help-0

[swift grail]

Thats 2 (in a good way)

[rigid shale]

there might be more sol where a^2 -4a = b^2

how do I write these?

[swift grail]

Wdym?

Thats good for b = 0

Now for a = -2

[rigid shale]

?

[swift grail]

Plug a = - 2 for other 2 sols

[rigid shale]

now we go to the other one?

thats a lot fo sols

[swift grail]

Yes like i said 4 sols

[swift grail]

Yes

[rigid shale]

is it possible that the other one has only 1 sol?

[swift grail]

Could be but idk

It prob has 4 too

[swift grail]

You did the same mistale like last time

Its not b = 0 and a = 2 its b = 0 or a = 2

[rigid shale]

but if you plug b=0 in the first equa you get a = 2

and the other way around

wait no

im dumb

give me a sec

[swift grail]

You get a = 4 or a = 0

[swift grail]

Check your a = 2 case

[rigid shale]

maybe now?

sry Im really tired rn so I make a ton of mistakes

[swift grail]

Is that a solution?

[rigid shale]

I dont think so

so should I eliminate it?

[swift grail]

Yes

$a , b \in \mathbb{R}$

[ocean seal]

casework

[rigid shale]

yeah right

ok we are left with these 4

[swift grail]

That would just give you 0 and 4 again

[rigid shale]

?

[swift grail]

Yes

[rigid shale]

ah k

I made every single mistake possible along the way but we made it

thanks for the help you are a real one

[swift grail]

a = 2 , b = +/- 2i

If number is complex then it can be written in the form $a + bi$ where $a , b \in \mathbb{R}$ if you get that one of them is complex then you shouldve gotten it in another way such that they are real

[ocean seal]

casework

[rigid shale]

I dont get it
if a or b are complex I should do what?

[swift grail]

Ignore it

[rigid shale]

k

[swift grail]

Like for example if you get a = i and b = 0 then that would give z = i. But if z = i then solving for a and b should give you a = 0 , b = 1

[rigid shale]

ohh so you should re-solve to get the correct writing

[swift grail]

If you dont understand you dont really need to but its nice for understanding

[rigid shale]

am I supposed to do it here?

we get a = 4 b = 0 or a = 0 b = 0

both we alrdy have

[swift grail]

Not really. Basically every complex number can be written in terms of $a + bi$ such that they are real. If they are not real you can ignore it. You wont lose a solution because if a solution exists it should be able to be written in that form.

[ocean seal]

casework

[rigid shale]

ohhh I get it

cool

[swift grail]

So like here for example you got a = 2 and b = 2i that gives 2 + 2i² = 0. But you can ignore it because you know there exist real a and b to write that solution.

[rigid shale]

okie Im gonna close the room now
thanks for the help!!!!!!

.close

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[subtle light]

what have you tried so far

[alpine sable]

Nothing, cuz I don’t know what to do.

[vapid shuttle]

Have you ever solved an equation before

[alpine sable]

Ofcourse

[vapid shuttle]

What do you normally do then

When you solve them

[alpine sable]

Collect like terms?

[vapid shuttle]

Okay so let’s say you wanted to collect like terms here

What’s stopping you

[alpine sable]

The fraction

[vapid shuttle]

Right

Is there any way to get rid of a fraction?*

[alpine sable]

uhm😨

[vapid shuttle]

If it was x/5 = 10

What would you do

[alpine sable]

divide both sides by 5?

[feral raven]

x=50

[vapid shuttle]

Multiply both sides by 5 you mean

[vapid shuttle]

!nosols

[lone heart]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[vapid shuttle]

And that’s wrong

So stop interrupting

[feral raven]

Sorry

[alpine sable]

dam😭

[vapid shuttle]

Anyways, what undoes division?

Multiplication

[alpine sable]

Yurrr

So wait, in this case I multiply both sides by (x+3)

[vapid shuttle]

Yes

And then collecting like terms should be simple from there

[alpine sable]

?

[vapid shuttle]

Is this a test

[alpine sable]

Nope

Im using a pamflet

[vapid shuttle]

Ah great thanks

[alpine sable]

😭😭

[vapid shuttle]

Okay then yes, you wrote that step correctly

Now just simplify

[alpine sable]

So would I cancel the x+3 on the lhs?

[vapid shuttle]

Yes

[alpine sable]

The answer is 1.8!!

Uhm hello?😭

Sir🧍🏾‍♂️

@vapid shuttle

[subtle light]

yep 1.8 is right

[vapid shuttle]

Agreed

[lone heart]

@alpine sable Has your question been resolved?

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[tardy river]

i just really need a soundboard to ask questions. 😦 sorry once again if this is wrong.

[lone heart]

@tardy river Has your question been resolved?

[tardy river]

no

[tardy river]

<@&286206848099549185>

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@tardy river Has your question been resolved?

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[paper crypt]

how can i explain this better, and how can i mathematically solve this without having to look at a graph?

[lone heart]

@paper crypt Has your question been resolved?

[paper crypt]

<@&286206848099549185>

[unborn flax]

hey

can sm halp me

\

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@paper crypt Has your question been resolved?

[toxic lion]

Try making sure you mark all of the congruent sides so you can visualize it.

[toxic lion]

For this one.

[lone heart]

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[alpine sable]

#19

[alpine sable]

for a (1,0,0)
for b (1,1,0)

is the question asking for just an example?

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[gleaming quartz]

I need help with a logarithmic function problem

[gleaming quartz]

the answer is there, but i'm not sure how to get there

Here's my work

<@&286206848099549185>

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@gleaming quartz Has your question been resolved?

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@gleaming quartz Has your question been resolved?

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[naive valley]

where's the rest of the question?

[gray pine]

Let me ask them

Linearly dependene

Linearly independence

It will be surely linearly dependence

[naive valley]

what is your reasoning?

[gray pine]

One Equation is mutpiple of other so?

[naive valley]

what equation?

i don't see any

[gray pine]

Vectors with matrix form?

[naive valley]

i don't know what you mean

[mortal magnet]

an equation is something in math that sets two sides equal with an =

theres no = sign in the picture, so what you are pointing at are not "equations"

[mortal magnet]

please include the answer choices in the question screenshot

[mortal magnet]

also, A is not a scalar, so Ax is not a "multiple of x"

[naive valley]

if the list were just x and Ax, you could not conclude whether they are linearly independent or dependent
so you need to explain what's special about the given list

[naive valley]

why assume that all of the entries of A are the same?

[gray pine]

Yes. I wanted to but someone sent me this shit

[gray pine]

Hmmmm

I guess i have to skip this problem.

[mortal magnet]

ask them for the answer choices

[gray pine]

Sorry mtt for not uploading full question 🫣🫣

[naive valley]

have you given more thought to what's special about a list of 6 vectors

[gray pine]

One can be free?

[naive valley]

can you state that more precisely?

[gray pine]

I mean five vectors will be connected each other and one vector will be free

.close

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[rapid crow]

terms are positive. In this sequence, (a5)^2 = 3a10, and for any three consecutive terms, 2(an + an+2) = 5an+1. Find the first term of this geometric sequence.

[rapid crow]

please help

im stuck after a = 3r

[hot swallow]

you should send the actual question

(a * r^4)^2 = 3 (a * r^9)

[rapid crow]

after simplifying this i get a = 3r

[hot swallow]

okay thats great

now use the second information

[rapid crow]

that is where im stuck

[hot swallow]

i see

this will fetch you a proper equation in terms or a or r

[rapid crow]

okay

let me try

[hot swallow]

i think you can solve it after this

[rapid crow]

yes

that helps

thank you

.close

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[vocal tapir]

If G is an undirected graph with vertices V={1, 2, 3, 4}, such so deg_g(1)=deg_g(2)=deg_g(3)=1, and deg_g(4)=2
Is this statement true or false.

[vocal tapir]

need help understanding this

[stoic hound]

Honestly, just try drawing it out

See if such a graph is possible

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@vocal tapir Has your question been resolved?

[vocal tapir]

<@&286206848099549185>

nvm

.close

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[fervent crystal]

Hi

[fervent crystal]

Can someone show me how to do this

No c i mean

a and b matched

c i got 7/8

[mystic swallow]

figure out what the chance is that they win

[fervent crystal]

Its supposed to be 1/8

[mystic swallow]

and then subtract that from 1

[fervent crystal]

Thats what i did bro

[mystic swallow]

okay

so?

[fervent crystal]

Answer doesnt match

Can u read what i wrote please

[mystic swallow]

is NOT the champion?

[fervent crystal]

Yes

[mystic swallow]

i think that should be it

7/8

i

[tidal summit]

that is 7/8

[mystic swallow]

i'll check again

it cant b 1/8

the answer

its not possible

unless theres smth unincluded

!done

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[agile copper]

help

[agile copper]

I did it likes this but my answer tells me it is wrong

:[

pls help

anyone? :[

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[agile copper]

someone pls help

.close

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[kind pewter]

Is this equivalent to[2ln(ax)]^2?

[charred jewel]

no

[kind pewter]

Can I ask another question

[charred jewel]

go ahead

[kind pewter]

Is this the dirrative?

[charred jewel]

seems about right

[kind pewter]

Thanks 😊 🙏🏻

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[young scaffold]

can someone explain how to work this out? I tried solving this but kept getting 1/12

[subtle light]

can you show your work

[subtle light]

i see

the integral of $sin^2(x)$ isn’t $\frac{1}{3}cos^3(x)$

[ocean seal]

y0shi

[subtle light]

since if we try and take the derivative

we have to do the chain rule as well

[young scaffold]

I see

[ancient temple]

In order to integrate $sin^2(x)$ you should use the fact that $sin^{2}(x)=\frac{1-cos(2x)}{2}$

[ocean seal]

smidgin

[subtle light]

yep

[young scaffold]

.close

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[ionic moat]

i currently have this formula
Angle = 0.5 * arcsin((0.35 * G * 1.8 * d) / v^2)
(Degrees = (A * 180) / pi)

The thing is, it's limited to a range of -45 to 45 degrees, I don't know how to make it... not limited to -45 to 45 degrees

(The 0.5 * arcsin... is required, result wont be accurate otherwise)

[alpine sable]

Can you explain more about the question? What do u need?

[ionic moat]

The formula only returns a number within the range of -45 and 45

[prime badge]

no, the question

[ionic moat]

That number is correct/accurate, but it shouldn't have to be limited to that range

[prime badge]

what does it calculate

[ionic moat]

Angle of elevation in rads

[alpine sable]

So u saying that sin inverse by 2 thing gives in between-45 to 45 ?

Not giving general solution?

[ionic moat]

i'm not familiar with math terms

[alpine sable]

Uhh like again

I’m not sure what you are exactly asking?

See

Angle gives output in radians

U wanna convert to degrees, fine that’s what u posted too

So what’s the issue

[ionic moat]

The degrees is limited to -45 to 45

[alpine sable]

Okay

[ionic moat]

I prefer if it isn't

The output, in degrees, isn't incorrect

It's just limited

[alpine sable]

Yeah depending on the input

[ionic moat]

e.g. fill in 5000 for d (distance) and 172 for v (initial velocity)
asin is returning, nothing, undefined, NaN

[alpine sable]

You can restrict the output like that range (if input is also restricted also yk)

[alpine sable]

Yes you know u can’t give any input right

[ionic moat]

-1 to 1

[alpine sable]

Input should be such a way that sin(arg), -1<=arg<=1

Ye

[ionic moat]

is there some way to like... work around that limitation

[alpine sable]

Uh like it depends on the derivation of that final expression

And also can u check the units?

[ionic moat]

wdym

[alpine sable]

Units value

[ionic moat]

also, a bypass, dividing the input for arcsin by 2, then multiplying the output by 2 seems to work

[alpine sable]

I see.

[ionic moat]

but i don't think that's.. proper math

[alpine sable]

Yes

[ionic moat]

i don't think that really matters as it works 🥶

[alpine sable]

Like u said this is angle of elevation so if 5000 is length and 172 is velocity, u expecting that it gives what’s the elevation angle.

I’m not sure about it, you have to check it again.

[ionic moat]

and the input with these parameters for arcsin is 1.043469442942131

I don't know what to do or what to change to make this work

The output isn't wrong, it's just limited

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@ionic moat Has your question been resolved?

[lone heart]

@ionic moat Has your question been resolved?

[lone heart]

@ionic moat Has your question been resolved?

[lone heart]

@ionic moat Has your question been resolved?

[ionic moat]

<@&286206848099549185>

[lone heart]

@ionic moat Has your question been resolved?

[ionic moat]

:/

[lone heart]

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[lone citrus]

hey Ive stuck on this trig problem to find the exact value for sin 7pi/4 and the professor wants me to use the unit circle to solve it

[limpid turret]

Sounds like you need to try some angle sum tricks

Err. Not even. Yeah just look at your unit circle

[lone citrus]

yeah I think I figure it out lmao

I was suppose look at the unit circle and find 7pi/4 and sin that

[foggy copper]

it's the same as sin(-pi/4), isn't it?

which is equal to -sin(pi/4)

[lone heart]

@lone citrus Has your question been resolved?

[lone citrus]

no, the unit circle gave me the degrees of 7pi/4 which is 315 degrees

[lone heart]

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[foggy copper]

but aren't the sines equivalent, since the two are 2pi apart?

[lone citrus]

um yeah. I honestly may be wrong

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[tough lake]

What is the proper formula to solve this

[tardy stag]

your pronoun field is the same as mine

you're trying to make a formula for the blue squares?

[tough lake]

Yup 😢

[tardy stag]

hmm well i'm not sure what turnover is but it will probably be everythign multiplied together

you should test on simple data that you can calculate by hand

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[tough lake]

No

[lone heart]

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[autumn vortex]

I want someone to check my work...

My work

[lethal belfry]

send your working first, don't ask in the future please

[autumn vortex]

i shared my working

it took some time to get uploaded

internet was slow

[lethal belfry]

OK, so if you construct a truth table , you;ll see the sample space is 36

[autumn vortex]

ok

[lethal belfry]

the answer you get should be 11/36, draw a truth table and you'll see why

[autumn vortex]

but see the question

[lethal belfry]

ah, I didn't see the second part, sorry

[autumn vortex]

they are asking for conditional probability

np

[lethal belfry]

so p(sum is 7 given 2 appeared atleast once)/p(2 appeared at least once)

right?

[autumn vortex]

yeah

A=GETTING 7 AS SUM

E=2 APPEARING ONCE

[lethal belfry]

p(sum is 7 given 2 appeared atleast once)/=1/12

[autumn vortex]

YES

[lethal belfry]

*1/18

my bad

[autumn vortex]

OH YES

[lethal belfry]

5,2 ; 2,5 are the possible combinations

[autumn vortex]

YES

[lethal belfry]

can you tell me what p(2 appears at least once) is?

[autumn vortex]

11 cases

(1,2),

[lethal belfry]

cool, correct, no need to list the cases

[autumn vortex]

(2,2)

[autumn vortex]

OK

[lethal belfry]

so what's the answer?

[autumn vortex]

the final answer?

[lethal belfry]

yes

[autumn vortex]

P(E/A)=P(A INTERSECTION E)=2/36*36/6=12/36=1/3

[lethal belfry]

11/18

[autumn vortex]

11/18?

[lethal belfry]

yes

p(sum is 7 given 2 appeared atleast once)/p(2 appeared at least once)

[autumn vortex]

they are asking conditional probability...

how did you get 11/18?

[lethal belfry]

p(sum is 7 given 2 appeared atleast once) is 1/18, right?

[autumn vortex]

oh...

[lethal belfry]

p(2 appeared at least once) is 11/36

[autumn vortex]

ok got it

[lethal belfry]

I think

I made a mistake in the calculations sorry

[autumn vortex]

yes

oh

11 possible cases

but we are considering 2 cases

so the probability will be 2/36

[lethal belfry]

which is?

1/18

2/36=1/18

[autumn vortex]

P(2 appering at least once and sum is 7)

so... 1/3 is correct...

[autumn vortex]

P(2 appering at least once and sum is 7)

[lethal belfry]

yes

that

[autumn vortex]

hmm

[lethal belfry]

is ok, say 2/36

now what's P(sum is 7)

[autumn vortex]

6/36

1/6

[lethal belfry]

11/36

order matters here

ok, gtg now, sorry

[autumn vortex]

11/36?

[lethal belfry]

yes

[autumn vortex]

wait but the cases are (1,6),(2,5),(3,4),

(4,3)

(5,2)

(6,1)

so its 6/36..... or 1/6

that is P(Getting seven as sum...)

question👇

my work 👆🏻

If anyone comes in this channel please check the answer if it's correct or not

THANK YOU!!

<@&286206848099549185>

[lone heart]

@autumn vortex Has your question been resolved?

[autumn vortex]

.close

[lone heart]

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[ebon talon]

I need help

[remote heron]

https://www.statisticshowto.com/errors-in-the-trapezoidal-rule-and-simpsons-rule/

$|E| \leq \frac{(b-a)^3}{12n^2} \max (|f''(x)|)$

[ocean seal]

jan Niku

[remote heron]

where'd you get stuck?

this is for trap rule

[ebon talon]

thank you

This will help i bookmarked the page

Actually, if you could answer one question

what would f'' be?

[remote heron]

,w D[D[9/x^2]]

[ocean seal]

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[ebon talon]

so how would i continue

i have been doing math for 11 hours now

[remote heron]

just use the formula

plug and chug

[ebon talon]

ok

[remote heron]

did you do the first one you posted?

[ebon talon]

no

i need to just go to bed

cant.... think.... straight

[remote heron]

oh, well

ill be around tomorrow

[ebon talon]

https://tenor.com/view/yikes-ow-gif-24458516

[remote heron]

if you wanna sleep, feel free to ping

or, we could do it now

[ebon talon]

hmm

[remote heron]

ill just be doing math all day tomorrow so

wont bug me none

[ebon talon]

it cant kill me

ill do one of the above

dealers choice

[remote heron]

i mean we can do one

[ebon talon]

^

[ebon talon]

up to you

[remote heron]

heres the formula

[ebon talon]

ok

[remote heron]

lets do your first one

$\int _{-5}^8 2 \sin (x+8) \dd x$

[ebon talon]

ok

[ocean seal]

jan Niku

[remote heron]

so, lets start with the easy part.

n unknown, desired to be found.

E is given, what is it?

[ebon talon]

yesh the #of partitions right

E is 4 x 10^-4?

[remote heron]

yea

whats a and b?

you can take a wild guess, its the bounds, but just so were on the same page

[ebon talon]

8,-5

[remote heron]

kk

now the hard part

f''(x)

[ebon talon]

would i integrate by parts 1st?

[remote heron]

you dont need to integrate

its asking for the second derivative

[ebon talon]

ok then -2/(x+8)cos(x+8)

[remote heron]

no, i dont think so

whats $\dv x \sin (x+8)$?

[ocean seal]

jan Niku

[remote heron]

we need the chain rule, yea?

[ebon talon]

uv'+u'v?

[remote heron]

product rule, but close

[ebon talon]

no thats product

yeah damnit

[remote heron]

$\qty( f(g) )' = f'(g) g'$

[ocean seal]

jan Niku

[remote heron]

im being really sparse with the notation here, does this track with you?

[ebon talon]

yes]

[remote heron]

okay

so we can apply that to $\dv x \sin (x+8)$

[ocean seal]

jan Niku

[ebon talon]

idk why i wanted to integrate at first

[remote heron]

first we need to know $\dv x \sin x$

[ocean seal]

jan Niku

[remote heron]

but thats just cosx

[ebon talon]

cosx

yea

[remote heron]

then, the chain rule hits

we end up getting $\dv x \sin(x+8) = \cos (x+8) \dv x (x+8)$

[ocean seal]

jan Niku

[remote heron]

can you simplify?

[ebon talon]

cos(x+8)^2?

d/dx

or no

(x+8)cos(x+8)

[remote heron]

don't get too tripped up over it, nothing special is happening here

[ebon talon]

d/dx

ok

[remote heron]

how about just $\dv x (x+8)$

[ocean seal]

jan Niku

[ebon talon]

where is cos

[remote heron]

covered up

you cant see it

[remote heron]

whats this simplify to?

[ebon talon]

1?

[remote heron]

yea

[ebon talon]

ok

[remote heron]

okay, now simplify $\cos (x+8) \dv x (x+8)$ using what youve just said

[ocean seal]

jan Niku

[ebon talon]

just cos(x+8)? idk i feel like i should see this

[remote heron]

yea, you got it

[ebon talon]

ok

whew

[remote heron]

so $\dv x \sin (x+8) = \cos (x+8)$

[ocean seal]

jan Niku

[ebon talon]

ahahhahahahahahah

[remote heron]

which is convenient

[ebon talon]

bravo

[remote heron]

can you do the second derivative? we need one more

[ebon talon]

just -sin(x+8)

[remote heron]

$\dv [2] x \sin (x+8) = \dv x \cos (x+8)$

[ocean seal]

jan Niku

[remote heron]

yup

okay, were almost done, actually

[ebon talon]

first time ive smiled tonight

[remote heron]

$|4 \times 10^{-4} | \leq \frac{(8+5)^3}{12n^2} \max( |-2 \sin(x+8)|)$

we gotta resolve one more thing

that max

but, take a guess

OH wait we lost a two ...

my fault

[ebon talon]

nw

[ocean seal]

jan Niku

[remote heron]

trust me this is what youd get, lets keep moving

care to take a guess on the max?

remember how sin looks

,w plot |-2sin(x+8)| from x=-5 to x=8

[ocean seal]

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[ebon talon]

2 is the max

[remote heron]

it is, yea

okay

$4 \times 10^{-4} \leq \frac{13^2}{6n^2}$

[ocean seal]

jan Niku

[remote heron]

ill do some algebra for you

you get it from here?

[ebon talon]

yes lemme at him

:0

[remote heron]

i think youre gonna have to trust your own math ultimately

i dont have any working trap code

maybe you have some? and you can test with an error plot

although i see no reason what you'd get by solving this problem using algebra would be wrong

[ebon talon]

lets see what desmos says

[remote heron]

I'd probably plot a max error vs n plot

if i had the dang code

[ebon talon]

1592.16 blah blah so 1593

[remote heron]

[ebon talon]

let me see

shit

let me see another way

[remote heron]

huh?

[ebon talon]

i am checking

not you

lol

my math was off

[remote heron]

,w (4E-4)<=13^2/(6n^2)

[ocean seal]

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Requested by janniku

[remote heron]

what

[ebon talon]

so 325?

[remote heron]

n bounded above you say

no this is nonsense

[ebon talon]

lol ok

[remote heron]

wait

[ebon talon]

mine was too... i was off by about 1k

nw

$-\frac{325\sqrt{2}}{\sqrt{3}}\le :n<0\quad \mathrm{or}\quad :0<n\le \frac{325\sqrt{2}}{\sqrt{3}}$

[ocean seal]

Drippy Scav

[ebon talon]

i got the same

[remote heron]

why is n bounded above

maybe i dont remember numerical right

[ebon talon]

https://tenor.com/view/shocked-surprised-gasp-what-cat-shock-gif-635629308990545194

[remote heron]

shouldnt it be consistent along n for some cts function?

[ebon talon]

yes we are looking for the amnt of partitions

[remote heron]

no i mean

[ebon talon]

for a specified bound

[remote heron]

if we increase n we should eventually get a better estimate

[ebon talon]

yes

but its asking for the min i think

[remote heron]

so why is your answer bounding n from above?

,w sqrt( (4E4) 13^2 /6 )

[ebon talon]

i typed it into symbolab and thats what it told me, a direct copy paste

[ocean seal]

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Requested by janniku

[remote heron]

[ebon talon]

1062 is incorrect

[remote heron]

im tired too so maybe this is a waste

[ebon talon]

meh its was a nice conversation

i missed you

[remote heron]

no no

i think were close

im trying to sort

[ebon talon]

np

formula is $|EsubT<=M(b-a)^3/12n^2$

[ocean seal]

Drippy Scav

[remote heron]

sub is _

and yea

[ebon talon]

just for interating that it is the trap rule i think

[remote heron]

so we should get an upper bound i hate it lol

[ebon talon]

bc i have some that are sub s for simpson

you did help me remeber how to use the chain rule

i can find the answer with one more incorrect answer

[remote heron]

okay wait

[ebon talon]

then our numbers all change

ok

np

[remote heron]

i think i get it

we want $|E|\leq 4E-4$

[ebon talon]

https://tenor.com/view/very-nice-excellent-yes-meme-nod-gif-17397471

[ocean seal]

jan Niku

[remote heron]

right

so really, were solving $|E| \leq \frac{(b-a)^3}{12n^2} \max |f''| \leq 4E-4$

[ocean seal]

jan Niku

[ebon talon]

^^^^^

yas

i think so

[remote heron]

this gives you the right answer

which here is uhh

[ebon talon]

you need a raise lol

[remote heron]

$\sqrt{ \frac{13^2}{6 (4E-4) }} \leq n$

[ocean seal]

jan Niku

[remote heron]

we dont get paid, actually

loose network of volunteers

[ebon talon]

i know i was being facetious

[remote heron]

i see

well, youd besurprised

[ebon talon]

?

[remote heron]

some people assume this is a real outfit

[ebon talon]

lol

informal upswing

start asking for venmo

so in this case E is?

[remote heron]

ah but then i couldnt put volunteer on my resume

[ebon talon]

true

[remote heron]

in this formula?

E is shorthand for scientific notation

[ebon talon]

is it the f''

oh ok

[remote heron]

4E-4 means 4 x 10^(-4)

[ebon talon]

right oj

[remote heron]

we should get the same thing you got before, but i guess off by one due to rounding

,w sqrt(13^3/(6 * 4E-4 ) )

so 266

it still like to see an n vs error plot

[remote heron]

whatd i miss

[ebon talon]

no clue

[ocean seal]

Results provided by WolframAlpha

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Requested by janniku

[remote heron]

typo

[ebon talon]

its ok

[remote heron]

do you get a new problem then

lol

[ebon talon]

yeah

[remote heron]

oh, this is nothin

the max is the same

well, its the same idea

here its 3

agreed?

[ebon talon]

yes

[remote heron]

a and b changed, but thats easy

[ebon talon]

9 not 13

mag max lowered too

[remote heron]

$\sqrt{ 3 \frac{(6-(-3))^3}{12 (2E-4) }} \leq n$

[ocean seal]

jan Niku

[remote heron]

EZ

[ebon talon]

lul

[remote heron]

,w sqrt( 3 9^3 /( 12 (2E-4) ) )

[ocean seal]

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[remote heron]

see

i told you it was easy

[ebon talon]

[remote heron]

ill be around tomorrow if you wanna tackle some others and you get stuck

i guess you get the idea now though

[ebon talon]

for tomorrow

lol

yes thank you

[ebon talon]

it was just that 2 instead of the 3

[remote heron]

its actually really similar

[ebon talon]

yeah ^5 and 180n^4

only diffy

[remote heron]

better image

ye

this is a coding class?

you should code a calculator

you shouldnt be doing this by hand

just a suggestion

[ebon talon]

lol i have went through a whole notebook so far and im only studying for exam 1

how much is a code calc

[remote heron]

numerical is pretty serious stuff

code calc?

[ebon talon]

yeah

[remote heron]

are you not coding at all in this class?

[ebon talon]

no its just calc 2

[remote heron]

i mean programming

[ebon talon]

yeah

ik

[remote heron]

oh, weird

well, you could start, if you wanted

but up to you

[ebon talon]

im shooting for a BS in aerospace engineering

i might need one eventually

[remote heron]

so, matlab

[ebon talon]

yee

[remote heron]

just get a license now

[ebon talon]

ok

[remote heron]

maybe after the exam

[ebon talon]

yes

i will look into it. i will be ahead of the curve

[remote heron]

if you can learn some matlab

figure out how to use mathematica alternatively

i mean

matlab can calculate symbolic integrals and derivatives

itll save ya

either way

ill stop keeping you up

[ebon talon]

no its totally fine

im a glutton for it

[remote heron]

chat gpt 3 can implement these

[ebon talon]

fr have been doing math more than 12 hours today

[remote heron]

in matlab

it happens

[ebon talon]

i really want to fully understand/memorize this

[remote heron]

only thing more important than calculus is linear algebra

[ebon talon]

i am on colleges presidents list for having 4.0

yes

i will have to do that and matrix solutions as well as defferential calc

[remote heron]

its pretty fun

[ebon talon]

maybe need to take english with that spelling lolol

[remote heron]

youll probably do controls and stuff too

presumably

i forget exactly what aero take at my uni

[ebon talon]

im excited. is that weird lol

[remote heron]

for classes?

nah isnt it nice to finally have shit you can care about

dont forget to get internships

you can start applying for jobs in your first year

no one will stop you

[ebon talon]

im applying for nasa pathways

[remote heron]

fantastic

[ebon talon]

i have been welding for more than 10 years

im 31

[remote heron]

oh, cool

im nontraditional too

i went back to college at 28

high school drop out

[ebon talon]

noice!

[remote heron]

about to get my masters

[ebon talon]

hell yeah

[remote heron]

waited a little long to get internships so applying for jobs late

but itll be fine

[ebon talon]

inspiration

[remote heron]

youll do better

[ebon talon]

nah

btw

yesterday or the day befopre i checked out your music on your profile

not bad

[remote heron]

oh, uzeda?

[ebon talon]

who is that

[remote heron]

i been on a noise rock tear lol

[ebon talon]

]yeah

[remote heron]

i always have random crap down there

muslimgauze and shit

[ebon talon]

where are you from

hmm

pm me

[remote heron]

colorado

[ebon talon]

ohj okj

[remote heron]

ah its general knowledge

i post pics on mountains all the time

[ebon talon]

no worries

[remote heron]

lol

you usa?

[ebon talon]

i will be attending boulder uni

hopefully

[remote heron]

ooooo

[ebon talon]

yeah im in idaho

[remote heron]

my brother got his masters in aerospace from there

hes currently a uhh

[ebon talon]

its number 6 or something for best aero schools

[remote heron]

well i dont wanna say bc that isnt general knowledge

[ebon talon]

yeah

[remote heron]

hes a senior aerospace engineer at a company

you can probably guess

[ebon talon]

noice

yee

my goals

fr

maybe space x

idk

[remote heron]

actually yea u wanna connect?

[ebon talon]

when i was in the army i working on chinooks

that would be EPIC

[remote heron]

HAHA i knew it

military ppl are cool

[ebon talon]

haha

[remote heron]

i went back to school through CC

[ebon talon]

im in CC rn

[remote heron]

so it was all GI ppl and highschool drop outs lmao

[ebon talon]

lmao

[remote heron]

fun crew

[ebon talon]

yeah im one of the old guys

[remote heron]

dude its nice everyone will assume youre a grad student at uni

[ebon talon]

i will pm you my info

[remote heron]

i mean u dont have to

i was gonna say we should connect on linkedin

but u can do whatever

[ebon talon]

i would like to ask your brother how and when and who and stuff... lol not too personal just basic tips ans tricks

[remote heron]

im down at the school in the brewery town

[ebon talon]

that works

and pick more of your mathematical brain

.close

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[surreal trellis]

hello

[surreal trellis]

is that circled fx within the d/dx or multiplied by it

[charred jewel]

within

[surreal trellis]

ok thanks

[lone heart]

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[sonic frigate]

ans: C) 35

is my solution right?

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@sonic frigate Has your question been resolved?

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[tidal summit]

why does the log go away?

[tidal summit]

and where does this infinite series come form

.close

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[vapid shuttle]

I am confused how this holds

it looks like it is trying to use the divergence theorem

but, gradf * n isn't a vector field

so I don't see how it would be applicable

[keen plinth]

thats exactly the divergence theorem

[vapid shuttle]

isn't divergence theorem for

F*ds

F being a vector field

[keen plinth]

,,\int_{\del R} \vb f \vdot \vu n \dd A = \int_R \op{div} \vb f \dd V

[keen plinth]

apply this with $\vb f = \nabla f$

[vapid shuttle]

mine states $$\iint_{\partial R} \vec{F}\cdot d\vec{s}=\iiint_{R}\text{div }\vec{F}dV$$

[ocean seal]

Austin

[vapid shuttle]

is this equivalent somehow to f*n

F*ds

[keen plinth]

people write $\vb n \dd A$ as well as $\dd \vb S$

[keen plinth]

,,\int_{\del R} \vb f \vdot \dd \vb S = \int_R \op{div} \vb f \dd V

[vapid shuttle]

f being a vector field

[keen plinth]

yes thats why im bolding it

[vapid shuttle]

Okay thank you

.close

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[misty marsh]

I need help please

[lone heart]

Please post images (such as PNGs or JPGs) of the question rather than other filetypes such as PDFs which have to be downloaded. Non-image downloads can potentially contain viruses or other security risks.

[modern skiff]

which one?

[misty marsh]

All

[naive valley]

!1q

[lone heart]

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[modern skiff]

okay ill give you hints

[modern skiff]

what answer did you get for the first one?

[full grotto]

shlama 3y

[lone heart]

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[lone heart]

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[alpine sable]

I'm not sure what formula to use here

It is obviously a water wave intereference problem

but would that mean it is the same as a double slit interference technically?

since there are two point sources etc.

[summer dirge]

do this in steps

first find the path-length difference

then the wavelength

then the speed

[alpine sable]

okay okay

the difference between the two

sources are

5 cm

but i don't think that's what your asking

actually no it is

5 cm

wavelength is

lambda

$v=f\lambda$

[ocean seal]

mj

[summer dirge]

that's the distance between the two sources, but you want the path length difference

[alpine sable]

could you elaborate on what that means?

is this something to do with making a triangle

like how far away it is from the

actual thing

[summer dirge]

that's the difference between the distance from first source to the point and the second source to the point

[alpine sable]

holdon

so

we have our "d" variable

being 5 cm

[summer dirge]

yes, but it turns out to be irrelevant to this question

[alpine sable]

we need our lambda variable

which we can get by finding velocity

which we need

[summer dirge]

after all, why should the seperation of sources affect how fast the waves they generate move?

[summer dirge]

correct

[alpine sable]

the thing you were talking about

path length difference

I think I know what you mean