help-0

[hybrid copper]

x = -10 is correct here

[sullen imp]

uh log eh

[hybrid copper]

yes

[sullen imp]

i think jus algebraic is what i need, if its even possible

[hybrid copper]

You mean solving it without log?

[sullen imp]

ya

log values might not be available

[hybrid copper]

Not sure this is solvable without

[alpine sable]

tried but didn't get the ans

[heady sequoia]

Can I see your work?

[carmine jetty]

help

[sullen imp]

yeah thats what i thought too

but even with log

[hybrid copper]

with log there is no problem, if you have a calculator

[sullen imp]

hmm

how would i go about that tho

[hybrid copper]

Did you get to the point where you have x = (smth)

[alpine sable]

pls

[sullen imp]

like simply taking the log of (7^3-7^-1+2.7)?

[alpine sable]

H the centre?

If so Central Angle Theorem, if not, Inscribed Angle Theorem

[carmine jetty]

its not in the center

[hybrid copper]

You just type it in your calculator like this with a log() around?

[carmine jetty]

i dont understand inscribed

please explain

[sullen imp]

ah

[hybrid copper]

You know how to calculate with logs? Like what you can do if you have log(a * b)?

[sullen imp]

yeah yeah

[hybrid copper]

and log(a^b)?

[sullen imp]

u sure its not possible without a calculator

cuz this is a qn for a non-calculator test iirc

[hybrid copper]

you sure?

[sullen imp]

not sure tbh

with a calculator this isnt much of a challenge lol

[jade portal]

Please help

<@&286206848099549185>

[sly mantle]

@jade portal wait 15min before pinging helpers

[wary stream]

What's the pattern?

The question is 1, _ , 5, 7, _ , 11, correct?

[hybrid copper]

Alright there may be a way. Try to first exclude your fraction and any 7^x, so you have one factor with your variable and the other one is just numbers

[wary stream]

There's a pattern, what is the pattern?

[sullen imp]

yeah i tried that, couldnt do much further

[wary stream]

There's arithmetic and geometric sequences, which one is it for that question?

Is it changing at a common value or exponentially growing?

So is it changing with a common difference or exponentially changing?

Look at how the values are changing

[hollow fable]

I cant see 😦

[wary stream]

Determine the pattern based on the given values and see if that common difference or geometric growth works

[hollow fable]

which pattern

What

What are the values

[wary stream]

It's plus 4 between 3 values

[short lily]

When I graph this, the graph is facing up when it should face down. What am I doing wrong?

[wary stream]

This channel is in use, please post in a different unused channel

Same to you @short lily

[hybrid copper]

The best thing I come to is a fraction that is big and I still need log, but it is correct. Though I don't know how to get to the result without a calculator

[short lily]

Alr

[wary stream]

You have a difference of 4 between 3 values, what is the difference between 2 values?

Hint: it's been given

[strange raft]

sorry

[alpine sable]

I dont understand where these numbers come from

e.g number one on the x - axis

when there is a 4

[wary stream]

You are given the difference between two values apply that given info

[heady sequoia]

Convert to rectangular form

[wary stream]

What is the difference between the two given values? The ones that are next to each other

[sullen imp]

ah thanks anyway

[wary stream]

No I won't tell, you have to see for yourself

[grave verge]

any help with this please?

[wary stream]

You are given a list of values, there are 2 values that are not separated by a blank, what is that difference? @alpine sable

2 values that are not separated by a blank

I'm using them interchangeably. Means pretty much the same

[valid galleon]

Any help would be appreciated

[wary stream]

The 2 terms that aren't separated by a blank

Yes, what is the difference and apply that to see if that pattern works

[strange raft]

can i ask my question now?

[wary stream]

Yes

[alpine sable]

Rectangular form?

[wary stream]

Plug in the given values and simplify

Not 26

[teal saddle]

2(6)

Do that with b also

What is a formula for the radius,r, of a regular n-gon with side length s?

[wary stream]

Do you know what a coefficient for terms are?

[heady sequoia]

a+bi where and a and b are real numbers

[teal saddle]

https://gyazo.com/c07d00679dee2e89adc84538f386ef2b

I dont understand

[barren pawn]

c

[wary stream]

https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-expressions-and-variables/cc-6th-evaluating-expressions/v/expression-terms-factors-and-coefficients
Watch this to understand cofficients

[teal saddle]

Thank you

[potent cedar]

Hi quick qs
Is the answer to this C? I believe

[muted raft]

for which?

[wary stream]

Big O is the complexity of the algorithm or function

[muted raft]

The time complexity of those function will completely depend on how you implement it.

This means if you for example decided to use adjacency matrix for dijkstra's algorithm, it will turn out to be O(V^2) where V is the number of vertices.

However, if you decided to use adjacency list, it then turns out to be O(V + V Log(E))

So it isn't necessary wrong to say that they would have quadratic time complexity.

Because like it was stated above, its the upper bound.

yes.

Worst case for dijkstra's is just dependent on how you implement it.

[teal saddle]

https://gyazo.com/3a97db2ea4413ad919a4ef1604a767da

[muted raft]

Like I said earlier, you can have either O(V^2) or O(V + E Log(V))

[teal saddle]

Dont really understand ;-;

[muted raft]

Clearly V+ELog(V) < V^2

@teal saddle Channel busy move to another.

[teal saddle]

Oh ok

[muted raft]

But to answer your question

If you have for example something like a complete graph.

Dijkstra's will try to determine the path from one vertex to all another vertex.

And to top it off, if you have adjacency matrix as your setup, you would get O(V^2)

This is your worst case, and it quite frequently so I assume.

Is it? I don't think so.

Let me confirm.

No looks like it isn't the same.

[alpine sable]

guys, i need help.

[muted raft]

Channel busy @alpine sable move to another channel

[alpine sable]

sorry

[muted raft]

By definition it seems Incidence matrix has rows corresponding to the vertex and columns corresponding to the edge. Which mean your matrix would be of size V * E. Whereas in the case of adjacency matrix, would be square since both rows and columns correspond to the vertex, hence V * V @alpine sable

Personally would prefer adjacency matrix, since it is symmetric.

you're welcome.

Also I forgot to mention but it is the similar idea for both kruskals and prims as well @alpine sable

They also have the time complexity of O(E Log(E)) if it is adjacency list but otherwise if you have adjacency matrix, they will be quadratic.

So it depends on how you represent your graph basically.

Thats the main factor.

And sometimes, time complexity is not always important.

Space would be important as well which is why adjacency matrix also exist as a potential structure.

[alpine sable]

Name a positive angle between 0 radians and 2π radians that is coterminal with an angle in standard position whose measure is −π/2 radians.

im in a middle a test lol so any help is appreciated

[muted raft]

#rules

Can't ask for help on test here.

[wary stream]

You're not allow to get help on tests

[alpine sable]

ohhh

damn oh well lol

[jade portal]

Someone please show me a solution

[glass lichen]

factor the area to find the length and width

[tender geyser]

i need a quick refresher on complex numbers in exponential form 😅

i have to compute |psi(x,t)|² with psi being a long fuction with constant factors which are all sqrts so this part is trivial but it also has an exp(-a+ib) part

so how do i correctly compute the square for the complex exponential function?

ahh its just |exp(-a)|² * 1 right?

[alpine sable]

$(e^{-a+ib})^2$ is what you're asking?

[tender geyser]

yup

[ocean seal]

Em

[alpine sable]

$(a^{x})^2=a^{x}×a^{x}=a^{x+x}=a^{2x}$

[ocean seal]

Em

[alpine sable]

Shorthand, the rule is $(a^{x})^y=a^{xy}$

[ocean seal]

Em

[tender geyser]

uhm
yeah i know the basics of exponential rules x)

i wasnt sure about the complex rules

but ty

[alpine sable]

$e^{2(-a+ib)}$

[ocean seal]

Em

[tender geyser]

well for the complex square, you use the complex conjugate

so the ib part cancels with itself

[pliant oracle]

Who comes first? Division or multiplication?

[tender geyser]

they are treated equally

[plush estuary]

does the formula for nature of roots of a quadratic equation always start on "D"=B^2-4AC?

[pliant oracle]

18 : 2 x 5 + 6 - 4
9 x 5 + 6 - 4
45 + 6 - 4
45 + 2
47

For example here, I did the division first, is that correct?

Oo

Ok

o.o

[tender geyser]

ah okay now i got it

yeah i got completely confused for a second, my bad 😂

you go from left to right

unless brackets appear

these are computed first

(and any +/- comes after * and : )

[alpine sable]

Was it just the exponent squared or the base as well?

[lost steeple]

https://gyazo.com/ef471867cd1bfbbd9fb1f76dfc0b6d77

Could someone tell me how to do this?

I got as far as sin(2x) = 1/3

but I'm not sure how to deal with the 2

I was told to either expand the domain to [0,4pi]

or could I just divide by 2 and do sin(x) = 1/6?

[alpine sable]

Just say, 2x=y

so sin (y)=1/3

Now find y and equate with 2x to get x

Cos sin function or any trigonometric function isn’t a homomorphism

f(ab) isnt f(a)f(b) except maybe in some special cases

[lost steeple]

Alright

[pliant oracle]

Thank you 🤍

[lost steeple]

@alpine sable How many answers am I suppose to get?

4?

[alpine sable]

One I guess

Cos it’s the principle branch

[lost steeple]

What is that?

[alpine sable]

x belongs to the interval [0,2pi]

[lost steeple]

Isn't there multiple occasions of which sin(x) = 1/3?

within that domain

[alpine sable]

Let me check

Yea only one

Abt 0.33 radians

[lost steeple]

isn't

0.1699

also one?

[alpine sable]

No I meant 0.33 is y

So x is 0.1699 yea

It’s only one value tho

[lost steeple]

https://gyazo.com/3a6fd0fb40d9a3a57d6c1ddd84628851

Isn't the answer everytime it ccrosses the x-axis

[alpine sable]

What did you graph?

[lost steeple]

https://gyazo.com/0b6d7844175d670710703346dd90bd04

it's for this

for whenever it is 0

[alpine sable]

Yea but they asked for x between 0 and 2pi

[frozen granite]

You can solve it algebraically though

[lost steeple]

2pi is like

6.28318531

[frozen granite]

Wdym?

[lost steeple]

Like the points is between 0 and 6.283 right

[frozen granite]

If you're writing out x in radians then you can use pi

Let me see

[lost steeple]

0.3398 and 0.169 are both in there

i thikn

[frozen granite]

Nevermind I forgot the 2x

[lost steeple]

isn't there 4 points of interception between 0 and 2pi?

[velvet pelican]

,w solve 3sin(2x)=1 on [0,2pi]

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Frosty_#7210

[frozen granite]

Pi/12, 5pi/12

[lost steeple]

,w solve 3sin(2x)-1=0 on [0,2pi]

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Mystifine#4924

[lost steeple]

is that 4 answers

[alpine sable]

y values for sine repeat every 2pi

So you’ll get only one solution

[lost steeple]

alr

[velvet pelican]

uhh no, there are 4 solutions

in the range

wolfram alpha gives them

[alpine sable]

Whatre they?

[velvet pelican]

these are the 4 solutions

all of them are between 0 and 2pi

[alpine sable]

Oh yeah my bad I forgot that sin doesn’t repeat for 2pi for every value there are special cases like, 0

[edgy zodiac]

any tips on how to solve this? without lhopital

[elfin snow]

multiply by the conjugate I guess

[barren pawn]

but why wont you with lhopital?

[edgy zodiac]

that would leave me with a cos^2/3 (x) term... not sure if this is the way

[edgy zodiac]

we're not allowed to

[elfin snow]

try using the cubic formula or smth

[edgy zodiac]

bc we technically dont know it yet

[barren pawn]

lol

[alpine sable]

Maybe a trigonometric identity

Let cos x be y^3 or something like this

[wary stream]

If you can use a calculator, I would plug in a value close to zero on the left but not zero and a value close to zero on the right. So a value on the right would be 0.00000000001 or something, that's what I would do

[alpine sable]

Split into two fractions

[civic lance]

Yo can I get help on 2 questions

That one

First

Bro everyone else is getting help and I’m not how does that work

Volume of what the cone?

Ok

I would add the volume of the cone and cylinder once I have them both right

Alright I have the volume for both

[cloud kiln]

Oops

[civic lance]

@alpine sable

Wdym I alr have the volume

I have to find the rate the silos were filled at

[potent goblet]

You can use the equation jealous provided

Divide time to both sides and simplify

[alpine sable]

what shape is this

[stark gate]

parallelogram

[lost steeple]

https://gyazo.com/b1c37eb822d3f43e0388c056fe79d06a

[civic lance]

What do I do after that tho

[potent goblet]

@civic lance plug in your values, but since they want cubic/minute, be sure to convert the hours to minutes

[lost steeple]

I've inputted 20m as the height and simplified to 4/5 = sin((pi/15)t - 7.5) but I'm not sure how to continue from here

[potent goblet]

@lost steeple take sin^-1 of both sides

[lost steeple]

I can do that?

Ok

the left side has a variable t though

I have 0.927295218 = arcsin((pi/15)t - 7.5)

@potent goblet What can I do from there?

[potent goblet]

Well arsine(sine()) will just be pi/5t -7.5

Arcsine is the inverse of sine, they canceled

[lost steeple]

Oh I see

Alright

@potent goblet I've figured out the answer of 40.2373 seconds however I think there are more than one answer

How can I find those other answwers?

[frail grove]

Oh is this channel still active?

[lost steeple]

Ye

[placid flare]

Hi everyone, I don’t understand how they got there

[potent goblet]

@lost steeple I'm not sure, I'm sorry. There might be more than just arcsine but I can't recall at the moment

[lost steeple]

Alright

[frail grove]

They just plugged in the m in the 2nd expression

[placid flare]

Yeahhh but where did they get (x-1/2) and 1/4 from?

I tried but couldn’t get it

[weak swift]

help

[frail grove]

I hope it's clear

[placid flare]

Ahhh thank youu

But can u tell me we need to add 1/4 to both sides?

[frail grove]

You mean why?

[placid flare]

Yeahhh

[frail grove]

Cause it's an equation

It should be written like that i guess

[placid flare]

As in like how did u get that 1/4?

I just got up to x^2 +y^2 -x =0

[frail grove]

Add from both sides

[placid flare]

After this I didn’t know what to do

[alpine sable]

Who can help me?

[frail grove]

Add 1/4 to both sides

[placid flare]

Yeahh I wanna know why u did this

I can’t seem to figure out why

[frail grove]

You mean why exactly i chose choose 1/4?

[placid flare]

Yeappp

[frail grove]

Cause your teacher did so... we could add 4

[placid flare]

It’s a mark scheme

But I can’t figure out why they did that

[frail grove]

You can add whatever you want you don't need to follow the book

[placid flare]

So even a 1/2?

[frail grove]

But maybe they chose 1/4 cause it's easier for upcoming calculations

[placid flare]

Or 1/5?

Hmm

[frail grove]

It must be squared though so we can apply the (a-b)^2 formula. We added (1/2)^2

[placid flare]

Okay thank uu

[frail grove]

No problem

[ashen wave]

what is the formula to find the endpoint when given the midpoint?

[whole dagger]

help

what is the formula to solve this?

[fiery adder]

can someone help me w part c of this please

[neon sonnet]

Yo quick question

[remote heron]

doesnt seem valid

[neon sonnet]

Only takes two seconds im doing a math problem and i want to double check

[remote heron]

trying to be certain though

[neon sonnet]

Is this sss or sas?

I think its sas

Im just not sure

Also sorry for horrible writing!

[fiery adder]

how do you know

like obv it feels wrong but idk how to formalize it

[remote heron]

im trying to find a really justifiable reason

yea

[neon sonnet]

Mm

[remote heron]

trying to determine how to write it

but i think its that like

$\exists x \exists y : P(x) \land Q(y) \to \exists x : P(x) \land Q(x)$

[ocean seal]

jan Niku

[remote heron]

i dont think this notation is right but thats my thinking

[fiery adder]

wait wait wdym

[remote heron]

wonder if i can find better reasoning

well thats the question right

its trivially true if x and y

but it doesnt follow directly if y=x

even though its true

[fiery adder]

thats so weird lol

[remote heron]

im gonna google though

[fiery adder]

<3

[remote heron]

well itd be like

[fiery adder]

pls @ me

[remote heron]

there exists an animal that is a dog

there exist green animals

therefore there exists a green dog

is it fallacy of composition?

im sure theres a stronger argument

[neon sonnet]

Can you double check something for me

[remote heron]

i cant understand the sas question sorry

[neon sonnet]

Well thanks man

Im going to have to guess then

50 50

[remote heron]

part c

[neon sonnet]

Im going crazy

[sly mantle]

@fiery adder @remote heron there exists an odd # & there exists an even #, so there exists a # that's even & odd

[neon sonnet]

Its a 50 50 chance i get this wrong

[fiery adder]

uhhhh

[remote heron]

I believe that

Im more curious if theres a stronger line of reasoning

than giving an example where it doesnt follow

[sly mantle]

you believe what

[remote heron]

idk why i said that

[potent goblet]

@neon sonnet well both triangles are connected at line BC, if the sides you have marked are congruent, then sss

[fiery adder]

a counterexample should be enough tho right?

[neon sonnet]

Hmm alright ill give it a shot

[remote heron]

i think so but then i was curious

[sly mantle]

i picked easier statements that should illustrate why the reasoning is bs

you do know there are no #s that are even & odd right?

[remote heron]

yea

but then does that example you gave extend directly to this one

i guess intuitively its wrong but

maybe theres not a really strong way to say its not true

or not uhh

not valid

[potent goblet]

Couldn't direct proof work?
Definition of prime and definition of even

The only viable number is 2

[remote heron]

well it happens to be true in this case

[fiery adder]

im not sure exactly how this breaks it hto

[potent goblet]

That's really tough

[remote heron]

its obviously faulty reasoning

im just curious if theres a stronger way to justify it

than by example

[fiery adder]

that example doesnt seemm fully right tho

[remote heron]

why not? which part seems weird

[sly mantle]

this is an example where $\exists x(P(x))$ and $\exists y(Q(y))$ but $\neg(\exists z(P(z)\land Q(z)))$

[fiery adder]

why is the odd # being mentioned

[ocean seal]

RokabeJintaro

[remote heron]

its just a different example with the same logical structure

the example they gave is false, in your case the conclusion is true

[sly mantle]

there exists an odd # and there exists an even # but there doesn't exist a # that's even & odd

[fiery adder]

so can i just say, "the existence of a prime number and the existence of an even number are not sufficient to guarantee the existence of an even prime number. consider: there exists an even number 42 and a prime number 13, but it does not follow from these statements that there exists an even prime"

feels scuffed

[remote heron]

up to your example seems good

rokettos example is pretty straightforward

you can abstract away the specifics though like roketto did just a few lines ago

you can find examples where it works like the one your problem gave

using that structure

and you can find ones where it breaks like the even/odd thing

[fiery adder]

i feel like it should stay in this example tho

[remote heron]

maybe if you really want an example close to your problem

you could use like

there exists an even number greater than two

there exists a prime number greater than two

therefore there exists an even prime greater than two

i think

[sly mantle]

validity refers to whether results must logically follow from the premises, and is independent of the actual truth of the premises

all dogs are bad and jan is a dog, so jan is bad. neither premise is true but the argument is valid

look at the form of the argument in the hw, not the exact premises stated, and think of another argument written in an equivalent form which is easier to decide as valid or not

[fiery adder]

alright i appreciate it <3

can you give be a hint on b) as well please

proving trickier than i thought

[ashen wave]

Can anyone help me

[sly mantle]

we should expect some foralls bc 'any prime numbers'. write it as a forall statement in english first

[neon sonnet]

Guys i need clarification

[vestal inlet]

Use the Pythagorean theorem

[ashen wave]

huh

[neon sonnet]

I think its sas

Its either sss but we did a problem like this a while ago and he said its sas

Nvm its sss

[potent goblet]

Use the distance formula

[ashen wave]

Huh

[elfin snow]

$D=\sqrt{(y_2-y_1)²+(x_2-x_1)²}$

[ocean seal]

gmod

[elfin snow]

@ashen wave

[limpid iris]

Determine the reduced expression of the lines

I didn't understand anything but i think it would be easy for you guys

[gusty gorge]

I assume they're asking for equations of the lines?

[limpid iris]

yes

It's easy people say

But i just dont understand

Ik that d1= 4

and that u do: y=mx+c and the intercept when x=0 and y=0 is given

[gusty gorge]

The answer to D1 is x = 4

[limpid iris]

But I just dont understand how

[limpid iris]

yeah i know it's a straight line x')

But i have big problems with d2/d3 type things

[gusty gorge]

well all of them are straight lines

the vertical lines are the hardest to do, because they're a special case

for all of the others, find two points on the lines

and then https://www.wikihow.com/Find-the-Equation-of-a-Line

[limpid iris]

Can you give me an exemple of how to do d2

i'll maybe figure out how to do the rest

[gusty gorge]

two points on D2 are (0,2) and (4,5)

[bronze geyser]

can someone send example of quadraric equation solve by factoring ||i forgot how im dumb heheh|| ||with solving||

[gusty gorge]

now if you go to the wikihow page I linked and go to method 2

we first find the slope of the line

m = (5-2) / (4-0) = 3/4

yknow what

fuck method 2

[limpid iris]

lol

[bronze geyser]

ping me please thx

[gusty gorge]

in general, you can solve it by plugging the points into the slope-intercept form and solving the system of equations

so

actually

let's handle the vertical case as well

[dim spear]

is this channel occupied

[limpid iris]

I can take any points of the line

Right?

[gusty gorge]

yes

lemme start over

so I give a non-ridiculous answer

you have y = mx + b, which is the slope-intercept form of a line

so what we do is we plug in the points

this gives us two equations:
2 = m(0) + b
5 = m(4) + b

writing it a little differently, we get

2 = b
5 = 4m + b

solve for m and b

b = 2, m = 3/4

[limpid iris]

cause 0 can't be written right

[gusty gorge]

uh no

I can definitely write 0

0

[limpid iris]

then why did you remove it

[gusty gorge]

therefore the equation is y = 3x/4 + 2

[limpid iris]

let me verify

[gusty gorge]

because 0m = 0 and b + 0 = b

[limpid iris]

it's the exact same

thx u so much i'll try to use this on the others

and see if it works

[stuck delta]

https://gyazo.com/cf7de1855a8523328ae6c2d7dcfd2338

how do you figure which ones are constant or not constant?

[worthy lynx]

Can someone help with this please im not to bad at maths but when it comes to this i always get stuck

[vestal inlet]

just plug in the numbers (for example -3) instead of x, and see what y-value that gives

what is it that feels tricky?

[alpine sable]

The average height of the eight shorts was 150 centimeters. The average height of the twelve mediums was 170 centimeters, and the average height of the five talls was 200 centimeters. What was the overall average of all 25?

[worthy lynx]

@vestal inlet thank you very much i just didnt know how to get started you just fixed my problem thank you again

[vestal inlet]

you're welcome and good luck man, graphs are awesome!

[flat sphinx]

find the total height of everything and divide by the total amount of items (they tell u its 25 items)

and if u were to do it yourself 8+12+5=25

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Guardian#7441

[heavy axle]

H=-16(t)^2+vt+s

How would I solve for Max height and height after 10 sec

V=60
S=0
T=10
H=?

-16(10)^2+60(10)+0

What would I do next?

[alpine sable]

help

[flat sphinx]

thats correct, what are you missing

s=s0+vt+1/2at^2

[smoky goblet]

Oh, coordinates?

[heavy axle]

@flat sphinx I would need to find the height after 10 second

[flat sphinx]

yes

u literally have the correct equation

[heavy axle]

Would I just plug that equation into a calculator for the answer

[flat sphinx]

solve it

yes

[heavy axle]

Ok

[smoky goblet]

Formula

[flat sphinx]

uhh just so u know thats a trick question

what value did u get

[heavy axle]

-1000 I don’t think that’s correct

[flat sphinx]

its "correct"

see how it says think

[heavy axle]

Yea

[flat sphinx]

its not in the air for 10 secs

its only in the air for ~4

so after 10 secs its been on the ground for ~6

[heavy axle]

Yea

[flat sphinx]

yeah so your answer is technically 0

cuz the ball wont dig into the ground

[heavy axle]

I see

[flat sphinx]

-1000 infers that it dug 1000 feet undeground

[heavy axle]

Oh

How would I find the max height

[flat sphinx]

velocity=0 at max height

think of it as velocity is positive as it's going up

so when it's going down it's negative

[split tapir]

Was hoping for help on this problem. Ik you have to distribute the 100 and use the quotient rule but didnt know how to solve the rest of the problem

[flat sphinx]

but to go from positive to negative it has to be 0 momentarily

when velocity is 0, it's max height

[flat sphinx]

they want u to solve for dy/dt, dx/dt is given, x is given. Apply the quotient rule as u mentioned, plug in values and you find dy/dt

[chilly topaz]

I moved my question.

[karmic sundial]

I need to find the x-component, y-component and z-component? x-component would be cos(theta) right?

[alpine sable]

Can someone help me

#❓how-to-get-help can

[hexed pasture]

How come this

Is not

-8x^3

And only 8x^3

[thorn kindle]

Sqrt(64x^6)=8x^3

Yes.

[hexed pasture]

Oh

Ok thanks

[scarlet spire]

not a math question but why is my pee white

[alpine sable]

Thirteen fastners cost $0.78. Write two rates (ratios) for this statement. Then find the cost for purchasing four thousand, six hundred eighty-seven fastners.

<@&286206848099549185>

[shell narwhal]

hello everyone, how do you calculate the norm of a tri dimensional vector ? do you do

$a^2=b^2+c^2+d^2$

[ocean seal]

ndam500

[alpine sable]

yes

[past plover]

Is rolling 2 sixes in a row on a number cube considered dependent?

[heady sequoia]

Dependent with what? You mean is each roll dependent?

[scarlet spire]

yea i dont think the question makes sense / is incomplete

[past plover]

Probability, dependent or independent

[heady sequoia]

The two rolls are independent as long as it's not a weighted die

[past plover]

Oh ok

[heady sequoia]

Well actually, it's still independent as long as you know the weight

[scarlet spire]

the theoretical probability is independent but the experimental probability is dependent on what you roll

[heady sequoia]

If you don't know the weight, then it's deoendent

[haughty granite]

can anyone help me with a question

This is the question

[heady sequoia]

Erm, this is not really what we mean when we say independent

[haughty granite]

can you help me with that?

[scarlet spire]

ignore me then

[scarlet spire]

search youtube its just y=mx + b from two points on a graph

[haughty granite]

Yah i know that but I was plugging in one of the coordinates for x and y but still didnt get the right anwswer

i found slope but cant find y intercept

[scarlet spire]

thats for slope which u got

and then to get y-intercept just plug in y, x, m, values into y=mx+b and solve for b

[placid tulip]

is this channel occupied?

[scarlet spire]

yes

[green hazel]

can someone help me do this

https://cdn.discordapp.com/attachments/833399740141010994/844032659646709762/317ec54489886c5b2460e765e83e585e.png

please

explain how to do chain rule

[remote heron]

you should learn to do the chain rule for sure but you dont need it here

[green hazel]

can u do it with chain rule

[remote heron]

you can, yea

[green hazel]

or is it just the regular rules

can u teach me how please

i need to learn chain rule

[remote heron]

you can do it with the chain rule or you can use the power rule

[green hazel]

This is what i did but its apparently wrong

[remote heron]

since (2x^2-5x)^2 = 4x^4 -20x^3 + 25x^2

[green hazel]

yeah

teach me to do it with chain rule please

if u know

[remote heron]

1s

[green hazel]

thank u sm

[remote heron]

sorry trying to think of how to write it

[green hazel]

it's okay if u don't know

[remote heron]

you know you need the chain rule because there is composition

so you just need to identify the composed functions

[green hazel]

yeah

[remote heron]

an outside function and an inside function

[green hazel]

but idrk how to do that

[remote heron]

sometimes they are composed deeper

here they arent

[green hazel]

Can u write it out for me

i think if someone gives the me the first steps i will be able to figure it out

[remote heron]

like heres one way

does it make sense up to that point

[green hazel]

i just don't know how to continue

what do i do after i write this

https://cdn.discordapp.com/attachments/833399740141010994/844032659646709762/317ec54489886c5b2460e765e83e585e.png

do i bring the 2 to the fron

front

Then subtract 1 leaving no exponent

[remote heron]

derivative of the outside times derivative of the inside

so yea youre talking about the power rule

x^2 becomes 2x^1

but x isnt 'x' here, if that makes sense, yea?

x is "2x^2 - 5x"

[green hazel]

so like this

[remote heron]

yea

tbh id leave the 1 off if it still makes sense to you

[green hazel]

and am i done , do i just multiply it out

[remote heron]

probably want to multiply it out

if its a calc 1 class

[green hazel]

Also when i multiply it out, does the 2 in front go ontl to the first set of parenthesis or all of them

Just the first set right

I think it's just the first set

[remote heron]

2(x)(y) = 2((x)(y))

it doesnt matter here

[green hazel]

oh deadass

[remote heron]

it will end up being distributed to all terms

[green hazel]

i didn't know that

yo im getting the wrong answer

[remote heron]

,w derivative of (2x^2-5x)^2

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by jan Niku#2119

[remote heron]

youve messed up the algebra somewhere i think

[green hazel]

this is the answer i got

[remote heron]

,w (4x^2-10x)(4x-5)

[green hazel]

Nvm this is right

sory

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by jan Niku#2119

[green hazel]

I just blundered with mathway

[remote heron]

wtf haha

[green hazel]

I put multiply in mathway.com instead of derivative

so it gave me the multiplied version

Lel

Thx my g for the hep

i appreciate you

[remote heron]

[silk loom]

hello, how do you determine if the equation is hyperbolic, elliptic, or parabolic?

[steel osprey]

Is it is it it is is is it it is it

[remote heron]

damn dont shitpost in question channels u weirdo

[steel osprey]

Dammit ghostpinged myself

[remote heron]

just go to #chill

[steel osprey]

Okay okay

Bye

[past plover]

Can someone tell me if i got something wrong, i wanna make sure im ready for tomorrows test

[steel osprey]

Read the rules

[past plover]

Yes i know of the rules, this isnt graded, im just making sure im ready

[remote heron]

dont mind this guy lol

[random rover]

can someone help explain how to sketch the graph of r=8sin(2θ) for 0≤θ≤360 with trajectory?

[remote heron]

are you sure on 1.2?

and 1.3, actually

[past plover]

What do you mean by that?

[remote heron]

if you have a bag of tiles, and you draw one, dont replace it, then draw another

does the probability of which tile you draw second depend on which one you draw first?

key thing being replacement

[past plover]

Ah i see

[remote heron]

if the outcome of the first event influences the outcome of the second event then its not independent

well thats oversimplified but i hope that makes sense

[past plover]

Makes enough sense for my low iq brain to understand

[remote heron]

im low IQ too 😄

i just got a C on my stats exam today haha

[past plover]

oof

[remote heron]

it looks like the independence/dependence issue tracks through a bit

usually things like coins, spinners, die are independent

because a spinner doesnt 'remember' what you got before

its right in some places and in others its not

usually just coins, spinners, and die are independent

[silk loom]

<@&286206848099549185>

[remote heron]

if its talking about drawing from a bag or a hat, you wanna look if theyre replacing between draws

sorry midifician

[silk loom]

issok

[raven plaza]

Does anyone know this?

Pre calc btw

[winter swan]

can someone help?

[short lily]

Tried visualizing this but I'm not sure the right way to establish the variables for this problem, can anyone assist? Thank you

[small sinew]

lol it's probably too late but I'd say none because it's not finding the tangent of a multiple of pi which most likely would result in some irrational number

but uh, now that I look at it more
what's x doing there?

[small sinew]

let's see, we could start by setting up some equations that describe the simple behavior of the fence

960 = 2x + y```
now we want to find the maximum area right so we want to set up the equation in terms of x
```960 = 2x + y
y = 960 - 2x```
now we can rewrite y in terms of x```
a = x * y = x * (960 - 2x) = -2x^2 + 960x```
and then we simply solve for the x value that gives the highest area, and then solve for y

[short lily]

Thanks 👍

[small sinew]

:)

[unkempt viper]

i’m not sure how to get the answer, any <@&286206848099549185> online?

[sinful shore]

anyone wanna hop on and help me understand

math

[sinful shore]

7x=42

u find the x, then multiple by 4 and by 3

the number that u multiplied by 4 will be the men

and the number u multiplied by 3 will be the women

@unkempt viper good?

[unkempt viper]

yes, thanks!

[sinful shore]

anyone wanna help me now lol, precalc <@&286206848099549185>

<@&838854934270574663> what is this role

@ me when someone decides to help me

[cobalt canyon]

<@&286206848099549185> would someone like to teach me trig I know the basics but I don't understand them

At me when you can help

[sinful shore]

Kinda need that type of stuff but with precalc

Help

[junior blade]

[lapis harness]

a_0=15, a_1=20 ... a_n= ?

https://en.wikipedia.org/wiki/Arithmetic_progression

read this

i know it's not math but could anyone help me with RLC circuits ? I can't seem to find info about deriving the impendance and other values online for custome RLC circuits. I know you somehow model it on an complex plane but that's it

a link to some article could be great

[kind basalt]

am I overcomplicating this or is it literally just 4/36, 6/36, 9/36, etc simplified ofc

I feel like the answer just isn't that simple

[remote heron]

seems like that to me

[kind basalt]

alright thanks, just making sure

[tacit bay]

Im stuck

[remote heron]

try changing this

$\cos (\sfrac{\pi}{2} - x) = \cos \left( (-1) \cdot (x-\sfrac{\pi}{2} \right)$

[ocean seal]

jan Niku

[remote heron]

if that helps

[tacit bay]

im still not sure tbh

[remote heron]

what do you know about evenness/oddness of cosine?

does cos(x)=cos(-x)?

[sharp basin]

iDK if this counts as too much help: ||Try drawing a right triangle, mark 90 and two variable angles as theta and theta2. You can then find cos theta by definition and cos 90-theta using the sum of angles of a triangle.||

[remote heron]

theres 2 things being applied, one is an application of evenness/oddness, and the other is a phase shift

[tacit bay]

Should be sin x right

[remote heron]

i think so

[flat turtle]

8yz - 7yz could be yz or zy right?

its the same variables it doesnt matter if its switched

im just making sure

can anyone confirm lol

[remote heron]

commutativity of multiplication 😄

[brave fossil]

hi

[bold token]

depends on what is asked, if with respect to z, you put zy, vierce versa.

[brave fossil]

im having some trouble sketching the second inflection point at x=1

my inflection point at x=1 always seems to have f'(1)=0 not greater than 0 as the question wants

[alpine sable]

help

[outer helm]

what's the goal here

[alpine sable]

something inequality

[outer helm]

are you supposed to draw the curve or something

[alpine sable]

idk thats why im here ):

[outer helm]

what was 1)

[outer helm]

and how did you solve this

[alpine sable]

i didnt

[ionic jewel]

this one makes sense, the first one has two variables but has a one dimensional number line so idk what they wanted from that

[outer helm]

i think drawing the curve is the only thing that makes sense

and shading given region

not very much space for the parabola though

[ionic jewel]

theres no way they want you to draw the parabola

they gave a number line

not a graph

[alpine sable]

do i skip the line

[outer helm]

are there any more questions

maybe they meant 0 instead of y

[remote heron]

row reduction 😄

[outer helm]

what's all the whitespace for if not drawing the curve

[alpine sable]

to answer the question maybe

[muted raft]

to show work

[ionic jewel]

these questions hurt me

[alpine sable]

same </3

[ionic jewel]

[outer helm]

it's like 1 line of working

i think you could just cross out the y's for 0

[ionic jewel]

no that cant be right either tho

[outer helm]

why not

[ionic jewel]

because $y \neq 0$

[ocean seal]

bunny

[ionic jewel]

well

[outer helm]

[ionic jewel]

it can be but it doesnt have to be

thats just changing the problem

i think your best bet is just drawing the y-axis and making the parabola

then shading

[alpine sable]

okay change it to 0, got it

[ionic jewel]

...

[alpine sable]

sorry i didnt see that

okay DONT change it

[outer helm]

well yeah but otherwise the answer, as the question is currently presented, is already both answered and not answered

[muted raft]

klee too busy with explosions.

[alpine sable]

definitely

brain explosions

[topaz cipher]

Maybe u draw it like this? Idk

[ionic jewel]

thanks i hate it

but that makes sense

[vast blaze]

Yeah I feel the question is asking it like this too

[ionic jewel]

back in my day they gave us both axis, society is really going downhill

[muted raft]

Uh make sure the line is dotted

You have $<$ not $\leq$

[ocean seal]

zslya

[nimble frost]

hello is this channel considered open?

[ionic jewel]

no

[alpine sable]

besides the number line, how do I solve it

[outer helm]

find the roots

indentify whether it's a u shape or n shape parabola

then just draw it and shade the region it's showing

and like zslya said, dotted line for strict inequalities

[alpine sable]

ahh okay thanks

[short olive]

hey guys can someone explain how cayley tables work ❤️

[alpine sable]

I have the three eqns:

2A + 5B + 7C + D = 0 
A + 2B + 3C = 0
4A + 5B + 6C = 0

how do i solve for them, since there are 4 variables and only 3 eqns

and furthermore how do i take into account D in the form they want

<@&286206848099549185>

resolvd

[narrow bane]

CAN SOMEOEN HELP. <@&286206848099549185>

Please god someone help me lord

<@&286206848099549185>

Pleaseeeeee

[honest berry]

pls sove this

[fallow jetty]

How can I tell where f is increasing by looking at the graph of f'

[tranquil parcel]

If I’m not mistaken it’s when the graph of f’ is above the x axis

[fallow jetty]

oh ok

[tranquil parcel]

Hol up I’ll check for confirmation

[fallow jetty]

ok thank you

[tranquil parcel]

Yes I was correct

It’s when the graph of f’ is above the x axis

[fallow jetty]

ok ok thank you so much

[oak birch]

Can anyone help me convert this language into a context free grammar

[tranquil parcel]

Np

[lethal vortex]

can someone help me argue with my teacher

lol

is this correct?

[warm tree]

1200 women are attending school for every 5 women there us one man on the school 5 : 1 how many men are on the school?

[torn lion]

Looks correct to me.

[warm tree]

thats my question and i dont know it

[lethal vortex]

why is there a 2ab there 😩😩

Oh

I see now

[torn lion]

Draw a square of side lengths $\alpha+\beta$, and then you'll see that you can cut it up into two squares of areas $\alpha^{2}$ and $\beta^{2}$ and two rectangles, both with area $\alpha\beta$. Thus, $(\alpha+\beta)^{2}=\alpha^{2}+2\alpha\beta+\beta^{2}$.

[ocean seal]

Bannanachair Monarch

[limpid iris]

Zina goes shopping. She buys in the same store two scarves and three T-shirts for
49 euros. A week later, it was the sales: reduction of 1.5 euros on scarves and 2 euros
on t-shirts. Zina took the opportunity and for 40 euros, she was able to buy four scarves and five T-shirts.
What was the price of a scarf and a T-shirt before the sales?

(i think its pretty easy but i just dont understand, with explanation pls)

[lapis harness]

x,y price of tshirt and scarves

2 equations

[limpid iris]

already know that and still tripping

[lapis harness]

2x+3y=49, 4(x-1.5)+5(y-2)=40

[limpid iris]

so what was the price of a scard

scarf and a t-shirt

[torn lion]

Well you solve the equations, find where the lines intersect

[limpid iris]

The thing is I have many exercices like this

I only sent one so you guys solve and explain how it works

so I do the rest

[torn lion]

Ah.

Well, there's multiple ways to solve it, but here's the one that should be easiest for the time being:

First, rewrite one of the equations in the form $y=mx+c$. For example, if we rearrange that first equation, we get $y=-\frac{2}{3}x+\frac{49}{3}$. Then, we can take that value of $y$ and substitute it into the second equation, getting $4(x-1.5)+5\left(-\frac{2}{3}x+\frac{49}{3}-2\right)=40$, and from there you just need to find $x$. Then, using that value of $x$, you can use that to find the value of $y$.

[ocean seal]

Bannanachair Monarch

[limpid iris]

ok thx ill go try figuring it out with this

[torn lion]

No worries. Good luck with your homework!

[lapis harness]

lol, are the numbers correct ?

[limpid iris]

thx

[restive prism]

3√27 = 3n

3√(9*3) = 3n

9√3 = 3n write the left side in terms of exponents using the base of 3

(3)2 * 31/2 = 3n

(3)5/2 = 3n

So n = 5/2
so umm how does 3 squared times 3 to the power of 1/2 =3 5/2

<@&286206848099549185>

[wise sigil]

Because 3^x * 3^y = 3^{x+y}. For example, 3^2 * 3^3 = (3*3)*(3*3*3) = 3*3*3*3*3 = 3^5 = 3^{2+3}.

In your case, you're using this identity with x = 2 and y = 1/2

[restive prism]

wont it be 2/2 + 1/2 = 3/2?

[wise sigil]

As a side note, you should really be more clear when you write down exponents. At first glance, most people will interpret 3n as 3*n rather than 3^n and 31/2 as 15.5 rather than 3^{1/2}

2 + 1/2 is 5/2

[restive prism]

oh

yaa

ok thanks btw

[warm tree]

okay so in the neighbourhood there are 48 cats and 56 dogs what is the ratio like i was thinking it was 1 : 8 ratio but i am not sure

[restive prism]

its wrong

[warm tree]

can you explain it to me?

right now i dont have a clue

[torn lion]

The ratio is 48:56

The numbers are right there

[restive prism]

find the hcf of 48 and 56

[warm tree]

yeah but i need to simplify it

[restive prism]

find the common multiple

ya simplify it

it should be 6:7

[warm tree]

okay thank you ❤️ not that smart of a person myself need allot of thinking but thank you ❤️

[glass orchid]

Any two sides of a
triangle are 40 cm and 58 cm respectively. If it's are is 840
cm2
,find the length of the third sides.

can you do this

[restive prism]

u mean the area is 840 right

so using the formula base x height /2

wait

Area( triangle ABC) = 1/2 * 52 * h = 480

=> h = (480 *2 )/52

=> h = 240/13 cm ……………. (1)

In right triangle ADB

BD² = 48² - h²

=> BD² = 48² - (240²/13²)

=> BD² = {48+(240/13)}{48–(240/13)}

=> BD² = (864/13)(384/13)

=> BD² = (2²2²3²6)(2²2²2²6) /13²

=> BD = 2232226 /13

=> BD = 576/13

=> DC = 52 - (576/13)

=> DC = 100/13 ………………. (2)

In right triangle ADC

AC² = h² + DC²

=> AC² = (240²/13²) + (100²/13²)

=> AC² = (240² + 100²) / 13²

=> AC = √{( 676 *100)/13²}

=> AC = √{(26² * 10²)/13²}

=> AC = (26*10)/13

=> AC = 2*10

=> AC = 20 cm
so ya i think its how u get it my teacher taught using this way with AB having 48 cm and BC having 52cm

[muted raft]

[restive prism]

or u just use Pytahagoras theorem

52^2 - 48^2=400
square root 400 =20 cm

then 1/2 * 48 * 20=480cm^2

ya this is easier

[faint salmon]

What is meant by "apply the inverse of F to U:" in this case?

[mortal thicket]

Bro you are teaching wrong.

Wait i will give correct answer

[woeful pulsar]

erm... don't just give answers

remember to engage the person who is asking

[mortal thicket]

See this is correct answer of that question. @restive prism

[restive prism]

ohh sorry

[mortal thicket]

🤪

[torn lion]

Nice feet.

[alpine sable]

i need help

[alpine sable]

lmao

[torn lion]

So gradient-intercept form is written as $y=mx+c$. Taking one of your problems as an example, we can put in the values at the points in order to get a system of equations: $4=m\cdot0+c$ and $8=m\cdot2+c$.

[ocean seal]

Bannanachair Monarch

[alpine sable]

oh is that it

ty

[gaunt coyote]

Hello

Anyone here good at math and excel?

I want to calculate the total loss but that’s harder then I thought

[limpid iris]

A(x)=x/x-1 and B(x)= 1/x+3
1)For which values ​​of x are the expressions A (x) and B (x) undefined; How? 'Or' What
do we name such values.

[runic dock]

A is undefined for x= 1
And B is undefined for x=(-3)

[alpine sable]

can someone tell me what the difference between numerical and exact solutions is? gotta code a program that prints both kinds of solutions of a quadratic formula.

[leaden goblet]

can someone help me im kinda stuck and its due tommorow

[leaden goblet]

<@&286206848099549185> pls help？

[last tiger]

@void yoke

[boreal prawn]

anyone know how to do this 😭

it’s due tomorrow

[void yoke]

er, shutfva I've moved to questions-3

[indigo jetty]

@leaden gobletwhat have you done so far?

[leaden goblet]

nothing

[indigo jetty]

so first step is to bring the lg down from the power

[leaden goblet]

how do i do that

[indigo jetty]

lg both sides first

then you can bring down those powers down

[alpine sable]

Lg5-lg2=lg3 is that how it works?

[indigo jetty]

no

[alpine sable]

Ok

[indigo jetty]

lg5 - lg2 = lg(5/2)

[alpine sable]

Is lg log?

[leaden goblet]

log 10

[indigo jetty]

lg is log base 10

[alpine sable]

Ohh it makes sense now

[leaden goblet]

wait so is it lg5lg5x=lg2lg2x

[indigo jetty]

yes

[leaden goblet]

OH

[alpine sable]

Yeah say

[leaden goblet]

I WAS RIGHT

what next

[indigo jetty]

now try to separate the 2x into 2 and x

do the same for 5x

[leaden goblet]

lg5lg5+lgx ?

is it

[indigo jetty]

remember your brackets

[leaden goblet]

huh

where

[alpine sable]

N*Logm =log m^n .... So how is this the answer

[indigo jetty]

lg5lg5x is not lg5lg5 + lgx

[alpine sable]

There should only be one log

[indigo jetty]

make it easier, put brackets between lg5x

[leaden goblet]

oh

[indigo jetty]

so it's lg5(lg5x)

now you see the difference

i think you should be able to do the rest from here onwards

[leaden goblet]

i still do not know how

[alpine sable]

Use log properties

[indigo jetty]

what is the aim of the question?

to find x

so your job is to make x the subject

after splitting the 2x and 5x, the rest is algebraic manipulation

[leaden goblet]

im confused

[indigo jetty]

try it yourself

[leaden goblet]

but i cant rlly divide it tho with like lg 5 can i

[indigo jetty]

lg 5 is just a number

treat it the same as any other number like 1, 5, 2/5 etc

[leaden goblet]

im still very lost

[indigo jetty]

at least show me what you have done so far based on our discussion

at least until the splitting part

[leaden goblet]

lg5(lg5 + lgx)= lg2(lg2 +lgx)

[indigo jetty]

good

[leaden goblet]

just that

[indigo jetty]

so what do you think you can do next?