#help-0

1 messages · Page 501 of 1

tight marten
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always

tough minnow
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don't think anyone here is going to solve it then

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.close

lone heartBOT
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lone heartBOT
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alpine sable
#

need help

lone heartBOT
alpine sable
#

no clue how to solve this ngl

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urgently 🙏 thnks

lone heartBOT
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@alpine sable Has your question been resolved?

hard harness
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@alpine sable Hey! Am I too late?

alpine sable
hard harness
#

Oof

alpine sable
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Its fine though I managed to fiigure it out

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with raw intelligence

hard harness
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Yeah, it’s not complicated

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Just make sure you don’t do things last minute. 😅

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As a fellow procrastinator, I would know

alpine sable
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I see wht youre saying though

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My teacher didnt guide me through this

hard harness
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Ah

alpine sable
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good thing I have the ability to interpret and think 🤣

hard harness
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Well, when you get stumped again, don’t be afraid to reach out, but it’s better if you reach out sooner rather than later if possible

alpine sable
#

thx

hard harness
#

Yw

lone heartBOT
#

@alpine sable Has your question been resolved?

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strange fractal
lone heartBOT
strange fractal
#

excuse me how to do thiswhen there is a power of 4

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is there a trick

vale wigeon
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yeah it's called de moivre's theorem

strange fractal
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is it this one

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does that 2 lines mean exact value

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the one under de moivres thereom

vale wigeon
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are you talking about |these|

strange fractal
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yes

vale wigeon
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that means absolute value a.k.a. modulus

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a.k.a. distance from zero

digital magnet
vale wigeon
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the upshot is that (cis(theta))^n = cis(n*theta).

strange fractal
digital magnet
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Ag

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Ah

strange fractal
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lemme tru

reef wren
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$(r(\cos(\theta)+i\sin(\theta)))^n=r^n(\cos(n\theta)+i\sin(n\theta))$

ocean sealBOT
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yoboiqimmah

strange fractal
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like dos

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dis

vale wigeon
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yes this is correct

strange fractal
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ok thanks

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.close

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lime warren
#

Can someone help me with this

lone heartBOT
indigo plinth
broken pivot
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$I = \ln \frac 43$?

ocean sealBOT
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King Leo

lime warren
broken pivot
indigo plinth
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no

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let me solve

vale wigeon
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im gonna say this preemptively:

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!nosols

lone heartBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

lime warren
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I know the answer but dont know how to solve it

indigo plinth
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dw

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i ll make it in detail

modest silo
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titipan pemda

vale wigeon
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thats my point

indigo plinth
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@lime warren

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you want me to solve it detailed>

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?

lime warren
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Yes

indigo plinth
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or i ll do it quick

lime warren
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Or atleast help me figure it out

indigo plinth
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i can teach you

modest silo
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what math topic is this by the way ?

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and what is the prequestie

lime warren
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Sure

modest silo
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i'm not familiar with the game

indigo plinth
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you know about this form of a grade 2 ecuation ?

(x - b/2a)^2 - delta/4a

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this solves your intergal

lime warren
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Hmm

indigo plinth
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alr

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i ll write it

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also

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i get ln(9/8)

lime warren
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I think i figured it out

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Oh well

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Ty

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.close

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indigo plinth
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i also did it in the end

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that's the right way to write it

lone heartBOT
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grizzled zephyr
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i got 4

lone heartBOT
grizzled zephyr
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answer key says its B though

opal kayak
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JEE advanced anyone ?

broken pivot
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,w average {2/5, 1/4 * 2/5}

grizzled zephyr
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yes

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then u flip it

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because they asking for december

broken pivot
lone heartBOT
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@grizzled zephyr Has your question been resolved?

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shy robin
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i am just confuse about the answer is it A or D

lone heartBOT
#

@shy robin Has your question been resolved?

fast nexus
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The answer is A.

lone heartBOT
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@shy robin Has your question been resolved?

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broken orchid
#

can anyone help with understanding the limits? I created a program that show a graph of the function 1/x and it is clear that the function would not reach 0. I also wrote down the formulation of the limit in terms of epsilon

broken orchid
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but how, for example, to prove that a is the limit of an

charred summit
indigo frost
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Limit approaches right

broken orchid
indigo frost
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limit only approach the value and not become equal

charred summit
broken orchid
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What should I do next?

charred summit
# broken orchid but how, for example, to prove that a is the limit of an

Here you would just make a synthetic or long division between the two function to get N purely alone in the denominator then check what would be the value of the function as N gets bigger and bigger

For the concept of a prove though, you would need to watch some proves of the epsilon and delta definition and how to use them to prove limits

broken orchid
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alpine sable
#

"There is a circle. Choose two points, A and C, and draw a line to form the chord AC.

Point O is the center of the circle. Take point B on the arc AC, then draw a line OD that intersects the arc AC at point B, with D being a point on the circle.

If
𝐴𝐵=3 𝐵𝐶=4 and OB=6, then what is the radius of the circle?"

i want to try with pythagorean theorem, but theres isnt any information that can prove ABO or CBO angle is 90 degree

i really confused on where to start, also sorry for broken english, i use google for that

north rover
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!original

lone heartBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

north rover
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I need a bit of clarification on the problem statement

alpine sable
north rover
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The construction for this is a bit odd

alpine sable
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here what i draw based on my understanding, not to scale

north rover
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It says "take point B on the arc AC"

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Or am I tripping?

north rover
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And you're done

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Yeah I will take your word for it

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@alpine sable Do you know what the Chord-Chord power theorem states?

alpine sable
north rover
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Extend the line DO to a point on the circle, and label that point where it intersects the circle E.

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We have that, by the Chord-Chord power theorem, EB*BD=AB*BC.

alpine sable
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ah okay thanks thankscatthumbsup

alpine sable
alpine sable
lone heartBOT
#

@alpine sable Has your question been resolved?

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shy lava
#

Hi,
Can I please have some help with this?

lone heartBOT
shy lava
#

$\lim (\frac{5+2(4^n)+5^n)}{(3(4^n)-4n^5}$

north rover
ocean sealBOT
shy lava
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oh lol

north rover
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It's fine.

shy lava
north rover
# ocean seal **;(**

First question: Does an expoential function grow faster than a polynomial function?

shy lava
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Yes?

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Exponent is the dominant term here, I think

north rover
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Then what can we do to the limit?

shy lava
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specifically 5^n

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divide?

north rover
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Yeah.

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Simple as that.

shy lava
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Why is wolfram alpha giving 3 different limits tho

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,w limit (5+2(4^n)+5^n)/(3(4^n)-4n^5)

shy lava
north rover
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What the fuck

north rover
shy lava
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What would the proper input be

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Just want to know to check my answers

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,w limit n->inf (5+2(4^n)+5^n)/(3(4^n)-4n^5)

north rover
shy lava
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is that ir

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ohhhhhhhhhhh

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$\lim_{n\to\infty}\frac{5+2(4^n)+5^n}{3(4^n)-4n^5}$\
$=\frac{5/5^n+2(4^n)/5^n+5^n/5^n}{3(4^n)/5^n-4n^5/5^n}$\
$\frac{0+0+1}{0-0}$\
Since $(\frac1{5})^n $ is a basic null sequence

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Is that correct

ocean sealBOT
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user.not.found

shy lava
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I get 0 that means
Not infinity

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Unless I've done something wrong

shy lava
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So the answer is 0?

north rover
shy lava
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undefined?

north rover
shy lava
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Ah ok

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Sorry I got confused with my book

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Anyways thank you for your help

#

.close

lone heartBOT
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brittle lake
#

How would i begin to start this integral?

brittle lake
#

i always have trouble at the start

broken pivot
brittle lake
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how would you integration by parts this?

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theres only one thing

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thingy

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idk

warm quarry
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1*ln

broken pivot
brittle lake
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and u make dv = dx?

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i assume

brittle lake
#

what are the indicators?

broken pivot
#

!occupied

lone heartBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

buoyant saddle
#

also, you can do trig sub here

broken pivot
wary fable
#

whats the question?

brittle lake
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thx

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.close

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brittle lake
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just random question

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is it that clear

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to u right away

broken pivot
fierce cipher
broken pivot
fierce cipher
#

its just that this way is so hilarious to be true because its so well-hidden

warm quarry
buoyant saddle
#

yes usually if ln is alone it’s a good idea to use ibp

lone heartBOT
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velvet copper
#

how do i do this

lone heartBOT
lone heartBOT
velvet copper
#

i got x = -1 but its wrong when i put it in the question

vale wigeon
keen idol
#

do u mean n=-1?

velvet copper
#

yes

keen idol
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damn

velvet copper
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sorry

vale wigeon
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show your work for how you got n = -1

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could just be an arithmetic error

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could be something more serious

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we can't really diagnose from just the answer unfortunately

velvet copper
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Wait

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I’ll make it’ll make sense

vale wigeon
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ok one moment...

velvet copper
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Oh

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Oh shoot

keen idol
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in 20/24

velvet copper
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I realised where I went wrong I think

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I forgot the n

vale wigeon
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i see the actual mistake

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in the 2nd line when you multiplied both sides by 24

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you forgor to multiply the 2n (on the left) and the 13 (on the right) by 24 as well

velvet copper
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ohh

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so iut would be 48 instead of 2

vale wigeon
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48n instead of 2n

velvet copper
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and 312 instead of 13?

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bc no n valu

vale wigeon
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,calc 13*24

ocean sealBOT
#

Result:

312
vale wigeon
#

yes, the 13 would become 312.

velvet copper
#

ok ty

#

so i just plug those in instead right

vale wigeon
#

so you would end up with

3n + 48n - 20n = 18n + 312

vale wigeon
#

there's nothing to plug things into.

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you redo your work properly, with the corrections i gave.

velvet copper
#

yes i meant that

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idk math vocab that well

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i got n=20.8

vale wigeon
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ok im gonna need you to show your work again

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this may be correct but i wanna make sure you didn't screw up further down the line

velvet copper
#

omg

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wtf is wrong with my brairn rn

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i wrote 33n instead of 31n

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ugh sorry let me restart

vale wigeon
#

yup now it seems good

velvet copper
#

ok ty

#

.close

lone heartBOT
#
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smoky haven
lone heartBOT
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shut halo
#

Hey, I need help with something:

lone heartBOT
shut halo
#

We know that [BC] is the side of a square inscribed in the circumference

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And [AC] is the side of a hexagon inscribed in the circumference

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Asks to prove that angle of vertex C is 105°, angle of vertex A is 45° and angle of vertex B is 30°

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It's easy to prove that alpha is 105°

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Because it's just the internal angle of the square + half of 120-(the internal angle of the square)

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(because the internal angle of the hexagon is 120°)

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Wich means that alpha= 90°+((120-90)/2)°

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Wich is just 90+15 wich is 105°

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But, how can I find out the value of the angle of vertex A for example?

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Oh wait, I see it. Angle of vertex B must be 90/3

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sorrry

river totem
#

B is 120/4

shut halo
# river totem why?

Because. Well, if we call the vertices of the regular hexagon CADEFG in anti-clockwise order.

The, the angles ABC, DBC and DBE subtend an arc of the circumference with the same amplitude

river totem
#

yeah

shut halo
river totem
#

that works too

shut halo
#

😅😅

#

Anywayyyy, I'll close the channel

#

Thanks

#

.close

lone heartBOT
#
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small nimbus
lone heartBOT
alpine sable
#

use isoceles triangle

lone heartBOT
#

@small nimbus Has your question been resolved?

small nimbus
#

<@&286206848099549185>

alpine sable
#

you got eyes?

lone heartBOT
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grizzled zephyr
lone heartBOT
grizzled zephyr
#

can someone help please

languid plaza
#

find the area under the graph

grizzled zephyr
#

why

languid plaza
#

area under a-t graph gives velocity

grizzled zephyr
#

oh right

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but how do i do that

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like i take from what interval

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to what

languid plaza
#

first statement they asked you to compare the velocities of t=1 to t=3

grizzled zephyr
#

they asked me to compare the velocities of t1 and t3

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not to

languid plaza
#

plot t=1 on that graph and find the area

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hold on I'll send a rough graph

topaz schooner
#

v = a * t, at t = 1 the acceleration was equal to 4 m/s^2

grizzled zephyr
#

oh fk

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how i didnt think of that

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dang

languid plaza
#

completely butchered the graph but you get the idea

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the area is 4*1

grizzled zephyr
#

so from 0 to 1

topaz schooner
#

nvm, i think they are asking for the total velocity

grizzled zephyr
#

and from 0 to 3

languid plaza
#

so 4m/s

grizzled zephyr
#

but doesnt that sound counter intuitive, if the acceleration is decrease, that must mean that the object is speeding down

topaz schooner
#

its still accelerating

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acceleration is still positive

grizzled zephyr
#

if acceleration is decreasing , velocity is decreasing

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so acceleration is positive and velocity is negative

grizzled zephyr
topaz schooner
grizzled zephyr
#

yesss

#

that is why its counter intuitive

topaz schooner
#

its not counter intuitive

grizzled zephyr
#

how t= 3 acceleration is bigger than t= 1

topaz schooner
#

its not bigger

grizzled zephyr
topaz schooner
#

huh

#

wdym you got acceleration equal to 8 at t=3?

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you can see that its 2

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2 m/s^2

grizzled zephyr
#

not acceleration

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so i guess speed is 6 m/s

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at t = 3

warm quarry
#

what is the formula for speed?

grizzled zephyr
#

but that is acceleration graph

warm quarry
#

there should also be another one

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you can also look at it like this:

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we have on the x-axis seconds

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and on the y-axis meter per seconds²

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what is the unit for speed?

grizzled zephyr
warm quarry
#

yes

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so we have someting in m/s² and we s, how can we get m/s?

warm quarry
#

you understand why?

grizzled zephyr
warm quarry
#

yes

grizzled zephyr
#

3 x 2

warm quarry
#

and with that step

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you actually just did the following:

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m/s² * s = ms/s² = m/s

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U understand?

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that is how I always remembered what the area under a graph will give me

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doesnt matter if it is about speed and distance and acceleration or something about quantum mechanics

#

just look what will happen to the units

lone heartBOT
#

@grizzled zephyr Has your question been resolved?

#
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warm gyro
#

yo

lone heartBOT
warm gyro
#

so i'm trying to figure out what power series are and doing interval of convergence

#

i'm in my senior year of high school doing calculus bc

mental python
#

whats your question

warm gyro
mental python
ocean sealBOT
mental python
#

and it converges for $|x|<1$

ocean sealBOT
warm gyro
#

oh and also i have like problems that have a rational function and i have to write an expanded form of the series and do a summation notation

#

and idk how to do those either

mental python
#

can you show an exmaple

warm gyro
#

ok

#

my main problem with power series is finding the radius and finding the interval of convergence for it

#

uh

tacit arch
warm gyro
#

idk how to do any of them tho

tacit arch
#

Showing 10+ problems is not productive

warm gyro
#

yea i'm trying to go through one at a time

inner parrot
#

Nv

lone heartBOT
#

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#

@warm gyro Has your question been resolved?

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alpine sable
#

I have not been able to find a solution to this problem, the way I approached it was by trying to combine a greedy approach for encompassing nodes and topological sorting for prerequisites but it is complicated to take them both into account

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#

@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

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sick tree
#

How do I determine the value of chocolates priced at $6 when there are 17 pieces in a box

sick tree
#

how much does each piece cost

#

someone help

#

I tried dividing $6 by 17 but the answer doesn't make sense

ocean whale
sick tree
ocean whale
#

Why doesn't that make sense?

sick tree
#

idk

#

!close

#

sorry

#

.close

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rigid marlin
#

can someone please help me rq

lone heartBOT
rigid marlin
#

I need to finish this delta

#

and im only

#

3 questions away

minor trout
#

?

rigid marlin
north rover
rigid marlin
#

idk

#

I just need to finish this

#

in 10 minutes

#

OR IM FAILING

#

SO PLEASE HELP.

north rover
rigid marlin
charred jewel
#

papa pythagoras to the rescue

rigid marlin
north rover
#

Note that the side lengths of the square are the legs of the isoceles triangle.

rigid marlin
#

I got 1.9

minor trout
rigid marlin
#

😔

#

ima fail bro

#

yall aint even helping omg

north rover
rigid marlin
#

BRO

north rover
rigid marlin
#

x = 1.9 IS WHAT I GOT

north rover
# rigid marlin I TRIED THAT

It does not seem like you applied it correctly. Try it again, noting that the side lengths of the square are the legs of the isoceles triangle.

minor trout
#

pythagorean theorem is $a^2+b^2=c^2$, a is equal to b because you are given a square, a is given to be 2, x is equal to c

ocean sealBOT
#

fdgdfg

minor trout
#

i did like half of the job

rigid marlin
lone heartBOT
rigid marlin
#

Ima just ask my friend..

north rover
celest swift
#

?

#

u do

rigid marlin
#

yall aint helping

celest swift
#

2 squared plus 2 squared

north rover
lone heartBOT
celest swift
#

= x 2

#

and do root of 8

#

which becomes 2 root 2

lone heartBOT
# celest swift and do root of 8

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

north rover
lone heartBOT
rigid marlin
celest swift
#

SORRY

rigid marlin
#

like explain what I have to do

minor trout
#

we are

rigid marlin
#

not the answer

north rover
celest swift
#

IM SORRY SO SORRY

minor trout
#

pythagorean theorem is $a^2+b^2=c^2$, a is equal to b because you are given a square, a is given to be 2, x is equal to c

ocean sealBOT
#

fdgdfg

minor trout
#

plug the givens into the theorem

rigid marlin
#

I got 2.8

north rover
ocean sealBOT
#

Result:

2.8284271247462
north rover
#

Hooray!

rigid marlin
#

..

rigid marlin
north rover
ocean whale
minor trout
#

they couldn't even gum it up

rigid marlin
rigid marlin
minor trout
#

ok

rigid marlin
#

ok so for this one I got 3.46 do I do 3.5 or 3.4

#

@north rover

minor trout
#

,calc sqrt(12)

ocean sealBOT
#

Result:

3.4641016151378
minor trout
#

3.5

rigid marlin
#

ok

north rover
rigid marlin
#

im solve the next and ask yall

north rover
rigid marlin
#

ok can you kinda explain this one

north rover
rigid marlin
#

can you explain it a little

minor trout
north rover
north rover
minor trout
#

ok

north rover
rigid marlin
#

im slow on this part…

#

😔

north rover
rigid marlin
#

OH UHHH

north rover
#

Can you tell me the measure of the red angle and green angle?

minor trout
rigid marlin
minor trout
#

each angle has the same measurement

rigid marlin
#

so are all

rigid marlin
rigid marlin
#

ok so all angles are around 60°?

north rover
#

So what can you identify the red angle as?

rigid marlin
#

ok ok

rigid marlin
north rover
rigid marlin
north rover
rigid marlin
north rover
#

Remember that we are considering the right triangle, in which red+green+right angle=180. Is that a little clearer?

rigid marlin
#

so how are they not all 60

#

but green is 60

north rover
rigid marlin
#

red is 60

#

mh

#

mb*

minor trout
#

now what is green?

rigid marlin
#

WAIT

#

120?

minor trout
#

if you look the green is part of an angle that has been split

#

in half

rigid marlin
#

OHHHH

#

SO 30

minor trout
#

yes

#

so an equilateral triangle creates a triangle with angles 30, 60, and 90 always

#

these are great because they have the property where the hypotenuse is double the length of the short leg and the long leg is sqrt(3) times longer than the short leg

rigid marlin
#

hm

minor trout
#

$h = 2s$ and $l=\sqrt{3}s$

ocean sealBOT
#

fdgdfg

minor trout
#

we are given one of these values and one of these values is the one we are solving for

#

can you figure out which ones?

rigid marlin
#

..

#

ima just guess…….

minor trout
#

the answer?

#

we are literally one 2 divisions away

#

,calc 10/sqrt(3)

ocean sealBOT
#

Result:

5.7735026918963
rigid marlin
#

I was so close I said 6…

#

😔

#

I got .7

#

do I put .7 or 1

minor trout
#

,calc 1/sqrt(2)\

ocean sealBOT
#

The following error occured while calculating:
Error: Syntax error in part "\" (char 10)

minor trout
#

,calc 1/sqrt(2)

ocean sealBOT
#

Result:

0.70710678118655
minor trout
#

0.7

lone heartBOT
#

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#
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safe meadow
#

Is there any general formula to find the closest distance from a point

jagged imp
#

Like the shortest distance between a given line and point?

minor trout
#

the pythagorean theorem gives the length of the shortest path

safe meadow
#

Whatt I mean is that

#

For example

#

The closest distance from lnx to point 10,10

minor trout
#

what is lnx

safe meadow
#

The graph lnx

minor trout
#

ln(x)?

safe meadow
safe meadow
#

The closest distance of a point to a line is |ax_0+by_0+c|/√(a^2+b^2)

#

I'm curious is there any formula for any graph

#

Or any function

minor trout
#

i think you would need to manually check until you find one using a binary search

safe meadow
#

Hmmmm

#

Ok

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#

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echo ocean
lone heartBOT
echo ocean
#

I found formula: (A*B) - (C*D), true for 1, 2, 4

Appilication for first:
10*11 - 7*5 = 110 - 35 = 75

#

Doesn't work for 3rd, which gives 14 (None of the options)

#

10 mins now...

#

<@&286206848099549185>

versed tide
#

It’s 18

#

AC+BD

echo ocean
#

Mind explaining mate?

#

oh

echo ocean
#

What sense are you using in this?

#

I used
A B
X
C D

#

I got a exam in 10 mins, this comes on it

#

AC + BD for 3rd one is now 23

spring barn
tiny fable
#

well the answer im thinking of isn't even an answer choice...

#

14 makes sense to me, these puzzles are ridiculous lol

echo ocean
versed tide
#

14 seems logical and the rest is typos

#

I goofed before

echo ocean
versed tide
#

Yeah that’s the only thing that fits all of them

echo ocean
#

No options tho. I chose 17

versed tide
#

Unless we’re trying to find some other way like lowest common denominator of all three or left side right side

echo ocean
#

Ima come after... like 30-45 mins. Ima give my exam

echo ocean
#

Which is option, but for other 3 are now incorrect

lone heartBOT
#

@echo ocean Has your question been resolved?

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crude sage
lone heartBOT
crude sage
#

i need help with this, please someone help me

winter light
#

Do you know the definition of the mean (or average)?

crude sage
#

yes

#

i got my answers

winter light
#

Alright nice

crude sage
#

i dont know if i did it right

#

could u check it for me

winter light
#

Yeah

crude sage
#

Answer
(21 + 25 + 22 + 42 + 53 + 41) / 6 = 34.

  1. Answer: 34.

Since there are 6 ages (an even number), the median is the average of the middle two ages: (25 + 41) / 2 = 33.

  1. Answer: 33.

District 1: 3, District 2: 3, District 3: 2, District 4: 1, District 5: 2, District 6: 3.

District 1 and District 2 have 3 attendees each.

  1. Answer: District 1 and District 2.
#

<@&286206848099549185>

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restive timber
#

Is this proof correct? I has chatGPT translate it from German

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#

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restive timber
#

.close

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tired socket
lone heartBOT
tired socket
#

how to solve a

wary fable
#

use vector product

surreal fog
tired socket
#

coordinates?

surreal fog
#

Coordinate vectors

#

Vectors defined in terms of coordinates along a canonical basis

#

We need more context

tired socket
#

well thats all i was given

#

what do i do now

tired socket
surreal fog
#

ok then it's probably the orthogonal basis vectors then

#

Use cross product

#

a.
[i j k]
[2 -3 5]
[-4 0 3]

#

and use the formula above

#

same for b, find the appropriate places

tired socket
#

ok ill solve

#

and u check

surreal fog
#

,w (2i-3j+5k)×(-4i+3k)

surreal fog
#

solve a and check against ^^

#

if you got it right, you now know how to solve and check as well

#

(Just repeat what I did)

tired socket
#

ahh

#

i understand

#

i got it

#

,w (3i+j-2k)x(-i-j+2k)

lone heartBOT
#

@tired socket Has your question been resolved?

#
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valid phoenix
#

hi, i dont know how to proceed from here. im not sure if im using the correct method to approach this question

vale wigeon
#

your method is correct

#

you should be seeing some cancellations happen

alpine sable
#

some things simplify

vale wigeon
#

notice that you are essentially summing unit fractions with coefficients 1/4, -1 and 3/4

#

thinking about it this way may make finding the pattern of simplification a bit easier

valid phoenix
#

can i combine the 3 fractions into one

short vapor
#

yes! you can in a way

#

notice all the terms with 3 in the brackets

#

give me a second

valid phoenix
#

okay

short vapor
#

the first term, r = 2, so the "r+1" term has a 3
the 2nd term, r = 3 so the "r" term has 3
and the 3rd term, r = 4, so the "r-1" term has 3

#

does that make sense?

valid phoenix
#

ye

#

s

short vapor
#

oki

#

so

#

let me isolate them

valid phoenix
#

so u can group them into one

#

?

short vapor
#

yeah!!

valid phoenix
#

i calculated the sum of it equals to 0

short vapor
#

mhm

#

and notice it doesn't just work for 3

valid phoenix
#

doesnt work for the next group tho

short vapor
#

no it does

#

$$\frac{3}{4x} - \frac{1}{x} + \frac{1}{4x} = 0$$

ocean sealBOT
#

Everbound

short vapor
#

for our example, x = 3

#

but if you work it out it doesn't actually matter what x is

valid phoenix
#

oh yeah

#

it actually work

short vapor
#

yea

valid phoenix
#

so the pattern is like the sum of the terms in the group equals to 0

#

which means the terms in the group can be cancelled

short vapor
#

mhm

#

all those diagonals sum to 0

valid phoenix
#

so the remaining would be the ans rite

#

ohh

#

thx i understand it now

#

: D

#

.close

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#
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knotty garnet
#

fyi this technique is known as "telescoping"

valid phoenix
#

does it refer to the diagonal cancellation

knotty garnet
#

each time you cancel its like the telescope collapsing one segment

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thick trail
#

Reduce the Eqn $x^3+x^2+9x+12=0$ into a standard cubic Eqn and use Cardan's method for finding it's roots

ocean sealBOT
#

TᖇᗩᑎᔕᑭᗩᖇEᑎT ᔕᕼᗩᗪOᗯ

lone heartBOT
#

@thick trail Has your question been resolved?

thick trail
#

<@&286206848099549185>

tight pier
#

well isn't it already reduced?

#

are you supposed to turn it into a depressed cubic?

thick trail
ocean sealBOT
#

TᖇᗩᑎᔕᑭᗩᖇEᑎT ᔕᕼᗩᗪOᗯ

thick trail
#

GG

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#

@thick trail Has your question been resolved?

thick trail
river totem
#

that works

river totem
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past geode
#

hello! could you help me try and remember all of these definitions please?

past geode
#

prime number, composite number, prime factor, multiples,

#

Thanks

vale wigeon
#

we cannot really help you memorize these

#

bc we do not know what memorization method(s) work for you

past geode
#

ok i get it and one other question aswell: lets say the exchange rate from euros to dollars is for euros 0.93 and dollars: 1 how would i work out how to find 15 euros?

#

or if i have 15 dollars how would i work out how many euros i have?

halcyon mango
#

15*0.93=amount of euros

past geode
#

ok and if it said work out how many dollars 15 euros is what would i do?

halcyon mango
#

1 dollar = 0.93 euros

#

correct?

past geode
#

yes

halcyon mango
#

You just divide in that case

past geode
#

so to find out how many dollars 15 euros is i would do 15 divided by 0.93?

halcyon mango
#

15/0.93

#

Indeed

past geode
#

ok thank you so much on this i have got a test tommorow and my teacher didnt rly explain it well

halcyon mango
halcyon mango
past geode
#

kinda ann said she couldnt explain

#

but if you could help me memorise then that might help more

halcyon mango
#

Prime numbers are numbers that are only divisible by themselves and one

#

one sec

past geode
#

ok np

halcyon mango
#

Or what

past geode
#

Yeah

#

I just need definitions for them thats all

halcyon mango
#

Don’t really have a way of memorizing

#

But

#

If it’s up to 100

#

Just try for yourself

#

Divide the number by 2 up until 10

past geode
#

Ok thanks alot your like one of the best helpers on this whole mathamatics server 🤣

halcyon mango
#

If you get decimals for each answer it’s a prime number

past geode
#

Ok

halcyon mango
#

Ty tho

past geode
#

What grade?

halcyon mango
#

11th

#

You?

past geode
#

Ah at least your near the end of school

#

Grade 8

#

Just started

halcyon mango
#

I see

past geode
#

Alot of painful years to come

halcyon mango
#

Stuff like that can be tricky

#

So just ping if you need anything

past geode
#

I just find this kind of math hard where you have to memorise stuff

#

Do i ping you?

halcyon mango
#

Yeah or dm

past geode
#

Kk thanks

halcyon mango
past geode
#

Yeah eventually

halcyon mango
#

Bye and good luck

past geode
#

Cya thanks again

#

.close

lone heartBOT
#
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runic obsidian
#

fellas what am i missing

lone heartBOT
exotic canopy
#

how did you arrive to that expression?

runic obsidian
mighty pasture
#

(in order to think about how to get this blue area in the first place !)

runic obsidian
#

kinda blanking on what im looking at 😭

marsh hamlet
mighty pasture
#

because so far its blue - white, but you have no good way of finding white, right ?

#

but you can find the intersect of the two lines and integrate to find red

#

and you can subtract the white triangle left behind as well

#

so whole integral - red - white triangle

#

then vol of revolution

runic obsidian
#

ahh ok

#

(im stil kinda lost)

#

.close

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#
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dim turtle
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dim turtle
#

need help understanding this

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so this i understand the power rule, but what confuses me is why does (-1/2 +1) get multiplied by negative 1?

#

im confused on how to solve the integral not the improper integral part

dim turtle
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could you elaborate?

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i dont understand where exactly or why you would apply chain rule here

dim turtle
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@dim turtle Has your question been resolved?

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hollow cedar
#

Any stat heads in here? not too sure if this is the right approach and i really don't wanna have to redo all the other questions if i get this wrong LOL. Just want to confirm this is the correct method:

prime badge
#

,calc 0.25(0.5)+3.5(0.3)+6.5(0.25)+0.2(13)

ocean sealBOT
#

Result:

5.4
prime badge
#

i don't know waht i'm doing just checking what i would get

hollow cedar
#

fair enough

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.close

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devout dock
#

<@&286206848099549185>

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is anyone here?

alpine nacelle
#

call x the number of poles in tel aviv and y the number of poles in ramat gan

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write what the exercise says as two equations

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then you can solve the system

devout dock
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x = 1500
y = x * 1.5

???

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wait actuall no, it's 0.5

alpine nacelle
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not quite, the exercise doesn't say that there are 1500 poles in tel aviv

devout dock
#

either way, I keep getting 750

alpine nacelle
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also, it's not 1.5 nor 0.5

devout dock
#

I wrote it incorrectly mb

alpine nacelle
#

oh ok

#

lemme read it again then

devout dock
#
In Tel Aviv, there are 1,500 Poles, which is 50% more than the amount in Ramat Gan. The amount in Ramat Gan is 25% greater than the amount in Eilat. How many Poles are there in Eilat?
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devout dock
#

In Tel Aviv, there are 1,500 Poles, which is 50% more than the amount in Ramat Gan. The amount in Ramat Gan is 25% greater than the amount in Eilat. How many Poles are there in Eilat?

#

here's the fixed translation ^

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coarse elm
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coarse elm
#

did i do a mistake or something

pseudo ice
#

You should have a -25 rather than a -5, if you did difference of two squares? catLove

north rover
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misty ember
#

Is there an equation for a rotated circle in some point in 3D space

misty ember
#

I also throught that I could apply a rotation matrix then translate

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But I wonder if there's something already there

kind sparrow
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It depends if you are going to use quaternions or not, but the two formulas I see used otherwise are given's rotations and the rodrigues rotation formula

misty ember
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So the simplest is to take a circle in parametric anf do a rotation matrix?

alpine nacelle
#

if you want to rotate a circle around some point A, you can do the translation A->O, then rotate around O with matrix of rotation around origin, then do the translation O->A

misty ember
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But a rotation is a linear transformation, if I translate first then I'd rotate around (0,0,0)

alpine nacelle
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yes that's the point, if A is your center of rotation you want to rotate around it like if it was O ?

misty ember
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Yeah, but first rotation no? And then translation

alpine nacelle
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imagine a square with center at (1, 1), if you want to rotate the square around its center by 90°, you should get it invariant right ? because it's like translating the center to O, then rotating, then translating back

misty ember
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I want to rotate the circle around the circle centre not around (0,0,0), if I translate first then rotate then it wouldn't be the result I want

alpine nacelle
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I'm not sure what result you want so try your way

misty ember
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I want to rotate a circle around it's centre in 3D, first I thought interesting a plane with a sphere of the same radius but that devolved into way to many steps and it was not elegant

#

Okay so wolfram has a page for it sorry, it does a matrix multiplication 😅

#

Sorry for asking

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.close

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old yew
#

(c) Every sequence of rational numbers has a convergent subsequence.

I'm trying to prove this statement (well disprove) in this case

If i can show n is a convergent sequence of rational numbers, then show that any subsequence of (n) does not converge, then the original statement is disproven right?

old yew
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that any subsequence of (n) does not converge, then the original statement is disproven right?

How do i prove this part specifically

pallid scarab
#

but yes that's a fine counterexample

old yew
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original statement says every sequence so it should include divergent ones too

pallid scarab
#

but you can notice that if you're trying to disprove that statement, the counterexample would have to be a divergent sequence

old yew
#

Ah okay

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urban bane
#

how to solve for limits with square roots in expression

urban bane
#

in other limit problems I understand how to use factoring to get the epxression and evaluate it

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but when square roots get involved I'm lost

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and mind you my algebra is rather rusty when it comes to square roots, I'm not sure how to deal with it

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#

Show your work, and if possible, explain where you are stuck.

urban bane
#

plugging in 0 for T obviously leads to an evaluation of 6/0

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which is not possible, can't divide by 0

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I could try breaking the expression apart

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but I'm not sure what to do beyond something like this

7/(sqrt(49 - t)) * 1/t - 1/t

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I know there is a method of using conjugates... which I don't quite fully understand how that even works in practice

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but with some magic you somehow wind up with a expression with canceled out square roots

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and for the record I am given the answer... but the problem is I'm stuck on how you can even manage to get to the solution

rustic coral
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If not, do that

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b/c what you're trying to do rn is just going to give you infty - infty (plus or minus some signs)

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which is indeterminate

urban bane
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combine what two fractions?