#help-0

1 messages · Page 640 of 1

plucky crow
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then the area of the side parrallelogram twice

vale wigeon
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you have six faces here

plucky crow
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ann can explain

vale wigeon
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two trapezoids and four what appear to be rectangles

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this is a right trapezoidal prism right?

small holly
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what the flippy is a trapezoid

vale wigeon
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a shape with one pair of parallel sides

small holly
#

these words are too big

vale wigeon
#

sometimes called a trapezium

small holly
#

i only know trapezium

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YES

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THAT THING

vale wigeon
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yeah

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so you have two of those as faces

small holly
#

wait ill type you what i did please correct me

vale wigeon
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oh

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you should include that next time, makes the helpers' job this much easier

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anyway, brb for a few mins but im still here

small holly
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(12.5^2)+(9.2x5.3)+(6/2(9.2+12.5))+(6/2(12.5+5.3))

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=323.51

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way off the answer

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im pretty sure its somthing wrong with the trapezoids

ornate yarrow
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Anyone here knows matlab?

vale wigeon
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@ornate yarrow i do, but we'll need to move to another channel

ornate yarrow
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Which one ?

vale wigeon
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@small holly are you told that the top face is a square?

small holly
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im guessing it is

vale wigeon
ornate yarrow
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Ok

small holly
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wouldnt they have just given me another integer if it was a rectangle

vale wigeon
#

hold up

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the depth of the prism is 5.3

cursive moth
#

can someone help me write a reflection

small holly
#

wait whats the depth

vale wigeon
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okay i might have to go now

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but uh. try not to kill two birds with one stone ig

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work out the area of each face separately THEN add them up

small holly
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alright

oak chasm
#

It has Fibonacci numbers in the answer.

n:           0  1  2  3  4   5   6   7   8    9   10
fib(n + 1):  1  1  2  3  5   8  13  21  34   55   89
fibcalls(n): 1  1  3  5  9  15  25  41  67  109  177

How does the fib(n + 1) line change to the fibcalls(n) line?

harsh acorn
#

Are there easy way to solve this question without hard force?

stark rampart
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this is a contest problem right?

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i remember this is hkimo

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is that right?

oak chasm
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@alpine sable What does r stand for?

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OK, what's n?

harsh acorn
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My country will be in first time

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anyway

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do you know how to solve this easily?

oak chasm
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@alpine sable It's the number of parts you're dividing the year into.

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How many parts are you dividing the year into if it's quarterly?

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No.

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That's how big a part is.

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How many parts?

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Right.

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So, n is 4.

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What's t?

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No.

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What does t stand for?

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No.

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Right.

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Do we know how many years?

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Right.

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What's P?

safe robin
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what are the points of discontinuity for this

clever locust
#

Ask somewhere else, this channel is busy

oak chasm
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@alpine sable Right, what's A?

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Nope.

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Close.

left gate
oak chasm
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A is the total amount you have after t years.

left gate
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How do I draw the graph

oak chasm
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@left gate Sorry, channel is busy.

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No.

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What's the total amount you expect to have at the end?

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What?

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Do you understand how bank accounts work?

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Do you know what principle and interest are?

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Principle is the amount you first put in a bank account.

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Interest is the extra money the bank gives you.

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Principle plus interest is the amount you have after a certain amount of time.

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Yes, A is the amount you have after a certain time.

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It's the principle plus the interest.

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Right.

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So, what's your formula with the variables you know filled in?

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Right.

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So, how do you solve for t?

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No, I don't mean to ask a computer to do it for you, because that won't teach you how to do it.

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I mean to use algebra to do it.

ocean sealBOT
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Chai T. Rex

oak chasm
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What can you do to get rid of part of the right side so that we're closer to t by itself?

frigid hatch
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bro?

twin condor
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Divide by 400 so its a bit simpler

small holly
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you divided P by itself (400/400) so it cancels it out

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and what you do on one side you do to the other

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so it becomes 2300/400 = (1+0.07/4)^4t

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ok then

twin condor
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U can even make simpler by cancling the 00 so its 23/4 = the rest

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Why? Xd

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We are simplifying it we didnt find the answer yet tho

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Lemme cheack ma methoed since am not 100% sure

clever locust
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Take the logarithm of both sides to move down the exponent

harsh acorn
oak chasm
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@unborn leaf Sorry, we don't help with exams.

harsh acorn
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@unborn leaf it is occupied

oak chasm
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<@&268886789983436800> exam @unborn leaf

sly mantle
#

ty

fading citrus
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👍

harsh acorn
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what a speed lol

sly mantle
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@alpine sable knock it off

clever locust
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It's either use the logarithm or let the computer do it for you

harsh acorn
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btw, @alpine sable are u done with your question?

tame shell
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they are done with their question stare

harsh acorn
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Can i solve this question without hard force?

oak chasm
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What does the range mean?

harsh acorn
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maximum value- minimum value

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which equals to 70

clever locust
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How far from the mean it can be?

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Or no

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Nevermind

harsh acorn
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you mean median?

clever locust
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Read that wrong

oak chasm
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@harsh acorn Well, I solved it, I think.

harsh acorn
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Can you explain me how did you solve?

oak chasm
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Well, the lowest number is 70 less than the highest number.

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So, you want the lowest number to be somewhat high.

knotty sleet
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Did you get 138

oak chasm
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No, I got lower.

knotty sleet
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Oh

oak chasm
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Oh, now I've got 141.

knotty sleet
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Does nine 68s, fifty 69s, sixty 70s and 138 work

oak chasm
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Oh, I can't be right on the 141.

knotty sleet
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😅

harsh acorn
knotty sleet
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Max is 140

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And if the minimum of your set is 69 you can only get to 129

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Or 127 or something

harsh acorn
oak chasm
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Right, that's what I got to.

knotty sleet
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So then try setting minimum to 68

harsh acorn
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okay, can someone explain me properly please ;p

knotty sleet
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Okay right sry

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So you know 70 needs to be attained

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Cause it's the mode

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If 70 is attained and the range is 70 then the maximum element can't be greater than 140

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But if your smallest element is 70 then the restrictions force everything to just be 70

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So then try smallest is 69, and you want the numbers to be as small as possible so that the max can 'balance' it out by being large

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Listed in order it has to be 59 numbers, then two 70s, then 59 more

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So if smallest is 69, and you want the sum excluding the max to be the smallest possible, you'd have fifty-nine of 69s, and sixty of 70s

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Then the mean =70 condition gives the max element can only be as large as 129

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So now we know that 139 is impossible because it requires the minimum to be 69, which we showed can't work

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Then we try minimum is 68 and hopefully we can construct 138

harsh acorn
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Okay, I didin't understand the part that 140 is the maximum possible value

knotty sleet
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which we can

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Would you agree that 70 needs to be in the 120 numbers

harsh acorn
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yes

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it is occupied

knotty sleet
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So in the extreme case, 70 is the smallest

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Then the range is 70, so 70+70=140

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...I haven't done something completely stupid have I

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hopefully not...?

knotty sleet
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Does this make sense??

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@harsh acorn Are you still there

harsh acorn
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still thinking to understand

knotty sleet
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Oh cool 🙂

harsh acorn
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@knotty sleet Can u explain again that why it is not possible to be 69-139

oak chasm
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Solve for x.

ocean sealBOT
#

Chai T. Rex

harsh acorn
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Oooh that's right

knotty sleet
#

Thanks @oak chasm 😄

oak chasm
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No problem.

ocean sealBOT
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Chai T. Rex

knotty sleet
#

For 68, you can say, let there be n of 68, and (59-n) of 69, and sixty of 70s, add 138 and set the sum of all that to 70*120 and solve for n which gets 9

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Exactly^^

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How did you change the background colour?

oak chasm
#

,texconfig colour

ocean sealBOT
#
Configuration options for `colour`

Your LaTeX colourscheme.
​ Current value: Using the light colourscheme
​ Default value: Using the grey colourscheme
Accepted input: One of the colourschemes listed below.

Colourschemes

​ ​ ​ ​ ​ ​ white: Pure white background, with black text.
​ ​ ​ ​ ​ ​ light: Very light grey bckground, with black text.
​ ​ ​ ​ ​ ​ ​ grey: Discord-grey background, with white text. (Recommended)
​ ​ ​ darkgrey: Dark grey background, with white text.
​ ​ ​ ​ ​ ​ ​ dark: Dark background, with white text.
​ ​ ​ ​ ​ ​ black: Pure black background, with white text.
transparent: Transparent background, with white text. (May cause issues)
trans_black: Transparent background, with black text. (May cause issues)

knotty sleet
#

I've always wondered

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Oh wow

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Wait so what's the command to change it?

oak chasm
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,texconfig colour light

ocean sealBOT
#

You have switched to the light colourscheme.

knotty sleet
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Ah that's cool

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Thank you! 🙂

oak chasm
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No problem.

harsh acorn
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"Given that the mean, median, range of 80 integers are also 45. If A is the largest integer among those 80 integers, what is the maximum value of A?"
so the maximum value is 90
90 cant be it bcs 45,45 (79times), 90's mean is not 45 obv.
89 cant be it bcs 44, (39 times),45 (40 times),79's mean is not 45

knotty sleet
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,texconfig colour darkgrey

ocean sealBOT
#

You have switched to the darkgrey colourscheme.

oak chasm
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@knotty sleet You can test out all the combos in #latex-testing. See what they look like.

harsh acorn
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now, when i check 88, will be numbers like 43,44 (38 times), 45 (40 times) and 88 or 43, 45 (78 times), 88?

oak chasm
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@harsh acorn Remember, there's no mode here.

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You don't need 40 instances of 45.

harsh acorn
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oh

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i tought it was same as last question

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How would numbers be in A=88?

oak chasm
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,w solve (a 44 + (79 - a) 45 + 1 89)/80 = 45 for a

ocean sealBOT
oak chasm
#

So, that's not going to work.

harsh acorn
oak chasm
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Well, it misinterpreted.

harsh acorn
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and can I determine it is wrong without big calculations?

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I mean, another way

oak chasm
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,w ((a*44) + ((79 - a)45) + (189))/80 = 45

ocean sealBOT
oak chasm
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There's the solution.

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But it doesn't work.

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It needs 44 instances of 44, which means the median will be 44, not 45.

harsh acorn
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so answer is 88

oak chasm
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,w ((a43) + (b44) + ((79 - a - b)45) + (189))/80 = 45 && a + b < 40

ocean sealBOT
oak chasm
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,calc (5 * 43 + 34 * 44 + 40 * 45 + 1 * 88)/80

ocean sealBOT
#

Result:

44.9875
oak chasm
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Oh.

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,w ((a43) + (b44) + ((79 - a - b)45) + (188))/80 = 45 && a + b < 40

ocean sealBOT
oak chasm
#

There.

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,w (443 + 3544 + 4045 + 188)/80

ocean sealBOT
oak chasm
#

@harsh acorn There, that's a solution.

harsh acorn
#

Given that the mean, median, range, and the only mode of 300 integers are also 168. If A is the biggest integer among those 300 integers,what is the maximum value of A?

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i get 166

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I want to check that I understand the concept

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@oak chasm

oak chasm
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If the median is 168, there must already be integers higher than 166.

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For example, 168 is one of the integers which is higher than 166.

harsh acorn
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Oh my bad

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i wanted to say 334

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not 166

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166 is the smallest value

oak chasm
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Well, let's try to get 335.

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,w (a*167 + (299 - a)168 + 1335)/300 = 168

ocean sealBOT
harsh acorn
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so it is not 335

oak chasm
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Looks like it is. Let's see.

harsh acorn
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,w (a166 + (299 - a)169 + 1*334)/300 = 168

harsh acorn
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uhm did i do wrong thing?

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or is it false too

oak chasm
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,calc 299 - 167

ocean sealBOT
#

Result:

132
oak chasm
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OK, so it can't be 335.

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Let's try 334.

harsh acorn
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what does 299 represent there?

oak chasm
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,w (a166 + b167 + (299 - a - b)168 + 1334)/300 = 168 && a + b < 150

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299 is count of the numbers that aren't the max.

harsh acorn
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so what does it mean

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I didn't understand it

ocean sealBOT
oak chasm
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There.

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,w (17166 + 132167 + 150168 + 1334)/300

harsh acorn
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nono i mean what does it mean now? is 334 right? I didin't get anything from bot's answer

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s answer

ocean sealBOT
oak chasm
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So, there's a solution.

harsh acorn
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Oh good I think i get the concept

woeful ridge
#

Hello for this question

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I answered d. But the correct answer is B. How can you solve that?

gray isle
#

consider the locations of the peak and trough

clever locust
#

Notice that the distance between the peak and the trough will be half a period

woeful ridge
#

Ah okay ty

worldly void
rich fractal
#

Hi, sorry if this is a dumb question (I think it is) but I've just started learning maths and my instructor has just said this:

"every fraction has three signs associated with it.

One out in front one in the numerator and one in the denominator.

And you can change any two signs of the fraction without changing the value of the fraction and sometimes

that can be useful"

So can I literally change any 2 of 3 signs? Could I change one of denominator, one of numerator ? or one of the front and one of denominator? or one of front one and one of numerator ?

oak chasm
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@rich fractal Yes.

gray isle
#

instead of blindly changing signs, you should understand the reasoning behind it.

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i.e. multiplication by something equivalent to 1

worldly void
oak chasm
#

Look at the input and the response.

rich fractal
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@gray isle

worldly void
#

oh

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kk

rich fractal
gray isle
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$\frac ab \times \frac{-1}{-1} = \frac{-a}{-b}$

ocean sealBOT
#

ℝamonov

gray isle
#

$-\frac ab = \frac{-a}{b} = \frac{a}{-b}$

ocean sealBOT
#

ℝamonov

muted nymph
#

question is this correct

alpine sable
#

guys quick question

muted nymph
#

wait i asked first

alpine sable
#

in double integrals, is the outer integral written with respect to the first d or the second d

glass lichen
alpine sable
#

ok ty

muted nymph
#

anybody able to confirm for me

versed osprey
#

what is the mid point between 15.8 and 21.8 on a measuring scale

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im getting confused

small holly
muted nymph
alpine sable
small holly
glass lichen
#

I don't officially know, I believe it's outer and outer.. but I could be wrong

muted nymph
#

ok

glass lichen
alpine sable
#

aight ty

versed osprey
#

its a 20 mark project

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wait

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i got an idea

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bruh

glass lichen
#

just find the average. ..

versed osprey
#

yeah

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bruh

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wtf

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lemme go reset my brain

zealous garnet
versed osprey
#

so 18.8?

alpine sable
cloud kiln
#

How is sin AOP’ = M’P’/OP

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angle POP’ is a right angle

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M’ and M are right angles too

fervent holly
zealous garnet
cloud kiln
#

How is sin AOP’ = M’P’/OP

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<@&286206848099549185>

alpine sable
stable pecan
cloud kiln
vague coral
#

projection

stable pecan
#

angle AOP' = angle POP' + angle AOP

cloud kiln
#

Yes

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POP’ is right angle

stable pecan
#

yup

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so sin(AOP')= sin(angle POP' + angle AOP)

cloud kiln
#

Yeah what is sin(AOP’)

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My book says M’P’/OP but why

cloud kiln
#

Do not use sum formula

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Not established yet

stable pecan
vague coral
cloud kiln
#

You’re proving that thing..

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How can u use it..

vague coral
#

He should try it by doing some projection or something

stable pecan
cloud kiln
#

They have given that in the proof that sin(AOP’) = M’P’/OP

fervent holly
#

can anyone help with this?

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i got 6,11

stable pecan
vague coral
#

the triangle OMP rotates by 90 degree to get P'M'O

cloud kiln
#

Let me send pic of the expanation

vague coral
#

sin POA = MP/OP
sin (POA+ 90) = -cos(OP'M') = -OM'/OP'

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OP' = OP

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🤔

cloud kiln
vague coral
#

-OM' = MP

cloud kiln
#

yes

vague coral
#

sin (AOP + 90) = MP/OP

cloud kiln
#

No

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M’P’/OP

vague coral
#

I'll try again

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wait

cloud kiln
#

Battery low i’ll have to figure this out on my own

wet fulcrum
#

i think you should blur out your name first

fathom rain
#

850/3 + 11/3y = 375

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i know i gotta multiply both sides by 3

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but do i do it twice or just once?

glass lichen
#

why do it twice?

fathom rain
#

well first for 850/3 then 11/3 right?

glass lichen
#

what?

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no

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multiply both sides by 3, done

fathom rain
#

but doesnt that only get one division out of the way but there's two of them

glass lichen
#

distributive property

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$3(a+b)=3(c) \implies 3a+3b=3c$

ocean sealBOT
wary stream
fathom rain
#

so like if its 700/3 + 400/3 + 293/3 + 544/3 = 500 do i just multiply both sides by 3 once?

ionic jewel
#

yes

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thats the same as $700+400+293+544 = 500(3)$

ocean sealBOT
hearty gazelle
#

How to prove that it is an ideal T?

alpine sable
#

hello, can you help me to find the remainder of 207! when divided by 209 ?

sinful monolith
#

do i divide by 1000?

clever locust
#

To get from cm^3 to liters? Yes

pseudo summit
#

400020

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can this number exist?

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in binary system

clever locust
median creek
clever locust
pseudo summit
#

lol

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i think i complicated it too much

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my logic was wrong

pseudo summit
wary stream
# pseudo summit 400020

Are you asking if this number can be converted to binary or is this number a valid binary number?

nocturne carbon
#

Can someone help me please

wary stream
nocturne carbon
#

1

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I don’t understand how to find 2 angles with 1

wary stream
#

It says to measure each angle

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Not just one

nocturne carbon
#

How without dot paper my teacher aid

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Said

wary stream
#

Use a protractor

clever locust
nocturne carbon
wary stream
alpine sable
#

i think this channel is free

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so imma take it

#

f(t)=3⋅(0.95)^t, 0<t

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how can i find the derivative of this

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i already treid

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saying that the outer function is: 3x^t

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and the inner: 0.95

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but then when i use this (f(g(x)))’=f’(g(x))⋅g’(x)

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g’(x) becomes 0

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cause constants are 0

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and the whole thing becomes 0

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cause its multiplied

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im doing something wrong

wary stream
#

No need for chain rule

nocturne carbon
alpine sable
#

oh ok

nocturne carbon
#

In the 2nd question

alpine sable
#

oh shoot

alpine sable
wary stream
#

Rewrite the decimal as a fraction

gray isle
#

consider expressing 0.95 as e^ln(0.95)

alpine sable
#

alright ty guys

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ill try and see if i figure it out

marsh summit
#

can someone help me figure out how to solve this?

gray isle
wary stream
alpine sable
wary stream
alpine sable
#

oh wow

#

t

ocean sealBOT
#

dldh06

alpine sable
#

y

#

ty

gaunt coyote
#

iam not even clicking anymore

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lol

nocturne carbon
gray isle
#

it's an isosceles triangle

clever locust
#

I think this channel is busy, so ask in another one

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@gaunt coyote

nocturne carbon
#

Okay I thought it was done since they said ty

gaunt coyote
#

already did 🙂

clever locust
#

Great :)

royal ruin
#

How do I go about solving this

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I know the right answer as I looked it up but I can’t figure out how to get said answer, and I have a test tomorrow so I need to figure out how to do it

alpine sable
#

i dont know:&

gray isle
#

BE is the altitude relative to DC

ebon mica
#

If you know BE and BC, you can use Pythagorean theorem to find CE

gray isle
#

area you able to apply distance formula to calculate the length of DC?

marsh summit
#

can someone help me with this

royal ruin
#

Yes

gray isle
#

and then apply formula for the area of a parallelogram

royal ruin
#

It got the length of AB is the square root of 16

#

I

ebon mica
wicked axle
#

I managed to find the ground velocity

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but not sure how to calculate the bearing

gray isle
royal ruin
#

Actually might be 14

ebon mica
gray isle
#

how are you getting 14

wicked axle
#

where |r| is 462.54

#

hoping thats correct at least

ebon mica
#

I don't think this diagram is right

wicked axle
#

what about it is incorrect?

ebon mica
#

You want to label the 210-degree angle and the 50-degree angle

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It's hard to visualize where the 160-degree angle came from even though I know it's the difference between them

wicked axle
#

oh ok

#

i used microsoft word

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and so i did the minimal amount of labelling :/

ebon mica
#

Try to use Paint or something

royal ruin
wicked axle
#

would it be this angle?

gray isle
#

that's a complete mess. that's not representative of the distance formula

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also issues with how ur applying the sqrt

ebon mica
wicked axle
#

sry im confused

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isnt that wind blowing FROM 50degrees?

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so it would be going southwest

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i think?

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if im understanding the q properly

ebon mica
#

You need to draw a point as your origin. I assume the question is saying the wind is blowing northeast even though I'm not entirely sure, but that's based on the past similar problems I've seen.

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I mean I'm not sure based on the wording. But I've seen a bunch of problems like this before.

wicked axle
#

here's an example from the online notes im using

ebon mica
#

Yes, you have to draw it just like that. See how they have the coordinate plane with the origin in the middle? And all the vectors are coming out of the origin.

wicked axle
#

oh ok

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i figured the triangle formed by the two vectors was the only relevant information

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and thought i could find the resultant angle based on that

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since I was able to find the magnitude

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ok so say we were using the above example, how would I find the resultant angle?

ebon mica
#

Draw a vector from the origin at 210 degrees and magnitude 420. This is the airplane. Then draw another vector from the origin at 50 degrees and magnitude 45. Then draw the third vector with the tail at the wind and the head at the airplane. Determine the angle and magnitude of the third vector.

#

I don't think the 160-degree angle you got earlier is correct because the difference between vectors doesn't work like that. You can't just subtract one angle from the other to get the answer.

wicked axle
#

so is it just coincidence that I got the magnitude correct?

#

this is my work for the magnitude

ebon mica
#

I didn't check if your magnitude is correct

wicked axle
#

cause i used the 160degrees in there

ebon mica
#

Don't use the 160 degrees for that

#

I don't think that's right

#

You can use the distance formula to get the magnitude

#

You don't need law of cosines

wicked axle
#

for the distance formula wouldnt you need to find the x/y components first

#

the question says to use geometric vectors as opposed to cartesian vectors

#

so i assumed they didnt want us to use the distance formula

#

cause that would involve cartesian vectors

ebon mica
#

I think we should use the same vectors as the one in the example notes

wicked axle
#

in the example they also used cosine law

charred girder
#

Hey ! Can someone explain wilson theory to me ..Everytime i think i understand i find out that i have absolutely no idea how to solve the problem

ebon mica
#

The airplane is going at 420 (-cos 30 i + sin 30 j), wind is blowing at 45 (cos 50 i + sin 50 j)

charred girder
#

Sorry for interrupting

wicked axle
#

it looks like in the example the blue angle is what they are using as the resultant angle

#

based on theta in this diagram

#

i just find this all really confusing

#

i suck at vectors

ebon mica
#

Resultant vector should be (-420 cos 30 - 40 cos 50) i + (420 sin 30 + 45 sin 50) j

#

To find angle of resultant vector do tangent, to find magnitude do Pythagorean theorem

wicked axle
#

yeah im pretty sure that is a way to do it

#

but im just trying to follow how the notes are doing it

#

and im getting quite lost

ebon mica
#

I think the notes are doing it the same way I am doing it. There is really only one way to do it that I can think of.

wicked axle
#

but in the notes they used cosine law to find magnitude

#

and then sine law to find the bearing

#

and im also not sure how that specific angle is representative of the bearing

ebon mica
#

Oh, I see now. I see how they use law of cosines. But you could also find it without law of cosines.

wicked axle
#

i just want to do it the same way they are

#

in case i lose marks or something

ebon mica
#

Yes, it looks like they have three angles and two vectors, and they want to find the resultant vector based on that.

wicked axle
#

but how do we know theta here is the resultant angle

#

and not this for example

ebon mica
#

It takes practice to figure out

wicked axle
#

not sure what you mean :/

ebon mica
#

If you do enough of those problems and make enough mistakes, eventually you will learn

wicked axle
#

what?

#

so there's no logic here?

#

no intuition or anything?

#

that doesnt make much sense

ebon mica
#

So my trick is try both scenarios and see which one makes sense

#

You know whether you want the bigger angle or the smaller angle

wicked axle
#

that seems so odd to me

#

you would think there would be a definite way of knowing which the resultant angle would be

ebon mica
#

There probably is but I'm not very good at it

#

So I just plug and chug

wicked axle
#

yeah fair enough

#

thanks for the help

lime gorge
#

Quick request , can someone help me with 12 hw geometry questions? It’s a lot, so we can take it to dms if possible

lime gorge
#

<@&286206848099549185>

woeful pulsar
livid mesa
#

hey guys how do I solve problems with this method? I dont understand the book's explanation

#

This is the original problem

rain lake
#

dividing d dollars by a apples gives the price for 1 apple. This is then multiplied by 20, as the question asks, to find, in terms of an expression, that 20d/a is the amount of dollars for 20 apples. I'm assuming the word apples is stricken out to simplify the expression and to show that d/a = the price of an apple.

#

I apologise if that's not helpful. I'm new.

livid mesa
#

It is really helpful and I do appreciate it, but I still don't understand the way the book did the problem, was hoping someone could elaborate on how that method works.

glass lichen
#

$a\text{apples}=d\text{dollars}\implies \frac{a\text{apples}}{d\text{dollars}}=1$

ocean sealBOT
glass lichen
#

so you get a conversion factor for units of apples and dollars

alpine sable
#

a car costs 10,2000 and depricates in value by 5% per year. How much will the car be worth after 5 years?

#

does anyone know this?

#

my calculator is fucking up

woeful pulsar
alpine sable
#

after 5

woeful pulsar
#

yeah

alpine sable
#

i have two different answers

woeful pulsar
#

if you can do the 1 year, then repeating 4 more times you should get the answer

alpine sable
#

is it 7892?

woeful pulsar
#

that looks too small

#

does the car really cost 102000?

alpine sable
#

thats what it came out to

#

10,200 lmfao

#

oops

#

added an extra 0 srry

woeful pulsar
#

oh 10200, yeah, that looks about the right magnitude

last sinew
#

Hi, is this channel soon to be unoccupied, or will it be in use for a while?

alpine sable
#

alright thanks!

#

yeah im done

#

u can use it

last sinew
#

Oh, thank you!

#

I'm having trouble with question 2b, the answer is in the second attachment, could somebody please explain the answer? Thank you :)

woeful pulsar
#

so far you got that?

last sinew
#

Yes

#

That's what's being used in a) right?

woeful pulsar
#

yeah

last sinew
#

Okok yes i got that

woeful pulsar
#

so for B we have to do a very similar thing

#

to come up with the distribution of times

last sinew
#

Yes

woeful pulsar
#

do you see how we can get the $P\left(z<\frac{-5+m}{6.403}\right)$?

ocean sealBOT
#

Element118

last sinew
#

Uhh

#

Sort of?

woeful pulsar
#

or is that part somewhat unclear?

last sinew
#

Like i sorta dont get why (5-m) is the new mean

#

That's the part that's stopping me

#

^^,

woeful pulsar
#

so originally it's 30-25

#

but now the 30 guy is now going m minutes earlier

#

so it's (30-m)-25

toxic dust
last sinew
#

Ah

toxic dust
#

For curve sketching what do I do after this

last sinew
#

Thing is though, how does going early help make you faster? I thought they were asking for difference in walking times

woeful pulsar
last sinew
#

Like you still take the same amount of time

woeful pulsar
last sinew
#

But you just go earlier xd

#

Ohh

woeful pulsar
#

originally they leave at the same time

last sinew
#

Ok

#

Im clear now i get it

#

Thank you so much

toxic dust
#

But I also have to find second derivative aswell

alpine sable
#

I need help

woeful pulsar
#

and see the behaviour near that

alpine sable
#

I need help on a answer

woeful pulsar
woeful pulsar
ocean sealBOT
#

Element118

alpine sable
#

8

#

Number 8

woeful pulsar
#

do you understand the question?

alpine sable
alpine sable
#

Because 10x3 is 30

woeful pulsar
#

how about 20? 30? how do you check?

alpine sable
#

Because it say 3 fruit a day

#

10 barbaloots

#

10x3

woeful pulsar
#

yeah

alpine sable
#

Which meant they can eat from that time for 2 days

woeful pulsar
#

but we are looking for one day here

alpine sable
#

Oh yeah

woeful pulsar
#

because the next day it the same thing happens

alpine sable
#

Yes

#

I UNDERSTAND

#

It I think

woeful pulsar
#

nice

#

show your work?

alpine sable
#

Yes

#

They want me to find how many barbaloots can eat off of 1 tree

#

??

#

Am I right?

woeful pulsar
#

yeah

#

the maximum number that can

alpine sable
#

29

#

20**

#

I meant 20

#

No

#

21**

#

Is the answer

woeful pulsar
#

want to show how you got that?

alpine sable
#

Sure

#

Like I said I said they want me to find out how many can eat off of 1 tree then I look back it say 3 fruits PER DAY and there 63 and each tree but we talking about 1 tree here so then I do 63/3 equal 21

#

I also did 3/21

#

3x21 I meant

#

Sorry

woeful pulsar
#

yeah 63/3=21 yeah

alpine sable
#

Yes

woeful pulsar
#

and you can see $3\times21=63$

ocean sealBOT
#

Element118

woeful pulsar
#

yeah looks good

alpine sable
#

Thank you so much

harsh quartz
#

I need help answer

charred flint
#

sin(theta) = opposite / hypotenuse

harsh quartz
charred flint
#

all of them

harsh quartz
#

Oh that's all the answer?

charred flint
#

yea

harsh quartz
#

Oh tysm

charred flint
#

oops fixed

gray isle
#

um

#

wtf are these triangles

#

there are major issues with the lengths

#

these aren't remotely close to right triangles

harsh quartz
gray isle
#

you should probably clarify the questions

#

those right angle markings look so dodgy too

#

have you started stuff like cosine law yet?

harsh quartz
#

Cause our lesson is trigonometric ratios

gray isle
#

ugh..
i guess your best option here would be to erase a random side length from each triangle

#

actually I'll choose which one to remove

#

that'll let you use a different ratio for each question

alpine sable
gray isle
#

have you been introduced to sohcahtoa yet?

harsh quartz
gray isle
#

consider googling that

#

for a quick intro to trig

harsh quartz
#

Kk

woeful pulsar
#

wait a minute

#

those aren't even right triangles

#

@harsh quartz @gray isle something's wrong with the diagram

gray isle
#

yeh i pointed that out

woeful pulsar
#

oh lol

gray isle
#

hence that erasure to at least make the problem make some sense

tropic willow
#

Could someone explain how to do this again?

#

I forgot all about it

#

We did this in like January

warm canopy
#

Sure

#

They want the length of the highlighted section?

tropic willow
#

Arc Length

warm canopy
#

Its just circumference *angle/360

glass lichen
#

not +4

warm canopy
#

Tis -4

alpine sable
#

Whats the answer

warm canopy
alpine sable
#

the journey is just as important, maybe even more important than the "answer"

#

how did you figure it out

tropic willow
alpine sable
ocean sealBOT
alpine sable
#

Can I post another one

tropic willow
#

Holy

#

No way I’m getting this

#

Finding circumference is

oak chasm
#

@tropic willow OK, you have arc length, right?

tropic willow
#

Of this one or the first one I sent

oak chasm
#

This one.

#

You don't have arc length for the first one.

next linden
#

🏳️‍🌈 HAPPY PRIDE MONTH🏳️‍🌈

oak chasm
#

@tropic willow What's an arc?

alpine sable
#

🏳️‍🌈 HAPPY PRIDE MONTH🏳️‍🌈

oak chasm
#

@alpine sable Sorry, channel is busy.

tropic willow
#

how do you math people do this..

alpine sable
tropic willow
#

I don’t actually study but I do well

alpine sable
#

thats very good

tropic willow
#

Math not so much there’s some stuff I do amazing in math

alpine sable
#

you will not be able to sustain this in grad school

tropic willow
#

Anything to do with circumference I just suck at

oak chasm
#

@tropic willow Do you know what an arc is?

tropic willow
#

Yes and no

#

I know what it looks like but

#

Can I guess the answer and say it’s 60

oak chasm
#

OK, so an arc is a part of the circumference, right?

tropic willow
#

Should be

oak chasm
#

OK, so you have an arc and its central angle, right?

tropic willow
#

Yeah

oak chasm
#

OK, so the arc length is the central angle's portion of the whole circle times 2 times the radius.

ocean sealBOT
#

Chai T. Rex

tropic willow
#

Ohhhhhhhh

oak chasm
#

This is like the circumference formula.

ocean sealBOT
#

Chai T. Rex

tropic willow
#

Why am I so stupid

oak chasm
#

The circumference is the arc length when the central angle is 360 degrees.

ocean sealBOT
#

Chai T. Rex

#

Chai T. Rex

tropic willow
#

Um

#

It’s not 60 is it

oak chasm
#

@barren torrent Sorry, channel is busy.

#

@tropic willow Yes, that's right.

tropic willow
#

Chai please don’t pixelate me

oak chasm
#

,calc 360/132 * 22

ocean sealBOT
#

Result:

60
tropic willow
#

Maybe I’m not dumb

oak chasm
#

This stuff isn't about being dumb, it's about how much you know.

tropic willow
#

very little

#

But thank you so much

oak chasm
#

You're welcome.

gray oasis
#

can anyone answer a question about if a time series is stationary or not?

oak chasm
#

@gray oasis Sorry, channel is busy.

#

@tropic willow Are you done with the channel?

tropic willow
#

Well I have one more

oak chasm
#

OK, go ahead.

tropic willow
warped carbon
#

Michael currently 45$ has in savings. He had been saving 9$ each week. Yesterday he spent 126$ of the savings. For how many weeks had he been saving? i need help what is the equasion

oak chasm
#

@warped carbon Sorry, channel is busy.

warped carbon
#

k

ocean sealBOT
#

Chai T. Rex

oak chasm
#

@tropic willow ^

#

It's how much of the total angle of the circle you have times the circumference.

tropic willow
#

Is it

#

4.29..?

oak chasm
#

It is.

tropic willow
#

Tysm Chai T . Rex

#

Sorry I was so slow for answering questions

#

And thanks for your time

oak chasm
#

You're welcome.

gray oasis
#

@oak chasm chan free now?

oak chasm
#

@tropic willow Are you done with the channel?

tropic willow
#

Yup

oak chasm
#

@gray oasis OK, go ahead.

gray oasis
#

is this likely to be a stationary time series?

#

ACF and PACF of it below

#

v new to time series etc etc

calm kiln
#

This correct?

alpine sable
#

yes

#

is there a way to use dot product and find a vector perpendicular to two other given vectors?

#

ik i can use a system of equations, but i have the two vectors (0,3,4) and (2,0,0)

#

so some of the terms are 0, how can i find a perpendicular vector to these two

alpine sable
#

ive only learned dot product so far

#

is there a way to do it with dot product?

glass lichen
#

no

alpine sable
#

oh

#

my teacher trolling :((

glass lichen
#

oh you can do 2 equations 2 unknowns is my guess

alpine sable
#

for dot product between w and u, i get 0=3y+4z

#

and w dot v, i get 0=2x

#

x has to be 0

#

idk abt the other two

wary stream
# alpine sable

If you're referring to number 10, if you know how to find the null space, that's how you do it

alpine sable
#

how can i do that?

wary stream
#

Do you know what null space is?

alpine sable
#

no?

wary stream
#

Is this linear algebra?

alpine sable
#

this is vectors, im not sure if it's linear algebra

#

we jus started the unit

wary stream
#

Do you know matrix reduction like RREF?

alpine sable
#

no not yet

wary stream
#

So the best option that I can tell you to is how solve it, divide the u vector by 3. This is to create a pivot row, set it equal to y

#

Or j

#

The free variable, meaning that it can any value, is going to be k/z

#

You already know x/i, so plug in any value for k/z to find a suitable j/y

#

And that vector is is w

alpine sable
#

oh, but isnt x/i =0

wary stream
alpine sable
#

lemme try it

grave cradle
#

I have an algebra eoc tmr what is the best review packet/paper that shows stuff that will be in it

#

since I rlly would appreciate if there is like a packet/paper reviewing the important parts during algebra 1

wary stream
grave cradle
alpine sable
#

3/3=1, so 1/y?

#

4/3/z = 4/3y?

#

3z=4y? is this what u mean?

marsh summit
#

can someone help me?

wary stream
noble smelt
#

hey @wary stream could you help me in #help-1

alpine sable
ocean sealBOT
#

ffaizy

alpine sable
#

is this not it?

wary stream
#

You have it as the reciprocal, you don't need to do that

alpine sable
#

$y=\frac{3z}{4}$

ocean sealBOT
#

ffaizy

alpine sable
#

4y=3z?

wary stream
#

Forgot the sign

#

It's originally u = 3y + 4z, set it equal to zero, solve for y

#

So 3y + 4z = 0

#

And so y = -4z/3

pine herald
#

is getting a result with a sum of 7 from a 6 sided die an example of an event, a sample space or a statistical experiment

alpine sable
#

oh so that's the ans?

#

y=-4z/3

wary stream
#

Now plug in any value for z, so get y

pine herald
#

oh srry

#

didnt know it was in use

wary stream
#

To prevent fractions

alpine sable
#

oh i see

#

so we get (0,-4,3) right

#

as w

wary stream
#

So in this case, x = 0, y = -4, and z = 3

wary stream
paper minnow
#

Hey weird question here, but is there any work done for functional fixed points? (If that even makes any sense) That is, a function/set of functions which under some operation has that function as an output? Like how e^x gives itself under the derivative operation

wary stream
#

And you can double check by doing the dot product of w and u and w and v

charred flint
#

eigenfunctions

alpine sable
#

but the ans has (0,4,-3)

paper minnow
#

Oh lol, I completely forgot about eigenfunctions 🤦‍♂️

wary stream
carmine bronze
#

`Find the indicated roots. Express answers in trignometric form.

  1. The square roots of 4(cos90+isin90)`

Help?

alpine sable
#

oh i see, thanks a lot

wary stream
charred flint
#

@carmine bronze do you know how complex number multiplication adds the angles?

alpine sable
#

i forgot there is more than 1 possibility

carmine bronze
#

I'm learning de moivre's theorem rn

wary stream
alpine sable
#

ah yes

#

thanks

lime gorge
#

Need some help here

woeful dirge
# lime gorge

use tangent on the triangle. set up an equation where tan55 is on one side and see where it takes you.

lime gorge
#

Ty

wary stream
lime gorge
#

Rounded to 714.1

woeful dirge
lime gorge
#

This one is sin?

wary stream
#

What sides are you given?

lime gorge
#

A side and two angles

#

90 degrees and 37 degrees

wary stream
#

What two sides of the right triangle

lime gorge
#

The base and side

#

Not the hypotenuse

#

So it’s tangent again?

wary stream
#

What's that base and side called in respect with the angle?

lime gorge
#

Opposite and adjacent

#

No?

#

So tangent

wary stream
#

And yes it's tangent

lime gorge
wary stream
#

Nope

#

You wrote the ratio wrong

lime gorge
#

I did tan 37 * 6

wary stream
#

What is the ratio for tangent?

lime gorge
#

Opposite over adjacent

wary stream
#

And what form did you have it in?

lime gorge
#

So 6/X?

wary stream
lime gorge
#

But how do I get that?

#

With the angle provided

#

I do know the last angle is 53

#

Using basic algebra

wary stream
#

So you have $$tan(37) = \frac{6}{x}$$, correct?

ocean sealBOT
#

dldh06

lime gorge
#

Yes

#

How do I solve that?

wary stream
#

How would you find x?

lime gorge
#

That’s what I need to know lol

wary stream
#

If you had $$10 = \frac{6}{x}$$ what would you do to find x?

ocean sealBOT
#

dldh06

lime gorge
#

10/1

#

Wait no

#

Hmm idk 😬

#

10/1=6/x?

wary stream
#

Multiply by x on both sides?

lime gorge
#

oh

wary stream
#

Then divide by 10?

lime gorge
#

So 10x?

#

10x and 6x?

#

10x=6x/x

wary stream
#

It wouldn't be 6x

lime gorge
#

Ohh yeaaaaa

#

Because it takes away the x below it

#

So 10x= 6?

wary stream
#

Then?

lime gorge
#

Then subtract ?

wary stream
#

Why would you subtract?

lime gorge
#

4x=0

#

Wait that makes 0 sense

wary stream
#

But the 6 and 10x aren't combinable

lime gorge
#

So how do I do it then?

wary stream
#

Well how would you solve for x?

lime gorge
#

If I knew that I’d be happy 😂

#

I forgot it

#

Multiply both sides by 6?

wary stream
#

What other operations are there?

lime gorge
#

So 36= 60x?

wary stream
#

Why multiply by 6?

#

Does that get x by itself?

lime gorge
#

Oh divide by 2! Yes?

#

So 3 = 5x

#

That makes it smaller

wary stream
#

Not by two

#

How do you want 10x to just be x?

lime gorge
#

Divide by 10?

#

But that makes no sense

#

Then it’s 1x = .60

wary stream
lime gorge
#

Could that be right?

wary stream
#

Yeah, it's a decimal. And this was an example I gave you

#

Not the actual problem

lime gorge
#

I know lol

wary stream
#

So do the same process for that

lime gorge
#

Tan (37) = 6/x

wary stream
#

So step one?

lime gorge
#

How do u deal with the tan?

#

Or ignore that?

#

And act like it’s normal numbers?

wary stream
#

It's the same process as the 10x

lime gorge
#

So tan (37x) = 6?

wary stream
#

No

#

The x doesn't go inside

lime gorge
#

So tan (37) (x) = 6?