the y-coordinates?

[chrome monolith]

Pi/2,5

[rigid smelt]

actually nvm, we cant do that, since the graph is stretched, instead choose an x-intercept

[chrome monolith]

Pi

[rigid smelt]

and then correlate that x-int to the second graph

see how much the y value is shifted

that is your shift

[chrome monolith]

Uhhh

[rigid smelt]

in the sin(x) graph, the x-int is (pi,0)

now correlate that to the second graph

see what y is at x=pi

[chrome monolith]

3

[rigid smelt]

so how much has the y value changed?

[chrome monolith]

3

[rigid smelt]

so thats your vertical shift

[chrome monolith]

Oh okayy

And the other thing

[rigid smelt]

choose a point on second graph
plug it in and find b

[chrome monolith]

A point

Uh

4 ?

[rigid smelt]

you can just choose the x-int for easy-sake but suit yourself

[chrome monolith]

Pi then

So what do i do next

[rigid smelt]

oh nvm, dont do that, sin(pi) is 0, thats not gonna help much

any coords that wont resolve to sin(x) being 0

any coords that you can specify that is

[chrome monolith]

Pi/2 and 1

[rigid smelt]

(pi/2, 1) is not on g(x)

[chrome monolith]

2pi

And 3

[rigid smelt]

no you are missing the point here, we need a coords on g(x) that when plugged in sin(x), it wont equate 0

since we need an equation with b as a variable so we could find it

[chrome monolith]

What would u use

[rigid smelt]

you were very close when choosing x=pi/2

[rigid smelt]

the reason i say this is because you can plug this into g(x)

the point is not on g(x)

you must choose a point on g(x)

so what other (pi/2, y) point(s) are there that is on g(x)?

[chrome monolith]

3pi/2 ?

[rigid smelt]

sure, but we only have the x coordinate

we need the y coordinate too

[chrome monolith]

3pi/2 and 1

Wait

[rigid smelt]

yes its on g(x)

[chrome monolith]

Oh

So 3pi/2, 1

[rigid smelt]

so plug it in and find b

[chrome monolith]

Plug 1 into sin x ?

[rigid smelt]

which one is the x-coordinate?

3pi/2 or 1?

[chrome monolith]

3pi/2

[rigid smelt]

so where do you plug the x coordinate in?

[chrome monolith]

I got 0.08

[rigid smelt]

?

[chrome monolith]

Sin (3pi/2)

[rigid smelt]

...you are supposed to be plugging it into g(x) and find b, also try to use the exact value

[chrome monolith]

So a is 3

[rich basin]

would anyone be able to please help me at question 1

[rigid smelt]

yes

[chrome monolith]

3 + b sin (3pi/2)

[rigid smelt]

g(3pi/2) = 3 + b sin(3pi/2)

so sin(3pi/2) is a quite nice value

dont know why you got 0.08

probably you had it on degree mode

[chrome monolith]

-1

Oh

Shit

So -1

-3

I mean

[rigid smelt]

solve for b

[chrome monolith]

-1 + 3

[rigid smelt]

please stop typing down random numbers

[chrome monolith]

😭

[rigid smelt]

i cant understand

[chrome monolith]

Sin (3pi/2) is -1

So

[rigid smelt]

at least you can write it as an equation of some sort

[chrome monolith]

3 - 1 = 2

[rigid smelt]

ok slow down

what is g(3pi/2)?

[chrome monolith]

3 + b -1

[rigid smelt]

can you answer this?

[chrome monolith]

This

[rigid smelt]

no im asking for the value

[chrome monolith]

-1

[rigid smelt]

g(3pi/2) is the output of the function g(x) at x=3pi/2

and it definitely isnt -1

remember how i told you to plug in (3pi/2, 1) into g(x)?

[chrome monolith]

Can you just write out the answer plz

[rigid smelt]

ok cool

just wait a moment, and read the exercise

i definitely will write out the answer for you

[chrome monolith]

....

I have an exam

Mann

This is not the exam

Its practice

[chrome monolith]

Bro please

I alrdy said what i know

Im not understanding what ur saying

[rigid smelt]

once again, plug in the coordinates into g(x)

and find b

[chrome monolith]

Ive been

Doungg that

[rigid smelt]

g(x) = 3 + b*bsin(x)

thats your equation

all you just need is to plug in the numbers

[chrome monolith]

3 + -1b

3 + -b

[rigid smelt]

and thats not an equation

[chrome monolith]

3 - b

[tawdry bough]

random question

[chrome monolith]

@tawdry bough help me plz

[tawdry bough]

wait you ugys are busy nvm

[rigid smelt]

this is the equation, the numbers you wanted to plug in was (3pi/2, 1)

[chrome monolith]

Yes

[prime peak]

i can help you @tawdry bough

[rigid smelt]

so seems like you understand what to do

[chrome monolith]

3 + b × 3pi/2

[rigid smelt]

....

[chrome monolith]

What

[rigid smelt]

once again, i gave you the equation, you turned it into an expression

it doesnt make any sense?

[chrome monolith]

No

[rigid smelt]

no it doesnt

secondly, you are supposed to replace x's place with 3pi/2 and not sin(x)'s place

[chrome monolith]

Bro ive wasted 15 mins on this one question

G(3pi/2) = 3 + b × sin (x)

What do i do with that

[rigid smelt]

and what is g(3pi/2)?

[chrome monolith]

I dont know

[rigid smelt]

are you familiar with function notation?

im trying really hard to guide you thru the thing without giving away the answers

[chrome monolith]

I need the answer

[rigid smelt]

yeah too bad

[chrome monolith]

Ill try figure it out

Just type it out

[rigid smelt]

are you familiar with how function are notated?

[prime peak]

isn't it just g(3pi/2) = 3+bsin(3pi/2)

[chrome monolith]

Whats the answer

[rigid smelt]

đừng cho câu trả lời

anyway

[chrome monolith]

Bro

[prime peak]

KEK

[chrome monolith]

This is not helping

At all

[rigid smelt]

again slow down

are you familiar with how functions notated?

[chrome monolith]

Yes

Idk

[rigid smelt]

for example lets say we have f(x) = x

if i were to tell you to find f(1)

can you evaluate it?

[chrome monolith]

1

Its 1

[rigid smelt]

yes

[prime peak]

we don't have g(x) yet thouggh

we can't evaluate it

[rigid smelt]

so now you know that on the graph of g(x), at x=3pi/2, g(x) has a y value of 1

so what is g(3pi/2)?

[prime peak]

oh it's on the graph

[chrome monolith]

Idfk

Mannn

[rigid smelt]

the y value is the output

if you just calm down and think

it will help you

[chrome monolith]

No it wont

[rigid smelt]

all im doing is giving you the information you need

im not supposed to be giving you the answer

[chrome monolith]

I need the answer

[rigid smelt]

alright i guess i wont be able to help then

[chrome monolith]

I can try understand

After

Idk wtf ur saying

Ughhhh

[vague iris]

Hey guys!
How did (2^x)+(2^x) become 2(2^x)?

[prime peak]

cuz it's just adding two of the same thing

[chrome monolith]

Can u tell me the answer

[prime peak]

STAN + STAN = 2STAN

[chrome monolith]

Plz

[prime peak]

idek what your question and what work you've done so far man

[chrome monolith]

B is 3

[vague iris]

oh God I'm getting dumber everyday. I forgot. Thank you!!

[chrome monolith]

I need a

[prime peak]

we're trying to find a and b

[chrome monolith]

Yeah ik b is 3

[prime peak]

ok

so we need another equation to find a

[chrome monolith]

Yeh

The top one

[prime peak]

how'd you find b

[chrome monolith]

U alrdy know how to right

[prime peak]

i actually dont rn i'm busy lookin at a

[chrome monolith]

Wait i forgot

[prime peak]

wth how did you find b first

ok so far i c an see that we can use the points (0,3) and (3pi/2,1) to find it

actually we can use a lot of points

but we only need 2

[chrome monolith]

Y value at pi is 3

So it shifted by 3

How do we find a

[prime peak]

we can find a if the bsinx = 0 right

so we need to make bsinx=0

that means we need to make sinx = 0

[chrome monolith]

What

[prime peak]

what

we need to substitute a value of x into the equation g(x) = a + bsinx such that sinx will be 0
this way we'll get
g(x) = a

and we can evaluate whatever g(x) at that specific x

[chrome monolith]

Yea

[prime peak]

we can try 0

or pi

doesn't rly matter they're both the same

[chrome monolith]

Yh

[prime peak]

when x = 0 -> sinx = 0 -> g(0) = a = 3

so a = 3

make sense?

[chrome monolith]

A and b are both 3 ?

[prime peak]

idk

i haven't found 3

how would you do it

find b

i mean

[chrome monolith]

Idk how to

Waler said it shifted 3

[prime peak]

ok well so far we have

g(x) = 3 + bsinx

now we need to plug in a value that will allow us to turn the equation into

g(x) = 3 + b

right?

we wanna isolate b

if we could find a value of x that would isolate b it would help

the way i see it

we could set sinx = 1

if sinx = 1, then x can be pi/2

[chrome monolith]

@rigid smelt b is 3 right

[prime peak]

so g(pi/2) = 3 + b

b= g(pi/2) - 3

what's g(pi/2)

if we look at the graph it's 5

you followin? @chrome monolith

[chrome monolith]

Uhh

The ans key said b is 2 and a is 3

[prime peak]

mhm

[chrome monolith]

I thought b was 3 man

[prime peak]

g(pi/2) = 5
b = g(pi/2) - 3 = 5 -3

idk how you got there

that b = 3

[chrome monolith]

5 ?

[prime peak]

yea

[chrome monolith]

G (x) = a + b sin x

[prime peak]

yes

no disagreements so far

[chrome monolith]

So

What did u do

[prime peak]

we have a = 3

you agree w me on that?

[chrome monolith]

Idk how u got that

[prime peak]

i just explained it to you above but ok

i'll explain it again

[chrome monolith]

Thanks

[prime peak]

g(x) = a + bsinx

[chrome monolith]

Yh

[prime peak]

let's say we had some juicy magic value that we can plug into this equation that wouold give us the value of a

eventually we want the eqaution to look like "a = SOMETHING"

right?

[chrome monolith]

Uhuh

[prime peak]

where SOMETHING is a concrete number

ok

g(x) = a + bsinx

wouldn't it be nice

if we could make g(x) turn into SOMETHING1 and bsinx turn into SOMETHING2

[chrome monolith]

Yea

[prime peak]

that way we could rewrite the equation into a = g(x) - bsinx = SOMETHING1 - SOMETHING2

ok

so

in order to find this

magic value

for x

we need to look at points on the graph

[chrome monolith]

Yh

[prime peak]

if you notice

[prime peak]

(0,3) is on the graph, yes?

[chrome monolith]

Pi,3

[prime peak]

ok

pi,3 works too

[chrome monolith]

Yeah

[prime peak]

so (pi, 3) is on the graph

[chrome monolith]

Yh

[prime peak]

let's try plugging it into our equation

a = g(pi) - bsin(pi)

g(pi) = 3 because the point on the graph is (pi, 3)

so a = 3 - bsin(pi)

and sin(pi) evaluates to 0

so a = 3 - 0

a = 3

everything good so far?

[chrome monolith]

How g(pi) = 3

[prime peak]

g(pi) = 3 because (pi, 3) is on the graph for the equation y = g(x) = a + bsinx

[prime peak]

are you ok with that? does that explain how g(pi) = 3 to you

[chrome monolith]

Sure

[loud iris]

are you done ? i also have a doubt, maybe you can clear it ?

pls

[prime peak]

is it quick

ask here

[loud iris]

guys can you help me out w this ?
sin2x=cos3x
find the general solutions

its very small

i just need one catch

[prime peak]

change sin2x to cos(SOMETHING)

[urban holly]

I kinda need some help at the moment.

[prime peak]

and then solve for cos(SOMETHING) = cos(SOMETHINGELSE)

@chrome monolith you good?

[chrome monolith]

Nah

[prime peak]

ok

[chrome monolith]

Help him tho

Ill wait

[prime peak]

ok

[loud iris]

i got x=2npi/5+pi/10

[prime peak]

there should be 2 solution families

[loud iris]

which is not the correct ans

[prime peak]

wait

[loud iris]

yea

[prime peak]

this one looks like one of the correct ones though

[hollow beacon]

draw it out will probs help

[prime peak]

eh

usually in these trig courses they'll have you do it algebraically

[hollow beacon]

at least you'll know when u get it right tho

[prime peak]

how did you do it

[loud iris]

my textbook says
x=(4n+1)pi/10 or x=(4n-1)pi/2

thats the ans in my textbook

[prime peak]

(4n+1)pi/10 is the one you got

[loud iris]

yup

cant seem to get the other one

[prime peak]

show your work?

[loud iris]

i would have to do it on paint

dont have a phone

wait a sec

[prime peak]

it's probably faster to just type it out

the general solution of cos(theta) = cos(alpha) is given by theta = 2npi ± alpha, n ∈ Z.

i think that will help you ^

@loud iris

[chrome monolith]

Yo

[loud iris]

@prime peak

[loud iris]

yes ik that

sorry

dont beat me

the plus

pls

[prime peak]

you're also forgetting the case where
-3x = 2npi + pi/2 - 2x

[loud iris]

forgive me

[loud iris]

wait

[prime peak]

found this off a vietnamese forum post in 2016

[loud iris]

how did 3x get negative

[prime peak]

i'm assuming you know what the square bracket is

[prime peak]

there's a plusORminus sign before alpha

the general solution of cos(theta) = cos(alpha) is given by
theta = 2npi + alpha OR theta = 2npi - alpha
for n in Z

[loud iris]

well in that case shouldn't be (pi/2-2x) minus

like

in negative

[prime peak]

you can try it

loll

it'll work out to be the same thing

[loud iris]

ok

thanks man

[prime peak]

cuz n is in Z

it'll just go in the other direction

[loud iris]

yea i got it

[chrome monolith]

Ur done

[loud iris]

https://tenor.com/view/cat-jumping-excited-play-time-gif-9841068

[loud iris]

yes bro

[prime peak]

yep

[chrome monolith]

Alr

[prime peak]

where were we

a = 3

now we find b

[chrome monolith]

Yh

No

I dont know how u got 3

[prime peak]

oh ok

ok so we have

a = g(x) - bsinx

and we're plugging in the point (pi, 3)

the point (pi, 3) is actually telling us that we have 2 other equations we can subsitute into a = g(x) - bsinx)

pi, 3 really just means
x = pi and y = 3

y = g(x)

that's why g(pi) = 3

does that make sense?

[chrome monolith]

Yh

[prime peak]

ok

so

a = g(pi) - bsin(pi)

a = 3 - b*0

a = 3

good?

[chrome monolith]

Yy

[prime peak]

pog

so now we have a = 3

let's find b

our equation can now be written as

g(x) = 3 + bsinx

because we already know that a = 3

we go through the same process

wouldn't it be nice if we had another point we could use

to make it so that our equation turns into

b = something

what if we could make sinx = 1 and g(x) = somethingElse

that way our equation would be b = 3 - somethingElse

[prime peak]

so we need to find a point that will make sinx = 1

[chrome monolith]

U have a vid on this

[cold copper]

what do we do here?

[prime peak]

i don't

@cold copper every chord has a radius that is orthogonal to it

[chrome monolith]

What point

[prime peak]

if you draw the radius from the smaller circle to the chord

[prime peak]

what value of x will make sinx = 1?

[chrome monolith]

Idk

[prime peak]

look on the graph

you have sinx graphed

[chrome monolith]

Pi

2

[prime peak]

what

[chrome monolith]

Pi/2

[prime peak]

oh

yea

ok

so x = pi/2 -> sinx = sin(pi/2) = 1

we plug x = pi/2 into the equation

g(x) = 3 + bsinx

g(pi/2) = 3+ bsin(pi/2)

g(pi/2) = 3 + b

[chrome monolith]

Man wtf

[prime peak]

what's wrong

[chrome monolith]

This whole question

[prime peak]

would you like me to continue? or would you like to me to backtrack to somewhere you don't understand

[chrome monolith]

Bro

[prime peak]

i got all day

[chrome monolith]

Why do i have to do so much working

For 4 marks

[prime peak]

maybe it could be because you don't really see the relationship between points on a graph and how the coordinate components of those points are variables that satisfy the equation of that graph

it's really not that much working

it's just plugging in two points
(pi/2, 5)
(pi, 3)
into the equation g(x) = a+ bsinx

and then solving for a and b

much like you would a linear system of equations

[chrome monolith]

Yea

I dnt get it tho 🥲

Isnt there a easier way

Why do i have to do all of this

???

[chrome monolith]

Can we run thru it again

[prime peak]

do you wanna join a voice channel?

i can share screen and explain it to you

[chrome monolith]

Yh

I cant talk tho

[prime peak]

ok

[chrome monolith]

Thx

[open idol]

hello

i need help creating a math function for my code

im creating flappy bird rn, but i usually model my jumps with a parabola

but the motion in flappy bird is wierd

its like a horseshoe motion

is there a graph that can model that

[ionic jewel]

thats called a parabola yes

try drawing it, horseshoe and parabola seem pretty similar to me

[open idol]

like this?

[ionic jewel]

do you not have physics?

[open idol]

like i want the top to be more flat and the bottom to be more of a parabola

[ionic jewel]

hm

i don't remember flappy bird well enough to give a better thing for the motion sorry

[open idol]

: / nw

actually, i think i got it, ill just model it with an exponential function

[chrome monolith]

What is the derivative of ln 2x

[ionic jewel]

,w derivative of ln(2x)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[chrome monolith]

The ans key put (2/2x)

[ionic jewel]

that's literally the same thing

2/2 = 1

[chrome monolith]

Ik

So

X^2 × 1/x

X ?

[ionic jewel]

yea

assuming x = X

[chrome monolith]

,w derivative of x^3 ln(2x)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by heyguysimhere#7917

[ionic jewel]

product rule my dude

[chrome monolith]

Yh ik

But this working

Is confusing me

Oh wait

Lolol

When u factor out x^2

Where does the 1 come from

3ln2x

[mossy berry]

if two random variables X and Y are independent. Will their standardized random variables also be independent?

[vale wigeon]

wym by standardized?

[serene hearth]

Can someone explain to me how he devised (a)

[lusty pewter]

hey is this channel free to ask a question?

[ionic jewel]

derivative wrt x then derivative wrt y

[mossy berry]

$$\frac{(X - E[X])}{SD(X)}$$

[ionic jewel]

that's why they are both on the bottom

[serene hearth]

ohhh

[ocean seal]

ImperfeKt

[serene hearth]

I see

I thought he multiplied xD

[ionic jewel]

how would that possibly change the independence

[vale wigeon]

it would not

[lusty pewter]

Ann can you help me in questions-1

[vale wigeon]

if X and Y are independent then so are f(X) and g(Y) for sufficiently-nice functions f and g of a real variable

[mossy berry]

but E[X] and SD(X) are constants

[vale wigeon]

and?

[mossy berry]

so would that make (X - E[X])/SD(X) a real valued function of X?

[vale wigeon]

...yes?

yes, it would

assuming that the expectation and SD of X both exist, of course

[mossy berry]

so accordingly, (X - E[X])/SD(X) and (Y - E[Y])/SD(Y) should also be independent. Or am I missing something?

[vale wigeon]

yes

that was my point

[mossy berry]

wait a second, was this message for me? or someone else?

I thought it was for me.

[vale wigeon]

it was at bunny

[mossy berry]

🤦‍♂️

[lusty pewter]

can i have some help with

1 / x + 1 / a = 1 / b

make x the subject ?

[vale wigeon]

how much progress have you made?

[lusty pewter]

nothing

im stuck

lmao shouldt u be asleep

if its like 2.30

[vale wigeon]

bold of you to assume i'm in the united states or anywhere else with those timezones

[lusty pewter]

oh wait nvm wrong person

nah sorry i was just talking to someone

[vale wigeon]

it's 10:37 here

[lusty pewter]

lmao soz

[vale wigeon]

anyway

how about a simpler equation to hopefully jog your memory:
1/y = z
can you solve for y here?

[lusty pewter]

1 = yz

1/z = y

[vale wigeon]

great

now look back at your equation

1/x + 1/a = 1/b

[abstract breach]

yup

[alpine sable]

Ann! how are you?

[vale wigeon]

@lusty pewter can you first isolate *1/x here?

@alpine sable i am not in the mood for smalltalk and i am not in the mood for excel fuckery either.

[lusty pewter]

hey no swearing

[alpine sable]

can you please help me after you are done with Asher?

[abstract breach]

no.

[lusty pewter]

1 / x = 1 / b - 1 / a

1 / ( 1 / b - 1 / a) = x ??

[vale wigeon]

yes

you can now simplify 1/(1/b - 1/a)

[rocky cloak]

As I understand it, mutual information is the same under reversible transformations.

[lusty pewter]

ab = x ??

[rocky cloak]

sorry didnt notice this was active

[lusty pewter]

all good

[vale wigeon]

no.

[lusty pewter]

i do that all the time lmao

[vale wigeon]

1/(1/b - 1/a) does not simplify to ab.

[lusty pewter]

i am feeling like a monster i might just be impostor

i dont know how to simplify that

[vale wigeon]

can you simplify 1/b - 1/a first

[lusty pewter]

no

[vale wigeon]

why not?

do you not know how to add fractions?

[lusty pewter]

😦

[vale wigeon]

is it more excel shit you need help with? if so, then i believe i've already made myself clear, but in case i haven't: i'm not in the mood for it.

[lusty pewter]

no

lol

i forgot

[vale wigeon]

so if i asked you to add 1/5 + 2/7 you would be unable to do it?

[lusty pewter]

12 / 35

a / ab - b / ab

1 / a - b = x

?

@vale wigeon

why u such a sussy baka

dubstep music plays

im feeling like a monster i might just be impostor

insane electronic music beatdrops

among us is life

[vale wigeon]

...

[lusty pewter]

12 / 35
a / ab - b / ab
1 / a - b = x
?

is this right?

[vale wigeon]

no, 1/5 + 2/7 is not 12/35, it's 17/35.
no, 1/(1/a - 1/b) does not simplify to 1/(a-b).

[lusty pewter]

1 / b - a

my bad

[vale wigeon]

no it doesn't simplify to that either

[lusty pewter]

i am mathematicen

[vale wigeon]

also. 1 / b - a reads as (1/b) - a and not as 1/(b-a)

[lusty pewter]

oooooh

[vale wigeon]

okay so are you going to keep memeing at me or what

[lusty pewter]

i am literally not memeing

[vale wigeon]

the whole "sussy baka" thing makes me feel like i'm having to discipline a child

[lusty pewter]

fax

[vale wigeon]

1/b - 1/a simplifies to (a-b)/(ab).

taking the reciprocal of that gives ab/(a-b).

[lusty pewter]

wait so doesnt it turn to 1/ (a/(ab) - b/(ab))

[vale wigeon]

if by "it" you mean 1/(1/b - 1/a), yes it does.

[lusty pewter]

letsgo

im a mathematicen

ok

[storm crystal]

Bruh

There are so many YouTube videos lol

Just look up “adding fractions”

[vale wigeon]

god yeah why do i even bother

[lusty pewter]

😦

[vale wigeon]

obviously it's leagues better to accrue several thousands of hours in YouTube video watch time than have a real human person attempt to explain basic algebra to you

(sarcasm)

[lusty pewter]

huh

so ur a racist

wow

[vale wigeon]

???

[lusty pewter]

that was uncalled for

cya

[vale wigeon]

i beg your pardon?

was my last message racist somehow???

[lusty pewter]

no

[vale wigeon]

then why are you accusing me of being racist?

[lusty pewter]

you dont like blue dude?

[vale wigeon]

???

[lusty pewter]

blue??

[vale wigeon]

when did i express any sort of dislike towards you in particular?

[lusty pewter]

is 1/(a-b)/(ab) the final answer

wait no

i divide

[vale wigeon]

you haven't answered my question.

why are you accusing me of racism? on what grounds?

[lusty pewter]

no im not

blue people are family

[lusty pewter]

so is the answer ab/a-b = x

[vale wigeon]

"huh
so ur a racist
wow"
so this ISN'T an accusation of racism?

[lusty pewter]

no

i am confused

[vale wigeon]

then why the hell do you make it sound like one

[lusty pewter]

how does that look like a racism accusation to u??

[vale wigeon]

"so you're a racist"

you claimed i was racist

[lusty pewter]

are u calling me a racist now??

[vale wigeon]

no

[lusty pewter]

wow

[vale wigeon]

i am quoting what you said

[lusty pewter]

so now ur accusing me of being racist

[vale wigeon]

no, i'm not.

[lusty pewter]

what did i do that was racist

i am just a blue dude

[gray isle]

This conversation is clearly productive. /s

[lusty pewter]

wait so is the answer ab/a-b = x

[vale wigeon]

are you being difficult on purpose

[lusty pewter]

no

i am learning maths

[vale wigeon]

parentheses around the denominator

but yes

[lusty pewter]

ab/(a-b) = x

thanks for help

[vale wigeon]

for future reference, if you're going to accuse people of something, you need to have a way to back up your accusations.

especially for an accusation as serious as racism.

[lusty pewter]

huh

im not racist

stop saying im racist

[fervent grail]

Given f(x)=x²+ax+b is HCF of g(x)=x⁴-3x³+2x²-3x+1 , h(x) = 3x⁴-9x³+2x²+3x-1 , Find a and b.

[vale wigeon]

@lusty pewter I'M NOT SAYING YOU'RE RACIST, YOU DIPSHIT

[lusty pewter]

cool

[alpine sable]

hey hey knock it off guys

[lusty pewter]

apparently i am racist

i am confused

but ok

[vale wigeon]

you aren't and i never said you were

[lusty pewter]

i will leave chat

[alpine sable]

why are you leavining?

[lusty pewter]

cos u said knock it off

[alpine sable]

no lol I'm saying make peace and leave it

the both of you

no need for us to argue

[lusty pewter]

yes

[alpine sable]

you all good blue dude?

This will help you

https://www.youtube.com/watch?v=68ugkg9RePc

[lusty pewter]

that slaps

@alpine sable can u help me with math

[alpine sable]

what level math is it?

[lusty pewter]

9

15 yr old

it is ez

1/2x + 1/3x = 1/4

isolate x

[uneven garnet]

$x^a ≥ x^b \Leftrightarrow a≥b$ ?

[ocean seal]

Thk

[alpine sable]

Sorry man

[uneven garnet]

😦

[vale wigeon]

@uneven garnet no

[alpine sable]

I usually go to Ann for help

[vale wigeon]

thk, that is not true

[lusty pewter]

does 4 = x

[uneven garnet]

Okay, I have to add a condition ?

[alpine sable]

no idea brother, ask Ann

[vale wigeon]

blue dude, do you mean $\frac12x + \frac13x = \frac14$ or $\frac{1}{2x} + \frac{1}{3x} = \frac14$?

[ocean seal]

Ann

[lusty pewter]

the 2nd one

[vale wigeon]

okay

so why not write it as 1/x * (1/2 + 1/3) = 1/4

[lusty pewter]

idk y

[alpine sable]

how to do question 1 a

[vale wigeon]

@alpine sable channel busy please move

[lusty pewter]

,w help

[ocean seal]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by Blue Dude#5953

[fervent grail]

Given f(x)=x²+ax+b is HCF of g(x)=x⁴-3x³+2x²-3x+1 , h(x) = 3x⁴-9x³+2x²+3x-1 , Find a and b.

[lusty pewter]

i found the answer

,w 2018^{2018}

[vale wigeon]

OH MY GOD WHY DO PEOPLE KEEP QUEUING UP HERE

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Blue Dude#5953

[vale wigeon]

QUESTIONS ZERO IS FUCKING CURSED ISTG

im out

[lusty pewter]

can u help @vale wigeon

1/2x + 1/3x = 1/4

1/ x(1/2 + 1/3) = 1/4

[vale wigeon]

im out

[lusty pewter]

😦

[vale wigeon]

so no i can't help you

[lusty pewter]

ok

bye

[vale wigeon]

have a nice fucking day

[lusty pewter]

ok

[fervent grail]

Given f(x)=x²+ax+b is HCF of g(x)=x⁴-3x³+2x²-3x+1 , h(x) = 3x⁴-9x³+2x²+3x-1 , Find a and b.

[lusty pewter]

i like rick and morty

[chrome monolith]

Can i get help please

With c (ii)

[jagged imp]

use the formulas for mean and variance to get a system of equations in n and p

[chrome monolith]

I tried

So P (X < 1)

9C0 × (0.4)^0 × (0.6)^9 right ?

And then

9C1 × (0.4)^1 × (0.6)^8

When i put it in tho i dont get the same ans

[jagged imp]

is this meant to be relevant to the question?

also, that second calculation isnt even relevant to P(X<1)

[chrome monolith]

P (X=1)

And P (X=0)

It is relevant

[chrome monolith]

Yes

[jagged imp]

Have we completely

just gone past cii)?

[chrome monolith]

P (X </= 1)

[jagged imp]

what does </= mean

and again, what does it have to with cii

[chrome monolith]

Greater or equal to

Finding P (X > 2)

Bruh

[jagged imp]

WHICH HAS WHAT TO DO WITH CII

[chrome monolith]

FINDING IT

Omfg

What the fuck

[jagged imp]

oh cii

i thought you meant ci

[chrome monolith]

No

Jesus

[jagged imp]

,,,

[jagged imp]

so you didnt get the right answer when you did 1-this and

[chrome monolith]

No

I didnt find that

[jagged imp]

good cause you shouldnt have sorry

lmfao

[chrome monolith]

So

???

[jagged imp]

you have the right calculation

you must have put it into your calculator wrong or something

is the answer key's answer 0.929456 or so?

[chrome monolith]

0.9804

Thats the ans key

[vague gate]

[spring harbor]

you can't have >= sign, you need to work it out by doing 1-P(X=<a)

Is there an issue?

[jagged imp]

it seems to be wrong.

,w binomial distribution n=9 p=0.4 X=0

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Sneaky#0928

[jagged imp]

for instance, they have the value for X=1 succeses wrong

[spring harbor]

,w binomial distribution n=9 p=0.4 X=1

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Echo#1357

[spring harbor]

I think this should be your answer

Or 1-that at least

[chrome monolith]

Huh

[spring harbor]

Because you got >=2 or 1 - P( 1 and 0 )

[chrome monolith]

Yeah

P (X </= 1)

[spring harbor]

Your teacher might've messed up the ans. key

[chrome monolith]

So what wud the ans be

I got 0.929

[vale wigeon]

P(1 and 0) is zero, you meant P(1 or 0)

[spring harbor]

My bad sorry.

[vale wigeon]

,calc 1 - 0.6^9 - 9 * 0.6^8 * 0.4

[ocean seal]

Result:

0.929456128

[chrome monolith]

?

[vale wigeon]

that's the answer to part ii

[chrome monolith]

This is from the exam board man 😭 they r such a mess

Wtf

[vale wigeon]

0.929 is close enough

does that disagree with the answer key in a way that can't be attributed to rounding?

[vale wigeon]

huh

,calc 0.6^9

[ocean seal]

Result:

0.010077696

[jagged imp]

those values seem to have nothing to do with P(X=0) and P(X=1)

[chrome monolith]

Exactly

[vale wigeon]

,calc 9 * 0.6^8 * 0.4

[ocean seal]

Result:

0.060466176

[vale wigeon]

yeah they messed up bad

[chrome monolith]

🥲🥲

[vale wigeon]

or maybe it's the wrong problem

[chrome monolith]

Maybe

[vale wigeon]

let's see if it's possible to recover what values of n and p were used here

p^n = 0.00218
np^(n-1) (1-p) = 0.0174

,calc 0.0174/0.00218

[ocean seal]

Result:

7.9816513761468

[vale wigeon]

about 8... hm

[strong dome]

Hi.
How many subsets of {1,2,...10} contain at least one of these pairs: {2,3}, {4,5}, {5, 6}?

[minor crypt]

3+3×8!

hmm no this is actually a combination problem

[strong dome]

yes

[cosmic granite]

@minor crypt i have ran a lot of simulation tests on the equation you gave me yesterday. It’s working to some point but if you check, the time division either gives you your entire chance of item rate or it decreases it for you. I need some sort of a way to increase it when the day is about to finish and not all items has been given.

[alpine sable]

do i have to use pi in this?

[hazy aurora]

you probably have to use polar coordinates, and there should be a pi in there

[alpine sable]

wdym by polar cordinates?

[hazy aurora]

https://en.wikipedia.org/wiki/Polar_coordinate_system

Since you have a circular region, it is easier to describe it by an angle and a radius instead of bounds on x and y itself

so if you apply a coordinate transformation into polar coordinates, the integral will be easier to calculate

[alpine sable]

i did somthing like this

[hazy aurora]

yeah this looks right to me

[alpine sable]

aah okay thanksss 😄

[ocean seal]

n256

[alpine sable]

anyone here good with excel?

how to solve this?

I tried for AP but it gave a really complicated equation with quadratic of n and r

[hollow pelican]

can anyone help?

[dawn wraith]

There is a well-known identity with cosine that enables you to have an equivalent term in terms of sine

Do you know what it is?

@hollow pelican you there?

[hollow pelican]

yes

is it this?

[dawn wraith]

Nope

I’ll hand you a hint

Think about right triangles with trigonometry

[sage summit]

well you can use the cos(A-B) one if you want

[dawn wraith]

Yeah but that’s overkill

[sage summit]

yes it would be

[dawn wraith]

Well, they’re complementary

@hollow pelican do you know as to what I’m referring to?

[hollow pelican]

oh

[hollow pelican]

is it this formula?

[dawn wraith]

No.