#help-0
1 messages · Page 650 of 1
cause you don't go to -inf vertically
you're bounded below by -2
it'd be infinity if it went to infinity
the asymptote prevents f from getting lower than -2
The reason he moved the 3x first is to get rid of the negatives, less signs to handle. Moving the -3x to the other side, makes it positive 3x, moving the 2 to the other side, the 3x is still negative while the 2 becomes a negative value
Anyone have any bright idea for parrt ii
you can say that the sides of the rectangle are x and 24-2x
now write the equation for area
and solve the quadratic inequality set to greater that 27cm^2
oh
What kind of assignment is this?
A test?
No
What is the answer
ok
Not sure, you can easily look up the equation that can help with that
Expand the equation then use the vertex relation to find y coordinate
Determine the area and the centroid (x. y) of the area
idk what to do
help
Do you know how to find the area?
This ones easy but I cannot find this anywhere in my notes. What is the biggest and smallest segment?
Disregard the work from above
the length of a line is directly proportional to the angle opposite it
so in a triangle, the side opposite the largest angle is the largest side
etc
although this might end with you just picking a value for the middle line then using law of sines to solve for all the lines
I dont see a trick but I imagine there could be one
But for segment AC, it has both a 57 degree and 61 degree angle
And we haven’t learned the law of sines in this course.
solving a quadratic inequality is basically just solving the quadratic equation, then stating the values of x for which y<0.
-2x^2 + 24x > 27
2x^2 -24x +27 < 0
Here's a graph of the function from your question
so x belongs to (1.257, 10.743)
AB > CB > AC = AC (from the other triangle) > AD > DC
you can use only the one fact I told you to get this ^
by comparing the a sides by using their opposite angles
Ok that makes sense. Thank you
which part are you confused on?
Assuming your statement to be in the form "if A then B", the contrapositive is "if not B, then not A"
the converse is just the reverse: "if B then A"
the contrapositive and the original are logically equivalent statements, meaning proving one true, also proves the other
but the converse is not logically equivalent, thus proving it true does not necessarily prove the original true
Hey! I have an algebraic equation like this - x/150 * 3 = x/50 Why x/50 is equal to x/150 * 3?
x/150 * 3 = 3x/150
you simplify the fraction by dividing both numerator and denominator by 3
then you get x/50
3/150 = 1/50
has anybody here done a roller coaster project for calculus? involves multiple functions in the shape of a roller coaster that have matching first and secon derivatives at the connecting points
help
Consider the juxtaposition of this shape with itself such that you would have an infinite grid of parallelograms
Or even just a single 2×2 grid rather
ik how to do it but idk what to do when y has 2 infront of it
Set up the equation
2y is not 208 but half of that, since you have 2y two times
so 104 is the answer or do i have to half it again since there are 2
Yeah
How does this work
Also translation:
Given point P(-7, 2). The point P is being rotated around the center C(-2, 2) over an angle of -180 degrees. Give the position of P.
Wait why’d it be in radians?
radius*
Why’d I need the radius?
because it said it rotated 180 around a center
meaning it forms a semi-circle
to find the new point you just subtract value of radius from center, as shown in diagram
What’s up nerds
I’m looking for a blockchain dev who can help me build the next doge
Dogecoin
wrong place
sry bout the diagram btw, the number scale is in reverse lol
Wrong channel and wrong discord
lol
amd the radius is C*P?
its the difference of the x values of C and P
Do you guys have like a business channel where I can post my ideas and get feedback
?
Which does?
No
darn
You have to do -2+5
What
Since the center c is at -2
To find the X point sorry
What my brain
Y=2 akways
Do you mean that this calculation is wrong?
How to know area of a circle
X it's 5 units from the center in the opposite direction
No
That is the calculation to find the radius
Of the X?
Now add that in the opposite direction to find the X of the new point
so -5
Of the semicircle that forms rotating the point
Right...
No, the center is (-2,2) so you have to add 5 to the X, which means X=-2+5
Which is 3
So this'd be the same but for the Y then?
Yes
I was asking you to try to find the answer ahah
Why -2 at the beginning?
Wrong 2
I'm so good at math you'd not believe lmao
And add that to the original point which is Q and Q = (-2, 3) so that'd be (-2, 3-1) = (-2, 2)?
Maybe drawing a graph can help you understand the situation faster in this type of problems
Not to the original point but to the center
That's where you are rotating the point around
So C = (-2, 2) and then add that to C so (-2, 2-1) = (-2, 1)?
Yep
Man this is confusing lol
O(0, 0) and C(-2, 2) deg -180
So like
Both are different
So calculate for both?
Yes
Take just the x
Okay
It would be O-C=0-(-2)
Where is the other 2 from?
.
Try to draw that on a graph if you can
If it's C-O it's 2 right?
It's the same
how
What
Yeah I meant to just find the difference between the points
But that'd make a difference, no?
It depends how you use that later
Hm
Just do O-C for now
Yeah in the X axis
And now do the Y?
Yeah
Yeah
So now I've calculate the rotation thing
Then you have to subtract them both from the center C
No (-2-2; 2-(-2))
what
Trust me that helps a lot, try if you can
Yes
I don't know how to draw graphs what do you want from me lmao
I want to help you understand... You just have to plot the points on an X/Y graph
With their coordinates
O is 0,0
You basically need to find the "opposite" point of O. so you understand the signs of the coordinates better
right
Ah, Desmos. A man of culture.
With C as center
You can easily see that it must be a positive y and a negative x
You calculate the differences like we did before and find the points with the help of the graph
To understand the signs of X and Y and to understand wath the problem is asking for
integer limit lol
Sorry for being bad at math I do try I swear 
It's just hard to imagine rotation like that lel
Don't imagine rotating the point, just imagine finding the simmetrical point with C as center
As much as I want that to help, it really doesn't
I've no idea what to do with that information
Yeah
I'm so dumb lmao
They are all on the same line but in opposite directions and same distances from C
Right?
Np
It'd end somewhere here right?
Try to calculate the difference like we did before
Yeah
-2-(-7)=5
Yes
And then Cy-Ry
Yeah
It's not really the radius but you have to add those values to the center to find the opposite point
The radius is not a point so it doesn't have coordinates
But?
Bc we were working on a line parallel to the X axis
And it's 5, not (5,y)
It's just a number
Also add or subtract?
Bc I thought we subtracted them before
Or am I being dumb
Don't use the radius anymore, ignore that and just imagine the distances
right
You did that bc you subtract everything in the opposite order before, but always do C-R before and then C+X after
The graph helps you understand that you have to add, since you need to go in the opposite direction
You basically did something like a double negative, which is a positive anyway
I guess that makes sense
Just always do that from now on if you're not 100% sure
Sooooo C+X which'd be (2+5, 2+-1) = (7, 1)?
The X is -2+5
A cookie factory used 9.5 kilograms of chocolate chips to make 2 batches of cookies. How many kilograms of chocolate chips did they put in one batch?
Pay attention to the sign
yeah woops my bad
(-2+5, 2+-1) = (3, 1)?
A cookie factory used 9.5 kilograms of chocolate chips to make 2 batches of cookies. How many kilograms of chocolate chips did they put in one batch?
Help
Yeah
Could anyone help me
A cookie factory used 9.5 kilograms of chocolate chips to make 2 batches of cookies. How many kilograms of chocolate chips did they put in one batch?
Good job
You're really desperate for that cookie factory lmao
:D
Lol I was waiting for wumpie to finish his question
Could u pls help
Or their
Sorry 👀
For what
Or use one of the other 10 channels...
^
I was referring to aspect
Ohh ok
Oh
Btw,now we can help you
Me?
Yes
How can I find the component form of 5v+2u when v=<-7,11> and u= <20,-15>?
Yes
Oh no I don't like the looks of this
I've no idea what that is lol
I’ve been trying to get the hang of it but it has me stumped
Yeah I'd be too
Can someone help me out with this one?
I did find the point where sin|x| is non differentiable
Which is 0
ping me wherever you post this
You need to multiply the vectors
So
I thought I was supposed to subtract them ?
I did not know that and that might be very useful
I’ve been subtracting -7 with -20
No you have to multiply the values by 5 and 2
someone help me
Since you have 5v+2u
man just said you have to multiply first why are you subtracting
On my notes I have that I have to subtract each vector x1 and x2
Then vice versa with the y’s
So that means you would get <5(-7)-2(20) , 5(11)-2(-15)>
You have to use them like they are variables/points in a graph basically
Andreas is probably how you want to think about it, although it's perfectly legal to calculate 5v then 2u, then subtract them
Wait till you get Vector3's and Matrixes
I would usually do it in two steps
Oh ok
But wait v and u are seperate vectors. So shouldn't it be like:
If we let v vector be xi+yj
you added the vectors, you should be subtracting
And u vector be ai+bj
Lol I’m confused
Yeah sorry I wrote one thing for the other
We put those point in place of x, y and a, b and then subtract them? Idk of anyone got it-
.
- multiply vector v by 5
- multiply vector u by 2
- subtract the result of the second from the result of the first.
which of these steps is confusing?
What does finding the component mean exactly?
Okay I got it
,w 5(-7,11)-2(20,-15)
yep
Oh okay I see what I did wrong
👍
Nice embed?
I was trying to do the subtraction first
And not the multiplication of the 5v and 2i
PEMDAS/BODMAS
The what now
Is the channel free now?
sure
;-;
inb4 soya posts a high level question we can't answer
lmao
I need help with this one
How can I solve it without this graph?💀
oh yeah i have no idea how to do that one, absolute values are annoying
Graph was like the last option
PLEASE THIS IS HIGH SCHOOL LEVEL
Because I'm in high school. I mean this is for my college entrance-
I'm very confused
Idk what it is man
It looks like OR statements
I'm a game dev not a mathmatician lmao
Free math problem solver answers your algebra homework questions with step-by-step explanations.
Just try to yeet stuff in here potentially
iirc the usual method for such questions would be identifying values of interest(here it would be 0, 1, 2 and -1) and just checking if the derivative exists at those points. I think it should be differentiable at all other points
I mean you should find it using the limit definition of derivative to check, not by differentiating
if it turns out that the one-sided limits are equal(and finite) it's differentiable at the point
Yes I definitely know what you mean
Yes. I found those critical points but Idk how to proceed after that because if I check differentiabiltiy in the usual way, that is LHD and RHD then it would take a hell lot of time
R u sure about that lmao
🥲🥲
.
Differentiating it would require a lot of work.
yip
I'm so confused about this. Sigh
😃
What's with the happy face
It's a broken face. It's like "You know what life is good" but in a sarcastic way.
It just looks broken
It's just a regular smiley but sure lmao
Please I feel all smile faces look broken😭
f
Hey at least you don't have to do this
It's not really worse
But still
It's still funny that it's so dumb that it doesn't fit okay lmao
Matrices multiplication?
Oh yes I have to do this too lol
oh fun
It's just a lot of work.
But it's easier than my question
yes
is anyone online here?
for sure lmao
yes
6x6 matrices have entered the chat
no
lol
maybe
Oh no
heres my problem
Yours is like rocket science
💀💀
Trust me when I say this is for high school students
I really don't lmao
You can find the third side and then use Heron's formula
wut that-
Good question
Can't you just use base * height / 2?
Heron's formula wait
i think its a scalene not a right triangle
You don't need a right triangle for that
Oh wait yeah THATS simple
Sorry. Take out the area of XWZ and subtract the area of XWY
^
Does this help?
ok
Heron's formula is for scalene, actually any triangle
You have the base of the triangle, which is the side YZ, so 6cm, then you have the height, which is XW, so 9cm, then just use base * height / 2
my teacher wanted 0.00 format thing or something like that
You mean 2 decimals?
yes
This helps?
Why do you all have such simple questions?😭😭
This is literally all you have to do
Hey not my problem you decided to study rocket science
It's not rocket science ISTG
ISTG what
What's the problem the two of you are struggling with?
jow do i get xwy
1/2 b*h
That problem just seems tedious
But really it just boils down to finding the zeros of x^2-x-2 and x, doesn't it?
Then using the definition there
You have the base, you have the height.
And it's right angled triangle
oh yeah, right'
Because those are the only points where the absolute value can mess it up
Yes I found those points but Idk how to proceed after that
The definition of the derivative
I searched online and it said modulus changes its definition on 2 and not -1 and I have no idea what that means
thanks for that, @heavy canopy
Or how is that possible
No problem!
I'm on my phone but let me type up the first step real quick so you get what you're supposed to do
Okay!
Line across from left and right corner?
hmmm
Yeah now that I think Abt it they would be fully equal
That would made the top triangles bigger than the bottom ones I think
i agree
Wait I think it would be similar
but it would make the top one much more taller
Since these are squares and that line would be dividing those squares in half
It just looks like that
I think
i know but its much more long-
So the bottom vertex that the line of symmetry runs through, if we make it go directly to the top left so it makes a right triangle. Then from that point go to the midpoint of the bottom right line on the left side
Ill try to draw it
I'm and to geom tho tbf
So you know that by definition, the derivative at a point $c$ is given by
$$f'(c)=\lim_{h\to0}\frac{f(c+h)-f(c)}{h}$$
Now since you're dealing with absolute values, you have to first find where $x^2-x-2=0$ and where $x=0$, because that's where the absolute value changes based on its piecewise definition. So I'll show you how do to at one of the zeros of $x^2-x-2$. We know that the zeros of this are $-1$ and $2$, so let's consider the derivative at $2$. Then we would have to consider the one-sided limits separately, yielding us
\begin{align*}
f'(2)&=\lim_{h\to0^+}\frac{f(2+h)-f(2)}{h}\
&=\lim_{h\to0^+}\frac{((2+h)^2-1)((2+h)^2-(2+h)-2)+\sin(2+h)-(2^2-1)((2)^2-2-2)-\sin(2)}{h}
\end{align*}
and
\begin{align*}
f'(2)&=\lim_{h\to0^-}\frac{f(2+h)-f(2)}{h}\
&=\lim_{h\to0^-}\frac{((2+h)^2-1)(-(2+h)^2+(2+h)+2)+\sin(2+h)-(2^2-1)((2)^2-2-2)-\sin(2)}{h}
\end{align*}
Then all you have to do is check if these limits are equal
@heavy canopy
I think I have it
@bitter kite
That should be right
"dividing"
It's divided
Lorago
Typing this on my phone was a really bad idea lol
Hopefully it's at least a bit readable
but idk if its allowed to be extended
Its not
Ahh yess I knew this one. I didnt want to try it cause it would be too complicated. We are basically having a problem with the picewise function.
What I did was I let the the whole modulus thingy be h(x) and sin|x| to be g(x) Then I started solving h(x) separately @Lorago#9459
you typed that on ur phone? what a legend
Also did y'all start discussing other problems while I was typing that up?
yes
Wow-
Go on #help-5
ok
It's actually not as bad as it looks. You start off with a really annoying expression but a lot of terms should simplify right away since you're plugging in numbers for x from the get go
But yeah, just as you said the problem is it being a piecewise function
@heavy canopy am i correct?
Which might not be clear immediately
? 
Yep
thx
You typed that all on your phone
Yes, and I had to fix it a bunch of times because of that lol
Just woke up so it might not be the best
Also one last question, we don't really have a problem x^2+1 ? It's basically the modulus function that's troubling us?
@north flower we found the solution, it's in #help-5
*x^2-1
Alr
Yeah exactly, for that one everything should be fine
Since it's already differentiable everywhere
And not piecewise defined
The Toronto Maple Leafs have a 35% chance of winning their next hockey game, while the Montreal Canadiens have a 65% of winning their next game. The probability that they both win their next hockey game is 15%.
Benny was asked to draw a Venn diagram that reflects this scenario. His sketch is below.
Is Benny correct? If not, identify is error or errors and then create the correct Venn diagram.
the image is a venn diagram with 2 circles, left circle is 35% middle is 15% and the right circle is 65%
HELP ME
Sounds good
HELP ME HOMIE
Nah I'm going to have breakfast
Wait I think I got ir
*it
Okay so @shut tartan
Benny is not correct
Basically subtract 15.
Id really know how to explain myself
If Bob ate my Pizza, how many miles will John run if my sister did the dishes?
But its something related to A U B= A+ B- A N(intersection)B
U
👍
answer is always 7
correct
Hello how would I find a angle that is formed from two vectors ?
dot product of two vectors is |a|*|b|*cos(theta)
use dot prod
ajuze
Let me try and figure it out on notes
Would I have to figure out the magnitude for each vector ?
yes
if you have three numbers, 1, 2, 3
how many ways can you arrange them into 4 boxes, using all three numbers at least once and one number twice?
e.g. 1123, 1213, 2213 are all allowed but 1113 is not
i think i have an answer, not sure if it's right tho
u got 18??
no i got more than that
i did
3! * 4 choose 2
3 x 3 x2 shud be the right one..
yes
4 choose 2 why?
because there's that many ways to choose where the two repeated numbers go
but actually
that would count things twice?
don't overthink..
Just put 4 boxes
Count how many ways u can place those numbers in first box
then do for the second
similarly for 3 and 4
actually I think it is 3! * 3
thats correct I guess
this is a different question?
2! * 2
n! * n maybe
0! = 1, but that doesnt really matter
generally , if u have n numbers , n+1 spaces , with the condition
n ways to put the number in first box
n ways again to put the numbers in second box (2nd repetition)
n-1 ways to put the number in third box
n-2 ways in next box
so on... upto 1
so simplifying will give us n! x n
Where can i ask someone for help
literally any channel without an active conversation
paradox
Oh so not here?
not a big thing.. because u have no number and only 1 space , u can't really place twice of the number
whats the answer to a
n^2 + 2
p^2 + 2= 123,
p^2 = 121
p = 11
(11)^2-2(11)-120 = 121 - 22 - 120 not 0
is that right?
guess i went wrong somewhere
yeaa
I get n^2 - 2n + 3
n^2+2 seems to work assuming u start at n=0
yep
oh kk
I literally cannot wrap my head around that question
Part A and C were easy
B messed with my head fsr
then u should use p-1 right?
not p
u'll get 12 (sorry i got p-1 = 11)
100-20-120 is also not equal to 0
Yea
,w p^2-2p-120=0
12
Yea i got that for part C
so you have to shift it the other way
wdym
p-1 = 11
^
what is the objective function of the support vector machine with logsitc
huhh
substitute p-1 instead of p
p = +/- 11 + 1
p^-1? or p^1?
p-1 , since u assumed the first term n to be = 0 , not powers of p
Oh yea tru
i think i get it now
Should we factorize it
Or did i confuse myself again
don't confuse .
For them pth term = 123 , but for us , we have assumed n = 0 , pth term = p-1 th term
substitute p-1 in n^2 +2 and equate it to 123
get the value of p
then substitute in the given quadratic
thats how u prove it
oh makes sense
Yeayea
thanksss
So simply find one of the P terms, substitute it into the given equation, and show how it equals 0
finally
@mellow hatch thanks mate
adios
5 oz = 91.7% of the total
welcome dude!!
can you explain how u came to that conclusion
hey
anyone know how to solve this
0, 5, -3, 5, -3, ?, 4, 3, 8, -4, 1, 3, ?, 7, 9, 6, ?, 8, 2, 3, 3, 5, 4, 7, 9
is it a sequence or something ?
hmmm hard patterns
yep
i tried everything
this is something that requires you to think outside the box
at the second question mark its 5
yea i was a bit confused haha
its (75%)*(5 oz) = 91.9% (of the 22carat mixture)
the best part about sequences is you can make it be whatever you want
^
lmao
yep
how would i find how much pure gold is mixed in though
91.7 no?
okay here
we have 5oz of 18 carat gold
that means its 3/4 * 5 oz of gold
15/4
and 5/4 oz of not-gold
we want the ratio of gold/total stuff = 0.919
(15/4+x)/(15/4+x+5/4) = 0.919
,w (15/4+x)/(15/4+x+5/4) = 0.919
add 10 oz of gold I sps
ohhhh okay thank you so much
i got gf(x) = x-5 for b
but for c, i thought it was {x|x ∈ ℝ}
but it is {x|x ≤ -√5 or x ≥ √5, x ∈ ℝ}
why is that
for part c it asks for f(g(x))
@delicate mango fg(x) = sqrt(x^2-5) and you cannot take the sqry of a negative number, so you need x^2-5 >= 0
ohhh so the square outside of sqrt doesnt cancel the sqrt ?
I don't understand what you mean
no there are two terms (x^2) and (5) seperated by a minus sign
6×85+4?
i still cant make sense of this
What do you think fg(x) is if not what I said?
oh wait
i got ittttt
omggg
i thought it was gf(x)
alrighttt thanks @quaint trout @gleaming granite
it is... because its a linear function
It would be {x in R: x >= 2}
It is a linear function, but it is a linear function on this domain.

When you find gf(x), you are right that it simplifies into a linear function. But by the definition of gf(x), you must first be able to put x into f and then put f(x) into g.
wait that means you have to take the domain of gf(x) from the range of f(x) only?
Since f is only defined for x >= 2, you cannot put a smaller x into f
wannna play minecraft join this SpaceCraftCity.aternos.me join this too https://discord.gg/aCz8SrBGAJ
dom(gf) = {x: x in dom(f) and f(x) in dom(g)}. Normally you have that f(x) is always in dom(g), then it becomes dom(gf) = dom(f)
i see
if its fg(x) then the domain should be in g(x) rite
I don't understand what that means
if its fg(x) then the domain should be in the range of g(x) right
The domain should be a subset of the domain of g
The range of g is only relevant in that you need the image of that subset to be contained in the domain of f
ohh i got itt
thank youu
im in university for engineering and i cant figure out what DF is for the second triangle
worst moment of my life
is it 6 or 4?? i think its 4
would u solve it by finding AC by adding AF with FC to get 6 and then know that 6 is 1/2 of 12 therefore DF is double AF which is 4
,rotate
printer issues?
a friend on disc sent me it like that i tried to explain it to him
im pretty sure its a cutoff 2
for AF
yeh, it'll be 4
thank you !
how do i work this out?
The price of the computer is $1550 including 10% GST.
The amount of GST paid when purchasing this computer is closest to:
im really having trouble with these financial questions
let the base price of the computer be x,
express the gst in terms of x
express the total price in terms of x
solve for x
have you done any algebra before?
yeah but its just abit confusing since we dont really use that much algerbra in financial arithmetic
what is did was 10% of 1550 which is 155
but apparently thats wrong
because b is the correct answer
although wouldnt 10% of 1550 just be the amount of gst
idk
What they mean is that you are paying 10% on the original price
So if the price without GST is X, you are paying 10% * X in GST
They are not saying that 10% of the final price is GST
Do you understand the difference?
i didnt say $10 is the final price did i?
Okay
lmao wasnt being snarkey
the price without GST would be 1550-155?
oh
Let me give an example
Let's say an apple costs $4 without tax, but tax is 25%
Then 25% of $4 is $1, so with tax the apple costs $5
yes
But 25% of $5 is not $1
That's because the tax percentage is given on the original price, not the price with tax
Yes
its with 10% gst included
oh im sorry
alright
If I tell you that something costs $100 and you need to pay 20% in tax
How much does it cost with tax? And how do you work it out
How you work it out is the important part
let me try and figure it out
I want to know, if I give you a price without tax and I give you a tax percentage, how do you work out the price with tax?
If something costs X dollars and you have to pay r % in tax
Remember that r % means r/100
Then the tax is X * r / 100
Does that make sense?
So the final price is X + X * r /100
I am not looking at your problem specifically
No
1550 here is the price with tax. X is the price without tax.
Well, that's what I'm asking
when you say here
i literally have no idea what you mean
Did you understand the previous part where I said the tax is X * r / 100?
is r=to rate or in this case GST?
r is the tax percentage
Well
Price with Tax = Price without Tax + Tax
Price without tax is X
Tax is X * r / 100
So Price with Tax = X + X * r / 100
Does that make sense?
hmm idk
what
You still haven't told me if you understand this part. I need you to confirm every time when I explain something if you understand it
.
The X is the price without tax.
maybe be we can use my example so i can understand it?
yes i know its the price without tax but idk how to get that
at the beggining i thought it was just 10% of the principal
You don't need to know what X is yet. You need to understand the formula.
Can you see that I can factor X out of X + X * r \ 100 to get X* (100+r)/100?
$X + X \times \frac{r}{100} = X \times \frac{100}{100} + X \times \frac{r}{100} = \frac{100X + rX}{100} = X \times \frac{100+r}{100}$
Lunasong the Supergay
Yes
ok
Final Price = Initial Price * (r+100)/100
Initial Price = Final Price * 100 / (r+100)
I was trying to derive these 2 formulas for you
oh
i just thought of it as
Cost without GST = Cost with GST/1.1
and cost with= cost without x 1.1
vice versa
Yes, 100/(10+100) = 1/1.1
np
sorry my engish is bad
It's okay
:)
🙂
eww ok thats creepy
i may have more questions but well see
(on different stuff)
Lol
$f(x) = (\sqrt (x^2 + 1 ) -1) / x$
$f(x) = \frac{\sqrt{x^2+1} - 1}{x}$
Ann
did you mean this?
yes
did you just decide to post this function here for fun?
okay
I need to find lim when x=0
yes I move x outside of the sqrt
you... what?
x*sqrt(1-1/x^2)
?!
okay, did you mean x * sqrt(1 + 1/x^2)?
as in, you rewrote just the root as this?
yes
this is going to be useless in your scenario
can i suggest multiplying & dividing by the conjugate instead?
@keen citrus channel busy please move
@hollow owl yes this is correct, now you can plug in x=0
yes you are correct, the limit is 0
Removable discontinuity
your function had a removable discontinuity at x=0 yes
thanks!
Biot-savart law moment
???
It’s how you find the magnetic field produced by a closed loop of wire
Anyway
Finding y in terms of x
You know the total length right?
yes
2m
Ok, so if you calculate the total length in terms of y and x using the formula for the circumference of a semicircle and then adding on the 3 sides of a rectangle, you know that has to be equal to 2m
There’s derivatives in the question bro I KNOW you know how to find the perimeter of a semicircle
yes
sorry i didnt understand
yes
It’s alright dw
im just stuck on the first one
bye 😫
?
help me when?
I am currently helping you.... lol....
ok
thanks, idk what to do next
