#help-0
1 messages · Page 611 of 1
If x<0 then y-x<0 and y<x, but as y y is positive this cannot happen.
Well y>x and y>0 has the solution y=5 x=-3
right
So 1/x > 1/y and y>0 forces x>0
But y>x and y>0 doesnt force x>0
@ashen wave Read #❓how-to-get-help
@ashen wave You have like 10 other channels
Find a channel that did not have a message in last 30 min and post there
For example in channel-9 noone has posted in last hour.
i am fully aware, but @alpine sable aren't you finished?
If you are aware then why you interupt us. I still have something to say.
nevermind
@alpine sable So is the answer none of above?
I think the best way to solve it is to sketch the space of solutions for each of them.
It was pretty tricky question, but yes, going the proper way and checking x>0 x<0 (or immediately concluding x>0) does it.
Yea, was easy to make your mistake, I dont think I would get it on the exam. That was the trick of the poster.
Np. Have a nice day.
hii can someone help me with how to start this proof?
show that √(1001) - √(1000) < 1/[2√(1000)]
sorry about the ugly formatting im not sure how to use the formatting bot properly yet
$\sqrt{1001} - \sqrt{1000} < \frac{1}{2\sqrt{1000}}$
Yes ツ
yes omg thank u lol:)
so i think we can start with multiplying the fractiom onn the right by sqrt1000
so it would be sqrt1000 / 2
wait if u multiplied the fraction by sqrt1000
wouldn't it just be 1/2
bc it cancels the denominator
Yes ツ
simplify the rhs
its just \sqrt{10}
which is less than 5\sqrt{10}
and $5\sqrt{10} = \frac{10\sqrt{10}}{2} = \frac{1}{2\sqrt{1000}}$
Yes ツ
@tacit pollen
$0 < \sqrt{1001} - \sqrt{1000} < \sqrt{1210} - \sqrt{1000} = 11\sqrt{10} - 10\sqrt{10} = \sqrt{10} < 5\sqrt{10} = \frac{1}{2\sqrt{1000}}$
Yes ツ
does that make sense
wait does 5sqrt10 = 1/2sqrt1000
someone german who can help me
okay i'm still a bit confused ngl
but i'll give what u said a go
thank you so much!! to both of u:)
what are you confused about
let me check
ohhhh okay
omg nono that's okay
Hey, can someone please help me with this question
This is what I have done so far
Don't quite understand how to approach part b
@tacit pollen ive got something
maybe not what youre expected to do though
but here it is
omgosh thank u regardless
yeee i read thru and i kind of get it but my school hasn't learnt that theorem yet
so i dont know if im allowed to work it out like that
thank u tho!!
First note that $10.01^2 = 100.2001 \newline 0 < \sqrt{1001} - \sqrt{1000} < \sqrt{1002.001} - \sqrt{1000} < 10.01\sqrt{10} - 10\sqrt{10} = 0.01\sqrt{10} = \frac{1}{100}\sqrt{10} < \frac{1}{20}\sqrt{10} = \frac{1}{2\sqrt{1000}}$
Yes ツ
do you understand this? is it ok? @tacit pollen
Already posted it there
omgosh bro i hate to bring this up again but idk if √10/20 = 1/2√1000
aw let me check again
u can rewrite as a quadratic in sqrtx
HASHA nono its okay you've been helping me w this question for agess
i'll go think abt it some more myself
nooo i must do this
HAHA okay i will think abt it too i'll update u if i get it
ok yes but we can modify the proof slightly
but before
$\frac{1}{2\sqrt{1000}} = \frac{1\sqrt{10}}{200}$
Yes ツ
yupp
$10.001^2 = 100.020001 \newline 0 < \sqrt{1001} - \sqrt{1000} < \sqrt{1000.20001} - \sqrt{1000} = 10.001\sqrt{10} - 10\sqrt{10} = 0.001\sqrt{10} = \frac{1}{1000}\sqrt{10} < \frac{1}{200}\sqrt{10}$
@tacit pollen
IM SO SORRY FOR MAKING MISTAKES
EARLIER
is this correct now thoug?
YAYAY
YEEE
fml
lol
its wrong
omg
i keep making mistakes!!!
ill dm you a correct solution
small error but ill fix hopeuflly
@lucid ember don't multipost
Help:)
What have you tried?
Not really anything, I don’t understand what to do:,(
rewrite -3(log5)4 !!
lol sorry idk how to format but basically rewrite the power thingy
Alright I’ll try
after u rewrite that as a log5(something)
Just use an unknown?
no. the thing in front the algorithm put inside as an exponent
to move the -3
i just didn't know if i should give the answer or let you work it out
Like this?
not quitee
anyways once u rewrite it in the form log base 5 (something)
Yea?
so just use the third law down from this pic to rewrite the exponent
Ok..
Woah this is confusing
do u want me to write it down for you
I think I kinda get it?
The most important thing to know about logs is the one thing they never teach anyone. They just yell about log rules.
log_b (a) is the exponent of b that gives you a.
That's what it means
So when log_b (a) is the exponent of b, the answer is a.
Alright
So it's not a rule you should memorize. It's how you should intetpret what a log is.
Thanks guys!! 😄
in this problem were dealing with solution in an interval
so should the solution be: $u = e^{Re(\lambda)t}cos(bt)$?
Anticipation

Could someone dm me to help me with geometry? Im really struggling and I need some help.
ok yeah, its just a lot of questions
ive been having trouble focusing in class so im kind of behind
these are a few of them
Is this a test?
no its a classwork
Use distance formula for ques1
,w sqrt(26^2 + 10^2)
Does anyone know the difference between Spearman and Pearson correlation coefficient?
- The midsegment of a trapezoid is the average of the parallel sides
- Diameter is twice radius
How do we find the height of a triangle knowing an angle and only one side?
right so I would probably have to drag the line down a little, thanks
ok
yeah my height cuts my angle
Say I am told x<3+sqrt(36+a), how can I find when f(x) is smaller than 0
<@&286206848099549185> could someone confirm if this is true?
so the angle a equals 40° and the side AC is 8cm. The point of the exercise is to find the area of the triangle in gray. I would like to find the height to find the side BC.
no I understand french dw
i know ur french
but
this is an english server
uh
i am not gonna be a karen but yeah u can continue
i dont wanna be a fun ruiner and cause a drama for no reason
So what are you doing here
Nobody said this has to be an English speaking server
but @modern surge i appreciate that ur taking time into helping a needy man a mate who needs help. u can continue
well okay
ok so what are you doing...
nothing
just chilling
ok? So why are you here?
i can be? this server is public
Hey don't be rude
You infiltrated their help session just to say "speak english"
when they clearly are both french speakers
its cool
He/She is right this server is public
i thought this server is an english server
plus this is not an English speaking server, it's just we all speak English cause it's a generic language
i didnt knew you could speak any language
bruh i said
stop poking me for no reason
So what would you do if someone spoke only Mandarin CHinese
Tell them to speak english?
fresh
Hey man its over
Ok then why are you here?
Hey, calm down. We're here because we struggling with maths shit, that's the reason why we're here, fighting won't solve anything. So please respect each other
I know but still, arguing with each other is pointless. So hey, just chill and ignore them. Do maths idk
@viscid lagooni know right but this guy is just exacerbating the fight and making it worse
je sais pas ce que représente D et O
@modern surge@half cobaltbonjour
it's all good, just chill with each other for now. I don't wanna interrupt people with their maths rn. Good luck buddy
yes same thanks good luck
anneyongahseyo
Can some one take me through this
what are u confused about
you didn't post a problem
can i send pic to show?
Yes
K 2 min
can anyone help me with this question?
An infinite geometric series begins at 15 and converges to 9. The second term of this series is
I think its -10 but im not too sure
a/1-r = 9
and in this case a = 15
-10 is way far off
but at least you knew it was negative!
wait i'm sorry
i thought you wanted to find r
nah its the second term
what did you get for r?
-2/3
awesome thanks!
sorry that i misread the question
i got a couple more about series/sequences if you dont mind helping me out
A sequence has the following explicit definition: An = ((n+1)/n)^n. Which of the following statements best describes this sequence?
This sequence does not converge
this sequence converges to 0
this sequence converges to 1
this sequence converges to a different number
I think its another number
𝔙eryhappyperson
yep
what number do you think it converges to
You could split the fraction in the middle first, if that makes it more obvious.
I got around 3.5 ish, not too sure if its right
this might be more recogniseable:
$$A_n = \br{1 + \frac 1n}^n$$
ℝamonov
Does it?
wut
,w lim as n to infty (1+1/n)^n
Bruh
I got around 3.5 ish
how high were you testing
if n-inf the lim f(x) ^ g(x) is equal to e^(f(x)-1)*(g(x))
even a relatively small number like 100 gets you pretty close to e
,calc (1 + 1/100)^100
Result:
2.7048138294215
even 1 doesn't give you 3.5 xD
,w solve (1 + 1/x)^x = 3.5
lol
That is close to -e
,w (1+1/-e)^(-e)
If a sequence converges, then the corresponding series will also converge.
If a series converges, then the corresponding sequence must converge to zero.
If a sequence converges to zero, then the corresponding series must also converge.
If a series converges it must be geometric.
If an arithmetic sequence has a common difference that is between -1 and zero, it may converge
I think its
the middle 3
huh
what do they mean by corresponding
Series is the sum of a sequence
I mean, you hit one correct one xD
MAN
Im taking this on my own and the vids hasnt been of too much help
so i have just been grinding questions
wait can you guys explain pls
For the third statement, consider this:
$$\sum_{n=1}^{\infty}\frac{1}{n}$$
𝔙eryhappyperson
The limit of the corresponding sequence is 0, but the sum diverges.
so its second and fourth?
sorry im still getting kinda lost here
so just second in that one
For the 4th one, consider something like the sum of the reciprocal of the Fibonacci numbers.
I don’t get it either lmfao
What don't you get?
This was a good counterexample for 4th as well
So just 2 for this one then
lol sorry I am so lost at this
I think this is prob it?
Ye I don’t rly remember any of this... my b
Any of this that well*
Gl on the rest of ur questions!
How do I solve this? If M's coords are (u,v), then the midpoint of OQ is (u,v), which would be the coordinates of point P, meaning that point P lies on OQ, yes?
Would u be the magnitude of vector(u)?
i need help
@alpine sable occupied channel #❓how-to-get-help

There is a problem in the way you have named things but if you mean x-ordinate of M is magnitude of position vector of P then you are incorrect
Also to solve this do you know the matrix equation for rotation of points in 2D Cartesian plane?
Yeah, that's part of the previous question
And do you know the relation between the coordinates of M and Q?
This is it, yes?
Yes
You have to use this result with the relation between vector OM and OQ or matrix M and Q
ohh
Vector OM would be (x, y), yes?
Should be (u,v) no?
u is an ordinate and v is an ordinate they are not individual points
If you're looking for a relation between u and x
You should be looking at u and x' first
Hey, could someone please help me with the last part of this?
Part circled in orange is my working for the last bit
You need to prove that 2 opposite sides are parallel, and then that the other pair of sides aren't.So to prove that 2 sides are parallel, their vectors must be multiples of one another. You find OC and see if that's a multiple of AB. Then find CB and see if that's parallel to OA. The question tells that it is a trapezium, so you will have one pair of parallel sides and another won't be making it a trapezium
thank you
Is this correct?
Last answer
-6(a-2)(a-1)
is wrong
you wrote -6a + 12(a-1)
when it should be -6a(a-1) + 12(a-1)
Which line?
i happen to be stuck on some hw i need some help pls
@alpine sable Which number are you doing first?
OK, do you know how to find the hypotenuse?
no
OK, do you know how to find the right angle?
tbh I dont remember mostly everything. Im so confused to the point where i dont even know how to approach the problem
OK, we'll start with finding the right angle.
See point C on the triangle? It has a tiny square next to it. That means right angle.
Does that make sense?
yes
OK, now see the two sides of the triangle that touch the right angle?
yea
25 is the hypotenuse?
Right.
That's how you find the hypotenuse. Cover up the two sides touching the right angle. The other side is the hypotenuse.
Does that make sense?
yeah i remember doing that
OK, now the other two sides are called the legs.
Let's look at angle A.
Cover up the hypotenuse. See the other side that touches A?
yes
yup
OK, cover up the two sides next to A. What side is uncovered?
7?
Right.
The 24 side is A's opposite side. Opposite means all the way on the other side of the triangle.
OK, so let's switch to angle B.
Cover up the hypotenuse again. What uncovered side is touching B?
24
Right. The 24 side is B's adjacent side. Adjacent means "next to".
Now cover up both sides that touch B. What side is uncovered?
7
Right. The 7 side is B's opposite side. Opposite means all the way on the other side of the triangle.
OK, now have you heard of SOH CAH TOA?
i dont think so
OK, say SOH CAH TOA (so cuh toe-uh) out loud a few times.
It's important to memorize saying it.
ah ok
OK, so the first letters are SOH CAH TOA.
They stand for sine, cosine, and tangent.
The other letters stand for Adjacent, Opposite, and Hypotenuse.
The middle letter is on top of a fraction. The last letter is on bottom of a fraction.
So, SOH means "sine equals opposite over hypotenuse".
CAH means "cosine equals adjacent over hypotenuse".
TAH means "tangent equals opposite over adjacent".
Does that make sense?
yes
soh?
Right.
The first letter of sin matches the first letter of SOH.
OK, now remember how we had something over something with SOH CAH TOA?
We have O over H with SOH. What do O and H stand for?
opposite over hypotenuse
Right. Now what's the opposite side from A?
24
25
Chai T. Rex
Yes, that's right.
ah ok
Ready for the cos(A)?
yes
OK, for cos(A), which of SOH, CAH, or TOA do we want?
cah
adjacent over hypotenuse
25?
No, adjacent means "next to", but it means the one that's not the hypotenuse.
So, to find adjacent, cover up the hypotenuse and look at what other side is touching A.
oh so 7
25
Chai T. Rex
Ready for tan(A)?
yup
OK, for tan(A), which do we use: SOH, CAH, or TOA?
toa
OK, what does O and A stand for?
opposite over hypotenuse
Adjacent
Right, so what does OA stand for?
opposite Adjacent?
kinda
OK, the last two letters in SOH, CAH, or TOA are two sides from Opposite, Hypotenuse, and Adjacent.
The first one is over the second one.
So, with SOH, it's Opposite over Hypotenuse.
Does that make sense?
yes
OK, what does CAH mean?
adjacent over hypotenuse
OK, what does TOA mean?
opposite Adjacent
opposite over Adjacent
24?
Right, what's the adjacent side to A?
7
Chai T. Rex
Does that make sense?
yes
OK, now say SOH CAH TOA (so cuh toe-uh) a few times out loud to help memorize it a little more.
alright
OK, now we switch to angle B.
We want to find sin(B). Which of SOH, CAH, TOA do we want?
soh
OK, what does OH mean?
opposite over hypotenuse
OK, what's the opposite side from B?
7
OK, what's the hypotenuse?
25
Chai T. Rex
OK, now let's change things up a little.
We're going to find cos(B).
Tell me the steps you'd take to find it.
so i assume we going to use CAH
Right.
ah meaning adjacent over hypotenuse
Good.
and adjacent to b would be 24?
Yes, that's right.
so it would be 24/25
I'd use TAH
TOA
Right.
Opposite Adjacent
OK.
25/24?
What's the opposite side from B?
7
TANGENT = OPPOSITE over ADJACENT
What's the adjacent side to B?
24
OK, what's opposite over adjacent?
7/24?
Right.

OK, now say SOH CAH TOA a few more times out loud to help memorize it.
ok
OK, now what problem are you doing next?
i think i can do 2 now on my own can we do 3?
OK, but be careful with TOA.
alright
Make sure to check that you get the correct O and the correct A.
OK, question 3.
Set your calculator to degrees mode (usually DEG shows up).
is there a website i can go to i don't have my calculator charged at the moment
Sure, just do this here:
,w sin(85 degrees)
Make sure to say "degrees" in it.
,w sin(85)
See how I did that?
kinda confused
WA is usually pretty good at determining whether you need deg or rad
@alpine sable OK, so what does your problem ask for?

it says " sin63° "
OK, say ,w sin(63 degrees)
,w sin(63 degrees)
OK, see the decimal approximation part?
yup
What's that rounded to four decimal places?
.8910
OK, that's your answer.
oh thats easy
You can also go to https://wolframalpha.com and ask sin(63 degrees).
Try that and see where the decimal approximation shows up.
Yep. ,w cos(24 degrees)
,w cos(24 degrees)
,w tan(24 degrees)
,w tan(42 degrees)
Be careful. Check problem 5.
,w tan(86 degrees)
No problem.
i want to make sure these are correct?
cos = cal
Check cos(A).
which is adjacent/long
Other ones look good.
12/37?
thank you. im now on number 7
OK, now it says to use tangent ratio. Which of SOH CAH TOA is tangent?
toa?
toa stands for tan = opposite/adjacent
Chai T. Rex
See how I have the angle, then the opposite over adjacent (TOA)?
yes
OK, now you do normal algebra to solve for x.
One thing to not do. Don't do anything to what's inside tan's parentheses.
Does that make sense?
kinda
another way of looking at that can be to say tan(41) = a
For example, you can't divide the angle by 2 or something.
bruh this sounds hard not gonna lie 😭
It takes some practice to get used to.
Chai T. Rex
multiply it ?
12?
Chai T. Rex
If you do that, x isn't any closer to being by itself.
You can cancel it by dividing both sides by 12.
That'll put a 12 in the bottom on the right.
Then it'll cancel with the 12 in the top on the right.
Chai T. Rex
See how that worked?
yea
Chai T. Rex
See how I flipped both fractions?
yes
OK, so that's the exact value of x.
If you want an approximate value, ,w 12/tan(41 degrees)
,w 12/tan(41 degrees)
If you ask that on https://wolframalpha.com, it'll have a more digits button.
You can then get as many digits as you need.
Hmm, never mind, not on this, apparently.
You can also Google search for 12/tan(41 degrees). Try it https://google.com/search?q=12%2Ftan(41+degrees).
ok
cos^2(3x) - 1 = - (sin^2(3x)) = -(3x)^2 = -9x^2
And denominator 2x(3x/4) = 3x^2/2
So -18/3 = -6
I guess it is crossed out cause x^4 is much smaller than x^2 in small x values, so it is ignore
ok but why was the 81/4 x^4 crossed out in this example though?
i see
as in because its very small its basically zero?
yes
oh ok thanks g
If x is for example 0.001 then x^2 is 0.00001, and x^4 is 0.000000001
So x^4 term is ignored
is this right i wanna make sure?
hm
,w 15tan(27)
i was right orrrrrrrrrrrrrrr
@alpine sable Yes, I get that answer.
Hit the blue more button under it.
Hmm, guess it doesn't like approximate solutions.
wolfram i hate you sometimes
,calc 22/tan(58 degrees)
Result:
13.747125742005
,w 22/tan(58)
hm
@alpine sable We get a different answer.
,w 22 tan(58)
where did i plug into wrong?
@alpine sable Don't use online calculators to help yet. You still need practice doing it by hand for later tests and such.
it says use sine
OK, which of SOH CAH TOA do you use for sine?
soh
no idea
OK, what does SOH stand for?
sine equals opposite over hypotenuse
OK, so write sin(angle) = opposite/hypotenuse.
Then fill in the angle, the opposite side, and the hypotenuse.
That's an equation, so it's your starting equation.
e is left
Yes, e is all the way across the triangle from the angle, so it's the opposite.
can u put it in the bot
Chai T. Rex
Now fill in the hypotenuse.
12
Chai T. Rex
This is your starting equation.
What can you do to get e on a side by itself?
Want to know a trick?
You said earlier to cancel, right?
multiply?
The thing other than e on the right is 12, right?
So, you need to cancel 12.
So, the 12 now is in the bottom.
So you need to put a 12 on top.
So, multiplying by 12 puts a 12 on top.
Dividing by 12 puts a 12 on bottom.
So, we multiply.
Does that make sense?
yea
Chai T. Rex
?
,calc 12 sin(35 degrees)
Result:
6.8829172362126
OK, how do you find the adjacent side?
Oh, wait.
Let me check it.
@alpine sable Yes, that's correct. Do you need a refresher on how to identify sides?
for a triangle like that yea
top angle
Right, it has the little square next to it.
OK, so cover up the sides that touch the right angle.
What side is left?
n
Right. That's the hypotenuse.
Now, let's find the opposite side from 39 degrees.
Cover up the two sides that touch the 39 degree angle.
What side is left?
25
Right. That's the opposite side from 39 degrees.
Now, let's find the adjacent side to 39 degrees.
Cover up the hypotenuse.
What other side touches 39 degrees?
25
No, 25 doesn't touch the 39 degree angle.
Yes, that's right.
I need to calculate h can someone help me? I dont understand how to do it
I checked the answer and it was h = 30-30sin(35) but I dont understand how and why
<@&286206848099549185> Hi 👋
Ahh
I think I get it
Yeah makes sense
Thanks alot 👍
Very simple when u made such a good drawing
Wher
I mean I understand what u did
hey
Np 👌
ok ._.
ill send a pic of the paper im doing rq
its with like circles and stuff but i dont really get how to do it and im terrable at math
I need to get this verified but from what I think I know all the corners on those quadrillaterals will add up to 360
Ah true
the quadrilateral is the shape in the circle right?
Yeah
ok
ive been trying to use this website called cheg but they dont explain it lmao they just kinda throw awnsers at me with no context
ok
yes
uhhhhh
theres alot of numbers there
ok
btw i have no clue on how to solve these, my teacher doesent rly "teach"
But if we would make a line from L to J the angles would be 180 but L wouldnt be 92 anymore but that might not matter at all
Or wait
Oh yeah nvm I understand I believe (I dont even need to know this but its interesting)
i dont understand what yall r saying ._.
Me neither
I'm rlly dumb when it comes to math
@alpine sable Read the article he sent it makes sense if u just read it for a bit
ok
can someone hop in vc and help me out? Just 8 questions and we both can work on it sinc eill also need to learn this material eitherway :c
<@&286206848099549185>
30 minutes before request <@&286206848099549185> if possible :3
please help
when is an implication always true
when the left is F
but I need to use axiom and all of this here
and I dont know how to prove it by using axioms
jan Niku
but idk if thats what youre being asked to do here
,tex $n^{3}-(n-y)\times n\times (n+y)=y^{2}\times n$
if I am use 2 axiom I must put the same x,y,z in both of them or it dosent metter?
Ranok Hui
i dont understand the question
you only have the statement x
so you should be okay to just use x
if youre applying an axiom that uses other letters thats fine as long as its applicable
I haven't learn arrows and that thingy in front of the first x
And also is this true?
I just kind of made that discovery on the calculator.
I mean if on the first axiom I put alpha = X can i put on the second alpha = \neg X?
second alpha?
you need to make alpha consistent
if you have a second alpha just use another letter
i mean you probably wanna use something like $P \to Q = \neg P \lor Q$ then $P = \neg Q$...
jan Niku
youll end up with something like $\neg P \lor P$ or whatever
jan Niku
idk if you have that as an identity?
Idk, and can anybody explain what the arrow and the thing that looks like 7 mean?
$\neg$
Ranok Hui
So $\neg x$ is not x
Ranok Hui
?
yea
How about arrows?
In logic, a set of symbols is commonly used to express logical representation. The following table lists many common symbols, together with their name, pronunciation, and the related field of mathematics. Additionally, the third column contains an informal definition, the fourth column gives a short example, the fifth and sixth give the Unicode ...

Thanks
theres a lot of symbols
idk if that person is still here
Ranok Hui
sort of yea
I still can't understand it.
It has another definition of if then
If not x then x?
Then if x then x?
you should check out the wiki article or something if youre curious
its primarily using definitions of a logical statement
or if you track down a book on proofs theyll usually cover logic before anything else
So does the example mean: if x = 2, then $x^2$ = 4?
Ranok Hui
@alpine sable Yes.
if x=2, then is x^2 necessarily 4
the aim of the example is to show that implications are not necessarily equivalent to their converse
"all dogs are mammals" doesnt mean that "all mammals are dogs"
Ok
that kind of thing
Chai T. Rex
the most fascinating thing is that A-> B doesnt mean B->A but it does mean NOT B -> NOT A
well at least its cool to me
i.e. implications are equivalent to their contrapositive
that allows you to do proof by proving the contrapositive
Because not A and not B just needs to be different from its original value, so just chose any value that is neither A nor B?
these things are a little more tightly defined than youre treating them
Oh
were not really picking a value for x
were dealing with the statement A: "x=2"
so x isnt equal to anything really
A is either true or false
So if A: x = 2, B: $x^2$ =4, then $A \to B$ is true, but $B \to A$ is false?
No.
Chai T. Rex
Ranok Hui
$A \to B$ doesn't disprove $B \to A$, it just doesn't prove it.
Chai T. Rex
So most of the time the converse is not true?
yea
No, that's not true.
well
yea most is a weird word
usually you dont assume the converse because its not true
You can't rely on the converse being true or false.
Yes?
jan Niku
jan Niku
idk its not important lol
assuming the converse is a really common mistake early on
you can trivially create examples where its true
tautological statements like if x is 2 then x is 2
if x is a multiple of 2 then x is even
stuff like that
@alpine sable The mistake you're making is in thinking that the truth or falsehood of A -> B tells you something about B -> A. It doesn't. They can be the same. They can be different.
So for example the example given by wikipedia, C is true, D is false so C -› D is false?
And sometimes the converse can be true?
And $\neg A \to \neg B$ is true because if A is false, B can't be true?
Ranok Hui
$\neg A \to \neg B \leftrightarrow B \to A$
jan Niku

@alpine sable for real if youre curious pick up a prepositional logic bok
you can find good ones for free
or khan academy
do the whole thing of building truth tables and looking at all this stuff
its less complicated than it probably seems at first
Also, a non-free option is Language, Proof and Logic, which is excellent. It comes with software to let you practice in a more intuitive manner.
$B \to A \leftrightarrow \neg A \to \neg B$
Ranok Hui
?
Is this still true
Because the left right arrow means iff, the converse is also true.
the implication being true implies its contrapositive is true
and the converse is true since the contrapositive being true implies the implication is true
<@&286206848099549185> could someone verify if this is true?

