#help-0
1 messages · Page 681 of 1
ohhh
i see
so how do i know at what point to apply the +-?
should it be from the beginning of my equation?
because its a quadratic?
you took a square root...
any even root brings a +/-
I need some help on this, I have 10 more minutes till i can submit these two questions, if someone can help i would be greatful
transposing is my greatest enemy
why the time limit?
i only got 10 minutes till the assignment goes late
ok obviously apply order of operations
and
how would you
how would you explain how to rearrange an equation verbally
algebraic manipulation
uh
sorry i dont really understand
ok you could apply some properties of shapes over here in terms of angles, consider AB||DE you could also apply some angles in parallel lines
and thats about it
sqrt(v/pi *h) = r
Basic LaTeχ syntaxes include \sqrt[]{} \pi \cdot or \times \qty or \left\right for autoscaling brackets \frac for fractions
what about in this example? There are no x-intercepts, so how do they know what the third point is? they say to find one more point, and to determine the point for x = -1, where did the get -1 from? how did they know to make x equal that?
Thanks
$r = \sqrt{\frac{v}{\pi h}}$
Vex
$v = \sqrt{\frac{P-mg\times r}{m}}$
I think thats correct
Good way of checking is using https://cymath.com
\times for the x and \cdot for the interpunct
just wait until you hear about Wolfram alpha
Central dot, middle dot, or whatever you call it
Vex
$\cdot$
bunny
I was way off lol
If you're given two line equations, how can you find the angle they make with each other?
wot
what?
Is my question unclear?
Let's say you have y= 2x and y=x, how can you find the angle they make with each other?
So I am supposed to do arctan(m1)-arctan(m2)?
It's given that it's an acute angle
But m1 is 2/3 and m2 is 3/2. How can I find the arctan of these numbers?
I am not supposed to be using a calculator.
hmm
Trivial Trigonometric Identities maybe?
Such as?
In mathematics, trigonometric identities are equalities that involve trigonometric functions and are true for every value of the occurring variables for which both sides of the equality are defined. Geometrically, these are identities involving certain functions of one or more angles. They are distinct from triangle identities, which are identit...
Also using the formula I get 0.4 (if my calculator is in rads) which is none of the options
Hmm
Then convert them to degs
I get 22
Can I look at the question itself
nevertheless i still get the wrong answer
Yeah sure wait let me translate it
this is a
can someone helpm e out with this
Ren can't you see us talking here?
this is b
we need to find the tangent line of b
which i did
i got 2/3x + 3
mb
then i need to find cos alpha of the angle they make
ok what does in het punt (3,5) mean
can someone help me
Channel taken
Yeah no worries, thank you regardless.
But now that I think about it, tanx * tan y = 1, so we can say that cosx cosy = sinx sin y
maybe we have to use that for something
Channel taken
or
cos^2 x cos^2 y - sin^2 x sin^2 y = 0 <=> cos^2 x - sin^2 y = 1 => cosx = sin y => cos y = sinx
hmmm
cos(x-y)=cosxcosy + sinxsiny => 2cosxsinx = 2cos^2(x) tanx
cos^2(x) = 1/(1+tan^2(x)) so we get cos^2(x) = 1/(1+(3/2)^2) = 4/13
so 2 * 4/13 * 3/2 ?
or 12/13
Hello everyone, hope you are having a great day, I need help with this solid geometry question
But no one answered my question bro, try another channel please
tough
this channel is occupied can u leave please
what
Don’t start clowning
Did you get your question answered
I still don't understand it
but i think your working is fine
who
Echo
Yup I showed the steps above
Did you read them?
Not sure if it’s correct though but it seems reasonable
2 is wrong; that's not a proper transformation
It seems so far fetched though
How can I fix it
I will post my question in another channel
why aren't these parallel?
I fail to understand how that diagram is even possible
Maybe if you bent the ends?
No
All straight lines are 180
U cant do more
Plus it doesnt look like 130
Legit is 110
well yeah, but nowhere in the problem does it say that two lines are being cut by a single line
yeah no that's totally wrong
you could have something like this
Well yeah
But thats not gonna happen on a simple quiz
It would be impossible to solve
How would you calculate the height of this figure, given that the diameter of one of the circles equals 10?
connect the centers of the circles and use the properties of equilateral triangles
Yikes
yes
How did u come up with that so fast mchen
Yeah I kinda already had that, but not sure how to progress
yup
mm?
Ye
We can split that in half, and use cos 30 = the height of that triangle, then we can add 10cm to it
Ye
or no we need to use sin 30 = x/20 my bad
Can someone explain this small step for me
why is the equality true?
I mean equal to 0
or expand $\frac{1}{n^2-1}$ by partial fractions, write it out, and see which terms cancel out
mchen10
Wut
Whst
?
What is dirichlet
nevermind found the answer
Oh lol
nice handwriting
just wanna know how to prouve it
it's the professor not me😂
anyways i am in 9th grade so i am out
ok not a problem dude
<@&286206848099549185>
@hushed pasture can I check that that says
$\lim_{n \to +\infty} \frac{|x-a|^{n+?}}{(n+?)!} = 0$
Xetrov
I don't know what it says in the question marks
looks like a 1
well i was doing a calculus exercice and then the prof said that this limit is tend to 0
but I didn't understand it
yeah that's logical, but there is a way to prove it
Im starting 8th grade and i suck at algebra
@hushed pasture does that say 1?
not to mention i am asian
no it's 0, it's just the prof said that this limilt is equal to 0
but I didn't get it
@hushed pasture No lol, the question marks
here
could you prove it like you don't know the output yet?
that's what I'm looking for
you're ignoring me lol, I can't read the Profs writing
what is your question, i thought that you didn't ask me
so the fraction is (X-a)^(n+1)/(n+1)!
they're 1s?
yeah 1
$\lim_{n \to +\infty} \frac{|x-a|^{n+1}}{(n+1)!} = 0$
Xetrov
unknown x ya?
yeah but the limit is for n not x
yes I see xD
so you know how to prove it on paper?
well so
probably L'hopitals but I've not tried it
I'm doing it in my head
lmao
Pretty sure this is related to the Taylor Remainder theorem. So yes, the ? Is 1
exactly
and since its in the denom
But tbh, the constant does not matter for the limit (just the theorem).
itll go to 0
hmm
wait that makes a ton of sense actually
yeah 😂
the error goes to 0 as the terms go to infinity
Precisely :)
that's the exercice in french, you can easly tanstlate it
but we're not French 😅
i don't why the prof use Taylor-Lagrange instead of Young
or most of us anyway
ok i'll translate it for you
im extra not french
A bit like me giving you a question in Chinese and expecting you to be able to translate it just because I know Chinese
well to be fair french is more readable than chinese to the average english speaker
that's a fair point, but similar concept
matter of fact i think i can read that problem
Let f R to R be a function of class c^inf somethign something proper, there exists a polynomial of degree something something n geq 0 for all x in R
close enough
I took French in high school. Still can't read much
i speak broken spanish so that probably helps
#bilingual gang
dackid (jump king +)
,w translate soit F une fonction de R vers R tel que F est infiniment derivable. il existe un polynome P impair tel que
oups my bad hhhhhhhhhhhhh
for every n of N: |F(x)| <= |P(x)|```
It was close
very
the 2nd question is to proof that F is null
and you should consider that that what ever the derivative of F, always F(a) = 0
For quesiom 17 is the following valid?
Proof by contradiction: assume there exists an int n such that (n^2+2) is divisible by 4. If this is the case it must be that (n^2+2) is even because 4 is a multiple of 2. Further in order for a number plus 2 to be even it must already be even. Thus n^2 is even. It is obvious that if n^2 is even n must also be even. Thus n is even. Thus n can be re-writren as n=2x where x is an int. Meaning n^2+2=(2x)^2+2=4x^2+2 this is not divisible by 4. Since 4x^2+2=4(x^2- 1) +2. Thus (n^2+2) is both divisible by 4 and not divisible by 4
Ie a contradiction
I posted the question in the above pictue it is asking for a proof that for every n in the int, that (n^2+2) is not divisible by 4
ah
It is obvious that if n^2 is even n must also be even. idk about this
but w/e
Since 4x^2+2=4(x^2- 1) +2 idk what ur doing here
this makes it more compex
Sorry that Is just showing it is indivisible it is just how my textbook did similar questions
i feel like doing just by cases is easier here but idk if you cleaned this up (dont even really have to) i think itd be valid if weird
maybe easier pathway if you wanna just assume the n is odd case doesnt work
is just show that you can factor n^2 + 2 in a fancy way such that it's an odd number + 2
e.g. cant be divided by 4
sorry
Oh that would prolly be easier
2*(m+2)
where m is odd
fuck
i cant type it correctly
maybe ill just scribble it
if you dont get what i mean
lemme scribble
Also I checked the proof, I think you can pretty easily prove with contraceptive n^2 even =>n even
That would be appreciated thanks!
lmao contrapositive* but thats a funny typo
gimme one sec
Yeah take your time
so something like this for even
i guess this should go first
sorry my writing is bad
you can be as pedantic as you want about all this
i probably wrote too much
something like "4 divides p implies that at the prime factorization of p includes at least 2 factors of 2..."
np
Got it
If I'm given (x) = x^2 and I'm told to evaluate f(2+3i) would that mean (2+3i)^2
?
If so I got -5 + 12i
yea youd just plug the input into the square
Ty for clarification :)
they make a 90 degree angle together
its also marked in the image
by that tiny square near where they intersect
So how would I find AB and BC?
i dont actually know geometry 
this looks hard
I'm trying to practice for the SATs, but geometry is my weak point
this is wayy harder than the sat
BAM and BMC are similar to ABC use that
proof would be the right angle and B or C (AA similarity)
2 is to x as x is to 18. x = 6. A = (1/2) * 20 * 6.
I should have made x an h. because we are looking for the h of the triangle. but, you know....
whats x tho
given f(x) = 2x - ln(2x), how can we find the tangent line of f(x) that goes through the origin?
i gotchu
itll be when the slope equals the y value
or is a multiple of it
Could you explain what you mean a bit further?
I need to find the tangent line equation
do u know how to take a derivative
Yeah; Df(x)= 2 - 1/x
I believe you're wrong
no worries
set f'(x) to f(x)
why would we do this?
basically
if u want it to hit the origin
the slope should be able to reach 0 from the inital value
wait wait
i messed up
it has to hit both
no im right
I am sorry I am not following
Is this correct?? I guessed.
If it's wrong I will delete it.
@woven pollen the question is asking me for the slope of that tangent line; these are the options I got
any polynomial
the answer is not y=2x-1
is always continious
I assume yours is wrong
oof
y=2x-1 is the relation between y and x coordinate of the point of tangency
which also lies on the curve
so y=2x-ln(2x) should satisfy it
ah. ok.
so you have 2 simultaenous equations y=2x-1 and y=2x-ln(2x) for the point of tangency
Wait I apologize I am not exactly following
ok so if a line passes through origin it is of the form y=mx correct?
yup
hes asking a diff question not answering urs
if the point of tangency is (x1,y1) then line is y=(2-1/x1)x correct?
Why 2-1/x1?
thats the slope of tangent line you got by differentiating
$\frac{\Delta y}{\Delta x}$
(x1,y1) must lie on this line so y1=2x1-1
and it also lies on the given curve
so y1=2x1-ln(2x1)
solve for x1 get the line equation
We get e/2 = x
2-1/2/e = 2-e/2 = (2e-2)/2
which is one of the option
Hmmmmmm yeah I get it now
So basically set f(x) equal to f'(x) * x
Solve for x1 and fill x1 in f(x)
this was a problem specific thing you would need to set y=f'(x1)*x+c and then satisfy the given point in this case the point happens to be(0,0) so c=0 is kinda trivial
yeah normally it is y-fa = f'a(x-a)
Hi please excuse me, is this channel soon to be open or should I redirect myself to another channel? Thank you :)
wait what
I learned that formula
so I was close
Why does f'(x) go through the origin origin again?
I see what they did
It's what the question asked for
its what ur tryna get
Yeah you can post your question
Thank you!
Thanks Sussy & Kefir
sure thing
Will someone kindly explain why sqrt(p(1-p)) must be less than or equal to 0.5? That is all that's troubling me
Any help would be highly appreciated
ima guess that
its because u need to be less than 2.5%
the function sqrt(x) is monotonically increasing and x(1-x) has maxima at 1/2
how did u get that so fast
mhm
What does z*sqrt((p(1-p)/n) have to do with anything again
So where does the z pop out of 😭
Wait
NEVERMIND
I REMEMBERED
THANK YOU ALL SO MUCH
you too 😄
I literally relate to this feeling so often 😄
i would ask this in the uni math
this looks like uh
hard calc
or linaer algebra
Did you cut a part out of the pic?
Hey yo guys, just came here for an emergency and because my head is going to blow xd, i have hours looking for any calculator and trying to simplify but i do not have found the answers i need.
Is someone available who can help me out?
sure
monomial should just be a linear
mb mb
it means one term
so they can be the same
u didnt even give the question tho
this legit just means
2+ terms divided by 1 term
will have multiple terms
The graph displays the number of tests given at a particular school over a five-day period. Explain why this graph could be misleading.
The scale in the vertical axis is broken. It appears as if half as many tests were
given on Monday as on Wednesday, but actually twice as many tests were given on
Monday than on Wednesday.
The axes of the graph are wrong. The number of tests should be on the horizontal axis, and the days should be on the vertical axis. It appears as if there are fewer
days than the number of tests.
The scale in the vertical axis is broken. It appears as if 5 times as many tests were given on Monday as on Wednesday, but actually only 4 more tests were given on
Monday than on Wednesday.
The scale of the graph is wrong. The vertical axis should represent equal intervals of numbers. It appears as if 5 times as many tests were given on Wednesday as on Monday, but actually only 4 more tests were given on Wednesday than on Monday.
?
are those options for the answer
yes
im not sure all ik is it isnt the axis one
bye
What was that?
The scale in the vertical axis is broken. It appears as if half as many tests were
given on Monday as on Wednesday, but actually twice as many tests were given on
Monday than on Wednesday.
is it that one?
how would it be that one
idk how to explain it-
it shows it on Tuesday
what
please just say the answer
i cant, thats not the point
its not a or b tho
thats my hint
The scale in the vertical axis is broken. It appears as if 5 times as many tests were given on Monday as on Wednesday, but actually only 4 more tests were given on
Monday than on Wednesday.
that?
i want to get it done i just have no clue how to do it
taka break tbh
nah theres just irrelvant info below it
ill send it again cuz i still dont know what to do
How would I show that D_vf(0,0) = 0 for all unit vectors v?
my initial approach was using the limit formula with f(0 + hv1, 0 + hv2) - f(0,0)/h
and then subbing in the values and cancelling h out
but i end up with v1^2 v2^4/3 / (v1^10 + v2^2)
so idk how to show that equals zero
<@&286206848099549185> still struggling here! would appreciate help
pls someone i have pain
this is calc 3 tho
Send the full pic please. Even if it’s irrelevant. Just want to see
What does the D_u operator do?
You’re looking for how to do question a?
Does D_u take the derivative of f(.) with respect to u?
Yes send a pic of your work please
my guess is directional derivative in the direction of u
did you divide by h ok? it looks off.
k im off my break
lol
can you just tell me the answer this assignment is already 2 hours late
I don’t think that the question is asking for it to be equal to zero. All its asking is for the directional derivative of Du (f(0,0))
can you please give me the answer
e.g. (h · v_1)^10 = h^10 · v_1^10. how did you cancel 10 h's?
uhhh then is what i did fine?
thats the one i chose
which one though
I was here first-
haha no u werent
yea i was...
lmfao
look though the chat
u were 1.5 hrs later @old swan
idgaf
it is hard
The graph could be misleading because y = (1 .. 4) is cut off.
tensor do u know
ik i messed up with the cancelling
but i still dont know what to do
I'm working on it. gimme a few minute.
thank u
dude just give me the answer please
im not talking to you
;-;
i cant
thats not the point of this server
well i dont get it
what dont u get
Hi. I want to know how to sold question5 in this photo.
@simple pond @woven pollen uhh i thought of another method to solve this questions
so i know this is true
I was just reading that! on a webpage.
i mightve messed fx up
and fy
cuz this doesnt make sense
ideally fx and fy should be 0, then that would make sense
maybe i cant math
yay. I'm trying to get my head around the correct way to make the substitutions
wait isnt that for a different equation
Hey guys does 9t^2 + 25t + 6 represent a soccer ball after being kicked off an initial height of 6 ft?
no
Why? @slate monolith
Ahhh
Probably because it doesn’t make sense for a ball to be 157 feet in the air after 3 seconds?
no, because it would keep going up foreever
A factory produces 15,000 computer monitors per day. The manager of the factory claims that fewer than 800 defective computer monitors are produced each day. In a random sample of 220 computer monitors, there are 5 defective computer monitors. Determine whether the manager's claim is likely to be true. Explain.
No, the manager's claim is not likely to be true. Based on the data, you can predict that there are 805 defective computer monitors produced per day.
No, the manager's claim is not likely to be true. Based on the data, you can predict that there are 810 defective computer monitors produced per day.
Yes, the manager's claim is likely to be true. Based on the data, you can predict that there are 346 defective computer monitors produced per day.
Yes, the manager's claim is likely to be true. Based on the data, you can predict that there are 341 defective computer monitors produced per day.
lmao ikr
I’ll switch
looks like they're reflections of each other in the x axis
mine is the easiest in the chat i need halp
Every point (x,y) has been changed to (x,-y) so like on the blue graph, you can see (0,3) on the blue and (0,-3) happens to be on the black graph. This is true of every point, which means its a reflection in the x axis if you want ig an "empirical" justification
but i just looked at it and it looked like a reflection in the x axis
wait so you want to understand why the image of a dilation of 1/n from the y-axis gives you f(nx)?
yes
u could give me an example of a graph if u wish
Pls halp
I mean i can give you an example here of the dilation in action here, but I'm not sure if that's quite what you're looking for. I'm finding it hard to explain at your level since when I was at your level all i was told to do was memorise the rules so my intuition for this is based on some higher level maths(kinda higher level)
Best way is to pick a simple f (say a line), pick a value of n (say 2). Then graph it and see what's happening.
@jagged imp it makes perfect sense thank u
parabola was the best choice of functions to explain the concept
People still have school?
you could try obtaining the perimeter of each rectangle, then add them together.
the formula for the perimeter of a rectangle is $2(l + b)$, where $l$ is the length and $b$ is the breadth
g-e-o-m-e-t-r-i-c
some countries handled the pandemic better than others
or just coincidentally or for whatever reason aren't bad enough affected to have schools closed down
Ima need this server in august
Ok. I'll try. Thanks
i don't understand how to do this
theres still math summer classes and camps i guess
graph the region bounded first
use the bounds of the first triple integral
i need help setting up this triple integral
I can solve em fine I just never know how to set em up
- (x + 9)^2
- x^3 - 9
- (x - 9)^2
- x^2 - 9
None of these are examples of the difference of two square right?
@tough hatch why the reaction?? Lol
This is just the start
Is the derivative of natural log x³ = 3/x ?
well at least I had the same order lol....
thanks
🤔
u sure?
Wdym
have u checked everything?
Is it correct? @tough hatch
Well a difference of two squares, a^2 - b^2 = (a + b) (a - b)
Thanks
But none of those equal (a + b) (a - b)
well (x+9)^2 is just one square by itself
why not look for the ones that look like a^2 - b^2 instead
(x + 9)^2 = (x + 9) (x + 9)
a^2 - b^2 is what difference of two squares looks like
Right..
it's not a difference of two squares, it's just one square by itself
how about x^3-9
it's a difference right?
im asking if $x^3-9$ is a DIFFERENCE
sure it's a difference but it's not a difference of squares
You’re subtracting
yes
is x^3 a square?
9 = 3^2
@nova widget stop answering the questions not intended for u
sure
u keep trolling around lol
@wise jewel
not u
Oh
wtf is bringen
x^3 is cubed
squared is different from raised to the exponent ___
so its not squared
redundant
if it's squared then it's raised to the power of 2
lol
so B is also not ur answer
in general u can check if
- it's a difference
- of BOTH SQUARES?
OR - it's a product
- in the form (a PLUS b)(a MINUS b)
@wise jewel
that's what we've been doing so far
now how about 3)?
NOTE: if it's a single square, it's not a difference of two squares
note what i said
since it's already a single square it's just in the form (a+b)^2
no a-b factor there
Sooo not correct
Wait when you say single square
^
Wdym
by single square i mean (a+b)^2
use this
x^2 - 9
Oh ok
is it a product or difference?
i.e. is x^2 a square AND is 9 a square?
Well 9 has a square root
no think of it as c-d
Of 3
soooo?
Ohhhh wait so this is after the square root has already been applied
9 IS the square of 3
so now?
That means that $x^2 - 9$
is?
¿Black Hat? ͜..
Is indeed a difference of 2 squares
yep
YAYYYY
Ty!!!!
Do I have to know how to factor by grouping when I can just use the slide n’ divide method to factor?
what is this slide n' divide
One second
A trick for factoring, I’ll post the steps here
^^ @tough hatch
It’s way easier than grouping IMO and does the same thing
factoring by grouping applies to more polynomials
u can probably use this when it's not possible to factor (let alone by grouping)
Oh ok
So if I’m factoring 6x^2 - 7x - 20
The middle term should be rewritten as -2x - 5x right? @tough hatch
?
can u help with my question
…
ok
But yeah if I’m factoring 6x^2 - 7x - 20
The middle term should be rewritten as -2x - 5x right?
idk what ur doing but I'd just throw that into the quadratic eqn tbh
have you tried setting up an equation?
factoring
not solving for x
i doubt they only factor second-degree polynomials
ur goal is to get a common term out
why not factor by grouping
m^2 - mn = ?
3n - 3m = ?
yes
Good job!
so u good?
no
pull a -m out of the first two and a 3 out of the second two
i was thinking it became (m-3)(m-n)
how do i learn 7 times tables
u follow?
yeah
@alpine sable channel is busy, u may post on another #questions- channel
wait why is there a + in the first one then a - on the second
im so confused
n-m = -(m-n)
yeah
can you help me out with parabolic quadratic essays bro?
sheeeeesh ur big brained
channel is busy
wait so it becomes (m-3)(m-n)?
yes
but if i factorise that it becomes m^2 - mn - 3m + 3n not m^2 - mn + 3n - 3m
or is there no difference?
oh okay
What is the value of n if n is the largest of 5 consecutive numbers that multiply to give 95040?
@tough hatch
yo superficialsicko
i need help :]
ok sorry

ok lol
have you made any progress on this?
confused at what, exactly?
how to get 95040
what do you mean by "get 95040"?
like what does n have to be to get 95040
"i'm a bit confused at how to solve this problem" in other words
which is not very informative unfortunately
i literally said that
what do you want me to stay instead when i have no clue how to solve it
"i have no clue how to solve it"
anyway, if you treat this as an algebraic equation, it's going to be hard to solve, as it's 5th-degree
however, since we know n must be an integer, we can look at what 95040 is divisible by
you may notice that 95040 is divisible by 9 and by 10
figure what out
like how it was divisible by 9 and 10
these both have simple to check divisibility rules
a number is divisible by 10 iff it ends in a zero
and by 9 iff the sum of its digits is divisible by 9
oh ok
you know your divisibility rules, right?
no

lmao i am being bullied
and how exactly was i meant to know it's a joke?
y do we need to find what it is divisible by
ok
try writing down some products of 5 consecutive numbers that involve 9 and 10
there aren't many options for that
maybe you'll be lucky.
y do they involve 9 and 10
well 95040 is divisible by 9 and 10. maybe 9 and 10 could appear in the product directly
you know
when a number is divisible by 9, it can be written as 9 times something
oh so its 10
Result:
15120
,calc 10 * 9 * 8 * 7 * 6
Result:
30240
close enough
no, not nearly.
no.
at your level in math, you cannot get away with "close enough".
what is my level
from what i can see, you're studying basic algebra.
yeah
and right now, you're being stubborn.
bet you haven't actually done this
seeing as all i got from you were two incorrect guesses
Result:
1.39536e+6
yikes
1395360 is too big
im on the right track
no you're not
oh
this list of numbers includes neither 9 nor 10
9 is in 19
it feels as if you're deliberately not following my instructions
no lol
is that answer
oh
yes that's an example of the kind of list i wanted you to write out
but this particular one won't give you 95040
it is but that's of no use here
wow
Result:
55440
do i need to know that
no
no you don't, you can ignore what bunny said up there
factorial
