help-0

[cinder goblet]

thank you

[lone heart]

@cinder goblet Has your question been resolved?

[lone heart]

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[floral oxide]

help

[floral oxide]

So I have an exam soon and I dont understand proofs at all

I dont understand anything about it except how you start with given or something

<@&286206848099549185>

[fervent kestrel]

!status

[lone heart]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[fervent kestrel]

also, what is the exact question(s)?

[floral oxide]

Its just prrofs in general that doesnt make sense

you know, triangles, transversals, those things

[lethal crag]

yooo we have a similar username

I might be able to help, I'm not very good at proofs

Any specific problems?

[floral oxide]

yoo twinning

[lethal crag]

🔥🔥

[floral oxide]

Also let me see

This is just a boot camp ppt from my teacher

so it has the answer

but Im not good at it either

[lethal crag]

Yeah, what problems do you have

I can show you how to solve

[floral oxide]

some of it is glitch sadly too

but i have the paper so ill say what it is

[lethal crag]

Ooh kk

[floral oxide]

the 4th one is LM=KM

its segment

[lethal crag]

Alright, what parts of this proof do you struggle with understanding?

Which parts do you need clarificationo n

[floral oxide]

like the 2nd one

[lethal crag]

Ok, when it is a perpendicular bisector it will always make 2 right angles with the line that it is bisecting

What else?

[floral oxide]

ohh ok

[lethal crag]

AB is a perpendicular bisector of XY

[floral oxide]

the 5th one?

[lethal crag]

If you have a segment AB

AB will always be equal to AB

AB will always be equal to BA

[floral oxide]

mmk

[lethal crag]

You got it?

[floral oxide]

theres this one slide

ill send a pic

[lethal crag]

Kk

[floral oxide]

the second one is m<TUR+ m<PUR= 180

[lethal crag]

TR is a line, and a line will be 180 degrees

so the angles that add up to that line will add up to 180

[floral oxide]

the third is:
m<TUR = 2 x mTUS
m<PUR= 2 x mPUQ

x is to multiply and the < is angles

[floral oxide]

oh ok

[lethal crag]

US bisects TUR so TUR has been split into the halves TUS and SUR

so 2xTUS=TUR

Same thing with the other angle

[floral oxide]

ph ok

Makes sense

Thank you so much twin

[lethal crag]

No problem 👍👍

[floral oxide]

Ur in college?

[lethal crag]

Nope

High school

Wbu

[floral oxide]

Middle but in geo hon

[lethal crag]

Nice

[floral oxide]

what math you taking?

[lethal crag]

Precalc

[floral oxide]

so 11th?

[lethal crag]

Nope but I'll just say I'm in high school

[floral oxide]

ight

[lethal crag]

Alr if you don't need any more help make sure to type ".close"

good luck with math

[floral oxide]

thanks

you too

.close

[lone heart]

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[hushed dove]

Hello, can somebody explain what such notation can mean?

[mortal magnet]

this means "multiplying the scalar sx by the vector (sz0, cz0) is equal to the vector (r02, -r12)"

[hushed dove]

Thank you so much good man ❤️

[mortal magnet]

np

[hushed dove]

If you would like to help more, are you able to explain me it, I completely don't understand what is the sense of it

[lone heart]

@hushed dove Has your question been resolved?

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[undone sun]

Hi, Please help, <@&286206848099549185>

[fresh mist]

does anyone know how this has been solved?

[reef pier]

what are you trying to find?

banking angle?

[fresh mist]

I just might have to prove how to solve this in an exam but dont know how he got from step 4 to step 5

[alpine sable]

fairly sure they just divided evreything by Mgcos(alpha)

[fresh mist]

yes tried this and then somehow another g has appeared

[reef pier]

i don't see where the other g has appeared, they've exactly divided by Mgcos(alpha)

v^2 / gR as expected

the Mgsin becomes tan

the parentheses become (1 + v^2 /(gR) * tan(alpha) and expanding gives mu + mu * v^2 / (gR) tan(alpha)

[alpine sable]

i think this is an error on your part

[alpine sable]

i agree

[fresh mist]

yes this is what it comes out as apparently :))

[undone sun]

.close

[lone heart]

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[static harbor]

A rectangular prism's length is doubled, while its width and height remain constant. How does this affect the surface area?

[summer dirge]

think about the simplest example of a rectangular prism, which is a cube

for a cube, the length, width, and height are all the same

[static harbor]

yeah'

[summer dirge]

try drawing a cube, and then the cube with doubled length (which is now a rectangular prism)

[static harbor]

ok

i did

[raven dagger]

You can't really find a direct proportionality tho can you?
As some sides remain unchanged and some change

[static harbor]

i drew it

now what

@summer dirge

[summer dirge]

actually, I'm unsure now

I don't think there is a direct proportionality after all, like 2 3 5 7 said

[tardy stag]

do some examples

[summer dirge]

if you double all the dimensions, there would be

[static harbor]

i have to only double the length

[summer dirge]

let me get a piece of paper

[static harbor]

thats what the questions saying

and width and height stay constant

[summer dirge]

the SA doesn't seem to change by a constant factor

[tardy stag]

but does it change by a function of the width and height?

[summer dirge]

indeed it does

[tardy stag]

idk just write out the SA before and the SA after and subtract

[static harbor]

A rectangular prism's length is doubled, while its width and height remain constant. How does this affect the surface area?
this is the exact question

[tardy stag]

use L, W, and H for variables

[summer dirge]

I guess yeah, that would be the strategy

[static harbor]

<@&286206848099549185>

[raven dagger]

Well for general prisms you don't even know how many sides it has

[summer dirge]

I suppose you have to write out an explicit expression for the initial surface area, and for the new one after the length is doubled

that should be our first step

[raven dagger]

And which sides are parallel to the width and which are parallel to the hight

[static harbor]

???

its a rectangular prism

[summer dirge]

but we're talking about rectangular prisms lol

[raven dagger]

Oh
I thought the rectangular prism was an example

Nvm the example was a cube

[static harbor]

??

did anyone figure it out

this is what chat gpt says

and this

[tardy stag]

it's not quite right

but

[static harbor]

then can u help

[tardy stag]

if you read it and use your brain

then you can identify what makes sense and what doesn't

[static harbor]

so can you help

[raven dagger]

Well finding it interms of h and w is the only option then because you can't do better

[static harbor]

cuz i cant identify

[tardy stag]

not if you're not willing to put in the effort.

[static harbor]

i am very willing

ive been trying at this for 30 min

please hayley

[tardy stag]

what is the original surface area of the prism?

answer in terms of W, L, and H

[static harbor]

2lw+2lh+2wh

[tardy stag]

great, now if we replace L with 2L, then what is the new surface area?

[static harbor]

4lw+4lh+2wh

[tardy stag]

okay, and what's the difference between those? like if you take the "after" and subtract the "before"?

[static harbor]

2lw+2lh?

[tardy stag]

yeah great

so that's how much the surface area grows

[static harbor]

so can i write as the length of the rectangular prism doubles the surface area grows by 2lw+2lh

[dreamy scroll]

I need halp

[raven dagger]

Yes
You could also represent the growth as a ratio instead of a difference depending on your requirements

[raven dagger]

#❓how-to-get-help

[lone heart]

@static harbor Has your question been resolved?

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[sharp river]

Can smeone help me with this question? I don't understand waht it means by whether the function is continuous in the interval (-∞,∞)

[median oar]

If you can make the denominator 0

[restive pumice]

Okay well, a function isn't continuous where it is undefined

[median oar]

It’s definitely not continuous there

[sharp river]

I just dont understnad the infinity

[median oar]

If you have a log and can make the inside 0 or negative

Also not continuous

If you have sqrt and can make the inside negative

Also not continuous

[restive pumice]

Its basically saying "Is the function continuous for every x?"

where x ranges from -infinity to infinity

[median oar]

That’s pretty much the main ways a function can be discontinuous/undefined

[sharp river]

Oh I thought it was giving me coordinates like (x,y) 🤦‍♂️

oh ok thanks guys

since there's a discontinuity, it's not continuous in the given interval

right?

[restive pumice]

yup, and its discontinuous at the x value that makes it undefined

[sharp river]

kk gotcha, thanks guys

.close

[lone heart]

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[lone heart]

@alpine sable Has your question been resolved?

[shadow coral]

yeah

have u learned

the circle chord theorem

any like that goes from the centre of a circle to a chord that splits the chord in half makes a right angle

amazing diagram

[lone heart]

@alpine sable Has your question been resolved?

[shadow coral]

sorry next time ping me 😭

[lone heart]

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[errant torrent]

Whats the answer?

[errant torrent]

The video says the answer but i don't think it's right so I want to see what others think

[summer arch]

i think its D

it cant be A or B cause its not increasing

and since its concave down its gonna be decreasing at a decreasing rate

[pseudo ice]

"increasing at an increasing rate"

[untold crane]

Agree with you

[errant torrent]

help 💀

I thought it was D

and the video said it is C

and i commented it and now the owner of the channel is telling me its still C

even D is right

[restive pumice]

is this supposed to mean velocity vs acceleration and all that?

decreasing meaning slope is negative, decreasing again meaning acceleration is also negative?

[errant torrent]

bruh idk

[untold crane]

Yes exactly

[restive pumice]

I would think it’s decreasing at a decreasing rate because it’s decreasing.. and the rate at which it is decreasing is decreasing

[untold crane]

The owner is just wrong here

The concave argument you gave is the only good argument

Not the only but it’s the definition of concave

Oh no my bad

But it’s just so poorly worded

[restive pumice]

Like if you had a vertical asymptote, the function would obviously be increasing at a increasing rate as it goes right

So it would make sense that with a horizontal asymptote, a function would be decreasing at a decreasing rate as it goes down

[untold crane]

It’s decreasing at a increasing rate bc at the beginning it decrease at a rate of let’s say -6 and at the end it’s decreasing at a rate of 0

So the rate is increasing

[restive pumice]

didn’t you just point out that function is decreasing at a decreasing rate though

[untold crane]

I was wrong before

[restive pumice]

Oh because the rate is technically negative

[untold crane]

Here I point out that the rate is increasing

[restive pumice]

so in a sense it’s increasing

[untold crane]

Yes I canceled out the minus in my head too bc of the way it was worded

[lone heart]

@errant torrent Has your question been resolved?

[lone heart]

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[grizzled hemlock]

1+1?

[tardy stag]

1+1 = 2 day mute, please don't troll in help forums

.close

[lone heart]

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[torpid ember]

that was a zinger

[lone heart]

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[mellow pendant]

How would I find the volume for Part C? @ me when whoever responds

[valid token]

for each individual dx that you take, multiply that dx by dx*5

and integrate it over interval

@mellow pendant

so the integral would be

gimme a sec

smth like this @mellow pendant

ping when ur back

[mellow pendant]

@valid token wait so is what I did just wrong?… and why would it be from 0-1 instead of .239?

Since it asks for the region R

[valid token]

because im stupid

and illetrate

and have dyslexia

and cant read

😭

this is why im getting a 4 frfr

[mellow pendant]

…

💀

[valid token]

ye its .239

ur right

bro i swear time flys

[mellow pendant]

I got $80 on the line for a 5 on AP calc im cooked

[valid token]

it was 11:10 5 min ago

[valid token]

💀

u got this

[mellow pendant]

I been studying for the last 3 hours

I’m cooked bro

[hot hatch]

Hey

[mellow pendant]

Hello

[hot hatch]

So you need part c

Lemme see if I can solve

[valid token]

i just did 😭

u got this tho

[glacial raptor]

What does part b says, I cant understand

[valid token]

find the volume when you spin it around x =1

[mellow pendant]

Y=1*

Horizontal not vertical

I think

[valid token]

im illetrate, as previously stated

[mellow pendant]

💀

[valid token]

😭

pray for me on the test

[mellow pendant]

Praying for both of us 🙏🙏

[glacial raptor]

Revolving 90°?

[valid token]

you have to use disc method of integration

[mellow pendant]

^

[mellow pendant]

I think I did it right…

I’m not sure tho but

[valid token]

lmao

[glacial raptor]

I want to know about geometrical representation of it

[valid token]

as long as you get the general idead ur good

[hot hatch]

Then ?

[glacial raptor]

How would the shape look like

[valid token]

plug it in

@hot hatch

[valid token]

smth like that

idk

im big dumb

[valid token]

for this

change from 0 to .239

[glacial raptor]

Ohk Thanks

[valid token]

ru taking the calc exam 2mrrw also?

this doesnt really matter for the exam

[glacial raptor]

Nope

[valid token]

🫡

ur safe then xd

[mellow pendant]

Imma be so lost on the test tmr imma get cooked

[glacial raptor]

You guys have a test tomorrow,?

[mellow pendant]

AP test for calculus AB is tmr

[valid token]

🤝

[valid token]

bc for me

😭

[mellow pendant]

😭

My school doesn’t offer BC imma have to take stats next year

😵‍💫

[valid token]

🫨

not taking stat

actually

maybe for senior year

idk

what grade u in?

[mellow pendant]

Junior atm

[valid token]

sophmore for me

[mellow pendant]

Wait ur taking calculus as a sophomore I don’t think I could handle that when I was a sophomore

😭

[near pebble]

oh yeah
is shell method on the bc thing💀

[valid token]

its light bro

[near pebble]

js totally forgot arc length and surface area

[valid token]

😭

[near pebble]

yoo i am too🔥

[valid token]

we dont need htat

[valid token]

ur also taking the exam?

🔥

[near pebble]

yes

my school is so sweaty
kid got a 100 last year

he also coincidentally is my neighbor

neighbors kid

[mellow pendant]

My school is the opposite of sweaty 👨‍🦯👨‍🦯

[valid token]

its out of 108 😭

[mellow pendant]

@valid token do you know who to solve this one?

[valid token]

my neck hurts 😭

yes

just please

rotate

🙏

uhh

dont you use the formula

one sec lemme solve it rq

[hot hatch]

,rotate

[ocean seal]

Couldn't find an attached image in the last 10 messages.

May 13, 2024, 4:02 AM

[mellow pendant]

Sending

[valid token]

🙏

tx

first find anti deravitive

ur given basecase

one sec

im dumb

lemme find antideravite

cause im dumb

[mellow pendant]

Ur gud im solving some FRQs rn

[valid token]

👍

im pretty sure this is ftc 2 type shit

lemme think

im big dumb

oh im so dumb

you tripped me up

you dont take the antiderivative

you differentiate it

so it would be (ln(1+2^x)'

and you would get

[mellow pendant]

Wait I’m looking for v(t) tho to plug in for v(2)

[valid token]

yes

and you have the a(t)

and v(t) is a(t)/dt

[mellow pendant]

Ye

Wait

[valid token]

so differentiate it

[mellow pendant]

No

[valid token]

not integrate

oh wait

am i high rn

nvm

[mellow pendant]

💀

[valid token]

ye im high

im dropping the exam

you just do a definte integral then

from 2 to 1

and wtv you get

add 2?

idk

[mellow pendant]

I did it from 1-2 n the answer wasn’t on the choice 😵‍💫

Wait nvm ur right

I forgot to add 2

Im failing

💀

[valid token]

💀

LMFAOO

[mellow pendant]

I forgot abt the intiital position entirely

[valid token]

we're getting first place frfr

ez 1st place

[mellow pendant]

Yumps

Ez 1st

[valid token]

HOW TF IS IT ALR 12??

TIME IS FUCKING FLYING

[mellow pendant]

West coast only 9 ova here 🗣️🗣️

[valid token]

an hour just got thanos snapped away

[valid token]

https://tenor.com/view/fnb-roblox-friday-night-bloxxin-fnf-dance-gif-26685592

[mellow pendant]

Nah fr

I am in Cali too 😭

[valid token]

nah im in NY

im fucked

exam in 8 hrs

💀

[mellow pendant]

Ik I meant u used the perfect gif 💀

Not that u we’re in NY but

Ya know

[valid token]

is that not you?

😳

[mellow pendant]

Maybe 🤭

[valid token]

https://tenor.com/view/ip-leak-yfh-gif-8855524988664585524

[mellow pendant]

My exam in 11 hours🤭🤭

[valid token]

lmao

guh

i need to study series

if you have any more questions dm me

[mellow pendant]

Fs

Imma close this

.close

[lone heart]

Channel closed

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Use .reopen if this was a mistake.

[lone heart]

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[silk junco]

hello i need help please

[silk junco]

𝑍~N(0; 1) .
P( 𝑍 > −0,7 ) = 75,8 %

i dont understand how the answer is 75,8%

i have the table to find the number but i still dont undert

understand

<@&286206848099549185>

[alpine sable]

please wait 15

m

i think

[silk junco]

ok sorry

[shut kayak]

$P(Z > -0.7) = 1 - P(Z \le -0.7)$

[ocean seal]

Akuma

[silk junco]

i find the thing here?

[silk junco]

what do i have to find here i understand nothing lol

[ocean hawk]

what is that table?

[silk junco]

center reducted law

but if there is a way to not use it please tell me

[silk junco]

@ocean hawk i just dont understand how the answer here is 75,80

i understand the formula but where do the number comes from

[shut kayak]

This is the table for that thingy

[silk junco]

yes

[silk junco]

mine is shorter

but yea

could you tell me how to proceed now?

@shut kayak

[shut kayak]

I mean since it's treated like starting from the mean, you just add .5 + .2580 which will get you the same thing

[silk junco]

whatt??

[ocean hawk]

P(Z > -0.7) = P(Z < 0.7) since it's symmetric. so just look at the table for row 0.7

the first value is 0.2580. add 0.5 (because that table starts at the mean). so it equals 0.7580

[silk junco]

@ocean hawk when you say you it is the things on the left?

i see the 0.2580 but why add 0,5?

[ocean hawk]

Akuma's table gives the area from the mean to the given value

not from -infinity to the given value

[silk junco]

what do you mean the mean

[ocean hawk]

so you have to add 0.5, because 50% of the curve is to the left of the mean

[silk junco]

i always add 0,5?

for everything everytime?

[shut kayak]

This is what you're tryna find

[ocean hawk]

only if the table is in that form

[shut kayak]

But using your table you can do this to find the same thing

[silk junco]

yes

does that mean sometimes i do -0.5?

[shut kayak]

No

If you're trying to find the area like this you'd do 0.5 - 0.4265

[silk junco]

ok can we make the second one together please

P( 𝑍 > 1,54 ) = 6,18 %

here do i have to find 1,54 in the table? @shut kayak

[shut kayak]

Yeah so pretend like in the pic here the line is at 1.54 instead of 1.45

So the shaded region would represent 0.4382

[silk junco]

how does the table work, whya re there number over and on the side?

[shut kayak]

Wdym?

[shut kayak]

That's the z score

The top row is the hundredth decimal place

[silk junco]

so here i would find 0.4382

[shut kayak]

Yes

[silk junco]

and i would have to do -5.0?

i mean -0.5

[shut kayak]

Well you can do 0.5 - 0.4382

[silk junco]

yea thats better

why did you do this?

before we added 0.5

[shut kayak]

Do what

[silk junco]

0.5 - 0.4382

[shut kayak]

You know what the question is asking

P(Z>1.54)

[silk junco]

to find bigger than 1.54

so when we have to find bigger we do -5.0 and when we have to find smaller we do +0.5?

[shut kayak]

It depends on the area you're looking for

[silk junco]

i dont really understand

wouldnt the area be left right and middle&

?

[shut kayak]

You either find the area left or right of a z score right

The shaded part so to speak

[silk junco]

could we say then when we want the left we do +0.5?

[shut kayak]

Well not always but

Ok so as a rule of thumb

[silk junco]

cool thx

if you have time and dont mind

what we do when there is 2?

[shut kayak]

If a question asks for $P(Z \le +z)$

[silk junco]

P(0,5 < 𝑍 < 2 )

[ocean seal]

Akuma

[shut kayak]

You would add 0.5

[silk junco]

i think this is too advance

[shut kayak]

No

[silk junco]

i only have bigger and smaller

not equal or bigger/smaller

[shut kayak]

I mean kinds the same

[shut kayak]

So you're saying P(Z<z) right

[silk junco]

yes

[shut kayak]

You can just think of it as the same doesn't really change anything rn

[silk junco]

ok alr thx for the trick

i will do 0.5 for left and -0.5 for right

[shut kayak]

So +z is a positive z score and -z will be some negative z score and let's say X is the number you get from the z score

P(Z > +z): 0.5 - X
P(Z < +z): 0.5 + X

P(Z < -z): 0.5 - X
P(Z > -z): 0.5 + X

Wait

Actually yeah

[silk junco]

i dont understand where that come from

[silk junco]

this is not right?

[shut kayak]

Nope

[shut kayak]

Just follow these general rules

[silk junco]

but the answers are always positive because its a %

[shut kayak]

Yes

It should always be positive

[silk junco]

i dont understand your rules

maybe i can reformulate them

[shut kayak]

+z for positive z score values

-z for negative z score values

[silk junco]

yes

what is z?

[shut kayak]

Like your question earlier

P(Z > 1.54)

1.54 is the z score

Or P(Z > -0.7)

[silk junco]

oh could i do something easier

always turn it positive

i change the sign and make it positive

or the opposite

[shut kayak]

Well usually P(Z>z) = 1 - P(Z<z)

[silk junco]

P(0,5 < 𝑍 < 2 ) would you know what to do here ?

since there are two numbers

[shut kayak]

That's asking you for the area between the z score of 0.5 and 2

[silk junco]

so 1,25 is the number i should get in the table?

[shut kayak]

No

[silk junco]

[shut kayak]

You have to find the values for both z scores and subtract the larger from the smaller

[silk junco]

so 0,3944 - 0,4772?

@shut kayak

[shut kayak]

No

0.4772 - 0.1915

0.4772 is the area from the center to the z score of 2

But since you want the area from 0.5 < z < 2

You have to subtract the area from center to 0.5

[silk junco]

where did you get 0.1915

[chrome forge]

Hi

[silk junco]

hi

could you help me? @chrome forge

[chrome forge]

Ok

What's up

[silk junco]

i need help with the following

[chrome forge]

Ok I'll try my best ok

[silk junco]

P(0,5 < 𝑍 < 2 ) would you know what to do here ?

[chrome forge]

To find the probability that a standard normal variable ( Z ) falls between 0.5 and 2, we can use the standard normal distribution table or a calculator that provides the area under the curve for the specified ( Z )-score range.
Here’s how you can calculate it:

Find the probability that ( Z ) is less than 2.
Find the probability that ( Z ) is less than 0.5.
Subtract the probability of ( Z ) being less than 0.5 from the probability of ( Z ) being less than 2.

The formula to calculate this is:
P(0.5<Z<2)=P(Z<2)−P(Z<0.5)
Using the standard normal distribution table, we find:

( P(Z < 2) ) is approximately 0.9772.
( P(Z < 0.5) ) is approximately 0.6915.

So, the probability that ( Z ) falls between 0.5 and 2 is:
P(0.5<Z<2)=0.9772−0.6915=0.2857
This means there’s about a 28.57% chance that the standard normal variable ( Z ) will fall between 0.5 and 2. Remember, these values are approximate and can vary slightly depending on the source of the standard normal distribution table. If you need more precise values, you might want to use a statistical software or a calculator designed for this purpose.

Is it ok

There u go

[chrome forge]

Is it ok

Or was it not helpful

[silk junco]

how did you find 0.99772 and 0.6915

[chrome forge]

Lemme find out

[silk junco]

thx

but your answer is good

[chrome forge]

I apologize for the confusion; there was a typo in my previous message. The correct probabilities from the standard normal distribution table are:

( P(Z < 2) ) is approximately 0.9772.
( P(Z < 0.5) ) is approximately 0.6915.
These values are found using a standard normal distribution table, which provides the probability that a standard normal variable is less than a given value. Here’s how you can find these values:

Look up the value of 2 in the Z-table, which gives the probability of ( Z ) being less than 2.
Do the same for the value of 0.5 to find the probability of ( Z ) being less than 0.5.
The difference between these two probabilities gives the probability of ( Z ) falling between 0.5 and 2.

If you need to find these values yourself, you can refer to a standard normal distribution table online or in a statistics textbook. The table shows the cumulative probability from the left up to a given Z-score. For example, for a Z-score of 2, you would find the corresponding cumulative probability, which is the area under the curve to the left of that Z-score. The same process applies for a Z-score of 0.5. Subtracting these two probabilities gives you the area between the two Z-scores, which is the probability we’re interested in. 📊📈

I'm searching the questions for u is it fine

[chrome forge]

Is it ok if I searched

[silk junco]

yes thx

can you help me with something else?

@chrome forge

P( 𝑍 < 𝑎 ) = 80% so 𝑎 = 0,84

what should i do here it is completely different

[chrome forge]

The statement “P( ( Z < a ) ) = 80%” means that the probability of the standard normal variable ( Z ) being less than ( a ) is 80%. To find the value of ( a ), we look at the standard normal distribution table for the Z-score that corresponds to a cumulative probability of 80%.

The Z-score that corresponds to a cumulative probability of 80% is typically found in the Z-table, and it is approximately 0.84. This means that ( a ) is approximately 0.84.

So, if you have a standard normal distribution, and you want to find the value of ( a ) such that the area under the curve to the left of ( a ) is 80%, you would look up the value in the Z-table that corresponds to 0.8000 (or as close as possible to it), and you would find that ( a ) is approximately 0.84.

This is a common procedure in statistics when dealing with normal distributions, especially when you want to find thresholds or cutoff points for certain probabilities. 📈📊

[chrome forge]

Was that ok or bad

[silk junco]

are you an ai?

[chrome forge]

Nah

Why

Its an app I have

[silk junco]

you type like one lol

[chrome forge]

Thnks

Send another on

[silk junco]

but one thing tho

i am not able to find 80 in the table

is it that my table is too small?

[chrome forge]

What u mean

In ur four figure

[silk junco]

here is the table

[chrome forge]

Ik

Ok send

[silk junco]

send what?

[chrome forge]

Ur table u said u were sending

[silk junco]

is there a way to do it without the table?<

[shut kayak]

Bruh

[chrome forge]

Friend me

[shut kayak]

P(Z < +z) = 0.5 + X

[chrome forge]

Ok lemme try

[shut kayak]

Z score of 0.84 is the closest to .80

0.5 + 0.2995

[silk junco]

how did you know without looking at the table?

[shut kayak]

You do look at table

What value + 0.50 = 0.80

[silk junco]

where in the table did you find it then

0,30

[shut kayak]

What z score is closest to that value

[chrome forge]

The expression ( P(Z < +z) = 0.5 + X ) suggests that you’re looking for the Z-score, ( z ), where the probability to the left of ( z ) in a standard normal distribution is ( 0.5 + X ). Here, ( X ) would represent the additional probability beyond the mean (since the mean of a standard normal distribution, which is 0, has 50% of the data to its left).

To find the Z-score corresponding to ( P(Z < +z) ), you would typically use a Z-table or a statistical calculator. The value of ( X ) needs to be known to find the exact Z-score. For example, if ( X ) was 0.3, you would look for ( P(Z < +z) = 0.8 ) in the Z-table.

If you provide the specific value of ( X ), I can help you find the corresponding Z-score. 📈🔍

[silk junco]

0.84

[shut kayak]

Yes

Ok I'm going to sleep now

Gl

[silk junco]

good nighy

[chrome forge]

Friend me

[silk junco]

night

[silk junco]

i did

[chrome forge]

See ya and friend me

[silk junco]

yes are you leaving?

[chrome forge]

I'm back

[silk junco]

P(−𝑎 < 𝑍 < 𝑎 ) = 99% so a =

[chrome forge]

Ok

[silk junco]

could you help me with that too?

[chrome forge]

To find the value of ( a ) when ( P(-a < Z < a) = 99% ), we refer to the standard normal distribution table or Z-table. The probability of 99% corresponds to the middle area under the normal curve, and we need to find the Z-score that leaves 0.5% in each tail, since ( 100% - 99% = 1% ) and half of that is ( 0.5% ) for each tail.

The Z-score that corresponds to ( 99.5% ) (0.5% in the tail) is approximately 2.58. This means that:

[ a \approx 2.58 ]

So, ( a ) is approximately 2.58. This is the Z-score that leaves 0.5% in the tail beyond ( a ) and ( -a ) on the standard normal distribution. Feel free to ask if you need help with more probability problems or any other questions! 😊

[chrome forge]

Hope it helped u

Ii it ik

Ok

I'm offline I go eat break fast

[silk junco]

ok thx

[lone heart]

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[knotty moss]

my task is to calculate what AC is in a triangle where BC is what I would assume is the hypotenus, the side where the angles are, the length of BC is 992 millimeters and the angle is 63 degrees
I need help asap

[nimble fern]

is there a right angle?

[knotty moss]

thats all I got

[nimble fern]

hmmm
we need at least 3 info of side or angles to find the other 3

[knotty moss]

I need to figure out AC

[nimble fern]

if there isn't any more information, we cannot find AC 😦

[knotty moss]

Sin(63*) = AC/992
its just 992*sin(63)

[lone heart]

@knotty moss Has your question been resolved?

[lone heart]

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[crystal mountain]

in B am i to use the integral from 0 to 2 of V(r(u)) dot r'(u) to find the line integral?

[lone heart]

@crystal mountain Has your question been resolved?

[crystal mountain]

<@&286206848099549185>

[lone heart]

@crystal mountain Has your question been resolved?

[lone heart]

@crystal mountain Has your question been resolved?

[jolly forum]

yes

[lone heart]

@crystal mountain Has your question been resolved?

[idle juniper]

Need help?

[lone heart]

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[full prairie]

I've been tagging with this problem for about five minutes now, all I need to do is the time (Y axis) any suggestions for the time axis?

[lone heart]

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[alpine sable]

Why does this become 1/5 ln x instead of 5 ln x?

[alpine sable]

.close

[lone heart]

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[stiff hound]

lol

[lone heart]

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[desert bolt]

how do i find the three trigonometric functions with the point

[waxen flame]

SOH-CAH-TOA

[lone heart]

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[median oar]

#1229263782770114581 message

[rose sigil]

hi kepe

[median oar]

[summer dirge]

Frosst = Kepe?

[lone heart]

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[untold crane]

No

There is a mistake on the first line

In the right side of the equation, you should extend the minus on 2x + 7 not just 2x

[buoyant saddle]

you didn’t distribute the negative

[vague river]

^

final exam is crazy

[buoyant saddle]

ohhh

wild

i didn’t even realize

lol

[untold crane]

If she’s really in the class it’s a bold move

[buoyant saddle]

<@&268886789983436800>

final exam

[ocean hawk]

<@&268886789983436800>

[rose sigil]

it says take home on it

[buoyant saddle]

😭😹😹

yea sure buddy

[buoyant saddle]

but it still has points

[rose sigil]

i was just responding to the “if she’s really in class”

[night geyser]

show the header text

[buoyant saddle]

show the header

and we will👍🏻

[vague river]

just distribute

[buoyant saddle]

trust

[vague river]

you got it👍

[buoyant saddle]

durb?

[night geyser]

request not met

tragic

.close

[lone heart]

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[night geyser]

anyway dont help people cheat pls

[lone heart]

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[wanton compass]

Hello

[wanton compass]

How to solve this math equation?

Hello

[narrow hedge]

um u need to give us the equation

[wanton compass]

Okiii wait

How do you find the x like what is this seriously😭

[hot hatch]

,rotate

[buoyant saddle]

proportionality

[narrow hedge]

ye

[wanton compass]

So how do we solve this😃

[narrow hedge]

What are you stuck with

Show us your working and we'll work from there

[wanton compass]

Both💀

[buoyant saddle]

set up a proportion

between the side lengths

[narrow hedge]

Do you know how to set up proportions?

[wanton compass]

Nopee

What is proportion?

[narrow hedge]

A ratio

[wanton compass]

How do you set it up?

[narrow hedge]

Is BD a length of 6?

Or AB?

[wanton compass]

BD

[hot hatch]

If you want solution, $\frac{X+2}{X+8}=\frac{2}{X+3}$

[ocean seal]

Monarch of Eternal Night

[wanton compass]

Huh😭

[hot hatch]

The sides are proportional

[wanton compass]

Where did 8 and 3 came from?

[hot hatch]

So basically $\frac{AD}{AE}=\frac{AB}{AC}$

[ocean seal]

Monarch of Eternal Night

[hot hatch]

Btw I think I swapped AE and AB

but both are same still

[wanton compass]

Then what is the value of AC and AB tho?

[hot hatch]

AC is AE +EC

2+X+1

[wanton compass]

So AC is 2x + 1? Or x + 3 or 3x + 1?

Hello?

Ok bro left me👍

[lone heart]

@wanton compass Has your question been resolved?

[wanton compass]

Nope

[hot hatch]

X+3

How is it 2x+1

[lone heart]

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[hot hatch]

X+1+2

[lone heart]

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[stiff fog]

Hello

[alpine sable]

Hi do you have a question?

[stiff fog]

Oh yes

And i just didn't find where to ask

[raven lark]

you can just ask here

[alpine sable]

,rccw

[lone heart]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[alpine sable]

context please? what you sent makes no reference to U_0

[balmy apex]

seems to be an a.p.

[stiff fog]

My original context isn't in English

[ocean hawk]

post it anyway, per the message above

[alpine sable]

هل تعرفي كيف تحلي المتتاليات الحسابية؟

[stiff fog]

Not really , it's a new lesson for me

[alpine sable]

thats ok. Do you prefer if i speak in English or Arabic btw?

There is a formula for arithmetic progression you may know about

[stiff fog]

Speak Arabic

Should i use it too?

[alpine sable]

اذا بدك ايه

المهم، هل عطوكي المعادلة a_n = a_1 + (n-1)d

[stiff fog]

يمكننا استعمالها

لقد مررت بها في الدرس

[alpine sable]

تمام هل تقدري تعبري عن U_5 و U_2 خلال المعادلة U_n = U_1 + (n-1)r

يعني حطي n = 2 و n =5 وخبريني شو تحصلي

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[lone heart]

@stiff fog Has your question been resolved?

[lone heart]

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[carmine inlet]

Three points are chosen independently an at random on the circumference of a circle with radius r. What is the approximate probability that none of the three points lies more than a straight-line distance of r away from any other of the three points?

[carmine inlet]

the answer cannot be 1/6^3 but why so?

[small lance]

May I see your progress?

[carmine inlet]

firstly i assumed that the first point can be anywhere, so it has a probability of being selected as 1. second point must lie between +60 deg and -60deg of the previous point so has a probability of 1/3, i am confused about the thrid point.

[small lance]

Your attempts seems correct

[carmine inlet]

ill get back to my main question after i understand the positioning of the thrid one

[small lance]

The third point must lie on between the first point and the second

[carmine inlet]

but somehow, some sort of average needs to be taken, (as per the answer goes)

here i am confused as to why that is the case

a more comporehensive diagram of where 2nd point might lie

[alpine sable]

what app did u use to draw that

[alpine sable]

same with this

[small lance]

Discord

[alpine sable]

?

[carmine inlet]

incorrect i am only considering where to plac the 2nd point, which can lie in any of the region i gave in my original diagram. selecting third point will determine whether it would exceed r or not.

u drew the conclusion too early

if u look closely if it lies within those region, the most they can form is an equilateral triangle and we know that all sides of an equilateral triangle are equal, hence the distance between the two points be equal to r, and selecting any point less that that would be less than r.

[small lance]

yeah, I know

[carmine inlet]

i am just confused about taking average between 120 deg and 60 deg for the last point

if u want, you may refer this to some friend who is good at these type of sum

[lone heart]

@carmine inlet Has your question been resolved?

[robust bane]

Can anyone help with statistics

[lone heart]

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[crisp sun]

!help

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To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[crisp sun]

hi

am i right

WOOHOO

THX

how long is khan academty gonna take me

[mighty snow]

!help

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[tawdry crystal]

Given in space an orthogonal monometric reference, consider the line $r$ represented by:

$$
r: \begin{cases}
x+y = 0 \
z = 0
\end{cases}
$$

the point $A(1,1,1)$ and the plane represented by
$$\alpha : x + y + z + 1 = 0$$.Represent:

$1.$ The line through $A$ parallel to $\alpha$ and incident to $r$.

[ocean seal]

alee

[tawdry crystal]

can someone help me pls

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[strange mason]

Can anyone help me prove this using AM-GM (or any other method)

[cinder sundial]

,rotate

[elder forge]

he gave a,b,c are positive

ok

and abc=1

so if one of them is fraction then other would be big number

for numbers>1

a^2>a

b^2>b

c^2>c

[coarse laurel]

can i suggest an easier approach?

[elder forge]

wot this is easy right

[coarse laurel]

a^2 + b^2 + c^2 ≥ 0 already

[elder forge]

yes

[coarse laurel]

if we look at (a-1)^2 + (b-1)^2 + (c-1)^2 it must also be ≥ 0

if you expand it out you get a^2 -2a + b^2 - 2b + c^2 - 2c + 3 ≥0

[elder forge]

yea tht works

[coarse laurel]

a^2 + b^2+ c^2 ≥ 2a + 2b + 2c - 3

by am gm we have that (a + b + c )/3 > cuberoot(abc)

which is (a + b + c ) > 3 cuberoot(abc)

a^2 + b^2+ c^2 ≥ 2a + 2b + 2c - 3 ≥ a +b+c +3 -3

a^2 + b^2+ c^2 ≥ a +b+c

[elder forge]

yep tht works

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[alpine sable]

How would you do d

[hushed ether]

juz sub it in?

since u got f(x) eq

(x+3) is the real root now x=x-5

[alpine sable]

Nvm

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[quasi apex]

Need help factoring 2u^2-5u+3=0

[fleet crown]

what have you tried so far?

[quasi apex]

I havent been able to find help on the process of it anywhere

i have the answer but dont know how to get there

[stiff hound]

using the discriminant always works

[quasi apex]

i know it goes to this but how?

[fleet crown]

do you know how to solve this equation?

[quasi apex]

not really

same with this idk how the got -5 and -1

[fleet crown]

ah I guess it's this way then

rewrite the middle term as a sum of the outside terms

so rewrite -5u as -2u -3u

so you then have

2u^2 - 2u -3u + 3 = 0

now factor out 2u from the first pair

and -3 from the second pair

so then you have

2u * (u - 1) -3 * (u - 1) = 0

and then factor out u-1

[quasi apex]

i think i get it

so same thing for the other one i sent as well?

imma try it

[fleet crown]

ye

[quasi apex]

can i get help with this?

[royal grail]

@quasi apex you should use product rule for log here

[quasi apex]

thank you

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[quartz fable]

Need help solving this

[ocean seal]

cwatson

[ocean hawk]

use those rules

[quartz fable]

Ok but witch one

And on what part

[long axle]

figure it out

[quartz fable]

Solved it

36

Thanks

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[spring sonnet]

for part b whats the number of terms in that sequence

im trying to use the sum of geometric but i cant make up out if i should use n+1 terms or just n terms

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@spring sonnet Has your question been resolved?

[spring sonnet]

<@&286206848099549185> hi i just need a quick little idea of whether i should use n or n+1 in the geometric series sum equation

[blazing sky]

You have to break it down into the 2D components that make it up.

[spring sonnet]

the surface area question isnt mine i dont know who sent that

[spring sonnet]

^

[blazing sky]

I don't know about that. Sorry.

[spring sonnet]

np

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[eager fable]

I am attempting to solve the following problem and while I am able to factor the top one, I am struggling on the denominator.

So far I have been able to turn it into:

5(x^2-4)

but i'm unsure where to go from here.

[limpid turret]

difference of squares

[eager fable]

will that work on every similar problem though?

[limpid turret]

Consider, in general, what is $(a-b)(a+b)$ when you expand it?

[ocean seal]

SWR

[ocean hawk]

No single approach will work on every problem

[eager fable]

Ok ill go and try to learn the difference of squares then for this case. Didn't know it was a thing so ty

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[whole chasm]

Ayoooo

[fleet crown]

Eyoooooooooooo

[whole chasm]

Sooo what's up

[tardy stag]

.close

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