#help-0

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alpine sable
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All together?

agile compass
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What is 800?

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I don't know what """its""" is

alpine sable
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48 x 50

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Times

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1/2

agile compass
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That's our area of the base

alpine sable
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Yes

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Now what do i do

agile compass
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Volume = area base * hight

alpine sable
#

But

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I still

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Dont get that

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For an answer

agile compass
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,w 48501/2

agile compass
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So thats our base

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And the hight is given in the picture

alpine sable
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mhm

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So 192,00

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Would it still be the same

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As this

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I got 19200

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But the answer is

agile compass
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,w 1200*80

alpine sable
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192,000

alpine sable
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Wait how did u get

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80

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O

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But now

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1/3

wanton otter
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I see an alternate angle shape (aka Z pattern) where the angle below c and the angle to the right of b are equal (so theyre both 22 degrees). an angle across a straight like = 180 degrees so angle b = 180 - 22

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the entire shape = 360 degrees so take each angle, subtract them from 360 and the remaining angle is angle a

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hope this helps ๐Ÿ™‚

spring harbor
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can someone rephrase this so that it makes sense

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its referring to the p value being 0.003

uneven fulcrum
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@spring harbor could you send the whole question?

spring harbor
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@uneven fulcrum

uneven fulcrum
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@spring harbor i dont want to give you the wrong answer so i would just @ a helper as im not 100% sure of my answer

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however i would also say its C just not sure as the questions i get on my exam board are very different

loud barn
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So the word PARIS, the first letter must be a vowel (This is for permutations)

Can someone explain how it would be 2 x 4 x 3 x 2 x 1 = 48

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Why did we put the 2 first which is I

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When we could also use A which would be 4 x 4 x 3 x 2 x 1

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unless im doing this wrong

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Is it because theres 2 vowels

shell widget
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suppose we put A as the first vowel. Then we have 1 * (4 * 3 * 2 * 1) for total arrangements. then suppose you put I as the first vowel. We still have 1 * (4 * 3 * 2 * 1) for total arrangements, add them you get 2 * ( 4 * 3 * 2 * 1 )

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And yes, the 2 at the start is for the 2 choices we have for the vowels

loud barn
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Ooooh i get it thank you

mossy cedar
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anyone know 9?

alpine sable
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anyone who can help me over basic category theory definition of slice category?

real forum
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What is 2+2?

alpine sable
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oh, sure

onyx bridge
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@real forum do you want help with that?

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if anyone needs help with honors pre calc or below i can help

real forum
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Lol im kidding

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Sorry

woeful pulsar
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intensively studies definition okay I got this

alpine sable
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I'm reading Aluffi's Algebra, and it introduces slice category C/c of C, in which objects are morphisms of C and morphisms are "commutative diagrams" in C.

my que is:

  1. why it needs to be commutative diagram?
  2. if f1 and f2 are two objects of C/c then how to make sense of morphisms between them? what's the domain and codomain of morphism between f1 and f2?
woeful pulsar
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  1. commutative diagrams are just another way to represent of a bunch of relations
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For objects in C/c, they are simply (A, f) such that f: A->c

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that you got so far?

alpine sable
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yeah

woeful pulsar
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a commutative diagram is just a bunch of relations that says "which arrows compose to make which arrows"

alpine sable
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Someone plspls help

woeful pulsar
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In particular if g: A->A' in C, then there is an arrow g: (A, fg)->(A', f) @alpine sable

alpine sable
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Are the first 2 answers

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Correct

woeful pulsar
alpine sable
woeful pulsar
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yeah, the commutative diagram is another way of showing the definition of slice category

alpine sable
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and 2nd que? @woeful pulsar

woeful pulsar
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Hmm... let me check if there are any good examples of slice categories

woeful pulsar
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yeah for example, the first two are more familiar to me

alpine sable
woeful pulsar
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well, you can construct a poset out of the powerset of a set

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by inclusion

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then you can construct a down set from there

south wing
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I could use some help with 4 and 5

alpine sable
glass lichen
south wing
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ohhhhhh

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would it be 6 times 5 times 4 times 3 times 2 times 1?

glass lichen
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yes, 6!

south wing
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and what about 5?

glass lichen
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how many ways if I fix the last 2 letters to be CK (in that order)?

south wing
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so would that be 5!

glass lichen
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yes, but if I swap the C and K, it's still 5! ways

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so it's 2*5!

south wing
alpine sable
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help

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Pls

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Is number 2 right or no

woeful pulsar
alpine sable
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Pls help me

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What do i do

woeful pulsar
alpine sable
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V=1/3bh

woeful pulsar
alpine sable
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uh

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V=1/3x12x25.2

woeful pulsar
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and where did you get 25.2 from?

alpine sable
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6.3x4

woeful pulsar
alpine sable
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25.2

woeful pulsar
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what quantity are you trying to calculate here?

alpine sable
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Base

woeful pulsar
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is that how you calculate the area of the base?

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look at the shape of the base

south wing
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for 3 would you do 4! times 1?

woeful pulsar
glass lichen
south wing
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ty

alpine sable
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oh?

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Determine the equation of the polynomial function that has the following zeros and passes through the point
(7, 5000): x = 2 (order 1), x = -3 (order 2), and x = 5 (order 1)

onyx bridge
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@alpine sable yo i can help i dm

glass lichen
alpine sable
woeful pulsar
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you need to find the area of the base, right?

alpine sable
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Yes

woeful pulsar
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do you know the formula for the area of that?

south wing
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iโ€™m confused on how you would set up 6 and 7?

alpine sable
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I don't understand why this is coming up as wrong

patent burrow
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it's probably the symbol

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you put 0 instead of theta

worthy verge
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Theta

glacial pier
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I dun know how to do it with change of variable

patent burrow
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isn't that a test?

glacial pier
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It's assigment

patent burrow
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oh alright

woeful pulsar
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x^(1/4) is kinda trippy to work with isn't it

alpine sable
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its big ideas hw and yeah i put theta

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same with this idk

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both showing up as wrong

patent burrow
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like use a single letter multiple times

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XXXX or TTTT

full walrus
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hello

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can somebody help with this

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How from this can i get pi^4/15

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/15 is not in the exponent

ionic jackal
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Shape of the Base?

woeful pulsar
full walrus
woeful pulsar
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hmm strange

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,w integrate x^3/(e^x-1) from x=0 to infinity

ocean sealBOT
woeful pulsar
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yeah wolfram alpha is giving the exact value here

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@full walrus

full walrus
woeful pulsar
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yeah

full walrus
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thank you very much

full walrus
alpine sable
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Hello, so I used the alternating series test to prove that it is converging, i just have two things I want toclear up

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  1. If you want to find the maximum amount of error of a nth partial sum, would you just have to do 1/(n+1)^(4/3) in this case?
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  1. This series would be absolute convergence as the absolute value of the series is still converging right?
woeful pulsar
woeful pulsar
alpine sable
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@woeful pulsar

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Can u check my answers

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For me?

woeful pulsar
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why not ask wolfram alpha

alpine sable
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Who is that

lost steeple
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It's an online calculator

alpine sable
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Can someone help me with this. Just dm me ig

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could sm1 explain

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this for me

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i dont understand what the question is saying

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and how get got 48/16

glass lichen
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ok well you have a vertex of (-4,12)

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so $y=a(x+4)^2+12$

ocean sealBOT
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moshill1

glass lichen
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then you have a point to determine a

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$60=a(0+4)^2+12$

ocean sealBOT
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moshill1

alpine sable
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yeah i got that

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thats what i have

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wait

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its x +4

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or no

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since we dont have x

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@glass lichen

glass lichen
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what do you mean?

rocky kite
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Could anyone review this proof?

alpine sable
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@glass lichen 60 = a(x+4)^2 + 12

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isnt it that

glass lichen
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you cant plug in half a point

alpine sable
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wdym?

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@glass lichen ?

glass lichen
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you plugged in y=60, but not the x value of the point

alpine sable
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ohhhh

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i see

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ok i get it

rough sky
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can someone explain solids of revolution to me?

charred flint
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@rough sky for an integral you add a bunch of vertical lines from x=a to x=b

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if you spin a shape around, these lines correspond to circles with the radius of that line

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so for a solid of revolution, you add circles instead, and integral of f(x) turns into integral of pi*f(x)^2, the formula for the area of a circle

grim mango
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how do i do number 12

vestal hollow
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This diverges right?

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As n -> infinity

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Here it is in Desmos

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I'm not sure how I'm supposed to evaluate this lol, L'Hopital's rule won't give me anything

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Or actually

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Hm

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If I apply it 2020 times I just get 0/e^n

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but how could the limit be zero?

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if the function just keeps climbing as we approach infinity

vestal hollow
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Yeah I forgot it would come back down ๐Ÿ˜›

opal shell
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Can someone help me with this

vestal hollow
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Is there any way to evaluate the limit (approaching infinity) algebraically or am I just supposed to know that it goes to 0 when the constant is <1?

alpine sable
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why is -sinxtanx+cosxsec^2x=cosx?

alpine sable
rocky kite
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Could someone verify this?

alpine sable
gray isle
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there's a pinned list in every channel

alpine sable
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I am in need of a math tutor for a specific subject

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Pre-calculus, the professor, nor the textbook explains clearly enough for me to understand, and I'm pretty sure I flunked my first exam, and I only have 2 more exams of the quarter.

crystal cape
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The function f is defined by f ( )x=x2โˆ’4x+7 forx<k, wherekis a constant.(ii)State the largest value ofkfor which f is a decreasing function.

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how do i do this

alpine sable
vestal hollow
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You only need to know a couple

alpine sable
alpine sable
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first you need to know these definitions

vestal hollow
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Defining relations, Pythagorean, and double angle

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Those are most common

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The others can be useful though

crystal cape
alpine sable
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you only need to know the first one here, as you can get the bottom two from the first one by dividing by sin^2 (x) and cos^2 (x)

vestal hollow
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Yup

alpine sable
vestal hollow
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Should be, yeah

alpine sable
alpine sable
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tbh, I barely survived and I don't know how I managed to get an A

vestal hollow
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The Pythagorean and double angle ones are really useful for polar integration

alpine sable
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know sine/cosine addition identities

crystal cape
alpine sable
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on the interval (-inf, 2), the function is decreasing

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but after you get to the turning point the function will start increasing

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so the largest k that works is k=2

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because when x<2 the function is decreasing

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@vestal hollow @alpine sable thank you very much fellas

royal veldt
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Hi, would anyone want to help me do this math equation?

crystal cape
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whats the formula for volume obtained by rotating a curve

alpine sable
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solids of revolution?

crystal cape
alpine sable
#

guys

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I need help with my math homework

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I don't understand how to graph inequality

alpine sable
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dont just memorize the formulas you should understand why they work

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also be familiar with disk/washer method

crystal cape
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ohk

crystal cape
alpine sable
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yeah its a definite integral

crystal cape
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thx

thorn tulip
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Could anyone help with this stats problem?

crystal cape
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the limits are 3 and 0 here right?

alpine sable
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yeah

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lower bound is 0 upper bound is 3

thorn tulip
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oh, my bad

crystal cape
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how do i solve this

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its part of the solid revolutions question

vivid kayak
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How do I even find Q?

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for iii)

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nvm

lusty charm
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Okay guys

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So this is related to the polynomial thing, we just learned it today

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I have two questions; but my first one is this

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How do I do this question?

stuck kestrel
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ok

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since side is x

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then side of the shaded square is x-3

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area of the shaded square is (x-3)^2

lusty charm
stuck kestrel
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the black part inside the bigger square

limber fable
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what a wonderfully confusing question. I'm pretty sure they just want you to notice that the x^2 square consists of 4 parts - two squares of area(x-3)^2, 3^2, and two rectangles of area (x-3)*3. Hence, x^2 = (x-3)^2 + 3^2 + 2*(x-3)*3, and therefore (x-3)^2 = x^2 - 2*(x-3)*3 - 3^2.

lusty charm
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i still dont understand what ^ is lol

limber fable
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exponentiation

stuck kestrel
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to the power

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yes

lusty charm
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OH

alpine sable
stuck kestrel
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so it says that area of the entire square is area of black square + area of rectangles

lusty charm
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uhm

stuck kestrel
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which is x^2=(x-3)^2+(x-3)*3+(x-3)*3+9

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good

lusty charm
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Im still confused ill ask my teacher tmr

stuck kestrel
#

ohk

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which grade are you in?

paper wave
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I need halp

stuck kestrel
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can you send a pic of the question

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or diagram

valid bone
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sure

lusty charm
stuck kestrel
#

integral of the solid?

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volume?

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ok

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what figure do you get after rotation

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yes

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wait

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let me do it

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basic question

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yeh it is correct

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ans = 81pi/2

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same here

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ok then

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bye

verbal ermine
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can someone tell me how they got from the top line to there

stuck kestrel
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ok

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NM^-1 IS N/M

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(N/M)^-1

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=M/N

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=M*N^-1

verbal ermine
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mhm

stuck kestrel
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Umm

verbal ermine
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and i get M = M lol

stuck kestrel
#

hah

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i dont know how they got m^2=n

verbal ermine
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lemme see the mark scheme

stuck kestrel
#

yeh

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ok so (NM^-1)^-1 = N^-1 * M^1

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=MN^-1

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AGAIN!!!!

verbal ermine
#

ikr

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how did they get M^2?

stuck kestrel
#

hmmmmm

lilac kestrel
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yo sm1 help with c

stuck kestrel
#

did you factor b?

lilac kestrel
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wdym

stuck kestrel
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i mean did you factorise b

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hi

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um

ionic jewel
stuck kestrel
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YEZ

lilac kestrel
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im sorry if the answer completely missed the mark

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i took the vid on the lesson the same day

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@stuck kestrel

valid bone
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@compact flax I dont know sorry

ionic jewel
#

what does this even mean

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which number are you doing

alpine sable
#

<@&286206848099549185>

vale wigeon
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there is none, and if there is, it's arbitrary.

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and subjective.

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im tempted to say that the intended answer for #10 is a 2ร—2 grid of squares but honestly who knows

ionic jewel
#

ah yes deleting all your posts

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a classic

gray isle
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magic

alpine sable
#

Should I not

vale wigeon
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bruh

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yeah you should not

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it leaves the other half of the convo just hanging there

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simply acknowledge the question is fucked up / unanswerable and move on

alpine sable
#

Ok but is no one is working on the problem , how's there a problem in deleting it ?
I mean you don't want others to spend time on a problem like that
?
I'm new on discord..

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@ionic jewel

ionic jewel
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why

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did you ping me

alpine sable
#

Do u wanna explain me ?

alpine sable
ionic jewel
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don't delete posts, it's generally annoying at best and rude at worst

alpine sable
#

Okay.

alpine sable
#

If A={<1,1,2>,<2,1,2>,<3,2,1>}
What values can b take to be a member of the span of A for <b,1,2>

woeful pulsar
#

like, vectors, or continued fractions

proud bough
#

Find all functions f: R -> R satisfying the following condition:
F(x+y) = f(x)*f(y)*f(xy), for all x, y in R.

ionic jewel
proud bough
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I tried the only method I knew which was sub but I cannot get anything

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Please help &-&

fallow epoch
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guys

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i need help

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quic

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this assignement is due

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in like 1 hour

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anyone help?

woeful pulsar
#

c and a are quite similar, and I suppose b and d uses the same ideas too

fallow epoch
#

well for C i did the quotient of 500/8 over 500

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theoretically they're all equal

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but in the spinner's context

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they're different

woeful pulsar
#

actually, the problem with this is we don't know if the spinner is biased, and how it is biased

fallow epoch
#

if its theoretical, it probably wont be biased

woeful pulsar
#

since we don't know how it is biased, the experimental evidence gives some information how the spinner is biased.

fallow epoch
#

because you cant calculate which nimber it'll go to

woeful pulsar
#

but it might also be affected by random error

fallow epoch
#

what i've come to for C

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is 62.5/500

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but the thing is i cant decided whether to round up or down

solid schooner
#

Anyone willing to help?

woeful pulsar
solid schooner
#

no clue this is parametric equations. I have no clue how to solve this

woeful pulsar
#

looks sus, I think there's a mistake in this question

indigo jetty
#

@solid schooner probably just a printing mistake for y, so just treat it as y = 3sin2t

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notice that sin t = x/2?

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find an expression for cos t based on this

tawdry urchin
#

hey guys

indigo jetty
#

also, 3 sin2t = 6 sin t cos t

tawdry urchin
#

I have a final problem that i am struggling with can someone please help me with this?

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ignore the bottom text

left spear
#

You have a product whose cost depends on how many are sold I guess

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If you try toying around with different values of q you can see how it affects p and in turn the total revenue (which is the price per unit times the number of units sold)

tawdry urchin
#

these word problems got me trippin xD

left spear
#

To be fair it's badly phrased

tawdry urchin
#

it is

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wouldnt first derivative be a solution to this?

noble sinew
#

it would but you have to rewrite the expression given

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p=200-q is price for 1 unit

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so what is total price for all units sold then?

tawdry urchin
#

Im stupid

noble sinew
#

what do they say q is?

tawdry urchin
#

price per unit

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but has no value

noble sinew
#

q

tawdry urchin
#

oh demanded

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units demanded

noble sinew
#

so if q was 10 we would be selling 10 units for a price of 200-10 each, agree?

tawdry urchin
#

yeah..

noble sinew
#

so we would be selling for (200-10)*10

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does that make sense

tawdry urchin
#

a little bit

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i wish i was better at math

noble sinew
#

so the total amount we sell for is then (200-q)*q

tawdry urchin
#

i see

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200q - q^2

#

?

solid schooner
noble sinew
#

yep

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now we want to find maximum of money made

tawdry urchin
#

-2q + 200?

noble sinew
#

that is the derivative yes

tawdry urchin
#

god this is awful xD

noble sinew
#

why? you need 1 step more and you are done

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what do we do after finding the derivative?

tawdry urchin
#

i forgot... havent done this in llike a year ๐Ÿ˜ข

noble sinew
#

so the derivative tells us where a function is increasing or decreasing. So a maximum (and minimum) must be where the function stops increasing (decreasing), which it does when the derivative is equal to 0.

tawdry urchin
#

ahhhhhh..... now it makes sense

#

q = 100?

noble sinew
#

yep

tawdry urchin
#

final answer?

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xD

noble sinew
#

now plug in q=100 in the equation we made

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to find money made

tawdry urchin
#

the one we made? the q^2 +200q?

noble sinew
#

yep

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200q-q^2 but yes

tawdry urchin
#

10k

noble sinew
#

indeed

tawdry urchin
#

Thanks so much <3

#

Do you have any source of like a video where i can fully understand the concept of what i just did ?

noble sinew
#

if its the derivative thing then can prob google finding min/max of a function and find something

lost creek
#

so i have this function, i've determined that it has a pole of order 3 at z =0. I'm having trouble finding the residue at z = 0

#

used series expansion instead

sour cypress
#

Hey, in the formula (see attached image) the result is 1.08. My question is, is it possible for me to figure out the S and F values if i only know the RESULT value, for example if my RESULT is 5.2 what would S and F have to be in order for the formula to be valid?

gray gorge
#

You've got one equation and two unknowns S and F, so no

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Unless you have an additional, different equation relating S and F to each other

sour cypress
#

Ok thanks

carmine lion
#

how do i eliminate the parameter

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$x=a\cos \theta - b\sin \theta \$
$y=a\sin \theta + b\cos \theta$

ocean sealBOT
light dagger
#

Hey guys can u guys help me? my question is: how can i divide N items into M groups with as near equal size as possible

carmine lion
#

bruh i took the channel

carmine lion
gray gorge
carmine lion
#

theta

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basically just a direct relationship between x & y

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no theta

light dagger
# noble sinew Divide it into N groups :))

for example: I have 39 runners and I need to split them into equal groups with those groups being as big as they can (up to 8 runners per group) while still being near equal.

carmine lion
loud barn
#

Wal first figure out what numbers from 1-39 can be divided into 39

noble sinew
#

But okay I asumme 1<M<N? Then find common divisor of N (39), which is 3,13. So we can have 3 runners in each group

light dagger
#

but in that case i will have 13 groups, i want to have the small number of groups but they had to have the max size as possible

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for example 4 groups of 8 and one of 7

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and i want my algorithm to work with every number

gray gorge
# carmine lion so yea

the idea is that you wanna write sin(theta) and cos(theta) in terms of a, b, x, and y
so here's a hint: calculate ay - bx, and also calculate ax + by

noble sinew
#

define near equal then

alpine sable
#

The volume of the sphere is

You can use 3 as an approximate value for ฯ€

No calculator allowed

light dagger
#

for example 90 runners and i want them to be in groups of 8. u can do 90/8= 11.25, 11 groups of 8 runners and the last one will only have 2

#

i want the groups to be the max size possible but near equal.

noble sinew
#

Yes so it is to make it into as few groups as possible then minimise length of group i from group i+1?

light dagger
#

i know that i can just take one member of witch group until i fill the last group

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I thought there could be some possible mathematical calculation

alpine sable
#

how are you weighting the two factors

#

average size of a group and standard deviation of the sizes of all the groups

noble sinew
#

So in the example with 90 the best solution would be 6 groups of 7 and 6 groups of 8?

#

or what

light dagger
#

8+8+8+8+6+4
8+8+8+7+7+5
8+8+7+7+7+6
8+7+7+7+7+7

#

something that does this.

alpine sable
#

so start with 12 groups of 8, then remove one from each group until you get to 90 total

knotty garnet
#

Or start with 11 groups of 8 and add one to each group

noble sinew
#

Your top one is 42 and the other ones are 43 total btw from what you posted

light dagger
#

yeah that's the way i will program this, but i thought that was a possible math equation to know the answer

knotty garnet
#

Yeah you already did it

#

90/8

#

N/m

light dagger
knotty garnet
#

Then floor it and give the remainder to some of the groups

light dagger
gray gorge
#

tfw you want to make groups of 8 and in the end you only end up with one group of 8 sadcat

knotty garnet
#

Er 12 groups of 7

#

My bad

light dagger
gray gorge
#

o

light dagger
#

i only want the number per group be the biggest possible in each group.

karmic spoke
#

Is this 27.86 or 25?

#

the answer was 25 but I got 27.86 idk what I got wrong

#

๐Ÿ˜”

tidal badge
#

what is that in the bracket

#

0-12.30?

tidal badge
karmic spoke
#

yeh

#

12:30

#

sorry for answering late

#

@tidal badge

tidal badge
#

as in, time?

#

or 12.30, decimal

#

@karmic spoke

alpine sable
#

looks like a colon

tidal badge
#

yea thats what i was thinking

alpine sable
#

some people use that ratio for division

tidal badge
#

ahhhh

#

makes sense

alpine sable
#

which is not wrong

#

A:B is A/B

tidal badge
#

yea ive just never seen it written like that in a solution

#

in that case 12/3=4 but the square cancels with the root? and 25^2 is 625 so 625+4

#

but

alpine sable
tidal badge
#

does that mean the entire thing is under the root then?

violet loom
#

Guys I need help

#

This question, dafuq

tidal badge
alpine sable
#

yesss exactly, but it still doesn't equal 25 so idk

tidal badge
#

i wonder if they wanted them to round?

#

so then 4^2+25^ = 641, if you root that, you get 25.31

#

which rounds to 25

#

oh nvm its divided by 30

#

u right

alpine sable
#

ohhh, I interpreted it as 0-12.3

tidal badge
#

its 0-0.4

#

which is still

#

625.16

alpine sable
tidal badge
#

so root that and yea u get 25.00

#

ye ye

#

lol had a field day with that ratio

alpine sable
#

ahahahaa my dumbass wasn't even able to read it ๐Ÿ˜ƒ

tidal badge
#

same tho phew lets look at this parametric question

#

ahh i believe this is a further topic on polar coordinates since theres that 2r for the y

violet loom
#

It should just be regular A level parametric

tidal badge
#

hmm okay lemme see

#

the whole thing with parametrics is equating your equations for t

violet loom
#

I get that bit but the y parametric doesnโ€™t have a t in it

tidal badge
#

yea and they haven't defined r at all

#

it could be a misprint, let me solve and suppose r = t

#

yea okay so

#

i think its a misprint because it works

#

k= 9/4 and you will obtain the given form

#

try solving it and assume r=t

#

@violet loom

violet loom
#

Thank you @tidal badge

tidal badge
#

no problem

junior magnet
#

could anyone explain how the summation on the left is simplified to the formula on the right? I can't seem to see it

gray isle
#

seems to be applying the formula for the sum of the first n squares

junior magnet
#

oh okay, thanks! I'll look that up

carmine lion
#

hey gy

ocean sealBOT
carmine lion
#

how do i simplify this

tough ether
#

If I have a complete directed simple graph on n vertices where between any pair there exists a edge in both directions, why is that thing edge transitive? This was trivially stated, but what is the explicit automorphism?

karmic spoke
#

@tidal badge oh I see

#

Thanks

#

But would that ratio thing still hold up since 12:30 is fine

#

Time*

#

Not ratio

#

Sorry for not being clear

#

And sorry for not being here

#

I was doing something rq

shell widget
#

@carmine lion try multiplying/dividing by 1 + cos(theta) + sin(theta)

shell widget
#

you got that?

carmine lion
#

yes

shell widget
#

lemme check

carmine lion
#

im aiming to get to this last step

#

cuz its a proof question

#

$\frac{1+\sin\theta}{\cos\theta}$

ocean sealBOT
nocturne wolf
#

I need help

carmine lion
#

is taken

#

please go to another channel

nocturne wolf
#

Wht

#

Oh okay

carmine lion
shell widget
#

im getting something else

carmine lion
#

huh

#

what are u geting

shell widget
#

can u show ur working

carmine lion
#

ok

carmine lion
shell widget
#

idk what uve done

#

the numerator becomes $( 1 + cos\theta + \sin\theta )^2$ and the denominator becomes $( 1 + \cos\theta )^2 - \sin^2 \theta$

ocean sealBOT
shell widget
#

using (a+b)(a-b) = a^2 - b^2 identity for the denominator

#

now expand the numerator using (a+b)^2

#

same for denominator, expand (1 + cos(theta))^2 using a^ + b^2

carmine lion
#

$\frac{[(1+\cos\theta)+\sin\theta]^2}{[(1+\cos\theta)+\sin\theta][(1+\cos\theta)-\sin\theta]}$

ocean sealBOT
shell widget
#

yes

carmine lion
#

did i do something wrong here

shell widget
#

thats right

carmine lion
#

so?

shell widget
#

now expand the numerator using (a+b)^2

#

and for denominator, you have (a+b)(a-b) = a^2 - b^2

carmine lion
#

yea

#

so shouldn't u get what i wrote

shell widget
#

no

#

try again

neon tinsel
#

Can I send an image here?

shell widget
#

$\frac{1 + 2\cos\theta + \cos^2 \theta + 2( 1 + \cos\theta )( \sin\theta ) + \sin^2 \theta}{1 + 2\cos\theta + \cos^2 \theta - \sin^2 \theta}$

carmine lion
#

is that right

#

so far

ocean sealBOT
shell widget
#

This is what you should get

carmine lion
#

yes

#

then what

shell widget
#

cos^2 + sin^2 = 1

#

1 + 1 =2

candid torrent
#

this trig is disgusting

neon tinsel
shell widget
#

$\frac{2 + 2\cos\theta + 2\sin\theta + 2\cos\theta \sin\theta}{2\cos\theta ( \cos\theta + 1 )}$

ocean sealBOT
carmine lion
#

yes

#

i got there

neon tinsel
#

Try this maybe?

gaunt ember
#

probably a very stupid question but, if there isn't a number near the 1st Y, how can divide?

#

equations system btw

gray isle
#

um you really need to improve your handwriting

#

i'm finding it extremely hard telling your ys and 4s apart (which also look somewhat like Gs and lightning bolts)

gaunt ember
#

wait i'll rewrite it

gray isle
#

,rcw

ocean sealBOT
gaunt ember
#

those "lighting bolts" are 4

alpine sable
#

why would u divide?

gray isle
#

if you insist on doing some stuff like that, consider y = 1y

gaunt ember
gray isle
#

if you wanted to solve using substitution, you could add 4 to both sides of the first equation

#

to isolate y

#

which you could then sub into the second

alpine sable
#

or divide by 4 in the second one

gray isle
#

^

gaunt ember
#

got it

#

thanks

alpine sable
#

would this be A?

#

<@&286206848099549185>

noble sinew
#

Yes

native temple
#

Hello

#

Can rational expressions not have a common demoniator

raw valve
#

@native temple yes I'm pretty sure

native temple
#

oh

oak chasm
#

@native temple Do you mean within a single rational expression or two or more rational expressions?

native temple
#

is it because some polynomials arenโ€™t factorable

#

by any method?

oak chasm
#

Polynomials are always factorable over the complex numbers.

native temple
#

what do you mean over the complex numbers

ocean sealBOT
#

Chai T. Rex

native temple
#

is that by p/q?

#

in the complex plane

#

how would you even find those numbers....?

oak chasm
#

No, it's because the complex numbers are a splitting field.

#

I don't know all the methods, but, for example, Wolfram Alpha can compute the roots.

native temple
#

ohh

oak chasm
#

Some polynomials can't be factored over the real numbers, though.

alpine sable
#

but all polynomials can be written by linear and quadratic factors

rare lotus
#

how do i go about answering this

#

mostly i

oak chasm
#

@rare lotus Which discrete probability distributions do you know?

rare lotus
oak chasm
#

Try what?

rare lotus
oak chasm
#

See if one of the descriptions matches.

rare lotus
#

ight jn

alpine sable
oak chasm
#

@alpine sable Sorry, channel is busy.

alpine sable
#

unfrrtdyoof

#

understood*

oak chasm
alpine sable
#

i think im in the wrong server as well

oak chasm
#

Oh, OK.

rare lotus
oak chasm
#

Yes, I think you're right.

#

What parameters does the Wikipedia article for binomial distribution list?

rare lotus
#

yes/no

oak chasm
#

No, that's the decision or something, what numeric parameters does it list?

rare lotus
#

"It is a discrete probability distribution with two parameters, traditionally indicated by n , the number of trials, and p , the probability of success."

oak chasm
#

OK, so that should answer part i.

ocean sealBOT
#

Chai T. Rex

oak chasm
#

That's also part of part i.

ocean sealBOT
#

Chai T. Rex

rare lotus
oak chasm
#

@rare lotus Please keep reading past that ๐Ÿ™‚

rare lotus
#

i think i have somewhat an idea what to do now thank you

oak chasm
#

You're welcome.

oblique charm
#

hey i have a combinatorics question and i have no clue which formula to use

oak chasm
#

@oblique charm How far have you gotten?

oblique charm
#

i've gone as far as having k = 2 and n = 12

#

if that makes any sense

#

i'm not entirely sure if i'm supposed to use k-selection formula or k-combinations

sudden patrol
#

i need help

oak chasm
#

@sudden patrol Sorry, channel busy.

#

There's only one pear left, but enough of each of the other fruits to satisfy the two you have to pick.

#

So, separate it into a sum where one term has you picking the remaining pear and one term has you leaving the one pear.

oblique charm
#

uhhh

#

i'm sorry i'm going in clueless but i get what you mean

#

i do know i have to use one of these formulas, unless i'm wrong

oak chasm
#

You have to choose one fruit from banana, apple, and kiwi + you have to choose two fruits from banana, apple, and kiwi.

oblique charm
#

okay okay, i'll see what i can do for thatt

jovial adder
#

Determine the convergence or divergence of the following improper integrals. If an improper integral converges, evaluate it. $\int xe^(-x^2) dx$ Where the limits of integration are 0 to $\infty$

ocean sealBOT
#

RudyTheButler

alpine sable
#

Google confused me with the formula lol

#

assuming its a half circle

#

calculate the area of one of the half circles

#

and multiply by lenght to get volume

#

So i have to calculate the area of the half circles then multiply by 15 and that gives me volume

#

of one

#

just one half circle

#

how would u do that

#

A = 3.14 x r^2/2

= 3.14 x 36 /2

= 56.52

#

use pi

#

3.14 right

#

so pi*r^2/2

#

to get 18pi

#

What

#

$\frac{\pi\cdot r^2}{2}=\frac{\pi\cdot6^2}{2}=\pi\cdot18=18\pi$

ocean sealBOT
alpine sable
#

to have an exact value

#

u can round up at the end, not in the middle

#

ok thx

glacial pelican
#

pls

alpine sable
#

how do i get sa though

#

occupied

#

the area (halfcircle) is 18pi so what is the volume

#

847.8

#

or 18*15 *pi

#

and u get that correct

#

oh yeah i have to round

#

yeah underestandaple

#

im not a human calculator tho so cant tell

#

ye

#

then the area

#

of the entire figure

#

This is what i did

#

thats fine

#

u should use the pi symbol

#

and round up at the end

#

o

#

now u rounded up in the middle assuming pi=3.14 even tho it is not

#

my teacher says just make pi = 3.14

#

i dont think it matters here but generally that is the case

#

k

#

how do I find sa now?

#

the area of the entire figure

#

how I find that

#

what sides does it have

#

er

#

like it has 2 half circles

crude root
alpine sable
#

one in both ends

#

ye

crude root
#

its a half a cylinder so do half the formula

alpine sable
#

no

#

so

crude root
#

semicircle area x height

#

then

alpine sable
#

k

#

we already did volume

#

ye we need sa

#

we are doing surface area now

crude root
#

in the cross section

alpine sable
#

pls

#

let me explain

crude root
#

o

#

ok

alpine sable
#

hmm

#

using formulas does no good if u dont know where they come from

#

ye

alpine sable
#

ok so we have 2 half circles

#

and the rectangle in the back

#

and that curvy bit

#

SA of Cylinder = 2x3.14xrxh + 2x3.14xrx2

#

do i jus do that then divide the answer by 2

#

no

#

then get sa of rectangle and add those two together to get the total surface area

#

waht

#

u know the area of the half circles

buoyant anchor
#

I need help solving my hw problem

alpine sable
#

they are 18pi as we calculated'

#

occupied

#

oh

#

so we have 2 half circles

#

the rectangle

#

yes

#

which is how much?

#

3

#

whar

#

show how did u get that

#

uh 2 half circles = 2

#
  • the rectangle is 3 shapes lol
buoyant anchor
#

I don't know where to start

alpine sable
#

nvm

#

how do u calculate the area of a rectangle

#

l*w

#

what is the lenght and what is height

#

and pls use * if you could

oak chasm
#

@buoyant anchor Sorry, channel busy.

alpine sable
#

15*6

#

that x is throwing me off

#

is it 6?

#

yes

#

look carefully

#

12

#

good

#

so 12*15

#

or 180

#

yes

#

then the curvy bit

#

how would u do that

#

I dnt know

#

imagine straightening it up

#

what shape would it have

#

Rectanglular right

#

yeah

#

we know one of its sides

#

correct

#

yes

#

what is the other side

#

equal to

#

umm

#

Is it 12

#

why

#

6

#

why

#

will it be longer than the bottom rectangle

#

no

#

oh 15

#

why

#

because bottom one is 15

#

and side is 6*2 would be 12

#

yeah that was the one we knew

#

but when u straighten it it gets longer

#

like if u have a string

#

and u straighten it

#

it gets longer

#

yes

#

so

#

the other side is equal to what side

#

in the diagram

#

Bottom?

#

it is longer than the 12 in the bottom

#

o

#

its equal to the half circles side

#

can u see it now?

#

no bro

#

i stll dont get it

#

wait a sec

#

k

#

i mean this

#

of the half circle

#

s

spice tendon
#

What is the answer to this?

alpine sable
#

idk

nova slate
#

Lol

#

Idk

ionic jewel
#

probably 4 for both

alpine sable
#

occupied

ionic jewel
#

i think it wants you to complete the square?

nova slate
#

Yes

#

I think same

ionic jewel
#

oh sorry delta

alpine sable
alpine sable
#

ill try and find a video so u can see why

#

k thank you

#

when u fold a paper to a cylinder

#

one of its sides will be equal to the circles cirumference

#

@alpine sable

#

Ohh

potent knoll
alpine sable
#

no

#

y+14+0 isnt 0

alpine sable
#

hanh yeah i know

potent knoll
alpine sable
#

but it is not 0

#

i just fucked up my explanation

dire wren
#

lmao its 4

#

because you can complete the square into (x+2)^2

#

just as bunny said

alpine sable
#

Tysm @alpine sable

#

did u get it

static pasture
#

Hi! could someone please help with this

ionic jewel
static pasture
#

im still lost lol

ionic jewel
#

alright lets use angle C

ionic jewel
#

soh cah toa

static pasture
#

To be honest I have no clue...

ionic jewel
#

tan(x) = opposite side divided by adjacent side

static pasture
#

so would it be 27 divided by 6?

ionic jewel
#

opposite side

#

27 is an angle not a side

#

what side is opposite the 27 degree angle?

static pasture
#

its a triangle... there is none? Sorry im really bad at math.

#

does the right angle have somethingn to do with it?

ionic jewel
#

trig only works because its a right angle

ionic jewel
#

look at the triangle

#

what side is far away from angle C

#

the only sides that isnt part of making angle C

static pasture
#

a

ionic jewel
#

a??

#

there is no side named a

static pasture
#

sorry im lost

ionic jewel
#

the triangle is made of 3 lines

#

AB, BC, and AC

#

one of them is oppsite of angle C

#

the one on the other side of the triangle