help-0

[ocean seal]

Xetrov

[solar pebble]

oh yeah

sorry didn't mention that

hmm this isn't so nice

[wanton smelt]

ijadwojdaw wtf

[solar pebble]

tbh I'd probably just stick it in a calculator

I'm not working today either, DW lol

[wanton smelt]

cant use a calc :(

[solar pebble]

I'll have another think

$3\frac{\log2}{\log0.2}\times \frac{\log5}{\log0.5}$

[ocean seal]

Xetrov

[solar pebble]

(anyone wanna contribute? I'm just fumbling)

@wanton smelt I got it

log 2 * log 0.5

[solar pebble]

@alpine sable multiply by dx * beta* y

or you can attempt a Laplace transform

[wanton smelt]

omg what

one sec

oh lol i saw sloko's thing and thought you sent it

[solar pebble]

no lol

@alpine sable ?

[wanton smelt]

?

[solar pebble]

log (10/5) / log(5/10)

[alpine sable]

so what's the answer

[solar pebble]

not telling you do it yourself

I've given you a hint already

[wanton smelt]

isn't it log2*log5?

[alpine sable]

still

[solar pebble]

$\frac{a}{c} \times \frac{b}{d} = \frac{ab}{cd}$

[ocean seal]

Xetrov

$\frac{a}{c} \times \frac{b}{d} = \frac{ab}{cd}$

[wanton smelt]

oh i misread

[solar pebble]

You're doing a very poor job of justifying your laziness SLOKO

[wanton smelt]

does it simplify anyhow

[solar pebble]

yes :)

[wanton smelt]

how lol

[solar pebble]

try it

you should get -1

[wanton smelt]

yeah im not sure how to go about it

you mean like on a calc

[solar pebble]

nope

[wanton smelt]

yeah idk how to do it lol

[solar pebble]

hold on

I'm still writing out

I meant 1

-1*-1

[wanton smelt]

i'm still at 3((log(10/5)/log0.2)(log5/log(5/10))

[solar pebble]

notice that

$1 - \log 5 = -(\log 5 - 1)$

[ocean seal]

Xetrov

[solar pebble]

$\frac{\log 2}{\log 0.5} = \frac{1 - \log 5}{\log 5 - 1}$

[ocean seal]

Xetrov

[solar pebble]

@wanton smelt

[wanton smelt]

thats even more confusing lol

[solar pebble]

so we have

$3\frac{\log2}{\log0.2}\times \frac{\log5}{\log0.5}$

[ocean seal]

Xetrov

[solar pebble]

agreed?

[wanton smelt]

yeah i was there

[wanton smelt]

so this * log5/log0.2?

[solar pebble]

by some stupid but useful property of the multiplication of fractions, you can swap the denominators

nope

actually yes

[wanton smelt]

ijaodiijdaoiwj

and then?

[solar pebble]

10/5 = 2
5/10 = 0.5

giving you

(a pain)

[alpine sable]

Hey everybody so if something takes 900 hours to learn and there are 8760 hours in a year and i have 2 years to learn this thing how much could i split the 900 hours into

[solar pebble]

$\frac{\log 10 - \log 5}{\log 5 - \log 10} \times \frac{\log 10 - \log 2}{\log 2 - \log 10}$

[ocean seal]

Xetrov

[solar pebble]

@alpine sable are there any other factors such as forgetting xD

[wanton smelt]

jesus christ

[alpine sable]

wdym nah lets just say thats perfect

[wanton smelt]

wait so

[alpine sable]

actually

[solar pebble]

okay

[wanton smelt]

-1*-1?

[alpine sable]

@solar pebble changed it to 900 hours just in case

[solar pebble]

I'm not quite getting your question

@wanton smelt yas

[wanton smelt]

omg

thanksss

[solar pebble]

so clean

[wanton smelt]

wait how long did this take

[solar pebble]

for it to click?

too long

[wanton smelt]

almost 1 hour

imma cry

i got 8 tests as homework due tomorrow still at my 3rd iodwaijwaijwa

[solar pebble]

in your honour

good luck!

[wanton smelt]

lol thanks

[solar pebble]

mind you

most of that page is garbage

irrelevant

[wanton smelt]

relatable

[solar pebble]

ya

maths is mostly trial and error whether you like it or not

[minor elbow]

what the heck

how do i start

what do i even write

[wary stream]

I think it wants you to solve the system, when you set it equal to 0

[minor elbow]

ah i see

how do i do that?

[wary stream]

Null space, I believe @minor elbow

[ocean seal]

Hyl1s

[vague coral]

i dont think its null space. Alpha, beta and gamma are linear independant, they definitely have a value on their own.

[harsh acorn]

Oh, Channel is occupied, sorry

[wary stream]

That problem has infinitely many solutions

[vague coral]

yes

[wary stream]

So null space would give you the answers, for alpha, beta, and gamma

[vague coral]

oh wait, alpha, beta and gamma isnt a family

[wary stream]

To be more exact, a singular answer for alpha, beta, and gamma, based on the values picked

[muted raft]

they just want you write a particular solution it looks like

[vague coral]

if you have an infinite number of solutions, you dont call that null space

oh lord null space, I suck at english

Null, like ker f ?

[viral rampart]

Parametric equation

[vague coral]

sorry I'm a bit dumb today

[wary stream]

Which is null space concept

[vague coral]

yeah your right

[viral rampart]

They just want one solution from null space yes

[glass lichen]

yes, checking independence of co-ordinate vectors uses kernel/nullspace/homogeneous system

[wary stream]

I refer kernel as null space often. I learned the term null space first before kernel, even though it means the same

[viral rampart]

Moreover nullspace is 2D, so gamma can be anything

[vague coral]

I was a bit lost with null space, I thought it was empty set for a second I dont know why

[vague coral]

gamma will stay gamma maybe

[wary stream]

Gamma will most likely be the free variable

[vague coral]

and write the other two in terms of gamma

[muted raft]

nullity = #of free variables

[viral rampart]

Wait it's expressed as columns

Take transpose first

[glass lichen]

you should probably wait for the person that asked the question to comment, so you're not just giving the answer

[wary stream]

Don't think that's necessary

If you take the transpose, then that row of zeros will become a column of zeros

[viral rampart]

Ye

[wary stream]

Making it overdetermined

[viral rampart]

What

[wary stream]

More equations than variables

[viral rampart]

No lol

It just is a matter of representation

Moreover it's not an augmented Matrix

[glass lichen]

solving independence is an augmented matrix

the column vector is just 0, so it'll never change with row operations

[viral rampart]

You can check independence without the 0 column

With just the square matrix, since it's homogeneous

[glass lichen]

yeah, it's still an augmented matrix

[viral rampart]

U is not an augmented Matrix

[glass lichen]

wow didnt know my eyes didnt work

[wary stream]

Taking transpose, means row of zeros becomes column of zeros, meaning gamma is zero, meaning 3 equations with 2 variables, so therefore should not take transpose

[glass lichen]

Im aware U isnt augmented

However checking independence is checking that A is invertible, which is checking that Ax=0 means x=0 only

[viral rampart]

I represent V1,V2,V3 as rows of a matrix to solve. It's simply a matter of representation as long as you know what you are doing

[viral rampart]

There are 10 other ways to check independence

[wary stream]

You find null space of U, not of U'

[viral rampart]

My brain hurts

They're the same

Ty

[glass lichen]

b on FTIM is what's being checked

[wary stream]

Null space of U vs U' is going to be different, I believe

[viral rampart]

Yeah

That's not what I meant

I'm about to puke, I'm unwell

Cya later

[wary stream]

.

[viral rampart]

Lol, take transpose and find the relationship between rows

Big difference

[wary stream]

Thought you were saying take transpose then find null space

[viral rampart]

.

U'*[a b c]=0

I mean alpha beta gamma

I can't look at screen, my head hurts

Sorry

Bai

[wary stream]

I normally do U * [α β γ]' = [0 0 0]'

[mellow canyon]

is this an error? I used to 10mm=1cm fact and 450 as an answer, not 45. and it looks like they switched it from 10 to 100 randomly in the steps

[rigid smelt]

No, its because they squared the the fraction

10^2=100

[mellow canyon]

I see that, why though? 1cm=10mm, it says nothing about squaring

[glass lichen]

you need to change cm^2 units

[mellow canyon]

oh we're canceling cm^2

[glass lichen]

yes...

[mellow canyon]

ok that makes a bit more sense haha

I think I need a break I'm missing stuff like this...cya guys. thanks

[wanton smelt]

i need to find out the x for which (x^2-x)^(2x) is correctly defined
any help?

[viral rampart]

I'm sorry @wary stream @glass lichen. my head hurts, I didn't mean to talk like that

[mellow canyon]

talk like what?

or is this something from before

[viral rampart]

ye

[glass lichen]

something from before.

[mellow canyon]

ok nvm

[minor elbow]

how do i put tanh is this form?

im feeling hella braindead

i know the answer is ln(cosh(x))

but how do i put this in this particular form?

[rigid smelt]

Just do it like how you would do it for tan(x)

Using the fact that tanh(x)=sinh(x)/cosh(x)

[minor elbow]

sorry i cant do it

[minor elbow]

my head hurts

[glass lichen]

sinh(x)/cosh(x) is doable w/ u-sub..

[quasi cave]

Can sum help me with a simple question?

https://andrew.life-is-pa.in/0pSMFM

<@&286206848099549185>

[glass lichen]

#❓how-to-get-help

[quasi cave]

oo okja

[uneven garnet]

Hello,\
How can I find the taylor series of $\ln(e^x -\frac{1}{2})$ [x=0, order 4] ?\
Someone advice me to find the $\frac{f^{(n)}(0)}{n!}$, but this method looks me too long… Is there a faster way to solve the problem ?

[ocean seal]

Thk

[vale wigeon]

sure is

you can write $\ln(e^x - \frac12)$ as $\ln(e^x) + \ln(1 - \frac12 e^{-x})$

[ocean seal]

Ann

[vale wigeon]

ln(e^x) is just x

er. ok hold on

this will be a little awkward

looks like we're better off with $\ln(1/2) + x + \ln(2 - e^{-x})$

[ocean seal]

Ann

[vale wigeon]

by moving to a different channel because this one's currently occupied. @sharp sparrow

[vale wigeon]

and ln(2 - e^{-x}) in turn can be rewritten as ln(1 + (1-e^-x)) for which you can use the taylor series of ln(1+t)

[uneven garnet]

Ohh I see

Thank you !

[alpine sable]

I'm running into issues with understanding this formula

as far as I get it, the formula goes something like this 1/5 x 2,2833 x 1/Rk where Rk equals the 1/rj

however that seems to be incorrect since I don't get the same results as the wj(ROC) column

[fervent locust]

traductor: 1. The graph records the height of 40 3rd graders. high school. Build the frequency table: (Class mark, absolute frequency, accumulated absolute frequency)

plis :c

help

[alpine sable]

I'm pretty sure that posting in two channels is against the rules, beside I occupied the channel before you did

[fervent locust]

zorry

[alpine sable]

<@&286206848099549185> mind taking a quick look at my question?

[heady sequoia]

not sure how you get this

basically, summation sign means start from the index at the bottom and add till the index at the top

so lets fix j. w1(ROC) = 1/5 * (1/r_1 + 1/r_2 + 1/r_3 + 1/r_4 + 1/r_5)

w2(ROC) = 1/5 * (1/r_2 + 1/r_3 + 1/r_4 + 1/r_5)

and so on

[alpine sable]

ok jesus thanks @heady sequoia

I've been looking at it the wrong way the entire time

[weary hazel]

Hello, please help with this word algebra problem

The average height of Tom, Jerry and Sam is h cm. Tom is 84 cm tall. Jerry is twice as tall as Sam.

a) Find Sam's height in terms of h
b) If h=73, how much taller is Tom than Sam?

[fallow jasper]

$h=\frac{\text{Tom+Jerry+Sam}}{3}$

[ocean seal]

Blackdeath39

[weary hazel]

Yeah but what is Sam's height?

[alpine sable]

you just gotta find the formula

$h=\frac{\text{84+2Sam+Sam}}{3}$

[ocean seal]

Grincek

[pallid lance]

8e^-pi/4* i should be equal to 4sqrt(2) - 4sqrt(2) * i

right?

[weary hazel]

Is the answer of option b 39??

@alpine sable ?

[alpine sable]

Yeah I think so

[weary hazel]

Thank you 💕

[crude moth]

Someone help asap

[torpid delta]

eyo

[crude moth]

Hi

[ebon wing]

hi

i need help Find an equation for a line with a slope of 1/4, passing through (8, -2).

[arctic mango]

Write y = mx +c.
Plug in x = 8 and y = -2 to get a relation between m and c.
Substitute m = 1/4 into this relation.

[cinder sleet]

i need help

[ebon wing]

thankou

[stark trail]

$y-y_1=m(x-x_1)$ where m is the gradient or slope
and $(x_1,y_1)$ is one of the points where the line goes through

[ocean seal]

Muzan Jackson

[arctic mango]

The slope-point formula for the equation of a line. It's very helpful to remember.

[cinder sleet]

can anyone help me

[arctic mango]

2x + 10 = 2(x+5), is that what the question is asking?

[ebon wing]

can someone help me Find an equation of a line perpendicular to y =1/3x − 5, passing through the origin.

[cinder sleet]

need help with this

[weary hazel]

g = (x-2)/3

[glass lichen]

they asked for help.

not the answer.

don't just give the answer away as it does nothing

[alpine sable]

factor out the common factors

[ebon wing]

Find an equation of a line perpendicular to y =1/3x − 5, passing through the origin.
i need help

[arctic mango]

What's the slope of a perpendicular line?

[alpine sable]

The gradient of a perp like is the negative reciprocal of the initial

[arctic mango]

Yes. Now use the slope-point formula.

[weary hazel]

Take common factors, or just rearrange the numbers so that your subject stays in left side, and move all other numbers to the other side of the equation

[alpine sable]

hallo

so i understand picking the u here and all of the steps in getting the intergral

but i dont understand is how 3/5 was gotten

[little quarry]

How do I make the TeXit bot display my latex stuff with larger fonts?

Possibly causing "taller" images.

[alpine sable]

i thought that the u would make the intergral become 3/u....

can anyone explain it to me? 🙂

[stark trail]

the 3 comes from the original equation but the 5 comes from the dy equation where dy=1/5 du

[alpine sable]

so, you can just seperate the 3 from the U like that?

[stark trail]

yes it's a constant number multiplied with a function so you can take it out

$\int nf(x)dx=n\int f(x)dx$

[ocean seal]

Muzan Jackson

[alpine sable]

okay thats why 1/u is left

[stark trail]

yes

[alpine sable]

thank you very much 🙂

[stark trail]

ur welcome

[viral patio]

what have you tried already? (also reply to my messages to i get ping'd pls)

[wanton smelt]

not much, no idea what to try

was told to multiply by 5+3i and got (16+30i)/34 but that sounds wrong

[ancient creek]

yea, that's 16/34 + 30i/34.......... so what is the real component of this?

[wanton smelt]

ooh

16/34

fuck i forgot

[viral patio]

so that's the first step - you've now got a real denominator so things are easier to work with
can you split the complex numbers into its real and imaginary components? don't forget to simplify

[wanton smelt]

i could do that

[ancient creek]

yup

[wanton smelt]

thanksj aiuwhiudawh

[ancient creek]

np

[wanton smelt]

what about uh

tg(2arctg3)?

is tg(arctg3) just 3

[visual imp]

Can someone help me with the next questions?

How many diagonals can be drawn at a single vertex of an undecagon?

[glass lichen]

draw a undecagon and count..

[visual imp]

There are 8 but I was not sure haha

[glass lichen]

yes, there are 8

an n-gon will have n-3 diagonals from any vertex (prove it for yourself)

[visual imp]

Calculate the number of sides and indicate the name of the polygon of 77 total diagonals

[alpine sable]

is the question wrong?

[ancient creek]

Yes, tan(arctan(3)) is 3

[alpine sable]

nvm i see now

[viral patio]

do you still need help?

[cinder wedge]

I have a question

[alpine sable]

yea

i see what i did wrong but all the choices look wrong D:

[cinder wedge]

$x²+y³= z^4$

[ocean seal]

Samed

[viral patio]

can you go to an empty room? we're still using thhis one

[cinder wedge]

which is empty?

[viral patio]

have you tried to solve each of the options?

[viral patio]

have a look, find the one whose last message is the least recent

[alpine sable]

illl do that noww

[visual imp]

Determine the value of the exterior angles of the following polygon

I don't remember how to do this

[alpine sable]

i closed the old question the new one is this

[minor elbow]

exterior sum of any polygon is 360

[alpine sable]

i got 1,8x,10,9x=-10

[minor elbow]

so add all the equations and make it equal to 360

lad @alpine sable you asking a question on top of someone else's question

[alpine sable]

scroll up

[visual imp]

Thankss

[minor elbow]

oh lol soz

i guess the other dude did it to you then lol

[minor elbow]

nws

[alpine sable]

hello guys. are vertically opposite angles equal? I haven't came across it since years and I wanna make sure. they are the angles which form like an X shape right?

[oak chasm]

@alpine sable Yes.

[alpine sable]

@oak chasm thank you!

[oak chasm]

No problem.

[tardy pulsar]

I inputted an equation involving logarithms into symbolab and the answer is in an unfamiliar format, does anyone mind explaining/rewriting it?

[ocean seal]

Chai T. Rex

[tardy pulsar]

yeah

[oak chasm]

ln means natural logarithm

Have you done logarithms?

[tardy pulsar]

what does that mean?

a little bit

[ocean seal]

Chai T. Rex

[tardy pulsar]

er

im not sure

im only familiar with format like this

\log _a\left(x\right)

[oak chasm]

OK, so the base there is a.

[ocean seal]

Chai T. Rex

[tardy pulsar]

yeah

[ocean seal]

Chai T. Rex

[oak chasm]

,calc e

[ocean seal]

Result:

2.718281828459

[oak chasm]

That's the value of e.

Very commonly used base of a logarithm.

[tardy pulsar]

ok, thank you so much!

[oak chasm]

You're welcome.

[full dome]

can someone check my trig answers in dms

[toxic dust]

Would |b| = 9?

[viral patio]

why

[toxic dust]

cause isnt it b-a sqaure root

[viral patio]

what?

[toxic dust]

Ur finding magnititude

This is vectors

[wraith cairn]

the dot product finds how much 2 vectors go in the same direction. a dot b = |a||b|cos(theta)

[viral patio]

yes i know
if you have a . b = 9
how did you get to |b| = 9?
(also can you reply to my messages so i get ping'd)

[wraith cairn]

try isolating |b| to see whether or not it is constant.

[toxic dust]

To find the magnitutude isnt it Sqr a + b

[wraith cairn]

no it is not

I don't even know what that means

[toxic dust]

More information is required

[wraith cairn]

a and b are vectors. How do you square root a vector.

[viral patio]

i think there's confusion with sqrt (a^2 + b^2)
e.g. when the vector has co-ordinates (a,b)

[wraith cairn]

ahh that makes sense.

[toxic dust]

yeah thats what i meant 😅

[wraith cairn]

a and b in that theorem is completely different from this question.

it's like saying a^2+b^2=c^2

[toxic dust]

But according to what you said about how there needs to be a dot b = |a||b|cos(theta) There isnt enough information given to me so i wont be able to solve it

[wraith cairn]

it's not true for all of a,b and c for every single question.

yes that should be right

there is not enough information

as long as the "horizontal component of b relative to a" is the same, then it'll be true.

[minor dagger]

can someone help me with these

[wraith cairn]

@toxic dust here's what I mean. As you can see, the vectors on the left have different magnitudes, but the dot product will be the same.

[viral patio]

i think this channel is still in use, i think you should ask your question in another (empty) channel

[toxic dust]

Yep

Speaking of which, can you guys also help me expain this one @viral patio @wraith cairn

So its 2a and 2b right

[wraith cairn]

it's asking (2a) x (2b)

[toxic dust]

Yeah but in Cross product right

So when we line those up

[wraith cairn]

just do it on paper. Try a=(a1,a2,a3) b =(b1,b2,b3) get the cross product, then try doubling both and see what happens to the cross product.

[toxic dust]

Like this?

[wraith cairn]

that is not the cross product.

[vagrant rover]

Is greater infinity a thing?

[alpine sable]

how do you Calculate the SURFACE AREA and
PERIMETER

[vagrant rover]

ping me

Is greater infinity a thing?

[alpine sable]

aye yo is this chanell bussy?

[toxic dust]

?

[dense snow]

soryr, my bad

[toxic dust]

no worries

[dense snow]

i didn't read the whole q

[remote heron]

i feel like asking in #category-theory is better place to get responses fwiw

[glass gale]

oh crap I didn't see that

should I delete it from here or?

[remote heron]

up to you

[glass gale]

I'll do just so it doesn't clutter

[unique tapir]

hi

in used?

There are s students in the art club. Each member painted 13 pictures for the art show. Write an expression that shows the number of pictures the club painted.

Type an asterisk ( * ) if you want to use a multiplication sign and a slash ( / ) if you want to use a division sign.

if its not may someone help

[barren mauve]

Silly question - A, B, and R are matrices
Does A * B * R * B^-1 * A^-1 equal R?

[gusty gorge]

nooooo

[unique tapir]

wga?

what?

[gusty gorge]

there's actually an entire decomposition built around matrices that look like that

look up diagonalization

[barren mauve]

Ok the thing is I have some code I wrote ages back which essentially does this and I don't know why it works

[gusty gorge]

a lot of matrices can be written as $A = PDP^{-1}$, and $A \neq D$

[ocean seal]

Saccharine

[gusty gorge]

Maybe A and B are orthogonal matrices and therefore rotation matrices, so it just rotates the thing and doesn't skew it?

[glass lichen]

someone asked before the matrix question

[barren mauve]

My context is rendering, and one of the matrices is a projection matrix, which is more than a skew right since it's not an affine transform?

[glass lichen]

@barren mauve channel was in use.

[barren mauve]

Apologies

[glass lichen]

what have you tried..?

[unique tapir]

yes

[glass lichen]

that doesnt answer my question at all

[unique tapir]

.

s/13

?

13s

[steep briar]

s/13 or 13s? Also, what's your reasoning? (does not mean you're wrong)

[unique tapir]

cuase it said each

so maybe diviade

didve

[steep briar]

Well, let's say there's one person (s=1)

then how many paintings were painted?

[tardy pulsar]

Can anyone help?

[remote heron]

the leaves being 30 db implies the intensity is 10^15 w/m^2

well i guess i can describe the whole thing if you want

[tardy pulsar]

Yes please

[remote heron]

you just use the $\beta dB = 10 \log \frac{I}{I_0}$

[ocean seal]

jan Niku

[remote heron]

I_0 is 10^-12 w/m^2

[tardy pulsar]

What does the left side represent?

The sound of the car?

[remote heron]

how many decibels a sound is

youll do one of these for each sound

so $30 db = 10 \log \frac{I_L}{I_0}$

[ocean seal]

jan Niku

[tardy pulsar]

Yeah

[remote heron]

does it make sense why $\frac{I_L}{I_0}$ is 1000?

[ocean seal]

jan Niku

[tardy pulsar]

cause 10^3?

[remote heron]

yea

then the log gives you 3, times 10 is thirty

so if I_0 = 10^-12 w/m^2, then I_L has to be 10^15 w/m^2

[tardy pulsar]

Oh I see

Ty so much!

[remote heron]

youre not there yet

alternatively i mean

this is really probably the long way to do it

generally you can just remember like

an increase in intensity of 10^k is an increase of k*10 decibels

so 10^3 more intense is 3*10 more decibles

[small holly]

i was looking at this graph and then saw functions near the top left of it

im pretty sure its calculus

what does it mean?

[remote heron]

statistical stuff

linear correlation

[small holly]

alright ty

[remote heron]

the function is the equation for the line that best fits the data

the R^2 probably better off watching a video lol

[small holly]

alright thanks

[halcyon nova]

<@&286206848099549185>

Anybody there?

[merry burrow]

I don’t think so

[halcyon nova]

Mhm

[remote heron]

this is almost a normal trig function

check out uhh

http://jwilson.coe.uga.edu/EMAT6680Fa11/Nguyen/HHN-Assignment 1/Behavior of Sine Graphs.html

maybe something like this?

i guess id have to ask what you tried or where you got stuck

[halcyon nova]

I know A=2

Idk how to get B

[remote heron]

i think youre close with the 2

note the shape tho

,w graph 2 sin(x)

[ocean seal]

Results provided by WolframAlpha

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Requested by jan Niku#2119

[remote heron]

compare with yours, not the period just the general shape

here it starts at 0 and goes up

[halcyon nova]

Mhm

[remote heron]

so what does A have to be

[halcyon nova]

2?

[remote heron]

no its not 2 but thats close

[halcyon nova]

I thought amplitude is what A is

[remote heron]

it is, but another thing is baked into it

[halcyon nova]

What would that be?

[remote heron]

idk how else to say without giving it away

hmm

it should be more obvious if you compare the two graphs

to make it begin going down

instead of going up

[alpine sable]

oops

[halcyon nova]

I am confused

[remote heron]

how would you flip a graph

around the x axis

do you see what i mean by its not going the correct way?L

[halcyon nova]

You would make the opposite Y values

[remote heron]

how do you do that, numerically

[alpine sable]

Y = opposite (whatever)

opposite = ???

[halcyon nova]

Ya

[alpine sable]

Hello people i need a question i have a sum of $ln(1+1/(2^(2^n)))$ from n = 0 to infinity

[ocean seal]

macoro

[halcyon nova]

So -2 would be 2

[remote heron]

yup

[halcyon nova]

And 2 would be -2

[remote heron]

yea

so A isnt 2, but its...

[halcyon nova]

-2

[remote heron]

yea

[halcyon nova]

Ohh ok

Now for B

[remote heron]

for B is mainly that uhh

i wanna try explaining it

im not sure its gonna make sense

you know the normal shape of a sine graph like

you start at the beginning of a circle

and you go all the way around

back to where you started

thats the same as a sine graph starting at 0, going all the way up, back to the x axis, all the way down, then back up

[halcyon nova]

Ok

[remote heron]

so does that cycle take longer in your graph?

than normal a mean

or is it happening faster

or just normal

[alpine sable]

it takes twice as long on your graph right?

[remote heron]

how long should it usually take

[halcyon nova]

Umm I’m not sure

[remote heron]

heres a normal one

,w graph sinx

[alpine sable]

on your graph, 2 waves goes every 4pi

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by jan Niku#2119

[alpine sable]

normally for sin(x), 2 waves go every 2pi

[remote heron]

how long does this cycle take

how long does it take in yours

[halcyon nova]

Mine is faster

[remote heron]

are you sure?

[halcyon nova]

No wait

[remote heron]

it takes 2 pi in a normal sin function

by what factor is yours slower?

like does it take twice as long

ten times as long

[halcyon nova]

Takes twice as long

[remote heron]

yup

so if you can imagine like

x starting at 0, and moving forward to 2 pi

in a normal sine graph

to complete the function

well, one period

you want this to happen half as quickly

(or equivalently twice as slow)

if you divide x by 2 in the input

[halcyon nova]

So I would do 2pi/2

[remote heron]

i dont think 2pi

you usually start doing that if your graph is intersecting on integers

but here its just intersecting on pi like a normal sine function (sort of)

but divided by 2 yea

[alpine sable]

ok

[remote heron]

if you divide x by two in the input

then x has to get twice as big to go one full rotation

[alpine sable]

this channel open?

[remote heron]

e.g. takes twice as long

so many people typing

[wraith cairn]

coefficient of x = 2pi/(length of 1 period)

[tardy pulsar]

erm i have a quick question

[alpine sable]

ive tried conversion into a product and observation of the next term, it essentially becomes ln (product from k = 0 to infinity of (1+1/(A^k)), where A = 2^(2^n),

[halcyon nova]

…

[remote heron]

,w graph 2 * sin(x/2)

@halcyon nova

oops

,w graph -2 *sin(x/2)

[ocean seal]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by macoro#4287

[remote heron]

ye

before you lose this channel completely haha

look right?

[halcyon nova]

Mhm

So what would x be?

[remote heron]

whatever you want

[alpine sable]

just a variable

[halcyon nova]

So B= x/2

[remote heron]

probably say B=1/2

its implied the x is there

since youre talking about graph

[halcyon nova]

Ok

[alpine sable]

,w graph 2sin(-1/2x)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by macoro#4287

[alpine sable]

alternatively this works

Hello people i need a question i have a sum of $ln(1+1/(2^{2^n}))$ from n = 0 to infinity

[ocean seal]

macoro

[alpine sable]

ive tried conversion into a product and observation of the next term, it essentially becomes ln (product from k = 0 to infinity of (1+1/(A^k)), where A = 2^(2^n),

2^(2^n), here, is a constant in this case

[ionic jewel]

,w sum from n=0 to infinity ln(1+1/(2^(2^n)))

[radiant blaze]

do people know how to solve dfq in here? I have a question

[alpine sable]

do you rlly need alot of numbers using pi to multiply thousands of numbers?

Plz help

So anyone know how to simplify product from k=0 to infinity of (1+1/A^k) (A is a constant)

[ionic jewel]

well wolfram does give answer to your sum correctly

not sure how to do it by hand

[wraith cairn]

pretty sure that's a geometric sum

try using A = 2 on paper

[alpine sable]

its not a sum

[tardy pulsar]

hi i have a quick question is this statement true or false

[alpine sable]

false

[tardy pulsar]

how come?

[wraith cairn]

logn(a)/(logn(b)) = log_b(a)

[alpine sable]

test it, ln 10/ln 3 does not equal ln 10 - ln 3

[oak chasm]

@tardy pulsar Let's say the top is 3000 and the bottom is 300. Will the sides be equal?

[tardy pulsar]

Ah

Its false then?

[alpine sable]

@ionic jewel hmm so how do you get ln2

it looks oddly close to ln2 on wolfram

[oak chasm]

@tardy pulsar Well, the top can be 3000 if a is n^3000. The bottom can be 300 if b is n^300. So, is 3000/300 = 3000 - 300?

If not, then it's not always true.

So it's considered false.

[tardy pulsar]

Tyty

[oak chasm]

No problem.

[alpine sable]

hai

Anyone help me pls

do you rlly need alot of numbers using pi aka π to multiply thousands of numbers or you just like do 3.14 × 2,296?

channels not open, but for a quick answer, if ur talking precision with the thousands, id use 5 digits of pi

[oak chasm]

@alpine sable Do you know about significant figures?

[alpine sable]

Yes

[oak chasm]

Well, 3.14 lets you use up to 3 significant figures in your answer, depending on how many significant figures are in the other number.

If you need more significant figures, use more digits of pi.

[alpine sable]

OHHHHH

Okay thanks

[oak chasm]

No problem.

[alpine sable]

You saved my life

[wraith cairn]

this is very much a geometric sum.

[alpine sable]

its a product

[wraith cairn]

have you tried expanding out when A = 2.

I am talking about (1+1/2)(1+1/4)(1+1/16)...

it's a geometric sum 1+1/2+...

[alpine sable]

its not a geometric sum tho

[wraith cairn]

so the answer is ln(2)

[alpine sable]

yeah thats what wolfram spits out

[wraith cairn]

it's a geometric sum.

ln(1+1/2) + ln(1+1/4)+...

= ln(1+1/2 + 1/4 + 1/8 +...)

= ln(2)

[alpine sable]

ok but why did you select A = 2

[wraith cairn]

because A=2 in the question.

pretty sure it only works with A^(A^n)

[alpine sable]

your calculations arent correct tho

ln(1+1/2) + ln(1+1/4)+...
= ln(1+1/2 + 1/4 + 1/8 +...)

this part isnt

plus A = 2 would be completely arbitrary

[wraith cairn]

actually nope, it only works with A=2.

how is it not correct

have you tried expanding it.

do it on paper.

expand (1+1/2)(1+1/4)

then expand (1+1/2)(1+1/4)(1+1/16)

you will see a pattern.

[alpine sable]

I didn't, could you explain it

[wraith cairn]

what did you get on your paper.

[alpine sable]

1+1/4 + 1/8

1 + 1/4 + 1/8 + 1/16 + 1/64 + 1/128

[wraith cairn]

(1+1/2)(1+1/4) = 1+1/2+1/4+1/8

[alpine sable]

oh yeah mb

[wraith cairn]

(1+1/2)(1+1/4)(1+1/16) = 1+1/2+1/4+1/8+1/16+1/32+1/64 +1/128

in general, (1+1/2)...(1+1/2^(2^n)) = 1+1/2+...+1/2^(2^(n+1)-1)

[alpine sable]

wait a sec

no wonder i got a discrepency

did we multiply (1+1/8) if its A = 2

[wraith cairn]

no. That doesn't exist.

[alpine sable]

ln (product from 0 to infinity of (1+1/A^k)) right?

where A = 2

and if k = 3

[wraith cairn]

it's 1 + 1/2^(2^n)

as you said here

[radiant blaze]

can anyone help with this

kinda stuck on the yp(t)

[alpine sable]

oh ur talking about the original. I understood what you did, thanks for the help

[radiant blaze]

and finding the yc

[wraith cairn]

ok np.

[radiant blaze]

this is dfq section 4.4 btw

[small maple]

How can I factor x^2+1

[alpine sable]

u cant

can someone telel me why these two calculations yield different answers

i thought for directional derivative only the direction matters for 2nd vector

the first vector is the gradient

[slender marten]

It must be a unit vector.

[alpine sable]

really?

[slender marten]

The rate of change of f in the direction of u is nabla f dot u, where u is a unit vector.

[alpine sable]

oh ok i see

[slender marten]

It from the derivation of the formula.

[alpine sable]

alright ty

[radiant blaze]

so fuck my question huh

[elfin snow]

yeah fuck it

[west fern]

alright so how did you get this answer?

[rich gorge]

Hi guys, I have a question, what x0 means? I've just started to learn functions and I don't know where I can find x0

[ionic jewel]

just means the point x=5

its naming a specific point

[rich gorge]

thank u

[rich gorge]

is it a discontinuous function right?

[acoustic kiln]

can I get some help with this please

-6, -1, 6, 13, 15, 19, 20, 22, 23, 26, 29, 32, 37, 46, 52

here are the numbers in order

[ionic jewel]

yea

[rich gorge]

Thank you so much

[acoustic kiln]

i really don't understand how I am wrong in this

[west fern]

isnt Q1 the mean of min and Q2?

[acoustic kiln]

if that was the case, it would be (-6+-1+6+13+15+19+20+22)/8=11

it's not right either

[gray isle]

Q1,Q2,Q3 refer to the quartile values

(Q2 would be the median)

[acoustic kiln]

yes

there are 15 values

so the median aka Q2 is 22

and the 25th and 75th quartiles should be 13 and 32 if I count correctly

[gray isle]

strange

[alpine sable]

Hey helpers can someone pls help me verify this

I think I have an answer

Hw problem

[gray isle]

maybe they want you to include the median value when calculating Q1 and Q3

[acoustic kiln]

:/

[gray isle]

i.e. find median of
-6, -1, 6, 13, 15, 19, 20, 22 for Q1
and
22, 23, 26, 29, 32, 37, 46, 52 for Q2

[acoustic kiln]

wtf

yep

it's that

I'm sad

thanks

[gray isle]

there's nothing wrong with the values you entered

just slightly different interpretations/definitions lead to different results

[acoustic kiln]

I followed the notes the teacher gave

[dull shuttle]

hello

[nova falcon]

help me?

[dull shuttle]

rotate

[viral plover]

Can someone pls help me with 15c it’s a homework problem and I’m unsure and confused what the textbook solutions did

[nova falcon]

what.

[nova falcon]

15c?

[alpine sable]

Hello

[viral plover]

Yh

[nova falcon]

ok

so (m2 - 6) z = z x m2 - z x 6

so 3x - 2y + zm2 - 6z = m - 4

i think thats the answer

simplified

[viral plover]

So your saying taht m =4

[nova falcon]

no?

[viral plover]

Ohh is ur answer in the form of an equation

[alpine sable]

hmm

[nova falcon]

yes

[viral plover]

Thanks for the help

[nova falcon]

wlc

[alpine sable]

y+z=0 and x=-2 are yielded from equations 1 and 2 I believe @viral plover

Maybe that's relevant for you, or maybe it isn't, I'm not sure

Then you could write m as a quadratic, with only 1 other variable, y or z [you get to pick]

But infinite number of solutions

[viral plover]

I’m just looking for a single value of m

All my teacher told me when u use elimination that your supposed to get 0=0

[green fable]

its a cone

the sa is total, not lateral

im trying to find the two pieces combined surface area

so top cone merged withbottom whats the new sa

[gusty gorge]

wtf did they tell you to do
you need to bring the system to rref and then you should have some terms with m in there

[viral plover]

At this point I’ll just follow what the textbook says which makes no sense

[gusty gorge]

If you apply row operations, you get $\left[\begin{matrix}1 & 0 & 0 & -2\0 & 1 & 0 & - \frac{1}{m - 2}\0 & 0 & 1 & \frac{1}{m - 2}\end{matrix}\right]$

[ocean seal]

Saccharine

[gusty gorge]

For m = 2, there is no solution

[wispy ember]

1+1=3

[viral rampart]

If addition is defined as a+b=a+b+a.b

Or a million other possibilities

[tawdry cedar]

How do i do this? Can anyone help me please?

[glacial hedge]

hint

$(a-b) = (/sqrt(a)-/sqrt(b))*(/sqrt(a)+/sqrt(b))$

[ocean seal]

Elonmosqito96

[tawdry cedar]

sorry but i have no idea what that means 😅

[alpine sable]

Oh sorry

[gusty gorge]

$(a-b) = (\sqrt{a} - \sqrt{b})(\sqrt{a} + \sqrt{b})$

[ocean seal]

Saccharine

[gusty gorge]

there I wrote it for you

[tawdry cedar]

oh ok thanks

[glacial hedge]

yep i suck at latex xD

[gusty gorge]

I guess it might be helpful to note that $(a-\sqrt{ab}) = (\sqrt{a} - \sqrt{b})\sqrt{a}$

[ocean seal]

Saccharine

[small maple]

how do you factor x2+1

[tawdry cedar]

omg thank you so much!

[pearl marlin]

and $\sqrt{a^3} +a = a(\sqrt{a}+1)$

[ocean seal]

learn4math

[glacial hedge]

if you do it right you should get sqrt(a)/a

[tawdry cedar]

ok doin' it

then simplify it by 1/ sqrt a right?

or just keep it like that?

[glacial hedge]

i mean its fine as it is, but it is a common thing to rationalize the denominator

*propper thing

[gusty gorge]

tbh I prefer $\frac{1}{\sqrt a}$, but idk why most high school teachers don't like it

[ocean seal]

Saccharine

[tawdry cedar]

imma do it anyways

Thanks for your support!!!

[candid hill]

Umm.guys can you give me atleast 5 algerbatic expression equation plss (THIS IS NOT FOR HOMEWORK)

[glacial hedge]

linear, quadratic, quartic?

[woven pollen]

$e^s = \frac{1}{(s-2)(s+3)}$

[ocean seal]

tensor

[woven pollen]

there's one

$e^{-t} + e^{t} = \frac{\pi}{4}$

[ocean seal]

tensor

[woven pollen]

two

[gusty gorge]

$x e^x = 5$

😉

[ocean seal]

Saccharine

[glacial hedge]

regarding circular corodinate systems, on tripple integrals, for spheres do we restrict phi to be 0, pi? Because if we have phi go to 0, 2pi, don't we go over the volume twice?

whoops

didnt mean to tag u

[ionic jewel]

yes

phi is bounded between 0 and pi

[pearl marlin]

put x=e^t and make quadretic

[woven pollen]

🙂

$t'=\frac{t}{\sqrt{1-\frac{v^2}{c^2}}}$

[ocean seal]

tensor

[gusty gorge]

ew

t' = $t\gamma$

better

[ocean seal]

Saccharine

[woven pollen]

[ionic jewel]

what happened to handwritten solutions :o

[woven pollen]

my ipad is upstairs, is all.

[gusty gorge]

I never understood that 4-momentum stuff

well I did at some point

but whoosh

[tacit mortar]

hi

is this a quadratic equation

[ionic jewel]

no

that's a circle

[sharp sail]

no that's an ellipse

[ionic jewel]

ellipse with eccentricity 0

aka a circle

[pearl marlin]

circle is also a ellipse

[ionic jewel]

don't correct people if you aren't right

unless you were answering his question (badly) rather than correcting my answer

[tacit mortar]

ok thanks

[alpine sable]

can i ask questions?

[alpine sable]

can someone explain me how to approach this?

[alpine sable]

For proving the sequence given by $a_n := \frac{1}{(n+1)^2}$ converges to zero is a choice of $\frac{1}{\sqrt{\varepsilon}}-1$ appropriate?

[ocean seal]

Maciekchelmicki

[fair hamlet]

Sort of, we want the answer to be < than epsilon, not epsilon itself, so replace epsilon with epsilon/2 and choose any integer larger than that and you should be fine

[alpine sable]

Thanks

[fair hamlet]

Np

[twin haven]

how to simplify 26x225x314x10^-12 using logarithms.

[fair hamlet]

log(ab)=log(a)+log(b) and log(a^b)=blog(a). This should help you out i hope

[left gate]

How to find out the General SOlution of tan 2x = -cot(x + pi/3)

[twin haven]

yeah so log(26x225x314x10^-12)?

we will get log 26 + log 225+ log314 -12

[fair hamlet]

It gets turned into the sum of the logs, like log(26)+log(225)+..etc

Yeah exactly

[twin haven]

after that i cant understand

[fair hamlet]

Well, isn’t this simplified?

[twin haven]

we need a no. value

[fair hamlet]

In that case you’re better off just multiplying. Do they want you to use log tables?

[twin haven]

um no idea, my teacher told me if you use logs the answer would come faster, so to save time i want to know.

[fair hamlet]

Well, maybe she meant log tables, those make multiplication and stuff quicker

[twin haven]

yeah my book once mentioned them, i dont know how to use them tho.

[fair hamlet]

Basically it is just a collection of log values for a lot of numbers. I had to use them in my school. They are kinda pointless these days though

[twin haven]

Hmmm so does higher level mathematics not use it?

[gray isle]

dunno why you'd use "logs" for that

[twin haven]

So it was a physics problem.

related to resistivity.

after rearranging all the values

i have to simplify the given ones. and calculator is not allowed

[gray isle]

$= \underbrace{2 \cdot 2 \cdot 225}{900} \cdot \underbrace{13 \cdot 157}{2041} \cdot 10^{-12}$

not logs, but properties of multiplication and exponent laws

[wanton smelt]

i'm stuck at
26(logx/log2)=18
if anyone can help

[twin haven]

you can use the properites

wont this change the value?

[gray isle]

why would it change the value?

[twin haven]

oh so you broke it down

[vale wigeon]

2 * 2 * 225 is not equal to 10^3 is it?

it's 900, not 1000

[gray isle]

fk

typo sry

[ocean seal]

ℝamonov

[twin haven]

yeah this made it easier

[heavy mural]

anyone have experience with r studio?

[twin haven]

Thanks for your time @gray isle @vale wigeon @fair hamlet

[wanton smelt]

how do make a sqrt into a cbrt

or vice versa

[twin haven]

hmm? for eg.

[wanton smelt]

i got cbrt(2) over root(2^5)

[full kayak]

i was doing some basic differential calculus

and there was a question sayind

[twin haven]

so cube root of 2 and 32nd of cube root?

[wanton smelt]

what

the second one is sqrt

[full kayak]

find dy/dt when y=1/x

so i did it

i did not get correct answer

can someone tell me how to do it

[vale wigeon]

stinkbug, maybe you're looking for converting all your roots into fractional exponents?

[twin haven]

um i dont know to write latex

[wanton smelt]

into what

im giving up on that one but like

what do i do if delta is negative

[full kayak]

hyelp

[vale wigeon]

what delta

@full kayak you will have to move to another channel, sorry.

[vale wigeon]

@wanton smelt you're progressively making less and less sense

[twin haven]

do you mean this?

[wanton smelt]

it be like that

[twin haven]

do you mean this ?

[wanton smelt]

cube root of 2

square root of 2^5

its a fraction

[vale wigeon]

$\frac{\sqrt[3]{2}}{\sqrt{2^5}}$

[ocean seal]

Ann

[wanton smelt]

ah

[twin haven]

oh

[wanton smelt]

i gotta learn to use that bot sometimes

[vale wigeon]

so you want to simplify this?

[wanton smelt]

yea

Its actually log of each but hhh

[vale wigeon]

what

is it actually $\frac{\log(\sqrt[3]{2})}{\log(\sqrt{2^5})}$ ?

[ocean seal]

Ann

[wanton smelt]

yup

[vale wigeon]

okay so this is very different lmao

log(x)/log(y) ≠ x/y

[wanton smelt]

oop

[vale wigeon]

anyway apparently you're unfamiliar with fractional exponents

[twin haven]

we can use the properties of log

if you know that

[wanton smelt]

wish I did

[twin haven]

log(ab)=log(a)+log(b) and log(a^b)=blog(a).

[vale wigeon]

i guess demoniccommander2 can take over from here.

[twin haven]

these are some properties

[alpine sable]

If x1= 5, y1= 7.5, x2= 7.5 then find y2 if x and y vary directly.

[twin haven]

yeah no wories sir

[vale wigeon]

don't call me sir.

[twin haven]

ok

[vale wigeon]

seriously what the fuck is wrong with so many people who insist i'm a man 😒

it's getting old

[alpine sable]

If x1= 5, y1= 7.5, x2= 7.5 then find y2 if x and y vary directly.

plz help

[twin haven]

x1/y1=x2/y2

[wanton smelt]

[old swan]

A factory produces 40,000 computer monitors per day. The manager of the factory claims that fewer than 940 defective computer monitors are produced each day. In a random sample of 200 computer monitors, there are 2 defective computer monitors. Determine whether the manager's claim is likely to be true. Explain.
No, the manager's claim is not likely to be true. Based on the data, you can predict that there are 950 defective computer monitors produced per day.
No, the manager's claim is not likely to be true. Based on the data, you can predict that there are 945 defective computer monitors produced per day.
Yes, the manager's claim is likely to be true. Based on the data, you can predict that there are 405 defective computer monitors produced per day.
Yes, the manager's claim is likely to be true. Based on the data, you can predict that there are 400 defective computer monitors produced per day.

[twin haven]

im extremely sorry

[twin haven]

did you use the properties

[wanton smelt]

yeah im trinna get the next ex done

i had like 8 pages due friday

whats sin(223pi/6)?

[twin haven]

um let me convert and see

[wanton smelt]

like not a number

but the pi can be lowered i think

is a full circle like 2pi

[old swan]

Can someone please help me

[twin haven]

um sorry but i dont know that

[old swan]

well im fucked

[twin haven]

um im not sure about this

[wanton smelt]

figured it out

[alpine sable]

A bus travels 40kms in 30 minutes. If the speed of the bus remains same, how far can it travel in 3hrs?

[twin haven]

im actually a 10th grader so trigonometry is new to me