help-0

[opal tinsel]

anyone?

[glacial hedge]

same

[woven pollen]

Are you in calc based Econonomics?

[glacial hedge]

[woven pollen]

Profit = R(x) - C(x). Marginal cost is C'(x). Marginal revenue is R'(x).

[opal tinsel]

no

[woven pollen]

huh.

ok. then just find the slope of both C(x) and R(x) at x=15.

maybe.

[rocky dock]

hi

how did the above happen ^

i dont understand how the 7/x flipped into a term with a negative power

[gleaming granite]

negative exponents are reciprocals

[wary stream]

1/x can be written as x^(-1)

[glass lichen]

$a^{-n}=\frac{1}{a^n}$

[ocean seal]

Mosh

[wary stream]

Oh, bot works again

[rocky dock]

oh ok

are there any other things like this i should keep in mind

so i now know to keep an eye out for things like the above when determining if something is a polynomial function or not

[lethal stump]

square roots

surd

*surds

any function with fractional indices isn't a polynomial

i.e. f(x) = sqrt(x) or x^(1/2)

[opal tinsel]

thanks

[rocky dock]

@lethal stump

[wary stream]

Yes

[rocky dock]

things like that, if included, arent polynomial functions?

ok

[glass lichen]

polynomial is of the form $p(x)=\sum_{i=0}^n a_ix^i$

[ocean seal]

Mosh

[rocky dock]

thanks guys

i understand

[lethal stump]

nws

oh um just to clear out any misunderstanding sqrt(x) and x^(1/2) are the same thing

[feral apex]

Find remaider when 3^123 is divided by 7

Any idea what is this method called ?

<@&286206848099549185>

[thorny canyon]

you multiply everything by seven in the first equation

6/7 * 7 = 6

since 1- 1/7 = 6/7

anything that is melded into a bracket like 5(5) counts as 5x5

or 5(1-3/5) = 5 - 3 = 2

idk what ur trying to do with the 2nd image @feral apex

3^3 = 27 means that 27 = 27 which is an objective fact, you divided both by 7 in two sides, so equation is like a balanced scale, meaning that both of them has to be equal to each other

thats why that equation is made

as for tthe very first and very third it's just simple division with remainders

nothing special

[wraith cairn]

find how many ways they can sit next to each other and subtract that from all the possible combinations

[surreal spindle]

9!-(4!)(6!)?

[surreal spindle]

^?

[alpine sable]

what a coincidence i have doubt on same kinda question can you help?

[wraith cairn]

yep.

that should be right

[alpine sable]

help me on this

even it is solved down but i cant understand it

<@&286206848099549185>

[covert berry]

uhh so

you're gonna multiply those two

[gleaming granite]

https://tenor.com/view/big-brain-pewdiepie-big-brain-pewdiepie-pewdiepie-brain-brain-gif-16837310

[opal tinsel]

hi

[covert berry]

hi

[opal tinsel]

anyone is willing to explain the part highlighted please

[glacial hedge]

@opal tinsel r u taking regular calc or economics calc?

[opal tinsel]

regular calc

[glacial hedge]

Bruh Moment

@opal tinsel has your class defined the meaning of marginal

[opal tinsel]

no but the formula is the derivative of r(x) for marginal revenue

and derivative of c(x) for marginal cost

[glacial hedge]

so calculate the integral of both?

[opal tinsel]

i just dont understand what they mean by 15 products

[alpine sable]

yes

[covert berry]

i literally meant it, can you elaborate on your problem

[alpine sable]

i want help on multiplication of root3 and cuberoot2

[opal tinsel]

@glacial hedge i got the derviative but what do they mean with the 15 products

[glacial hedge]

@opal tinsel it means plug in 15 for x

[covert berry]

convert them to root6 and multiply them, it's what they did

because you can't comfortably multiply numbers with different power

[alpine sable]

im getting so confuse on that method

[covert berry]

i'm not sure but maybe introducing to you that root2 is actually power of 1/2

and so on

it may be less confusing for you

[alpine sable]

i mean they took lcm of them and after that it is hard

[covert berry]

they took lcm of the roots

like lcm(2,3) = 6

so they want root6

[wraith cairn]

$n^{\frac{1}{2}} = n^{\frac{3}{6}}$

[ocean seal]

Xiangli

[covert berry]

[alpine sable]

yes but im confuse on how they put power 3 on 6root3 and how 3root2 convert into 4?

[fading rover]

Fr

[alpine sable]

yes

im dumb sorry

[wraith cairn]

$\sqrt{n} = n^{\frac{1}{2}} = n^{\frac{3}{6}} = \sqrt[6]{n^3}$

[ocean seal]

Xiangli

[covert berry]

$\sqrt{3} = 3^{\frac{1}{2}} = 3^{\frac{3}{6}} = \sqrt[6]{3^3} \newline
\sqrt[3]{2} = 2^{\frac{1}{3}} = 2^{\frac{2}{6}} = \sqrt[6]{2^2}$

[wraith cairn]

$\sqrt[3]{k} = k^{\frac{1}{3}} = k^{\frac{2}{6}} = \sqrt[6]{k^2}$

[ocean seal]

Xiangli

[covert berry]

thonk

[alpine sable]

omg so many examples thankyou guys

[glacial hedge]

lag

internet

[ocean seal]

rudy

[wraith cairn]

in $n^{\frac{k}{t}}$ the t is the "root" and the k is the power. You can write it as $\sqrt[t]{n^k}$ or $\sqrt[t]{n}^k$

[ocean seal]

Xiangli

[wraith cairn]

yo latex is so fun.

[alpine sable]

i see thankyou guys

[wraith cairn]

noproblem

[alpine sable]

im so dumbo but its good now

[wary stream]

If you use double $ around the stuff, so $$, it makes that latex a new line so the stuff is slightly bigger

[glacial hedge]

just curious how did u learn to type latex?

$test$
$$wait wut$$

[ocean seal]

Elonmosqito96

[glacial hedge]

what happened....

[wary stream]

I learned it here, and a lot of Googled for the functions

[glacial hedge]

smort

[wary stream]

in $$n^{\frac{k}{t}}$$ the t is the "root" and the k is the power. You can write it as $$\sqrt[t]{n^k}$$ or $$\sqrt[t]{n}^k$$

[ocean seal]

dldh06

[wary stream]

That's what I meant

Copied from xiangli

[glacial hedge]

not as nice tho

in my opinion spaces are too big

[livid lintel]

does anyone know this?

[wary stream]

Slope formula and point slope formula

[livid lintel]

what should i do exactly?

[wary stream]

Find the slope then use point slope

[livid lintel]

does m=3?

[wary stream]

Yes

[livid lintel]

how do i find b

[wary stream]

You can either use point slope or plug in a coordinate into that given equation

[livid lintel]

is b -6?

so m=3 and b=-5

[wary stream]

You should have just stopped here instead of giving the final solution

I meant stopped at this step

They should have found b themselves from there

[livid lintel]

yeah

[wary stream]

I'm "exercising" the rules of the server

[minor dagger]

can someone help me with the one i got wrong

y intercept?

so where its at y?

[wary stream]

You should, because not following rules would get you banned

[minor dagger]

-1,1,-1/3,1/3

yes

what

[red jetty]

sorry

[wary stream]

Says the one giving solutions, and just not listening to what I was saying

[minor dagger]

theyre helping

yes...

would i plug in 0 into the equation?

[wary stream]

All you do, look at your answers in A, and the graph, and write down the solution that overlaps in both the graph and A

[minor dagger]

1 and 1/3?

[wary stream]

There's still one more

[minor dagger]

1 and -2

[wary stream]

They know what a factor is

[minor dagger]

ooh

yh

yes

[wary stream]

Where did -2 come from?

[minor dagger]

x+2

okay

thank you

[wary stream]

You're talking about the example that was given, not the question itself

[minor dagger]

how did you get this tho

ooh

[opal tinsel]

hello what is the derivative of 1000 + 300x i keep getting 300

[wary stream]

That's right

What was the answer you were expecting?

[opal tinsel]

bruh my teacher says my marginal cost is wrong

isnt the marginal cost 4500?

[minor dagger]

@alpine sable what about this...

<@&286206848099549185>

[wary stream]

Do the same process that you did for the last one

[opal tinsel]

@wary stream hi

[covert berry]

@opal tinsel hi

[wary stream]

I don't know anything about marginal costs

[opal tinsel]

😭

anyone?

know about marginal cost

[covert berry]

hi

[opal tinsel]

hi do you?

[covert berry]

i'm fine thanks

[opal tinsel]

pain

[covert berry]

how about you

[opal tinsel]

im good

[covert berry]

i'm glad to hear that

[opal tinsel]

you know anything bout marginal costs

[covert berry]

no

are you like in economics or something

[opal tinsel]

no calc

[covert berry]

hmmm ehh /shrug

helplessness

maths sucks

i'm bad at maths too

worry not

just squash squash

play games

entertain yourself

studying is for the weak

[north spruce]

does anyone remember how to do this

sobs

[gray isle]

apply the definition of roots

[mossy basin]

Does anyone know hwo to calculate to find how many times the inner loop will run?

[wary stream]

Isn't it n times?

[north spruce]

wdym

[mossy basin]

im not sure im confused since ive not seen this ← before and cant find the defionition

[covert berry]

it's just how people write algorithms

it means assigning

[gray isle]

do you know what roots of a polynomial function are?

[north spruce]

no

[covert berry]

i think it's n1 * n2 times btw

[north spruce]

i was talking about geo

i dont remember this

[mossy basin]

oh so it assigns 1 to i and will do it n times?

[covert berry]

uhh wait

the inner loop is also i

UHHHH

tf

it depends then

n1 and n2

[mossy basin]

Im not given an n1 or an n2

[covert berry]

if n2 > n1 then the inner loop runs n2 times

if n2 = n1 then 2*n2 times

if n2 < n1 then uhhh, really depends

my brain can't process this shit

[wary stream]

That's pseudo code notation

[covert berry]

oh, if n2 < n1, then the inner loop runs n1*n2 times

[mossy basin]

could I write a program just to check quick like in java and do something similar like:

for(int i = 1; i = n1; i++){
  for(int i = 1; i = n2; i++){
      println(inner)
      }
  println(outer)
}

[covert berry]

you shouldn't be able to do that

you declared i twice

remove "int" from the second loop

also i think the condition is uhm

<=

I think that's what you meant

for (int i = 1; i <= n1; i++)
{
  for (i = 1; i <= n2; i++)
  {
    println(inner)
  }
  println(outer)
}```

meow meow bambam bow

[wary stream]

What programming language did you learn first?

[covert berry]

backlabackla bam bam moo

C#

[wary stream]

That explains the C style brackets

[covert berry]

0-0

[wary stream]

If you look closely, @mossy basin did Java style brackets, so that most likely means (s)he learned Java first. Am I right?

[mossy basin]

Technically i learned python first but it was only for a semester. but java is the first language that i took for about 1.5 years so far thats been a constant

[covert berry]

but tbh

[mossy basin]

so its my go to lang

[covert berry]

my first language is not C#

it's Pascal

[wary stream]

Python has no need for brackets, I believe

[covert berry]

i have a hard time reading people's python3 codes on codingame

like

reee

they combine a ton of shits in a line

the round wasn't even about shortest

[wary stream]

Just write a one line C# code

[covert berry]

pspspsp

i'm still a basics boy

@mossy basin hi

[mossy basin]

hello

[covert berry]

what are you studying

[mossy basin]

did a 2 year diploma in comp programming but never touched an algorithm course in it. Decided to go to university and enter into 3rd year CS but to do so I have to take a few summer courses like algorithms which ive never done

[covert berry]

what i was wondering too tbh

i wonder why like 1.5 years of java and studying loops

i was just confused lol

[mossy basin]

Yeah lol seeing it like the way i posted it confuses me instead of seeing it in a way of programming syntax

[covert berry]

bambam baba blahblah kunkun popopopo lamlamlam

[wary stream]

That's just pseudo code

[covert berry]

aka illustration of how an algorithm works

bambam beebee pupu kakaka

[wary stream]

Sorta, it's pretty much the code written on paper, just ignoring the extra stuff, like the body of the loop, method signature, etc

[covert berry]

yaya kaka lalala

[sudden tulip]

i

i dont undertsand the answer provided

ans is (8-x)m

but i dont understand

[covert berry]

uhmm

so

the whole thing is 8

one thing is x

so the other is 8 - x

tadaaa balalalala kamkam chuchu

yapyappie kuku malasate

[sudden tulip]

Oh ok

Why speaking melayu

[covert berry]

melayu?

wats dat

[languid python]

If anyone doesn't know this answer i think this Discord Server is for no reason

Hello?

[sudden tulip]

tick butterfly and dragonfly

?

so basically becuse both sides must be symetrical

fish cannnot be symmetrical because there are no scales ont he bottome side

[languid python]

Ok thanks

[low lion]

<@&286206848099549185>

[ionic jewel]

push in the exponent using exponent rules, then divide using exponent rules

[low lion]

sorry if im picky but can you show me a screenshot or work on it

[ionic jewel]

no but I'll give you the two rules you need

${(a^b)}^c = a^{bc}$

[ocean seal]

bunny

[ionic jewel]

actually that's the only one

in this case

you apply it twice

[languid python]

<@&286206848099549185> what ue the answer for this

[ionic jewel]

Elizabeth please #❓how-to-get-help

and you can just follow the arrows

you know directions?

north south east west?

[low lion]

<@&286206848099549185> can you help me with both of these

[wary stream]

What grade is this stuff?

[placid zinc]

Did you have any feedback for bunny?

[languid python]

7

[wary stream]

Exponent rules

[alpine sable]

damn ur 12 and on discord

thats a no no

[low lion]

idk that

[wary stream]

<@&268886789983436800> Maybe against TOS?

With the grade

[ionic jewel]

bad ping

[wary stream]

I said maybe

[ionic jewel]

if they don't say they are under 13 you don't ban thsm

not worth pinging the mods

[wary stream]

They should double check because no way line of symmetry is 7th grade math

[ionic jewel]

also PT ignored my help :(

oh he found a new channel

[low lion]

no way i'll ignore someone helping me out

I respect you 😄

[ionic jewel]

both of your posted problems you can slap the rule i sent onto

then with the negative exponent rule someone else gave it all comes together

also (ab)^n = a^n * b^n

[low lion]

i just need 2 questions

just 2

if you could help me out here with a drawing

[wary stream]

Apply the exponent rule that bunny showed you

[wary stream]

.

[low lion]

i dont know what you mean

sorry but idk what to do

[wary stream]

Look at the info bunny said

[low lion]

?

[wary stream]

Please use parentheses

[tame falcon]

As long as they don't admit to being underage explicitly, we can't really pry.

[wary stream]

Understood, sorry for that ping

[alpine sable]

Grade 7s are usually 12 year olds

11-12

[tawdry cedar]

how do i prove that CKH is the same kind as BCA?

sorry for the bad shot cause i don't have it online

[alpine sable]

Got a physical document of it?

,rccw

[tawdry cedar]

it's in Vietnamese...

[alpine sable]

hm

I mean we don't really need the text

just the diagram

then you could translate any important text

[tawdry cedar]

sorry prove that CKH is similar to BCA

[alpine sable]

ok in the mean time could you like get the actual paper

[tawdry cedar]

so ABCD is a parellelogram

[alpine sable]

cause I kinda want to look at it there might be more stuff

maybe not

anyways

[tawdry cedar]

uh wdym the actual paper lol

[alpine sable]

the question

on the document

nvm

[tawdry cedar]

do you understand Vietnamese lol

[alpine sable]

nope

but i could make out

what its saying

[ionic jewel]

he's gonna speed learn vietnamese on the go

[tawdry cedar]

oh boi

[alpine sable]

yup

I speed run everything

[ionic jewel]

vietnamese looks super hard, i was interested in learning it at some point

[tawdry cedar]

oh bruh

why would you even learn it

[alpine sable]

Thought of learning Khmer

[ionic jewel]

to talk to vietnamese people obviously

[tawdry cedar]

here 😂

[ionic jewel]

ended up choosing mandarin tho

[tawdry cedar]

on discord?

or IRL

[ionic jewel]

sure both

but it's too late now

i don't know any vietnamese besides like happy birthday

[alpine sable]

lol

[tawdry cedar]

idk if you really wanna talk to vietnamese people

[alpine sable]

why 👀

[tawdry cedar]

they're like idiotic grown-up children...

[ionic jewel]

[tawdry cedar]

and toxic sometimes

[alpine sable]

[ionic jewel]

i have a vietnamese friend that's cool

[tawdry cedar]

you don't really see a Vietnamese going around that is polite lol

yeah

that's the 0.01%

[ionic jewel]

so that's false from my sample size of one

[tawdry cedar]

[ionic jewel]

anyway this is a math server sorry to interrupt

[alpine sable]

right trapezoid

So you got a right trapezoid

fuck

what am I pasting

ok can you translate this

[tawdry cedar]

ok so how the hell do i prove that CKH is similar to BCA lol

[tawdry cedar]

ok sure

ABCD is a parallelogram
AC > BD
draw CH perpendicular to AD at H
draw CK perpendicular to AB at K

basically what i drew

[alpine sable]

oh so thought you were provided a diagram

ok then

[tawdry cedar]

oh bruh

ok thanks

[tawdry cedar]

also does that make any sense?

[alpine sable]

dude whys your image 13.39 mb

reuploading your drawing

[alpine sable]

yeah

[tawdry cedar]

ok nice

[tawdry cedar]

bad phone

😅

[alpine sable]

ok so you should notice you have 2 right angled triangles

[tawdry cedar]

yeah

i know

[alpine sable]

ok wait firstly

have you tried anything

[tawdry cedar]

uh

yes

idk tho

[alpine sable]

wdym you dunno

[tawdry cedar]

it's grade 9 level

just say your solution

and i'll see if it fits my education level

[alpine sable]

ok sorry im in class and this is gonna take me some time considering i'm Lateχing some stuff and drawing images to help assist the problem and for visualisation of what i'm about to write

i'm working on your problem though

[tawdry cedar]

oh thanks

you could totally save it for later tho

[alpine sable]

ok wait just a question

[tawdry cedar]

ok

[alpine sable]

are we supposed to prove it only with the stuff provided

[tawdry cedar]

you can ask anything lol

[alpine sable]

or could we draw external stuff and use other things

like could I draw a circle around it

and use circle theorems

[tawdry cedar]

no

soryr

[alpine sable]

just that?

[tawdry cedar]

with only the stuff it gave

yeah

[alpine sable]

hm alright

[tawdry cedar]

have you noticed that DCK is a right angle?

idk how that might help

but just so you know

[alpine sable]

,rotate

[hardy vault]

can somone help

[placid zinc]

@noble stone
Thoughts on the question? Are you good with matrix multiplication/addition?

@hardy vault
The trick is to think in terms of sidewalks per hour. So Alphonse can shovel 0.5 sidewalks in an hour, ect.

Ah I see xxxx has been helped. This is why we don't multipost

[high wolf]

is this a substitution problem?

[placid zinc]

What makes something a substitution problem? Haha

[high wolf]

i dunno i'm clueless lmao

[placid zinc]

No need for complicated moves here.
∫ x²y dy = 1/2 x²y²

So do that, apply the bounds, then do the outer integral

[high wolf]

uhm i have no idea how you turned that into 1/2 x^2y^2

[placid zinc]

Can you carry out ∫ y dy?

x² is really just a constant, since it has nothing to do with y

[high wolf]

yea i just solved the thing, just wondering how your method worked

[placid zinc]

So you can?

[high wolf]

yea x^2 \int y dy

[placid zinc]

Happy you were able to solve it

[high wolf]

what is this though? i'm puzzled ∫ x²y dy = 1/2 x²y²

like how

[tough hatch]

what do u do when there's a constant in the integrand?

i.e. x^2 is that constant

x^2 is constant in ∫ x^2y dy since it's in terms of x, not y

[ornate quest]

Hello guys, could someone give me example of function that start exponential and finish logaritmique (see picture)

[tough hatch]

arctan x

[tough hatch]

function that start exponential and finish logaritmique

bad way to describe it

function that looks like this would've sufficed

[jagged imp]

soln of the logisitic differential equation also kinda looks like that

[vapid ermine]

sorry i was busy. My lessons star at 07:00 (Am) and end at 08:00(pm) i am so tired. so i cant use Discord a lot. sorry again

[ivory otter]

hey so i need help with understanding this
tan^2 A + 1 = 1/sin^2 A

[hidden storm]

adding brackets might be helpful

[ivory otter]

question doesnt give any brackets

confuses me too

tbh

[hidden storm]

it would make more sense to assume it's $\tan^2(A)+1 = \frac{1}{\sin^2(A)}$ i think

[ocean seal]

yoavmal

[ivory otter]

im assuming its tan^2(A) + 1

yes

[hidden storm]

so do you have an idea on how to start?

[ivory otter]

well kind of, basically

im thinking about changing the 1 into cos^2 + sin^2

[hidden storm]

that seems like a promising approach, lets try it

[ivory otter]

im not sure if i can change the tan^2(A) into sin^2(A)/cos^2(A)

ok lemme do that then

$\tan^2(A) + sin^2(A) + cos^2(A) = frac{1}{sin^2(A)}$

[hidden storm]

$\tan^2(A)+\sin^2(A)+\cos^2(A)=\frac{1}{\sin^2(A)}$

[ocean seal]

yoavmal

[hidden storm]

this seems to complicate things a bit

[ornate quest]

Thank you that's exactly what I needed

[ivory otter]

it does?

[hidden storm]

well it adds a bunch of terms that do not cancel out, and we later need to multiply by sin^2(A)

[ivory otter]

yes true

[hidden storm]

what about the other 1 though?

[ivory otter]

do i do it for the right hand side instead?

ok

we could cancel out the sin^2(A)

making it cos^2(A)

right?

[hidden storm]

where?

[ivory otter]

right hand side

[hidden storm]

$\tan^2(A)+1=\frac{1}{\sin^2(A)}$

[ocean seal]

yoavmal

[ivory otter]

if we substitute the 1 with pythogoras identity

[hidden storm]

oh ok

$\tan^2(A)+1=\frac{\sin^2(A)+\cos^2(A)}{\sin^2(A)}$

[ocean seal]

yoavmal

[ivory otter]

ye

would that be good idea?

[hidden storm]

seems to be pretty good

[hidden storm]

so if we do that

[ivory otter]

ye?

[hidden storm]

$\tan^2(A)+1=\frac{\sin^2(A)}{\sin^2(A)}+\frac{\cos^2(A)}{\sin^2(A)}$

[ocean seal]

yoavmal

[hidden storm]

$\tan^2(A)+1=1+\frac{\cos^2(A)}{\sin^2(A)}$

[ocean seal]

yoavmal

[ivory otter]

which is the same as the left hand side right?

[hidden storm]

that would mean any A, and solve our question

but we need to make sure it's true

so lets first simplify a bit to see a clear formula

[ivory otter]

isnt cos^2 A / sin^2 A = tan^2 A?

[ivory otter]

ok

[hidden storm]

so what do we do from here?

[ivory otter]

hmm

we can substitute the tan^2(A)

with

idk if i can tbh

[hidden storm]

how about we first subtract 1 from both sides?

[ivory otter]

oh

ok

[hidden storm]

$\tan^2(A)=\frac{\cos^2(A)}{\sin^2(A)}$

[ocean seal]

yoavmal

[ivory otter]

ye

[hidden storm]

so are these two equal like you said earlier?

[ivory otter]

identity 2

says its sin/cos

so they arent right?

[hidden storm]

seems not

[oak chasm]

They are right.

[ocean seal]

Chai T. Rex

[ivory otter]

ye

i meant

the part where we are at

not the identity

lol

[hidden storm]

they're not equal

[distant plume]

help launge is turkish

[hidden storm]

we're currently using this channel, could you use an unoccupied one?

[hidden storm]

the identity is useful here, though

[distant plume]

what

[hidden storm]

oh @ivory otter sorry, i've got to go

[hidden storm]

#rules

[ivory otter]

Oh ok, thank you tho

[tough hatch]

are u actually trying to prove that
$$\tan ^2(A)+1 = \frac{1}{\sin ^2(A)}?$$

[ocean seal]

!superficialsicko

[ivory otter]

Prove?

Idk its just says ”show”

That they are equal

I guess prove ye

[tough hatch]

yeah, that's what i mean

they are not.

[oak chasm]

That's not an identity.

You can solve it for what A is.

But you can't prove that it's true for all A.

[ivory otter]

What do they want then?

[tough hatch]

u don't need the fancier identities for this

[oak chasm]

What do they say exactly?

[ivory otter]

It says this:

[tough hatch]

just the basic ones

[ivory otter]

”Show that tan^2A + 1 = 1/sin^2(A)”

[ivory otter]

Aha ok

[tough hatch]

then it's impossible

[oak chasm]

I'd answer it by showing that it only works for some A.

[tough hatch]

u could also ask if they did a typo there

[oak chasm]

Ahh, even better.

[ivory otter]

Lemme screenshot

[tough hatch]

that, or the one who formulated this problem was not in their ideal mind

[tough hatch]

aha

[oak chasm]

Oh, maybe.

[tough hatch]

that is now correct

[ivory otter]

Aha did i do something wrong when typing it?

[oak chasm]

Yeah, you had sine on the bottom.

[ivory otter]

Aaaaah

[tough hatch]

maybe u interchanged sin with cos

[ivory otter]

I did yes

You are right

So now i can make the 1 on the right aide

[tough hatch]

u need only use the basic identities

i.e. pythagorean

[ivory otter]

Cos^2 + sin^2

Ye

Then cancel out

But does this

[oak chasm]

I'd subtract 1 from both sides.

[ivory otter]

Do i have to?

Seems like its unecessary

Does this sin^2/cos^2 = tan^2?

[oak chasm]

Well, it's not the only way to get the answer, but it's one way to get closer.

Yes, that's right.

[tough hatch]

there is another pythagorean identity that could help you do it faster

there are three pythagorean identities

[ivory otter]

Wait why dont i just cancel out the right hand side

That would leave me with sin/cos + 1

Or no

It wouldnt

It would

[tough hatch]

you could also mulltiply both sides by a certain expression

that would be easier for you, i suppose

[tough hatch]

look closely at the right side of the equation

[ivory otter]

Ok

But lemme try to solve this one and you tell me what you think

Gonna do the cancel out part

[tough hatch]

go ahead

[ivory otter]

is this right?

[stiff mural]

This is a very silly question that I want to ask, but I will very much appreciate your help without condescending or mockery.

-3 + 7 = 4 ?Why!

I thought this 👆🏾 equates to 1 😕

[alpine sable]

what

how'd you think that equals 1

[stiff mural]

xD 😂

[alpine sable]

no but seriously

[tough hatch]

u would have to assume that cos A is nonzero

[alpine sable]

Also don't interrupt active channels

thanks

[stiff mural]

PLEASE can you show me a practical way of solving this

[ivory otter]

they both have the same value tho

[tough hatch]

yes there is still an active discussion here

[alpine sable]

I uh dunno how to "show" how to do it

as theres really no way we could

except draw a number line

[tough hatch]

u may ask in channels with questions that have not been answered for hours

[alpine sable]

ig thats the best I could offer

[tough hatch]

both what?

[ivory otter]

A

does that mean my solution is not correct?

[ocean seal]

!superficialsicko

[ivory otter]

aha yeee

[tough hatch]

if A is pi/2 for example

then cos (pi/2)=0

[ivory otter]

interesting never thought about it

so do i need to say like

[tough hatch]

u can't have that

[ivory otter]

as long as cos or sin != 0

[tough hatch]

there are faster ways of showing that ur equation holds

[ivory otter]

ok how?

for all A ?

[tough hatch]

no

i mean

other than using ur method

[ocean seal]

!superficialsicko

[ivory otter]

sec^2?

we dont use those

[tough hatch]

oh well nvm

[ivory otter]

those are the identities that we need to learn

[tough hatch]

at the start cos A is never going to be 0

since the right side of ur equation is 1/(cos^2 x)

so what u did is fine

[ivory otter]

yes true

[ivory otter]

you came to this conclusion because we cant divide by 0 right?

[tough hatch]

you can't divide a nonzero number by zero

[ivory otter]

ye

[tough hatch]

otherwise the right side of equation would have been 1/0

[ivory otter]

yes

[tough hatch]

so its fine

[ivory otter]

ok

[tough hatch]

u can also observe that the least value of 1+tan^2 A is 1

[ivory otter]

yes, these are things i never pay attention to

until someone points it out

thank you for the help

[nova dune]

Hiiiiiiiiiiiiii

What's a strictly positive number?

I've this note in my textbook saying that eigenvector x has strictly positive coordinates

Doesn't positive mean the same?

Any positive number > 0

[hollow siren]

yes

same thing

[nova dune]

So why tf would they say strictly positive instead of positive?

[tough hatch]

ah i suppose they mean all positive

[hollow siren]

idk

[nova dune]

Thanks, guys

[hollow siren]

oh

[nova dune]

Also I like how the numbering in this discord server starts from 0

[hollow siren]

i get it

a positive number can be 0

a strictly positive cant

[nova dune]

everyone at my uni says that 0 is not a natural number which triggers me

[tough hatch]

perhaps that's their convention

[nova dune]

I thought positive numbers HAVE to be greater than 0

[tough hatch]

but it really is cringey and wrong

[nova dune]

^

[vale wigeon]

please do not use the word "trigger" in a (seemingly) joking manner like that

[hollow siren]

no a positive number can

be 0

[nova dune]

Okie 👍

[tough hatch]

some of us like to misassociate positivity with the inclusion of zero

[hollow siren]

0 is a natural number...

[tough hatch]

in some conventions, yeah

[nova dune]

In the maths department at my uni it isnt considered one

[hollow siren]

tf

weird

[nova dune]

Our theorems are slightly different from yours

[tough hatch]

same

[nova dune]

Yeah, New Zealand mafs is weird

[ocean seal]

!superficialsicko

[tough hatch]

some like to think of the natural numbers as counting numbers

perhaps that is why we don't consider 0 as positive

[vale wigeon]

'positive' in english means greater than 0, does it not?

[nova dune]

Yes

[tough hatch]

we have different conventions apparently

this is not the first time i have heard about this culture

so in my uni it's made strict that 0 is not positive

usually strictly is used when there is some sort of fuzziness in the definitions

[nova dune]

👍

[ivory otter]

it seems like after every new question

i hit a wall

crazy

anyways

$\frac{1 - cos2x + sin 2x}{1 + cos2x + sin2x}$

[ocean seal]

MEOWBRO 父

[ivory otter]

im supposed to simplify this to tan x

now in my head im thinking about many ways

first one is, substiuting the 1 with pytho identity

second is to substitute the cos2x with cos^2 A - sin^2 A identity

and the sin2x with 2 sinA cos A

so it would end up being

$\frac{sin^2 x + cos^2 x - sin^2 x - cos^2 x + 2 sin x * cos x}{sin^2 x + cos^2 x+ sin^2 x - cos^2+ 2 sin x * cos x}$

[ocean seal]

MEOWBRO 父

[ivory otter]

and in that case, the above part would just get cancelled since its +

0*

$\frac{ 2 sin x * cos x}{sin^2 x + cos^2 x+ sin^2 x - cos^2 x + 2 sin x * cos x}$

[ocean seal]

MEOWBRO 父

[ivory otter]

the below part would end up being

[tough hatch]

btw u can do \ before sin and cos

as in \sin and \cos

[gray isle]

your numerator is wrong

and so is your denominator

[real briar]

isnt it like this?

[ivory otter]

$\frac{ 2 \sin x * \cos x}{\sin^2 x + \sin^2 x + 2 `\sin x * \cos x}$

[ocean seal]

MEOWBRO 父

[real briar]

plus 1 down there that i forgot

[ivory otter]

why

[ivory otter]

ah this is your solution

to the question?

[gray isle]

your signs are messed up

[real briar]

ramonov

is my answer corect?

i forgot the plus 1

down there tho

[gray isle]

no

[tough hatch]

do \times for multiply

[real briar]

hmm

[ivory otter]

ok

[gray isle]

you all need to check your signs

[ivory otter]

im following this sheet

[gray isle]

use \cdot for multiplication

[tough hatch]

• has a ton of uses in higher maths

[tough hatch]

yes \cdot is actually better

[ivory otter]

look at the sheet

[ocean seal]

!superficialsicko

[tough hatch]

than

[ocean seal]

!superficialsicko

[tough hatch]

saves u the time distinguishing x from \times

[ivory otter]

aha ok

[real briar]

so whats wrong here?

[gray isle]

nothing yet

[real briar]

oh okay

[tough hatch]

u should also fix how u notate squares

[ocean seal]

!superficialsicko

[real briar]

yeah man i know

im focusing on solving not on writing it beautifully and when a solution is here, im occupied with that too

[ivory otter]

how is this wrong so far

the signs should be correct

im using a mouse, my handwriting is horrible

[tough hatch]

this channel is busy, u may ask in another #questions- channel

[tough hatch]

what exactly are u trying to do?

[ivory otter]

simplify it down to tan x

now i can just start cancelling out

[tough hatch]

mind ur sign

-cos(2x) = ?

[ivory otter]

ooooooooooooh

[tough hatch]

as in the numerator

[ivory otter]

its positive

or no

[tough hatch]

type it out

[ivory otter]

nvm i thought it was cos(-2x)

but wait before that, i cant cancel out?

[real briar]

anything wrong?

until now?

[gray isle]

last two steps are wrong

1 + 1 != 1

[tough hatch]

i am so confused now lol

[ivory otter]

i cant do this because of - cos(2x)

?

[gray isle]

apply distributive property properly

putting parentheses around (cos(2x)) may help

[tough hatch]

i cant tell if u both coincidentally have the same problem

[ivory otter]

lol

[gray isle]

they're both trying

[tough hatch]

or is the other one trying to help meow?

thats why im confused

[real briar]

im tryin to help kinda

[tough hatch]

ok

[real briar]

i got it

[ivory otter]

wait

1 - cos^2 x, cant that be written to sin^2x?

@real briar is that what you did ?

[real briar]

nope

[ivory otter]

wait

[real briar]

ignore the 4 line

[ivory otter]

i got confused i thougt it was ^2

[real briar]

its wrong as i forgot to add another cos

[ivory otter]

im just confused at this point

why did you write 1 - cos^2 x?

did you substitute the cos2x immediately?

shouldnt that be a - ?

https://cdn.discordapp.com/attachments/536995777981972491/855012312200511528/cd.png

[real briar]

nahh

i will write it

rewrite

to ve more intelligible

be*

or

we can go to a channel

[ivory otter]

wait pls someone explain how did he get it to 1 - cos^2x + sin^2 x ?

[real briar]

cause i got a tablet

[tough hatch]

cos(2x) = cos^2(x)-sin^2(x)

[real briar]

meow

do you want to get in a channel?

i will share screen

and shit

[ivory otter]

ok, but why did he add a +

[tough hatch]

since it's -cos(2x)

[ivory otter]

not now better in here :d

[real briar]

its easier when ill share the screen

and show you every step

but as you please

[ivory otter]

thank you

[real briar]

its in your interes i think

lets get into a channel and talk

it is more easy to present the steps and stuff

[ivory otter]

i dont have a mic anyways

[real briar]

i will explain

you can keep yourself on mute

and write

[ivory otter]

can we do that a bit later then?

if i can ping you?

[real briar]

a bit later means?

[ivory otter]

today

but later

[real briar]

im learning for an exam as well and this was my pause

so my time is kinda limited

unfortunaetly

[ivory otter]

well fk it then i cant now anyways

[real briar]

well

ill try to write it with my table

and send the picture

here

at least we can do

[ivory otter]

thank you very much

[paper temple]

Can anyone help me with a reverse chain rule question

for intergration

[alpine sable]

please post your question and don't ask to ask. and read #❓how-to-get-help rule 1.

[paper temple]

,rotate

[paper temple]

Question 5 using reverse chain rule

[paper temple]

channel taking

[real briar]

@ivory otter

ok robbie

what your question

[tough hatch]

actually they're not completely done

[paper temple]

question 5 how would i use reverse chain rule to solve this

[tough hatch]

but if u would like to take on another rask then it's all u

[real briar]

@vernal lakebro you must impose that cos(x) differs from 0 and see what intervals you get to be completely specific

[ivory otter]

ye true, you pinged the wrong guy xD

[ivory otter]

thank you for the walkthrough was good!

[real briar]

np

[tough hatch]

@paper temple do u still need help?

[native tartan]

can someone help me with this

[alpine sable]

,rccw

[alpine sable]

ok well know any log rules that apply here

[native tartan]

thats the problem

i dont know any log rule which can be applied here

[alpine sable]

A level

Just to clarify the 3 is not an exponent of log base 2 and 4 is not an exponent of log base 3?

[ocean seal]

Πολλά άτομα είναι

[alpine sable]

ok so

wait lemme just

hm

shit

oh wait

used natural logs before?

[native tartan]

hmmmm nope

[alpine sable]

Damn

ok well natural logs are just log base e

e being Euler's constant

[native tartan]

ok

[ocean seal]

Πολλά άτομα είναι

[native tartan]

Now I think I can do it

[rigid smelt]

why dont you just change the base 3 to 2

its more straight-foward

but yeah, same thing

[native tartan]

okay let me try this first

[candid mural]

help me olsss

[native tartan]

@alpine sable thnx mate got the answer

[undone dock]

What are you having trouble with

[candid mural]

the mode

mean

and median

[alpine sable]

I mean

[candid mural]

the tanlt

[alpine sable]

just search the definitions up

[undone dock]

Mean is the average

[candid mural]

table

no i dont know how to do it

[alpine sable]

This cumulative frequency type stuff?

[undone dock]

To find the mean, add up how many badges were given out in total and then divide by the sum of the frequencies

[light topaz]

Hello
I'm in need of calculating a "Look at" rotation/vector between 2 points in space. It is 2d vector operation
So far I have this in pyhton:

import math
# X = ------ x
# Y = |||||| Y
vecA = [100, 0] # look right 90 deg
vecB = [0, 100] # look up 90 deg
eye = [0,0] # centre of world - ignoring for now lets assume were at 0 anyway

dot = vecA[0] * vecB[0] + vecA[1] * vecB[1]
det = vecA[0] * vecB[0] - vecA[1] * vecB[1]

print(math.atan2(det, dot)) ## should give me 90 deg? if its in deg...

This should give me... some value, but all I got is 0 :- (

[trail tusk]

Definitely cheating😂

MEAN is 5 though
Median 2
And mode 1

But they wont see it cause the papers over hahahahahahah

[alpine sable]

wot

[tough hatch]

"work out"

solutions needed lmao

also it's not very nice to just give answers, better explain how

[wary stream]

The thing is, that person was saying "the papers over" because that angle and background environment of the picture looks like a school setting so some sort of test or quiz and they were sneaking a picture to get help/cheating

[tough hatch]

it does look like an exam though

[alpine sable]

detective dldh and superficial

[cinder wedge]

can someone help me?

[alpine sable]

bet its that inequality

yeah just post dude

[wary stream]

Don't ask to ask, just ask

[cinder wedge]

how can I use teXit?

[alpine sable]

Dollar signs to enter math mode

and ig thats about it really

[wary stream]

You can also post a picture or screenshot of the question

[cinder wedge]

ok wait

na I solved my problem

[alpine sable]

ok

[nimble meteor]

ok guys i know I might sound retarded but I was getting a little excited because I thought I found a "loop" in math.

not an actual loop just like a flaw

ok

never mind

I'm stupid

bye

[alpine sable]

atan2 returns the arc tangent of x/y measured in radians

[cinder wedge]

What is the problem?

[cinder wedge]

Do you want to know what x is?

[glass lichen]

they implied they had figured it out already...

[cinder wedge]

If you want to know what x is then you can split the denominator into two terms and then you can use the zero product theorem

[alpine sable]

But they said they already solved it though

So you're kinda talking to yourself really

[cinder wedge]

(x+3)(x-3) = 0