No idea where I went wrong
#help-0
oblique stirrup
Confused what this question is asking
Find how far the rider is away from theta right? Ignoring the distance of of the lower half of the circle.
oak chasm
@silent geyser Sorry, computer problems.
ocean sealBOT
Chai T. Rex
silent geyser
<@!312693417769566221> Sorry, computer problems.
Thanks
oak chasm
@oblique stirrup They're similar triangles.
oak chasm
So, what do you multiply a side in the smaller triangle by to get the side in the larger triangle?
oblique stirrup
correct which i can just times 1 by 220 right
oak chasm
@silent geyser Do the work by hand.
@oblique stirrup Right, so multiply the height in the smaller triangle by 220.
oblique stirrup
but isnt the distance from theta to the person just the radius
silent geyser
I got the derivative right I’m just missing a second point
oak chasm
@oblique stirrup Yes, but I don't understand the "but" in your statement.
oblique stirrup
<@!134516533937307648> Yes, but I don't understand the "but" in your statement.
Am I trying to find the length opposite of theta
silent geyser
I got the derivative right I’m just missing a second point
I plugged in for y and I only got 1
silent geyser
I plugged in for y and I only got 1
1 Answer*
oak chasm
@oblique stirrup You want the height at that angle, right?
,w D[Sqrt[(x - 5)^2 + (4x^2 + 80)], x]
ocean sealBOT
oak chasm
@silent geyser ^
ocean sealBOT
Chai T. Rex
ocean sealBOT
Chai T. Rex
silent geyser
And when I plug in for y I got 9.165
silent geyser
**Chai T. Rex**
I did that
That’s why I’m confused
Apparently there are several answers
ocean sealBOT
Chai T. Rex
oak chasm
@silent geyser ^
silent geyser
And when I plug in for y I got 9.165
^
oak chasm
Right, and there's another answer.
oak chasm
It's an easy mistake to make.
oak chasm
You're welcome.
oak chasm
Sorry, have to help madeInHeaven.
silent geyser
Aight thanks anyway tho
oak chasm
@oblique stirrup The height is the side opposite the angle, yes.
oblique stirrup
<@!312693417769566221> ^
@oak chasm
so in addition to finding "y" I also find the bottom quads lenth too?
oak chasm
No, they only ask for the height.
oblique stirrup
and that would be the same as y becasue its a circle so 176 times 2?
oak chasm
,calc 4/5 * 220
ocean sealBOT
Result:
176
Oh, I see.
No, not quite.
The height is all the way to the ground.
So how far is it from halfway up the circle to the ground?
oblique stirrup
the radius which is 220
oblique stirrup
only at a certain point though
oak chasm
No, that's incorrect.
oblique stirrup
the person is at that blacck dot on the top right and drawing a straight line down does not lead to the ground?
oak chasm
Is the ground below the person?
oblique stirrup
of course lol?
oak chasm
Then drawing a line straight down from the person will eventually hit the ground.
oak chasm
Yes, so how high is the horizontal line in the middle of the circle up from the ground?
oblique stirrup
220 if theta is 270
oak chasm
No, it's parallel to the ground, right?
oblique stirrup
i think that would work if the shape was a square..
oak chasm
Look at the horizontal line in the middle of the circle.
Is it parallel to the horizontal line that's the ground?
oblique stirrup
yes
oak chasm
Then the distance between them stays the same throughout the line because they're parallel.
The angle is irrelevant.
oblique stirrup
I see but ok looking back at the question, the answer is just simply 176 ft I think
If we have the following information about the location of the rider at angle θ for the model, calculate the height the rider is off the ground, at angle θ on the real loop.
oak chasm
No, that's the height above the midline.
oak chasm
No, read the question.
It says above the ground.
"calculate the height the rider is off the ground"
oblique stirrup
off the ground at angle theta, meaning the ground in this caase is at theta but offset a bit to face towards the ground
ill input both to my answer and explain in sentence form
dire dove
Can someone check this out for me, I feel like I did something wrong since there’s so much space left in the paper, and my teacher doesn’t usually give excessive space. I can give a rough translation if needed
alpine sable
How do they simplify the z component?
I don't see how they can pull a sin^2x+cos^2x out of there
chilly hatch
what would the z component be then?
try simplifying it yourself
u should be able to see it right away
alpine sable
I tried already
ah
I had a negative somewhere where it shouldn't have been
can someone #help me
i don’t know how to do the stuff when they give me points, i only know when they give me an equation, a SF and that it’s centered at origin
i still need help
it would be funny if i said i still need help
<@&286206848099549185>
Hey guys, what does it mean when it asks what situation could each graph represent?
like the context
i think you make up something that would go with the data
bleak ibex
Hey guys, what does it mean when it asks what situation could each graph represe...
The first one could be a body at rest
Second could be a body projected upwards
alpine sable
bruh
how you gonan come into my channel and steal help from me like that i see how it is
bleak ibex
how you gonan come into my channel and steal help from me like that i see how it...
I would love to help, but coordinate geometry isn't my strong point
wanton turtle
Pretty sure they're just asking the area under the graph
Take area below x axis as negative, and above as positive
bleak ibex
Pretty sure they're just asking the area under the graph
They want to find a value
bleak ibex
Tho, my poor eyesight could not get it😂
wanton turtle
Find each area individually
upbeat shadow
Would it be 5.5?
wanton turtle
Wait, should we take the area present on the left side of the y axis as negative? 
Confirm with someone else too
bleak ibex
Wait, should we take the area present on the left side of the y axis as negative...
That's the general convention
wanton turtle
Oh ok
alpine sable
can someone tell me the diff between line integral of scalars vs line integral of vectors? like in a question how do we determine which is which? i googled but it made me more cofused?
charred flint
@alpine sable for an integral of vectors you just integrate each component normally
nimble mulch
how do I solve this
nimble mulch
yeah I did all the simplification stuff and got till here
but how do I integrate it
charred flint
partial fraction decomposition because the denominator is x(2x+a)
you'll get 1/x - 1/(2x+a)
nimble mulch
oh god. I totally forgot about partial fractions. spent the last 10 mins trying to complete the square in the denominator and solving from there
let me try
alpine sable
<@456226577798135808> for an integral of vectors you just integrate each compone...
what abt integral of scalars
charred flint
that's just integration
it's what you do in calc 1
maybe you're asking about what makes line integrals different from usual ones?
delicate gust
can someone help me please? heres the problem: A radioactive element decays at a rate of 5% annually. Initially there are 40 grams of the substance present. Write an exponential equation that will model this situation
nimble mulch
@charred flint I solved that and got this
but how do I substitute the limits, I dont think I can do log of infinity
charred flint
yea infinity - infinity is super hard to deal with
but you can combine the logs to make a fraction that works well
raw apex
I tried
nimble mulch
convert that cos^2 into (1-sin^2)
nimble mulch
show what u did
nimble mulch
apply the quadratic formula
bleak ibex
substitute x in place of sin and solve the eqn
nimble mulch
like this
pine lake
Can someone help me with this question?
This question is under indices, surd and log
woven marsh
Pog
alpine sable
maybe you're asking about what makes line integrals different from usual ones?
hmm im kind of unsure like how to differentiate them in a question? bcos line integral of scalars vs line integral of vectors has different formula.
is there a way or some key words
to actually determine which is which?
charred flint
I mean it would have a vector inside?
sometimes it's with a dot product of dt or whatever too
wanton turtle
<@&286206848099549185> even i would like to know the solution, im not getting any ideas
wanton turtle
I saw a similar question in Youtube earlier..
i was asked a similar question around a year back as a challenge 
stone shard
lol
wanton turtle
still dont have the solution lmfao
wanton turtle
Found it:
https://www.youtube.com/watch?v=i0dZukEw1JY
thanks for this
pine lake
Lmao
stone shard
😆 👌
alpine sable
Can anyone tell me if i did this right? If not what should i change
bleak ibex
looks correct
stone shard
agree
gray isle
units shouldn't be required in your equations
and the equation for the second question isn't ideal since you have both dollars and cents
bleak ibex
units shouldn't be required in your equations
and the equation for the second qu...
hmm, i agree with that
alpine sable
units shouldn't be required in your equations
and the equation for the second qu...
But it says to work with cents or dollars so which one do i remove
stone shard
Dollars is probably better since the other 2 terms is also in dollars
alpine sable
So i would remove the cents symbol on 12k , alright
bleak ibex
and convert it to dollars
alpine sable
Hm so it would be $34.95 + $0.12 = $55.11
stone shard
Dont need the dollar sign
bleak ibex
remove the units
stone shard
Also you forgot to add k to 0.12 -> (0.12k)
bleak ibex
in both the questions
tribal geyser
Can someone help with 14)b? I don’t know why it’s 90 degrees
vale wigeon
@tribal geyser AB is perpendicular to plane FAT
carmine lion
can anyone hint at how i should approach this problem
$2\cos(x) -1 = 2\cos(2x), 0\leq x\leq 2\pi$
ocean sealBOT
abe
rigid smelt
you can use the double angle formula to write cos(2x) in terms of cos(x)
after that, you only need to solve for cos(x)
carmine lion
cos^2(x)-sin^2(x)
carmine lion
after that, you only need to solve for cos(x)
but im stuck here
rigid smelt
theres another formula
carmine lion
illl show u
rigid smelt
cos^2(x) - sin^2(x) = cos^2(x) - [1-cos^2(x)]
carmine lion
$1-4\cos^{2}(x)+2\cos x=0$
ocean sealBOT
abe
rigid smelt
.
lost violet
how can i show that $(1+h)^{n} \geq 1+\frac{n(n-1)}{2} h^{2}$ using newton binomial
ocean sealBOT
alef0
vale wigeon
are you sure you aren't missing anything here?
$(1 + h)^n \ge 1 + \frac12 n(n-1)h^2$ is false for $n = 5$ and $h = -1/2$
ocean sealBOT
Ann
vale wigeon
@lost violet
lost violet
sorry one condition is h>0
vale wigeon
you should say these things outright.
okay then it follows from $(1+h)^n \geq 1 + nh + \frac12 n(n-1)h^2$
ocean sealBOT
Ann
vale wigeon
what is known about n, actually?
lost violet
n is in N, oh this is because we delete the rest of the terms of the binomial expansion right?
vale wigeon
the other terms are all positive so yes
lost violet
thank you!
carmine lion
i am stuck on a question:
lost violet
oh just another question, is there a way to prove that if we delete positive terms of some sum of positive terms then is less than theoriginal?
final crag
Is G false?
quaint trout
oh just another question, is there a way to prove that if we delete positive ter...
There is a property of real numbers that if x < y then x + z < y + z for any z. So if 0 < a then b = 0 + b < a + b for any b. So take the smaller sum as b, then add the extra terms as a, and it has to be greater than b since a is greater than a.
lost violet
thank you
blissful ether
Long story short trying to create a model to forecast future performance in baseball. Does anyone have any ideas on how I can quantify age? I've considered comparing the stats of those at the same age and using the deviation from the mean but there may not be many data points for this. Another idea I had was to just assign a value to age and as the players get older increase the impact of this.
fresh quail
Question related to proportionality:
if x is proportional to y then x/y or y/x have a constant ratio right?
so if we have the following problem: the municipality of x(population 280000) and y(70000) decided to facilitate a common public park between the two cities at the cost of 150 000 000.
What cost, PROPORTIONAL TO ITS POPULATION must be covered by each municipality?
to be a system:
x+y= 150 000 000( where x and y is the cost paid by each)
second equation would be:
x/280 000=y/70 000
because we have them PROPORTIONAL then their ratio is equal, and to their population hence x/its pop=y/its pop
Am I right?
alpine sable
3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣
3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 3️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 1️⃣ 1️⃣ 3️⃣ 3️⃣ 1️⃣ 3️⃣ 1️⃣ 3️⃣ 3️⃣ 1️⃣ 3️⃣ 3️⃣ 1️⃣ 3️⃣ 3️⃣ 3️⃣ 3️⃣ 1️⃣ 3️⃣ 3️⃣
bleak ibex
?
stone shard
??
vale wigeon
???
wanton turtle
copper summit
can you retype it? its not very understandable
cinder sundial
theres a mistake
ok
i will
let me rewrite it
ok they looks good now
its 1 instead of 7 btw
copper summit
is it 40? or 90
copper summit
start by narrowing down the two equations as much as you can till you get x= something or y= something
like the first one can be x= 6y -60 right?
cinder sundial
its ok
alpine sable
How to find out the answer for this
harsh swallow
you square the smaller 2 and add the squares
and then take the root
and if it becomes the biggest number you add it to the list of correct ones
alpine sable
Thank u
Is this a good conclusion for an assignment?
From the above calculations, we can see that Nyvej 3 uses on average more than Nyvej 5, however, the average is very similar. So they use about the same amount of water consumption.
Nyvej 5, however, has a greater maximum and minimum value, as well as a somewhat greater spread. This means that since both parties have approx. the same average, then Nyvej 5 has some that use more and less water than the others, which is why the spread is so great.
The range of variation of both parties is also very small, therefore it makes sense that the mean is approx. the same.
<@&286206848099549185>
(Remember to ping me if you can help)
harsh swallow
can you show the graphs? @alpine sable
alpine sable
I only have calculations if you wish to see
alpine sable
can you show the graphs? <@456226577798135808>
^^
harsh swallow
holdup lemme see if when i read this i get what you want to say
harsh swallow
you found that 3 uses more water than 5 on average but not by much. 5 is also more irregular in water consumption.
alpine sable
Yes. 5 has a greater spred, maximum and minimum value aswell as a larger median.
It only uses 0,2 more on average! So it's very low.
harsh swallow
higher median but lower average?
harsh swallow
ok so number 5 is skewed to the left
harsh swallow
i don't really understand what you mean by
This means that since both parties have approx. the same average, then Nyvej 5 has some that use more and less water than the others, which is why the spread is so great.
everything else seems good
alpine sable
the reason why the spread is so big, and yet they still have nearly the same average, is because they have such a big maximum and minimum value difference.
Honestly I'm confusing myself now.
I think?
I'm not sure.
harsh swallow
that makes sense
alpine sable
Awesome, so is the conclusion fine?
harsh swallow
sorry i had to graph it
even better graph
you can see that the orange, which is 5 is more spread
but they're both skewed to the left
and the average and means are similar
i think your conclusion is fine
harsh swallow
i found something you did wrong @alpine sable you didn't sort them before getting the median
clever tapir
can anyone help e with domain and range i dont remember the material
<@&286206848099549185>
acoustic shadow
What are domain and range ? @clever tapir
pale cargo
I tried all possible ways i just cant
Can someone please prove this on paper ^
I'm starting to suspect the question itself is wrong
bleak ibex
can anyone help e with domain and range i dont remember the material
Domain is the values on x axis
Range is values on y axis
@ionic jewel , is that better?
pale cargo
<@&286206848099549185>
ionic jewel
<@153882568322711553> , is that better?
yes that's great
of course he probably left lmao
pale cargo
if he left than someone help me please 🙂
feral star
what have you tried?
pale cargo
making it in terms of x only and differentiating twise
and differentiating implecitly
didn't get that in both
feral star
you can do it, but a better way would be just to differntiate it
using the chain rule
try doing first dy/dx - do you know what is it?
feral star
no
pale cargo
then?
ionic jewel
yeah you want implicit differentiation here
pale cargo
i did implicit differentiation
feral star
y'y= -x
feral star
Keep doing it becomes messier
for one more round though..
acoustic shadow
It’s becoming weird to manipulate
feral star
but you know y'
pale cargo
okay so the first one would be 2y(y') + 2x = 0 , right?
feral star
yea
pale cargo
and y' = -2x/2y ?
feral star
yes
pale cargo
now what?
pale cargo
quotient rule implicitly?
pale cargo
i would reorganize it to y'y+x=0
wdym?
feral star
you said y'=-2x/2y
reorganize this term to get y'y+x=0
and now diffrentiate again in respect of x.
pale cargo
how do you do it again with y'y
pale cargo
how do you differentiate y'
pale cargo
oh
feral star
so what did you get
pale cargo
2 times?
pale cargo
cuz its y' x y'
pale cargo
kk
pale cargo
than you will need to use the fact that x^2+y^2 = 2
??
feral star
no
pale cargo
😦
pale cargo
it's Iftar time out here
pale cargo
y''y+x^2/y^2 +1 = 0
yeah i got that
feral star
now change the 1 to y^2/y^2
pale cargo
now change the 1 to y^2/y^2
I'll check after
feral star
anyways, you should remove the x^2, using x^2+y^2 = 2
feral star
gl
pale cargo
Thanks!
prime steeple
Hi everyone. I am wondering the best way to evaluate if a given number is a whole number or not. What I am currently doing is dividing the given number by one. If there is no remainder, I am assuming the number is a whole number. Is my way ok, or is there a better way?
ionic jewel
Hi everyone. I am wondering the best way to evaluate if a given number is a whol...
if ur programming your language almost certainly has a native way to check it
another way I've seen is check if the number equals the rounded version of itself
prime steeple
another way I've seen is check if the number equals the rounded version of itsel...
Ahh this is a way I had not thought of.
harsh swallow
why implicit? i did it with y = sqrt(2-x^2) and it all cancels nicely
prime steeple
But do you see any potential problems with checking that the reminder == 0 to determine if it is a whole number?
harsh swallow
sorry jon
ionic jewel
But do you see any potential problems with checking that the reminder == 0 to de...
you mean modulus 1 and yes thats fine
but also whatever ur using to check if there's no remainder, you could just use on the original number probably
vale wigeon
just curious
prime steeple
@ionic jewel thank you! Very helpful.
vale wigeon
what context did this arise in
prime steeple
Writing an algorithm (in Rust) to find the factors of a given number.
vale wigeon
so then you aren't really checking a number for wholeness
you're checking one whole number for divisibility by another whole number
rust should have a dedicated remainder-of-division (or modulo) function
prime steeple
`fn main() {
let dividend = 72.0;
let mut divisor = 1.0;
loop {
let quotient = dividend / divisor;
if quotient < divisor {
break;
}
if quotient % 1.0 == 0.0 {
println!("factors of {} are {} and {}.", dividend, divisor, quotient)
}
divisor += 1.0;
}
}`
vale wigeon
triple backticks for a code block
like this
you can do multiple lines
you can even do
```rust
like this
```
and get syntax highlighting
okay so the first question is, why are you writing 72.0 and 1.0 instead of 72 and 1?
does rust not have integer data types?
prime steeple
Thank you, I will do that next time. So that is the algorithm as of right now.
It does, but dividing integers will not return a remainder.
for example 72 / 7 = 10
vale wigeon
but you have %
you can just check for dividend % divisor == 0
there is no need in your case to use floating-point numbers; all you get is unnecessary overcomplication
prime steeple
Hmm that that's a good point. I am going to give that a try. Thank you @vale wigeon and @ionic jewel for your time!
vale wigeon
for future reference, you should post the context along with your question, so as to not make people contend with the XY problem
chrome kestrel
Here is not someone German who is willing to learn Maths with me? I am struggling with "Bruchterme" If someone is willing to help me in VC it would be very appreciated.
alpine sable
i found something you did wrong <@456226577798135808> you didn't sort them befor...
I thought I had! Youre an absolute gem! Thank you.
wanton turtle
OK, in this diagram, what is PR?
And also, there's a particular property you can use to find the angle PQR
But that's really not needed
wanton turtle
Oh wait, I read the question wrong
limber ledge
I need to find length of RQ
wanton turtle
What does the 72° refer to here? The arc length?
wanton turtle
If so, then you can find the angle ROQ (where O is the center) by equating the formula for arc length to 72 degree
Then, by using some trigonometry, you should be able to find RQ
limber ledge
what is the formula
wanton turtle
(Theta / 360) x 2 pi r
(I think)
dawn wraith
That isn’t really necessary though
wanton turtle
Oh OK
dawn wraith
The inscribed angle is equal to half the measurement of the arc length by degrees
wanton turtle
That's the only thing that popped into my mind
wanton turtle
The inscribed angle is equal to half the measurement of the arc length by degree...
By inscribed angle do you refer to angle ROQ?
limber ledge
The inscribed angle is equal to half the measurement of the arc length by degree...
yes
dawn wraith
And from there just use sine
limber ledge
so would it be 36
wanton turtle
Ye
dawn wraith
Touché
wanton turtle
Should probably go through them properties again
dawn wraith
If required, do so
limber ledge
Yeah I should
geometry is so hard
I didnt struggle in Algebra but geometry im struggling a lot
wanton turtle
Yeah I should
I was talking about myself, but you should too 
limber ledge
wanton turtle
Hunnydrips' method should have been the first thing to pop up in my mind
K anyways, channel is free
dawn wraith
Is 2x + 220 the measurement for arc AB? (Large)
dawn wraith
Let us assume for now that it is I suppose
What I’d do first, would be making an inscribed angle that lies on chord AB from the opposite side of angle CBA
limber ledge
ok
dawn wraith
From there, we have a property that is very well-known these days in circle geometry
What can we infer about an angle that lies between a chord and a tangent?
limber ledge
they are congruent?
dawn wraith
The inscribed angle, and the angle between the tangent and the chord
Only that angle must lie from its other side
(The inscribed one)
dawn wraith
Let us suppose that vertex of the inscribed angle is D
limber ledge
ok
dawn wraith
Now, what would be the arc length in front of the inscribed angle?
limber ledge
arc length is 2x the inscribed angle
limber ledge
ok
dawn wraith
What do we know about the summation of all the arcs in a circle?
limber ledge
Im not sure
limber ledge
oh ok
limber ledge
0
dawn wraith
That’s correct bud
limber ledge
ok
tender geyser
i need a bit of a clue on solving a specific integral
i have to integrate over a function of the form 1/sqrt(a+2bx-x²)
i know that the solution should be arcsin((b-u)/sqrt(a+b²))
but im not sure how to get there
harsh swallow
$\frac{1}{\sqrt{a+2bx-x^2}}$
tender geyser
i tried an online integral calculator and its by hand solution (where i can look up the steps) goes completely nuts with i and some logarithmic functions
ocean sealBOT
Katharine
tender geyser
its numerical solution looks a lot more like what i need
maybe i shouldve just posted this xD
but i wanted to keep it simple 😄
dawn wraith
Definite or indefinite
tender geyser
wdym?
harsh swallow
that is the stuff of nightmares
harsh swallow
definite right, it has bounds
ionic jewel
are you actually expected to know how to integrate that outside of having it memorized or just using a calculator
tender geyser
according to the script, its an obvious integral that can be found in tables and such 😂
tender geyser
but i cant find it in this form
i found the simpler version that just yields arcsin(x)
but im not sure how to turn this polynomial in the sqrt into a 1-x² form
tender geyser
are you actually expected to know how to integrate that outside of having it mem...
funny enough, the paper im working on didnt even give me the hint above x)
but were expected to be good at finding these things written down in whatever resources we can get our hands on
ionic jewel
not sure why you would use an integration table written down when mathmatica exists but as far as I can tell there's no particularly nice way to solve that by hand
tender geyser
do you know a good table that covers more complicated variants of the 1/sqrt(1-x²) -> arcsin(x) integral?
harsh swallow
i found this one but it makes no sense with a -x^2 cuz there's a 1/i in there
number 39
ionic jewel
2 pages on a "single page integral table"
tender geyser
i found this one but it makes no sense with a -x^2 cuz there's a 1/i in there
yeah i think this solution allows for complex roots of the problem
but the integral comes from classical mechanics so no complex roots needed
and wolfram alpha tells me its an arctan
harsh swallow
integral-calculator shows how it's done but if you need to do this by hand i want you to slap your instructor for me
tender geyser
do you have a link? 🤔
harsh swallow
tender geyser
ah thx!
tender geyser
oh haha lol its just the english version of the one i use 😄
alpine sable
how can i write $a(e^{i\theta}) = cos^{2}(\theta)$ in terms of $t=e^{i\theta}$?
like what would be a(t)?
ocean sealBOT
nosequepasa
harsh swallow
XD
tender geyser
what is the angle sum needed for a line to be straight?
rose dune
<@&286206848099549185>
tender geyser
hmm?
rose dune
<@&286206848099549185>
halp meeeeeeeeeeee
limber ledge
what is the angle sum needed for a line to be straight?
180
tender geyser
halp meeeeeeeeeeee
you know youre only supposed to use this ping after 15 mins right?
rose dune
you know youre only supposed to use this ping after 15 mins right?
oops srry
harsh swallow
especially to get an arcsin instead of the log
stone shard
read #❓how-to-get-help
tender geyser
180
yes, now how much of these 180° are taken away by the intersection?
(if you look at the value that you already know)
rose dune
sir help mee :(
tender geyser
sir help mee :(
hang in there, ill get to you
harsh swallow
that's nice table
limber ledge
yes, now how much of these 180° are taken away by the intersection?
94
rose dune
hang in there, ill get to you
thanks sir
limber ledge
180-94=86
tender geyser
that's nice table
https://link.springer.com/content/pdf/bbm%3A978-3-322-83765-3%2F1.pdf
its german but shouldnt matter 😄
limber ledge
53+41
tender geyser
you dont have to add these angles
limber ledge
then what do I do
tender geyser
consider the line that goes from down left to up right okay?
limber ledge
ok
tender geyser
obviously, looking at the center, going from one side to the other should be 180° right?
limber ledge
yes
tender geyser
what is the angle between the intersecting line and the original line? (not x but the smaller angle)
limber ledge
what is the angle between the intersecting line and the original line? (not x bu...
inscribed angle
rose dune
omg thanks this server is epic
tender geyser
yes
so a formula for the angle should look like this:
x + 41 = 180
now just solve for x 🙂
limber ledge
ok thanks
ionic jewel
i like how there's 3 simultaneous questions in q0 while other questions channels are empty
stone shard
tender geyser
channel descriptions dont seem to be very eye catching eh? 😂
limber ledge
i like how there's 3 simultaneous questions in q0 while other questions channels...
how do I get better at geometry
I am so bad at it
lament wyvern
practice
ionic jewel
yes
limber ledge
ok
ionic jewel
that's the entire reason your textbook has practice problems
steel dirge
don't answer his question he is cheating for a maths test
stone shard
oops, should of asked first
steel dirge
<@&286206848099549185>
what a loser
stone shard
my bad
steel dirge
i shouldnt have brought u here
you shouldn't have cheated
rose dune
you shouldn't have cheated
shut
steel dirge
acting like you're starting to learn maths and starting to like it, when all you're doing is cheating
rose dune
<@&268886789983436800> pls kick this child
steel dirge
don't fight in here (:
tender geyser
fellas
keep the drama out of this channel please
its for people to actually get some help
ionic jewel
we don't support cheating and don't help on exams, that's a reasonable mod ping yes
tender geyser
btw @limber ledge i noticed that i told you some mad bogus, i mistunderstood the drawing im sorry xD
steel dirge
its for people to actually get some help
ok sorry for the inconvenience
rose dune
we don't support cheating and don't help on exams, that's a reasonable mod ping ...
nice
tender geyser
btw <@!662354986155638814> i noticed that i told you some mad bogus, i mistunder...
i thought the 41° meant the angle between the intersecting lines
but apparantly its basically a fraction of the full circle
(360°)
alpine sable
how can i write $a(e^{i\theta}) = cos^{2}(\theta)$ in terms of $t=e^{i\theta}$?
like what would be a(t)?
ocean sealBOT
nosequepasa
tender geyser
how can i write $a(e^{i\theta}) = cos^{2}(\theta)$ in terms of $t=e^{i\theta}$?
...
dude 😂
this channel is still in use
why is nobody reading the rules 
ionic jewel
becuause everyone assumes their question is highest priority and all the helpers should drop what they are doing and immediately help
tender geyser
i thought the 41° meant the angle between the intersecting lines
but apparantly ...
okay i gotta go now so i cant help you further, but basically you need to find the angle of the pizza slice, based on the fact that the outer edge is 41° of the full 360° rotation
@limber ledge
swift igloo
anyone any ideas on part (ii)? from the first paragraph I have the two general coordinates of M
not sure how to apply it to part (ii)(a) tho. from a diagram i know it's a circle, but idk
the coordinates of M are
$(\frac{ab^{2}}{b^2+1}, -\frac{ab}{b^2+1})$
ocean sealBOT
reaps
polar whale
can anyone teach me (c) ^
First make a table(for convenience) and make a column for class mark
quick surge
i did
cumulative freq 4 , 10 , 20, 35 , 43, 48, 50
im just getting confused on the passing mark thing
polar whale
Just calculate the number of students with class mark more than 45
polar whale
U are taking class mark as the marks obtained by each student in that class interval
quick surge
yes
polar whale
Then how many students got 45?
polar whale
Then how many students got 45?
The frequency of the class with class mark 45
That is the second interval.
polar whale
1st interval class mark is 35
2nd one is 45
And so on
quick surge
polar whale
Show what u did
quick surge
and bla bla bla
polar whale
That's not the class mark column
That's class intervals
Class mark is the average of a class interval
quick surge
polar whale
Class mark= (upper limit+lower limit )/2
quick surge
Class mark= (upper limit+lower limit )/2
isnt that midpoint
polar whale
We call it class mark here
Sry idk what terminology is used there
Yeah so make a column for mid points
quick surge
but why do we need mid points
my teacher teached this
it doesnt have any mid points
now i just wanna know
how do u find how many people passed
i dont need help on percentage
quick surge
this is the table
this is the graph
i dont see any midpoints and i dont see why u need midpoints to find how many people passed if the passing mark is 45
polar whale
The problem is we don't know how many of the 18 student in 41-50 got more than 45
polar whale
So we trying to plot the cumulative frequency on a graph as shown.
quick surge
yea
and
do we just
do i just plot at the 45
and pull up
until it touches the line
polar whale
Well that's what I would do
quick surge
i found 7
polar whale
And find the y value
quick surge
wat
polar whale
At x=45
polar whale
What's the cumulative frequency at x=45?
quick surge
YES
quick surge
?????????
polar whale
On that graph u pulled up and intersected the curve?
polar whale
.
polar whale
Oh
quick surge
IT WAS AN EXAMPLE
polar whale
Ooo
quick surge
BRUH
polar whale
So cumulative frequency at 45 is7?
quick surge
total - 7
polar whale
And total frequentcy is?
polar whale
Ohk
quick surge
right?
polar whale
Wait
polar whale
What's the cumulative frequency at x=44
polar whale
Ohk
quick surge
86%
quick surge
Huh
polar whale
People with 45 marks pass the exam
polar whale
Cumulative frequency subtracted at x=45 also include some people who passed
That's ehy
Why*
swift igloo
$(\frac{ab^{2}}{b^2+1}, -\frac{ab}{b^2+1})$
can someone look at this q pls <@&286206848099549185>
glad matrix
int (logx)² by parts!! plz
manic quail
int (logx)² by parts!! plz
Have you tried it like $\int \log{(x)} \cdot \log{(x)}dx$?
ocean sealBOT
verysadperson
glad matrix
ohh unfortunately not! but i have done int log(x)
manic quail
So, you could try this by parts, since you know the integral of log x.
glad matrix
So, you could try this by parts, since you know the integral of log x.
sure tq i will let you know after solving it
manic quail
Okay. I cannot guarantee that this works, btw xD It just seems like it could work to me.
thorn nebula
help
bleak ibex
Why does it look like physics?
glad matrix
yyeh it is i think
thorn nebula
its mechanics
bleak ibex
its mechanics
Wrong server bro😂
glad matrix
and this is maths server
grand kelp
I mean, many physics problems are just math problems about physical objects
glad matrix
yeh im on my way
bleak ibex
I mean, many physics problems are just math problems about physical objects
U need to know the concepts
manic quail
I think it works.
Mental maths suggests you should end up with this, let's see if I did it wrong, $$\log{x}(x\log{(x)}-x) - \int( \log{(x)} -1 )dx.$$
ocean sealBOT
verysadperson
alpine sable
how can i write $a(e^{i\theta}) = cos^{2}(\theta)$ in terms of $t=e^{i\theta}$?
like what would be a(t)?
ocean sealBOT
nosequepasa
still crest
How do I even start with this kind of problem?
glad matrix
**verysadperson**
i obtaine ans as
(logx-1)(xlogx-1) is it correct??
lament wyvern
How do I even start with this kind of problem?
draw the curve and then draw your line AB across it
where will the axis of the parabola be?
still crest
The exercise doesn't give that information so I suppose it's not needed
lament wyvern
nono I mean you can work it out
if you draw that parabola, where will it be symmetric about?
still crest
Ohhh xx'
manic quail
i obtaine ans as
(logx-1)(xlogx-1) is it correct??
How did you get that?
,w integral of (log^2 x) = (logx-1)(xlogx-1)
manic quail
I don't think that is the same...
still crest
if you draw that parabola, where will it be symmetric about?
From the y^2 = 4ax we know that it's x axis
right?
lament wyvern
,w plot y^2=4x
ocean sealBOT
glad matrix
yah i got the one of those above
lament wyvern
so now pick 2 points, anywhere
manic quail
yah i got the one of those above
Anyway, whatever you calculate, you should end up with x(log^2(x)-2log(x)+2).
glad matrix
sure thankyou
feral star
bar is complement set... so the complement of R\Q... which is not R...
so this might be wrong..
placid stag
this has something do with the density
noble sinew
same as ()
feral star
also N is empty set, then we have x in that set? this all photo look wrong
placid stag
okay thank you
acoustic bay
@remote temple Thats good man, hope you finish your senior year strong
celest void
an equilateral triangle has the same angles throughout (60 each - equiangular) therefore the sides are of equal length
winter linden
Yeah ..
wanton turtle
And the height of an equilateral triangle is (a sqrt3/2) if a is the side of the triangle
So use the area formula and equate it to the given value
winter linden
Wut
wanton turtle
1/2 (base) (height)
Let length of the side of the triangle be a
So it is 1/2 (a) (a sqrt3/2)
Which is equal to 4 sqrt3
winter linden
wanton turtle
What do you not understand?
winter linden
Whole thing
wanton turtle
OK I'll try my best to explain
winter linden
Please
wanton turtle
They want us to find the side length, so I'm assuming it as a variable "a"
They have given us the area as 4 sqrt3
The area of a triangle is 1/2 (base) (height)
winter linden
Ok understood
wanton turtle
We need to bring the area in a form such that it contains only 'a' which is the side length
The base is "a"
The height is "a (sqrt3)/2" from some trigonometry
I think the height is what is confusing you
celest void
You don't need to use 1/2 (base)(height) here?
celest void
Area = 1/2Ab sin(C) and it's much more efficient
wanton turtle
Well shit
celest void
Well idk don't u learn basic trigonometry as a 9th grader?
wanton turtle
Ye?
winter linden
Nope
winter linden
Yeah
winter linden
wanton turtle
Draw an altitude (height) from one vertex to another side
winter linden
Ok
wanton turtle
It divides the side into equal halves right?
winter linden
Yeah
wanton turtle
There you can see that it forms a right triangle
Let height be "h"
We know side length a
Which is the hypotenuse
One leg of the right triangle is "a/2"
We need to find "h" which is the other leg of the right triangle
wanton turtle
so h = sqrt( hypotenuse^2 - leg^2 )
Hypotenuse is a
Leg is a/2
By solving, we get h as a(sqrt3)/2
Once you know what h is, the problem is simple
wanton turtle
Anytime, hope it helped
weak cipher
my current idea is to ||sift through the vectors in X\{x} U Y and deduce we can find a vector in Y that is linearly independent to the vectors in X\{x} perhaps by applying the pigeonhole principle or something like that|| but not sure how to make the latter deduction or if I'm going down the right track
V is finite dimensional vector space over the reals
weak cipher
my current idea is to ||sift through the vectors in X\\{x} U Y and deduce we can...
hmm ok pretty sure this isn't right but could I say ||X\{x} is linearly independent and the set {y where y is not in X\{x} (which we can show is possible by pigeonhole principle) will also be linearly independent and we know the union of 2 sets of linearly independent vectors in independent therefore the set in question is linearly independent?||
dire dove
I have no clue what it’s asking me to do for part b, can someone give me directions to maybe make it more clear, and if you need me to translate I’m happy to do so
manic quail
I have no clue what it’s asking me to do for part b, can someone give me directi...
I think it wants you to express LC with a,b and c.
dire dove
I think it wants you to express LC with a,b and c.
But how can I do that if a b and c are already defined?
bleak ibex
I have no clue what it’s asking me to do for part b, can someone give me directi...
Maybe it wants u to express LC as a function of a,b,c?
dire dove
Maybe it wants u to express LC as a function of a,b,c?
What does, a function of mean? ( sorry not really good with english )
stable dune
i need help with this
manic quail
What does, a function of mean? ( sorry not really good with english )
Just write LC as a linear combination of a, b, and c
manic quail
But how can I do that if a b and c are already defined?
LC=-(a+b+c), I think.
dire dove
Wouldnt that answer be to long, I mean I only have like a 4 cm line to wright the answer down?
coral pagoda
I didn't realize I started
manic quail
Wouldnt that answer be to long, I mean I only have like a 4 cm line to wright th...
I think that's what they want though.
Or do you have any other idea?
bleak ibex
Or do you have any other idea?
Well, they asked to express it as a function
dire dove
The vector LC is a function of a b and c, which means LC=a?b?c or LC= ka+mb+uc
manic quail
The vector LC is a function of a b and c, which means LC=a?b?c or LC= ka+mb+uc
Exactly.
This is what I did.
LC=-(a+b+c)
dire dove
Im just gonna wait on monday to ask my teacher, I usually resort to here on weekends since I have no one to answer my questions, thank you guys for trying tho
manic quail
Okay.
Maybe the parentheses confused you, it's the same as LC=-(a+b+c)=-a-b-c
or -1a-1b-1c
alpine sable
why e^(x-y) is separable DE but 3e^xy is not?
loud orchid
because you cannot write 3e^xy as f(x)g(y)
vale wigeon
$e^{x-y}$ and $3e^{xy}$ are not equations at all, let alone differential equations, let alone separable differential equations.
ocean sealBOT
Ann
vale wigeon
they are expressions
if you meant dy/dx = e^(x-y) and dy/dx = 3e^(xy) then you should say that outright instead of making people guess what you meant
alpine sable
Understandable, have a great day.
vale wigeon
was that genuine, or was that a "fuck off i dont need your fucking pedantry" hidden behind a layer of politeness
keen wasp
can any1 explain why the answer is b and not a
i did dr/dtheta = 2cos theta
and then sub theta w/ 0
=2
vale wigeon
parentheses
keen wasp
hi i need halp i got -1/(2e) but answer is b
vale wigeon
how did you get a negative result from integrating a positive function
vale wigeon
,rccw
ocean sealBOT
vale wigeon
ah
keen wasp
i know i should have put limit statement for the second to last line but i was just trying to finish quickly
vale wigeon
you should've had $-\frac12 \int_{-1}^{-\infty} e^u \dd{u}$
ocean sealBOT
Ann
remote dagger
when it says find equation of a circle, do i find the radius or what?
or just display the formula with numbers correctly in
ocean sealBOT
Chai T. Rex
