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No but this isn't mentioned in the actual question
......
we figured this out
then it's ๐
seems like they put an olympiad level question in our uni entry exam..
can abc be 1 and 4?
yes
nvm i still don't get it lol
im still curious why its not just 900?
So what I get: first place has 9 possibilities, second would still have 9 (remove one from 10), then 8, ignore the last 2 since they're fixed, what do we get ? 9x9x8 = 648 ? Which seems wrong, there's some trick to it
thats what i got too
or maybe the options are wrong :p
That's what we got as well, we're stuck here
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
Dont forget 0 cant be for a
Yes, that's why there are 9 possibilites in a
i mean. For b and c
but b and c still have 10 possibilities
b and c can be 0
Yes!
no because u use up a digit for a
so b has 9 and c has 8
where in the question does it say they need to be unique?
So: (b,c =0)\neq a
And b=0 \neq c
thats what he told us that a b c are different idk
but thats not in the question
.
.
That's correct
it doesnt say that anywhere in the question
What if it can't be 1 and 4 either ๐
10014 is still a 5 digit number
We have to make assumptions until we get one of the answers
900 if abc can be same numbers
648 if abc unique
392 if not even 1 and 4 are unique
Hmmm, 648, and 448, what if the options are a typo ?
it doesn't state that abc14 are different numbers, like if it was abcde
right so assuming only abc are unique the answer is 648
Just choose the closest answer when not sure, that's the last resort in exams xD, jk
What if a could be 0
answer is 900
maybe there's a typo so id def say choose C if there's no other way
Did you use the following equation: 9 x (choices-for-a) x 8 (chocies-for-b) x 8 (choices-for-c)
08314 is like abc14
9 chouces for b
Think about it as a passcode
08314 is not a 5 digit number
So at this point we're trying to find how many 3 digit numbers can be formed? What's the point of 14 , is it just there to confuse ?
probably
In passwords, it is 5 digits.
So that they can say "5 digit num"
atp either answer is 900 or 648 tbh
in mathematics, its 4 digits
Try for a could be 0, and abc cant be 1 or 4
Idk so, maybe he had computers sciences exam
8 x 9 x 9 is still 648
this is math related, not cs
for this ^
thats just 8^3
sorry yeah 8x8x8
answer is 900
nothing more to it
possible answers are wrong or the question is not what they meant
At this point just try everything. In the end email the person who wrote this book.
yeah the question is incorrect and incomplete overall
we already concluded that abc can't be the same numbers
youre wrong
it doenst say that in the question
lmao
unless there is some more text above the question that you didnt show
I didn't withold any info
that's all we got
yeah and there isnt, so the question is just wrong and its 900
(with the given info)
there are 9 options for a, 10 options for b, 10 options for c, so 9 * 10 * 10 = 900
I'm willing to put money on 648
thats a 3 digit number
what digit number is that
you dont include the leading 0s
bro is trolling rn
thats 4 digit
This question is moving towards philosophy at this point.
look just by the question and not assuming anything is 900, assuming abc are unique it's 648 not really much to it
just skip
damn
Oh, what if all the numbers are multiplied ? Just an idea.
abc14 = 5 digit number. Unlikely but whatever
thats fun
a and b and c cant be 0
a*b*c*1*4?
yes
then the answer is 0
too many assumptions
9*9*9*1*4=2916<10000
if you assume a b c can be single digit numbers then only
nowhere it says a b c cant be bigger numbers
then the answer is much larger than the given answers
IFF we are multiplying everything
What if it wants us to calculate all the 5-digit numbers below abc14
is it
x >= 10000 and x <= abc14
this is so fun
yes, take b=c=1, then a can have like 20000 possibilities
multiply this by 3 for combinations
and then split it into factors
probably gives like 10^6-10^7 answers
no
even if thats what they were asking, its a really poor phrasing
You got it right, we got 648 after coding for a while
i can brute force it if you dont believe me
doesnt need coding honestly though def a wrong question
its easily more than 100k
do it
these are all the 5 digit multiples of 4
n = 22500
648 is the answer. Don't waste more time on it.
648, thank you all for your patience and time, you were amazing, thank you for working SO HARD
You are all awesome, keep at it!
good discussion
Had fun
dont close this yet im waiting for bonk to somehow prove that if its a 5 digit number formed by a x b x c x 1 x 4 then the answer s in 100k smth
my shitty python code is rly slow
If you are able to close as well, I will leave you with the honors, I have to go now
you know whats not slow? arithmetic progression
if its a 5 digit number that has 4 as a factor
it has to be divisible by 4
that means all 5 digit numbers divisible by 4
but you have multiplicity
also, if you have a=10000, b=1, c=1, then a=5000, b=2, c=1 is also a solution
and also a=5000, b=1, c=2
etc, etc
sure is
SELVATOR
so if you already have 24000 smth solutions for b=c=1
then its going to be many times more if you let b and c not equal to 1
how
???
with b=c=1
ah
a=2500,2501,2502,....,249999
im not sure what you are getting at though because its just nothing more than all 5 digit numbers divisible by 4
where did you get that extra 9 in the end from
there are 90000 5-digit numbers divisible by 4
r u ok bonk
true
lol
you should try using A.P
10000, 10004, ..., 99996
99996 = 10000 + (n-1)x 4
do the algebra
there are 22500 5-digit numbers that are divisible by 4
thats what i said
9x9x8x25 , i get 16200 ๐ค
.
i didnt bother with the exact amount
yes you definitely did
just an order
ah wait i realise my mistake now, by guess shouldve been 10^5-10^6
Bonk you're right
but its definitely much more than 10^5
probably more than 10^6
but unsure if its more than 10^7
HOW
its 22500 if you take b=c=1
???
i need a proof
okay lol
do you agree that a x b x c x 1 x 4 has to be a 5 digit number
yes
a=2500+n, for n in {0,1,...,22499}
b=c=1
i have been ignoring a b c
which has 25000 possibilities
now i take
a=c=1
b=2500+n, for n in {0,1,...22499}
which has 25000 possibilities
so up to 50000 already
now i take a=b=1
c=2500+n, for n in {0,1,...,22499}
right you are right my bad
which has 25000 possibilities
i was thinking of something else
up to 75000 now
thank you lol i feel stupid asf
yes you are right i only got the combinations not the permutations
now i take
b=2, c=1
a=1250+n, for n in {0,1,...,11249}
order matters
which has 12500 possibilities
i get it yeah
so up to 87500 now
now i take b=1, c=2
a=1250+n, for n in {0,1,...,11249}
which has 12500 possibilties
so up to 100000 now
already 10^5
i can keep going like this for quite a long time
anyway
you get my point
you were wrong
and trying to gaslight me
and paint me as the moron
this is going to be a fun question though ill solve this later yeah i was wrong
it is midnight
this was wrong tho 100%
!done @alpine sable channel is finished
If you are done with this channel, please mark your problem as solved by typing .close
cuz you tried to gaslight me and i second guessed myself
xD
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Can someone help me understand the question
I know squared is times itself
ye
but 6x?
6 * (2.5) * (2.5)
another similar question involved timing the number with the x and i just didnt get why multiplication was involved
also for one how would i type this into a calculator
you would type it as 6*(2.5)^2
see the x^2?
yeah
I think that works
6 times 2.5 and then x^2
like so?
Yes.
@kind trellis what is important to keep in mind for these questions? I used to do this around primary or secondary school but it's been so long I've forgotten or at least I don't remember it being like this
I recall x + x = x2, is that true?
no, x * x = x^2,
but, x + x = 2*x
so x adding another x actually means squared?
wait no
my b
x + x = 2 times x?
or did you mean it'd be written as 2x and not x2?
2x and x2 are the same. but the constant is written first, its just convention. ex: 2x, -5x, 10x
constant being the number right?
Krish
I don't get the use of the $
its just to show it as text
it makes it so its in "math" form and font
oh ok
you don't need to worry about that, and definitely do NOT write the dollar sign when writing math questions on paper lol
figured it coulda meant that but i got a little confused
anytime you see two dollar signs like that, just look at the message with the big image (in this discord at least)
x + x = x^2 feels like a convoluted way of saying 1 + 1 = 2 because it reaches the same result
x+x does not equal x^2
whoops i thought this was saying that
thats like saying $1 + 1 = 1^2$, which is not true. $1^2 = 1 * 1 = 1$.
Krish
^
no, that person said it correctly you just interpreted it wrong
$x + x = 2x$ an example of this, where $x = 2$. $2 + 2 = 2(2) = 4$, which is correct
Krish
$x = 2$ is actually a special case where $2 + 2 = 2 * 2 = 4$, but you wont encounter that in any other numbers.
Krish
I'm not very well versed in brackets so I'm assuming the 2(2) equalling four is via one adding onto another or multiplying
$2(2) = 2 * 2$
Krish
also could be written as $(2)(2)$
6x = ?
Krish
i guess i did i just forgot hold on a moment
x = 2.5
2.5^2 = 2.5 x 2.5 = 6.25
6.25 x 6 = 37.5
Although I got the answer I'm just trying to understand the process of these types of questions going forward
when you have and object and you have multiple of them
you dont say 6 times apple
you just say 6 apples
think of it this way
I guess I'll have to consider it answered for now, I shouldn't keep people waiting
what are you stuck on
Not sure at the moment, I'll have to wait until another question like that pops up which could be a while from now
$y=2x^5$ Use your calculator to work out the value of $y$ when $x=2$.
Krish
I'm on another question now I already got that one right
20?
the ^5 confused me, it's not squared so i had it as 2 x 5
2 x 5 = 10 x 2 = 20
exponents mean you multiply it by itself that many times
2^3 = 2 * 2 * 2. 2^4 = 2 * 2 * 2 * 2. etc..
exponents meaning little number?
yes
Courses on Khan Academy are always 100% free. Start practicingโand saving your progressโnow: https://www.khanacademy.org/math/cc-sixth-grade-math/x0267d782:cc-6th-exponents-and-order-of-operations/cc-6th-exponents/v/introduction-to-exponents
Taking an exponent is basically the act of repeated multiplication. You know how to multiply, right? If...
try watching this short video
If you keep pressing = on the calculator you get it doubled
it should make you more comfortable with exponents
yes but dont rely on that every time. you should know how to type exponents on a calculator.
but yes 32 is 2^5
Can I ask another question relating to another math subject?
thats what this server is for
the answers i put in there are based on percentages i got from making a pie chart
yeah the video you can look at for that mentions it
but i figured it'd be percentages based on 270 (the numbers of points scored when added)
270?
no
I'm always overcomplicating things in my head
using the video i looked at (https://youtu.be/L2a98g8Lx_k?si=9BLWGbHuNaVJ8u6m)
I'd have to check the fraction of 360 each of the points scored would be
A and C seem interchangeable
180
180
C and D should be 180 I see
why should they be 180?
I was thinking of the original question
yes
we have established that
A = 50
B = 75
C = 100
D = 45
Not in degrees
look here
what happened to C
360
yes
It always becomes 360 I get that now
yes
But I'm trying to figure out the fractions of the points scored
so the sum of the angles has to be 360
the total of points is 270
so if someone had 270 points
and nobody else had points
he would occupy the whole pie chart right?
Yes
360
yes
so for 270 points
360 degrees
you now cand make a raport of how many degrees for a point
do you understand or should i simplify it?
simplify it
i know it'll always add up to 360
think about this
each section is equal
i try to split A into 270 equal sections
Each section would be worth 1 then
A=270 x B
in terms of points not degrees
yes exactly
but A=360
so the degrees for the B section(the one worth 1 point) is equal to?
yes
lets say A is worth 4 points
that means i can divide A into 4 equal parts of 1
the equal parts of 1 we will call them B
I think we need to address the points scored from the original chart
how much would one point be in degrees here
1 each ik
nono in degrees
90
it doesnt matter
it is 45
so it's 45 degrees
D is 45 degrees?
and u had from here
what's the B in 45B for then
no i wrote poorly disregard this
you have that the total of the pie chart is 270
points
yes ik
for those 270 points you have 360 degrees right?
lets call T total
T=A+B+C+D
and you have that degrees of T =360
because its the whole pie chart
the whole circle
is everything clear up until now
?
well yeah i know what the total is
yeah ok we will get to the rest
I'm asking how to find out what fraction each of the points scored is of 270
if you understand the concept you will have it much easier next time
dont just go for a formula
try to understand the concept
lets have another letter U
U=1
if 45 is 1/6 of 270...
T=270 x U
16.66/100
degrees of U = degrees of T : 270
so degrees of U = 1.33
A=50
U=1
A=50 x U
degrees of A= 50 x degrees of U
does this make sense
?
what is U
U is just something we chose to simplify the problem
it is if you divided T
which is equal to 270
into 270 parts
each equal to 1 point
45 is a sixth of the point total so it'd be 60 degrees
yes
I think we'd get further with this by knowing what to divide
because you have D/T=degrees D/degrees T
45/270 = degrees D/360
1/6 = degrees D/360
degrees D = 360/6
so 360:6
Yeah I know D = 60
But what about A, B and C
you can either choose
degrees C=100 degrees U
and you have already found degrees U=1.33
so what, 100 x 1.33?
or use C/T=degres C/degrees T
yes
C + D = 193
remaining = 167
75 x 1.33 = 99.75 or 100 when rounded up
@tulip lagoon Is this correct? 100 degrees?
no
dont round up
nvm
round up
sorry
you dont have 1.33 its actually 1.333333333... to infinity
and when you use 1.333333333 this
you get closer to 99.99975
and nines keep adding
So is B 100 or not?
yes
final answer?
something is wrong
oh no my bad
it s correct
yes
i added up the angles and got 330
it is getting to late for me
how old are you?
im not asking for your personal information i just want to know what grade you are in
:))
27, I used to do maths like this in primary or secondary school but I'm back in college and I figured some maths revision was warranted because I'll be retaking GCSE's
yeah makes a more sense then the other theory i had
11yo with amazing vocabulary that is up at 2am seemed a bit too far
)))
I don't think I'd be here at 11 years old
you never know
well good luck to you with your revision
hope i was of some help to you and the explanations made sense
we got there eventually
yeah my bad i didnt really know who i was explaining this to))
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im pretty confused with this question
the teacher said "To be able to be differentiable at x=1, we require both f(x) and f'(x) to be continuous at x=1" but i don't understand why
why does it need to be continuous?
because a function has to be continuous in order to be differentiable
differentiability->continuity, remember
no..
i dont remember
i will re-read my notes
is there a reason why it needs to be continuous tho
yes
like you said "just because" basically
imagine the graph has a jump
and we want to evaluate the derivative at that jump
will it exist?
answer is no, since the function doesn't have a proper limit to begin with
If you are proving this is differentiable, you don't necessarily also have to prove it is continuous
but is it possible to set terms on the differentiation?
(Maybe your teacher wants to see this anyway, though)
like if its not differentiable for a < x < b, then cant you restrict the domain for the differentiation?
elaborate
yes
i don't see a problem with that
answers your question pretty well
then a function doesnt have to be continous to differentiate it
okay
but if you restrict the domain for the differentiation, the law can be broken! thats what i dont get
but i understand that for the differentiation to be continuous (and just like a basic, non restrained domain & with the same function throuhgout) then the function beforehand must be continuous too
also, does this mean that f(x) being continuous automatically means f'(x) will be continuous and so will f''(x) and so on, or are there other factors

if you restrict for differentiation, you must for continuity
else the function will just not behave like a function
yes
no
big nono
so restricting a domain makes it continuous
$\text{differentiability}\implies\text{continuity}$, but $\text{continuity}\cancel{\implies}\text{differentiability}$
ah i see
but it does say for it to be differentiable, both f(x) and f'(x) must be continuous
ooaa
i do understand that
indeed
always
sorry i am just like brain dead at the moment
its fine
but the statement that they said, for it to be differentiable, it must be continuous
sorry does that notation mean that if something is differentiable it is continuous
or if it is continuous it is differentiable
because if it means if differentiable it is continuous, then f(x) isnt necessarily differentiable just because its continuous
HUH
but then
proving that its continuous does not prove that its differentiable
just because its continuous at these values does not mean its differentiable at these values bc continuity =/> differentiability
yes
again, going back to the statement
^
then whats the point of proving its continuous?
because we are given differentiability, not continuity
the teacher said "To be able to be differentiable at x=1, we require both f(x) and f'(x) to be continuous at x=1" but you're saying that it doesnt mean its differentiable
que
what do you mean "given differentiability"
ur teacher wrong bruh
hablas espanol?
you should change ur role to undergraduate math
hola
but its mathematics specialist, a bridging course
bc i only did a year of it in hs instead of 2 years
like, we are given the function is differentiable, or are told that it is so
i mean idk if ur teacher actually said that
the f' continuous implies differentiability part is iffy, but in higher mathematics
for now, just be a sponge
wait
So I remember my teacher also asked to show continuity. I think they just wanted to see it done. But indeed, you don't need to show this
oh
but i dont understand how it being continuous means it is going to be differentiable
because you guys are saying that it doesnt mean it necessarily
That's questionable yes. We all make mistakes!
so shes wrong?
but then how would i know what values its differentiable for
like how would i do it correctly?
The way you really should solve this is with the limit definition of the derivative, applied at x = 1
ok well whats that?
thank you guys btw
im sorry if im coming off as annoying or argumentative, im just pissed that its not actually right
whats ur defn of being diffble
Okay well hold up.
They are choosing a value of a and b, such that f is differentiable.
They used the fact that f is continuous, to help get those values.
f' being continuous is weird to include, and I feel you can find examples where this gets the wrong answer
because f'(x) is not necessarily differentiable because we arent given that it is?
u mean f
f depends on a and b
set a = 1, b = 2
u gotta check f is diffble in dis case
well we know that f(x) is differentiable if it is continuous because differentiability => continuous
wait no
thats what she said
we know that for it to be differentiable it must be continuous
The goal of the question is to find a,b such that f is differentiable.
We can use the fact that f is continuous to help us.
f' is not necessarily continuous, that's a mistake.
but it might not necessarily be differentiable because its continuous
but we are given that it is differentiable
so it must be continuous
u are just given the function
u not given that it diffble
but f'(x) is not necessarily continuous because we dont know if its differentiable
but then couldnt it not be differentiable at any values?
of a,b?
yeah
correct
lke how do u find that its differentiable then
a priori that is a possibility
^
wait so if you differentiate a continuous function f(x)
does that mean f'(x) is continuous
absolutely not
then what she said is wrong
yes we established that
diffble just means f' EXISTS
it says for what values is it differentiable
at x = 1
how do you find that then
because we just found when its continuous
ie the limit of difference quotient exists
a=1, b=2
check if it's diffble in this case
using limit defn
do u know limits
$f'(1) = \lim_{h\to0} \frac{f(1+h) - f(1)}{h}$
do you mean this?
martingale
yes ofc
did u do epsilon delta defn
ok so is this like an analys course or whats up
cuz ur trying to be rigorous but not fully at the same time
im talking abt defin
dis
what's f(1)
no i dont know that
oh wait
thats just differentiation
yes thats the basic form of differentiation
"The derivative exists" means that limit exists. So you can use that to get a,b
u don't neeed diff for f(1) bruh
but how do we know that the derivative exists
sorry guys
i feel like an idiot rn
That's part of the question, as far as I can tell. "Derivative exists. What's a and b?"
Okay, so i should assume a question like that means the derivative exists
because to me
its saying "the derivative may exist"
because there may be no values of a and b that work
I assume it's stated in the question, but I admit I haven't seen it
so we back to trying to understand the question now ๐
yeah basically thats the whole problem
Tbh the question might have been "the derivative exists and is continuous" now that I think about it, haha
idk the question is pretty clear to me
Oh wait, you posted the question way above. Nvm I take that last statement back. We don't know the derivative is continuous. But it's stated in the question that f is differentiable.
(at x = 1)
it says "for what values" it doesnt necesarrily mean there are values right?
or am i thinking too hard on it
i think i answered this twice
True, an answer could be "there are no values". But you'd just figure that out by assuming f is differentiable, and getting a contradiction
,tex $\lim\limits_{x \rightarrow 1^{-}} f'(x) = \lim\limits_{x \rightarrow 1^{+}} f'(x)$
what was this for tho
You are thinking a bit too hard on it, haha. They ask this with the intention of values existing
okay sorry
i will now assume that that means that its differentiable at some value for sure
not hard enough imo
i meant as in just what the question was trying to say, because "for what values" can include no values
mhm
like "what are the roots of" and then a quadratic equation with no roots
suds
thats a bit different
but lets move on
yeah i get that now but lets just continue lmao
so after proving continuity, why must these two be equal?
they mustn't.
why u want this
because thats the next move of the teacher
yeah she's wrong
they said for it do be differentiable, we require (continuity proof) and that
oh
okay
but she got the values of a and b?
does ur teacher have a phd
i believe so
yes
she has a long linkedin
anyway
IT DOESNT MATTER
i need help
you cant just say my teacher is wrong, im cooked and not tell me how to do it 
how do i do this
whats f(1)
technically we didn't prove cty.
we showed that if it's cts then a=1, b=2
but it's easy to see that's it's cts in this case
now u prove it's diffble
remember we fixing a=1,b=2
$f'(1) = \lim_{h\to0} \frac{f(1+h) - f(1)}{h}$
martingale
?
oh
you first prove continuity, find out the values for that
and then sub them in to see if its differentiable?
u don't prove cty
then how do you get a = 1 b = 2
u find for what values of a,b is it cts
yes
that was for cty
yes
okay, you just said we dont prove it lol
no i dont want to, i thought u were just starting from the start lol
if we prove diff we auto prove cts
so its getting it cty, getting the valyes of a =1 b = 2
we only need prove diff
then sub to differentiate
mhm
no not to differentiate
to prove it's differentiable!
to prove we CAN DIFFERENTIATE!
i'm not angry btw just emphasis
yes i guess so
we sub in to find f'(x)
ok now time to sub
u can do it anytime u want
this correct
okay
wait a second
you said not to do what she said
i.e. the second part
but how else would you find the values of a and b?
unless we just use the value of a -b = -1
bc that second line is trying to prove that f'(x) is continuous correct? when it is not necessarily?
yes
u should've told me
oh okay
the second part gives u the right answer tho
u can still do that
just logically wrong
yes
then
thats not right
chat gpt says something similar
it says the left hand derivative must = the right hand
for differentiability at x = 1
does that make it more logical?
i dont understand why
correct
lim exists if and only if (iff) left and right hand limit exists
but for f'(x)
i mean this correct
f'(x) = lim
yes but isnt that what the teacher did
no
f'(x) = lim = 1? you mean?
when you search, you find things like this
bc its 2ax and 2
left hand derivative is $\lim_{h\to0^-} \frac{f(1+h) - f(1)}{h}$
similar for rgith
martingale
this diff to ur teacher
how is it different?
it's way different
u gotta understand lim defn first
will take a while
but do what she says and u get right answer
okay chat gpt is saying the exact same thing as you but they did it differently when actually working
because working through that ^ is a nightamre
they just did 2a = 2
for that reasoning
but thats not what you said exactly? its f'(x) 1- = f'(x) 1 +
the worst notation i have every seen
probably, but the important part is in there
i cant really read that lol
you said it was way different but its not???
isnt the writing of that just the equivalent of what u wrote earlier?
no
Closed by @real glen
Use .reopen if this was a mistake.
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โ
this is in my fucking formula sheet
What's the issue?
well...
the definition is a bit off because we don't know that f'(x) exists a priori
but if it does, then the definition is fine
it's kinda going the wrong way though
usually we define differentiability at a point first, and then say that f is differentiable if it's differentiable at each point
but I digress 
but it says its differentiable at x = a provided:
but we don't know that f' even exists a priori 
if f' doesn't exist, the definition makes no sense, is all I'm saying
what is priori
a priori means without further knowledge
oh ok
thats what ive been sayign!
if u look at the original question
im supposed to assume that f'(x) exists BUT IT DOESNT IMPLY THAT IT DOES
well like
a differentiable function is always continuous
that's that lim_{x -> a+} = lim_{x -> a-} = f(a) means
f' already exists everywhere except at x = 1 in your problem
that's because we know that polynomials are differentiable
so the problem is simply asking you to find values for a and b such that f is differentiable at that point x = 1
f' exists on both sides of x = 1
just not at the point itself, until you decide what a and b should be
no offence but i might just not read that
no i read it
i mean not listen
because what if it messess up my understanding more
fair enough, I won't force you to read it 
i did read it
ic
ok
so
what if theres no point where its differentiable at x = 1?
but everywhere else
I'm not sure I understand? 
but doesnt this formula apply for not just polynomials
like no value of a and b work
hole
ah, you're not sure whether there exists numbers a and b that will work?

