help-0

[glass lichen]

just use a calculator to check

and you dont need help, you need someone to use a calculator for you

[dry vine]

calculators use decimals

[glass lichen]

so?

[dry vine]

You dont use decimals here plz

[glass lichen]

if you get the same decimal expansion at the end. . then it's right

[dry vine]

just quickly plz

[glass lichen]

no

[spring bolt]

Can anyone help me with this?? 🤔🤔🤔

[glass lichen]

do simple tasks yourself

,rotate

[dry vine]

ow

[sage rapids]

The last one √48=4√3

[wispy nest]

plz help i dont understand this on my hw

[spring bolt]

I'm learning for the exam so can anyone help me fast??

[spring bolt]

Area??

[glass lichen]

you havent explained what you're stuck on nor what you have tried

[spring bolt]

Q26

[wispy nest]

yes area of the trapizoid

[glass lichen]

no shit, what part?

[spring bolt]

3 parts

[tawny tree]

hi, I need help with this the topic is called reading views and I don't know how to put the figures together, if someone knows about the topic I would appreciate your help

[glass lichen]

ok im not helping

if you're not going to give straight answers

[spring bolt]

Idk how to do straight line geah even

Grah*

Graph *

[desert sage]

can someone help me for question B

[glass lichen]

is it a test?

[desert sage]

No

its an assignment

I already did 4 and 5 a on a piece of paper

[desert sage]

So can you help me

im kinda stuck

[quasi scarab]

in a) you have one side that is 6 more than one times the other

now u have 5 less than 2 times the other

use algebra in the same way

[desert sage]

ok

so, wait im sorry

how would i right that as an equation again. Im pretty slow when it comes to math

bc I did 5-2a = 50 but I just dont feel it

why is algebra so annoying

[fathom matrix]

mr Mosh

i yearn for your attention

[spark ibex]

anybody know how to do equilibrium price?

im looking at my notes and im currently on the last part of step 1

But i am getting do different answers, the notes have both as 10 but i have one 5 and one 4 so im confused

oh wait nvm i figured itou

[desert sage]

i still need help pls

[alpine sable]

how would I know?

what makes it correct?

the 3rd one is correct?

[trim current]

It would be the 3rd one because the congruence would match with eachother

[alpine sable]

ok

[trim current]

Like n to p has 2 lines and p to r has none, while q to r has two lines and r to p has none

Get what I jan?

Mean*?

[alpine sable]

mean?

i know now

I don't get this. This is neither

68 / 4

The only patthrn I see is Angle side nothing

See

Angle side nothin g

sigh this is the triangle congruency postulate

are you in 5th grade or what

They have the same angle, the right angle

I dont understand..

why would it be SaS

[glass lichen]

keep the help channels to help, dont shitpost

[alpine sable]

well, so?

[dim spear]

bruh

[alpine sable]

What makes right angles special in postulates?

It's the same in both triangles

They have one side equal

And share one side

<@&268886789983436800>

[sly mantle]

👢

[alpine sable]

tell me where this shows SAS

I only see angle side nothing

angle side nothing

[runic dock]

wy common side for both triangle

[alpine sable]

Okay so how would that become SAS

[visual furnace]

help me with this

[alpine sable]

I don't se Side-Angle-Side for each triangle

[visual furnace]

I want to understand it

the answer is 2.5 but how?

[runic dock]

Wz=xy given

[alpine sable]

Yes

They're given

OK

I FIGURED IT OUT

You could've just said "You can see a SIDE and then an ANGLE and then a SIDE"

Is this AAS or ASA

[distant bay]

Hi can someone help me

[visual furnace]

why dont u ask gon instead

[distant bay]

🥺🥺🥺🥺

[visual furnace]

im jk

[alpine sable]

@alpine sable the side is between two angles

[visual furnace]

What do you want

[visual furnace]

What do you want

[visual furnace]

Can you answer my question btw

[distant bay]

Could u help me simplify a rational 😔 I just learned these tday and they’re confusing I got this for the answer -20+12 root 10

[alpine sable]

25 planks each 30cm, how many meters is it if nothing overlapped

[visual furnace]

Okay

Let see

wouldn't it be 25 times 30

which is

750

?

[alpine sable]

Thats cm

[visual furnace]

in m

7.5

?

Im confused

[clever sail]

Can someone help me?

[visual furnace]

This is extra work aswell

[clever sail]

I need help with this

[alpine sable]

@visual furnace 7.5m would be if they didnt overlap

[desert sage]

ok If the length of a rectangle is 5 less then twice its width, what would the dimensions be if length and width is the perimeter is 50cm

[alpine sable]

And 6.9 if they overlap

2 of the end planks only overlap on one side

[clever sail]

need help

[alpine sable]

Go to the channel #rules for help @clever sail

[visual furnace]

Go ask Sanji (Your best freind) 🙂

[clever sail]

?

[visual furnace]

Can you explain a bit more

[clever sail]

??

Im just asking for help...

[visual furnace]

I was joking by the way

[clever sail]

ik

[alpine sable]

This channel is occupied, go to one of the 9 others

[visual furnace]

Yes

Go the one of the question text channels

[alpine sable]

Anyways, overlapping means that the planks shorten by a certain amount

[clever sail]

legit no one is answering me....

[visual furnace]

I know

[visual furnace]

Go to one of the other question text channels

[clever sail]

I am

no ones answering

I went to question 6

[visual furnace]

Then another one

so it shortens by .6m

60 cm

[lethal glacier]

could a math helper help me with this please

I am confused on the premice of the question

[alpine sable]

Can someone help me

[solar tapir]

Send a screenshot, not that

[lethal glacier]

ok my bad :/

im trying ot but it keeps becoming a pdf

[distant bay]

I opened it, I can send it 4 u if u want

[lethal glacier]

fr bro thats much appreciated thank you

[distant bay]

That correct

[lethal glacier]

yes

thank you

[lethal glacier]

Is that better?

[distant bay]

That question seems weird what does it mean by two zeroes and no zeroes?

[shell widget]

No zeroes means no "x" intercepts, that means no solutions to kx^2 - 5x + 4 = 0 exist.

And that means the discriminant will be < 0.

For the second part, the discriminant will be > 0.

[lethal glacier]

How would i find the discriminant?

[shell widget]

You have a quadratic in the form ax^2 + bx + c

The discriminant is b^2 - 4ac

[lethal glacier]

of

oh*

so the discriminant is the quadratic formula

[shell widget]

some part of it

not the whole quadratic formula

[lethal glacier]

do i just write x<0 and x>0 for this question nothing else? How come?

[shell widget]

wdym?

Can u tell me what the discriminant is for kx^2 -5x + 4?

[lethal glacier]

5^2-4(kx)(4)?

[shell widget]

almost

[lethal glacier]

are we solivng for i or ii

[shell widget]

(i)

[lethal glacier]

ohh

k

[shell widget]

(-5)^2 - 4(k)(4)

is the discriminant

which is just 25-16k

and for no zeroes, we need the discriminant < 0

[lone folio]

Can someone explain this question to me? I don't get what it's asking with the x's

[lethal glacier]

ok i see and we just leave it like that as 25-16k

thank you

sir

[shell widget]

yes so solve for k now, you have 25-16k<0

[lethal glacier]

wait for ii) do i sub in 2

oh k

so 25-16 signs flip

k=-25+16

[shell widget]

for 2, you need 25-16k>0

@lone folio Let the rectangles width be x.

Then the length will be 3x.

[lethal glacier]

wait would i set the k to be negative then

[lone folio]

oh, that makes sense. Thanks!

[lethal glacier]

25-16=-k

[shell widget]

@lone folio Not done yet, find the area. And then after that, increase the width by 1, so the width is now x+1. Find the new length now, and then the new area.

And then subtract the new and old area to find the change in the area.

@lethal glacier For first part, you need 25-16k<0

[lone folio]

yeah, I see

[shell widget]

which just means 25<16k

which is just 25/16 < k

so we must have k > 25/16

That's it.

For the second part, we need 25-16k > 0

Which is just 25 > 16k

Which is just 25/16 > k

which is just k < 25/16

[lethal glacier]

you are a god

[shell widget]

No

[lethal glacier]

yes

[random crypt]

Can someone help me w a Calc questions

[glass lichen]

dont ask to ask

[random crypt]

Suppose we know f′(x) = 2x+ 1. Write an equation of the tangent line to the curve y=f(x) at the point (1,2).

[glass lichen]

just find the slope of the tangent then plug everything into point-slope

[weary solar]

hollup

he has the tangent line

he needs to integrate

[random crypt]

Idek how to do that

[weary solar]

wait so you have the derivative of f'(s)

ohhhh

i see

yeah

right so you just need to plug the points in to the derivative

that gives you the slope

[glass lichen]

you have the derivative of f, so you can know the slope at (1,2)

[weary solar]

yeah

and then you can use point slope from there

to find the full tangent line

[random crypt]

Wait so the point slope formula is y-y1= m(x-x1)

[lethal glacier]

could soemone explain how to write a domain statement with two x intercepts, like x= 0 and x=8, how would I state a restriction, this would usually happen for a parabolic path question aswell

[weary solar]

yeah

where (x1, y1) is your provided coordinate

[random crypt]

Y-2=m(x-1)

Then what ?

[weary solar]

well you need to find the slope right

so you utilize the derivative

[random crypt]

Idk what that means

[weary solar]

plug your x coordinate into the derivative

so

you have

f'(x) = 2x +1 right?

[random crypt]

Yeah

[weary solar]

this is the derivative of f(x)

so

if you have an x coordinate

[lone folio]

Can anyone help with this quick question? Pretty sure its logxy=a, but I need to double-check since this is my first time learning log

[weary solar]

you can find what the slope is at f(x)

and thus construct a tangent line

so plug 1 into f'(x)

[random crypt]

F’(1)=2+1

??

[weary solar]

yeah

therefore

when x = 1

the slope is 3

and then you just put that in your point slope equation

and that's your tangent line

[random crypt]

Y-2=3(1-1)

Y=2?

Wait ...

Is that right ?

[weary solar]

yeah

well

don't plug in x on the right side

so your final equation would be y - 2 = 3(x - 1)

[random crypt]

Is this right

What do I do after that

[weary solar]

nah that's good

you're done

[random crypt]

That’s it ?...

[weary solar]

yeah

[random crypt]

Oh

[weary solar]

that's your tangent line

y = 3x - 1

[random crypt]

Oh ok

Thank you so much

[weary solar]

no problem

[distant bay]

Could someone help me model an equation

I’m thinking the equation is 2.00-0.25x+(50x+300

Could some help me sirs

And Ma’ams

[lethal glacier]

doesn't it have 2 be a quadratic

[distant bay]

That’s why I’m not too confident in my equation

[naive belfry]

tbh the equation looks fine for me

[lethal glacier]

expand it out and it becomes a quadratic

take away the + sign

[naive belfry]

yea

[distant bay]

Thank you Goats

[naive belfry]

(2-0.25x)*(50x+300)

-12.5x^2+25x+600

[distant bay]

How do I find the maximum revenue?

[distant bay]

Do I find the vertex which is the max revenue?

[naive belfry]

I'd make it a derivative and check where the slope is 0

[distant bay]

Haven’t learned those yet lol

[naive belfry]

oh

[lethal glacier]

does it not want the vertex?

do -b/2a?

[naive belfry]

to be honest I've always done it with derivatives, can't help you with something else

[distant bay]

Could we compare answers, I’ll answer using -b/2a and could u lemme know if I did it right

[naive belfry]

alr, tag me when you have yours

[naive belfry]

my price is 1.75 with a revenue of 612.5

[lethal glacier]

same I got that

[distant bay]

I graphed it, and it gave me -3,712.5

[naive belfry]

Tf

That doesn't seem right

[distant bay]

The -3 could mean the amount of decreases in 0.25?

So 2.25$ is the maximum selling price?

Nvm

Lol

1.25*

[naive belfry]

Can you send me an image of your graph?

[distant bay]

If it is that what does it mean

[alpine sable]

amogus

[naive belfry]

That equation is different

I got that:
-12.5x^2+25x+600

[alpine sable]

amogus=impostor=>Amgus is sus

*using the sussy theory

[distant bay]

It’s 75x

-75x

Because y foul -0.25 x 300 which is -75

[naive belfry]

you probably forgot the 100x

[distant bay]

Yes ur right

Lol

How did u model the selling price equation?

[naive belfry]

the first one?

[naive belfry]

You did that here, only mistake was that you didn't take the price times the units but +

[distant bay]

So should it be 1.75, 612.5

[naive belfry]

yep

depends

[alpine sable]

uhh

rip

[distant bay]

Wait how did u determine the cost price? By subbing in 1? Into the older equation?

[naive belfry]

haven't done geometry in a long time, just wait if someone else is able to help here :)

[lethal glacier]

thats a google form test lmao

[alpine sable]

😳

[lethal glacier]

u can't post those :/

[alpine sable]

your name has to be ironic right?

[lethal glacier]

your ionic 😔

[naive belfry]

Tbh I'm really bad at explaining that

IchigoSolosEveryVerseExceptDBZ might be able to?

[lethal glacier]

nah lol idk what u guys did i went to the washroom😫

[distant bay]

Lol

[naive belfry]

The first equation you made

[distant bay]

Ok and then I foil?

[naive belfry]

wdym exactly?

[distant bay]

In the bracket equation do I sub it in? Like (2+0.25x)(50x+300)

[naive belfry]

Ah yes

Just sub in the 1 and you'll find your max revenue

Except it's 2-0.25

[distant bay]

Okk bet

And how would I get the selling price

I know it’s 1.75

[naive belfry]

just 2-0.25*x and x subbed in by 1

[distant bay]

Your a god

[unreal valve]

For this graph im confused whether point c is the absolute maxima because there is a higher point after g

[glass lichen]

it's a local max, not an absolute max

[unreal valve]

What about point d? Its neither max or a min. So would it be be considered neither because f=0?

Or am i wrong and its somehow a max or a min

[glass lichen]

f=0 what?

f doesnt equal 0 at d

[unreal valve]

So would d considered a minimum then or neither?

Im so confused

I was guessing min since its decreasing as its going to point g

[glass lichen]

d is clearly not a max or min

cause it's not a turning point

[dusk smelt]

could be point of inflection

[alpine sable]

could someone help me in #help-9 if you have time please

sry to intrude

[unreal valve]

Oh okay thank you

[distant bay]

I got F-1(7)=7

Could someone help me

[vale wigeon]

trick question, f has no inverse

[ivory estuary]

might be derivative tho

[vale wigeon]

definitely not, just_mee

[ivory estuary]

idk

[distant bay]

No my teacher said there’s an answer

[alpine sable]

stop sending ur test lol

[distant bay]

Lol

[ivory estuary]

use the mid point formula. do you know it? just place the values of the coordinates there and use the ratio 1:1

[dusk smelt]

@alpine sable google this: "How to find the midpoint of a line segment"

you dont need our help

[distant bay]

Fax

[ivory estuary]

lol

[naive belfry]

@distant bay i think it's 9

[distant bay]

💀

[vale wigeon]

i am not going to help anyone in this cesspool of a channel at this hour

[distant bay]

I thought it could be f-1(7)= and f-1(7)=9

[golden falcon]

it does have an inverse, it'll just be a multibranch function.

[naive belfry]

ye

[distant bay]

Oxy your a god

[naive belfry]

don't quote me on that tho

can't guarantee it's right

[kind torrent]

f is not one-one because inverse image of 7 is 7 and 9.

[distant bay]

Your still a god

[bronze spade]

I don't think so, moreover the function does not seem to be differentiable at this point

[kind torrent]

(2,1.5)

[nocturne niche]

can anyone help me classify this aaa

matrix

i hate matrixes

[muted raft]

well write it as a matrix first

then row reduce it

[nocturne niche]

thing is, i barely learnt it

my teacher sucks

[bronze spade]

No need to use matrices, proceed by elimination

[nocturne niche]

and im doing a test rn

[alpine sable]

uhhhh

[muted raft]

uhhh

Yeah no test questions here please

[kind torrent]

2, 3/2

[nocturne niche]

as soon as you say that, someone posts a test question lmao

[naive belfry]

lmao

[muted raft]

<@&268886789983436800> test questions here

[sly mantle]

👢

[dusk smelt]

find the slope of CF first

[bronze spade]

You can work on that by yourself and verify your results with Wolfram Alpha. It's all about practice and training

[alpine sable]

is V x (U+W) a scalar?

they are vectors

[kind torrent]

vector product of vectors is vector

[alpine sable]

oh

the dot produc

t

is scalar right?

[dusk smelt]

yes

[alpine sable]

when x is 45

degrees

[glass lichen]

$\sin(x)=\cos(x)\implies\tan(x)=1$

[ocean seal]

Mosh

[glass lichen]

,w solve tan(x)=1

[alpine sable]

oh

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by moshill1#9771

[glass lichen]

what I did

[kind torrent]

yes then find the values of x

yes

[kind torrent]

this is the set of solutions

yes where n in Z

integer

[blazing rose]

what formula do i use to find the arc length of a line segment?

[alpine sable]

somone help me on this

[ruby token]

EYY

im big brain

:>

[alpine sable]

oh ok so whats the answer?

[outer elm]

you do arcsin12/15

then you just round the angle

im gonna assume you know how to do that

[alpine sable]

yeah

thx man

[outer elm]

i gotcha

[rapid horizon]

can someoen help

[outer elm]

st * tr = qt * pt

[rapid horizon]

alr thanks
ima have more questions btw i have like four questions

[outer elm]

aight

[sour lynx]

what is the difference between a adjacent and non adjacent angle

[outer elm]

1 and 2 are adjacent angles

[rapid horizon]

@outer elm ik i did it wrong but idk what i did wrong

[sour lynx]

yes but i have to draw a nonadjacent angle and i dont know what that looks like

[outer elm]

1 and 3 are nonadjacent

adjacent means sharing a common vertex and side

[rapid horizon]

@outer elm what did i do wrong with that

[outer elm]

your calculation is wrong man

just redo it

qt ~ 5.229

aka answer 3

[rapid horizon]

ye i gotta show work tho

[outer elm]

your way is right

wait

bruh

[sour lynx]

i have to draw 2 42° angles that have the same vertex, but not adjacent can you draw that dark

[outer elm]

you subtracted 4.28

you need to divide 4.28

[rapid horizon]

ohh yeah im dumb lmao

[outer elm]

take the last drawing i did

1 and 3

make them both 42

[rapid horizon]

yeah i got it thanks

[sour lynx]

ok

[outer elm]

theres a theorem that if from a point outside a circle you draw a tangent and a secant, then the square of the tangent is equal to the secant times the outer part of the secant

DB^2 = AD*CD

[rapid horizon]

so do i just solve this?

[outer elm]

yes

substitue x

dont solve

just get to the expression

[rapid horizon]

is it 3

[outer elm]

wait

no

ur thing is wrong

its not 8

read what i sent

properly

[rapid horizon]

ohhhhhh

so like what is ad

or how would you find it

[outer elm]

ad is 8 +x

[rapid horizon]

oh so i did have it right

[outer elm]

bruh

no

[rapid horizon]

ohh plus

yeah

so would it be three

yes

[outer elm]

ITS NOT 3 MAN

oml

3^2 = (8+x) * x

[rapid horizon]

oh ok lemme do that

[outer elm]

number 2

the answer is 2

XD

just put 2 and move on

[rapid horizon]

yeah lmao

this is last question

[outer elm]

finally

[sour lynx]

i have to draw to nonadjacent angles again but it says they have to be congruent angles. What does that mean

[kind torrent]

1

[rapid horizon]

ty

[lucid tendon]

Could someone give me a hint as to how to tackle this problem? I have difficulty visualising how this function F is related to the map between the balls with the two radii

so (y,s) = F(x,t) only if (x,t) is the map of (y,s) onto the ball with r1

and I need to show that this function G exists but I don't see how to think about what this relationship means

[dim spear]

is this place occupied

I should begin with the quotient rule right?

[sour lynx]

how to do this

i have to draw it

[dim spear]

two angles are complentary to 90°

a + b = 90

fact check please? before going forward

[violet ether]

correct.

[dim spear]

okay thanks

can you fact check the work above

[violet ether]

looks good

[dim spear]

@sour lynx

Matti gave it a thumbs up

[alpine sable]

Did I do this right?

word problems are a hassle

[warm verge]

what is the first step for this?

i know i have to do integration by parts, but not sure if i should use cos^2(x) or 9x to integrate

[alpine sable]

@alpine sable why is sin(85d) equal to 1?

since sin 85 gives like 0.996

so I rounded it to 1

i see

is this a vector or meaningless?

im pointing towards vector

since i dont thing the 5 matters

force is vector

so yeah

you did great

thanks

actually

no problem

[hardy sky]

hi

so, sum of a,b is the term for a + b

what is the term for a - b ?

difference!

got it 😄

[violet ether]

noice

[hardy sky]

although

[neon sonnet]

Guys im going to need help later....

[hardy sky]

sum of a,b,c is a + b + c

but we can't say that the difference of a,b,c is a - b - c

[wild dove]

no, difference is only between 2 numbers

[hardy sky]

so, is there a proper term for a - b - c, then?

[violet ether]

it's the sum of a,-b,-c. 😅

[fossil sundial]

<@&286206848099549185> can any1 help me with some questions for my exam practice

[dim spear]

please I need help this is what I have done so far

[violet ether]

$\frac{d}{dx}(x+y(x))^2=2\cdot (x+y) \cdot \frac{dy}{dx}$

[ocean seal]

Matti

[dim spear]

did you multiply x+y

from the left

[violet ether]

i meant the numerator of the quotient rule.

[dim spear]

oh

what i did was wrong?

[violet ether]

yes

[dim spear]

where

f' or g'

on the left or right

[violet ether]

I was wrong, sorry.

[warped crag]

Right so wat u want to do is

[dim spear]

this is what am solving

[warped crag]

U want to get rid of x2

[outer elm]

do you have that in any more blurry?

[dim spear]

i used quotient rule

[warped crag]

U shouldn’t u need to

[outer elm]

why is this so hard lmfao

[warm verge]

i found the trick

well it is my old exam

[dim spear]

what should i do

[warm verge]

reviewing it so i can get a 100 on finals yk

i bombed this exam 😦

[warped crag]

U need to get rid of x to find the vinculum then find the apolothem

[dim spear]

ummm

[warm verge]

but i found out how to do it, the gist is that you have to sub cos^2(x) for( 1/2)((cos(2x)+1)

[dim spear]

sorry what is the vinny thing

really lacking on the math vocabulary

[outer elm]

ohhh

@warm verge thats smart

wow

[warm verge]

yeah

[dim spear]

do i get rid of the denominator

by the product of (x+y)^2

and then subtracts

[strong furnace]

if you're talking about the integral

IBP is the way to go diffeentiate x

[warped crag]

Find the vinculum and then it’ll be easy

[dim spear]

to get dy/dx alone

what about the dy/dx on the right

there is 2 of them

both on the left and right

[warped crag]

Get rid of them or find the antilog that will help u out

[dim spear]

antilog

[outer elm]

@warm verge whats the answer? i still cant get to it

[warm verge]

https://www.integral-calculator.com/

use this

[outer elm]

0 XDDD

[warm verge]

if u want the steps

yeah i gave up during exam lol

biggest L i ever took 😦

[outer elm]

wow it looks so hard

i could never

[warm verge]

i think class avg was a 30

so

[turbid mica]

Homework help

[outer elm]

7

D

[heavy axle]

Can someone help out w number 1

[outer elm]

@turbid mica lol i fixed it

not 14, its 7

[outer elm]

x = 0, y = 1
x = 1, y = 2

[bleak barn]

i got z=14 and Measure of 180 degrees

[outer elm]

z = 12

[bleak barn]

thanks

[outer elm]

160 degs

[bleak barn]

thanks

[heavy axle]

What’s the answer to this

[ocean seal]

Jukelyn
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[north hemlock]

c^2 sorry

[north hemlock]

solve for y in the 2nd equation and then substitute that into the first one, it's a super easy quadratic

after that just take those 2 x-values and use the 2nd equation (easier) and get the 2 points that are the solutions to the system of equations

should be ||(0, 7) and (-1, 6)||

[heavy axle]

Y=7

[north hemlock]

yes

that's one of htem

them*

[heavy axle]

Then plug that 7 back in for y in the first equation?

[north hemlock]

perhaps

it's easier to do it how I said

it's shorter as well, about 5 steps

practically

go for it

(n+1)^2

yeah

np

[bleak barn]

yo

[north hemlock]

yo

[bleak barn]

can i get some help with my hw

[north hemlock]

send

[bleak barn]

work is not needed

[north hemlock]

you need the height of the pilar?

[bleak barn]

yeah

confused how to get it

[reef sinew]

Find the sf

[north hemlock]

is there more to this question? assuming they're similiar, just use the ratios

[bleak barn]

idk

this is all i got

[reef sinew]

Yeah if you need no working and that's al I think you just find the scale factor

[north hemlock]

just take the ratios

[bleak barn]

how?

thats why im asking

[turbid mica]

What is 7 lol

[reef sinew]

4 ft 6 in × x = 6 ft 3, find x and multiply the mans height by it

[turbid mica]

I was here waaaay earlier buuuut ok

[north hemlock]

$\frac{x}{99}=\frac{63}{54}$

[ocean seal]

Jukelyn

[north hemlock]

?

[turbid mica]

Scroll up I asked way earlier

[reef sinew]

First convert to inches

[turbid mica]

And my questions weren’t answered

[north hemlock]

send again

[turbid mica]

Ok

[bleak barn]

okay

[outer elm]

the answer bro

[turbid mica]

It was these two

Someone said 7, D

Don’t understand that tho lol

[north hemlock]

already solved this

I'll do it again

[outer elm]

bro its me

i said that

[north hemlock]

set it up like this:

I said it too lol

[outer elm]

i just gave you the answers

[north hemlock]

okay

anyways

[turbid mica]

No, that’s not helpful tho the point here is to get help

Not answers

Read the rules

[north hemlock]

$a^2 + b^2 = c^2 \implies 24^2 + r^2 = (18+r)^2$

[bleak barn]

i got 63/54 and x/99 like it showed before

[ocean seal]

Jukelyn

[north hemlock]

now just solve

it's a right triangle so we can use this

[reef sinew]

Ah I see

[north hemlock]

now you can solve for r

[icy basin]

isn't this just a^2 + b^2 = c^2

[north hemlock]

yes

[icy basin]

i have a stupid simple question once this frees up

[flat estuary]

How do i find thease out?

[north hemlock]

@turbid mica

[north hemlock]

is that a Canvas quiz?

[turbid mica]

Ty

[north hemlock]

it should work out pretty clean

[flat estuary]

Idk.

Its not mine

[north hemlock]

interesting

[flat estuary]

Asking for an friend

[north hemlock]

also interesting

[icy basin]

cross multiply

[north hemlock]

I won't help on quizzes and tests so

[flat estuary]

its wtv ← he or she said this

Im not american

So i don't know what is that.

[icy basin]

g=10

why does this = 5 and not 10?

[flat estuary]

The text is so small

[north hemlock]

solving for t?

[icy basin]

Yes

[north hemlock]

it is 10

[strong furnace]

,rotate

[icy basin]

the answer is 5 though

[strong furnace]

they are asking for maxima

probablt

[north hemlock]

,w solve(-5x^2+50x = 0,x)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Jukelyn#9848

[north hemlock]

ah

prob max height

that'd make sense

if they asked how long it took to return to the ground then 10 would be right

[strong furnace]

it says maximum height

[north hemlock]

the issue is that this doesn't actually have a question

[flat estuary]

Oof im not familiar with thease type of calculations

[north hemlock]

Just physics

[flat estuary]

I'll go help someone else

[north hemlock]

speaking of physics, my exam in 3 days 😰

[strong furnace]

h'(t) is just rate of change of h with parameter t

t is time in this context

[flat estuary]

I haven't had physics in school for like half an year

[north hemlock]

aka the velocity

[alpine sable]

yes

[icy basin]

so it should be 50 = -1/2gt^2 +v0t?

[north hemlock]

since h(t) is a function of time that represents the position at a time t

[alpine sable]

h as in height

keep that in mind

[north hemlock]

no, you want to get the maximum, there are two ways but the "easier" way is to derive it once and set the derivative to 0 and solve for t

[alpine sable]

h'(t) = v(t)

although i hate physics

[north hemlock]

the other way is that assuming it's launched from the ground and returns to the ground, you just do half the time it takes to fall back dwon

down*

[strong furnace]

if you wanna look at it mathematically

[north hemlock]

it's better to use the first method since we aren't sure if the ball was thrown off a certain height or anything

[strong furnace]

the maxima is for x=-b/2a

[north hemlock]

indeed

[alpine sable]

yes

[north hemlock]

that axis of symmetry for a quadratic

the*

[icy basin]

i'm so confused, i've done several types of questions like this, this was a past test question i got wrong. Its not solveable in anyway we've been taught prior.

[north hemlock]

send the question

[strong furnace]

what have you been taught?

[icy basin]

basically solve for h(t). usually were give h(t) = -1/2gt^2 + height

[north hemlock]

well g should be constant

[icy basin]

yes g =10 here

[strong furnace]

but what are they asking for here?

[north hemlock]

oh u wrote g(t) originally

[icy basin]

normally average velocity

[strong furnace]

I am asking what are they asking here not what they ask generally

[icy basin]

or instantaneous velocity folowing that

oh

[north hemlock]

instantaneous = derivative

average = average slope

[icy basin]

they want : a) Find the time when the ball reaches its maximum height.

[north hemlock]

okay, for this just take the derivative and set it = to 0 and solve for t

bc at the max heigh, the ball has a velocity of 0

[strong furnace]

from their solution

[north hemlock]

meaning that it's turning

[strong furnace]

I am assuming you know calculus

[icy basin]

makes sense

[north hemlock]

height*

[alpine sable]

yeah, due to the acceleration of earth's gravity

[icy basin]

I do and i understand derivatives. but technically we haven't even learned derivatives yet

[north hemlock]

Have you done derivatives in your physics class?

or rather, problems where they were used to solve questions

[strong furnace]

physics derivatives is probably just the formulae

[icy basin]

this is from a math classs

[north hemlock]

oh

[icy basin]

no

[north hemlock]

which math class

[icy basin]

we start derivitives now after this test

[north hemlock]

that's interesting

[icy basin]

just basic calculus

first university level

[north hemlock]

Typically limits and derivatives are the first thing you learn in a calculus course but idk, that's weird imo

[icy basin]

everything with these tests are backwards. we are given questions to do. then usually the test questions have little to do with what we've been taught lol

[north hemlock]

Hmm

Welp

[icy basin]

i finished the course last semester, but my internet cut out during the final, so i got 0

[north hemlock]

the derivative of position is velocity and the derivative of velocity is acceleration

[north hemlock]

that's unfortunate

[icy basin]

so now i'm retaking this, and i still don't understand how they are getting this answer haha

[north hemlock]

If it helps...

[ocean seal]

Jukelyn

[alpine sable]

i nowadays am like, is physics prerequisite of math?

[north hemlock]

no

the other way aroun

around*

Calc 1 or AP Calc AB (same) have a unit where it's basically derivatives in context or applications of derivatives

[icy basin]

every math class i've seen lots of questions are physics related haha

[north hemlock]

and so physics kinda leaks in

yeah

they're all related

[icy basin]

yeah exactly more or less

[north hemlock]

Math is like the umbrella of everything

sciences branch off of math

[strong furnace]

classical physics uses a lot of applications of derivatives and integral stuff

[north hemlock]

^

[icy basin]

is the derivative of -1/2gt^2 is just -gt?

[north hemlock]

yes

[icy basin]

okay all makes sense then

just taking the derivative of the questions, even though we haven't actually learned it yet lol

t = 5 after you take the derivative

[north hemlock]

hmm

yes

bc you set v(t) = 0

[strong furnace]

but asking a problem like this as a math question and assuming this has to be solved using applications of derivatives without even teaching derivatives is sus

[north hemlock]

^^

[icy basin]

well thank you everyone for the help.

your telling me

[north hemlock]

I somehow find it hard to believe that's the case

did you miss class or something lol?

that's so

weird

[icy basin]

nope. we start deriviatives tomorrow

rather monday

[north hemlock]

tf

weird

complain

rat him out to the higher ups

[strong furnace]

since the function is quadratic they could literally just use quadratic to get the solution if they wanted

[icy basin]

might have to do something

[north hemlock]

true

but then why the solution use derivatives lol

kinda weirddddd nglllll

[icy basin]

i'm sure their is some way i'm not understanding. but i mean in the solutions they post they don't show their work they literally just posted the derivative

[north hemlock]

can you send the whole question 5

the question, all the info and the solution

bc it didn't even ask a question in the original screenshot you sent, it just stated the fact that the equation is h(t) given by blah blah blah

[north hemlock]

ahh

yeah, that's using derivatives

odd

Did your semester just start?

[icy basin]

yes

[north hemlock]

ohhh

I see

[safe island]

this is basic differentiation isn't it?

[north hemlock]

it is

[safe island]

i did this pre university

[icy basin]

i already know the course. but i didn't even think to use derivatives because we haven't touchedo n them yet

[north hemlock]

but the issue is that the person taking the test watsn't taught it before the tes lol

[north hemlock]

many people did

I don't like that everything is italicized

My latex is so much cleaner 😤

[icy basin]

haha

[safe island]

nox where are you from?

[icy basin]

canada

[safe island]

ah, i don't know much about canada

i think you should read up on some material

just to fill in the gaps

otherwise it will start snowballing

[icy basin]

techincally that's why i'm here, i'm reviewing trying to figure out what went wrong haha

but thanks everyone for the help! i'm gonna get back to studying

[north hemlock]

same here

good luck

Sup?

Idk about how accurate this is but I would say that you just do it

if it bothers you, you can just re-index it

sameee

lmao

exam

yes

nicee

I don't have a course 😔

I mean

meh

I have an anime pfp

how old could I possibly be

LMAO

mine in-person :(

[elfin snow]

same

I took the online macro test

so hard

nrn sry

[north hemlock]

I'm studying. sry

[alpine sable]

let's say i make a tall building on earth. would the building be leaning to the side at an angle or would it be shaped like the arc of a circle to the side at an angle? like, if i say that a tall building with height h describes an arc of θ degrees, which one would it be?

[charred flint]

both

[alpine sable]

uh..

[charred flint]

it would be an arc (not a circular one) from its structure, and it would be tilted from it's loose foundation on the ground

[alpine sable]

i don't really know how to solve this problem then..

it doesn't give any image

When designing very tall buildings, engineers should keep in mind the oscillation movement, which is typical of skyscraper structures. If the highest point in a 400-meter building describes an arc of 0.5°, what is the length of the arc described by that point?

if i don't understand it, how am i supposed to solve it?

[charred flint]

they're assuming a circle

[alpine sable]

so the second one?

[charred flint]

yea

[alpine sable]

and the arc would be theta times the radius, right?

in radians

[charred flint]

sure, but you don't have the radius

[alpine sable]

cuz if so i got this

[charred flint]

seems right

[alpine sable]

i tried putting it on google though, and all of them say it's 10pi/9 . what happened to the sin

i hate this question. they made it so ambiguous

and i don't understand it even after looking at the explanation

[strong furnace]

bruh

they used sinx=x

approximation

[trim current]

Would this be correct? The

The first 3 terms of a recursive sequence?

Would this be true?

[woeful pulsar]

looks okay but you probably should work on your handwriting, don't want to unnecessarily lose points for that

[trim current]

True true

[woeful pulsar]

wait

-53 instead of -68?

[trim current]

Wait wdym

[woeful pulsar]

a_4

[trim current]

Uhhg

Wait did I do my math wrong 💀 one sec

[woeful pulsar]

$a_4=5(-68)-3$ yeah?

[ocean seal]

811ττερραlE

[trim current]

Wait

[trim current]

Oh yeah my b

It was only for one two and 3 lmfao my b

I just put something random for 4 my b

[jade coral]

thread open?

[charred flint]

go for it

[jade coral]

cool, so i need to figure out how to find the inverse of an absolute value.
Im specifically trying to compute the inverse of the function
𝑓:𝑋→𝑋 if it exists. 𝑓(𝑥)=|𝑥|−2

[woeful pulsar]

when does an inverse exist

what is X?

[pseudo summit]

wdym?

[jade coral]

when there is only one y for every x?

[charred flint]

uh oh, the question is vague

[trim current]

Would this be correct?

[pseudo summit]

constant function?

[charred flint]

@trim current yes

[trim current]

Alright just wanted to check it haha

[stuck plinth]

hey guys

very quick question, quite stupid, not sure if theres an answer

[jade coral]

not sure what a constant function is, looking it up to answer lol

[stuck plinth]

but would you say -100 is bigger than -1?

[charred flint]

no

[stuck plinth]

or would you say its smaller

[woeful pulsar]

to check the formula, just check n=1, 2, 3

[stuck plinth]

some people definitely say its smaller @charred flint

[trim current]

Alright thanks bro

[alpine sable]

It is a smaller number

[charred flint]

that's because smaller has 2 definitions

[alpine sable]

There are more digits being used however

[stuck plinth]

right but if the word "is it a bigger negative number" is used

then yeah thats obvious

[jade coral]

oh ok, I assume it is a constant function