#help-0

1 messages · Page 417 of 1

cloud nacelle
#

toh

fading kestrel
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opposite sides equal

cloud nacelle
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length mai

fading kestrel
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han

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vector same hua na

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direction opppsite

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triangle law s

cloud nacelle
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parallel

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hote hai

fading kestrel
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achha

cloud nacelle
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anti nahi

fading kestrel
#

hmm

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is me

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triangle law lagaya maine

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ab + bc = ac

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sahi?

cloud nacelle
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ek cheez bataunga

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parallelogram mai

fading kestrel
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batao

cloud nacelle
#

opposites are parallel

fading kestrel
#

okay

cloud nacelle
#

lekin zaruri nahi ki equal hai

#

vector*

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vector equal hona zaruri nahi hai

#

kyuki khud dekho na

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starting points alag hai

fading kestrel
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oar bhaiya

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parallelogram

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ki property hai

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opp sides equal

cloud nacelle
#

true

fading kestrel
#

woh chorhho

cloud nacelle
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magnitude equal

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vector nahi

fading kestrel
fading kestrel
#

aap solve karwao

cloud nacelle
fading kestrel
#

theeek

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ab

cloud nacelle
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acha

fading kestrel
#

unhone manga

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unit vector parallel to diagonal

cloud nacelle
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basically

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a + b

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karna hai aapko

fading kestrel
#

apne pas aa gaya ac vector

cloud nacelle
#

bas

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resultant

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jaise aapne bola

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ab + bc = ac

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good

fading kestrel
#

haan toh dekho na

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kyunki answer match na hua

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isliye puchh raha

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ac aa gaya mera

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fir maine uska unti vector nikala

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sahi aya utna mera

cloud nacelle
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wohi toh pucha

fading kestrel
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perfect

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ab doosra bhi nikalna hai

#

dossra diagonal

cloud nacelle
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acha

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mai aproach bata ta hu

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kaise karna hota hai

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yeh toh pata hai na jab bhi resultant lete hai dono vectors ka tail match karte hai

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physics mai padha hoga

#

@fading kestrel

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thoda jaldi bataunga thike mujhe jana ha

fading kestrel
#

hmm

cloud nacelle
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parallelogram law aata hai?

#

traingle law bekaar chohd do

fading kestrel
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yes

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main aapse baad mein puchh lunga

cloud nacelle
#

hume chahiye XY

fading kestrel
#

mera system hang ho gaya hai

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cry aa raha

cloud nacelle
#

friend req bhejlo

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baadme bataunga

fading kestrel
#

omkay

cloud nacelle
#

12th mai ho?

fading kestrel
#

thank you bhai

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aapki jai

fading kestrel
#

aap?

cloud nacelle
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mai bhi

fading kestrel
#

wah bc

cloud nacelle
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boards hai

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12th ke

fading kestrel
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yes

cloud nacelle
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28th se

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lol

fading kestrel
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22 mere

cloud nacelle
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acha

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cbse?

fading kestrel
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yes

cloud nacelle
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i see

fading kestrel
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chalo

cloud nacelle
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chal bhai mai chalta hu

fading kestrel
#

yes

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.close

lone heartBOT
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lone heartBOT
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glossy gazelle
#

What does this mean

lone heartBOT
mossy gale
#

hasnt been resolved yet

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@glossy gazelle Has your question been resolved?

swift tulip
mossy gale
#

missclick my bad

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delicate aspen
#

Hello, how can I get access to type in the #modeling chat?

mortal trellis
#

see the description of the channel

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pseudo hatch
#

guys can anyone help me with this? can't really figure it out. i always get 1/3

alpine sable
#

BRO HELP WTF IS -a+2x

pseudo hatch
#

My hand writing is bad so sorry for that

ocean sealBOT
pseudo hatch
#

i see

ocean whale
#

At that step

pseudo hatch
#

thanks brother 👍

pseudo hatch
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tame acorn
#

2 runners run through a 5 unit track. runner number 1 runs 2 units in a minute. runner number 2 runs 1 units in a minute. after how many minutes will they be on the same unit? how can i write the equation?

tame acorn
#

since this track is a loop

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i thought i could use modulus for this but i dont know how to modify an equation that has a modulus

drifting gust
#

Do u need exact equation or way to do it

tame acorn
#

equation

tame acorn
drifting gust
tame acorn
#

okay ping me when ur done

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oh forgot

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they both start at unit 1

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so in minute 1. runner 1 at unit 2. runner 2 at 1

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you get the problem

potent ember
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So l = t(v_2 - v_1) where v_2 is speed of fastest runner, v_1 is speed of slower runner and l is length of circle, t is the time they meet first time

tame acorn
#

yea

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exactly

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damn

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can i ask u something

potent ember
#

Sure

tame acorn
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have you seen a similiar question or is this the first

potent ember
#

Not really, just a logical conclusion

tame acorn
#

damn

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i could never😭

potent ember
#

That also comes with practice and training brain

tame acorn
#

right

potent ember
#

Open your own help channel, please

tame acorn
#

.close

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alpine sable
#

i need help

lone heartBOT
quasi willow
#

tell us what you need help with

alpine sable
#

am I gonna get help or...

#

???

sour dove
alpine sable
#

ik

#

srry

lone heartBOT
#

@alpine sable Has your question been resolved?

royal meadow
# alpine sable

for total surface area, just find the area of the rectangle and each of the triangles and then add them up

#

for lateral surface area, just find the area of each of the triangles and then add them up

alpine sable
#

thx

#

.close

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lethal belfry
#

have you tried finding $u_2, u_3$ and so on

ocean sealBOT
#

Why am. I here

pseudo ice
#

Hiiii Hiii

#

Was gonna say, do you think there's anything special about the sequence you have?

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Hiii @rose sigil LoveYou

lethal belfry
#

||looks like an AGP to me , try using that ||

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I could be wrong though

rose sigil
#

hiiii waves

pseudo ice
#

What types of sequences/series do you happen to know about?

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Welllll, that's a hint there catGiggle

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Have you dealt with the sum of a geometric sequence?

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Alright, do you know what the common ratio of this sequence is?

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You should be able to easily find it catGiggle what do you know about geometric sequences?

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catGiggle such as?

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And how do you find the ratio then? RooPopcorn

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That works, or the ratio of any two consecutive terms, sure...

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With that, can you tell me what the common ratio of this sequence is?

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Almosstt, not quite SCsadkittyNO

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Alright, what do you think the second term u2 of this sequence is?

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Alright-

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do you know what this is saying?

#

Did you mean $u_{2 + 1} = 2u_2$?

ocean sealBOT
#

a ☆
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

#

@pseudo ice

pseudo ice
#

Well, not [just] quite that either SCsadkittyNO

pseudo ice
pseudo ice
#

Can you tell me what the common ratio is now? catGiggle

#

Always a pleasure! Have a good one OathLove

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mighty cosmos
lone heartBOT
mighty cosmos
#

I’ve got the right answer for part b

#

As in the right ranges

#

But I don’t get when to use intersection or when to use union for set notation

pseudo ice
#

What did you get as the ranges?

mighty cosmos
#

<@&286206848099549185>

mighty cosmos
pseudo ice
#

In that case, you're not allowed to be in between k and 5k/3

#

So you can take the intervals from (-♾️, k) and (k, ♾️) and union those, because you want to be in one of those

mighty cosmos
#

I wrote it out and thought a bit more about it

#

At first was iffy and confused but then got it

#

Cheers 👍

#

.close

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lethal belfry
#

kind of a stupid question , but why isn't the limit 0

lethal belfry
#

$\lim_{x\rightarrow0}\left[\frac{x}{\sin\left(x\right)}\right]$

ocean sealBOT
#

Why am. I here

lethal belfry
#

where [x] denotes the floor function

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,w graph sinc(x)

lethal belfry
#

so it approachs x from below 1 from both sides

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so shouldn't the limit be 0

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,w graph (x/sin(x))

lethal belfry
#

oh, yeah, nvm

tacit arch
#

,w graph floor(sinc(x))

lethal belfry
#

Thanks!

#

.close

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lone heartBOT
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rich basin
lone heartBOT
rich basin
#

Could someone please give me a hand with this question?

lone heartBOT
#

@rich basin Has your question been resolved?

rich basin
#

@craggy dagger

#

<@&286206848099549185>

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slate barn
lone heartBOT
slate barn
#

I dont know why my answer is wrong

red echo
#

, rotate

ocean sealBOT
red echo
#

It's because it's asking for the tangent line of the derivative's graph not the original function's graph

livid tundra
#

(-1)^3 is (-1)

#

not 1

red echo
#

In the problem he sent?

finite flax
#

Try to use the notation you know to keep it organized. The first expression is not equal to the second (first derivative set equal to second)

red echo
#

oh wait maxwell he sent the prompt above his notebook picture

slate barn
red echo
#

Ok so blacksin

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You wrote the original function as the derivative

slate barn
#

i found the derivative of f(x)

red echo
#

Or ok

#

The thing is though they're asking for the tangent line to the derivative graph

#

So you need to find the slope of the derivative graph at x = -1

#

Meaning double derivative

slate barn
#

oh so the second derivative?

red echo
#

Yeah

#

You got the process down but you just used the first derivative

slate barn
#

ok that makes sense

red echo
#

yeah

slate barn
#

thank u

red echo
#

yeah np

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#

@slate barn Has your question been resolved?

errant lily
#

is anyone here good at basic algebra

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floral ocean
#

for these type of questions is there 2 vertical asyptotes like -3 and +3?

floral ocean
#

or just +3

#

the function is undefined at x = -3 and +3

jagged cobalt
#

that doesnt seem to be what its asking

sharp crag
#

yea there is one at -3 as well

jagged cobalt
#

but yeah ^

sharp crag
#

but it's also not important for this lol

floral ocean
floral ocean
#

should I say VA = -3 and +3

#

I just wanna know if I should

jagged cobalt
#

not really clear wording

sharp crag
#

it's good to post the full question

jagged cobalt
#

VA's occur at x=3 and x=-3

floral ocean
#

I just wanted to know this

#

.close

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opal ridge
#

How did it turn into 2a(4-a) = -10 here ?

lone heartBOT
summer dirge
#

,rotate

ocean sealBOT
summer dirge
#

we have a+4-2a = 4 - a

#

and a*2 = 2a

opal ridge
#

Oh right 💀 how did not see that

#

I was thinkin they took 2a common lmfao

#

Thank u thank u

#

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fiery compass
#

im struggling with this question. I tried to use the recursion tree to help me come up with a good guess that i can use with the substitution method but i ended up with a complex summation that I have no idea how to solve. Is there a trick i can use to come up with a good guess without using the recursion tree?

lone heartBOT
#

@fiery compass Has your question been resolved?

lone heartBOT
#

@fiery compass Has your question been resolved?

fiery compass
#

<@&286206848099549185>

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@fiery compass Has your question been resolved?

fiery compass
#

🙏 someone save me from this proof please, this algorithms course has me by the throat

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gritty valve
#

Do I simplify this using trigonometry identities?

ripe skiff
#

Is anyone on this server a JEE aspirant??

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#

@gritty valve Has your question been resolved?

high shuttle
#

The most direct way to calculate the derivative here is to use the chain rule using f(y) = tan^-1(y) and y(x) = sec^-1(1/(2x^2-1))

#

@gritty valve I think that using chain rule of derivation should be enough

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surreal trellis
lone heartBOT
surreal trellis
#

could someone help me guess the powers in that first one pls

alpine sable
#

,, y^n + x^n = 1

ocean sealBOT
surreal meadow
#

for completeness you could say y^m + x^n = 1
but from the rest of the questions i would assume it's meant to say y^2 + x^2 = 1

alpine sable
#

is this it? the quality is kind of shite

surreal trellis
#

im just gonna assume y^2 + x^2

#

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surreal trellis
lone heartBOT
surreal trellis
#

i cant figure out whether ive done the wrong step or made a mistake in the working out

#

but that product does not look like -1

#

o shit i did make a mistake in the working out

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#

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vale junco
#

Hello!
Linear Algebra II
Could someone help me understand how to find the Jordan canonical form of a matrix and P such that A = P J P^-1?
I know the algorithm, I just have some questions about it.

I was taught that for every eigenvalue you should find the chain
ker (A-λI), ker (A-λI)^2 ....
Until you get that the dimension of this kernel is equal to the algebric multiplicity of λ.

My question is, that if dim (ker (A-λI)) = 1 and dim (ker(A-λI)^2) = 3? What do you do then?

vale junco
#

Oh its impossible nvm

#

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alpine sable
#

If a mapping is neither surjective nor injective, then it can't be well-defined, can it?

tawny condor
#

What is well defined?

#

I don't see a problem with a mapping that is neither

alpine sable
#

For instance if I have a map: f: V-->W

#

And not every element from W has a corresponding element from V

tawny condor
#

Then it's not surjective

alpine sable
#

So it cant be surjective

#

Yes but f is then under this condition not defined

tawny condor
#

What

#

f(v) is defined for every v in V

#

Just because it's not mapping to every element of W doesn't mean it's not defined

#

f: R^3 -> R^3, where f(x, y, z) = (x, y, 0) is neither injective or surjective

#

But it's defined pretty well if I may say so myself

alpine sable
#

Ah okay thanks

tawny condor
#

Accidentally wrote f twice

alpine sable
#

So I must always prove for well defined seperateley and cant say anything about it just from injective or surjective

tawny condor
#

!original

lone heartBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

tawny condor
#

What even is "well defined"?

alpine sable
#

Its not a work I had a thought regarding Rings

tawny condor
#

What are you trying to show

alpine sable
#

Since Rings have to be well definied

#

I thought maybe I could also prove it by saying a mapping is not surjective so its not well defined but yeah

tawny condor
#

I'm not knowledgable about rings so I can't really answer you, but maybe if you're defining an operation, show that it's a valid way of doing so

#

I don't think well defined has anything to do with surjective or injective, but maybe ask someone else.

#

Maybe in ring theory it is, idk

#

I'll let someone else take over

alpine sable
#

.close

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warm meteor
#

hello, bachelor here, I'm relearning integrals and I got stuck on this one equation

warm meteor
#

<@&286206848099549185>

earnest mural
#

does integration by parts work?

#

how can I type LaTeX here tho

warm meteor
#

I'm not sure

lament forge
#

$\sin(x)^\text{like this}$

ocean sealBOT
#

bee [it/its]

warm meteor
#

we were told to use a different method

lament forge
earnest mural
#

thx

#

$\int\sin^3(x)\cos(x)dx$
this one right?

warm meteor
#

yuh

ocean sealBOT
earnest mural
#

ok wait

warm meteor
#

you still there?

earnest mural
#

is this channel allow me to sent image?

warm meteor
#

I did so I think it's fine

earnest mural
warm meteor
#

as long as it provides the help needed

#

yeah Ok

#

forgot the vdu formula

earnest mural
#

need proof?

warm meteor
#

honnestly the proof is there

#

I was just stuck with the sin^3(x)

earnest mural
#

oh right

warm meteor
#

thank you for the help, have an awesome day my guy

earnest mural
#

np bro👍

lone heartBOT
#

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#
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surreal trellis
lone heartBOT
surreal trellis
#

the speed that its going up is 500 df/dx

#

the second part im struggling

#

@craggy dagger

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#

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upbeat eagle
#

Quick question

lone heartBOT
upbeat eagle
#

I got an r value of +1 and -1 as well

#

why is that not used

#

I forgot the reason

#

I got a ^4 quadratic of

r^4 - 1.16^2 + 0.16

woven plaza
# upbeat eagle why is that not used

your solution needs to be in the domain of original equation, as you can see in the first step you'd get a zero in denominator which is not defined so we reject those solutions

upbeat eagle
#

haha thank you

#

.close

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#
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neat socket
#

given a relation R difined (x,y)| y= 2x what is the reverse relation

lone heartBOT
#

@neat socket Has your question been resolved?

pallid scarab
#

what does it mean for yRx ? and then you'll get your answer

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alpine sable
#

i need help :)

lone heartBOT
analog falcon
alpine sable
#

this question😭

analog falcon
alpine sable
alpine sable
alpine sable
#

like idk how to find 1%..

#

she gets 1% interests added on her 220 punds

#

pounds**

#

what is 1 percent of 220?

alpine sable
#

you know how percentages work?

#

for 5% and 10%

#

but not for 1.

#

100% is 220 pounds we can agree on that right?

#

yes

#

thats the full sum

#

how many times can 1% fit in 100%?

#

100

#

right

#

If you gave me 100 pounds, and i told you i would only give you 1% back how much would i give you back?

#

99?

#

..

#

If someone gives you 1% of something is that a lot you thinl?

#

no

#

quite less

#

i think i needa learn percenatges again.

#

is it like 2.20

#

?

#

yes

#

oh

#

how did you find that number?

#

I just searched up how to find 1% for a number💀

#

and then u times it by 3? cuase its 3 years

#

Okay but if you compare 2.20 and 220 what do you notice?

#

u didvide by 100

#

?

#

yes 2.20 is 220/100

#

When we talk about percentages we talk about something as a whole, in which ''whole'' means 100%, and then a part of that ''whole'' as if you divided in 100 equal pieces.

#

Oooh i see

#

thank you

#

Ofcourse it depends on the context like 5% human doesnt exist

#

ye

#

so thats an easy trick you did

#

oooo

#

you divided 220 by 100 and then you multiplied it by 3 percent

#

but back to your question. how much interests did the person get?

#

£6.60?

#

why?

#

because

#

we times it by 3

#

cause its 3 years

#

no?..

#

it is 3 years your right

#

but

#

the amount changes after ONE year because the interests is added to the sum after EACH ANNUM

#

annum = annual = per year

#

how much interests is added after one year?

#

so we have to find 1% again?

#

precisely

alpine sable
#

and you repeat that

#

ooh

#

dammit

#

WAIT I THOUGHT U JUST TIMES IT

#

i thought thats compund

#

oh

#

you kind of do

analog falcon
alpine sable
#

what is the difference?

#

is simple interests just the 1% from 220?

#

or from the new sum?

analog falcon
#

Yes I think. In simple interest, the principle doesn't change. In compound, this year's amount becomes next year's pinciple

alpine sable
#

yea

#

ah okay yea then your right you do 3x 2.20

#

u add it on for compound

#

ye😭 thank youu

#

But compound isnt much harder either to calculate

#

you can make these questions easier by thinking them in terms of factors

#

factors/

#

how

#

You can express any percentage of any number by multiplying it with another number

#

can u give an example please

#

its better to let you do it but ill help you along the way

#

so imagine 220 pounds

#

yes

#

ah okay

#

if I had to express 100% of 220 pounds by what number do you think I would have to multiply with?

#

huh.

#

What is 100% of 220?

#

£220

#

Yes

#

What multiplication of 220 gives me 220?

#

1?.

#

yes

#

220 * 1 = 220

#

now what about 50%

#

thats a half?

#

yes

#

so £110

#

what number should i multiply with

#

2?

#

220 * 2 = ??

#

oooh i thought u meant £110

#

thats like 440

red jetty
#

100% of 220 is itself
then what about 10% of 220?

alpine sable
#

22?

#

yes

red jetty
#

Yep

#

1% of 220?

#

aka 10% of 22

alpine sable
#

"2.20???

#

yep

#

OOJ

#

I see

#

what number do you multiply by 10 to get 1?

red jetty
#

yep

alpine sable
#

huh

#

10

#

??? * 10 = 1

#

wait what

#

IDK

#

WHAT

#

fractions?

#

do you know how to add with fractions or do you know how to do math with decimals?

#

ye i do

#

ish.

#

idk 0.1,...

#

why 0.1?

#

nvm

#

im not saying your wrong just why

#

00

#

ooh

#

idk if u move the deciaml point

#

it gives 1.

#

IDK ..

#

yea thats one way to look at it.

#

yuhh

#

but more importantly if you add 0.1 ten times what do you get?

#

1

#

yep

#

oooh

#

I think you should practice alot with addition and multiplication with fractions because you can actually make things look a lot more easier and you are suprised how many commonalities there are

#

ye tru okayy

#

thanks man

#

no worries

#

.close

lone heartBOT
#
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trim bronze
#

d

lone heartBOT
trim bronze
#

..

#

i have a math project what do i do

#

about

#

Subtracting Linear Expressions

#

pls halp

gray isle
#

post specific questions instead of being vague

trim bronze
lone heartBOT
#

@trim bronze Has your question been resolved?

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gaunt grotto
lone heartBOT
gaunt grotto
#

Here's what I have so far

#

Where do I go from here?

#

Surely one of $U_1|0\rangle$ and $U_2|1\rangle$ would have to be zero

ocean sealBOT
gaunt grotto
#

But then one of the last two lines would be wrong

lone heartBOT
#

@gaunt grotto Has your question been resolved?

lone heartBOT
#

@gaunt grotto Has your question been resolved?

tacit arch
gaunt grotto
#

asked here because quantum information theory is a maths class for me

lone heartBOT
#

@gaunt grotto Has your question been resolved?

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gleaming lily
#

I have this εNFA and I have converted it into an NFA using a table (I'm not sure if its right). But anyways I need to continue to convert it into a DFA but if I attempt to do this it seems there are too many states and it just gets way to complicated.

gleaming lily
tardy stag
#

NFA to DFA tends to cause a lot of explosion in state space

#

there's some simplifications you can make

gleaming lily
#

I know I'm supposed to do something like this and continue with all the other ones but it just seems super excessive. I'm not sure whats going on tbh.

tardy stag
#

there's a lot of simplifications you can make to the NFA before you start

#

for example, state 7 seems completely useless

gleaming lily
#

Yea I see that

lone heartBOT
#

@gleaming lily Has your question been resolved?

gilded fjord
#

hello

gleaming lily
#

Hello

lone heartBOT
#

@gleaming lily Has your question been resolved?

lone heartBOT
#

@gleaming lily Has your question been resolved?

gleaming lily
#

.close

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#
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clear tendon
lone heartBOT
clear tendon
#

hello, can i get some help on how to start this question pls

#

ive written down all the forces and equations for friction: mu x n

#

78.4 x mu is the friction force but im not sure where to go from there

subtle light
#

i would recommend drawing a free body diagram for the block a, b, pulley system, and try to find the acceleration of the system using the information you know about block b

clear tendon
#

hmm

#

ok ty

#

so find the acceleration is the first step?

subtle light
#

yeah i’d say so

#

and you can use that with newton’s second law

clear tendon
#

sure

lone heartBOT
#

@clear tendon Has your question been resolved?

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sullen prawn
lone heartBOT
undone hornet
#

hint: write $n=p_1 ^ {a_1}\dots p_k^{ak}$, where $p_1,\dots,p_k$ are distinct primes. then you know that the number of positive divisors of n is given by $(a_1+1)(a_2+1)\dots (a_k+1)$ so in order for this number to be odd, each of the terms $a_i+1$ must also be odd. what does this tell us about each $a_i$?

surreal meadow
#

if a_i + 1 is odd, what must a_i be? oh sorry, i thought smack wrote the hint

ocean sealBOT
surreal meadow
#

it's a bit too good tho

empty moth
ocean sealBOT
#

nosqldb

empty moth
#

but if you don't know that each of the terms are odd, it might be dififcult to proceed

surreal meadow
#

to me what 42 wrote is basically the whole proof
the first step of writing it as a product of primes is a good first hint

#

if that's not sufficient then writing down the number of divisors in terms of a_i is a good next step

undone hornet
#

yeah maybe i said too much

sullen prawn
#

is it possible to do it without prime factorization

empty moth
#

but it will be like 5x more complicated

surreal meadow
#

wait what do i have to confirm

sullen prawn
#

ok i will do it with prime factorization

empty moth
#

but nvm

lone heartBOT
#

@sullen prawn Has your question been resolved?

dire harness
#

would this be right for the proof? I was just trying
||
\item(5pts) Let $n$ be a positive integer. Use a \textbf{direct} proof to show that ``If $n$ has an odd number of divisors, $n$ is a perfect square." (Note that a positive integer $a$ is a perfect square if $a = b^2$ for some $b \in \mathbb{Z}$.)
\sol{
Assume that $n$ has an odd number of divisors.
It is true that for each divisor $d$ of $n$, there is another divisor of $n$ with the value $\frac{n}{d}$.
Thus, every positive integer $n$'s divisors can be categorized into two categories, in which the total number of divisors is thus $2k$.
However, if $d = \frac{n}{d}$, a divisor is double counted and the total number of divisors becomes $2k-1$.
When the total number of divisors becomes odd, $d = \frac{n}{d} \equiv d^2 = n$, which indicates that n is a perfect square.
$\therefore$ $n$ is perfect square.
\hfill $\square$
}
||

#

@empty mothwhat do you think?

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alpine sable
#

this looks stupid it make me mad

lone heartBOT
alpine sable
#

one sec

lone heartBOT
alpine sable
#

lim x->4 (x^2-16)/(4-x)

#

every trick I try, it doesnt work

#

AHHH

fallen verge
#

did you factor the numerator

steep pendant
#

yeah you gotta factor it

#

might be more obvious if you change the way the denominator looks; (4-x) = -(x-4)

alpine sable
#

.solved

lone heartBOT
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humble pike
lone heartBOT
humble pike
#

i think i might be doing it wrong

ocean whale
#

How did you get that answer?

#

Do you know what csc is?

humble pike
#

the opposite of sin

ocean whale
#

Opposite as in what exactly?

#

Like -sin?

humble pike
#

i thought csc was the opposite of sin

ocean whale
#

What do you mean by opposite?

humble pike
#

as in reciprocal

ocean whale
#

Reciprocal and opposite mean two different things

#

So csc = 1/sin, yes that's correct

#

What exactly are you typing in to calculate that?

humble pike
#

sorry if im a little slow but i did the reciprocal of (-20) to get 1/(sin20)

ocean whale
#

What happened to the negative?

#

Why did it become 1/sin(20)?

#

It's csc(-20)

humble pike
#

im a little confused

#

how do you get that?

ocean whale
#

Which part are you confused on?

humble pike
#

the second step

ocean whale
humble pike
#

yes

ocean whale
#

That's the original problem

humble pike
#

yes, im a little confused on the process to get to the answer

#

I haven’t studied this part that much and I dont have the wifi to access my ebook

ocean whale
#

As stated, csc is the reciprocal of sin, or 1/sin

#

If given csc(-20), you are doing 1/sin(-20)

#

The inside stuff does not change when taking the reciprocal

humble pike
#

so the -20 doesnt change?

ocean whale
#

No

humble pike
#

okay let me pull up a calculator

ocean whale
#

Try it

humble pike
#

alright give me one second

#

correct!

#

thank you!!

solid smelt
#

close it after using

#

@humble pike

humble pike
#

is it .close?

#

.close

lone heartBOT
#
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pseudo dew
#

can anyone find a source for this function its made to scale my other desmos functions s is scale factor and a/b are the points its scaling from

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#

@pseudo dew Has your question been resolved?

pseudo dew
#

<@&286206848099549185>

pseudo dew
#

<@&286206848099549185>

#

.close

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barren marsh
#

Hello

lone heartBOT
#
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wooden topaz
#

help

lone heartBOT
wooden topaz
#

have no idea what to do

jagged cobalt
#

chain rule, quotient rule

#

ring any bells?

#

oops not chain

#

product rule lol

wooden topaz
#

yes i think

#

like taking the exponent down

jagged cobalt
#

thats power rule, not applicable here

wooden topaz
#

oh

#

then i dont know ig

jagged cobalt
#

these arent familiar at all?

wooden topaz
#

oh they are

jagged cobalt
#

you just need to apply them

wooden topaz
#

oh okay

jagged cobalt
#

youre given all the values you need to evaluate it

wooden topaz
#

so i can use them without variables

#

ok

#

it says its incorrect

#

i used the product rule

#

<@&286206848099549185>

#

<@&286206848099549185>

#

.close

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unborn axle
#

Suppose we shuffle together 8 standard decks of cards (so the resulting deck has 8·52 = 416 cards). How many different 8-card hands are possible? As with poker hands, order does not matter. It also does not matter which deck the cards came from.

stark scroll
#

Consider stars and bars

livid tundra
#

Is that a simple combination or am I just going wrong

prime badge
#

it's stars and bars

stark scroll
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slow pendant
#

hello

lone heartBOT
slow pendant
#

is there an online calculator where i can find the focal points of a hyperbola

#

i tried desmos but im not sure how

jagged cobalt
#

wolfram probably has one

#

,w properties of hyperbola [//math:x^2/5-y^2/3=1//]

jagged cobalt
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slow pendant
#

okayy thank you!

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worldly horizon
#

t^2 + 2t - 15

lone heartBOT
jagged cobalt
#

what an expression

worldly horizon
#

thanks

#

this question weird

jagged cobalt
#

how so

worldly horizon
#

I know that 5 and -3 give me -15

#

but I have a 2t

jagged cobalt
#

you havent actually asked anything yet aha

tawdry sentinel
#

ax^2 + bx + c right?

worldly horizon
#

what bro

tawdry sentinel
#

you're looking for two numbers, m and n, whose product is -15 and whose sum is 2

#

m * n = -15
m + n = 2

worldly horizon
#

wait I made a silly mistake

tawdry sentinel
#

Think about it for a sec 😉

worldly horizon
#

thanks

#

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worldly horizon
#

.reopen

lone heartBOT
#

worldly horizon
#

I need help this with question now

#

a^3 - a^2 - 30a^1

#

ignore my trying to distribute

cloud nacelle
worldly horizon
#

wdym

flat roost
#

then factorize a^2-a-30

worldly horizon
#

I did

worldly horizon
ancient temple
#

a^3-a^2-30a^1 is just an expression

ancient temple
worldly horizon
#

wwll

#

well

#

wait what? help me understand

ancient temple
#

If you expand (x-2)(x-3), you get x^2-5x+6

#

When you go in reverse (from x^2-5x+6 to (x-2)(x-3)) , we say that you have factorised x^2-5x+6

ancient temple
#

In your case, you have a^2-a-30, and you are asked to factorise it.

worldly horizon
#

bro what

worldly horizon
ancient temple
#

I know, factorise a^2-a-30 by solving a^2-a-30=0

#

I was giving an example to explain how factorisation is done

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#

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worldly horizon
#

wait so

#

I think 2 is the gcf?

brittle ember
#

why you need gcf?

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short sun
#

For this I got this answer. But I am pretty sure it isn't right after checking with symbolab. Just wondering where I went wrong

short sun
sharp crag
#

show your work then

short sun
#

sorry I had to switch over to my phone to take the picture

sharp crag
#

lol makes sense

#

yea it looks like this has some mistakes

short sun
#

dang it

vast moat
#

try use trig sub

short sun
#

I dont think I have done that before

vast moat
#

oh.

sharp crag
#

pay attention to dx vs du

hasty creek
# short sun

sqrt(a+b) isn’t equal to sqrt(a) + sqrt(b)
You forgot to do du = 2x dx

short sun
#

So I would do this instead?

hasty creek
#
  • C catthumbsup
short sun
#

sounds good, thank you

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charred plank
#

Let $F(x,y,z) = z^3+3yz-4x$ looking at the point (2,0,2) and the function $z=f(x,y)$ how do you compute
$\frac{\partial f}{\partial y}$(2,0) $\frac{\partial f}{\partial x}$(2,0) $\frac{\partial ^2 f}{\partial x^2}$(2,0) $\frac{\partial ^2 f}{\partial y ^2}$ (2,0) $\frac{\partial ^2 f}{\partial x\partail y}$(2,0)

ocean sealBOT
#

mtr123
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

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#

@charred plank Has your question been resolved?

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#

@charred plank Has your question been resolved?

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#

@charred plank Has your question been resolved?

surreal meadow
charred plank
surreal meadow
#

can you post the original question?

#

presumably you are meant to take some level curve of F and solve for z

charred plank
# surreal meadow can you post the original question?

$F(x,y,z) = z^3+3yz-4x$, we want to check if F(x,y,z) = 0 defines z=f(x,y) as an implicit function.
F(2,0,2) = 0, the partial derivative around this point are continous, $\frac{\partial F}{\partial z}(2,0,2) = 12$
therefore it could be written as z=f(x,y) around the point (2,0,2).
Now I need to calculate the above

ocean sealBOT
#

mtr123

surreal meadow
#

do you know what f would be then?

#

if so, you could just calculate the partials at that point

charred plank
surreal meadow
#

well you have that F(x,y,z) = 0 defines z = f(x,y)

#

oh i just noticed F has mutliple zs in there

charred plank
#

Yeah otherwise you could just write z = some x some y

surreal meadow
#

do you have the original question, like an image of it?

charred plank
surreal meadow
#

can you send it regardless

#

either way, you can solve this by finding the roots of the cubic, but i believe there should also be a trick to isolating the zs, just can't think of what it would be right now

charred plank
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alpine sable
#

Hey yall, quick question! If i have to run a unistrut support beam, every five feet and there is 670 feet that i have to run it. How many pieces of unistrut do i need? Also, every five feet i only need half a unistrut not a full piece of it. I need help with the calculations thanks.

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#

@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

elfin shuttle
#

Ll

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

Can someone atleast give me the formula to figure it out

tacit arch
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wet vector
#

need some help please with part a first of all

#

ive done the hypothesis part

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thick lynx
thick lynx
#

.close

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remote ether
#

Can I have some help with this? I'm getting 2/9*ac but would like to double check

alpine sable
#

thats wrong

#

,, \41c\2\4cc

ocean sealBOT
alpine sable
#

what do u think this is equal to

remote ether
#

is it just 1/c? the second fraction cancels itself out to equal 1 so theres just the first fraction that remains?

alpine sable
#

yes

#

but you have c in ur answer

remote ether
#

oh yeah... I'll have to give that another go.

#

can I cross simplify with these sort of problems?

#

thanks for pointing out that c. It looks really obvious now 🤦🏻‍♂️

#

If I had a fraction like b/b^3 could I simplify that to 1/b^2?

#

Tried again, is it 2a/9c?

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#

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paper sage
lone heartBOT
paper sage
#

How does this converge

#

what test should I apply?

#

does this converge??

limpid turret
#

Do you want to know only if it converges, or do you want to know specifically what it converges to (assuming it converges)?

paper sage
#

Only if it converges/diverges. I understand to use the ratio test, but can't seem to progress after writing it all out, as I don't seem to see the next steps

paper sage
limpid turret
# paper sage

iirc, ratio test only tells you if a series diverges, but is inconclusive on whether it converges

#

Personally, I would show that your series is less than another series that you know converges

frail grove
ocean sealBOT
#

Adam Chebil

frail grove
#

but i don't think it works here

lone heartBOT
#

@paper sage Has your question been resolved?

royal meadow
#

and 5^k gets bigger much more quickly than 4^k

#

so you can essentially consider 3^k/5^k

limpid turret
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royal meadow
lone heartBOT
royal meadow
#

basically there exists a tail after which the errors are less than e(3/5)^k

#

so the total error is less than epsilon basically

#

so you can just consider 3^k/5^k more or less

limpid turret
royal meadow
#

would you mind elaborating

limpid turret
#

3/4, not 3/5

royal meadow
#

ok yes

#

there we go

#

oh

#

.close

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gritty pond
#

Prove Z5 x Z5 x Z5 is isomorphic to Z25 x Z5.

vapid shuttle
#

!status

lone heartBOT
#
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