#help-0
1 messages · Page 417 of 1
opposite sides equal
length mai
achha
anti nahi
batao
opposites are parallel
okay
lekin zaruri nahi ki equal hai
vector*
vector equal hona zaruri nahi hai
kyuki khud dekho na
starting points alag hai
true
woh chorhho
itna sahi kiya?
ha
apne pas aa gaya ac vector
haan toh dekho na
kyunki answer match na hua
isliye puchh raha
ac aa gaya mera
fir maine uska unti vector nikala
sahi aya utna mera
wohi toh pucha
acha
mai aproach bata ta hu
kaise karna hota hai
yeh toh pata hai na jab bhi resultant lete hai dono vectors ka tail match karte hai
physics mai padha hoga
@fading kestrel
thoda jaldi bataunga thike mujhe jana ha
hmm
suno
parallelogram law aata hai?
traingle law bekaar chohd do
omkay
12th mai ho?
wah bc
yes
22 mere
yes
i see
chalo
chal bhai mai chalta hu
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What does this mean
hasnt been resolved yet
@glossy gazelle Has your question been resolved?
@mossy gale Please make your own help channel to request help
missclick my bad
@glossy gazelle Has your question been resolved?
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see the description of the channel
@delicate aspen Has your question been resolved?
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guys can anyone help me with this? can't really figure it out. i always get 1/3
BRO HELP WTF IS -a+2x
My hand writing is bad so sorry for that
i see
You "lost" the (x + 1) that was part of the numerator
At that step
thanks brother 👍
yeah my brain just stopped working for some reason
@pseudo hatch Has your question been resolved?
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2 runners run through a 5 unit track. runner number 1 runs 2 units in a minute. runner number 2 runs 1 units in a minute. after how many minutes will they be on the same unit? how can i write the equation?
since this track is a loop
i thought i could use modulus for this but i dont know how to modify an equation that has a modulus
Do u need exact equation or way to do it
equation
u here?
Just thinking about it
okay ping me when ur done
oh forgot
they both start at unit 1
so in minute 1. runner 1 at unit 2. runner 2 at 1
you get the problem
You need to notice that the first time they'll meet when the fastest runner ran exactly 1 lap more than slower
So l = t(v_2 - v_1) where v_2 is speed of fastest runner, v_1 is speed of slower runner and l is length of circle, t is the time they meet first time
Sure
have you seen a similiar question or is this the first
Not really, just a logical conclusion
That also comes with practice and training brain
right
Open your own help channel, please
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i need help
tell us what you need help with
dude patience. Helpers are here on a volunteer basis. Someone wil get to you when they can
@alpine sable Has your question been resolved?
for total surface area, just find the area of the rectangle and each of the triangles and then add them up
for lateral surface area, just find the area of each of the triangles and then add them up
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have you tried finding $u_2, u_3$ and so on
Why am. I here
Hiiii 
Was gonna say, do you think there's anything special about the sequence you have?
Hiii @rose sigil 
hiiii 
What types of sequences/series do you happen to know about?
Welllll, that's a hint there 
Have you dealt with the sum of a geometric sequence?
Alright, do you know what the common ratio of this sequence is?

You should be able to easily find it
what do you know about geometric sequences?
such as?
And how do you find the ratio then? 
That works, or the ratio of any two consecutive terms, sure...
With that, can you tell me what the common ratio of this sequence is?
Almosstt, not quite 
Alright, what do you think the second term u2 of this sequence is?
Alright-
do you know what this is saying?

Did you mean $u_{2 + 1} = 2u_2$?
a ☆
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
@pseudo ice
Well, not [just] quite that either 
What this is saying to you, in words, is "to get the next term of the sequence, multiply the current term in your sequence by 2"
Well, the fact that you should know the common ratio of the sequence from this statement here
Can you tell me what the common ratio is now? 
Always a pleasure! Have a good one 
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I’ve got the right answer for part b
As in the right ranges
But I don’t get when to use intersection or when to use union for set notation
What did you get as the ranges?
<@&286206848099549185>
Got x < 5k/3 and x > k
In that case, you're not allowed to be in between k and 5k/3
So you can take the intervals from (-♾️, k) and (k, ♾️) and union those, because you want to be in one of those
Lysm
I wrote it out and thought a bit more about it
At first was iffy and confused but then got it
Cheers 👍
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kind of a stupid question , but why isn't the limit 0
$\lim_{x\rightarrow0}\left[\frac{x}{\sin\left(x\right)}\right]$
Why am. I here
so it approachs x from below 1 from both sides
so shouldn't the limit be 0
,w graph (x/sin(x))
oh, yeah, nvm
,w graph floor(sinc(x))
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Could someone please give me a hand with this question?
@rich basin Has your question been resolved?
@rich basin Has your question been resolved?
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, rotate
It's because it's asking for the tangent line of the derivative's graph not the original function's graph
In the problem he sent?
Try to use the notation you know to keep it organized. The first expression is not equal to the second (first derivative set equal to second)
i found the derivative of f(x)
Or ok
The thing is though they're asking for the tangent line to the derivative graph
So you need to find the slope of the derivative graph at x = -1
Meaning double derivative
oh so the second derivative?
ok that makes sense
yeah
thank u
yeah np
@slate barn Has your question been resolved?
is anyone here good at basic algebra
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for these type of questions is there 2 vertical asyptotes like -3 and +3?
that doesnt seem to be what its asking
yea there is one at -3 as well
but yeah ^
but it's also not important for this lol
the question is to determine if limit exists and find vertical asymptotes
it is cus its the question
should I say VA = -3 and +3
I just wanna know if I should
not really clear wording
it's good to post the full question
VA's occur at x=3 and x=-3
okay tysm
I just wanted to know this
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How did it turn into 2a(4-a) = -10 here ?
,rotate
Oh right 💀 how did not see that
I was thinkin they took 2a common lmfao
Thank u thank u
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im struggling with this question. I tried to use the recursion tree to help me come up with a good guess that i can use with the substitution method but i ended up with a complex summation that I have no idea how to solve. Is there a trick i can use to come up with a good guess without using the recursion tree?
@fiery compass Has your question been resolved?
@fiery compass Has your question been resolved?
<@&286206848099549185>
@fiery compass Has your question been resolved?
🙏 someone save me from this proof please, this algorithms course has me by the throat
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Do I simplify this using trigonometry identities?
Is anyone on this server a JEE aspirant??
@gritty valve Has your question been resolved?
The most direct way to calculate the derivative here is to use the chain rule using f(y) = tan^-1(y) and y(x) = sec^-1(1/(2x^2-1))
@gritty valve I think that using chain rule of derivation should be enough
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could someone help me guess the powers in that first one pls
,, y^n + x^n = 1
for completeness you could say y^m + x^n = 1
but from the rest of the questions i would assume it's meant to say y^2 + x^2 = 1
is this it? the quality is kind of shite
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i cant figure out whether ive done the wrong step or made a mistake in the working out
but that product does not look like -1
o shit i did make a mistake in the working out
@surreal trellis Has your question been resolved?
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Hello!
Linear Algebra II
Could someone help me understand how to find the Jordan canonical form of a matrix and P such that A = P J P^-1?
I know the algorithm, I just have some questions about it.
I was taught that for every eigenvalue you should find the chain
ker (A-λI), ker (A-λI)^2 ....
Until you get that the dimension of this kernel is equal to the algebric multiplicity of λ.
My question is, that if dim (ker (A-λI)) = 1 and dim (ker(A-λI)^2) = 3? What do you do then?
Closed by @vale junco
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If a mapping is neither surjective nor injective, then it can't be well-defined, can it?
For instance if I have a map: f: V-->W
And not every element from W has a corresponding element from V
Then it's not surjective
What
f(v) is defined for every v in V
Just because it's not mapping to every element of W doesn't mean it's not defined
f: R^3 -> R^3, where f(x, y, z) = (x, y, 0) is neither injective or surjective
But it's defined pretty well if I may say so myself
Ah okay thanks
Edited that
Accidentally wrote f twice
So I must always prove for well defined seperateley and cant say anything about it just from injective or surjective
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
What even is "well defined"?
Its not a work I had a thought regarding Rings
What are you trying to show
Since Rings have to be well definied
I thought maybe I could also prove it by saying a mapping is not surjective so its not well defined but yeah
I'm not knowledgable about rings so I can't really answer you, but maybe if you're defining an operation, show that it's a valid way of doing so
I don't think well defined has anything to do with surjective or injective, but maybe ask someone else.
Maybe in ring theory it is, idk
I'll let someone else take over
This is what I needed answers my question thank you
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hello, bachelor here, I'm relearning integrals and I got stuck on this one equation
I'm not sure
$\sin(x)^\text{like this}$
bee [it/its]
we were told to use a different method
(just put $s around it)
yuh
Gene
ok wait
you still there?
is this channel allow me to sent image?
I did so I think it's fine
need proof?
oh right
thank you for the help, have an awesome day my guy
np bro👍
@warm meteor Has your question been resolved?
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the speed that its going up is 500 df/dx
the second part im struggling
@craggy dagger
@surreal trellis Has your question been resolved?
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Quick question
I got an r value of +1 and -1 as well
why is that not used
I forgot the reason
I got a ^4 quadratic of
r^4 - 1.16^2 + 0.16
your solution needs to be in the domain of original equation, as you can see in the first step you'd get a zero in denominator which is not defined so we reject those solutions
Oh right yeah thats true
haha thank you

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given a relation R difined (x,y)| y= 2x what is the reverse relation
@neat socket Has your question been resolved?
what does it mean for yRx ? and then you'll get your answer
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i need help :)
That's what this server is for! So we know that much already 🙂
What do you need help with?
You know what is simple interest?
How much interest does she earn after one year?
ye
thats what i cant firgure out
like idk how to find 1%..
she gets 1% interests added on her 220 punds
pounds**
what is 1 percent of 220?
ye idk.
you know how percentages work?
for 5% and 10%
but not for 1.
100% is 220 pounds we can agree on that right?
yes
thats the full sum
how many times can 1% fit in 100%?
100
right
If you gave me 100 pounds, and i told you i would only give you 1% back how much would i give you back?
99?
..
If someone gives you 1% of something is that a lot you thinl?
no
quite less
i think i needa learn percenatges again.
is it like 2.20
?
yes
oh
how did you find that number?
I just searched up how to find 1% for a number💀
and then u times it by 3? cuase its 3 years
Okay but if you compare 2.20 and 220 what do you notice?
u didvide by 100
?
yes 2.20 is 220/100
When we talk about percentages we talk about something as a whole, in which ''whole'' means 100%, and then a part of that ''whole'' as if you divided in 100 equal pieces.
Oooh i see
thank you
Ofcourse it depends on the context like 5% human doesnt exist
ye
so thats an easy trick you did
oooo
you divided 220 by 100 and then you multiplied it by 3 percent
but back to your question. how much interests did the person get?
£6.60?
why?
because
we times it by 3
cause its 3 years
no?..
it is 3 years your right
but
the amount changes after ONE year because the interests is added to the sum after EACH ANNUM
annum = annual = per year
how much interests is added after one year?
so we have to find 1% again?
precisely
£2.20
and you repeat that
ooh
dammit
WAIT I THOUGHT U JUST TIMES IT
i thought thats compund
oh
you kind of do
Sorry to interrupt, but wouldn't it be 1% at 220 pounds for all three years, since its simple interest and not compound?
what is the difference?
is simple interests just the 1% from 220?
or from the new sum?
Yes I think. In simple interest, the principle doesn't change. In compound, this year's amount becomes next year's pinciple
yea
ah okay yea then your right you do 3x 2.20
u add it on for compound
ye😭 thank youu
But compound isnt much harder either to calculate
you can make these questions easier by thinking them in terms of factors
factors/
how
You can express any percentage of any number by multiplying it with another number
can u give an example please
its better to let you do it but ill help you along the way
so imagine 220 pounds
yes
ah okay
if I had to express 100% of 220 pounds by what number do you think I would have to multiply with?
huh.
What is 100% of 220?
£220
Yes
What multiplication of 220 gives me 220?
1?.
yes
220 * 1 = 220
now what about 50%
thats a half?
yes
so £110
what number should i multiply with
2?
220 * 2 = ??
oooh i thought u meant £110
thats like 440
100% of 220 is itself
then what about 10% of 220?
yep
huh
10
??? * 10 = 1
wait what
IDK
WHAT
fractions?
do you know how to add with fractions or do you know how to do math with decimals?
ye i do
ish.
idk 0.1,...
why 0.1?
nvm
im not saying your wrong just why
00
ooh
idk if u move the deciaml point
it gives 1.
IDK ..
yea thats one way to look at it.
yuhh
but more importantly if you add 0.1 ten times what do you get?
1
yep
oooh
I think you should practice alot with addition and multiplication with fractions because you can actually make things look a lot more easier and you are suprised how many commonalities there are
ye tru okayy
thanks man
no worries
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d
..
i have a math project what do i do
about
Subtracting Linear Expressions
pls halp
post specific questions instead of being vague
i wanna project
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Here's what I have so far
Where do I go from here?
Surely one of $U_1|0\rangle$ and $U_2|1\rangle$ would have to be zero
Jacob
But then one of the last two lines would be wrong
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#old-network for physics server
asked here because quantum information theory is a maths class for me
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I have this εNFA and I have converted it into an NFA using a table (I'm not sure if its right). But anyways I need to continue to convert it into a DFA but if I attempt to do this it seems there are too many states and it just gets way to complicated.
NFA to DFA tends to cause a lot of explosion in state space
there's some simplifications you can make
I know I'm supposed to do something like this and continue with all the other ones but it just seems super excessive. I'm not sure whats going on tbh.
there's a lot of simplifications you can make to the NFA before you start
for example, state 7 seems completely useless
Yea I see that
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hello
Hello
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hello, can i get some help on how to start this question pls
ive written down all the forces and equations for friction: mu x n
78.4 x mu is the friction force but im not sure where to go from there
i would recommend drawing a free body diagram for the block a, b, pulley system, and try to find the acceleration of the system using the information you know about block b
sure
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hint: write $n=p_1 ^ {a_1}\dots p_k^{ak}$, where $p_1,\dots,p_k$ are distinct primes. then you know that the number of positive divisors of n is given by $(a_1+1)(a_2+1)\dots (a_k+1)$ so in order for this number to be odd, each of the terms $a_i+1$ must also be odd. what does this tell us about each $a_i$?
if a_i + 1 is odd, what must a_i be? oh sorry, i thought smack wrote the hint
42
all good
very good hint 🙏
it's a bit too good tho
I guess this part: "so in order for this number to be odd, each of the terms $a_i+1$ must also be odd. what does this tell us about each $a_i$?"
nosqldb
but if you don't know that each of the terms are odd, it might be dififcult to proceed
to me what 42 wrote is basically the whole proof
the first step of writing it as a product of primes is a good first hint
if that's not sufficient then writing down the number of divisors in terms of a_i is a good next step
that makes sense
yeah maybe i said too much
is it possible to do it without prime factorization
I can try and @surreal meadow will have to confirm
but it will be like 5x more complicated
wait what do i have to confirm
ok i will do it with prime factorization
I was going to try and prove it without prime factorization
but nvm
@sullen prawn Has your question been resolved?
would this be right for the proof? I was just trying
||
\item(5pts) Let $n$ be a positive integer. Use a \textbf{direct} proof to show that ``If $n$ has an odd number of divisors, $n$ is a perfect square." (Note that a positive integer $a$ is a perfect square if $a = b^2$ for some $b \in \mathbb{Z}$.)
\sol{
Assume that $n$ has an odd number of divisors.
It is true that for each divisor $d$ of $n$, there is another divisor of $n$ with the value $\frac{n}{d}$.
Thus, every positive integer $n$'s divisors can be categorized into two categories, in which the total number of divisors is thus $2k$.
However, if $d = \frac{n}{d}$, a divisor is double counted and the total number of divisors becomes $2k-1$.
When the total number of divisors becomes odd, $d = \frac{n}{d} \equiv d^2 = n$, which indicates that n is a perfect square.
$\therefore$ $n$ is perfect square.
\hfill $\square$
}
||
@empty mothwhat do you think?
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this looks stupid it make me mad
one sec
did you factor the numerator
yeah you gotta factor it
might be more obvious if you change the way the denominator looks; (4-x) = -(x-4)
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i think i might be doing it wrong
the opposite of sin
i thought csc was the opposite of sin
What do you mean by opposite?
as in reciprocal
Reciprocal and opposite mean two different things
So csc = 1/sin, yes that's correct
What exactly are you typing in to calculate that?
sorry if im a little slow but i did the reciprocal of (-20) to get 1/(sin20)
Which part are you confused on?
the second step
Second step as in this line?
yes
That's the original problem
yes, im a little confused on the process to get to the answer
I haven’t studied this part that much and I dont have the wifi to access my ebook
As stated, csc is the reciprocal of sin, or 1/sin
If given csc(-20), you are doing 1/sin(-20)
The inside stuff does not change when taking the reciprocal
so the -20 doesnt change?
No
Try it
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can anyone find a source for this function its made to scale my other desmos functions s is scale factor and a/b are the points its scaling from
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help
thats power rule, not applicable here
oh they are
you just need to apply them
oh okay
youre given all the values you need to evaluate it
so i can use them without variables
ok
it says its incorrect
i used the product rule
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Suppose we shuffle together 8 standard decks of cards (so the resulting deck has 8·52 = 416 cards). How many different 8-card hands are possible? As with poker hands, order does not matter. It also does not matter which deck the cards came from.
Consider stars and bars
Is that a simple combination or am I just going wrong
it's stars and bars
you could have multiples of cards (like 3 ace of diamonds)
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hello
is there an online calculator where i can find the focal points of a hyperbola
i tried desmos but im not sure how
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okayy thank you!
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t^2 + 2t - 15
what an expression
how so
you havent actually asked anything yet aha
ax^2 + bx + c right?
what bro
you're looking for two numbers, m and n, whose product is -15 and whose sum is 2
m * n = -15
m + n = 2
yes
wait I made a silly mistake
Think about it for a sec 😉
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✅
I need help this with question now
a^3 - a^2 - 30a^1
ignore my trying to distribute
factor out
wdym
I did
^^^
That isn't a question
a^3-a^2-30a^1 is just an expression
He's asking you to factorise a^2-a-30
If you expand (x-2)(x-3), you get x^2-5x+6
When you go in reverse (from x^2-5x+6 to (x-2)(x-3)) , we say that you have factorised x^2-5x+6
The way you go in reverse, is you solve the equation that youre trying to factorise. If you solve x^2-5x+6=0, you get x=2 and 3, so you can factorise x^2-5x+6 as (x-2)(x-3)
In your case, you have a^2-a-30, and you are asked to factorise it.
bro what
this is a new question
I know, factorise a^2-a-30 by solving a^2-a-30=0
I was giving an example to explain how factorisation is done
@worldly horizon Has your question been resolved?
why you need gcf?
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For this I got this answer. But I am pretty sure it isn't right after checking with symbolab. Just wondering where I went wrong
show your work then
sorry I had to switch over to my phone to take the picture
dang it
try use trig sub
I dont think I have done that before
oh.
pay attention to dx vs du
So I would do this instead?
- C

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Let $F(x,y,z) = z^3+3yz-4x$ looking at the point (2,0,2) and the function $z=f(x,y)$ how do you compute
$\frac{\partial f}{\partial y}$(2,0) $\frac{\partial f}{\partial x}$(2,0) $\frac{\partial ^2 f}{\partial x^2}$(2,0) $\frac{\partial ^2 f}{\partial y ^2}$ (2,0) $\frac{\partial ^2 f}{\partial x\partail y}$(2,0)
mtr123
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
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are you asking how to compute them visually, or just how to compute them?
Since I don't know f I don't know how to compute the derivative and I guess there's some other way which I'm not aware of
can you post the original question?
presumably you are meant to take some level curve of F and solve for z
$F(x,y,z) = z^3+3yz-4x$, we want to check if F(x,y,z) = 0 defines z=f(x,y) as an implicit function.
F(2,0,2) = 0, the partial derivative around this point are continous, $\frac{\partial F}{\partial z}(2,0,2) = 12$
therefore it could be written as z=f(x,y) around the point (2,0,2).
Now I need to calculate the above
mtr123
do you know what f would be then?
if so, you could just calculate the partials at that point
nope, if I knew f it would have been just the partials
well you have that F(x,y,z) = 0 defines z = f(x,y)
oh i just noticed F has mutliple zs in there
Yeah otherwise you could just write z = some x some y
do you have the original question, like an image of it?
it's not in English so thats a problem, but I wrote it pretty accurate I believe
can you send it regardless
either way, you can solve this by finding the roots of the cubic, but i believe there should also be a trick to isolating the zs, just can't think of what it would be right now
what I tried is this -
so I'm pretty sure we get dF/dx = -4, dF/dy = 3z, then we know that
df/dx = -(1/12) (dF/dx) = 1/3 \to_{2,0,2} = 1/3
df/dy = -(1/12) (dF/dy) = -z/4 \to_{2,0,2} = -1/2
-1/12 is the Jacobian of F at (2,0,2)
now differentiating again will get me 0 at each point, but I'm pretty sure it's wrong
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Hey yall, quick question! If i have to run a unistrut support beam, every five feet and there is 670 feet that i have to run it. How many pieces of unistrut do i need? Also, every five feet i only need half a unistrut not a full piece of it. I need help with the calculations thanks.
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Ll
what do you think
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Can someone atleast give me the formula to figure it out
this is a math server, not an engineering server. google another server for your answer
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Can I have some help with this? I'm getting 2/9*ac but would like to double check
what do u think this is equal to
is it just 1/c? the second fraction cancels itself out to equal 1 so theres just the first fraction that remains?
oh yeah... I'll have to give that another go.
can I cross simplify with these sort of problems?
thanks for pointing out that c. It looks really obvious now 🤦🏻♂️
If I had a fraction like b/b^3 could I simplify that to 1/b^2?
Tried again, is it 2a/9c?
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Do you want to know only if it converges, or do you want to know specifically what it converges to (assuming it converges)?
Only if it converges/diverges. I understand to use the ratio test, but can't seem to progress after writing it all out, as I don't seem to see the next steps
I wanna basically know the method, can I just look at the serie and determine directly?
iirc, ratio test only tells you if a series diverges, but is inconclusive on whether it converges
Personally, I would show that your series is less than another series that you know converges
It does. It's inconclusive when the limit of ratio = 1
Adam Chebil
but i don't think it works here
@paper sage Has your question been resolved?
3^k gets bigger much more quickly than 2^k
and 5^k gets bigger much more quickly than 4^k
so you can essentially consider 3^k/5^k
not quite.
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basically there exists a tail after which the errors are less than e(3/5)^k
so the total error is less than epsilon basically
so you can just consider 3^k/5^k more or less
not quite
would you mind elaborating
3/4, not 3/5
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Prove Z5 x Z5 x Z5 is isomorphic to Z25 x Z5.
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
