help-0

[woeful dirge]

it's helpful to keep it in parentheses so you remember not to mix stuff into it

[wary stream]

Yes

Next step?

How to isolate x?

[lime gorge]

Divide both sides by 6?

I’m not really sure

[wary stream]

Why 6?

[lime gorge]

It’s the opposite side of the equation

[wary stream]

If you wanted to isolate x, what do you have to divide to get 1x?

[lime gorge]

37 tan?

[wary stream]

The 37 still stays in the parentheses

Of the tan

[lime gorge]

So how then??

How would I do it?

[wary stream]

Divide by tan(37)

[lime gorge]

That’s what I meant with this lol

So divide by tan(37) on both sides

[wary stream]

You just can't move things around like that

[lime gorge]

Gotcha.

You’re right

[wary stream]

If I had 2x + 6, could I say 6x + 2?

[lime gorge]

No

So 8.25829152283?

Is x?

So 8.3

Final

[wary stream]

You typed something wrong, I think

[lime gorge]

6/tan(37) no?

[wary stream]

That's right

I mean typed into the calcuator

[lime gorge]

I plugged that in the calculator

On degrees

[wary stream]

You mistyped it

[lime gorge]

So 7.96226892972

I used 36 lmao

So 8.00

Final

[wary stream]

Yes

[lime gorge]

Would you mind helping with a few more?

I have all of these to do

As well as these 2

So i wanted to work on this one

^

[wicked steeple]

uh

[wary stream]

It's all the same process, just apply the trig ratios properly

[lime gorge]

Not all trig tho

Is it?

[wary stream]

I suggest doing it all on your own first, and if you get stuck, ask

[lime gorge]

Gotcha tysm

[wary stream]

It is

[lime gorge]

Mind if I ping you?

If I need help?

[wary stream]

No, because I'm leaving but someone would be by to help

[lime gorge]

Ok ty

[wicked steeple]

you can ping me @lime gorge

[lime gorge]

Tysm

[wicked steeple]

sure thing

[lime gorge]

Well, exponents first

So 10 to the 76th power

Lmfao no that’s not right

You can’t do 10 to the 76th power

Um that’s 10*10 repeating 76 times

You sure it’s not 10*76?

[zealous garnet]

i mean you can

x approx 0 then

[lime gorge]

Yea but it’d take all day and there’s no point I don’t think that this was what they r going for

[wicked steeple]

ping me if you have a question cause I'm on another screen doing my hw @lime gorge

[lime gorge]

Gotcha ty

Don’t think I’ll finish it anyway

I think I’ll do my other missing assignments

Then work on it more tomorrow

[alpine sable]

how do i find the limit of y = mx

[frigid stream]

Replace y by mx, and compute the limit

[slow fjord]

Anyone here to explain me pole and polar of circle

[wicked steeple]

@slow fjord shoot your question

[slow fjord]

I don't know What is pole and polar of a circle

I want explanation

[wicked steeple]

I'm not sure I know how to answer your question

[tepid otter]

https://i.imgur.com/45tINYY.png

can someone help me answer this?

i get this in symbolab

[thorn kindle]

Yeah

So you need 4 decimal places

Type that into your calculator

Lmao

[tepid otter]

lm(37)/0.4ln(2) into the calculator?

oh yeah it worked

thanks

[tender pulsar]

In “A house cleaning business charges $20 per hour and a flat fee of $25 per home.” What would be the independent and dependent variable in the relationship?

[wicked steeple]

Alright

[tender pulsar]

I think that the cost would be the dependent but I’m not sure

[wicked steeple]

what variable is changing in your scenario?

[tender pulsar]

They both would be changing, no?

Wait no the flat fee wouldn’t

[wicked steeple]

right

so the $20 per hour is

what is it dependent on

[tender pulsar]

The amount of hours?

[wicked steeple]

right

[tender pulsar]

So the independent variable is the numbers of hours and the dependent variable is the cost?

[wicked steeple]

yeah

[tender pulsar]

Alright thank you

[random talon]

Hello everyone, I have a very simple question on logical forms

[ocean seal]

Alepsruiz

[lapis shadow]

Excuse me

Is this correct

[zealous garnet]

no

[wooden crag]

that's not correct, adding squares does not equal squaring the sum

square first, then add

[torpid notch]

my heads about to explode I don´t belong here :(

[random talon]

I would like some clarification on a logical form. If I am asked to analyze the logical form of ${x_i; | ; i\in I} \subseteq A$, I know there are two possible answers. The first one is $\forall x(\exists i\in I(x=x_i) \rightarrow x\in A)$, which I understand. The second one is $\forall i\in I(x_i\in A)$. I don't understand how to go from the first to the second. I would appreciate any guide. Thank you in advance.

[ocean seal]

Alepsruiz

[golden arch]

How do you calculate the determinant of a 3 x 2 matrix

[random talon]

You can't

[celest void]

Because it's not a square matrix

[golden arch]

oh owkey

Thanks!

[shell iron]

Do I find the nth root or use De Moivre's Theorem for question C?

Or anything else.

Set 1

<@&286206848099549185>

Nevermind, I got it.

[alpine sable]

ummmmmm

i need help

with some of my calculas

and equation

s

[shell iron]

Just ask

Don't ask to ask.

And wait...maybe they'll help.

[stark rampart]

sure sure

[alpine sable]

i'm writhing a paper on dark matter

[stark rampart]

oh sori im not quite knowledgeable in dark matter haha

[alpine sable]

i know

but math

EA = dy/dx = D

intregel dy/dx sq = D

confusing

[umbral schooner]

if u notice the card number that each gets has a difference of 5
for eg: jessica gets 1, 6 and 11
6-1 = 5
11-6 = 5

so that way you can figure out who gets card number 48

[stark rampart]

wait i dont think it's about card numbers

because jessica gets 6 cards not card number 6

[umbral schooner]

the question is who will get the last card

[stark rampart]

6eah

so

[umbral schooner]

last card is number 48

so we need to name who gets card number 48

[stark rampart]

1+2+3+...=48

[alpine sable]

btw im 14

doing cal

[stark rampart]

ohhhh i see yeah ur right @umbral schooner

[alpine sable]

ye

me to

no

but 14

[umbral schooner]

its just simple logic, nothing to be taught here

[alpine sable]

i discoverd that dark matter breaks the theory of genrel reletivity

but could not share it

[umbral schooner]

no no you are not dumb

what i meant to say is, if you count up to 48 distributing those cards to each person you will see the pattern

after that it becomes easy

see melissa gets cards 2, 7 and 12
they have a common difference of 5
7-2 = 5
12-7 =5
that means the next card melissa will get, will be 12+5

[gray isle]

snake

[umbral schooner]

this is the pattern

left to right
right to left

[willow bluff]

Can someone help me?

[wooden crag]

ask

[willow bluff]

There

[wooden crag]

it gives you the arc length of that little section, so you need to figure out the arc length of the rest of the circle, add the two together, and you'll get the circumference

do you know how an arc length and an angle relate?

[willow bluff]

Nope

Really lost tbh

[wooden crag]

do you know how to get radians from degrees

[willow bluff]

Nope

[wooden crag]

okay so, do you know what radians are at all

[willow bluff]

It’s like really old homework and I’m trying to get credit kinda thing

Not really, online school never taught me anything

[wooden crag]

radian is a unit for measuring angle, just like degrees, but it relates to the circumference and radius

so a circle is 360 degrees, which equals 2pi radians

a circumference of a circle with radius 1 is 2pi

first you need to figure out the radius of the circle

(he took it to my DMs)

[jagged imp]

,rotate

[golden arch]

Thanks

hox would I solve this using the gaus Jordan method?

im stuck after a few Steps

[random thunder]

How to do this ???

[hollow pelican]

guys how to do this?

[clever locust]

Start by rewriting the expression in some way that makes it easier to solve

[alpine sable]

@vale wigeon yo you in the house?

[vale wigeon]

uh

i suppose so, yes

what is it

i'd appreciate if you did not wait unnecessarily before asking your question

[random goblet]

how do i solve this

[alpine sable]

Quick question please

nice to see you again btw

[wooden crag]

occupied channel, but similar triangles have sides with the same ratios

[random goblet]

its a rectangle

[wooden crag]

oh whoops

[wooden crag]

well, their sides are still proportional

[alpine sable]

From this information is it possible to work out how long they have worked for the company?

[astral sluice]

yo im doing a practice test and im doing a question on some stuff i never coverd in class
is it possible to get into a call with someone to just help me run through t
..

[alpine sable]

@vale wigeon?

[vale wigeon]

...

@alpine sable we will have to move to another channel if you don't want to get swamped by help-seekers who constantly flood this channel.

[alpine sable]

ok, which channel?

your choice 🙂

[vale wigeon]

#help-7｜zen1thxyz seems free rn

[dapper nacelle]

Can someone please help me with this

[wooden crag]

pythagorean theroem, friend

[dapper nacelle]

Ik

Idk how to do it

[wooden crag]

c^2 = a^2 + b^2

substitute in the known values, solve for b

[dapper nacelle]

What's c tho?

[wooden crag]

hypotenuse

the largest length

[dapper nacelle]

Oh

Tank

So I find out what B is?

[wooden crag]

yes

[dapper nacelle]

And square that to find the answer?

[wooden crag]

no, you just need b, not b^2

[dapper nacelle]

Ok

Tank

[wooden crag]

after you find the solution, post it here so i'll check

[dapper nacelle]

K

What do I do with B?

Nvm

[wooden crag]

solve it using algebra

as if its just x

isolate it

[dapper nacelle]

5625?

Is B 5625

[wooden crag]

nope, that's b^2

you need to get the square root

[dapper nacelle]

Ohhh ok

Thx

[astral sluice]

idk if u can see that

[dapper nacelle]

45?

[wooden crag]

actually 5625 isn't even b^2

how did you do the algebra, what

[dapper nacelle]

WHAT

I'm dumb

I hold 45 to the power of 2 right

[astral sluice]

@dapper nacelle

[dapper nacelle]

DONT GIB ME THE ANSWER

[astral sluice]

oh my fault

[dapper nacelle]

Thx

[astral sluice]

basically what u want to do is

u want to rearrange a^2+b^2=c^2

to get ur a value

do u know how to do that ?

[dapper nacelle]

Lemme see

[astral sluice]

how would u rearrange that to solve for b

thats the first step

[wooden crag]

are we gonna teach algebra 101

[astral sluice]

looks like we gotta

[dapper nacelle]

NO

Fortunately

I'm not that stupid

[astral sluice]

lmfao ok

can u rearrange the eqn though

[dapper nacelle]

Is it 60?

Yeah

[astral sluice]

YES

good

[dapper nacelle]

Finally

[astral sluice]

👍

[dapper nacelle]

tank

[astral sluice]

how u get to that answer though ?

[dapper nacelle]

B)

Ok ao

So

I did 45 x 45

[astral sluice]

riiight

[dapper nacelle]

Then did 75 x 75

[astral sluice]

riight

[dapper nacelle]

Subtracted them

[astral sluice]

riiiight

[dapper nacelle]

Got 3600

[astral sluice]

riiiight

[dapper nacelle]

Then squared that

And for 60

[astral sluice]

dope

[dapper nacelle]

Ok finally

Lmao

[astral sluice]

@wooden cragyo how good r u at maths

i want to see if u can help me with sum

[fossil wind]

THE ANSEUR IS 87,46

[dapper nacelle]

Tg

Tf

[astral sluice]

real

[wooden crag]

sure just post it

[astral sluice]

naw its easier if i explain in a call

if that works with u just gotta show u the screen

[wooden crag]

can't really call right now, sorry :(

[astral sluice]

maan

[fossil wind]

yes

[astral sluice]

fuck

[wooden crag]

its better if you screenshot and post it here

[astral sluice]

ok

no idea how to do c onward

never learned this in classs

doing a practice exam

[jagged imp]

which part?

oh c onwards

sorry im illiterate

[fossil wind]

because 45 *45 = 2025
and 75 * 75 = 7650
and then add both together 2025 + 7650 = 9675

then you do this

then the nummber C will be 98.36

[wooden crag]

that's not correct

75 is c, and 45 is a

the theorem says a^2 + b^2 = c^2
not c^2 + a^2 = b^2

[fossil wind]

oh wit

ohhhhh he is looking for B

[wooden crag]

yup

[fossil wind]

i thot he is looking for C

😂

[wooden crag]

nah

[fossil wind]

ok so c^2 - a^2 = b^2

[heavy lagoon]

yes

[fossil wind]

so 5625 -2025 = 3600

[heavy lagoon]

mhm

[wooden crag]

sqrt(3600) = 60

[fossil wind]

then you do this

[wooden crag]

which is what the answer was

[fossil wind]

then the b=60

3600 is b^2

then you do root and it = 60

[alpine sable]

.

i need help

[wooden crag]

ask

@alpine sable

[verbal storm]

Alpha and beta are roots of equation ax^2+bx+c then find an equation whose roots are alpha+1,beta+1

[wooden crag]

quadratic formula probably helps a lot

go backwards

[verbal storm]

I just dont understand

[vapid swift]

let alpha + 1= x

alpha=x-1

[stark lantern]

using the formula is unnecessary

$(x-\alpha)(x-\beta) = x^2 - (\alpha+\beta)x+\alpha\beta$

[ocean seal]

error 404

[stark lantern]

you should realize from this that -b/a is the sum of roots and c/a is the product of roots. Find the sum and product of roots for the equation with roots alpha+1 and beta+1 in terms of a,b and c then construct the quadratic.

[verbal storm]

Oh

[wooden crag]

i feel like using the formula would probably make it easier

[vapid swift]

or else you can go this way ....since alpha is the root of the equation you can substitute alpha=x-1 in the equation and simplify it

[verbal storm]

Okie

I have another i just forgot how to draw parabolas the question is draw graph of x^2+x-12 with specific points

[wooden crag]

find intercepts, and the vertex

[verbal storm]

Okie

[brittle grove]

in isosceles triangle are the median and altitude same just like in equilateral triangle?

[wooden crag]

isosceles has three medians

same as equilateral

isosceles only has one altitude, however

unlike equilateral

[vale wigeon]

the median, altitude and bisector drawn from the apex are all the same. @brittle grove

[verbal storm]

@wooden crag the x and y intersepts right

[brittle grove]

thanks

[brittle grove]

thanks

[wooden crag]

if they both exist

[verbal storm]

Oh

[wooden crag]

they'll always have a y intercept

[verbal storm]

My x are coming 3,0 and -4,0 @wooden crag

[wooden crag]

right

now you figure out the vertex

draw two points at the x intercepts, a point at the vertex, a point at the y intercept
(and if you really want you can do extra points at arbitrary x values to get a better drawing)

once you have the point, connect

you should get this shape

[verbal storm]

Oh thanks for the help

[neat merlin]

$\frac{1}{0!} + \frac{1}{1!} + \frac{1}{2!} + \frac{1}{3!} + \dots$

[ocean seal]

qcanser

[strong furnace]

If you're looking for the value that is the definition of e or you could say that is e^(1) according to the power series for e^x

[marsh summit]

can someone help me pls

[vale wigeon]

is that $\bar{x} = 60$?

[ocean seal]

Ann

[vale wigeon]

that's wrong lol

60 is not the mean, it's 1 SD above the mean

(and also you're asked for the mean, not sigma)

[fading jay]

ok,i tried to translate without a translator

[vale wigeon]

?

[fading jay]

English is not my native language

[vale wigeon]

so you didn't know what the word 'above' meant?

[fading jay]

yes i'm wrong, forget it

[dapper nacelle]

Can someone help me with this?

[wooden crag]

blurry photo but

angles on a straight line add up to 180

[dapper nacelle]

Ok so that's x

[wooden crag]

no

look on the right

126

plus the angle inside the triangle

[dapper nacelle]

Ok

[wooden crag]

is 180

[dapper nacelle]

Idk what u mean

[wooden crag]

big red angle is 180

[dapper nacelle]

Ok

And

What about it

Do I subtract 180 bu 126

By

[frigid hatch]

yes

[dapper nacelle]

Pog

Thx

[wooden crag]

that way you find a

once you have a, you can find the other angle of the triangle

and then get x using the same thing we did on the right

[frigid hatch]

knowing that the sum of angles in a triangle is 180

degrees

[vapid swift]

or else sum of two opposite interior angles is equal to the exterior angle

58+y=126, say y is the angle inside the triangle near x

[dapper nacelle]

I get it

Can someone help me with this

[woeful pulsar]

try drawing a best fit line

to help estinate

[dapper nacelle]

Idk how ti

WAIT

[wooden crag]

just draw a line through the points

[dapper nacelle]

WAIT

I do know how too

[wooden crag]

see where it interests x axis

[dapper nacelle]

I just

Dont have paper

[dapper nacelle]

Tank

Next one

[woeful pulsar]

well, you could have done the same in paint or any drawing app

[dapper nacelle]

How do I solve this? I dont understand it.

[woeful pulsar]

are there any relations that you see about the angles?

[dapper nacelle]

I don't understand anything aboutbjt

It

[clever locust]

So you know that the arrows are parallel, correct?

[dapper nacelle]

Accidental ping

[dapper nacelle]

Jaja

[clever locust]

And there is a line with a right angle intersecting it, correct?

The one in the bottom left

[dapper nacelle]

Ok

Yeah what about it

[clever locust]

You also know that these two angles should add up to 180 degrees because the lines are parallel, correct?

You should also know that these angles are the same, correct?

[alpine sable]

The coefficient of direct propocial sizes whose graphics belongs to dot T(2,4) is:

a) k = 1/2 b) k = 2 v) k=6 (g k=8

[dapper nacelle]

Ah ok

Thx

[clever locust]

You got it now?

[knotty egret]

hi, I have this question

and this another one, are these are the same can i use the same method?

[alpine sable]

<@&286206848099549185>

[solemn shuttle]

what is propocial ?

[alpine sable]

Sorry,iam talking about proportion

[dapper nacelle]

Can someone help me with this

[wooden crag]

try it first
what do you not get

where are you stuck

[dapper nacelle]

Dude I dont know anything

[wooden crag]

then learn the material

[dapper nacelle]

Yeah that's why I came here

[wooden crag]

so far you've just been asking questions and letting people solve things for you

[alpine sable]

Is k=2 the right answer?

[dapper nacelle]

No???

Wtf

I've been learning

[wooden crag]

if you understand nothing about the material, then it's better to start with actually studying it rather than blindly trying to solve questions

[dapper nacelle]

Well its 2am on a school night

[alpine sable]

is this channel occupied

[dapper nacelle]

And idk where to study about it

[wooden crag]

yes

[alpine sable]

oh ok

[solemn shuttle]

isn't this like yr 6/7 curriculum

[dapper nacelle]

8

[solemn shuttle]

and kale i'm not sure sorry :(

[wraith peak]

yes it is

[solemn shuttle]

ah fair enough, bbc bitesize https://www.bbc.co.uk/bitesize/guides/zrck7ty/revision/1

[dapper nacelle]

8

Year 8

[wraith peak]

It depends

[orchid lance]

does anyone know the answer to this ?

[dapper nacelle]

Ok well how do I di that question

Do

[orchid lance]

mos websites say its sin and close to this

but my teacher keeps saying its cos and that everyone that posted in the internet is wrong,im confused

[orchid lance]

even by graphin this doesnt make much sense to me :/

[solemn shuttle]

Hegarty right?

[dapper nacelle]

Ifk

Idk

[solemn shuttle]

okay do you know what the topic you're trying to tackle is called?

[dapper nacelle]

No

Sorry

I'm tryna do this so I can go to bed

Ayo?

@solemn shuttle

Ok nvm

[knotty egret]

What should I do here?

[alpine sable]

this chat occupied?

[cloud ginkgo]

I need help with this

Can someone please help me with this?

[upbeat abyss]

Isnt this a test?

[cloud ginkgo]

no its just a practice one

its on onenote

[upbeat abyss]

Ok then

[glass lichen]

Find the coordinate vectors of each basis vectors then those become the columns of the matrix representation

[wooden crag]

i thought that was gonna be a related rates problem

[untold egret]

rangan buys 3.6 kg of potatoes and 2.8 kg of leeks the total cost is $13.72 leeks cost 2.65 per kg .what is the cost of 1 kg potatoes​

Can i have help please

[near pendant]

1.75 per potato kg

[untold egret]

Also with this please

[old walrus]

Surface area should just be (3x4)+(3x4)+(6x4)+(6x4)+(3x6) right?

If I’m not wrong (haven’t done this in ages) u just have to calculate the length x width of each of the faces

So two (3x4)’s are the triangles, (6x4) is the sloping piece and the base and (3x6) is the back rectangle

[woeful dirge]

for the sketch, you need to draw each face of the prism on a 2d space, connected to the other faces such that you could create the 3d shape if you had it as a piece of paper or smth.

[old walrus]

The grid is 1cm square so just draw as it it was open so above the square that’s draw for u u should have the sloping piece, behind would be the back rectangle n the triangles at the sides

[lofty pond]

Sloping piece will be 5x6

[old walrus]

Oh why

[old walrus]

Yeah maybe in ur case u might want to try make a 3d model of it out of paper that’ll help u understand other shapes next time too ^

[lofty pond]

Hypotenuse is 5 right?

[old walrus]

U don’t have to calculate the slope right? Just the size of the pieces

If it was 6x5 that wouldn’t fit within the base right? Haha I’m not too sure

I’m assume it’s calculated from the grid so the numbers would be taken from there

Actually for the triangles idk if u have to divide by 2 it’s been so long since I’ve had to do these lol

[lofty pond]

Yes u have to

Else u get area of square

Or rectangle

Here both sides are different so rectangle

[fiery meadow]

hello

would it be okay if someone could help me with this please?

[violet sphinx]

Is k= 8.66?

@woeful dirge Can you help me with the question I sent in #help-9

[alpine sable]

Find the angle of tangent

$11 = 6 \sqrt{5} \cos \theta$

[ocean seal]

sshaagar

[alpine sable]

$m = \tac \theta is slope of line $

[glass lichen]

you can find the length of OQ

[static crypt]

^ what I would do is find the length of OQ using Pythagorean theorem, then do Pythagorean again with 11 and k as the legs and OQ as the hypotenuse

[stuck plaza]

Where did the 3j come from?

[twin condor]

j + 2j = 3j

@stuck plaza

[alpine sable]

anyone?

[glass lichen]

find the circumference of the circle

[alpine sable]

oh

thx

[willow bluff]

Can someone help me with this?

[glass lichen]

,rotate

[glass lichen]

is it a test @willow bluff ?

[willow bluff]

No homework check

Basically a review that’s 5 questions

[ionic jewel]

... I dont think you even need the 14.5

iirc the octogon area can be only dependent on that side length

yeah its $A = 2(1+\sqrt2)s^2$

[ocean seal]

bunny

[willow bluff]

So even when I’m given a raise I don’t use it?

[ionic jewel]

what?

[willow bluff]

The 14.5

[ionic jewel]

perhaps you learned a formula that uses it

the one I sent does not

[fiery meadow]

hey thanks!!

[woven dock]

Well, in that case, you can divided the octagon into 8 congruent triangles with base 12 and height 14.5

[ionic jewel]

yeah but why do that when you can not do that

but yes I suppose thats a way to include the 14.5 if you really wanted

[willow bluff]

I got 630.75 if that’s right

[ionic jewel]

sounds right

no

its not

[willow bluff]

What the correct answer?

[ionic jewel]

about 695

with some decimals

[willow bluff]

How’d you do it?

[willow bluff]

What would I do?

[ionic jewel]

im really not sure what you did

,calc 2(1+sqrt(2))(12^2)

[ocean seal]

Result:

695.29350596345

[willow bluff]

How would I find exact area of a hexagon with a side length of 12?

[woeful dirge]

hexagons can be split into equilateral triangles

since 360/6 = 60

so it makes 6 equilateral triangles with side length 12, you should be able to do the rest

[vapid swift]

only if it's a regular hexagon right?

[woeful dirge]

yeah sry

forgot to say that

[willow bluff]

It is a regular hexagon sorry 😅

[woeful dirge]

wait why are you sorry thats great

[willow bluff]

Just forgot to include information lol

How would I get it into exact area?

I know that it equals like 374

[ionic jewel]

your image is an octogon

unless you mean a new problem

[willow bluff]

New problem

[woeful dirge]

do you know how to find the height of an equilateral triangle?

[willow bluff]

Wait would it be A = 216 square root 3?

[woeful dirge]

yes

[alpine sable]

Can someone speak german

[obsidian lantern]

Nein ich spreche kein deutsch

[alpine sable]

Ich hab ne frage zur analysis

[ionic jewel]

ich kann etwas deutsch lesen

[alpine sable]

Die frage lautet eine ganz rationale funktion zu ermitteln für einen bestimmten temperaturverlauf zu ermitteln dabei habe ich eine funktion für den beschränkten zerfall die lautet: f(t)= 36,5+3e^-0,23t

Diese funktion beschreibt eben den kurvenverlauf

Und nun soll es eine passende polynomfunktion geben

[ionic jewel]

Polynomfunktion?

[alpine sable]

Yea

[ionic jewel]

du brauchst Taylor series

[alpine sable]

Wie mach ich das

[opaque frigate]

doki

[alpine sable]

Yes

[ionic jewel]

,w taylor series f(t)= 36.5+3e^(-0.23t)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[opaque frigate]

r u good at equations and inequalities

[alpine sable]

Im alright

[ionic jewel]

I dont know how to say it in german, but the more terms of the series expansion you have, the more accurate it will be

[alpine sable]

Okay

[floral garden]

Je länger die Reihe desto genauer beschreibt dein Polynom die Funktion

[ionic jewel]

danke

[alpine sable]

Danke

@ionic jewel how did u come up with the solution

What did u calculate

[opaque frigate]

can i dm you @alpine sable

[floral garden]

Das Taylorpolynom der Funktion

[ionic jewel]

i mean you can do the math manually, but the one wolfram generated is right

[alpine sable]

@opaque frigate yes

Ist das taylorpolynom eine formel

[floral garden]

Das ist einfach ein Verfahren, mit der man aus vielen Funktionen Polynomfunktion (also mit x hoch irgendwas) machen kann

bzw diese annähern kann

I've actually got a question too, not really related to Taylor series, but rather to the Gaussian distribution and the standard normal distribution.
So I've got my function f(x)=e^(-x²) which is a bell curve (duh), and I want to use it for a Gaussian distribution. For this, my integral from -infinity to +infinity should be exactly 1, but for my function it's sqrt(pi). To adjust for this, I multiplied my function by 1/sqrt(pi). I didn't change the exponent from -x² to -1/2x² like in the the normal standard distribution. This leaves me with a standard deviation of sqrt(0,5) and an unknown expected value µ. How can I figure out my expected value µ from what I already have?

[alpine sable]

Danke michdi btw

[floral garden]

np :)

[alpine sable]

mind if someone helps

[floral garden]

This is what I have, for the normal standard distribution it would be 1/sqrt(2pi), and sqrt(2)*sqrt(0,5) is 1, so that's why it's just 1pi and not 2pi here.

[graceful thorn]

whats the name of the site where you can put a function and it shows it on a graph

[floral garden]

GeoGebra?

[graceful thorn]

Yes!

thx

[floral garden]

https://www.geogebra.org/graphing/

[ionic jewel]

or desmos

[floral garden]

I'm a bit on the fence with this question and I need to figure it out within the next two hours somehow because I did a stupid and left this part of my presentation for the last day, and now I'm stuck with this problem which is probably super easy to solve but somehow I can't get there. I somehow feel like my expected value is sqrt(2), but I can't really prove it because I haven't really ever learnt about the Gaussian distribution and now I need it for my presentation.

[graceful thorn]

also

yea

[willow bluff]

Y’all know stuff about solving for apothems?

[floral garden]

<@&286206848099549185> I tried explaining my question in full detail but some people asked other questions in between I would be extremely grateful if anyone could give me a hint this, I'm a bit lost right now and I really need to figure this out :/

[woeful dirge]

try splitting the pentagon into triangles again. the apothem will be the height for each.

[floral garden]

Ay why do my questions always have to be like this, I'd be very grateful for any hints at all, and I'm glad to clarify my question if there is anything unclear about it 😔

[lilac dragon]

the mean μ will be zero for this pdf too :)

one way to see this is that the equation is symmetric in x, ie. f(x)=f(-x), so in particular it is centred at 0

if you need to prove this fact you could either compare it to the general normal pdf, or use that the mean can be calculated as
[ \int_{\mathbb{R}} xf(x)dx ]

[ocean seal]

adamskiij

[floral garden]

So basically my standard distribution here would be N(0,sqrt(0,5))?

[lilac dragon]

yes

by the way, it is more common to write the variance as the second parameter rather than the standard deviation, but ignore this comment if you've been told to use the standard deviation instead

[floral garden]

Yeah, I haven't been told anything really, I started reading more about the Gaussian distribution yesterday

Hmm, that makes sense, but plugging it into the formula it doesn't make that much sense. Or maybe I'm just mixing things up here

Plugging it in here I mean

[lilac dragon]

ah I see. fair enough. I think distributions are very unfriendly to newcomers

[floral garden]

I know about the binomial distribution but that's about it

Like, with the standard deviation of sqrt(0,5) it makes sense, because with root laws it's the same as the Gaussian distribution, but the exponent just doesn't make sense to me, or maybe I'm still too confused as how to work with this

[lilac dragon]

you can find the mean and variance using that by simply seeing which values of mu and sigma give the equation you have, in this case mu=0 and sigma=sqrt(1/2) will do the job

[scenic oak]

hii quick question, is there a general formula for E(X) in a poisson distribution?

[floral garden]

But then I would have -1/2(0-0/sqrt(0,5))² which wouldn't be equal to -1, would it, or am I just mixing things up here

I'm incredibly sorry if I'm just confusing things all the time, I still feel like there's something to this that I don't quite grasp yet

[lilac dragon]

btw depending on what you're doing, it might be useful to read about algebra of random variables (there is a wikipedia page on this I think)

std deviation definitely shouldn't be negative

[lilac dragon]

yes, it is just the rate parameter (usually denoted lambda)

[floral garden]

Hm no, I just mean for the exponent in general. Like, it's e^(-x²) in my function, and I'm just trying to figure out how I can get there with the Gaussian distribution formula

Maybe it's too basic how I think about it, but pretty much I've got my equation and I'm trying to figure out why it is the way it is 😳

[lilac dragon]

don't worry about not understanding it yet, it's only been a day, people study these things for years, and honestly it'll probably only start making real sense after some measure theory

[scenic oak]

may i link you to #help-9 when youre free?

[lilac dragon]

there is a minus sign in the formula you know

[lilac dragon]

this one

[floral garden]

yeah

[lilac dragon]

the minus sign is there pretty much so that the tails taper off

[lilac dragon]

yes sure :)

[floral garden]

Also for random variables, I didn't know it means what I now know it means (I'm not a native speaker), but I do know about random variables, although the stats lingo still confuses me (even in my native language)

[lilac dragon]

well you're doing the right things to understand them better by asking about them :)

if there is any word or anything in particular that is confusing you, you can ask about it

[floral garden]

I don't need to understand all of it actually. My job is to explain probability density functions, and because before that I'm talking about Taylor polynomials with the function f(x)=e^(-x²) it just makes sense to go from this function, and I managed to get it into the right form for a Gaussian distribution, I just don't know what it describes (like what kind of problem)

So that's why I am trying to figure out the standard deviation and the expected value

Hmm

[lilac dragon]

I see

you might be able to make it easier for yourself by considering much simpler pdfs

for example a continuous uniform distribution

[floral garden]

And I'm worried that my teacher might ask me about why I'm using this function and what it describes, so I figured I'd better try to understand what I'm actually describing with it

[floral garden]

Hmm, the task is

In stochastics, functions of the type f(x)=e^(-x²) are used to calculate probabilities for continuous random variables. Explain the term "probability density" in this context.
So I don't think I can do that :/

[lilac dragon]

ah okay

I can share what my first uni probability prof said about pdfs

[floral garden]

So, I'd just explain what probability density functions are, but preferably with the function I built myself and not the normal standard distribution

That might help!

[lilac dragon]

he said to imagine the number line as a long (infinitely long) plank of wood, and you have a kilogram of marmalade. you can spread the marmalade however you like on the plank. the height of the marmalade at each point on the plank is described by the probability density function. to find the probability that the distribution takes values in an interval, or any other subset of the plank, you measure the mass of the marmalade that is on top of that part (or parts) of the plank, and divide by 1kg

it was a kind of silly explanation but sometimes the funny ones are the easiest to remember 😄

[floral garden]

That's true haha

[iron tartan]

Can someone help me with this.

[floral garden]

Hmm, divide by 1kg given that the marmalade is 1kg in total though :p

[lilac dragon]

hehe well yes, can't report statistics as 600grams of the population 😆

[floral garden]

Hmm, I'm just still trying to think of an example for what my pdf describes. I guess knowing that the standard deviation is sqrt(0,5) helps but ay

[lilac dragon]

your pdf is the density of a normal random variable with mean zero and variance one half

[floral garden]

hmm, makes sense

[lilac dragon]

no need for taylor expansions, for that

[floral garden]

Yeah, I mean I won't use them here, I'll just mention that they could be used because Taylor series are the main part of my presentation

The pdf part should be 5 minutes max

[lilac dragon]

anyway, hope you do well!

[floral garden]

Thank you, and thank you for your extensive help! Really appreciate it!

If I can ever help you with anything language-related in English, German or Spanish just let me know haha, I can't offer much else really

[lilac dragon]

haha thank you!

♥️

[prisma lion]

how do i prove that Σ1/n^3 converges?

[radiant turtle]

sa

[lilac dragon]

this can be done a number of ways. the easiest would be the p-series test. I think you could also use the cauchy condensation test and geometric series.

but, depends on what you've learned really, if this is for an assignment or something, then your profs are probably looking for a certain way that they've taught you

[prisma lion]

no its just used without proof in an exercise an i wanted to see the proof

[lilac dragon]

ah okay I see. in that case, just read about the p-series test. essentially, the harmonic series diverges, but when each term is raised to a power greater than one, it converges.

[lilac dragon]

if you're interested, this is the riemann zeta function evaluated at 3, for which there doesn't exist a closed form, and it is known as apéry's constant

[alpine sable]

General Q that was asked in an oral exam but i don't quite know the correct answer: what happens if i have two equal and opposite dipole on the x axis?
My idea (considering the basic case of 4 charge, all equal in charge and with a - + + - placement) is that the dipoles will try to repell each other while the torque will be 0 as the electric field that i need to consider for each dipole is simply the one generated by the other one and lines are radial on the x-axis.
Is this correct? what other observation i could make?

[prisma lion]

ok thanks i will look it up

[alpine sable]

Do you know anything about sum of 1/n{2}?

[prisma lion]

if you mean 1/n^2 only that it converges

[alpine sable]

with the comparison test you should be able to prove your statement

(i think, really hope i am not saying bullshit, long time not working with this stuff haha)

but no, it works, im pretty sure

[terse merlin]

are you asking a question? @alpine sable

i dont wanna interupt u

[alpine sable]

I will

when @prisma lion is satisfied with the answer

General Q that was asked in an oral exam but i don't quite know the correct answer: what happens if i have two equal and opposite dipole on the x axis?
My idea (considering the basic case of 4 charge, all equal in charge and with a - + + - placement) is that the dipoles will try to repell each other while the torque will be 0 as the electric field that i need to consider for each dipole is simply the one generated by the other one and lines are radial on the x-axis.
Is this correct? what other observation i could make?
And if i'm asked for general dipole (our definition is kinda vague, we usually say p=qd as a vector where q is charge and d distance) i'm right in apporismating all with this case or i can make more general statement only considering the electric dipole moment?

[prisma lion]

ok thanks

[clear portal]

hey if you are done can you help me with a question?

[alpine sable]

It depends on the question lol

I can for sure try 😄

[clear portal]

can you help me find where the zeroes and global max of F(x) are looking at the integral?

[alpine sable]

It's really easy

hit me with the definitio

let's see what are you missing

i don't want to spit number on you

[clear portal]

Well im given the area but how do i find the zeroes of the original function

[stable dune]

can someone help?

[clear portal]

i assumed it would be where the area starts decreasing, but thats not right cuz thats just the zeroes of this current function

[prisma lion]

of which function do you want to find the 0s?

of F?

[clear portal]

yeah

[alpine sable]

Post in a vacant channel, don't post in an active channel. Interior angles in a triangle are supplementary.

[clear portal]

im not sure how though ( i also need to find the global max of F)

[prisma lion]

its probably 0 wherever the sum of the areas equals 0

if the area is above the x axis its +that area and if its below its - that area

[maiden geyser]

could someone help me with this please

[clear portal]

oh okk thank you!

and for the global max?

[twin condor]

10x + 8x + 85 = 180

[prisma lion]

its certainly somewhere where f(x) = 0

not sure where

[clear portal]

yeah im debating between 1 3 and 5

but idk what

[modern ginkgo]

To get the circumference of the circle: 2pi*r
Now, we are given the angles...

For example in number 1, the angle is 80°
Meaning arc AB has length 80°/360° or 2/9 of the circumference of the circle...

But, there are formulas for these probs... wait.

[alpine sable]

how do i do this?

[modern ginkgo]

Please excuse me 😅
Ctto

[subtle bison]

<@&268886789983436800> ^

#rules 😭

[sly mantle]

@iron tartan don't offer cash for hw help

[tame falcon]

We discourage payment for help. Ask your question here, show your effort and someone would likely help for free.

[iron tartan]

my fault

[subtle bison]

This isn't a test, nor is it an exam its just hw
I want to know how to solve Linear systems. I don't understand math very well and virtual teaching dosent help how can anyone help me?

[gray isle]

have you read up on elimination or substitution?

[subtle bison]

uhh I don't think so no sorry

I tried doing it, and got a root of -28, 0

[twin condor]

In a nut shell u find 2 equations and try to cancle a varible

[subtle bison]

there's 2 ys, so I would do y-y on both sides?

that should cancel them both

[gray isle]

wdym by do y-y?

[subtle bison]

removing them both

[gray isle]

no

[subtle bison]

how would I go about starting

[gray isle]

I highly recommend reading up on the basics of substitution

(and copying the equation correctly)

in short, substitution is replacing something with something of equivalent value (add parentheses if needed)

in the first equation x is already isolated and is equal to 2y+56

you can then replace the x in the second equation with (2y+56)

which you can then solve for y

[subtle bison]

Alright so something like this?

[gray isle]

no

that isn't what I said

[subtle bison]

oh I replaced the y

sorry

[gray isle]

also have better spacing between separate equations especially if you plan to write different equations on the same line

[subtle bison]

il use a new sheet

[timid wind]

#bots

[subtle bison]

is this sheet better?

[twin condor]

When he meant space he meant space between the 2 equations

[subtle bison]

oh holdon

[twin condor]

Like for a moment I thought they were one xd u could put a line if too lazy thats wut i do

[subtle bison]

yeah I don't understand why my teacher worded it like that

I don't understand how I'm suppose to find the root of it

[harsh knot]

how in the world did i get this wrong

[twin condor]

a^2 + b^2 = c^2

[subtle bison]

alright I fixed it

more space

[gray isle]

you have a linear equation in 1 variable
simplify and isolate y

[harsh knot]

ohh i was only focusing on the biggest side= or less than the other sides added up

[twin condor]

Yea they should be same value

[quasi cave]

https://andrew.life-is-pa.in/jmvMqv

Can someone help me?

[harsh knot]

last question, what formula do i use for this

[twin condor]

Just look for formula of a traingluar

Nice name since we have to formulas we can either isolate x and replace everything by the value of that x or same ting but with y

@subtle bison

[harsh knot]

wdym

[subtle bison]

how would I go about starting that

what I have right now is

5(2y+57) + 13y = -410

[twin condor]

Just search on google formula of area of traingle

[twin condor]

Correct

[harsh knot]

it is 1/2 base times height but how do i know which side is which

[twin condor]

Now distripute the 5

[sand lichen]

Fredreka wrote 2/5 of her report in 1 h. How much time will she need to complete the entire report at this rate?

[twin condor]

Not 100% sure but i rember( AB + BC ) / 2

[subtle bison]

5-5(2y+56)+13y = -410 -5

like this?

[twin condor]

No distripute means mutiply

[subtle bison]

5x5

on both sides?

or x 5 on both sides

[twin condor]

No we have 5 ( 2y +56)

[subtle bison]

yes

[twin condor]

So 5 times the practe

So 5 x 2y + 5 x 56

[harsh knot]

im still lost it didnt work

[twin condor]

Imma cheack da rule 1min

Then we use AH + BC / 2

How we find h? Well we change it to a right traingle

[subtle bison]

10y + 280 + 13y = -410

?

[twin condor]

Yea

Now whats 10y + 13y ?

@subtle bison

[quasi cave]

Can someone help me?

[twin condor]

@harsh knot

[quasi cave]

https://andrew.life-is-pa.in/jmvMqv

Help?

Please?

[oak chasm]

@quasi cave Sorry, channel is busy.

[quasi cave]

Rip

[twin condor]

@quasi cave

[quasi cave]

?

[twin condor]

681/1000

[quasi cave]

Thx

Ye but than u have to suptract

[twin condor]

Does the black dots mean we can ignore?

[quasi cave]

subtract*

Black dot

means

[subtle bison]

23

[quasi cave]

reacurring

[twin condor]

Correct so we have 23y +280 = -410

Take 280 to other side

23y = -410-280

@subtle bison

[alpine sable]

is this room occupied

,help

[ocean seal]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[alpine sable]

,list

[ocean seal]

My commands!

Use ,ls to obtain a briefer listing, and use ,help <cmd>to view detailed help for a particular command, or ,help to view general help.

If you still have questions, talk to our friendly support team here.

Meta

View or set meta-information about me.
​ ​ ​ ​ ping: Check heartbeat and API latency.
​ ​ ​ ​ help: Bot and command usage information.
​ ​ ​ ​ list: Lists all my commands!
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Page 4/4

[unborn pagoda]

hey sorry if this is occupied but does anyone know how to solve this?

"list the sample space for drawing a marble from a bag containing 2 red, 3 blue, and 1 white" LMAO

[quasi scarab]

A sample space is a collection or a set of possible outcomes of a random experiment.

[subtle bison]

oh

alright

so

wait but the question is

[twin condor]

Find x and y ?

[subtle bison]

its a linear problem

I need to find the root I'm pretty sure

which one is it

[unborn pagoda]

.. so would it be RBW.. lol

[twin condor]

Let us continue where we stopped xd

23y = -410-280

23y=-690

So y = -30

And we have formula of x

X is 2y + 56

So x = -30 x 2 + 56

X = -4

[subtle bison]

ohhh

[twin condor]

@subtle bison

[subtle bison]

thank you alot

so basically

I have to isolate the variables first

[twin condor]

Yea

Xdd

[subtle bison]

question number one out of nine finished lol

thank you

[alpine sable]

you done?

[subtle bison]

probably for a bit

go ahead don't worry

[alpine sable]

Alright heres my integral

this is painful

[twin condor]

Its isnt if u dont know wuts integral to beign with xd

[alpine sable]

i wanna integrate this

ur saying u can integrate this easy? if so tell me how because my brain has turned to mush figuring this out

[twin condor]

Ask someone else i have no idea havnt studied it yet

Am saying i dont know wuts integration to begin with 😂😂

[alpine sable]

Alright well thanks then ill just repost it for the next person to see it

Need help with integrating this

[gray isle]

express tan(x) as sin(x)/cos(x)

then u sub

and partial fractions

[alpine sable]

sub what?

[gray isle]

integration by u-substitution

[alpine sable]

subbing u for what tho?

cosx?

[gray isle]

yes

[jade stratus]

How do you do that

[alpine sable]

so i get to -1/(u(1+u^4)) i think

how do i partial fraction this?

because the A(1+u^4) term i cant set =0 because u^4 needs to equal -1

,partial fraction decomposition \frac{-1}{u(u^{4} + 1}

[ocean seal]

You must be a bot manager to use this command!

Jun 1, 2021, 5:27 PM

[alpine sable]

,w ,partial fraction decomposition \frac{-1}{u(u^{4} + 1}

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by The Torrent#5588

[alpine sable]

$\frac{-1}{u(u^{4} + 1}$

[ocean seal]

The Torrent

[alpine sable]

$\frac{-1}{u(u^{4} + 1)}$

[ocean seal]

The Torrent

[alpine sable]

,w partial fraction \frac{-1}{u(u^{4} + 1)}

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by The Torrent#5588

[gray isle]

should be able to equate coefficients

of the decomposition

[alpine sable]

with what?

[gray isle]

with your expression

[alpine sable]

-1 = A(1+X^4) + B(X)

[gray isle]

no

[alpine sable]

with my expression?

no?

$\frac{-1}{u(u^{4}+1)} = \frac{A}{u} + \frac{B}{1+u^{4}}$

[gray isle]

the numerator of your fraction with a denominator of (1+u^4) will be up to degree 3

[ocean seal]

The Torrent

[alpine sable]

oh

how would i fix that?

[gray isle]

write a general degree 3 polynomial in u

[alpine sable]

i dont know what that means i dont think

[gray isle]

write a degree 3 polynomial in u with other variables representing the coefficients and constant

[alpine sable]

i fully dont know what that is, is this like a new method of doing partial fractions?

[gray isle]

no

it's not

[alpine sable]

does it like have a name or anything so i can watch a video? because im not sure how to write a degree 3 polynomial in u

or do you just mean B should say Bx^3 + cx^2 + cx + e instead of B

[gray isle]

yes. that

but you used c twice

maybe also be consistent with your capitalisation

and your variable here is u not x

[alpine sable]

oh yea alrighttt, hmmmmmmmmmm one sec lemme scribble some stuff down

and once i got a big 3rd degree polynomial with A B C D and E in it

where do i go from there?

[gray isle]

write what you have

[alpine sable]

oh wait no its degree 4 isn't it

well once you replace B with the Bu^3 + cu^2 + du + e

then do you multiply it all by u(u^4+1) like normal i assume?

[gray isle]

yes

and then equate coefficients

[alpine sable]

with what?

should i expand it out fully first?

[gray isle]

with the original expression

collect like terms etc

[alpine sable]

the original expression was 1/ though

[gray isle]

yes

[alpine sable]

and it was litearlly just -1/u(u^4+1)

[gray isle]

wdym?

compare the coefficients of your decomposition with your original expression

[alpine sable]

(A+B)U^4 + CU^3 + DU^2 + EU + A

and im comparing that with -1/u(u^4+1)

[rustic kiln]

Can I get help after you’re done with them?

[gray isle]

and that would need to be equivalent to -1 (for all U)

[alpine sable]

(A+B)U^4 + CU^3 + DU^2 + EU + A = -1
Compared With
-1/
u(u^4+1)

cant lie no clue how to do that

so the A coefficient is 0 i assume

[gray isle]

whit?

[alpine sable]

theres a u^-5 term in the original so im like wut