#help-0
1 messages · Page 483 of 1
how old
like middle school?
in middle school we were just taught to be able to regurgitate the pythagorean theorem tbh
i was never shown a proof or an intuitive explanation
just accepted it as fact
14
sad
indeed
yea i didnt see that until after though
pythagorean theorem was a meme throughout elementary school
but in early middle school i didnt see that
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Hiii so questionn here. I'm trying to find the derivative of 2^-0.274a
the rule is b^x = b^(x)lnb
and so I see that and i would just think
it's 2^(-0.274a) * ln2
where does the -2.74 come in from?
I've had to use this rule multiple times in class before but there's never been this third number that just appears
feels like a mistake, the derivative of 2^(-0.274a) is (-0.274) 2^(-0.274a) ln 2
where does the (-0.274) in front come from?
thats from chain rule
the outside function in 2^(-0.274a) is 2^x
the inside function is -0.274a
np
Nevermind that was the wrong answer apparently 
I guess this is the full question
but i'm trying to find the derivative at a=7
i tried plugging 7 into this equation
and then converted it to seconds
But apparently this is not the derivative(?)
that is because I guessed what T was since you didnt tell me
the derivative of 2^(-0.274a) is (-0.274) 2^(-0.274a) ln 2
so the derivative of 10 * 2^(-0.274a) is 10 * (-0.274) 2^(-0.274a) ln 2
or (-2.74) 2^(-0.274a) ln 2
oh sorry 
nw
is there more to (c)?
dont get how this is wrong
just to be sure, can you screenshot this little bit of blue text below the (c)'s answer box
nw, I didnt notice either
I didnt look too closely at the screenshot and I saw the = as a ≈
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im confused here lim x-->x_0 f(x) = f(x_0)
so what does this mean
What part aren't you sure about?
i dont get what this means
Well, it means the limit of f(x) as x approaches x_0 is equal to f(x_0)
In practice, if that equality holds, it means the function f(x) is continuous at x_0
so it means this is true only for continous functions?
.
i mean limits
or functions actually
It’s true for functions continuous at x_0
bruh thats what i thought at first but for some reaosn in another group, someone told me it was for discontinued functions
you can take it to be the definition of continuity
anyways i have another may i ask that rn as well?
So there is a theorem that if a function is differentiable, then it's continuous, and to prove it, there is an equation like this. So I was confused as to how proving this equation right will let us prove the statement.
because f(x0) is a constant, you can add it to the right hand side
,, \lim_{x \to x_0} (f(x) - f(x_0)) = 0 \Implies \lim_{x \to x_0} f(x) = f(x_0)
oh we can do this even with limits?
yes
ok so if this true, this must mean this is continous but how can prove that its differntiable then?
hopefully you have learnt some "algebra of limits" properties
continuous does not imply differentiable
you have a differentiable function, and you can prove that it must also be continuous
how can we do that using the equation aobve?
in other words
can u explain me this
why did that expresison have to be 0 in the firstp place to prove that f(x) is differntiable?
and please ping me if someone helps
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I dont understand this, where did the 0 come from. Like why did you multiply it by 0. Why not just cross out thr (x-x_o)
so he said the limit of the first time is f'(x_0) and the limit of the other term is 0
so it becomes 0
so even i dont get why he did this and how he did this
A function being continuous doesn't imply it's differentiable
but vice versa?
But a function being differentiable imply that it's continuous, yes
so we need to proove that
and apparently this is the proof for it
and i dont get how this proves that
the first expresison is just the fact that the function is continous
i donget get anything else
The second expression proves the first expression
you have to prove that f(x) - f(x_0) = 0 as x approaches x_0 but you can't immediately do so
but why do we need to prove that
we need to prove that do show that f(x) is continous/
You need to prove the continuity, given that it's differentiable
Which is equal to proving the first sentence
So you multiply the expression by (x-x_0)/(x-x_0)
Then the limit becomes ( f(x) - f(x_0)/(x-x_0) )*(x-x_0) which evaluates to f'(x)(x-x_0)
So now we can plug x in as x_0 so the second term is 0, making the expression 0
so basically he converted the first equation in a form that it can also simultaneouly be a derivative * 0?
Yeah
.
oh ok
got it tysm for ur help
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$\frac{\sum^{399}{k=1}\sqrt{20+\sqrt{k}}}{\sum^{399}{k=1}\sqrt{20-\sqrt{k}}}$
Skill_Issue
i neee to find the value if this
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let that expression be equal to S
add 1/S
errrrr
$$S=\frac{\sum^{399}{k=1}\sqrt{20+\sqrt{k}}}{\sum^{399}{k=1}\sqrt{20-\sqrt{k}}}$$
$$S+\frac{1}{S}=\frac{\sum^{399}{k=1}\sqrt{20+\sqrt{k}}}{\sum^{399}{k=1}\sqrt{20-\sqrt{k}}}+\frac{\sum^{399}{k=1}\sqrt{20-\sqrt{k}}}{\sum^{399}{k=1}\sqrt{20+\sqrt{k}}}$$
Skill_Issue
cross multiply
$$S+\frac{1}{S}=\frac{(\sum^{399}{k=1}\sqrt{20+\sqrt{k}})^2+(\sum^{399}{k=1}\sqrt{20-\sqrt{k}})^2}{\sum^{399}{k=1}\sqrt{20+\sqrt{k}}\cdot\sum^{399}{k=1}\sqrt{20+\sqrt{k}}}}$$
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numerator = x, denominator = y, find x+y
yeah this will work
looks much easier too
this is also a direct result i think
this?
$\frac{\sum_{k=1}^{m^2-1} \sqrt{m+\sqrt{k}}}{\sum_{k=1}^{m^2-1} \sqrt{m-\sqrt{k}}} = 1+ \sqrt{2}$ for $m\ge 2$
uh
yea its correct but how did you get that
Astar777
how is it k^2
so $\sqrt{2}\sum_{k=1}^{399}\sqrt{20+\sqrt{400-k}}$
Astar777
how did you get sqrt2
o
and $x = \sum_{k=1}^{399}\sqrt{20+\sqrt{k}}$
Astar777
do you notice anything
so $x+y = \sqrt{2}x$
Astar777
right
get x/y from here
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if say theres a polynomial with roots like say a,b,c is there an easy way to change the roots to a+1, b+1, c+1
like say its x^3-x+1=0
Hola math geeks
like say i dont know the roots nor the cubic formula, if the x^3-x+1=0 has roots a,b,c, can i easily somehow change it to a polynomial
er wait yeah
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Anyone able to help with probability and statistics (mainly using R)
Yes
sorry, i do js
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Yo
Can anyone help me do 5-8 it's for a group activity idk how to do it
<@&286206848099549185>
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Can sb help me with this?
this is a drawing to this task
And i know that the quadrilaterals LNDF and CMKE are similar to each other
But idk what,s next
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Hello
I need help calculating an inverse function
It is defined on D=[-2,0]
And its values are on [-30,2]
Sorry if my math termimology is bad, I've never stidied maths in english
Im trying to figure out b rn
to get the inverse, u can replace f(x) by y , put it in the expression of f(x) and solve for x
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✅
I did that and i got a wrong answer
But i am alsmost sure i did all the solvimg steps correctly, but its wrong, i think its because there is a very specific definition of the functuin, its only supposed to be defined on 2 elements
Look on the pic, the correct answwr is way more complicated than just solving for x
Or what am i missing?
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@steep wing Has your question been resolved?
Can you please translate this into English?
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yo guy
guys
i gotta simplify
x^3/x^3+2x
so what i do here is i make it
x(x^2)/x(x^2+2)?
but then i cant do anythng
!xy
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
.
well yea
i mean after that
wait
thats the solution in the solutions
xy
☠️
Typing original takes too long xy is nice lol
Yeah
what about
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
12x^2-12x/2x-2
Cancel 2
ohh alright i will start doing iut and then ill ask
yep okay
what
ye
okay now idk what should i do
should i do ruffini?
i got 6x^2-6x/x-1
or should i do long division?
!1q
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Bro is on a roll lmao
ohh
my bad
didnt know that
Can you take anything common in the numerator?
After this q close this and occupy a new one lol
no? i guess/
It starts with S
where did you get 5
Also it comes before y
now sjould i divide thwt?
Lmao
Lmao
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I apologise for shitty handwriting n blue shit, but did I fuck up because the coefficient of x in the numerator is a negative, whence I had to flip signs at some point?
😂😂😂😂😂😂
Kool aid 🔥

I acc have 0 clue how that got there, I looked down at my paper n it somehow was there n coated multiple pages. I’m not even playing
I have nothing blue on my desk, this shit just denatured r sum
Anywayssss thooo, -3x = flip of signs?
Ohhhhhhhhhhhh
ty ty
.solved
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how do i figure this out im in 8th grade trying to start calc
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don’t understand this..any help?
m is the midpoint so its halfway between A and B
right, what is the formula and how would i solve it?
(A+B)/2 = M
no no i meant how to solve for b
well rearrange it
okay..does (a+m)/2 work?
no, thats the midpoint between a and m
ohh
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Is that simply just a reference to the classic sohcahtoa stuff ?
We have to show that dy/dx (left side), is equal to the cos(t)/-sin(t). I knew that we had to do the converting stuff but I didnt expect them to do x/-y
I'm just unclear how they transition from x/-y to -x/square root of 1-x^2
post the original question
I was about to do cos divided by sin
oh I see, then yea its a reference to that
if you have y as a function of x, then thats sort of "sin(t) as a function of cos(t)"
and sin(t) = sqrt(1 - cos(t)^2)
so y = sqrt(1 - x^2)
I see
just one thing more related to this whole thing
They do something similar in the following question
This part here, I just don't seem to know all the trig function computations and stuff
I searched it up and realised that tan pi/3 is actually 0, but also can be written as ( (negative square root of 3) / 2 )
They've done this with other stuff in the past such as square root of 2 over 2, but idk how they remember
I guess, i'm not sure how to sort of get ((negative square root of 3 )/ 2)
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Trig proofs
can some help me pls
gtfo
36x^{4}+60x^{3}-47x^{2}-60x+36, How do i graph this?
why are you on here..go ask somewhere else
i can try to help i have limited knowledge on this though
thank you
because i need math help...
get ur own channel
Omg man why did my channel close 
why is ninja coming to my channel
its proofs
look at the full equation on the top of the first image, i have to prove that the left side is equal to right side
so basically simplify it until its the right side of eq
so basically, you’re trying to say that 4. is equal to 5.?
?
how do i make my own channel
OH SORRY i was looking at the wrong image
in this case i don’t think i would know how to justify it, as i do not have much knowledge sorry
no prob
anyone help w this^
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8x^3 + 1
last time i did a sum of cubes it was x^3 + 27
but this is a bit different i still know the a^3 + b^3 = a^2 - a(b) + b^2 right?
@heavy drift Has your question been resolved?
@fallen mortar i am trying to get help myself, helpers seem very busy right now, but and it doesn't look like any other help channels are open rightn ow
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why do multiply 1/6 x 1/6 rather than add them?
so when do we add then?
whats the probability of rolling a 4 or a 6 on a single die roll?
1/6
no
wait so u add them here?
well there are 6 possible outcomes 1, 2, 3, 4, 5, 6, and you want to know the probability of rolling either 4 or 6, so thats 2 of the outcomes
so thats 2/6
well i was trying to give you an example, what causes us to add in that case?
when there are multiple outcomes in one situation?
or ig mutually non-exclusive events
like if u think of a venn diagram but there's nothing in the middle
yes, generally whenever you have an "or" in the question
alrlr
the actual formula is P(A or B) = P(A) + P(B) - P(A and B)
yea ive learnt that one
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hi
sorry this is off topic but can anyone help with a grade 12 physics problem. I've been trying for days and sometimes I get 300N and other times I get 250N. The correct answer is 351 N. I would apreciate anyone attempting
You can paste your question, if someone knows they will respond
thanks boss
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Is there any easy way to know how a graph would look? For example I have to know how the graph y=(0.5)^x
Would look like
how i know its decreasing?
or how i konw it would look like an exponential function
yes
when the base is smaller than 1
This
Just how it looks in general
when x is the exponent
When it's ^x the graph will look that way? And the number just signifies where to "shove" it
shove in terms of being more or less steep
We know that it's a decreasing graph, but is there a way to know like which way it's going without graphing it?
Number 1.32
Without graphing I'd be stuck between option 2 and the last
Is there a way past it?
check using values x=-1,x=0,x=1
Yes that would be graphing it, so there's no other way right?
lim
Exponential functions in form a^x
won’t have values of y be negative
so the answer should be ?
Б (the second one)
yep
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can someone explain a to me?
the image is blur could you send again?
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Hi can anyone help
let (x;y) belong to R2 / xy<1
show that:
arctan(x) + arctan (y ) = arctan(x+y/1-xy)
ren
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How do I check
lim x=>π/2 (k cosx)/π-2x
Without using L'hopital rule
$\lim_{x \to \frac{\pi}{2}} \frac{k\cos x}{\pi - 2x}$
k
is this correct?
Yep
definition of derivative
sorry for the delay
${f'(x) = \lim_{x \to c}\frac{f(x) - f(c)}{x-c}}$
k
@alpine sable
Yeah
u can use that
rearranging in such a way that it fits the limit definition of a derivative
How
Wait let me think
wdym
Got it, thank you so much for your efforts🙏
Alright
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I'm also here to seek help 😭 i suck at maths XD
oh
Man
sure just ask
yo she got the channel first you might need to get a new one lmao

NO LIKE HE ASK FIRST
ik
AND I KINDA JUST STOLE IT
IM SO SORRY
I DIDN'T KNOW AND IM JUST NEW HERE
IM SO SORRY IM REALLY SORRY
allg dw
the bot doesn't read a message with a "." at the start of it
nah its better if he gets his own channel
Idk how this system works at all lol 🫠 i'm read the how-to channel
Hmm
yo
Nah you can go first
go to #help-34 and post your q
lmao
Pov: you go to a polite competition and these ppl are your opponents 
Ok
ive lost 💀
Thank you so much and I'm really sorry for taking this!!
Pls ask your doubt now
Okay So..
!da2a
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
Can someone actually help me-
Doctor of reverse psychology 👀

Hello?? Can someone help me??
Istg
Just go ahead and ask the question
I'll just start placing each question
First is this
- MIKE and his friend are playing a number - guessing game. MIKE asks his
friend to think a positive number, then add four to the number. Next, square the
resulting number, and multiply the result by 3. Finally, divide the result by 2. If
you are his friend and you get a result of 50,
(a) write an inverse function that will give you the original number and
(b) determine the original number.
(c) graph
It is suggested that you limit yourself to one question per help channel, opening a new one once your original question is answered and your original channel has been closed. This is to make your channel easier to follow for potential helpers and can bring attention to the fact that your question has changed.
I kinda know but the thing is..
It'll just look weird if I just do f(x) = 3(x + 4)^2 = 50
Looks very weird
I'm gonna need help after this 💀
This is correct imo
thats because you forgot to divide by 2 in the end
No like this is the start.
Like the steps are
- Change f(x) to y
- Interchange x and y variable
- solve for y
I stead of equation to 50
I mean in the f(x) you got.
Replace the x by y
f(x) should be 3(x + 4)^2 / 2
And keep 50 as x
Is that how it's suppose to look like??
just.. 3(x + 4)^2 = 50
x -> x+4 -> (x+4)^2 -> 3(x + 4)^2 -> 3(x + 4)^2 / 2
But there's 50
thats how you perform the operations
You need a function in x and y
"Finally, divide the result by 2."
We will put the value of 50 in b part
what's a b part?-
"Determine the original number "
💀
ok
Okay so
f(x) = 3(x + 4)^2/2
y = 3(x + 4)^2/2
x = 3(y + 4)^2/2
From '3(y + 4)^2/2', Do I use the foil method on 3(y + 4)?
.
No cause that'll only turn f-1(x)
Hmm
Want me to show an example to better understand it?
Yeah sure
f(x) = 3x + 1
y = 3x + 1
x = 3y + 1
x - 1 = 3y
x - 1/3 = 3y/3
y = x - 1/3
f-1(x) = x - 1 /3
(from teacher)
Idk what am I gonna do next-
.
You understand how x becomes f(x) following this order of operations right?
im right there with you brother
Yeah but the design is suppose to be like this
Now you have to figure a way to step back from f(x) to reach x
So what I did on the first step was correct
so follow the operations backwards one step at a time, and then combine them together
IM NOT THAT DIFFICULT TO DEAL WITH STOP.
nah dw youre not
theres been worse today
How do I do that?-
Lets take a small step. x -> x+4
Real
Now someone told you the number x+4, how do you get x from that?
What country btw?
f(x) = 3(x + 4)^2/2
y = 3(x + 4)^2/2
x = 3(y + 4)^2/2
x = (3y + 12)^2/2
????
@sour mica
What are you trying to do
Finding the inverse of y?
Inverse Function. I'm trying to know what to do after x = 3(y + 4)^2/2
can you start with this? We can reach your problem step by step
this is unnecessary
no...
...
you subtract 4 from x+4 to get x
x = 4...
no, x = (x+4) - 4
oh
this is how you get inverse for x+4
by subtracting the 4
doing the opposite operation of what we did before
theyre just doing small egs of what the q is aiming for, idk what quad youre talking about
why can't we follow this example?-
So what you have at hand right now is the function $f(x) = \frac{3 \cdot (x+4)^2}{2}$
Bacter10Fr4g is not fr0g
cause the problem isnt the question, its the concept
if you notice, x+4 is a part of the problem
Can we just use foil method?
Sorry if I misunderstood his question . "Inverse Function. I'm trying to know what to do after x = 3(y + 4)^2/2"
I thought he is finding the inverse of y and it's a quadratic function which has two solutions I.e the inverse of y is not possible because it's not one-one .
foil is not a method, it is the order of operations
we will use foil to get the inverse
Since you love foil so much, can you tell what is the first operation we should do here on $f(x) = \frac{3 \cdot (x+4)^2}{2}$ ?
Bacter10Fr4g is not fr0g
Can you tell when to use foil?
3 (x + 4)^2
3 ( x^2 + 16)
3x^2 + 48??
FOIL is to be used when you actuallyy need to multiply two terms in brackets
...
this is wrong
You need to use (a+b) ^ 2 formula. Which is something you dont need to do here
And how does this help
To remove 3?
that 3 hasnt disappeared. It simply moved from outsside the bracket to inside
we need that 3 on the side of y
so what you are doing is not necessary to solve the problem
When you are looking for the inverse, you have to follow the order of the problem in the reverse direction
thats why I kept mentioning x -> x+4 -> (x+4)^2 -> 3(x + 4)^2 -> 3(x + 4)^2 / 2 this
Check dms
but the steps state that
- Change f(x) to y
- Interchange x and y variable
- solve for y
Therefor,
f(x) = 3(x + 4)^2/2
y = 3(x + 4)^2/2
x = 3(y + 4)^2/2
Yes, and the part of solving for y means you go back the way of the steps
and not foil
Hm...
Constructing the function had a specific order of operations given in the problem
that you add 4 before you square the number and so on
okay..
So, it is important we follow it in backwards direction
how did you get 4y?
Add 4 (y + 4) = 4y?
I swear im bouta lose it
Same
can you please read this?
not that you had logic backing stuff you did before
this is better
WHAT?

WHICH ONE??
but still you seem to not know the difference between addition and multiplication
Sorry 
So..
Addition and subtraction work in ways opposite to eachother
3 (y + 4 - 4)...?
And multiplication and division do too
please don't make fun of people in help channels, don't post if you aren't gonna be helpful
Same way squaring something and taking square roots
now now, wait a moment. Like I said, you need to reverse the order of operations
Can you tell what was the last step that you did to the number? According to the question?
I mean in the statement of the problem
I'll tell you: you divided by two
Finally, divide the result by 2.
So you start by undoing this
MIKE and his friend are playing a number - guessing game. MIKE asks his
friend to think a positive number, then add four to the number. Next, square the
resulting number, and multiply the result by 3. Finally, divide the result by 2. If
you are his friend and you get a result of 50,
(a) write an inverse function that will give you the original number and
(b) determine the original number.
(c) graph
So.. it'll be x = 3/2(y + 4)^2/2?
You have an extra /2 in there
x = 3(y + 4)^2/2?
What do I do next?
Now you can start by listing the operations you did starting from mike was told the number. I'll start
- Add 4 to the number
- ...
You fill the rest
Which number-
MIKE and his friend are playing a number - guessing game. MIKE asks his
friend to think a positive number,
This number
Why are you skipping stuff ahead
I THOUGHT OF A POSITIVE NUMBER.
Can we just go in the order of what I ask you and you answer?
.
And then what? Write step by step
Can you please wait? Clearly you havent understood anything I told you yet, and still you skip ahead without understanding anything...
And what you do is not even correct
I THOUGHT OF A POSITIVE NUMBER WHICH IS 2. I ADD IT TO 4 SO 4 + 2 IS 6
clearly, you have misunderstood something and I am looking to correct that
WHAT AM I NOT GETTING??
why are you writing this then?
BECAUSE I DID WHAT'S SUPPOSE TO HAPPEN
No you dont have to do that. Clear everything you did from your head, and start from scratch. What is the first step?
- Add 4 to the number
What is the second step? - Square the resulting number.
What is the third step? -
Can you now answer something which should be in place of the ___ ?
We are breaking down the problem into managable parts that are relevent later
ADD 4 TO THE NUMBER
I PICKED 2 FOR THE POSITIVE NUMBER
ADDING 4... TO THE NUMBER (2)
4 + 2 !!!!!!!!
GREAT
SO IT'S 6.
BUT YOU STILL HAVE TO SQUARE IT AND SO ON
ALSO FORGET ABOUT YOUR CHOICE OF NUMBER
f(x) = 3(x + 4)^2/2
y = 3(x + 4)^2/2
x = 3(y + 4)^2/2
x = 3(y + 4 + 2)^2/2
Finally
Now square
Again you are skipping steps 😭
what.. DID I DO
can you just answer what to put in 3 here?
I DID EXACTLY AS THIS
4 + 2!!!!!
NO. NO. YOU SAID THIS
がんばれman you got this. reread the question
AIN'T NO WAY YOU JUST CHANGED YOUR MIND
No you dont have to do that. Clear everything you did from your head, and start from scratch. What is the first step?
- Add 4 to the number
What is the second step? - Square the resulting number.
What is the third step? - Multiply by 3
STOP CHANGING YOUR MIND.
I wanted the anwer multiply by 3
BUT THE WHAT?
Can you read what I wrote in the message I replied to?
ADD 4 TO THE NUMBER
I PICKED A POSITIVE 2
2.
ADD 4... TO THE NUMBER (2)
4 + 2
I did not ask you to do anything, other than fill in the blank
- Add 4 to the number
- Square the resulting number
- Multiply the resulting number by 3
- Divide the resulting number by 2
Is it hard so understand I just want the question reformatted in this form?
calm down kio
THIS THING IS KILLING ME
In the question, when this fictional character of MIKE is told the number by fictional character that is his firend, that is what the friend does to the number
NO CAUSE IM DOING THE EXACTLY SAME INSTRUCTION AND THIS IS STILL NOT CORRECT.
You are NOT SUPPOSED to multiply or add or whatever
I ADD 4 WHAT'S WRONG WITH WHAT IM DOING???
4 AND THEN A POSITIVE NUMBER
4 + 4?!?!
Will you just stop adding when the text says Add. Stop and read stuff written before and after the word too
IT SAYS ADD 4
WHAT AM I SUPPOSE TO DO WITH THAT INFORMATION NOTHING???
JUST 4?
THERE
4
if you read this, its in the beginning, and no one asked you to start addition and multiplications and whatever
I clearly said start listing
it means write stuff down, not perform maths
IT SAYS ADD
THEN JUST SAY "OH PUT THE 4 IN STANDBY"
SIMPLE.
SO IT'S STILL LIKE THIS
f(x) = 3(x + 4)^2/2
y = 3(x + 4)^2/2
x = 3(y + 4)^2/2
Ok
Okay Finally
Now we put that function aside
Btw I kinda forgot to tell you
WE PUT MATHS ON STANDBYE
like that needed telling
Next step Square the resulting number
ONLY WRITING
I DIDN'T DO ANYTHING YET
Good
IT'S STILL LIKE THIS
f(x) = 3(x + 4)^2/2
y = 3(x + 4)^2/2
x = 3(y + 4)^2/2
NEXT STEP.
We are writing down the original order of operations (WE WILL NOT DO MATHS YET)
- add 4 to the number (DO NOT ADD, I AM WRITING TEXT)
- Square the resulting number (DO NOT SQUARE I AM WRITING TEXT)
- Multiply result by 3 (DO NOT MULTIPLY I AM WRITING TEXT)
- Divide result by 2 (DO NOT DIVIDEI AM WRITING TEXT)
Ok?
To take the inverse, we need to follow the order in opposite way, so that we can undo the above operations
Do you understand this previous sentence?
...
Yes...
So this is still a stand by
f(x) = 3(x + 4)^2/2
y = 3(x + 4)^2/2
x = 3(y + 4)^2/2
YES
Okay.. so that's the answer?-
yes
So now we start inverting the function
Like I said, we have to undo the operations
MATHS TIME, TIME TO PULL STUFF OUT OF STANDBYE
Okay :3
we start with step 4
Divide result by 2. (DO NOT DIVIDE)
To undo the division, what do we do?
UNDO the division
what is the name of operation that reverses the division?
Hmm... (2)x = 3(x + 4)^2/2 (2)?
YES
2x = 3(y + 4)^2
Multiply..
be more specific
2x = (3y + 12)^2
😭 nooo
once again, you started reading only half of the text
2x/3 = 3(x + 4)^2/3?
Yes
2/3x = (x + 4)^2
still there is y on right hand side
OH RIGHT
JUST LEMME REWRITE IT
f(x) = 3(x + 4)^2/2
y = 3(x + 4)^2/2
x = 3(y + 4)^2/2
(2) x = 3(y + 4)^2/2 (2)
2x = 3(y + 4)^2
(2/3)x = (y + 4)^2
There
opposite of square
2/3x = (2y + 8)??
-# (a minor mistake in 2/3x, it should be (2/3)x)
Huh? Why
you have to take square root of both sides
2/3x^2 = (y + 8)^2?
nope
Catgod
Back from here we start
Yeah- aren't they both the same?
Okay
in first you divide by x, in second you multiply by x. Two are different
take square root of both sides
We go back once again
You have to undo step 2
step 2 was squaring the result
maybe this clarifies, they are both different functions
undoing the squaring means taking the square root. There is no need to take the opposite of square root
I don't get it
what does this say? Opposite of square root.
We want opposite of SQUARE. which is different from square root
triangle-
If you read it again, step 2 was
Square the resulting number (DO NOT SQUARE I AM WRITING TEXT)
We have to undo the square
This means, we have to take the square root
Sorry to interrupt, what problem are you trying to solve?
So just do nothing?
HOW
this is the question you are trying to solve, right?
If you read the sentence completely (I AM ONCE AGAIN ASKING YOU TO DO THIS) you would see
sqrt((y+4)^2) = y+4
THIS IS NOT THE SAME AS (y + 4)^2 = y + 4
(2/3)x^2 no one mentioned this anywhere
we did not take x^2 in previous steps
This is EXTREMELY WRONG. DO NOT DO THIS ANYWHERE
WELL EXCUSE ME IF I DON'T KNOW WHAT IS A sqrt!
square root
THANK YOU
maybe this helps?
the top is how you start from the original number and end up to the final number
√(2/3)x = √(y + 4)
$\sqrt{\frac{2x}{3}} = \sqrt{(y+4)^2} = y+4$
Bacter10Fr4g is not fr0g
ok?
Where did y + 4 Why is there another y + 4?
there is an equal sign there 😭 no new term
f(x) = 3(x + 4)^2/2
y = 3(x + 4)^2/2
x = 3(y + 4)^2/2
(2) x = 3(y + 4)^2/2 (2)
2x = 3(y + 4)^2
(2/3)x = (y + 4)^2
√(2/3)x = √(y + 4)^2 = y + 4
yes
And now we invert the first step
back from y+4 to y
WE SUBTRACT 4 TO UNDO THE ADDITION
minus 4
y - 4?

