help-0

[mystic swallow]

i'll send one, hang on

[ancient hedge]

Alright thanks

[mystic swallow]

https://www.youtube.com/watch?v=WUvTyaaNkzM&list=PLZHQObOWTQDMsr9K-rj53DwVRMYO3t5Yr&ab_channel=3Blue1Brown

[upbeat eagle]

U do A level?

[mystic swallow]

its the first video in a course, but he explains things well along with the underlying concepts so i think you'll enjoy it

https://www.youtube.com/watch?v=XOUwIdufY9Y
here's a good blackpenredpen video for integral practice; he has quite a few others on calc and is generally a great channel

[ancient hedge]

Im not really sure what that is 😓😓 since its not really here in my country

[mystic swallow]

!done

[lone heart]

If you are done with this channel, please mark your problem as solved by typing .close

[mystic swallow]

@ancient hedge

[ancient hedge]

Alright thank you for thr help 😭😭😭

Hope i will pass my exams

[mystic swallow]

np

[upbeat eagle]

by typing .close

[ancient hedge]

Hello i watched the video and i get how to solve it now thank you so much guys

.close

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[vital mortar]

Hi i wanna ask,

The original question in bahasa indonesia, here the translate:

Purchasing a bag will get a 30% discount, while for shoes it will be 10%. The initial price of bags and shoes is the same, namely p. The amount of money that must be paid is cheaper... than the initial price.

(Note: all percentages are against original price)

A. 30%

B. 40%

C. 50%

D. 60%

E. 70%

What i already do:
P = same for 2 item,

Let say P = 100.000
100.000 for bag
100.000 for shoes

So bag 30% = 70.000
And shoes 10% = 90.000

So,

X/100 * 200.000(from p multiply by 2) = 160.000

X is percentage i get 80%

100% - 80% = 20%

[vital mortar]

Original question

I get answer 20% but they say the right answer is 40%

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[slim perch]

I need help

[slim perch]

It is in geometry

With similar triangles

I just need to find z on question 28

<@&286206848099549185>

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[silk steeple]

I need help with this

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[silk steeple]

i know it's tan right

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[alpine sable]

need help w this

[alpine sable]

taking x^4 as t

u get 1/t+3root(t)+2 dt

but i dont see how to go further

[sour verge]

You can factor the denominator and use partial fractions

[alpine sable]

thats what i was thinking

but factor how

[foggy pecan]

also:

[alpine sable]

ahh

ok i was subbing in x^3

and this too

i always struggle w these type of questions

[mellow tartan]

cant we just factor here too?

[mellow tartan]

yeah

[foggy pecan]

then, decompose into partial fractions

[alpine sable]

ok and then partial fraction

alr ty guys 🙏🙏

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[foggy pecan]

yw

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[hard mountain]

anybody see whats wrong with this?

[lone heart]

@hard mountain Has your question been resolved?

[hard mountain]

import numpy as np
from numpy.linalg import inv

A = np.array([[1,2],[3,4]])
b = np.array([6.0,6.0])

Ad = np.diag(np.diag(A))
Al = np.tril(A,k=-1)

def SplitSolve(A,M):
    N=A-M
    invM=inv(M)
    x=np.ones(len(A[0]))
    for i in range(1000):
        x=invM@(b-N@x)
        print(x)
    return x


Jacobi=SplitSolve(A,M=Ad)

[hard mountain]

Apparently Jacobi method doesn't work for any non-singular matrix, but for matrices that strictly diagonally dominant.

.close

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[alpine sable]

yo

[alpine sable]

im on a redemption and ik its not 100 or 50

if i get this wrong im cooked

i fr need help

[fallen verge]

each part of the chart is 25%

[alpine sable]

i dont get it

cus i already did 50 and ik it aint 100

[alpine sable]

nvm i got it wrong

close this

[limpid turret]

.close

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[limpid turret]

@alpine sable you can always close it yourself, too

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[crimson spire]

can someone explain how I get from the second equation to the general solution in terms of u and v

ive tried all sorts of ways of manipulating it and i cant get to the desired form

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[foggy pecan]

read and analyze:

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[fleet iris]

Hi, I have an issue with 2022 aime II problem 14

[fleet iris]

According to https://artofproblemsolving.com/wiki/index.php/2022_AIME_II_Problems/Problem_14#Solution, floor(999/c) stamps of value c, floor((c-1)/b) stamps of value b, and b-1 stamps of value 1 are needed. But shouldn't we need floor(1000/c) stamps of value c? For example, take c divides 1000, and b divides c, e.g. c = 200, b = 20. Then, we have floor(999/200) = 4 stamps of value 200, floor(199/20) = 9 stamps of value b, and 19 stamps of value 1. The maximum such a collection can give is 200*4 + 20*9 +19*\1 = 999, just shy of the needed 1000. Is this my error, or is this an error in the solution?

[lone heart]

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[fleet iris]

<@&286206848099549185>

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[fleet iris]

<@&286206848099549185>

[livid sage]

when i did this problem some time ago i came to the conclusion the solution had the right answer but with a slightly wrong function

where the discrepancy occurs when c is a factor of 1000

[fleet iris]

Ok, just needed the confirmation!

Probably gonna edit the wiki page later

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[waxen walrus]

hi

[indigo forge]

.close

[waxen walrus]

i need help

in maths

[storm ridge]

!da2a

[lone heart]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[waxen walrus]

what is this

[gray isle]

that triggers the above bot message

noone knows what you need help with
so the longer you delay asking your question the more likely people will lose interest and stop checking out this channel

[grizzled burrow]

idk they MIGHT need it

[gray isle]

.close

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[left isle]

!status

[lone heart]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

@crisp fog Has your question been resolved?

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[ancient cargo]

The graph of y=ax(x-B) passes through the origin, why? Find the values of a and B in this quadratic given that: The axis of symmetry is x=-3 and the coefficient of x is -12

[ancient temple]

What are you having problems with?

[ancient cargo]

setting the question out

[ancient temple]

Do you see why it passes through the origin?

(0,0) is the origin here, and if you want a curve y(x) to pass through it, what must the value of y(0) be?

[ancient cargo]

y int?

[ancient temple]

Hmm?

Here, y(x)=ax(x-B) and they are claiming that the curve passes through the origin

[ancient cargo]

y int is zero

[ancient temple]

What does y int mean?

[ancient cargo]

intercept

[ancient temple]

Yep

[ancient cargo]

so what would we do next

[ancient temple]

You tell me, if the y intercept is 0, what is y(0)?

[ancient cargo]

0?

[ancient temple]

Yes

Now look at the curve we have been given

Y(x)=ax(x-B)

Is Y(0)=0?

[ancient cargo]

yes

[ancient temple]

Right, so it passes through the origin

[ancient cargo]

yep

but i need to find the values of a and B

given the info

[ancient temple]

Yes, we are getting there

What are the roots/zeroes of y?

[ancient cargo]

Im not sure

zero?

[ancient temple]

Yes, there's another one

If you put x=B, y=0 right?

[ancient cargo]

-3

[ancient temple]

No, -3 is not a root

[ancient cargo]

3

[ancient temple]

A root is a value of x when y becomes 0

If you put x=0 you get that y(0)=a(0)(0-B)=0

So x =0 is a root

[ancient cargo]

u would have to find that is x in the quadtatic equation?

[ancient temple]

The same way, x=B is also a root, since y(B)=aB(B-B)=0

[ancient cargo]

so y would be a

[ancient temple]

How?

Are you aware that the axis of symmetry passes through the midpoint of the roots?

[ancient cargo]

isnt that only for the y value?

[ancient temple]

What?

[ancient cargo]

u find the vertex of x then subtitute into the equation

[ancient temple]

You mean the vertex of the parabola

[ancient cargo]

yes

[ancient temple]

This will not help us in any way to find the axis of symmetry though

What will help us is the fact that the axis of symmetry passes through the midpoint of the roots

[ancient cargo]

can you expand on wt u mean by roots

like sqrt?

[ancient temple]

No, a root is when the value of y becomes 0

For example, take the quadratic equation x^2-2x+1=0

If you solve it, you will get x=1

So 1 is a root of y=x^2-2x+1

Are you following?

[ancient cargo]

so u mean x int

intercept

[ancient temple]

Yes

So the x intercepts here are 0 and B right?

[ancient cargo]

yes

[ancient temple]

The axis of symmetry will pass through the midpoints of the x intercepts

[ancient cargo]

yes

[ancient temple]

Right, so our x intercept are 0 and B, their midpoint is (0+B)/2

[ancient cargo]

yes

[ancient temple]

B/2=-3

So B=-6

[ancient cargo]

yep

[ancient temple]

So y=ax(x-(-6))=ax(x+6)=ax^2+6ax

And we also know that the coefficient of x =-12

What is the coefficient of x here?

[ancient cargo]

1

i mean a

a

[ancient temple]

No, its 6a

[ancient cargo]

i was thinnking abt x^2

sorry

[ancient temple]

Np

[ancient cargo]

yea its 6a

[ancient temple]

Yeah, and the coefficient of x is -12 according to the question

So, 6a=-12

a=-2

[ancient cargo]

yep

so B would be zero and a would be negative 2

[ancient temple]

No,B is -6 from here

[ancient cargo]

ok

i was looking it after you subsitituted

mb

do u time for one more but its the same question

[ancient temple]

Try doing it on your own if it's the same question

[ancient cargo]

i meant by same question but different information

i got my answer and just double checking for it

[ancient temple]

Okay

[ancient cargo]

The graph of y=ax(x-B) passes through the origin, why? Find the values of a and B in this quadratic given that: The vertex is (1, 4)

i got my equation to be

y=a(x-1)^2+4

[ancient temple]

What about a?

[ancient cargo]

is it just 1?

[ancient temple]

No, also this is wrong

You know the vertex right?

Can you find the axis of symmetry from that?

[ancient cargo]

is it reverse operations?

[ancient temple]

I don't know what you mean,

Do you know that the axis of symmetry passes through the vertex?

[ancient cargo]

do i turn vertex form into quadratic from

[ancient cargo]

yes

[ancient temple]

ok, the axis of symmetry will look like x=c right?

We want to find c, then we will know the equation of the axis of symmetry

[ancient cargo]

dont u need a and b?

[ancient temple]

Yes, we will find it

But right now, if we find the axis of symmetry we can find B, just like last time

So let's try to find the axis of symmetry

[ancient temple]

Do you agree with this?

[ancient cargo]

by c do u mean b?

[ancient temple]

No

C is some other number we don't know yet

Do you remember in the last question, the axis of symmetry was x=B/2?

[ancient cargo]

yes

[ancient temple]

Since the equation of the parabola is the same, you can make B/2=1, since the vertex lies on the axis of symmetry and the x coordinate of the vertex is 1

So B=2

So y=ax(x-2). Now we have to find a

[ancient cargo]

so substitute

[ancient temple]

Yes

[ancient cargo]

so it would be 2(2-2)

[ancient temple]

You substituted the wrong values

y=ax(x-2) passes through (1,4), so when x=1, y should be equal to 4

4=a(1)(1-2) so a=-4

[ancient cargo]

oh ye

[lone heart]

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[past spade]

can someone solve this with steps? (It's the wrong answer but I did find the right answer, I just want to see if 1. There's an easier trick and 2. What I'm doing wrong

[lavish cave]

What did you do to get that answer?

https://www.symbolab.com/

BTW Symbolab can give you the steps

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[oak gulch]

a) find the tangent line at x=-1
b) the tangent line intersects the function in a different point than (-1, f(-1)), find it

what I have:

I found the tangent line or w/e it's called

and I'm unsure how to find the other point where it intersect

I can find it in Geogebra by doing -x+5=f(x) but idk how to show the math

Sorry if it's super obvious or something

[lone heart]

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@oak gulch Has your question been resolved?

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[humble steeple]

if sm1 can pls help

[lethal belfry]

!status

[lone heart]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[humble steeple]

😏

1

[lethal belfry]

Identify the vertically opposite angles to begin

[humble steeple]

ok

Idk what that is

[gray isle]

quick google search

[raw stream]

Did you miss classes?

You could

try

Khanacademy

[gray isle]

its essentially just an application of angle sum on a line twice

[humble steeple]

dawg i’m tired

😭

Throw a bone to the dog

😭🙏

my last one n i’m tired

pls

[fallen warren]

we have the equation:5x+20=6x-4(because they are opposite angles)
solve for x we have x=24
we also have:(5x+20)+(y-18)=180 because they are supplementary angles
=>5*24+20+y-18=180
=>y+122=180
=>y=58

[humble steeple]

thank you

so much

😭😭🙏🙏

[fallen warren]

just forget the n line lol, it won't do anything

[humble steeple]

I’m done with that ima gts now thanks bro🙏🙏🙏

[lone heart]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

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[lone heart]

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[alpine sable]

i don't think that's even elementary

[tiny fable]

yeah I don't think that's doable either

[lone heart]

@alpine sable Has your question been resolved?

[weary sleet]

Try byparts

[lone heart]

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[past spade]

Is this the right answer?

[tiny fable]

it is not

[past spade]

would it be the method doesn't apply?

not valid*

[tiny fable]

what are f(-1) and f(-1/2)?

[past spade]

-2 aand -1/8-1/4+1?

5/8

[tiny fable]

it says f(-1/2) = -1/8

they already did the math for you

[past spade]

oh

I thout we were checking if -1/8 was imbetween -2 and 1

since f(-1) = -2 and f(0)=1

[tiny fable]

in order to contain a root in an interval, you need f to be negative on one side and positive on the other

but if you use the interval they claimed, f is negative at both of those points

[past spade]

oh okay I understand

[tiny fable]

alrighty

[past spade]

thanks

.close

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• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid shuttle]

Could anyone check my proof for me? Accidentally cropped the question one sec

[lone heart]

@vapid shuttle Has your question been resolved?

[pseudo ice]

Think you missed negative signs in the other steps? Otherwise seems all good to me, other than minor things (e.g. make sure you state that you’re assuming the polynomials with b’s to be the inverse of 1 + ax)

[vapid shuttle]

oh right, the sign should alternate right?

b2=-ab1

=a^2

and then -a^3

and so on

TY

.close

[lone heart]

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[lone heart]

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Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

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[sweet valley]

Hey guys, m trying to figure out somethng for this question.

For the constraint "x+y is less than or equal to 210" the x value ends up being 210, but the y value isnt? Howcome is this?
I thought you have to make one equal to 0 and then solve for the other one, but by doing that wouldnt y also be 210?
Any help appreciated!!

[royal meadow]

you have to satisfy multiple constraints

so (0, 210) would satisfy that constraint but not all of the other ones

[sweet valley]

okay so, how would i go about it?

which constraints should i start with?

[royal meadow]

each of the inequalities is a region on the graph

[sweet valley]

is there lke a good rule of thumb to go by or? just trial and error?

[royal meadow]

the things that satisfy all of the inequalities is graphed as the intersection of all of those regions

in this case you can see it's that unshaded region

then the optimal points will always be the corners

so you can just look at the corners

or work out the corners

the intersections of the lines

[sweet valley]

okay that makes sense but

when im trying to draw the line

for say x +y is less than or equal to 210

how do i figure out the value of y that will satsfy all constraints

[royal meadow]

you should graph the thing and find the region

and then each of the region's corners will be just two lines intersecting

probably

and then you can find the corners

[sweet valley]

but how can i graph it without knowing what the y value wll be for the line

[royal meadow]

when you're graphing each individual line, you don't need to satisfy all the constraints

you just need to satisfy the constraint for the line

then after you have all the lines you can look at the region that satisfies all the constraints

[sweet valley]

so i would start by graphng y as 210 and x as 210 too? even though the graph only goes up to 150 on the y axis?

[royal meadow]

yeah

[sweet valley]

how would i do that if the axis only goes to 150 tho

[royal meadow]

if it goes off the graph space it probably doesn't matter

the region will probably always fit on the graph

otherwise they wouldn't do it like that

[sweet valley]

okay let me give it a goo

thank youuu ill see f i can get to it

nah i dont get it

how can i figure out the y value

i get that it has to satisfy all the constraints

but how on earth am i meant to get to fguring it out to be 100, like t is in ths case

<@&286206848099549185>

[royal meadow]

ok so can you basically see the region

do you know what it looks like

[sweet valley]

thats the mark scheme, youre asked to make the region yourself using constraints you made in the part of the question prior

[royal meadow]

ok

but have you done that

[sweet valley]

yeah

[royal meadow]

like have you graphed it

[sweet valley]

these are the ones

[royal meadow]

ok cool

ok but yeah so it helps to actually graph it

[sweet valley]

yeah but

the graph im given

goes up to 150 on the y axis right?

[royal meadow]

yeah

[sweet valley]

and lets say for the x+y 210 one

[royal meadow]

but like can you see the actual region

fits in the space

[sweet valley]

i dont follow

[royal meadow]

like

the lines go out of the space

but it usually turns out that the region that satisfies all the constraints fits in the space

[sweet valley]

so i would plot it so the lines go off the graph and the region i get in the end would still be the same?

[royal meadow]

yes

like

[sweet valley]

howcome they did it diff on the mark scheme?

[royal meadow]

the lines always go off the graph, right? they just go on forever

[sweet valley]

yeah yeah ig that

[royal meadow]

i'm not really sure

[sweet valley]

alright thank you tho :)

ill gve it another go

[lone heart]

@sweet valley Has your question been resolved?

[lone heart]

@sweet valley Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

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[lone heart]

Available help channel!

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Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cloud nacelle]

Have you tried

king's rule

with that you could get rid of x

[alpine sable]

what is kings rule

never heard of that

[cloud nacelle]

uh

i think its not a rule

rule in the sense i dont know what its called

but

do you know that you can write integral of f(x) as f(a+b-x)

where a and b are the limits

[alpine sable]

mhm

[cloud nacelle]

now you add up these two

so 2I = ( )

youll get rid of x

and then solve

[alpine sable]

hmm

[cloud nacelle]

understood?

[alpine sable]

yeah

just replace fx

[cloud nacelle]

continue solving

then

[alpine sable]

so xsin^3(pi-x)/1+cos^(pi-x)

[cloud nacelle]

you forgot x

(pi-x)(sin^3(pi-x)

as i said f(x)

[alpine sable]

oh okay

(pi-x)(sin^3(pi-x)/1+cos^(pi-x)

[cloud nacelle]

yeah

[alpine sable]

so do i use quotient rule orrr

how to solve this

[cloud nacelle]

quotient rule?

[alpine sable]

oh nvm

trig identities

[cloud nacelle]

can you show me the integral

which ur gonna solve

[alpine sable]

this one?

(pi-x)(sin^3(pi-x)/1+cos^(pi-x) with tis instead

[cloud nacelle]

you gotta add up this

and the question

[alpine sable]

1+cos^pi-x becomes 1-cosx

[cloud nacelle]

.

[alpine sable]

oh

[cloud nacelle]

yeah

[alpine sable]

hnmmmm

[cloud nacelle]

got it?

[alpine sable]

not really sorry

[cloud nacelle]

ill try to use paint

hold on

[alpine sable]

yeahhhh

i did that

[cloud nacelle]

you add these 2

now

[alpine sable]

oh okay

[cloud nacelle]

what did you get

[alpine sable]

xsin^3x+(pi-x)sin^3(pi-x)/1+cos^2x+1+cos^2(pi-x)

[cloud nacelle]

whats sin(pi-x)

[alpine sable]

sinx

[cloud nacelle]

yes

[cloud nacelle]

now simplify this

tell me what you get

[alpine sable]

hmm

xsin^3x+sin^3x / 2 +cos^2x -cosx

[cloud nacelle]

uh?

you should get this

because

xsin^3x - xsin^3x = 0

[alpine sable]

oh okay 😅

[cloud nacelle]

now you have to solve this

[alpine sable]

alright

[cloud nacelle]

now you can do this

right

[alpine sable]

so then 1+cos^2x is -sinx right

then u do u sub?

[cloud nacelle]

you could just divide the numerator and denominator by

cos^2 x

and then substitution

[alpine sable]

oh true

[cloud nacelle]

no..

[alpine sable]

i mean

sin^2x

[cloud nacelle]

cos^x - 1`= -sin^2x

[alpine sable]

yes

[cloud nacelle]

not cos^x + 1

[alpine sable]

oh

yeah true

[cloud nacelle]

yup

[alpine sable]

so wait what would that give

sinx^2/1?

[cloud nacelle]

sec^2x in the numerator

and

sec^2x + 1 in the denominator

[alpine sable]

so sec/cos is basically 1 right

wait no

sec is 1/cos

so then 1/cos^2x?

[cloud nacelle]

sec^2x

[alpine sable]

sec^2x/cos^2 x

that's 1/cos^4x

right

[cloud nacelle]

yes

ur gonna find a problem in this

did you try though?

[alpine sable]

it's a bit complex

so the denomenatior would be 1/cos^4x + 1/cos^2x

[cloud nacelle]

no...

you did something wrong

[alpine sable]

oof

[cloud nacelle]

ill show u

[cloud nacelle]

btw ill add the sin^3(pi) later cuz its constant

okay

[alpine sable]

alr

[cloud nacelle]

i divided the numerator and denominator by

cos^2x

[alpine sable]

ohhhh

so then do u factor the fraction out or

[cloud nacelle]

what will you do next

[alpine sable]

wait nvm

[cloud nacelle]

there's no point

[alpine sable]

yeah

i just saw

[cloud nacelle]

yeah

Whats your next step after this?

its a bit tricky

[alpine sable]

make it sec^2x

[cloud nacelle]

mhm

then?

[alpine sable]

oh

what about u sub

[cloud nacelle]

exactly

think

[alpine sable]

-tan^2x?

[cloud nacelle]

why?

[alpine sable]

or

[cloud nacelle]

there's no tanx

in the question

no use

[alpine sable]

oh yeah

[cloud nacelle]

the numerator is

sec^2x right?

[alpine sable]

yup

[cloud nacelle]

so you need to use the substitution whose derivative is sec^2x

to get rid of it

which is?

[alpine sable]

if there's no tanx idk

[cloud nacelle]

you gotta substitute tanx

tanx = u

[alpine sable]

mhm

[cloud nacelle]

reason being

when you differentiate

you get sec^2x dx = du

so you get rid of numerator right

[alpine sable]

yes

[cloud nacelle]

but now the problem arises what about the denominator?

there's no tanx

[alpine sable]

mhm

[cloud nacelle]

in denominator

so now

u use triangle

and right secx

in terms of "u"

[alpine sable]

woah

[cloud nacelle]

yeah its long

[alpine sable]

a triangle?

[cloud nacelle]

i mean

[alpine sable]

how do u use that

[cloud nacelle]

i mean

trigno identity

[alpine sable]

oh alr

[cloud nacelle]

because tanx = u

i want to write secx in terms of u as well

[alpine sable]

1 over root 1+u^2

[cloud nacelle]

i think now u understood

i got a better method

[alpine sable]

okay

[cloud nacelle]

tanx = u

right

sinx/cosx = u

now square both the sides

you get [sin^2x]/[cos^2x] = u^2

[alpine sable]

yup

[cloud nacelle]

now write

sin^2x in terms of cos^2x

[alpine sable]

1-cos2x/2

[cloud nacelle]

2?

hope its visible?

[alpine sable]

yupp

[cloud nacelle]

wrote the same thing

again

so

1/cos^2x = u^2 + 1

now integrate

the numerator is 1

though

remember

and you have to change limits

[alpine sable]

pi^3/3 + pi

[cloud nacelle]

dont forget the sin^3(pi)

integrate this

basically

do put the limits

I think now you can proceed

:)

[alpine sable]

tysm :D

[cloud nacelle]

??

[alpine sable]

wait nvm

one sec

[cloud nacelle]

ur telling me answer?

[alpine sable]

arctan(pi/root 2)/root 2

[alpine sable]

ye

[cloud nacelle]

idk about the limits

[alpine sable]

0 to pi right

wait

gotta change them

[cloud nacelle]

no

[cloud nacelle]

yes

you have to change em

[alpine sable]

from 1/2 to 1/pi^2+2

[cloud nacelle]

1/2>>>

???

we did tanx = u

put x = 0

what's u

[alpine sable]

0

[cloud nacelle]

yes

wait

hold on

tanx = u

tanpi is also 0

wtf

[alpine sable]

XD

[cloud nacelle]

the substitution

[alpine sable]

so it's all 0

[cloud nacelle]

ah

we tanx = u

right

[alpine sable]

yes

[cloud nacelle]

😂

is there a mistake

check ur answer

is the answer given?

[alpine sable]

nope

[cloud nacelle]

oh no

[cloud nacelle]

OH FUCk

WE DID A MISTAKE IG

[alpine sable]

[cloud nacelle]

UH

IM SO SORRY

[alpine sable]

DW ty for trying

[cloud nacelle]

i found the mistake

the question is simpler

[cloud nacelle]

the question was simpler 😭

small mistake complicated

we have to solve this

[alpine sable]

oh yay

[alpine sable]

let's get it

[cloud nacelle]

its easy now

dude i forget to include

bruhh

my bad

[cloud nacelle]

solve this get yo answer

[alpine sable]

pi^2-2pi

[alpine sable]

this is after applying kings method right

[cloud nacelle]

yes

dont forget to divide the answer by 2

after you get the integral

cuz we addded right

[alpine sable]

yup

[cloud nacelle]

you can proceed now right

[alpine sable]

yup tysm

.close

[lone heart]

Channel closed

Closed by @native radish

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fading kestrel]

did not understand the question

what does it want me to find?

[cloud nacelle]

do you know what scalar triple product is?

[fading kestrel]

no

it was not taught

oh okay

yet this was given in the questio

[cloud nacelle]

a.(b+c)

[fading kestrel]

okay

[cloud nacelle]

or you can just

find the

determinant

[fading kestrel]

you mean first a x b

then that x c?

[cloud nacelle]

dont do that

find the determinant

[fading kestrel]

how

oh okay

[cloud nacelle]

understood?

[fading kestrel]

so the result is gonna be a scalar?

[cloud nacelle]

yeah

[fading kestrel]

ohhhhh

i have more doubts

wait lemme solve this one

[cloud nacelle]

okay

[fading kestrel]

what is the answer coming ?

determinant value

i calculated 4

it says -30

[cloud nacelle]

the sign

is missing here

[fading kestrel]

oh wait

i did not take into account any signs

fuck

[cloud nacelle]

oh no

[fading kestrel]

what were u sayin tho

what is missing

[cloud nacelle]

sign

before 2j

[fading kestrel]

i think a i see a minus

you don't?

minnus are a bit blurry ig

if you look at vector c

youll see a minus before 3 as well

am i right? @cloud nacelle

[cloud nacelle]

wait

[cloud nacelle]

its blurry

[fading kestrel]

hmm

great

answer confirmed

[cloud nacelle]

alr

[fading kestrel]

trying method 2

[cloud nacelle]

method 2?

[fading kestrel]

.

[cloud nacelle]

bxc*

not +

sorry

[fading kestrel]

yeah

it was coming to be zero that way

[fading kestrel]

oho thank you for helping me out man

you dont how much youve helped

[fading kestrel]

answer is not coming this way too

it came by determinant method tho

[cloud nacelle]

a.(bxc)

hmm

sure no calculation error?

[fading kestrel]

could you try once? sob

do you solve multiple doubts at the same time?

[cloud nacelle]

ask

why not

ill see if I can help or not

[fading kestrel]

no no

im sayi

mutliple channels

[cloud nacelle]

your choice

you can ig

[fading kestrel]

wbu personally

like isn't it tiring

mentally

those who do

anyway

did you get to minus 30

[cloud nacelle]

i didnt try 💀

[fading kestrel]

cuz i got -4 by this formula

[cloud nacelle]

im on pc

[fading kestrel]

sed

[fading kestrel]

so?

[cloud nacelle]

workout

[fading kestrel]

what

[cloud nacelle]

solve i mean

i dont trust my self solving determinant

mentally

[fading kestrel]

anyway

its outta syllabus ig

next question

[cloud nacelle]

yup you should know applications

[fading kestrel]

look

[cloud nacelle]

mhm

whats the issue

[fading kestrel]

what did your angle come out to be?

my one came zero

[cloud nacelle]

in that case they are collinear

so ur answer is right

[fading kestrel]

but the youtube video says angle is 180

[cloud nacelle]

can be 180 or 0

[fading kestrel]

but

you see

they asked angle

[cloud nacelle]

u did something wrong

[fading kestrel]

look

there are two ways

one is bby vector prodcut

and other by scalar product

[cloud nacelle]

scalar = 0

[fading kestrel]

yeahhhhhhhhhhhhhhh

ya get me

and by cross,

[cloud nacelle]

but um

yeah

[fading kestrel]

cos theta = 0

[cloud nacelle]

go ahead

[fading kestrel]

no no wait

n

no no

by scalar way

[cloud nacelle]

cross product should be 0

no

wait

what am i asying

fuc

dot is non 0

if they are collinear

[fading kestrel]

look

[cloud nacelle]

did you find AB and CD

[fading kestrel]

listen to me

[cloud nacelle]

ok

[fading kestrel]

and i will be grateful

i am dying aaah

[cloud nacelle]

😂

say it

[fading kestrel]

hm

now

ab = i + 4j - k

cd = 2i - 8j + 2k

has been also verified from google

https://www.teachoo.com/3459/748/Example-27---If-i-j-k--2i-5j--3i-2j-3k-and-i-6j-k-are-position/category/Examples/

now

the matter is

[cloud nacelle]

ah

this aint collinear

teachoo

damn bhai

[fading kestrel]

man

you dont listen

[cloud nacelle]

sorry bhaiya

[fading kestrel]

youre an indian helper

hehe

noice

[cloud nacelle]

yes

[fading kestrel]

ab x cd = |a||b|sin(theta)

so

sin(theta) = ab x cd/|a||b|

[cloud nacelle]

yes

id recommend using scalar/dot product

[fading kestrel]

but why

[cloud nacelle]

because

[fading kestrel]

that is what i wanna ask first

[cloud nacelle]

dot product is easier

compared to vector

[fading kestrel]

hmmm

par chalo

maan lo bande ko chull hai

[cloud nacelle]

phir sahi hai

fayda nahi chull ka timewaste hai

[fading kestrel]

par ayega kaise usse angle

yeh batao

sin theta = -4j -16k/36 aa raha bkl

ab kya karein?

@cloud nacelle bhai

[cloud nacelle]

bolo

[fading kestrel]

batao na

cross se kaise karte hain

sin theta

achha chalo cos se kar liya

aa gaya 180 degree

@cloud nacelle

pls

fir ab lekin isse sirf anti parallel prove hota hai

collinear kisne bola

upar neeche bhi toh ho sakte hain

teachoo ne yahi khatam kar dia answer

maine lekin i showed that unit vector of both will be same if they are collinear

aap kya kehna chahoge?

[cloud nacelle]

um

antiparallel collinear nahi hota?

[fading kestrel]

look

kya bologe isko?

[cloud nacelle]

collinear

anti parallel

[fading kestrel]

collinear kaise bola

[cloud nacelle]

vector ko shift karo

[cloud nacelle]

collinear vector search karo

[fading kestrel]

achha

achha

matlab chalo maine faaltu working dikhayi but koi nahi

next question pe chalte

then

yeh dekho

first question

answer diya hua hai

dekho unit vector parallel to the diagonal two each ayenge na

cuz ulti direction mein bhi hoga ek vector

bas sign ulta

right?

zerome bhau

@cloud nacelle

[cloud nacelle]

hi

[fading kestrel]

zerome bhau aap apna doubt clear kar rahe ya fir

helping there?

[cloud nacelle]

hogaya

ab idhar

hu

batau

[fading kestrel]

aapko bhi doubt tha?

yeh kaise?

[cloud nacelle]

chota sa

[fading kestrel]

bhagwaan mein khot?

[fading kestrel]

.

[cloud nacelle]

lekin

wo vector do hi diya na

[fading kestrel]

hain?

[cloud nacelle]

• nahi

bruh

• nahi

abe

(-) sign nahi aayega

usse vector ka direction ulta hoga

thodi na dusre diagnol ka direction aayega

[fading kestrel]

dekho

abcd apna paralleogram

[cloud nacelle]

ha

[fading kestrel]

ab is a vector

bc is b vector

now

[fading kestrel]

yes

[cloud nacelle]

jo diagnol wo likha

wo ye hai

minus lagane pe arrow ka direction change hoga diagnol ka

dusra diagnol thodi hai wo?

[fading kestrel]

ruko

yeh dekho

sahi banaya

?

am i wrong here?

[cloud nacelle]

-a nahi hai wo

-2a hoga toh?

kisko pata

[fading kestrel]

parralelogram hai na

same magnitude