help-0

[high furnace]

basically i need to solve one of these two, so either for amplitude or phase

phase = acos((sample2-sample)/((-((sample-sample2)*sec((Omega/2)+phase))/Omega)*Omega)) - Omega/2

amplitude = -((sample-sample2)*sec((Omega/2)+(acos((sample2-sample)/(amplitude*Omega)) - Omega/2)))/Omega

sorry had a mistake in the above

http://notepadcalculator.com/s/d6b9ccc8ac3474adb58207af84109b7f0a9f85fe

maybe like that

solve for alpha or phi

[dire prairie]

A square has a semicircle drawn on one side, as shown in the figure if the side of the square is 14cm. Find the perimeter of the figure?

can someone help

[alpine sable]

@dire prairie you know the formula for the perimeter of a circle?

[high furnace]

maybe it's unsolvable and i just have to do this https://ccrma.stanford.edu/~jos/sasp/Sinusoidal_Amplitude_Phase_Estimation.html#eq:Ascrhopt

[alpine sable]

can somone help me

[limpid spade]

Yrs

[dreamy timber]

can i get some help??

[worthy verge]

@dreamy timber have you tried googling for a specific calculator

Because it looks hella advanced whatever youre doing

[dreamy timber]

yeah nothign seems to work

they just gave it to us

[worthy verge]

What topic is that @dreamy timber

Calc?

[dreamy timber]

discrete math

[worthy verge]

Oh

#discrete-math

100% quicker than question channels

@dreamy timber gl

[dreamy timber]

thankyouu!

[solid plume]

if I have this inequality: 0<= 2k <= 100, can I divide the whole thing by 2 and end with 0<=k<=50?

[high furnace]

yes

[alpine sable]

can somone help me

How do I solve for X?

[vale wigeon]

how familiar are you with logarithms?

@alpine sable

[pallid sail]

so i figured out how to find volume of things using integrals

however sometimes i dont guess the upper bound and lower bound correctly

like i switch their places and my result becomes negative

like in this case, i thought that the upper bound was 3 and lower bound was 1

and my volume ended up being negative

so how do i get the placement of the bounds right?

[alpine sable]

the volume of the solid of revolution obtained by rotating the black region around the x-axis?

[pallid sail]

yeah

[alpine sable]

can you show the equations and your work

[pallid sail]

this was the integral i solved

the number i got at the end was right, but it was negative

when i ended up switching the bounds i got it right

[vale wigeon]

you got the function order wrong

not the bounds

both lead to a (clean) sign error

but your fix is more like making 2 wrongs make a right

than actually righting the wrong you did

[alpine sable]

[pallid sail]

oh yeah the pi was supposed to be outside of the integral

[vale wigeon]

no not that

you should have had (4-x)^2 - (3/x)^2

[alpine sable]

when you're using the washer method you need pi(R^2-r^2)

[vale wigeon]

as opposed to (3/x)^2 - (4-x)^2

[pallid sail]

to be honest that makes absolute sense and im just dumb

thanks

[alpine sable]

Is this occupied?

If not,

What does 10 represent?

[gray isle]

do you know how wipers work?

[alpine sable]

Yeah I think so

[gray isle]

(diagram is not to scale)

the whole horizontal part would be the mechanism
the red part would be the blade

the green shaded region is what can be wiped

[alpine sable]

Oh!!!!!!

😔 ✋ Ive been studying math for hours and Ive lost my common sense Thank you

[visual fractal]

a company has 180 workers. their salary is "m". After they hire 20 more workers, the salary goes down by 3.5%. The new salary can be "s". I need to get s/m. How do i solve this? Thanks

[alpine sable]

hello

stupid question

but

is x³/3x = x²/3

Wait its occupied rn by ugudango

oh

[alpine sable]

You mean the mean/average salary is 'm' right?

Not cumulative or smth weird

[dire geode]

?

[alpine sable]

Do you understand how the sine rule works? Just asking cuz it makes it make more sense and so you'll be much less likely to 'forget' it

Anyway if you don't care, use the sine rule and the fact that sum of angles of triangles = 180

[dire geode]

no 🙂

[alpine sable]

lolol

here ya go

Have you used this before?

[dire geode]

really no because now i know some rules

[alpine sable]

if you want an intuition for it the logic is pretty straight forward; the angle is directly proportional to the corresponding side. just picture in your mind what happens to the opposite side of those angles as the angle increases and decreases

and since sum of angles stays 180, as one angle changes in size, the others must change an equal amount

hence those ratios stay equal

[worthy verge]

Okay

Cools

[alpine sable]

and solving the question is just plugging the numbers in and some algebra...

[worthy verge]

I like bjhorseman too

It was sadge ending 😭

[alpine sable]

so to go down by 3.5% means to be 96.5% of the original salary right? (since 100% - 3.5% = 96.5)
that means m=0.965*s

then just rearrange for s/m. you should get 1/0.965

@visual fractal ^

[alpine sable]

all of s6 was so much sage lmao

best show ever though

[worthy verge]

😭

He's just damaged mentally

Broken man-horse

[alpine sable]

well

[worthy verge]

This topic is on complex numbers in rectangular form? Lol

[stuck kestrel]

complex conjugate

[worthy verge]

Yeps

[alpine sable]

equate real and complex parts in 0+j0=-3x-2+j(y+2)

[stuck kestrel]

well i think this channel is busy

[worthy verge]

Er

[alpine sable]

*imaginary

what

[worthy verge]

Sec

[alpine sable]

what

[vale wigeon]

laz. calm down.

[worthy verge]

Kalm

Thanks for help dud

I'll be running along nao

[hexed glacier]

i want to try solvng the question myself, but

how do i find f(z), i am still quite shaky with laurent series

erm, this is taken

[civic vigil]

Oh im sorry

[hexed glacier]

i suppose if i remove (z-i)^k, i will get the terms for a_k? then i am lost

like why does k begins at -5? and not 0

[alpine sable]

An ice cream shop offers two ice cream cones. The waffle cone holds 12 ounces and is 5 inches tall. The sugar cone also holds 12 ounces and is 8 inches tall. Which cone has a larger radius? Explain your answer.

help

[oak chasm]

@alpine sable What's the volume formula for a cone?

[alpine sable]

the same as a cylinder and divide by 3

(pi R^2 h)/3

@oak chasm

[oak chasm]

,w volume of cone

[alpine sable]

if you're going to suggest to solve for r

I don't think that's what the question wants me to do

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Chai T. Rex#7323

[alpine sable]

yes

I was right, no?

[oak chasm]

Yes.

So, if the volume stays the same and the height increases, what happens to the radius?

[alpine sable]

the radius decreases?

I'm just guessing

[oak chasm]

Right.

[alpine sable]

why is that?

[ocean seal]

Chai T. Rex

[alpine sable]

ah ok

I think I know how to solve the problem now

thanks

[oak chasm]

You're welcome.

[snow tundra]

hey is anyone free to do this question with me

What is the amount of the excise taxes charged to a seller who sells a property for $143,250?

im just not sure how u know what the excise tax is tbh

[vale wigeon]

sounds more accounting than math

[carmine lion]

$\cos3\theta+\cos\theta=\cos2\theta, 0\leq\theta\leq\pi$

how do i go about solving this equation

[woeful pulsar]

probably sum to product

[ocean seal]

abe

[carmine lion]

which one

i tried the cos(a)cos(b)

[vale wigeon]

well what do you have a sum of here

it's a sum of cosines

[carmine lion]

i have a sum of cosines

[vale wigeon]

cos(a) + cos(b)

[carmine lion]

OMFG

why am i so blind

[carmine lion]

i get to this step

$\cos2\theta\cos\theta-\sin2\theta\sin\theta+\cos\theta$

[ocean seal]

abe

[vale wigeon]

bruh

[carmine lion]

should i convert to sin^2 or cos^2

[vale wigeon]

i said cos(a)+cos(b) not cos(a+b)

sum to product

[woeful pulsar]

erm...

yeah sum to product, not cos angle addition formula

[carmine lion]

lemme show u working

[vale wigeon]

no need

i know exactly what you did

[carmine lion]

huh

i used the sum to product thing right

[vale wigeon]

you wrote cos(3θ) as cos(2θ+θ)

[carmine lion]

or did i do the other way

[vale wigeon]

NO YOU DIDNT

you didnt use the sum to prod formula

[carmine lion]

i used product to sum

[vale wigeon]

no you didnt use that either

[carmine lion]

??

[vale wigeon]

you used the angle sum formula for cos

you used $\cos(a+b) = \cos(a)\cos(b) - \sin(a)\sin(b)$

[ocean seal]

Ann

[vale wigeon]

you were meant to use $\cos(a) + \cos(b) = 2\cos(\tfrac{a+b}{2})\cos(\tfrac{a-b}{2})$

[ocean seal]

Ann

[carmine lion]

oh

i changed the LHS into the sum side

[carmine lion]

from the formula sheet i have

the closest thing i have is this

2sinAcosB = sin(A+B)+cos(A-B)

[vale wigeon]

b r u h

[carmine lion]

im literally new to this

[carmine lion]

:|

[woeful pulsar]

okay looks like the formula sheet might not have sum to product

[carmine lion]

mhm

i only have compound and double angle

and product to sums

not sums to products

[carmine lion]

any way of going about this

[woeful pulsar]

you can learn how to derive it

$\cos(a)=\cos(\tfrac{a+b}{2})\cos(\tfrac{a-b}{2})-\sin(\tfrac{a+b}{2})\sin(\tfrac{a-b}{2})$

[ocean seal]

Element118

[woeful pulsar]

$\cos(b)=\cos(\tfrac{a+b}{2})\cos(\tfrac{a-b}{2})+\sin(\tfrac{a+b}{2})\sin(\tfrac{a-b}{2})$

[ocean seal]

Element118

[woeful pulsar]

are these obvious?

[carmine lion]

nope

[woeful pulsar]

they are simply your cos(a+b) formulas with different values

[carmine lion]

why /2

[carmine lion]

can you walk me through the steps of how its the same

or how u got there

[woeful pulsar]

apply cos( (a+b)/2 + (a-b)/2 )

[carmine lion]

$\cos(\frac{a+b}{2} + \frac{a-b}{2})$

[ocean seal]

abe

[woeful pulsar]

yeah

[carmine lion]

ok

wait

isn't that just cos(a)

[woeful pulsar]

yeah but what if we use the formula for cos(x+y)?

[carmine lion]

u get

$\cos{(\frac{a+b}{2})(\frac{a-b}{2})}-\sin{(\frac{a+b}{2})(\frac{a-b}{2})}$

[ocean seal]

abe

[carmine lion]

that

[woeful pulsar]

missing cos and sin

also do it for $\cos(\frac{a+b}{2} - \frac{a-b}{2})$

[ocean seal]

Element118

[carmine lion]

$\cos(\frac{a+b}{2})\cos(\frac{a-b}{2})+\sin(\frac{a+b}{2})\sin(\frac{a-b}{2})$

[ocean seal]

abe

[woeful pulsar]

what happens when you add them together?

cos(a)+cos(b)=?

[carmine lion]

u get $2(\cos(\frac{a+b}{2})\cos(\frac{a-b}{2}))$

[ocean seal]

abe

[carmine lion]

right?

cuz the 2nd terms of the two cancel

[woeful pulsar]

yeah

that's the identity you want to use

now apply this identity to the question you have

[fathom wind]

Can someone help me if its true or false

[woeful pulsar]

does it make sense?

if it does try an example

if it works try to prove it

[fathom wind]

Im guessing it would be true?

[woeful pulsar]

did you try an example?

what example did you try?

[fathom wind]

How would I try an example?

[woeful pulsar]

pick a simple function f

[fathom wind]

Oh okay thanks

[gentle ocean]

Can someone help me with this question

[chrome salmon]

dy/dx=1 then

[gentle ocean]

?

confusion

[chrome salmon]

Angle of inclination at that point is 45°

Thet mean dy/dx =1

[gentle ocean]

yes

but

the answer

in the book

says

[chrome salmon]

And dy/dx = 4x²+k

Wait

At point (-2,5) we have dy/dx = 4(-2)²+k=1

[gentle ocean]

4x^3/3 -15x -14 1/3

[chrome salmon]

Ok ok

See the steps

[glass lichen]

$\tan{\theta}=m$

[chrome salmon]

4(4)+k=1

[ocean seal]

moshill1

[chrome salmon]

16+k=1

So k=-15

Then dy/dx = 4x²-15

[gentle ocean]

oki

[chrome salmon]

Which gives y=4/3 x³ -15x +c

[gentle ocean]

then i find anti-derivative of that

right

[chrome salmon]

Yws

[gentle ocean]

OK

TY TY TY

[chrome salmon]

Now they gave us (-2,5)

So substitute to get c

[gentle ocean]

Then is sub values

Yes

THANK YOU SO MUCCHHH

[alpine sable]

hello

I want to know the method to calculate this with a calculator please.

[glass lichen]

is x times or a variable?

[alpine sable]

variable

is that a nine or a g

[gray isle]

wdym by calculate

[alpine sable]

nine

😅

[gray isle]

$f(9) = \frac13 x 9^3 - 9x9^2 +4$?

[ocean seal]

ℝamonov

[polar whale]

Is this f(g)=(g^3)/3 + 9g^2 +4

Oh

Ok

[gray isle]

looks like a complete piece of trash

do you have the original question?

[polar whale]

I think this was the question

Maybe

[gray isle]

they said that g looking 9 was a 9

[alpine sable]

yes that’s right I know the result it’s -482 but I don’t know the method to do it on a calculator

[polar whale]

But that looks wrng

[gray isle]

what also said that multiplication looking x was the variable x

[polar whale]

Oh

[glass lichen]

cause there's no method to get a number if x is a variable

[polar whale]

How did U get a result if there is a variable?

[gray isle]

do you have the original question?

[alpine sable]

https://youtu.be/gge4xdn6cFA?t=1325

[gray isle]

were you perhaps given:
$$f(x) = \frac13 x^3 -9x^2 + 4$$
and asked to find $f(9)$

[ocean seal]

ℝamonov

[polar whale]

Hmm could be

Otherwise the question does make sense

[glass lichen]

the x is times, the g is 9

[gray isle]

in which case, your response to

is x times or a variable?
should have been times

[alpine sable]

This is if the professor does not show the calculations but directly the result. I left the school benches a long time ago and I don’t know how to do it on a calculator

[polar whale]

Yea

[gray isle]

in which case its just a simple problem of multiplication, division, addition and subtraction

[polar whale]

Yea

[alpine sable]

so 1 on 3 is 1/3

[gray isle]

wdym by 1 to 3

[polar whale]

Yup

[alpine sable]

ho

[gray isle]

well 1/3 is what's written...

[alpine sable]

so I divide 1 by 3

[polar whale]

-_-

No

That would make it complicated

[alpine sable]

ha ok

[gray isle]

that implies that you plan to do stuff with a calculator

so I'm gonna tell you to keep your hands off it right now

[polar whale]

U are asked f(9) so just substitute X with 9 in the given polynomial

And then just simple calculations

If u need I can write it out.

Yo @gray isle

Want to try out a problem?

A good problem

[alpine sable]

yes

thx

[polar whale]

Kk wait a bit

[alpine sable]

but I wish I could do it in a calculator

[polar whale]

Try the middle question

[gray isle]

$f(9) = \frac13\cdot 9^3 - 9\cdot 9 ^2 + 4$ \
note that i used the multiplication dot: $\cdot$ instead of $\times$ to avoid confusion with the variable $x$

[ocean seal]

ℝamonov

[polar whale]

Do u know how to use a calculator?

Sry not trying to be rude

U can ofcourse do it in a calculator

[gray isle]

you could apply certain algebra tricks to make the calculations less tedious

[alpine sable]

not for this kind of calculations

[polar whale]

Yea

[gray isle]

in which case its just a simple problem of multiplication, division, addition and subtraction

what's stopping you from doing with a calculator if you have access to one?

[polar whale]

Idk how to help u then sry

I will however write out the calculation

Incase it helps

[alpine sable]

well I don’t know how to write the calculation directly into the calculator or even reduce it to get the result in the calculator

[glass lichen]

so you dont know how to press buttons..?

[alpine sable]

yes if you want

[polar whale]

Idk if it helps or not

[alpine sable]

i know

[polar whale]

U could take 9^3 common from the start but it might be too much

[polar whale]

So no one gonna try this out?

😔

[gray isle]

well the order of operations are already consistent

you can pretty much just enter what's written into the calculator directly

$1 \div 3 \times 9 \verb|^| 3 - 9 \times 9 \verb|^| 2 + 4$

[ocean seal]

ℝamonov

[polar whale]

Yea it's fine

[polar whale]

Yea just do this but in the calculator.

U guys get to use. Calculators

Lucky

[alpine sable]

can somebody help me with this

[polar whale]

Everything is solved and correct

What other help do ya need?

[alpine sable]

Oh dang i didnt even notice it was just for a review

.- im dumb

[polar whale]

No u r not

:)

[alpine sable]

cP

cp

cap

i couldnt solve fractions until the 3rd grade

[polar whale]

Mhm

[alpine sable]

.-.

[polar whale]

It's ok to take ur time. Not everyone learns at the same pace.

[alpine sable]

ok

[polar whale]

Mhm

👍

[alpine sable]

btw

is anybody here good at science

;-;

[polar whale]

I caan help u

Maybe

[alpine sable]

😮

okie lemme send screen shot

[polar whale]

Depending on the question

So shoot

[alpine sable]

sw

see

[alpine sable]

ok thx

[polar whale]

It's correct 👍

[alpine sable]

HOWWWW

i aint even write anything'

;-;

[polar whale]

Oh u didn't draw the circle chart?

Oh

[alpine sable]

No

my teacher did ;-;

[polar whale]

So what's the question?

Oh

Lmao

[alpine sable]

i guess i dont have school today

;-;

[polar whale]

Umm I still don't get what the question is

Coz the diagram is accurate

[alpine sable]

tbh idrc anymore

[polar whale]

Oh

Ohk

Oh it's class notes Ig

Not a question

Smh

[alpine sable]

you are super thanks for your help i also find what I was looking for here https://fr.wikihow.com/trouver-les-points-d'inflexion

[polar whale]

Oh ok👍

Don't know if I helped at all but your welcome :)

[pallid flax]

need help, asap

[alpine sable]

your calculation allowed me to understand the logic manually so it’s cool

[gray isle]

why the urgency?

[gray isle]

assuming you mean the middle one? consider factorising the numerator

[polar whale]

I did it. I just thought it's a fun problem so I shared.

[limber jolt]

is the algebra 1 eoc hard?? im taking it on tuesday

[polar whale]

Find out CD by Pythagoras theorem, then u get the value of tanB. Then try to find how close it is to the nearest known tan value and evaluate.

[pallid flax]

okk, ty

[alpine sable]

taking a sniff smells like updog figga

[pallid flax]

wait so 3.9 is o? or is side CD o?

[gray isle]

if by 'o' you mean opposite, that depends on which angle you're using

and you really should know the definition of "opposite" by now

[pallid flax]

ik but it does not show the angle on the diagram

[gray isle]

size of angle DBC

that unambiguously tells you which angle they want

[polar whale]

[pallid flax]

kk

[visual fractal]

Thanks for the answer, but they provided an answer of 0.65

I can't seem to get to that number

[alpine sable]

can i write this more beutiful?

$\sum_{n=-\infty}^{-1}(n-1)^{-1} + \sum_{n=0}^{\infty}(n+1)^{-1}$

[ocean seal]

nosequepasa

[solar salmon]

how do i solve this?

[valid wagon]

Anyone thing they are capable of manipulating the green into the black or visa versa

Where the + is plus or minus in the logs

[rigid smelt]

technically log represent the exponent

so when a log is negative

it means that the exponent is negative

which implies that the number inside a log can be represented as a reciprocal of some number

[stable dune]

i dont understand this

[rigid smelt]

this is confusing, to me at least, so i can represent in equations

channel might be in use

you can ask in another one that is free, or use this one if unanswered 15min later

so basically, lets say we have ln(a) = c and ln(b) = -c for a, b, c are some random positive numbers. then b is the reciprocal of a, or b=1/a

how do you know that its true, well just plug 1/a into b

and you will see that it equates -c

@valid wagon

[stone shard]

Use the pythagorean theorem

[rigid smelt]

so you can apply this to your log

[valid wagon]

Okay

I found a way

@rigid smelt

[rigid smelt]

ermm the first portion looks right

[valid wagon]

U see

[rigid smelt]

but afterwards, i cant really see what you wrote

this to be exact

[valid wagon]

and those are what are inside the logs so therefore both solutions or equity

[rigid smelt]

ok, that is wrong

like i said earlier, the number inside the negative log is the reciprocal of the number inside the positive log

not those are equal to each other

[hasty hatch]

(4^5) ^5 =

guys can u help me

with that problem

[rigid smelt]

that is equivalent to 4^(5*5)

and please use a free channel next time

[hasty hatch]

i dont know what that means

are u doing 4x4x4x4x4

[rigid smelt]

no, its 4 to the power of (5 times 5)

[hasty hatch]

ok

so is it 5120

[gloomy lintel]

4x4x4x4x....4 25 times

[rigid smelt]

thats a bit too small for something to the power of 25

[hasty hatch]

wait guys

[rigid smelt]

this seems like a better number

[hasty hatch]

we just learned this so i dont know

[alpine sable]

Yo

Could someien help me with my homework please

[hasty hatch]

so am i doing 4x4x4x4x4 25 time

times

[alpine sable]

NBA YOUNGBOY 😨

Could someone help me with this please

[rigid smelt]

$(a^{b})^c = a^{b\cdot c}$

[ocean seal]

waler

[rigid smelt]

and please use a free channel

[polar whale]

Which question?

[hasty hatch]

bruh im so confused

[alpine sable]

All of them please or as much as you can ^_^

I really need it

Guys what is the answer for this

b

[glass lichen]

what have you tried?

[alpine sable]

A

I am trying to do B

AND I FORGOT

UGH

[glass lichen]

what have you tried for solving b...?

[alpine sable]

3/8 = 3L

[gloomy lintel]

Well 3/8 has got to be 3 litres right?

Yeah

[glass lichen]

yes, so you know the fraction 1 L makes up

[alpine sable]

Yea?

[glass lichen]

so you can figure out 5/8 of the can is in L

[gloomy lintel]

^^

[alpine sable]

Basically that

[glass lichen]

yes

[alpine sable]

Then after what do I do???

[glass lichen]

write the answer on the page..?

[alpine sable]

wait

[glass lichen]

maybe put it in a box idk, whatever you want

[alpine sable]

omg this is so easy

What happened to me today

[glass lichen]

what's the answer?

[alpine sable]

5l

[glass lichen]

yes

[slow mason]

i need help with this

[gray isle]

apply angle sums

[slow mason]

190

[gray isle]

by apply angle sums i don't mean add everything you see

[slow mason]

oh

[gray isle]

apply angle sums of a triangle and angle sum on a line

or the combination of the two (which will be the exterior angle theorem)

[slow mason]

40+x=150 for the exterior theorem right?

[gray isle]

yes

[fossil yew]

aaaaaaaa im trying to verify the left side but i dunno what trig proof to use

[rigid smelt]

That seems wrong

[gray isle]

that doesn't look right

,w sin^2(x) + tan^2(x) + cot^2(x) = sec^2(x)

[ocean seal]

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Requested by ramonov#0921

[fossil yew]

wh

[rigid smelt]

Yep

Well if you look at it, you notice that its related to tan^2(x) + 1= sec^2(x)

But sin^2(x) + cot^2(x) is never 1

[gray isle]

did you mistype the question?

[fossil yew]

No, that’s exactly how it said on my assignment

[gray isle]

because it really feels like that cot^2 is supposed to be cos^2

[fossil yew]

should I put no solution then

[gray isle]

depends on what the question was asking you to do

[fossil yew]

I’m just trying to verify that the left side = to the right

So im only doing work on the left to equal sec^2(x)

[gray isle]

i didn't ask what you're trying to do

i asked for what the question is asking you to do

preferably exactly as stated

[vale wigeon]

for θ = π/4, you will get 1/2 + 1 + 1 = 2, which is clearly BS

[fossil yew]

It said to verify the left side

[vale wigeon]

so clearly you must have typo'd the question

[fossil yew]

nope

[alpine sable]

Guys 5/8 = 24L

how much liters is 3/8

[gray isle]

wtf does verify the left side even mean...

is the worst wording I've seen for these types of questions

[fossil yew]

aha

[gray isle]

anyway the equation is false,
like Ann demonstrated write a counter example

[vale wigeon]

@alpine sable channel occupied, please move

[gray isle]

and write an essay on how it seems like the cot^2(x) should instead be cos^2(x)

[fossil yew]

mk mk

[alpine sable]

For the first fraction if I wanted to rewrite it, would I multiply the 4 by 3 and set the exponent negative?

And for the second fraction if I were to rewrite it would it be 6x^-7?

[gloomy lintel]

For the first fraction it’s 3(4^-7) because if it was 3/x^7 it’d be 3x^-7, which is 3(x^-7), not (3x)^-7

Second one is right

[alpine sable]

Could someone help@me with this please

1-8

Please

I’m stuggljng

[stone shard]

This should help you

[fossil yew]

@alpine sable well, do you know what to do exactly?

[alpine sable]

Kinda

I know the first is 50 and the 2nd is 135

[fossil yew]

Yeah that’s correct, number 3 is the same concept as 1 and 2

and 4 is also the same concept

[alpine sable]

Ohhh

So 3 would be 85

[fossil yew]

Yes, yes

[alpine sable]

And 4 is 120

[fossil yew]

Yupp

[alpine sable]

Ohh

Thanks

I don’t get 5,6,7 and 8 tho

Well I forgot

[fossil yew]

So number 5 is the same concept as well but more steps

You’re finding angle JIK
We can assume that segment JL is the diameter of the circle. Therefore, half of the circle equals 180.
You can find the missing angle with the information i just gave you

[alpine sable]

Ok thanks

So it’s 180 or was that the steps

[zinc ridge]

Find the area of region bounded by the graph f(x) = 4-x^2; 0<x<3

My lecturer slides say the answer is 23/3 But im getting 3

[alpine sable]

Nah, it's 3.

[ionic jewel]

show your work

ah lemme check it then

yea i got 3 too

[zinc ridge]

I swear my lecturers slide & the amount of typos

[ionic jewel]

not sure why you decided to split the integral

[gray isle]

is there more to the question?

[zinc ridge]

First I did without split and I got 3 so I decided to split them

No

[ionic jewel]

$\int_a^b f(x) , dx + \int_b^c f(x) , dx = \int_a^c f(x) , dx$

[ocean seal]

bunny

[gray isle]

because that doesn't look like it describes a bounded region

[zinc ridge]

Its just a slide full of question

[ionic jewel]

i imagine its implied to just take the integral

[zinc ridge]

It says: Exercises. Find the area of region bounded by the graph f(x) and the x-axis between an interval a<x<b

[ionic jewel]

wait

[gray isle]

ffs

[ionic jewel]

its probably abs(f(x))

does that give 23/3?

[gray isle]

you can't just omit "and the x-axis" from the question

[ionic jewel]

yep then the answer is 23/3

not 3

[gray isle]

drawing a pic helps

gotta be careful of signs and signed area

[fair igloo]

@gray isle is this it or? asking first before I ask my own question so as not to be rude

wait I meant to ping bunny, sorry

[ionic jewel]

its not my question

[fair igloo]

or whoever it is

I guess I'll try asking

[zinc ridge]

Wait so how do solve it then

[fair igloo]

nevermind

[ionic jewel]

positive area

[zinc ridge]

Im completely lost

[ionic jewel]

dont subtract the area when its under the x axis

you need to add your two integrals together

right now one of yours is (incorrectly) negative

should be 7/3 + 16/3

consider graphing to see the area

[zinc ridge]

I see, Thank you

[limber kraken]

Bob's yard is in the shape of a semicircle with a diameter of 20 feet. Bob wants to buy grass to cover the area of his entire yard. How many square feet of grass does Bob need? Round to the nearest tenth.

628.3

31.4

157.1

62.8

[ionic jewel]

what have you done so far?

[limber kraken]

nothing idk how to do this

[ionic jewel]

do you know how to get the area of a semicircle?

[limber kraken]

all i know is that the semi circle equation for area is 1/2(πr2 )

[ionic jewel]

great

$A = \frac{1}{2}\pi r^2$

[ocean seal]

bunny

[ionic jewel]

so we need the radius

[limber kraken]

so thats 20 right

[ionic jewel]

how does radius relate to diameter?

no

the diameter is 20

what is the radius?

[limber kraken]

radius is divided by 2 of the diameter

[ionic jewel]

yes

[limber kraken]

because diameter is x2 the radius

so

10

[ionic jewel]

exactly

now you can plug it into that equation to get the area

[limber kraken]

1/2(3.41)(10)(2)?

[ionic jewel]

notice that its $10^2$ not $10\times2$

[ocean seal]

bunny

[limber kraken]

ohhhhhhhh

100

1/2(3.41)(100)(2)

[ionic jewel]

also $\pi \approx 3.1415$ not 3.41

[ocean seal]

bunny

[ionic jewel]

just use the "pi" button on your calculator tho

dont estimate it

@limber kraken so what is your final answer?

$A = \frac{1}{2}\pi (10)^2$

[limber kraken]

so 31.4 (rounded to tenth)

[ocean seal]

bunny

[ionic jewel]

no

where did you get that?

[limber kraken]

1.2(pie)(100)(2)

[ionic jewel]

(1) its 1/2 not 1.2
(2) pi*
(3) 10^2 NOT 100*2

[limber kraken]

0.5?

[ionic jewel]

1/2 = 0.5 yes

[indigo forge]

so if i drew a circle with 1 unit being the diameters i could draw a square around it and have the perimeter b 4 right?

[limber kraken]

and 10 to the power of two is 100

[ionic jewel]

sure

[ionic jewel]

yes

so $0.5(pi)(100)$

[ocean seal]

bunny

[limber kraken]

OHHHHHHH

[indigo forge]

and if you remove the corners of the square the perimeter is still 4, right?

[limber kraken]

157.1

eould be my

answer

tysm

[ionic jewel]

it gets close but its never equal to a circle

[limber kraken]

i get confused

becuase

these need to remain in pi terms

[ionic jewel]

otherwise you could prove pi = anything, with any regular polygon

[indigo forge]

ok, cause i was gonna say if it was still 4 you could just remove corners until infinity and pi would equal 4

[ionic jewel]

yes it doesnt work

for obvious reasons

you can look up why that doesnt work if you want a more scientific answer

[indigo forge]

ok

[limber kraken]

how do i do this leaving in terms of pi

[lament lintel]

what is the answer of this

just to check my answer

[limber kraken]

bruh ur supposed to wait till the person finishes

[lament lintel]

i put F

[limber kraken]

.

[lunar garden]

i need help on this

[zealous epoch]

what is 1+1

[remote dagger]

3

[glass lichen]

0

[zealous epoch]

ok

[remote dagger]

Why is AB = 2x8cos0.9

?

[glass lichen]

angle C is $\pi - 1.8$ rad so if length AB is x, $$x^2=8^2+8^2-2(8)(8)\cos(\pi-1.8)$$

[ocean seal]

moshill1

[light berry]

help

[remote dagger]

And why is C pi - 1.8

[glass lichen]

it's an isoceles triangle, so angle A is also .9 rad

and then angle sum of a triangle

[remote dagger]

ah okk

[lament lintel]

i picked F was ir right? just double checking

[remote dagger]

ivthought pythahoras only work in righ angle triangle

[glass lichen]

pythagorean does only work in right triangles

I never used pythagorean

[vivid citrus]

it is

[lunar garden]

is the answer 33?

[lament lintel]

k

thx

i think this is wrong can some tell me if i chose the right answer

[lunar garden]

is it 33?

[glass lichen]

dont crosspost

[lunar garden]

ok

[vivid citrus]

it is

32.968

[lunar garden]

thx

[alpine sable]

can any one hel pyou can just translate it https://HashGamerYT.api-minecraft.net/​​‌‌‌​​​​‌​​​‌​​​‌‌‌​​​‌​‌​​‌‌​​​‌​‌​‌​‌​‌‌‌​​​​​‌​​​‌‌​​‌​​‌‌​​

[remote dagger]

I still dont get it where does the cos come from if it is not right angle triangle

[vivid citrus]

it's cosine law

[remote dagger]

hold up

wait a minute

some ain right

ah ok

[vivid citrus]

same as this one

[gray lark]

can anyone help @here

[glass lichen]

what have you tried?

[vivid citrus]

just put h equal to 0 and solve bhaskara

[gray lark]

i substituted h=0 and t=0

[glass lichen]

h=0 is correct

t=0 means h=-18 which doesnt make sense

[gray lark]

ok

the answer would be when the ball was kicked in the air right

[vivid citrus]

and when landed

since it is quadratic will give 2 answers

[gray lark]

wdym

[vivid citrus]

when the ball is in the ground h = 0

if you solve for h = 0 it will give 2 values for t

[gray lark]

i solved and got t=0.53

[vivid citrus]

hmm

almost

but not quite right

and you should find 2 values

[gray lark]

how

would I put the value back in the equation

and solve for h

[next void]

With the quadratic formula, you should get a positive and negative value for your answer.

[vivid citrus]

not necessarily

in this case you will get 2 positives

i will make this on latex

brb

[gray lark]

im so confused

[glass lichen]

No you dont

You get the 2 roots.

[next void]

isn't it usually + and - the square root so then there are 2 values, with one positive and one negative?

[glass lichen]

yes you take the plus and minus of the sqrt, but that doesnt mean the roots are 1 pos and 1 neg

like you said

[next void]

Ok my bad.

[glass lichen]

$ax^2+bx+c=0\implies x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

[ocean seal]

moshill1

[zinc quartz]

Can anyone help with this

[gusty gorge]

Do you know your right triangle trigonometry?

[vivid citrus]

it should look like this

[livid lintel]

how do i find NPL?

[dawn wraith]

Is this a parallelogram?

[gloomy lintel]

180- 144 as co interior angles between parallel lines sum to 180, if this is a parallelogram

[livid lintel]

it doesn’t specify

[lucid bough]

Omg I miss geometry

Just a sec

[dawn wraith]

Still buddy, we don’t know if it’s a parallelogram..

[gray lark]

can someone help

[lucid bough]

You need the area

or the angle?

[livid lintel]

i just to find what NPL equals to

the measure of NPL

[lucid bough]

Okay

[livid lintel]

i’m pretty sure it is 180-144 but i just wanted to make sure

[lucid bough]

Yes

Because

All the angles in a parallelogram are 360*

[livid lintel]

thank you

[lucid bough]

<P=<NPL

[lucid bough]

Np ❤️

[livid lintel]

can you help me with this?

Angle 3 is 90 right?

[wide mountain]

I’m so confused

[lucid bough]

Wait, not sure because it s not really specific

Just a sec

[livid lintel]

alright

[lucid bough]

Yes, I think 3 is 90

And the other are just 180- the nr

Like this:

[livid lintel]

so angle 1

[livid lintel]

180-65

right

[lucid bough]

Exactly

[lucid bough]

A sec

[bright maple]

o

thx

[lucid bough]

My brain is blank

I forgot how you do this

[dawn wraith]

||Start by finding the tangent||

||tanx=1/cotx||

[bright maple]

wait how do u do it

if cot = root 3/5

[dawn wraith]

Maybe multiplying by the reciprocal?

Seems like a good idea to me

Anyhow

tan(theta)=5/sqrt(3)

Continue

[bright maple]

nvnm

coould u help me with this

[dire dove]

Can someone help me with a calculus question please

The question is, if a=[1,3] and b=[4,1], determine what a↓b

Dont I need to know the angle between a and b to find a↓b?

[lucid bough]

I don't know math in English

So what means “the terminal side of an angle “

?

I made the graf

[dawn wraith]

-4 bud

Ya gotta go under

[lucid bough]

Yhea, I didn’t saw that

Just reverse it

[dawn wraith]

The x should be 6

Not the y

[lucid bough]

4 is on the x

Oh I messed up

I just rotate it

[dawn wraith]

That looks good

[vale tundra]

Can anyone help with this?

We just change x with y

So is becomes x= 7^(y-5)

Right?

[lucid bough]

I m not sure for the others

[lucid bough]

Not sure

[vale tundra]

hmm

[lucid bough]

I don’t remember how you find the inverse

Sorry

[vale tundra]

Ahh its okay

If anyone else can help me

[gloomy lintel]

Ok so, swap x for y like you did

[vale tundra]

With this

[gloomy lintel]

Take the natural log of both sides

[vale tundra]

Why

The function is in y

[gloomy lintel]

Because we want x=

[ashen wave]

I just got this packet from my teacher (we are starting a new unit) is this talking about direct variation? Is there any videos I could watch because I don’t understand any of it.

[vale tundra]

This channel is occupied

[ashen wave]

Oop

[vale tundra]

They are in terms of Y

[gloomy lintel]

I’d swap after if I was you

That’s how I was taught

[vale tundra]

Oh really?

[gloomy lintel]

So rearrange to get x=

Yes

And then when you have x=

Swap x and y

So now you have the inverse function

So yeah

[vale tundra]

So y= 7^(x-5)

Then it becomes

x=7^(y-5)

Idk still

[gloomy lintel]

So

ln y = ln 7^(x-5)
ln y= (x-5)ln7
x-5 = ln7/ lny
x= (ln7/lny )+5
Swap x and y
So y = (ln7/ln x)+5

Oh wait

It says h^-1 (y)

Not x

I’m so dumb

So it’d be

y = (ln7/ln y)+5

So my working out is right but y is the value of x

If that makes sense

I feel like I’m just waffling on rn lol

I hope that makes some sense

So in functions when we have f(x)= ...
f(3)= the function with 3 subbed in
so h(y) is just subbing in y for x

[vale tundra]

Hmmm

IDK

That is not how i was taught

we swapped x and y

Then solved

[gloomy lintel]

Yeah we did that but at the end instead

But notice the inverse function isn’t h-1(x)

It’s h-1(y)

So the x value was y in the first place

So you sort of rearrange to get the y that’s already in the function on it’s own

That’s a really crappy explanation I’m so sorry

[wild shard]

ln

[vale tundra]

I see

[vale tundra]

No its okay

[neon sonnet]

Hey guys im going to need help later just giving people heads up

[alpine sable]

May I have help

[lucid bough]

Yes, you may have help; but only after you address your question. :))

[alpine sable]

@lucid bough

[lucid bough]

I am not sure this works

But I did it like this:

For 1

[alpine sable]

Your handwriting is so fancy 😱

Thank you

[ashen wave]

Do you think you could help me out aswell xD?

[lucid bough]

I don’t know until I see the question

[ashen wave]

Could you tell me what unit this is?

[alpine sable]

What does that question even mean

Could someone help me

For@nitro

[ashen wave]

;-; im just wondering because my teacher gave us this packet and I need to know what to search up to understand the stuff

Do you know what unit it is tho?

[lucid bough]

I think is the metric system

[harsh swallow]

unit?

[lucid bough]

No

[ashen wave]

yeah-

[alpine sable]

You can probably google box plots

[lucid bough]

Wrong

[alpine sable]

Could someone help with

Nvm

[harsh swallow]

there aren't any units

although you can argue that the unit is 1 but that's meh

[alpine sable]

It seems like all the information you need to answer the question on the bottom right is already on the paper actually

[ashen wave]

but the title says measures of spread/variation is that the name of the unit or is it box plots

[lucid bough]

I think that you have there just some algebra data

Not sure

[alpine sable]

What more do you need from google?

[harsh swallow]

unless you mean what part of maths this is in which case it's a small part of statistics if i got that right

the page is just explaining what a box plot is and why it is used

[ashen wave]

erm its not just for googling its more of my notes. Its going to drive me crazy not knowing what the name of all my notes is

[harsh swallow]

and then wants you to make one

[ashen wave]

yeah but just the first page is talking about box plots

[alpine sable]

I’d probably call it “box plots and quartiles”

[harsh swallow]

from just this one page

and thinking about how it is written

[ashen wave]

alright thank you that helps so much T-T

[harsh swallow]

i think it probably is something along the lines of

ways to represent data

but obviously that's just from the one page

[ashen wave]

the next page is talking about outlirers

[harsh swallow]

and then?

[ashen wave]

and something about a 1.5*IQR rule?

also quantitative date?

and categorical date

mean and medium

S.O.C.S?

thats all

[harsh swallow]

box plots
outliers
deviation
data in the form of numbers
data in the form of types
mean and medium
don't know what S.O.C.S. is

it's an acronym

to help remember how to describe distributions

data