help-0

[bitter sparrow]

0

Well 00

[jagged imp]

if the after part is confusing you you can replace the word after with "at." "What's the instantaneous rate of change at 30 weeks."

[alpine sable]

I'm looking at the work for this problem and im not quite understanding this specific portion of the work

this might sound kind of stupid but where did they get the 5x from?
I understand the concept is to factor out the like terms with the smallest exponents and such but it seems like they randomly got a 5x, not sure if im making sense

[misty pebble]

I'm still not getting anything remotely close to 4.4, I know it's probably trivial but im still at a loss

[jagged imp]

what happened to the picture? I can't check for myself without the picture

[jagged imp]

yeah i get about 3kg/wk. I wouldn't worry too much about it unless all the other questions are also largely off

[misty pebble]

alright, they seem all to be a bit odd

ill remember to replace after with at though, that helps me alot. thanks!

thanks @jagged imp

does this server have a thanking system?

[jagged imp]

not really lol. dw about it

[pliant tundra]

is f(x) = ax^2 a parent function of some sort?

[meager jasper]

How do you do this exactly?

I'm just a little confused on how to start...

[rigid smelt]

you can start with finding h'(x)

[meager jasper]

Wait I think i figured it out, would it be -2x x -4x

[rigid smelt]

and no

thats both wrong and horribly written

use * for multiplication next time

[ionic jewel]

notation hurts my soul

[meager jasper]

Okay lol

[ionic jewel]

what's the derivative of two functions multiplied together

[tawny lion]

@meager jasper what is the product rule?

[ionic jewel]

they have a whole name for it ^

[tawny lion]

you are given table values for each function and it's derivative

[tawny lion]

you just need the formula for

[meager jasper]

-2(4) + 2(-4)

I see now

Okay thank you

4(-2) + -1(4) = -12

[rigid smelt]

seems wrong

check the table carefully again

[meager jasper]

okay

[rigid smelt]

the input is x=3 btw

[meager jasper]

Oh

I see

[rigid smelt]

so dont randomly choose some numbers from the table

[meager jasper]

4(-2)+4(-4)

-24

[rigid smelt]

yeah thats better

[meager jasper]

WOOO @rigid smelt thank you

And everyone else

[floral mango]

may i have some pointers on how to solve for r?

would I need log for this problem?

[ionic jewel]

isn't this the arithmetic sequence formula

s = (1-r^n)/(1-r)

[viral rampart]

^

I was just gonna say

summation formula

infinite gp

[ionic jewel]

this doesn't actually solve for r tho

[viral rampart]

not infinite

n

[ionic jewel]

you end up with a sum 1 to n-1 of ar^n

which isn't nicer

[languid crescent]

is it possible for someone to check over a question i already did but im unsure if i got the right answer on?

[oak chasm]

@floral mango Well, one solution is to notice that you have s, minus, and a on both sides.

@languid crescent Sorry, channel is busy.

[languid crescent]

alright

[viral rampart]

a^n-b^n is divisible by (a-b)

[oak chasm]

@floral mango What can you multiply s by and a by on the right to get s - a?

[viral rampart]

so u end up with a polynomial in r

[floral mango]

it is geometric i believe

[viral rampart]

yes

u get

[ionic jewel]

whatever same difference

[floral mango]

sorry I don't understand

[viral rampart]

(summation(r^i), i ranging from 0 to n-1 )=s-a

[floral mango]

i want to solve for r because I would have s, a and n

[oak chasm]

@floral mango You have s - a on the left. You have s r - a r^n on the right. What can r be so that you have s - a on the right?

[viral rampart]

simplified expression

of what chai is saying

[oak chasm]

No, I'm not pointing to a summation.

I'm pointing to a basic feature of multiplication.

[viral rampart]

that's the general solution

[ionic jewel]

Interesting result you can also get from this:

$$s = \sum_{k=0}^{n-1} ar^k$$

[ocean seal]

bunny

[floral mango]

r = 1?

[oak chasm]

Right, that's one solution.

[floral mango]

okay but that's not very useful if r != 1

[viral rampart]

That spans all possibilities of r

[floral mango]

this solves for s, isn't it?

woah what are these weird symbols ive never seen before

oh that's an r

[viral rampart]

Sorry

One sec

There

That's basically summation of gp

[ionic jewel]

tha doesnt sovle for r unfortunately but its just kinda cool its the geometric* sum formula

[viral rampart]

We established that without what I did 😂

[heavy canopy]

Is this channel free?

[viral rampart]

Hm?

[floral mango]

it is the geometric sum formula

i'm trying to solve for r, i simplified it partly

[floral mango]

how would this solve for r?

[viral rampart]

you'll have n-1 solutions

so...

u won't get a general explicit equation

wait

I mean a maximum of n-1

solutions

[floral mango]

hmm why can't it be an explicit equation

[viral rampart]

y=60

cause, the degree of the equation is varying

[floral mango]

can't log magic solve this mess?

[viral rampart]

it could if it were in a product form, but it's a polynomial

so no

[floral mango]

i see

[floral mango]

thank you for your help @viral rampart @oak chasm @viral rampart

[viral rampart]

np :3

[civic elbow]

Hello can anyone help me with this question? Pretty sure it is 40

[nova dune]

wRoNg

[civic elbow]

actually its 60

mb

[nova dune]

sweet as

[viral rampart]

where did the graphing question go?

[nova cloud]

https://cdn.discordapp.com/attachments/546941040205234176/855675967728648222/image0.jpg

Cant find y

[viral rampart]

3x=96

[covert berry]

They say "Can't find y"

It can be interpretted as "I found x, but y, not yet."

@nova cloud Is this a vector problem?

[viral rampart]

Lemme think

[nova cloud]

no

its to do with properties of paralleogram

I found x not y though

geometry

[covert berry]

Anything special?

[viral rampart]

it's possible to find y, my I'm sleepy

u wanna know how?

first find the other two angles of parallelogram

u get 84

[covert berry]

It is impossible without extra information

[viral rampart]

the do triangle total sum

for upper two triangles

u get the answer

[covert berry]

X + y + alpha = 180

If I make it higher, it doesn't affect the angle

Yet the alpha is changed

Therefore y is changed

[viral rampart]

I can solve it fully if u really want me to

[covert berry]

So we need more information

Do so please

Please do note there is no 90* there

[viral rampart]

where

wot

[covert berry]

Nothing :*

[viral rampart]

ye ur right

i din simplify

u get infinite solns

[covert berry]

ok

so the problem is purely unsolvable

but if we let the two sides be constants, we can solve it

such a, b

[viral rampart]

it just has infinite possibilities for y

[covert berry]

if the lengths are fixed, it's not

[alpine sable]

are you guys done?

[viral rampart]

yeah

[covert berry]

$$x + y + \alpha = 180\degree$$
$$b^2 = a^2 + c^2 + 2ac \cdot \cos(\alpha)$$

[alpine sable]

so i have little doubt

[ocean seal]

seru
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[viral rampart]

cosine rule

[covert berry]

c can be calculated

by applying cosine rule

[viral rampart]

ye

[covert berry]

then we have cos(alpha)

[viral rampart]

I'm aware tx

[covert berry]

i'm not writing that for you lol

it's in case grooby's back

[nova cloud]

Im so confused

[covert berry]

dejavuu

[viral rampart]

issokie

[nova cloud]

Im pretty sure theres enough info thoigh

[viral rampart]

nope

[alpine sable]

if we take a digit common from numerator of a fraction does we have to take from denomerator aswell

[covert berry]

take a look

[viral rampart]

not unless that thing is a half diagonal

[covert berry]

alpha is variable therefore y is variable

[covert berry]

.... digit?

12/14 = 2/4? You mean it?

[nova cloud]

Its a rhombus

btw

osz

soz

[covert berry]

jeez

[viral rampart]

is it mentioned?

[nova cloud]

yes

its mentioned

my bad

i didnt read

[viral rampart]

wait, I meant

[alpine sable]

like there is a fraction like 2x-3y/2xy so can we write it as 2(x-y/xy)

[viral rampart]

this

[covert berry]

there's 3

[viral rampart]

nope

[covert berry]

and

nope

[alpine sable]

or we have to take 2 common for both term in 2(x-y)/2(xy) like this

[covert berry]

$$\frac{2x - 2y}{2xy}$$

[ocean seal]

seru

[covert berry]

yes

the 2 in num and den can be eliminated

as 2/2 = 1

[alpine sable]

$$\frac2{x - 2y}2{xy}$$

[ocean seal]

Devie❄

[alpine sable]

$$\frac2{x - y}/2{xy}$$

[ocean seal]

Devie❄

[alpine sable]

lol

[covert berry]

$$\frac{2(x - y)}{2(xy)}$$

[ocean seal]

seru

[covert berry]

so 2/2 = 1

you can get rid of it

[alpine sable]

yes like this

thankyou for clearing this confusion

[covert berry]

np

[elfin snow]

if g(x+a)=f(x)+a, would g(x)=f(x)? I was thinking that if a=0 to make g(x+0) then the RHS would be f(x)+0 but it doesn't seem right

[undone dock]

g(x+a) would shift the graph of g(x) A units left and f(x)+a would shift f(x) a units up. As far as I'm aware g(x+a) wouldn't be able to equal f(x)+a for all a

[tawny lion]

take x^2 for example

graph (x+2)^2 and x^2 + 2 on desmos

[elfin snow]

mhm

oh but if instead of 2 it was 0 then they're the same

[elfin snow]

hmm

[rigid smelt]

well technically the answer is no

but if you restrict the case to some type of functions, then the answer is yes

[elfin snow]

oh no wait I was just defining g(x+a) to be f(x)+a

[rigid smelt]

for example, lets say you restrict f(x) and g(x) to linear functions, then that would be correct

[elfin snow]

oh okay

[rigid smelt]

so the word "would" is wrong

[elfin snow]

"can" is a better word then

[rigid smelt]

g(x+a) can equal f(x)+a for some f(x) and g(x)

yes

[elfin snow]

ok cool

well I was defining g(x+a) to be f(x)+a

[undone dock]

But not if f(x) = g(x) though right?

[elfin snow]

yeah bc that's my question ^

[rigid smelt]

no, it would still work if f(x)=g(x)

for example, f(x)=g(x)=x

shifting it right by 2 is also moving it up by 2

[elfin snow]

yeah

[undone dock]

Oh actually you're right

Nvm

[elfin snow]

ok I understand now

thanks everyone

[alpine sable]

Why is x^2 + y^2 = 1 a circle?

[jagged imp]

We can think of the unit circle(circle of radius 1 centered at the origin) as the set of all points a distance of 1 away from the origin

by pythag theorem, the distance from the origin to a point (x,y) is sqrt(x^2+y^2), so the unit circle fulfills sqrt(x^2+y^2)=1

then square both sides to get x^2+y^2=1

[ivory otter]

im supposed to show that the top equation is true

are my steps correct so far?

[jagged imp]

yes

maybe could be formatted better but correct

[ivory otter]

aha ok

but

how is sin^2/cos x = sinxtanx

ahh wait i see

i see it

its basically sin x * sinx / cos

[jagged imp]

yes

[ivory otter]

which is the same as sinx / cos x * sinx/1

ye ok

great

[patent tinsel]

Help plx

[alpine sable]

The ques and answers both need to be in the form of y/n?

Pls mention while replying

[undone dock]

The angle sum of a parrelelagram is 360 degrees, so, 12x=360 and just solve for x

[patent tinsel]

Oh OoO thank uuuu

[surreal delta]

Top one is the solution, bottom one is how I solved it.
As you can see the issue lies in my +, being a - in the solution.

Anyone has an idea why?

[slim geyser]

is this physics... or am i not smart enough to understand

[surreal delta]

This is pure math, it's integrals using partial integration 😄

Hence the "PI" 😄

[slim geyser]

so im guessing your good at maths?

if yes i kinda need some help

[surreal delta]

I mean, I kinda needed help myself cuz I can't even get a + or - correct so I wouldn't say I'm good at math 🥲

[slim geyser]

i mean its only year 10 maths

*for me

[surreal delta]

Sure I could help in #help-1 so people can still find my question here :)

[slim geyser]

sure

[sharp breach]

This one is correct

[alpine sable]

^

help pls

[sharp breach]

When you take -(1/2) e^(-2x) common in the 3rd step it's (sin2x+cos2x)

[surreal delta]

Yea so I heard :((
Apparently I was too dumb to copy it in class cuz online it's also showing +, I just wrote a - for some dumb reason xd

Thanks :D

[wet veldt]

@alpine sable I think you need to use induction for that

[rocky axle]

hi dunno if this is the right channel but I have a test on Z transform of discrete time signals
I've studied the chapter and read the properties and all of that only problem im having is when solving problems where I get lost and dont know what to do
any help is appreciated

[wet veldt]

One question to consider is to have each person answer whether the other two people have a different mission

[alpine sable]

The question can only be in the form of y and n right ?

[wet veldt]

Say 'n' if the other two players have the same mission

You can see the mission of the person you're compared to

[alpine sable]

Say 'n' if the other two players have the same mission
How will I communicate this reference with anyone

What if someone else thinks its just the opposite

Say 'y' if the other two players have the same mission
^

[wet veldt]

It's asking you to come up with the question

For them to deduce anything, there has to be some circumstance that ultimately asks a question for them to answer

[alpine sable]

can the question be in the form of simple plain english?

Or that also has to be in the form of y/n

[wet veldt]

Reread the paragraph before part a.

[alpine sable]

My english is a bit weak

[wet veldt]

Also, part a asks for a question, right?

[alpine sable]

Yep

[alpine sable]

Could not figure the question and answer part

What I could figure was

That any message typed whether reply or question can be in the form of y/n only

[wet veldt]

They don't have to communicate the question to each other. The idea is that the question is agreed by all of them before playing.

(In other riddles, the question is implied by the circumstance)

[alpine sable]

hmm,so the question can be "What's your mission,type n for mission 'a' and for else type b" ?

[wet veldt]

You can't ask someone for something they can't answer. They can't figure out their own mission.

They can only tell the other people's missions

[alpine sable]

Ohhh got it

And one more thing

For the mathematical side I figured the number of possible distribution of missions

It should be:-

(No. of missions^No.of players)-No. of missions

Is it correct?

[wet veldt]

Possible distribution of missions?

Do you mean the combinations?

[alpine sable]

Yep

For 3 players and 2 missions

Possible combinations =6

[wet veldt]

Why are you subtracting the number of missions?

Wouldn't it just be players^missions?

[alpine sable]

Because everyone can't have the same missions if the missions are more than 1

Every mission has to be atleast assigned to 1 player-Rule

[wet veldt]

Oh, I see

[alpine sable]

Then is it correct?

[wet veldt]

I'm considering it

Do you know about the choose operation?

Like 4 choose 2?

[alpine sable]

No sorry

I have not read combinatorics fully

Just know the very basics

[wet veldt]

Subtracting the number of missions doesn't work

[alpine sable]

why,it did not work for missions=1

But for greater than 1 it was working i think

[wet veldt]

It's hard to explain why it doesn't work if I don't know your reasoning for doing it

[alpine sable]

Let me explain it

If you have a coin

Total number of possibilities = 2

If you have 2 coins

Total number of possibilities = 4

Agreed?

[wet veldt]

Yeah

[alpine sable]

So a general formula will be equal to 2^no of coins

So in general sense

No of possibilities for 1 coin^Total coins = Total combinations

Agreed?

[wet veldt]

Yes

[alpine sable]

So if you use this analogy ,no of possibilities of a mission = No of possibilities for 1 coin

[slim geyser]

what you need help with

[alpine sable]

And total players= total coins

[slim geyser]

what kinda formulas

[alpine sable]

Agreed KD?

[wet veldt]

Yes

missions are sides on die, and players are die rolls

[alpine sable]

Yeppp

Exactly

[slim geyser]

w? have an example?

[alpine sable]

Could have explained it that way 🙂

Now if the missions >1

We can subtract the missions

[alpine sable]

So that the rule is followed

Conclusion of my reasoning = (Number of missions^Number of players)-Number of missions

Agreed?

[wet veldt]

Each mission is assigned at least once

[alpine sable]

Yep

And same mission can also

be assigned to multiple players

[wet veldt]

There are many ways that you fail to assign some mission to a player.

It's more than just the number of missions

[alpine sable]

Like?

[wet veldt]

It's complicated to calculate, I suspect. But if there are 3 missions, it could be 111, 112, 121, 211, 122, 221, 222

That is more than just three

[alpine sable]

1 and 2 being?

[wet veldt]

mission numbers

[alpine sable]

Got it

[wet veldt]

I'm listing when 3rd mission failed to assign

[alpine sable]

But why would it fail

The rule says every mission will be

assigned to at least 1 player

[wet veldt]

The problem with p^m is that it counts these invalid cases

You have to somehow remove invalid cases

[alpine sable]

M=3 in your case

What bout p?

[wet veldt]

p is number of players

[alpine sable]

What are taking them as an integers

If I take them 2

[wet veldt]

In the example, p was 3

[alpine sable]

I am confused

Missions =2

and players were 3

So total combinations (valid)=6

right?

[wet veldt]

Your formula used number of missions

I was just considering the formula

But 6 could be correct

[alpine sable]

Calculated using my formula

Riddles actually test your concepts

I feel mine are brittle

so will go ahead and just quit

But anyway KD ,thnx a lot for your help

[wet veldt]

I have an idea how I would do it

[alpine sable]

Pls tell

[wet veldt]

For counting the combinations

First step is assign each mission to at least one player

Then with remaining players, you can assign freely

[minor crypt]

@pallid lance Hey, sorry for bothering you, do you know if learning how to work with Python over the summer (2 months-ish) is doable? If so, do you know a good site/app/video(or whatever else) I can use?

[alpine sable]

Wouldn't that be complicated as we keep on increasing players and missions

[wet veldt]

It's a general formula of those numbers

[alpine sable]

Okay

[minor crypt]

@wet veldt cant seem to find your original question. can you ask again, I might be able to help.

[wet veldt]

Kriger added a question to his original question

[alpine sable]

https://drive.google.com/file/d/1sozZNalBmXdeGPFpvyq-JWyX8xJOb3wz/view

[minor crypt]

oh Kriger is the one who asked

[alpine sable]

there are many, many different places/ways you can learn how to program. In my opinion youtube tutorials were the most clear/easiest to understand but it’s really what works for you. 2 months is a good time frame to learn to work with it as well just make sure to be consistent with it, hope this helps

[minor crypt]

That sure does help. Do you know a specific playlist that you can confirm works well? @alpine sable

[alpine sable]

I have no idea, do some looking around and it shouldnt be too hard to find

[wet veldt]

So for step 1, you pick number m players, p choose m. then you permute missions among them. m!
For step 2, you have (p-m) remaining players. So it's just (p-m)^m.
All of these terms are multiplied

This is my initial attempt at it

[alpine sable]

p choose m

[minor crypt]

Will do my research. Just like with anything, there's some good resources and some bad ones. I just want to make sure I find the right one before I jump in.

[alpine sable]

Don't know. the meaning^

[alpine sable]

Alright, good luck

[wet veldt]

https://en.wikipedia.org/wiki/Combination It is defined here

[alpine sable]

Okay

thnx

will research

[wet veldt]

p choose m = p! / (m!(p-m)!)

[alpine sable]

Goddd math is hard and beautiful at the same time

[wet veldt]

n! = n * (n-1) * (n-2) * ... * 2 * 1

[minor crypt]

do you know the answer for Part A? @alpine sable

[wet veldt]

Part B is more interesting

[minor crypt]

can you share your answers? @wet veldt

[wet veldt]

For part A, you just have each player compare the other players

It can be done with one question: Do the other players have a different mission

[minor crypt]

oh you're allowed to ask a question?

bruh

[wet veldt]

It's asking for a question

The y/n has to be in response to something.

[minor crypt]

so you just ask them:
"Do you have this mission?"

and then they reply with y or n

[wet veldt]

A scenario can have implicit questions

[minor crypt]

if n, they have the only other mission

[wet veldt]

No, you agree to answer certain questions before the game starts

[minor crypt]

oh

anyways, the answer is 3 right?

[wet veldt]

I don't think the last player actually has to answer.

[minor crypt]

what would the question be then?

the only way the last player wouldnt have to answer is if the forst two have the same mission

[wet veldt]

I mean if the players answer one at a time, the last player can deduce from the first two, couldn't they?

[minor crypt]

but you cant possible have them reply in that specific order, can you?

oh wait I only now understand the question

the players themselves dont know what mission they have

[zinc maple]

Hey everyone!

[minor crypt]

hi

[zinc maple]

Can u guys help me out with this?

[minor crypt]

@wet veldt can you give a question and the two answers they'd give that'd help them conclude what their missions are

[wet veldt]

Hmmmmm, yeah they can't coordinate answering in sequence

[slim geyser]

does someone know how to do trigonometry well

[wet veldt]

If they can't even coordinate that, then everyone must answer at least once

Maybe they can coordinate though

[minor crypt]

assuming O(0,0,0)

then
A(-2,1,3) and B(2,3,-1)

Therefore: AB=(4,2,-4)

Given that (lets call C(x,y,z) for now)
AB=2BC
(=)(4,2,-4)=2×(x-2,y-3,z+1)

4=x-2(=)x=6
y-3=2(=)y=5
z+1=-4(=)z=-5

C(6,5,-5)
and OC(6,5,-5)

[wet veldt]

They can have there be two messaging rounds, and only send a message in the first round under certain conditions

[zinc maple]

But there is no option like that

[minor crypt]

Oh i forgot the 2 times @zinc maple

but you get the point now, just add the ×2 , so 4=2×(x-2) ...

4=2x-4(=)x=4
2y-6=2(=)y=4
2z+2=-4(=)z=-3

OC=(4,4,-3)

[minor crypt]

there's so many possibilities but I cant seem to find the minimum answers needed

[zinc maple]

Got it! Thank u a lot!

[versed osprey]

how can you express a decimal like 0.6 as a vulgar fraction

[wet veldt]

Well you can have it so first round, you say 'y' if others' missions are different.

Someone must see the other two as having the same mission

Actually, thinking about it, one person must see two others having the same mission

[minor crypt]

6/10=3/5?

[wet veldt]

Ah, so it can be settled with just one message

[minor crypt]

"If the two others have the same mission, type 'y'."

brilliant

[reef quartz]

guys i have 4 examination about statistic and i can't do it

can you guy help me out step guy

[minor crypt]

1. you can do it

[wet veldt]

For the general case, I think induction needs to be used

[reef quartz]

but I as a poor math experience is no

[wet veldt]

Round 1: type 'y' if there is some mission number that you don't see among the others. That is how you signal that you know your mission number and that it isn't the same as theirs

[minor crypt]

person A: mission 1
person B: mission 2
person C: mission 1
"Do the two other guys have the same mission"
Person B: y

Therefore Person B knows he has mission 2 (because you cant have 3 people with mission 1).

Person A and C know they have the same one, but they dont know if it's mission 1 or 2.

this is so confusing

[wet veldt]

They know it's mission 1, because they know they can't have mission 2

[minor crypt]

how do they know they cant have mission 2? @wet veldt

<@&268886789983436800>

[wet veldt]

The other guy doesn't have mission 1, but someone must have mission 1

[minor crypt]

the other guy?

[wet veldt]

B

This logic then is used inductively for the general case

[minor crypt]

they dont know if person B has mission 1 or 2 though

[wet veldt]

They can see B's mission, since they are another person

[minor crypt]

wait can they see specifically to which person the mission is attached?@wet veldt

I though they'd just see:

Mission 1 and Mission 2, but not who has which

It isn't really specified in the question

[wet veldt]

they can see mission assignments of all other players

[minor crypt]

(ty mods, sorry for ping)

yeah that's the only thing that's said

but it ca´ be in 2 ways

[wet veldt]

Assignment implies an association

[minor crypt]

it does?

[wet veldt]

They already know every mission is assigned to at least one play

[minor crypt]

let's just assume it does so we're done with this

[wet veldt]

What would an assignment mean?

[minor crypt]

if that is the case, we solved it

[wet veldt]

Would it just be multiplicity of missions?

[graceful hull]

can anyone help me understand class intervals tally frequency and true limits mean?

[jagged imp]

looks good to me

[alpine sable]

I’m rlly dumb

[graceful hull]

same

[alpine sable]

BET IM DUMBER

[graceful hull]

do u know class interval means?

[alpine sable]

Nope

[graceful spruce]

really? :oo most of my answers were just based on guesses and some stock knowledge I never read through the lesson at its fullest its 160 slides of powerpoint presentation hahaha

[graceful hull]

same

[alpine sable]

I don’t even know if question 5 is correct

Wait wait

[graceful hull]

i dont even know what ur doing ngl..

im too dumb

[alpine sable]

Isn’t this like grade 8 stuff

[jagged imp]

lol your intuition was correct then. The first one is true since you can find plenty of examples of positive integers that divide 77, the second one is false since there are some integers that dont, and i doubt any more explanation is needed for the last 3

[graceful spruce]

Owww okay thank you very much for the additional info appreciate the help :>

[pallid lance]

how i can proof that : (A ∪ B) ∩ (A∪C') = A

i hate proofing questions

[alpine sable]

Algebra way or venn diagram way?

[stable knoll]

Can somebody explain how do i find this angle?

black one

both triangles are equilateral

[pallid lance]

algebra way

not diagrams

[fallow jasper]

@stable knoll denote the intersection point O

We can solve for triangle AOD

Angles will be:
OAD=50
ODA=52
AOD=78

Then angle BOF will be 78 as well

Hence we solve for FOA and BOD

We have
CAO=60
ACB=60
And solved for AOF
We can solve for C(intersection between FD and CB)O
Then 180 - that = shaded angle

[stable knoll]

lol i dont know what i was thinking i forgot they were equilateraal so OBF is 60 deggres

[thorny bough]

If there are 4 choices and one of them is incorrect and someone has to guess the 3 that are right

what is the probability of them getting all of them right

or how would I calculate it

[stable knoll]

75%

[thorny bough]

Thats for the first guess

I mean that they get the 3 guesses right

[sly escarp]

I'm finding Jacobi symbol for (182/625) is my math right?

[clever pulsar]

heyo, how do you even start to solve this? what would i need to know?

x' =  y + x*(1-x^2-y^2) 
y' = -x + y*(1-x^2-y^2)```

i know that the solution is ```x=sin(t), y=cos(t)

but why

[sullen nova]

yoo

any one here?

hello?

how to write the letter phi in greek?

[clever pulsar]

φ

here you go

[sullen nova]

But I saw someone people write it different

[clever pulsar]

wdym?

Φ?

[sullen nova]

no

[clever pulsar]

im literally using a greek keyboard :p that is phi

[sullen nova]

why are you usgin greek keyboard?

[clever pulsar]

because im greek

[sullen nova]

how can you type english

[clever pulsar]

i also have an english keyboard, japanese too 今日は

[sullen nova]

omg

Can you type japanese?

[clever pulsar]

はい

[sullen nova]

wow

they write it like that

[clever pulsar]

ye thats how you would write it if you were using a pencil, but pc uses a specific font so you cant do much about that

[sullen nova]

Which one should I write?

[clever pulsar]

doesnt matter

whatever feels more natural i guess

[clever pulsar]

bump cause it got buried

[alpine sable]

anyone here who will come to help me

Am I using the correct method to state the range of fx?

[clever pulsar]

you generally shouldnt replace e with its value, unless you want a numerical answer, but since you are applying the logarithm you dont need to

also ln(e)=1

[gray isle]

where's 3 coming from?

of, that's a 5?

why did you set f(x) to 5

[alpine sable]

Typical algebra duh

I used 5 to test the function

[gray isle]

well what you did shows that
5 is in the range

[alpine sable]

My lecturer has not taught natural numbers yet

[alpine sable]

That’s what I did

[clever pulsar]

if you wanna find the range of f(x), then just apply the range of x

[gray isle]

which doesn't really tell you much about the range of the entire function

[clever pulsar]

since its monotonous

[alpine sable]

The range isn’t given

[gray isle]

do you plan on testing every single number you can think of?

[alpine sable]

I plan to test 3

5,10 and -2

[clever pulsar]

if there is no range for x then just do -+infinity

[alpine sable]

Wait

[tacit ferry]

anyone

[gray isle]

its quite inefficient to test numbers like this

[gray isle]

testing/considering three numbers like that would only tell you that your range would include values of 5 to 10 inclusive

instead you should have a decent idea of the basic properties/shape your function has

[clever pulsar]

do you know what the lowest and the highest e^x can get to?

[alpine sable]

What will you expect of an AS level maths?

[gray isle]

and in this case you only really need to consider horizontal asymptotes / continuity / end behaviour

[harsh acorn]

are the answers 6! (1.24) and 7! (1.25) ?

[wraith cairn]

yeah

lol you couldn't find the solutions book for C & P online?

I couldn't either.

[alpine sable]

correct?

[woven sphinx]

sorry no

[alpine sable]

wait

what's correct?

[woven sphinx]

correct would be x^2-4x+4

[alpine sable]

uhhh

elaborate

[woven sphinx]

do you know how to add, subtract and scale matrices? if so then just solve like you would a linear equation

[clever pulsar]

(a-b)^2 = a^2 -2ab + b^2

[tacit ferry]

thx

[random fossil]

is it ok to swap numbers in factorization questions?

like:
"8b - 4a + 8a - 4b" = "-4a + 8b + 8a - 4b"

it's still the same right?

[slim geyser]

does anyone have a clue what to do here

nevermind

[rigid smelt]

not sure what you mean by "swapping"

but yeah that is correct

commutative law

[slim geyser]

anyone have a clye

[rigid smelt]

can you determine the quad first?

[wicked ember]

using cos^2(x) + sin^2(x) = 1

[slim geyser]

like which quadrant its in?

[alpine sable]

how do i divide 213.2 by .41

[wicked ember]

wait firstly

have you learnt that

[wicked ember]

this

[slim geyser]

uh

i probably forgot

[wicked ember]

idk if you need to use it

if you learnt it use it

if not draw a triangle

[slim geyser]

ive grinded a lot of maths today and ive forgotten what i did in the morning

soo

[wicked ember]

cos is adjacent over hypotenuse

[slim geyser]

yea

[wicked ember]

so we have adj = 3 and hyp = 7

so

[slim geyser]

ah..

[wicked ember]

by pythagoras

[slim geyser]

thanks

[wicked ember]

np

[slim geyser]

all my memory came back

[wicked ember]

cool

[random fossil]

thank you

[rustic star]

Can someone explain 29 to me?

You use the product rule but shouldn't DQ be a trans vector?

[ocean seal]

Hyl1s

Hyl1s

[harsh acorn]

I get 13, but answer is wrong
Can someone explain why

[woven sphinx]

are you sure a|bm+cn implies a|b+c?

[harsh acorn]

wait

[woven sphinx]

it means c|a, c|b => c|ma+nb

[harsh acorn]

yes

so it is x|19 and x|1

and x|y?

so x is -1,1,19,-19,y,-y

so answer is 6?

[woven sphinx]

no

c|a, c|b => c|ma+nb does not imply c|ma+nb => c|a, c|b

[harsh acorn]

Then I have no idea how to solve this

maybe euclid theorem?

[woven sphinx]

https://artofproblemsolving.com/wiki/index.php/Simon's_Favorite_Factoring_Trick

[harsh acorn]

wow

so $(x-1)(y+1)=18,x\neq -1$

answer is 12

[spare fern]

Use \neq for ≠

[brisk wedge]

help pls

[harsh acorn]

$(x-1)(y+1)=18 \rightarrow x-1|18,x\neq1$

[sly mantle]

@brisk wedge don't multipost

[ocean seal]

Hyl1s

[brisk wedge]

but no one answering bro 😦

[sly mantle]

please see the rules in #❓how-to-get-help

[brisk wedge]

ok got it i am sorry bro

[harsh acorn]

$B+A$ and $B+C$ are relatively primes. If $9A+5B=4C$, then find $C-A$

[ocean seal]

Hyl1s

[harsh acorn]

@woven sphinx Can you give me a hint to this problem?

[arctic zinc]

I blocked

[sullen nova]

hello

yo know physic?

pls halp meh

[slim light]

Try Bézout's identity

[sullen nova]

gaddamn

physic, anyone nuh?

[wary stream]

Join the physics server listed in #old-network

[alpine sable]

so i got a question involving chain rules

in multivairable calculus

so suppose cos(xyz) = sin(z)

and x = t^2 and y = t^-2

how do you get ∂z/∂t

i figured you assumed you could express z as a function of x and y so z = f(x,y)

and ∂z/∂t = ∂z/∂x*∂x/∂t + ∂z/∂y*∂y/∂t

is this a right start?

[harsh acorn]

How?

Oh I see it now

$5(A+B)=4(C-A)$

[ocean seal]

Hyl1s

[harsh acorn]

And apply bezout's identity?

Actually, i dont need that idendity

simply C-A=5 and A+B=4

[minor crypt]

oh thats a cool trick

I nevzr thought of it like that

[tough ice]

What is the modulus of 6i? (complex numbers)

[simple perch]

can someone give me an answer to this simple question. im trying to prove a point to my friend

[minor crypt]

x^(-1)

[tough ice]

What is the modulus of 6i? (complex numbers)

[alpine sable]

please avoid just giving away answers.

[sand lichen]

Last spring, 40 cats were adopted from the local animal shelter. This spring, the number of cats adopted dropped by 35%. How many cats were adopted this spring?

[simple perch]

why negative 1?

[minor crypt]

that all he asked for, so I figured he already knew how to solve it

I assumed he wqs having a debate with a friend over which one of them is correct

[minor crypt]

there's some rules for the exponents:

x⁴×x¹⁰=x¹⁰+⁴=x¹⁴

(x³)⁵=x³×⁵=x¹⁵

x¹⁴/x¹⁵=x¹⁴-¹⁵=x-¹

I recommend you refresh those rules

[alpine sable]

by just giving away the answer doesn't help them understand why. explaining it at least helps them to do so.

[minor crypt]

true

my bad

[sand lichen]

can u help me

in another room

[simple perch]

do you agree with it being negative aswell? im a kinda confused now

[minor crypt]

The reason I tend to avoid typing out all the steps is because I'm not sure how to type math symbols. I see people here use some sort of command, but I'm not sure how to do it.

[minor crypt]

these are all the rules you havd to know

[alpine sable]

#latex-help

There should be some stuff in it

[simple perch]

alright man i understand now thx!

[minor crypt]

ur welcome, btw did your friend have it right?@simple perch

[minor crypt]

hey thats cool, is it some sort of digital maths language?

[alpine sable]

Uh ever had any experience with programming?

[minor crypt]

:( no

[alpine sable]

LaTeχ is a programming langauge

search it up

[simple perch]

no we talking about the difference between simplified and single power

[minor crypt]

and yet I'm considering starting a computer science degree

[alpine sable]

Type it as LaTeX (don't go to images; unless 😏 )

LaTeX (Programming Langauge)

What's the default naming order for shapes? For square ABCD, which point is which?

[minor crypt]

ahahahahha ofc I'm gonna go to images now

[alpine sable]

$ $ to enter math mode, ^ for exponents, \frac for fractions, \qty or \left \right for autoscaling stuff

the most basic things

[minor crypt]

x^1

$$x^1

[alpine sable]

$\frac{\qty(x^4)\qty(x^{10})}{\qty(x^3)^5}$

[minor crypt]

oh got it

[ocean seal]

Πολλά άτομα είναι

[minor crypt]

$x^1$

[ocean seal]

Axhraf

[alpine sable]

{} for grouping items

[minor crypt]

you dont mind if I mess with it here, do you?

[alpine sable]

we do mind

#latex-testing , #bots

[minor crypt]

oh yeah

[alpine sable]

ask plante, majixed

they're your latex programming go to guys

[ocean seal]

Hyl1s

Hyl1s

[harsh acorn]

Can someone explain why?

[wet veldt]

Did they claim that without explanation?

[charred flint]

@harsh acorn over integers? the smaller y is the better, so y=2

[quiet hill]

wouldn't y=1 be better?

[charred flint]

oh

[harsh acorn]

ooh, Forgot to mention, x and y can't be equal to 1

[quiet hill]

well there you go

[wet veldt]

Values of y between 1 and 2 can break it as well, so that's not the only context

[quiet hill]

yeah I guess they assume integers as well

[small epoch]

What is this?

[charred flint]

<@&268886789983436800> @thorn river

[sly mantle]

b&

[drifting saddle]

I'm wondering how many permutations there are for this specific password:
Merging 2 random words randomly together: RevPlaErseTform (Reverse and Platform)

I already know that ReversePlatform has 171,000 ^ 2 permutations (words in dictionary ^ word count).
How can I express the merging of N words to calculate the number of expressions?

Not sure if this is the right place to ask, feel free to redirect me if you know a better place. Thanks in advance!

[charred flint]

@drifting saddle not exactly sure what you mean by merging, but it's probably a multinomial or a product of binomial coefficients

like is just alternating for RPelvaet... allowed? as long as the original words are spelled in order?

[drifting saddle]

Theoretically, yes. Practically, probably not since it would make the password much harder to remember.

[charred flint]

okay yea should be a multinomial

[wraith cairn]

Reverse platform doesn't have 171000^2 permutations. 171000^2 is the number of combinations of two words

I don't understand the question

[charred flint]

basically you have all (n1+n2+n3+...) letters randomly in a row, but you want them in the original word order, so you divide by the number of ways to arrange the words individually

[drifting saddle]

I based the example on this: https://paul.reviews/passwords-why-using-3-random-words-is-a-really-bad-idea/ (See: The Combinator Attack)

[charred flint]

here's the formula

the k's are the word lengths, n is total length

there's also cases where the words share letters and it doesn't matter if you swap them, but counting those cases doesn't seem possible without computer simulations

so like reverse + platform has 13!/6!/7! ways as an upper bound

most of these combinations looks like gibberish though lol

just use fake words in your passwords

[drifting saddle]

Shouldn't it be 15!/(7!*8!)?

[charred flint]

yup, I can't count

I can only do combinatorics

[drifting saddle]

No worries. So the result of this is the number of permutations, right? 6435 permutations in this case. So the total permutations are words in english dictionary ^ permutations, correct?

[charred flint]

idk if you can look at the total permutations like that

depending on the words you choose you get different permuation #'s with the formula

[wraith cairn]

Wut are you calculating ? 15!/8!/7! Is the number of ways to order 8 red balls and 7 blue balls

[nova dune]

What r u guys doing? Calculating the total number of novels possibe?

[wraith cairn]

I literally have no idea

[drifting saddle]

Calculating how many options there are to brute force a password that combines 2 random words.

[nova dune]

If total number of novels = n (word limit = m), whenever someone writes a novel, they're discovering one of these permutations

Some philosophy for u guys. Aight I amma head out

[wraith cairn]

It's just dict^words

So in general , dict^n

I'm not sure what the stonks guy is calculating

[ionic jewel]

the other guy is right tho you need the other part too

it's an ugly calculation

[wraith cairn]

I thought we were assuming the words are regular

[ionic jewel]

you can mix the words together

his example was like

for forest and clouds it could be like foclouredsst

[cinder wedge]

Hello guys I have little problem with geomerty

Problem: Show that a trapezoid is cyclic if and only if it is isoscele

[drifting saddle]

Exactly.

[wraith cairn]

Ah well if it's mixed you would divide by the number of repeats of each letter

Not the letters of each word

[prime badge]

it's not permutations

if you merge 2 parts of each it's not even multinomial whatever that is

[wraith cairn]

Forest and clouds, 12 letters ,2o 2s it would give 12/2!/2!

[ionic jewel]

depends if the words have to stay in order

if they do the other calculation was right

[prime badge]

if you always have 2 parts of each
171000×170999×length1×length2

[hearty root]

Hi, can you expalin to me why 6^1 * 6^1/2 does not equal 36^3/2

[drifting saddle]

Still not entirely sure but I'll look further into it. Thanks for the help!

[hollow siren]

hello

we can see that the y intercept is -5, and they gave us 1 point, but how do we combine these info together to get the Axis of sym

[ancient creek]

the axis of symmetry passes through the middle of a parabola (that is the maximum / minimum point). It can be easily found by drawing a straight line through it, and dividing its length (inside the parabola) by 2. In this case, u can pass a line through (-8, -5) and (0, -5). it's length is -8. Thus, -8 / 2 = - 4, so 4 units to the left from (0, -5). that is x = -4. That is your axis of symmetry.

[hollow siren]

one sec

[hollow siren]

oh nvm

iw as gonna send a clear image

[hollow siren]

ahh makes sense, thanks

[ancient creek]

np

[alpine sable]

how did you get 6*6 to be 36^3

[hollow siren]

but here the two ys are -9 and -1 when we divide by 2 its 8 units so its 4 but here its 5 ?

[ancient creek]

ah sorry i should have been more clear, 4 units from the point where the line entered the parabola, so for example: from -1, 4 units to the left, that's -5

[hollow siren]

wait what XD

[torpid delta]

in use?

[hollow siren]

wdym when the line entered the parabola

y intercept?

[torpid delta]

ye wtf?

[alpine sable]

Hello

[ancient creek]

well yes, in this case the x intercept, sorry im not that good with formal language

[alpine sable]

Anyone who knows accounting

[hollow siren]

ah alright thanks

[ancient creek]

np

[graceful pier]

2+2 is 4 -1 is 3 quick math

[cyan slate]

yeah buoi

[graceful pier]

Two plus two is four
Minus one that's three, quick maths

[alpine sable]

If anyone knows pls help

XD

Me ded

[graceful pier]

uhhh

um

[alpine sable]

Yepss

[graceful pier]

ima be honest

[alpine sable]

Sad

[graceful pier]

I don’t know

[alpine sable]

XD respect

Well in case who can help just a bit I would be very thankfull

:<

[quiet citrus]

hey, stupid question: how do you calculate "nested" powers mathematically?

like in 2^3^4, do you calculate (2^3)^4 or 2^(3^4)?

innermost first (2^(3^4)), right?

(cause innermost makes the most sense to me)

[jovial field]

yas, innermost first

[hexed pasture]

anyone know how to do 40 and 41

[glacial hedge]

x component = x displacement

aka distance between the terminal and initial point only x tho

What are you guys getting on this? I am getting sqrt(2)/8 and I see that in the answer but there is a (pi-1)

My integral is as follows

Am I seting up my integral's wrong, because i used a calculator and it got sqrt(2)/8 as well

<@&286206848099549185> ?

[hexed pasture]

ik that but, how am i supposed to draw the lines

like

would this be right

and then the x component is 2 and the y component is 2?

[glacial hedge]

count the grid spaces

x=-2, y=0

[hexed pasture]

why is y 0

[glacial hedge]

because y doesnt change......

[hexed pasture]

[glacial hedge]

Dude

the initial point (starting point) is on the same y coord as the end y-coord

[hexed pasture]

wheres the initial point

[civic elbow]

This is 31 correct?

[glacial hedge]

yes

[hexed pasture]

:0

[civic elbow]

Alr since my teachers said the answer is 75.

[glacial hedge]

they on crack then xD

wait

[civic elbow]

The angle is 75

but they say find the value of x

[glacial hedge]

yeah

they solved for 3x-18 instead of x.. xD

also what's the point of that perp line in the middle... it serves no purpose xD other than to confuse you

[civic elbow]

ya thats why the did it

they*

[glacial hedge]

bruh momenty

[minor crypt]

3x-18=75
(=)3x=93
(=)x=31

[hexed pasture]

nice pfp

[minor crypt]

@lethal canyon no, just ask

[hexed pasture]

[lethal canyon]

o

[minor crypt]

me? thanks

[lethal canyon]

I dont want help i just want it solved

Solve i + j + t (3i - j) = -i + s (j)
In the context of Vector Equations of a Line

[minor crypt]

[glacial hedge]

convert it into vector form

like i = <1, 0, 0>

then it should be easier to add x and y components

[minor crypt]

yup, and before you do that close roblox

[lethal canyon]

LOL

[glacial hedge]

BUSTED

[minor crypt]

and dont say you just want it solved, you have to learn how to solve it

[lethal canyon]

Its not for school

[glacial hedge]

it dont matter

[lethal canyon]

im in 8th grade

o ok

[minor crypt]

wiat 8th grade

and you see vectors

[lethal canyon]

i dont even know waht vector form is

[minor crypt]

lol what

[glacial hedge]

[minor crypt]

where did you get the question from then?

[lethal canyon]

Its not for school like i said

[minor crypt]

[glacial hedge]

use i = <1, 0, 0>

j = <0, 1, 0>

k = <0, 0, 1>

t and s are scalars

[lethal canyon]

ok

[minor crypt]

@glacial hedge ur talking to an 8th grader

[glacial hedge]

yep

i am an 8th grader

[lethal canyon]

yeah well i just finished pre algebra

[glacial hedge]

wait dafuq

[lethal canyon]

Yep

[glacial hedge]

who gave you this problem

[lethal canyon]

uh

well

[glacial hedge]

im pretty sure u learn 3d line equations in multivariable calc or geo

[lethal canyon]

Can u just solve it for me

Im not going to understand anyhting your saying

[minor crypt]

but why do you need it solved? @lethal canyon

[lethal canyon]

its for a game

[minor crypt]

a roblox game?

[lethal canyon]

yes

[minor crypt]

lmao they're trying to make kids do maths

[glacial hedge]

also

[minor crypt]

this is truly revolutionary

[glacial hedge]

im not sure how this can be solved in terms of a line....

s and t?

[lethal canyon]

yea i got this answer and he said there is one more step

t = -2/3, s = 5/3, j ≠ 0

[glacial hedge]

oh

[lethal canyon]

do you know it?

[glacial hedge]

😤 he wanted that not equation of a line

[lethal canyon]

whats the last step?
/

@glacial hedge

[glacial hedge]

? i believe there is no solution

[lethal canyon]

alr lemem try that

[minor crypt]

I'm actually confused, did someone ask you to solve that for him? @lethal canyon

[lethal canyon]

bo