help-0

[rich bough]

depending on sign

[thorn kindle]

Yes

[rich bough]

but if the denominator increases faster i think its 0 right?

[thorn kindle]

Yes

[rich bough]

okay thank you so much for the clairfication

also nice name hehe

^^

ty for the help again

[ripe turret]

i had a question

how is that right

[gray isle]

its not

[ripe turret]

isnt this right

[gray isle]

they should've had a 3 instead of a 5 at the front

[ripe turret]

wait i dont understand

u cant do anything to those numbers

like u cant get the gcf

so isnt what i did right

[gray isle]

what you did was legal but isn't fully factorised

since both 6 and 15 have a common factor of 3

[ripe turret]

oh im stupid

LOL

[final crag]

Do you happen to know some statistics?

Geometric distribution

[alpine sable]

I did my work wrong i did not need to use distributive property after all since i was just looking for a simplified expression for the area 😆

[thorn kindle]

I mean area is length * width

How were you wrong? You just algebraically expanded the expression

Unless you're saying they wanted you to leave it in factored form

[final crest]

How do you do it

[thorn kindle]

Take the partial derivative with respect to x twice

Then take the partial derivative with respect to y thrice

[ripe turret]

i dont understand

how they solved this

[alpine sable]

I actually dont know if they want me to leave it that way it just says this from a-c

[final crest]

Is anybody good with calculus here

[potent knoll]

Here you go

[dapper owl]

Anyone mind helping me with a hint to solve the inequality for 3a? I keep trying to mess around with the values but I just don't know how the 1/4 comes about

At least where to start?

[alpine sable]

Could anyone help me find out the one with the algebraic tiles because when i tried doing the division statement that i got it did not really match with the left side( factor 1)

black rectangles represent x, black squares represent x^2 white rectangles represent -x

[dapper owl]

<@&286206848099549185>

[alpine sable]

I figured it out

Good night.

Is this channel taken?

[jade coral]

ok, so I have what I consider to be a very hard question and am not sure where to post it. But I would reeally like some help figuring it out

[alpine sable]

Feel free, my man.

[jade coral]

the question is as follows

You are given a set of points which must be fully linked.
Each point is given a random set of possible directions from which they may link expressed as a set x = {up, down, left, right} in which 1 means a connection is able to be made, and 0 means no connections can be made.

For example, if given the set of points A = {1,0,0,0}, B = {0,0,1,1}, C = {0,1,1,0}
Point A would not be able to form a link to Point B, but it would be able to form a link to Point C.

Likewise Point B would be able to form a link with Point C, but only from Point B’s right side to Point C’s left side.

Every set of points will contain a starting point and at least 1 point E = {0,1,0,0} which cannot be linked to the starting point.

The starting point of any given set of points will always have a 0 in the down space. {x,0,x,x}

No points may consist of {0,0,0,0}
The list of points may contain duplicates, and can consist of any number of points and no two points may share the same connection.
Connections between points may not intersect, and all consist of the same length

With these rules in mind, what constraints would any given set of points require to ensure that the list can be fully linked, and are there any set of constraints which would ensure that the list can be fully linked even if the two points being linked are chosen arbitrarily from the initial set of points?

Pic for clarification

I also dont know if constraints is the right word, just sounded closest to what I was thinking

[alpine sable]

Graph theory?

[jade coral]

I honestly dont know

This is just a problem ive run across in actual life and am trying to solve XD

[alpine sable]

Ooh, damn.

Ok, lemme give it a look.

Can two points be linked to a same point?

Say A={1,0,0,0} and B={1,0,0,0}?

Ok, that's not exactly what I meant.

[jade coral]

ah definitely need to add that to the question, but no

[alpine sable]

It's meant to be perfectly perpendicular, right?

[jade coral]

yes

[alpine sable]

Ooh, ok.

[jade coral]

I mean technically, they could be rotated so long as connecting lines do not overlap

if nothing else this is helping me figure out what rules i missed lol

[final crag]

could someone help me with part C?

[alpine sable]

This channel is taken, bruv, sorry.

But I'll try to help.

[jade coral]

I know nothing about probabilities, but i came out to 0.0000000001%
am interested to see what the real answer is

[stone shard]

She have to lose 10 games to lose all her money because 30/3 = 10

[alpine sable]

Well, since there's 0.1 chance she loses 3$, getting 27, there's 0.1^2=0.01 chance of losing again ... With what I believe is the final answer being 0,1^10, but I'm probably wrong.

[stone shard]

I think your right

[jade coral]

thats what i went with as welll

[alpine sable]

So for a point A={1,0,0,0}, a point B={0,1,0,0} must exist.

As well as for all points A={0,0,1,0}, there must be B={0,0,0,1}, right?

I guess that you could use that.

[jade coral]

Both of those options would stop the list from being fully completed

[alpine sable]

Let us call those points nodes.

[jade coral]

Id say first constraint is that no 2 connecting nodes may fully terminate

[alpine sable]

If we say there's a node connected upwards, that implies that there is a node up there connected downwards.

[alpine sable]

Oooh.

[jade coral]

yes, connections require the directions to be available on both Points/Nodes

[alpine sable]

You've forgotten one thing.

You've established which is the direction, but not to which node is a given node connected.

Very impolite of yours, aye?

was i supposed to post in a channel that's not busy?

That's in the rules, but I'mma help ye.

oh my bad

Wait, but the cat traveled for 4 minutes?

[jade coral]

why does t give you a range, and then expect an exact response?

[alpine sable]

Exactly.

[jade coral]

well, if you substitute T for the maximum of the cats speed (4) you do get one of those options as an answer

but I cant imagine why they gave you a range to work with, so I might just not be understanding this correctly

[dark umbra]

Are you guys done? I would like to ask

when you guys are over.

[jade coral]

honestly peeps just keep interrupting mine lol, but one of the other channels should be free

[true hamlet]

Please someone help

[dapper owl]

Can anyone help me with this?

[alpine sable]

let x be an ordered set with four elements such that we'll call its first member up, second down, third left, fourth left, such that all its elements are either 0 or 1
no x can equal {0,0,0,0}
there is an x called E such that E={0,1,0,0}
let T be the set of all possible finite sequences of members of x, duplicates included
let R be a symmetric relation such that:
{1,0,0,0}R{0,1,0,0},
{0,0,1,0}R{0,0,0,1}
there is an element A, called the initial element
E is not related to A
What are the restraints that make a subset of T valid under R?

Probably poorly worded.

But I'm drunk as a donkey.

[final crag]

Wait .1^2 is .01

i think its .1 chance she wins right

[alpine sable]

A cent times a cent equals a cent?

Neutral element of multiplication is 1.

[final crag]

i meant .1 my bad

[alpine sable]

Np

[alpine sable]

You're right.

[final crag]

wait so the answer still is .1^10?

im so confused about this question lol

[alpine sable]

That's what I'd answer.

Not sure if it's true though.

[final crag]

so .90 chance of losing

[alpine sable]

DANG BRO

[final crag]

lmao

[alpine sable]

I DID IT SO WRONG

LEEEEEEEEL

[final crag]

i think ur on the right track though

[alpine sable]

Prob .9^10

[final crag]

cuz u lose 90% of the time

thats 27

9/10 timess

-$27

cuz u lose 9 out of 10 times

i guess when u lose 10 times u lose $30

[alpine sable]

0.9^10, right?

[final crag]

no idea lolll

i think so?

[alpine sable]

Circa 0.3486784401000001

[final crag]

that makes sense i think

[stone shard]

"Your" probability of winning is 0.1
"Your" sister's probability of winning is 0.9
So her probability of losing is 0.1

[final crag]

this is a geometric distribution

if that changes anything idk

[alpine sable]

Bruv I'mma let actually smart people answer for me, lel.

[final crag]

LOL

idk wtf is going on now

i might just sleep on a L soon here

[worthy verge]

@final crag Go sleep, wake up, refreshed, grind.

[final crag]

damn i really wanted to figure this one out before i go to sleep tho

[worthy verge]

Heck you may even think of the answer while sleeping

Or dreaming

I know have 😆

The dreaming one, not while sleeping

Oddly

[alpine sable]

She haves to lose 10 times.

[stone shard]

The question is asking for "your" sister's probability of losing all her money, not "yours"

[worthy verge]

Go sleep man, when fatigued your thoughts are slowed

[stone shard]

So it is still 0.1^10

[alpine sable]

For the first time, she has 0.9 chance of losing.

[alpine sable]

OH!

SO I DID IT RIGHT?

LEL

[true hamlet]

help

[stone shard]

Idk could be wrong, lol

[final crag]

but thats winning no?

or could it actually be 1- .1^10

[true hamlet]

even the wrong answer will work

[final crag]

but that would just be .9^10

[true hamlet]

just answer

[final crag]

LOL

god dammit

[alpine sable]

What'd be that correlation coefficient?

[true hamlet]

yes

[final crag]

<@&286206848099549185> anyone want to help us sleep

[true hamlet]

what is coffecient

[stone shard]

Is the probability for her to win 0.1?

[alpine sable]

Yes, please.

[final crag]

yeah

[stone shard]

Oh, then it is 0.9^10
Sorry for the confusion, I guess I did not read the question carefully

[final crag]

hmm what about this

every 10 game she wins one

actually nvm idk where im going with this

[stone shard]

Meaning she loses 9 games

[final crag]

all i can think of is .9^10

[alpine sable]

YEah

[final crag]

i feel like i gotta do something with geometric distribution tho rip

https://homepage.divms.uiowa.edu/~mbognar/applets/geo1.html

listen to tthis

p = .10

x = 30

1 - .00424

Bam?

or would x = 27 since she wins 3 in 30 games

that gives u .00581

which might be valid

okay im going with .9^10

[alpine sable]

I mean.

She got .9 chances of losing, then .9*.9 of losing again ... then .9^10

[jovial edge]

How do I do this question

I found the ratio of a: b: c but can’t seem to find the required fraction

[wanton turtle]

what did you find the ratio as?

[jovial edge]

Oh wait I’m overthinking this question

I can just find everything in terms of a and substitue it

[wanton turtle]

yes

[jovial edge]

This is irrelevant tho

[vale wigeon]

so then a : b : c = (1/21) : (1/18) : (1/28)

,w lcm(21,18,28)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[vale wigeon]

a : b : c = 12 : 14 : 9, if you rewrite the ratio to have all integer components

so no @jovial edge it's not irrelevant

[fervent grail]

When (2x³ + 2x² + px ) is divided by (x - 3), the remainder is 2. find the value of p

Pls help

[vale wigeon]

have you done questions like this before?

are you familiar with the remainder theorem?

also @fervent grail you should not post the same question across multiple channels

[fervent grail]

Okay sorry

[fervent grail]

Is the ans -68/3 ??

[vale wigeon]

let me check.

[fervent grail]

Hmm pls check

[vale wigeon]

also why didnt you say right away that you had an answer?

theres a big difference between "please help me with this problem" and "here's this problem, i got this as the answer, can someone check?"

[fervent grail]

Actually I have did this now

And I am new ..... Sorry

Can u pls say that is this ans correct ??

[vale wigeon]

no, p = -68/3 is not correct

if you show your work, i might be able to see where you went wrong.

[fervent grail]

F( x ) = 2x³ + 2x² + px - 2 which is divisible by x - 3
F ( 3 ) = 54 + 18 - 2 + 3x = 2
P = -68/3

[vale wigeon]

wait

there was a -2 term in your polynomial?

you didn't have it at first.

[fervent grail]

Ooh that's a mistake 😕

F( x ) = 2x³ + 2x² + px
F ( 3 ) = 54 + 18 + 3x = 2
P = -70/3

Now is it correct ???

[vale wigeon]

F ( 3 ) = 54 + 18 - 2 + 3x = 2

why the -2 on the left-hand side, and why did the p become an x?

assuming these are both typos, now you have the correct answer.

[fervent grail]

That was a typo

So the ans is -70/3 ??

[vale wigeon]

yes i just told you

[fervent grail]

Ok thank👍

[shell comet]

Can someone please explain to me the process or the techniques? answer is b

[wanton turtle]

A^3 = -I

Cube both sides

it becomes A^9 = (-I)^3

(-I)^3 = -I

[vale wigeon]

satisfaced.....

[wanton turtle]

(since I^n = I always)

then multiply A on both sides

you'll get option B

@shell comet

[real loom]

answer is b for this one?

i get cos2(t-(pi/2))U(t-(pi/2)) as answer

but its not there

[alpine sable]

Guys

What's the answer for htis

The percentage profit

[vale wigeon]

@alpine sable we don't give out answers here.

[alpine sable]

i MEAN like

[vale wigeon]

also this channel is occupied so you'll have to move to another.

[real loom]

@vale wigeon can you help with that one

[vale wigeon]

,w inverse laplace transform se^(-πs/2)/(s^2 + 4)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[vale wigeon]

θ is the unit step function i guess

[real loom]

but theres nothing like that in the given answers

[jagged imp]

trig identities

cos(x-pi)=?

[real loom]

sin x

[vale wigeon]

wrong

cos(x - pi) is not sin(x)

[real loom]

owh cos (x - pi/2) = sin x

[jagged imp]

cos(x-pi)=-cosx

[real loom]

owhh thanks

[wanton turtle]

No idea how to even begin to solve the question (15th)

myself and a couple of my friends are trying our best

[vale wigeon]

the wording of this question leaves something to be desired

[wanton turtle]

is the question itself wrong? i dont think it is because i havent had an incorrect question in this book so far

[vale wigeon]

i'm not saying it's wrong

i'm saying it's difficult to parse

[wanton turtle]

oh ok

i misunderstood

we tried to focus on the orthogonality condition for P

[vale wigeon]

so... $R = P^T Q^K P = P^T PA^KP^T P = A^K$

[ocean seal]

Ann

[wanton turtle]

one friend made Q as equal to A, but he changed the order, which is not correct right?

[vale wigeon]

Q is not equal to A

[wanton turtle]

ye

[vale wigeon]

matrix multiplication is not commutative

[wanton turtle]

yes

[vale wigeon]

however P^T = P^-1

[rough knoll]

can some one help with this?

[wanton turtle]

i dont understand how you did this

[vale wigeon]

@rough knoll channel busy please move

[wanton turtle]

you substituted P that i understand

[vale wigeon]

$Q = PAP^{-1}$ so $Q^K = PA^KP^{-1}$

[ocean seal]

Ann

[wanton turtle]

shouldnt it be P^K . A^K . P^-K ?

[vale wigeon]

no

$(AB)^n \neq A^n B^n$ for matrices

[ocean seal]

Ann

[wanton turtle]

oh

[vale wigeon]

$(PAP^{-1})^2 = PAP^{-1}PAP^{-1} = PAAP^{-1}$

[ocean seal]

Ann

[rough knoll]

ok

[wanton turtle]

ohhh

only the first P and last PT remains

in the repeated multiplication

rest cancel each other out

right?

[vale wigeon]

yes.

[wanton turtle]

THANK YOU

[vale wigeon]

don't call me dude. but you're welcome

[wanton turtle]

oh sorry

thanks again

[crude tendon]

can anyone help me with this:
Find all function f: R->R such that f(xy-1)+f(x)f(y)=2xy-1 for all reals x, y.

[fresh quail]

in the equality, 6y=12x+30 since all 6,12, and 30 are divisible by 6, we directly divide 6y/6=12x/6 +30/6 to get y=2x +5 right? another example is 14y=420, both are divisible by 14 then we divide both sides by 14 so 14y/14=420/14 to get y=30 right?

[crude tendon]

absolutely

[rough knoll]

ok thanks

[fresh quail]

alrighty thank youu

[ocean seal]

PAYR!M9
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[analog terrace]

How many line segments can be formed from 6 given points with no three of which are collinear.

whats the value of n and r here?

6 and 3?

[tame falcon]

How many points do you need to uniquely describe a line?

[analog terrace]

two?

so its 6 and 2?

[tame falcon]

Yes.

[analog terrace]

so what's gonna be the use of "three" in the sentence?

im actually confused lmao

[tame falcon]

If three of the points were to be collinear, the number of unique line segments would reduce

Suppose points A, B, C were to be all collinear

Then you'd get only one unique line through them

But if they were non-collinear, you'd get 3(AB, BC, CA would all be unique)

[analog terrace]

ohhh

i see

thanks

[tame falcon]

No worries!

[analog terrace]

so if it said "no four of which are collinear" the r would be 2 and 3?

[tame falcon]

No, 4 wouldn't make much sense. 2 points are always collinear, so when you say no three of which are collinear, it means that fixing two points, none of the remaining points lies on the line formed by them.

[analog terrace]

i get it now

thanks a lot

[tame falcon]

[sly mantle]

@pastel pelican what did you try?

[alpine sable]

don't really understand how to do this, help !?

[vagrant rover]

Is there are correct answer here? I feel like there is no correct answer.

[radiant pasture]

what is a relative max/min?

the definition of it

[vagrant rover]

A relative maximum point is a point where the function changes direction from increasing to decreasing (making that point a "peak" in the graph). Similarly, a relative minimum point is a point where the function changes direction from decreasing to increasing (making that point a "bottom" in the graph).

^Khan academy

It's not A)

It's not B)

Is it C)? I don't understand exactly how you check for relative min/max

[radiant pasture]

eyeball it

literally

a relative min is a min relative to its near area

not for the entire function

a function like x^2 has one min, which is the absolute min

[vagrant rover]

Um

Okay but do you check from right to left

or left to right

Or does it not even matter

[radiant pasture]

doesn't matter

[vagrant rover]

@radiant pasture What is an even degree function

np

[vagrant rover]

Wait so it could be either C) or D)?

Ohoh

Okay it's not D cause the given graph is an odd degree, not an even degree

So C)?

Cause it looks like it does have one relative minimum. The 2nd and third points on the graph.

[radiant pasture]

If so, show me the relative min

[vagrant rover]

^

[radiant pasture]

2nd and 3rd points
1 min

[vagrant rover]

np

[radiant pasture]

Dude

[vagrant rover]

Wait

1 minut

e

I understand nothing loll

[radiant pasture]

Are you sure you've understood what a relative min is

[vagrant rover]

Yeah, decreasing slope?

[radiant pasture]

No

[vagrant rover]

K then I don't know

[radiant pasture]

A min is a point

one point

[vagrant rover]

Oh

[radiant pasture]

It's why I asked you for the definition

[vagrant rover]

Then the 3rd point only

It's a lower than the point before it

right?

[radiant pasture]

i'll give you a small tip

[vagrant rover]

Is that still wrong??

Oof

[radiant pasture]

for relative mins/maxs

think of a very tiny enclosure around the point of interest

is the point, within that tiny enclosure, the smallest value?

then it's a relative min

relative to the values around it

not absolute

i prefer this definition

some open interval

actually, i'm not a fan of that either

[vagrant rover]

um, so then there is no relative min since the third point isn't less than the first point?

[radiant pasture]

don't think in points

[vagrant rover]

I'm sorry if I'm not udnerstanding

[radiant pasture]

you're thinking in domains

[vagrant rover]

Okay 🤔

[radiant pasture]

see

think of it like this

you have that tiny area

is f(c) the largest/smallest value in that tiny area

[vagrant rover]

Okay sec

When you tiny area

Do you mean the two areas where you drew lines around

[radiant pasture]

yes

the little one enclosed in red

[vagrant rover]

Okay so two tiny areas

[radiant pasture]

and the little one enclosed in green

yes

2

[vagrant rover]

Okay okay

[radiant pasture]

a point relative to its immediate surroundings

not the entire function

have you done derivatives?

at every relative/absolute min/max, $f'(x) = 0$

[vagrant rover]

No, I'm just going back to review math that I never learnded

[ocean seal]

Subdivisions X-1

[radiant pasture]

i see

well in any case

[vagrant rover]

Yeah this is why I'm not understanding much

[radiant pasture]

any positives or negative peaks you see

are relative mins/maxes respectively

when you have x^2

[vagrant rover]

So the green peak is a min and the red is a max?

[radiant pasture]

yes

also, look at this graph

[vagrant rover]

And the green is less compared to the red

[radiant pasture]

how many mins/maxes does this have

[vagrant rover]

Yes

One min?

[radiant pasture]

you don't compare those points with each other, they're separate

yes, one min

where

[vagrant rover]

(0,0)

[radiant pasture]

correct

is it a relative min, or an absolute min?

[vagrant rover]

Thank god, I thought I said something wrong

[vagrant rover]

Idk what the difference is

absolute means that there is nothing around it that is less and relative means it is less relative to itwhat is around it?

THe peaks around it?

[radiant pasture]

no, not the peaks

the values

you have a function

a continuous one

[vagrant rover]

right

[radiant pasture]

f(x) = y for every x in the function's domain

in your graph, the points are just marked for easy reference

[alpine sable]

Is anybody here good at probability?

[radiant pasture]

doesn't mean the function does not return for every other value

[radiant pasture]

1. don't ask to ask, just ask
2. go to an unoccupied channel

[vagrant rover]

🤔 right

[alpine sable]

You good at probability?

[radiant pasture]

what did i literally just tell you

[alpine sable]

I asked I didn’t ask to ask

My bad

[radiant pasture]

yes

[vagrant rover]

Lmao

[radiant pasture]

also

go to some other channel

[alpine sable]

I asked to get help not to ask

Man..

[radiant pasture]

#rules are a thing

[alpine sable]

I love you

[radiant pasture]

anyways

[alpine sable]

[radiant pasture]

@vagrant rover

moving on

[alpine sable]

helppp

[vagrant rover]

[radiant pasture]

https://www.youtube.com/watch?v=GaltHJF6WyI

[vagrant rover]

Alright, let me watch

[radiant pasture]

that's physics, not maths

i'm afraid i can't help

can't vouch for anyone else, but this is a maths server not a physics server

[vagrant rover]

Alright one sec

So you're tellin' me that x=-8 isn't a relative minimum?

The only relative minimum?

@radiant pasture

[radiant pasture]

-8 or +8?

[vagrant rover]

+8 my bad

Wait

Isn't relative minimum value written using the Y value?

So y = 0 is the relative minimum

right?

[radiant pasture]

we say a function f shows a relative min at x

referring to the position along the x axis

[stable glen]

Hi is anyone still using the channel ?

[wanton turtle]

you can ask your question @stable glen

[stable glen]

Thanks

If $A \subset [0,1]$ and A is a closed set, and that the convolution of f with g is continuous on R (f is the indicator function of A and g is the indicator function of -A), how can I deduce that the set A-A contain a neighborhood of 0?

[ocean seal]

Perrier citron

[stable glen]

I can see how that true since A-A is basically right shifting -A by the values of A

But i don't understand how i can deduce the result from the fact that the convolution is continuous

<@&286206848099549185>

[alpine sable]

Hi everyone

Let's find you it's true or false (if false why?)

[wanton turtle]

,rotate

[wanton turtle]

this is just an AP

with common difference 1

[alpine sable]

AP in English is?

[wanton turtle]

Arithmetic Progression

[alpine sable]

OK I translated

OK thanks

@wanton turtle

[wanton turtle]

anytime

[peak lantern]

so i have this question

and im stuck on this part of the question

"when does the balloon have the same speed as it does at 4:00pm"

[wanton turtle]

since this is a distance-time graph the speed is found through the slope

so we try to find where the slope matches

here, we need to compare only the MAGNITUDE of the slope since it's speed and not velocity

12 30 seems to have the same slope

[peak lantern]

this is what i had so far

https://prnt.sc/12b1f4b

[alpine sable]

Which function is not represented

A) f (x) = 1/x
B) f (x) = exp(x)
C) f (x) = log(x)
D) f (x) = x^3

[wanton turtle]

im not really sure how i can answer in a proper way, i'll let other help you

[peak lantern]

did u say 12:30 cause thats when the slopes look similar

to 4pm

[wanton turtle]

yes, the magnitude looks similar

[alpine sable]

@alpine sable so that's the answer A

[honest echo]

In Chi Squared GOF tests, do both the observed and expected values need to be over 5?

Or does that rule only apply to expected values?

[alpine sable]

the sum of three consecutive numbers is 90. what is the smallest of the three numbers

[stone shard]

x + (x+1) + (x+2) = 90

x would be the smallest

You have to solve for x

[swift igloo]

not sure where to start with this

[alpine sable]

try difference of squares factorization on the LHS

[swift igloo]

uhh... doing that, i've just proved that it's possible apparently? p = 3, q = 2

[alpine sable]

looks like the question is wrong then

that's odd

[swift igloo]

lol

[vale wigeon]

[swift igloo]

a linear function would be applying y = mx+c. so multiplying the values in the x row by something, and adding something, gives the value in the bottom row

you can then setup either a simultaneous equation or just eyeball it

[remote hound]

ok

[normal jasper]

Could someone tell me what kind of problem this is called

[noble sinew]

Its binomial coefficient

[limpid spade]

Permutation

[normal jasper]

Thanks

Would the answer be 10?

[alpine sable]

,w 5 choose 3

[ocean seal]

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[noble sinew]

yep exactly

[normal jasper]

Alright thanks

,w 1000 choose 1000

[ocean seal]

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[normal jasper]

nice nice

Could someone double check I got this right

I used the binomial expansion theorem

[alpine sable]

in general $n \choose n$ = 1 as well as $n \choose 0 $ = 1

@normal jasper

[noble sinew]

yep sounds right, what did you get?

[ocean seal]

xi64

[normal jasper]

17010

[noble sinew]

yep

[normal jasper]

Alright

[muted whale]

does anyone know how to do this problem

[glass lichen]

domain of a composite function is the intersection of their domains, excluding when the denominator function is 0

[stable dune]

can someone help me out with this?

[crude tendon]

A) 13.4

[alpine sable]

Anyone know the answers?

Please I’ll buy you nitro

[stone shard]

Use pythagorean theorem
sqrt(14^2 - 4^2) = 13.416407....

[stone shard]

I told you how to do it in #help-1

[alpine sable]

Nobody is responding

[stable dune]

i got 14.6

[alpine sable]

They’re tryna expose me rather than help

Like wyd

[stone shard]

how? what did you do?

[alpine sable]

Anyone know this

Anyone k

[stable dune]

a^2+b^2=c^2
4^2+b^2=14^2
16+b^2=196
add 196 and 16 then find the square root which is 14.6 rounded to the tenths

[stone shard]

People in this community teach you how to do math, they dont just give you the answer

[stable dune]

^

[alpine sable]

im not saying give me the answer

and they do give you the answer

they explain

see look what you're doing

[alpine sable]

No.

you're trying to expose rather than help

COULD YOU HELP ME PLEASE

[stable dune]

im confused

[alpine sable]

4^2+b^2=14^2
16+b^2=196
b^2 = 180
b = sqrt(180)

You don't add them togethee

[stable dune]

ah okay thank you

[alpine sable]

You subtract at the last step

Otherwise it's looking fine.

,w calc sqrt(180)

[ocean seal]

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[alpine sable]

answer ^

[stable dune]

ah thank you

[alpine sable]

np

[sick kettle]

after i find summation, i multiply it by 2/3?

[stable dune]

never mind

found the answer

[alpine sable]

9^2 + 15^2 = c^2
81 + 225 = c^2
310 = c^2
c = sqrt(310)

,w calc sqrt(310)

[ocean seal]

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[tawdry urchin]

Can yall please assist me

[stone shard]

Bruh 310 = c^2 what?

[alpine sable]

What?

[tawdry urchin]

oh shit did i interfere

[stone shard]

306 = c^2

[stone shard]

Its fine

[alpine sable]

Oh yeah I did the calculation in my head quick

[stone shard]

Lol, always check

[alpine sable]

so i might've messed something up

it should give a whole number as well

[stone shard]

You dont want to do that in a test

[alpine sable]

,w calc sqrt(306)

[ocean seal]

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Requested by Shaky#0505

[alpine sable]

Should be 17

[fresh wigeon]

how do i do this

[alpine sable]

you know how to solve $\left(\frac{a}{b}\right) - c$ ?

[fresh wigeon]

i think

i just dont know how to join those things

[alpine sable]

uh

the LHS is the thing you want to get to the RHS

so

[ocean seal]

xi64

[alpine sable]

you can multiply the denominator of the first fraction with the c term and then get a global denominator

doing that , you should quickly see the RHS

and btw the root will be removed since 1/2 power + another 1/2 power equals a full 1 power which means no square root

[fresh wigeon]

whats the c term

[tender portal]

root 3x+5

[fresh wigeon]

can someone plz write it out for me

im confused

[tender portal]

Am I supposed to use the derivatives rules here?

[gray isle]

yes

[tender portal]

Uh a little confused to how

[gray isle]

chain rule

[tender portal]

I think i got a and d right but b and c confuse me

Did I do them wrong because I was supposed to use the chain rule?

[gray isle]

yeh, you need to use the chain rule

[tender portal]

so I can't just plug the numbers in

I don't understand the notation on c either

what does g^2(x) mean?

[gray isle]

that notation is ambiguous and they should really state what it means when they write it

[gloomy lintel]

I assume it’s g(g(x))

[gray isle]

its usually interpreted as g(g(x)), but may also be viewed as (g(x))^2

but seeing as you have g(g(x)) in part d)

[gloomy lintel]

Yea they shouldn’t really write it like that tbf

[tender portal]

I think it's g(x)^2

just cause the next question is g(g(x))

[gray isle]

evaluated at the same value,
you should interpret it as (g(x))^2

[tender portal]

Alright

[gray isle]

part d) would be better if you added some parentheses

and you did apply chain rule for that question

[tender portal]

Oh yeah sorry

[gray isle]

so do the same for b and c

[still hemlock]

hello can somebody help me with this

[tender portal]

Is this right now?

[gray isle]

at a glance yeh

[tender portal]

alright

if you have time to take a closer look it would be much appreciated

just tryna make sure I get all the details right before the test

[chilly garden]

hello

i am trying to create a study on the different rating systems for zero-sum games

i've found a few research papers already

but before my school approves it, they want to know how im going to approach it

but im not sure what to put in for these details

here's some BG info

[dense violet]

Help with part b

[stone shard]

Perimeter = 2 ( length + width )

[sacred laurel]

no cap?

[stone shard]

no cap

[tender portal]

<@&286206848099549185>

[alpine sable]

guys

[stone shard]

There is a solution region

[alpine sable]

Is this how do u calculate the fourier coeficients of a function?

$c_n = \frac {1}{2\pi} \int_{0}^{2\pi} e^{(-in\theta)} f(\theta) d\theta$

[ocean seal]

nosequepasa

[stone shard]

Area under the line is distance
Express the area in terms of v and let it equal to 2500
And you can just solve for v

[alpine sable]

you can man

how do you remember all these maths

[wanton crow]

Could iget help finding the preimeter of bcde

[stone shard]

Well, its a square so you can find the perimeter if you know the length of one of the sides

Consider using the pythagorean theorem

[pastel mauve]

i need help with the equation

[regal whale]

can someone solve this for me?
find a Linear equation that pass (1,5,1) and it's equal with this vector V=-1i+5j-1k

[pastel mauve]

can someone help me w mine first lol i asked first

[alpine sable]

in the first round there are 64 teams and 32 matches, so G(1)=32
after the first round the 32 losers get eliminated and the 32 winners move on
2nd round we have 32 teams and 16 matches, G(2)=16
so every round the number of matches gets halved
see if you can figure out an exponential function that would model this

[pastel mauve]

what i did was divide by two each time

to get the first answer

so uh

0.5(64)^x?

[alpine sable]

how did you get that

[pastel mauve]

wait no

[alpine sable]

try not to throw out wild guesses

so we are multiplying by 1/2 every time

[pastel mauve]

yeah

[alpine sable]

so what should the base of the exponential be?

[dense violet]

Help with part (b) and (c) pleasee!!

[alpine sable]

repost your question in an unoccupied channel

this one's busy

[pastel mauve]

i have no idea im trying to think

[alpine sable]

well we're multiplying by 1/2 every time so the base is 1/2

[pastel mauve]

1/2(64)

but i dont know

[alpine sable]

no

[pastel mauve]

what the exponent

would be

how do i make it go down every time

[alpine sable]

the base of an exponential function

(1/2)^x

[pastel mauve]

oh

okay

[alpine sable]

then you just need to make sure the starting points match

so our function will look like a(1/2)^x for some number a

[pastel mauve]

thank you so much

[alpine sable]

64*(1/2)^x works

[pastel mauve]

how about this

h(22)^(14/100)?

[alpine sable]

no

i feel like you're just guessing randomly

[pastel mauve]

im not

[alpine sable]

try to think about what happens every day

[upper mesa]

help?

@alpine sable

[alpine sable]

every day there is a 14% decrease

[upper mesa]

You don't have to hold hands for me haha

[alpine sable]

channel is occupied

[pastel mauve]

each hour he gets 14% of the 22mg

so we have to find 14 percent of 22

[alpine sable]

no

its consumed at a rate of 14% every hour

[upper mesa]

Other channels are inactive so I'll just wait

till ur done with him

[alpine sable]

so every day there is a 14% decrease

100%-14%=86%

[pastel mauve]

oh mybad i read it wrong

22(0.14)^h

let me try that equation

[alpine sable]

this isn't it

[pastel mauve]

it should be the other way

like thats how much is being used

hm

22- 22(0.14)^h

[alpine sable]

every hour 14% of the magnesium currently in the body is removed

so that means 86% of the magnesium in the body remains
so every hour we multiply the amount of magnesium in the body by 86%=0.86

does that make sense?

[pastel mauve]

oh

so 22(0.86)^(h)

[alpine sable]

no

[pastel mauve]

.

what

[alpine sable]

oh yes

you edited it

now it's correct

[pastel mauve]

yea my bad i was testing it

im sure there are calculators that can do that ^

[tender portal]

any ideas anyone

[proper wyvern]

Ik #1 is wrong and I fixed it help with #2 and #3?

[glass lichen]

is it a test?

[proper wyvern]

no its hw

[rocky tinsel]

Can someone help me with this

[glass lichen]

Ok well what's the probability the first letter is A?

[rocky tinsel]

Oh is this channel being used

Well my question was, how am I supposed to work anything out without OA or AB

[pseudo summit]

3 + 5²² = 8²²?

[glass lichen]

clearly not

[alpine sable]

Is it better to ask question in this channel or #prealg-and-algebra

[hardy sparrow]

can soemone help mee

[glass lichen]

whatever you wish, just follow the rules

[alpine sable]

0.7^-x = (0.7^-1)^x is this because -x is -1x?
and (0.7^-1)^x = 0.7^(-1*x)

[pseudo summit]

I cant remember this properties

[glass lichen]

$a^{bc}=(a^b)^c=(a^c)^b$

[ocean seal]

moshill1

[alpine sable]

Thanks :)

[rocky tinsel]

bump

[glass lichen]

so your first line is right $h(x)=H(\sin{x})-H(0)$

[ocean seal]

moshill1

[glass lichen]

however finding h' was wrong

cause you didnt use chain rule and didnt differentiate a constant correctly

$h'(x)=\cos{x}H'(\sin{x})$

[ocean seal]

moshill1

[cyan saddle]

Hi, I would like to know that's this symbol

[gloomy lintel]

For all

So for eg you can say for all x in the set of real numbers

P convenient over having to write out ‘for all’ in words

[cyan saddle]

Great thanks a bunch

[glass lichen]

you have to differentiate a composite function with chain rule always

[final crag]

is this binomial distribution?

n=34, p =1/7?

[oblique stirrup]

how do I put tan(30) into my calculator and get √3/3? If i put it in normally, I just get 0.57.

[wanton turtle]

If you simplify sqrt3/3, you'll get the same value

I'm pretty sure most calculators don't show 1/sqrt3 as the value for tan 30

[gloomy lintel]

I think it depends which calculator you have

Mine always gives it to me as a surd

But with a rationalised denominator

[wanton turtle]

Oh OK

Didn't know that

[oblique stirrup]

ok but using decimal normals would scew my numbers a bit because its rounded

[wanton turtle]

Be sure to memorize the values for the sin cos and tan functions for the angles 0,30,45,60,90

[keen mason]

\cos\left(0.5x+45\right)

2cos(0.5x+45)=3^0.5

how would u simplify that

[alpine sable]

$\cos(0.5x+45) = \frac{\sqrt{3}}{2}$

[ocean seal]

Em

[keen mason]

resolve left forces

so

a^2=b^2-c^2-2bccosA

idk bro

im also special

==32

32.688

so thats resolve left

imma guess that t=29

coz like its halfway through

no

Im not

trust trust

IDK

FAM

Wait wait

Do u have the answers with u or no

OK

dont tell me

lemme figure it out

and tell me if its right

[gloomy lintel]

Think vertical and horizontal components

It’s a lot easier to see then

Resolve vertically to get psin x= something

[keen mason]

OK NGL

im special

[gloomy lintel]

Resolve horizontally to get pcos x= something else

Then manipulate one for the other

You’ll get a value for tan x

Find x and sub it to either one to find p

Yea

Oh crap lol didn’t even realise they used t

[runic vine]

Even tho this is math does anyone know chemistry ?

[abstract hedge]

@runic vine #old-network

[next void]

Can someone explain how to do this?

[alpine sable]

,av

[ocean seal]

NRG Suger#9251's Avatar

Click here to view the image.

[next void]

<@&286206848099549185>

[spark ibex]

can someone verify i did question 5 correct?

<@&286206848099549185>

[alpine sable]

@spark ibex b part is wrong i think

[spark ibex]

wait really?

[alpine sable]

the position function has local extrema at the points where velocity is = zero

because that's the point at which it starts moving in the other direction

unless tha graph would "bounce off" the x axis

[spark ibex]

wait im confused lol

[alpine sable]

you can think of it like this: as long as velocity is positive, the object is moving in the positive direction, so at the moment when velocity becomes negative, position is the most extreme

[spark ibex]

here is the actual graph if its better to understand from this

so just a?

[harsh swallow]

yeah so you have the velocity graph

but the questions

[alpine sable]

think about it: if velocity is positive, what is happening with position

[spark ibex]

increases

[alpine sable]

yes!

so even after c, velocity is still positive

[spark ibex]

is my part a right tho?

[alpine sable]

yes

[spark ibex]

ok

let me see lol

[tawdry bough]

@spark ibex when you throw a ball in the air, the highest point is when velocity is zero

same with the lowest point

aka extrema

[spark ibex]

is it 0,b,d?

[alpine sable]

yes

and i don't know if you should also consider the ending point

[spark ibex]

f?

[alpine sable]

yes

[spark ibex]

the graph isnt at 0 on f tho

[harsh swallow]

they stopped measuring while it was still moving

[spark ibex]

so dont include f right

just 0,b,d

[harsh swallow]

at f the object is still moving in the negative direction

[alpine sable]

but i think it's just as much of an extreme as 0

[harsh swallow]

slowing down but still moving

[spark ibex]

what would you guys do

i was just not gonna include f

[harsh swallow]

i would leave out f

[alpine sable]

idk let katharine decide

[spark ibex]

im pretty sure im right on 4 but could you guys verify it real quick

[harsh swallow]

the function doesn't have a global maximum

[alpine sable]

it seems to me that there are two absolute minimums

[harsh swallow]

it goes up infinitely

i forgot if that counts

it has 2 minimums

[spark ibex]

oh wait i didnt update it hold on

[alpine sable]

@harsh swallow where does the function go infinitely up?

[spark ibex]

here it is

[harsh swallow]

x<0 and x > 3

[alpine sable]

the question says "on interval [0,2]"

[harsh swallow]

sorry didn't read

[spark ibex]

how does that look now

[alpine sable]

it seems fine now

[harsh swallow]

if the interval is [0, 2] then x = 3 doesn't exist

[alpine sable]

oh yes of course

katharine is right

[spark ibex]

so just at x=0 for min and x=1 for max

[harsh swallow]

yeah

[spark ibex]

not both x=0 and 3

[alpine sable]

yes

no not both

[harsh swallow]

yeah because x = 3 is not in the interval [0, 2]

[alpine sable]

so turns out you were right at the beginning 🙂

[spark ibex]

for question 2b i think i did it wrong

[alpine sable]

seems fine to me

[spark ibex]

mathway has the answer as this which is confusing me

[alpine sable]

your solution is correct

they made a mistake

thats the function at a larger scale

[harsh swallow]

from -infty to -8 the slope of the function is positive

then -8 to 0 it's negative

then 0 to +infty is positive

[spark ibex]

man mathway is slacking

i was so confused i was like im pretty sure this is correct

hey @harsh swallow @alpine sable

for that end of the graph would you say that it is infinity?

or it stops

[harsh swallow]

the graph just stops

[alpine sable]

what infinity?

[harsh swallow]

as if they stopped measuring

[spark ibex]

ok i wasnt sure if the graph keeps going or not

[harsh swallow]

or stopped notating it on the graph

[north hemlock]

can somebody help me with b?

I was thinking something like this:

$$V(x)=A_s(x)\cdot h(x) =\int_0^{2\pi} [4-f(x)]dx\cdot \int_0^{2\pi} d(x) dx$$
$$V=\int_0^{2\pi} [4-(\cos{x}+2)]dx\cdot \int_0^{2\pi} [2\cdot \sin{(0.5x)}]dx$$

since Volume is just the area of the section times the depth

and since they're both functions of x, we integrate both and then multiply them?

[ocean seal]

Jukelyn

[harsh swallow]

i cannot see any problem with this

[north hemlock]

Me either

I think it's correct

but I'm not 100% sure and so that's why I'm here 😅

actually

I need to be more confident

this is correct.

I like my answer

it's 32pi

[silent geyser]

Anyone know how to do this?

[ocean seal]

Chai T. Rex

Chai T. Rex

[oak chasm]

Then, you have a one variable expression.

[north hemlock]

plus 80?

[oak chasm]

Then you can take the derivative and find the minimum points.

Oh, yes.

[north hemlock]

haha

oops

[ocean seal]

Chai T. Rex

[silent geyser]

Thanks bro

[oak chasm]

No problem.

[silent geyser]

So I would plug in 4x^2 +80 into the root and derive right

And then set to 0?

[ocean seal]

Chai T. Rex

[oak chasm]

Yes, that's right.

That'll tell you the extreme points.

[silent geyser]

Ah ok

I appreciate it

[oak chasm]

You're welcome.

[silent geyser]

Wait isn’t the only x value 1

[oak chasm]

What did you get for the derivative?

[silent geyser]

I got this as the derivative set to 0 and got 1 on Symbolab