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wheat saffron
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claimed it lol sorry

proud mortar
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Sorry

wheat saffron
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its fin e

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Provide a trigonometric equation. Considering only the space between š‘„ = 0 š‘Žš‘›š‘‘ 2šœ‹, the
equation must only have solutions at š‘„ = 1 and š‘„ = 2. Explain your thought process and
the work you did to create the equation. You may round decimal values to 3 places.

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I've tried using desmos just to visualize what equation works but i cant find anything as changing the variables of a transformed sin function or cosine function allows me to just have zeros at x=1 and x=2

midnight wharf
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@wheat saffron you can try solving for it

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er i mean

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you can write your guess equation like

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A cos(k x + phi) = 0

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this should be true with x = 1 or 2

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then you can solve for the "unknowns" in your guesses - the variables A, k, and phi

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you could also put the guess equation in desmos to see how it works

wheat saffron
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thanks i will try it

lone heartBOT
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ornate schooner
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is it acceptable to rewrite $\lim{x \to 2^+} e^{3/(2-x)}$ as $e^{\lim{x \to 2^+} 3/(2-x)}$

ornate schooner
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is it acceptable to rewrite $\lim_{x \to 2^+} e^{3/(2-x)}$ as $e^{\lim_{x \to 2^+} 3/(2-x)}$

ocean sealBOT
ornate schooner
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guess latex doesnt wanna format it correctly

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but yeah, question still stands. is there a property in which a limit can be moved to the power

limber widget
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$$\lim_{x\to2^+} e^{3 / (2 - x)} = e^{\lim_{x\to2^+} 3/(2 - x)}$$

ornate schooner
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kekw

limber widget
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puts on glasses Oh actually it did, it did the inline notation

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Also:
I'm 80% sure that it's correct to do that, but I'm currently trying to see if I can track down justification for it

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I recall doing it in school, at least

ornate schooner
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I know the limit evaluates to 0, I'm just struggling to understand how to justify this. Currently I'm doing something like:
Let k = 3/(2-x)
Since lim_(x->2^+) (3/(2-x) = -inf, the original limit can be rewritten as
lim_(k-> -inf) (e^k) = 0

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oh, yeah so i just did a google search. apparently that's similar to how some dude on math exchange solved it

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I don't think the multiplication by 2 really matters here lol

limber widget
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Let me see how I remember...
The way we did this I believe is to set your limit equal to something, say L. We then take the log of both sides. Giving you $log(L) = \lim_{x -> 2^+} \frac{3}{2 - x}$
You then solve the limit, and then solve for L.
Your way should be equivalent, though.

ocean sealBOT
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SpiderString

ornate schooner
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yeah it seems about the same. I appreciate the help šŸ™‚

lone heartBOT
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viral loom
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How do i make :
a^4 - 7a^2 + 2ab - 10a + 2b^2 - 16b + 56 as sum of squares ?

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vital grove
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IF h=12 and p= 45 and b=66 then what is the value of 4h/p x 78p/h / bb

vital grove
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Anyone here to solve??

jagged cobalt
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i dont get what the last part is meant to be, brackets save lives

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but this seems like a simple sub in the numbers no?

vital grove
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Yh but somehow my book answer and my answer is not matching

tacit arch
vital grove
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My answer is 78 and book answer is 75

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there may be some mistake

fresh wedge
vital grove
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its 4h divided by p mutiplied by 78p divided by h and also divided by bb means b x b

fresh wedge
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Is this correct?

vital grove
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yes it is

lusty token
vital grove
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may my book has got mistaked

lusty token
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not very likely

vital grove
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This is the answer i got

fresh wedge
lusty token
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you need to be precise in your typing

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usually * is used instead

vital grove
lusty token
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it also confuses us, so it'd be great if you could use that too

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oh you actually meant x

vital grove
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yh wht did i typed then

lusty token
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your typing makes no sense

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4h/p x 78p/h / bb is a jumble of confusion

vital grove
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bro i am new here i dont know wht to dooo

lusty token
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consider ((4h)/(px * 78p))/(h/(bb)) instead

fresh wedge
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No worries @vital grove , from next time just paste a screenshot of your original question

vital grove
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ok

vital grove
lusty token
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that's a very odd answer though

vital grove
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Gauth ai is telling that

lusty token
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i doubt it's interpreting it correctly, i don't see why a textbook would give that as an answer

vital grove
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ok then i am going for my school its late now

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i will ask with my teacher

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thank everyone

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.close

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chilly zephyr
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Can somebody explain pythagoras theorem

chilly zephyr
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:/

ocean sealBOT
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wtr.on

chilly zephyr
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Can you help me solve a question

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Ok wait

chilly zephyr
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Idk how to find e value like I found the hypotenuse of the triangle with the values given which is 106

limpid heart
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pythagoras

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a^2 + b^2 = c^2

chilly zephyr
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Arent both the sides the same

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Can you tell the answer I'll understand from it

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Yes

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Idk 😭

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Ohh

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Alright

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Is the answer 9.4

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I don't got a pic but it's like this
4²+e²=106
16+e²=106
e²=106-16
e²=90

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And then you just use square root

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Oh no worries

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Ohh

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Don't we already have the base for thw triangle?

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Ohhh

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Tysm

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Wait what

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Wait wdym

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Alright I understand

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Tysm

lone heartBOT
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orchid gate
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Hey so I have this question right

lone heartBOT
orchid gate
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i multiplied by (a^2-ax) and by 4(a-x)

orchid gate
orchid gate
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from here i got to

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no clue what to do from this point

verbal blaze
fair parcel
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nono

orchid gate
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i just separated the steps of multiplying the denominator

orchid gate
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which idk what I can do with as if i try to root it, then the equation breaks right

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cuz at this point on the second half (xa^2 - ax^2) only the a and x are squared and not the first number

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ie its x*(a^2) - a*(x^2) so i cant root

verbal blaze
orchid gate
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oh

verbal blaze
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you have 4(a+x), not (4a+x)

orchid gate
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yep

orchid gate
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when i have something like xa^2 only the a is squared

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IE i cant connect these two right?

verbal blaze
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or, what would be better is to move them to the LHS of the equation, and get a quadratic ...x^2 + ...x + ... = 0

orchid gate
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a's on their own, squared a's, (same for x's) and ax^2 and xa^2

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which was my question

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they're not interchangeable or are they

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(this specifically: ax^2 and xa^2)

verbal blaze
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pick one, doesn't matter, and make a quadratic in terms of it.#

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e.g. (...) x^2 + (...) x + (...) = 0 for a quadratic in terms of x.

orchid gate
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i understand what you mean but i dont see how it can be done here

orchid gate
verbal blaze
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what do you have when you put all terms on the LHS?

orchid gate
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6 different parameters

verbal blaze
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check the LHS

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the RHS is good

orchid gate
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fixed it

verbal blaze
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yep

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there, you have x^2 terms, x terms, and constant terms.

orchid gate
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right but i still have 5 different parameters

verbal blaze
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so you can refactor it into a quadratic

verbal blaze
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2 terms: ax + bx
1 term: (a+b) x

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you need to refactor it into a quadratic

orchid gate
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I dont know how

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in this specific case

verbal blaze
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what are the x^2 terms?
what are the x terms?
what are the constant terms?

orchid gate
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this is the closest i could get

verbal blaze
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you can reorder the terms

orchid gate
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nevermind, thanks for the help and time though

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much appreciated

verbal blaze
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hint:
ax^2 + 3a + 2x^2 = ax^2 + 2x^2 + 3a = (a+2) x^2 + 3a

orchid gate
lone heartBOT
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wicked tree
lone heartBOT
wicked tree
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So I know I can do x'=concentration(in)rate(in) - concentration(out)rate(out), with concentration(out) equalling x/volume, then plugging in volume from v=volume(initial)+(rate(in)-rate(out))*t

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finding an integration factor, multipling then dividing by it etc etc

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then plugging in x(0) = 0 with the formula I found to find C

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but then, I assume that will give me the formula for the amount of plutonium itself, not its concentration?

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so can I just divide that whole formula by 2000 to get the formula for concentration?

vale crag
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so no you don't just divide by 2000

wicked tree
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so where does 2000 enter the equation?

vale crag
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v=volume(initial)+(rate(in)-rate(out))*t

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what do you think the initial volume of water is

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@wicked tree

wicked tree
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oh well 2000

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but then do I use it anywhere else?

vale crag
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not by itself no

vale crag
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if anything it's x(t)/v(t) whatever the volume ends up being

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and v(t) isn't 2000 for all t

wicked tree
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hmm, so how do I find v(t)?

vale crag
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v=volume(initial)+(rate(in)-rate(out))*t you just wrote the equation right here

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just plug in the numbers

wicked tree
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v=2000+(4-2)t=2000+2t

vale crag
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yeah

wicked tree
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then I do all the integration stuff for x(t) and then divide that by 2000+2t

vale crag
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yes

wicked tree
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I guess that makes sense

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feels weird dividing formulas like that lol

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but alright ill just do that then, thx

vale crag
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you can keep the channel open if you want your work checked afterwards

wicked tree
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aight

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@vale crag idk does this look right

lone heartBOT
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dawn quail
lone heartBOT
dawn quail
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I am confused with row 9 the conditional proof

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It’s saying take the first statement and imply that to the 8th statement

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Why are we allowed to just put an arrow between both statements like that?

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If we are allowed to do that couldn’t we do it at any row? Row 1 implies row 7 for example

lusty token
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so basically, we're assuming statement 1 is true right?

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given that statement 1 is true, we know that statement 8 is true

dawn quail
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Yes we are assuming all statements are true

lusty token
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thus 1 implies 8

dawn quail
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But with that logic can’t we say row 1 implies row 2 implies row 3 etc etc

lusty token
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you can

dawn quail
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Just keep going down in any order and with any statement

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Wth lol

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That’s so weird

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I thought proof is about extracting true statements

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Equivalency is comparing two expressions for being the same

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Each of these rows is a single statement that is true from the original expression

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So any row above can imply any row below?

lusty token
dawn quail
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Hmmm

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So that’s the idea with proof

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Each step is implication

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That’s always how proof works?

lusty token
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pretty much, given premise is true, some statement is true

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if premise isn't true, who cares about the statement

dawn quail
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I thought we are just taking true statements from expression but not necessarily in relationship to one another

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What if we have two expressions using equality?

lusty token
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but assuming this is itself an implication, rather, any result you obtain is implied by the premise

dawn quail
high cargo
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But you’ll learn about that some point later if you haven’t already

dawn quail
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How do you know where to begin with the very first step: assumption

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Just trial and error?

lusty token
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usually given

dawn quail
lusty token
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i don't know where they got the first statement

dawn quail
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Lol

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They explained as working backwards but I don’t see it right away

dawn quail
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Usually you never have to find the assumption? (First step)

lusty token
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it'd be kind of weird to find the assumption?

dawn quail
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This is uni first year discrete math for me btw

lusty token
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cuz you can just assume the result

dawn quail
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Yeah exactly, this example is proving tautology

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Always true

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So maybe that’s why he started at answer and worked backwards for first assumption

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I believe just using de Morgan’s law to go backwards if I’m not mistaken

lusty token
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why would you have to go backwards?

dawn quail
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Just to get the assumption

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Row 1

lusty token
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are you trying to prove biimplication?

dawn quail
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You were saying you don’t know how they got assumption, I’m saying it’s working backwards from answer

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Prove tautology

lusty token
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that doesn't make sense as a proof, they're in order

dawn quail
lusty token
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tautology is a statement that is always true

dawn quail
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They are in order yes, one sec lemme send video

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This will explain it better, how the first step was derived

lusty token
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yup im wrong it's just true

dawn quail
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Row 1

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Do you absolutely need to start there? To show this proof

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Or could you start at a completely different assumption and still get same result in the end

lusty token
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I guess you can just take contrapositive and start with a different assumption if u wanted to

dawn quail
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That’s where I am confused the most. Where or how to find the very first assumption

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Assumption feels like bad idea with math, but i guess I have to remind myself it’s human assumption and only for proof, not Computer assumption

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Computers cannot make assumptions

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(Maybe AI is changing that now tho)

lusty token
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I think I sort of get it

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you're assuming A then proving A implies B, this statement, A implies B is always true, then you can manipulate A implies B and still get a statement that is always true

dawn quail
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Oh because A being true can never imply B to be false

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Is that the idea here?

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So we know with A being true there is only one true statement for B. It also must be true to satisfy implication

lusty token
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assume A is true, then it proves B is true, thus B is true if A true, or A -> B

lusty token
dawn quail
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Contrapositive

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Or material implication

lusty token
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yea, very cool indeed

dawn quail
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We can manipulate until we get it to where we need it

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Kinda crazy

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But also overwhelming if a lot going on

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Trying to find like a needle in a haystack sometimes

lusty token
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for sure

dawn quail
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But at least there are many ways to solve a proof so maybe there are many assumptions that can be made a lot of times too

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Depends on the expression I guess

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Hopefully first year they will not make them super complicated

lusty token
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i think condition proof u just want to get the tautology to an implication cuz then you can make an assumption

dawn quail
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Computers are so much better at this lol, we are like 0.000001 MHz processor single threaded

lusty token
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yea we operate at 10 Hz

dawn quail
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With coffee as our overclock

lusty token
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daily dose of the overclocking juice

dawn quail
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I feel like we are living through the birth of an evolution though… especially with web and AI.. maybe it felt like in the 50s with ENIAC and whatnot too. I know it’s a bit off topic to original question, but dang who know what our clock cycle will be in another 100 years

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Prob the exact same 10 Hz but ā€œriced outā€ as the modding community puts it

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I mean.. single celled organism > fish > monkey > reptile it just makes sense it will keep growing, but it kinda feels like we are on the cusp of speeding up the process from the million year pathways of nature in some ways

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Haha this discrete math has got me thinking all philosophical now, which is what the Greeks were all about, still using their philosophy terms

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Alright I will close this now

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.close

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fleet dagger
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Is it reasonable to assume you can gain a "sense" for trigonometry like you can with other fields of mathematics? I struggle to remember alot of the identities (I am in calculus 2).

fleet dagger
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If anyone has any tips for studying or has an intuitive way to think about trig and its trig functions that would be super appreciated.

remote heron
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most all of the identities can be derived from scratch without too much trouble

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so if you are worried to not remember something, its possible to convince yourself on the fly provided you remember some base identities from which to work

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alternatively there are pretty powerful mnemonics for trig

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for example

fleet dagger
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Which base identities should i try to remember?

remote heron
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pythagorean, sum and difference for sure

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shift identities are obvious and sometimes helpful

fleet dagger
remote heron
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sum and difference gets you very many

fleet dagger
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What about trig derivatives and integrals? Is there any good way to remember those?

remote heron
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honestly that might be all id remember

remote heron
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im sure it exists

fleet dagger
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Ah thats okay, I'll keep looking arround. Thank you!

remote heron
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i think being aware of the techniques is pretty powerful

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like power of sine integrals, power of cosine integrals

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when to use trig sub, inverse trig sub

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etc

fleet dagger
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Power of sine?

remote heron
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im not aware of anything like the magic hexagon though

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yea like $I_n := \int \sin ^n x \dd x$

ocean sealBOT
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jan Niku

fleet dagger
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Ah okay

remote heron
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or sometimes people look at ones like $I_{m,n} := \int \sin ^n (x) \cos ^m (x) \dd x$

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or things like that

ocean sealBOT
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jan Niku

remote heron
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you can sometimes work these out in general

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but just knowing how theyre approached is pretty good IMHo

fleet dagger
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Trig substitution is probably the thing I am struggling with the most right now. Do you have any resources or videos i could watch to help me gain a better intuition when it comes to trig substitution? Practice problems would be great too if you know where I could find some.

remote heron
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I'm in love with this guy, michel van biezen

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here is one of his playlists

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i love his format of short, results focused videos

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but you may find some other format more helpful

fleet dagger
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Hmm okay I'll check out his stuff, thanks.

lone heartBOT
#

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lavish smelt
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I need help figuring this one out please

knotty schooner
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uhh i kinda forgot how this works but

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the filled circle means its closed

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so its more "defined"? meaning you use the [] bracket

lavish smelt
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yes

knotty schooner
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hollow circles are open so it would be ()

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you would go from left to right for domain

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wait

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its whatever was less to more

lavish smelt
knotty schooner
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it works for both pretty sure

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left right, down up

lavish smelt
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yea

knotty schooner
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im kind of rusty but im PRETTY sure you take the highest value for the range in this

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because theres no defined point, you would use )

lavish smelt
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I need to find both the range and domain for this problem

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i would have assumed the domain is (-infi,2]

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but its wrong

sharp trail
# knotty schooner uhh i kinda forgot how this works but

the domain is the lowest to highest points of a line on the horizontal axis
the range is the lowest to highest point of a line on the vertical axis

For this problem.

The line to the left goes towards -x indefinitely while ending at a x of 2 however that is a hole making it (-infiinty, 2)

The range would be [-5, 4] because the lowest value gets to -5 with a close hole therefore inclusive and it goes to 4

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oh shoot i replied to wrong person

knotty schooner
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not 4) ?

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four isnt closed

lavish smelt
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i got the domain correct but the range is not

knotty schooner
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hm

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what did u put for the range

lavish smelt
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[-5,4]

sharp trail
lavish smelt
#

shouldn't it be correct since those are the lowest and highest points?

knotty schooner
#

it should but

#

4 isnt defined

#

as a closed point

#

closed point would mean it literally is 4 on the graph

lavish smelt
#

so it should be 2?

knotty schooner
#

what no

sharp trail
lavish smelt
knotty schooner
#

how did [5,4) not work

#

weird

#

for range?

lavish smelt
sharp trail
#

omg

#

im stupid

lavish smelt
#

im going to need to try another problem now

sharp trail
#

its right

#

its infinite

#

the arrow on the left side of the graph

#

is always going up

knotty schooner
#

oh lol

sharp trail
#

so it can go above the 4

lavish smelt
#

this is the new graph

sharp trail
lavish smelt
#

so domain is (-infi,3)

sharp trail
#

ok

sharp trail
lavish smelt
#

yep its right

#

and range [-5,infi)?

sharp trail
#

nope

sharp trail
lavish smelt
#

open

sharp trail
#

you should use a parantheses

#

because it means

#

it doesnt include the -5

#

it just goes down to -5

#

so (-5, infi)

lavish smelt
#

correct thanks

sharp trail
#

np

lavish smelt
#

this one just broke my brain

sharp trail
#

Basically, look at them as different lines

#

and combine them with U which means union

lavish smelt
#

how do i figure out the interval notation tho?

sharp trail
#

Do you see the red line between the 2 black lines?

#

Thats the asymptote

lavish smelt
#

ok

sharp trail
#

ok

#

so lets focus on the left side of that line

#

for domain

lavish smelt
#

ok

sharp trail
#

where does that line start from

lavish smelt
#

no sure because it seems to be continuous

sharp trail
#

well when it doesnt end. it would mean (-infi

lavish smelt
#

ok

sharp trail
#

most lines approach the asymptote but it never reaches it

#

so its kind of like a open hole

lavish smelt
#

the other end of the line seems to be reaching towards -10 but it isnt for certain

lavish smelt
#

so -2?

sharp trail
#

nop

#

it approaches 0

#

thats where the asymptote is at

#

so it would be

#

(-infinity, 0)

lavish smelt
#

ahhh your right

#

i was thinking of the x-axis

#

so then for the other part of the interval notation i would need to find the range?

sharp trail
#

nope

#

u gotta find the domain

#

of the other line

lavish smelt
#

ah

sharp trail
#

on the left side of the asymptote

#

its like

domain = domain of line U domain of line

lavish smelt
#

didnt we just do the left side and it was (-infi,0)

sharp trail
#

ye

#

so, so far we have domain = (-infi, 0) U ???

#

we gotta find the ??? which is the other part of the domain

lavish smelt
#

the right side of the line

#

?

sharp trail
#

yeah this part now

lavish smelt
#

ok

#

so (0,infi)?

sharp trail
#

it appears so

lavish smelt
#

now i need to find the range of K

sharp trail
#

yep

lavish smelt
#

ahhh ok isee where this is going

sharp trail
lavish smelt
#

yes its correct

sharp trail
#

good

lavish smelt
#

we do lowest to highest or highest to lowest? for range

sharp trail
#

lowest to highest

lavish smelt
#

ok walk me through this

sharp trail
lavish smelt
#

yes

sharp trail
#

where

lavish smelt
#

in the middle

sharp trail
#

nuh uh

lavish smelt
#

the red line im assuming no?

sharp trail
#

thats a vertical asymptote

#

bcs the line is vertical

lavish smelt
#

ok

sharp trail
#

do you see a y value where there wont be an x value

lavish smelt
#

yes i guess based on assumption

#

because i cant scroll down or up on the graph so it cant be for certain

sharp trail
#

true, since it doesnt really say lets say no and make them infinite

lavish smelt
#

ok

sharp trail
#

what is the lowest value, that y can get to

#

if it never ends

lavish smelt
#

maybe -15

#

or is it -infi

#

if it never ends

sharp trail
lavish smelt
#

ok

sharp trail
#

now you know that, whats the highest y value the graph goes up to

lavish smelt
#

also -infi

sharp trail
#

uh no

#

it wouldnt be negative

#

it goes above the x axis

lavish smelt
#

2?

sharp trail
#

no it owuld be infinity

lavish smelt
#

ok

sharp trail
#

think of the whole thing as a one line now

#

bcs there are no vertical asymptotes

lavish smelt
#

ahhh ok

sharp trail
lavish smelt
#

so (-infi,infi)

sharp trail
#

see it goes up forever

sharp trail
lavish smelt
#

yes i got it thanks

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fervent lichen
lone heartBOT
low ermine
#

if i got a question do i sent it here?

fervent lichen
#

You could but now i sent it

#

So you can go for one that is available

low ermine
#

okok

fervent lichen
# fervent lichen

I tried doing it, may anyone tell me if there is anything correct in it

#

Sorry for bad english

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@fervent lichen Has your question been resolved?

fervent lichen
#

Anyone?

lone heartBOT
#

@fervent lichen Has your question been resolved?

fervent lichen
#

😭

#

<@&286206848099549185>

proud zealot
#

the question is from 1962, has math changed since then?

lone heartBOT
#

@fervent lichen Has your question been resolved?

fervent lichen
proud zealot
#

such task cannot be solved by the rules of mathematics that we know today

fervent lichen
#

Why?

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lilac jolt
#

convert the equation of an ellipse into standard form: x^2 + 2x + 100y² - 1000y + 2401 = 0

lilac jolt
#

i have

#

((x+1)²/100) + ((y-5)^2) = 1

#

is that correct

#

$\frac{(x+1)^2}{100} + \frac{(y-5)^2}{1} = 1$

ocean sealBOT
#

sterling

alpine sable
#

you can check if it is correct by simply calculating the squares and simplifying
if the expression you get is the same to the initial expression then is correct
as long you followed the method of completing the square it should be correct

lone heartBOT
#

@lilac jolt Has your question been resolved?

deft ledge
#

you can check if it is correct by simply calculating the squares and simplifying
if the expression you get is the same to the initial expression then is correct
as long you followed the method of completing the square it should be correct

deft ledge
#

And clearly needed to be reiterated

#

Because OP did not read it

alpine sable
#

ok (my english writing is not that bad then lol)

deft ledge
#

No worries, what you said made sense

lone heartBOT
#

@lilac jolt Has your question been resolved?

lilac jolt
#

sorry, I was giving the bot the x reaction so it doesn't close yet ToT

#

but yes, thank you

#

my problem is

#

is that my answer doesn't match the answer of wolfram alpha

#

idk how u use the command for wolfram here

lone heartBOT
#

@lilac jolt Has your question been resolved?

pseudo ice
pseudo ice
#

Put whatever you want after the ,w

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indigo anchor
#

hey lol i need someone to explain the explanation

indigo anchor
#

so i understand the f'(x) = 0 , < 0 , > 0 stuff

#

but from that i dont understand how they got the derivative graph

uneven isle
#

we know the turning point (stationary point), so f'(x) will = 0 at that point

#

we know its decreasing for x<3, so it will be negative gradient = negative in derivative graph

#

we know its increasing for x>3, which is positive gradient = positive in derivative graph

indigo anchor
#

yup

uneven isle
#

as in why its a straight line

#

i think its bad practise for the textbook to not actually include the function since a lot of functions might look parabolic

#

but it seems they just assumed you will treat the graph (a) as a parabola

indigo anchor
#

ahh i think i get that

uneven isle
#

which takes form of ax^2

#

the derivative of that will be a straight line

#

for the second graph

indigo anchor
#

so its increasing after 3 and decreasing before 3

uneven isle
#

yep

indigo anchor
#

ok yeah

#

im just a bit stuck on the single line one

#

ok so its just constantly positive

#

so always above the axis ok i get it

#

thank you

#

.close

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uneven isle
#

if you think about a straight line of the form y=mx+b

#

we know the derivative of gradienti s just m

#

regardless of what value x is

#

so the derivative is constant value

#

which means its just y = m for all values of x for the derivative

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safe vine
#

can anyone help me do simultaneous of these three equations? i can rewrite in terms of a but im not sure how to get rid of the rest of the constants

white marsh
safe vine
#

so take out -a?

#

i did sin(a-b) so theres not much difference

white marsh
#

wdym take out -a

safe vine
#

like

#

factor

white marsh
#

there is no way to factor out anything from these equations

safe vine
#

ok

#

how do i get b and c from this?

#

.close

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devout helm
#

Why is 3150000 the nearest million 3000000

prime badge
#

it's not

#

0 is the nearest million

hushed locust
#

maybe you left out a 0?

prime badge
#

makes sense

devout helm
#

So why is 3000000 the nearest million

hushed locust
#

round to the nearest million means that everything after the millions place should be 0

devout helm
#

So for 2539836000 the nearest million is 254 0000000

hushed locust
#

yes

devout helm
#

Ok thanks bro

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#

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raw jetty
#

is there a polyhydron where its made with 12 triangles and 8 squares that are identical?

raw jetty
#

it came out in an exam yesterday and i want to know whats its called

#

or maybe its 12 squares and 8 triangles idr

#

the thing is, it was named a "cuboctahedron" in the exam but that thing has 8 triangles and 6 squares

white marsh
#

have heard 6 squares and 8 triangles (cuboctahedron). maybe there is some nomenclature that you can name all the polyhedrons I am not sure

raw jetty
#

huh ok i remember copying the drawing and when i looked at it again it was a cuboctahedron, wierd

#

.close maybe my teacher swapped it with verticies and edges

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fossil pelican
#

a

lone heartBOT
lone heartBOT
# fossil pelican a

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

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dusk moth
#

ive been trying to solve this thing where i need to find their intersection points, theres a rule that it cant be negative but it keeps coming out negative on my end.
Had to use only elimination method on this one. what am i doing wrong

ocean whale
#

,rotate

ocean sealBOT
ocean whale
#

I think you misheard something

dusk moth
ocean whale
#

I'm not sure what a decision variable is but you can have negative solutions. The intersection is where the two lines meet, so are you saying that line can only intersect in quadrant 1?

#

Because that's where the values are only positive

dusk moth
#

yes

#

i tried putting it up in desmos to graph it out and it does show negative too

charred jewel
#

!xy

lone heartBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

ocean whale
#

I think you should ask your teacher on what they meant by decision variable

#

Because I'm not sure what that means

#

But you can have negative solutions

#

As I mentioned, the intersection is where the two lines meet, and what you are saying, it's only bounded in quadrant 1 which is not true, it has 3 other quadrants that it can be in

dusk moth
#

yea i might have misunderstood the rules and such. ill redo it maybe it would help

#

Thanks!

#

oh wait im an idiot

#

i messed up the givens

#

its supposed to be 18 and not 8

#

.close

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devout helm
#

Why is this a minimum point plus I need help with qn 5b (ii)

charred jewel
devout helm
#

Positive

charred jewel
#

do you know what a positive quadratic graph looks like?

devout helm
#

No

charred jewel
#

looks something like this

mossy jasper
#

Alternatively, if you don't know the shape of the graph, you can differentiate it twice, if d^2y/dx^2 >0 then you have a minimum

devout helm
charred jewel
#

yes

devout helm
#

Since the curve is at the bottom

mossy jasper
#

if d^2y/dx^2 < 0, you have a maximum, and if it = 0 then it's a POI

devout helm
mossy jasper
# devout helm ?

Okay, so, you know that if you differentiate once, and make it = to 0, you get a stationary point, right?

#

so dy/dx = 0 is a stationary point

devout helm
#

Are you using gradient formula?

mossy jasper
#

No, differentiation, have you not learnt that? If not then yeah I don't know how you're gonna get the 2nd one

devout helm
mossy jasper
#

Honestly, if you haven't learnt it then they probably just expected you to plot the graph

devout helm
mossy jasper
#

Differentiation's got a lot to it, you're better of waiting for once it's taught

mossy jasper
charred jewel
mossy jasper
#

Tbf, it's (x+4)^2 + 12, that can be a lot harder for people to imagine than just x^2, hence plotting can help with that

devout helm
mossy jasper
# charred jewel

no, if it looks like this, it's a minimum, if it looks like the image is flipped upside down, it's a maximum, you probably don't care about POI yet so you can just ignore that for now

devout helm
charred jewel
mossy jasper
#

If I had to put it into words, if you look at the graph from left to right, the minimum is the point at which it goes from going down to going up, and vice versa for maximum

devout helm
mossy jasper
#

wdym by at the right side?

#

Okay, how about this, a minimum point looks like a u, a maximum point looks like an n

devout helm
mossy jasper
#

Yes, and the stationary point is the exact point at which the direction changes

mossy jasper
mossy jasper
mossy jasper
#

The actual graph of y = (x+4)^2 + 12 is pretty similar to x^2, which, as they showed, x^2 has a minimum

charred jewel
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ember mango
#

any hint to answer this?

lone heartBOT
tight pier
#

to its length

ember mango
tight pier
#

ok good

ember mango
#

so r^2=length^2-h^2

subtle light
#

and if it’s an equilateral triangle

#

what would length be?

tight pier
#

thanks for asking

ember mango
#

equilateral meaning same side length?

subtle light
#

yep

tight pier
#

comon alan you got this almost

ember mango
#

r^2=h^2-(2r)^2 ?

subtle light
#

bingo

subtle light
#

just rearrange and solve for r^2 and you should be fine

ember mango
#

hmm not sure why its wrong

tight pier
#

you need to solve for r^2

ember mango
#

r^2=1/3*h^2

#

thanks guys it was correct!

tight pier
#

nice work

ember mango
#

.close

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ember mango
lone heartBOT
ember mango
#

my attempt

verbal blaze
#

what's the formula for the area under the ladder?

ember mango
verbal blaze
#

not 2-x

#

remember pythagoras

lone heartBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #ā“how-to-get-help for instructions).

tight pier
#

ok bro

left isle
#

my bad

tight pier
#

šŸ˜‚

ember mango
verbal blaze
#

yep

#

Now, the question is asking you to find the rate of chage in A wrt t, knowing the rate of change in x wrt t.

ocean sealBOT
tight pier
#

why would you use partials btw

verbal blaze
#

just habit

#

because, if A is a multivariate function, then you need partial derivatives

#

makes no difference in your particular case, where A only depends on x

tight pier
#

I see A = A(x(t)) but sure

ember mango
tight pier
ember mango
tight pier
ember mango
tight pier
#

no

#

x = x(t)

ember mango
#

sry what deos x(t) mean?

tight pier
#

the distance x depends on time t

#

I think x = 1

#

Basically dA/dt denotes the change in area when x = 1 I think

ember mango
#

yea you are right

tight pier
#

and now i am up

ember mango
#

.close

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wispy nebula
#

I'm doing basic fluid dynamics and I struggle to plot streamfunctions when they are in polar coordinates. For example:

wispy nebula
#

$r = \frac{\psi}{Usin\theta}$

ocean sealBOT
#

trayan_b

wispy nebula
#

Psi and U can be anything

#

I need to plot the whole family of functions

#

But I notice there's gonna be singularities because of the denominator

#

Also why is there no fluid dynamics channel?

#

even if you could help me plot $\frac{1}{sin\theta}$ it would be helpful

ocean sealBOT
#

trayan_b

zealous ingot
#

first identify the areas where 1/sin(theta) is not defined, i.e. when sin(theta)=0

lost badger
zealous ingot
#

those give you the vertical asymptotes

lavish cave
# ocean seal **trayan\_b**

if you want to plot $r = \frac{k}{\sin \theta}$, just note that $r \sin \theta = k$

so $y = k$

and $k = \frac{\psi}{U}$ in your case

ocean sealBOT
#

higher's secret twin brother

lavish cave
#

(r cos theta, r sin theta) if you scale everything here by a factor of r

#

and yes this is undefined for sin theta = 0 or when theta = k pi, k is an integer

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#

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smoky river
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I need help creating a quantitative death curve for wolfs.
For context I am working on a project to model the wolfpopulation in Europe. With different sources I found useful information, such as the lifespan, and so also my domain [0,13].
What I need for the deathcurve is that the area under the curve equals 1(, or is approximately equal) as logically speaking eventually every individual dies once.
Now the difficult part, I want the distribution to begin at a value somewhere between 0 and 1, than at x=6 half of the population died. The minimum shoudl be somewhere between x=0 and x=6, here the wolf is independent and can survive.
I found a graph of this sort for humans in a work from Murray (2011), I added a screenshot of this graph.

Now finally my question, what kind of equation or distribution can I use to create my deathcurve, which has the form of the graph in the screenshot?

lone heartBOT
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@smoky river Has your question been resolved?

smoky river
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<@&286206848099549185>

lone heartBOT
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@smoky river Has your question been resolved?

tired sail
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Hello everyone who can help me

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Please solve me this exercise

smoky river
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Wrong chat my friend

lone heartBOT
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@smoky river Has your question been resolved?

alpine sable
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anyone knows about basic logical functions?

rugged schooner
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hello

alpine sable
smoky river
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<@&286206848099549185>

lone heartBOT
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@smoky river Has your question been resolved?

lone heartBOT
#
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#
Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #ā“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lapis pelican
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what is 19 * 2

lone heartBOT
lapis pelican
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i got 15

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@cedar kelp

cedar kelp
lapis pelican
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how

cedar kelp
lapis pelican
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bruh why

mint flare
cedar kelp
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it also has some rules

lapis pelican
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ok

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i understand

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so i just wait

cedar kelp
mint flare
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ok

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how do you get the helper role

cedar kelp
lapis pelican
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but my algebra teacher said it was wrong

cedar kelp
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,w 19*2

ocean sealBOT
lapis pelican
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i think i might need albert enstain for dis one

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oh

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nvm

cedar kelp
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,calc 19*2

ocean sealBOT
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Result:

38
lapis pelican
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how did you get 38

cedar kelp
cedar kelp
lapis pelican
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my math teacher said to not use calculators or its ceating

cedar kelp
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19*2 is 19 added to itself 2 times

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so 19+19

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=38

lapis pelican
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ok but why

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like i need a proof for it

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or smt

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smth

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hold on

cedar kelp
lapis pelican
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ill post a screen shot of the question

lone heartBOT
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@lapis pelican Has your question been resolved?

lapis pelican
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wait

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here is the problem

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this shit hard af

lapis pelican
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<@&286206848099549185>

lone heartBOT
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@lapis pelican Has your question been resolved?

lapis pelican
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<@&286206848099549185> i need help

lone heartBOT
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@lapis pelican Has your question been resolved?

lone heartBOT
#

@lapis pelican Has your question been resolved?

lone heartBOT
#

@lapis pelican Has your question been resolved?

lone heartBOT
#
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Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #ā“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

spring dawn
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Help me in precal I forgot how to solve quadratic equation

spring dawn
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Wait lemme take a pic of it

manic wyvern
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You can use the quadratic formula

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Or like complete the square

spring dawn
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Anyways it's linear equation

manic wyvern
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Can you send the pic I'll take a look

spring dawn
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Here

alpine sable
spring dawn
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So basically quadratic formula it will be written as this wait lemme write it

alpine sable
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where are you confused

spring dawn
alpine sable
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let me see

spring dawn
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Our teacher made us solve it by quadratic since we thought it wasn't factorable

alpine sable
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ig no

spring dawn
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And I forgor how to solve quadratic equations

alpine sable
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wait i ll show you

spring dawn
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Thank you!

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And also how to write it in quadratic formula... Like which number do I put... Is it the 3, 2 or -17

alpine sable
spring dawn
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Oki thank you

alpine sable
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if you forgot

spring dawn
alpine sable
spring dawn
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Oh okay

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Then we solve the ones inside the radical first right?

alpine sable
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yes

x = -b/2a +- root(D)/2a

alpine sable
spring dawn
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Yeah

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Ah wait no

alpine sable
spring dawn
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Thank you šŸ˜

spring dawn
alpine sable
alpine sable
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using perfect square

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(x+a)^2 identity

spring dawn
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Oh

alpine sable
spring dawn
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Looks complicated but familiar I think we did this before

spring dawn
alpine sable
alpine sable
spring dawn
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Will the answer be the same w quadratic?

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Can you teach me that one too?

alpine sable
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see above

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i derived quadratic formula using perfect square method only

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lol

alpine sable
spring dawn
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I am confused 😭

alpine sable
spring dawn
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Oh

spring dawn
# alpine sable where

Can you just help me solve quadratic equation first then I'll try doing the perfect square method after

alpine sable
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see

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and below is the one for general terms, a,b,c

spring dawn
alpine sable
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theyre all mutliplied bro

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you can solve in any order

spring dawn
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Oh okay lol

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Okay what now?

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Wait lemme take a pic

alpine sable
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solved?

spring dawn
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Since idk what to do here

alpine sable
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shhow

spring dawn
alpine sable
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show

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yes

spring dawn
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Idk what to do next 🄲

alpine sable
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a+-b = a+b or a-b

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so

spring dawn
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Oki

alpine sable
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(-1+2root(13))/3 is one ans

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other is -1-2root(13) / 3

spring dawn
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I don't get how you got that answer šŸ’€

spring dawn
proven depot
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plus or minus symbol

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either plus or minus

spring dawn
alpine sable
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explain clearly bro

proven depot
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-2/6

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and4sqrt(13)/6

spring dawn
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Oh

proven depot
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splitting them because denominator is the same

spring dawn
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Okay

proven depot
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and then you can merge those both

spring dawn
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Ok thanks

alpine sable
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hopefully

spring dawn
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.close

lone heartBOT
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Channel closed

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lone heartBOT
#
Available help channel!

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stuck otter
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Hi guys, have a big question abt this mathematical problem, dont rly know to witch kind of math capitol it suppouse to fit.
So the problem is: in isolated square or rectangle by size m*x meters and lays only on x,y axis, on this x,y axis somewhere is a satelite (cant be in a corner), witch can move inside of this area and bounce from "walls", also size of satelit is matter and angel "a" is in range (0deg, equal or bigger then "a" < 360 deg.)
and here is to quesions what i have left with
1.
We have a specified maximum distance D that the satellite can travel. Depending on D, determine
how many different pairs of (d, α) exist, where d ≤ D denotes the distance traveled by the satellite and α
the angle at which it starts to move, such that the satellite stops exactly in one of the corners
rectangle?
2. We have specified the maximum number of satellite reflections N . Let's assume that the reflection by the corner of the rectangle counts
for two bounces. How many different pairs of (n, α) exist, where n ≤ N denotes the number of satellite reflections
o the edge of the rectangle and α the angle at which it starts to move, such that the satellite moves exactly n
will the reflections stop just at the corner of the rectangle?

I will be glad for any help or tip/trick how to get what i need to do.
Thanks ā¤ļø

trim plinth
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didn't the other person tell you a trick already?