#help-0

1 messages · Page 531 of 1

lusty laurel
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fucntion one it took some time but did that as well

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only course i didnt study i was unable to do

turbid narwhal
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your prep is going too well man from where you are studying

lusty laurel
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it doesnt matter from where im studying

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consistency matters

turbid narwhal
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you did adv question i'm asking about mains

lusty laurel
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of what i was able to

turbid narwhal
lusty laurel
#

my school also does mocks and their paper is damn good

turbid narwhal
turbid narwhal
lusty laurel
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see this

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from one of the papers

turbid narwhal
lusty laurel
#

here, do this

worthy lichen
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H_max from the ground will be 30m for that case?

lusty laurel
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qaudratic

turbid narwhal
lusty laurel
worthy lichen
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I am giving you calculated h max

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Just confirming

lusty laurel
worthy lichen
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v² = u² + 2ax

turbid narwhal
worthy lichen
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It gives x = 5

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So 5+5+20

lusty laurel
lone heartBOT
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lusty laurel
#

its 25 then

lone heartBOT
lusty laurel
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why 5+5

turbid narwhal
worthy lichen
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The distance

lusty laurel
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so height of building + height it reached

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20 + 5

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why you adding the length it fell down as well

turbid narwhal
turbid narwhal
lone heartBOT
#

@lusty laurel Has your question been resolved?

jade sierra
#

wsg chat

lone heartBOT
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raw jetty
#

how many ways are there for A,B,C, and 7 other people to sit around a round table if A,B,C dont sit adjacent with eachother

raw jetty
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i was thinking pairing them so like A-, B-, C-, then permutating

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so 7c3×3!×7!/10

nimble sleet
# raw jetty how many ways are there for A,B,C, and 7 other people to sit around a round tabl...

seems like a classic inclusion-exclusion principle question. If you let $A_1$ be that A and B are adjacent, $A_2$, B and C are adjacent, $A_3,$ A and C are adjacent

\medskip
then you need to calculate the "bad" cases for you to count off. Those being [
\text{Bad} = |A_1 \cup A_2 \cup A_3|
= |A_1| + |A_2| + |A_3| - |A_1 \cap A_2| - |A_1 \cap A_3| - |A_2 \cap A_3| + |A_1 \cap A_2 \cap A_3|
]

ocean sealBOT
raw jetty
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isnt A1 cap A2 cap A3 impossible pandathink

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so 9!-(3×2×8!-3×2×7!)?

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151200

nimble sleet
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also i think you should be doing 9! - blah, because the permutations for a circular arrangement is that much

raw jetty
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ah right

nimble sleet
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ok at face value that seems correct yes

raw jetty
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ok thank you!

#

.solved

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static saffron
#

Lets say i have the following system of differential equations:
$$\frac{db}{dt} = \chi b^$$
$$\frac{db^
}{dt} = \chi b$$
How would i solve this?
The matrix for this seems $((0, \chi),(\chi,0))$ and i guess i will just do the normal approach of solving a system like this?

ocean sealBOT
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derdotte

static saffron
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Just for some more context. b is actually the complex number representation of an operator $\hat b$ in a base where $\hat b$ has a defined eigenvalue. And this equation arises from parametric downversion in quantum optics. Gotta solve it for figuring out correlations

ocean sealBOT
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derdotte

lone heartBOT
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@static saffron Has your question been resolved?

static saffron
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found a way that doesnt revolve around solving this awkward system of conjugates.
Differentiate first equation, insert second, solve second order instead. Much easier

#

.close

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tender aspen
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In Q-10, what does the question mean by bounded by y axis? I mean, the other equation is a circle and the y-axis goes right through the middle of it
So which side would be bounded by y-axis?

tender aspen
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I took the positive side of y-axis

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But then I wasn't getting the right answer

coral flower
gray isle
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this isn't a full circle

tender aspen
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Ohh

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But even after that, I wasn't getting the right answer

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I mean lamda= (-1, infinity) because of y axis

gray isle
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how are you getting that lambda could be negative

tender aspen
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That's not what I'm getting

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It's in the answer

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I'm getting lamda > 0

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Option A is the answer given

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Why do we have to take
(lamda + 1) >0
instead of
lamda > 0?
I mean, y axis is x=0, right?

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Why are we taking y-coordinate?

lone heartBOT
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true phoenix
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Prove that there exist no integers a and b such that a³ + (a+1)³ + (a+2)³ ..... (a+6)³ = b⁴ + (b+1)⁴

true phoenix
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My idea was to try every mod 6 case as I am unable to find any alternate method for solving it

vale wigeon
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why not mod 7

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you got 7 terms on the left

true phoenix
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I tried mod 6 because when cubed the remainder remains the same so i thought that might be related to the question

vale wigeon
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do it mod 7 and the left hand side is always zero

true phoenix
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I will give that a try

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Thanks

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.close

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thick beacon
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pretty simple proof here but my problem is in the marking scheme the contradiction they used was that there exists positive numbers a, b such that a+b<2sqrt(ab)

thick beacon
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however my question is why can you use a contradiction like there exists negative numbers a, b such that a+b=>2sqrt(ab)

iron roost
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proving there's a negative number such that a+b>=2sqrt(ab) doesn't prove that for all real positive numbers a,b, it applies

lone heartBOT
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@thick beacon Has your question been resolved?

thick beacon
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im sorry but isn't tht how contradiction works ?

iron roost
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the contradiction in this case would be that a and b are both positive real numbers and there exists a,b such that the inequality isn't true

thick beacon
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i proved that negative numbers doesn't exist to satisfy the equation, wouldn't it follow that a positive number will ?

iron roost
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you don't want to prove that a positive exists

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you want to prove that it is true for all positives

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take x=x+1, obviously not the case for numbers less than 0, but also not the case for numbers greater than 0

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verbal elbow
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How do I do question 34 part b? (Sorry for the poor lighting)

lethal belfry
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,rccw

ocean sealBOT
lavish cave
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did you do 34a?

verbal elbow
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Yep

lavish cave
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okay, what did you get for that?

verbal elbow
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Just not sure how to simplify the expression

lavish cave
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ah

lethal belfry
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Let $f(x) : \R \to \R$ , where $f(x)=e^{3x+2}$ and let $g(0,\infty) \to \R$ where $g(x) = \ln(x)$
\
find the value of k such that $f(g(2))=ke^x$

lavish cave
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right then you can write it as $e^2 \cdot e^{\log_e (x) \cdot 3}$

ocean sealBOT
verbal elbow
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e^(3ln(x)+2)

ocean sealBOT
verbal elbow
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Oh I see thank you

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lone heartBOT
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glad terrace
lone heartBOT
glad terrace
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can someone tell me where I went wrong here?

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I was checking my answer (top right) and I got close but not exactly what I started with

twin nimbus
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@glad terrace what is exactly different between the two? They look identical to me, but I also just woke up

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Oh, 47 vs 3

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10 is multiplied by both (x+1) and (x+2), similar error with 11

twin nimbus
glad terrace
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I have little to no clue how to multiply them when it’s 3 fractions

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like what goes where

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ts so buns

twin nimbus
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Are you aware of the term "least common multiple?"

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Honestly, I think the way fractions are taught are a little bit bleh, like they don't bother to teach GCD and LCM to 4th graders learning how to add fractions, because they're number theory, but they really should. A little discussion about prime numbers is probably not beyond children, and it sets you up for actually understanding how fraction addition works.

glad terrace
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but like could I apply it here?

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nope

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should I just be multiply each thing by every other denominator or something?

twin nimbus
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@glad terrace figure out what the common denominator is, then multiply each fraction so that they have a common denominator

lone heartBOT
#

@glad terrace Has your question been resolved?

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latent hazel
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can anyone help me with my revision for school, im in grade 8

vale wigeon
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you need to send specific questions here that you're using to revise

latent hazel
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imma send the stuff

vale wigeon
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one at a time preferably

latent hazel
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Oh ok

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can i send the google doc of everything

vale wigeon
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mmmm

latent hazel
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I kinda forgot abt gradient

vale wigeon
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that's quite a lot. you need to come here with the questions you struggle with and get them resolved one by one

latent hazel
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and slope intercept form

vale wigeon
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an entire Google doc of them is kind of a big ask

latent hazel
vale wigeon
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i can send you some videos or tell you to look up the channel known as The Organic Chemistry Tutor yourself

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on YT

latent hazel
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oh

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ok ill watch him

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hushed shale
#

guys what are your all qualifications?

lone heartBOT
hushed shale
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n=24 ...?

potent mirage
lone heartBOT
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@hushed shale Has your question been resolved?

hushed shale
potent mirage
#

<@&268886789983436800>

gray isle
#

.close

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hushed shale
lone heartBOT
potent mirage
#

type .close

hushed shale
#

.close

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mortal junco
#

I've accidentally proven some big math equation that hasn't been proven for a long time and I am trying to write a valid math proof in math words and terms [I understand my proof but it isnt in "math language" if you know what I mean] and I have nobody around me to help me with learning how to properly write math proofs and reviewing what I wrote and give me feedback after.

to put it short, how do you write math proofs and what are all the basics I need to know before writing one and how should I organize it? I have some examples on what I've written which the image linked to this message is that example [remember I've never dealt with math proofs advanced math, I've just excelled and dealt with extracurricular mathematics in highschool and I am in 12th grade right now]

slate vortex
#

what are you trying to prove

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Also your statements don't really make sense

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$\exists n \in Z, n/2 \in Z \implies n$ is even

ocean sealBOT
slate vortex
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You should remove the "there exists n in Z"

mortal junco
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ahh

slate vortex
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Also we usually use $\mathbb{N}$ or $\mathbb{Z}^+$ for positive integers, not $Z$

ocean sealBOT
slate vortex
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some people consider N to have 0 though so maybe Z+ is better

mortal junco
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yeah at the time of writing that part didn't know about mthbb

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i forgot to change it

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I just felt like defining it more specifically cuz

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the actual thing im trying to prove depends on positive integers

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a lot

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the entire thing is positive integers

mortal junco
slate vortex
mortal junco
mortal junco
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collatz conjecture

slate vortex
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Remove $\exists n \in Z$

ocean sealBOT
slate vortex
mortal junco
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i dont know what to tell you

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i see it working

sharp thorn
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cant we just say $\forall \frac{n}{2} \in \mathbb{Z}^{+} \implies n$ is even?

slate vortex
ocean sealBOT
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Bettim

mortal junco
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thats why i didnt even say

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what im trying to prove

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at the beginning

mortal junco
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that is pretty good yeah

slate vortex
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well explain the general idea then

mortal junco
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i can also just do

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actually now that i think ab it how does it make sense to say

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something like for all n in Z while trying to define what is even or odd

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specifically the for all / exists

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oh

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is that what you're saying

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Ahh

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makes sense

mortal junco
# slate vortex well explain the general idea then

I divided all natural numbers into some specific grouping where they all follow a certain pattern without repeating and therefore every number does not grow till infinity and there are no other loops other than 4-2-1-4

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and no, i didnt do this for some arbitrary number sets where i attempt

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it is general

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i dont know how to write math proofs

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but i spent the last 3 days

small fog
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are you trying to prove the collatz conjecture

mortal junco
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not trying

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i did

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but i cannot show

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in math language

small fog
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okay, explain the general idea of the proof then

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like the logic

small fog
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okay, what is the specific grouping and the patetrn

mortal junco
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i wont say that

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cuz then you find it

slate vortex
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Son, there's no way your proof is correct if you're not even in university yet

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There's a reason this problem is unsolved

small fog
mortal junco
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i've seen this often

patent dirge
mortal junco
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I hope I never said it I guess

small fog
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if you think people are gonna "steal" your proof

mortal junco
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I didn't want to brew this "suspicion"

small fog
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you are not making anything worthawhile

mortal junco
small fog
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no like

mortal junco
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I don't know what it means to be proving something and owning that proof

small fog
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the concept of stealing proofs

slate vortex
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There's nothing to plagiarize here because your proof isn't correct.

small fog
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in general

patent dirge
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@mortal junco whats ur background

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in math

mortal junco
patent dirge
small fog
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there is no reward for solving the collatz conjecture

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you dont get anything

slate vortex
solemn sparrow
mortal junco
patent dirge
mortal junco
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suddenly i was inlove with math

small fog
mortal junco
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and spent 800 hrs in a row

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studying math

patent dirge
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mathematicians dedicate their entire life

mortal junco
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excluding sleep etc.

patent dirge
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to solve problems like collatz

slate vortex
small fog
#

this is a learning moment

mortal junco
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don't let it discourage you that you didn't study math your whole life or something like that

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I just liked math

small fog
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@mortal junco you can learn a lot from what went wrong with your proposed proof

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just like

mortal junco
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and tried to solve whatever I didn't think I could

small fog
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say it

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we'll see where it went wrong

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and you can learn from it

patent dirge
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how old are u

slate vortex
mortal junco
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I want to study for my actual exam

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so I'll say it

solid saffron
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i just solved the Collatz Conjecture

small fog
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alright

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guys no mocking him

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like

patent dirge
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what classes havs u taken

mortal junco
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geniunely yes

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please don't just

small fog
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he genuinely thinks he proved it

mortal junco
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outright obliterate me

patent dirge
small fog
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like

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hear him out

patent dirge
mortal junco
small fog
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hear out his mistaken proof

mortal junco
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youre forced to take

slate vortex
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Yes this is a learning moment

mortal junco
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the same math lessons

patent dirge
small fog
patent dirge
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what is your mathenaticla bacjground

mortal junco
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ill just say the proof

small fog
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it doesnt fucking matter let him say his false proof and we can learn from it

mortal junco
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ill talk ab wht i know later

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so

patent dirge
mortal junco
#

I've heard from somewhere that every number can be written by adding powers of 2 and that meant every positive integer can be written with 2 groups, dividing them into 50% of all integer numbers

patent dirge
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might as well

mortal junco
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2n and 2n-1

small fog
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he just said he can

mortal junco
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and when I thought about it

small fog
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odd and even numbers

mortal junco
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I said, why not expand this to 3?

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and when I was messing around with 3 came across 3n+1

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and I realized that

small fog
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yep you can write everything as either 3n, 3n+1, or 3n+2

mortal junco
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some numbers show a specific property

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i pick any number

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like lets say

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5

small fog
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yep

mortal junco
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5 is a number i call

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has no odd leading to it

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so the only option is for me

small fog
#

wym

mortal junco
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okay so

patent dirge
mortal junco
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we are reversing

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the number

small fog
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like it is not expressible as 3n+1

mortal junco
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I reverse numbers

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in collatz

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yes

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it isnt expressible as 3n+1

small fog
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so its either 0 mod 3 or 2 mod 3

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5 is 2 mod 3

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continue

mortal junco
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in collatz

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what i realized

small fog
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yep

mortal junco
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every number is

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either led by 2 numbers

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or 1 number

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1 of those is always avaliable for every single integer

small fog
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wym

mortal junco
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which is

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multiplying it by 2

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remember

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im thinking reverse

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for me

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collatz is

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(n-1)/3

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and 2n

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right now

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im trying to find

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leading numbers to numbers

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what are the leading numbers to 5

small fog
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10

mortal junco
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is there an odd leading to it?

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n-1/3

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there is no odd

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but always

small fog
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yes

mortal junco
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theres even leading

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10

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and i realized

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10 can be expressed as odd and even

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then 20 is only even

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leading to it

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40 has odd and even

patent dirge
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yea

mortal junco
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80 has even

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160 has odd and even

#

and I realized

#

66% of all integers

#

show this property

#

while 33% being powers of 3

small fog
#

ok so the problem with this is that its a heuristic argument.

Your argument is basically "on average, every number will lead to 1".

mortal junco
#

powers of 3 are never expressible by 3n+1

solid saffron
#

what if he actually proved it and we're all witnessing math history

small fog
#

but this doesnt rule out that theres like

mortal junco
#

it isnt just

#

that

#

there is

#

so much more

#

this is like

#

definitions

#

this is understanding

#

what i did

small fog
solid saffron
#

make a youtube video

mortal junco
#

if i just tell you

#

E3N E3N+1 E3N+2 O3N O3N+1 O3N+2 groups

#

youre not gonna understand that much

#

i mean

#

you could

#

cuz its obvious

solid saffron
#

make a youtube vid

patent dirge
#

explain it

mortal junco
#

but you wont understand

#

where its coming from

#

I AM

patent dirge
#

alr continue

mortal junco
#

i am explaining the core idea

#

reverse collatz

#

2n and n+1/3

#

so what I noticed is

#

66% of numbers as I said

#

shows the same property likewise 5

#

if you reverse it

small fog
#

actually 66% of integers are NOT writable

mortal junco
small fog
#

as odd and even

mortal junco
#

integers

small fog
#

take 7

mortal junco
#

thats

#

not what i meant

#

okay

#

yk ill just wait

#

imma send to my whatsapp my paper

small fog
#

no wait

mortal junco
#

and ill send from whatsapp

small fog
#

im trying to understand

mortal junco
#

to discord

#

my paper

small fog
#

ok no wait

#

so like

#

7

#

has no odd leading to it right

mortal junco
#

yes

small fog
#

so like

#

66% of numbers

#

have no odd leading to them

mortal junco
#

also id like to vc if its possible sometime now or later

small fog
#

and 33% do

mortal junco
#

yes

#

exactly

#

but

#

thats not

#

true

#

its actually

#

33% of numbers have odd leading to them

#

and i said 66% have

#

not 33%

#

its just the process of realization

small fog
#

yes but 33 is the right number

mortal junco
#

at first im wrong and i deduce something right

#

its like contradiction proof

#

im first saying smtn wrong and stating whats wrong and getting something out of it

small fog
#

33% of numbers have odd leading to them

#

because like

#

think about it

mortal junco
#

ill say this

#

okay

#

imagine:

#

ill give you 3 example numbers

solid saffron
#

bro jus publish ur video

mortal junco
#

i dont have

#

a video

#

idk what to

#

prove

#

here

small fog
#

he's trying to explain it

mortal junco
#

legit

#

for 3 days

#

i couldnt study

#

for my uni exam

#

cuz of this

#

and i have 22 days left

solid saffron
mortal junco
#

let me explain

solid saffron
#

if he says it here and hes right you could prolly just steal it

#

if he makes a video its kinda hard to steal

mortal junco
#

i made a video at may 29

#

showing my papers

small fog
#

bro

#

fym steal

mortal junco
#

and me mentioning this proof

#

i didnt upload it

solid saffron
#

ye you gotta publish it

small fog
#

@mortal junco just explain the proof

#

what do you mean 66% of numbers

#

have an odd leading to them

#

they dont its 33%

#

right

mortal junco
#

its

small fog
#

unless i misunderstood

mortal junco
#

33% of numbers having odd leads cuz

#

66% was assuming from the 5 tower

#

one second

#

imma do smtn rq

#

my mom

#

is telling me

small fog
#

yes 33% of numbers have odd leads

mortal junco
#

ill be back in 3-5 mins

small fog
#

ok

solemn sparrow
#

Imagine the next Fields medalists is being prepared in one of these channels ah hell nah lmao 😭

mortal junco
#

im back

#

i also got my papers

mortal junco
#

and also this would just make me

#

"who found the idea that lead to collatz being proven by someone else"

#

i guess id rather take that now

#

geniunely

solemn sparrow
#

Keep cooking brother

mortal junco
#

I just need help

#

I aint capable of soloing this

small fog
#

also

#

and then like when its wrong nothing happens

mortal junco
#

i found these type of websites

#

and i DONT understand them either

#

like geniunely

#

i dont

#

idk how to publish

#

what it means

#

am i missing smtn

solid saffron
#

it means you are stating you are the first person to think of this new theory or proof

mortal junco
#

okay so

#

lemme put it there

#

how do i put my

#

real life papers

#

in there

#

my phone doesnt have google btw

small fog
#

upload a pdf

mortal junco
#

i deleted google cuz it is a distraction

solid saffron
#

idk you figured out the Collatz Conjecture u could figure this out

mortal junco
#

on phone

#

dude

#

i speak math

#

not white page english words

small fog
mortal junco
#

but

#

the math i speak is like

#

in my head

#

neurons

#

neuron language

small fog
#

ok so

mortal junco
#

i cant express it

small fog
#

wait

#

is your paper

#

a pdf

#

or like

#

is it a picture

mortal junco
#

its

small fog
#

or a physical paper

mortal junco
#

real life

#

paper

#

of scribbles

#

listen

#

i wasnt able to

#

express my idea

#

in general algebra form

solid saffron
#

ye you gotta digitize that

mortal junco
#

but i see it

#

i cant algebra it

#

its general

small fog
#

ok you can like

mortal junco
#

its true

#

i see it

#

but i cant

#

write it

#

therefore i technically

#

havent proved it yet

small fog
#

ok so just keep explaining the basic idea

#

so like

mortal junco
#

thats why i need help

#

i cant finish

small fog
#

33% of numbers

#

have an odd leading to them

mortal junco
#

collatz conjecture was 3 steps for me and im stuck on the 3rd step

#

could we vc

#

im tired of typing

#

i can also camera share

#

in vc

small fog
#

alright

mortal junco
#

is there any vs

#

in this server

#

i dont see any vcs

small fog
#

dont think so

#

just call in dms or something idk

lone heartBOT
#

@mortal junco Has your question been resolved?

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#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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hardy arch
#

Hey, so I'm basically learning trignometry for Right angled triangles. and i'm just not sure when to either use multiplication or division to find the specific length of a triangle.

short vapor
#

which length?

hardy arch
#

let me show rq

#

What am I supposed to find, also how do I know what to use

short vapor
#

ahhhhh

#

okay

#

you know SOHCAHTOA?

hardy arch
#

yeah

short vapor
#

so, each of soh, cah, and toa connects two sides and an angle

#

(sorry if im being a bit simplistic i dont know how much you know)

#

whne you're solving a problem like this, what you need to figure out is which two sides you know

#

oh no you got that

#

sorry

#

it's basically just some algebra from here....

#

how far have you gotten? or just up to the pictures you got

hardy arch
#

Well I've gotten assignments on both using multiplication/dividing to get the specific length. but when I start by finding out whether if its soh cah toa, I always seem to get the sin cos tan wrong. For example I said it was sin32, while the answer key says cos32

short vapor
#

for... which question

hardy arch
#

second image

#

well it is sin32, but how would you know not to use cos or tan?

short vapor
#

sohcahtoa gives us 3 rules

#

sin(θ) = O/H
cos(θ) = A/H
tan(θ) = O/A

#

these rules each connect two sides and an angle

#

so depending on which sides you know, and which sides you are trying to figure out, you use different rules

#

for image two, you know the opposite side, and want to know the hypotenuse

#

so you would use sin(θ) = O/H

hardy arch
#

mhm

short vapor
#

that's how you know which one to use. it would be sin(32) because if we used cos(32) or tan(32) we wouldn't be able to get the answer

hardy arch
#

what happens if we used cos32 or tan32, would the answers be obvious that it's wrong?

short vapor
#

lets say we tried to use cos(32)

#

we get cos(θ) = A/H right

#

but we dont know the adjacent side

#

right?

hardy arch
#

oh

#

i thought 32 was adjacent

#

I just name everything before solving it

short vapor
#

didn't you write down opposite?

hardy arch
#

i wrote adj on the right side

short vapor
#

oh you thought 32 was a side length?

hardy arch
#

yeah

short vapor
#

ah okay

#

yeah it's an angle

hardy arch
#

yep

short vapor
#

okay

#

well yeah figuring out which formula to use is really just a case of which sides do i know / want to solve

hardy arch
#

Great, is it possible if you could maybe do a bullet point of this so I can maybe screenshot for another time?

#

Just in case if I forget

short vapor
#

okay yeah

#

SOHCAHTOA

  • sin(θ) = opposite / hypotenuse
  • cos(θ) = adjacent / hypotenuse
  • tan(θ) = opposite / adjacent
    pick the identity that connects a side you know with a side you want to find out, and then solve for the side you are trying to figure out
hardy arch
#

thanks!

short vapor
#

np!

lone heartBOT
#

@hardy arch Has your question been resolved?

#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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worldly sleet
#

Guys, I need your help

lone heartBOT
worldly sleet
#

How do I find something that’s undefined

zinc bolt
#

!xy

lone heartBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

zinc bolt
#

@worldly sleet

worldly sleet
#

The problem is that the one on the right is undefined

#

Basically, meaning that it ruined any equation that’s in

zinc bolt
#

Yea because 0 doesn't equal 1

hushed locust
#

desmos apparently returns 1 for true inputs and undefined for false inputs

worldly sleet
#

Basically thinking if i equal one then i(1+1)+1=3

#

And i = nothing should =1

#

Do you know how I can fix this problem?

hushed locust
tidal lintel
#

=3

tawdry lily
worldly sleet
#

Basically imagine it like a switch

#

{i = 1}= on
{i= undefined} = off

#

And I thought this would work

hushed locust
#

just because two things are undefined doesn't mean they're equal, because "undefined" isn't a number

worldly sleet
#

So there’s no way I can make this work

tacit arch
#

That's usually how undefined works yes

worldly sleet
#

But how can I code :(

tacit arch
#

Don't code undefined things

tawdry lily
#

Here Desmos says i = undefined because it only works in a cartesian plane diagram

#

Desmos does not compute anything in the Argand's diagram

worldly sleet
#

Making on and off switch

tawdry lily
#

Usually coordinates are writen in the form of a + bi

worldly sleet
#

Insert happy noises

lone heartBOT
#

@worldly sleet Has your question been resolved?

#
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alpine mural
#

Klaas Creek is on a bearing of 314° from Hampervale and the distance between them is
158 km. Badgerton is 325 km from Hampervale and its bearing from Klaas Creek is 044°.
Find the bearing of Badgerton from Hampervale.

How do I draw this, I have no clue

lunar saddle
#

Remember bearing is from north clockwise

alpine mural
lone heartBOT
#

@alpine mural Has your question been resolved?

alpine mural
#

<@&286206848099549185>

#

<@&286206848099549185>

alpine mural
#

Aren't bearings clock-wise not counterclockwise

hushed scroll
#

B can be above or below x-axis

hushed scroll
#

If you want to find angle between them, either draw exact figure or a figure like this, this won't change the angles or distance or anything, the answer will be same

#

If you want exact figure then draw what you think is correct

#

You can try

#

Are you up to something?

alpine mural
#

.close

lone heartBOT
#
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hushed scroll
#

Do you think you can find angle between H and B from here

lone heartBOT
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desert raptor
#

Hi, how do I proceed further?

lone heartBOT
#

@desert raptor Has your question been resolved?

desert raptor
#

<@&286206848099549185>

dire plover
#

ok

#

so what you do is exand the H's into summations

#

you mutiply boths sides by -n

#

and you convert the iterated sums into sums over sets

#

then they will turn identical

#

for example look at the number of terms of the type 1/a*1/b*1/c where a =\=b=\=c=\=a for particular abc, in the RHS, this is 6 ( 6 from H_n^3, 0 from 3H_nH_n^(2), 0 from 2H_n^(3)) and in the RHS it is also 6 (6 from 3 (H_k^2)/k, 0 from 3H_k^(2)/k)

#

do the same for
a=b=\=c and a=b=c

#

and you will find they all match

#

does this make sense?

desert raptor
dire plover
desert raptor
#

do it for this one

dire plover
desert raptor
#

do it for this one, a simpler case

dire plover
#

does this step make sense to you?

desert raptor
#

lemme see

#

aren't the first and the third terms the same @dire plover

#

or did you mean to write a > b

#

oh nvm

#

yes go on @dire plover

dire plover
dire plover
desert raptor
#

true

#

i see the logic

dire plover
#

they both give same thing due to symmetry

dire plover
desert raptor
#

that's nice

#

you did this, in a way

#

right?

dire plover
#

yup

desert raptor
#

okayy

#

now exploiting that in the third case seems tricky

#

dude harmonic sums are interesting asf

dire plover
desert raptor
#

so now u want me to do smth similiar but with sum 1/abc

desert raptor
#

dude wait lemme send u smth rq

#

thanks1

#

.close

lone heartBOT
#
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tepid scroll
#

claim

lone heartBOT
tepid scroll
#

is the answer not written incorrectly

#

it should be like this no?

lone heartBOT
#

@tepid scroll Has your question been resolved?

lone heartBOT
#

@tepid scroll Has your question been resolved?

tepid scroll
#

<@&286206848099549185>

#

HELP ME

lone heartBOT
#

@tepid scroll Has your question been resolved?

red fractal
#

i cant find to figure it out?

lone heartBOT
#

@tepid scroll Has your question been resolved?

tepid scroll
tepid scroll
#

<@&286206848099549185>

alpine sable
#

Hm

#

@tepid scroll

tepid scroll
#

Yee

alpine sable
#

This is your particular solution I guess

tepid scroll
#

this is a homogenous system

#

it doesnt have a particular system?

#

solution*

lone heartBOT
#

@tepid scroll Has your question been resolved?

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desert raptor
#

How do I prove the following result?

lone heartBOT
desert raptor
#

,w sum i = 1 to inf H_i/i^2

desert raptor
#

Abel's summation is not working well

ivory fern
#

What is H_i?

vast harbor
#

harmonic number ig

desert raptor
desert raptor
#

<@&286206848099549185>

desert raptor
#

A second question

#

Au-Yeung's quadratic series

#

,w sum i = 1 to inf (H_i/i)^2

desert raptor
#

This is 17/4 * zeta(4)

#

@thick lynx

thick lynx
#

Looks like that one is famous too

desert raptor
#

Since both proofs require them

#

Suggest a resource please @thick lynx

thick lynx
#

Where did you find these?

desert raptor
thick lynx
thick lynx
desert raptor
desert raptor
desert raptor
thick lynx
#

is that integration bee?

desert raptor
thick lynx
#

Ah, that integration book

desert raptor
#

But it's fun

#

When you attack the integral correctly it just falls apart into a known result

#

Anyways, thank you

#

.close

lone heartBOT
#
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thick lynx
#

yeah looks interesting

desert raptor
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tepid barn
lone heartBOT
tepid barn
#

Is the first exercise a definite integral

#

And is the second exercise the lenght of Arc lenght of curve

#

If thats the case then how can i solve the second exercise

sacred tundra
#

does anyone do a level maths??

tepid barn
#

Wym

lone heartBOT
#

@tepid barn Has your question been resolved?

lone heartBOT
#

@tepid barn Has your question been resolved?

proven leaf
# tepid barn

the arc length of a parametric curve (\mathbf{r}(t)=\langle x(t),y(t)\rangle) over ([t_0,t_1]) is given by:
[L=\int_{t_0}^{t_1}\sqrt{\qty(\frac{dx(t)}{dt})^2+\qty(\frac{dy(t)}{dt})^2}dt]

ocean sealBOT
#

PajamaMamaLlama

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#
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#

Please don't occupy multiple help channels.

#
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opaque shard
#

I think i have the not continuious and not differientiable correct, but to make sure im just gonna ask anyways.

My main question is how the heck do i graph f'() of this thing

leaden bobcat
#

you are correct on continuous - differentiable

#

for graphing the derivative, can you do it for 2 < x < 3?

opaque shard
leaden bobcat
#

in that interval the graph of f is a line

#

doesn't ring any bell?

opaque shard
#

no 😦

leaden bobcat
#

Do you know what the derivative of a function is?

opaque shard
#

i know how to get a derivative from a problem but not from a graph or the definetion

leaden bobcat
#

Can you write down what the derivative of a function at a point is for you?

#

So we can go from there

opaque shard
#

is this what ur asking?

3x^2 = 6

leaden bobcat
#

this looks like an equation
did you mean to write “the derivative of 3x² is 6x”?

opaque shard
#

yes sorry i forgot the x

#

how did u do the superscript/?

leaden bobcat
# opaque shard yes sorry i forgot the x

not only that, that equal sign is inadequate for what we are saying
you wrote 3x² = 6x, which is a completely different thing from saying “the derivative of 3x² is 6x”

leaden bobcat
#

you can write in LaTeX here

#

The derivative of $3x^2$ is $6x$. Like this

ocean sealBOT
opaque shard
#

oh thats cool

leaden bobcat
#

dollar signs for whatever you want to format in a “mathematical way” so to speak

#

anyway, this is only operational, but doesn't really tell us what the derivative of a function is

#

where did you learn about derivatives?

opaque shard
#

i had to self teach myself

leaden bobcat
#

Okay

#

Do you know what a tangent line for a graph at a point is?

opaque shard
#

no

leaden bobcat
#

okay, do you know what the slope of a line is?

opaque shard
#

yes

leaden bobcat
#

great

#

now, tangents in geometry, no clue what they are?
Something like “a line tangent to a circle”

opaque shard
#

i remember learning it but it was a while while back

leaden bobcat
#

what would you say distinguishes these 2 lines?

opaque shard
#

secant intercets through the circle twice tangent only once

leaden bobcat
#

okay, now for a graph of a function
if you take a point on a graph, and start drawing lines from there, most of them will touch the graph in many points

opaque shard
#

got it

leaden bobcat
#

but (if the graph if nice enough) you will find a special line that “touches” the graph only once (if you restrict yourself close enough to the point)

#

This is a colloquial introduction to what we call the “tangent line” of a function a specific point

#

The derivative of a function is defined as the slope of this line (if it exists)

opaque shard
#

so a tangent line is a point where a line only touches it once?

leaden bobcat
#

the black line is a tangent line for the blue graph because it touches it only at 1 point

opaque shard
#

got it thats a better definition

leaden bobcat
#

Mind this is very colloquially

#

because there are a lot of pathological examples where what we just said doesn't really make sense

#

but for “nice enough” graphs, this is true

left wharf
#

what kind of pathological examples?

leaden bobcat
# left wharf what kind of pathological examples?

I told him “a tangent line touches the graph ones”, this requires many asterisks since to start, it may touch a lot of times again outside of a neighbourhood of the point (just extend the graph outside to do so)
secondly, it may touch infinitely many times even in a neighbourhood of the point (for ex. x²sin(1/x) at x = 0 extended as 0)

#

looks like this

leaden bobcat
opaque shard
#

got it so how do we graph this f'()

leaden bobcat
left wharf
opaque shard
leaden bobcat
left wharf
#

I don't think that function is differentiable at x=0?

leaden bobcat
#

it is

#

you need to compute it using the definition

left wharf
#

oh yeah nevermind

leaden bobcat
opaque shard
#

would it not be 2 because of the curve

leaden bobcat
#

What is the subject of what you wrote?
I'm talking specifically about the function for 2 < x < 3

leaden bobcat
#

look at the function only for 2<x<3

#

it's the segment you marked with a “1”

opaque shard
#

got it

leaden bobcat
#

it's already a line (segment)

#

we said the “tangent line” of a graph is the best line that approximates the graph
but for 2<x<3 our graph is already a line, so what would you say its tangent line is?

opaque shard
#

maybe x=-1 because its flat or x=3

leaden bobcat
#

I think you are confused about what I am asking
x=-1 or x=3 are numerical values for some x
I am asking about what the tangent line is (a geometrical object)

opaque shard
#

im saying would you not put a tan line there?

leaden bobcat
#

you are looking at a different part of the graph
I wanted your attention for 2<x<3

#

here

opaque shard
#

but if that a segment there cant be a tangent line though i thought

leaden bobcat
#

the “better” definition I gave you of tangent line is “the best line that approximates the graph”
if the graph is already a line, then it is its own tangent line

#

Maybe you want a few mins to think about it?

opaque shard
#

i think i might just take the L on this problem

leaden bobcat
#

you said you are self-teaching

#

on what bases do you start?

#

As in, do you know elementary algebra, etc.

opaque shard
#

honeslty i was looking for the answer then i would look at the answer for a while and determine how you got the answer

leaden bobcat
#

I'm confused by what you just said
you're saying you want me to give you the answer so you can think about it?

opaque shard
#

so i can see how you got the answer and determine how to do it, I did the othe problems i just cant figure this one out

leaden bobcat
#

Did you solve the other problems?

opaque shard
#

yes

leaden bobcat
#

then you understand how to draw the graph of the derivative when the function is a line

left wharf
leaden bobcat
#

same for when the graph is a parabola

opaque shard
#

yes but this has a jump a curve all this

leaden bobcat
#

Then I'm not sure of what's stopping you in this one

for x < 2 your graph is a parabola, so in there you do it exactly like B.

leaden bobcat
#

as you said at x=1 the graph is “flat” so there derivative is 0
you eyball another value (tangent line looks like has sloop 1 for x = -4)
since, just like for B., you know you will get a line, you can just draw the line passing though these points

#

you will have to stop once reaching x = 2 when the jump occurs

opaque shard
#

so y = 0 until 2 then its a line with the slope of 5 then a slope of 1

leaden bobcat
#

are you sure the slope of the first line is 5? It's going down, it cannot be positive

opaque shard
#

-5

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or 1/5

leaden bobcat
#

not 1/5

#

(1/5 is still positive)

#

if anything you should wonder about whether it is -5 or -1/5

#

which one is it?

opaque shard
#

-5

leaden bobcat
#

yes

opaque shard
#

down 5 over 1

#

-5

leaden bobcat
#

so what should your drawing look like?

opaque shard
leaden bobcat
#

That looks like the graph of the original function

#

We said that for 2<x<3 the slope is -5 and for x > 3 the slope is 1

#

Look at how you did C.

opaque shard
#

wait are the lines always straight (left to right) when graphing f'

leaden bobcat
#

all lines are straight, that's what a line is

#

you mean horizontal?

opaque shard
#

yeah

leaden bobcat
#

not always, just when the original function is a line

#

which is what I was trying to explain to you before

opaque shard
#

so 2 <x<3 should be horizontal as well as x>3

leaden bobcat