#help-0

1 messages · Page 529 of 1

lavish cave
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there are, well maybe the helpers who know multivar calc are sleeping

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for ratio and proportion, here

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dilation should be in here

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Khan Academy has both videos and quizzes

lone heartBOT
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grand falcon
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if 2+5 is 3, what is 4+7

lone heartBOT
alpine sable
grand falcon
zinc bolt
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Yea, maybe mod 4, maybe a + b is defined to be b - a

alpine sable
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idk if mod 4 makes sense cause they use 5

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idk

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can you do that? i have no experience with mod

ruby current
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or + could just be the constant function 3 lol

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it's unclear without more context

zinc bolt
alpine sable
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or a + b = b - a

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both would be 3

zinc bolt
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Actually in all the relations we defined, it seems to be coming to 3, what a crazy coincidence lol

alpine sable
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lmao

zinc bolt
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Yea but still this doesn't mean that it'll always be 3 tho

ruby current
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a + b - 4

alpine sable
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lmao

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ig you can make infinitely many that would work

ruby current
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a + b = 3 cos^2(a - 2) sin^2(b - 5) + 3

alpine sable
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a + b - 2(a!)

zinc bolt
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I think you can just write 2a! and that works

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as what you're writing

lone heartBOT
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glacial sundial
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wait hi

lone heartBOT
glacial sundial
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can someone help me with this please

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.open

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sorry ive never done this before

mossy reef
glacial sundial
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yeah

mossy reef
glacial sundial
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ive done this problem like a handful of times and i am getting it wrong

mossy reef
glacial sundial
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yeah leme type it out my phoen is broken

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I first did (0,0), which resulted in 3

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then I did the first partial derivs (fx and fy)

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which were 2/sqrt(9+4x+5y)

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and 5/2sqrt(9+4x+5y)

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which when you plug in (0,0) you get 2/3 and 5/6

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then I solved fxx, fxy, and fyy

mossy reef
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,w partial z = sqrt(9 + 4x + 5y) at (x, y) = (0, 0)

glacial sundial
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fxx was -8/(9+4x+5y)^3/2

glacial sundial
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fxy=10/(9+4x+5y)^3/2

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anyways i think im correct but im gettign it wrong

mossy reef
glacial sundial
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wait its negative

mossy reef
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Also, what did you get for $\diffp{f}{{y^2}}$?

glacial sundial
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is that the error youre thinking of?

ocean sealBOT
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@mossy reef

glacial sundial
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fyy = -25/(4(9+4x+5y)^3/2

mossy reef
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-# Let me check once more...
I checked, and it's definitely wrong.

glacial sundial
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fxy, fyy, fxx are all negative

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wait I might have solved fyy

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wait idk

mossy reef
glacial sundial
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wait so fxx is correct, is fxy?

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nevermind i just reread what you sent

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do you know what i am doign wrong?

mossy reef
glacial sundial
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thats the worst type lmao

mossy reef
glacial sundial
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wait am i off by a factor of 2

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okay so, I should multiply fxx, fyx, and fyy by 2?

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or just fxx

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i tried doing both and im still incorrect

mossy reef
glacial sundial
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oh my god thank u so much

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subtle meadow
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Im not too sure what to do for part b. I can take K to be 1/2 as a good choice probably, but I'm not sure how to lay it out. I think I can assume properties of familiar functions, even though its an Analysis 1 course P-Set 4, but how should I lay this out properly

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vale wigeon
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oh ffs

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slate oracle
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The flight of an airplane from Korea to Poland can be modelled by the relation h=-2.5t^2+200t where t is the time in minutes and h is the height in metres.
a. How long does it take to fly from Korea to Poland?
b. What is the maximum height of the plane? At what time does it reach this height?

slate oracle
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im cooked for my math exam i gotta review and i forgot how to do this pls help 😭🙏

fervent knoll
slate oracle
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ive set the height to 0

fervent knoll
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Find t then

slate oracle
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so right now i have 0 = -2.5t^2 + 200t

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but idk how to find t

fervent knoll
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Cancel one t. As we know t is not zero

slate oracle
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oh okay

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ill try

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not sure if its correct

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but i got t = 80

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😭

fervent knoll
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It's right

slate oracle
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okay!

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tysm!

fervent knoll
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U need (b)??

slate oracle
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oh right

fervent knoll
slate oracle
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uhh not really..

fervent knoll
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Do you know calculus??

slate oracle
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i havent learnt calculus

uneven jewel
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for quadratic optimization you don't need calculus

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just complete the square and go from there

slate oracle
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currently i have learnt this but forgot most of it..

fervent knoll
slate oracle
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alright

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i got max height of 4000meters

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did i get it

fervent knoll
slate oracle
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okay thanks!

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lone heartBOT
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@dense wren Has your question been resolved?

raw jetty
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if you asked there then why open here

dense wren
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im getting n*2^(-n+1)
cause for an angle/point to be acute there should be n-1 points on the semicircle facing that point
which has 2^(-n+1) chance of happening
and since they are disjoint u add them up

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vale phoenix
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Just a simple arithmetic question, how did he squared the whole fraction of complex numbers? Wouldn't that change the ratio?
Is there a property or identity I'm missing?

vale wigeon
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he's working with |ratio|^2 with the intent of taking the square root at the very end

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@vale phoenix

vale phoenix
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but wouldn't that change the question itself?

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i am little confused about that..

like (2/5)² is not equal to 2/5 in ratio

so what im finding it wrong?

vale wigeon
vale wigeon
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again the idea is

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instead of working out x directly

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we work out x^2 and then AT THE END we take the root

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do you accept this as a valid approach yes or no

vale phoenix
copper pond
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Could somebody explain to me why it is negative 1 and not positive 1

vale phoenix
copper pond
vale phoenix
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.close

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lucid surge
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...

lone heartBOT
lucid surge
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Why not use k= 2...?

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Helpp

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ANYBODY

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This is from IAL FP2 btw

tawdry lily
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Oh here you go

tawdry lily
lucid surge
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The last?

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Like ig since I said to solve z⁴, we got 4 solutions (kinda confused why we don't have more tho)...so instead of using k= -2, why can't we also use k = 2

tawdry lily
lucid surge
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Wait so apparently negative values won't be correct answers?

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Literally got my main fp2 exam in a couple of days, and I'm dying over dis–

tawdry lily
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Since we're using complex numbers the 4th roots are periodic

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Which means the roots should repeat every 4 values of k, correct?

lucid surge
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Ohh

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Yes yes

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So is k= 2 bringing a repeated root here?

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The theta it gives is 13π/12

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<@&286206848099549185> ...

tawdry lily
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Correct

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So that's why k=2 is unnecessary since we already have k=-1

lucid surge
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Finally got it!!

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TYSM BRO

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U r a lifesaver

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proper glade
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i can’t figure out where i went wrong, because apparently the answer is 8pi/3

vast harbor
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,rccw

ocean sealBOT
vast harbor
proper glade
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i think i just forgot to add the pi, but i squared it so the answer should still be 8/3

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but i didn’t get it for some reason

vast harbor
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how did you get $\frac{4y^{\frac{3}{2}}}{3}$

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shouldnt it be just $\frac{y^{\frac{3}{2}}}{3}$

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nvm lol

glad fern
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there's a minus though in it

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should it not be posistive?

proper glade
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for which part?

glad fern
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the second last part where you worked out to get 40/3

vast harbor
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you wrote 4^2/2 -

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should be +

proper glade
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ohhhhhh i tried it again but i still didn’t get the answer 😭

vast harbor
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the solid is a cylindre ?

proper glade
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it’s the shape i drew out i think, cuz it’s rotated about the y axis

glad fern
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i think it should $4\sqrt{y}$

ocean sealBOT
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MaxeulRaggedus

glad fern
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btw

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not $2\sqrt{y}$

ocean sealBOT
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MaxeulRaggedus

proper glade
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OHHHHH

glad fern
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you know when you expanded it?

proper glade
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yess

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thank you!

glad fern
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np 👍

proper glade
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.close

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vast harbor
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A * H

lone heartBOT
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proper glade
rich quiver
proper glade
ocean sealBOT
tight pier
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Your y-bounds are from 0 to 4 and x is supposed to vary within [0,2] so the negative solution is the right one.

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@proper glade

proper glade
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ohh ok thanks!

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hearty nest
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watch me solve, if I get stuck I will ask for hints

hearty nest
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gcd(a, b) = 3

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a, b < 100

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lcm(a, b) = 12 * a

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max( a + b ) = ?

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3 * 12 * a = a * b

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b = 2^2 3^2

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gcd(a, 3^2 2^2) = 3

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lcm(a, 3^2 2^2) = 3 2^2 a

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a = 3 ?

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but that gives a + b = 39 which is wrong answer

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how is this giving definite values of a, b when it is asking to maximize it

empty mason
# hearty nest b = 2^2 3^2

I’m pretty sure that once you find what b is from here the LCM condition is not needed anymore. You just focus on the GCD condition

empty mason
empty mason
hearty nest
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yeah

empty mason
hearty nest
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3 * 5 * 5

empty mason
hearty nest
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3 * 29

empty mason
hearty nest
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wro9ng

empty mason
empty mason
hearty nest
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3 31

empty mason
hearty nest
hearty nest
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.close

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crisp nova
#

how do i claim this>

lone heartBOT
vale crag
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it is claimed now

crisp nova
#

oh

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so i was working on a past math exam paper to prep for my math finals next week so i stumbled accros this question

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and got very confused

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i assigned x as the radius of the sphere

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im not sure if im on the right track

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similar triangles got me x/15 = (36-x)/36

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but i just dont feel like its right

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i got x = 180/17

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i can technically go on and calculate the volume of the sphere but am i doing it right?

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i clearly did went on the wrong track at first cuz i messed up the base radius and height

raw jetty
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id say the best way is just to view it as a 2d diagram

slate vortex
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I don't think you need similar triangles for this problem

crisp nova
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i see..

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so then how do i get r

slate vortex
crisp nova
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im sorry but i still dont get it, i know that the hypotenuse is 39, the height is 36 and the radius is 15..

crisp nova
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ohhhh

slate vortex
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The key thing to notice is the radius divides the hypotenuse into 15 and 24

crisp nova
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thank you!!

slate vortex
lone heartBOT
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@crisp nova Has your question been resolved?

crisp nova
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how can i get the top part hypotenuse

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i have to calculate the curved surface area of the bottom half cone

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can i get some extra help?

lone heartBOT
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@crisp nova Has your question been resolved?

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pseudo aurora
lone heartBOT
pseudo aurora
#

hi anyone here??

elder forge
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hello

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what did u try?

pseudo aurora
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I got 99%

spring dagger
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correct

pseudo aurora
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is it correct?

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Really

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Are you sure??

spring dagger
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1.1 x 0.9 is 0.99

winter light
pseudo aurora
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ok sorry

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thank you anyway!

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.close

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elder forge
#

99% is wrong

pseudo aurora
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.reopen

lone heartBOT
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elder forge
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what did u try

pseudo aurora
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why??

elder forge
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consider intital length is l and breadth is b

winter light
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Huh? 99% is correct 🤔

elder forge
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so area is lb right

elder forge
pseudo aurora
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working??

elder forge
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ok so

winter light
elder forge
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initial area is lb

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new length is l + 0.1l = 1.1l
new breadth is b + 0.1b = 1.1b

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new area is 1.21lb

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and initital area is lb

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so 21% increase

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or u can say new area = 1.21*old area

spring dagger
# elder forge nah 21% is correct answer

by definition the area is lw. l increased 10%, meaning it mulitlies by 1.1. w is decreased by 10%, meaning it multiplies by 0.9. lw becomes (l)(1.1)(w)(0.9). by commutivity, is 0.99lw

elder forge
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oh wait

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decreased ahhh

crude urchin
pseudo aurora
elder forge
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mbmb

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but answer should be 1% decrease in area tho

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not 99% increase

spring dagger
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1% decrease is 99% of the original

elder forge
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or yea 99% of old area

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yea got it

pseudo aurora
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ok thank you so much!!!!!!!!!!!1

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.close

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woeful zenith
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burnt reef
#

Where does this conversion comes from?

lone heartBOT
burnt reef
#

Random variable theory and Bayesian network.

charred summit
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$$P(A|B) = \frac{P(A\cap B)}{P(B)}$$

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Because of that

ocean sealBOT
#

Sherif Player

charred summit
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Then
$$P(A\cap B) = P(A|B)P(B)$$

ocean sealBOT
#

Sherif Player

burnt reef
#

but there is a new variable on the right of the |

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That's what confuses me the most.

#

.close

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lone heartBOT
tacit arch
#

no

warped hedge
#

ah okay

#

.close

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shadow pond
#

Hello.

lone heartBOT
shadow pond
#

So, I have a question regarding problems in introduction to proofs.

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So, I'm confused to how epsilon is selected in each case and why n should be an even and odd integer in cases 2 and 3, respectively.

tacit arch
#

can you negate the statement "a_n is divergent" using epsilon-N?

shadow pond
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Sorry, how would that work?

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I'm confused.

tacit arch
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negation of "a_n is divergent" is "a_n is convergent"

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can you write convergence using epsilon-N?

tacit arch
shadow pond
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I'm don't know if I can write convergence using epsilon - N.

tacit arch
#

then start by reading definitions of words you're taught

shadow pond
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So, doing the example problems, N would equal a ceiling function in relation to epsilon.

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I can't seem to find a N equal to a ceiling function in relation to epsilon.

tacit arch
#

what are you even doing

tacit arch
shadow pond
#

No.

shadow pond
#

Yeah, I'm reading it right now.

lone heartBOT
#

@shadow pond Has your question been resolved?

shadow pond
#

Here's the work I have so far.

shadow pond
#

Could you close this problem? I think I'm too lost and maybe need more exposition.

tight pier
shadow pond
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Thank you.

#

.close

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#
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#
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sharp stag
#

what is Fundamental Theorem of Calculus?

lone heartBOT
sharp stag
#

in a nutshell, what I'm understanding is basically it says that 1. integration and differentiation are inverse operations 2. integral a to b f(x)dx = F(b) - F(a) where F is antiderivative

#

is that it?

tight pier
sharp stag
tight pier
#

Well, you have to watch the bounds too.

#

Because then the integrand is not necessarily the derivative of the antiderivative.

safe tartan
#

that statement is wild

tight pier
sharp stag
sharp stag
#

yeah idk

#

what use is the FTC?

ocean sealBOT
tight pier
# tight pier

Your bounds have to be in the form like there so that the differential operator and integration act like an "inverse operation".

#

Where they "cancel out".

sharp stag
#

okay cool

#

yeah I think ik what ur talking about

#

ima look into it more then '

#

thanks sm

tight pier
# sharp stag what use is the FTC?

The FTC is pretty useful when it comes to computing the derivative of an antiderivative, that doesn't exist in terms of elementary functions. For example:
[ F(x) = \int_0^{g(x)} e^{t^2} , dt. ]
You can't evaluate the integral, yet you can still find $F'(x)$ using FTC.

ocean sealBOT
sharp stag
#

appreciate it!

#

.close

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#
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zenith flax
lone heartBOT
zenith flax
#

Unsure of how to do this

#

Not understanding why we'd put the .8/.23 for part one

#

I read it as, given the probability that they read books is .23, what is the probability they read art

#

which means both

north rover
#

P(B)=0.07+0.03+0.05+0.08

north rover
#

We cannot deteremine if these events are independence, hence we use the formula

zenith flax
#

We didnt use a formula int his one though?

#

We just applied what i said above

pseudo ice
north rover
zenith flax
#

So what formula are you signaling to

#

Is it because thats the only thing thats not in A

north rover
ocean sealBOT
north rover
#

Cause we are considering something given something here

zenith flax
#

was just guessing

north rover
north rover
zenith flax
#

Okay thats not really explaining much to me sadly

north rover
#

There isn't even worded context, that's the thing

north rover
zenith flax
#

Why we chose .8. I understasnd that A n B is the intersection aka what a and b have in common

#

wait

#

.5+.3

#

my god

#

Im so slow lmfao

reef wren
zenith flax
#

im lost again

reef wren
#

why ?

zenith flax
north rover
north rover
zenith flax
#

Okay so the .04, and .05

north rover
#

Drumroll please

#

You're taking the common things between A and the region contained by both B and C

zenith flax
#

I get the A part

#

Not the B and C part

#

Why did we select .04 and .05 for the B and C?

north rover
#

It's these fuckers we wanna analyze

north rover
#

Or drawing tool

#

Whatever

#

Draw this diagram

#

Label the circles A, B, C

#

Then first shade in the region $B\cup C$

ocean sealBOT
north rover
#

And then $A$ afterwards, and find the common region between $A$ and $B\cup C$ (this is your region of $A\cap (B\cup C)$)

ocean sealBOT
zenith flax
#

no like i totally get that .05 is shared amonst a b and c in that case

#

I guess im getting logic and alg mixed up with this

#

because

#

for a union, we'd include all of it when doing b u c

#

Im confused as to why .8 isnt included

#

as b and c share it

#

If were doing the intersection, B and C share .05, and .08

#

I cant tell if im over thinking this lmfao

north rover
#

Sorry, I went to get some food

north rover
#

We are finding the common area between A and B U C

zenith flax
#

Yes I get that part

#

can we try breaking down step by step

#

So were first combining B and C

#

Correct?

#

Or is it, we're finding where both B and C intersect eachother

#

I think im getting mixed up because Im just now figuring out union is different in stats versus logic & algorithms

north rover
zenith flax
# north rover Yes

Is that .05 and .08 as the intersection of the two, or is it .04 + .05 + .03 + .20 + .08 + .07

#

Like the .04 + .05 + .03 + .20 + .08 + .07
is the combination of them both (the denominator)

#

Im having trouble getting the numerator

north rover
#

It'll get excluded from A

zenith flax
#

wait that was a "or" question 😢

#

So the .47 is excluded

#

aka the combination of b and c

#

Im just not getting how im getting .03 + .04 + .05 in the numerator

north rover
zenith flax
#

im just not getting why its those, Im trying to understand with the intersection and union why we picked those

#

wait

#

i get it

#

i got it thank you

#

.close

lone heartBOT
#
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lone heartBOT
#
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misty sleet
#

I was wondering if anyone has good resources (free if possible) to study for the ALEKS. I need to do well on this test next year and I want to study.

quiet birch
#

Hey @misty sleet , try to check out the book recomendations / study discussion rooms. They might help you better there.

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#

@misty sleet Has your question been resolved?

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forest cargo
#

Hi

lone heartBOT
forest cargo
#

, rotate

ocean sealBOT
forest cargo
#

My work coming

#

Here it go

#

I have no idea about the question

#

Anyone helping me????

#

If yes then type something

#

<@&286206848099549185>

#

If i don't get respond soon i might be afk as i have short time for my classes if u have any clue how to solve the question leave some hints for me ok

#

<@&286206848099549185>

#

@mossy reef

#

<@&286206848099549185>

lone heartBOT
#

@forest cargo Has your question been resolved?

nocturne veldt
#

you're pinging helpers a little frequently...

#

hmmm wow this is a pretty annoying problem

nocturne veldt
# forest cargo

might be better to just represent this as a system of equations somehow

#

rather than working with all these pictures

lilac scroll
#

wait let me attempt it a bit. Not sure if I can do it.

lone heartBOT
#
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eager swallow
#

.help

lone heartBOT
#

Commands:

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  • factoids: .tag
  • help: .help
  • version: .version

Type .help <command name> for more info on a command.

eager swallow
#

.open

#

Erm

lone heartBOT
eager swallow
#

Oh

#

A cylinder is cut from solid sphere of radius R. Find maximum volume of cylinder

unique dune
#

So like

#

Cylinder inscribed in a sphere?

eager swallow
#

Yes

#

I'm not even able to understand how to start it-

#

So i haven't made any progress yet

unique dune
#

Maybe let’s start by drawing a diagram of what it could look like

lilac scroll
#

Is there any diagram?

unique dune
#

Let’s consider one cross section

#

The biggest one

eager swallow
eager swallow
#

We had to make one ourselves

eager swallow
unique dune
eager swallow
#

According to my teach this question includes the concept of maxima minima

unique dune
#

Then cylinder is this cross section rotated about the y axis

unique dune
unique dune
#

Find a rectangle that maximizes the area and u should be done

eager swallow
#

Lemme try

#

Is this wrong

unique dune
#

,rccw

ocean sealBOT
unique dune
#

Maximize $2x\sqrt{r^2 - x^2}$

ocean sealBOT
unique dune
#

Do u know why I derived this?

eager swallow
#

No

unique dune
#

Consider a rectangle inscribed in this semicircle

unique dune
#

Its width is x

#

Its height is 2 times rhe function

#

Remember the height from the x axis at x=a is the same as the function non-negative f(a)

eager swallow
#

Yes

unique dune
#

Ok

#

So

unique dune
eager swallow
#

Gotcha but

eager swallow
unique dune
#

It is the area of that rectangle

eager swallow
#

Ohh

#

Gotcha

#

.close

lone heartBOT
#
Channel closed

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lone heartBOT
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south geode
#

Does anyone know how to create pictures in desmos

south geode
#

I have to create an image and I have no idea how

lavish cave
#

what kind of picture?

#

oh that

south geode
#

It is like torture

lavish cave
south geode
#

Haha I gues all the teachers are using it

void bear
lavish cave
#

the thing you need to learn is how to make the domain restrictions

south geode
#

Could you slide the tutorial

lavish cave
south geode
#

oh

lavish cave
#

there is one, but it's not that useful

south geode
#

okay thank you

lavish cave
#

no worries!

south geode
#

.close

lone heartBOT
#
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lone heartBOT
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tulip helm
#

need help on q14 a pls

lone heartBOT
cold cargo
#

I'm guessing you mean 14b?

tulip helm
#

oh yes

#

i meant 14b mb

cold cargo
#

you need to think about what the relation in the picture between e^x and ln x is

#

this is true for all inverse functions

#

f^{-1} is the reflection of f in the line y=x

#

so given this, can you translate the area into something you can calculate?

tulip helm
#

I’m not sure how honestly, it’s not making sense

cold cargo
#

try rotating the picture by 90 degrees and looking at the shaded region

tulip helm
#

ohhhh

#

okay I got it now, the bounds are just the x values of y=-1 and y=-2

cold cargo
#

I'm not sure if you understand, do you know what the calculation is now?

tulip helm
cold cargo
#

yeah exactly

#

if the top bound is -1

tulip helm
#

-1 as upper bound

#

ahh i see now i didnt even think of rotating it

#

but the y=x thing makes sense

cold cargo
#

yeah all we are doing is swapping x and y essentially

#

in order to do that we must be able to invert the function

tulip helm
#

understandable

#

thanks for your help

cold cargo
#

no problem

tulip helm
#

👋

#

.close

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#
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lone heartBOT
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pliant shale
lone heartBOT
pliant shale
crimson field
#

Looks good, well done

#

Oh wtf that's not one of the answers?

pliant shale
crimson field
#

Looks good to me, idk

#

Strange

pliant shale
alpine sable
#

Yeah your working seems fine

pliant shale
#

.close

lone heartBOT
#
Channel closed

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pliant shale
#

How to find the inverse of f(x)=x^3 + x?

#

Don't this channel work?

#

.close

raw jetty
#

its already closed

alpine sable
#

@pliant shale could you please reopen the channel?

pliant shale
#

.reopen

lone heartBOT
#

alpine sable
#

Thank you. Your working is incorrect unfortunately

#

Sure the substitutions seem correct but you didn't factor the nature of f into the picture

#

To see that,

Since f(x + f(y)) = f(x) + y for every Real x,y

Set y=0

This implies f(x + f(0)) = f(x)

#

This may imply that f(x) can be periodic with period f(0), but it's not the case (can you see why and hence prove that f(0) must be 0)?

pliant shale
#

what is the problem with the function being periodic?

alpine sable
pliant shale
alpine sable
#

Actually wait an easier way to see this is assume f is not injective, meaning, let a,b in R such that f(a) = f(b) => a ≠ b

#

So now in the functional equation, put y=a then y=b

#

You get f(x + f(a)) = f(x) + a

f(x + f(b)) = f(x) + b

#

Can you see the contradiction now?

#

If f(a) = f(b)

Then x + f(a) = x + f(b)

So....

pliant shale
#

oh yes i see

alpine sable
#

Yep

#

So by contradiction, f must be injective, and hence must have period 0

#

which implies f(0) = 0

alpine sable
#

Because if f(x+T) = f(x) and f is injective, then it implies x+T = x which implies T=0

alpine sable
#

Can you see how this will be useful in f(x + f(y)) = f(x) + y?

pliant shale
#

yes it makes f(x+y)=f(x)+f(y)

#

does the period 0 mean aperiodic?

alpine sable
#

And the solution to that functional equation assuming f(x) is nice and all is...

alpine sable
pliant shale
#

How do we get f(0)=0?

alpine sable
#

y=0 implies f(x + f(0)) = f(x) for every Real x

#

So f(x) could be periodic with period T=f(0)

#

Like sin(x + 2π) = sinx for every Real x

pliant shale
#

since the function is injective x+f(0)=x

alpine sable
#

Mhm

pliant shale
#

then do f(x+f(y))=f(x)+y invariably means f(x+y)=f(x)+f(y)?

alpine sable
#

Yes because f(0+f(y)) = y + f(0) = y

So putting y=f(y) in the original functional equation gives that

pliant shale
#

Can I use this result anywhere for x,y belongs to some R?

alpine sable
#

Yeah

#

I mean in this case, from the given functional equation only that holds for every x,y in R by assumption we deduced that f is injective and f(f(y)) = y, so it's valid here

pliant shale
#

Is there any reason why we can't directly use that functional rule for numbers? @alpine sable

lone heartBOT
#

@pliant shale Has your question been resolved?

alpine sable
#

You indeed can, and it's one of the ways to get the values of f(x) for certain x's

#

The problem is that the question is inconsistent

#

No such function exists such that

f(x+f(y)) = f(x) + y and f(1) = 2

#

The bold part is where the inconsistency lies

#

This is because solving f(x+y) = f(x) + f(y) gives f(x) = cx for some c in R

#

But f(f(y)) = y forces c² = 1

So the only possible solutions (remember we didn't even use the inconsistent f(1) = 2 condition yet) are f(x) = x or f(x) = -x
You can even substitute these functions in the given functional equation and check if they satisfy it or not for every Real x,y

#

With this, we get f(1) = ±1, which is not 2

alpine sable
#

@pliant shale

#

So yeah the question is itself inconsistent

alpine sable
pliant shale
alpine sable
#

The condition f(1)=2 is wrong yes

pliant shale
alpine sable
#

yes

#

Inconsistent is a better word here

pliant shale
#

Thank you!

alpine sable
#

Welcome. Have a great day

pliant shale
#

.close

lone heartBOT
#
Channel closed

Closed by @pliant shale

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lone heartBOT
#
Available help channel!

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Ask your math question in a clear, concise manner.
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After 15 minutes, feel free to ping <@&286206848099549185>.
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dull pilot
lone heartBOT
#

@dull pilot Has your question been resolved?

dull pilot
#

<@&286206848099549185>

gray isle
#

what issues are you having with this

dull pilot
#

Tbh everything

#

It’s like everytime I get it it changes and the answer key they provide is like

#

Idk a foreign language almost

#

😞

#

I also need help with geometry as well

gray isle
#

don't skip the work
write steps clearly

frigid niche
#

U need someone to help you solve or explanation

dull pilot
#

Little bit of both honestly

frigid niche
dull pilot
#

Its more or less pattern recognition knowing what to do for what problem

gray isle
#

e.g. in the first question, you jumped directly to an (incorrect) result
so noone knows where exactly it went wrong

dull pilot
#

But when I get to a pattern it just switches randomly so now it’s all wrong

gray isle
#

try make another attempt

dull pilot
#

I’d actually like

#

Need to vc and stream it cause this is wildly inconvenient 😞

gray isle
#

the same mathematical rules apply,
a slightly different question shouldn't matter

#

unfortunately vc is very limited on this server. (and people usually don't like doing this through dms)

#

try your best to comminicate what you're doing

frigid niche
#

Is the first questions answer -10x +16?

dull pilot
#

What do I even do here💔

dull pilot
gray isle
#

they also seemed to provide an explanation for it

frigid niche
dull pilot
frigid niche
#

The - in the middle is important

frigid niche
#
    • =+
    • =-
    • = +
dull pilot
#

I’m so confused how’re you doing this

frigid niche
#

Like

gray isle
#

distributing that - to the ()

dull pilot
#

VA pls can I vc you I need like real time feedback on what I’m supposed to be doing or one of you it doesn’t even matter I’m so determined to pass this test

frigid niche
#

Yeaa

#

Uhmm

#

Is this urgent?

#

Because I'm at outside now

dull pilot
gray isle
#

focus on the first step first

dull pilot
frigid niche
#

Oh

gray isle
#

did you have any issues with that?

frigid niche
#

I will be home after 40minutes

dull pilot
#

And I gotta jampack all of this I have a basic understanding it’s just getting a concrete foundation

dull pilot
gray isle
#

what issues did you have with the first step of distributing the -

dull pilot
#

Here’s what I’m on now

#

And what I got so far

frigid niche
#

It's 9x+30

dull pilot
#

Ignore that

frigid niche
#

3 × 3x = 9x

dull pilot
#

Pretend I accidentally wrote the 9 upside down

gray isle
#

so what's your issue with this?

dull pilot
dull pilot
gray isle
#

simplify all of them

dull pilot
#

How do I do that for 39x

gray isle
#

39x is just 39x

#

its already as simple as it can be

dull pilot
#

YIPPIE

#

working on it one sec

gray isle
#

and should be clear that its not the same as 9x + 30 due both the different coefficient of x and lack of constant term

dull pilot
#

I got it wrong on to the next question

#

I don’t even wanna talk about this one

frigid niche
#

It's okay

#

Practice more so u get familiar to it

dull pilot
#

Here’s one

modern geyser
dull pilot
#

Yeah :3

gray isle
#

for this you could solve the given equation
or plug in the options and see which one works

dull pilot
#

No :<

modern geyser
#

do you have an answer in mind?

gray isle
#

yeah or no, which one is it?

dull pilot
#

X=-8

modern geyser
dull pilot
modern geyser
#

have you learnt what exponents are?

gray isle
#

they've been auto muted

modern geyser
#

oh

#

seems like someone a bit too young to be on discord to me

gray isle
#

.close

lone heartBOT
#
Channel closed

Closed by @gray isle

Use .reopen if this was a mistake.

#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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glad cradle
lone heartBOT
glad cradle
#

this is my diagram

#

(refer to my diagram)

#

i think of the point in the first quadrant as x being plugged into an func to give y as f(x)

#

however, the point in the 4th quadrant, x is being plugged into a func to give f(-x)

#

what is wrong in my reasoning

modest cradle
#

It should be first and second quadrant for first question

glad cradle
#

ohh fuck

#

thanks got it

#

.close

lone heartBOT
#
Channel closed

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lone heartBOT
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worthy lichen
lone heartBOT
worthy lichen
#

I've solved it up to this point, give me a hint for the next step so I can quickly finish it in one go.

zinc bolt
#

$7^{\log_{70}(2)} = 2 \log_{7 \times 10}(7)$ 🤔

ocean sealBOT
#

@zinc bolt

zinc bolt
#

Even then, $7^{\log_{70}(2)} = 2 \log_{7 \times 10}(7) = \frac 1 5$

worthy lichen
#

i ate steps

#

explaining

ocean sealBOT
#

@zinc bolt

zinc bolt
worthy lichen
#

two

#

7 log_70 (2) = 2 log_70 (7) = 2 log__(7*10) (7)

#

from here

#

__ is for subscript btw

#

otherwise it becomes itali

#

c

zinc bolt
#

You can escape it with \

#

but w/e

worthy lichen
#

do you get now

#

what i did

#

after that 2*(1/10) log_7 (7)

#

because

#

log_b (a) = 1/b log (a)

zinc bolt
#

Ok, first of all, this value is just verifiable not gonna be 1/5

worthy lichen
#

2/10?

zinc bolt
#

Also, you can't willy nilly seperate bases in factors

worthy lichen
#

is it not allowed?

#

then how can i continue from 4th step

zinc bolt
ocean sealBOT
#

@zinc bolt

zinc bolt
# worthy lichen

Did you try seperating the whole and logarithmic powers and using $a^k \cdot b^k \cdot c^k = (abc)^k$?

ocean sealBOT
#

@zinc bolt

vale wigeon
#

$N = 2^{\log_{70}(9800)} \cdot 5^{\log_{70}(140)} \cdot 7^{\log_{10}(2)}$

#

this is what it said, right?

ocean sealBOT
vale wigeon
# worthy lichen

honestly i think this approach will be difficult and also a breeding ground for errors.

#

wait i misread

#

$N = 2^{\log_{70}(9800)} \cdot 5^{\log_{70}(140)} \cdot 7^{\log_{70}(2)}$

ocean sealBOT
vale wigeon
#

working out log_70(N) using log laws is cooking

#

you do have to be careful though

lone heartBOT
#

@worthy lichen Has your question been resolved?

worthy lichen
#

Tell me the solution

lone heartBOT
#
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lone heartBOT
#
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floral cairn
#

Need verifying for problem E.

lone heartBOT
slate vortex
#

You can't do that

unkempt wind
#

Infty/infty is not valid

#

Are you allowed to use L'hôpital's rule?

floral cairn
#

No, idek what is that rule

#

But we’re not allowed to use it on the test

unkempt wind
slate vortex
#

You can just notice that x grows toward -infinity, the +3 and -4 become basically irrelevant

floral cairn
#

Yes

slate vortex
#

that should help you the ans

floral cairn
#

Bottom is -infinite, top is positive infinite

slate vortex
#

No

floral cairn
#

Since there is 1 negative. The whole equation is negative?

slate vortex
#

it is negative but you can't use infinities

unique dune
#

Note: ${\sqrt{x^2} = |x|}$

ocean sealBOT
slate vortex
#

$\frac{\sqrt{2x^2 + 3}}{x-4} \approx \frac{\sqrt{2x^2}}{x} = \frac{\sqrt{2}|x|}{x}$

ocean sealBOT
floral cairn
#

So we’re not using infinites

#

Which makes the answer sqrt2

slate vortex
#

No, you can't just plug in infinity for these types of questions

slate vortex
unique dune
#

There is no such thing as limit ‘at’ infinity, just limit ‘approaching’ infinity

floral cairn
#

What about D then?

#

I did it wrong as well?

unique dune
slate vortex
#

It's correct

unique dune
#

Lnx and x are both increasing functions

#

There’s nothing to stop their growth

floral cairn
#

Can’t we use the same method for E?

unique dune
#

Because denominator is stopping the growth that the numerator is doing

floral cairn
#

Oh, so the two infinites cancel out, leaving me with just sqrt(2)?

unique dune
#

So, you can’t really say that this won’t outgrow this

unique dune
#

They are notions of unboundedness.

slate vortex
floral cairn
#

Hmm

slate vortex
#

for example in x^2/x, the infinities would also "cancel out"

floral cairn
#

Right

#

Ok

#

That means for F. The only HA will be sqrt(2) then

slate vortex
#

-sqrt2

floral cairn
#

Right because limit goes to -infinite

#

Because sqrt2|x| / -x

floral cairn
slate vortex
floral cairn
#

.close

lone heartBOT
#
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#
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radiant badger
#

I have a doubt.

lone heartBOT
radiant badger
#

in the third step, why there's a + sign in the middle, why cant it be -

vale wigeon
#

why would the plus sign from step 2 become a minus

north rover
#

The terms will not match anyways

radiant badger
#

I'm asking in step 2 what sign has to go in the middle

gray isle
#

the sign depends on what you have

median oar
#

If you stick the - onto the number and put a + in front, then you see that + is associative

#

a + (-b) + c + (-d) = ( a + (-b)) + ( c + (-d))

radiant badger
#

This is a factorisation question

gray isle
#

are you referring to the
4x(x-2) + 3(x-2)

lone heartBOT
#

@radiant badger Has your question been resolved?

lone heartBOT
#
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tender shard
#

Can someone help me solve this?

lone heartBOT
tender shard
#

btw |EF| = |EK|

unique dune
#

,calc (4*180)/6

ocean sealBOT
#

Result:

120
unique dune
#

its a equally-sided hexagon, right?

tender shard
#

yep

unique dune
#

or not specified?

#

equally-sided, right?

tender shard
#

yes

unique dune
#

do u know trig?

tender shard
#

no they didn't teach us that yet

#

is that helpful

unique dune
#

,calc 360 - 120 - 75 - 90

ocean sealBOT
#

Result:

75
unique dune
#

,calc (180 - 75)/2

ocean sealBOT
#

Result:

52.5
unique dune
#

are u sure that they are 'equally-sided'?

tender shard
#

did this but 120 + 75 should be below 180

#

yeah

#

I did the degrees wrong

#

lol

unique dune
#

,calc 180 - (75*2)

ocean sealBOT
#

Result:

30
unique dune
#

if trig is used 🥹

tender shard
#

didn't get a single thing lol

echo socket
#

||Draw KD||

tender shard
echo socket
#

Determine the angle KDL

unique dune
#

,calc 120 - 45

ocean sealBOT
#

Result:

75
unique dune
#

Damn

#

Its always the drawing lines inside that i miss

#

😭

tender shard
#

oh its 8

#

How do you even see stuff like that

echo socket
#

It’s pretty natural to want to make a triangle with x as one of its sides, for that you could either do what k did, draw KD or draw LE

#

Drawing KD happens to not require trig

tender shard
#

thanks

#

.close

lone heartBOT
#
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lone heartBOT
#
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tender shard
#

It's asking about the bottom piece's area

tacit arch
#

what is this even saying

lone heartBOT
#

@tender shard Has your question been resolved?

unique dune
#

Do u know what the area of a trapezoid is

tender shard
#

nah only the top piece is known

#

which is 60