#help-0
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for ratio and proportion, here
dilation should be in here
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if 2+5 is 3, what is 4+7
is that the entire question?
yes
I'd say undefined because 2 + 5 = 3 doesn't exactly define the operation + is doing
Yea, maybe mod 4, maybe a + b is defined to be b - a
idk if mod 4 makes sense cause they use 5
idk
can you do that? i have no experience with mod
You could make it a property of + so yea
Exactly
Actually in all the relations we defined, it seems to be coming to 3, what a crazy coincidence lol
lmao
Yea but still this doesn't mean that it'll always be 3 tho
a + b - 4
a + b = 3 cos^2(a - 2) sin^2(b - 5) + 3
a + b - 2(a!)
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wait hi
Have you heard of a MacLauren Series?
yeah
Can you recite the formula?
ive done this problem like a handful of times and i am getting it wrong
Can you show what you have done previously?
yeah leme type it out my phoen is broken
I first did (0,0), which resulted in 3
then I did the first partial derivs (fx and fy)
which were 2/sqrt(9+4x+5y)
and 5/2sqrt(9+4x+5y)
which when you plug in (0,0) you get 2/3 and 5/6
then I solved fxx, fxy, and fyy
,w partial z = sqrt(9 + 4x + 5y) at (x, y) = (0, 0)
fxx was -8/(9+4x+5y)^3/2
This needs to be fixed.
Also, what did you get for $\diffp{f}{{y^2}}$?
is that the error youre thinking of?
@mossy reef
fyy = -25/(4(9+4x+5y)^3/2
-# Let me check once more...
I checked, and it's definitely wrong.
Actually, you're right and this should be negative. But that's not the only error.
wait so fxx is correct, is fxy?
nevermind i just reread what you sent
do you know what i am doign wrong?
I'm not sure entirely, but it's definitely just a silly error.
thats the worst type lmao
||Your partial derivatives differ from the true derivatives by just a constant multiple.||
wait am i off by a factor of 2
okay so, I should multiply fxx, fyx, and fyy by 2?
or just fxx
i tried doing both and im still incorrect
Both fxx and fxy should be divided by 2.
oh my god thank u so much
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Im not too sure what to do for part b. I can take K to be 1/2 as a good choice probably, but I'm not sure how to lay it out. I think I can assume properties of familiar functions, even though its an Analysis 1 course P-Set 4, but how should I lay this out properly
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oh ffs
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The flight of an airplane from Korea to Poland can be modelled by the relation h=-2.5t^2+200t where t is the time in minutes and h is the height in metres.
a. How long does it take to fly from Korea to Poland?
b. What is the maximum height of the plane? At what time does it reach this height?
im cooked for my math exam i gotta review and i forgot how to do this pls help 😭🙏
When the plane lands the height will be 0
ive set the height to 0
Find t then
Cancel one t. As we know t is not zero
It's right
U need (b)??
oh right
Do u know to find the maximum value??
uhh not really..
Do you know calculus??
i havent learnt calculus
for quadratic optimization you don't need calculus
just complete the square and go from there
currently i have learnt this but forgot most of it..
Yea do this
Yes
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@dense wren Has your question been resolved?
if you asked there then why open here
im getting n*2^(-n+1)
cause for an angle/point to be acute there should be n-1 points on the semicircle facing that point
which has 2^(-n+1) chance of happening
and since they are disjoint u add them up
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Just a simple arithmetic question, how did he squared the whole fraction of complex numbers? Wouldn't that change the ratio?
Is there a property or identity I'm missing?
he's working with |ratio|^2 with the intent of taking the square root at the very end
@vale phoenix
but wouldn't that change the question itself?
i am little confused about that..
like (2/5)² is not equal to 2/5 in ratio
so what im finding it wrong?
it isn't and nobody is claiming it is
not really, it is more of a change of approach
again the idea is
instead of working out x directly
we work out x^2 and then AT THE END we take the root
do you accept this as a valid approach yes or no
it makes sense a bit to me, but ig this feels new to me lol
Could somebody explain to me why it is negative 1 and not positive 1
is it related to this question? you can create your own question forum #❓how-to-get-help
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Oh here you go
From which line?
The last?
Like ig since I said to solve z⁴, we got 4 solutions (kinda confused why we don't have more tho)...so instead of using k= -2, why can't we also use k = 2
k = -1 and k = -2 correspond to the same roots as k = 2 and k = 3, just expressed with negative values
Wait so apparently negative values won't be correct answers?
Literally got my main fp2 exam in a couple of days, and I'm dying over dis–
It will
Since we're using complex numbers the 4th roots are periodic
Which means the roots should repeat every 4 values of k, correct?
Ohh
Yes yes
So is k= 2 bringing a repeated root here?
The theta it gives is 13π/12
<@&286206848099549185> ...
Yep
Correct
So that's why k=2 is unnecessary since we already have k=-1
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i can’t figure out where i went wrong, because apparently the answer is 8pi/3
,rccw
you calculated the area not the volume
i think i just forgot to add the pi, but i squared it so the answer should still be 8/3
but i didn’t get it for some reason
how did you get $\frac{4y^{\frac{3}{2}}}{3}$
shouldnt it be just $\frac{y^{\frac{3}{2}}}{3}$
nvm lol
for which part?
the second last part where you worked out to get 40/3
ohhhhhh i tried it again but i still didn’t get the answer 😭
the solid is a cylindre ?
it’s the shape i drew out i think, cuz it’s rotated about the y axis
i think it should $4\sqrt{y}$
MaxeulRaggedus
MaxeulRaggedus
OHHHHH
you know when you expanded it?
np 👍
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i just used the volume formula for volumes of a solid revolution
Can you send the formula?
interesting , thx
Your y-bounds are from 0 to 4 and x is supposed to vary within [0,2] so the negative solution is the right one.
@proper glade
ohh ok thanks!
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watch me solve, if I get stuck I will ask for hints
gcd(a, b) = 3
a, b < 100
lcm(a, b) = 12 * a
max( a + b ) = ?
3 * 12 * a = a * b
b = 2^2 3^2
gcd(a, 3^2 2^2) = 3
lcm(a, 3^2 2^2) = 3 2^2 a
a = 3 ?

but that gives a + b = 39 which is wrong answer
how is this giving definite values of a, b when it is asking to maximize it
I’m pretty sure that once you find what b is from here the LCM condition is not needed anymore. You just focus on the GCD condition
Yes it’s wrong
Try maximise a now. You should try test some values
yeah
You actually know from this that || gcd(a/3, 2^2 * 3) = 1 || so you can limit your search
You can do better
3 * 29
Even better
wro9ng
Say a = 3x. From here, we get that || gcd(x,12) = 1 || Now what’s the largest value of x less than or equal to 33 that satisfies this gcd condition?
Yeah it’s wrong
3 31
Correct. That’s the value of our a, 3*31
thanks, I got it
common 3 will be taken out from gcd.
and since 3x <= 100
x <= 33
Great! And yes, exactly
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how do i claim this>
it is claimed now
oh
so i was working on a past math exam paper to prep for my math finals next week so i stumbled accros this question
and got very confused
i assigned x as the radius of the sphere
im not sure if im on the right track
similar triangles got me x/15 = (36-x)/36
but i just dont feel like its right
i got x = 180/17
i can technically go on and calculate the volume of the sphere but am i doing it right?
i clearly did went on the wrong track at first cuz i messed up the base radius and height
I don't think you need similar triangles for this problem
im sorry but i still dont get it, i know that the hypotenuse is 39, the height is 36 and the radius is 15..
ohhhh
The key thing to notice is the radius divides the hypotenuse into 15 and 24
thank you!!

@crisp nova Has your question been resolved?
em may i as well get help on part b lol
how can i get the top part hypotenuse
i have to calculate the curved surface area of the bottom half cone
can i get some extra help?
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hi anyone here??
I got 99%
correct
1.1 x 0.9 is 0.99
You don't need to write it every time you claim a help channel
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.reopen
✅
what did u try
why??
consider intital length is l and breadth is b
Huh? 99% is correct 🤔
so area is lb right
nah 21% is correct answer
working??
ok so
What the heck?
initial area is lb
new length is l + 0.1l = 1.1l
new breadth is b + 0.1b = 1.1b
new area is 1.21lb
and initital area is lb
so 21% increase
or u can say new area = 1.21*old area
by definition the area is lw. l increased 10%, meaning it mulitlies by 1.1. w is decreased by 10%, meaning it multiplies by 0.9. lw becomes (l)(1.1)(w)(0.9). by commutivity, is 0.99lw
It decrease isn't it
the breadth decreases by 0.1
1% decrease is 99% of the original
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A2 = l1.1 * w0.9 = lw*0.99 = 0.99A
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Where does this conversion comes from?
Random variable theory and Bayesian network.
Sherif Player
Then
$$P(A\cap B) = P(A|B)P(B)$$
Sherif Player
but there is a new variable on the right of the |
That's what confuses me the most.
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no
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Hello.
So, I have a question regarding problems in introduction to proofs.
So, I'm confused to how epsilon is selected in each case and why n should be an even and odd integer in cases 2 and 3, respectively.
can you negate the statement "a_n is divergent" using epsilon-N?
negation of "a_n is divergent" is "a_n is convergent"
can you write convergence using epsilon-N?
hi
read #❓how-to-get-help
I'm don't know if I can write convergence using epsilon - N.
then start by reading definitions of words you're taught
something like 2.1.2 https://connect.gonzaga.edu/asset/file/1514/ch02_1_convergence_v00.html
So, doing the example problems, N would equal a ceiling function in relation to epsilon.
I can't seem to find a N equal to a ceiling function in relation to epsilon.
what are you even doing
did you do this yet for your sequence?
No.
.
Yeah, I'm reading it right now.
@shadow pond Has your question been resolved?
Could you close this problem? I think I'm too lost and maybe need more exposition.
You can close your channel with .close
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what is Fundamental Theorem of Calculus?
in a nutshell, what I'm understanding is basically it says that 1. integration and differentiation are inverse operations 2. integral a to b f(x)dx = F(b) - F(a) where F is antiderivative
is that it?
When you say "inverse operations" what do you mean?
what addition is to subtraction and what multiplication is to division
Well, you have to watch the bounds too.
Because then the integrand is not necessarily the derivative of the antiderivative.
that statement is wild
I just saw it in a vid
Your bounds have to be in the form like there so that the differential operator and integration act like an "inverse operation".
Where they "cancel out".
okay cool
yeah I think ik what ur talking about
ima look into it more then '
thanks sm
The FTC is pretty useful when it comes to computing the derivative of an antiderivative, that doesn't exist in terms of elementary functions. For example:
[ F(x) = \int_0^{g(x)} e^{t^2} , dt. ]
You can't evaluate the integral, yet you can still find $F'(x)$ using FTC.
okay bet, I'll make note of this
appreciate it!
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Unsure of how to do this
Not understanding why we'd put the .8/.23 for part one
I read it as, given the probability that they read books is .23, what is the probability they read art
which means both
P(B)=0.07+0.03+0.05+0.08
No
We cannot deteremine if these events are independence, hence we use the formula
(this is given in the table already btw)
Yes
So what formula are you signaling to
Is it because thats the only thing thats not in A
$P(A\mid B)=\frac{P(A\cap B)}{P(B)}$
;(
Cause we are considering something given something here
was just guessing
I mean, this is the question you asked
They used this
Okay thats not really explaining much to me sadly
There isn't even worded context, that's the thing
So what don't you understand
Why we chose .8. I understasnd that A n B is the intersection aka what a and b have in common
wait
.5+.3
my god
Im so slow lmfao
at least you got it
im lost again
why ?
0.05 and 0.03, yes

Okay so the .04, and .05
Drumroll please
You're taking the common things between A and the region contained by both B and C
I get the A part
Not the B and C part
Why did we select .04 and .05 for the B and C?
It's these fuckers we wanna analyze
Ok, get a piece of paper
Or drawing tool
Whatever
Draw this diagram
Label the circles A, B, C
Then first shade in the region $B\cup C$
;(
And then $A$ afterwards, and find the common region between $A$ and $B\cup C$ (this is your region of $A\cap (B\cup C)$)
;(
no like i totally get that .05 is shared amonst a b and c in that case
I guess im getting logic and alg mixed up with this
because
for a union, we'd include all of it when doing b u c
Im confused as to why .8 isnt included
as b and c share it
If were doing the intersection, B and C share .05, and .08
I cant tell if im over thinking this lmfao
Sorry, I went to get some food
.8 isn't in A
We are finding the common area between A and B U C
Yes I get that part
can we try breaking down step by step
So were first combining B and C
Correct?
Or is it, we're finding where both B and C intersect eachother
I think im getting mixed up because Im just now figuring out union is different in stats versus logic & algorithms
Yes
Is that .05 and .08 as the intersection of the two, or is it .04 + .05 + .03 + .20 + .08 + .07
Like the .04 + .05 + .03 + .20 + .08 + .07
is the combination of them both (the denominator)
Im having trouble getting the numerator
Yeah, part of it
It'll get excluded from A
wait that was a "or" question 😢
So the .47 is excluded
aka the combination of b and c
Im just not getting how im getting .03 + .04 + .05 in the numerator
^
im just not getting why its those, Im trying to understand with the intersection and union why we picked those
wait
i get it
i got it thank you
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I was wondering if anyone has good resources (free if possible) to study for the ALEKS. I need to do well on this test next year and I want to study.
Hey @misty sleet , try to check out the book recomendations / study discussion rooms. They might help you better there.
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Hi
My work coming
Here it go
I have no idea about the question
Anyone helping me????
If yes then type something
<@&286206848099549185>
If i don't get respond soon i might be afk as i have short time for my classes if u have any clue how to solve the question leave some hints for me ok
<@&286206848099549185>
@mossy reef
<@&286206848099549185>
@forest cargo Has your question been resolved?
you're pinging helpers a little frequently...
hmmm wow this is a pretty annoying problem
might be better to just represent this as a system of equations somehow
rather than working with all these pictures
Can you try using the formula instead of Venn diagram?
wait let me attempt it a bit. Not sure if I can do it.
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Oh
A cylinder is cut from solid sphere of radius R. Find maximum volume of cylinder
Yes
I'm not even able to understand how to start it-
So i haven't made any progress yet
Maybe let’s start by drawing a diagram of what it could look like
Is there any diagram?
Yes I did
According to my teach this question includes the concept of maxima minima
Then cylinder is this cross section rotated about the y axis
.
Yes
Find a rectangle that maximizes the area and u should be done
,rccw
Maximize $2x\sqrt{r^2 - x^2}$
k
Do u know why I derived this?
No
Consider a rectangle inscribed in this semicircle
.
Its width is x
Its height is 2 times rhe function
Remember the height from the x axis at x=a is the same as the function non-negative f(a)
Yes
X=? Maximizes this?
Gotcha but
How did you derived this
.
It is the area of that rectangle
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Does anyone know how to create pictures in desmos
It is like torture
I've seen this exact task asked by another student
Haha I gues all the teachers are using it
yes
should be self-explanatory how to type those in
the thing you need to learn is how to make the domain restrictions
Could you slide the tutorial
oh
WELCOME TO THE DESMOS GRAPHING CALCULATOR The Desmos Graphing Calculator can be used to graph functions, plot tables of data, evaluate expressions, animate and create art, and much, much more! Get Started Graphing Log in, Save, and Share Your Graph Animate with Variables and Sliders Sh...
there is one, but it's not that useful
okay thank you
no worries!
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need help on q14 a pls
I'm guessing you mean 14b?
you need to think about what the relation in the picture between e^x and ln x is
this is true for all inverse functions
f^{-1} is the reflection of f in the line y=x
so given this, can you translate the area into something you can calculate?
I’m not sure how honestly, it’s not making sense
try rotating the picture by 90 degrees and looking at the shaded region
I'm not sure if you understand, do you know what the calculation is now?
-1 as upper bound
ahh i see now i didnt even think of rotating it
but the y=x thing makes sense
yeah all we are doing is swapping x and y essentially
in order to do that we must be able to invert the function
no problem
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yeah that's why I am asking am i correct?
Thank you for your help!(I will check what's wrong with the options)
Yeah your working seems fine
Then the options is wrong I think(Thank you!)
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its already closed
@pliant shale could you please reopen the channel?
.reopen
✅
Thank you. Your working is incorrect unfortunately
Sure the substitutions seem correct but you didn't factor the nature of f into the picture
To see that,
Since f(x + f(y)) = f(x) + y for every Real x,y
Set y=0
This implies f(x + f(0)) = f(x)
This may imply that f(x) can be periodic with period f(0), but it's not the case (can you see why and hence prove that f(0) must be 0)?
what is the problem with the function being periodic?
Hint: ||Separately plug in x=0||
Do you mean f(0+f(y))=f(0)+y?
Actually wait an easier way to see this is assume f is not injective, meaning, let a,b in R such that f(a) = f(b) => a ≠ b
So now in the functional equation, put y=a then y=b
You get f(x + f(a)) = f(x) + a
f(x + f(b)) = f(x) + b
Can you see the contradiction now?
If f(a) = f(b)
Then x + f(a) = x + f(b)
So....
oh yes i see
Yep
So by contradiction, f must be injective, and hence must have period 0
which implies f(0) = 0
how the period 0?
Because if f(x+T) = f(x) and f is injective, then it implies x+T = x which implies T=0
So we have f(f(y)) = y
Can you see how this will be useful in f(x + f(y)) = f(x) + y?
And the solution to that functional equation assuming f(x) is nice and all is...
Yeah
How do we get f(0)=0?
Here
y=0 implies f(x + f(0)) = f(x) for every Real x
So f(x) could be periodic with period T=f(0)
Like sin(x + 2π) = sinx for every Real x
since the function is injective x+f(0)=x
Mhm
then do f(x+f(y))=f(x)+y invariably means f(x+y)=f(x)+f(y)?
Yes because f(0+f(y)) = y + f(0) = y
So putting y=f(y) in the original functional equation gives that
Can I use this result anywhere for x,y belongs to some R?
Yeah
I mean in this case, from the given functional equation only that holds for every x,y in R by assumption we deduced that f is injective and f(f(y)) = y, so it's valid here
Is there any reason why we can't directly use that functional rule for numbers? @alpine sable
@pliant shale Has your question been resolved?
You indeed can, and it's one of the ways to get the values of f(x) for certain x's
The problem is that the question is inconsistent
No such function exists such that
f(x+f(y)) = f(x) + y and f(1) = 2
The bold part is where the inconsistency lies
This is because solving f(x+y) = f(x) + f(y) gives f(x) = cx for some c in R
But f(f(y)) = y forces c² = 1
So the only possible solutions (remember we didn't even use the inconsistent f(1) = 2 condition yet) are f(x) = x or f(x) = -x
You can even substitute these functions in the given functional equation and check if they satisfy it or not for every Real x,y
With this, we get f(1) = ±1, which is not 2
Because of this, in your working, you assumed f(1) = 2 right from the start. Starting with something inconsistent will yield inconsistent results
@pliant shale
So yeah the question is itself inconsistent
If you naively ignore the f(f(y)) = y condition we got from injectivity, then f(x) = 2x (mind you this is still not the correct answer for the original functional equation) and you get f(4) = 8. That would be one of my answers by guessing, even though it's wrong
The correct answer should be f(4) = 4, and the condition in the question should be f(1)=1 not f(1)=2
Do you mean the question itself is wrong for the options given?
The condition f(1)=2 is wrong yes
for the functional rule give, right?
Welcome. Have a great day
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<@&286206848099549185>
what issues are you having with this
Tbh everything
It’s like everytime I get it it changes and the answer key they provide is like
Idk a foreign language almost
😞
I also need help with geometry as well
don't skip the work
write steps clearly
U need someone to help you solve or explanation
Little bit of both honestly
Which question
Its more or less pattern recognition knowing what to do for what problem
e.g. in the first question, you jumped directly to an (incorrect) result
so noone knows where exactly it went wrong
But when I get to a pattern it just switches randomly so now it’s all wrong
try make another attempt
the same mathematical rules apply,
a slightly different question shouldn't matter
unfortunately vc is very limited on this server. (and people usually don't like doing this through dms)
try your best to comminicate what you're doing
Is the first questions answer -10x +16?
What do I even do here💔
Yeah :3
they also seemed to provide an explanation for it
I honestly don’t mind I have my own server for my fans and what not but honestly inviting a tutor wouldn’t even hurt
The - in the middle is important
-
- =+
-
- =-
-
- = +
I’m so confused how’re you doing this
Like
distributing that - to the ()
VA pls can I vc you I need like real time feedback on what I’m supposed to be doing or one of you it doesn’t even matter I’m so determined to pass this test
But the thing is where’d you get a 10 from
focus on the first step first
I have like 3 more days to study for this test :<
Oh
did you have any issues with that?
I will be home after 40minutes
And I gotta jampack all of this I have a basic understanding it’s just getting a concrete foundation
Absolutely
what issues did you have with the first step of distributing the -
It's 9x+30
Ignore that
3 × 3x = 9x
Pretend I accidentally wrote the 9 upside down
so what's your issue with this?
No clue where to go from here
simplify all of them
How do I do that for 39x
and should be clear that its not the same as 9x + 30 due both the different coefficient of x and lack of constant term
do you know what x² represents?
Yeah :3
for this you could solve the given equation
or plug in the options and see which one works
No :<
do you have an answer in mind?
yeah or no, which one is it?
X=-8
can you explain why you picked that answer?
Not for this one I was taught that if no value is given to a variable it’s equal to 1
have you learnt what exponents are?
they've been auto muted
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this is my diagram
(refer to my diagram)
i think of the point in the first quadrant as x being plugged into an func to give y as f(x)
however, the point in the 4th quadrant, x is being plugged into a func to give f(-x)
what is wrong in my reasoning
It should be first and second quadrant for first question
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I've solved it up to this point, give me a hint for the next step so I can quickly finish it in one go.
$7^{\log_{70}(2)} = 2 \log_{7 \times 10}(7)$ 🤔
@zinc bolt
Even then, $7^{\log_{70}(2)} = 2 \log_{7 \times 10}(7) = \frac 1 5$
@zinc bolt
How many?
two
7 log_70 (2) = 2 log_70 (7) = 2 log__(7*10) (7)
from here
__ is for subscript btw
otherwise it becomes itali
c
do you get now
what i did
after that 2*(1/10) log_7 (7)
because
log_b (a) = 1/b log (a)
Ok, first of all, this value is just verifiable not gonna be 1/5
2/10?
Also, you can't willy nilly seperate bases in factors
Also, pretty sure this is also supposed to be $2^{\log_{70}(7)}$ rather than $2\log_{70}(7)$
@zinc bolt
Did you try seperating the whole and logarithmic powers and using $a^k \cdot b^k \cdot c^k = (abc)^k$?
@zinc bolt
$N = 2^{\log_{70}(9800)} \cdot 5^{\log_{70}(140)} \cdot 7^{\log_{10}(2)}$
this is what it said, right?
Ann
honestly i think this approach will be difficult and also a breeding ground for errors.
wait i misread
$N = 2^{\log_{70}(9800)} \cdot 5^{\log_{70}(140)} \cdot 7^{\log_{70}(2)}$
Ann
@worthy lichen Has your question been resolved?
Tell me the solution
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Need verifying for problem E.
You can't do that
Differentiate the top and bottom then take the limiy again, but as you can't use it, don't worry about it
You can just notice that x grows toward -infinity, the +3 and -4 become basically irrelevant
Yes
that should help you the ans
Bottom is -infinite, top is positive infinite
No
Since there is 1 negative. The whole equation is negative?
it is negative but you can't use infinities
Note: ${\sqrt{x^2} = |x|}$
k
$\frac{\sqrt{2x^2 + 3}}{x-4} \approx \frac{\sqrt{2x^2}}{x} = \frac{\sqrt{2}|x|}{x}$
Ari
No, you can't just plug in infinity for these types of questions
Negative
There is no such thing as limit ‘at’ infinity, just limit ‘approaching’ infinity
Correct
It's correct
Can’t we use the same method for E?
Because denominator is stopping the growth that the numerator is doing
Oh, so the two infinites cancel out, leaving me with just sqrt(2)?
So, you can’t really say that this won’t outgrow this
Infinities are not numbers.
They are notions of unboundedness.
You can't say infinities cancel out
Hmm
for example in x^2/x, the infinities would also "cancel out"
-sqrt2
Ok thank you very much. Appreciate it!

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I have a doubt.
in the third step, why there's a + sign in the middle, why cant it be -
why would the plus sign from step 2 become a minus
You're distributing a positive 3...?
The terms will not match anyways
I'm asking in step 2 what sign has to go in the middle
the sign depends on what you have
If you stick the - onto the number and put a + in front, then you see that + is associative
a + (-b) + c + (-d) = ( a + (-b)) + ( c + (-d))
This is a factorisation question
are you referring to the
4x(x-2) + 3(x-2)
@radiant badger Has your question been resolved?
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Can someone help me solve this?
btw |EF| = |EK|
,calc (4*180)/6
Result:
120
its a equally-sided hexagon, right?
yep
yes
do u know trig?
,calc 360 - 120 - 75 - 90
Result:
75
,calc (180 - 75)/2
Result:
52.5
are u sure that they are 'equally-sided'?
,calc 180 - (75*2)
Result:
30
didn't get a single thing lol
||Draw KD||
Determine the angle KDL
,calc 120 - 45
Result:
75
It’s pretty natural to want to make a triangle with x as one of its sides, for that you could either do what k did, draw KD or draw LE
Drawing KD happens to not require trig
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It's asking about the bottom piece's area
what is this even saying
@tender shard Has your question been resolved?
Do u know what the area of a trapezoid is
