#help-0

1 messages · Page 611 of 1

civic crypt
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Now, if x>0 then y>x

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If x<0 then y-x<0 and y<x, but as y y is positive this cannot happen.

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Well y>x and y>0 has the solution y=5 x=-3

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right

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So 1/x > 1/y and y>0 forces x>0

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But y>x and y>0 doesnt force x>0

ashen wave
#

oh sorry I thought you were done

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Is this chanell open now ;-;

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channel

civic crypt
#

@ashen wave You have like 10 other channels

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Find a channel that did not have a message in last 30 min and post there

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For example in channel-9 noone has posted in last hour.

ashen wave
#

i am fully aware, but @alpine sable aren't you finished?

civic crypt
#

If you are aware then why you interupt us. I still have something to say.

ashen wave
#

nevermind

civic crypt
#

@alpine sable So is the answer none of above?

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I think the best way to solve it is to sketch the space of solutions for each of them.

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It was pretty tricky question, but yes, going the proper way and checking x>0 x<0 (or immediately concluding x>0) does it.

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Yea, was easy to make your mistake, I dont think I would get it on the exam. That was the trick of the poster.

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Np. Have a nice day.

tacit pollen
#

hii can someone help me with how to start this proof?
show that √(1001) - √(1000) < 1/[2√(1000)]

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sorry about the ugly formatting im not sure how to use the formatting bot properly yet

cinder lily
#

$\sqrt{1001} - \sqrt{1000} < \frac{1}{2\sqrt{1000}}$

ocean sealBOT
#

Yes ツ

tacit pollen
#

yes omg thank u lol:)

cinder lily
#

so i think we can start with multiplying the fractiom onn the right by sqrt1000

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so it would be sqrt1000 / 2

tacit pollen
#

wait if u multiplied the fraction by sqrt1000

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wouldn't it just be 1/2

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bc it cancels the denominator

cinder lily
#

5sqrt10 ?

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ok

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so

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$0 < \sqrt{1001} - \sqrt{1000} < \sqrt{1210} - \sqrt{1000}$

ocean sealBOT
#

Yes ツ

cinder lily
#

simplify the rhs

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its just \sqrt{10}

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which is less than 5\sqrt{10}

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and $5\sqrt{10} = \frac{10\sqrt{10}}{2} = \frac{1}{2\sqrt{1000}}$

ocean sealBOT
#

Yes ツ

cinder lily
#

@tacit pollen

#

$0 < \sqrt{1001} - \sqrt{1000} < \sqrt{1210} - \sqrt{1000} = 11\sqrt{10} - 10\sqrt{10} = \sqrt{10} < 5\sqrt{10} = \frac{1}{2\sqrt{1000}}$

ocean sealBOT
#

Yes ツ

cinder lily
#

does that make sense

tacit pollen
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wait does 5sqrt10 = 1/2sqrt1000

cinder lily
#

yes

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multiply by \sqrt{1000}

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and simplify to get 5sqrt10

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what is c

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i see

alpine sable
#

someone german who can help me

cinder lily
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but

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you dont know that its smaller than 5root 10

tacit pollen
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okay i'm still a bit confused ngl

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but i'll give what u said a go

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thank you so much!! to both of u:)

cinder lily
tacit pollen
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the 5sqrt10 = 1/2sqrt1000 part

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when i put it into calc they have diff values

cinder lily
tacit pollen
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ohhhh okay

cinder lily
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they look the same to me

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@tacit pollen what different answers are you getting

tacit pollen
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i get 5√10 = 15.8...

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and 1/2√1000 = 0.0158...

cinder lily
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:/

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my mistake :o

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sorry

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let me do it again

tacit pollen
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omg nono that's okay

bronze grotto
#

Hey, can someone please help me with this question

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This is what I have done so far

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Don't quite understand how to approach part b

cinder lily
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@tacit pollen ive got something

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maybe not what youre expected to do though

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but here it is

tacit pollen
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omgosh thank u regardless

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yeee i read thru and i kind of get it but my school hasn't learnt that theorem yet

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so i dont know if im allowed to work it out like that

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thank u tho!!

cinder lily
#

First note that $10.01^2 = 100.2001 \newline 0 < \sqrt{1001} - \sqrt{1000} < \sqrt{1002.001} - \sqrt{1000} < 10.01\sqrt{10} - 10\sqrt{10} = 0.01\sqrt{10} = \frac{1}{100}\sqrt{10} < \frac{1}{20}\sqrt{10} = \frac{1}{2\sqrt{1000}}$

ocean sealBOT
#

Yes ツ

buoyant vale
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8x-16=3x-2sqrtx

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could someone get the roots of that

cinder lily
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multiply by x

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maybe

bronze grotto
cinder lily
bronze grotto
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Already posted it there

tacit pollen
#

omgosh bro i hate to bring this up again but idk if √10/20 = 1/2√1000

cinder lily
#

aw let me check again

tacit pollen
#

HASHA nono its okay you've been helping me w this question for agess

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i'll go think abt it some more myself

cinder lily
#

nooo i must do this

tacit pollen
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HAHA okay i will think abt it too i'll update u if i get it

cinder lily
#

ok yes but we can modify the proof slightly

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but before

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$\frac{1}{2\sqrt{1000}} = \frac{1\sqrt{10}}{200}$

ocean sealBOT
#

Yes ツ

cinder lily
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right? @tacit pollen

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we can choose a smaller initial value

tacit pollen
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yupp

cinder lily
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$10.001^2 = 100.020001 \newline 0 < \sqrt{1001} - \sqrt{1000} < \sqrt{1000.20001} - \sqrt{1000} = 10.001\sqrt{10} - 10\sqrt{10} = 0.001\sqrt{10} = \frac{1}{1000}\sqrt{10} < \frac{1}{200}\sqrt{10}$

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@tacit pollen

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IM SO SORRY FOR MAKING MISTAKES

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EARLIER

tacit pollen
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BRO WHAT no need to apologise AT ALL

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OMG ASDHDH okay this makes sense

cinder lily
#

is this correct now thoug?

tacit pollen
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wait idk if the last step is obvious tho

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wait jkjk

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YEAH

cinder lily
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:D

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so you understand and its clear to you?

tacit pollen
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YAYAY

cinder lily
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YEEE

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fml

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lol

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its wrong

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omg

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i keep making mistakes!!!

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ill dm you a correct solution

tacit pollen
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omg what i didnt even realise

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okayiee

cinder lily
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small error but ill fix hopeuflly

tacit pollen
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OHH OKAY OMG i got it

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i'll dm u then hehe

sly mantle
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@lucid ember don't multipost

desert kernel
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Help:)

civic crypt
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What have you tried?

desert kernel
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Not really anything, I don’t understand what to do:,(

tacit pollen
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rewrite -3(log5)4 !!

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lol sorry idk how to format but basically rewrite the power thingy

desert kernel
#

Alright I’ll try

tacit pollen
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after u rewrite that as a log5(something)

desert kernel
#

Just use an unknown?

tacit pollen
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oh wait it's not an unknown

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u can use log laws

civic crypt
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no. the thing in front the algorithm put inside as an exponent

tacit pollen
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to move the -3

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i just didn't know if i should give the answer or let you work it out

desert kernel
#

Like this?

tacit pollen
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not quitee

tacit pollen
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yeahh^^

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the third law

desert kernel
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Alright

tacit pollen
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anyways once u rewrite it in the form log base 5 (something)

desert kernel
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Yea?

tacit pollen
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u can cancel the 5 and the log

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bc the base is 5

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and the answer is (something)

tacit pollen
# civic crypt

so just use the third law down from this pic to rewrite the exponent

desert kernel
#

Ok..

civic crypt
#

This also says on wiki page.

desert kernel
#

Woah this is confusing

tacit pollen
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do u want me to write it down for you

desert kernel
#

I think I kinda get it?

quaint trout
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The most important thing to know about logs is the one thing they never teach anyone. They just yell about log rules.

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log_b (a) is the exponent of b that gives you a.

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That's what it means

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So when log_b (a) is the exponent of b, the answer is a.

desert kernel
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Alright

quaint trout
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So it's not a rule you should memorize. It's how you should intetpret what a log is.

desert kernel
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Thanks guys!! 😄

nova anvil
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in this problem were dealing with solution in an interval

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so should the solution be: $u = e^{Re(\lambda)t}cos(bt)$?

ocean sealBOT
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Anticipation

charred heron
alpine sable
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Could someone dm me to help me with geometry? Im really struggling and I need some help.

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ok yeah, its just a lot of questions

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ive been having trouble focusing in class so im kind of behind

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these are a few of them

quaint trout
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Is this a test?

alpine sable
quaint trout
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Asking because of the I'm Done button

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Okay

languid prism
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Use distance formula for ques1

alpine sable
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ok thanks i just finished the first one

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i got 27.9

quaint trout
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,w sqrt(26^2 + 10^2)

copper heath
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Does anyone know the difference between Spearman and Pearson correlation coefficient?

upper kayak
# alpine sable
  1. The midsegment of a trapezoid is the average of the parallel sides
upper kayak
half cobalt
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How do we find the height of a triangle knowing an angle and only one side?

alpine sable
quasi sable
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right so I would probably have to drag the line down a little, thanks

alpine sable
#

pls help

quasi scarab
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and round up

alpine sable
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ok

half cobalt
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yeah my height cuts my angle

latent iron
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Say I am told x<3+sqrt(36+a), how can I find when f(x) is smaller than 0

nova anvil
half cobalt
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so the angle a equals 40° and the side AC is 8cm. The point of the exercise is to find the area of the triangle in gray. I would like to find the height to find the side BC.

alpine sable
#

@modern surge?????

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ah k

mystic palm
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someone can help me ?

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i'm french i need help

alpine sable
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@modern surgedude

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hes speaking english

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so just speak english

half cobalt
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no I understand french dw

alpine sable
#

i know ur french

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but

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this is an english server

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uh

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i am not gonna be a karen but yeah u can continue

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i dont wanna be a fun ruiner and cause a drama for no reason

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So what are you doing here

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Nobody said this has to be an English speaking server

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but @modern surge i appreciate that ur taking time into helping a needy man a mate who needs help. u can continue

alpine sable
alpine sable
alpine sable
#

just chilling

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ok? So why are you here?

alpine sable
alpine sable
#

You infiltrated their help session just to say "speak english"

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when they clearly are both french speakers

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its cool

alpine sable
#

i thought this server is an english server

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plus this is not an English speaking server, it's just we all speak English cause it's a generic language

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i didnt knew you could speak any language

alpine sable
#

stop poking me for no reason

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So what would you do if someone spoke only Mandarin CHinese

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Tell them to speak english?

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fresh

alpine sable
alpine sable
viscid lagoon
#

Hey, calm down. We're here because we struggling with maths shit, that's the reason why we're here, fighting won't solve anything. So please respect each other

alpine sable
#

You really think we're arguing?

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well idk about them

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I was just informing them

viscid lagoon
alpine sable
#

@viscid lagooni know right but this guy is just exacerbating the fight and making it worse

half cobalt
#

je sais pas ce que représente D et O

alpine sable
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@modern surge@half cobaltbonjour

viscid lagoon
alpine sable
#

anneyongahseyo

fringe robin
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Can some one take me through this

shell widget
#

what are u confused about

sly mantle
#

you didn't post a problem

fringe robin
#

can i send pic to show?

shell widget
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Yes

fringe robin
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K 2 min

alpine sable
#

can anyone help me with this question?

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An infinite geometric series begins at 15 and converges to 9. The second term of this series is

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I think its -10 but im not too sure

tight locust
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a/1-r = 9

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and in this case a = 15

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-10 is way far off

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but at least you knew it was negative!

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wait i'm sorry

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i thought you wanted to find r

alpine sable
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nah its the second term

tight locust
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what did you get for r?

alpine sable
#

-2/3

tight locust
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right

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so 15* -2/3 =

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-10

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good job!

alpine sable
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awesome thanks!

tight locust
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sorry that i misread the question

alpine sable
#

i got a couple more about series/sequences if you dont mind helping me out

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A sequence has the following explicit definition: An = ((n+1)/n)^n. Which of the following statements best describes this sequence?

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This sequence does not converge

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this sequence converges to 0

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this sequence converges to 1

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this sequence converges to a different number

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I think its another number

manic quail
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$$A_n = {(\frac{n+1}{n})}^n$$

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This?

ocean sealBOT
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𝔙eryhappyperson

alpine sable
#

yep

gray isle
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what number do you think it converges to

manic quail
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You could split the fraction in the middle first, if that makes it more obvious.

alpine sable
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I got around 3.5 ish, not too sure if its right

gray isle
#

this might be more recogniseable:
$$A_n = \br{1 + \frac 1n}^n$$

ocean sealBOT
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ℝamonov

alpine sable
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ahhhh so it converges to 1

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thanks

strong furnace
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Does it?

manic quail
alpine sable
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shit im slow

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mb lol

manic quail
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,w lim as n to infty (1+1/n)^n

strong furnace
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Bruh

ocean sealBOT
gray isle
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I got around 3.5 ish
how high were you testing

fringe robin
#

if n-inf the lim f(x) ^ g(x) is equal to e^(f(x)-1)*(g(x))

gray isle
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even a relatively small number like 100 gets you pretty close to e

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,calc (1 + 1/100)^100

ocean sealBOT
#

Result:

2.7048138294215
manic quail
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even 1 doesn't give you 3.5 xD

gray isle
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,w solve (1 + 1/x)^x = 3.5

gray isle
#

lol

strong furnace
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That is close to -e

manic quail
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,w (1+1/-e)^(-e)

alpine sable
#

hmm honestly i have no idea what i did last night to get that

#

rip

ocean sealBOT
alpine sable
#

If a sequence converges, then the corresponding series will also converge.

If a series converges, then the corresponding sequence must converge to zero.

If a sequence converges to zero, then the corresponding series must also converge.

If a series converges it must be geometric.

If an arithmetic sequence has a common difference that is between -1 and zero, it may converge


#

I think its

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the middle 3

manic quail
#

huh

gray isle
#

what do they mean by corresponding

strong furnace
#

Series is the sum of a sequence

manic quail
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I mean, you hit one correct one xD

alpine sable
#

MAN

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Im taking this on my own and the vids hasnt been of too much help

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so i have just been grinding questions

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wait can you guys explain pls

manic quail
#

For the third statement, consider this:
$$\sum_{n=1}^{\infty}\frac{1}{n}$$

ocean sealBOT
#

𝔙eryhappyperson

manic quail
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The limit of the corresponding sequence is 0, but the sum diverges.

alpine sable
#

so its second and fourth?

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sorry im still getting kinda lost here

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so just second in that one

strong furnace
#

How?

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That is not a geometric sequence either

manic quail
upbeat talon
#

I don’t get it either lmfao

manic quail
strong furnace
#

This was a good counterexample for 4th as well

upbeat talon
#

So 2,4,5?

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:/

alpine sable
#

lol sorry I am so lost at this

alpine sable
upbeat talon
#

Ye I don’t rly remember any of this... my b

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Any of this that well*

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Gl on the rest of ur questions!

reef spindle
#

How do I solve this? If M's coords are (u,v), then the midpoint of OQ is (u,v), which would be the coordinates of point P, meaning that point P lies on OQ, yes?

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Would u be the magnitude of vector(u)?

alpine sable
#

i need help

reef spindle
alpine sable
strong furnace
strong furnace
reef spindle
strong furnace
#

And do you know the relation between the coordinates of M and Q?

reef spindle
#

This is it, yes?

strong furnace
#

Yes

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You have to use this result with the relation between vector OM and OQ or matrix M and Q

reef spindle
#

ohh

reef spindle
strong furnace
#

Should be (u,v) no?

reef spindle
#

Yeah

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And u = (x,0) and v = (0,y)

strong furnace
#

u is an ordinate and v is an ordinate they are not individual points

reef spindle
#

Ohh wait

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oop

strong furnace
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If you're looking for a relation between u and x

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You should be looking at u and x' first

bronze grotto
#

Hey, could someone please help me with the last part of this?

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Part circled in orange is my working for the last bit

buoyant vale
#

could soemone help me with this?

cloud vapor
#

You need to prove that 2 opposite sides are parallel, and then that the other pair of sides aren't.So to prove that 2 sides are parallel, their vectors must be multiples of one another. You find OC and see if that's a multiple of AB. Then find CB and see if that's parallel to OA. The question tells that it is a trapezium, so you will have one pair of parallel sides and another won't be making it a trapezium

buoyant vale
#

thank you

indigo storm
#

Is this correct?

shell widget
#

3rd line

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last part

indigo storm
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Last answer

shell widget
#

-6(a-2)(a-1)

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is wrong

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you wrote -6a + 12(a-1)

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when it should be -6a(a-1) + 12(a-1)

indigo storm
#

Which line?

shell widget
#

3rd line

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last part

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1st line being the question itself

alpine sable
#

i happen to be stuck on some hw i need some help pls

oak chasm
#

@alpine sable Which number are you doing first?

alpine sable
oak chasm
#

OK, do you know how to find the hypotenuse?

alpine sable
#

no

oak chasm
#

OK, do you know how to find the right angle?

alpine sable
#

tbh I dont remember mostly everything. Im so confused to the point where i dont even know how to approach the problem

oak chasm
#

OK, we'll start with finding the right angle.

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See point C on the triangle? It has a tiny square next to it. That means right angle.

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Does that make sense?

alpine sable
#

yes

oak chasm
#

OK, now see the two sides of the triangle that touch the right angle?

alpine sable
#

yea

oak chasm
#

OK, cover them up with your fingers.

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What side is left over?

alpine sable
#

25 is the hypotenuse?

oak chasm
#

Right.

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That's how you find the hypotenuse. Cover up the two sides touching the right angle. The other side is the hypotenuse.

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Does that make sense?

alpine sable
#

yeah i remember doing that

oak chasm
#

OK, now the other two sides are called the legs.

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Let's look at angle A.

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Cover up the hypotenuse. See the other side that touches A?

alpine sable
#

yes

oak chasm
#

The 7 side is A's adjacent side. Adjacent means "next to".

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Does that make sense?

alpine sable
#

yup

oak chasm
#

OK, cover up the two sides next to A. What side is uncovered?

alpine sable
#

7?

oak chasm
#

No, 7 is a side that touches A.

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It should be covered up.

alpine sable
#

OH

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24?

oak chasm
#

Right.

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The 24 side is A's opposite side. Opposite means all the way on the other side of the triangle.

#

OK, so let's switch to angle B.

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Cover up the hypotenuse again. What uncovered side is touching B?

alpine sable
#

24

oak chasm
#

Right. The 24 side is B's adjacent side. Adjacent means "next to".

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Now cover up both sides that touch B. What side is uncovered?

alpine sable
#

7

oak chasm
#

Right. The 7 side is B's opposite side. Opposite means all the way on the other side of the triangle.

#

OK, now have you heard of SOH CAH TOA?

alpine sable
#

i dont think so

oak chasm
#

OK, say SOH CAH TOA (so cuh toe-uh) out loud a few times.

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It's important to memorize saying it.

alpine sable
#

ah ok

oak chasm
#

OK, so the first letters are SOH CAH TOA.

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They stand for sine, cosine, and tangent.

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The other letters stand for Adjacent, Opposite, and Hypotenuse.

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The middle letter is on top of a fraction. The last letter is on bottom of a fraction.

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So, SOH means "sine equals opposite over hypotenuse".

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CAH means "cosine equals adjacent over hypotenuse".

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TAH means "tangent equals opposite over adjacent".

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Does that make sense?

alpine sable
#

yes

oak chasm
#

OK, so let's do the first one. sin(A).

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Which of SOH, CAH, or TOA is for sin?

alpine sable
#

cah

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i think

oak chasm
#

Nope. Let's make it easier.

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sin(A). Do we use SOH, CAH, or TOA?

alpine sable
#

soh?

oak chasm
#

Right.

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The first letter of sin matches the first letter of SOH.

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OK, now remember how we had something over something with SOH CAH TOA?

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We have O over H with SOH. What do O and H stand for?

alpine sable
#

opposite over hypotenuse

oak chasm
#

Right. Now what's the opposite side from A?

alpine sable
#

24

oak chasm
#

Right.

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What's the hypotenuse?

alpine sable
#

25

ocean sealBOT
#

Chai T. Rex

oak chasm
#

See how we did that?

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We used SOH to help us.

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Sine equals opposite over hypotenuse.

alpine sable
#

ok

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so the first answer would be 24/25?

oak chasm
#

Yes, that's right.

alpine sable
#

ah ok

oak chasm
#

Ready for the cos(A)?

alpine sable
#

yes

oak chasm
#

OK, for cos(A), which of SOH, CAH, or TOA do we want?

alpine sable
#

cah

oak chasm
#

Right.

#

So, what do A and H stand for in CAH?

alpine sable
#

adjacent over hypotenuse

oak chasm
#

Right.

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What's A's adjacent side?

alpine sable
#

25?

oak chasm
#

No, adjacent means "next to", but it means the one that's not the hypotenuse.

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So, to find adjacent, cover up the hypotenuse and look at what other side is touching A.

alpine sable
#

oh so 7

oak chasm
#

Right.

#

So, what's the hypotenuse?

alpine sable
#

25

ocean sealBOT
#

Chai T. Rex

oak chasm
#

Ready for tan(A)?

alpine sable
#

yup

oak chasm
#

OK, for tan(A), which do we use: SOH, CAH, or TOA?

alpine sable
#

toa

oak chasm
#

OK, what does O and A stand for?

alpine sable
#

opposite over hypotenuse

oak chasm
#

Nope.

#

What does A stand for?

alpine sable
#

Adjacent

oak chasm
#

Right, so what does OA stand for?

alpine sable
#

opposite Adjacent?

oak chasm
#

Right, opposite over adjacent.

#

Does that make sense?

alpine sable
#

kinda

oak chasm
#

OK, the last two letters in SOH, CAH, or TOA are two sides from Opposite, Hypotenuse, and Adjacent.

#

The first one is over the second one.

#

So, with SOH, it's Opposite over Hypotenuse.

#

Does that make sense?

alpine sable
#

yes

oak chasm
#

OK, what does CAH mean?

alpine sable
#

adjacent over hypotenuse

oak chasm
#

OK, what does TOA mean?

alpine sable
#

opposite Adjacent

oak chasm
#

Almost. Don't forget the "over".

#

What is TOA with "over" in it?

alpine sable
#

opposite over Adjacent

oak chasm
#

OK, so we're doing tan(A).

#

What's the opposite side from A?

alpine sable
#

24?

oak chasm
#

Right, what's the adjacent side to A?

alpine sable
#

7

ocean sealBOT
#

Chai T. Rex

oak chasm
#

Does that make sense?

alpine sable
#

yes

oak chasm
#

OK, now say SOH CAH TOA (so cuh toe-uh) a few times out loud to help memorize it a little more.

alpine sable
#

alright

oak chasm
#

OK, now we switch to angle B.

#

We want to find sin(B). Which of SOH, CAH, TOA do we want?

alpine sable
#

soh

oak chasm
#

OK, what does OH mean?

alpine sable
#

opposite over hypotenuse

oak chasm
#

OK, what's the opposite side from B?

alpine sable
#

7

oak chasm
#

OK, what's the hypotenuse?

alpine sable
#

25

ocean sealBOT
#

Chai T. Rex

oak chasm
#

OK, now let's change things up a little.

#

We're going to find cos(B).

#

Tell me the steps you'd take to find it.

alpine sable
#

so i assume we going to use CAH

oak chasm
#

Right.

alpine sable
#

ah meaning adjacent over hypotenuse

oak chasm
#

Good.

alpine sable
#

and adjacent to b would be 24?

oak chasm
#

Yes, that's right.

alpine sable
#

so it would be 24/25

oak chasm
#

Right!

#

Now, tell me how you'd find tan(B).

alpine sable
#

I'd use TAH

oak chasm
#

Nope.

#

Remember what you said out loud?

alpine sable
#

TOA

oak chasm
#

Right.

alpine sable
#

Opposite Adjacent

oak chasm
#

OK.

alpine sable
#

25/24?

oak chasm
#

What's the opposite side from B?

alpine sable
#

7

tight locust
#

TANGENT = OPPOSITE over ADJACENT

oak chasm
#

What's the adjacent side to B?

alpine sable
#

24

oak chasm
#

OK, what's opposite over adjacent?

alpine sable
#

7/24?

oak chasm
#

Right.

thorn kindle
oak chasm
#

OK, now say SOH CAH TOA a few more times out loud to help memorize it.

alpine sable
#

ok

oak chasm
#

OK, now what problem are you doing next?

alpine sable
#

i think i can do 2 now on my own can we do 3?

oak chasm
#

OK, but be careful with TOA.

alpine sable
#

alright

oak chasm
#

Make sure to check that you get the correct O and the correct A.

#

OK, question 3.

#

Set your calculator to degrees mode (usually DEG shows up).

alpine sable
#

is there a website i can go to i don't have my calculator charged at the moment

oak chasm
#

Sure, just do this here:

tight locust
oak chasm
#

,w sin(85 degrees)

ocean sealBOT
oak chasm
#

Make sure to say "degrees" in it.

tight locust
#

,w sin(85)

oak chasm
#

See how I did that?

alpine sable
#

kinda confused

tight locust
#

WA is usually pretty good at determining whether you need deg or rad

oak chasm
#

@alpine sable OK, so what does your problem ask for?

tight locust
alpine sable
#

it says " sin63° "

oak chasm
#

OK, say ,w sin(63 degrees)

alpine sable
#

,w sin(63 degrees)

oak chasm
#

OK, see the decimal approximation part?

alpine sable
#

yup

oak chasm
#

What's that rounded to four decimal places?

alpine sable
#

.8910

oak chasm
#

OK, that's your answer.

alpine sable
#

oh thats easy

oak chasm
#

Try that and see where the decimal approximation shows up.

alpine sable
#

ok

#

for cos24° do i replace sin with cos

oak chasm
#

Yep. ,w cos(24 degrees)

alpine sable
#

,w cos(24 degrees)

alpine sable
#

,w tan(24 degrees)

alpine sable
#

,w tan(42 degrees)

oak chasm
#

Be careful. Check problem 5.

alpine sable
#

,w tan(86 degrees)

alpine sable
#

ah

#

thank you

oak chasm
#

No problem.

alpine sable
#

i want to make sure these are correct?

harsh swallow
#

cos = cal

oak chasm
#

Check cos(A).

harsh swallow
#

which is adjacent/long

oak chasm
#

Other ones look good.

alpine sable
#

12/37?

oak chasm
#

Right.

#

You're doing pretty well.

alpine sable
#

thank you. im now on number 7

oak chasm
#

OK, now it says to use tangent ratio. Which of SOH CAH TOA is tangent?

alpine sable
#

toa?

oak chasm
#

Right.

#

So, here's what we do.

#

Tangent equals opposite over adjacent.

harsh swallow
#

toa stands for tan = opposite/adjacent

ocean sealBOT
#

Chai T. Rex

oak chasm
#

See how I have the angle, then the opposite over adjacent (TOA)?

alpine sable
#

yes

oak chasm
#

OK, now you do normal algebra to solve for x.

#

One thing to not do. Don't do anything to what's inside tan's parentheses.

ocean sealBOT
#

Chai T. Rex

#

Chai T. Rex

oak chasm
#

Does that make sense?

alpine sable
#

kinda

harsh swallow
#

another way of looking at that can be to say tan(41) = a

oak chasm
#

For example, you can't divide the angle by 2 or something.

ocean sealBOT
#

Chai T. Rex

#

Chai T. Rex

oak chasm
#

So don't do that without a good reason.

#

Does that make sense?

alpine sable
#

bruh this sounds hard not gonna lie 😭

oak chasm
#

It takes some practice to get used to.

ocean sealBOT
#

Chai T. Rex

alpine sable
#

multiply it ?

oak chasm
#

Multiply both sides by what?

#

x?

alpine sable
#

12?

ocean sealBOT
#

Chai T. Rex

oak chasm
#

If you do that, x isn't any closer to being by itself.

alpine sable
#

i thought 12 would cancel out

#

i guess not

oak chasm
#

You can cancel it by dividing both sides by 12.

#

That'll put a 12 in the bottom on the right.

#

Then it'll cancel with the 12 in the top on the right.

ocean sealBOT
#

Chai T. Rex

oak chasm
#

See how that worked?

alpine sable
#

yea

oak chasm
#

OK, now here's a trick.

#

If you flip both sides over, you get x on the right.

ocean sealBOT
#

Chai T. Rex

oak chasm
#

See how I flipped both fractions?

alpine sable
#

yes

oak chasm
#

OK, so that's the exact value of x.

#

If you want an approximate value, ,w 12/tan(41 degrees)

alpine sable
#

,w 12/tan(41 degrees)

oak chasm
#

You can then get as many digits as you need.

#

Hmm, never mind, not on this, apparently.

alpine sable
#

ok

simple dragon
#

can someone explain something for me

#

why is the 81/4 x^4 crossed out

civic crypt
#

cos^2(3x) - 1 = - (sin^2(3x)) = -(3x)^2 = -9x^2

#

And denominator 2x(3x/4) = 3x^2/2

#

So -18/3 = -6

#

I guess it is crossed out cause x^4 is much smaller than x^2 in small x values, so it is ignore

simple dragon
#

ok but why was the 81/4 x^4 crossed out in this example though?

rigid pollen
#

i see

simple dragon
#

as in because its very small its basically zero?

civic crypt
#

yes

simple dragon
#

oh ok thanks g

civic crypt
#

If x is for example 0.001 then x^2 is 0.00001, and x^4 is 0.000000001

#

So x^4 term is ignored

simple dragon
#

yh yh i got it now thank u very much bro

alpine sable
#

is this right i wanna make sure?

harsh swallow
#

tan(27) = x/15

#

,w tan(27) = x/15

alpine sable
#

hm

harsh swallow
#

thanks wolfram

#

thank

#

fucking idiot

#

😄

rigid pollen
#

crap i put sin instead of tan

#

i don't deserve to be studying maths

harsh swallow
#

,w 15tan(27)

alpine sable
#

i was right orrrrrrrrrrrrrrr

oak chasm
#

@alpine sable Yes, I get that answer.

alpine sable
#

ah thank you

harsh swallow
#

tan(58) = 22/x

#

,w tan(58) = 22/x

oak chasm
#

Hit the blue more button under it.

oak chasm
#

Hmm, guess it doesn't like approximate solutions.

harsh swallow
#

wolfram i hate you sometimes

oak chasm
#

,calc 22/tan(58 degrees)

ocean sealBOT
#

Result:

13.747125742005
harsh swallow
#

,w 22/tan(58)

alpine sable
#

hm

oak chasm
#

@alpine sable We get a different answer.

harsh swallow
#

,w 22 tan(58)

alpine sable
#

where did i plug into wrong?

harsh swallow
#

you put in 18 for b

#

b = 22

oak chasm
#

@alpine sable Don't use online calculators to help yet. You still need practice doing it by hand for later tests and such.

alpine sable
#

ok

#

need help with this

harsh swallow
#

it says use sine

oak chasm
#

OK, which of SOH CAH TOA do you use for sine?

alpine sable
#

soh

oak chasm
#

Yep.

#

So, what's the starting equation?

alpine sable
#

no idea

oak chasm
#

OK, what does SOH stand for?

alpine sable
#

sine equals opposite over hypotenuse

oak chasm
#

OK, so write sin(angle) = opposite/hypotenuse.

#

Then fill in the angle, the opposite side, and the hypotenuse.

#

That's an equation, so it's your starting equation.

alpine sable
#

sin(35 degrees) =

#

what would the opposite be?

oak chasm
#

Cover up the two sides that touch the angle.

#

What side is left?

alpine sable
#

e is left

oak chasm
#

Yes, e is all the way across the triangle from the angle, so it's the opposite.

alpine sable
#

can u put it in the bot

ocean sealBOT
#

Chai T. Rex

oak chasm
#

Now fill in the hypotenuse.

alpine sable
#

12

ocean sealBOT
#

Chai T. Rex

oak chasm
#

This is your starting equation.

alpine sable
#

alright so

#

i kinda forgot the next step

oak chasm
#

What can you do to get e on a side by itself?

#

Want to know a trick?

#

You said earlier to cancel, right?

alpine sable
#

multiply?

oak chasm
#

The thing other than e on the right is 12, right?

#

So, you need to cancel 12.

#

So, the 12 now is in the bottom.

#

So you need to put a 12 on top.

#

So, multiplying by 12 puts a 12 on top.

#

Dividing by 12 puts a 12 on bottom.

#

So, we multiply.

#

Does that make sense?

alpine sable
#

yea

ocean sealBOT
#

Chai T. Rex

alpine sable
oak chasm
#

,calc 12 sin(35 degrees)

ocean sealBOT
#

Result:

6.8829172362126
oak chasm
#

Almost.

#

Rounding is off a little.

alpine sable
#

ah ok

#

this one im not to sure about cuz i dont know what side is what

oak chasm
#

OK, how do you find the adjacent side?

#

Oh, wait.

#

Let me check it.

#

@alpine sable Yes, that's correct. Do you need a refresher on how to identify sides?

alpine sable
#

for a triangle like that yea

oak chasm
#

OK, find the right angle.

#

Which angle is it?

alpine sable
#

that would be where a and b meet

#

?

oak chasm
#

I don't know what you mean by a and b.

#

Is it the left, right, or top angle?

alpine sable
#

top angle

oak chasm
#

Right, it has the little square next to it.

#

OK, so cover up the sides that touch the right angle.

#

What side is left?

alpine sable
#

n

oak chasm
#

Right. That's the hypotenuse.

#

Now, let's find the opposite side from 39 degrees.

#

Cover up the two sides that touch the 39 degree angle.

#

What side is left?

alpine sable
#

25

oak chasm
#

Right. That's the opposite side from 39 degrees.

#

Now, let's find the adjacent side to 39 degrees.

#

Cover up the hypotenuse.

#

What other side touches 39 degrees?

alpine sable
#

25

oak chasm
#

No, 25 doesn't touch the 39 degree angle.

alpine sable
#

oh

#

its the side with no number

oak chasm
#

Right.

#

So that's how you find the adjacent side.

alpine sable
#

i see

oak chasm
#

Yes, that's right.

dusty oxide
#

I need to calculate h can someone help me? I dont understand how to do it

#

I checked the answer and it was h = 30-30sin(35) but I dont understand how and why

#

<@&286206848099549185> Hi 👋

#

Ahh

#

I think I get it

#

Yeah makes sense

#

Thanks alot 👍

#

Very simple when u made such a good drawing

#

Wher

#

I mean I understand what u did

alpine sable
#

hey

dusty oxide
#

Np 👌

alpine sable
#

question

#

im currently doing geometry work, can someone help me with my homework

dusty oxide
#

Something I see everywhere people say "Dont ask to ask, just ask"

#

^

alpine sable
#

ok ._.

#

ill send a pic of the paper im doing rq

#

its with like circles and stuff but i dont really get how to do it and im terrable at math

dusty oxide
#

I need to get this verified but from what I think I know all the corners on those quadrillaterals will add up to 360

alpine sable
#

uhhhhhhh

#

im not sure

dusty oxide
#

Ah true

alpine sable
#

the quadrilateral is the shape in the circle right?

dusty oxide
#

Yeah

alpine sable
#

ok

#

ive been trying to use this website called cheg but they dont explain it lmao they just kinda throw awnsers at me with no context

#

ok

#

yes

#

uhhhhh

#

theres alot of numbers there

#

ok

#

btw i have no clue on how to solve these, my teacher doesent rly "teach"

dusty oxide
#

But if we would make a line from L to J the angles would be 180 but L wouldnt be 92 anymore but that might not matter at all

#

Or wait

#

Oh yeah nvm I understand I believe (I dont even need to know this but its interesting)

worldly gulch
#

My math is bad

alpine sable
#

i dont understand what yall r saying ._.

worldly gulch
#

I'm rlly dumb when it comes to math

alpine sable
#

me too

#

i have 9 papers due monday

worldly gulch
#

I mean it's not that bad for me

#

but

#

it's still bad

#

yk

alpine sable
#

bro do you know geometry

#

somewhat

dusty oxide
#

@alpine sable Read the article he sent it makes sense if u just read it for a bit

alpine sable
#

ok

fallow sun
#

can someone hop in vc and help me out? Just 8 questions and we both can work on it sinc eill also need to learn this material eitherway :c

#

<@&286206848099549185>

fallow sun
#

30 minutes before request <@&286206848099549185> if possible :3

hollow owl
#

please help

remote heron
hollow owl
#

when the left is F

#

but I need to use axiom and all of this here

#

and I dont know how to prove it by using axioms

remote heron
#

i guess me either

#

i think a good way would be to let $L(x) = \neg x \to x$

ocean sealBOT
#

jan Niku

remote heron
#

but idk if thats what youre being asked to do here

alpine sable
#

,tex $n^{3}-(n-y)\times n\times (n+y)=y^{2}\times n$

hollow owl
ocean sealBOT
#

Ranok Hui

remote heron
#

you only have the statement x

#

so you should be okay to just use x

#

if youre applying an axiom that uses other letters thats fine as long as its applicable

alpine sable
#

I haven't learn arrows and that thingy in front of the first x

alpine sable
#

I just kind of made that discovery on the calculator.

hollow owl
remote heron
#

second alpha?

#

you need to make alpha consistent

#

if you have a second alpha just use another letter

#

i mean you probably wanna use something like $P \to Q = \neg P \lor Q$ then $P = \neg Q$...

ocean sealBOT
#

jan Niku

remote heron
#

youll end up with something like $\neg P \lor P$ or whatever

ocean sealBOT
#

jan Niku

remote heron
#

idk if you have that as an identity?

alpine sable
#

Idk, and can anybody explain what the arrow and the thing that looks like 7 mean?

#

$\neg$

ocean sealBOT
#

Ranok Hui

remote heron
#

logical negation

#

same as like

#

NOT

alpine sable
#

So $\neg x$ is not x

ocean sealBOT
#

Ranok Hui

alpine sable
#

?

remote heron
#

yea

alpine sable
#

How about arrows?

remote heron
#

In logic, a set of symbols is commonly used to express logical representation. The following table lists many common symbols, together with their name, pronunciation, and the related field of mathematics. Additionally, the third column contains an informal definition, the fourth column gives a short example, the fifth and sixth give the Unicode ...

alpine sable
#

Thanks

remote heron
#

theres a lot of symbols

alpine sable
#

Yeah

#

So the definition of your question is (not x implies x) implies x

#

?

remote heron
#

idk if that person is still here

alpine sable
#

$(\neg x \to x)\to x$ = (not x implies to x) implies to x?

#

Oh my

ocean sealBOT
#

Ranok Hui

remote heron
#

sort of yea

alpine sable
#

I still can't understand it.

#

It has another definition of if then

#

If not x then x?

#

Then if x then x?

remote heron
#

you should check out the wiki article or something if youre curious

#

its primarily using definitions of a logical statement

#

or if you track down a book on proofs theyll usually cover logic before anything else

storm solar
alpine sable
#

So does the example mean: if x = 2, then $x^2$ = 4?

ocean sealBOT
#

Ranok Hui

oak chasm
#

@alpine sable Yes.

remote heron
#

if x=2, then is x^2 necessarily 4

woeful pulsar
#

the aim of the example is to show that implications are not necessarily equivalent to their converse

remote heron
#

"all dogs are mammals" doesnt mean that "all mammals are dogs"

alpine sable
#

Ok

remote heron
#

that kind of thing

ocean sealBOT
#

Chai T. Rex

remote heron
#

the most fascinating thing is that A-> B doesnt mean B->A but it does mean NOT B -> NOT A

#

well at least its cool to me

woeful pulsar
#

i.e. implications are equivalent to their contrapositive

#

that allows you to do proof by proving the contrapositive

alpine sable
#

Because not A and not B just needs to be different from its original value, so just chose any value that is neither A nor B?

oak chasm
#

No, not A doesn't mean any proposition but A.

#

Not A means that A isn't true.

remote heron
#

these things are a little more tightly defined than youre treating them

alpine sable
#

Oh

remote heron
#

were not really picking a value for x

#

were dealing with the statement A: "x=2"

#

so x isnt equal to anything really

#

A is either true or false

alpine sable
#

So if A: x = 2, B: $x^2$ =4, then $A \to B$ is true, but $B \to A$ is false?

oak chasm
#

No.

ocean sealBOT
#

Chai T. Rex

remote heron
#

the converse isnt always false

#

its just generally not true

ocean sealBOT
#

Ranok Hui

oak chasm
#

$A \to B$ doesn't disprove $B \to A$, it just doesn't prove it.

ocean sealBOT
#

Chai T. Rex

alpine sable
#

So most of the time the converse is not true?

remote heron
#

yea

oak chasm
#

No, that's not true.

remote heron
#

well

#

yea most is a weird word

#

usually you dont assume the converse because its not true

oak chasm
#

You can't rely on the converse being true or false.

remote heron
#

like you define these implications as statements right

#

C: A->B

#

D: E->F

#

yadda

alpine sable
#

Yes?

remote heron
#

well wait thonk

#

lets do this

#

$C:= A \to B \ D:= B \to A$

ocean sealBOT
#

jan Niku

remote heron
#

so C is either true or false

#

D is either true or false

#

but $C\to D$ isnt given

ocean sealBOT
#

jan Niku

remote heron
#

idk its not important lol

#

assuming the converse is a really common mistake early on

#

you can trivially create examples where its true

#

tautological statements like if x is 2 then x is 2

#

if x is a multiple of 2 then x is even

#

stuff like that

oak chasm
#

@alpine sable The mistake you're making is in thinking that the truth or falsehood of A -> B tells you something about B -> A. It doesn't. They can be the same. They can be different.

alpine sable
#

So for example the example given by wikipedia, C is true, D is false so C -› D is false?

#

And sometimes the converse can be true?

#

And $\neg A \to \neg B$ is true because if A is false, B can't be true?

ocean sealBOT
#

Ranok Hui

alpine sable
#

I'm feel like I'm mixing everything up

#

Idk

remote heron
#

$\neg A \to \neg B \leftrightarrow B \to A$

ocean sealBOT
#

jan Niku

remote heron
#

@alpine sable for real if youre curious pick up a prepositional logic bok

#

you can find good ones for free

#

or khan academy

#

do the whole thing of building truth tables and looking at all this stuff

#

its less complicated than it probably seems at first

oak chasm
#

Also, a non-free option is Language, Proof and Logic, which is excellent. It comes with software to let you practice in a more intuitive manner.

alpine sable
ocean sealBOT
#

Ranok Hui

alpine sable
#

?

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Is this still true

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Because the left right arrow means iff, the converse is also true.

remote heron
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the implication being true implies its contrapositive is true

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and the converse is true since the contrapositive being true implies the implication is true

nova anvil