#help-0
1 messages ยท Page 679 of 1
to clear out that one
yes and you also have to remember the 4th entry of the row too
go through with gauss jordan like normal
but then there's no way to make the -2 or second 0 a 1?
well we're only focusing on the first column right
oh
Why a square root times a square root equals cancels the square root?
when we get to the second we can fix it
ohhhhh ok
because the square root can be written as a fraction
How
sqrt(2) = 2^(1/2)
And when you have x^a multilied by x^b
you get x^(a + b)
so if it's 2^(1/2) times 2^(1/2) multiplied by eachother you get 2^(1/2 + 1/2) = 2.
Yeah
So the cancellation is simply the exponent becoming a one
Thank you
ye
I don't get it but thanks
which part?
Wow
he probably doesn't understand why exponents add like that
It's the property of powers.
squaring and square rooting are inverses is the loose idea
ye
Yeah
They're inverses because of that^
$\sqrt{x^2}=\abs{x}$ is why it's loose
Mosh
But can I ask you a question?
You should take the time to understand why those properties hold
ok, so the first column is good now, but if we go to the second column and do something like E1 - E1 then yeah the middle number of the first row becomes a 0 like we want but then the first number of the row changes from a 1 to a 0 as well :/
How do I become like you?
Am I ever gonna be like you?
Like I'm just a high school student I dunno how you know this
the channel is in use by Black, can you ask in a different channel?
The way you know it, it's like easy
But to me it's very hard to know those things
Did you find it on your own?
@red ledge it all comes with time i would imagine
It'll come with time. ]
Or was it writtten in a book
That's not the case with me
There's another dimension indeed by time
But what are you doing in this time
is what I wanna know
abstract can you move the discussion to a diff channel?
Blackhat is asking some questions here
Indeed
๐
Blackhat, can you write out the matrix so far in this notation [ [x, y, z], [middle row], [btm row]]
I think I gotta be more interested in Math and have a passion for it if I want to reach a level
Thank you both
``` stuff ```
test
x=3
lol
a b c
d e f
g h i
1
like this^
in use.
ok ill write it out now
?
someone's talking here
1 1 1 | 3
0 -2 -3 | -3
0 -2 0 | 5
alright good
this is with the first column done
So now we should get the zero's in the second col
right
we can fix the -2 to be a 1 after that
ok
or row swap 2 and 3
wait but how do you know to swap those rows
because you need the middle row to be of the form 0 1 0 in the final state
ah right
and it'a already quite close to that state
do you remember what the system represents
yes you can
Yeah you can do row or column operations
however ERO's are used more
this is with it switched
we want the middle # of the first row to be a 0...but idk how id do that without changing everything else in that row to a 0 as well
Help me plz
@paper bay this channel is currently in use
oh
yesterday someone cutted over my question
Well if you add any of the other rows it's not going to change the 1
By solving the equation a = 2 - 9a, the value of a will be
yes therefore we can all do it and it's alright
i need help
then pls help me
You need to ask in an empty chat room and then you may get help.
that goes for @modest kindle too
hmmm... i see what you mean, if i do E1 + E3, then E1 changes to 1, -1, 1 right?
so then E1 (1, -1, 1) + 1/2 (E2) (0, -2, -3) would make E1: 1, -2, -1/2 | 6.5 ?
My idea is that half of E2 will have -1 in the middle of the column which will get rid of the 1 above it
but -1 - 1 = -2, not 0
Oh in your earlier matrix you wrote 1 1 1 as the top col
in that case you can fix it by multiplying by negative 1/2
oh ok mb i added E3 to E1 after i made that matrix but i realize that doesnt do anything
@green robin ok so if we do E1 + 1/2 E2 then the new matrix should be
1 0 -1/2 | 1.5
0 -2 -3 | -3
0 -2 0 | 5
You can swap the rows at this point instead
how can i know if I'm ready for mathematics or physics exam
so now we want to make the -2 in E2 a 1, right?
i did and here i am I'll retake the exam
You also need to get rid of the -2 in btm row
right and turn that into a 0...so then the question is what to do to make that happen...
yeah, see if you can do it
is this linear algebra?
I could do E3 + - E2 right?
usa one
did i do this right?
there we go ๐
so now we have the 0's beneath the diagonal all there ๐
now to make that -2 a 1
and how would one do this?
couldn't I just do E2 + 1?
@wise jewel we need to remember the underlying structure
well what about it?
does that mean i can only like
combine rows with other rows
and not free numbers
| x1^2 x1 1 | | a | | y1 |
| x2^2 x2 1 | | b | = | y2 |
| x3^2 x3 1 | | c | | y3 |
Can someone explain me this
is it bad if colleges see that you took ap caclulus bc then college caclulus the follwoing year in high school?
@wise jewel
what is dim
sorry that was for that other guy
oh
I'm just
nw
| x1^2 x1 1 | | a | | y1 |
| x2^2 x2 1 | | b | = | y2 |
| x3^2 x3 1 | | c | | y3 |
Does that make sense?
as our original set-up
yep
first row is all a, second is b, and third is c
oh nvm u wrote that out alr LOL i didnt see that mb
ok i thought i saw someone do that in a video but ig not
hm
1 0 -1/2 | 1.5
0 -2 0 | 5
0 0 -3 | -8
all numbers below and above -2 are 0...adding -2 or subtracting -2 with 0 wouldn't change it to a 1 
Ok, I got a ltitle lost but we need to multiply the middle row by -1/2
answering too many Q at once
sorry if i confused you 
also i thought you said that you cant add stuff to it?
wouldnt multiplying a row by a random number apply to that
It's ok All I'm trying to say is this
if you have an equation ax^2 + bx + c = k
it's fine to multiply both sides by any number
the equality still holds
ohhhh ok
so thats an exception then
but you cant subtract or add
because that wont let the equality hold?
You can, but it's not that simple
oh ok
In the matrix form
alr, then i wont
Ok - I can explain that in the future more if you like, but it would have to be later
Yup
tyyy!!!! ill just keep working out what i can here
And now we have to fix the last column
oh i thought you were leaving now LOL
No I mean, I can explain the other more complicated part later
Ok, yeah so now our matrix should look diff, see if you can paste that in'
so now the matrix is:
1 0 -1/2 | 1.5
0 1 0 | -2.5
0 0 -3 | -8
Ok looking good
We can see that the first row isn't perfect
but let's fix the bottom row first, make the -3 into a 1
quick question thats a bit off topic, would you consider it odd that my book throws this stuff at us right after we just learned about complex numbers and equations when I've never seen what a matrix is and never in my life heard of the term "gaussian elimination"?
or do textbooks usually do that
they dont really explain it either, its like they expect you to know how to do it which i clearly dont
i didnt miss an intro lesson to it or anything like that either lol
It's actually quite standard
ohhhh...was i supposed to learn this in alg 1?
ok because we def didnt lol
It's fine though - you're learning it now
yeah..we cant do any add/sub. since it would change other numbers
i was trying like -3 * -8 and -3 * -1/2 and dumb stuff like that expecting it to magically become 1 hahahah
right, got it ๐
๐
1 0 -1/2 | 1.5
0 1 0 | -2.5
0 0 1 | 8/3
So then if you sub in the point (3,0) into the first eqn, it holds, in all other cases it doesnt. @covert breach
Good work @wise jewel
getting close now.
finally, now we need to turn -1/2 into 1
which can be done by doing E1 * -2 right?
wait no
cause that would turn the 1 into a -2
Yes, multiplying in this case won't work, because that would change the first entry

RREF form?
they're trying yes.
could i do E1 + E3, and then E1 + 1/2 E3?
You don't need that first step
Yeah you should add 1/2 R3 to R1
Just the second half
I did 1/2(8/3), which gave me 4/3, and then did 4/3 + 1.5, which was 17/6
ayy
ok im gonna try a practice one on my own
unfortunately the book only gave me one question so ill have to search one up ig ๐ฅฒ
ill lyk how it goes ๐
aight I gtg now
What's the original matrix?
ummm hold on....the book got this as the final matrix ๐ฌ
@wary stream this was the og matrix
and they ended with this
,w RREF {1, 1, 1 | 3}, {4, 2, 1 | 1}, {1, - 1, 1| -5}
You did math wrong then
wait so then how tf did i get
1 0 0 | 17/6
0 1 0 | -2.5
0 0 1 | 8/3
๐ฅฒ
oh boy
welp
Post your full work?
@wary stream i worked through it all on discord with cuppajoe
you could scroll up and follow through our convo? its not that much but it would be a quite bit to copy and paste with other people talking ๐
First step?
Because that's wrong
Look at that
"so add -4 of row 1 to row 2 to get a zero there, then you need to add -1 of row one to row 3"
^ this gets that first matrix i posed i think
1 1 1 | 3
0 -2 -3 | -3
0 -2 0 | 5
this one
hahaha yeah ๐
what would i search to find a practice problem of this type of question?
so do i substitute for each of these types of questions?
or is there a better way?
RREF practice problems?
ok, ty!
Can anyone help with this question? A mathematician goes into a supermarket and buys three items.
It has been a while since she has used a calculator and she multiplies the cost (in pounds, using the decimal point for the pence) instead of adding them.
At the checkout she says, "So that's ยฃ5.88" and the checkout attendant, correctly adding the items, agrees.
i guess it has to be either a or c
and then i can substitute and solve
?
@green robin
is RREF an algebra 1 or alegbra 2 skill? @wary stream
neither
but closer to algebra 2 i guess
it's usually taught in a class called linear algebra
although you may be taught that basics in alg2
Apparently one of the values are ยฃ2.50
That has a few
oooo ty
i think both Wolfram and Khan academy have good automatic problems too iirc
@ionic jewel makes sense...i have never even heard the word matrix or term guassian elimination before but my book throws equations at you expecting you to know how to do it
ab = 5.88
a+b = 5.88
but I took algebra 1 freshman year, geometry sophomore year, and now im taking alg 2 over the summer so i can do precal in junior year
yeah it's all in linear algebra, but knowing how to row reduce a matrix and what it means is good I suppose
a+b+c=ยฃ5.88 abc=ยฃ5.88
i learned the basics in alg2 as well
ah alr
oh three items oops
,w a+b+c=5.88, abc = 5.88
there you go, pick any of infinite solutions
ok thx
he left ๐ฆ
oops typo
yeah he had to go he said @covert breach
there you go, here's the solutions
unless we both misunderstand, that's a poorly written question
!rank
whatever Wolfram put isn't something you can do by hand, and there's infinite solutions so idk what they want
!levels
@ionic jewel All I know is that a=ยฃ2.50
well you can use either of the provided solutions to solve for b and c, and see if you get reasonable numbers
here lemme make it easier
,w 2.50+b+c = 5.88, 2.5bc=5.88
there we go
thanks!
do ya'll think it's possible to finish all of algebra 2 by august 1st ๐ฌ
if i spend as much time as i can on it
or is that not possible
... yes
at my school we do 6 week summer courses
so definitely possible to learn a class in that amount of time
sure
o well
can someone else help?
or is this place busy?
how do i go about solving this?
and this
(this is a practice test btw)
(not an actual test)
anyone?
<@&286206848099549185>
show your work for that one
the first, or second?
tbh im clueless as to how to even approach these
either of them
well second one I'll do
i guessed a cuz there is no constant factor
so first of all that ^3 is really annoying, so how do we get rid of it?
i dont wanna expand it
oh i have an idea
hint: ||do the same thing to both sides||
yeah its a
no
no?
ok
u solve
just substituting something random
that way i can use quadratic formula
2a^2 + 5a = 0
oh i see
so what about that maria and aldo bullshit?
once you get this there's an easier solution
pull out an x^2 from both terms on the left for me
and tbh
even without doing all this
intuition would tell u that its gotta be 0
cuz there is no constant term
0 is one of the solutions, it's not the only one
ah
yeah but, others are complex
so they dont matter
?
nah
its all good
wtf is this?
lol
im such a fucking dumbass.. i didnt even see that option of 85
๐คฆโโ๏ธ
but srsly, what is this cube stuff?
In a kindergarten, 12% of the students are Malays and the rest are Chinese. 50% of the Chinese and 12.5% of the Malays are boys. There are 912 more Chinese than Malay students. How many girls are there in the kindergarten?
Help
Help pls
dont crosspost
sorry I just joined
then you wont get help 
new as opposed to which
@glass lichen This server is being used.
tbh any of these can be the pre image but i guess its the red one
for 2nd, its a translation of some units in X and Y (find that out)
then 3rd: its a rotation of 90* clockwise with C' as the center
and 4th idk what it means
can you help me , idk how to
i needa finish this rn i wanna sleep
do i find the coordinates or something
<@&286206848099549185>
like this ?
i like your pfp btw
idk if in the center is a good phrasing

id use the language "90 degree rotation about the point BLAH"
and in which direction too but you have that
or maybe 90 degree rotation CW centered on the point BLAH
which point is the center of the rotation?
idk man
the center of a rotation doesnt move
i havenโt slept in a day
think about spinning a piece of paper around
uh
the point on the paper right at the center of it spinning doesnt move
360
it just sorta spins
but it doesnt move to a new location
which point didnt move to a new location
thats the center of the rotation
so what do i say
i cant answer it for you lol
i think so yea
1 down, 5 right
its all correct
oh do u get banned for it
same shit
idk if youre even required to specify the point
but i would
because there are tons of different 90 degree rotations
u should be
in any direction
ok so i donโt need to change ahything??
otherwise u can rotate from any point and fuck it up
iโm so confused
clockwise
its not in the center lol
with C' as the center/origin
have u tried google
technically is
bullshit lol
i was hoping it was a lesson plan but noooo
but ok continue
u guys can just pick different channels instead of fighting
ill ask somewhere else
๐
we arenโt fighting ???
well its confusing to me but im also about to be off work so not helping any more anyways
yeah i guess
do you know why there are prime symbols?
@hardy crest
Like
A -> A' -> A'' -> A''' -> etc
They don't mean primes
I've been those before
like a coupla times
and plus they probably wouldn't know what prime is
is 28 right?
Can someone please check my RREF workthrough? I messed up along the way but I'm not sure where
<@&286206848099549185>
hello
i did this question on a test andi got i wrong but i dont understand why
i cant cheat because im already done with the test
i just subtracted the amount from type b from the total
13 were B but not A, so we know 40-13=27 is A and B
so now from inclusion exclusion we have
would it be 15 then?
yep
doesn't factor in the people that are both A and B
42+40=82>63 so there are some people that are both
So 40 is only (Only B) + Center
yes
and total is (Only A) + Center + (Only B)
๐ question is very much confusive
mine or the test?
si
that test one
the language of question is creating many doubts
so then total - 40 = [(Only A) + Center + (Only B)] - [(Only B) + Center]
which simplifies to Only A
which needs to be solve for
and total was described to be 63
so Only A should be 63 - 40 = 23 right?
ye i thought it had some contradictions
but i just chose what seemed to be simplest route
i am also getting the same answer
23
but if you do it the other way
by doing (Only B + Center) - (Only B) = center
you get 27 for the center
therefore (Only A + Center) - Center = 15
two routes get different answers
hmm
why would this be true?
i just substituted what i said above it
wait
i made a typo
A and B is supposed to be center*
wdym with center
Intersection of A and B
how
wait
ill rewrite without errors
Total = (Only A) + Center + (Only B)
40 = (Only B) + Center
Total - 40 = [(Only A) + Center + (Only B)] - [(Only B) + (Center)] = Only A
Total = 63
Thus Only A = 63 - 40 = 23
The user shall be able to choose to save up a specified amount by a certain date for a specified reason, e.g. save R100 000 for an honours degree over five years. Given the interest rate that will be earned on the savings, calculate how much the monthly saving should be to reach the goal.
What would the equation be?
if this were true then A=Only A+(A and B)=23+27 which is not 42
yeah that's maybe a little bit too many exercises
maybe post one or two you are stuck on
Also maybe review complementary, supplementary and similar angles
you'd easily be able to solve them all
im stuck on all of them
then you should review what you learned
if you really have no clue what you're seeing then you shouldn't start with the homework/tasks
This basic geometry video tutorial discusses parallel and perpendicular lines in addition to transversals and all the angles that are formed by it such as alternate interior and exterior angles. This video contains plenty of examples and practice problems.
My Website: https://www.video-tutor.net
Patreon Donations: https://www.patreon.com/Mat...
Watch this
if you're still stuck after that, @ me I will help you
but I need to see you doing efforts
@ocean sapphire you were already told to read how to get help
And in particular do not send unsolicited pings
So at this point you're getting kicked from the server, come back when you're willing to follow the rules
ight peace
Yes, you can
cool, thanks!
Can someone please check my RREF workthrough? I messed up along the way but I'm not sure where
<@&286206848099549185>
dont instaping, wait 15 minutes
i posted this about 40 mins ago and im just reposting now with the helper tag @sleek elbow
oh thats fine probably
Anyone know where to start learning calculus just for fun
Khan academy
Ty ๐
anyone...?
@wise jewel for 28, why bisect and not midpoint?
huh?
Ok
So this was my walkthrough process
Iโm stuck at the last matrix I made, I can not turn that 8 into a 0 without changing other entries
-2-10 isnt 8
in use
while u helping
no
ok
LOL
#linear-algebra or a channel not in use
@glass lichen it wasnt -10 tho?
you subtracted R3
$R_1-R_3\to R_1$
Mosh
but i didnt subtract them i added them
E1 - ( - E3) --> E1 + E3
I just wrote it weird
-2 + 10 = 8
@glass lichen
@alpine sable anyway this is the question
So you did 10-2 and got 8
Okay fix that for now
alr
welp
im confused again
why is dividing by 1/3 correct but doing E1 - E3 not
it still got me one for the first # of the first row

wdym followed it explicitly, isn't gaussian just going number by number, column by column?
trying to make it [1, 0, 0]^T, [0, 1, 0]^T, and [0, 0, 1]^T ?
Gauss Jordan is just getting the pivot columns, so get the 1 then make the entries below 0, repeat for all columns
thats what i did
then make the entries above the 1's 0's if possible
wait
https://matrixcalc.org/en/slu.html also shows the steps
System of linear equations calculator - solve system of linear equations step-by-step, Gaussian elimination, Cramer's rule, inverse matrix method, analysis for compatibility
gauss jordan is where the numbers above the 1s are 0s, so is gaussian where the numbers above 1s aren't 0s?
Gauss Jordan gets the matrix into RREF
which is when the #s above the 1s are 0s
and gaussian gets it into REF, where the #s above the 1s are not 0s
if thats the case, why did my book say to use gaussian elimination, but then they ended up with their final matrix in RREF?
I also got this question wrong on a quiz and I don't know what my mistake is
Does Stephen Abbott's Understanding Analysis introduce metric spaces?
I also cant cheat because I already submitted the quiz.
dunno what was already initially given in the diagram and what you put
for mine?
yes
everything about the problem is there
the number line was all thats given
and the question asks what Ln Segment WY U Ln Segment YZ is
and what did you submit?
Line Segment WZ
how do i simplify nยฒ(n-1)ยฒ(n-2)
distribute?
i got to nยฒ(nยฒ-2n+1)(n-2) but after that i just got lost
Continue distribution
i did
but i failed
i dont know how to sinplify (nยฒ-2n+1)(n-2)
i tried and tried checking it with a graphing calculator but i got different shapes
(nยฒ-2n+1) * n - (nยฒ-2n+1) * 2
serioisly that simple?
yes
sure
then multply your answer by n^2
if you dont mess up calculations it should turn out correctly
its quite difficult thought because there are many terms
(n-1)(n-1)
(n-1)*n-(n-1)*1
nยฒ-n-n+1
oh yeah i guess this works
normally i did it in my head
(nยฒ-2n+1) * n => nยณ - 2nยฒ + n
(nยฒ-2n+1) * 2 => 2nยฒ - 4n + 2
nยณ - 2nยฒ + n - (2nยฒ - 4n + 2)
nยณ - 2nยฒ + n - 2nยฒ + 4n - 2
nยณ - 4nยฒ + 5n - 2
you should use paper for such distributions
the empty set?
thanks fuys
how is an empty set?
yw
because they dont share any segments
Welp i guess i will never be able to learn gaussian/gauss-jordan elimination despite spending 8+ hours on it nonstop ๐
actually, they share the point Y 
isnt it a union?
thus it should be both together right?
wait are curse words allowed onteh server
whoops
A system of linear equations in matrix form can be simplified through the process of Gauss-Jordan elimination to reduced row echelon form. At that point, the solutions can be determined directly from the matrix, without having to convert it back into equations.
thought it was the upside down symbol
What would happen when you use the x axis?
I would just work the parabola out to y=...
Then take the integral of the line minus integral of parabola.
@weepo#0165
(why wont the pings work sometimes ffs)
does anyone know why this is wrong
@jagged trout i did the dx one and it said to use dy as your variable of change
im just confused why not use dx?
@minor crypt
looks legit to me idk
ask prof
@formal abyss ok I ask it in another way, what happen to the area of an integral when it is above and under the axis
@formal abyss
When you try to get the area from this, and you would integrate it from 0 -> end , will you get 3*A or 2 * A?
no idea
or whoever assigned the problem
k
what is swapping and pivoting in gauss elimination?
@formal abyss Ok, I ask another, would the middle area have a positive or negative value?
@formal abyss and now look at your figure and where the position is
@tropic axle nothing on metric spaces. it introduces a particular topological space (R with the usual topology) and stays in that space from then on as it develops analysis concepts
I guess the only reason you would, is because it's much faster to find x=13-y then it is to find y=whatever that parabola becomes
although both should give you the same solution
you will get 1A 
I dont understand the question
@minor crypt yeah, you're right
Which part
Yeah my teacher said to pick points on a number line between 0 and 1

He said something like there was 2n+1 points
And x^n was the probability that n points came before x
So Iโm assuming (1-x)^n is the probability that n points come after x
But I donโt know what to make of that
just know that (1-x)^n is not the same as 1-x^n
Yh
but what's the question here?
Integral from 0 to 1 of x^n(1-x)^ndx
And what's the problem?
Iโm not understanding how to use an argument based on probability to come to the answer
I think you're combining stuff from your answer with what was given in the problem here. Can you just give us the problem by itself? I will try to solve it.
Area of a triangle is bรh/2
(x+15)ยฒ/2=100
You do the rest
This is the problem
and what is n in that case?
Any natural number
you have to do integration by parts n times 
Heck it may be extended to reals
oh it's an ugly answer
@charred flint his teacher told him he has to use 'a probability argument'
not sure what that means
oh just express it as the probability of some made up event, that's doable
so like x would be a probability of something happening
(1-x) that it doesn't happen
you want x to occur n times then (not x) to occur n times

Yep those are the hints he gave
and the integral means you take the average over all x values
I donโt know how to proceed with that
oh sorry I'm being real dense
screenshot please
You cant see?
it's readable, but not ideal
^
what im having trouble with is putting the derivative of the function equal to -1/pi, and solving for x
wasnt anwering your question
because:
x^(1/2))^2 = x^(1/2 * 2) = x^1 = x
take the integral of both sides, that will cancel out the differential and then you find x 
is there a different way to go about solving it? i havent learned integrals yet
:o you have not?
no...
hmm lets see
it is
have you determined the differential of 2sinx yet?
Okay
uhh 2cosx?
i set 2cosx equal to -1/pi right?
hold up, are you sure about -1/pi
Whered you get -1 from
well if im using the equation f(b)-f(a)/b-a it should equal -1/pi no?
no
bruh
whats the sin(pi)
0
and sin(0)
wrong
wait whaaa
thats the cos(0)
Axhraf
ye im here im trippin up on my unit circle lol
they are not so many possibilities for 2 * x = 0 so cos(x) must be already 0
yeaaa its just that i though that sin(0)=1 lol
x=pi/2;3pi/2
you're welcome
where did we go wrong lmao
o
lmao baka
no its homework lol, this 5 week course is killing me ive got 5 assignments due tomorrow 
:p well good luck
@glass lichen am i allowed to swap columns in a matrix?
is there a stats discord server in the network?
what's the difference between undefined and indeterminate?
for limits?
Dont think so. Ask it here
ok well
is anyone familiar with the "An Introduction to Statistical Learning with Applications in R" text
like when someone ask what zero over zero is some people say it's indeterminate
do u have calc experience
yeah a limit 0/0 is indeterminate
but some say undefined
1/0 is undefined
no sorry
well
for inderterminate forms in my experience
there are some ways to approach them as they are solvable
What questions do you have
undefined is not solvable
i was wondering if it would be reasonable for a highschooler to go through the content
i have been asked to go through it for an internship but idk if its managable
R is a fun language
So what is the answer to the question what is zero divided by zero?
well
usually means you messed up somewhere
not really
so say u have x/x
as x -> 0
then its 0/0
however u can use some rules to find out that the value is actually 1
but for 1/0 u cant do anything
indeterminate form
^
If its for an internship definitely do it. It could open up so many doors for you. Great opportunity. Take it! What are you trying to be when you finish college?
probably cs
but this isnt like a competieive internship
i didnt write any essays or antyhing
Is it a paid internship?
okay so 0/0 is indeterminate but 1/0 is undefined?
no
yes
its more like
because connections i can hang out with the grad studetns
Ohh okay thanks!
and do some work
thing is I'm not a huge fan of stats
planning on majoring in cs
Whats the internship for? Yeah even if you dont get paid connections are everything. If anything you could just quit if you dont like it
lots of fun data structures and algorithms around the corner
its um
well they didnt tell me actually
its at a biology lab at a university
i did it 2 years ago
but legit last time it was sorting a list
based on a genome
so not exactly uh
groundbreaking work
@slate monolith Try to find an even better internship that suits your future of cs or something to that effect and if you dont find anything better just take that internship and try it out for a bit. Could be a big regret if you dont try it out at all. Could be a good experience this time around who knows
yeah no im def going
dont got much else
i just dont know if i try to read the book
or use some other recourses
Look on YouTube too. Theres a whole 8 hour course on it. One hour a day or 30min a day along with some practice and youll be done in no time.
for that specific text?
A prop was used to secure a wall that was collapsing. Using the strut, the wall is perpendicular to the ground. It is known that the steepest inclination of this strut to the ground is 30 degrees, so CALCUATE the smallest inclination of this strut to the wall.
<@&286206848099549185> sorry for ping, but im with headache and just want to sleep and i am not understanding this




