help-0

[hybrid patio]

Oh I get it now

Thanks for the helo

help.

[quaint trout]

Okay, can you answer your own question then?

The last two answers are just nonsense because they need 4 answers for multiple choice lol.

It's a yes or no question so answer with yes or no.

[hybrid patio]

yep, I believe the answer is no.

[quaint trout]

Yep

Gj

[hybrid patio]

ty

[smoky barn]

a2b+ab2-ab=?

can someone explain how to solve this please?

[ionic jewel]

does this mean $a^2b+ab^2-ab$?

[ocean seal]

bunny

[smoky barn]

yes

[ionic jewel]

i mean you could factor out an ab, but that doesnt make it much nicer

what are you supposed to do with it

[smoky barn]

my teacher told me to solve it without any more instructions

[ionic jewel]

well I dont believe that has any meaning in this context, so I think there is nothing for you to do

[smoky barn]

oh okay then

[ionic jewel]

best you can do is some factoring that may or may not actually make it simpler

[smoky barn]

okay I’ll try to factor it out

[hollow axle]

How 2 solve this?

[stark lantern]

I think you'll just have to find the first and second derivative, substitute them in the expression. Doesn't look like there's any short method

[strong furnace]

if you have learned about radius of curvature that expression represents that

for a circle it would be constant

but they probably want this through derivative so go through the thing

[main slate]

Hi, I have a little problem

If x is in Z, then (x(x-1))/2 is in Z too

But i don't know how I can prove it

[strong furnace]

this is false for x = 1

but other than that

[oak chasm]

What do you mean by the natural numbers? Do they include zero?

[strong furnace]

casework for even odd should be pretty simple

[main slate]

my bad, it s not N but Z

[main slate]

it s Z, not N, my bad

[main slate]

i don't really see how i can do it

[oak chasm]

@main slate You have two factors in the numerator. Is one of them even?

[alpine sable]

Is the amount f ways that i can arrange the word COFFEE 6!/2! * 2!?

[strong furnace]

you can use the closure propert of integers

[oak chasm]

@alpine sable Sorry, channel is busy.

[strong furnace]

you just have to show x/2 or (x-1)/2 is an integer

[main slate]

wdym ? one is even, the other is odd

[main slate]

ah ok

[oak chasm]

@main slate So, if you divide an even number by 2, it's an integer, right?

[main slate]

yep

[oak chasm]

So, you have an integer times the odd integer.

[main slate]

ah ok

[alpine sable]

Is the amount f ways that i can arrange the word COFFEE 6!/2! * 2!?

[ionic jewel]

yes

[oak chasm]

@alpine sable Is that 180?

[ionic jewel]

,w 6!/4

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[ionic jewel]

yes it is

[oak chasm]

OK, then it's correct.

[steep jasper]

Think this is linear algebra question: Making a game, implemented a way to look around in 3D space successfully without really understanding the camera direction vector. I understand that the Y component depends on the sin(pitch). Why is the pitch relevant for the X and Z components? Using the x component for example, https://gyazo.com/8067ac48a82202bd1fda6822f9c372fa

[spark shadow]

Can I get some help

[woven dock]

Hello Pratham_GG#2134 I'm glad that you didn't ping helpers immediately after you asked the question this time :D

[paper parrot]

Does anyone have a bit of time to help me with maclaurin transformations? (generally)

[alpine sable]

Stop cheating on stupid jee tests

[lavish mango]

https://gyazo.com/8505308b59f9d58b1beb65117422e480

[short dagger]

limit x->6, x<6

limit would be 5 here i assume ?

[spark shadow]

This is not test

[lavish mango]

would this be for my question?

[frigid stream]

Yes

[short dagger]

@frigid streamwhat would it be if x was bigger than 6 instead of smaller?

[frigid stream]

It would still be 5 too, do you understand why? @short dagger

[short dagger]

i assume because the only defined point at x=6 is 5

[night ice]

Guys can u help me with this

[frigid stream]

What do you mean by "the only defined point at 6"?

[short dagger]

a connected dot or something similar

[frigid stream]

That's not really the way to see it, what matters if what value you approach at x = 6 (from the left or from the right)

In either cases you approach 5

However the function has value 2 when x=6 , that is f(6) = 2

[woven dock]

is it A?

[short dagger]

so for example x->1 would have a different value from x->1 ,x>1 ?

im sure x->1 ,x>1 is not defined

[frigid stream]

The left or right limit at x=1 exist and have a value

It is not defined at x=1 only

[short dagger]

x>1 would be -2

i guess

[frigid stream]

For the limit, yes

[spark shadow]

A what ?

[short dagger]

@frigid streamto calculate the derivative

is f'(x)=4g'(x)g(x)x^2 a good answer ?

thats the closest thing i got lol

[frigid stream]

No it doesn't look good

You need to use product rule

[short dagger]

g'(x)+4x^3 g(x) 🤔 ?

[woven dock]

The answer, is it A? I've been thinking for 15mins :D

[frigid stream]

Almost, the second term should be seen indeed

[hybrid patio]

Could anyone help me with this question?

[frigid stream]

But for the first one you should get g**'**(x) x^4

[frigid stream]

The channel is occupied

[hybrid patio]

what does that mean?

[frigid stream]

It means someone is already asking questions here, go in another channel below where no one is talking

[hybrid patio]

oh ok

[frigid stream]

Channel 8 looks empty

[hybrid patio]

ok i will go to channel 8

[short dagger]

do we also use product rule for f(x)=cos(g(x)+h(x))

[frigid stream]

No, there's no product here

[short dagger]

o

[alpine sable]

C

or A

not B

[hybrid patio]

Its A

[plush shuttle]

It would be A right? Because Rise over Run

[hybrid patio]

Sorry, but you're right, but how do i do rise/run to answer this question?

[plush shuttle]

Well it rises by 3 for every 1 it goes along the x axis, so that’s the 3x part

Then the last part of the equation is just the y intercept

[short dagger]

if we want to optimize this using 400ft of fencing

for a maximum area

[woven dock]

You mean like x+x+y+y+y=400

[hybrid patio]

Sorry, but I dont get that, isn't it increasing by 1 on the x - axis

[short dagger]

yeah

[woven dock]

Can you use graphs to solve? lionheart

[short dagger]

not sure about that

[frigid stream]

Write y in term of x

And use derivatives

I think that's how it's meant to be solved

[woven dock]

Oh,okay I was solving graphically

[hybrid patio]

wait i get it nvm

I read it carefully and I got it

[plush shuttle]

Ok then

[vagrant jetty]

guys i need help

[plush shuttle]

Oops didn’t mean to reply to that message

[vagrant jetty]

whats the a, h, and k in y=x^2

this is harddd

[plush shuttle]

I had a question like that in an exam a few years ago and I think we used parabolas to solve it

[woven dock]

Oh right!

[plush shuttle]

The maximum on the parabola is the most efficient use of fencing iirc

[woven dock]

Very clever @plush shuttle

[plush shuttle]

¯_(ツ)_/¯

[short dagger]

would there be a better maximum than 60,205 ?

[woven dock]

And I guess the answer is x=100,y=66 and 2/3

Let's say

We have
2x+3y=400
And
2xy=A where A is the area

Then sub the 2nd eq.into the first one

And we got quadratic

[plush shuttle]

I can’t remember anything else about these kind of questions but yea that makes sense

[flat pollen]

hello does anyone know how to find the directrix and focus of x^2=4py

[flat pollen]

<@&286206848099549185>

[woven dock]

Dunno if this helps
https://www.mathsisfun.com/geometry/parabola.html

[flat pollen]

nah not really

it's asking for focus point and directrix

[spark shadow]

Can you give explanation

[steel flax]

could someone explain this for me

[late tundra]

try taking derivative of tanx

[steel flax]

got it, thanks.

[patent lynx]

Hey, I am trying to find the curvature of a spline, and I got to this formula, where B(t) is the spline function, given t, it will return the point on the spline for that t, B'(t) is the derivative and B''(t) is the second derivative.

Now, the article talks about 2D splines, and I want to convert the formula to 3D, how I can approach this?

https://pomax.github.io/bezierinfo/#curvature

By the way, this is the article I am reading from, this is the section on Curvature

[woven dock]

It is because Object A has initial velocity u with 0 acceleration and Object B has initial velocity 0 accelerated by gravity.
So the speed of B will gradually reach u, and then the string will become taut....
Wait...... I think I was wrong. But to think of when the distance travelled by A is equal to the distance travelled by B, the string will be taut.... So I may have to calculate it again, oh gosh

[patent lynx]

<@&286206848099549185> Can someone help me please?

[runic dock]

i did it but my answers are incorrect

[quick talon]

is age or temperature the independant variable

[runic dock]

?

[quick talon]

plz help

[vital lichen]

lol

we will need more context

[mellow marlin]

How do u do this?

[quick talon]

me?

is age or temperature the independant variable

[vital lichen]

Do you know what an independent variable is?

I suggest you google that :)

[quick talon]

yes

[fringe robin]

m=-4/5?

[vital lichen]

It will help you more than we can help you

[quick talon]

I just need conformation if i have right anwser

[vital lichen]

Its impossible to know the right answer, it depends on your context. Since you keep asking this question, its convincing me that you don't know what the independent variable actually is

[quick talon]

Temperature is dependant on the age of the child so temperature is dependant and age is indipendant

its the normal temperature for a child of different ages

[vital lichen]

Yup, sounds good then

[quick talon]

ok

tysm

[vital lichen]

all goods 🙂

I didnt help much tho haha

[quick talon]

and is that continus or descrite

[vital lichen]

depends, discrete means it can only be constricted to a finite set of values

continuous means it can be infinitely many values (like all the real numbers between 0-10, i.e. 0.0385494895... etc.)

[quick talon]

well it uses temperature and age

[alpine sable]

bruh help me

[quick talon]

@vital lichen ???

[vital lichen]

again, depends on the context

can a child be 12.9454584958 years old? Or can they only be 12 years old in your context

[oak chasm]

@vital lichen Discrete means noncontinuous. It doesn't mean finite. For example, the integers are discrete, but not finite.

[vital lichen]

Ah, my bad

[quick talon]

so if it says the temperature is 20.9 degrees then that is continus correct

[mellow marlin]

Anyone knows solution?

[fringe robin]

50 as i told in the other channel 🐾

[rotund lance]

^

if AB is a diameter, arc ADB is 180 degrees

[vocal obsidian]

Can anyone help?

[fringe robin]

d<0

[vocal obsidian]

?

[fringe robin]

d=b^2-4ac

since no real roots d<0

[drowsy scroll]

Is this channel in use

[fringe robin]

nope

[drowsy scroll]

So how do I plot the second equation
https://i.gyazo.com/1c3a04566986ecf6235c57a0a6b8ea52.png

$y = 2x - 4$

-*

[fringe robin]

well you could find two coordinates and join the line

[ocean seal]

Quadro

[drowsy scroll]

what do i do with 2x, I need a run

there is only rise

[fringe robin]

?

[drowsy scroll]

rise and run

do u know about that

[alpine sable]

The rise is 2 and the run is 1

2/1 = 2

[drowsy scroll]

ok

[alpine sable]

you rise two squares for every increment in x by 1

[vocal obsidian]

Can you show working out for this question please, i understand b^2 - 4ac but dont know how to apply?

[drowsy scroll]

https://i.gyazo.com/87072ea541926361fb8cde8b78b6f886.png

This?

Did I do it right

[fringe robin]

channel in use bruh

[alpine sable]

yeah

[drowsy scroll]

ok wait what do I write for the solution it is not exact. this is what I mean
https://i.gyazo.com/c6b658a0e428925bb19dfa037d8c160c.png

[alpine sable]

ooh

you need to find the solution of the two?

[drowsy scroll]

ye

like where they intersect

[alpine sable]

can you show me the two equations?

[drowsy scroll]

when the 2 lines meet

ok

[alpine sable]

you can solve using elimination

[drowsy scroll]

https://i.gyazo.com/ac3acc7a77999df391f564079c4c81d1.png

[alpine sable]

alright

What I would do

is

multiply the top equation by 2

2y = -x + 6

ir

or no

[drowsy scroll]

what is ir

[alpine sable]

Are you trying to find x?

multiple the first equation by 4

[drowsy scroll]

trying to find where the 2 lines meet

[alpine sable]

4y = -2x + 24

[alpine sable]

Ah alright

the bottom one is still y = 2x - 4

what I would do next

is add them up

5y = 20

y = 4

[drowsy scroll]

yes u solved for y

right

[alpine sable]

substitute 4 into second equation

4 = 2x - 4

2x = 8

x = 4

so

(4, 4)

[drowsy scroll]

4 4

[alpine sable]

is the intersection

[drowsy scroll]

bruh this thing isnt teaching me this

:(

[alpine sable]

wym?

[drowsy scroll]

The homework site doesnt teach this, it just give the problem

and expects you to solve it

[alpine sable]

hmm

well

If you need help, my dms are open.

[drowsy scroll]

ok

[vital tree]

help

please and thanks

[frigid stream]

Show your work

[vital tree]

?

[frigid stream]

Have you tried something so far

[vital tree]

nah my teacher is out today and we havent gone through this material yet

[frigid stream]

Then if you haven't learned it in class you can't do it

[vital tree]

i literally know the concept

😐

[frigid stream]

Then what are you stuck on?

[vocal obsidian]

Curve has equation y=4x^2 - 5x, the curve passes through the point (2,6). Use diffrentiation from first principle to find the gradient at P?

can anyone show step by step working out for this?.

[vocal obsidian]

Curve has equation y=4x^2 - 5x, the curve passes through the point (2,6). Use diffrentiation from first principle to find the gradient at P?
can anyone show step by step working out for this?.

[sullen osprey]

The area ?

[stable dune]

can someone help?

[alpine sable]

Still need help

[alpine sable]

Wouldn't you just move the points right 2 then down 4

[winged quail]

*left not right

[sullen osprey]

@alpine sable yea

[alpine sable]

Yeah sorry

[alpine sable]

First figure out the area of the large rectangle

[knotty tiger]

Help please

[alpine sable]

Do you know what Pythagorean theorem is

[knotty tiger]

Kinda do yes

i dont get the concept perfectly though

[alpine sable]

a^2 + b^2 = c^2

[knotty tiger]

alright

yeah thats the formula

[alpine sable]

C is the hypotenuse

So in this case

3^2 + x^2 = 5^2

[tall sage]

how would I do this?

[knotty tiger]

oh ok

thank you

[alpine sable]

Remember multiply it by 2

[haughty bronze]

can someone help :/

[alpine sable]

Im unsure, I think it would probably be B but

I would crop out the final test next time

[haughty bronze]

why?

[alpine sable]

● Do not cheat on tests or exams. Do not be academically dishonest. Do not offer money for doing homework assignments, and vice versa.

[haughty bronze]

oh okay

[icy trail]

how do you find the location of a median, do you do
frequency/2
or
(frequency +1)/2

[vocal obsidian]

+1

[wooden anchor]

Hi, can someone pls tell me if its alright?

[fathom matrix]

yeah

they are

equivalent.

if you wanna check, go to desmos and type the functions in to see if theyre equal

i keep getting -13/5 i.e 2.6

but when i graph that shit, it seems mor elike 2.75

[unreal dune]

Can someone help me with this question? An international company has 11,500 employed in one country. If this represents 32.8% of the company’s employees how many employed does it have in total

[fathom matrix]

this channels busy

[unreal dune]

Oh alright

[alpine sable]

u have to use the law of cosines to prove SAS.

[fathom matrix]

<@&286206848099549185>

[alpine sable]

idk abt that but i think ur answer wrong cuz x aint between 1 and 2

[fathom matrix]

😐

M is the output that the function within the inequality is supposed to be less than for the x values between 1 and 2.

@alpine sable

[alpine sable]

It is secant if the radius is more than the line right

[alpine sable]

Look at the x and then the y (oops wrong tag)

What does x -> x1 go to and y->y1

What do the numbers look like

[rugged lynx]

help

[alpine sable]

first turn 2 1/2 into 5/2

[rugged lynx]

ok

[alpine sable]

Then turn it into 10/4

[rugged lynx]

what about 10/4

ok

[alpine sable]

Now find 3/4 of that

[rugged lynx]

10/4-3/4= 7/4

this channel is occupied

go to a different channel

[naive rune]

OOPS

[alpine sable]

Not minus

[rugged lynx]

wait what

[alpine sable]

She poors 3/4 of the whole bottle

[rugged lynx]

ohhhh

i get it

[alpine sable]

How can i find the value of SSW, i have the N=20, k=4 (group means =>m1=4, m2=8, m3=12, m4=7) and SSB=22 . Starting from SST=SSB+ SSW.

[rugged lynx]

so 1 7/8?

[versed perch]

Ignoring the first line how to derive the given equation.

[charred flint]

steradians is the % of sky taken up by the star

the star's visible area is pi*R^2

[alpine sable]

I think

[charred flint]

the total sky would be the giant sphere up to how far the star is away

surface area is 4pi*r^2

[alpine sable]

15 / 8 - 3/8

So 12/8

= 3/2 = 1 1/2

[charred flint]

the textbooks seems to be off by 4pi though

[lapis fjord]

Can i get some help

[alpine sable]

Guys, if the line is less than the radius on a circle its a secant rght

[versed perch]

@charred flint if the visible area is pi*R/2 still will not get the desired result

[charred flint]

you mean pi*R^2

[versed perch]

yes

[charred flint]

not sure what your objection is

[versed perch]

@charred flint I know angle in steridians or the solid angle is the area of the projection of the star on the sphere divided by the square of the distance from the star . So even if area is Pi * R^2 result will not be the same as given in the textbook.

[charred flint]

I see, yea I disagree with the textbook by a factor of 4pi

[versed perch]

@tight birch I think its right

[cyan saddle]

Hi I have a doubt

I was trying to solve this question

I haven't solved such a question before

I wanted to know if my approach is conceptually right

Is this acceptable?

[charred flint]

that's right

[cyan saddle]

and for the product things, I can use the same concept, but with a multiplication thing instead?

[alpine sable]

anybody know statistics?

[charred flint]

yup

[cyan saddle]

x=8 * root x?

[cyan saddle]

thanks a lot!!

[charred flint]

x=8sqrt(x) is wrong I think

oops nvm it's good

[cyan saddle]

why do you say so?

[cyan saddle]

oh ok no issues

once again thanks for your help

👋

[alpine sable]

If a the line is less than the radius in the circle, is it a secant?

[unkempt talon]

hola

[vital mulch]

I am trying to understand the proof at the beginning of this paper: https://people.math.ethz.ch/~sudakovb/zero-forcing-sets.pdf. Specifically I don't see how the statement im going to post as a screenshot follows, and I dont understand their notation for the entries of x.

[pastel mauve]

i need help

<@&268886789983436800>

[sly mantle]

👢

[noble turret]

Oop-

[pastel mauve]

good

[pastel mauve]

i need help with this pls

[noble turret]

I can't help you there sorry🙇‍♀️

Maybe someone else

[vital mulch]

@pastel mauve What work have you done so far

[pastel mauve]

i dont remember how you find the inverse

i learned it like 2 months ago

[vital mulch]

To find the inverse, solve for r in terms of V

[alpine sable]

I have a question on math which I could not solve it

I have done this but not sure if it is correct <@&268886789983436800>

[sly mantle]

@alpine sable don't use the mod ping for hw help

[violet hemlock]

Please don't ping mods for this

[gray gorge]

[tall wing]

[pastel mauve]

😆

[alpine sable]

sorry

Hey can some one make me understand how to do this question plz :)??

[oak chasm]

@alpine sable See the side the two small triangles share?

[alpine sable]

Yes

[oak chasm]

OK, look at the right small triangle.

It has a right angle and another, known, angle.

It also has the bottom side.

Use the other known angle and the bottom side to get the shared side.

[pastel mauve]

👍

[haughty bronze]

i forgot how to do this ;C

[pastel mauve]

i think you just

find the square roots and add them? according to the choices

[haughty bronze]

just so i know what im doing

P would be 3 right?

[pastel mauve]

L is a rational number

yes

M is also a rational number

N and P is not rational

[haughty bronze]

P is rational bc its 3

[pastel mauve]

wait a sec

[haughty bronze]

4 is rational

[pastel mauve]

im dumb

[haughty bronze]

bc its 4

i meant N is rational

[pastel mauve]

i thought rational numbers were

like

3.233333333333

yk

[haughty bronze]

no thats irrational

yea

[pastel mauve]

crud my bad

[oak chasm]

No, that's rational.

[pastel mauve]

what

[haughty bronze]

3.23333 is not rational

[oak chasm]

Rational numbers have decimal representations that end or repeat forever.

[haughty bronze]

its unpredictable tho it cant be rational

[haughty bronze]

its 2333

not

33333

[pastel mauve]

tahts useless

[haughty bronze]

that would be rational

[pastel mauve]

wait

[oak chasm]

There's nothing in it that indicates what it does after the numbers it says.

If you want to go that way.

So, when you say that it's random, you have nothing to base that on.

[haughty bronze]

it just depends of if its predictable r not which the question dictates ig

[pastel mauve]

L and M are rational so I would assume it would be choice A

[oak chasm]

No, it deponds on whether it ends or repeats the same few digits.

[pastel mauve]

^

[oak chasm]

Pi is predictable since we can get all digits in it.

But it's not rational.

[haughty bronze]

https://media.discordapp.net/attachments/490557019623915520/846440068473421884/unknown.png

its C tho

bc

4+3

it has to be C

[pastel mauve]

oh

yea

its C

[haughty bronze]

yea imma just go with that

[pastel mauve]

L and M were irrational

and NP rational

👍

[haughty bronze]

ngl this question

i have no idea

what to do

[pale terrace]

I don't think velocity is relevant

if this is not a physics question

[hardy bobcat]

i think you just have to equal h(t) to 0 and solve for t

[pale terrace]

you need to simply set the equation equal to nine and solve for t

[haughty bronze]

its an algebraic question

[pale terrace]

yeah then if you set the equation to 9 and solve for t you should find your answer among the choices

[haughty bronze]

i really would do this question by myself but i am so confused do you think you could help me do it?

[pale terrace]

yea no worries

[haughty bronze]

it explains the equation in the middle i am so lost i appreciate it

[pale terrace]

they tried to confuse you by giving you irrelevant information about the softball's velocity

[oak chasm]

It's not irrelevant. It shows up in the equation.

[vagrant jetty]

its a real life example

[oak chasm]

Note the 5 and the 9 in the equation.

[pale terrace]

all you need to do is ignore that and solve for this equation: 9 = -4.9t^2 +5t + 9

[pale terrace]

oh then I was mistaken

[oak chasm]

No, they want it when the height is zero, not 9.

[haughty bronze]

that equation makes no sense to me

[oak chasm]

The ground is at height zero.

[haughty bronze]

lmao fist bump

[pale terrace]

my fault sorry

[oak chasm]

@haughty bronze The h(t) is the height at time t.

[hardy bobcat]

just solve -4.9t^2+5t+9=0, when h(t)=0 the distance is 0 and when you find t you find how many seconds it takes for the distance to the ground to be 0

[oak chasm]

What's the height of the ground? 0, so h(t) = 0

So, the formula for h(t) is also equal to 0.

So, you have -4.9t^2 + 5t + 9 = 0

That's a nice use for the quadratic formula or some other method.

[haughty bronze]

but they said the height starts at 9 meters im so confused

[oak chasm]

That's where the + 9 in the formula comes from.

When you do h(0), you get -4.9(0)^2 + 5(0) + 9, which is 9.

So, at time 0, height is 9.

Which is what the problem says.

But the problem doesn't ask what the height is at the start.

They tell you the height they want is zero.

Then they ask what time that happens at.

[haughty bronze]

idk if im dumb for not understanding anything you just said but, i didnt understand anything you just said

[oak chasm]

OK, if you hold a softball in your hand and throw it up into the air, it'll eventually hit the ground, right?

[haughty bronze]

"h(0), you get -4.9(0)^2 + 5(0) + 9, which is 9." this doesnt make sense to me at all smh i should've payed attention in class

[haughty bronze]

yup

[oak chasm]

OK, when you start, you're holding it in your hand, which is above the ground, right?

[alpine sable]

f

v

v

v

vg

gf

s

dg

fd

[oak chasm]

<@&268886789983436800>

[alpine sable]

BRO IDK UNDER STAND THIS

can some one help me

[pale terrace]

this channel is in use

there is a better way you could have asked

[sly mantle]

@alpine sable stop spamming and ask your question in an unoccupied channel

[haughty bronze]

bro chill

[alpine sable]

sorry

[alpine sable]

ok

[haughty bronze]

chai T rex is explaining something to me ask questions in a different tab

[alpine sable]

how do ik what unoccupied

[fading zephyr]

you read the time stamp of the last message

and see if anyone is currently typing

[alpine sable]

ok

thank u

[oak chasm]

@haughty bronze So, let's say you take a video of you throwing the softball in the air and waiting until it hits the ground. You put it on YouTube. You know how you can stop the video at any timestamp?

[haughty bronze]

yea

[oak chasm]

@alpine sable Sorry, channel is busy.

[muted raft]

don't spam please?

[oak chasm]

@haughty bronze So, if you stop it at 3 seconds timestamp, you can see how high the softball is.

And if you stop it at 5 seconds, you can see how high the softball is then, and so on, right?

[haughty bronze]

yes

[oak chasm]

OK, the h(t) is something that tells us how high the softball is at a timestamp.

Does that make sense that we might have a formula for it?

[haughty bronze]

yea that makes sense

[oak chasm]

OK, so we want to know what timestamp it is when the softball hits the ground.

So, the height of the softball will be zero.

So, our height formula will give an answer of zero at some timestamp, right?

[haughty bronze]

yes

[oak chasm]

That timestamp will tell us when the softball hits the ground.

So, the formula gives out zero, which is written h(t) = 0. The height the formula gives is zero, so it's hitting the ground.

[valid herald]

Does anyone know stats 🥲

[oak chasm]

Does that make sense?

@valid herald Sorry, channel is busy.

[haughty bronze]

yes

i completely understood everything you just said go on

[oak chasm]

OK, so h(t) = 0. We know that h(t) is also written as -4.9t^2 + 5t + 9.

[haughty bronze]

mhm

[oak chasm]

So, we can write -4.9t^2 + 5t + 9 = 0

t is our timestamp.

We can use algebra to find our timestamp.

[haughty bronze]

woah

-4.9t^2 + 5t + 9.

what?

[oak chasm]

That's the height formula from your problem.

Based on the timestamp.

[haughty bronze]

ok

[oak chasm]

So, we want the height to be 0, so the formula gives 0: -4.9t^2 + 5t + 9 = 0

Does it make sense what I'm doing here?

[haughty bronze]

yea i get it

9 is how high it is

so we want it to reach 0

right?

[oak chasm]

Right.

And this formula equal to zero tells us what timestamp it is when it hits zero height, the ground.

So, we have -4.9t^2 + 5t + 9 = 0

Do you know how to solve for t?

(the timestamp is t)

[haughty bronze]

guide me through it because im not sure on how to solve that to be honest

[oak chasm]

OK, have you heard of the quadratic formula?

[haughty bronze]

i have heard of it but i dont know how to do it

[oak chasm]

OK, so we have -4.9 in front of the squared t. We have 5 in front of the t by itself. We have 9 without a t.

See how I got those from the formula?

[haughty bronze]

oh so the t is squared wows thats why it looked that confusing

yeah i see

[oak chasm]

Yeah, ^ means "to the power of"

So, ^2 is squared.

[haughty bronze]

yeah i see the fact that you couldnt make the 2 small and higher than the t confused me

[oak chasm]

So, we have a = -4.9, b = 5, c = 9.

a is the part in front of the squared t. b is the part in front of the t by itself. c is the part without a t.

[ocean seal]

Chai T. Rex

[oak chasm]

Now, we have a special formula called the quadratic formula for telling us what t is.

@devout linden Sorry, channel is busy.

[haughty bronze]

delete that please

[devout linden]

Awww dang

[ocean seal]

Chai T. Rex

[oak chasm]

So we fill in a, b, and c to it.

[haughty bronze]

wow im reading another language

[oak chasm]

Yeah, but it's just normal algebra.

We have letter variables.

We have squaring, subtracting, adding, multiplying, and dividing.

It's a new formula, but it's normal algebra.

[ocean seal]

Chai T. Rex

[oak chasm]

See how I filled in the variables?

[haughty bronze]

mhm

[oak chasm]

OK.

[haughty bronze]

yeah

[oak chasm]

So, what's 5 squared?

[haughty bronze]

25

[potent rock]

may I ask a question here

[oak chasm]

What's 4 times -4.9 times 9?

@potent rock Sorry, channel is busy.

[haughty bronze]

not rn

[potent rock]

ok

[haughty bronze]

-4.9 times 9 you said?

[oak chasm]

4 times -4.9 times 9

Like in the filled in formula

[haughty bronze]

so you want me to multiply 4.9 times 9

and then

multiply that

times 4?

[oak chasm]

Well, negative 4.9, but yes.

[haughty bronze]

smh lemme do the math 😂

-44.1

but

i need to

multiply that

times 4

and it wont be positive since its a negative

and postive

im multiplying

-176.4

[oak chasm]

OK, and what's 2 times -4.9?

[haughty bronze]

9.8

[oak chasm]

[t = \frac{-(5) \pm \sqrt{(5)^2 - 4(-4.9)(9)}}{2(-4.9)}]
[t = \frac{-5 \pm \sqrt{25 + 176.4}}{-9.8}]

[haughty bronze]

well

[ocean seal]

Chai T. Rex

[haughty bronze]

-9.8

[oak chasm]

Right.

So I filled those answers in.

So, what's 25 + 176.4?

[haughty bronze]

201.4

i think

[ocean seal]

Chai T. Rex

[haughty bronze]

yea 201.4

[oak chasm]

OK, what's the square root of 201.4?

[haughty bronze]

uhh i dont think thats possible

[oak chasm]

You can do it with a calculator.

[haughty bronze]

what do i round to?

[oak chasm]

Let's say four places.

[haughty bronze]

14.1915467797

this is what i got

i mean 14.20

i guess?

[ocean seal]

Chai T. Rex

[oak chasm]

Oh, no, I mean four places past the decimal point.

Just to be safe.

[haughty bronze]

yeah ok

[ocean seal]

Chai T. Rex

[haughty bronze]

yeah

[oak chasm]

It means plus OR minus.

[haughty bronze]

i have no idea

okay

so it doesnt matter then?

[vagrant jetty]

i thought it meant plus and minus

[wet fulcrum]

no it does

[vagrant jetty]

u do both of those

u plus and minus

[wet fulcrum]

u take 2 cases where 1 is + and second is -

so u have two roots

[ocean seal]

Chai T. Rex

[oak chasm]

See how we have one with the plus and one with the minus?

[haughty bronze]

mhm

[oak chasm]

That's how it works.

Plus or minus.

[haughty bronze]

mhm so what then

[oak chasm]

So, what's -5 + 14.1915?

[haughty bronze]

hmm brain fart

give me a sec

9.1915

[oak chasm]

What's -5 - 14.1915?

[haughty bronze]

-19.1915

[ocean seal]

Chai T. Rex

[oak chasm]

So, what's 9.1915/-9.8?

[haughty bronze]

thats a very

large number

i would have to use a calculator

give me a sec

[oak chasm]

OK.

[haughty bronze]

-0.93790816326

lol

[oak chasm]

OK, what's -19.1915/-9.8?

[atomic glade]

,w -19.1915/-9.8

[haughty bronze]

stop

[atomic glade]

sorry

tried to help

[haughty bronze]

its okay

1.95831632653

[ocean seal]

Chai T. Rex

[oak chasm]

Now, we have a negative timestamp.

We don't care about that one because the ball hitting the ground happens AFTER we start.

Does that make sense?

[haughty bronze]

yes

so now i would round?

[oak chasm]

OK, so the timestamp is 1.9583 seconds.

Yes, now check your answers for which one matches.

[haughty bronze]

or 0.9379 right?

[oak chasm]

No, that's a negative number.

[haughty bronze]

oh yeah

right

okay

1.96

[oak chasm]

Right.

That's your answer.

[haughty bronze]

thats a lot

thats a lot of work though

[oak chasm]

Yeah, but it gets faster once you practice it a lot.

[haughty bronze]

you said thats a new equation right?

[oak chasm]

The quadratic formula is a new formula for you, I think.

[haughty bronze]

yeah it is

i thought you mean generally new

[ocean seal]

Chai T. Rex

[oak chasm]

Oh, no, it's a few hundred years old now.

[wet fulcrum]

thats a really complex equation for a starter

[haughty bronze]

im pretty sure my teacher taught it not too long ago i just wasnt paying attention

[wet fulcrum]

is this channel free now ?

nobu u done or do u have work to do

[haughty bronze]

math isnt bad if you pay attention that just goes to show i should be paying attention in her class

i dont normally pay attention in classes since i usually know the information in a lot of the assignments already but in math theres always something new and complex

[oak chasm]

Yeah, completing the square and the quadratic formula are very useful.

[wet fulcrum]

maths can be like that it can get very overwhelming too

like me i have 2 years of maths to go thru in 3 months

[oak chasm]

@valid herald Sorry, channel is busy.

[ocean seal]

Chai T. Rex

[oak chasm]

What does the |x| < 1 part mean?

[haughty bronze]

im assuming it isnt busy in here anymore

i also need help with this problem its not as complex with the equation earlier but

[wet fulcrum]

mod of 1 is less than one ie its in the 0 to 0.99999999999 range

i think

[haughty bronze]

oh nevermind

[wet fulcrum]

wait wait

[haughty bronze]

?

[wet fulcrum]

i didnt read question properly wait

[haughty bronze]

okay

[wary stream]

I believe that this channel is still in use. You should wait at least 15 minutes of inactiveness before asking. I can help you in #help-8

That one is inactive

[haughty bronze]

tsunderecyanide wants to help

[wary stream]

Anyone can help

[wet fulcrum]

3rd one persume

[haughty bronze]

you sure or your guessing?

[oak chasm]

@wet fulcrum One of the rules is to not just give the answer, but to lead them to the answer.

[wet fulcrum]

ok my bad let me explain

[haughty bronze]

okay

[wet fulcrum]

i didnt really factorize it but i did trial and error with the answers given

the simplest factorization given in the options was the 3rd one

[wary stream]

Channel is busy

[wet fulcrum]

just multiply it and if u get the equation given the thats the answer

is that a viable method or no

[lapis fjord]

Ill post in another channel

[haughty bronze]

actually

yeah it makes sense

[wary stream]

You can do trial and error like that but the real way to do, first factor on the GCD from each term

[haughty bronze]

GCD?

[wary stream]

Then you should get a quadratic and factor that quadratic

[oak chasm]

@wet fulcrum No, not here. All the answers expand to give the original equation.

[wet fulcrum]

oh ok my bad then

[wary stream]

Greatest common divisor

[haughty bronze]

hmm i dont think i've ever heard of that

[wary stream]

You observe and see what all the terms have in common that you can "pull" out

[wet fulcrum]

ok whats the most common term in the equation given

here its 2x

[wary stream]

Greatest common term

Not most common

[wet fulcrum]

yeah mb

[haughty bronze]

https://media.discordapp.net/attachments/490557019623915520/846454752618348604/unknown.png

i just posted it again

so i can see the question

[wet fulcrum]

so now u have 2x(x^2+2x-3)

[wary stream]

So the greatest common divisor, or GCD, for all the terms is 2x

[wet fulcrum]

now we simplify further

[wary stream]

So factor out the 2x and you get what tsunderecyanide stated

[wet fulcrum]

2x can be written as (3x -1x) no?

[wary stream]

Then factor that quadratic

[wet fulcrum]

can i write the method on a sheet of paper and send it here ?

[fast wave]

answer is C

[haughty bronze]

im aware

[wary stream]

You don't tell the people the answer

[haughty bronze]

i just wanted to see how he got it

[wary stream]

You teach them

[wet fulcrum]

@wary stream can i?

[haughty bronze]

wait

he is explaining it to me

[wary stream]

The factoring method?

[haughty bronze]

was that it @wary stream

[wary stream]

Which part exactly are you asking?

[fast wave]

2x^3+4x^2-6x
2x(x^2+2x-3)
FACTOR (x^2+2x-3) = (x-1)(x+3)
2x(x-1)(x+3)

@haughty bronze

[haughty bronze]

mhm

[wary stream]

Don't show all the steps either, you take it one step at a time, to see what they understand and what confused them

[haughty bronze]

so why did you replace the negative with the positive near the end

[fast wave]

this step ```FACTOR (x^2+2x-3) = (x-1)(x+3)

@haughty bronze

[haughty bronze]

yes

[fast wave]

factor formula

[wary stream]

Do you know how to factor quadratics?

[haughty bronze]

no im not sure

[wary stream]

Not factoring

[wet fulcrum]

yea

[wary stream]

There are multiple ways to factor, the method I do is multiply the a and c term and find factors that that sum to b

[fast wave]

https://www.youtube.com/watch?v=t71H2R68TZc @haughty bronze is called common factor method

[wet fulcrum]

its a pain typing everything out

[fast wave]

u can just watch a vid and they will explain it better

[wary stream]

Because the form is $ax^2 + bx + c$

[ocean seal]

dldh06

[haughty bronze]

bro i have 2 people trying to explain it to me

[wary stream]

You're not helping. You're just shoving information at the person

[fast wave]

nobu u dont know how to common factor just watch a video on it

its a concept

u gotta learn the concept

[wary stream]

Dude, just go away. I'm explaining

They probably know how to factor, just forgot the terminology for it

[haughty bronze]

ok can you continue thank you

[wet fulcrum]

im not really good at explaining taking factors so dldh06 can help u out

[wary stream]

That's an integral chart?

[wet fulcrum]

shit mb wrong picture

[wary stream]

So which part did you get stuck on?

[haughty bronze]

2x^3+4x^2-6x
2x(x^2+2x-3)
FACTOR (x^2+2x-3) = (x-1)(x+3)
2x(x-1)(x+3)

[haughty bronze]

i need to know how to actually factor

[wary stream]

You can do factor by group which is what tsunderecyanide did in the picture he just posted

[wet fulcrum]

i dont know how to teach factoring by group so pardon me for that

[fast wave]

its a concept fam a video will easily explain it to u

once u got the concept its smooth sailing

[wary stream]

But I do a different method
So if the form of a quadratic is $ax^2 + bx+ c$
You do a * c and the factors of a * c should sum up to $b$

[haughty bronze]

hold on bro kuya let didh06 explain it to me

[wary stream]

You're no help right now, please go so I can explain

[cloud lance]

a video is probably best

[cloud lance]

this is super confusing

[haughty bronze]

yeah it is confusing

maybe i should watch a video didh06

[wet fulcrum]

dldh06 can explain it but its hard to explain on text

so try a video

[alpine sable]

Could somebody please help with this?

[wet fulcrum]

channel isnt free

[haughty bronze]

thanks a lot didh06 but i have no sense in what your typing i might just watch a video

[alpine sable]

Oops

[wary stream]

There's multiple factoring techniques so yeah, I guess it would be best to look at videos to see which one you are comfortable with using

[haughty bronze]

okay

[fast wave]

u kno how to do this @wary stream

[wary stream]

tsunderecyanide uses factor by grouping and I do it a different way but in the end it produces the same answers

[oak chasm]

@haughty bronze Here's a video that uses the AC method that dldh06 was talking about: https://www.youtube.com/watch?v=kKE4t7R_KWc.

[wary stream]

I could be wrong but what I would do is find the roots/factor of the first equation, and the second and find a k and produces different roots from the first

[wary stream]

Thanks for that. Do you do the AC method too or grouping?

[fast wave]

i dont know how to do it

[wet fulcrum]

i can teach u how to group if u want nobu

[wary stream]

Factor the first and the second equations

[oak chasm]

I use the AC method usually, or quadratic formula if the coefficients are wild.

[fast wave]

can u show me the steps to the solutions in one paragraph it just makes it alot clearer on whats happening

[wary stream]

What I would do is use the discriminant which tells you how many roots there are, $b^2 - 4ac$
And based on the a term of the equation you can determine that the first one opens up and the second opens down
And for extra visual, plot the first equation
For the second, apply the discriminant again, and say that the first equation has one root(touches the x axis) then the second should have a k <= 0 meaning that it has one root or zero roots

[ocean seal]

dldh06

[fast wave]

can u show me the steps to the answer

i dont even know what discriminant means

[wary stream]

The discriminant has 3 cases, greater than 0, equal to 0, and less than 0, and respectively, that's 2 real roots, 1 real root(that appears twice), and 0 real roots(imaginary roots)
So with $y = x^2 - 6x + 14$, you can apply the discriminant so $(-6)^2 - 4(1)(14)$ which then equals -20 so zero real roots. So in other words that means that the parabola opens upwards above the x-axis

[ocean seal]

dldh06

[wary stream]

Like this

[spring harbor]

Is this channel free?

[wary stream]

I realized there's something that you can do, same idea using the discriminant

Set the equations equal to each other(because that's for intersection)

[fast wave]

can u give me the steps like this

i'll tell you what im confused on

[wary stream]

$$x^2 + -6x +14 = -x^2 -20x + k$$ because when two lines intersect, should equal to each other
$$2x^2 +14x + (14-k) = 0$$ shifted everything to the left side
Using the discriminant $$b^2 - 4ac$$ we get $$(14)^2 - 4(2)(14 - k)$$
Set that equal to zero so $$(14)^2 - 4(2)(14 - k) = 0$$ and find k because then k has to be less than that value so the parabolas don't intersect

[ocean seal]

dldh06

[wary stream]

@fast wave

[fast wave]

got it whats next

[wary stream]

Solve for k

And that's your answer

If k is less than that value, it won't intersect

[fast wave]

so i just plug in random numbers? till i get 0?

[wary stream]

You can solve for k using $$(14)^2 - 4(2)(14 - k) = 0$$

[ocean seal]

dldh06

[wary stream]

So $$196 -112 + 8k = 0$$, just distributed

[ocean seal]

dldh06

[wary stream]

Then $$ 84 + 8k = 0$$

[ocean seal]

dldh06

[native temple]

How to solve?

this?

[wary stream]

Channel busy

[wary stream]

Also there's no probelm

[wary stream]

So from there you should be able to find k

[fast wave]

so 14?

[wary stream]

$$84 + 8k = 0$$ and you got 14?

[ocean seal]

dldh06

[wary stream]

As k?

[native temple]

How to solve this my ti-84

won’t return 8/9^20

as a fraction

[wary stream]

This channel is busy

[native temple]

and i’m NOT CALULATING THAT by Hand

q

[fast wave]

-84/8
-10.5
@wary stream
?

[native temple]

w

[wary stream]

Yes

[fast wave]

thanks :3

[wary stream]

So k has to be less than -10.5

So the lines don't intercept

[fast wave]

k => -10.5 right?

[tall pivot]

hy all how can i solve this pls help me, Find a way to apply the tour strategy to find the smallest element in a 127 value vector. What if the vector has 96 values? But if you can only process 256-length vectors, do you have 2048 values to process and 4 processors available?

[wary stream]

k <= -10.5

[fast wave]

oh ye my signs got mixed up

[native temple]

I’m sorry for interfering

[wary stream]

If you tested it out by graphing, you can see that -10.4 intercepts but -10.5 doesn't and -10.6, and so on so k <= -10.5

[fast wave]

ya i did test it with desmos

[verbal stratus]

How would I do this?

I’ve tried finding the gradient for both values of x and finding fx and just inputting random values nothing works

I got -8sqrt(1-x) + c

And y=2x-5 for (-3,-11), can I use the same c?

[velvet pelican]

you have f(x) = -8sqrt(1-x) + c

use the point given to find c

then plug in x=-8 to get the y value at -8

and hence the point

[upper jewel]

hi i have a math test tomorrow at nine o'clock unless the teacher changes something.

[verbal stratus]

The one thing I didn’t try 💀 tyy

[velvet pelican]

yw

[upper jewel]

can help me?

?

[scarlet spire]

dont ask to ask just ask

[wet fulcrum]

anyone good in inegration

[vague coral]

u sub should work

[rustic hatch]

how to find side in cosine

i need to find side b

[wintry ice]

send pic

[wet fulcrum]

sine rule my friend

[rustic hatch]

what is the equation

[rustic hatch]

?

[wet fulcrum]

1 min im doing

ill send u a picture in a minute

[wintry ice]

substitune nd solve

[rustic hatch]

its the sine rule bro

[wintry ice]

yea use it

[rustic hatch]

which one do i take out because im using it to find b

do i take out sin b

from the equation

[wary stream]

The variables are arbitrary, you can use any

[wary stream]

As long as the proper side corresponds to the proper angle

[wintry ice]

yep

[wet fulcrum]

@rustic hatch

i hope u can youre allowed to use a calculator cuz its a nightmare without it

[wary stream]

I understand that you're trying to help people but you should let people solve it themselves and ask us for help if they get stuck

[verbal stratus]

I’m not good at integration but I would expand it first?

[rustic hatch]

thx bro i appreciate it

[wintry ice]

yep expand

[wet fulcrum]

oh ok no its just that i give them the way to do it too i mean theyre here because theyre stuck

[wet fulcrum]

yes it works thank you

[wintry ice]

and use int[f(x)+g(x)+k(x)]= int[f(x)]+int[g(x)]+int[k(x)]

[wary stream]

They're stuck because they probably don't know the equation to use, and once they know, they can plug it given info in and work it out and if they get stuck more, you can see where they got stuck at and help from there. Sometimes people just go straight to the answer and don't digest the written help you gave and won't fully understand it for an exam or quiz. They'll rely on memory and be like "what did that person write on paper again" instead of understanding the concept fully

[wet fulcrum]

yeah i guess youre right

[wary stream]

Now that's just from my experience

[wet fulcrum]

its just that if people are motivated enoguh to come to DISCORD for help they really want to learn

[wary stream]

They come to discord wanting the answers most of the time

[wet fulcrum]

yeah welp my bad then

jimmy u aint getting answers anymore

[wary stream]

It's just a heads up, just so you know for next time

[wintry ice]

lol

[ocean seal]

dldh06

[wintry ice]

ohhhhhh

looks good

[wary stream]

Look into latex if you're curious

[wet fulcrum]

ahh ive heard of it

[verbal stratus]

How do I find the function for the shape from 0<x<3 so that I can find the area?

I’ve got y=3, y=-3x+3, y=3x+1 but idk how to turn that into something I can integrate

[wary stream]

Just find the area under the curve

[verbal stratus]

What

[wary stream]

So between 0 and 3, find the area of that shape

[verbal stratus]

Is there any way to do it using integration?

[wary stream]

No because it says area interpreation

Which is the area of the shapes

[verbal stratus]

Oh

Thank you