#help-0
1 messages · Page 596 of 1
you have to have a fancy calculator
desmos work?
how would i plug it in?
wdym plug in
we know from sohcahtoa, that tan=opposite/adjacent
adjacent is the distance from the base of the building to the observer
and the opposite is its height
-55.6/150?
or 1.46/-150
no
nvm ill keep listening to your explanation
height is the opposite so we'll name it o
o/150=tan=1.46
o/150=1.46
multiply both sides by 150
you'll get o=219
which is your answet
answer*
219 feet?
yeah
np
i really needed the help
bruh wtf the sun is rising
thanks for your help
someone just asked before you
the other channels are occupied
also he just got help so I can go real quick
what
.
k
@worthy verge Bye
I got ghost pinged
will be telling
is the angle in the top left a right angle?
ugh
can't sleep
just use sqrts
sides of a 45/45/90 and a 30/60/90 triangle
the side shared between both triangles will be 12sqrt(2)
because in a 45/45/90 triangle, the sides are a/a/a*sqrt(2)
the sides are ordered the same as their opposing angles
now the sides in a 30/60/90 are in the following proportions
or relations
idk
a*0.5/a*0.5sqrt(2)/a
what
ah
i see
why tho
yes
but x=a*sqrt(3)/2
and a=12sqrt(2)
so we end up with x=6sqrt(6)
we don't care about the 1:2 sides, we care about the 1:0.865 sides
im not sure about d-f
i think it would be undefined for d
but i dont know what e is
yeah
no
isnt that what im suppose to find out?
zslya
would it just be 1?
for what
for the question
why would it be 1?
Anyone here able to do this?
channel is busy
What is going to happen as I keep moving left on your function f(x)?
Is it -x or -inf?
where is -infinity in the x-axis?
What
Can you post a new picture but a bit zoomed in?
I highly doubt we have lim x->-x here 
ikr what could this even mean?x approaching x from the left?
thats what it says
Show the damn picture clearly then
x(3) y(7) -5 = 3x + 7y -5 =
ik my discord is loading on phone
thats not x
3x and 7y -5?
idk what it means
That still says $\lim_{x \to -\infty} f(x)$
zslya
so it would be infnite then?
going to assume not occupied anymore because of inactivity
find the spring constant
Both have same areas, the formula for area is 1/2 ab sinC
Time period is 2pi sqrt ( m/k)
ur time period is 14/14=1, u know the mass too
Nah this 1/2 ab sin C is an alternate formula
u use this when u have 2 sides and the angle between them
what do i do after that?
Plug in the formula
what formula
This one
can some1 explain to me why my solution is wrong? (i have the answer which did it differently)
thatt was my approach to it
Chai T. Rex
oh wait nvm i think i got it
i dont understand whats it asking me to find
the sine of the angle would that just be like
Sin30? or the solution of sin30
It doesn't need to say, you can figure it out with the Pythagorean theorem and the area formula.
We dont know if its a right triangle though
Whether it's a right triangle, I mean.
What's the range of sine?
Chai T. Rex
Chai T. Rex
alr now how about 5b
What's an included angle?
i know what it is but i dont know what it means when it says "find the two possible measures of the included angle."
So, there are two angles with that sine.
so, sin30 and sin150?
Yes.
Chai T. Rex
No problem.
(6a)^2 how do I write that without exponents wouldn’t it be 6•6
multiply 6a by 6a
Chai T. Rex
^ this also works
Ok thx
No problem.
@alpine sable Which part?
Start by finding all their ages in one timeline
Yeah
Yes, the first Christmas, I think that's correct.
Alright
But part a is about the second Christmas.
You need to find how much time has passed between the first and the second Christmas
U add x to all their ages and equate the mother's and Emma's ages
Timeless facts:
Emma = Lara + 3
Dad = Lara + 30
Mom = Lara + 25
During the second Christmas
What is x tho
.
3 Emma = Mom
3 (Lara + 3) = Lara + 25
2 Lara = 16
Lara = 8
Jason = Lara + 4
So, for any year at Christmas:
Emma = Lara + 3
Jason = Lara + 4
Mom = Lara + 25
Dad = Lara + 30
What's x?
The time elapsed between the first and the second Christmas
Oh
When you find x, you just add it to Emma's age from the first Christmas, and you get her age for the second Christmas
So, 3(Emma+x)=(mother+x)
?
x isn't 4.
Ahh
@alpine sable Stuck?
Yeah
OK, let's do this.
I'm sorry im dumb
Person = Lara + years
gm
@alpine sable Get everyone in the family as an equation Person = Lara + n
Do you see how this equation works for any year?
Like if Jim = Lara + 10 You can see that it works for any year. Year 50? Add 10 to Lara's age.
Still works.
Does that make sense?
@alpine sable Still there?
Oh, OK.
You want each person to be Lara's age plus a number of years. Get all those equations.
So, Lara starts out as three, right?
Yes
Her father is 11 times as old, right?
How old is her father?
1/11 th?
No, Dad isn't 1/11th of a year older than Lara.
Od dada age to Lara?
How many years older is Dad than Lara?
OK, so your first equation is done! Dad = Lara + 30
What about Emma? How old is Emma when Lara is three?
How many years older than Lara is Emma?
Oops didn't mean to type y
@alpine sable How many years older than Lara is Emma?
3
OK, so our first two equations are done!```
Emma = Lara + 3
Dad = Lara + 30
See how we're making progress?
Everything you doing now is for the first Christmas
Now, what does the second part tell us about Dad and Mom?
How many years older than Mom is Dad?
OK, so if Dad is 30 years older than Lara, how many years older than Lara is Mom?
25
Good!```
Emma = Lara + 3
Mom = Lara + 25
Dad = Lara + 30
Now, for the second Christmas, Emma is 1/3 of her mother's age, right?
Yes
3 Emma = Mom
3 (Lara + 3) = Lara + 25
See how we write the first equation and then fill it in with their ages in terms of Lara?
Now it's a one variable equation.
Solve for how old Lara is the second Christmas.
But why aren't you accounting for the time elapsed?
@alpine sable What do you get?
@bleak ibex Because we're trying to get everyone in the family's age in terms of years older than Lara right now.
Ahh, got it
OK
Well, it's 3 times Emma's age is Mom's age, right?
Right, so ```
Emma = 1/3 Mom
3 Emma = Mom
3 (Lara + 3) = Lara + 25
Do you see how I got that?
Yes
OK, solve the last one for Lara's age.
Yes, Mom is 25 years older than Lara
Yes
So, how old is Lara this second Christmas?
Idk the time in years though
Yes, solve the equation to get that.
Is Lara = to Lara as in 3 years old
No, that's the first Christmas.
Do you know how to solve 3 (Lara + 3) = Lara + 25?
Like as in expand?
What?
Rn, Lara is a variable
Yes
Don't skip ahead, please.
That's what I meant
Good.
Correct
So, how old is Jason that second Christmas?
12
12
How much older is Jason than Lara?
4
Emma = Lara + 3
Jason = Lara + 4
Mom = Lara + 25
Dad = Lara + 30
Now we have all five family members in terms of Lara.
So write that down (you should have wrote down the work you did, too)
Is it written down?
Yes
OK, now the parts will be much easier.
Let's do part a.
In part a,
Jason = 12
Replace Jason with Lara + 4.
Find out how old Lara is.
How old is Lara?
Jason is 4 years older than laura?
Yes, look at the equations I had you write down.
Oohhh ok
So, what do you get?
Emma
Right. What's Emma according to our equation table?
Right.
So, that's the answer to part A.
Now, part B.
Write an equation for part B:
Mom = Lara + Emma + Jason
Do you see how that's the right equation for part B?
Ahh yes
OK, replace everyone with their formula from the equation table.
What do you get for the equation?
Don't skip ahead to the answer.
Just tell me what the equation is with everything replaced by stuff in the table we wrote.
Im walking rn so I'll have to do in my head
OK.
Instead on paper
Do it on the keyboard 🙂
You don't know what age they are.
Like from emma
Use the equation table we made.
OHH ok
This is a new Christmas.
25?
No, Lara + 25.
?
Look at the equation table.
The one you just posted
What exactly is written for Mom?
Right.
Mom = Lara + Emma + Jason
Lara + 25 = Lara + Emma + Jason
What is Emma on the table?
Lara + 25
No, Emma.
Yep!```
Mom = Lara + Emma + Jason
Lara + 25 = Lara + Lara + 3 + Lara + 4
So, see how our second equation has only Lara and numbers?
Yes
OK, so it's a one-variable equation.
What is the mysterious Lara tho
Solve for Lara's age on this new Christmas.
Lara is the variable for Lara's age.
Ok
Does that make sense?
Yep
OK, so solve for Lara.
Solve for Lara from this one
?
Yes.
Read the problem.
Wait are we on the 1st question?
Part B.
Oh ok
So whose age are we looking for?
Mum
And what is Mom on the equation table?
+25
And how old is Lara?
8?
No, we took a while to figure it out, and it wasn't 8.
9
Right.
So,
Mom = Lara + 25 = 9 + 25
See how I replaced Mom with the equation table entry?
Then I replaced Lara with Lara's age?
No, first, we write what we're looking for, then we replace anyone who's not Lara with the equation table entry, then we replace Lara with Lara's age.
Does that process make sense?
So replace
That
Sorry?
How?
Well, maybe.
Yes, you can do that, but that doesn't answer whether you understand the process.
No.
Damn
Let's start part B over.
What's the equation with variables in it for the statement part B makes?
For mom=?
How old was the mother when her age was the sum of 3 children
OK, what information does it want?
3 children's ages?
No.
Mothers age
Sorry?
That her age is the sum of 3 children's ages
Do you see "is" in your statement?
Yes.
So that's how you get the equation.
Ues
Now see all the variables that aren't Lara?
What do you mean?
Do you see the variables in your equation?
Look at your equation.
Forget I said that
Go through the variables one by one.
Idek
Sorry?
Like numbers
What?
Idek= I don't even know
Yes, I know.
Oh
I don't know why you said that.
Idek the variables is what I meant
Look at your equation. How many variables are in it?
Huh?
Look at each variable, starting from the left.
Yes.
Mom
Emma
Jason
OK, now replace all the ones that aren't Lara with the equation table entry.
Mom= emma+jason?
Mom = Lara + Emma + Jason???
You don't know how to look at a list of things and figure out which ones aren't Lara?
Like if there are four people in a row, you can't figure out which ones aren't Lara?
Then what's the problem?
Right.
That went lara
But you also said you didn't know how.
We have gone through this tho
So I keep getting confused
Ok
So why are we substituting Lara out?
We want to get the equation to have only one variable.
Ok
We do that by replacing everything that's not Lara with its entry on the equation table you wrote down a long time ago.
Leave Lara alone.
Replace the other three with their equation table entries.
Oh ok
No, hold on.
No
What does replace mean?
please use a different channel
@alpine sable No.
Damn
What did I say to replace?
Lara
No.
Yes. With what?
Right.
Ok
So, replace everything that's not Lara with their entries in the equation table.
Emma=lara+3
Right.
Jason=lara+4
Emma + 3
Sorry?
OK, what's your equation for part B?
Right for what?
Chai T. Rex
No I don't think I did
Oh.
Sorry
OK, if you have something equal to something else, you can replace something with that something else.
Ok
Chai T. Rex
See how I replaced a with 3b?
Chai T. Rex
Yes, that's fine.
Well, we'll have to talk about how you can replace something with what it's equal to.
yooo its dream
@marble otter What's the formula for interior angles of a convex or regular polygon?
(n-2)x180
That's the sum of the angles, yes.
So, there are six angles. What's their sum and then what's one of them?
the sum is 720
720/6=120
Chai T. Rex
@alpine sable Sorry, channel is busy.
@alpine sable Sorry, see the timestamps on the last chat and whether the chat is done.
If it's been long enough of they finished in a channel, you're good there.
Chai T. Rex
180?
oof
isoselece
That's a triangle.
hmm try inscribing it in a circle
@marble otter I mean the angle, not the triangle.
oh 120
what do u mean?
Which angle is it?
Right angle?
Meant for dream
Right.
Yeah
Yes.
Okay
thanks
No problem.
How do I find the y intercept of a logarithmic function?
Wow, that means I did this in a longer method
What's the logarithmic function?
🙂
Question 10
what relations have you found?
@fiery bronze Sorry, channel is busy.
i they have given two forces values and i need angle xp1A
i m no clue wht to do, like i m just balnk
@ashen schooner OK, so see point X?
what happens when you resolve the forces about x?
Write one force on the northwest line, one force on the south line, and one force on the northeast line.
if someone can then please solve it and upload pic of working. i have been trying this ques from so long but have no idea how to solve it
@ashen schooner We can help you, but we can't do it for you.
can you just explain me how to find the angle
Sure.
First do this.
force Ta in direction north west and force Tc in direction north easr
maybe send a picture of your working
Yes, I realize that those are the forces.
I mean to write numbers for them instead of just telling us how pulleys work.
there's a third force too
wht is the third force
you only drew two of the 3 forces acting on X
obviously X isn't accelerating upwards, so what's going on?
dynamics 👎
??
@ashen schooner Yes, and write numbers or variables for the other two as well.
the other two value are unknown
A is acting downwards5.5 and
No, write the numbers next to X.
i dont understand ?
Do you see point X?
yes
Do you see the line leading up and to the left from X?
Do you see a portion of that line right next to X where you can write a number?
Yes, that's right.
huh i wonder how u find AP₁X
Well, we find angle B X P_1
this
here i dont get how cm line XP1 is 5.5 in the ques they said A is 5.5 And A will act downwards
They don't even understand not to add wires.
yes but shldnt A =Ta cos x
I don't think they're to conservation.
like shouldnt A (5.5) be a component of Tension A
Where did the extra wire come from?
yeah your 7.3 N wire across the top there is odd
so here A = Ta cos x
one part goes down one part goes up
No.
then
The force going down on the left side of pulley 1 is going up and to the left on the right side of pulley 1.
So, do you see point X?
i dont get it at all..i give up
thanks though for the help
You have AE and ED how do you find AD?
we dont have ED right? isnt 24 FD ?
By Pythagorean theorem AD=25
Then BC=25
Then again by Pythagoras theorem FC = 20
Then drop perpendicular to point F to BC
Then calculate the length of the perpendicular
By triangle similarity you can say that the ratio of the corresponding sides are equal
oh sorry i didnt read the question properly
Then again drop a perpendicular to point F to side AD
Then calculate the length of perpendicular to point F to side AD
By triangle similarity
Then add the perpendiculars length you get AB
You get AB=50/3
And that is right answer
Damn, u answered your own question @alpine sable
can anyone help with this
wait a minute, what is t?
and what have you tried?
im assuming t is tan?
It happens in my country 😂
true, but where could that variable come from?
and for the final expression im pretty sure you can make (1-t)/(1+t) equal to sec - tan IF t is tan
And why would they take an arbitrary variable?
then you are left with a trigonometric identity
ye it's just a proof right?
the question is pretty much
"Prove that (sec a - tan a) = (1 - tan a)/(1 + tan a)"
(i think)
yeah
oh ok
i believe i figured it out, i got to (t-1)^2/1-t^2
and that can simplify to (1-t)/(1+t) right
yup you are correct
do you understand the question?
what looks useful to calculate first?
there's Julie and Max
you'll have to calculate for both it seems
annuity? idk
probably you want to be able to do it on your own first
before you use a online calculator to automate the process
it usually comes with a geometric series
so you'll need to be able to apply the formula for geometric series
a geometric sequence is a list of numbers with a common ratio
a geometric series is what you get when you sum number in a geometric sequence
you need it to be able to calculate
Given f(x)=x+6 and g(x) = x-3
(a) find fg(x)
(b)find fg(2)
for example, 1, 2, 4, 8, 16, ... is a geometric progression
and the sum 1+2+4+8+16 = 31
but you don't have to add one by one
you can use a formula to help
it takes longer to put in a calculator
then that means you have to add every single payment into the annuity
composition or multiplication?
how much does the first payment contribute to the annuity
the first payment is $1250
it accrues 15 years of interest
wait, 45 years
45 years of interest
how much is that
no, because that's not how interest works
how does 5.4% annual interest work?
0.054, but you need to know how interest works
if you can't do 45 years of interest yet
how do you do 1 year of interest?
I FINSH
If g(x) = 4-3x, solve the equation f(x) = -3
f is not provided
that's simple interest
what you want is compound interest
the difference is you get interest on your interest
do you want interest on your interest?
erm...
but that's what banks provide today
that's why you have to learn how to calculate it
the fastest way is...
- derive a formula for annuity if you haven't yet
- apply the formula whenever you see a question like this
or at least that's what I think the fastest way is
we still have to derive it
if you want a formula you would want to generalise
with a annuity contribution of P and a interest rate of r for k years
If you add everything together you should have P(1+r)^k+P(1+r)^(k-1)+P(1+r)^(k-2)+...+P(1+r)^(1)
yeah so you need to know about geometric series
because it is geometric
For that I remember the polynomial identity (x^n-1)=(x-1)(1+x+x^2+...+x^(n-1))
here
well it's a variable in a polynomial identity
n is some integer
this polynomial identity is true for all positive integers n and real numbers x
1+r because it's the common ratio for x
and n is probably k
that allows you to match the formulas together as closely as possible
After simplifying you should get something along the lines of P(1+r)((1+r)^k-1)/r, which you still have to apply interest for 30 years to see what happens at 65 years old
well, math literally builds on itself
to be fair the formula you just derived will be the same idea for all the other questions
so what you learnt previously is used a lot when you learn more
maybe learn some foundations
Khan Academy is what I know
you can potentially go there to learn stuff
getting less than A is a math class is a sign you are missing a lot of stuff tho
like enough to mess up foundations
We won't, but there's a chance you will
god forbid you ever have to render something
you can live life and not understand how a lot of it works, but we like math here so seeing stuff like this makes us sad
good luck in the future tho
you won't, but it's possible it will make some things harder
you need math you already completed, most of the stuff you are doing now and would be in the future is "extra"
you can be fine without it
plz don't cheat
your classmates grades may be devalued if you cheat
it's not just about you
would you want to be in a university where all your classmate cheated?
but that means your degree has no value
my current class is literally graded by standard deviations off the mean
cheating is simply unethical/misrepresentation of your skill
it's not supported here
this is a pointless discussion
I'm pretty sure ur gonna cheat anyways whatever I say so I don't see the point
cheating is a pretty serious academic offense, if it runs rampant it would devalue all the degrees. If it's one or two cases which is not caught, it may incentivise more, and more means more devaluing of degrees
you look so stressed judas
Stressed 😫 too cortisol level increased
I know it says no help for tests, but its just homework and i really cant solve this, can someone help me please :(
What's the language
Its german
Translation: you have X > 0 und E|X|^p < ∞ for p > 0 and need to prove that the middle equation is correct. then last line is a tip: use partial intergration or do X^p=[x^p]x 0
oh |sin(x)|+|cos(x)|?
Yes That only
do you know how to find the coefficients via integration?
can you set up the relevant integral?
yea i know the formulae
hmm integration by parts? since what we really want is the integral of x^p, not x^(p-1)
then can you plug it in?
Ohh yeah i got it now, Thanks man 😄
,rotate
^
So no one can help me here? :(
I don't get what to do in your question
it's not in english
U have to proof that the middle equation is correct
have you tried integration by parts?
i don't how to do it with that EX(p)
p is a constant right?
you have an integral, you can integration by parts it?
yes
okay gonna try that now
ty :D
is this channel free?
ys
right, i already posted a question in #calculus can someone look at it? posted what i've tried as well
and added some sketches for people to see where i got my answer
is for this exercise, the explanation of my answer was also posted along with the image, should i post it here as well?
Does anyone know how to get complex numbers as polar form in wolfram?
,w 2 + 3i in polar
@waxen shadow don't post the same question in different channels, all you are doing is making people ignore you
and hes posting his exam thought :)
nope, thats illegal
i-.
try ln both sides
how much do you think ln(e) is?
What next?