#help-0
1 messages · Page 670 of 1
@woeful ridge you cant cancel the 1-tan^2(x) and the 1-tan(x)
factor the 1-tan^2(x) into (1+tan(x))(1-tan(x))
then you get
(1+tan(x))/tan(x)
which is equal to 1+1/tan(x)
hello i wanted to ask a question regarding floor function
say floor(n/x) + floor(n/x^2) is something
nice floor function
is it same as floor(n/x) + (floor(n/x))x
floor
my bad
i often get confused
in those two
no you can't do that lol
why so?
I assume you meant floor(n/x)/x?
I did because the channel was busy
try it with any number
okay
i havent been taugh many things, doesnt mean they dont exist
you're taught about floor already
Thanks 😩
i want to test this thing only for x^n <= n
you're probably solving a problem elsewhere right
and if the above thing worked, you can solve it?
assuming
ill cut my bullshit, you are familiar with legendre's formula? the one where you calculate exponent of prime in n!
this one
yes that is right
Two gears are attached to one another. The smaller gear X has 16 teeth while the larger gear Y has 20 teeth. When the smaller gear makes 7 turns, how many turns does the larger gear make? Record your answer to the nearest tenth of a turn. For example if the answer is 3.721, then write 3.7
the answer is 8.7 right? or am i wrong?
ill go there then i guess
i suck at comp maths but i'll take a view too
if i have no idea i'll just offer you sweet silence
lol
the bigger gear should make less turns
20/16 = 7/x
x = 140/16 = 35/4
wait- uh
right
yeah you're right, i messed up
shouldn't the larger make less turns though
same distance travelled, larger radius uhh
nvm
ok
there, it's 28/5
The quadratic formula is the direct result of the completing the square method
Yes it's generalized formal
i checked each answer choice and i swear they're all correct but i prob screwed up somewhere
Is it possible to make this equation, 1-tan^2a = 2tana/tan2a? Or how would I manipulate it?
@woeful ridge thats an identity....
Yeah but can you manipulate it?
are you allowed to use any identities?
because you would have to at least use an angle adition identity
just multiply both sides by 1-tan^2a then divide both sides by tan2a
oh xD that works too
Basically trying to solve this
What am I doing wrong why can’t I get this answer
Starting on the left side
@ionic jewel do you have any probability knowlege?
yes but i don't like it
could u help with this. i kinda suck
techincally its not probability but like an application of mvc... but i have no idea how to do this
don't know this one sorry
I have 0 clue where to even start with this problem
use d=10t
oh so it would b y=10000e^0.42?
not quite
OKay the solution is
$y=10000e^(0.42d)$
$y=10000(1.5219)^d$
Elonmosqito96
oh alright thx
$$ \frac{-4\pm\sqrt{24}}{2}$$
Nerdy_Coder
@safe kite
see
also another thing
nice
so
uhhh
here's your equation
@safe kite
anyone able to help me with any of these?
what do you call a geometric sequence in which r = 1 or -1
A geometric sequence with r = 1
or An = a1+1*(n-1)
see
easy
how would i solve this?
i know f(2) = 6
and that f'(2) = -132
so does that mean f(3) = 6-132?
this is just an ODE
im currently learning calc 1, so i dont think we've gotten to ODEs yet
this is the topic on linear approximations and differentials
but the answer cant be 6-132 since mass cant be negative
-132 is ROC in gram/min
yes...
Well the and is different
wdym by
and is different
the ans is 5 or -3
that isn't part ii)
yes
seems those are the answers for part iii)
ii) is for the area which is 1/2 * 5 * 5 (simplfied)
iii) are the values of k satisfying the specified properties
the practice book must have some problems
because it clearly stated ii) answer as 5 or -3 which is weird
does the answer provide solutions to all three parts?
so yeh, they wrote the answers for iii) in ii)
Don’t spam them jeez
no test
Please dont give out answers
@sullen nova I posted the answers but I think I’m supposed to walk you through it so you actually learn
do you know what independent means?
...
Havent you been told about these rules Le Vorn?
again
if you learned it you could answer yourself...
Then the questions shouldn’t pose any trouble for you
true
unbelievably ironic lol
Then post your answers
^
^
We will verify it for you
yep
all are indep
what do yall think?
that just goes to show that u're trying to fool us into giving us answers u likely don't actually have
they are not all independent
Channel is occupied
then what is it?

see?
it's now obvious u want answers from us but u don't even have ur own answers to post here
I have my ans?
justify your answers
my ans are all indep
then tell us your answers
??
and tell us why each is independent
did you read my previous message?
Le Vorn, we have all the time we want, you basically arr just wasiting your time.
that may well just be guessing without actually explaining why
So what do you want from me?
its easy to say that they're independent without actually justifying why
you want me to explain the ans?
so we need u to tell us why each of them is independent
this question seems like u're implying u don't even need help anymore
like it's obvious enough to u
lmao
do u know what independence means?
yeah
tell us then
it means they are "not related"
they are separate
"the result of the future ones does not depend on the result of any past ones"
exactly
events are independent if they can each happen without affecting how likely the other can occur
think about why they would be independent/not independent
hint: events are also independent if they happen in different experiments
go through each one carefully
and explain to use why you made your conclusions
reasoning?
one sec
bc a ball was removed from the box at the first selection
in the second selection, one ball was already removed
I can't remember how to do this exactly but this is angular minutes so just recall the 'DMS' Formula
uh convert rads in degs
no wait
wasmt it just 5pi radians = 2 and a half full rotations=900 degrees
and then divide by 11?
¯_(ツ)_/¯
An example I took off the web:
- Reduce the following numbers of radians to degrees, minutes, and seconds.
(a). 0.47623.
(b). 0.25412.
Conversely, to convert radians to degrees divide by π and multiply by 180. So, 0.47623 divided by π and multiplied by 180 gives 27.286°. You can convert the fractions of a degree to minutes and seconds as follows. Multiply the fraction by 60 to get the number of minutes. Here, 0.286 times 60 equals 17.16, so the angle could be written as 27° 17.16'. Then take any fraction of a minute that remains and multiply by 60 again to get the number of seconds. Here, 0.16 times 60 equals about 10, so the angle can also be written as 27° 17' 10".
thanks!
yk you could always plug the answers into desmos.com or something
Who won't?
just doesn't let me use the website
what doesn't let you? is this for a test or something?
it's not
it's homework
i can't go on the website on this pc for some reason
gives me an error
Oh, well do you have a graphing calculator?
nope
its from wolframalpha actually
Yeah but I didn't know it had a wolfram command built in
I've literally had it on my own server for like, a year and a half and never knew
now if u transform cos(x) accordingly u can get ur function @alpine sable
can't see
try clicking on it
I have
screenshot what's happening and send it here
nothing loading
Sounds like you have a really weird firewall or something
borrowed?
@tough hatch He couldn't access desmos either so I bet there's some kind of blocker installed
that explains it
im not even using the browser
anyway do u know how to do transformations?
kinda
right
f(x) = acos(bx+c)+d
i'm just trying to submit this homework
where |a| is the amplitude of ur graph
?
its the general cosine function
possibly with transformations
is that borrowed from school?
a friend
u have a smartphone?
i just wanna get over this 1 problem
otherwise u won't really see any images
so i could continue with the others
cause waiting could take ages when i could complete other questions yknow
i can't that's the thing
there's 15 questions
you have to complete one to move on
that's harsh af
i can't find anyone to do this problem i'm on
i've done 11
im just stuck on 12
been on this for 30 minutes man
no websites work huh
ur friend might've been a little too paranoid
So do you know the amplitude?
No.
Basically the amplitude is the distance from the maximum to the midline
The midline is basically the line between the maximum and minimum
imaginary line*
Yeah
So basically if you take the mean of maximum and minimum you get the midline
And if you take the difference between the maximum and midline you get amplitude
Since this doesn’t start on zero it’s cosine
And the period (how it cycles) is 2pi divided by the value in the cosine
Huh
the distance between the peak y=p and the trough y=q is |p-q| or p-q in this case
so u will get |a| from (p-q)/2
@alpine sable
the peak is y=15
trough is y=2.5
that's not entirely true
This is so confusing
bear with us
absolute value gives distance between two points
which is why |15-2.5| gives distance between y=15 and y=2.5
In this case it is
You can write any function as either soo
u could indeed write this function as either cosine or sine
but cosine would be easier to use
then |15-2.5|/2 = |a|
but since the graph curves downward from x=0, then a>0 @alpine sable
so 8.75
still nope
odd
oh 6.25
@alpine sable why are u adding sin and cos together
sin stays though correct?
the replace the sin with the cos
the replace?
Use cos not sin
like get rid of the sin and cos and put the cos in the sin's old place
Yeah
just put 0 next to sin.
that would've been multiplying two cosine functions..
put 0 next to sin
Just put cos
in the 1st line
?
Close
???
it should be plus 8.75
oh alrigh
why the username, your just a mock e xD
oh, didn't realize we just have to drag the expressions
might need help with another problem
Yoo
What is the quadratic formula
I think they're asking another question
You can just search it up
@undone dock you could help?
just search quadratic formula
lmao
does r = 1 / r = -1 diverge or converge in geometric sequences?
Diverge
how come?
I thibk it would be just -3 because it shifts the whole graph of 2cos(x/4) down by 3, and 2cos(x/4) is horizontally symmetrical
y=-3 ig?
Not really sure though
I've done this before
It's fine
36 * sqrt(3)
62?
Which part is confusing you?
62.35
Whatever that comes out to; I'm too lazy to find out
If r = 1, then you just add the first time over and over
If r = -1, then you alternate between the first term and 0, so it doesn't converge to a unique value
b?
well that's pretty clear from the identity tan x = sin x / cos x
if cos x = 0 then tan x is not defined at that point
It isn’t horizontal though
why are u guessing
then it's not healthy to do school stuff in that state
Ok, so can you give a reason as to why you think it is c?
Hint:when does 1/sin(x) =0
hi i am new to math pls tell me how to calculate imperfect sqrt
just read the rules sry for disturbing
hey how much is 11,340+9,4100?
105440?
wlc
..........
antanaas, if your question can be answered by a calculator, it doesn't belong here.
kame blitz, refrain from giving out answers in the future.
ok
ig my question is also calc-ish, but tell me if there is a way to calculate imperfect sqrts
OK
Guys dumb question: but can you take the "half life" of ln(x)? if you even can
since the graph goes to minus
or how does this work
what would that even mean
what would what mean
"half-life of ln(x)"
I mean you can take the half life of e^x
half-life is a property of exponential decay.
the function y = ln(x) does not describe exponential decay, not directly anyway.
oh okay
there is no constant h such that ln(x+h) = ln(x)/2 for all x.
(also, for exponential growth, one speaks of a 'doubling time' rather than a half-life)
just take "or" and "ro" as one entity and solve
and dont ping helpers within 10 mins of posting the question
sigh on android/non ios software there is nothing as good as notability is their?
I think if O and R are together, you have 5 other places places to put the other 5 leyter
how
Just add 5! For every place o and R can be(togethrr) and add
Ig
Waig
Actually mo
Uh
Not really sure
<@&286206848099549185>
how to ping helpers while you are being helped
is this $\sum_{n=1}^{\infty} y^{n/2}$?
Ann
yeah
ok mb
yoo @vale wigeon how you did that?
do what
We have a latex bot
summon TeXit?
$where you can learn its language$
Devie❄
can anyone help
Ann gave you the hint
it's a GP
write out a few terms
try to find out the common ratio
have they given the magnitude of y to be less than 1?
yeah actually
yup then you can use that
i actually made a mistake
the common ratio's magnitude should be less than 1
only then can you use the infinite GP formula
how would i solve it if the magnitude of y is greater than 1
it doesn't depend on the magnitude of y
^^
what is the common ratio here?
sqrt(y)
how would i solve it if the magnitude of sqrt(y) is greater than 1
pretty sure you can't
It doesn't converge then
So you need 0 <= y < 1
common ratio
you're looking for the word "common ratio"
thanks ann
Well, here is a hint: try to see how many permutations of the 9 are equivalent. That is, for any given permutation how many others is it equivalent to?
,w 9!
That isn’t what i asked. Let’s be more specific: how many permutations look like BBBBGGGGG
1 ?
its the factorial of 9 right?
and @fair hamlet asked you to find the permutations of 9
and that's what I did
Look, imagine each kid is holding a number from 1 to 9. How many permutations have the pattern i gave above
9!
No! you can’t just put the boys and girls anywhere
Boys have to be in the first 4 slots and girls in the last 5
Do you see why there are 4!5! permutations which give us this one pattern?
Ok now do you see that for every pattern there is 4!5! permutations which give that pattern?
So the number of patterns is: 9!/(4!5!)
ans 100800
Look, the number isn’t that important, do you get the logic behind it?
How to do what?
this
I just told you how to do the first thing. Try to use similar logic to get the rest
I dont ge tie i
What part
this
given a permutation, ypu can rearrange all the girls amongst themselves and all the boys amongst themselves and it won’t change the pattern of boys and girls. There are 4!5! ways of doing this for every permutation, hence the answer is 9!/4!5!
u didnt explain why
u know?
in the first one there are 2 of a kind
so what do u do to 9!
u treat everyone else as of the same kind
,w P(7,7)*P(5,2)
hm?
wdym
THAT'S THE ANS
to what item?
scroll up
(a)?
yes
thats not the answer to (a)
it is
u're asked for the permutation of having the first two people as girls
then everyone else doesn't matter
ok...
no it isnt
what
its ur homework so do as u please lmao
how would u even explain this..
we wont tell you
tf
ur choice to believe that lol
since u declare it's the answer then this question is closed
bruh
stating that something is a fact is believing in it
what is your answer?
better question to ask next time is "how would i solve this?"
no
how would you solve this?
dude, you have been telling me that my ans is wrong and giving no fuckinng clue what I did wrong
I want to know how you did it
because u were saying that it is the answer
and I'll compare it to mine
I fucking know it's an answer
but I don't know if it is right
if you think it is wrong
then show me
ok
for a) u're asked for permutation of two girls being first in line
and u have 9! ways to arrange them without categorizing them
mb
if they are going to be in the first two slots of the line, u can choose them separately from the other 7 members
final ans?
there are 5P2 ways to choose the two girls assigned to the first 2 slots (choosing 2 from 5 girls)
and 7P7 ways to choose the rest of them (choosing 7 from 7, doesn't matter if they are boy or girl)
for (b)
4P1 ways to choose the boy that goes in the first slot
5P1 ... girl in the last slot
7P7 ways to choose the rest
for c, would it just be 2!4!5! ?
do u hv the ans for c and d?
,w 4!6!
how'd u get 4!6!
because there are 4! ways that the boys can be arranged
and there are 6 slots for those boys to fit amongst the 5 girls
so 6!
ohh i see, i jus assumed the girls had to be together too for some reason
I am using python script to verify
u wrote it urself?
yes
yes
ah okay
from math import perm, comb
import itertools
def filterperm(obj_to_perm : str, filter_func):
#obj_to_perm: takes iterable preferably string
#filter_func: takes a filtering function to filter the permutation
print("Number of Permutations: " + str(perm(len(obj_to_perm))))
res = 0
for case in itertools.permutations(obj_to_perm):
res += 1 if filter_func("".join(case)) else 0
return res
print(filterperm("history", lambda x: "or" in x))```
Why are you using Python for this?
how can I do this q?
a or b?
if you want to split into cases according to which card is the highest then you will need to do 4C3 + 5C3 + 6C3 because the highest card is fixed
for a, the following hands are forbidden:
- anything containing the 8 or the 9
- 1234
everything else is fair game
so it's 7C4 - 1
ohh i see, so if 5 was the largest number, we hv one number out of the 4 and the other 3 can be chosen from 1, 2, 3, or 4
that makes sense
and for b) would it be 4C2+7C2?
nvm that's not it
i got it
where should i start with learning integration?
Learn how to use substitution methods, then all the basic formulas, partial integration and other special substitutions like u = sinx etc.
substitution then basic methods is certainly an interesting way to go
Oh, with basic formula's I meant more of advanced ones, not the typical ones like integral of x^n etc.
anyway, just following like khan academy or a textbook is probably your best bet
and doing plenty of questions too
Knowing how to differentiate will help massively too, they’re inverses of each other. If you can apply the chain rule, you can apply it backwards to integrate
if you can apply the product rule you can learn integration by parts
And most simply if you take the power down to the front and then take one off the power when you differentiate, you can then add one to the power and divide by the new power to integrate x^n, provided n is not -1 ofc
And then yea standard results
Like int 1/x dx = ln lxl + c
I dont understand any of this stuff, I ended up getting curious about an equation I saw
I do want to be able to understand this soon though
Gotten to Differential Calc yet?
I mean you usually do that before Integral Calculus
@solemn juniper yo hellow
someone in chess-go told me your good in excel
would u like to help me a bit with my sheet ?
hi :> im having a hard time trying to solve this trig problem
i tried to illustrate it this way but i dont know the value of the legs
dont mind the wrong angles i will fix that later... i just need insight on how to solve the problem :>
Find the slope given the following
points: (2, −7) 𝑎𝑛𝑑 (3, 6).
How do I convert cubic meters to liters?
a cubic meter is 1000 liters; multiply the value to 1000
Isn't there a way to do it in fractions?
liters to cubic meters would require you to divide by 1000, if thats what you mean
but i dont see another way to use division for cubic meters to liters
i mean
you could, if you really wanted to, frame multiplication by 1000 as division by 0.001
In other words, I have 0.15 cubic meters, I multiply it by 1000 and I will have the value in liters?
you need to use the slope equation: (y2 - y1)/(x2 - x1)
yes
yes
0.15 m^3 = 150 L
Ok, thanks u very much
The slope is 13
<@&286206848099549185>
wich is
reasonably easy
and not like stupidly hard
also
if anyone decides to elp me, @ me
hey guys is anyone here good in excel?
i could need some help with my sheet i know how to calculate some of them but i dont know how to make the formular correct
hey can someone check with me my answer to this
Write the equation of the line in slope
intercept form. −2𝑥 + 3𝑦 = 21
Help
y= [(x^2 /5) + cx^-3]^2 ?
hey guys, I need an equation that uses distributive property and some fractions and has an answer of 11, if someone could help I would appreciate that
,calc 8 * (11 + 9/2)
Result:
124
yes, this equation has x=11 as its solution
k
give me the hardest permutation problem
I can do it no matter how hard it is
memememe
<@&268886789983436800>
b&
wait i wanted to know what he was gonna call me :(
Consider all permutations of the numbers 1 to n. A good permutation is one where for any number i at position p in the permutation, i+1 is never at position p+1. For a given n, count the number of good permutations.
For example, for n = 3, the good permutations are:
1, 3, 2
2, 1, 3
3, 2, 1
Come up with a form of an answer which can be easily calculated.
not sure how hard it is but here's one to do
wdym ii & pp?
permutation problem: show
[
R(r, s) \leq \binom{r+s-2}{r-1}
]
and hence
[
(1 + o(1))\frac{s}{\sqrt{2}e}2^{s/2} \leq R(s, s) \leq (1+o(1))\frac{4^{s-1}}{\sqrt{\pi s}}
]
where $R(r, s)$ is the smallest size $n$ such that any gaph of size $n$ has a clique (complete subgraph) of size $r$ or its complement has a complete subgraph of size $s$
Namington
good luck
what the hell is that?
<@&268886789983436800> this was an exam question btw
A doozy
and how do you know that?
Could you show us?
he had a screenshot and then deleted it
an inequality on ramsey's number, this particular result is due to Erdos i think
its technically a permutation problem
@night geyser Message history of that user seems to agree
for a flexible enough understanding of what that means
Yeah got info in dms too
is anyone available to help me in this problem? thanks a lot in advance :>>
Hello everyone! I need to pick up the coefficients for the model so that it maximally describe the experimental data. I wanted to solve this with the help of optimization methods, but I can not choose the target function to my nonlinear dependence. I tried to use R ^ 2 but it does not work correctly for my data - the result of the calculation does not match all this data although r2 = 0.94
No need some fancy math formula ```py
from math import perm, comb
import itertools
def filterperm(obj_to_perm : str, filter_func):
#obj_to_perm: takes iterable preferably string
#filter_func: takes a filtering function to filter the permutations
#for the amount of occurances
print("Number of Permutations: " + str(perm(len(obj_to_perm))))
occurances = 0
for case in itertools.permutations(obj_to_perm):
occurances += 1 if filter_func(case) else 0
#k = print(case) if filter_func(case) else 0
return occurances
def filter_func(x):
for i in range(len(x)):
try:
if x[i] + 1 == x[x[i]]:
return False
except IndexError:
continue
return True
print(filterperm(
[x for x in range(1, 5)],
filter_func
))
i feel this should b such an easy problem but im very confused now
i suppose you could argue thats a form of the answer that "could be easily calculated"
think it should b 3/4
but my friend said u were supposed to multiply the values instead
E or F means either E or F
you can brute force
lmao my code can support up to n = 10
P(A or B) = P(A) + P(B) - P(A and B)
since they are independent, P(A and B) = P(A) times P(B)
so P(A or B) = P(A) + P(B) - P(A) * P(B)
1/2 + 1/4 - 1/2*1/4 = 3/4-1/8 = 5/8
@shy prairie
no
idk have my rules confused
thats for independent
if P(A and B) = 0 (no overlap), then P(A or B) = P(A) + P(B)
which is what you had before
but its independent, not disjoint/exclusive
lol m8
Does anyone know what my equations would be for these systems?
d+m+b=130, (do the money equation yourself), 3d=b
Can anyone please tell me the general formula for the series->(1/2),(1/10),(1/30),..... ?
Needed Badly
Two consecutive odd numbers are such that 7/9 of the reciprocal of one is equal to the reciprocal of the other. Find the two odd numbers.
Anyone need help for this
Two unknown consecutive odd numbers: 2x +1, 2x +3
7/9 x 1/2x+1 = 1 / 2x + 3
simplify further
Convert your GPA how?
yeah howt?
No, that’s not what I meant. What are you asking?
Convert your GPA could mean a lot of different things
"tell me the answer to the problem i'm telepathically transmitting to you, or i will get angry if you try to tell me you're not a telepath"
Lol, I’m betting English isn’t their first language so they get a pass in my book
Don't abuse the helper ping. Ping helpers after at least 15 minutes from posting your problem.
Also, it is good practice to add more context, and show what you've tried when asking problems.
Colleges report GPA (grade point average) on a 4.0 scale. See how to calculate your GPA and convert your grades to the 4.0 scale.
can someone help me with this thing please? I'm trying to find the math to have a nice curve between 2 points like so
That's not how that works
this guy has been trolling since yesterday
Colleges don’t only care about gpa
then what?
basically I need to find the correct tangents
Not sure how though
I can make it so it's a perfect circle and then hack the ends but it doesn't look very nice
Why is there a spider nearby?
Off-topic conversations are better suited to #chill . Question channels are intended for help with problems and related discussions.
yeah but I initially asked for a formula to convert percentage to gpa
So I dropped a little reason why I asked the question at the last bit
Just a small story behind the question
That's altogether better suited to one of the discussion channels.
The chill channel? I thought the discussion channels were better suited for off topic discussions
Either works, really.
even if someone could point me out to a formula i'd appreciate that, nothing I find seems helping
@boreal matrix Sorry for the digression. You can repost here.
or maybe it's not possible?
np
I'm trying to find the math to have a nice curve between 2 points like so
What function is this?
I don't think I've ever seen coordinate notation like that before, with the vertical bars, in the "points" section
Also, what's the full question? Like what exactly are you looking for?
I'm not a mathematicians the red lines are to showcase the tangents directions
@graceful pier Channel occupied
Not the red lines there
But here, in your screenshot, top of the page where it lists the points, it uses vertical bars
you mean these @wary stream ?
This, the coordinate notation, with vertical bars
@boreal matrix I'm not exactly understanding what your question is. Do you want parabolic curves between two points on a plane?
just use quadratic equation
Not exactly that easy
I don't really like how it looks though, I was wandering if there was a way to keep the parable more thight at the top like the drawing
Okay, so if you have a regular Cartesian plane, and you want the endpoints to lie on the same horizontal line(for convenience, let it be x-axis, and coordinates of endpoints be (a,0) and (b,0)), then you can get parabolas passing through them by the equation y=-m(x-a)(x-b), where m>0.
Something like the upper half of an ellipse?
yeah something like that
Is there more to the question or just what was in the screenshot?
(x-h)^2 = 4p(y-k) This is parabolic equation
You can search up more about equation of an ellipse, and toy around till you get what you're looking for. Can you provide the context in which this problem came up?
I'm creating a spline for my videogame between tho characters
I can make it look alright with some hacking but I was wandering if there was something more precise
(x-h)^2/a^2 + (y-k)^2/b^2 = 1 where a>b This is an elipsetic equation
Ah, I see. I'm not familiar with the background here, but I suppose you have some coordinate system running in the background to describe motion, etc.?
Alright, so I suppose you want an equation describing some sort of a nice trajectory between two points?
yeah
Like throwing a ball?
yeah 🙂
Then you can use physics right away haha
are you using one of those systems that has y as the vertical axis
with the xz plane being flat/ground
z is verical in my case
ah good
go on @cyan willow I think I'm not clear enough on what I need anyway
thanks all for the help!
Also, this channel was busy
@boreal matrix If you don't mind learning some physics, this is good and might lend some intuition behind what you're trying to do: https://openstax.org/books/university-physics-volume-1/pages/4-3-projectile-motion#:~:text=h %3D v 0 y 2,component of the initial velocity.
(Also gives a lot of mathematical apparatus, although you'll have to modify it according to you needs)
that's amazing, thanks!
No worries; goodluck!
cheers
That's basic eom
im learning this on my own
Do you know what degree is?
nope
Also, wants you to do long division with polynomials
division
I solved the first question,
How do I solve the first part of the second question?
yoo
i know what degree is
tell me
I know ur name
Oh thanks I guess it's on my profile so that's why.
Can you help though
For that problem, do long division with polynomials
it's Maria
Will you stop getting off topic
@sudden tulip What degree is it?
3 ?
lmao