help-0

[wanton wigeon]

We also had minus

Bye need to go

[burnt reef]

what the fuck is your issue man

<@&286206848099549185>

[humble wraith]

@burnt reef is oppailol trolling you

[burnt reef]

well, clearly yes

[lone heart]

@burnt reef Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[daring tree]

Hello, i tried solving my homework in probability. Would it be possible, that someone could verify my work and guide me through potential mistakes?

[prime badge]

it's all correct

[daring tree]

also thank you

.close

[lone heart]

Channel closed

Closed by @daring tree

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusk cave]

Hi, just asking to make sure but the highlighted question doesnt have an inverse, right? Because of the 2?

[dusk cave]

Just wanna know if i remembered it right 😔

[tall topaz]

You're right

Oh wait

What do you mean by because of the 2?

[dusk cave]

If x = 2, sqrt(4-4) = sqrt(0) which isnt possible

[mossy jasper]

Yes it is

[tall topaz]

[mossy jasper]

sqrt(0) is 0

[dusk cave]

😔oh

[mossy jasper]

LMAO

[dusk cave]

So there exists a unique inverse for the function?

[dusk cave]

😔😔😔😔

[tall topaz]

,wolfram plot y = sqrt(4-x^2) with 0<=x<=2

[ocean seal]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by pure1144

[tall topaz]

damn

[tall topaz]

What do you think?

[dusk cave]

If sqrt(0) is possible, then sure??

Only if it becomes sqrt(-1) it wont have one, right?

Unlessnim wrong again

[tardy stag]

,w graph sqrt(4-x²) from 0 to 2

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by kitten.in.a.teacup

[tall topaz]

Thank you Hayley

[tall topaz]

Yes, square root of negative numbers are not real

You have a one to one function so the inverse exists here

[dusk cave]

Oooh!! So like if it was [0,3] then there wouldnt ve a unique inverse, right??

[tall topaz]

Then f wouldn't be a function

Unless you define it to be something else on (2,3]

[dusk cave]

Oooh

Alright, thank you so much!!

.close

[lone heart]

Channel closed

Closed by @dusk cave

Use .reopen if this was a mistake.

[tall topaz]

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bright remnant]

Im not sure how to solve this but I think I have to use fourier integrals because there are no bounds?

[lone heart]

@bright remnant Has your question been resolved?

[sharp plaza]

not necessary in this case

the forcing function, r(t) = sin(4t), is already a single frequency sine wave

just get it to the same form as the forcing function and solve for the coefficients

[bright remnant]

do you mean get the left side to the same form

the issue is when I use the quadratic formula it gets messy and I dont know what to do

because of the cy'

[sharp plaza]

essentially yeah

just focus on the coefficients of the sine and cosine terms

so first substitute the assumed particular solution and its derivatives into the differential equation, group the terms on sine and cosine, then math coefficients

[bright remnant]

what do you mean by this

so are you saying I dont need to use the quadratic formula

[sharp plaza]

i dont see why you need to

[sand sage]

This is how I solved an ODE Fourier series problem one time

I basically just did this

And added on the Fourier series of r(t) later on

So I was thinking this is how you would solve the problem

[finite citrus]

How did you get to this level

[bright remnant]

?

[finite citrus]

I just got interested in maths and I’m shit at it

[bright remnant]

please use another channel

[finite citrus]

Idk what steps to take

[finite citrus]

Sorry

[lone heart]

@bright remnant Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wet vector]

for part b i get 700m

but ms gets 710m

how?

[alpine sable]

show your work

what did you do to reach this answer

[wet vector]

1/2(10x20) + (25x20) + 1/2(10x20)

=700

[vale crag]

how long do you think the car takes to accelerate to 20m/s ?

yea that's the problem

[wet vector]

bruh

mb didnt see it lol

[vale crag]

the car doesn't accelerate in 10 sec

it takes 9 sec

[wet vector]

yh i got it

thanks

[vale crag]

but honestly the graph has shitty resolution, so I get you

[wet vector]

yh lol

thank u

.close

[lone heart]

Channel closed

Closed by @wet vector

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic nebula]

The graph of f consists of line segments, as shown in the figure. Evaluate each definite integral by using geometric formulas.

[mystic nebula]

so i dont understand how this works

for part a

do i read that as -3 times the interval of the function from 0,1

[small lance]

What does it mean?

[mystic nebula]

they multiplied -3 by something to get 3/2

[small lance]

No, ignore -3

[mystic nebula]

but thats the solution

[small lance]

Just explain what I underlined

[mystic nebula]

no clue

[small lance]

What’s the definition of integral?

[mystic nebula]

an antiderivative

[small lance]

Another one

Explain it geometrically

[mystic nebula]

the area of a function in a specified x interval?

[small lance]

Correct

That’s what I’m asking for

[mystic nebula]

so i want the area of the function in the [0,1] interval

[small lance]

Correct

But don’t forget the area you are looking for is below the axis

Therefore, a negative sign should be added

[mystic nebula]

so uh

which is the triangle

[small lance]

Yeah

[mystic nebula]

would i shade the top half

[small lance]

Wdym

[mystic nebula]

i want the area of the shaded region right

or does it have to be under the line

[mystic nebula]

gotcha

so i use A = -1/2bh

b and h are both 1

so its just -1/2

-3 times that is just 3/2

for part b i find the area of this

btw will i always be calculating the base and height just from looking at the graph

[azure needle]

🧐

[mystic nebula]

whats confusing

oh nvm its a dumb question since base and height only applies when there's a graph

ty

.close

[lone heart]

Channel closed

Closed by @mystic nebula

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

This is an SAT question. I did something with rewriting the first equation as 4y=4x-2 and then dividing by 2 to get y=x-1/2 and the second equation stays as ty=2x+1/2. For two equations to have no solutions, they can be parallel(same slope) and different y intercepts so the if the t value is 2, the 2x/2 would make the same slope but different y int. So it could be y=x-1/2 and y=x+1/4

[alpine sable]

But my solution is wrong so I just wanna know what's wrong because even when you put it in desmos, it's wrong

[thorny patio]

Ok once you get the equation to be in a similar form

Try to match the number of x

[small lance]

You made mistakes on your first step

[alpine sable]

Rewriting it?

[thorny patio]

Yea you did an algebra error there actually

[small lance]

Consider doing it again

[alpine sable]

..

[thorny patio]

Try doing it all one action at a time

[alpine sable]

It's 16y

Lol

[thorny patio]

Yea xD

[alpine sable]

I didn't realize it was

4x-6y

I prolly saw it and just instictively subtracted anyways

Sorry about that, that was dumb

My method still worked

[small lance]

No worries

[alpine sable]

.close

[lone heart]

Channel closed

Closed by @hot birch

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[snow lodge]

How do you solve this (no L'Hopitals)

[nimble fern]

by expanding the fraction with
(7x)/(7x) and (5x)/(5x)

it's usually the case involving sine's of different values on the numerator and the denominator

[cinder tundra]

Have in mind than lim x->0 sin(ax)/(bx) = a/b

[snow lodge]

I don't get it

[snow lodge]

But why

OK I gtg

.clos

.close

[lone heart]

Channel closed

Closed by @snow lodge

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

help

[lone heart]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[still temple]

1

[hoary nimbus]

Which part?

[still temple]

basically right

its the step to find centripetal force

i get conservation of energy

but how do i find centripetal force

[hoary nimbus]

R-mg ig

[still temple]

whats R

wouldnt it be N+mg

normal force

[hoary nimbus]

Reaction force

[still temple]

yeah

oh i see

[hoary nimbus]

Depends on where the car is on the loop

[still temple]

at the bottom it would be

at the top its different

yeah your right

[hoary nimbus]

Yes exactly

[still temple]

but wouldnt the forces magnitide be constant

[hoary nimbus]

Only at the lowest point of the circle

[still temple]

oh yeah

at the highest

[hoary nimbus]

And highest point

[still temple]

if we talking min speed

it can loose contact with the loop

right

momentarily

and thats what the question asks for

minmium speed

so the centripetal force is only mg

[hoary nimbus]

But we want min speed so it doesn’t lose contact

[still temple]

but it looses contact at the top before catching itself again

right?

[hoary nimbus]

Why must it lose contact at the top?

[still temple]

surely bc we need minium speed

to traverse the loop

not to be attatched at all times

am i wrong

genuinly i have no clue

[hoary nimbus]

Ye i think ur right

[still temple]

so would the asnweer to the second part be root 6g

[hoary nimbus]

No

Ur kinda close tho

[still temple]

its units isnt it

fuck

[hoary nimbus]

Nah but that’s incorrect too

It’s not just units

[still temple]

hmm

[hoary nimbus]

Ur value for m/s is wrong too

[still temple]

v = root gr

from equating mv^2/r = mg

r = 6

im confused from here

[hoary nimbus]

Not quite

[still temple]

waht

how

it is no

what is it

take square root

[hoary nimbus]

Wait no that’s correct my bad

But that is the incorrect final answer

[still temple]

could you correct me pls im lost

[hoary nimbus]

You found v

That’s the velocity of the particle or whatever at the highest point of the circle

But we want velocity at where?

[still temple]

at the start

idk how to do that

wouldnt that be the sanwer tho

nah i have nothing bro

[hoary nimbus]

Yes

[still temple]

i was right

[hoary nimbus]

But units

Mph is miles per hour?

[still temple]

yeah

then just convert

but in essence iw as right

right?

[hoary nimbus]

Yes

[still temple]

https://tenor.com/view/leonardo-dicaprio-clapping-clap-applause-amazing-gif-1812735758324318601

thanks bossman

[lone heart]

@still temple Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hidden hazel]

Did I solve this correctly?

[onyx tinsel]

f(x) isn't always 2 in[-6,4)

@hidden hazel -6 isn't even in the range

at all

[hidden hazel]

Oh my mistake sorry

[onyx tinsel]

btw the filled dots mean that a certain point is part of the graph

[hidden hazel]

Yeah its the conditions of an inequality isn't it?

[onyx tinsel]

so

if the line at y = 2

has two filled dots

that means that the 2 part starts and ends with [ ]

and the 1 part has one open dot at first and ends witha closed dot

which is ( ]

the 3 part starts with an open dot and ends with a closed dot

( ]

[hidden hazel]

Okay one moment

So the different dots being open or closed represent the different symbols we use to denote an inequality SO

let me try and figure this out...

[lone heart]

@hidden hazel Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

I have to find difference quotient of this but I don’t know what to do after

[lone heart]

@alpine sable Has your question been resolved?

[tacit arch]

Do the multiplication in the numerator correctly using parentheses

(a-b)(a+b) =?

[alpine sable]

a^2-b^2

[alpine sable]

Like which part

[tacit arch]

.

The numerator of a fraction is the part above the horizontal line

And the numerator of the product of two fractions is the product of the numerators

[alpine sable]

You mean like this?

[tacit arch]

From here. Just factor out a 4 then apply

[tacit arch]

This

[alpine sable]

?

What do I do after

[lone heart]

@alpine sable Has your question been resolved?

[tacit arch]

what

are you going backwards?

[tacit arch]

do this multiplication

[alpine sable]

You told me to factor 4

[tacit arch]

well yes i thought you could do more than 1 step at a time

[tacit arch]

can you do this multiplication now?

[tacit arch]

and do you know where you could use this ?

[alpine sable]

Multiply by Like square root of x Times Square root of x+h?

[tacit arch]

no

after you've factored out a 4, this becomes

$4 (\sqrt{x} - \sqrt{x+h}) (\sqrt{x} + \sqrt{x+h})$

[ocean seal]

riemann

[lone heart]

@alpine sable Has your question been resolved?

[hard glade]

Can someone help me?

[tacit arch]

! occupied

[lone heart]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac jolt]

for item 7, do i just substitute the x on y = sin(x)?

so the first one will be sin(0), sin(pi/6), and so on? and theyre my final answers?

[still ruin]

yes

You will plot the output off the sine function

[lilac jolt]

but thats for item 8 right?

just for item 7, after the substitution is my final answer?

[still ruin]

yeah, you will put sin(0) and in y= sinx you will put the output (in this case it's 0)

and continue for each

[lilac jolt]

output?

[still ruin]

x in your input and y is your output

[lilac jolt]

oh okay thank you

[still ruin]

your welcome

[lilac jolt]

how do i plot these sin functions

from the table

[still ruin]

just like how you will plot any function (quadratic, linear equation). YOu will plot the (x,y) of each corresponding column in the table you made

since in the sien function, you will not get whole numbers, you will approximate the placement of the values

[lilac jolt]

https://youtu.be/bm8oYKKlCXI?si=F9g5lEu-RvX35Igc

like this?

sorry, we dont learn math in english

[still ruin]

oh, that's okay

but the video you show above us what I am talking about

[lilac jolt]

thank you, i will try

[lone heart]

@lilac jolt Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[indigo anchor]

i’m stuck on this

[twin nimbus]

3/x^2 = 3 x^(-2)

Do you remember how the power rule for differentiation works?

[indigo anchor]

yeah

[indigo anchor]

wait sorry i’m confused with this

[twin nimbus]

The first part?

$\frac{3}{x^2} = 3x^{-2}$

[ocean seal]

OmnipotentEntity

[indigo anchor]

ahhh

i forgot about that rule

i get it now

tysm

.close

[lone heart]

Channel closed

Closed by @indigo anchor

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

If I had to differentiate something like this e^(tanx - sinx) wrt x. I could straight up use chain-rule right?

[serene ridge]

yeah why not

[alpine sable]

All the problems like this take ln and proceed so was just wondering

Sorry

I have an exam tomorrow

[tardy stag]

yep chain rule and others

[alpine sable]

And everything is jumbled up in my head

[mortal trellis]

there are often several ways to solve things. I would also just use chain rule

[alpine sable]

So there is no ugly expression where I couldn’t use chain rule?

[serene ridge]

I mean if you have something like x*sin(x) you can't use chain rule there, but you can use product rule

[mortal trellis]

well I mean chain rule should of course be applicable. it should still be a composition of things

but otherwise you can always apply it. it might just be more painful than some other trick

[serene ridge]

chain rule always works when you have the composition of two functions

[alpine sable]

Yes because I remember something like this on the last test and I was so puzzled because it was getting very long

[alpine sable]

Okay!!!

Thank you so much guys

I really appreciate it

.close

[lone heart]

Channel closed

Closed by @vivid walrus

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dreamy blade]

I need help on the Test for algebra 1.

[desert oak]

народ , помогите мне с математекой

[ivory slate]

What

[lone heart]

@dreamy blade Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viral falcon]

Still need help with this one #help-12 message

[lone heart]

@viral falcon Has your question been resolved?

[fresh wedge]

That channel is closed, you can ask your question here if you want

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[odd moon]

Integrate 1/(1+e^x) from 0 to infinity

[cedar kelp]

!status

[lone heart]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[odd moon]

3

[cedar kelp]

what process did you go about?

[odd moon]

Wait a min pls I will upload a photo

[cedar kelp]

okok

[odd moon]

How do I put in the limits though??

[cedar kelp]

use limit as x tends to infty of F(x)

[cedar kelp]

(antiderivative I mean)

[odd moon]

Sorry I didn't get it

[cedar kelp]

$\lim_{x\to\infty}ln\left(\frac{e^x}{1+e^x}\right)$

[karmic bolt]

ln(e^x/1+e^x) factor out e^x and subsitute limits

[cedar kelp]

here you can divide both numerator and denominator by e^x

or use what Urabot said

[odd moon]

Thnx guys

But what is the problem in my solution

[cedar kelp]

you didn't got any final solution

[odd moon]

No

That's the problem

The ans is supposed to be ln2

But I get inf-inf

[karmic bolt]

its not wrong, u have to subsitute limits which if u do u won't get a finite ans so in these cases u have to take limit x aprroches to infinity or limit x approches to o

[odd moon]

Ok

[cedar kelp]

yeah so that's indeterminant form

you have to do more work

[odd moon]

So if I take limits I will get an answer

[cedar kelp]

yeah

[odd moon]

??

[odd moon]

Ok thanks

[cedar kelp]

{kinda}

[odd moon]

It's the first time I have encountered a problem like this

[odd moon]

What do you mean now

??

[cedar kelp]

nothing just ignore

[odd moon]

Nah just tell me now

[cedar kelp]

it doesn't matter

[odd moon]

Ok I trust you

Thanks though

.close

[lone heart]

Channel closed

Closed by @odd moon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[supple linden]

hello, i am stuck in this question, could u please help?

[supple linden]

the underlined part is a bit confusing for me

where did iota go? and how did 4x2^2y2^2 come?

[mighty prawn]

hello

no.3

[supple linden]

to get help, kindly go to #❓how-to-get-help

[wintry wadi]

it's squared, so it becomes -1

[supple linden]

alright so its squared that means that minus should turn into + as - - is +

[supple linden]

and what about the 4x2^2y2^2 part?

[wintry wadi]

that's from what you underlined on top

[supple linden]

could u simplify it?

how did it come

what was the step and what was the rule

[wintry wadi]

the $-2x_2^2y_2^2$ comes from $(x_2^2-y_2^2)^2$

[ocean seal]

Sepdron

[supple linden]

alrighty thank youu

[wintry wadi]

np

[lone heart]

@supple linden Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vague vessel]

hello

[vague vessel]

In interval notation where is the graph continous

I put (1,4]

[lone heart]

@vague vessel Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

no specific problem but when performing LU decomposition, why are we only allowed to use row operation 3 (multiply row by scalar and add to another) and not the other 2 row operations (row swap and multiply a row by a scalar)?

[alpine sable]

i have an inkling idea of why from reading things online but i couldn't find a super clear explanation

also, when performing row operation 3, the row you multiply by a scalar by and the row you add it to can't be the same (e.g. 3R1+R3->R1) is not allowed

why???

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twin flare]

trigonometry

[twin flare]

its a chapter test I am needing help with and needing to pass it with flying colors

[lone heart]

@twin flare Has your question been resolved?

[torpid dirge]

can u fly yet

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unique flower]

how can number 2 be done

I have the following sketch:

but I'm not sure I have the right expression for r

[lone heart]

@unique flower Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fluid iris]

ive been stuck with my answeer. i got told i am wrong

[cedar kelp]

you sure function is increasing from -3 to infty?

[fluid iris]

hello, so the way i got this was to read the graph from l to right and then it tell me where it gets the higest point

unless it means the whole thing which would be -infi, +infi

[cedar kelp]

you entered -3 to 0 in decreasing part

so it doesn't makes sense to include that -3 to 0 in increasing part too

[fluid iris]

oh

[cedar kelp]

notice the graph

[fluid iris]

so it means from (0,0) the increase ahead>

[cedar kelp]

from -3 to 0 the slope of graph is constantly negative
id est it is decreasing on that interval

[fluid iris]

?

from -3 it is rising?

[cedar kelp]

that's how the function is categorized between increasing and decreasing on some interval

[fluid iris]

tbh it doesnt make sence in my head

[cedar kelp]

you need to focus on the graph not to imagine all of that in your head

carefully examine the graph in the interval of -3 to 0

[fluid iris]

okay, -3,0 is the top of the line goes

i understand that

but shouldnt i start from the very left, which would be -infi

to the top

that is what i am getting at w my incorrct a

[cedar kelp]

of course for examining where the function is increasing

[cedar kelp]

that -infty to -3 part is indeed

but that -3 to infty part is not

since from -3 to 0 the function is decreasing and not increasing (what they are asking in part A)

[fluid iris]

i dont understand that part

are you begining from that point

-3 to infi

that goes down

[cedar kelp]

exactly

that's the interval where the slope of the function is negative

hence it is decreasing on that interval

but you need the interval where it is increasing

[fluid iris]

from 0, to infinity??

question mark]

[cedar kelp]

yeah from 0 to infty

and also -infty to -3

[fluid iris]

but why

ah

is that what the u means

U

\cup

[cedar kelp]

yeah

union of both intervals

[fluid iris]

like so. i am nervous to submit

❤️

my goodness

it makes a bit more sense, just as a fyi

union means within the line per say

[lone heart]

@fluid iris Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[urban agate]

For question 1 regarding linear velocity, why does the value change from radians/seconds to meter/seconds?
For question 2 regarding angular velocity, why does the value change from inches/seconds to radians/seconds?

[jagged cobalt]

v=rw and w=v/r

is what they were doing

[urban agate]

did I convert wrong?

[jagged cobalt]

im confused you have the same answers

[urban agate]

for the part where V=3m(3pi rad/2sec), why does the radian disappear?

although I got the solutions, I'm unsure about that part

[lone heart]

@urban agate Has your question been resolved?

[urban agate]

.close

[lone heart]

Channel closed

Closed by @urban agate

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sacred geode]

!help

[lone heart]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[sacred geode]

Idk how dividing 10 and 2 makes 5

[tough adder]

can ask for a derivative problem?

[lone heart]

@sacred geode Has your question been resolved?

[lone heart]

@sacred geode Has your question been resolved?

Channel closed

Closed by @sacred geode

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dull lintel]

few ways to do it:

1. This is derivative definition, convert the definition to function

[dull lintel]

have any idea what's definition is that?

[iron dragon]

f(x +h) - f(x) / h

[dull lintel]

yeah and what is f(x) in that case

[iron dragon]

the function output y

[dull lintel]

so f(x+h) = (x+h)^3 and f(x) = x^3 right?

[iron dragon]

yea

h^3 + 2x^2h / h

h^2 + 2x^2

[dull lintel]

it wants you the differentiated version of x^3

[iron dragon]

what's that mean

[dull lintel]

don't you know how can you differentiate that

[iron dragon]

(x+h)^3 - x^3 / h

[dull lintel]

okay nevermind, expand (x+h)^3 and then simplify numerator and denominator by h

[iron dragon]

h^2 + 2x^2 + xh + x^2 + 2xh

[dull lintel]

,w expand (x+h)^3

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by metumortis

[iron dragon]

right ok

now as h goes to 0?

[dull lintel]

simplify h

if you plug 0 in h you get 0/0

[iron dragon]

h^2 + 3hx + 3x^2

[dull lintel]

after simplifying plug 0

[iron dragon]

so we get 3x^2

[dull lintel]

yes

[iron dragon]

thank you

[dull lintel]

you're welcome

[iron dragon]

can you help me with another?

[dull lintel]

sure

[dull lintel]

so now we have to get rid of (simplify) x so we don't get 0/0 right?

[iron dragon]

yes

[dull lintel]

hint: (a-b)(a+b) = a^2 - b^2

you'll have to multiply (expand) numerator and denominator by something so you get rid of square roots and then you well be able to simplify

[iron dragon]

sqroot(x +9) - 3 / sqroot(x + 9) - 3

[dull lintel]

sqroot(x +9) + 3 / sqroot(x + 9) + 3

you already have a-b you need a+b

[iron dragon]

1 / (sqroot(x+9) - 3)

[dull lintel]

after multiplying by that you get $\frac{x+9-9}{x \cdot (\sqrt{x+9} + 3)}$

[ocean seal]

MetuMortis

[iron dragon]

1 / (sqroot(x+9) +3)

[dull lintel]

yes

after that just plug 0

[iron dragon]

1/6

[dull lintel]

yes

[iron dragon]

thank you

I have done Calculus 9 years and I tried doing Calculus 2 and keep having to drop, this is Calculus 1 work again, do I need to re do Calculus 1 to be able to pass Calculus 2 or is there not much over lap and you would focus on Calculus 2? I have trouble doing integrals, I can't remember most of the derivatives and the integration formulas are hard to remember, especially the trigonometric ones and trigonometric identities I don't know

I noticed you have a github, I am trying to do a Computer Science degree but I still need to do Calculus 2, Linear Algebra, Discreet Math, Calculus 3 and Stats. I am afraid it might take me a long time

and I might even have to re do Calculus 1 or Pre Calculus since it's been years since I passed Calculus 1 and Pre Calculus

[dull lintel]

Have no idea about what does Calc 1 and 2 include, I graduated from highschool recently and will be studying Computer Engineering at college. I'm probably not the best person to answer that

[iron dragon]

did you do Calculus in highschool?

[dull lintel]

Yes

[iron dragon]

if I don't remember trig identities will I learn them a long the way in Calculus or is it from before Calculus

[dull lintel]

Not sure :/

[iron dragon]

how would I solve this one?

@dull lintel can you please help me again?

[lone heart]

@iron dragon Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Am I simplifying this right?

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

.close

[lone heart]

Channel closed

Closed by @buoyant skiff

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ocean seal]

Stef

[hidden pecan]

I know there is the function $f(x,y)=x^n+y^n$

[ocean seal]

Stef

[hidden pecan]

How can I prove that it is the only one?

[lyric ruin]

may i ask what composition of function is?

[hidden pecan]

What do you mean?

<@&286206848099549185>

[final shore]

What is N*

[hidden pecan]

Natural numbers greater than 0

So 1,2,3,...

[final shore]

Aren't those just natural numbers

N

[hidden pecan]

N includes 0

[final shore]

Whole numbers?

[hidden pecan]

Yes

[final shore]

Bro W includes 0 and natural numbers

[ivory fern]

Is this correctly written?

[final shore]

Natural numbers are 123

[hidden pecan]

Yes

[ivory fern]

Should the numerator be x^m in the three fractions in rhs?

[hidden pecan]

Yes

Here is the original

In my language

[ivory fern]

Then what you wrote has a typo

[hidden pecan]

Where?

[ivory fern]

^

You wrote x^m/something three times

[hidden pecan]

Oh

Thanks

[lone heart]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[hidden pecan]

Let $n,m \in \mathbb{N}^{*}$. Determine $f:(0,\infty) \times (0,\infty) \rightarrow (0,\infty)$ with the property that, for every $x, y, z > 0$, with $f(x,y)=f(y,x)$ and
$\frac{x^m}{f(y,z)}+\frac{y^m}{f(z,x)}+\frac{z^m}{f(x,y)}=\frac{x^m}{y^n+z^n}+\frac{y^m}{z^n+x^n}+\frac{z^m}{x^n+y^n}$

[ocean seal]

Stef

[ivory fern]

Now you have to open a new help channel

[hidden pecan]

Ok

.close

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[weary quartz]

help

[weary quartz]

how would i simplify the bottom

[alpine sable]

Can't you just plug the values in?

[alpine sable]

You can make the denominator (2x+y)^3

[weary quartz]

when i do it i get this

[sterile trench]

after taking lcm

[weary quartz]

it won’t let me send my screen shot but i get

(-3x^2+6xy-3y) / (2x+y)^3

but the mark scheme says it’s 12xy on the top

i just don’t see how to get that

[sterile trench]

top is called numerator

in numerator, after taking lcm

you will get
-3x(-(x+2y)) - 3y(2x+y)

and whole fraction would be

-3x(-(x+2y)) - 3y(2x+y) / (2x+y)³

[weary quartz]

ahh i’ve got that now thank u

[lone heart]

If you are done with this channel, please mark your problem as solved by typing .close

[weary quartz]

.close

[lone heart]

Channel closed

Closed by @weary quartz

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[heavy prairie]

To determine if a function's limit exists or not, I need to check if the limit from the left and the limit from the right both approach the same value, right?

[heavy prairie]

If they approach different values, the limit does not exist.

[alpine sable]

Aye

[heavy prairie]

Okay: For some functions I find that to be easy to see by just looking at it or graphing the function, but if I have a periodic function that I have trouble graphing, I wish there was a purely algebraic approach to determining if the limit does not exist

Is there a purely algebraic method to determine if a limit exists or not?

I can easily see that the limit for 8/x as x approaches 0 doesn't exist.

However, I can not easily see that the limit for sin(8/x) as x approaches 0 doesn't exist.

8/x would be the "angle" of the the sin function in sin(8/x)?

and the angle approaches both positive and negative infinity

[tepid turtle]

can anyone explain relations,reflexive,symmetric,anti symmetric 😭

i suck at math fr

[heavy prairie]

!occupied

[lone heart]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[heavy prairie]

<@&286206848099549185>

[solemn stream]

?

[heavy prairie]

I can easily see that the limit for 8/x as x approaches 0 doesn't exist.

However, I can not easily see that the limit for sin(8/x) as x approaches 0 doesn't exist, because I have trouble imagining the graph for the function.

8/x in sin(8/x) would be the angle

So the angle would be + or - infinity

an angle that is + or - infinity doesn't tell us anything about the function

so it does not exist?

How do I reason around a limit that doesn't exist of a trigonmetric function?

<@&286206848099549185>

[azure needle]

Can you have sin(±∞)

[sterile trench]

yeah sin(8/x) where x is ending to 0 does not exist

[heavy prairie]

I am not sure to be honest, I have never seen it before and I can't imagine what it would mean.

[sterile trench]

it's because sin oscillates between -1 & 1

if you check the graph

[azure needle]

Yeah

[heavy prairie]

Yeah but the angle could be infinite, couldn't it?

We would end up somewhere between -1 and 1

[sterile trench]

yes

[heavy prairie]

But since it is infinite we never end up anywhere?

[sterile trench]

sin(1/0+) = sin(infinite)

sin(1/0-) = sin(-infinite) = -sin(infinite)

[sterile trench]

yeah we don't end up anywhere

[azure needle]

It's not defined imo

[sterile trench]

so limit DNE

[heavy prairie]

Okay, I think I am happy with that explanation. Thanks.

.close

[lone heart]

Channel closed

Closed by @heavy prairie

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plucky fulcrum]

Im confused how to do thsi

[plucky fulcrum]

where do i even start on it?

[lone heart]

@plucky fulcrum Has your question been resolved?

[plucky fulcrum]

<@&286206848099549185>

[solemn stream]

what rules have you guys learned so far for geometry?

[plucky fulcrum]

wdym

like vertical angles

?

[solemn stream]

ya

Have you guys learned that all the angles in a triangle add up to 180?

[plucky fulcrum]

yes

ohh

i see

ty

[solemn stream]

ok, glad it helped ig lol

[plucky fulcrum]

step 2 find my textbook xd

[solemn stream]

ya, you gotta somehow infer another angle based on one of those rules and probably use that rule of all angles in a triangle add up to 180 to find it.

[plucky fulcrum]

yeah

i didnt realize they were triangles

[solemn stream]

ya, that's how I would do it if I could. It seems like a bit of a tough problem at first glance tbh

You'd probably need to set a bunch of sums of angles as 180 and then use some algebra to solve... but idk 'cause I haven't done geometry in like 10 years.

[plucky fulcrum]

alr lol, yeah i just finished algebra 2 and am now learning geometry

all before high school lmao

[lone heart]

@plucky fulcrum Has your question been resolved?

[plucky fulcrum]

?

[tacit arch]

<@&268886789983436800> still spamming

[wide tartan]

they’ve been timed out

[lone heart]

@plucky fulcrum Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[novel remnant]

How do I do this?

[novel remnant]

Damn this is gonna be a long one🥲

[buoyant saddle]

differentiate

[tight pier]

Do you know the derivative of sine?

[novel remnant]

Nope

I only did derivatives with regular numbers

[tight pier]

@buoyant saddle what is the derivative of sine

[buoyant saddle]

cos

[novel remnant]

Wait really?

[buoyant saddle]

why are you asking me

💀

[novel remnant]

It’s that simple?

[tight pier]

and the derivative of cos?

[buoyant saddle]

-sin

man thinks i don’t know

[tight pier]

damn bro is cooking

[novel remnant]

Negative?

[tight pier]

yes

[novel remnant]

Why is that

[buoyant saddle]

do you need a proof

with limit definition

[novel remnant]

Yea I’m curious

[buoyant saddle]

prove it yourself

[novel remnant]

How in the hell🤣

[buoyant saddle]

using limit definition

[novel remnant]

What does that mean

[tight pier]

you can do that as an exercise

[novel remnant]

There is such a thing as anti derivative ?!😭😭

Oh my god

[buoyant saddle]

yes

[tight pier]

intergrals

but ignore it

[buoyant saddle]

just going in the other direction

[tight pier]

it's kinda sad that knief cannot do a limit definition proof for you 😔

[alpine sable]

lmao

[novel remnant]

So basically you are left with cos+(-sin)?

So cos-sin

[tight pier]

yea, just dont forget the coeffcients

[novel remnant]

Don’t they drop out

[alpine sable]

no

[tight pier]

no

they are factors

not summands

they stay

[novel remnant]

What is summands lol

[tight pier]

bro

1+2

1 and 2 are summands

[novel remnant]

Oh lol, so basically because they are being multiplied?

[tight pier]

yes

that's why factors

[novel remnant]

I see, I’m not good with terms in English lol

[tight pier]

me either

[novel remnant]

So basically it’s 5cos-6sin?

That’s the derivative?

And the x’s drop out

[tight pier]

yes

[novel remnant]

It’s wrong

[tight pier]

bro

the x dont drop out

wtf

[novel remnant]

How??

Then how is this a derivative

[tight pier]

they are the argument

[novel remnant]

Like the derivative of 2x is 2

X drops out

[tight pier]

5cos(x)-6sin(x)

no

[novel remnant]

Why is this one different 🥲

[tight pier]

cos and sin have no meaning

without the x

[novel remnant]

Ohh because they have to calculate something?

[tight pier]

yes they are functions

[novel remnant]

This is a weird derivative lol

The regular one is much simpler

You drop one x multiply the numbers and call it a day

[tight pier]

you have yet to see much more :)

[novel remnant]

Yay me😭🤣

I have cal2 next semester so🫠

What do I do with the second one

I plug it in x?

Do I take the derivative first or do I plug it first and then take the derivative?

[tight pier]

yes

[novel remnant]

Which one🤣

[tight pier]

no

you are already given the derivative

f'(x) is given

[novel remnant]

Oh I plug it after taking the derivative

[tight pier]

yes

[novel remnant]

So like that was the first step

Thank you

What did I do wrong

I told the cos of it and the sin of it multiplied and added

Wrong answer

Nvm now suddenly it gave me -1 as an answer

[tight pier]

dont round your stuff unless you are being told so

[novel remnant]

Isn’t it infinite

It’s still wrong why??

Now it gave me the previous answer again..

I did - instead of + it’s 9.83🤦🏻‍♂️

How do I do this?

I put pi in the x’s and got 11.56 but that’s not m so I’m not sure what I got

[lone heart]

@novel remnant Has your question been resolved?

[stone marlin]

Help me

[tight pier]

!occupied

[lone heart]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[tight pier]

for m to be found you need to calculate y'(pi)

[novel remnant]

The derivative of pi??

How do I even do that

Isn’t it 0

Every number by itself is 0

So the derivative of 3.17 is 0

I’m so confused

[tight pier]

no

the derivative of y

that's y'

[novel remnant]

Ohhh

[tight pier]

and y'(pi) means pi plugged in

[novel remnant]

I take the derivative and then plug pi??

[tight pier]

yes

[novel remnant]

Ohh omg

So I found the slope of the original equation?

[tight pier]

what is the derivative of 4xcos(x)

[tight pier]

you find the slope at your given point

[novel remnant]

4-sin(x)?

[tight pier]

no

you need product rule

it's a product not a sum

[novel remnant]

Wth

[ocean seal]

bacc

[novel remnant]

Oh right that thing🥲

[tight pier]

Here f(x) = 4x and g(x) = cos(x)

[novel remnant]

What if it was 4xcos(x)sin(x) how’d you do it then

[tight pier]

haha

i could say use identity for cos(x)sin(x)=sin(2x)/2 but i get your point

[ocean seal]

bacc

[novel remnant]

Holy🥲

[tight pier]

this comes from using this

if for example you treat (fg) together as one

and so one

but anyway

[novel remnant]

??????

I did all of this and it’s wrong oh my god🫠🫠🫠

[tight pier]

you should review algebra

[novel remnant]

What did I do wrong

[tight pier]

,, y'(\pi) = 4\cos(\pi)-4\pi \sin(\pi) = 4(-1) = -4

no calculator needed

sine at pi becomes 0

cosine becomes -1

[ocean seal]

bacc

[novel remnant]

Wait hold on

(4x)(-sin(x))

[tight pier]

it's being multiplied

[novel remnant]

Isn’t that 4x-sin(x)

[tight pier]

no

[novel remnant]

How do you multiply it then

[tight pier]

it's like saying

2(-3) = 2-3

the left is

-6

the right is -1

so obviously wrong

[novel remnant]

My brain

How do you multiply it then🥲🥲

[tight pier]

imagine the - was (-1)

a(-b) = a(-1)b = (-1)ab

[novel remnant]

-4xsin(x)??

[novel remnant]

What the fuck

It’s still wrong

Oh cuz it’s multiplied by 0

Bruh this is breaking my brain

One hour to find the slope💀

[crystal berry]

bro took an hour to differentiate

respect

[novel remnant]

It’s so much more difficult with sin and cos wth🥲

Alef one help

Bruh I made the same fucking mistake

[tight pier]

bro help him

im eating

[novel remnant]

I was definitely not the cook😭

[crystal berry]

wait till you try intergating e^-x^2

[crystal berry]

bruh

[novel remnant]

Wth am I looking at

Alef don’t scare me like that🥲

[crystal berry]

brings me back 5 years ago lolz

anyway

ill help

[novel remnant]

Product rule again,

?

[crystal berry]

step 1: product rule, step 2: done

[novel remnant]

🤣🤣

[crystal berry]

bro

okay differentiate

sinx cosx

what do you get

[novel remnant]

Coscos+sin-sin?

[crystal berry]

huh

[novel remnant]

Isn’t it the product rule

[crystal berry]

yeah

but

they way you write it

is funny

[novel remnant]

It’s because of the discord thing🤣🤣

[crystal berry]

cosx cosx - sinx sinx

[crystal berry]

👍