help-0

[mortal trellis]

thats not what I meant

show what you did

[uncut siren]

oh okay

wait

i think i solved it @mortal trellis

what do u think

[mortal trellis]

what you got as simplification was wrong

[uncut siren]

why

[mortal trellis]

well I dont know where you made a mistake cause you showed no steps

[uncut siren]

i just order the polynomial

and simplify the X

like 4x³-2x³

and x+2x = 3x

[mortal trellis]

the 2x is inside (2x+1)^2

[uncut siren]

here first i made 2² and it gave me 4 then 4+1 = 5

[uncut siren]

ok ill check it again

but i wont touch that numbers

but what can i do with that?

[mortal trellis]

first expand (2x+1)^2

[uncut siren]

4x+1?

[mortal trellis]

no

(2x+1)*(2x+1)

foil

[uncut siren]

im spanish

be patient with me 😭

[uncut siren]

'k

[mortal trellis]

foil is a way to remember how to multiply out brackets like that

(a+b)(c+d)=ac+ad+bc+bd

first terms, then outer terms, then inner terms, then last terms

f-o-i-l

[uncut siren]

oh okay

let me check

[uncut siren]

isnt 9x right?

[mortal trellis]

how did you get rid of x

[uncut siren]

9x + x = 10x

[uncut siren]

(2x+1)*(2x+1) = 9x
9x + x = 10x

[mortal trellis]

(2x+1)(2x+1) is not 9x, no

[mortal trellis]

do this

[uncut siren]

k

[uncut siren]

its "a * c + a * d + b * c + b * d"?

[mortal trellis]

yes

[uncut siren]

ac+ad+bc+bd
2= a
1= b
2= c
1= d

[mortal trellis]

no

what happened to the x

[uncut siren]

2x = a
1= b
2x = c
1= d

?

[mortal trellis]

yes

[uncut siren]

then

2x*2x = 4x²

?

is that right

[mortal trellis]

yes

[uncut siren]

ok finally

one good

mmmm

then

ac= 4x²
ad = 2x
bc = 2x
bd = 1

4x² + 2x + 2x + 1
4x² + 4x² + 1
8x⁴ + 1

its right?

@mortal trellis

[mortal trellis]

2x+2x is not 4x^2

[uncut siren]

ok

then

4x² + 2x + 2x + 1

this is ok?

[mortal trellis]

well you can combine the 2x+2x

its just not 4x^2

[uncut siren]

oooooooooooo

u right

4x

it is

4x² + 4x + 1

i have to do bhaskara formula?

[mortal trellis]

I dont know what that means

[mortal trellis]

no

[uncut siren]

ok

ty

let me check again

im missing something

@mortal trellis

[mortal trellis]

still not quite right

you have -3x^2+4x^2

so +1x^2, not -1x^2

[uncut siren]

yh

i saw that

still wrong

[uncut siren]

@mortal trellis

[mortal trellis]

well at least now the simplifcation is correct

[uncut siren]

lol

[mortal trellis]

I am not familiar with this specific notation of polynomial division tho

[uncut siren]

ohhh

nothing to do then

it's something at least

ty

<@&286206848099549185> anyone can help me?

what could be the error

[fringe scroll]

Hola

El ruffini en sí está bien hecho

pero se te ha olvidado el término independiente

o sea, tendrías que haber puesto 2 1 5 0

arriba

@uncut siren

[uncut siren]

sigue sin ser correcto

no cambia ponerle el 0 o no

[fringe scroll]

cambia el resultado

si

[uncut siren]

aver

[fringe scroll]

pruébalo y me dices

[uncut siren]

pero @fringe scroll

[fringe scroll]

dime

[uncut siren]

si pongo el 0 despues tengo que poner

-1 x 0

lo cual da 0

[fringe scroll]

no

[uncut siren]

sigue siendo 6 y el ruffini tendria que dar 0

[fringe scroll]

-1 x 6

Pero por que tiene que darte 0

[uncut siren]

-1 x 6 = -6

[fringe scroll]

eso

[uncut siren]

-6 + 0 = -6

[fringe scroll]

entonces te queda

[uncut siren]

porq ese es el objetivo del ruffini no?

[fringe scroll]

2x²-x+6, resto - 6

[fringe scroll]

no, ruffini es una división

[uncut siren]

estas seguro

[fringe scroll]

si

[uncut siren]

confio en mi gente

[fringe scroll]

puede ser que te hayas equivocado al simplificar, pero si lo has simplificado bien puede darte algo que no sea 0

[uncut siren]

es que

en todos los ejemplos da 0

por eso digo

todos los de youtube

por decir un ejemplo @fringe scroll

[fringe scroll]

pero que quieres hacer exactamente

factorizar o hacer una división

[uncut siren]

nose

ahora lo hago

[fringe scroll]

es que ruffini se usa para las dos cosas

[uncut siren]

entiendo

gracias pibe

[fringe scroll]

de nada

[uncut siren]

no me ayudas con otra?

que tambien tengo dudas

[fringe scroll]

pero rápido que tengo sueño

[uncut siren]

te mando solicitud

y hablamos mañana

[fringe scroll]

ok

[uncut siren]

porq tengo q ir a la chamba

gracias

[fringe scroll]

jaja

[uncut siren]

.close

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[wet vector]

could someone explain to me plz where they get 'n-k' from?

why is it n-k divisions and assignements

dont rly get that

[surreal meadow]

<@&268886789983436800>

[wet vector]

what the

nah im scarred

[real gazelle]

That was really disgusting I'm sorry

Some people >.<

[wet vector]

dw i understand, totally out of all the mods control

[real gazelle]

This notation is terrifying but it's because k+1, ..., n is n-k different numbers

[wet vector]

ohh that makes sense

thank u

[real gazelle]

no problem :)

[wet vector]

.close

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[fiery reef]

i need help

[fiery reef]

damn

[waxen flame]

First of all, factor out the nines.

[lone heart]

@fiery reef Has your question been resolved?

[fiery reef]

OKAY

sorry for caps

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[latent walrus]

is the simplifying correct?

.close

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[latent cosmos]

Whats the bottom n?

[vapid shuttle]

a subscript

[latent cosmos]

Ah ok, looked it up from there. Just wasnt even sure what I was searching for. Thanks lol

.close

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[barren marsh]

Here I am confused what happens to it horizontally?

[jagged cobalt]

shifted left by 5, stretched by scale factor 5 and reflected in y

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[barren marsh]

.reopen

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✅

[barren marsh]

Sorry I am still confused.So it would be horizontally stretched or compressed by 5?

Which one?

<@&286206848099549185>

[jagged cobalt]

stretched

[barren marsh]

Makes sense

Thanks!

[barren marsh]

And why is that?

Why not compressed?

[jagged cobalt]

it would be compressed if it were -5 rather than -1/5

does the opposite of what you may expect

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[digital token]

I am doing very basic topology and was practicing for an exam. The question was basically to determine if

[B = {(x, y) \in \mathbb{R}^2 : |xy| \leq 4 }]

is closed.
The correction said that we can define the function
(f : (x, y) \mapsto xy) which will be continuous and since $B = f^{-1}([-4, 4])$ and [-4, 4] is closed in $\mathbb{R}$, B is also closed. However this solution seemed a bit weird to me?
In our handout it is said that if F is a mapping from a metric space ((E_1, d_1) \longrightarrow (E_2, d_2)) there is equivalence between "F is continuous" and "if U is a closed set of (E_2) then (F^{-1}(U))" is also closed. However isn't the f proposed in this without inverse, since it's not bijective? Or is the proposition in my handout wrong and this is true even for such "fake inverses"?

[ocean seal]

mippen

[ionic socket]

can someone help me to solve this ?

[nimble fern]

! occupied

[lone heart]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[mortal trellis]

F^-1 doesnt mean inverse here, it means preimage

[digital token]

Oh okay, that makes a lot more sense, thank you! Is there anyway to tell the difference in notation? If I hadn't stumbled upon this training question I would've probably continued to have the wrong idea of the whole thing

[nimble fern]

i believe that f^{-1}(U) is the inverse image, or the preimage of f on U

[mortal trellis]

the notation is the same

its just from context

[nimble fern]

oh my... I'm too slow

[mortal trellis]

generally when you say f^-1(set) you generally mean preimage

[digital token]

That's embarassing 😅 , guess I haven't been paying close enough attention

Thanks to both of you! :)

[mortal trellis]

in topology etc its quite rare that functions actually have inverses

preimages are much more common

[digital token]

Yeah, I guess I just heard about inverse functions first and mentally erased every time I heard "pre-image" from my mind. Gonna close this now to leave space for others!

.close

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[clear hull]

could some1 explain this problem to me? i know it has something to do with pigeonhole principle but idk where to go from there

[lone heart]

@clear hull Has your question been resolved?

[mortal magnet]

which answers have you eliminated?

[lone heart]

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[clear hull]

.reopen

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✅

[clear hull]

i havent really eliminated any i just dont know where to start with pigeonhole

[mortal magnet]

first of all

which set is bigger?

[clear hull]

X right

i think-

[mortal magnet]

X is indeed bigger than Y

so which answers can you eliminate by doing that?

(Im making sure you understand what the answers are saying)

[clear hull]

and just to make sure thats because |X| > |Y| implies that at least two distinct elements map onto an arbitrary element in the codomain?

[clear hull]

A

[mortal magnet]

yes

[mortal magnet]

also D, because then |X| < |Y| would be allowed and that cant happen

[mortal magnet]

now consider if |X| = 2|Y|

you can come up with a way to map up to 2 elements to X to one element in Y, right

[clear hull]

i dont quite get this part, why would |X| < |Y| be allowed? since n is multiplied to |Y| right so wouldnt there exist an |X| > |Y| and |X| < n|Y|? like |X| = 7, |Y| = 6, n = 2

[mortal magnet]

|X| < Y < n|Y|

reread it

the answer cant allow wrong answers

[clear hull]

gotcha gotcha

[clear hull]

yeah just both elements mapping to the singular y in Y

[mortal magnet]

now say I introduce one more element

it would be inevitable that three elements map to a y

you can argue that you tried to minimize this by having 2 elements -> 1 element everywhere, and then theres this one extra that needs to map somewhere

that is using the pidgeonhole principle, where you show that |X| > 2|Y| must mean """ |x| > 2|y| """ (those are in big quotes because thats not how its typed)

[clear hull]

ohhhh i think i get what you are saying

[mortal magnet]

you can think of it as

[clear hull]

so if |X| = n|Y|, then for every n elements in X you can just map it to a distinct y in Y

[mortal magnet]

yea

[mortal magnet]

heres a funny way of thinking about it

youre trying to overbook a plane by making n passengers sit in a seat

so you naturally can get away with placing n * number of seats passengers in the plane

if one more comes in, if |PASSENGERS| > n|SEATS|,

then theyre not going to fit in the plane

stand in the aisle maybe

[clear hull]

wait idk if my brain is just not working right now, but if this, doesnt this imply that there are n distinct elements x1, ..., xn s.t. f(x1) = ... = f(xn)

[mortal magnet]

yea

just like with 2 elements or with n passengers

[clear hull]

hmmm

then why wouldnt the answer be |X| = n|Y|

cause thats what the question is asking for right

[mortal magnet]

oh right

|X| > n|Y| already works

so if its really supposed to be |X| ≥ n|Y| thats cool but you just choose an answer that necessarily must work

[clear hull]

ah gotcha

thanks for the help i appreciate it 🙏

[mortal magnet]

np

[clear hull]

.close

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[ocean seal]

Someone

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[stiff harness]

bruh

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[pure mural]

anyone mind helping me on this 1?

[strange marsh]

can i get a solution for this problem:

[pure mural]

wrong channel, buddy.

[strange marsh]

whops sry i just joined

[pure mural]

np

[pure mural]

#help-18

[pure mural]

still need help :)

[heavy lily]

hello

?

[pure mural]

hi

[pure mural]

mind helping me with this problem?

[lone heart]

@pure mural Has your question been resolved?

[minor path]

can i get a solution?

[lone heart]

@pure mural Has your question been resolved?

[lyric dune]

Can I get help for this one

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[alpine sable]

Yo

[lone heart]

Please don't occupy multiple help channels.

[alpine sable]

I don't got alot of time

I'm a quick learner

Dawg

Are you asleep

[jagged cobalt]

(who are you talking to)

[alpine sable]

Prob you

Anyways

I want to know the title of this thing

[jagged cobalt]

youve been waiting 7 minutes and youre acting like this

mad guy

[alpine sable]

It's been 17 minutes

[storm elbow]

why you open another channel?

[alpine sable]

It's close to 20 minutes

[storm elbow]

it's been 8 minutes...

[alpine sable]

I just want to know

The title of

The upper half thing

So I can speed blits it

[jagged cobalt]

your other channel was open for 8 minutes mate

thats just trig and how the functions relate to eachother

[alpine sable]

What do I type In on youtube

[storm elbow]

💀

[alpine sable]

I speedran a chapter in less than an hour

So...

What's do I type in

[storm elbow]

well certain trig functions are positive or negative based on the quadrant

https://www.youtube.com/watch?v=ijIw4dFN89w&pp=ygUZVHJpZ3ZhbHVlcyB3aXRoIHF1YWRyYW50cw%3D%3D

something like this will help?

[alpine sable]

Thank you @storm elbow

[jagged cobalt]

'find other trig functions from one given ratio' or some nonsense

[alpine sable]

.close

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[toxic wasp]

This is what my textbook has written down. I am so confused. Are these not directly contradicting each other? The harmonic series diverges but that same sequence would converge at 0. Then this theorem says that a sequence converging at 0 have a convergent series. But the harmonic series is clearly divergent despite its sequence converging at 0.

[vapid shuttle]

no they are not contradicting eachother

it does not say that if the limit of an -> 0 then the sequence converges

it is saying that, if the sequence converges, then it limits to 0

this does not guarantee that any sequence which limits to 0 is convergent, as your example of the harmonic series shows

The theorem is not an "If and only if" theorem

[toxic wasp]

Ohh

My professor explained it the other way around in class

I was so confused 😭

.close

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[zealous lichen]

If it's R * (2pi+R) you get 2piR + R^2

[rich quiver]

ab × c = abc not ab × bc

[zealous lichen]

Oops

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[alpine sable]

how is it confirmed that the solutions of denom are the vertical asymptotes here?

i'm guessing any num/ 0 = inf

[hushed locust]

in general vertical asymptotes will appear wherever the denominator approaches 0 (while the numerator does not). to confirm you can check that the numerator does not equal 0 at the same points

[alpine sable]

okay

if a fn doens't have a denom

does it mean it wouldn't have vertical asymptote?

[hushed locust]

if it's a polynomial then yes, but other types of functions (e.g. logarithms) it can be more complicated

[alpine sable]

u're right, gotcha

one last ques

is there any relation between asymptotes of fn and inv fn, does horizontal asy become vertical asy or anything similar?

google search answers that i guess

anyway unimp, just curious

.close

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[old mirage]

I'm lost. So far I have that a and b are relatively prime and I wrote a as a product of distinct prime numbers

should I go about it where I should write b as a product of distinct primes as well, and given that a|bc write that ad=bc

[empty moth]

I would first write out bezouts identity

There’s an very easy proof with this

[old mirage]

I know that that's the simpler way, but I don't know how to apply the fundamental theorem of arithmetic

yea for sure i was just asked to use FTA

I proved it earlier with bezouts

[empty moth]

I mean it kinda follows directly from this

Since you would have the same set of prime factoring

And gcd(a,b) is 1

[old mirage]

so I was on the right track by using ad=bc?

[empty moth]

You basically had it yeah

[old mirage]

epic

[empty moth]

It’s just one step away literally

[old mirage]

yea that's on brand for my math lol

thank you!

[empty moth]

Ofc have a good night

[old mirage]

u 2!

.close

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[frail grove]

$\int |f|$ converge $\implies \int f$ converge

[ocean seal]

Adam Chebil

[frail grove]

can someone explain the intuition behind this ?

like why is it true ??

[alpine sable]

Absolute convergence implies convergence

[surreal meadow]

[\left | \int_D f\right | \le \int_D|f|]

[ocean seal]

maximo

[surreal meadow]

this is part of the intuition behind it

[frail grove]

i got that one

but how does that relate to the first assertion ?

[surreal meadow]

if the integral of the absolute value is convergent, and so bounded, then the absolute value of the integral will also be bounded

what class is this for?

[frail grove]

i think it's the equivalent of calc 2

[surreal meadow]

does this make sense?

[frail grove]

it does

[surreal meadow]

on a bounded domain this should be enough intuition

as for integrals to infinity, we would also like to check that the integral doesnt oscillate or act up in a similar way

[frail grove]

but i still don't understand why absolute convergence imply simple convergence

[frail grove]

you explained why the abs value of the integral is bounded

[surreal meadow]

yes

so the integral itself is bounded

[frail grove]

ohhhh

ye i think i got it now

[surreal meadow]

[-\left|\int_Df\right|\le\int_D f \le \left|\int_Df\right|\le \int_D |f|]

[ocean seal]

maximo

[frail grove]

yeah, understood

thnx

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[molten pivot]

find E[min(X,Y)] where X,Y are iid standard uniform random variables over the unit square in R2

[molten pivot]

@craggy dagger

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<@&286206848099549185>

[molten pivot]

<@&286206848099549185> '

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[surreal meadow]

e

[vapid shuttle]

I have a doubt about how to prove this. My sir tried to do it by induction but his answer key is wrong

oh nevermind he made a mistake in has base case

should be n=1

gosh I fucking wish my sir taught me maths for hours

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[drifting bane]

Help

[drifting bane]

help

.close

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[drifting bane]

.reopen

[lone heart]

✅

[drifting bane]

Hi, I am really stuck on how to graph sin and cosine with the phase shift and vertical shift. And for tan and cotangent graphs how many graphs do u have to draw and same issue with phase and vertical shift. Also how do u graph csc and sec

thank you!

[viscid surge]

so am I let me know if you get an answer

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[sick vigil]

how is this simplified

[surreal meadow]

2 = sqrt(4)

they then bring the 4 into the square root

[sick vigil]

ahhh

[sick vigil]

I'm trying to simplify it now with that

give me 1 sec

okay that makes sense, ty

.close

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[drifting bane]

@viscid surge

i think i figure it out

i figured out the sin and cosine

but not the tan and cot

and csc and sec maybe i figured it out?

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[hot trail]

Could someone explain what the question is asking exactly?

Some examples of elementary row operations (i think):

R_1 = R_1 + R_2

Swapping two rows

R_1 = 2*R_1

[vapid shuttle]

if you apply E1 to a matrix A from the left

what elementary row operation does this perform on A?

[hot trail]

Any hints?

[vapid shuttle]

hint: do it and find out

[hot trail]

E1 is similar to identity matrix

ok will do

[hot trail]

does this look right?

So the row operation is R_2 = \lambda R_2

[vapid shuttle]

yes

[pastel drum]

where am i going wrong how do i find X and ɸ

[vapid shuttle]

@pastel drum

[pastel drum]

give me second

[hot trail]

ty

i think i got it now,

[pastel drum]

idk how to do that

[vapid shuttle]

use #help-24

[pastel drum]

thx

[hot trail]

.close

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[pastel drum]

can i please get some help

[lone heart]

Please don't occupy multiple help channels.

[pastel drum]

i dont have another one?

[hushed locust]

#help-24

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[lone heart]

Please don't occupy multiple help channels.

[true axle]

help pls

[vernal root]

do you know what the ticks on line PQ and QR mean

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[sacred pebble]

I am confused on how to set up the equation on this problem

<@&286206848099549185> 😔

[full dome]

Hey

[sacred pebble]

Wsg I’m confused on this problem

[full dome]

Okay what's the question?

[full dome]

This?

[sacred pebble]

Yes

[oblique acorn]

step 1: find the question

[full dome]

Lol

[sacred pebble]

We got step 1

[oblique acorn]

its kinda hidden

[sacred pebble]

mb

but I know you’re supposed to write an equation using the info given but my brain ain’t working rn

[full dome]

So you can set 3 equations up

So first denote a variable to Joni's time when painting alone

Then we get the following:

Trinidad alone: x-6
Joni alone: x
Trinidad and joni: x+2

[sacred pebble]

O

So we are solving for x

[full dome]

Yes

Can you do that from here?

[sacred pebble]

Would the equation be 1/x-6 + 1/x = 1/x-2

[full dome]

Nope

[sacred pebble]

Why not

[full dome]

Hang on lemme re-read the question

Trinidad alone is 6 hours faster than joni, so that's x-6.
x-6 is 2 hours slower than both, right?

The difference in x-6 and x is therefore 8

So x-(x-6) = 8

[sacred pebble]

No it’s 2 hours slower than Joni and Trinidad together

[full dome]

That's what I meant

[sacred pebble]

But you said just Joni

[full dome]

I meant both

[sacred pebble]

🗿

Oh

[full dome]

Piss off

[sacred pebble]

Fr

[full dome]

Anyways

We know Trinidad alone is x-6

And both is x+2

And we know they're 8 hours in difference right?

[sacred pebble]

I’m confused how you got x+2

[full dome]

Ah I misread it 🗿

[sacred pebble]

Lol

This question is worded so poorly

[full dome]

So together, they take x-2, agreed?

[sacred pebble]

That’s what I would think but it doesn’t make sense how it’s slower than just trini which is x-6

[full dome]

Yeah i know the wording is meh

x - (x-6) = 2

That's the important equation anyways

[sacred pebble]

Oh lemme try it

[full dome]

Wait

What am I talking about 😂

[sacred pebble]

I’m like that means we have no x

[full dome]

Yeah this question is dog shit

Spam a random answer and see what it wanted?

The wording is appalling idk what it wants

[sacred pebble]

It’s probably a decimal so it would take many tries

💀

[full dome]

8

I think it's 8 but like

The wording is dog shit

[sacred pebble]

8 is wrong

😭

[full dome]

Yeah I know now look at the actual answer 😂😂😂

[sacred pebble]

Well I asked a couple of AI’s and they couldn’t do it saying there is no answer 💀

[full dome]

That's what I'm thinking

Not enough info

The fact that both slows Trinidad down means that it's not possible, right?

Nowehere does it say that Joni's time alone is proportional to her affect on Trinidad

[sacred pebble]

I don’t know

Both of those info tells us about Trinidad’s time

1/x-6 = 1/x+2

[full dome]

The question has no solution I don't think

The wording is complete ass

[sacred pebble]

I tried no solution too 💀

No luck

I might just skip this one

[lone heart]

@sacred pebble Has your question been resolved?

[lone heart]

@sacred pebble Has your question been resolved?

[lone heart]

@sacred pebble Has your question been resolved?

[lone heart]

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[tawdry sentinel]

Got a sketch yet?

[tawdry sentinel]

So in class, how have you solved these kinds of problems?

[narrow wedge]

im going ahead

to be real

[narrow wedge]

just trying something new

[tawdry sentinel]

Ok! How comfortable are you with slope and distance formulae?

[narrow wedge]

im ok with using them

which ones in particular would we use

[narrow wedge]

?

[tawdry sentinel]

You'll need to find the slope of AC in order to generate BD, which is perpendicular to it

[narrow wedge]

oh thanks a lot

[tawdry sentinel]

Couple ways to work out the distance from B

[narrow wedge]

what is one

[tawdry sentinel]

Finding the point where AC and BD intersect... let's call that point O

BO will be equal to OD

[narrow wedge]

alr i think im good with it now

appreciate it

[tawdry sentinel]

np

[narrow wedge]

.close

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[weary abyss]

.close

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[left gale]

just been struggling on how to enter it and confusion with notes

I've been struggling with this question for a bit and not sure exactly sure what im doing wrong

this is a bit confusing lol

[floral plaza]

You may want to review interval notation -> https://brilliant.org/wiki/interval-notation/#:~:text=Interval notation is a way,inequality or system of inequalities.
Parenthesis are used to show a lower or upper bound while square brackets are used to show that the limit is inclusive.

I'm not sure how you got to (-2, 0) for it's range, but the range should be the set of numbers that the function is capable of producing as output

[left gale]

i was grabing for straws at that point, i just switched the numbers around and was being told that it was wrong

im just at my wits end lol

[floral plaza]

I see, you might consider a vocab table and/or flashcards for the terms

[lone heart]

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[pallid hare]

how do you know its 1/16

[oak gulch]

by calculating the odds

[pallid hare]

why is the denominator 16

[oak gulch]

it's probably simplified from a different value

do you know how to calculate odds?

[pallid hare]

number of favorable / number of possible

[oak gulch]

yeah, use that, find out what to put above the fraction and what below

I'm sure you can figure it out

[pallid hare]

can u help

[oak gulch]

what would count as favorable?

[pallid hare]

dart landing in A

[oak gulch]

so how would you divide favorable/total?

[pallid hare]

im asking how they found the number of total possible / favorable not how to divide them

[oak gulch]

start by calculating the area of the circle, and the area of A

[pallid hare]

12.57 area of A

201.06 area of circle

u cant simplify

[oak gulch]

what does your calculator say...?

[pallid hare]

419/6702

[oak gulch]

weird

what kind of calculator do you have?

ah wait

[pallid hare]

i tried on ti 84 and online calculator

[oak gulch]

I know the problem

[pallid hare]

ok

[oak gulch]

you are rounding the numbers

keep them as they are and you will get a neat number

[pallid hare]

im not

[oak gulch]

yes you are

[pallid hare]

oh the calculator i used to find the area auto rounded

sry abt that

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by nextgrips

[oak gulch]

,w (4pi)/(64pi)

lol

[ocean seal]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by nextgrips

[oak gulch]

ah yeah I didn't even realise you don't even need a calculator

look you can cancel the pi 🙂

[pallid hare]

oh

ty

same thing for b

?

[oak gulch]

yeah

[pallid hare]

then - 1 for the overlap

ok thanks bro

.close

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[rustic oxide]

how are you supposed to denote that?

nvm got it

.close

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[subtle blade]

is tangential acceleration of point P negative or positive?

[subtle blade]

i got 9.81 m/s^2

but im not sure if its positive or negative

[fallen verge]

which direction is the acceleration? clockwise or counterclockwise?

[lone heart]

@subtle blade Has your question been resolved?

[subtle blade]

i thought it was pointing down

because the bucket is reaching the ground

but now im thinking im wrong on that

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[drowsy oyster]

How do i solve this compound interest question?

[drowsy oyster]

the video aint helping

been on this for 30 mins

.close

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[coarse coral]

For a vector calculus course I am taking, k=x and L=y. I tried to start it but I believe I must be going wrong somewhere

[vapid shuttle]

“Do no use”

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@coarse coral Has your question been resolved?

[coarse coral]

I did not write the problem

<@&286206848099549185>

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[hallow vessel]

can i get some help with a geometric proof

[hallow vessel]

i think my equation must be wrong

but

1 sec

[lone heart]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[hallow vessel]

we r just supposed to prove this

.close

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[paper mango]

has it resolved itself?

if you meant a geometric proof then you just show that it includes 5x the other shape

or more elegantly: 4x the copy of the initial triangle

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[paper creek]

Yo

[paper creek]

Can some one help me on my algebra 2 homework

[hallow vessel]

can i ping u in a channel

[paper mango]

sure

[paper mango]

and directly post the question :)

[paper creek]

The first one

I have a 3 page packet

Can you help me out finishing it

It is due next period

[paper mango]

,rotate

[paper mango]

what have you attempted so far

[paper creek]

My calculator does work

Doesn’t

I need it to find the intersex

Intersection

[paper mango]

well it requires W-Lambert

which I presume you hadn't so far?

[paper creek]

What does that even mean

Sorry, I’m freaking out rn

[paper mango]

ok, then you're probably meant to find it iteratively

[paper mango]

np

using the calculator you'd likely either get an immediate result

or, if you've practised that way in class, you can find the solutions iteratively

because you know that 2t+5 is linear

and 3(1.43)^x is exponential

so they have at max two intersections

especially since they say "to the nearest tenth"

you shall likely approximate

@paper creek dyk how to approximate them?

[paper creek]

Nope

[paper mango]

or which method you used in class for it

[paper creek]

Idk

I am freaking out rn

[paper mango]

why 🐛

we want to approximate:

which is equivalent to

now, what we want to do is interval-wise approximation

by taking some starting interval

and making it smaller repeatedly

here are the graphs visualised

so we'd want some interval (here in green)

that we can make iteratively smaller

which we can do using the derivative!

meaning that if the derivative is the positive, we can minimize to the left

and for negative derivative we can minimize to the right

if you had a different method before then mention @paper creek

for the derivative one would find that at 1.741 we have 0, so that's where we can set the starting point for the intervals

and since we search for at max 2 intersections

we'll have two intervals

a similar but slightly different method would be to instead have a climber, that remembers his last position

and goes half the step size each iteration

also left/right depending on the derivative

welp :/

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[subtle cloud]

Physics, Electric Flux

i dont get items 2 and 3

and I think item 3 meant the same situation in item 2 instead of 1

but my answer for item 1 is inward, idk if that's correct

and my answer for item 4 is 0

and for item 5 i just dont get it

[hushed locust]

2 & 3: the amount of flux is related to the angle between the surface normal vector and the electric field
4 & 5: Gauss' law applies here

[subtle cloud]

what should I solve for for items 2&3? the angle?

<@&286206848099549185>

[lone heart]

@subtle cloud Has your question been resolved?

[subtle cloud]

does the answer look like cos(0) and cos(360°)

is the answer for item 5 equal?

like the electric field lines passing through the surface is equal to the ones entering it since there's an equal amount positive and negative charges

I ignored the values of the charges and just based on the signs of their charges idk if that's right

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[prime spire]

How can I get the equation of the path? I already got the x and y components with integrating and I also tried to substitute the t in the y equation but that doesn't work.

[prime spire]

That's the right answer, but I don't know how to get the rectangular equation.

the parametric equations are crystal clear, but idk how one should get to the euqation of the path.

[quasi vector]

one thing you can do is find y in terms of x

as in, just find out what t is in terms of x

and substitute that in y

there will be a +-, which is why you then square

and simplify

[prime spire]

I'll try that

If I plug the t in terms of x in the equation of y, then I can't get this form even through simplifying and why / how did he get the y on the right side of the equation

when I express t in terms of x I get:
t = ±(x-0.75)^(0.5) + 0.5

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[lusty yoke]

Hello everyone! I'm having a problem with this question where the answer im computing is not in the same formula as the question is asking

[quasi vector]

!show

[lone heart]

Show your work, and if possible, explain where you are stuck.

[lusty yoke]

two moments

so the format is aln(b)-b

the question is asking for a and b

i calculated the arc length of the function at -8ln(4) + 2 + 8ln(2)

which is not in the form of a and b

[quasi vector]

it is

ln(4)=2ln(2)

[lusty yoke]

i also dont believe im supposed to solve the arc length but use a theorem? because the computation for arc length here is absolutely absurd

[lusty yoke]

but that still isnt aln(b) + b

[quasi vector]

it is

[lusty yoke]

ooooh i see

but

question

is there a theorem that makes this any less painful?

at all?

[quasi vector]

what do you mean theorem?

[lusty yoke]

the solving process was quite honestly immensely brutal

finding the derivative of that function takes an entire page

well thank you for the help i didnt realize that ln(4) = 2ln(2)

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[river swan]

how do i do iii.)

I was also stuck on ii but figured it out thanks to some help

so since ii gives us four roots

there must be 3 stationary points

that easy

are the x coordinate of the stationary points 1/2 the roots of the equation?

or how else can I do it

I tried differentiating but dont get anything meaninful

only

0=(e^2x-e^(-2x))-5(e^x-e^(-x))

[foggy vigil]

The stationary points are where the derivative equals zero so you’ll want to find those x values in the equation you sent then plug them into the original function to get y

[river swan]

?

if I plug the values in, ill get y=0

Surely I need to differentiate and find when 0

at which point the previous values are useless

[foggy vigil]

Yeah you’ll get a new set of x values unrelated to part (ii). Those are where the function equals zero. You want when the derivative of the function equals zero

[river swan]

yh how do i find that

when I differentiate I get a horrible function

that I can't solve

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[pliant oak]

0=(e^2x-e^(-2x))-5(e^x-e^(-x))
Multiple e^(2x)by both sides
0=e^(4x)-1-5(e^(3x)-e^x)
Let e^x=t>0
Then
t⁴-5t³+5t-1=0
(t-1)(t+1)(t²-5t+1)=0
There are four real roots of t
But t=-1 don't have corresponding x
So there are three roots of x

[river swan]

Thank you!

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[late maple]

I tried solving this with the two phase method but I got stuck at phase 2

[late maple]

Did I make a mistake?

And if I didn’t what does a tableau like this mean?

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[late maple]

<@&286206848099549185>

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[velvet jacinth]

Hi can someone teach me 2.3 polynomial identities

[lone heart]

Please don't occupy multiple help channels.

[zinc haven]

stick to your channel

[lethal belfry]

chose a channel ,either this or help 2

[velvet jacinth]

Ok I didn’t know

Delete it

This

One

[lethal belfry]

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[velvet jacinth]

دخيلكم حد يساعدني مب فاهمه شي وعندي امتحان باجر

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Please don't occupy multiple help channels.

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[keen glade]

if P(A)=3.0 and P(A|B)=0.1, how do i solve this?

[nova swift]

Can someone help me?

[wintry sluice]

post it in some other channel

this channel is occupied

[wintry sluice]

p(A|B) = p( a intersection b)/p(b)

wait also

are you sure p(A) is 3.0?

[keen glade]

yes

[wintry sluice]

it isnt possible

[raw stream]

srry for irrelevant chat but do you play Warthunder?

[wintry sluice]

probability of an event must be less than 1

[wintry sluice]

yes 💀

lmao

its ok

[raw stream]

Dm?

[keen glade]

let me check the question again, brb

[wintry sluice]

alr

[keen glade]

oh sorry it was 0.3

[wintry sluice]

yes

[keen glade]

the answers are: P(B)=3P(B|A), P(B)+P(B|A)=1, 3P(B)=P(B|A) and P(B)=P(B|A)

but idk how exactly to calculate

[wintry sluice]

what should you find

in the question

[keen glade]

it siy says if P(A)=0.3 and P(a|b)=0.1 then

[wintry sluice]

thats all?

[keen glade]

yes

[wintry sluice]

in order to find p(b) or the intersection of a and b

you need one more parameter

wait

are there options?

[keen glade]

yes there are 4 options

[wintry sluice]

what are they

[keen glade]

these

[wintry sluice]

ah

didnt see those

sorry

so

p(A) = 0.3

so you can find p(b) by subtracting p(a) from 1

which is 0.7

you can then find the intersection of a and b

and solve the options

got it?

[keen glade]

not really, sorry

[wintry sluice]

its ok

[keen glade]

like if i want to find P(B) how would i do that?

[wintry sluice]

1 - p(A)

[keen glade]

okay so P(B)= 0.7