help-0

[daring violet]

oh aight

[alpine sable]

PQ would be pir^2(110/360)
PRQ would be pir^2(250/360)

[daring violet]

move to #help-8

i'll help

[pallid horizon]

K

[alpine sable]

why the fuck is it in italics but

[terse iron]

ok thanks

[glass lichen]

italics *italics*

[balmy radish]

Hello, any help on that one please ? (it's not an home work)

We know $D$ and $A$, solve for $x$ \\
$D = \sin(A)\sin(x)+\cos(A)\cos(x)$

[vale wigeon]

for future reference, the commands \sin and \cos exist

anyway, this is literally just cos(x-A) = D

[ocean seal]

ScottHamilton

[alpine sable]

this is just a trig identity

[balmy radish]

Ok, thanks

[alpine sable]

@balmy radish these

[balmy radish]

Ok

[alpine sable]

Hi is this channel in use?

[daring violet]

no

[hexed nimbus]

I have a multiple choice question that I would just like to get confirmation on if its correct or not:

[woven shoal]

hey posato, i need help with my exercice

i dont understand it

[daring violet]

i'll take a look into it

oh no

[woven shoal]

what

dont say oh no

[daring violet]

sorry can't help you here

i don't know where to start

[woven shoal]

why

oh

ok thanks anyway

do you know any other place

where i can find hel0

help*

[daring violet]

no clue

[alpine sable]

i can help you with this

AMND is a square

[daring violet]

ohhhhhhh

[alpine sable]

so lets focus on AMND see if you can fill in any central angles

[woven shoal]

the problem is

in my class, we havent do geometry

because of covid

and im 15 years old

...

[alpine sable]

but they still give you geometry assignments to do?

covid sucks

[woven shoal]

this is my first homework of geometry

they just talked 'bout TRIANGLES

[alpine sable]

do you know about circular sectors central angles and area of triangles?

[night blade]

dont ping helpers immediately. nobody wants to help you when you do. read the rules

[woven shoal]

no

wth is that

[alpine sable]

is this channel in use?

yes

[woven shoal]

man

[alpine sable]

lets label the center point O

[woven shoal]

whats that

realize im 15 years old and i dont even know what a vertex is

so chill

[alpine sable]

vertex is just a point

[woven shoal]

its an example

[alpine sable]

first step to solve the problem is to find angle AOM

there's some symmetry in this problem that we can use

[woven shoal]

wheres O

[alpine sable]

center of the circle on the left

[woven shoal]

oh

k

[alpine sable]

on the left*

[woven shoal]

its left

oh

kk

i think i understand it(my brother explained it)

is it 100cm2

??

[alpine sable]

let me check

[alpine sable]

correct

[woven shoal]

yess

[alpine sable]

oh actually looking back at it now i see a much faster way to solve it

[woven shoal]

can u tell

[alpine sable]

we "shift" the area in the circle

[woven shoal]

can you tell me is another ex is good?

[woven shoal]

i dont understand

how did you do it

anyway

can you tell me if this is correct please?

A card has a diagram printed on one side and the other side is plain white. The card is first flipped over downwards and then to the right (see diagram below). Which picture is obtained

i choosed this one

[alpine sable]

so you end up with something looking like this

for the other problem, after shifting the area

[woven shoal]

what do i have to do after of doing that

[daring violet]

oh crap that is 100cm^2

[alpine sable]

add up the area of the triangles

[woven shoal]

and?

[alpine sable]

you'll get 100

[woven shoal]

hw

wait wait

explain how

[daring violet]

i got something completely different

[woven shoal]

same

[daring violet]

lemme take a photo

[woven shoal]

but one friend says thats the correct

one

[alpine sable]

so realize that the regions A and B have the same area

[woven shoal]

yes

[alpine sable]

so if we color A white, and B grey, the shaded area stays the same

[woven shoal]

i dont understand

sorry im spanish

my english is not that good

i have to leave for 7 minutes, can u wait?

[alpine sable]

ok but idk if i can help at that time

[woven shoal]

here back

[woven shoal]

can u explain?

or show a phoyo

phoyo

photo

[ornate grove]

If one eigenvalue of the matrix of order 2 is À=0 the it is invertible
T F

[wild jungle]

https://gyazo.com/968631e6baef6004f5dc4f474992c70b

please help

[alpine sable]

find arc JK

find arc KL

[woven shoal]

several people are

[alpine sable]

find arc IH

I mean you can find all of em

[woven shoal]

know the answer?

i tried and cant find it

[alpine sable]

IJ is pretty straight forward

[alpine sable]

You should notice all angles are central angles

Is this

some brain test or smth

[woven shoal]

are u talking to me

no

its homework

[alpine sable]

Yeah but doesn't even seem math related

it's just a matter of you visualising

what's happing

[woven shoal]

geometry

[alpine sable]

in ya head

[woven shoal]

the problem is

i dont have a brain

please help

[alpine sable]

also

[cunning junco]

May I send a question here?

[alpine sable]

it says

what picture is obtained

what's the picture

[wild jungle]

@alpine sable wait what is IJ

[woven shoal]

different options

do i send them

[alpine sable]

yes please

[alpine sable]

Angles there are supplementary

[alpine sable]

You should notice the angles lie on a straight line

so just 180-95-45

[woven shoal]

there you go

options

[alpine sable]

Top right

[wild jungle]

yeah ik everything but IJ and HL

[woven shoal]

B?

[alpine sable]

yeah

B

[woven shoal]

ty

[final skiff]

Hey I need someone to confirm this is right or wrong

[woven shoal]

@alpine sable

[alpine sable]

@wild jungle

Cause they're supplementary

[final skiff]

(2t^4)(2t^4)(2t^4) = (2t^4)^3

Is this true or false

[alpine sable]

true

[final skiff]

Yeahh so my friends are idiots then

[alpine sable]

what's a*a*a

[final skiff]

They are telling me I'm wrong

[pallid horizon]

Can someone help me in 8 or is everyone busy

[alpine sable]

your homework is doo

i don't like it

cause it requires more brain power than actually physically doing shit

[woven shoal]

I KNOW

[alpine sable]

my mental capacity is doo doo

[woven shoal]

I dont even know whats a poligon

[final skiff]

Nvm it was just confusion

[alpine sable]

Polygon

[woven shoal]

my bad

im spanish

and its poligon here

[alpine sable]

no worries

[final skiff]

So someone wrote a false equation and I was trying to say its wrong. And they thought I meant it was right

[alpine sable]

ok so each page has an area of 4?

meaning the square?

So the square has an area of 4

[alpine sable]

See the image on the left

the area of that will equal to the triangle on the right

[woven shoal]

give me an answer please

[alpine sable]

Still confused on this one phil?

[alpine sable]

4

the image on the left is equal to the image on the right

no

whjat

no

wait

stop

I'm brain dead

[woven shoal]

some people say its 6 😦

😦

[alpine sable]

Is each square

4a?

4

has an area of 4

[woven shoal]

idk

read the thing

so answer is

??

[alpine sable]

yeah

6

[woven shoal]

ty

[alpine sable]

can't be bothered

if the majoirt say 6

it's 6

[woven shoal]

now next ex

yeah but imagine you re right

and you are albert einstein

[alpine sable]

nope

[woven shoal]

answer

now

baby

[alpine sable]

baby?

[woven shoal]

like

baby boy

im a fuck girl

[alpine sable]

baby boy?

a fuck girl?

[oak chasm]

<@&268886789983436800>

[woven shoal]

SORRY

NO

[sly mantle]

what's this

[woven shoal]

DONT BAN ME

I WERE JOKING PLEASE

well ok ban me

[gray gorge]

[alpine sable]

huh

ok

[woven shoal]

but

before i get banned

please answer

very important

[sly mantle]

please familiarize yourself with the rules

[woven shoal]

yes

[sly mantle]

in particular we don't straight up give answers here

[alpine sable]

yup

[heavy otter]

please take your time reading the rules

[misty moat]

any help?

[limpid spade]

Circle - triangle

Area of circle - area of triangle

Wait no

[oak chasm]

@misty moat Area of the portion of the circle minus area of triangle.

[limpid spade]

Yes

[viral owl]

hey guys

[misty moat]

i still dont understand how to get the answer

[alpine sable]

find the missing arc measure

that'll be that central angle thing

[limpid spade]

Hi

[misty moat]

still doesnt help xd i need some1 to explain how do i get the answer and the steps getting there

[oak chasm]

@misty moat What's the angle next to the center of the circle of that triangle?

[misty moat]

it doesnt say

the picture is all the info

[oak chasm]

Right, but there's another angle. What is that for?

[misty moat]

im not sure

the other half of the circle idk

[alpine sable]

what other half

[misty moat]

the other half of the circle thats not shaded in

[alpine sable]

Damn would be nice if they labelled the things

So it'll be much easier to verbally explain

[cold monolith]

The large arc is 240 degrees

[alpine sable]

Can you find the measure of the remaining arc

[cold monolith]

How large is the small arc?

[misty moat]

120?

[alpine sable]

ok cool

[misty moat]

thats a guess im not sure

[alpine sable]

how'd you guess that

it's quite logical

really

you're not wrong

ok now using that

you could easily find the rest

[misty moat]

uhh no

i literally said i dont know how to get the answer and youre saying its easy to get the answer and expect me to know the answer when i legit came here since i dont know the answer lmao

[alpine sable]

Central Angle Theorem.

if the measure of the remaining arc

is 120

therefore the measure of that angle between those 2 radii are

......

[misty moat]

idk

[alpine sable]

also 120

The measure of the intercepted arc and the central angle are equivalent.

ok find the area of the sector

[misty moat]

?

[alpine sable]

the area of the sector

[misty moat]

is what

[alpine sable]

Do you know what a sector is??

A circular sector or circle sector (symbol: ⌔), is the portion of a disk enclosed by two radii and an arc, where the smaller area is known as the minor sector and the larger being the major sector.

[misty moat]

a secotr of a circle is a region bounded by an arc of the circle and the two radii to the arc's endpoints

[alpine sable]

ok

now find the area of it

[misty moat]

so 25x240divided by 360?

[alpine sable]

what

$A_\triangledown=\dfrac{120^\circ}{360^\circ}\cdot\pi\cdot5^2$

[misty moat]

oh 25x120 divided by 360?

[ocean seal]

Several people are

[misty moat]

i think that might be why i was getting it wrong

[alpine sable]

That upsidedown triangle is supposed to be ⌔

but couldn't find the syntax for it

[misty moat]

so 8.3?

[alpine sable]

ok so that's the area of the sector

[winter yacht]

hey

[alpine sable]

find the area of that triangle

the isosceles triangle

then just take the area of the sector from the isosceles

[misty moat]

what

how do i find the area of that triangle

[alpine sable]

uh

.

many formulas

[viral owl]

several people are

help

[alpine sable]

uh

forgot about you guys

[normal turtle]

help

[viral owl]

The diagram shows two rectangles whose sides are parallel to each other. By how much is the perimeter of the bigger rectangle greater than the perimeter of the smaller rectangle?

[surreal meadow]

hopefully this makes it clear

[surreal meadow]

im assuming you know riemann squares?

[viral owl]

i think its 24

can you confirm?

its because the big one does 36 and the little one 12

and 36 - 12 is 24

[surreal meadow]

24 looks right but i dont get your reasoning

[viral owl]

let me tell why

im not a mathematic so idk too

but

wait no

or yes

this is so difficult

let me explain with paint

idk if you understand but i + all the sides

and then i + them

and i got the big parameter

then i did the same with the small one

and got 12

so 36-12 is 24

if im wrong say it please

im going to give the home work back via digital

[surreal meadow]

its impossible to get the small perimeter

[viral owl]

oh

[surreal meadow]

we don't have side lengths for it

[viral owl]

its 12

[surreal meadow]

if you want to do something similar

[viral owl]

right

[surreal meadow]

you can do this:

so we have that

the long side lengths are W

and the short are L

so the perimeter is 2L+2W

and the big perimeter

is

(2L+2W) + 4 + 4 + 2 + 2 + 3 + 3 + 3 + 3

so the difference would be

(2L+2W) + 4 + 4 + 2 + 2 + 3 + 3 + 3 + 3 - (2L + 2W)

which is 24

[viral owl]

OI FUCK ANOTHER DUDE TELLS ME ITS 12

OMFG

what do i do

[surreal meadow]

who said 12?

how did they get that?

[viral owl]

another server

im waiting them for response but wait

[surreal meadow]

here ill paint it again more clearly

[viral owl]

2(l+b)

2(l+7+b+5)=2(l+b+12)

Comparing both, we get answer as 12.

he said that

[surreal meadow]

the red sides we can get rid of

since they are the same for both

so

now we can add up the lengths

the top left is 2 + 3 = 5

top right is 2 + 4 = 6

bottom left is 3 + 3 = 6

bottom right is 3 + 4 = 7

5 + 6 + 6 + 7 = 24

[viral owl]

this is so difficult to my brain

[surreal meadow]

the picture should make it clear

the red sides are shared by both rectangles

so we don't include them in the calculation

[viral owl]

im sending the same thing u said to the other dude

and lets see what he says

he said u made a mistake, the formula of the perimeter is sum of all sides, or 2(l and w) for rectangles

[surreal meadow]

can you send me an invite to the server

[viral owl]

sure

[alpine sable]

there's this question that's been on the student forum for 5 years and still nobody's answered it. I think the person made a typo and it should be y=kx^n. Does anyone think they can do it?

[viral owl]

i dont understand these ones

of my homework

[viral owl]

6

[viral owl]

100cm 2

tell me if im wrong

[surreal meadow]

$\ln(ny) = \ln(kx^n)$ and therefore $\ln(n) + \ln(y) = \ln(k) + n\ln(x)$ and so $\ln(y) = n\cdot\ln(x) + C$ where $C =\ln(k) - \ln(n)$

[ocean seal]

maximo
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[surreal meadow]

so the trend is visible because ln(y) is proportional to ln(x) by a factor of n

table and graph are self explanatory once you have the above formula

and so should be estimating the values

[surreal meadow]

yes

[surreal meadow]

how did you get 100?

[viral owl]

i dont remember fine but let me explain

nah i dont remember

if its wrong, can u explain how please

if tommorrow they ask me how did i resolved it, im gonna be dead

[surreal meadow]

@viral owl try it again

and show me your work

[viral owl]

no gonna lie man i just choosed a random number of the options

sorry for lying

[surreal meadow]

then try

and give me an explanation and i'll help you go from there

[viral owl]

i dont even know how to start

but one thing

i really need help at the other ex

the 24 one

[surreal meadow]

what 24?

[viral owl]

the 12 and 24 issue

[alpine sable]

Hello can someone help?

Given this dot product, https://gyazo.com/d7985836b10a11aa9ac976abbb196f15 , with coeficients on C, how can i prove z^n is orthonormal?

[surreal meadow]

what part of it do you need help with

[viral owl]

i dont understand how did you get that solution

got

[surreal meadow]

did you look at the picture

?

i feel like that's the clearest way to show it

[viral owl]

can you send it again?

or its in the other server

[viral owl]

ok

[surreal meadow]

your goal is to find the difference between the perimeters

that red perimeter is the perimeter of the inside square

[viral owl]

wait

that

right?

[surreal meadow]

yes

[viral owl]

kk

[surreal meadow]

and do you see how the red sides are also on the big rectangle?

[viral owl]

yes

why?

[surreal meadow]

wdym why

[viral owl]

these?

[alpine sable]

ohhh thank you, i think that makes sense

[surreal meadow]

yes

[surreal meadow]

np

[viral owl]

why are those there

[surreal meadow]

they are the same length as the inside lengths

[viral owl]

OH

ok

[surreal meadow]

and the yellow and red lines above and below it

those are the lengths they gave us

[viral owl]

yes

[surreal meadow]

ok but we want the difference between the two perimeters

[viral owl]

yes

[surreal meadow]

and since all those red sides are in both perimeters

we can remove them

what we're doing here

is taking the big perimeter

and subtracting the small perimeter

[viral owl]

ok

[surreal meadow]

do you follow>

[viral owl]

no

[viral owl]

here

why you take it

[surreal meadow]

we want to find the difference

so we do big perimeter - small perimeter

[viral owl]

ok

and?

[surreal meadow]

then you just add up the side lengths

and you're done

[viral owl]

man the problem is i dont understand how to do that

[surreal meadow]

ok im going to do it algebraically

[viral owl]

i understand we want to do big- small

no no please

is it hard

[surreal meadow]

the pictures are clearly not working

[viral owl]

yeah

[surreal meadow]

so this is the next best approach that I know of

[viral owl]

ok u can start

[surreal meadow]

the perimeter of the smaller rectangle

actually

lets start with this picture right here

those are the side lengths for the width and length of the rectangle

[viral owl]

what

sorry if im an idiot

i just dont understand

[surreal meadow]

the original picture doesn't have side lengths for the inside rectangle

we're just calling them W and L

they might as well be 10 and 15

200 and 345

whatever

they are just L and W

[viral owl]

k

[surreal meadow]

its just a variable for their size since we don't know their size exactly

ok

so if we want the perimeter of that small rectangle

then we do

W + L + W + L

do you get that?

[viral owl]

yes i do

[surreal meadow]

ok

so now to compute the larger perimeter

the top side length of the big rectangle

is 3 meters on the left + W + 4 meters on the right

do you get that?

[viral owl]

yes

[surreal meadow]

ok

so the top side length is 3 + W + 4

or

W + 7

another channel please

[viral owl]

1

[surreal meadow]

following that

the top and bottom sides are equal

[viral owl]

yeah

[surreal meadow]

so the top is W + 7 and the bottom is W + 7

now

can you do the same thing for the left and right side

[viral owl]

yeah

5+L

right

?

[surreal meadow]

right

so we have W + 7, W + 7, L + 5, L + 5

and we add them up

[viral owl]

yes

[surreal meadow]

we get

2W + 2L + 24

and we want to find the difference between this and the small perimeter

so

[viral owl]

isnt it 12

[surreal meadow]

2W + 2L + 24 - (2W+2L)

[viral owl]

?

[surreal meadow]

no

[viral owl]

wait

[viral owl]

i dont understand this part

[surreal meadow]

2W + 2L + 24 is the big perimeter

(2W+2L) is the small perimeter

we want the difference between them

so we want to subtract them from each other

[viral owl]

but what 2W means

[surreal meadow]

look at the picture again

W is the arbitrary side length we gave to the big side on the small rectangle

[viral owl]

can you paint it

[viral owl]

oh there are 2 W so then the two W's?

[surreal meadow]

yes

and 2 Ls

[viral owl]

OH

i see

then its

5+7+24- what

[surreal meadow]

what?

where did you get that

[viral owl]

there are 2W, 2 and 3

2+3 is 5

[surreal meadow]

here

im gonna draw 2 more lines

[viral owl]

k

[surreal meadow]

what is the length of the blue line

[viral owl]

3

[surreal meadow]

and yellow?

[viral owl]

4

[surreal meadow]

so if i do this

what is the length of that side

3 + 4 + W right?

[viral owl]

yes

[surreal meadow]

so the big side on the big rectangle

is 3 + 4 + W

now

what is this side length

L

right?

[viral owl]

yes

[surreal meadow]

what about the green and pink?

[viral owl]

2 and 3

[surreal meadow]

ok

so the small side

on the big rectangle

what is the side length for it?

[viral owl]

2+3+L

[surreal meadow]

right

so L + 5

so one side is W + 7

the other is L + 5

so what is the perimeter for the large rectangle?

[viral owl]

idk

[surreal meadow]

do you know what perimeter means?

[viral owl]

yes

[surreal meadow]

how do you calculate perimeter?

[viral owl]

sum

all the

i cant say it in english

sumas todas las arestas

[surreal meadow]

hablas espanol>

listo

tenes que sumar los lados del rectangulo

[viral owl]

si

[surreal meadow]

entonces

si un lado es W + 7

y el otro es L + 5

entonces cual es el perimetro?

[viral owl]

W+7+5+L?

[surreal meadow]

banca

[viral owl]

pero que numero es ese

como lo "convierto"

[surreal meadow]

acabas de hacer esto

te faltan 2 lados

[viral owl]

pero es lo mismo no?

[surreal meadow]

no

[viral owl]

fuck

[surreal meadow]

te faltan 2 lados

[viral owl]

si

[surreal meadow]

W + 7 + L + 5 + W + 7 + L + 5

si?

[viral owl]

si

[surreal meadow]

ahi tenes todos los lados

entonces

nos da

2 W + 14 + 2 L + 10

[viral owl]

si

[surreal meadow]

entonces

2 W + 2 L + 24

ese es el perimetro del rectangulo grande

ahora

cual es el perimetro del chiquito?

[viral owl]

se me olvido por completo

lo siento

[surreal meadow]

un lado es W

y el otro L

[viral owl]

si

[surreal meadow]

entonces

cual es el perimetro?

[viral owl]

del pequeño?

[surreal meadow]

si

[viral owl]

W+L

no?

[surreal meadow]

hiciste lo mismo

solo 2 lados

te faltan 2 mas

[viral owl]

2W+2L

[surreal meadow]

claro

y ahora tenemos los dos perimotros

grande: 2 W + 2 L + 24

pequeno: 2W+2L

y queremos la diferencia

[viral owl]

si

[surreal meadow]

entonces hacemos

grande - pequeno

(2 W + 2 L + 24) - (2W+2L)

y nos queda 24

[viral owl]

entiendo

muchas gracias

lo que no veo es porque antes dijiste 50

o algo asi

debatiendo contra el otro

[surreal meadow]

cuando

ah

nono

es que envez de usar W y L

[viral owl]

usabas 10 y 5

[surreal meadow]

dimos 10 y 5 para testear nuestras soluciones

[viral owl]

ahhh

pues muchas gracias, ahora lo que no entiendo es el otro

[surreal meadow]

pero no es buena idea hacer eso en el momento

este lo entendes?

[viral owl]

no

pero me dijeron la respuesta

y asi vamos mal

[surreal meadow]

bueno este es facil

[viral owl]

el problema es que en mi curso todavia no nos han enseñado ese tem

tema

y tengo 15 años

osea imaginate..

[surreal meadow]

sisi no te preocupes

ahora te lo explico

[viral owl]

ok

[surreal meadow]

bueno

el cuadrado tiene area 4

no?

[viral owl]

que significa eso

[surreal meadow]

area?

[viral owl]

si

area 4

[surreal meadow]

ah ok

sabes lo que son lados

no?

[viral owl]

no

[viral owl]

ahh

ok

[surreal meadow]

oops

el area es la parte azul en el ultimo cuadrado

digamos es el espacio que toma el cuadrado entero

vale?

[viral owl]

ok

[surreal meadow]

entonces

el espacio rojo aca

tiene area 4

ok?

[viral owl]

pero 4 cubitos?

AH NO

4 lados

[surreal meadow]

hm?

no te preocupes mucho de los lados ahora mismo

[viral owl]

como el cuadrado tiene 4 lados el area es de 4?

[surreal meadow]

no

[viral owl]

entonces no entendi

[surreal meadow]

al area es el espacio que toma una figura

te muestro

el cuadrado primero tiene area de 1 cm^2

[viral owl]

ah va por centimetros

[surreal meadow]

cuando usamos area

usamos centimetros cuadrados

[viral owl]

hm

[surreal meadow]

$cm^2$

[ocean seal]

maximo

[surreal meadow]

bueno pero

mirando la imagen

el area del primer cuadradito es 1 cm^2

y lo calculamos haciendo lado * lado

[viral owl]

entiendo

[surreal meadow]

como el lado es 1cm

nos da 1*1 = 1cm^2

el del segundo

tiene lados 2 y 2

entonces hacemos

2*2

4cm^2

se entiende?

[viral owl]

si

[surreal meadow]

entonces el ultimo cuadrado

que tan largos son los lados?

[viral owl]

a k te refiered

refieres*

[surreal meadow]

el cuadrado azul en la imagen

los lados del cuadrado

que tan largos son

[viral owl]

de 4 cm

[surreal meadow]

entonces como encontras el area

[viral owl]

espera que me ha dado un lapsus

no me lo digas

haciendo 4*4 no?

[surreal meadow]

sisi

claro

bueno

[viral owl]

ya veo

[surreal meadow]

entonces

volviendo a esta

este cuadrado rojo tiene area de 4

listo?

[viral owl]

si

[surreal meadow]

ok

entonces

cuales son los lados?

que tan largos?

[viral owl]

de 2

[surreal meadow]

perfecto

ahora

[viral owl]

si

[surreal meadow]

el cuadradito chiquito

en la derecha

abajo

que tan largos son los lados?

[viral owl]

cual

[viral owl]

ah

de 1*1 creo

osea 1

[surreal meadow]

si

entonces el area es

1

claro

y ahora

los triangulitos

el area es la mitad del quadrado

y te muestro rapidito porq

ves que toman un cuadrado y lo cortan en la mitad

[viral owl]

si

[surreal meadow]

ok

entonces

estas son nuestras areas

ahora llenamos la foto

[viral owl]

el 5 no lo entiendo

ah es 0.5?

[surreal meadow]

sisi

.5

[viral owl]

ok

[surreal meadow]

viste lo que hice?

[viral owl]

si

[surreal meadow]

ahora sumas las areas

y te da el area total

[viral owl]

ok espera

1+1+1+1+1+1

ostia 6

es verdad

[surreal meadow]

si

perfecto

bien facil no?

[viral owl]

muchas gracias

ya lo entendi

es que mira tu quien pone unos deberes de mates en inglesç

[upper mesa]

help?

basically trying to find max area of the triangle

[viral owl]

despues esta el del demonio @surreal meadow

[upper mesa]

but it doesn't fit any of the answers

[surreal meadow]

@upper mesa can you change channels

we're busy

[surreal meadow]

bueno este es un poco mas dificil

y medio que hice trampa un poco

pero igual

te lo muestro

empezamos cortando la imagen en la mitad

para si es mas facil

oka?

[viral owl]

ok

[surreal meadow]

nos queda asi

[viral owl]

ok

[surreal meadow]

ahora sabemos 1 lado

AD

[viral owl]

como sabemos que es 10

[surreal meadow]

lo dice en la pregunta

[viral owl]

ah ostia

perdon

[surreal meadow]

nono

es buen pregunta

oka

ahora, vamos a asumir que ese ovalo en el centro es un circulo

porque sino es imposible encontrar el area

[viral owl]

ok

[surreal meadow]

entonces lo que vamos a hacer

bueno primero te explico algo

los quadrados

[viral owl]

si?

[surreal meadow]

tienen diagonos

[viral owl]

creo que se que es un diagono

[surreal meadow]

si estos 2

[viral owl]

eran las lineas esas que podian conectarse con otros puntos que no estaban repetidos?

me refiero

[surreal meadow]

claro

[viral owl]

las dos flechas del medio son los diagonoso

[surreal meadow]

son esas 2 lineas en la imagen esa

[viral owl]

diagonos*

[surreal meadow]

si

bueno

en los cuadrados

cuando los diagonos se unen

crean angulos de 90 grados

asi

entendes?

[viral owl]

si

[surreal meadow]

ok

lo cual significa

que

todas estas areas

son iguales

[viral owl]

entiendo

[surreal meadow]

ok

entonces

con el circulo este

la idea es la misma

todos estas areas son iguales

ok?

[viral owl]

ok

[surreal meadow]

por lo cual

envez de calcular todas las areas grises separadas

lo que podemos hacer

es calcular este triangulo

[viral owl]

yo lo que haria es girar el circulo ese

[surreal meadow]

envez de esa area gris

exacto

eso es lo que queria decir 🤣

[viral owl]

ahhh

[surreal meadow]

pero no sabia si me ibas a entender

pero si

giramos el circulo

y nos da 2 triangulos grises

[viral owl]

si

[surreal meadow]

ok

ahora

queremos encontrar los lados de arriba y abajo

pero eso es bien facil

porque los circulos son simetricos

entonces estas dos lineas negras son iguales

por lo tanto

v

oka?

[viral owl]

ok

[surreal meadow]

entonces

ahora tenemos lo proximoe

proximo

queremos encontrar las areas rojas

y para hacer eso hacemos esto:

el area de un triangulo como este

es base * altura / 2

[viral owl]

esto no lo entendi

[surreal meadow]

te muestro

este triangulo es uno muy especial

porque el angulo en la izquierda

abajo

es de 90 grados

en ingles se llama right angle

triangle

[viral owl]

isosceles?

no se eh no me acuerdo

[surreal meadow]

no necesariamente

bueno

a banca

nonoono

no te preocupes de esto

volvemos a esta

[viral owl]

ok

[surreal meadow]

el area de un triangulo

es base por altura dividido por 2

[viral owl]

aha

[surreal meadow]

entonces

cual es la altura de estos triangulos

[viral owl]

5?

no se

[surreal meadow]

si

y la base?

[viral owl]

ah

emm

10

[surreal meadow]

si

entonces 50/2

= 25

[viral owl]

mm

[surreal meadow]

entonces cada uno de estos triangulos es de 25

entendes?