help-0

[prime badge]

yeah

[tiny sky]

mb i can't read lol

[prime badge]

i thought exactly the same before reading properly

[charred cloud]

can u explain why

[prime badge]

that's just what it means, if they are distinguishable
there's dice 1,2 and 3, you put them in order 1-2-3, and only then it counts as a match

[charred cloud]

mhm

[prime badge]

you can divide 216 by 46656, nothing wrong with that

[charred cloud]

how did u land at 6^3

cos theres 6 options for first,second and 3rd

so 666?

[prime badge]

yes

for part b i would divide by 46656 as well
one pair has 90 possibilities

(6×5) × 3

giving 90×90 outcomes

[charred cloud]

no but since

in part a

me and my friend have a slight doubt

we're only expecting numbers even though theyre distinguishable right

so example:
[assume each colour corresponds to the die roll]

4,3,1(r,gb) is also the same as 4,3,1[g,b,r]

i get what ur saying but i kinda get what hes saying too

im just hella lost now

[prime badge]

that's what i expect b to mean

yes, it's all confusing

[charred cloud]

but if theyre indistinguishable( identical)

how are there 6^6 total possible outcomes

[prime badge]

like in real life, if you throw two indistinguishable dice, they have double the chance to show 1,2 compared to 2,2

idk how to explain

if you intepret it in a way where those have the same probability, this means you;re throwing some magical dice that don;t behave normally

and i can;t say for certain they don't expect the magical answer

but usually they don't

[charred cloud]

hm

i see

tysm

[prime badge]

so i'm interpreting it like the dice still roll one of 46656 outcomes equally likely, you treat 2,1,2 and 2,2,1 as the same, but the dice don't

[charred cloud]

yeah im guessing thats what my friend meant too

why is (a) 1/6^3 again

[prime badge]

i don't know

there's 216 outcomes because each dice rolls one of 6 numbers

we can tell them all apart

so there's no complicaited stuff

[charred cloud]

my friend asked this

[charred cloud]

yeah alright

he was so ready to prove chung and keller wrong

[prime badge]

it's the wording of the quesiotn that's the problem

[charred cloud]

yeah thats what he said too

tysm for helping

[prime badge]

it says same numbers, so, you could even expect it to mean stuff like 1,1,1

[charred cloud]

mhm

[lone heart]

@charred cloud Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torpid dirge]

why cant H int K be 6?

[keen plinth]

its a subgroup of H and K which are sylow

[torpid dirge]

hi snow

[torpid dirge]

so what does that say about the intersection of the groups

[keen plinth]

its cardinality is a power of 2

[torpid dirge]

how did we get that

[keen plinth]

H is sylow

[torpid dirge]

:(

elab more

[keen plinth]

|H| = 2^n

[torpid dirge]

yes

in this case 2^4

[torpid dirge]

no i mean, why does this say the intersection has to be 8

or why does the intersection have to be a power of 2

[keen plinth]

because H \cap K is a subgroup of H

[torpid dirge]

OH yea

intersection is a subgroup of H

thanks

.close

[lone heart]

Channel closed

Closed by @torpid dirge

Use .reopen if this was a mistake.

[torpid dirge]

nocap

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[full crystal]

How to do 19 and 20

[lone heart]

@full crystal Has your question been resolved?

[charred pilot]

How would you start

Talking about 19

[full crystal]

Find g(x) is usually how I start

but

It’s already found

So I would probably start by subtracting them in the same equation

[charred pilot]

It’s asking about the domain for f + g, start with adding together function f and function g

[full crystal]

Oh yeah I’m looking at the top

lol

Wouldn’t that just be 5x-5+(4/x+6) ?

[charred pilot]

Yes

But combine the terms for sake of simplicity

[full crystal]

You can’t unless we destroy the fraction

[charred pilot]

Just put it all into 1 big fraction

So ((5x-5)(x+6)+4)/(x+6)

[full crystal]

So we put f(x) +4 all over x+6?

[charred pilot]

Yes

But f is multiplied by x+6

That’s how we can combine the two

The question is asking for domain, do you know what that is?

[full crystal]

The x value

[charred pilot]

But what is it graphically

What does it mean for x to belong to all reals or for it not to?

[full crystal]

it’s not when it’s in a denominator

it is in almost every other instance

[charred pilot]

I’m not talking about the function itself I mean on a graph

Look at the option choices

[full crystal]

It’s c

[charred pilot]

How would the graph be different from each of those

[full crystal]

cuz it can’t be -6

Because that would make the denominator 0

which it cannot be

right?

[charred pilot]

And why not

[full crystal]

Cuz anything divided by zed is undefined

[charred pilot]

Yes

So C is the answer

[full crystal]

but how does it look like in the beginning

when u combine

can u show

[charred pilot]

You mean f + g?

((5x-5)(x+6)+4)/(x+6)

$\frac{(5x-5)(x+6)+4}{x+6}$

[ocean seal]

mari

[full crystal]

yeah that

where did the x+6 come from

[charred pilot]

In the numerator?

[full crystal]

Yah

[charred pilot]

Fractions combine over the same denominator

So I multiplied the f function by x+6 over x+6

[full crystal]

why what

[charred pilot]

Why which part

[full crystal]

(x+6) on top

I don’t get why you combine

[charred pilot]

$(5x-5) + \frac{4}{x+6} = (5x-5) \cdot \frac{x+6}{x+6} + \frac{4}{x+6} $

This is what I did

For the function f

[full crystal]

Why

[charred pilot]

So that it has x+6 as a denominator

To combine with function g

[full crystal]

What happens to the 4

[charred pilot]

Nothing

Unless you simplify the numerator

But you don’t have to

Here’s the whole f + g

[full crystal]

why is there 2 now

[charred pilot]

That’s f + g

[full crystal]

2 denominators of x+6

[charred pilot]

Because that’s before I combined them

[full crystal]

You split?

[charred pilot]

no

The left term is f

The right term is g

I am adding them

[full crystal]

Yeah but how did x+6 come out

and be over itself

And why did the 4 seperate

[charred pilot]

What do you mean x+g?

Nothing separated

[full crystal]

I meant x+6

how did that come out of nowhere and seperate into that over itself and 4 over x+6

[charred pilot]

Nothing separated

The right term is g

That’s just what g is, 4/x+6

[full crystal]

How

I just don’t get the x+6/x+6

[charred pilot]

$(5x-5) + \frac{4}{x+6} = (5x-5) \cdot \frac{x+6}{x+6} + \frac{4}{x+6}$

[ocean seal]

mari

[charred pilot]

A/A = 1

So I am just multiplying by 1

To rearrange

[full crystal]

I guess

[charred pilot]

no guessing

That’s what I am doing

[full crystal]

I know but I guess that’s how it works

I don’t see the logic

Moving into 20

[charred pilot]

Sorry I can’t help right now

[full crystal]

Sorry I have a girlfriend

[charred pilot]

@tacit arch

[tacit arch]

wassup homie

[charred pilot]

I’m sending you out

Residential math virtuoso

[lone heart]

@full crystal Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wet turret]

Hey guys. Im trying to get ahead of everyone in my Algebra 2 class by doing my teachers calculus problems but the problem is... I dont know anything about calculus. Can somebody help me out and maybe help me understand it all?

[livid sage]

to understand integration by parts, one should probably first understand integration;
to understand integration; one should probably first understand differentiation;
to understand differentiation, one should probably first understand limits; etc (list not fully inclusive)

i believe you are missing some requisites to be doing this

try looking at math on khan academy to get a feel for how math curriculum is structured

[neat folio]

khan academy and other sources can help build fundamentals

but I definitely recommend having a very solid understanding of algebra and differentiation before going to integration

[wet turret]

I see

So you guys recommend i do a bit on khan academy before i get to advanced stuff like this

[wet turret]

How hard are these topics to learn? And how long will it take me to learn all these things

[livid sage]

idk see for yourself

as far as I’m concerned math education before late uni level isn’t something that needs a standard attached to it

[wet turret]

I see

[lone heart]

@wet turret Has your question been resolved?

Channel closed

Closed by @wet turret

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fleet grove]

tan^-1 root3= 1/3pie

tan repeates every pie

so i tried adding and taking way pie from 1/3pie

but thats grater than the window

.close

[lone heart]

Channel closed

Closed by @fleet grove

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[novel remnant]

Where did the *8 come from??

[novel remnant]

The chain rule the newton one says to multiply by the derivative of the inner function

The derivative of sin(8x) is cos(8x)

So why is there a times 8

[ocean whale]

Derivative of the inside of this

[neat folio]

derivative of sin(8x) is 8cos(8x)

given by the g'(x) in the chain rule

[ocean whale]

You need to find the derivative of 8x as well

[novel remnant]

Why do you touch that?

So the derivative of sin(7) is cos()?

I thought you don’t touch what’s inside the parentheses cuz it’s being calculated by the trig function

And the derivative of sin(x) is cos(1)?

Ohh wait these are three functions??

[ocean whale]

No because that's just a constant

sin(7) is a constant

[novel remnant]

How tho

It’s a function

[ocean whale]

No it's not

A function takes an input

[novel remnant]

Isn’t sin a trig function

[ocean whale]

That's just a value

[novel remnant]

Wdym🥲

[ocean whale]

sin(7) is just a number

It's not a function

[novel remnant]

So when is it a function

[ocean whale]

When there's a variable

[novel remnant]

Ohhh

[novel remnant]

So this is true then?

[ocean whale]

No

[novel remnant]

There is a variable

[ocean whale]

If you wanted to apply chain rule to that, which you don't need to do; the outside is sin, the inside is x

So derivative of outside, keep the inside, times by the derivative of the inside is chain rule

[novel remnant]

So why do we not apply it in my question??

I don’t see the difference between all of these🫠

Why does sin become cos

[ocean whale]

Because what's the derivative of sin?

[novel remnant]

But you just said not to take it

[ocean whale]

I never said that

[novel remnant]

You said it’s sin and keep the value inside

Then multiply by the derivative of the value inside

[ocean whale]

I said doing chain rule on sin(x) is not needed

[novel remnant]

But this is also chain rule

There are three chain rules

[ocean whale]

No

[novel remnant]

Our professor said that today

[ocean whale]

Probably 3 different forms

[novel remnant]

Yes^ one complicated one simple and one for 3+ functions

[novel remnant]

This is the second one

[ocean whale]

It's all the same process, your professor said there are 3 because the complicated and the one for 3+ functions is built off of the simple

[novel remnant]

Ohh I see

Well for this question I don’t see why we have to take the derivative twice,
Cuz the outer is ()^-4
And inner is 1+sin(8x)

So one derivative for outer
-4()^-5

And one derivative for inner
1+cos(8x)

Why do we take the derivative of the inner function again

[simple wigeon]

think abt the graphs of the sine and cosine

[novel remnant]

I didn’t mean it that way

[simple wigeon]

what way did u mean it

[novel remnant]

I didn’t mean it like why I meant why specifically there cuz if sin(x) doesn’t become cos(1) why does it for sin(8x)

Becoming cos(8x)

[simple wigeon]

bc you can’t just plug in 1

the x is the input

and you don’t need to take the derivative of that input

you can put cos(1) in ur calculator and get a number

[novel remnant]

That’s what I was saying!

[simple wigeon]

you cannot put cosx in and get a number

bc it’s a function

[novel remnant]

That’s my original question

[simple wigeon]

no but ur still chaining lol just don’t convert to cos(1)

[novel remnant]

“You don’t have to take the derivative of that input”

Yet they took the derivative of the input

8x

[simple wigeon]

bc that’s chain rule

u can’t leave 8x in there

[novel remnant]

But we already applied it

[simple wigeon]

and that’s why there’s an 8

[simple wigeon]

u keep going

until all chains are complete

[novel remnant]

So these are 3 functions?

[simple wigeon]

well

no

it’s 1 function

[novel remnant]

So why are there 3 chains

[simple wigeon]

y=

[novel remnant]

I meant outer and inner wise

[simple wigeon]

bc you have the derivative from the power rule -4(1+sin(8x))^-5 and you have an input still (1+sin(8x)) so u take the derivative of that

which is cos(8x)

and then the derivative of 8x

[novel remnant]

So it is 3 functions

[simple wigeon]

which is just

8

[simple wigeon]

no…. it’s the 1st derivative of one function

[novel remnant]

But you separate them for the chain rule that’s what we were taught today

Like (3x+2)^3

[simple wigeon]

yes you do separate but you’re not creating diff functions you’re taking the derivative of the chains

[novel remnant]

Outer function is ()^3
Inner function is 3x+2

[simple wigeon]

you don’t just make up a function they give u it

[novel remnant]

I know I’m just asking to understand

Are there “three” functions in this one

Is that why we keep going with the chain

[simple wigeon]

i guess yes you can think of it like that

but don’t separate them into 3 functions

bc it’s still just 1

[novel remnant]

I see so that’s what I was looking at wrong

There is
outer inner inner
Then
Outer inner
Then
Inner

In this one

[simple wigeon]

yes

and you’re just taking the derivatives of the “inner” until satisfied

[novel remnant]

I see that’s what I didn’t notice

Until there are no more inner ones right?

I see it now, thank you🥲🥲

[lone heart]

@novel remnant Has your question been resolved?

Channel closed

Closed by @novel remnant

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silent mason]

Can anyone tell me what I'm doing wrong for the part c?

[silent mason]

the graph of f is supposed to be concave up when f''(x) > 0 and concave down when f''(x) < 0

[neat folio]

what was your f'(x) and f''(x)?

[neat folio]

so just question C?

[silent mason]

Yes, that's what I'm getting wrong

[neat folio]

well for question C the method would be to take your stationary points and find the second derivative to determine concavity

[silent mason]

from my calculations, f''(x) is positive in the interval (-infinity, 1) and negative on the interval (1, inifnity)

[silent mason]

that's what I think I did here, right?

If you look at the first notebook image I sent?

[neat folio]

isn't f''(x) -6x+2?

[silent mason]

yes

[neat folio]

so concavity would change at x = 1/3

from increasing to decreasing

[silent mason]

so, from positive to negative?

[neat folio]

yes

[silent mason]

oh you're right

[neat folio]

that should give you your intervals

[silent mason]

so, you solved f''(x) = 0?

yes, that did

[neat folio]

for the intervals yes

[silent mason]

got it

[neat folio]

and then based on the function you can determine whether it increases or decreases depending on which side

[silent mason]

wow, how did I totally miss that?

thank you so much

[neat folio]

np

[lone heart]

@silent mason Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[chrome isle]

last 2 questions, pls show steps on how to (preferably write them down and then send a photo so i can understand easier). because idk how to do the formula for that one 😭

[chrome isle]

also ping when able to help

[void swift]

try factoring

[chrome isle]

im.. not really sure how to do that

[void swift]

thats what u did for the 2 questions above them tho?

u factored the x out

[chrome isle]

that was mostly photomath ima be fr 😭i tried doing them myself and i couldnt figure out how to factor or, even remotely solve the equations.

[void swift]

well that is problematic

do u know/understand what factoring is?

[chrome isle]

is it where you find the gcf?

[reef hull]

its were you take out a common number

so yeah

[reef hull]

you find and take out the gcf

[void swift]

it doesnt always have to be the gcf just whatevers convenient

[reef hull]

yeah true

[chrome isle]

but how do you find the gcf of a variable

[void swift]

in ur photomathed answer u see that they factored out the x

cuz its a common term

like with x^2 and 5x, u can tell that they both share x as a common factor

[chrome isle]

ohhh

[void swift]

and when u write it as x(x-5) u can easily see what x has to be for the whole thing to equal 0

try it out with question 3 if u can

[reef hull]

you can also do quadratics to get the answers to this problem

@chrome isle there is a eiser way

[void swift]

theres no +c so i think factoring is easier than quadratic formula

[reef hull]

no like

you can bring all the terms to the same side

and then its x(x +2)

[void swift]

isnt this just factoring

[chrome isle]

?

[reef hull]

oh true..

[reef hull]

its -2

i think

because its x (x + 2)

[chrome isle]

i thoufht since (2-2) is 0 itd be just 2

since, 0+(2-2)=0

[void swift]

when ur moving -2x to the other side u flip signs

[reef hull]

this should be +2

[chrome isle]

ohhh

okay

[reef hull]

yeah

the next question is the same thing

[chrome isle]

what about 4? that adds 12x, would it just be factoring

like

3 is the gcf of 13 and 3

[reef hull]

yeah so if you move it all to the same side

you get 3x^2 - 12x = 0

right?

so you can factor out 3x

[chrome isle]

idk im just having a lot of trouble when it comes to what exactly factoring is, like i believe i know how to set up the stuff its just

my brain isnt processing what factoring means i guess

[reef hull]

ok

[chrome isle]

i have the equation set up, but i do not know where to go from there

[reef hull]

so factoring means finding the terms that are multiplied together to get an expression

[reef hull]

alright

show the equation

[reef hull]

Alright, good

so whats the same in both of 3x^2 and 12x?

[chrome isle]

uhhhhh

theres an x in both of them?

[reef hull]

yeah

[void swift]

good job, what else

[reef hull]

what else?

@chrome isle its a number

[chrome isle]

3x4 equals 12, and 3x1 is 3 so would it be 3?

[reef hull]

yeah

so you can take out (factor out) 3x right?

[chrome isle]

OH WAIT

SO IT WOULD BE LIKE

4 and 1 used?

[reef hull]

yeah

so you would get 3x(x-4) right?

[chrome isle]

yeah i got that

i got confused on the ^2 for a second my bad 😭

would that be it?

or is there another step to it

[reef hull]

yeah i think thats the answer

oh wait no

my bad

i reread the question

3x(x-4) = 0

[chrome isle]

oooh okay

[reef hull]

yeah

can you solve from there?

[chrome isle]

i think so!

[reef hull]

ok, good luck!

[chrome isle]

i got it ^_^

thank you both so much

.close

[lone heart]

Channel closed

Closed by @chrome isle

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

have no idea how to start

[barren bolt]

Ok I’m sorry but your teacher did tell you how to start

Essentially you want to use induction on n

What happens in the base case start there

What do you get when n=1

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

the set become {1,2}
A1 = {1} & B1 = {2}

right?

[barren bolt]

Yeah

That’s the base case technically you need to show that it also satisfies the equation

But it does because i can only be 0 when n=1

Now for the induction step you have assumed that the premise is true for n and you need to then prove it for n+1

The question provides you with the constructions on An+1 and Bn+1

So all you have to do is prove that they satisfy the requirements

Those being that they are disjoint, they partition the original set ( A u B is the whole set ) and the equation of sums for each and every i = 0,1,…, n

[alpine sable]

im a little new to this math do u think u can explain it all a little bit simpler? sorry in advance

[barren bolt]

Ok so the first step is to make clear your induction hypothesis, this it what you will take to be true at the nth step and you need to to use it to show the n+1 step satisfies the properties. The induction hypothesis in this case is that An and Bn partition the original set in such a way that for all $$i \in {1,2,…n-1}$$ we have $$\sum_{a\in A_n} a^i = \sum_{b\in B_n} b^i $$

[ocean seal]

llspacebarll

[barren bolt]

This is the facts that you take as true

What you need to prove is that $A_{n+1}$ and $B_{n+1}$ satisfy the same conditions

[ocean seal]

llspacebarll

[barren bolt]

Namely that they partition the set {0,1,2,…,2^(n+1) - 1, 2^(n+1)}

That means they are disjoint but their union is the whole set

And finally that they satisfy the same equality above but with n+1 in place of n

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

@barren bolt im sorry can we start from base case, i read everything but i dont think im computing it properly

from my understanding, for n=1 we have the set {1, 1, 2}

how does this set get seperated into A = {1} and B = {2}?

[barren bolt]

A set doesn’t have duplicate entries

[alpine sable]

oh that makes sense

so the set rather becomes {1,2} and separates to A = {1} and B = {2}

but if we plug in these values for i=1 for the base case, wouldnt i get 1=2 meaning it doesnt hold?

[barren bolt]

No n = 1

Notice that i only goes up to n-1

[alpine sable]

ohhh so that means i would use 0 instead for i? getting 1 = 1?

[barren bolt]

Yeah

[alpine sable]

ok i understand the base case now

i understand the hypothesis to as well can u explain the induction step a little more please @barren bolt

[barren bolt]

Bedtime I’m sorry 😢

[alpine sable]

ok thats fine, do u think u can help me tommorrow or in dms?

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

whats 1/x the derivative to?

[alpine sable]

like d/dx of a value gives 1/x. whats that value

[ionic jewel]

ln(x) +C

[ionic jewel]

the question is "what is the integral of 1/x" if you wish to Google this (also called antiderivative)

[alpine sable]

oh

thanks

why is it the absolute value

i googled it

you said it was ln x

[pseudo ice]

Well, if x is positive, you get ln(x) differentiating to 1/x, but if x is negative, then -x is positive, and ln(-x) differentiates to (-1)/(-x) = 1/x

[lone heart]

@alpine sable Has your question been resolved?

[ionic jewel]

ln(x) is often written with the assumption that x > 0

but the abs answer is the correct one for all x

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

question a

Please help@

<@&286206848099549185>

Hey, could I have some help?

Please, I have no clue what to do.

[opal jolt]

!occupied

[lone heart]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[sonic reef]

open ur channel and i can help u

[alpine sable]

How do I do that?

I’m lost on how to open one.

[sonic reef]

check what said the bot just on the top #❓how-to-get-help

go there you'll see

[alpine sable]

I did read all of that.

Wait..

I’ll read it again.

I’m still figuring it out.

[sonic reef]

the thing here is to find out how you get a rectangle shape's perimeter of 500m

then you divide it by 4 and find when the area is the highest with pic a ou b

[alpine sable]

wait

when it says find each

what does it mean by each?

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fleet river]

How do i calculate sin or cos from tan?

[alpine sable]

sine over cosine

well

tan x = sin x / cos x

you can find out sin and cos

if u know value of tan and cos and sine respectively

[raw jetty]

(alternative) assuming you know tan and want to find sin and cos, draw a triangle

[alpine sable]

^

lots of alternatives. depends what you wanna do

[lone heart]

@fleet river Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[visual merlin]

Hello

[visual merlin]

Any idea how I can solve this?

It was from my book, I just wrote it on a small sheet of paper to solve it nearby (to avoid mistakes on my homework sheet)

I thought of using u = x+1 substitution but I havent found out how to simplified after

I just end up with a quartic eq. divided by u^4

[dusty zodiac]

I would tackle it by doing first cross multiplication

Then I would expand using binomial theorem

[visual merlin]

Smart

Wait

[dusty zodiac]

and collect tham all on one side, and see where I end up, either you'll be lucky and stuff will cancel out, or you'll end up with some equation and after that you can look to substitue

to solve the equation

or factorise

[visual merlin]

Havent done cross substitution since 6th grade lol

[dusty zodiac]

Yea, so begin with that, then expand the one with the exponent of 4 using binomal theorem

gather all the x together, and from there you can explore what to do

either you substitute the variable to solve equation, or maybe stuff cancel, or you would have to do long division

by guessing a root and doing long division to factorise this equation

if that makes sense

like, it all depends from how the equation ends up looking like after you've expanded

[visual merlin]

A symmetric quartic equation

W

Multiply by -1 and divide by x² innit

[fleet river]

Can you give me an answer for tan=0.5?

[dusty zodiac]

hmm, you won't get a pretty solution

dividing by x^2

I would personally just guess roots at this point

And then divide by that factor

until you get it fully factorised

[granite kelp]

what channel should i go to if i want help with an exercise?

[dusty zodiac]

look at the ''how to get help'' channel

[visual merlin]

Divide by x², sort it out like that, substitute x + 1/x = u

You get a quadratic for u

[dusty zodiac]

Good job

[visual merlin]

Thanks

[dusty zodiac]

I didn't see it initially

[visual merlin]

I'll just quickly solve it and check it

[dusty zodiac]

throw in the equation into some online calculator

to check so that the roots are true

after you're done

[visual merlin]

Yes

[dusty zodiac]

so you can confirm if you've done it correctly

[lone heart]

@visual merlin Has your question been resolved?

[visual merlin]

@dusty zodiac Sorry took me too much time (I miscalculated 8×4 in my head and got messed up)

But yes it works

Solutions apply

Thanks for helping

.close

[lone heart]

Channel closed

Closed by @visual merlin

Use .reopen if this was a mistake.

[alpine sable]

someone help

[mossy jasper]

@alpine sable !1c

!1c

[lone heart]

Please stick to your channel.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uneven isle]

hi

[uneven isle]

im not really sure where to start, context is highschool math if that matters

i would appreciate a hint rather than full solution but any advice is still appreciated 🙏

[uneven isle]

<@&286206848099549185>

ive tried messing with geometric ideas but that didnt lead me anywhere

[solar narwhal]

You know that arccot(x) = arctan(1/x) ?

[uneven isle]

yep

[solar narwhal]

Use that on the LHS

Now

What do you have in LHS?

[uneven isle]

arctan(1/1-x+x^2)

im assuming u are asking for something else hto

[solar narwhal]

Yeah

[solar narwhal]

No

[uneven isle]

oh

i realise

its compound angle inside

[solar narwhal]

.

[solar narwhal]

Yeah

[uneven isle]

thats tech

because x and 1-x cancels the x out

[solar narwhal]

Yeah

Do that

[uneven isle]

i just get integrating dx then no?

[solar narwhal]

No?

It's

[uneven isle]

does lhs not turn into arctan(tan(x+(1-x))

[solar narwhal]

No

?

It's
Arctan( Tan( Arctan(x) + Arctan(1-x) ) )

[uneven isle]

wait yeah im bugging

[solar narwhal]

Yeah

[uneven isle]

failing basic math

🤣

forgor

[solar narwhal]

It took me a minute too

[uneven isle]

oh right

can apply geometry ideas so arctan(1-x) under the integral is equivelant to arctan(x)

so lambda is 2?

[solar narwhal]

Should be

[uneven isle]

lemme try part 2 now

[solar narwhal]

Ok

[uneven isle]

i got pi/4 - ln(sqrt2)

i did u sub

[solar narwhal]

What did you do

[uneven isle]

let x=u^2

[solar narwhal]

Yeah

[uneven isle]

for the arccot expression

[solar narwhal]

That's correct

[uneven isle]

and then there is a ffactor of 1/2

so really it is just evaluating integral from 0 to 1 arctanx dx

[solar narwhal]

Then used the above result

[solar narwhal]

No?

x = u^2

dx = 2u*du

It'd be 2

[uneven isle]

fml im making basic math mistakes

ok so it will just be 4 times what i got for my integral then

t=t

[solar narwhal]

Then using the above result that
Integral Arccot( 1-x+x^2) from 0 to 1 is
2 * integral Arctan(x) from 0 to 1

[solar narwhal]

4 or 8?

[uneven isle]

i think 4 times?

[solar narwhal]

You had a factor of 1/2

[uneven isle]

oh

and cancelled the 2

but then it should have been multiplied

yeah u right

that was a series of brain slump

thx for the help tho

🙏

[solar narwhal]

I'm

Getting

Pi - ln( 4)

?

[uneven isle]

oh

then it was 4 times not 8 times

i got pi/4 - ln(sqrt2)

when i factored 1/2

[solar narwhal]

?? But you had an factor of 1/2

[uneven isle]

i had factor infront of my expression for the arccot

[solar narwhal]

,w integrate arctanx from 0 to 1

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by rishabh_nirwan

[uneven isle]

which computes to arctanx dx

because the origina lexpression had lambda infront of arctanxdx expression

which was 2

[solar narwhal]

My ans is right

At least

[uneven isle]

yeah

i had 1/2 arccot(1-x+x^2)dx instead of 2 arccot(1-x+x^2) dx

[solar narwhal]

Idk what you said but as long as we both know how to get the right answer

[uneven isle]

sry my wording was confusing

[solar narwhal]

No, my brain isn't functioning right

Watched too many Math 505

Vids

[uneven isle]

im assuming thats a youtube channel or some kind of platform

[solar narwhal]

YouTube

Does some cool integrals and stuff

Anyways remember to close this channel

[uneven isle]

.close

[lone heart]

Channel closed

Closed by @uneven isle

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[earnest bobcat]

In abcd rectangle with 24,30cm sides, 30Cm side becomes radius and goes up and cuts other rectangle size, and removes that sector now there is small piece left in that side, and in that corner there is square, find area of the square

[earnest bobcat]

Need help

[lone heart]

@earnest bobcat Has your question been resolved?

[nimble fern]

do you have a figure to show or drawn?

[nimble fern]

,rccw

[nimble fern]

any workings so far?

[earnest bobcat]

Im unsuccessful so far, did some pythagoryms

[nimble fern]

I'm thinking now

,rccw

did you get these? @earnest bobcat

[earnest bobcat]

I think u calculated wrong

Top one is 18,12 not 20,10

[nimble fern]

oh, where?

oh right!

lemme do again

,rccw

[nimble fern]

is this what you get? @earnest bobcat

oh no

the blues are wrong 😦

ignore the blue ones 😦 thanks

[earnest bobcat]

Yes i got the black ones

Did u find any clue?

[nimble fern]

,rotate

[nimble fern]

yea, i find that we can use cosine rule!

[nimble fern]

do you think it's correct now? 😁

[earnest bobcat]

Yea

How to continue with cos?

[nimble fern]

[nimble fern]

oh, the upper cos(theta) and lower cos(theta) are the same

so we can equate them

[earnest bobcat]

My brain is not responding while equating them

[nimble fern]

hmmm

$$\frac{30^2+30^2-\sqrt{2x^2-48x+24^2}}{2(30)(30)}=\frac{30-x}{30}$$

[ocean seal]

Biscuity

[nimble fern]

you mean this?

[earnest bobcat]

Nah while trying to calculate X

[nimble fern]

ohhh

quadratic it is!

[earnest bobcat]

Continue it

[nimble fern]

$$(30)(30^2+30^2-\sqrt{2x^2-48x+24^2})=(30-x)(2(30)(30))$$

[ocean seal]

Biscuity

[nimble fern]

1800-√(2x²-48x+576)=1800-60x

then we have
√(2x²-48x+576)=60x

which will be quite easy now

[earnest bobcat]

Its messy number

[nimble fern]

haha it should be messy, lemme try

,w solve 2x^2-48x+576=(60x)^2

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by biscuityxd

[nimble fern]

hmmm

[earnest bobcat]

There is no 2

[nimble fern]

this number is weird....

lemme check if there are any mistakes

[earnest bobcat]

Idk why there is even root

When using cos formula

[nimble fern]

oh you're right!

that's my mistake!

$$\frac{30^2+30^2-(2x^2-48x+24^2)}{2(30)(30)}=\frac{30-x}{30}$$

[ocean seal]

Biscuity

[earnest bobcat]

There is no 2 behind x^2

[nimble fern]

,w solve 2x^2-108x+24^2=0

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by biscuityxd

[nimble fern]

is the answer 36cm²?

[earnest bobcat]

Yes

Wait what how did u get -108 lmao

[nimble fern]

lemme explain 🙂

[nimble fern]

the 2x is from
(24-x)²+x²=hypotenuse²

2x²-48x+576=60x

so we have
2x²-108x+576=0

[earnest bobcat]

Oh, i see

I got gaslighted by picture 💀

Alr then its done

Thank you

[nimble fern]

you're welcome!

[earnest bobcat]

,close

[nimble fern]

it's .close

[earnest bobcat]

🤦‍♂️

.close

[lone heart]

Channel closed

Closed by @earnest bobcat

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallow anchor]

Can someone tell me why the answer is not 1/2? Since we have guaranteed 1G, therefore we would only need to consider the second one, so 3/6=1/2

[mossy jasper]

I believe it's because you're taking it as them taking them at separate times

If he took 1 token and it was green, then if he took a 2nd it'd be 1/2, correct

But they took both at the same time, and you know what 1 of them is

So what it's really asking you is the probability of picking 2 green tokens if you take them at the same time

Hope that helps

[fallow anchor]

Oh right, so maybe the problem is that I was considering the order...

[mossy jasper]

Yeah, it's a sneaky trick because people often then count them separately

[fallow anchor]

I have noticed that I have only counted one order instead of two

[mossy jasper]

So, given what you know now, what do you think the answer is?

[fallow anchor]

I am quite bad at probabilities

[mossy jasper]

tbh I can be as well, I'm gonna guess you haven't learnt binomials? If so then there should be a simple way to do it

[fallow anchor]

But I think it should be P(get 2G)/P(at least 1G)

[fallow anchor]

I know binomials but not really how to use them in problems

The problem is that there aren't the same number of counters for each color

So I thought that with binomial was not porssible

[mossy jasper]

I don't see how you can calculate the probability of getting 2G, given that that's both tokens, whereas 1G is only 1

Unless you do binomials, but tbh even I'm struggling with that a bit

[fallow anchor]

P(2g) = 2x4/7x3/6 and P(at least 1g) = 4/7+4/6

[mossy jasper]

I'm blind and wrote the colours wrong anyway so no wonder I was getting horrible answers lmao

[fallow anchor]

But my answer doesn't appear in the options

[mossy jasper]

Probably because you are still lowering the power when it's established they were taken at the exact same time

Not power, denominator^

[fallow anchor]

Using binomials, maybe number of ways of getting 2Gs = 4!7!/5!?

Still not using binom though

Too high maybe

[fallow anchor]

Ok, so binom(6 1), that would be at least 1G

And 2Gs = binom (4 2)?

[mossy jasper]

Ah, if you do have to use binomials then I just realised I won't be able to help much because it clearly wants you to use it in fraction form, but I've always been taught to use calculator directly which does not give that with any combination I'm getting

[fallow anchor]

well but what we get with binomial we can divide it by the total cases and that would br fraction

[mossy jasper]

Problem is, what are we taking x, N, and p as?

Because there are multiple ways to do it

[fallow anchor]

what is that?

[mossy jasper]

Oh, ig you don't use calculator

[fallow anchor]

yeah, we are not allowed to use them

[mossy jasper]

That's very rough

[fallow anchor]

but for this problem i dont think we need to use big numbers

what is your approach to this problem?

[mossy jasper]

That's the question, isn't it. If you require a binomial then I can't help because I learnt on calculator, and I do not see any way to input this on a calculator

[mossy jasper]

Are you 100% sure it's not 1/2 ?

[fallow anchor]

the answer is 1/3

[mossy jasper]

Okay that probably would've been very helpful to start with lmao

[fallow anchor]

ah sorry I didn't say it because people say that that is spoiler or smth i dont know

[mossy jasper]

LMAO it wouldn't be a spoiler to us because we aren't part of your school, dw

[fallow anchor]

yeah you are right lol

[mossy jasper]

Yeah I'm really struggling to find how they got 1/3, my main thing is just that 1/2 would be right if they were taken at separate times, but they're not

[fallow anchor]

taken separate times and at the same time isnt that the same?

[mossy jasper]

no?

[fallow anchor]

you are not replacing it

[mossy jasper]

same time = you took 2 tokens in one go

different times = you took 1 token first, then a second after

Correct, you're not replacing

But replacements don't matter if they were taken at the same time anyway

[fallow anchor]

Ah okok

[mossy jasper]

wait I may be starting to work it out, lemme see

Nope, I've gotten almost every answer EXCEPT 1/3 lmao

[fallow anchor]

that is lit the nightware of prob

[mossy jasper]

Do you have a binomial formula, bc if so then you can do the prob of x = 2 first

Then for the probability of at least 1 green, that is the same as P(X≤2) - P(X=0)

[fallow anchor]

At least 1G= 2GG+GR+RG+BG+GB

[mossy jasper]

Small problem, that doesn't account for which token it is

That's the combos, but doesn't help for which token, with the exception of blue since blue only has 1 anyway

Do you have an actual generic formula?

[fallow anchor]

No

[mossy jasper]

Then I don't think this helps. There are 8 combos in total, and 1G is 5 of them, but that does not mean the probability of 1G is 5/8's because the actual probability of those combinations can be different

[fallow anchor]

true, well forget this problem then... Thank you so much for your help!!

[mossy jasper]

np, I'm sorry I couldn't actually work out why the answer is what it is for you

Feel free to type .close when you're done, hopefully your teacher can explain when you next see them!

[fallow anchor]

yeah thx!!

.close

[lone heart]

Channel closed

Closed by @fallow anchor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[visual zephyr]

chat

[visual zephyr]

what's the q3 for this?

is it 36 or 37?

<@&286206848099549185>

[unkempt pollen]

!15mins

[lone heart]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[visual zephyr]

yo dude what's the answer for this?

[simple spire]

You can’t simply ask for answers

[visual zephyr]

i have given choice between two

and what i calculated is 36

and the answ is 37

[simple spire]

So what else do you need?

if you alrdy have the ans

[visual zephyr]

reason?

[simple spire]

B) ?

[visual zephyr]

yeah quartile 3

[simple spire]

I *

[visual zephyr]

on god

i just want to know y the answer is 37 instead of 36 using the formula

is it that hard to tell 😭

@simple spireyo so may i know why now

[simple spire]

I get 36

[visual zephyr]

same

[mossy jasper]

whosdan if you showed your working that'd help

[simple spire]

Yea

[visual zephyr]

answer is 37

[visual zephyr]

3/4x25

[simple spire]

never mind it’s not

37 should be right

position Q3 = 3(25+1)/4 = 19.5 Q3 is halfway between 19th 20th values: 36 and 38 so 36+38/2 = 37

[visual zephyr]

o i got it

1 is needed to add?

[simple spire]

Where

[visual zephyr]

o nvm i guess i did wrong

[visual zephyr]

i used this and got 18.75

[simple spire]

Q3 = 3(n+1)/4

[simple spire]

Shoulda got 19.5

[visual zephyr]

wrong formula

[simple spire]

Yh

[visual zephyr]

thanks so much dude

appreciate it

[simple spire]

Yw

[visual zephyr]

.close

[lone heart]

Channel closed

Closed by @visual zephyr

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[somber pulsar]

hello! so i changed schools and they did functions ive never seen before and i need to find out the limits as x nears infinity. i tried doing something by watching some youtube tutorials and things but i dont know if i did it right as i couldn't find some functions there. could someone please go over them and explain it a bit if i did it wrong

[alpine sable]

maybe use ${-\infty}$ and ${\infty}$?

[ocean seal]

icannotdoanymorecauchy

[alpine sable]

also, this one the function oscillates

so u cant find the limit

[somber pulsar]

ok

[tiny sky]

well the limit DNE so i suspect they might be looking for DNE here

[tiny sky]

anyway yeah i normally don't see ppl writing empty set for limit not existing

[alpine sable]

yeah

[tiny sky]

normally u'd write limit "limit does not exist" or DNE for short

[somber pulsar]

wdym? like for the answer or? sorry i dont understand

[somber pulsar]

ah okay thanks

[alpine sable]

u can write that for my -infty and infty

[tiny sky]

they're saying that lim as x-> infinity of f(x) is infinity

[somber pulsar]

i was sick when they did it so idk haha

[somber pulsar]

ahhhh okay

and the other ones are good?

[alpine sable]

no

[alpine sable]

.

[somber pulsar]

other than those two

[alpine sable]

all good

[somber pulsar]

thank you!!

.close

[lone heart]

Channel closed

Closed by @somber pulsar

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tulip oasis]

sry ik its chem]

[tulip oasis]

but kind of math heree

So

That formula

like i fill out an example

It would be M= 12.01/6.02x10^23?

M = to mlar mass

[remote pebble]

no

[tulip oasis]

oh

[remote pebble]

6.02x10^23 atoms is 1 mole of it

so if there were that many atoms you would just do 12.01/1

[violet fable]

So can someone help me with matrix?

[tulip oasis]

Oh

[remote pebble]

also

the mass substance is how much of it is tehre

a better example would be

if there were 12.01 grams of carbon

do you know about the formula moles = mass/mr?

[tulip oasis]

uh no

[remote pebble]

ok

say they said there were 12.01g of carbon

this is 1 mole of carbon (i'm just giving you this information)

[tulip oasis]

oh

ok

[remote pebble]

so you can just say 12.01g/1 mol = 12.01 g/mol

[tulip oasis]

so this number under the symbol

[remote pebble]

yes

[tulip oasis]

is always equal to 1 mol

[remote pebble]

that's the number of grams in 1 mole of that atom

[tulip oasis]

Ok

[lone heart]

@tulip oasis Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[autumn crag]

Hi, im doing some linear algebra and i was trying to make sure my work is correct on the first matrix

[lone heart]

@autumn crag Has your question been resolved?

[autumn crag]

.close

[lone heart]

Channel closed

Closed by @autumn crag

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cobalt remnant]

Help guys pls how to do this

[cobalt remnant]

<@&286206848099549185>

[high cargo]

It says after 15 minutes, not after 15 seconds

[tight pier]

difference of squares

[simple spire]

LmaO

[lone heart]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

@cobalt remnant Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frigid anvil]

anyone know how to find difference quotient of these

.close