help-0

[sudden finch]

But what is g’(a)?

[glossy current]

oops already make him write it
From that he can write the parallel then

[glossy current]

a is a valuable like x₀

[glass lichen]

Derivative of g at x=a

[sudden finch]

So g’(x) but substitute a instead?

[glass lichen]

Yes, same way you did f'(2)

[sudden finch]

Okayy thanks

[alpine sable]

can anyone help me how u are supposed to find this answer

[oak chasm]

@alpine sable First, write the formula.

[alpine sable]

it is not 2x-10x4=440

cause i did it and got 400

[tame hound]

hey can u help me again

i just need someone to help me on this

[ocean seal]

Chai T. Rex

[main crane]

i need help

[oak chasm]

Simplify that.

@main crane Sorry, channel busy.

[alpine sable]

how did u find that equation ty

whats y?

[main crane]

what channel do i use

[alpine sable]

representing

[ocean seal]

Chai T. Rex

[tame hound]

@main crane #help-3

or 2

[oak chasm]

First you double it, then you subtract 10, then you multiply it by 4.

@alpine sable See the steps?

[tame hound]

@oak chasm after ur done can u help me on this ?

[alpine sable]

yea

[tame hound]

or someone

[alpine sable]

Oh ok

[oak chasm]

@alpine sable OK, x is the first person's original number. y is the second person's original number.

[alpine sable]

u do distruptive property right @oak chasm

yea yea k ty

[oak chasm]

That will help simplify it, yes.

[woeful pulsar]

distributive property

[tame hound]

is anyone

ready for helping me?

cuz i rly need this

sry if i am acting mean or something

[oak chasm]

@tame hound Please see #❓how-to-get-help for rules on getting help.

[tame hound]

kk

[alpine sable]

I got 8x + 8 y = 520

[oak chasm]

OK, now factor the 8 out.

[alpine sable]

hm

but they have 2 different variables

[tame hound]

ok thx

[alpine sable]

so i have to divid y 8 twice

divide

[oak chasm]

Sure, but they both have a factor of 8.

[alpine sable]

by

so its x+y = 8.125

yea

what does that mean though

[oak chasm]

What's 520/8?

[alpine sable]

65

but u do it again

65/8

[oak chasm]

,calc 520/8

[ocean seal]

Result:

65

[oak chasm]

No, you don't do it again.

[alpine sable]

why?

[oak chasm]

You divided both sides by 8, right?

You do the same thing to both sides.

[alpine sable]

yea but u only divided the 8 from y

not x

OH

k

nvm

[ocean seal]

Chai T. Rex

[oak chasm]

So, x + y = 65.

And both x and y are integers greater than zero, right?

[alpine sable]

yea

but now u need to find

how much possibilities lol

[oak chasm]

So, 1 and 64 works, right?

And 2 and 63, right?

[alpine sable]

Wait what

h yea

yea

what transformation is represented by (x - n, y)

so we do 65/2

to find

[oak chasm]

$$x + y = 65$$
$$1 + 64 = 65$$
$$2 + 63 = 65$$

[alpine sable]

not even google is helping me

[ocean seal]

Chai T. Rex

[oak chasm]

@alpine sable Nope.

[alpine sable]

why

[oak chasm]

@alpine sable Sorry, channel is busy.

[alpine sable]

i'll wait

i thought ur finding one persons possibilites

not both

[oak chasm]

Right.

[alpine sable]

for asima

not y represent nile

while x represents asima

[oak chasm]

Right.

I know.

[alpine sable]

so its 64

?

[oak chasm]

Yes.

[alpine sable]

k

[oak chasm]

Because any number from 1 to 64 works for Asima.

[alpine sable]

OH

sheesh

[oak chasm]

0 is too low, 65 means that Nile can't pick a number greater than zero.

So, 1 to 64 are the choices, so 64 choices in total.

[alpine sable]

Yea ty

[oak chasm]

No problem.

[alpine sable]

can u asnwer just one more quick question or nah

[oak chasm]

Maybe.

Depends on the question.

[alpine sable]

if u cant do that one

[oak chasm]

I don't know what "the net" means.

[dim spear]

where do i get help

[alpine sable]

@oak chasm

[dim spear]

from the section related to my question or here in the question section

i have a calculus question

[oak chasm]

@dim spear Either one. For questions channels, see #❓how-to-get-help for rules.

[alpine sable]

just ask in any question -1-9

[dim spear]

okay

[oak chasm]

@alpine sable Not sure how to do that one.

[alpine sable]

lol fr

[dim spear]

thanks

[oak chasm]

Sorry, I'm getting too tired.

[alpine sable]

can sum one explain how

[woeful pulsar]

which term dominates in the polynomial?

[alpine sable]

the one w the highest exponent right

[woeful pulsar]

yeah

[mellow panther]

E) 16 answer

[woeful pulsar]

so how does it determine the end behaviour?

[woeful pulsar]

don't just give ansewrs

[mellow panther]

Oh what am I supposed to do I am new

I just solved in my head and answered

[woeful pulsar]

you need to engage the person who asked the question

[mellow panther]

K

[woeful pulsar]

figure out where they got stuck

[mellow panther]

@alpine sable

[woeful pulsar]

and make sure they understand how to do the bit where they got stuck

[alpine sable]

uh does it approach infinity

[woeful pulsar]

as x -> infinity what happens?

[mellow panther]

1/x approaches 0

[alpine sable]

i not sure cries

[woeful pulsar]

how does -9x^12 behave as x-> infinity?

[alpine sable]

it increases ??

it’s going up

[mellow panther]

Approaches - infinity

[woeful pulsar]

how about x -> -infinity

[mellow panther]

Yes

Cuz 12 is even

Still it would approach

[woeful pulsar]

alright then you know how to present now?

[mellow panther]

-infinity

Idk I am in 1 st year highschool never done this

[alpine sable]

as x approach’s infinity, f(x) approaches negative infinity and as x approach’s negative infinity f(x) negative infinity

[woeful pulsar]

yeah

[alpine sable]

but how do i show that on graph

[mellow panther]

Let f(x) = y

[green marsh]

is this space free

[mellow panther]

Idk

[green marsh]

my question is in 5

:c if you can help

[mellow panther]

Ask here

[green marsh]

oh ok

[mellow panther]

I am in tenth grade I don't know if I can help

[green marsh]

its this

[mellow panther]

I will try

[green marsh]

i keep getting it wrong

and idk why

the top is the work i done

[mellow panther]

Ok

Dude is way beyond my level

Can't help

Ask someone else

[green marsh]

.. yes

<@&286206848099549185>

[alpine sable]

this is the graph but where does it show that as the end behavior

[green marsh]

is this related to my problem

[alpine sable]

oh no im asking for help

sowi

[green marsh]

well ask somewhere else

[alpine sable]

cus someone was helpin

[green marsh]

because im asking first

[alpine sable]

oh-

[green marsh]

❤️

sorry

:c

<@&286206848099549185> !!!!!!!!!!!!!!!!!!!!!!

[woeful pulsar]

the graph goes down on both sides

[alpine sable]

the question says not to include a constant in your answer
just remove the "-1" at the end and it should go through

[green marsh]

i finally found out my answer it was -2x at the end

[alpine sable]

oh no wait nvm

[green marsh]

i put -2x

[alpine sable]

yeah that was what i was gonna say

cani help anyone

[errant dagger]

i did the integral

x / (sqrt(x) + 1)

but it was absolutely disgusting

what would you guys do for it

[alpine sable]

u=sqrt(x) should work

[errant dagger]

how?

[alpine sable]

gimmie a min ill send a pic of my work

[errant dagger]

thank you

[calm kiln]

Is the correct?

[alpine sable]

How did you do this one

[muted raft]

No that does not look correct at all

[alpine sable]

@errant dagger

[alpine sable]

It's correct if you want to know that

[muted raft]

wait is it?

OH it says nearest integer

[calm kiln]

y did u think it was wrong?

[muted raft]

,w \frac{24325489}{19683}

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by zslya#7821

[muted raft]

uh

[calm kiln]

wut

[minor heath]

sum of geometric series then try to solve the nearest integer

[muted raft]

How is it correct?

[calm kiln]

I got 740

isnt ratio 5/3?

[alpine sable]

It's a gp lol

[muted raft]

,w \frac{4853288}{6561}

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by zslya#7821

[muted raft]

Huh I guess so then

[alpine sable]

a (1-r^n)/1-r

Hm

[muted raft]

I subbed n=10, maybe thats why

[minor heath]

yep

[calm kiln]

yea so 740 right?

[minor heath]

considering that the first term is 3, and the number of terms is 10, solve using the formula

[calm kiln]

yea I did and got 740

[alpine sable]

Yup it's approximately 740

[calm kiln]

so I am not sure how it can be wrong

ok bet

[minor heath]

yea i checked it

[calm kiln]

Yep it was correct

ty guys

[green marsh]

hi

i keep getting this wrong

and idk why

ill show you wht i done

wht i have done

[muted raft]

where did the negative on the four go?

[green marsh]

wdym

its in the answer

[muted raft]

I guess you missed it on one spot but fixed it later looks like

anyway its supposed to be +2.6 not - I am pretty sure

[alpine sable]

I got positive 2.6 for the constant

[green marsh]

how

you guys are right but.. idk why

[muted raft]

because you keep forgetting the sign on 4 it looks like.

[alpine sable]

F(x)=-4x^(-2)+(7/5)x^(-5)+C

0=-4+(7/5)+C

[green marsh]

yeah

i still dont get it but ill just check my work more

ty guys

[muted raft]

If you look at the right side of your paper, you sometimes write 4x^(-2) instead of -4x^(-2)

that may not be the cause of your errors but it sure sounds like it would mess you up.

[mellow panther]

I think it would go up in one side and down in one side

Up in quadrant 2 and down in quadrant 4

[shrewd sable]

expand the rhs using a cos(2x) identity

[indigo jetty]

try this identity

[alpine sable]

Complete the square

[thorn kindle]

Lol, dont you know power to sum?

[errant dagger]

@alpine sable tysm

way way easier than my method

[alpine sable]

Would be lengthy

[thorn kindle]

Or rather power reduction

[lyric sierra]

Hiya, I'm trying to understand an alternate definition to the gamma function, can anyone explain how one would numerically intergrate it?
Here:

[thorn kindle]

The bottom should simplify to

n!/(x-1)!

Right?

[lyric sierra]

Wait, I need to process that x)

How so?

[thorn kindle]

5 times 4 times 3 = 5!/2!

[lyric sierra]

What?!?

I'm severely confused

[thorn kindle]

It works out mathematically doesnt it?

Try simplifying

So that means the product of all integers from a to b should be:

b!/(a-1)!

[lyric sierra]

OK, this may be where I'm confused, I cannot see where a and b should come from, for something like the upper function ^^^ it's simple b = infinity, a = 0

Where does a or b come from?

[thorn kindle]

Wait my bad. It should be (x+n)!/(x-1)!

a and b are just arbitrary numbers such that b>a

[lyric sierra]

OK? So the "red" function ?doesn't? have a or b?

Sorry if I really took a step backwards :/

Just to make sure lol

[thorn kindle]

You really should learn about this concept called abstraction.

If i tell you that all dogs love steak

And that i have a dog named Francis

What can you conclude about Francis

[lyric sierra]

Francis loves steak

?

[thorn kindle]

Now if I tell you that the product of all integers from a to b is b!/(a-1)!

And you know that the denominator of that red function is the product of numbers from x to x+n

[lyric sierra]

b is a representation of n and a is a representation of x

[thorn kindle]

Not quite

You should look at the euler product for defining the gamma function

[green marsh]

hi

is this free

im having trouble understanding what the question is asking .. bc its a work problem

is it saying

fine the antiderivative of the function

and them find the answer to f(2)

?

then

[lyric sierra]

I shall give it a look and come back to you

[green marsh]

<@&286206848099549185>

'-'

[grizzled gyro]

the goal is to find f(2)

[green marsh]

mhm

[grizzled gyro]

because you are only given the second derivative function, your strategy should be to integrate it until you get to the original funciton

[green marsh]

how will i know i got it

o.o

[grizzled gyro]

if you integrate the second derivative, you get the first derivative

if you integrate the first derivative, you get the original function

[green marsh]

wait so.. im not good with math vocab but i have prior questions that i done

im wondering if its the same process

[grizzled gyro]

ok

[green marsh]

is it basically like this

?

[grizzled gyro]

yes

[green marsh]

also

[grizzled gyro]

similar

[green marsh]

the second part i tried to do, i keep getting a wrong answer

i can show you my work

[grizzled gyro]

integrate, get the function, solve the indefinite integral to determine the "+ C" component, repeat

[green marsh]

but i tried different answers

This is for the problem that says syntax error

Why am I always getting the wrong answer

<@&286206848099549185>

im still here

8wers

im askinga question

[lyric sierra]

this is 20% = 1/5 = 0.2?

Have I missed context to this, this doesnt seem like enough

[green marsh]

D: whts going on

i wasnt done asking my question

the rules are if someone is asking a question, you have to go to another room

<@&286206848099549185>

[shell iron]

oof

[indigo jetty]

Did you find f(2)? You are putting f(x) in the answer

[green marsh]

i did

i got -16

.. well

for c i got -16

i dont understand..

is my work wrong

[indigo jetty]

Some mistake in your final computation

Can you show your f(x)?

[green marsh]

i did

im redoing the problem

@indigo jetty

sorry

[marble jasper]

Can somebody help me with 67?

[thorn kindle]

Write it as a parametric first

[marble jasper]

Wdym

[thorn kindle]

Do you know what a parametric function is?

[marble jasper]

No

[green marsh]

:c

i keep getting syntax error

[marble jasper]

@thorn kindle do u think u could show me how to do it

I'm kinda stuck

[thorn kindle]

Why are you doing polars without knowing parametrics

A polar is just a specific type of parametric function

[marble jasper]

Oh ok

Idk this just for school i guess they didn't show us

[thorn kindle]

Just google it lol

It should be enough to get the gist

A parametric is representing the x coordinate and y coordinate as a function of a parameter t

[alpine sable]

Is this being used?

Could anyone help

How do I find the rest ?

[wooden flare]

Is blank 2 1/4

Cause 5 = 20 * (1/4)^1

[alpine sable]

Oh okay thanks

So for the 3

Where do I put that ?

[wooden flare]

20*(1/4)^3

[alpine sable]

I put that in demos I get 0.3125

Is that right

I don’t get this last one

Sorry for disturbing but I made a poem

.

.

Home Alone

When I was home alone ,
When storm clouds rumble in the sky ,
My feet’s got numb ,
And my nerves freeze like an ice .

I couldn’t even amble ,
I heard some noise of ramble .
Someone was coming near my room ,
And my room was filled with gloom .

It was like hell , which hurts from inside ;
Trying to push these demons aside .
I needed something better ,
To not feel all this terror .

I weeped a lot ,
My father woke me up .
Oh it was a dream ;
And I was Afraid without meaning .

Nice

[alpine sable]

How do I find blank 2 and 3

Okay I got 2

It’s 0.5

<@&286206848099549185>

I need help on the 3 blank😥

[warm halo]

it was a long time since i'd last done one of these problems, but do you think this equation could be helpful?

or actually, this would be better as this problem seems to model something with a half life

if you have 66 of something and take half of that what do you get? if you take half of that result, what do you get?

[alpine sable]

oop

[warm halo]

npnp

[alpine sable]

you would get 16.5

https://cdn.discordapp.com/emojis/783590502099976212.png?v=1

[warm halo]

yee
that should be the amount of monster still in this hypothetical person's body

[alpine sable]

i just realized you were answering this guys question

i was wondering why you just randomly said that

you shuld have made a reply so they would know it was them

@alpine sable

[warm halo]

^^ ooh ty

[alpine sable]

he answered your question

sorry

im confused

[warm halo]

lol imagine someone came up to you in the street and started demanding that you solve some math problems?

[alpine sable]

i would try to answer it even though im dum

[warm halo]

but then you end up deriving something like a totally general formula for n-body orbital motion

[rugged lynx]

help

[warm halo]

the radius is half the diameter (the height) of a circle

[warm halo]

if you don't mind me asking, what are you confused by?

[gilded frigate]

5/2 = 2.5

[alpine sable]

Last question

[jagged hornet]

he asks how many left

[warm halo]

what is (1/2)^2?

[jagged hornet]

we have to use the equation,

[alpine sable]

can someone explain why a negative times a negative equls a positive i already understand multiplction and division with negatives its really easy but i dont know the exact reason a negative times negative is a positive can soeone please explain

[alpine sable]

2.5 cm i think?

cause the diameter is 5

[warm halo]

maybe you could think of negatives as someone saying something like "not"
so, you might not not be a human (and the two nots would cancel out?)
there's probably a better analogy for it 😅

[alpine sable]

could you screenshot the whole tab?

[warm halo]

https://www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-negative-numbers-multiply-and-divide/cc-7th-mult-div-negatives/v/why-a-negative-times-a-negative-makes-intuitive-sense
This might be helpful

[alpine sable]

thanks

[sick phoenix]

hi can i get help

[lavish jasper]

So, the hcf (Also called gcd elsewhere) will in general be the product of all primes contained in either number raised to the minimum of the number of times it occurs in either number’s prime factorization (called that prime’s multiplicity), while the lcm will be similar, but use the maximum instead

For example: for 120 and 126
120=2^3 x 3^1 x 5^1 x 7^0
126= 2^1 x 3^2 x 5^0 x 7^1

So hcf = 2^1 x 3^1 x 5^0 x 7^0 = 6
And lcm = 2^3 x 3^2 x 5^1 x 7^1 = 2520

Another thing to know is that hcf(x,y) times lcm(x,y) = x times y

Try using these facts to solve it

If you’re still stuck @ me and I’ll give more help

[oak wigeon]

Can someone help me out with no related math

Has nothing to do with school

[alpine sable]

just post

[green marsh]

hii

i

i dont understand this

i posted first it seems chuggles :/

<@&286206848099549185>

and tyty

[fading zephyr]

what is troubling you

[green marsh]

:/ this problem

i looked at problems on how to do it but idk wht they mean by xi

or C

stuff like that

ed edd and eddy

[fading zephyr]

to be honest you should go look back at your lecture slides/course content

[green marsh]

i did

[fading zephyr]

the notation is a bit arbitrary

[green marsh]

this is a online class

i can show you

the examples im using

[fading zephyr]

how did they define c and d in your course content?

[green marsh]

.. they never did that

this is the beginning of the lesson

the only c im familar with is c from anti derivatives

the examples i use say things like

n, a or b

https://www.youtube.com/watch?v=YTKQswb60Pw

like that

https://www.myopenmath.com/assessment/watchvid.php?url=http%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3DBvwyTXeuLS0

[shrewd sable]

well the letters are just arbitrary anyway? they just have d instead of n

[green marsh]

ohh

well i dont know that

[shrewd sable]

and similarly for c

[green marsh]

so d is n?

what is c supposed to represent

or xi

[shrewd sable]

where the sum starts

[green marsh]

do you know where i can learn this from

that give specific examples of this

does that mean x is 5

and d is 13

bc its 5 to 13

meaning it starts at 5

[shrewd sable]

no, the x_i values range from 5 to 13

[green marsh]

yes

so when you mean start... do you mean the first "increment"

[shrewd sable]

Yeah

[green marsh]

like x1

[shrewd sable]

so like i = 1 starts at x_1

[green marsh]

so xi is where it starts

?

this is to give you context

[shrewd sable]

ok so theres 17 rectangles

you need an x_i for each rectangle

[green marsh]

mhm

[shrewd sable]

what is your range of i values then

[green marsh]

the rand i 5 to 13

so 9? i think

[shrewd sable]

no

not quite

your first x_i is 5, and your last one is 13 yes

but you need 17 total x_i, one for each rectangle

so what does i range from then, not x_i

[green marsh]

so d is 17 then

[shrewd sable]

yes

[green marsh]

so for the E symbol

theres a top number

and a bottom

the top number

is d

which is 17

?

im trying to visualize it

[shrewd sable]

yes, because i goes from 1 to 17

[green marsh]

so the bottom number then is 5

[shrewd sable]

i goes from c to d

no

[green marsh]

bc it starts at 5

oh

[shrewd sable]

because then you'd only have 12 different i values

[green marsh]

ok i see

.. i think

the bottom number is where it starts

why wouldnt it be 5 though

when it says 5 to 13

[shrewd sable]

because thats what the x values range from

the i just counts the number of x values

[green marsh]

im still confused on the c part

[shrewd sable]

you have 17 rectangles, and each rectangle has an x_i

right?

[green marsh]

yes

[shrewd sable]

so you need a different i for each x_i, right?

[green marsh]

i think so

[shrewd sable]

so how many i do you need

[green marsh]

to get to 17?

you need 17 i's

[shrewd sable]

yes

so if c is the first i

and d is the last i

[green marsh]

mhm

[shrewd sable]

what are c and d

[green marsh]

ik d is 17

[shrewd sable]

yes

[green marsh]

but i dont understand

c

[shrewd sable]

if c = 5, then i only goes from 5 to 17

thats not 17 i's

[green marsh]

but its saying its 5 to 13

[shrewd sable]

x is 5 to 13, not i

[green marsh]

oh

[shrewd sable]

if you want to count from 1 to 17, you have to start at 1 and end at 17

[green marsh]

yes

[shrewd sable]

so then c is 1 and d is 17

[green marsh]

so wht do i do about the xi

is that me plugging in 1 for the function

up to 17

and adding it up

?

[shrewd sable]

no

[green marsh]

oh

[shrewd sable]

x_1 doesn't mean 1, it means the first x value

[green marsh]

how do i do it

[shrewd sable]

so x goes from 5 to 13, so whats x_1 and whats x_17

[green marsh]

um

5 and 13

?

[shrewd sable]

yep

[green marsh]

ohhh

[shrewd sable]

and then the other x_i like x_2, x_5, x_7 or whatever are all values in between 5 and 13

[green marsh]

wait but

[shrewd sable]

separated by delta x

so x_2 = x_1 + delta x, and so on

[green marsh]

i didnt do it yet but dont you plug in

5

for the function

[shrewd sable]

it didn't ask for x_1 and x_17, it asked for x_i and f(x_i)

[green marsh]

i dont understand wht that means

xi is that starting point

and fxi

is the ending point

?

[shrewd sable]

no, x_i is just the generic expression for one of your x_i terms, and f(x_i) is the function f(x) at x = x_i

[green marsh]

can you say that im simpler terms

that apply to numbers or like.. the equation

bc im a visual learner

[shrewd sable]

you have many different x_i, eg x_1, x_2, ..., x_17

you only put in x_1

[green marsh]

wdym

meaning the value one

?

in the function

?

what is x_1

[shrewd sable]

5 + delta x

[green marsh]

mhm

which is 5 + 8/17

[shrewd sable]

yes

[green marsh]

but how is that xi

[shrewd sable]

its not, its x_1

[green marsh]

.. then what is xi trying to do

is xi just plugging in the numbers

adding them all together

to get the answer

like i said

?

[shrewd sable]

x_i represents any of the x_i values from x_1 to x_17

[green marsh]

can you write that in equation form

[shrewd sable]

no

[green marsh]

? or is that an explanation

oh

[shrewd sable]

thats an explanation

[green marsh]

.. so

i dont understand the xi still

we got to 5 + 8/17

but im not sure what am i supposed to do

'-'

@shrewd sable hi

<@&286206848099549185>

someone

ik its morning in some timezone

<@&286206848099549185> :c

[normal burrow]

hello I need help with algebraic functions

if someone can teach me how to do the first limit then id be glad

Ive been out for 3 months and im trying to follow up with the lessons and activities

but my book only has the activities, no lessons

[green marsh]

no

i need help please

:C im srry but my assignment is due in 4 hours

ive been asking prior

[digital vine]

is this like an urgent emergency

[green marsh]

yes

[digital vine]

mk

[green marsh]

bc i cant finish the other problems unless i know how to fix my issue

i hve 4 more problems left

[digital vine]

rip

my phone boutta die

[green marsh]

let it die

i got a future to revive

[digital vine]

ok

[green marsh]

xD dont

im kidding

[digital vine]

kk

[green marsh]

:c ill get any help i can

[digital vine]

can I see

[green marsh]

yes ma'am

[digital vine]

I wanna see if I can try it

[green marsh]

i posted it earlier but

yeah

my helper ghosted me

[digital vine]

nope I can't help you sorry I'm so dumb I apologize for this

[green marsh]

T_T

[digital vine]

I am deeply sorry

for wasting your time

[green marsh]

you must have smart friends

nonono, its okay, you might know someone

lll give them a free gift card

[digital vine]

ok thank you

[green marsh]

yw

<@&286206848099549185> !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

;D

[jade coral]

ok, I have to be doing this wrong.

[green marsh]

ty bom

[jade coral]

I am trying to figure out the following problem
How many different words can you form from the letters in the word “senselessness”?

[ornate raptor]

Can someone help me with these questions please

[green marsh]

... pelase go home boom

NO

Where is the respect

and authority

[jade coral]

you said thanks

[green marsh]

I was here first

[jade coral]

were you not done?

[green marsh]

no

no one is helping me

[jade coral]

well fuck sorry then

[green marsh]

ive been asking for 20 minutes

its ok dear

[green marsh]

NO

[ornate raptor]

Yes

I need help

[green marsh]

post it in the other chat

[ornate raptor]

No

[green marsh]

or im calling the mods

yes

[ornate raptor]

No

[green marsh]

its against the rules

@fierce herald

[ornate raptor]

It is?

[green marsh]

yes

[jade coral]

@ornate raptor hes being a prick about it but do go to another chat

if he was here first then its fine

[green marsh]

im not being a prick

[ornate raptor]

Ok

[jade coral]

yeah you kinda are

[green marsh]

ive been here for so long asking for help

[jade coral]

im done discussing, going to another one now

goodbye

[green marsh]

and when someone is asking for help you go to another chat

[acoustic shadow]

How many times have you pinged helpers in the last 10 hours

[green marsh]

idk maybe more than like.. 6 times

bc ive been waiting but its on and off

my helper was helping me but he left unfortunately

[green marsh]

@alpine sable you may take this spot sorry

[alpine sable]

no it's fine i got my problem solved already

[azure cove]

probability of union of two events

i dont get it

[vale wigeon]

what even is this problem

can you show the whole thing and not just the third part

[graceful lance]

How did we get that a in RHS

[agile compass]

the negatives cancel, the (a^2 + b^2)'s cancel and the b's cancel

[graceful lance]

??

oh wait

oh ok

ohk

Thank You

[left radish]

why me

wtf

[ornate tusk]

you pong a lot peter

[digital orbit]

Anyone here who codes in flutter

?

[untold lynx]

can u guys please do part c of this question

,rotate

[untold lynx]

part c

[vale wigeon]

we won't do things for you

[alpine sable]

Ann

Please can you help explain my question

[vale wigeon]

i don't feel like it rn

[inland jacinth]

Can someone help me with part c?

[inland jacinth]

<@&286206848099549185>

[manic quail]

Have you tried anything yet?

[graceful lance]

nope

[manic quail]

You probably should before asking

[graceful lance]

I don't know how to do it

[limpid spade]

you know how to do inverse?

[inland jacinth]

Find the determinant, det = ad - bc

[manic quail]

Okay, I am really not that good with typing matixes, but the usual way to finding the inverse is writing the matrix once again next to it, and trying to convert the first one to a diagonal matrix.

[strong furnace]

If your algorithm has determinant in it they want you to find the cofactor matrix first

I mean these are just instructions that you have to follow at least give it a try compare [ a b , c d] to your given Matrix

[graceful lance]

and 2 ?

[limpid spade]

system of equations but since it's about matrices u need to do with matrices

[graceful lance]

and how in that way

[limpid spade]

don't u have a course where u learnt it?

[strong furnace]

Multiplication of matrix is equivalent to dot product of row and column vectors respectively

[limpid spade]

it's occupied

[manic quail]

$A\cdot \begin{pmatrix} x \ y \end{pmatrix}=\begin{pmatrix} -5 \ 20 \end{pmatrix}$

[ocean seal]

𝔙eryhappyperson

[manic quail]

$\Longrightarrow A^{-1}\cdot \begin{pmatrix} -5 \ 20 \end{pmatrix}=\begin{pmatrix} x \ y \end{pmatrix}$

[ocean seal]

𝔙eryhappyperson

[limpid spade]

huh that's a weird way to solve

[manic quail]

That's how you solve it with matrices though.

[strong furnace]

That is the expected way I guess

[limpid spade]

I remember something else

like matrice 1 -5 -5
-4 -2 20

something like this

....

it's still occupied

can't u find an unoccupied channel?

#help-6

[upbeat gorge]

There’s 10 channels so if one is occupied, you have 9 more to go to

[limpid spade]

and now he's cross posting

imagine not reading the rules

remove your posts and post in one channel, an unoccupied one

[strong furnace]

Bruh just post it somewhere that is not busy don't be toxic

[red spear]

@karmic spoke stop being a cunt

[ionic sedge]

might someone take a look in #help-3

[limpid spade]

<@&268886789983436800>

lol

[fading zephyr]

wasup

[limpid spade]

hi

[upbeat gorge]

Stuff happened that we must forget

[fading zephyr]

was it already taken care of?

[strong furnace]

Did he leave the server?

[night geyser]

i banned

[fading zephyr]

awesome

[inland jacinth]

Can someone help me with part c?

[bronze dust]

someone explain this relation to me pls

[limpid spade]

niiy seems u were a bit too late

fluo was first

[bronze dust]

right

ill wait

[limpid spade]

u can go to an unoccupied channel

[bronze dust]

okay

[limpid spade]

,w (2.96)/0.47

,w 2.96*6.30

,w 1/(13.07-8.23)

[acoustic shadow]

Subtract sin^2 from both sides. Cos is a decreasing function is ([0,pi/2]

[bronze dust]

a + b + c = pi

a + b = pi - c

apply tan both sides and then use tan(a + b) identity

@chilly garden

[ripe ginkgo]

Anyone got a formula for the surface area of a hyperbolic paraboloid?

[real sinew]

You could possibly use integration to find it

[ripe ginkgo]

would have to be some kind of vector integral right?

this is the definition of the surface

[real sinew]

I would think you'd have to do a double integral with respect to u and v

On that bottom equation

It shouldn't be too difficult, just maybe a little time consuming

[chilly garden]

ty!

[ripe ginkgo]

seems like this is the integral i need

[real sinew]

Tbh I'm rusty with vector integrals

But I see nothing wrong with that

As long as you use the proper integral it should return the surface area though

[sage dune]

can someone help me solve this question?

[raven mist]

i am keep getting same figures of reduced cost , objective coefficient and allowable decrease

and i don't know the reason why

[chilly garden]

could you show me please!

i still didnt get it

[bronze dust]

ok 1 sec

[chilly garden]

nvm

i got it

sorry xD

[bronze dust]

okay

[chilly garden]

part b please

[quasi scarab]

make the left side a function only of sin

i mean write the cos in form of sin

[inland jacinth]

how do I start part a?

[indigo jetty]

form a new random variable based on what a) is asking for

[raven mist]

anyone who knows about linear programming??

[pallid hill]

Can someone explain how you do this

[real sinew]

Cubed root is another way of saying 1/3 power

So you multiply the powers together

[real sinew]

1/3 * x

[wanton canopy]

Anyone know this?

It’s probability

[pallid sparrow]

work it backwards, all probabilities add up to 1 or 100 in this case

[wanton canopy]

🤔

[polar whale]

Well I think the probability will just be the ratios

[silent widget]

ve = vg * ln(ma/me) /// i need ve and vg = 3000m/s & ma to me is a 10:1 ratio /// how can i solve this without a given base for my log?

[polar whale]

For P(X+Y) it should be (X+Y)/total length

[pallid sparrow]

natural log has base e

[polar whale]

For P(X)' it should be 1- P(X)

[pallid sparrow]

log with base x is different from ln which is the natural log

[silent widget]

ohhhhh isee

omg thanks

[rapid horizon]

can someone please help?

[ruby gorge]

2

[rain yacht]

need help please, i have to pass this test

[rain yacht]

2

[ruby gorge]

what to do?

[subtle bay]

@rain yacht 2(t-4) over 3 = 8, well first times both sides by three getting 2(t-4)=8*3

[alpine sable]

hii can someone help me with this please

[ruby gorge]

oppo. angles supplementary in cyclic quad.

[subtle bay]

then t-4=24/2

[rapid horizon]

would it still be 2?

[subtle bay]

then t=12+4

[alpine sable]

i dont understand what does it mean by model the difference

[subtle bay]

then t+16

= *

[ruby gorge]

generalize maybe

[alpine sable]

also for this one how do i find the period and length

[rain yacht]

ur a g, appreciate you fam

[subtle bay]

np

just work through it as a process, what you do to one side you do to another

[polar whale]

This has a non terminating recurring decimal expansion so it will be a rational no.

[rain yacht]

thanks again bro🖤

[alpine sable]

okay thanks so much

[mild oxide]

I need help

[granite gust]

indeed

[waxen harbor]

hi, basic question. If i have a force going into the origin from the second quadrant. Is its y component negative or is its x component negative?

[granite gust]

x component is negative

[glass lichen]

x is neg, y is pos

[mild oxide]

I jus came back to this school and my teacher tryna fail me if u don't get this done

[waxen harbor]

but in a different situation if the force is going out of the origin into the 2nd quadrant the x would still be negative and the y positive?

[granite gust]

yes the entire second quadrant has the x component negative and y component positive

[waxen harbor]

ok thank you so much @granite gust

[granite gust]

np

[alpine sable]

You know asking for help on tests is cheating and not allowed here right?

[crisp breach]

Which rules am i using for this?

[rain yacht]

my fault my fault

[subtle bay]

@alpine sable ...but like im guessing he is studying, no one just has the test questions, then it wouldnt be a test

[rain yacht]

correct

[glass lichen]

product, or you can use an identity to simplify first

@crisp breach

[crisp breach]

Okay thank you

[alpine sable]

Oh ok, thats fine then

[glass lichen]

$y=\frac{1}{4}\sin^2(2(x-1))$

[ocean seal]

Mosh

[alpine sable]

Sorry for the misunderstanding

[subtle bay]

ah all goods, i just realised some people must be doing online learning so i understand where ur coming from

[crisp breach]

@glass lichen My question only has two functions right?

[verbal stag]

I got this question wrong after I chose C, I know A is the correct answer but how do I get to that conclusion/how is A the correct answer choice?

[silent widget]

1 cycle is exactly 1 pi long

[verbal stag]

Okay, what about the amplitude?

I know it says it’s supposed to be 1 but the max is 2…

[silent widget]

true i didnt check the amp

it should be 2 if im not missing anyhthing

[verbal stag]

Yeah it should be but the question says 1

Idk if it’s a typo either because all of the graphs have an amplitude over 1

[silent widget]

amplitude is the highest point so it has to be a typo

i would just consult your teacher about this one

[verbal stag]

Okay, thank you for your help though!

[alpine sable]

That's not right, amplitude is the vertical distance from the midline to the highest point

[silent widget]

badly worded indeed but the fact that its a typo still stands right?

[alpine sable]

Its not a typo,A has an amplitude of 1

[silent widget]

can you elaborate?

OHH

i see it

ofc

1 and -1 right?

[alpine sable]

Distance cant be negative

The amplitude is 1

[silent widget]

ok thanks for clearing that up!

@verbal stag

[covert wind]

Can someone show me how i would make the tree diagram

[verbal stag]

Can you explain, I’m a bit confused

[silent widget]

wouldnt that be something like this?

just with every option

[covert wind]

Thats what i thought at first

But im not sure

[glass lichen]

yes that's a tree diagram

[covert wind]

Thats how you would do it?

[glass lichen]

draw the branches and label them

[covert wind]

Ok

[tough prism]

i got a probibility homework for geomtry can yall help me out? anyone?

[sage summit]

why would you not try some values for m,n ??

if you look at any one, it automatically removes 2 options so idk why anyone wouldn't like that

it removes 2 options from a) b) c)

then you are left with determining if it's d) or not

[oak chasm]

Well, what is the sign if m = n? What is the sign if m < n? What is the sign if m > n?

That should narrow it down a bit.

[sage summit]

you can try to write it as a sum of things that are obviously >=0, including one that is obviously > 0

such as squares

[oak chasm]

What other option is there for comparison of m and n?

Two naturals are m < n, m = n, or m > n.

There are no other options, so that's exhaustive.

I never said that was true.

[ocean seal]

Chai T. Rex

Chai T. Rex

[oak chasm]

We've narrowed it down a bit.

What if m > n?

[ocean seal]

Chai T. Rex

[oak chasm]

So we can ignore m > n.

[bleak stag]

hello guys

can someone help me with 2 math questions

[compact orchid]

Can someone tell me if I did 6.b correctly?

[bleak stag]

<@&286206848099549185>

[alpine sable]

How do you work out the hcf of 6x and 8x(squared) ? For the 6 and 8 I got a hcf of 2 but not sure what to do with the x and x(squared)

[gloomy lintel]

For 6, the first term is 3 by rationalising the denom, then 3 plus root 3 then three plus 2 root 3, so we’re adding root 3 each time

So next term is gonna be 3 + root 3

General formula is 3 + (n-1)root3

[gloomy lintel]

They both share an x term right, so so it’s gonna be 2x

[bright gust]

I need help with geometry

[tough prism]

anyone know this?

@ me if yall know please

[minor heath]

$P(Spanish\cap Math)= \frac{\text{people that like Spanish and Math}}{\text{sum of all the data}}$

[alpine sable]

Number of people in both Spanish and math part of circle

[ocean seal]

G3oG0dly

[tough prism]

just the ones in the circle ?

ir in the middles too

[minor heath]

spanish and math

just include the intersection between the spanish circle and the math circle

[kindred fable]

@minor heath hey can u help me rq

[tough prism]

alr i got 0.62 thx

[minor heath]

thats wrong tho-

[tough prism]

it is?

[minor heath]

just the intersection

only the intersection

so only 5 and 15 in the universal set only count

[tough prism]

0.08?

[minor heath]

yep

[tough prism]

u have to divide it the total too right?