#help-0
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Alright
U just need look and comapre numbers
anywasy im lost haha
I can help you run this question down to where im at
If you are interested
Sure
Ok so Basically,
The first question was to Prove ε is 1.6V
So we have 22/n = ε /I -r
I turn that into a y=mc + c
This should be very neat?
Looks right
Alright
Now
regarding find the r value
Im a bit confused
Ill sen you a picture one sec
,rotate
My question can I use method A and B to find r values does that work
And for B
Would it be 1/0.3 or 0.3
And also would you have to similtaneous equation it
@hasty creek
thats where my brain is just like wtf


Into part A?
Sure
1/I = 0.9, 1/n ~ 0
Then sure you can make two equations
So in part B you made y = n and x = I?
It’s better to continue with part A
Less stuff needed to figure out r
🤔

Using A r is 16/9
I guess ill just try trial and error?
and ill let you know?

can u double check its 16/9 i dont wanna fk it up
22y = ε x - r
22 (1/0)= 1.6 1/0.9 -r
-( 1.6 x (1/0.9) ) = -r
So r is 16/9
yeah should be right
imma trial and error
Err
1/n is 0
And 1/I is 0.9
So you don’t need to do 1/0.9
It should be 0.9*1.6
errr what
when i plugged in x and y values
Here
Okok
so 22y = ε x -r
and you r telling me
(0.9,0)
So you put in 1/0.9? as x aka 1/i
thats what i did
No
0 = ε x (1/0.9) - r

so 0 = ε 0.9 - r
Yep

i think i alrdy know whcih one
TY !
nah I dont
I threw it in the calc
didnt get any correct answers
Am I doing it wrong lol
0.3 = 5m -r
0.9 = 13.2 - r
can I plug it in into
x + y = 0
-1 + 5 = 0.3
-1 + 13.2 = 0.9
I got the correct y value (aka the gradient matches up)
@hasty creek
Sry last one

Might have to wipe my calculator
Actually
Since we know everything we can just plug in any single point lmao
No need for equations
Oh
Result:
1.4

Yeah it’s a rounding error
? But I can’t think of a reason
Ok
🙌
I’ll leave it as that
Well thank you once again
Luv u

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Im a bit confused on how to finish it
So
When 2 = even/ even
It means that the 2 evens must have a factor of 2 which related to the [2]
But in this case there is no factor therefore it is an irrational number
Is that a correct statement?
Also let’s say you got
2 = 1even/ 2even
2= (1/2) (even/even)
Would this mean it’s rational
Because these are integer factors
And are a factor of two

Proof is something I tell you
Suppose sqrt(2) is rational, then sqrt(2)=a/b in reduced form
we showed earlier that a is even and b is even, if this is true
(so you can't write it in reduced form)
contradiction
done
boom
pow
you're confusing yourself
Oh ok
If you got
This means that it is a rational number
Why do you keep doing this
It can produce a rational number
what are you writing
2=1even / 2even
it doesnt make any sense
What are you trying to say?
True
It’s more of a question of factors
You need a factor of 2 to be even
So if there is a factor of. 1/2
Is that a factor of 2
no stop
Ok
uh
if they're even, they share a factor of 2, THAT IS IT
the contradiction is they share a factor
we assumed they share no factors


Ok
sqrt(2)=a/b
and they share no common factors
but then we showed
they share a common factor of 2
so we can be done
that's the contradiction
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I was able to do 3a and 3b
I got stuck on 3c
I started to integrate the integral by parts and did that twice
Integration by parts I’m assuming
However, I got the following value:
$[x^nsin(x)+nx^{n-1}cos(x)-n(n-1)I_{n-2}]^{\pi/2}_0$
Yep, I did that
What was ur u and dv
u = x^n
dv = cos x
Might be x^n-1 xcosx
When I simplify this further, the last term cancels though
Since the previous question does xcosx
For u and dv?
Cayush
<@&286206848099549185> Please
Which part?
Part 3c
@civic dragon shut up bruh.
I was able to simplify it to this
We are here to help all our fellow comrades
However, the I_n-2 term seems to cancel
Well it might form a gp
In school, the method we learned was direct proof
So, I integrated the integral by parts twice, and substituted the general term
@silver widget Has your question been resolved?
@silver widget Has your question been resolved?
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My progress:
I am unsure if I did it right (am 60% sure I did smth wrong cuz there cm³ in question but Idk how do I get cm³)
volume is cm^3
notice lbh is (cm) x (cm) x (cm)
and idk why you put weight in cm
So all I have to do is add cm³ in ans?
no
Oh shi
the volume should be cm^3
weight should be in grams
actually I think your number is right
just the units
So in the end I just change it to grams?
,w 105(70)(1.5)8
yes, and correct volume's units as I mentioned
and change to kg
since the question asks in kg
Just cm^3 instead of ^2 right
Oh i didn't notice that ty
Tysm
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hello
Check out co interior angles.
sorry idk what u mean
In your notes wherever you're studying parallel lines,
Find the term co interior angles.
In this case, 2x and y are co interior angles.
There's a property for parallel lines that states sum of co interior angles is 180 degrees.
Might wanna check that out.
@upbeat bone Has your question been resolved?
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Hallo this is a q regarding bias of an estimator (in stats)
This is the question
This is my work
I was wondering if this was right?
I sorta just assumed $E[X_1]$ = $E[X_2] = \mu$
qwq
because that seemed like the only possible way to do the question
but i don't get why the statement above is true, since I thought $\mu = E[X_1+X_2]$
qwq
i mean, no?
the center of the sampling distibution of $\hat X$ is also $\mu$
also yeah this is fine
no worries haha
:D
The concept of bias is related to sampling distribution of the statistic so maybe its better if u think of it that way btw
I will note that thank u again :)
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guys what is this
I'm not familiar with macroeconomics
What are the entire formulas you are looking at
I think delta is 'depreciation rate of capital'
Where was this given?
@tight thunder Has your question been resolved?
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
<@&286206848099549185>
<@&286206848099549185>
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!show
Show your work, and if possible, explain where you are stuck.
,rccw
@torpid roost Has your question been resolved?
<@&286206848099549185>
you can only really add and subtract them if the stuff under the radical √ is the same
so like 3√x + 4√x = 7√x
but 2√x + 9√y is a dead end, nothing left to do
so do i need to make them all the same under the radical
yes but conveniently if you reduce it like you're doing that's the most you can do
they'll line up as much as possible
so what part of what i did was correct?
you reduced the first term correctly
do the same for the other terms
like make a factor tree / look for sets of 4
so would the simplified version be xy^2
Are these the correct 3 simplified equations
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I am having difficulty with units
ye
my brain!!! how?? why??
how is that legally allowed
is it because youre integrating
what does that do to units
We haven't even gotten to the integral yet haha
i know integration/derivation for things like acceleration
ok bro
youre killing me here
note that the number 6 has units of s/W
True, that's a way to fix it
me when "t" is in watts 💀
t has units s and 6 has units s/W, it cancels out to W
well, watts per second, so thats better. (1/6) watts/second
wha?? whered they get the seconds in .../12 (s/W) then
at the bottom equation
because the bottom is 2 * 6 s/W
so it doesnt cancel out then?
i dont know what you mean
if youre just left with W then why is the bottom 2*6s/W
the units of Q are not W
where are you left with just W
the units of Q dot are W
then youre integrating that with respect to time so the units become Ws (or kWhr if you scale)
ok so to clarify, Q dot (W) = t(s)/6 right? thats good?
aslong as you remember that 6 has units s/W
yes
ok so yes it is dimensionally homogeneous technically
because they all cancel out
ok i understand it now, thank you
much appreciated
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sry dumb question
but i can just rewrite this right
like put the = alll the way to the right
instead of all the way to the left
cuz i hate it when it looks like this xd
yes, but be careful with how you move things around
Ok
@tulip oasis Has your question been resolved?
U dont move the equals sign, u just move the values to the left and right of the equals sign
If thats what u r talking abt then yes
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stuck on this problem, think i’m in the right track but not sure ?
you have 3 y sides and 2 x sides
those are the fences
and the area is x times y
you know $3y + 2x = 1000$
TRAMPELTIER
and you wanna maximize $x \cdot y$
TRAMPELTIER
okay
lemme think
we can write x in terms of y (or y in terms of x)
take this $3y + 2x = 1000$ and solve for $x$
TRAMPELTIER
which gives $x = (1000-3y)/2$
TRAMPELTIER
and then, you can in the target function that we want to maximize substitute x by this equation
And then the target function only depends on y
and we can easily maximize it by taking the derivativ, setting to 0 and finding the maximum
questions?
so I substitute the x for 1000-3y/2
then derive the new target function and set it equal to zero to find the critical numbers ?
yes
because you'll see that the target function is a quadratic in y
and it will be a quadratic that grows negatively
so there's a maximum in that quadratic
ok thank you
np
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No idea where to start from in this problem ...
Also that, dont know how or if it will help. Very complicated problem for a 12th grade student imo... Help
@tacit barn Has your question been resolved?
<@&286206848099549185> please help me
Where do I even start in this?
i cant really see the problem well
im in the last year of high school
This is usually a problem youd encounter on the final exams, and it most likely is one of the final ones if not the final one
Its like the last 6/100 points
In my country the entrance exams to uni have like 4 problems, containing 4-5 sub-questions each of them(each problem is total 25 points) and this is like the D4 or D5
Thanks 🙏
been a while since ive done this
Just ping me because I'll close my phone to try it myself
Its alr man, most of our professors wouldn't be able to solve this either
ok
so
when you wrote [a, - inf)
did you mean ( -inf, a]?
@tacit barn
just to make sure
Where
at the top i think?
can you give some context for the problem so i have something to base it off of
At the domain and the range of f?
Well we have the function f(x) given to us with a domain of (0,+inf) and a range that ive found by the first derivative which is [1,+inf) (f has a total min value f(1)=1). Then we have the following information about x0 and that f is increasing on the mentioned interval (1,2) and that the tangent line is that of the above form. And it asks us then to prove that the limit above is -infinity
I tried my best translating the problem from greek to english man srry lol
My guess is that we play with the fact that f is increasing in the interval (1,2) not sure tho...
But we both agree the limit is a/0 but what a and what 0
Thats the issue
@tacit barn Has your question been resolved?
hm
@tacit barn Has your question been resolved?
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Are components of an eigenvector orthogonal?
Like for example, if you have an angle and a magnitude for a vector in 3d space
You can write the vectoe components as trig functions
Is this true for eigenvectors too?
For symmetric matrices yes
Eigenvectors for distinct eigenvalues are always ortho
For example, in PCA, we have symmetric matrices for covariance so the representative eigenvectors we get as output are indeed orthogonal
Is this with the caveat that the matrix is symmetric?
Yes
https://bit.ly/PavelPatreon
https://lem.ma/LA - Linear Algebra on Lemma
http://bit.ly/ITCYTNew - Dr. Grinfeld's Tensor Calculus textbook
https://lem.ma/prep - Complete SAT Math Prep
Watch this
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I could use some help with a statistics problem. I think I understand how to do the rest of this problem, but I straight up do not know how to get part a.
I'm trying to wrap my head around part a but I am having difficulty. I know there's 21 possibilities per stop and 4 stops total
I just don't know how to translate that into an actual answer. Unless my base assumption is wrong?
Part b is just 1/N x 1/N where N is the answer from a, right?
like, I feel like I'm almost there on my knowledge but something fundamental is not clicking. Any help is most appreciated.
So you’re right there’s 21 possible outcomes [0,20] for the first stop, but then you have to think about what happens on the second stop- if 1 persons gets off at stop 17, only [0,19] people can get off at stop 18
So if you had 1 person on the bus how many possible outcomes are there?
They have to get off eventually, so if we count the number of exits per stop you’ll see 4 possible outcomes: last stop: 0001, third: 0010, second: 0100, first:1000
So what happens if there’s a second person?
Try and reason your way through it, what choices can each person make?
They only get off once
off or not off at every stop
Or off at which stop?
so each individual person has 4 possibilities?
Yes
so it's 4^n where n is the total number of people?
Okay, that makes sense. I had it backwards on my paper. I was doing 20^4 and the answer felt wrong
4^20 = 1.1E12
In that case 1 person would have 1 possible outcome 1^4
11 billion looks about right though
Okay, cool. What about part b?
Is it 1/N x 1/N where N is 4^20?
Or do I have to figure out the total number of possibilities per individual stop?
So if no one gets off at stop 17, that's 1 out of the 21 total possibilities there
And if it happens again that is another 1/21 chance for the next stop?
so is it 1/21 x 1/21 or is it the first thing I said?
Oh, wait, maybe I'm misunderstanding the question. It's asking for the number of possibilities in the event that no one leaves in the first 2 stops, not the chances of it occuring.
Right, also I don’t think it’s either of those options
yeah, it isn't. Would it just be what we already did but for only 2 stops instead of 4?
That looks good to me
And then for c, if half the passangers leave in the first 2 stops, then all we have left are 10 passengers and 2 stops, so 2^10 possible outcomes?
That I’m not so sure about
oh, hm...then I'm not sure what it would be.
Is it exactly half or at least half?
exactly half
"the event that half of the passengers leave by stop 18"
Would it be double my original answer? Cuz either "half" could be in either place?
So 2^10 x 2 = 2048?
hello?
I’m not sure, I’m getting 48/128 for the case of n=4
wait, what?
for the probability of occurrence?
or for the total number of possibilities?
96 / 4^4 = 96/256
I have no idea what I am looking at...
I'm confused as to how the total number of possibilities could be less than 1
the questions is asking me to count how many different possibilities exist if half the people on the bus get off in the first 2 stops
So wouldn't that just be the number of ways exactly 10 people can get off in the first 2 stops + the total number of ways the other 10 could get off in the last 2 stops?
@manic ruin Has your question been resolved?
96 of the 256 possibilities have exactly 2/4 riders getting off on stop 1 or 2
You have to imagine the fourth column because it wouldn’t fit
I thought there were 20 riders?
How did we get to 4?
or does it not matter as long as the ratio is 1/2?
Because I was using 2 as a simple case but then I was worried about that being too small / similar to other things
okay, so how do I apply that to my answer?
Do I multiply the total number of possibilities obtained in part a by 96/256?
No
I am very lost
On the case of n=2, 8 have exactly 1 person getting off at stop 17 or 18, which looks like 1/2 of the cases, but let’s check another case, eg n=4 for exactly 2 people getting off at stop 17 or 18, which when we go out and count them there are 96/256 = 3/8 ≠ 1/2. So we know this is more complicated than it looks
okay, so then how do I figure it out for 20 people where 10 get off at stops 17 and 18 without counting as that seems difficult?
without counting by hand that is. I must be missing a formula somewhere along this process
Is the total number of possibilities 20 C 10 x (something)?
cuz the first 2 stops eat 10 of the people but it doesn't matter which 10 so it's just a nCr thing?
is it just 20 C 10 x 2?
idk, I think I'm not understanding something more fundamental here maybe. I think I'm just gonna talk to my professor about it tomorrow during her office hours.
Yeah it looks like the pmf = 0.5 for the sum of 20 uniform variables from 1:4 but I don’t have a simple solution
okay, well I still appreciate all the help you gave me. Thank you. I have some other questions for my professor anyway so I think it'll work out with me going to her office hours tomorrow morning.
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help
if you need help with a math question,
ask asap.
(before people lose interest and start skipping this channel when browsing)
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you can factor by grouping
i tried
!show
Show your work, and if possible, explain where you are stuck.
but i keep getting the wrong answer
one sec
this is the answer
what i did was
i grouped it
and i used binomial products to seperate -3xy^3 - 9y^4
I know what's the answer is like but I asked you to show your work
im doing that just give me time
actually ill show you my written working out instead of retyping it all
alr dnoe
done*
cant factorise further 😭
in this line, replace $(2x^2-3y^2)$ with $\rsq$ and try to factor it again
hayley!
replace it what? sorry
its a red box
you seem to be struggling with factoring it out
indeed
if you replace it with something abstract like a colored box (or another variable i guess) it can make it easier to see what you need to do
why would you expand when you just factored 
idk 😭
$(2x^2-3y^2)\blue{u} - xy\blue{u}$
hayley!
@tardy stag where did u pull u-xyu from ???
basically
you're getting really confused with the subexpressions
yeah
you're trying to factor out (2x^2 + 3y^2) right
2am moment
yes
💀
ill turn ur head into a skull irl stfu
what do I Need to Do
factor out u
where does u come in when the question is this
oh shit
im so dumb
there is no U
act like a normal human being for once
replace the d back
alr
lemme try solving it
jump
This channel is wild
easy now
no need to insult others or give them death threats
true its just the 2am math getting to me
@full apex Has your question been resolved?
do u need help with this?
everything
sorry go on
so like
what exactly is the question
ong bro
wait
all ive got
are you okat
ok bet
certainly
im going to kill you
that is ok
some people find it hot
u are definitely not ok if u want to kill someone
my bad brither
all is said in a not meant fully manner
boobs yea

ive heard of that show
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Im a e-kitten
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Could somebody help me with this please?
try expanding
The equation?
yes
use sin(a+b) and cos(a+b) formula
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Let △ABC, M ∈ (AB),
AM/AB = 2/7
Knowing that MN ∥ BC, NP ∥ AB, P Q ∥ AC, QR ∥ BC,
RS ∥ AB, N, R ∈ (AC), P, S ∈ (BC), Q ∈ (AB).
a) Calculate AN/NC, CP/PB, BQ/AQ.
b) Show that AM = BQ.
c) Show that SM ∥ AC
Seems like a fun problem. What did you try / got already?
@scarlet drum Has your question been resolved?
Thales' theorem and simillarity fundamental theorem
I get stuck a lot
Did you get AN/NC?
No.
Is it 7/2
Not really
You should write AC as AN + NC
From there you get
AB/AM = 1 + NC/AN
7/2 - 1 = NC/AN
Yes
Alright, what about BQ/AQ
2/5
I dont quite get it as AM is not BQ
Did you maybe mean AM/MB = 2/7
That would make way more sense
No... AM/AB
@scarlet drum Has your question been resolved?
<@&286206848099549185>
What about point c?
We have to prove that BMS is simmilar to BAC
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does anyone know what this symbol means in calculus?
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Hey, to prove that $\sqrt{2}$ is irrational, I need to proof by contradiction
∞
Setting sqrt(2) as p/q, etc.
Does this same proof apply to all irrational numbers?
For instance, sqrt(6), sqrt(15)...
yes
it should
in fact you can prove that $\sqrt n$ is rattional $\iff$ n is a perfect square
everg
Is there a way I can explain?
because you are basically using the principal prime property "p divides ab then p divides .."
The problem I'm trying to solve is:
Can you modify the proof that you used to show that √2 is irrational to show that √5 is irrational? What about √6? √15? √16? If you can do so, please explain how and why; if not, please explain why you are unable to do so
sqrt 16=4
Is there a way I can put things simply? I'm not well versed in proofs, this is legit my first discrete math problem
I'm just trying to understand how the proof can possibly be generalized to all irrationnal numbers
Yes and no. For all "rootable" numbers, the proof is the same. But some irrational numbers are hard to prove irrational, are have so far not been proven. But they do all so far seem to have the same idea of "assume rational and find a contradiction"
I get it
How would you answer this part of the question then? "If you can do so, please explain how and why"
Do you understand how the sqrt(2) irrationality proof works? If so, replace 2 with 5 and see if you get the same outcome? Why would you not get the same outcome for 16? What changes?
The question specifies that what it's asking is whether the proof to show that sqrt(2) is irrationnal works for other "rootable" numbers (/can be generalized)
I can maybe argument this way
No step in the proof that sqrt(n) is irrationnal is changed for all integers n
Nothing in the proof changes aside from the integer in the square root, same steps, same reasoning applies
pretty sure that it is needed to use the fact that n is a prime number ..
And for perfect squares like 16 (let's call them z), we don't reach a contradiction, but are rather able to prove the fact that sqrt(z) is indeed rational
Would the explanation above be fine to state this condition?
The question that comes after is this one, so I guess it's a generalization that's expected after all
Formulate a conjecture of the following form: “Let N be a positive integer. Then √N is irrational if and only if N is... [Complete the conjecture].”
Describe how you came up with your conjecture. Did your work on the previous questions contribute to your formulation of it? What other approaches did you take? Please describe. Then try to prove your conjecture.
you just don t reach a contradiction, but you can t even do all steps of the proof without n's primality
.
👍
Do you mind if I ping you if I encounter issues?
sorry but here it s pretty late ...1 a m
but i think a lot of helpers can help you with that problem
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Can someone explain how?
The second line I mean
it's the equivalent of expanding out (x-3)(x-3)(x-3) so you can do the first two, like a (x-3)^2, then multiply that by the last one if you'd like
I say if you'd like since there are other ways to distribute as well, but that may be the easiest way to see it
I get that (I also solved it irl and keep getting that answer)
so what is the problem?
That this is the “right” answer and it doesn’t make sense to me
This make sense
what doesn't make sense?
The second line in this image
subtract 8 from both sides?
No the second line
oh yeah that's interesting, it should distribute out to -9x^2
Maybe, I’m looking at a website with answers for my homework assignment (not cheating, just checking my answers, again, not cheating 😭😭)
Probably is a mistake
x^3 - 9x^2 + 27x -18
Any why would you expand it and not factor it?
is what I got
You litteraly have cubic on LHS and cubic on RHS
Same
Yea but the teacher said “do it this way 🤓☝️”
tell the teacher they're wrong and get extra credit points my friend
You goona use the cubic formula?
Hey, just joined
I meannnnnn 
Nah, I could but imma just do it this way
To get full credit

And what happens once you expand it?
I lowkey don’t know how to do cubic formula anyway, but I know 2^3 is 8 so 🤷♂️
If this is what you mean by expanding it, then this is what i get
So it would he x - 3 = 2
If I’m not mistaken
No i mean what do you get when you write it like
[x^3 - 9x^2 + 27x - 35 = 0]
And you add 3 to the other side so X = 5
casework
How will you solve that
Oh we’re tryna find the possible rational solutions
So imma just use synthetic division
With guessing and checking

yeah
since it's a difference of cubes
there should be one factor for sure
and you can use quadratic formula after you divide
Or you can expand it then factor it again then solve it
Theoretically you should get full credit
Yup, did this
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
Does the fact that 49 is the square of 7 help you to seeing where to go with this?
yeah so its 7^x-5=7^2
right
7^(2x) on the right but yeah
So what can we do on both sides to bring those exponents down?
x-5=2x
Nw
.close
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I need help
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need help trying to set equal to 0?
idk how to make common denominator?
or however to find when it equalszero..
@tired bone Has your question been resolved?
@tired bone Has your question been resolved?
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Could I go over this problem with someone?
or at least my solution to it
go ahead yes
This is what I've got so far:
why did you make it k+1 for your inductive step
you are simply assuming that [
P(k): ; 1^2+\dots + k^2 = \f{k(k+1)(2k+1)}6
]
holds
you want to prove that the implication $\m Pk \Implies \m P{k+1}$ is legit
we made the assumption that the formula is true for some positive integer k, shouldn't we then the formula must also be true for k+1?
we want to show that if our assumption holds, then the next step is possible
induction is akin to dominos in the sense that, if you can make sure that the first domino is falling down (basis case) and also can prove that the first domino can make the second domino fall (P(k) -> P(k+1)) then you can assure yourself all the dominos would fall eventually as well
induction is NOT simply just substituting in k+1 into your proposition P(k) if that's what you mean. You are not using your inductive hypothesis
This is my full work.
ok yes that is correct now
Thanks!
@high wolf if done do .close
@high wolf Has your question been resolved?
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im confused as to why the shell method doesn't work here
ignore the respect to y integral
i also tried it as just a solid of revolution but doesn't work either
something fundamentally changes at y=0
needs to be two separate integrals
this is also true at x=2 if youre going that way
im still confused
isnt the formula (integral symbol) 2pi(x)(f(x))dx
and in my case, i sbtract the outer integral from the inner integral
the outer integral being y=9x-19
@austere warren Has your question been resolved?
yeah but "the inner function" doesn't always exist
at the base
like the base of the cup
since the parabola only goes so low
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