help-0

[strange heath]

so lets say he investes for x months

[sick ibex]

.

[strange heath]

total money he investes will be 50x

[sick ibex]

And how about the years?

[strange heath]

and the amt of money he incvests per year will be

50x/12

he gets a 3% return on that

so 0.3 ( 50x/12)

[sick ibex]

Yes but every month

[strange heath]

i took care of that

[stray spruce]

What does annual return means? I forgot

[strange heath]

1 year = 12 months

x months = x/12 years

right ?

[sick ibex]

He simply gets 3% on top of the amount in the share

And that stacks

[strange heath]

and to this

[stray spruce]

The profit?

[strange heath]

add 1000

for the final answer

[sick ibex]

Basically yeah

[stray spruce]

Ok got it

[strange heath]

cuz he invested tht in the beging

so try that

[sick ibex]

So what func?

[strange heath]

1000 + 0.3(50x/12)

where x is the no. of months he invested for

[sick ibex]

Ah ok

But how about the 1000 euros?

[stray spruce]

Ok what will the fuction give me if i put a value in it

[strange heath]

i have added that

f(x) = 1000 + 0.3(50x/12)

[sick ibex]

The amount of money in x years/months

Unsure about what span of time lol

[stray spruce]

So if i put the time it will give me the amount of profit

[sick ibex]

Yes

for 2.

[stray spruce]

Another thing that is if i invest lets say 100 euro in a year and i get 10 euro and again i invest 100 euro in the next year, will i get 20 euro or 10 euro in return

[sick ibex]

20

[stray spruce]

Okkk

[sick ibex]

Have you heard of compound interest?

Yeah basically what you said

[stray spruce]

Oh yeah i got it now

As he paid 1000 euro at first so he gonna pay 50 euro for next 11 months

[sick ibex]

In every year yes

[stray spruce]

Ok

[sick ibex]

but the 1000 euros not

They are only paid once

[stray spruce]

Yeah i got that

[sick ibex]

Oh sorry

[stray spruce]

Hmm.. I was saying in the first year he will pay 50 euro for 11 months because he paid 1000 euro in the first month

[sick ibex]

yes yes

In the first month he will only pay 1000

[stray spruce]

Hmm

I got a function which can calculate the profit

$/func(x)= {5011+100+50(x-1)}*3%

$/func(x)= {5011+100+50(x-1)}*3%/

$\func{x}$

[ocean seal]

Tmr_chena_keu

$\func{x}$
```Compilation error:```! Undefined control sequence.
<recently read> \func 
                      
l.49 $\func
           {x}$
The control sequence at the end of the top line
of your error message was never \def'ed. If you have
misspelled it (e.g., `\hobx'), type `I' and the correct
spelling (e.g., `I\hbox'). Otherwise just continue,
and I'll forget about whatever was undefined.```

[sick ibex]

What is the function?

[sick ibex]

f(x)= (5011+100+50(x-1))×3%?

[sick ibex]

<@&286206848099549185>

[stray spruce]

Yes and the function is defined like f: N -> R+

Domain is natural numbers

And codomain is real numbers

[sick ibex]

Could you give me a general function with variables please? i wanna test out some stuff :)

[lone heart]

@sick ibex Has your question been resolved?

[sick ibex]

<@&286206848099549185>

.

[sick ibex]

<@&286206848099549185>

[stray spruce]

I mean the function i gave u that works

Where x is the number of years

[sick ibex]

For what does 5011 stand for?

[lone heart]

@sick ibex Has your question been resolved?

[lone heart]

@sick ibex Has your question been resolved?

[molten storm]

y= 1000 x 1.03^x for the initial investment.

However, we also invest another 50 per year.
so we also add
y = 50 x 1.03^x-1, and y = 50 x 1.03 ^ x -2 ... all the way up to 10.

Combining these together we get

y=1000 * 1.03^x + 50* 1.03^x-1....

Which we can write as a sum, or

y=1000*1.03^x + Sum from r= 1 to r=x-1 of ( 50 times 1.03^ x-r) (given x > 1)

@sick ibex

[vagrant grail]

Knowing that tan(a+b)= -2 and sen(a)=(4-square root of 5)sen(b), for a, b ∈ (0, pi/2), calculate tan(a+b/2), tan(a-b/2) and tan(a+b/2)/tan(a-b/2)

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone heart]

Please don't occupy multiple help channels.

[cinder sundial]

.close

[lone heart]

Channel closed

Closed by @cinder sundial

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torpid dirge]

why is the klein bottle homotopy equivalent to S1 wedge S1 wedge S2

[torpid dirge]

https://math.stackexchange.com/questions/366199/show-a-subspace-formed-by-a-klein-bottle-is-homotopy-equivalent-to-s1-vee-s1

i found a series of steps here but im confused about what is happening in the bottom part that lets us end up with a loop in the sphere?

i got it nvm thanks if u tried

.close

[lone heart]

Channel closed

Closed by @torpid dirge

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torpid dirge]

hi

[torpid dirge]

back to this, actually, isnt the first to second diagram not a homotopy as f1 in the first diagram is meant to be a hole and it disappears?

.close

[lone heart]

Channel closed

Closed by @torpid dirge

Use .reopen if this was a mistake.

[torpid dirge]

i got it

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone heart]

Please don't occupy multiple help channels.

[nimble elk]

would someone be willing to solve and explain this problem?

my online homework assesment counts where i put (8/5)x - (54/5) and the one below it as wrong

I was wondering how to find the correct formula

could you explain how to find the correct formula by any chance?

I'm going based off of the y=mx+b formula

ok thank you so much kind soul

yup!

thank you! would the same apply for the second function?

thank you!

[lone heart]

@nimble elk Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fleet elbow]

how do i do this

[torpid dirge]

do u know trig

[fleet elbow]

yeah

[fleet elbow]

yea

[torpid dirge]

draw this as a right angle triangle with two short sides being parallel to the x and y axis

u know an angle and hypotenuse so u can solve for the x and y lengths

[fleet elbow]

so would the y component be 1.7?

cause sin(30) = y/2

[torpid dirge]

arent u supposed to find the x component

[fleet elbow]

would the x be 1?

[torpid dirge]

yea

[fleet elbow]

then would y then be 1.7?

[torpid dirge]

i guess

u probably need more sf

digits

[fleet elbow]

ok thanks

[errant pine]

Let it be sqrt(3), no need to transform it like this ig

[lone heart]

@fleet elbow Has your question been resolved?

[fleet elbow]

wait this was wrong tho

[fleet elbow]

<@&286206848099549185>

[torpid dirge]

-1

[fleet elbow]

how did u get that?

[torpid dirge]

well

u got the magnitude

[fleet elbow]

yea 2

[torpid dirge]

it does say clockise from the negative x axis

i mean y axis

[fleet elbow]

how do u orient the triangle like that ?

[torpid dirge]

draw it

[fleet elbow]

can u give me an example how to draw it

[torpid dirge]

the red one is the one u want to find

in this case its negative as its pointing backwards

[fleet elbow]

Thank u

[torpid dirge]

welcome

[fleet elbow]

.close

[lone heart]

Channel closed

Closed by @fleet elbow

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sleek gyro]

please dont ping moderators for math help

and read #❓how-to-get-help on how to use the helpers ping

[fading citrus]

lol

[sleek gyro]

ok bye

.close

[tardy stag]

sigh

[lone heart]

Channel closed

Closed by @sleek gyro

Use .reopen if this was a mistake.

[fading citrus]

epic gamer moment

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rigid patrol]

help

[alpine sable]

With what?

[lone heart]

@rigid patrol Has your question been resolved?

[rigid patrol]

oops sorry

can someone help me for C please

i dont under stand for C

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tough citrus]

Can someone help me with ratios I can't do them at all

[alpine sable]

we cant understand answell

[tough citrus]

Wait I'll translate

6 years ago the ratio of Aldi and Dadang's age was 5:4. If the sum of their age now is 30 years, take a look at these declarations:
(I) Aldi's age now is 16 years
(Ii) Dadang's age 3 years to the future is 17 years
(Iii) The ratio of Aldi and Dadang's age now is 8:7

[alpine sable]

uh

let their present ages

be some x and y

[tough citrus]

Yes

[alpine sable]

If aldis age is x

And dabangs is y

Then (x-6)/y-6 =5/4

[tough citrus]

Uh huh

[alpine sable]

and x + y = 30

[alpine sable]

It says 6 years ago ratio of their ages is 5/4

[tough citrus]

Yeah I see I see

[alpine sable]

it means you have to subtract 6 from x and y

[tough citrus]

Yep

[alpine sable]

since we have taken x and y as present ages

solve the above two equations

[tough citrus]

X = 11; y = 10

Is this right?

[alpine sable]

no

x + y = 30

[alpine sable]

simplify this

you can't assume solution@tough citrus

you have to solve both equations simultaneously

i think it has been taught to you how to solve them

[tough citrus]

Wait

Where the hell do I start??

I haven't been taught this

[alpine sable]

Solve the equations

eliminate one variable to obtain the other

[alpine sable]

Thats stupid

you were probably taught this before you were assigned those problems

[tough citrus]

Yeah either it's that or I forgot since I haven't done ratios since grade 5 and now suddenly it's asking me about ratios

Is it like (x-6) /(y-6) = 5/4

Is this the same expression?

[alpine sable]

yes

and x + y = 30

since sum of their ages is given as 30

so put y = 30-x

[alpine sable]

in this ratio

and solve for x

you will get (x-6)/((30-x)-6)) =5/4

now you can find x

then once you find x

y is just 30-x

[tough citrus]

X = 16

Y = 14

Right?

[alpine sable]

yes

right

[tough citrus]

Well then the declaration of 1 and 2 is right

For the ratio

16:14

8:7

?

[alpine sable]

yes

[tough citrus]

Okay then that means all of them is right

Thank you

[alpine sable]

yw

[tough citrus]

. Close

[alpine sable]

.close

do this

[tough citrus]

Omg my keyboard lmao

.close

[lone heart]

Channel closed

Closed by @tough citrus

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

how do i solve these kind of questions

Do you know what polynomial division is?

yeah

is there anyway to do it on desmos?

I don't think so

[alpine sable]

Can you tell me what it is, then?

[alpine sable]

just like normal division, but we divide the polynomial by here in this case m+1

[alpine sable]

What does it mean to say that f divided by g is q with remainder r?

q is the quotient

g is the divisor

What does that mean exactly?

[alpine sable]

i got no idea

you wanna do vc?

it will be easier

I cannot do that

[alpine sable]

But it's good that you recognize you don't know what it means. Understanding what it means is the first step in order to be able to understand and solve the question

Anyway, we say that $f$ divided by $g$ is $q$ with remainder $r$ iff $f = gq+r$ with $\textrm{deg}(r) < \textrm{deg}(g)$

[ocean seal]

Bequi

[alpine sable]

And it can be proven that such q and r exist as long as g is nonzero

whaaat

wtf

[obtuse oak]

Hello👋

i'm new

[alpine sable]

That's the definition of division

[obtuse oak]

anyone?

[alpine sable]

Welcome to the server, but unless you want to help phelpsphelps you should go into another channel

[obtuse oak]

🆗

[torpid dirge]

its.. trivially 0

they already put it in a nice form

the question

[alpine sable]

how

yeah 0 is the correct answer

HOW

[torpid dirge]

lets work with numbers instead

whats the remainder when we divide by 13 of

[alpine sable]

can anyone of you join in the voice chat and i can try to do it on the whiteboard?

it will be way easier

😭

[torpid dirge]

(11283883)*(13)

[alpine sable]

11283...

that

1st

[torpid dirge]

no its 0

[alpine sable]

bro hwo

how

[torpid dirge]

when dividing by 2

the remainder of 0 is?

whats the remainder when we divide 0 by 2

[alpine sable]

0

that 112838,,,,,, is the quotitent?

not the rimeinrder

?

@torpid dirge

[torpid dirge]

yes

[lone heart]

@alpine sable Has your question been resolved?

Channel closed

Closed by @teal chasm

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[old flume]

c and d

[strange heath]

so

what way u want it

u can list out different primes b/w 1 and 30

and then add and subtract them

or

u can just think

thant any prime no. is of the the form 6k+1 and 6k-1

so let the no.'s be 6k+1 and 6n+1

so their sum is

6k+1 + 6n+1 = 6k+6n+2 = 2(3k+3n+1)

and difference is

6k+1-6n-1 = 6k-6n= 6(k-n)

so the no. is not a multiple of 2 ,3 , 6

that should narrow it down ig

one such no. is 25 = 5x5

shit its wrong

i just asked gpt

sorry

[foggy copper]

waht

[old flume]

Hits 23

Its 23 but i can not give a simple explanation of the answer

[strange heath]

what grade u in

[cedar kelp]

!nogpt

[lone heart]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[strange heath]

oh i didnt know

sorry

[mortal trellis]

well there arent many options to write an odd number as a sum or difference of two primes

[lone heart]

@old flume Has your question been resolved?

[strange heath]

if we take a look at the difreence of 2 primes

it is always a multilple of 6

or leaves a remainder of 2

if we take a look at sum

then it is always a multiple of 6

or leaves a remainder of 2 and 4

[old flume]

9

[strange heath]

so from this

we can say

the sum and diffrence of 2 prime no. is either of the form 6k , 6k+2 or 6k+4

nvm

why u getting such problems

[woven hornet]

I don't think anyone can make sense of whatever you're trying to say here

[strange heath]

ik

[woven hornet]

@old flume You may want to look in to twin primes

[strange heath]

🙂

[old flume]

idk dude

[woven hornet]

On top of that you might want to note that the difference between two primes (excluding 2) is always even

[old flume]

I think I am supposed to solve this problem using the trial and error method. the problem has been titled an investigation

[old flume]

any other notes

[woven hornet]

Well if the difference between two primes is always even then what does that tell you about which of the two methods you can use to construct 23?

[woven hornet]

This is just saying that the difference between two primes is always even but in a stupid convoluted way. If you're aware that you're spouting nonsense then can you please not?

[old flume]

Which is the only natural number from 1 to 30 that** cannot** be expressed either as the sum of any two different prime numbers or as the difference between any two different prime numbers? the problem says cannot so the number has to be a odd number right

what I am trying to say is that the difference between 2 primes is even then the answer has to be a odd number right

[woven hornet]

If the difference between two primes is even then you can't use the difference between two primes to construct 23

[old flume]

we have to find a number that cant be constructed with the difference of 2 primes

[woven hornet]

You already know that the answer is 23. You're just trying to prove it now, right?

[old flume]

exactly

[woven hornet]

So we're not trying to find anything here

[woven hornet]

So that just leaves you with a sum. Now we know that two odd numbers sum to an even number, so what does that tell us about how we can construct 23?

[old flume]

so that means the 2 numbers are not even isit

one is even and one is odd then

[woven hornet]

Yes, so what even prime numbers are available to use?

[old flume]

2

[rocky roost]

For the sum of two primes isn't there a conjecture that says that any no above 2 can be expressed as a sum of 2 primes

[woven hornet]

No, consider 23, as we're discussing here

[woven hornet]

And is 23-2 a prime?

[old flume]

no

[woven hornet]

And all that proves that there are no prime numbers that fulfil the conditions for 23

[rocky roost]

Ahh ok it's only valid for even no

it is the goldbach conjecture just looked it up mb

[old flume]

proving 23 is the right answer.

[rocky roost]

It's easy since every prime greater than 2 is odd and the sum or diff of odd no is even

So every odd no would satisfy your list other than those which are of the form prime +2 or prime -2

And ofc no even no would satisfy your list since we have the goldbach conjecture with us

Did I say something stupid why is there a silence over here

[old flume]

we already got an understandable answer and your answer is not proving it wrong that's why

[rocky roost]

So u have already solved the prob

[old flume]

yes

[rocky roost]

oh then close the channel what's the debate about

[old flume]

idk how to

[rocky roost]

.close

[old flume]

.close

[lone heart]

Channel closed

Closed by @old flume

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twilit temple]

Can anyone help me me and my friend kept debating about this fibonacci problem, my answer is 21 and her is 34. She said that the mother cow is included.

[twilit temple]

If a cow produces its first female calf at age 2 years and produces another female calf every year after that, how many female calves are there after eight years if we start with one newborn female calf and no calves die?

Im having 2nd thoughts rn whether its 21 or 34

[tacit arch]

can you show your work

[twilit temple]

Thats my table

[junior kraken]

How many initial 0 yo cows you start with ?

[twilit temple]

Thats where im confused ab

As far as i know we start with 1 calf whos 0 yrs old

But my friend said that the mother cow is also included

[junior kraken]

That makes a great difference

!xy

[lone heart]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[twilit temple]

Here is the original problem

[livid sage]

i believe the correct interpretation is 34

if the calf is newborn, then after 1 year, there will be 1 cow, but after 2 years, there will be 2

following this, after 8 years, there will be 34

[twilit temple]

But if its 34 then it doesnt really go with fibonacci table

Wait lemme explain further

[livid sage]

sure

[lone heart]

@twilit temple Has your question been resolved?

[twilit temple]

Oh wait nvrm imma hustle ask my teacher becaause its not clear wether there is a mother cow or not

[lone heart]

Channel closed

Closed by @twilit temple

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kindred atlas]

$\frac{2x}{x+3} = \frac{2x-3}{x}$ -- Solving for X

First I got like denominators...

$\frac{2x^2}{x^2+3x} = \frac{(2x-3)(x+3)}{x^2+3x}$

Then I multiplied the numerator on the right side for $2x^2+3x-9$ and subtracted it from both sides for $\frac{2x^2 - (2x^2+3x-9)}{x^2+3 x} =0$ which left me stuck with

$\frac{9-3x}{x^2+3x}=0$

[ocean seal]

smeagol

[kindred atlas]

Base problem

[long axle]

why didnt u just cross multiply

[kindred atlas]

I started with that

$\frac{2x^2}{x^2+3x} = \frac{(2x-3)(x+3)}{x^2+3x}$

[ocean seal]

smeagol

[long axle]

no, dont make common denominators

just cross multiply

[kindred atlas]

oh so

[buoyant saddle]

what’s good gollum

[kindred atlas]

$2x^2 = (2x-3)(x+3)$

[ocean seal]

smeagol

[kindred atlas]

that's still equal?

[buoyant saddle]

so long as x≠0 or -3

[kindred atlas]

struggling to review algebra

[buoyant saddle]

https://tenor.com/view/nsza-gif-26558816

[buoyant saddle]

you’re doing great

[kindred atlas]

i forgot so many rules XD

[buoyant saddle]

what do you think you should do next

[kindred atlas]

simplify the left into one number

[buoyant saddle]

hmm you mean the right?

[kindred atlas]

2x^2+3x-9

[buoyant saddle]

distribute on the right

[kindred atlas]

yeah right

[buoyant saddle]

then what happens to the 2x^2

[kindred atlas]

then 0 = 3x-9

9 = 3x

x = 3

[buoyant saddle]

good

and you can always check

[kindred atlas]

but 🏃

[buoyant saddle]

in the original

[kindred atlas]

oh wait -3

[buoyant saddle]

1=1

if you go back to the original

[kindred atlas]

ah makes sense

[buoyant saddle]

https://tenor.com/view/smeagol-smeagol-gif-sméagol-gollum-gollum-gif-gif-3793070065756050443

[kindred atlas]

https://tenor.com/JDTU.gif

thank you have a good one

ignore the happy birthday

[buoyant saddle]

you’re welcome and you as well

[kindred atlas]

just the party

XD

.close

[lone heart]

Channel closed

Closed by @kindred atlas

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lofty burrow]

i know all the steps and stuff but i keep getting lost like halfway through, any tips for problems like these (finding first derivative)

[lone heart]

@lofty burrow Has your question been resolved?

[lofty burrow]

<@&286206848099549185>

[alpine sable]

you first let u = x

and than you let $v = 3 \sqrt{1-2x^{3}}$

[ocean seal]

jl7up~

[alpine sable]

to differentiate that you sue the chain rule

afterwards you do the product rule

[lofty burrow]

where did the x^3 go though

on the outside

[alpine sable]

it stays

[alpine sable]

finally you will be able to get the first derivative

[lofty burrow]

ahh

ok, thnx man

[alpine sable]

dw

im closing this ticket now is it ok

[lofty burrow]

yea go ahead

[alpine sable]

.close

.close

i think only you can close it

cause you opened the help channel

[lone heart]

@lofty burrow Has your question been resolved?

[lone heart]

Channel closed

Closed by @lofty burrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable widget]

Would this be the correct answer?

Looking how other people did a similar problem by merging the integrals, it would’ve probably been way simpler to do it that way

It is what it is tho

[lone heart]

@stable widget Has your question been resolved?

[lone heart]

@stable widget Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tacit arch]

might want to translate if you want help

[lone heart]

@toxic breach Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tacit arch]

help channels are for specific math questions not some test's rules

[lone heart]

@dense lintel Has your question been resolved?

[lone heart]

@dense lintel Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frank basin]

I have a question about probability

[frank basin]

"Four prices will be given away to 20 of the best students at a school, including Euler and Thales. If each student can receive only one price, what is the probability that Thales or Euler is in the random group?"

I don't seem to be able to count the favourable cases

F stands for "favourable"

It doesn't work out, I don't know what I'm doing wrong

[junior kraken]

It's better a question, how can we select 4 students including Thales or Euler

So let's say how many ways can we select 4 students?

20c4

Now let's consider Euler is in the group

How many ways can we select remaining 3 excluding Thales ?

18c3

Similarly a case where Thales is in group but not Euler

Is 18c3

Now a case where both are in group

So remaining 2 in 18c2

So the probability should be , (2×18c3 + 18c2)/(18c4)

[junior kraken]

Heyy !

[frank basin]

But why doesn't my method work?

[junior kraken]

For that , i would like you to explain it

[junior kraken]

I would also recommend to check , if the method I mentioned gives you correct answer

[frank basin]

Considering the fundamental theorem of counting, I have to choose one of the two guys, so I take them with my factor 2

Then, I have to choose three other people out of the 19 I have left

Then, I divide by 4! because the order doesn't matter

[junior kraken]

19 left ?

Are you sure ?

Won't it be counting the same cases twice ?

Like Euler Thales , Thales Euler ?

[frank basin]

I don't think so, since I only took one away in the first round

[junior kraken]

One moment

,calc 21819*17/24

[ocean seal]

Result:

484.5

[junior kraken]

,w (2×18C3 + 18C2)

,calc 816*2 + 153

[ocean seal]

Result:

1785

[junior kraken]

,calc 21918*17

[ocean seal]

Result:

11628

[junior kraken]

,calc 11628/6

[ocean seal]

Result:

1938

[junior kraken]

,calc 1938 - 153

[ocean seal]

Result:

1785

[junior kraken]

So I said you're considering same cases twice , also we can't divide by 4! Like that !

[junior kraken]

153 == 18c2 overlaping region

[frank basin]

Sorry, I don't understand some of the symbols you are using lol

[frank basin]

Like, I thought we could do it this way because of that question with clothes and stuff

[junior kraken]

Nah it's always better to use combinations in this kind of problems

Also is the answer i found correct?

[frank basin]

Sorry, which of these numbers is the answer?

This is the answer

[lone heart]

@frank basin Has your question been resolved?

[frank basin]

Ok, I think I get it

There are multiple randomizations

The probability universe gets shorter and shorter

The way I did was if it were simultaneous

[lone heart]

@frank basin Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torpid tree]

hello can i just know if i have done this correct

[torpid tree]

these are the steps i am not sure about

2^12.3^12.2^22.3^11-3^11.2^5.2^16

3^72.2^11-3^16.2^8.3^24

the fulstops are multiply

i am not very good at english

[fallen carbon]

ok what is the goal of the exercise

to factorise

[torpid tree]

yes

i just want to know if its correct

[fallen carbon]

ok this might be wrong

bc u can't factorise like tht

[torpid tree]

can you explain please

[fallen carbon]

a^(c)-b^(c) is not equal o (a-b)^(c)

[torpid tree]

ok

so the last step is wrong right

[fallen carbon]

try to pass by a^(m) x b^(m) = (ab)^(m)

yes

[torpid tree]

oh ok ill try

2²¹ X 3¹⁰ X (2¹³ X 3¹³ - 1) is it something like this

[fallen carbon]

like this ye

[alpine sable]

can anyone help me with geometry 🙏🏼🙏🏼🙏🏼

[torpid tree]

thx ok i got it

[alpine sable]

i need like 4 other ones including the one i sent

[torpid tree]

thank you very much

[fallen carbon]

go find another lobby@alpine sable

[torpid tree]

no its ok i just needed it to know if it is correct

so thank you very much

cya

.close

[lone heart]

Channel closed

Closed by @torpid tree

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

whoops

[fallen carbon]

now u can here it's finished

[alpine sable]

alr thank youu

[fallen carbon]

what is ur problem ?

[alpine sable]

im trying to do some problems but idk and i give up and i just need answers🙏🏼😭

[fallen carbon]

i understand it's late

[alpine sable]

my assignment is called algebra when measuring segments and angles

[pseudo ice]

!noans

[lone heart]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[alpine sable]

whoops

[fallen carbon]

ye OK ik

[fallen carbon]

can u do screenshot pls

[sharp abyss]

yeah the quality is not that good

[alpine sable]

my camera is broken but sure ill try😭🙏🏼 there sending

[fallen carbon]

ok what is m

[alpine sable]

m?

[fallen carbon]

yes in the ratio m/TQS

m/BCE

m/RSQ

m/HEJ

whatever do u know what equals a right angle (in °)

and a demi-circle ?

pls be quick or i'll leave it

i leave

if u need it a right angle equals 90° and a demi-circle 180°

i let u with this

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[toxic light]

hi, we were assigned to create a cone out of this graph, then find the equation of the planes that made the conic sections on the cone, as if they were flat.

[toxic light]

The result looks something like this:

[tacit arch]

neat

[toxic light]

the problem is that we have to find the equations of the planes (the graphing paper slit into the cone) as if they were flat

[toxic light]

Thanks!

our teacher explained to us on how to find the first one, the circle

since the cone was 60 degrees at the apex, and the circle's plane is parallel to the base of the cone, it can be thought of as a 60-60-60 triangle with the base of said triangle being the diameter of the circle

and since the distance from the center (apex) to the 2d equation of the circle is 2, the diameter is 2

so the plane's equation would be x^2 + y^2 = 1 (radius is 1)

[toxic light]

however i dont know how to translate this information to the rest of the conic sections

(this assignment is from our precalculus class)

Are there some things I could try to find out the equations of the said planes?

[lone heart]

@toxic light Has your question been resolved?

[toxic light]

<@&286206848099549185>

[toxic light]

<@&286206848099549185>

[lone heart]

@toxic light Has your question been resolved?

[patent onyx]

tsup

[toxic light]

Hi 😭

[alpine sable]

hi

[cobalt shoal]

Do not click this link

how do you submit a report

wait he left lol

<@&268886789983436800> Bruh please delete this it's just a porn link

[toxic light]

<@&286206848099549185>

[lone heart]

@toxic light Has your question been resolved?

[toxic light]

<@&286206848099549185>

[lone heart]

@toxic light Has your question been resolved?

[toxic light]

<@&286206848099549185>

[alpine sable]

Haay

[toxic light]

Heeey

I've been trying to ping for the past 8 hours hahahahah

I still haven't figured it out tho

[alpine sable]

Figure what

[toxic light]

This

[young cargo]

You have 21 cells that can contain a random value of 52 elements. each row contains 7 cells, each column contains 3 cells. what is the probability to have exactly no duplicates in a row. what is the probability of 2 duplicates, 3, 4, 5, 6?

i been stuck on this for too long

[lone heart]

@toxic light Has your question been resolved?

[toxic light]

<@&286206848099549185>

[willow dagger]

<@&286206848099549185>

Can someone help me w this

[calm ingot]

!occupied

[lone heart]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[lone heart]

@toxic light Has your question been resolved?

[neat eagle]

Can someone tell me the answer

[winter light]

!occupied

[lone heart]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[winter light]

@neat eagle read #❓how-to-get-help

[alpine sable]

This answe can have multiple answers since no brackets

It's pretty much depends on the viewer

Even if you apply bodmas that is

[random cargo]

help

how do i tell

[tight pier]

!occupied

[lone heart]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[ebon hill]

Horizontal line test

[upbeat hornet]

The cone's angle here is 90 degrees, but you said the apex angle is 60 degrees. Is this diagram not to scale then?

[lone heart]

@toxic light Has your question been resolved?

[toxic light]

We printed the diagram with the 90 degree diagonal lines, then folded it into a cone so the ends of the curves would meet. It made a 60 degree cone since we could fit a 1-radius circle into the underside of the cone, where the circle's plane would be.

So the diagram and real cone are both accurate

[upbeat hornet]

So the 90 degree cone is before you curled it up?

[upbeat hornet]

Did you measure the 60 degrees accurately

[azure vale]

I got 1

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[granite light]

What is -2^2

[remote heron]

is it $(-2)^2$ or $-2^2$

[ocean seal]

jan Niku

[remote heron]

just to be sure

[granite light]

I'm not sure

[remote heron]

can you share the problem?

[granite light]

O

It table of values and its -2^x

So no brackets?

[remote heron]

that seems reasonable, (-2)^x is a pretty wacky function

so, $-2^2$ is just like $(-1) \times 2^2$

[ocean seal]

jan Niku

[remote heron]

can you simplify the second expression?

[granite light]

-4

[remote heron]

yea

you got it

[granite light]

O I c

So u reckon that (-2)^x would rarely be a question

[remote heron]

it has some unusual properties

it isnt very easy to deal with

but, if x were just some number

like, nice round number

say, 4, or something

then yea

say it were $(-2)^4$

[ocean seal]

jan Niku

[remote heron]

that's just $(-2) \times (-2) \times (-2) \times (-2)$

[ocean seal]

jan Niku

[remote heron]

maybe you can spot what happens here

[granite light]

2^4

[remote heron]

yea

but if it were instead (-2)^3

$(-2) \times (-2) \times (-2)$

[ocean seal]

jan Niku

[granite light]

-8

[remote heron]

yea

[granite light]

Not $2^3$

[ocean seal]

Storm09

[remote heron]

so $-2^n = (-2)^n$ only if $n$ is even, we would figure

[ocean seal]

jan Niku

[remote heron]

if n is not a nice round number, things get fuzzy

[granite light]

Ye

[remote heron]

anyways, hopefully that clears up your doubt

[granite light]

Ok thanks now I understand

.close

[remote heron]

np

[lone heart]

Channel closed

Closed by @granite light

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[queen hemlock]

How do I find a discontinuity in a function? Do they appear when the denominator is 0? For example, if the denominator is (x-1)(x+2), would the x values 1 and -2 be discontinuities? Or is there more to it

[onyx tinsel]

yes

[inner haven]

when the denominator is 0 that would be a infinitity discounty

[onyx tinsel]

also when sqrt(negative)

[inner haven]

Then u can cancel terms that would be a removable discountinity

[onyx tinsel]

or when log(negative

[queen hemlock]

So when there's a (x-1) on the top and bottom, you can remove it?

[onyx tinsel]

and it becomes a hole

[inner haven]

yeah thatll be removable disountity

[onyx tinsel]

instead of inf discontinuity

[queen hemlock]

And infinite discontinuities you can't remove right

[onyx tinsel]

wdym remove

[queen hemlock]

Or I mean, they're not removable

[onyx tinsel]

the same way you remove the factors in top and bottom?

[queen hemlock]

Cause holes are removable I think

[onyx tinsel]

well

yes but no

the factors are still part of the function

but you can remove them to see where the hole would be

where its y coordinate woulf be*

[queen hemlock]

Oh I see

So you can't find the y value for the infinite discontinuity because it goes on forever right

[onyx tinsel]

yeah

[queen hemlock]

Okay thank you

.close

[lone heart]

Channel closed

Closed by @queen hemlock

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx tinsel]

isn't this just finding A with inverse sin(4/5) and finding B from A=3B

[simple wharf]

Uh no

I have to use

Identities and formulas

I know it is 53 degree

They make us remember those stuff

For physics

[onyx tinsel]

i never learnt the ones between pi/6,4,3

but yeah same thing no?

except A=53 instead of arcsin(4/5)

[lone heart]

@simple wharf Has your question been resolved?

[lone heart]

@simple wharf Has your question been resolved?

[tacit arch]

Use double angle formula twice with 3B = 2B +B and 2B = B+B

Should be able to solve for cos(B)

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tepid zodiac]

How to solve this

[lone heart]

Please don't occupy multiple help channels.

[onyx tinsel]

Don't think you can if thats all ur given

[alpine sable]

yeahhhh-what?

[tepid zodiac]

I thought so too, that's why I wrote the algebra

Is the algebra correct

[onyx tinsel]

no

[tepid zodiac]

What's wrong

[onyx tinsel]

wh

why 90x and x

[serene talon]

shouldnt it be 90 - x

[onyx tinsel]

am i misreadin

[tepid zodiac]

Which angle

[onyx tinsel]

C

D*

[tepid zodiac]

It's 90-x

My handwriting is crappy

[onyx tinsel]

no the problem is crappu

crappy

i dont think i can solve it lol

[lone heart]

@tepid zodiac Has your question been resolved?

[tepid zodiac]

.help

[lone heart]

Commands:

• clopen: .close, .reopen
• consensus: .poll
• factoids: .tag
• help: .help
• version: .version

Type .help <command name> for more info on a command.

[tepid zodiac]

.close

[lone heart]

Channel closed

Closed by @tepid zodiac

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frank gate]

anyone can help?

[frank gate]

Cant seem to get to the answer by using this method. Is there smtg wrong?

[uncut surge]

do you know how to find the area of a triangle

just by knowing only its three sides?

no height included

no angle as well

actually nvm (QS) isnt perpendicular with (RP)

[uncut surge]

u can try finding lengthes PQ and QR since PQ/QR = 2/5 and u can replacr QR by 21-PQ to solve for PQ

[frank gate]

wait i calculated wrong 💀

[uncut surge]

o

[frank gate]

.close

[lone heart]

Channel closed

Closed by @frank gate

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strange fractal]

how do i do dis

[winter crown]

!status

[lone heart]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[strange fractal]

i think the picture shows that im stuck on what i do next

[winter crown]

the picture shows the question for god's sake

[junior kraken]

Maxima minima , calculus

[strange fractal]

ewtfruhiewfhuewf

[winter crown]

i dont see anything else

[strange fractal]

this one

[winter crown]

oh ok

[strange fractal]

howww

[winter crown]

i took h as 12-r

[gray isle]

differentiate to determine locations of local extrema
(would've also been less tedious to sub in h=12-r, and avoid expanding that binomial)

[strange fractal]

oh

[winter crown]

and then ig you can differenciate it

[strange fractal]

i dont get how to differentiate pih

is it just 0

[gray isle]

also ensure you have () where appropriate

[strange fractal]

i just want to say thx for all ur help 😭 you have helped me ever since i struggled on factorising

[gray isle]

you'd set the derivative = 0
to determine the location of stationary point(s)

and then determine which of those is your max

[strange fractal]

wait idk how to differentiate it

lemme try

and can u check

[strange fractal]

um.

idk

i got 0...

bc dy/dx of pih is 0

oh wait

i multiply everything first

did I do this right

[gray isle]

poor notation practices

only write V' when you've actually taken the derivative

[strange fractal]

oh\

[strange fractal]

its impossible to factorise

do i use

quadratic formula

[junior kraken]

3 is common

[strange fractal]

I can’t find any factors for 432

[junior kraken]

3h²-48h+144
= 3(h²-16h+48)

[strange fractal]

oh.

[junior kraken]

12 +4 = 16
12×4 = 48

[strange fractal]

I don’t get wat next

[junior kraken]

Now calculate f''(x) and see

For which value of x ,

f"(x) <0

It will give you maxima

[gray isle]

identify whether both values make sense in the context of the problem

[strange fractal]

i dont get it 😢

[gray isle]

does it make sense for h to be 12 here?

[strange fractal]

oh no?

cause 12-12 is 0

[gray isle]

yes

so you can disregard that value

and focus on the h=4

also where is this coming from

[strange fractal]

um..

i was trying to find trhe maximum 😭

[gray isle]

applying what?

[strange fractal]

minimum and maximum..

of a parabola...

....

[gray isle]

you're applying that to the derivative which doesn't really help you

[strange fractal]

ohh yh

cause derivative is just a slope

gotcha

[lone heart]

@strange fractal Has your question been resolved?

Channel closed

Closed by @strange fractal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[formal wraith]

Hey there!

[formal wraith]

So basically my problem is when resolving the right part, once I get to multiplying the equation I get something wrong:

I use 1/yx as it's the reciprocal of yx/1

and chatgpt says that the reciprocal is:

and that the expression becomes:

[formal wraith]

Why this is equal?

[heavy delta]

u can think of y dividing the fraction in the denominator, so it should be the numerator multiply with the reciprocal of the denominator
(-y) multiply with yx/(x^2+y^2)

the y doesnt cancel out

[formal wraith]

what

[heavy delta]

its therule when dividing a fraction, we consider it as multiplying the reciprocal of the fraction

[formal wraith]

I mean, even though if I do it this way:

[formal wraith]

Yeah, I know, but why he took the reciprocal of the denominators?

[formal wraith]

I always do it like this and worked

[heavy delta]

no, the (x^2+y^2)/yx is considered as a whole thing

in this case

u cant separate them

[formal wraith]

why?

[heavy delta]

a/(b/c) not equal to (a/b)/c

[formal wraith]

but if you imagine there is a 1 as denominator to yx, can't you do:

(a/b) / (c/d)?

[heavy delta]

cuz it come from (x/y+y/x)

[formal wraith]

aaaaaaaaaaaaaah

yeah

its like a "separate term"

yeah

[heavy delta]

yes

[formal wraith]

okay okay

I got it

[heavy delta]

finally u get it, i was strugglin on explain these basic stuff lol

[formal wraith]

hahahahha

[heavy delta]

cuz i am so used to just doing it without thinking the reason

[formal wraith]

hope i get there one day lol

thanks for the explanation

have a great time

.close

[lone heart]

Channel closed

Closed by @formal wraith

Use .reopen if this was a mistake.

[heavy delta]

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eager kraken]

Help plz

[gray isle]

!status

[lone heart]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[gray isle]

is this the first time you're seeing this notation?

has your teacher gone through any notes on this?

[eager kraken]

Nope but I just dont know where to look to find the answer

[eager kraken]

only spoke in domain and range graphically for algebra

[gray isle]

lets start with a)

[eager kraken]

oki

[gray isle]

the - in superscript indicates the direction you're taking the limit

which means you're interested in what f(x) is approaching as you approach the x-coordinate of 2 from the left side

[eager kraken]

ohhhhh ok

[gray isle]

^+ for the right side

[eager kraken]

so - is for left

okay

[gray isle]

and if there's no sign, you'd need to consider both (if its possible to approach from both sides)
and see if they match

[eager kraken]

Oh

Im little bit confused in that to be honest

because how will i know which number if u have to look at both

[gray isle]

well you'd first consider the one sided limits
if you get different values then the limit doesn't exist

[eager kraken]

Oh

[gray isle]

(don't 50:50 it)

[eager kraken]

Okay I guess when we get to that one ill try to see

[eager kraken]

yeh that what i was thinking 😂

Ok so for a) we look at 2 from x axis right on left

[gray isle]

its better to place your arrow along the graph of you function

[eager kraken]

Ohh ok

[gray isle]

to indicate that you're following along the curve

[eager kraken]

Like this way?

[forest marsh]

No

[eager kraken]

Oh

[gray isle]

no

[forest marsh]

Like at the red line

[eager kraken]

Ohhhhh

is it ok if you can show me please

[gray isle]

on the actual curve, not the axis