#help-0

1 messages · Page 670 of 1

woeful ridge
#

Did I do this right? Is the left hand = to right hand?

glacial hedge
#

@woeful ridge you cant cancel the 1-tan^2(x) and the 1-tan(x)

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factor the 1-tan^2(x) into (1+tan(x))(1-tan(x))

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then you get

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(1+tan(x))/tan(x)

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which is equal to 1+1/tan(x)

covert berry
#

beautiful handwriting

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🤩

bronze dust
#

hello i wanted to ask a question regarding floor function

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say floor(n/x) + floor(n/x^2) is something

wraith cairn
#

nice floor function

bronze dust
#

is it same as floor(n/x) + (floor(n/x))x

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floor

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my bad

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i often get confused

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in those two

wraith cairn
#

no you can't do that lol

covert berry
#

lmao

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someone deleted their message

bronze dust
wraith cairn
#

I assume you meant floor(n/x)/x?

alpine sable
wraith cairn
#

try it with any number

bronze dust
#

okay

covert berry
#

if such a convenient thing existed, you should have been taught it

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#strong-proof

bronze dust
#

i havent been taugh many things, doesnt mean they dont exist

covert berry
#

you're taught about floor already

wraith cairn
#

try it with n = x = 2

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it does not work.

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so it's not true

woeful ridge
bronze dust
#

i want to test this thing only for x^n <= n

covert berry
#

you're probably solving a problem elsewhere right

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and if the above thing worked, you can solve it?

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assuming

bronze dust
#

ill cut my bullshit, you are familiar with legendre's formula? the one where you calculate exponent of prime in n!

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this one

covert berry
#

kill my ass

#

competition maths

bronze dust
#

yes that is right

covert berry
#

there's a whole channel for that

alpine sable
#

Two gears are attached to one another. The smaller gear X has 16 teeth while the larger gear Y has 20 teeth. When the smaller gear makes 7 turns, how many turns does the larger gear make? Record your answer to the nearest tenth of a turn. For example if the answer is 3.721, then write 3.7

the answer is 8.7 right? or am i wrong?

bronze dust
covert berry
#

i suck at comp maths but i'll take a view too

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if i have no idea i'll just offer you sweet silence

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lol

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the bigger gear should make less turns

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20/16 = 7/x

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x = 140/16 = 35/4

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wait- uh

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right

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yeah you're right, i messed up

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shouldn't the larger make less turns though

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same distance travelled, larger radius uhh

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nvm

alpine sable
#

ok

covert berry
#

i messed up with the maths

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,w 20/16 = 7/x

covert berry
#

there, it's 28/5

wanton turtle
#

The quadratic formula is the direct result of the completing the square method

proud burrow
#

Yes it's generalized formal

shy prairie
#

i checked each answer choice and i swear they're all correct but i prob screwed up somewhere

woeful ridge
#

Is it possible to make this equation, 1-tan^2a = 2tana/tan2a? Or how would I manipulate it?

glacial hedge
#

@woeful ridge thats an identity....

woeful ridge
#

Yeah but can you manipulate it?

glacial hedge
#

are you allowed to use any identities?

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because you would have to at least use an angle adition identity

ionic jewel
glacial hedge
woeful ridge
#

Basically trying to solve this

safe kite
#

What am I doing wrong why can’t I get this answer

woeful ridge
#

Starting on the left side

glacial hedge
#

@ionic jewel do you have any probability knowlege?

ionic jewel
#

yes but i don't like it

glacial hedge
#

could u help with this. i kinda suck

#

techincally its not probability but like an application of mvc... but i have no idea how to do this

ionic jewel
#

don't know this one sorry

shy prairie
#

I have 0 clue where to even start with this problem

glacial hedge
shy prairie
glacial hedge
#

not quite

native temple
glacial hedge
#

$y=10000e^(0.42d)$

$y=10000(1.5219)^d$

ocean sealBOT
#

Elonmosqito96

shy prairie
#

oh alright thx

native temple
#

$$ \frac{-4\pm\sqrt{24}}{2}$$

ocean sealBOT
#

Nerdy_Coder

native temple
#

@safe kite

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see

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also another thing

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nice

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so

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uhhh

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here's your equation

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@safe kite

floral jungle
#

anyone able to help me with any of these?

alpine sable
#

what do you call a geometric sequence in which r = 1 or -1

stable vigil
native temple
#

or An = a1+1*(n-1)

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see

#

easy

sullen sigil
#

how would i solve this?

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i know f(2) = 6

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and that f'(2) = -132

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so does that mean f(3) = 6-132?

strong furnace
#

this is just an ODE

sullen sigil
#

im currently learning calc 1, so i dont think we've gotten to ODEs yet

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this is the topic on linear approximations and differentials

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but the answer cant be 6-132 since mass cant be negative

strong furnace
sullen sigil
#

ohhh

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it was just a unit thing

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thank u

sudden tulip
#

For 29 ii

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Isn't it

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1/2 x 5 x 5

gray isle
#

yes...

sudden tulip
#

Well the and is different

gray isle
#

wdym by

and is different

sudden tulip
#

the ans is 5 or -3

gray isle
#

that isn't part ii)

sudden tulip
#

yes

gray isle
#

seems those are the answers for part iii)

sudden tulip
#

ye it is for ii

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wait

gray isle
#

ii) is for the area which is 1/2 * 5 * 5 (simplfied)
iii) are the values of k satisfying the specified properties

sudden tulip
#

the practice book must have some problems

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because it clearly stated ii) answer as 5 or -3 which is weird

gray isle
#

does the answer provide solutions to all three parts?

sudden tulip
#

no

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it only provides for i and ii

gray isle
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so yeh, they wrote the answers for iii) in ii)

sullen nova
#

yoo

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halp

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<@&286206848099549185>

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helpers?

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<@&286206848099549185>

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HALP

ruby tree
#

Don’t spam them jeez

rigid smelt
#

Why are you so urgent?

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Is it a test of some kind?

sullen nova
#

no test

rigid smelt
#

Please dont give out answers

ruby tree
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Oh, sorry

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I’m new, didn’t realize

sullen nova
#

??

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then how tf do i know?

ruby tree
#

@sullen nova I posted the answers but I think I’m supposed to walk you through it so you actually learn

ionic jewel
#

do you know what independent means?

sullen nova
#

yes

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just tell me the ans

ionic jewel
#

...

sullen nova
#

I have already learned

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you don't have to walk me through

rigid smelt
#

Havent you been told about these rules Le Vorn?

sullen nova
#

again

ionic jewel
#

if you learned it you could answer yourself...

rigid smelt
#

I think i have seen you before

#

With the same attitude

ruby tree
ionic jewel
#

unbelievably ironic lol

sullen nova
#

I am asking for the ans to verify my ans

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I already have my ans

rigid smelt
#

Then post your answers

ruby tree
#

^

ionic jewel
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^

rigid smelt
#

We will verify it for you

tough hatch
#

yep

sullen nova
#

all are indep

alpine sable
#

anyone?

sullen nova
#

what do yall think?

rigid smelt
#

Well its definitely wrong

#

Try again

tough hatch
#

that just goes to show that u're trying to fool us into giving us answers u likely don't actually have

ionic jewel
#

they are not all independent

ruby tree
sullen nova
ionic jewel
tough hatch
#

it's now obvious u want answers from us but u don't even have ur own answers to post here

sullen nova
#

I have my ans?

gray isle
#

justify your answers

sullen nova
#

my ans are all indep

tough hatch
#

then tell us your answers

sullen nova
#

??

tough hatch
#

and tell us why each is independent

sullen nova
#

did you read my previous message?

rigid smelt
#

Le Vorn, we have all the time we want, you basically arr just wasiting your time.

tough hatch
#

that may well just be guessing without actually explaining why

sullen nova
#

So what do you want from me?

tough hatch
#

its easy to say that they're independent without actually justifying why

sullen nova
#

you want me to explain the ans?

tough hatch
#

so we need u to tell us why each of them is independent

tough hatch
#

like it's obvious enough to u

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lmao

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do u know what independence means?

sullen nova
#

yeah

tough hatch
#

tell us then

sullen nova
#

it means they are "not related"

ionic jewel
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yes

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well sorta

sullen nova
#

they are separate

tough hatch
#

thats a bad way to put it

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basically

ionic jewel
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"the result of the future ones does not depend on the result of any past ones"

sullen nova
#

exactly

tough hatch
#

events are independent if they can each happen without affecting how likely the other can occur

ionic jewel
#

yes

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and at least one of those is dependent

tough hatch
#

so reexamine ur answers

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we already told u they are not all independent

sullen nova
#

I have been trying

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before coming here

tough hatch
#

think about why they would be independent/not independent

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hint: events are also independent if they happen in different experiments

gray isle
#

go through each one carefully
and explain to use why you made your conclusions

sullen nova
#

ok the last is dependent

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right?

gray isle
#

reasoning?

sullen nova
#

one sec

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bc a ball was removed from the box at the first selection

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in the second selection, one ball was already removed

gray isle
#

that's the second last

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not the last

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but what you stated would indeed be dependent

sullen nova
#

ic

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forgot the last bit

novel zenith
#

(Also pls ping me if you have a solution)

alpine sable
#

I can't remember how to do this exactly but this is angular minutes so just recall the 'DMS' Formula

#

uh convert rads in degs

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no wait

undone dock
#

wasmt it just 5pi radians = 2 and a half full rotations=900 degrees

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and then divide by 11?

alpine sable
#

¯_(ツ)_/¯

#

An example I took off the web:

  1. Reduce the following numbers of radians to degrees, minutes, and seconds.
    (a). 0.47623.
    (b). 0.25412.

Conversely, to convert radians to degrees divide by π and multiply by 180. So, 0.47623 divided by π and multiplied by 180 gives 27.286°. You can convert the fractions of a degree to minutes and seconds as follows. Multiply the fraction by 60 to get the number of minutes. Here, 0.286 times 60 equals 17.16, so the angle could be written as 27° 17.16'. Then take any fraction of a minute that remains and multiply by 60 again to get the number of seconds. Here, 0.16 times 60 equals about 10, so the angle can also be written as 27° 17' 10".

novel zenith
#

thanks!

alpine sable
#

@alpine sable

ruby tree
#

yk you could always plug the answers into desmos.com or something

alpine sable
#

i can't

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wont let me use that website

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@ruby tree

ruby tree
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Who won't?

alpine sable
#

just doesn't let me use the website

ruby tree
#

what doesn't let you? is this for a test or something?

alpine sable
#

it's not

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it's homework

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i can't go on the website on this pc for some reason

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gives me an error

ruby tree
#

Oh, well do you have a graphing calculator?

alpine sable
#

nope

tough hatch
#

that function looks like a cosine

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,w plot cos(x)

ruby tree
#

Ooh

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I didn't know TeXit could do that

tough hatch
#

its from wolframalpha actually

ruby tree
#

Yeah but I didn't know it had a wolfram command built in

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I've literally had it on my own server for like, a year and a half and never knew

tough hatch
#

now if u transform cos(x) accordingly u can get ur function @alpine sable

alpine sable
#

i can't even see the graph

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it's not loading

tough hatch
#

assuming u know how to do transformations

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can u see images?

alpine sable
#

it's not loading in

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:l

tough hatch
alpine sable
#

can't see

tough hatch
#

try clicking on it

alpine sable
#

I have

tough hatch
#

screenshot what's happening and send it here

alpine sable
#

nothing loading

ruby tree
#

Sounds like you have a really weird firewall or something

tough hatch
#

can u ss ur discord settings

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for text & images

alpine sable
#

i didn't touch anything

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it's probably just the laptop i'm on

tough hatch
#

borrowed?

alpine sable
#

yeah

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very slow

ruby tree
#

@tough hatch He couldn't access desmos either so I bet there's some kind of blocker installed

tough hatch
#

that explains it

alpine sable
#

im not even using the browser

tough hatch
#

anyway do u know how to do transformations?

alpine sable
#

kinda

ruby tree
#

(he probably cant see that)

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(its an image)

tough hatch
#

right

alpine sable
#

just loading infinetly

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ugh

tough hatch
#

f(x) = acos(bx+c)+d

alpine sable
#

i'm just trying to submit this homework

tough hatch
#

where |a| is the amplitude of ur graph

alpine sable
tough hatch
#

its the general cosine function

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possibly with transformations

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is that borrowed from school?

alpine sable
#

a friend

tough hatch
#

u have a smartphone?

alpine sable
#

dead

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charging

tough hatch
#

its better to wait for it to charge

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and use it instead

alpine sable
#

i just wanna get over this 1 problem

tough hatch
#

otherwise u won't really see any images

alpine sable
#

so i could continue with the others

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cause waiting could take ages when i could complete other questions yknow

tough hatch
#

then why not move on

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skip this one for now

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and see if there are easier ones

alpine sable
#

i can't that's the thing

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there's 15 questions

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you have to complete one to move on

tough hatch
#

that's harsh af

alpine sable
#

i can't find anyone to do this problem i'm on

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i've done 11

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im just stuck on 12

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been on this for 30 minutes man

tough hatch
#

no websites work huh

alpine sable
#

yeah

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that's why i'm here

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still no luck

tough hatch
#

ur friend might've been a little too paranoid

alpine sable
#

Idk possibly

#

I just need help man

storm turret
alpine sable
#

No.

storm turret
#

Basically the amplitude is the distance from the maximum to the midline

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The midline is basically the line between the maximum and minimum

tough hatch
#

imaginary line*

storm turret
#

Yeah

#

So basically if you take the mean of maximum and minimum you get the midline

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And if you take the difference between the maximum and midline you get amplitude

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Since this doesn’t start on zero it’s cosine

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And the period (how it cycles) is 2pi divided by the value in the cosine

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Huh

tough hatch
#

the distance between the peak y=p and the trough y=q is |p-q| or p-q in this case

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so u will get |a| from (p-q)/2

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@alpine sable

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the peak is y=15

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trough is y=2.5

tough hatch
alpine sable
#

This is so confusing

tough hatch
#

bear with us

#

absolute value gives distance between two points

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which is why |15-2.5| gives distance between y=15 and y=2.5

storm turret
#

You can write any function as either soo

tough hatch
#

u could indeed write this function as either cosine or sine

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but cosine would be easier to use

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then |15-2.5|/2 = |a|

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but since the graph curves downward from x=0, then a>0 @alpine sable

alpine sable
#

so what's wrong with y=

tough hatch
#

a shouldn't be -8.75

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and it shouldn't be negative

alpine sable
#

so 8.75

tough hatch
#

still nope

alpine sable
#

odd

tough hatch
#

try calculating |15-2.5|/2

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it's not 8.75

alpine sable
#

oh 6.25

tough hatch
#

yes

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but a>0 so

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a = 6.25

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that's what u multiply to sin() as a whole

alpine sable
#

sin(pi/12x)?

glacial hedge
#

@alpine sable why are u adding sin and cos together

alpine sable
#

OH

#

mb

alpine sable
glacial hedge
#

the replace the sin with the cos

alpine sable
#

the replace?

storm turret
#

Use cos not sin

glacial hedge
tough hatch
#

just put 0 next to sin.

tough hatch
storm turret
#

No

#

Get rid of both

tough hatch
#

put 0 next to sin

storm turret
#

Just put cos

storm turret
#

Just delete it

tough hatch
#

in the 1st line

alpine sable
storm turret
alpine sable
#

???

glacial hedge
#

it should be plus 8.75

storm turret
#

Yeah

#

Not -8.75

alpine sable
#

oh alrigh

glacial hedge
tough hatch
#

oh, didn't realize we just have to drag the expressions

alpine sable
#

might need help with another problem

sullen nova
#

Yoo

alpine sable
sullen nova
#

What is the quadratic formula

alpine sable
#

?

#

you need to do quadratic for this

#

?

undone dock
#

I think they're asking another question

undone dock
alpine sable
#

@undone dock you could help?

undone dock
#

Uhh

#

Let me think

alpine sable
#

just search quadratic formula

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lmao

#

does r = 1 / r = -1 diverge or converge in geometric sequences?

gentle flame
#

Diverge

alpine sable
#

how come?

undone dock
#

y=-3 ig?

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Not really sure though

alpine sable
#

think so

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@gentle flame

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how are you sure

gentle flame
#

I've done this before

alpine sable
#

62 inches?

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@gentle flame@undone dock

undone dock
#

Uh

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I'm not very good at stuff like that

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Sorry

alpine sable
#

It's fine

gentle flame
#

36 * sqrt(3)

alpine sable
gentle flame
alpine sable
#

62.35

gentle flame
gentle flame
gentle flame
alpine sable
tough hatch
#

well that's pretty clear from the identity tan x = sin x / cos x

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if cos x = 0 then tan x is not defined at that point

fair hamlet
#

It isn’t horizontal though

tough hatch
#

yeah

#

vertical asymptotes

alpine sable
#

c?

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@tough hatch

tough hatch
#

why are u guessing

alpine sable
#

dude i'm drained rn man

#

just trying to get the homework done

tough hatch
#

then it's not healthy to do school stuff in that state

alpine sable
#

huh

#

I don't get how this correlates to my health

fair hamlet
#

Ok, so can you give a reason as to why you think it is c?

#

Hint:when does 1/sin(x) =0

bleak igloo
#

hi i am new to math pls tell me how to calculate imperfect sqrt

#

just read the rules sry for disturbing

alpine sable
#

hey how much is 11,340+9,4100?

bleak igloo
#

105440?

alpine sable
#

ty

#

((:

bleak igloo
#

wlc

vale wigeon
#

..........

#

antanaas, if your question can be answered by a calculator, it doesn't belong here.

#

kame blitz, refrain from giving out answers in the future.

bleak igloo
#

ok

#

ig my question is also calc-ish, but tell me if there is a way to calculate imperfect sqrts

sullen nova
#

YOO

#

I have just realize that dice is plural

pastel jasper
#

Guys dumb question: but can you take the "half life" of ln(x)? if you even can

#

since the graph goes to minus

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or how does this work

vale wigeon
#

what would that even mean

pastel jasper
#

what would what mean

vale wigeon
#

"half-life of ln(x)"

pastel jasper
#

I mean you can take the half life of e^x

vale wigeon
#

half-life is a property of exponential decay.

pastel jasper
#

Can you do it for ln(x) though

vale wigeon
#

the function y = ln(x) does not describe exponential decay, not directly anyway.

pastel jasper
#

oh okay

vale wigeon
#

there is no constant h such that ln(x+h) = ln(x)/2 for all x.

#

(also, for exponential growth, one speaks of a 'doubling time' rather than a half-life)

pastel jasper
#

og okay thanks man

#

I was just wondering thanks a lot!

sullen nova
#

<@&286206848099549185>

#

yo

#

halp

#

yooo

#

anyone?

#

halp meh pls

rose imp
#

just take "or" and "ro" as one entity and solve

#

and dont ping helpers within 10 mins of posting the question

native temple
#

sigh on android/non ios software there is nothing as good as notability is their?

sullen nova
#

wodth?

#

hpw

#

how ot do this

undone dock
#

I think if O and R are together, you have 5 other places places to put the other 5 leyter

sullen nova
#

how

undone dock
#

Just add 5! For every place o and R can be(togethrr) and add

#

Ig

#

Waig

#

Actually mo

#

Uh

#

Not really sure

sullen nova
#

<@&286206848099549185>

eager ginkgo
#

how to ping helpers while you are being helped

sullen nova
#

HOLY fkk

#

just treat the "or" as a single entiry

#

and boom!

#

fkkkkk yeah

austere osprey
#

how would i solve this?

vale wigeon
#

is this $\sum_{n=1}^{\infty} y^{n/2}$?

ocean sealBOT
austere osprey
#

yeah

vale wigeon
#

this is a geometric series

#

also, do NOT post in multiple channels at once.

austere osprey
#

ok mb

native tartan
vale wigeon
#

do what

quaint trout
#

We have a latex bot

vale wigeon
#

summon TeXit?

alpine sable
#

$where you can learn its language$

ocean sealBOT
#

Devie❄

austere osprey
wanton turtle
#

Ann gave you the hint

#

it's a GP

#

write out a few terms

#

try to find out the common ratio

austere osprey
#

do i use this formula

#

ik common formula is sqrt(y)

wanton turtle
#

have they given the magnitude of y to be less than 1?

austere osprey
#

yeah actually

wanton turtle
#

yup then you can use that

austere osprey
#

wait

#

what if y is greater than 1

#

how would i solve?

wanton turtle
#

i actually made a mistake

#

the common ratio's magnitude should be less than 1

#

only then can you use the infinite GP formula

austere osprey
#

how would i solve it if the magnitude of y is greater than 1

wanton turtle
#

it doesn't depend on the magnitude of y

wanton turtle
#

what is the common ratio here?

austere osprey
#

sqrt(y)

wanton turtle
#

yes

#

so the magnitude of sqrt y should be less than 1

austere osprey
#

how would i solve it if the magnitude of sqrt(y) is greater than 1

wanton turtle
#

pretty sure you can't

quaint trout
#

It doesn't converge then

wanton turtle
#

ye

#

you can find it for a finite number of terms

quaint trout
#

So you need 0 <= y < 1

vale wigeon
#

you're looking for the word "common ratio"

austere osprey
#

thanks ann

sullen nova
#

halp

#

@halper

alpine sable
#

Don't

#

@ helpers immediately

sullen nova
#

I didn't

#

gais pls halp

#

anyone?

fair hamlet
#

Well, here is a hint: try to see how many permutations of the 9 are equivalent. That is, for any given permutation how many others is it equivalent to?

sullen nova
#

,w 9!

sullen nova
#

olk

#

what now?

fair hamlet
#

That isn’t what i asked. Let’s be more specific: how many permutations look like BBBBGGGGG

sullen nova
#

1 ?

native tartan
#

and @fair hamlet asked you to find the permutations of 9

sullen nova
#

and that's what I did

fair hamlet
#

Look, imagine each kid is holding a number from 1 to 9. How many permutations have the pattern i gave above

sullen nova
#

9!

fair hamlet
#

No! you can’t just put the boys and girls anywhere

#

Boys have to be in the first 4 slots and girls in the last 5

#

Do you see why there are 4!5! permutations which give us this one pattern?

sullen nova
#

yeha

#

the ans is 201600

#

,w P(9,9)

#

,w P(8,8)*P(5,2)

fair hamlet
#

Ok now do you see that for every pattern there is 4!5! permutations which give that pattern?

#

So the number of patterns is: 9!/(4!5!)

sullen nova
#

ans 100800

fair hamlet
#

Look, the number isn’t that important, do you get the logic behind it?

sullen nova
#

I am trying

#

,w 9!/P(5,2)

#

,w 9!/(4!5!)

sullen nova
#

how to do that?

#

how man

fair hamlet
#

How to do what?

sullen nova
fair hamlet
#

I just told you how to do the first thing. Try to use similar logic to get the rest

sullen nova
#

I dont ge tie i

fair hamlet
#

What part

sullen nova
fair hamlet
#

given a permutation, ypu can rearrange all the girls amongst themselves and all the boys amongst themselves and it won’t change the pattern of boys and girls. There are 4!5! ways of doing this for every permutation, hence the answer is 9!/4!5!

sullen nova
#

ddon't get

#

what answer is this to?

#

9!/4!5!

#

<@&286206848099549185>

tough hatch
sullen nova
#

ans pls

#

anyone?

tough hatch
sullen nova
#

what to do?

#

it've been an hour

#

I got other things to do

tough hatch
#

all of us do

#

lol

sullen nova
#

u know?

tough hatch
#

in the first one there are 2 of a kind

#

so what do u do to 9!

#

u treat everyone else as of the same kind

sullen nova
#

,w P(7,7)*P(5,2)

tough hatch
#

hm?

sullen nova
#

FUCKING FINALLY

#

JESSUS CHRIST

tough hatch
#

wdym

sullen nova
#

THAT'S THE ANS

tough hatch
#

to what item?

sullen nova
#

scroll up

tough hatch
#

uhm..

#

u didnt state exactly what item u needed help with rofl

sullen nova
#

I did

#

just scroll up and you will see

tough hatch
#

(a)?

sullen nova
#

yes

tough hatch
#

thats not the answer to (a)

sullen nova
#

it is

tough hatch
#

u're asked for the permutation of having the first two people as girls

#

then everyone else doesn't matter

sullen nova
#

yeah

#

the ans is 100800

tough hatch
#

ok...

eager ginkgo
#

no it isnt

sullen nova
#

what

tough hatch
#

its ur homework so do as u please lmao

sullen nova
#

what is it

#

then

tough hatch
eager ginkgo
#

we wont tell you

sullen nova
#

tf

tough hatch
sullen nova
#

it is 100800 man

#

wtf do you mean?

tough hatch
#

ur choice to believe that lol

sullen nova
#

it's not what I believe

#

it's about the fact

tough hatch
#

since u declare it's the answer then this question is closed

sullen nova
#

bruh

tough hatch
#

stating that something is a fact is believing in it

sullen nova
#

what is your answer?

tough hatch
#

better question to ask next time is "how would i solve this?"

sullen nova
#

no

#

how would you solve this?

#

dude, you have been telling me that my ans is wrong and giving no fuckinng clue what I did wrong

#

I want to know how you did it

tough hatch
#

because u were saying that it is the answer

sullen nova
#

and I'll compare it to mine

tough hatch
#

so typically what i say would be useless

#

ok

sullen nova
#

I fucking know it's an answer

#

but I don't know if it is right

#

if you think it is wrong

#

then show me

tough hatch
#

ok

#

for a) u're asked for permutation of two girls being first in line

#

and u have 9! ways to arrange them without categorizing them

sullen nova
#

and?

#

,w (9-1)! × 2!

eager ginkgo
#

whats the point of 2!

#

it equals 2

tough hatch
#

mb

#

if they are going to be in the first two slots of the line, u can choose them separately from the other 7 members

sullen nova
#

final ans?

tough hatch
#

there are 5P2 ways to choose the two girls assigned to the first 2 slots (choosing 2 from 5 girls)
and 7P7 ways to choose the rest of them (choosing 7 from 7, doesn't matter if they are boy or girl)

ocean sealBOT
tough hatch
#

for (b)
4P1 ways to choose the boy that goes in the first slot
5P1 ... girl in the last slot
7P7 ways to choose the rest

sullen nova
#

lmao you got the same ans as mine for a)

#

and was braging that I was wrong?

alpine sable
alpine sable
sullen nova
#

17280

#

,w 2!4!5!

sullen nova
#

,w 4!6!

sullen nova
#

c is 17280

#

and you see 5760?

#

@alpine sable

alpine sable
#

how'd u get 4!6!

sullen nova
#

because there are 4! ways that the boys can be arranged

#

and there are 6 slots for those boys to fit amongst the 5 girls

#

so 6!

alpine sable
#

ohh i see, i jus assumed the girls had to be together too for some reason

sullen nova
#

I am using python script to verify

alpine sable
#

u wrote it urself?

sullen nova
#

yes

alpine sable
#

dam

#

is d) 4!*5! ?

#

@sullen nova

sullen nova
#

2880

#

,w 4!5!

sullen nova
#

yes

alpine sable
#

ah okay

sullen nova
#
from math import perm, comb
import itertools


def filterperm(obj_to_perm : str, filter_func):
    #obj_to_perm: takes iterable preferably string
    #filter_func: takes a filtering function to filter the permutation
    print("Number of Permutations: " + str(perm(len(obj_to_perm))))
    res = 0
    for case in itertools.permutations(obj_to_perm):
        res += 1 if filter_func("".join(case)) else 0
    return res

print(filterperm("history", lambda x: "or" in x))```
alpine sable
#

how can I do this q?

vale wigeon
#

a or b?

alpine sable
#

both

#

i thought a) was 5C4+6C4+7C4 but that's not it

vale wigeon
#

if you want to split into cases according to which card is the highest then you will need to do 4C3 + 5C3 + 6C3 because the highest card is fixed

#

for a, the following hands are forbidden:

  • anything containing the 8 or the 9
  • 1234
    everything else is fair game
#

so it's 7C4 - 1

alpine sable
#

ohh i see, so if 5 was the largest number, we hv one number out of the 4 and the other 3 can be chosen from 1, 2, 3, or 4

#

that makes sense

#

and for b) would it be 4C2+7C2?

#

nvm that's not it

#

i got it

narrow basalt
#

where should i start with learning integration?

spring harbor
#

Learn how to use substitution methods, then all the basic formulas, partial integration and other special substitutions like u = sinx etc.

jagged imp
#

substitution then basic methods is certainly an interesting way to go

spring harbor
#

Oh, with basic formula's I meant more of advanced ones, not the typical ones like integral of x^n etc.

jagged imp
#

anyway, just following like khan academy or a textbook is probably your best bet

#

and doing plenty of questions too

gloomy lintel
# narrow basalt where should i start with learning integration?

Knowing how to differentiate will help massively too, they’re inverses of each other. If you can apply the chain rule, you can apply it backwards to integrate
if you can apply the product rule you can learn integration by parts
And most simply if you take the power down to the front and then take one off the power when you differentiate, you can then add one to the power and divide by the new power to integrate x^n, provided n is not -1 ofc

#

And then yea standard results

#

Like int 1/x dx = ln lxl + c

narrow basalt
#

I dont understand any of this stuff, I ended up getting curious about an equation I saw

#

I do want to be able to understand this soon though

alpine sable
#

Gotten to Differential Calc yet?

#

I mean you usually do that before Integral Calculus

narrow basalt
#

i havent gotten to calc at all

#

im trying to learn trig ahead of my syllabus

gaunt coyote
#

@solemn juniper yo hellow

#

someone in chess-go told me your good in excel

#

would u like to help me a bit with my sheet ?

serene lily
#

hi :> im having a hard time trying to solve this trig problem

#

i tried to illustrate it this way but i dont know the value of the legs

serene lily
snow shale
#

Find the slope given the following
points: (2, −7) 𝑎𝑛𝑑 (3, 6).

alpine sable
#

How do I convert cubic meters to liters?

serene lily
alpine sable
#

Isn't there a way to do it in fractions?

serene lily
vale wigeon
#

i mean

#

you could, if you really wanted to, frame multiplication by 1000 as division by 0.001

alpine sable
#

In other words, I have 0.15 cubic meters, I multiply it by 1000 and I will have the value in liters?

serene lily
vale wigeon
#

0.15 m^3 = 150 L

alpine sable
#

Ok, thanks u very much

snow shale
#

The slope is 13

serene lily
dire iron
#

wich is

#

reasonably easy

#

and not like stupidly hard

#

also

#

if anyone decides to elp me, @ me

gaunt coyote
#

hey guys is anyone here good in excel?

#

i could need some help with my sheet i know how to calculate some of them but i dont know how to make the formular correct

shrewd topaz
#

hey can someone check with me my answer to this

snow shale
#

Write the equation of the line in slope
intercept form. −2𝑥 + 3𝑦 = 21
Help

torpid stump
shrewd topaz
dapper eagle
torpid stump
#

in the 2nd step

wooden silo
#

hey guys, I need an equation that uses distributive property and some fractions and has an answer of 11, if someone could help I would appreciate that

vale wigeon
#

,calc 8 * (11 + 9/2)

ocean sealBOT
#

Result:

124
vale wigeon
#

8(x + 9/2) = 124

#

this good enough for you?

wooden silo
#

I need and answer of 11

#

couldn't think of anything tbh

vale wigeon
#

yes, this equation has x=11 as its solution

wooden silo
#

oh yea my bad

#

thanks

sullen nova
#

k

#

give me the hardest permutation problem

#

I can do it no matter how hard it is

#

memememe

ionic jewel
#

<@&268886789983436800>

sly mantle
#

b&

ionic jewel
#

wait i wanted to know what he was gonna call me :(

sullen nova
#

where did he go?

#

where's my man?

ionic jewel
# sullen nova give me the hardest permutation problem
Consider all permutations of the numbers 1 to n. A good permutation is one where for any number i at position p in the permutation, i+1  is never at position p+1. For a given n, count the number of good permutations.

For example, for n = 3, the good permutations are:

1, 3, 2
2, 1, 3
3, 2, 1

Come up with a form of an answer which can be easily calculated.
#

not sure how hard it is but here's one to do

sullen nova
#

wdym ii & pp?

night geyser
#

probably copy paste error

#

should say i and p

ionic jewel
#

yeah math formatting where i got it from was wack

#

fixed

night geyser
#

permutation problem: show

[
R(r, s) \leq \binom{r+s-2}{r-1}
]

and hence

[
(1 + o(1))\frac{s}{\sqrt{2}e}2^{s/2} \leq R(s, s) \leq (1+o(1))\frac{4^{s-1}}{\sqrt{\pi s}}
]

where $R(r, s)$ is the smallest size $n$ such that any gaph of size $n$ has a clique (complete subgraph) of size $r$ or its complement has a complete subgraph of size $s$

ocean sealBOT
#

Namington

night geyser
#

good luck

sullen nova
#

what the hell is that?

obsidian wagon
violet tundra
#

A doozy

night geyser
#

and how do you know that?

obsidian wagon
#

im in the small maths server modding that

#

had to ban him there

fading citrus
#

Could you show us?

obsidian wagon
#

he had a screenshot and then deleted it

obsidian wagon
#

can i DM?

fading citrus
#

Awesome

#

Yeah for sure

night geyser
#

its technically a permutation problem

tame falcon
#

@night geyser Message history of that user seems to agree

night geyser
#

for a flexible enough understanding of what that means

tame falcon
#

A test like thing was posted by the user in #chill , which included this problem

night geyser
#

okay yeah im convinced

#

gone

fading citrus
#

Yeah got info in dms too

serene lily
worldly pagoda
#

Hello everyone! I need to pick up the coefficients for the model so that it maximally describe the experimental data. I wanted to solve this with the help of optimization methods, but I can not choose the target function to my nonlinear dependence. I tried to use R ^ 2 but it does not work correctly for my data - the result of the calculation does not match all this data although r2 = 0.94

sullen nova
# ionic jewel ``` Consider all permutations of the numbers 1 to n. A good permutation is one w...

No need some fancy math formula ```py
from math import perm, comb
import itertools

def filterperm(obj_to_perm : str, filter_func):
#obj_to_perm: takes iterable preferably string
#filter_func: takes a filtering function to filter the permutations
#for the amount of occurances
print("Number of Permutations: " + str(perm(len(obj_to_perm))))
occurances = 0
for case in itertools.permutations(obj_to_perm):
occurances += 1 if filter_func(case) else 0
#k = print(case) if filter_func(case) else 0
return occurances

def filter_func(x):
for i in range(len(x)):
try:
if x[i] + 1 == x[x[i]]:
return False
except IndexError:
continue
return True

print(filterperm(
[x for x in range(1, 5)],
filter_func

))
shy prairie
#

i feel this should b such an easy problem but im very confused now

ionic jewel
#

i suppose you could argue thats a form of the answer that "could be easily calculated"

shy prairie
#

think it should b 3/4

#

but my friend said u were supposed to multiply the values instead

ionic jewel
#

E or F means either E or F

sullen nova
#

you can brute force

ionic jewel
#

not E then F

#

its 3/4

#

your friend would be right if it was the other situation

shy prairie
#

gg somehow 3/4 isnt the right answer

#

website bugged

ionic jewel
#

oh

#

👀

sullen nova
#

lmao my code can support up to n = 10

ionic jewel
#

independent doesnt mean disjoint

#

i assumed the wrong thing for some reason

shy prairie
#

very unfortunate

#

appreciate the help tho

ionic jewel
#

P(A or B) = P(A) + P(B) - P(A and B)

#

since they are independent, P(A and B) = P(A) times P(B)

#

so P(A or B) = P(A) + P(B) - P(A) * P(B)

#

1/2 + 1/4 - 1/2*1/4 = 3/4-1/8 = 5/8

#

@shy prairie

shy prairie
#

oh alright thanks

#

is that for like mutually exclusive tho

#

or something

ionic jewel
#

no

shy prairie
#

idk have my rules confused

ionic jewel
#

thats for independent

#

if P(A and B) = 0 (no overlap), then P(A or B) = P(A) + P(B)

#

which is what you had before

#

but its independent, not disjoint/exclusive

shy prairie
#

oh i see

#

terminology confusing lol

sullen nova
#

lol m8

hollow canyon
#

Does anyone know what my equations would be for these systems?

wraith cairn
#

d+m+b=130, (do the money equation yourself), 3d=b

hollow canyon
#

So the money equation would be 150=1.b+1.5m+1d correct?

#

1.2b*

umbral blaze
#

Can anyone please tell me the general formula for the series->(1/2),(1/10),(1/30),..... ?

#

Needed Badly

tranquil hound
#

Two consecutive odd numbers are such that 7/9 of the reciprocal of one is equal to the reciprocal of the other. Find the two odd numbers.

#

Anyone need help for this

sullen nova
#

hey

#

<@&286206848099549185>

#

how to convert my gpa?

pulsar canopy
ruby tree
sullen nova
#

yeah howt?

ruby tree
#

No, that’s not what I meant. What are you asking?

#

Convert your GPA could mean a lot of different things

vale wigeon
#

"tell me the answer to the problem i'm telepathically transmitting to you, or i will get angry if you try to tell me you're not a telepath"

ruby tree
tame falcon
#

Also, it is good practice to add more context, and show what you've tried when asking problems.

sullen nova
#

so

#

percentage to gpa

#

how do?

boreal matrix
sullen nova
#

Ok

#

I am A

boreal matrix
#

can someone help me with this thing please? I'm trying to find the math to have a nice curve between 2 points like so

sullen nova
#

my gpa is A, baby

#

I'm go to Harvards

wary stream
sullen nova
#

what?

#

no way

strong furnace
#

this guy has been trolling since yesterday

storm turret
#

Colleges don’t only care about gpa

sullen nova
#

then what?

boreal matrix
#

basically I need to find the correct tangents

#

Not sure how though

#

I can make it so it's a perfect circle and then hack the ends but it doesn't look very nice

tame falcon
sullen nova
#

yeah but I initially asked for a formula to convert percentage to gpa

#

So I dropped a little reason why I asked the question at the last bit

#

Just a small story behind the question

tame falcon
#

That's altogether better suited to one of the discussion channels.

wary stream
tame falcon
#

Either works, really.

boreal matrix
#

even if someone could point me out to a formula i'd appreciate that, nothing I find seems helping

tame falcon
#

@boreal matrix Sorry for the digression. You can repost here.

boreal matrix
#

or maybe it's not possible?

#

np

#

I'm trying to find the math to have a nice curve between 2 points like so

sullen nova
#

What function is this?

wary stream
#

Also, what's the full question? Like what exactly are you looking for?

boreal matrix
graceful pier
#

ok so

#

I do home school right

#

and this is the problem in math that I got

tame falcon
#

@graceful pier Channel occupied

graceful pier
wary stream
boreal matrix
#

you mean these @wary stream ?

wary stream
boreal matrix
#

P=(X|Y)

#

x,y? i'm really bad at this

tame falcon
#

@boreal matrix I'm not exactly understanding what your question is. Do you want parabolic curves between two points on a plane?

boreal matrix
#

yeah I think so @tame falcon

#

but

sullen nova
#

just use quadratic equation

wary stream
boreal matrix
#

I don't really like how it looks though, I was wandering if there was a way to keep the parable more thight at the top like the drawing

tame falcon
#

Okay, so if you have a regular Cartesian plane, and you want the endpoints to lie on the same horizontal line(for convenience, let it be x-axis, and coordinates of endpoints be (a,0) and (b,0)), then you can get parabolas passing through them by the equation y=-m(x-a)(x-b), where m>0.

tame falcon
boreal matrix
#

yeah something like that

wary stream
sullen nova
#

(x-h)^2 = 4p(y-k) This is parabolic equation

tame falcon
#

You can search up more about equation of an ellipse, and toy around till you get what you're looking for. Can you provide the context in which this problem came up?

boreal matrix
#

I'm creating a spline for my videogame between tho characters

#

I can make it look alright with some hacking but I was wandering if there was something more precise

sullen nova
#

(x-h)^2/a^2 + (y-k)^2/b^2 = 1 where a>b This is an elipsetic equation

tame falcon
boreal matrix
#

yeah it's mainly vector math

#

xyz

tame falcon
#

Alright, so I suppose you want an equation describing some sort of a nice trajectory between two points?

boreal matrix
#

yeah

tame falcon
#

Like throwing a ball?

boreal matrix
#

yeah 🙂

tame falcon
#

Then you can use physics right away haha

ionic jewel
#

are you using one of those systems that has y as the vertical axis

#

with the xz plane being flat/ground

boreal matrix
#

z is verical in my case

ionic jewel
#

ah good

boreal matrix
#

go on @cyan willow I think I'm not clear enough on what I need anyway

wary stream
#

You already posted in #help-1, just wait

boreal matrix
#

thanks all for the help!

wary stream
#

Also, this channel was busy

tame falcon
#

(Also gives a lot of mathematical apparatus, although you'll have to modify it according to you needs)

tame falcon
#

No worries; goodluck!

boreal matrix
#

cheers

sudden tulip
#

i really need help with this question

sullen nova
#

That's basic eom

sudden tulip
#

im learning this on my own

wary stream
tawny lion
wary stream
sullen nova
final crest
#

I solved the first question,
How do I solve the first part of the second question?

sudden tulip
#

i know what degree is

sullen nova
final crest
# sullen nova yoo

Oh thanks I guess it's on my profile so that's why.
Can you help though

wary stream
sullen nova
#

it's Maria

wary stream
sullen nova
#

@sudden tulip What degree is it?

sudden tulip
#

3 ?

sullen nova
#

lmao