help-0

[peak niche]

@alpine sable yeah if it trig and Pythagoras

Go to another channel

Go to 2

[peak niche]

That's the whole y=k/x^3 stuff innit

Can someone remind me if there is a +c at the end of proportion

[glass lichen]

$y\propto\frac{1}{x^3}\implies y=\frac{k}{x^3}$

[peak niche]

Ok yeah thought not

[alpine sable]

what that symbol mean?

[peak niche]

Proportional to

[ocean seal]

Mosh

[alpine sable]

thank you

[rugged elbow]

ty

[tardy timber]

Have a differential equation problem, y'(x) = 3x^2/(3y^2-7), I found the implicit solution being y^3-7y=x^3-1. From here I wanted to find the interval(s) in which the solution is valid. I found which x values correspond to +-sqrt(7/3) i.e. vertical asymptotes in the solution curve, but I was told it does not include solutions outside that interval also? I thought it was only undefined at those two points only

[peak niche]

@rugged elbow 1/8 is 1/2 cubed

1/8 x 2048 is 256

So isn't it 4/27 cubed x 2048

Im not too sure but im fairly sure that's how u work it out

[tardy timber]

I guess a better question to my problem would be given the differential equation, y'(x) = 3x^2/(3y^2-7), is the interval in which the solution is valid (-1.83, 2.011) or (-inf, -1.83)U(-1.83, 2.011)U(2.011, inf)

[alpine sable]

I’m trying to find out how I got (85-9 root89) over 2

From squaring -9 over 2 + root89 over 2

[peak niche]

@alpine sable channel busy i think

[alpine sable]

?

[strong furnace]

It should be R-(values of x for which y^2=7/3)

[tardy timber]

right

thats what I thought

but prof said it also excludes values outside of those values of x

[barren pawn]

split it in 2 figures and sum up each area

[tardy timber]

channel in use

[strong furnace]

is there some other context as well?

[tardy timber]

oh sorry, I forgot the initial value

y(1)=0

[peak niche]

It's kinda fun helping here but I'm only smart enough to help with half the questions

[median kraken]

anyone got an idea what these two would be?

[strong furnace]

I really don't understand why your prof believes the interval and not the point itself should be removed , if I were to take this solution and take derivative at any point and put y(1) both the conditions should satisfy

[steady scroll]

hm I don't know why this is possible or why it becomes this

so I know -3/-2 will cancel out and become 3/2

[tardy timber]

yeah I thought the same

I'll ask again

[steady scroll]

why does -i sqrt3/2 become positive and why is the plus minus flipped?

[wise jewel]

Can someone please help me with this????

can someone help me figure out how the hell my teacher solved this?

[harsh swallow]

they're saying that the average of

QR and TS is YZ

and so QR + TS / 2 = YZ

and then you fill that in

and find x

and fill x into the formula for YZ

the reason they do that is because YZ is exactly halfway between QR and TS

which means you can use the average which in this case is the halfway point

or maybe it's easier to understand if you say you can find the halfway point which is the average

[wild gale]

How do I write a factored equation (g(x)) that is different from f(x) but still has the same zeros on a graph? That equation being y=(x+3)(x-1)(x-4)

I can’t wrap my head around how you could make a different equation that still had the same zeros

[harsh swallow]

you can scale the function and the 0s will be the same

(x+3)(x-1)(x-4) and 5 * (x+3)(x-1)(x-4) will have the same 0s

[wild gale]

Oh okay!

Thank you!

[harsh swallow]

green is original

red is 5 times

[wild gale]

That’s so helpful, tysm

[wise jewel]

ahhhh i see

@harsh swallow

what about this???

[harsh swallow]

👍

[wise jewel]

what's the ruling for how she solved that

like i see HOW she solved the problem

i just dont get the why

like why she put 7x-11/4x-2 yadda yadda yadda

😭

[harsh swallow]

using the similarity of the trapezium

[uncut thorn]

is there an error because im sure i got it right but the choices dont have what i got

[sudden hawk]

KoldBlazd ur in the premier Pro discord!

[uncut thorn]

or did i do it incorrectly

[sudden hawk]

Wtf is ur name

[uncut thorn]

bruh i forgot to change it

[wise jewel]

@sudden hawk oh shitttttttttttt

what're the chances LMAO

[sudden hawk]

Lmao

[wise jewel]

how do you remember me??? i only ever messaged there like once a loooong time ago hahaha

[sudden hawk]

Lol idk

[harsh swallow]

so first they see that the whole thing is 35 and the first part is 20 so the remaining part needs to be 15

then they use ratio of the larger trapezium to the smaller trapezium

7x - 11/4x - 2 = 20/15

[midnight crag]

x=22 in first question

[harsh swallow]

@uncut thorn you could use pythagoras as a double check

[nimble matrix]

how to solve this integral ?
i have tried u-substitution but i am still stuck

[muted raft]

u sub will definitely work here

[nimble matrix]

by u-substitution, i get du/2y=dy

[median kraken]

said it 22 was wrong lol

for this

[muted raft]

find a way to change 9 to 1

then you can apply the standard integral $\int \frac{1}{u^2+1} ,du = \arctan\qty(u)$

[ocean seal]

zslya

Πολλά άτομα είναι

[alpine sable]

Chord-Chord Power Theorem

x=12

[median kraken]

so would it be 12? @alpine sable

oh nvm

just saw you say that lol

thx

now would i do the same thing for this one?

9•8 = 36x?

so x=2????

[alpine sable]

If two chords of a circle intersect, then the product of the measures of the parts of one chord is equal to the product of the measures of the parts of the other chord.

[peak niche]

@median kraken yes

[alpine sable]

which indeed you're right

[ocean seal]

Πολλά άτομα είναι

[median kraken]

thx @alpine sable just did all other questions like that

helped a lot

[alpine sable]

👍

[median kraken]

any idea on this one?

[alpine sable]

Central Angle

So the measure of the arc will be equal to the central angle

[ocean seal]

Πολλά άτομα είναι

[harsh swallow]

@nimble matrix You need to find a way to substitute such that there is a 9 in front of the u^2

so that you can remove the 9 from the + 9

turn it into +1

[median kraken]

so i would enter <TSR? @alpine sable

[alpine sable]

Nah 104

[nimble matrix]

@harsh swallow ok thanks

[alpine sable]

says angle TSR=104

[echo river]

What is 0 divided by 0?

[median kraken]

56

lol

[echo river]

Lol

[median kraken]

wdym?

on the question is says m<RST=104

[alpine sable]

yeah

which is the same thing

just backwards

[median kraken]

yea i see that

[harsh swallow]

there is no 0/0

[alpine sable]

mk

[harsh swallow]

undefined

[echo river]

Ohk

[nimble matrix]

infinity

[median kraken]

ohh i see what your saying thx for the help man

[alpine sable]

same stuff

[median kraken]

48?

would this be the same thing also? @alpine sable

[nimble matrix]

@harsh swallow i tried hard but couldnt find a way to do that

[harsh swallow]

y = 3u

[nimble matrix]

from where that 3 came ?

[harsh swallow]

if you make y = 3u

the bottom part will turn into 9u^2 + 9

which you can then seperate

[alpine sable]

sorry had to go for a sec

[median kraken]

no worries.

[nimble matrix]

@harsh swallow so we actually assumed it
right ?

[harsh swallow]

that's the substitution you do

you start with y as the variable

substitute y = 3u

[nimble matrix]

ok thanks

[alpine sable]

inscribed

angle

[median kraken]

so what would that change for this problem

[alpine sable]

arc is double the measure of the angle

make up an equation and likewise find it for 1 hour of work

and then mulitply with 6

[median kraken]

i’m not quite sure what you mean by that lol

[alpine sable]

Double 56

140/8,75*6 to question 3 @hybrid roost

Which is 96 for 6 hours of work

[wise jewel]

how did my teacher solve this?

[alpine sable]

np

[median kraken]

so 112?

[harsh swallow]

@wise jewel so first they see that the whole thing is 35 and the first part is 20 so the remaining part needs to be 15
then they use ratio of the larger trapezium to the smaller trapezium
7x - 11/4x - 2 = 20/15

[wise jewel]

hm

alr

ill try to remember that

what ab this?

[harsh swallow]

JL = x

JM = 12

ML = x - 12

that's first step

and then again ratio

because it is an angle bisector

it means

JKM = LKM

and so you can us the ratio of

12 : x-12 = 18 : 30

[alpine sable]

would this be a euler path or circuit or none, I can't seem to do this..

[ashen berry]

Could someone please help me with my solving right triangles test i have it today in 2 hrs I would really appreciate it if someone could help me

[fading rover]

Not a Euler path

As per this

[fading rover]

We can’t help you with your test :( but we can help you with problems

[native remnant]

can someone help me with this

[alpine sable]

it's none

thank you for the help though!

[fading rover]

No problem

[fading rover]

The first step is to make a factor tree for the inside radicals and find out what can be taken out

[shrewd marsh]

Does someone know how to do this
This is the first time I’ve seen this type of question

[fading rover]

Please withhold, there is an ongoing question.

[shrewd marsh]

Oh sorry

[fading rover]

Here’s how I did the first term

Even though it’s a fraction, we can take the bottom term and factor the denominator out

[native remnant]

so far i have 4 (√1 / 3√3) + (7 / √3) - (3 / 8 ) * 4(√15)

[fading rover]

The first term should be changed, the second term should be 4 sqrt(1/3)

The last term is correct

The first two terms can be added together

[native remnant]

wait im confused

[fading rover]

What’s up

[native remnant]

how exactly do i add the first two terms together

sry im being really stupid rn

oh wait i see it now

[nimble matrix]

@harsh swallow how do we know that we have to do y=3u ?
I mean generally, we just let u =some term
I mean what is in the equation helped you to know that we have to let y=3u ?

[elder kindle]

Look for squares that can be taken out

[native remnant]

so (16 / 3)(√1 / 3) - (3 / 8)(4√15)?

[elder kindle]

27=9*3
49=7*7
240=16*15

[native remnant]

so the first term would be 4 * (√1 / 3√3)?

[elder kindle]

$\frac{4}{3√3}$

oops

[ocean seal]

zombiemode

[native remnant]

oh

[elder kindle]

Remember that the sqrt of 1 is just 1

[native remnant]

and then the second term is 7 / √3 right?

[elder kindle]

yup

[native remnant]

im still confused on how to simplify the last term

[elder kindle]

Here's a trick you can use

divide down in a tree (idk the term but when you do stuff like this )

and basically just start with 3s and 2s

[median kraken]

that looks like a person

like a 4yo trying to draw lmao

[native remnant]

so 4√15

[elder kindle]

until the term on the left is 1

3*2*2*2*2*5

2^4 is a sqrt, 16

240=16*(3*5)
take out the 16 and you're left with 15

So yes

the final term would be $\frac{-3√15}{2}$

[alpine sable]

yes

[ocean seal]

zombiemode

[median kraken]

do you mind if we talk in dms for the last three questjons? not trying to make everything clogged

[elder kindle]

since 12/8 simplifies to 3/2

[native remnant]

ah ok

[harsh swallow]

@nimble matrix We have $\frac{1}{y^2 + 9}$

[ocean seal]

Katharine

[harsh swallow]

and to get a 1 from that 9

we need to make it

$\frac{1}{9u^2 + 9}$

[ocean seal]

Katharine

[harsh swallow]

so that we can take out the 9

$\frac{1}{9} \frac{1}{u^2 + 1}$

[ocean seal]

Katharine

[harsh swallow]

sorry for barging in, we had a conversation on this channel but continue

🙂

[native remnant]

for the first two terms should i get rid of the sqrts on the deminators

[elder kindle]

Yes

[native remnant]

and then get a least common denominator

[elder kindle]

If that's your teacher wants

It's good form

[alpine sable]

yeah no worries

[native remnant]

so rn i have (12√3 / 27) + (7√3 / 3) + (-3√15 / 2)

so the least common denominator would be 54 right?

or would it be something smaller

[elder kindle]

yes

It's 54

[native remnant]

k

so (24√3 / 54) + (126√3 / 54) + (-81√15 / 54)

[native remnant]

i ended up with 150√3 - 81√15 / 54

[elder kindle]

pause

why did you get 12√3?

[native remnant]

shoot

uh

oh yeah

for the 4 / 3√3

the way my teacher wants me to do it is multiply both sides of the fraction by the demoninator

to get rid of the sqrt

[elder kindle]

It wouldn't give you 12

or 27

you should get $\frac{4\sqrt{3}}{9}$

[ocean seal]

zombiemode

[native remnant]

oh

god im retarded

[elder kindle]

you're good lol

so your lcd is 18

[native remnant]

so (8√3 / 18) + (42√3 / 18) + (-27√15 / 18)?

so doesnt that go to 50√3 - 27√15 / 18

but thats what i got before

so

im not sure if its right or wrong

[elder kindle]

your previous answer was wrong

[elder kindle]

your final one was right

[alpine sable]

Help someone

[warm marsh]

You can consider the area as the sum of 3 rectangle's area + 2 triangle's area.

[full walrus]

Can anybody please help id be really grateful

[warm marsh]

Help someone
@alpine sable
3015+3010+(30-5-5)5 + 2((5*5)/2) = 450+300+100+25=875

[alpine sable]

uh

tyyy

[full walrus]

I just need directions for the task

[warm marsh]

If that quadratic is < 0 it's graph will be under Ox axis

It means that the discriminant or delta will need to be negative, and the coefdicient of x^2 as well

[full walrus]

Yes but only for interval of 1,2

Not always

[warm marsh]

Firts i think you need to put that 2 condition for wuadratic to be <0 then to write x in terms of k

[full walrus]

Writing x in terms of k is basically imposible

No way to make this work

[warm marsh]

No way to make this work
@full walrus

And then substitude k=1 and k=2 in the quadratic and find x

[full walrus]

Bro i really appreciate

But

I need to find k

Which makes the quadratic less than zero only when x is less than 2 and greater than ona

One

[misty jasper]

can i get some help please?

[mossy stirrup]

How can you determine if a quadratic relation is a perfect square trinomial or a difference of squares?
Define both and provide an example

Help plz

[remote heron]

try just writing them down and expanding

for example a difference of squares is usually written x^2-a^2 with a as some number

or maybe going the other direction, if you have like (x-a)(x+a)

this is a difference of square

note the sign flip between factors

so theres a lot of ways

@mossy stirrup

if you explore them a bit youll see plenty of stuff to write, id try desmos too

they have neat easily identifiable forms and features

[raw raptor]

Why is -2^2 not 4?
I mean -2 * -2

[errant sparrow]

hi does someone know how to calculate the standard deviation?

[remote heron]

yea its a nice number

check out a normal distribution chart

nothing really to calculate

[remote heron]

$-2^2=-4 \ (-2)^2=4$

[ocean seal]

jan Niku

[remote heron]

[errant sparrow]

does someone know the answar to my question?

[remote heron]

yea

use a chart

[errant sparrow]

my teacher is a weirdo

[lapis mural]

Is this

-[(+2)^2]

[remote heron]

basically, yea

although youd probably never write the plus

the idea is that $-2^2=(-1)(2)^2$ but $(-2)^2 = (-1)^2(2)^2$

[errant sparrow]

thanks

[ocean seal]

jan Niku

[remote heron]

by exponent rules and stuff

[sonic trellis]

This free or in use?

[remote heron]

looks free i think

[sonic trellis]

ok

I am supposed to find EG

How should I go about that?

[remote heron]

solve the component triangles

[sonic trellis]

I don't follow

[sand arch]

Pls help me

[errant sparrow]

<@&286206848099549185>

[mossy mulch]

first solve for FG using pythagoras theorem, then solve for FH, using the same. finally using those two lengths calculate for HG and add it to 32

[alpine sable]

Dont understand how to find zeros. Did a similar problem a few minutes ago but for some reason this stumps me

[fervent sparrow]

Any ideas? Assuming that it is x csc^2 (x) *x dx

[sonic trellis]

Would I put (32+x)^2 + 40^2=FG?

fg squared

of course

[mossy mulch]

oh no

[sonic trellis]

?

[solar pilot]

can someone help me

[mossy mulch]

yeah i didnt realise 32 was for EH not for EG

my bad

[sonic trellis]

Its all good

the goal is to find EG

[mossy mulch]

is there any additional information?

[sonic trellis]

Nope

want the picture again

If so, here it is

[mossy mulch]

what did u get for FH?

[fallen saffron]

please help

[sonic trellis]

Let me solve rq

[mossy mulch]

i got 24 for FH

[sonic trellis]

Same

I did 32^2 + b^2 = 40^2

[sonic trellis]

what would be the following step

[somber oak]

How do you rationalise the denominator ?

[mossy mulch]

im also thinking

[mossy mulch]

root 2

or 2^1/2

multiply both numerator and denominator

[somber oak]

I multiplied both by root 8 and the answer was 2 x root 8 divided by 8

[mossy mulch]

multiply both with root 2

[somber oak]

Why with 2?

[mossy mulch]

8 is 2^3

if we multiply one more 2

it becomes 4

which is divisible by 2

also can someone please check #help-7｜zen1thxyz

[alpine sable]

https://cdn.discordapp.com/attachments/845015542070902784/845016180539392040/unknown.png

Yeah thanks

I remembered how t do it lol

Is there anything special to solving this Euler path?

can anyone help with https://cdn.discordapp.com/attachments/845015542070902784/845016180539392040/unknown.png

[alpine sable]

It seemed pretty straight forward to me

[valid wagon]

Can anyone help me with this question on binary operations?

Part b specifically

[alpine sable]

yall just skipped me

read #❓how-to-get-help

Does one have to start on an odd vertex for Euler Paths

Hmm, on my screen my post precedes yours

Is there any standard notation for Euler paths, does one write the numbers

[valid wagon]

Yes you start and finish on off

A graph is eulerian if all vertices have even degree

[alpine sable]

Yeah, I know those rules

and two for odd numbers

for Eulerian Path

[valid wagon]

Semi Eulerian if 2 off nodes

[alpine sable]

the other is Eulerian Circuit

[valid wagon]

*odd

Semi eulerian

Means you have specific start and finish points

Those are the odd nodes

[alpine sable]

Mostly curious as to the notation style

It seemed pretty straight forward to me otherwise

Also, does it matter if one starts on the odd vertices or even ones?

[valid wagon]

You just list the nodes

{a,b,c,d} for example however you can do the edges {ab,bc,cd}

[alpine sable]

look all the way up

lmfao

[valid wagon]

@alpine sable since you are doing discrete maths do you know anything about binary operations

[alpine sable]

Like this

?

[valid wagon]

Yeah

To notate it

You just list the nodes

In order

Of the route

[alpine sable]

Not enough to be of help I'd imagine

Started like two weeks ago with the math, mostly prepping for exam and Calculus at uni.

[valid wagon]

Yeah

[alpine sable]

Do you mean ennumeration or?

[valid wagon]

What

Is that

Lol

[alpine sable]

Otherwise I don't see how one discerns the order

[valid wagon]

In the curly brackets

You want to know how to notate it ?

[alpine sable]

Sure 😉

[valid wagon]

Like notate the Euler path?

[alpine sable]

What is the optimal notation for this

Ah okay, seems like this is it

Presumably that's what you meant

This chat free?

[limber sedge]

1 dollar now

[alpine sable]

Can anyone verify this

Also, if mathematically elaborating that this is a Euler graph is there anything significant to mention beyond the fact that all vertices are an even number?

<@&286206848099549185>

Hmm, unsure of how to plug this into CAS

When trying to do it this automatic way, obviously the definition overwrites itself

Anyone know this?

[teal rune]

Two circles have diameters of 8 units and 5 units.
How far apart are the centers if the length of the common external tangent segment is 12?

<@&286206848099549185>

[upbeat current]

How do I write a straight line in the Argand plane?

[upbeat current]

Let's say I want to put a line like y=-x in the Argand plane

[fickle ridge]

how can I solve that?

[upbeat current]

How do I write a straight line in the Argand plane?

Let's say I want to put a line like y=-x in the Argand plane

[teal rune]

yo

[rigid ravine]

Yes

[teal rune]

the bottom right tells you that its a 90 degree angle

im pretty sure

uh

[alpine sable]

https://media.discordapp.net/attachments/490557019623915520/845026398799659028/image0.jpg?width=394&height=525

anyone

?

[teal rune]

is WXY 90

[alpine sable]

can you guys help me on this

anyone know the answer ?

[somber oak]

How woikd you rationalise the denominator for this

[gloomy lintel]

Just Multiply top and bottom by root 12

You can simplify root 12 first if you want

So 2 root 3, then I’d only times top and bottom by root 3

[iron tartan]

Hello, can someone help me with this?

[somber oak]

I tried that but it’s not the answer

I got root 12 root 36 over 12

[gloomy lintel]

So what did you get

Well root 36 is 6

Root 12 is 2 root 3

So your answer is 2 root 3 +6 all over 12

Yeah that’s what I just said

So it’s root 3 plus 3 all over 6

[somber oak]

The answer is e

[gloomy lintel]

Yeah so it’s this one

[alpine sable]

The answer is always e

[somber oak]

E

I wish my maths teacher taught us this lol

I have to teach it myself

And the revision book doesn’t even teach this

[alpine sable]

The random variable X is said to be log-normal if the probability density function of ln(X) is normal. Suppose X and Y are two log-normal random variables. Suppose that the joint pdf of ln(X) and ln(Y ) is normal. Is Z = XY a log-normal random variable? Justify your answer.

Please help

[grizzled hull]

how do i find coterminal angle of -135

[strong furnace]

coterminal angles are those angles whose rays on the unit circle correspond

so -135 + 360n for n in Z

[grizzled hull]

ah i see

ye something about the circle

[alpine sable]

1 + _/3 / _/12
1+ _/3 / _/4 x _/3
1 / _/4
1 / 2 (not sure but I think it may be right)

Is the topic surds?

[somber oak]

Yes

[granite lily]

Is this correct and how do I do the rest

[native temple]

What to do here?

the difference is 3.07/15

but that’s a decimal

<@&286206848099549185>

[alpine sable]

find the average of the first and last numbers

and multiply it by 100

the amount of terms

[native temple]

won't the average just get term 50?

[alpine sable]

no...

[native temple]

also how was I supposed to figure that out?

[alpine sable]

It's a formula

[native temple]

The what does it get

[alpine sable]

Or maybe yes

idk

[native temple]

WHEN I GET THE AVERAGE WHICH TERM EILL IT GET(caps look on phone)

[jolly thistle]

Can anyone help? A pizza shop needs 1/4 cup of basil for each pizza. How much basil does it need for 25 pizzas? Write your answer as an improper fraction

[alpine sable]

If it's increasing at the same rate,

I think you're right

it should be the middle term.

but that's not the point of the problem

The point is to find the sum

[native temple]

It doesn’t use signa?

[alpine sable]

no...

[native temple]

I heard of carl gauss who’s that?

from my lesson

he did something with

[upbeat current]

How do I write a straight line in the Argand plane, like y=x?

I.e if a question asks me to solve |z-1|=|z-i|

How do I answer it?

z=a+bi

[somber oak]

How woikd I find out x as an interger?

[plush kestrel]

rearrange?

[teal rune]

^

[ocean seal]

Zyhlex

Zyhlex

[alpine sable]

help

I got 218.19 for the first one... idk if that's right

and for the next one I got 47.9 and i know that's wronmg because the answer was 11.2

[upbeat current]

how do I differentiate this lol

[harsh swallow]

write it as a power

[alpine sable]

do anyone know how to use octave ?

[gloomy lintel]

So the function is (2x-5)^-1, use the chain rule
Derivative of inside comes outside, bring the power down to the front, and take one off the power

[upbeat current]

yea I figured it out but thx

[unkempt stream]

why is it increasing for this question?

isn't when f' and f'' signs don't equal it's decreasing?

dy/dt=-.02y^2

[upbeat current]

it's decreasing when f'<0

f'' is the concavity

The question is asking at what speed the speed is increasing/decreasing

i.e, the derivative of your derivative

[unkempt stream]

fck I think I'm confusing it with speed

[upbeat current]

remember

when you differentiate, you're taking the y axis/x axis for the units

so if the y axis is distance, and x is time

y'=distance/time=speed

then, it's distance/time/time for y'', or acceleration

[unkempt stream]

yh the question doesn't have to do with distance

thanks

[upbeat current]

plz help

[upbeat current]

It's the same principle

[sturdy rapids]

Is this channel free?

I need help

[upbeat current]

no

[sturdy rapids]

ok

[knotty sleet]

The function is not continuous

It has a vertical asymptote at x=5/2

So although it is decreasing, the reasoning would only be correct if the function were continuous

And so due to the asymptote there is no global maximum as the function can obtain arbitrarily large values

@upbeat current

Does that make sense?

[upbeat current]

yeah thats what I got

[knotty sleet]

It may help to graph it

[upbeat current]

no calculator question :p

[knotty sleet]

Ok great👍 🙂

[upbeat current]

but

if I wanna write an equation

[knotty sleet]

You can sketch it by hand

[upbeat current]

is that this?

1 sec

or like how do I state this

[knotty sleet]

What about it?

Oh

[upbeat current]

its asking me to solve the problem

[knotty sleet]

You can say the limit from the RHS tends to infinity so the function is unbounded and so there is no global maximum

Don't just write the limit is infinity though because the limit doesn't exist

[upbeat current]

yeah thats what i realized

isnt there a limit I can write that will make it=infinity?

isnt it

like

x+

if it approaches from the right?

[knotty sleet]

Put a small '+' superscript on 2.5 to denote RHS limit

[upbeat current]

ah

so limx->2.5+ will be infinity?

[knotty sleet]

Yes

[upbeat current]

but I cant solve that

I can just express it like that

[knotty sleet]

Solve what

[upbeat current]

lim x->2.5+

of 1/(2x-5)

[knotty sleet]

You just need to state that the limit approaches infinity

You don't need to solve anything

[upbeat current]

Yeah alright

[knotty sleet]

And then add a brief comment like this

[upbeat current]

Yeah the question was worth a lot of points just seemed pretty trivial lol

but thanks mate 🙂

[knotty sleet]

Ahahah😅 Don't worry, you got it right!

[unkempt stream]

wait so when the second derivative's sign is not equal to the first derivative's the rate of change of something's rate is decreasing right?

[upbeat current]

what

look

when you go in a car

and you start driving

your speed is the change of distance in relation to time right

that is the first derivative

and your acceleration is your change in speed in relation to time, like if you go from 30km/h to 60km/h

that is your second derivative

[unkempt stream]

yh

this was what I was confused about

the second derivative's sign does not equal the first derivative's

[upbeat current]

d) is just asking about your second derivative

[unkempt stream]

ohhhhhhhhhhhhhh

damn

[sturdy rapids]

Hey I need some help

[unkempt stream]

thank you

[upbeat current]

np

[sturdy rapids]

plz

[upbeat current]

post your question

[upbeat current]

draw a tree diagram?

[sturdy rapids]

I tried but, I just got confused

[upbeat current]

i dont remember tree diagrams but

you have 7 items

so 7 different outcomes

if I have 1 notebook

or if I have 7 items

and one of them is a notebook

what is the probability that you will get it

if u choose one randomly

[sturdy rapids]

1/7

[upbeat current]

yeah now do that for all of them

[sturdy rapids]

for the sketchbooks it would be 3/7

and the sticky notes it would be 3/7 of as well

[upbeat current]

ah ok so for the tree diagram

draw one branch for example

where you remove the notebook

so that you calculate a new probability of dependent events

[sturdy rapids]

remove the notebook?

[upbeat current]

idk honestly

sorry

long time i did this

[sturdy rapids]

should I ask someone else?

[pale terrace]

0.5^x < sin(pi/3 *x)

I'm supposed to find a solution for this graphically but it's hard to come up with a range of where this can be true

[oak chasm]

@pale terrace See https://www.desmos.com/calculator/hminhntx40

[pulsar smelt]

can someone help me through this?? i dont know where to start ;-; (solved!!)

[shell widget]

You have g(x) * (x^2 - 3x - 4) <= 0

Basically, if the product of two numbers is negative, then one of the numbers is positive and the other is negative.

So either g(x) <= 0 and (x^2 - 3x - 4) >= 0 or g(x) >= 0 and (x^2 - 3x - 4) <= 0

solve both the cases, see what u get

[pale terrace]

thank you for taking the time to make this

[pulsar smelt]

ohhh thank you!

[oak chasm]

No problem.

[pale terrace]

how would I write a range for this in terms of x

I can't say when x is in between the period of the sin function because there are times when it's greater

if that makes sense

[oak chasm]

@pale terrace Let's switch to #help-2 since this got busy.

[pale terrace]

okay

[brave fossil]

hello

can someone check my implicit differentiation work?

[shell widget]

@brave fossil Hm wolffram says that dy/dx = (-1-xy)/x^2

[brave fossil]

so that should be correct

[shell widget]

yours is (1-xy)/x^2

[brave fossil]

hmm

do you where i went wrong?

@shell widget i really cant see where i made a mistake could u help me?

[shell widget]

im checking

[shell widget]

Oh LOL mb

I put the wrong thing in wolffram

Sorry!

Yes it's correct

[brave fossil]

ahh that makes sence

all goods man

just another quick problem :

is this correct?

[ocean seal]

Chai T. Rex

[brave fossil]

it also says

f'(1) >0

so how do i draw that

i thought f''(1)=0 means its an inflection point where concavity changes

[oak chasm]

Well, let's look at a few other things first.

Right, it also means it's equivalent to a linear function or a constant slope at that point.

Let's look at the last two bullet points.

[ocean seal]

Chai T. Rex

Chai T. Rex

[oak chasm]

You have it shown as concave up as it approaches x = 1.

[brave fossil]

i guess but how do i make it uncurved and increasing at the same time?

[oak chasm]

No, it should be curved so that it's concave down.

Let's see.

This section is concave up. The part just to the left is rising, but concave down. Make the whole thing concave down.

[brave fossil]

alright i sec

better?

[oak chasm]

Yes, looks better.

[brave fossil]

gotcha cheers man!

[oak chasm]

No problem.

[vivid jay]

do you guys work with parabolas?

[oak chasm]

Sometimes.

[vivid jay]

oki

[granite lily]

Can anyone check my trig hw for me

Just to see if it’s right

[upbeat current]

help pls

this my question

[shell widget]

integrate f'(x) to get f(x)

[upbeat current]

why?

[shell widget]

to study f(x)

[upbeat current]

ok

1 sec

ohh

i think i know why

one sec

DONE!

obviously + C but I removed it

ok so

sin is -1

for x/2=270

yes

so thats

540

im not getting anywhere

[shell widget]

okay

So for the first part

sin(x/2) does have a maximum but x^2 doesnt

[upbeat current]

i did that

im on b)

[shell widget]

Oh ok

[upbeat current]

sorry

[shell widget]

no prob

[upbeat current]

i did f''(x) tho

and showed it cant be less than 0

[shell widget]

what's the minimum value of 12sin(x/2)?

[upbeat current]

-12

but thats when x is 540

or 1.5pi i guess

3pi*

[shell widget]

uh

for minimum

[upbeat current]

oh but im only supposed to show it has a minimum

not determine it

but i have a quadratic

[shell widget]

well solve for f'(x) = 0

see if there is an x

that satisfies it

[upbeat current]

this equal to 0? :p

i was told its impossible

[shell widget]

well not impossible

[upbeat current]

yes

no solutions

[shell widget]

Oh wait

[upbeat current]

the answer sheet says that u get a point for showing that f' has a zero

like wtf

[shell widget]

you can solve for f'(x) = 0 using numerical methods

like newtons method or something

dunno if uve been taught that

Or

[upbeat current]

its not solveable

[shell widget]

-1 <= sin(x/2) <= 1, then -12 <= 12sin(x/2) <= 12

-12 + 2x^2 <= 12sin(x/2) + 2x^2 <= 12 + 2x^2

x^2 >= 0, 2x^2 >= 0, 2x^2 - 12 >= - 12

[upbeat current]

thats the second derivative

not the derivative

[shell widget]

So we have -12 <= -12 + 2x^2 <= 12sin(x/2) + 2x^2 <= 12 + 2x^2

and we've shown that the function 12sin(x/2) + 2x^2 >= -12

so yeah there does exist a minimum

[scarlet spire]

not a math question but what does the k in jfk stand for

[upbeat current]

chicken?

[scarlet spire]

no fr what is it

[shell widget]

who gives a shit

@upbeat current Any question?

[upbeat current]

i wasnt supposed to solve it

just show that it exists

[shell widget]

I didn't solve anything either

[upbeat current]

I can show f'(x)=0 has a solution

by just showing that f''(x) is always positive

and that x belongs to all real numbers

[shell widget]

dunno about that, i'm a bit rusty but have u studied intermediate value theorem?

just plug the values in

ill do part 1 for u

You'll have to do the other part yourself

$2(3) + 3(-1)^{2} - (2)$

[ocean seal]

Sup?

[shell widget]

This is what u get after plugging in the values of a,b,c

now can u simplify?

How is it harder?

[bold token]

you just simply substitute the values

wdym

[shell widget]

$(2 \times 3) + (3 \times -1 \times -1) - 2$

can u multiply

[bold token]

you square -1

-1x-1

[charred flint]

[ocean seal]

Sup?

[bold token]

think of the letters as values

[gray isle]

$(-1)^2 \neq -1$

[ocean seal]

ℝamonov

[bold token]

-1 times itself

[shell widget]

Yes but $- \times - = +$

[ocean seal]

Sup?

[shell widget]

Yes

sadly, no

how are u getting 5

[viscid fossil]

What is the best choice to get the maximum return after one year of deposit? Justify your answer.

[upbeat current]

can someone tell me

how i can express a straight line

in the Argand plane

such as y=-x

[shell widget]

y=-x works just fine

[upbeat current]

but I have

z=a+bi

theres no y or x axis

and b=-a wouldnt make sense would it

[shell widget]

b=-a works as well but we just let x=real part, y=imaginary part

[charred flint]

arg(z)=c

[shell widget]

but doesn't that restrict the line to only one quadrant?

[charred flint]

probably for some definitions yea

how about tan(c)=b/a

[shell widget]

@alpine sable Yes

[fringe yoke]

Y'all got time for a quick question ?

Im workin on series

rn

[shell widget]

try another channel

[fringe yoke]

Aight

[shell widget]

its busy

Yes

And it's free!

[rocky dock]

that answer is incorrect, can some1 explain what i am doing wrong?

[gray isle]

show work

[wary stream]

Which answer? The final answer?

[rocky dock]

@wary stream yes

@gray isle ok 1 sec

x = 6 (+/-) sqrt (80) / 2

x = 3 (+/-) 4 sqrt (5)

[gray isle]

and you're not dividing properly

are you doing this on paper?

[rocky dock]

yes on paper

[gray isle]

$\frac{6\pm\sqrt{80}}{2} \neq \frac62 \pm \sqrt{80}$

[wary stream]

Factor out the 16 from the square root first, then divide

[ocean seal]

ℝamonov

[rocky dock]

@wary stream dont quite understand

[wary stream]

Don't divide by two first

Take the 16 out first

[gray isle]

to be more specific don't only divide the 6 by 2 because that's not how fractions work

(as indicated in that tex above)

[rocky dock]

@wary stream can u display it

[gray isle]

do you understand the tex i displayed above?

[rocky dock]

@gray isle not really tbh

[wary stream]

$\frac{6 \pm 4\sqrt{5}}{2}$

[ocean seal]

dldh06

[rocky dock]

i understand but i dont know why the sqrt of 80 isnt divided by the 2 as well

[gray isle]

IT IS SUPPSOED TO BE

[wary stream]

Do that first

[gray isle]

but you didn't do that

[wary stream]

$\frac{6 \pm \sqrt{80}}{2} = \frac{6 \pm 4\sqrt{5}}{2}$

[ocean seal]

dldh06

[rocky dock]

so this isnt the answer, it was you pointing out my mistake?

@gray isle

[gray isle]

yes exactly

as indicated by that NOT equals sign

[rocky dock]

ill be back

i think i got it

[keen trail]

Can someone tell me how they got this as the particular solution

If someone can break it down for me

[wary stream]

Find the general equation of the right side. Take the derivatives, and plug them into the left side, solve for unknowns

[compact elbow]

Which one is right I did all of them and there all not equal

[wary stream]

Show your work

[compact elbow]

Ok

For A I got 6 8

[wary stream]

That's already wrong

Do you know how powers work?

[compact elbow]

no

[wary stream]

Like what is $4^2$?

[ocean seal]

dldh06

[compact elbow]

Um

[wary stream]

How else can you write a power?

[compact elbow]

Idk

[wary stream]

$4^2 = 4 * 4$, correct?

[ocean seal]

dldh06

[compact elbow]

O

I thought is was

4 times 2

So 8

But it’s 4 time 4

Ok let me do it now

[wary stream]

Is that written $4*2$ or $4^2$?

[ocean seal]

dldh06

[compact elbow]

4 2

Not with a *

[wary stream]

So it's a power, so what I said before 4 * 4

[compact elbow]

Ok

So like a is

2 time 2 time 2 and 4 time 4

Bc it said 2 3 times

And 4 2 time

[wary stream]

Yes, exactly this

[compact elbow]

Ty

[alpine sable]

sorry ik this a mathematics server but can anyone help me with this physics question i’m stuck on

[compact elbow]

So is it A

[keen trail]

@wary stream can you show me an example real quick?

Like from that problem

Since i got it wrong its going to give me a new problem but same format of the question

[alpine sable]

not math but physics w some math

can someone explain 🥲

please respectfully. 🥺

[compact elbow]

Just to be clear is -15 colder than -9

[alpine sable]

yes

[compact elbow]

Ty

[rocky dock]

ok im back, sorry im not disturbing just wanted to let you know that i got 3 (+/-) (4 sqrt (5) / 2)

@wary stream

[wary stream]

Can you post your work again/problem?

[wary stream]

It's just q3. This is an example

[wary stream]

Why did you only divide the 6 by 2?

[rocky dock]

i didnt

one se

one sec

thats my final answer

[wary stream]

You can still divide in the second fraction

[rocky dock]

really?

[wary stream]

Yes

[rocky dock]

i thought someone said the 4sqrt(5) was its own thing

it would be like mixing pineapples and oranges

[wary stream]

That would be something like $4+ \sqrt{5}$

[ocean seal]

dldh06

[rocky dock]

ohhhhhh

[wary stream]

You can rewrite $\frac{4\sqrt{5}}{2}$ as $\frac{4*\sqrt{5}}{2}$

[ocean seal]

dldh06

[wary stream]

Use a calculator

Look it up

If you're on a flip phone, how are you on discord?

How

The phone has a calculator

[wary stream]

Yes

[rocky dock]

@wary stream so just to clarify when i divide the 4 by 2

i dont keep it for the sqrt(5) right?

[wary stream]

We're busy sorry

[wary stream]

What do you mean exactly?

[glass lichen]

try a calculator

[wary stream]

No need for caps

[glass lichen]

then google a calculator

[rocky dock]

@wary stream nevermind, i got confused for a sec

im good now