#help-0

1 messages · Page 411 of 1

upbeat eagle
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You dont need to know any physics

hasty creek
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Alright

upbeat eagle
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U just need look and comapre numbers

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anywasy im lost haha

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I can help you run this question down to where im at

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If you are interested

hasty creek
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Sure

versed walrus
upbeat eagle
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Ok so Basically,
The first question was to Prove ε is 1.6V

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So we have 22/n = ε /I -r

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I turn that into a y=mc + c

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This should be very neat?

hasty creek
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Looks right

upbeat eagle
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Alright

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Now

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regarding find the r value

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Im a bit confused

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Ill sen you a picture one sec

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,rotate

ocean sealBOT
upbeat eagle
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My question can I use method A and B to find r values does that work

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And for B

Would it be 1/0.3 or 0.3

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And also would you have to similtaneous equation it

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@hasty creek

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thats where my brain is just like wtf

hasty creek
upbeat eagle
hasty creek
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You can just plug in the point (0.9,0)

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And solve for r

upbeat eagle
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Into part A?

hasty creek
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Sure

upbeat eagle
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nvm

hasty creek
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1/I = 0.9, 1/n ~ 0

upbeat eagle
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yeah

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What if you werent given an x intercept

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You just plug in any point

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right?

hasty creek
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Then sure you can make two equations

upbeat eagle
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Oh ok

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So that would be part B

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Would it be 1/n and 1/I or just n and I

hasty creek
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So in part B you made y = n and x = I?

upbeat eagle
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I think so yeah? i guess

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Im not sure if it matters

hasty creek
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It’s better to continue with part A
Less stuff needed to figure out r

upbeat eagle
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ok but I kinda need to know how B works

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just incase

hasty creek
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🤔

upbeat eagle
upbeat eagle
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I guess ill just try trial and error?

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and ill let you know?

hasty creek
upbeat eagle
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can u double check its 16/9 i dont wanna fk it up

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22y = ε x - r

22 (1/0)= 1.6 1/0.9 -r

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-( 1.6 x (1/0.9) ) = -r

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So r is 16/9

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yeah should be right

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imma trial and error

hasty creek
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Err

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1/n is 0

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And 1/I is 0.9

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So you don’t need to do 1/0.9

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It should be 0.9*1.6

upbeat eagle
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errr what

hasty creek
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1/I is 0.9, doing 1/0.9 will get you the value of I

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We are using 1/I

upbeat eagle
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oh ok

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How come in the very first picture i didnt have to convert it?

upbeat eagle
hasty creek
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You don’t have to convert it

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Keep it as 0.9 rather than 1/0.9

upbeat eagle
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Which picture r we talking about

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Im guessing 2nd with A.

hasty creek
upbeat eagle
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Okok

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so 22y = ε x -r

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and you r telling me

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(0.9,0)

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So you put in 1/0.9? as x aka 1/i

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thats what i did

hasty creek
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No

upbeat eagle
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0 = ε x (1/0.9) - r

hasty creek
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x is 1/I

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Aka 0.9

upbeat eagle
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oh

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OH bc

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ok

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I understand

hasty creek
upbeat eagle
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so 0 = ε 0.9 - r

hasty creek
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Yep

upbeat eagle
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1.6 x 0.9 = 36/25 = r

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ok imma do sim eq and see which one it is

hasty creek
upbeat eagle
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i think i alrdy know whcih one

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TY !

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nah I dont

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I threw it in the calc

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didnt get any correct answers

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Am I doing it wrong lol

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0.3 = 5m -r
0.9 = 13.2 - r

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can I plug it in into

x + y = 0

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-1 + 5 = 0.3
-1 + 13.2 = 0.9

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I got the correct y value (aka the gradient matches up)

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@hasty creek

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Sry last one

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Might have to wipe my calculator

hasty creek
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Actually

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Since we know everything we can just plug in any single point lmao

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No need for equations

upbeat eagle
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Oh

hasty creek
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Let’s say (5, 0.3)
22(0.3) = 1.6(5) - r

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,calc 1.6(5) - 22(0.3)

ocean sealBOT
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Result:

1.4
hasty creek
upbeat eagle
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But that’s different

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To what we just got for A

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1.44

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Probably rounding error

hasty creek
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Yeah it’s a rounding error

upbeat eagle
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? But I can’t think of a reason

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Ok

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🙌

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I’ll leave it as that

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Well thank you once again

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Luv u

hasty creek
upbeat eagle
#

.close

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upbeat eagle
lone heartBOT
upbeat eagle
#

Im a bit confused on how to finish it

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So
When 2 = even/ even

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It means that the 2 evens must have a factor of 2 which related to the [2]

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But in this case there is no factor therefore it is an irrational number

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Is that a correct statement?

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Also let’s say you got

2 = 1even/ 2even
2= (1/2) (even/even)

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Would this mean it’s rational

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Because these are integer factors

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And are a factor of two

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Proof is something I tell you

vapid shuttle
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Suppose sqrt(2) is rational, then sqrt(2)=a/b in reduced form

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we showed earlier that a is even and b is even, if this is true

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(so you can't write it in reduced form)

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contradiction

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done

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boom

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pow

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you're confusing yourself

upbeat eagle
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If you got

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This means that it is a rational number

vapid shuttle
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Why do you keep doing this

upbeat eagle
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It can produce a rational number

vapid shuttle
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what are you writing

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2=1even / 2even

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it doesnt make any sense

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What are you trying to say?

upbeat eagle
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True

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It’s more of a question of factors

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You need a factor of 2 to be even

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So if there is a factor of. 1/2

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Is that a factor of 2

vapid shuttle
upbeat eagle
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Ok

hot swallow
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uh

vapid shuttle
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if they're even, they share a factor of 2, THAT IS IT

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the contradiction is they share a factor

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we assumed they share no factors

hot swallow
vapid shuttle
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if they share a factor of 2

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it's over

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game over

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we win

upbeat eagle
vapid shuttle
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no more need to be thinking about it

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we said

upbeat eagle
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Ok

vapid shuttle
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sqrt(2)=a/b

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and they share no common factors

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but then we showed

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they share a common factor of 2

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so we can be done

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that's the contradiction

upbeat eagle
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Ok ok I gotchyu

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For now

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upbeat eagle
upbeat eagle
#

Everyone says warewolf

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But no one asks how wolf

lone heartBOT
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silver widget
lone heartBOT
silver widget
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I was able to do 3a and 3b

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I got stuck on 3c

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I started to integrate the integral by parts and did that twice

safe tartan
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Integration by parts I’m assuming

silver widget
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However, I got the following value:

$[x^nsin(x)+nx^{n-1}cos(x)-n(n-1)I_{n-2}]^{\pi/2}_0$

silver widget
safe tartan
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What was ur u and dv

silver widget
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u = x^n
dv = cos x

safe tartan
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Might be x^n-1 xcosx

silver widget
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When I simplify this further, the last term cancels though

safe tartan
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Since the previous question does xcosx

silver widget
ocean sealBOT
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Cayush

silver widget
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<@&286206848099549185> Please

civic dragon
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<@&286206848099549185> ASSEMBLE NOW

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A FELLOW COMRADE NEEDS US

ancient vapor
silver widget
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Part 3c

ancient vapor
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@civic dragon shut up bruh.

silver widget
civic dragon
silver widget
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However, the I_n-2 term seems to cancel

ancient vapor
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Well it might form a gp

silver widget
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In school, the method we learned was direct proof

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So, I integrated the integral by parts twice, and substituted the general term

lone heartBOT
#

@silver widget Has your question been resolved?

ancient vapor
#

@silver widget

lone heartBOT
#

@silver widget Has your question been resolved?

lone heartBOT
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grave verge
lone heartBOT
grave verge
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My progress:

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I am unsure if I did it right (am 60% sure I did smth wrong cuz there cm³ in question but Idk how do I get cm³)

frigid mirage
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notice lbh is (cm) x (cm) x (cm)

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and idk why you put weight in cm

grave verge
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So all I have to do is add cm³ in ans?

frigid mirage
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no

grave verge
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Oh shi

frigid mirage
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the volume should be cm^3

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weight should be in grams

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actually I think your number is right

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just the units

grave verge
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So in the end I just change it to grams?

frigid mirage
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,w 105(70)(1.5)8

frigid mirage
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and change to kg

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since the question asks in kg

grave verge
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Just cm^3 instead of ^2 right

grave verge
#

Tysm

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.close

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upbeat bone
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hello

lone heartBOT
upbeat bone
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9th grade geometry

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how to find y, i already know how to get x

slender gull
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Check out co interior angles.

upbeat bone
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sorry idk what u mean

slender gull
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In your notes wherever you're studying parallel lines,

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Find the term co interior angles.

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In this case, 2x and y are co interior angles.

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There's a property for parallel lines that states sum of co interior angles is 180 degrees.

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Might wanna check that out.

lone heartBOT
#

@upbeat bone Has your question been resolved?

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last aurora
#

Hallo this is a q regarding bias of an estimator (in stats)

last aurora
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This is the question

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This is my work

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I was wondering if this was right?

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I sorta just assumed $E[X_1]$ = $E[X_2] = \mu$

ocean sealBOT
last aurora
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because that seemed like the only possible way to do the question

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but i don't get why the statement above is true, since I thought $\mu = E[X_1+X_2]$

ocean sealBOT
alpine sable
#

the center of the sampling distibution of $\hat X$ is also $\mu$

ocean sealBOT
alpine sable
last aurora
#

thank you!

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I guess ill go read the textbook more

alpine sable
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no worries haha

last aurora
#

:D

alpine sable
last aurora
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tight thunder
lone heartBOT
tight thunder
#

guys what is this

lone heartBOT
fervent kestrel
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lower case delta

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In what context is it being used?

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@tight thunder

tight thunder
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amortization rate of capital in macroecnomics

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is it equivavlent to this?

fervent kestrel
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I'm not familiar with macroeconomics

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What are the entire formulas you are looking at

tight thunder
#

hmmmmm

fervent kestrel
#

I think delta is 'depreciation rate of capital'

fervent kestrel
lone heartBOT
#

@tight thunder Has your question been resolved?

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verbal galleon
lone heartBOT
#

@verbal galleon Has your question been resolved?

verbal galleon
#

<@&286206848099549185>

#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
verbal galleon
#

1

verbal galleon
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<@&286206848099549185>

verbal galleon
#

<@&286206848099549185>

verbal galleon
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Tf

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.close

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torpid roost
lone heartBOT
alpine sable
#

!show

lone heartBOT
#

Show your work, and if possible, explain where you are stuck.

torpid roost
#

This is what I did I was kind of just guessing what I had to do

alpine sable
#

,rccw

ocean sealBOT
torpid roost
#

I didnt know how to add them

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and subtract

lone heartBOT
#

@torpid roost Has your question been resolved?

torpid roost
#

<@&286206848099549185>

tardy stag
#

you can only really add and subtract them if the stuff under the radical √ is the same

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so like 3√x + 4√x = 7√x

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but 2√x + 9√y is a dead end, nothing left to do

torpid roost
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so do i need to make them all the same under the radical

tardy stag
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yes but conveniently if you reduce it like you're doing that's the most you can do

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they'll line up as much as possible

torpid roost
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so what part of what i did was correct?

tardy stag
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you reduced the first term correctly

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do the same for the other terms

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like make a factor tree / look for sets of 4

torpid roost
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so would the simplified version be xy^2

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Are these the correct 3 simplified equations

torpid roost
#

<@&286206848099549185>

#

@tardy stag

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.close

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alpine sable
lone heartBOT
alpine sable
#

I am having difficulty with units

lone heartBOT
alpine sable
#

So what are the units of t/6

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seconds/watts?

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watts = t (seconds) / 6?

placid zinc
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t/6 is seconds

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Note the units do not agree here.

alpine sable
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so its not dimensionally homogeneous

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?

placid zinc
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ye

alpine sable
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my brain!!! how?? why??

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how is that legally allowed

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is it because youre integrating

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what does that do to units

placid zinc
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We haven't even gotten to the integral yet haha

alpine sable
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i know integration/derivation for things like acceleration

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ok bro

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youre killing me here

worn fox
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note that the number 6 has units of s/W

alpine sable
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yes

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so dot_Q_out = t/(6 s/W) ==> t(W)/6(s)

placid zinc
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True, that's a way to fix it

alpine sable
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me when "t" is in watts 💀

worn fox
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t has units s and 6 has units s/W, it cancels out to W

alpine sable
#

well, watts per second, so thats better. (1/6) watts/second

alpine sable
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at the bottom equation

worn fox
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because the bottom is 2 * 6 s/W

alpine sable
#

so it doesnt cancel out then?

worn fox
#

i dont know what you mean

alpine sable
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if youre just left with W then why is the bottom 2*6s/W

worn fox
#

the units of Q are not W

alpine sable
#

where are you left with just W

worn fox
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the units of Q dot are W

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then youre integrating that with respect to time so the units become Ws (or kWhr if you scale)

alpine sable
#

ok so to clarify, Q dot (W) = t(s)/6 right? thats good?

worn fox
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aslong as you remember that 6 has units s/W

alpine sable
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so youre telling me that its Qdot(W) = t(s) / 6(s/W)

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?

worn fox
#

yes

alpine sable
#

ok so yes it is dimensionally homogeneous technically

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because they all cancel out

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ok i understand it now, thank you

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much appreciated

#

.close

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heady robin
lone heartBOT
heady robin
#

i asked this yesterday

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but still didn get en9ough heko

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@heady robin Has your question been resolved?

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tulip oasis
lone heartBOT
tulip oasis
#

sry dumb question

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but i can just rewrite this right

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like put the = alll the way to the right

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instead of all the way to the left

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cuz i hate it when it looks like this xd

fallen verge
#

yes, but be careful with how you move things around

tulip oasis
#

Ok

lone heartBOT
#

@tulip oasis Has your question been resolved?

median cove
#

U dont move the equals sign, u just move the values to the left and right of the equals sign

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If thats what u r talking abt then yes

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hollow frost
#

stuck on this problem, think i’m in the right track but not sure ?

meager portal
#

you have 3 y sides and 2 x sides

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those are the fences

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and the area is x times y

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you know $3y + 2x = 1000$

ocean sealBOT
#

TRAMPELTIER

meager portal
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and you wanna maximize $x \cdot y$

ocean sealBOT
#

TRAMPELTIER

hollow frost
#

yes

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im not sure how to though after where I got

meager portal
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okay

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lemme think

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we can write x in terms of y (or y in terms of x)

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take this $3y + 2x = 1000$ and solve for $x$

ocean sealBOT
#

TRAMPELTIER

meager portal
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which gives $x = (1000-3y)/2$

ocean sealBOT
#

TRAMPELTIER

meager portal
#

and then, you can in the target function that we want to maximize substitute x by this equation

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And then the target function only depends on y

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and we can easily maximize it by taking the derivativ, setting to 0 and finding the maximum

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questions?

hollow frost
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so I substitute the x for 1000-3y/2

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then derive the new target function and set it equal to zero to find the critical numbers ?

meager portal
#

yes

#

because you'll see that the target function is a quadratic in y

#

and it will be a quadratic that grows negatively

#

so there's a maximum in that quadratic

hollow frost
#

ok thank you

meager portal
#

np

lone heartBOT
#

@hollow frost Has your question been resolved?

#
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tacit barn
lone heartBOT
tacit barn
#

No idea where to start from in this problem ...

#

Also that, dont know how or if it will help. Very complicated problem for a 12th grade student imo... Help

lone heartBOT
#

@tacit barn Has your question been resolved?

tacit barn
#

<@&286206848099549185> please help me

wicked sparrow
#

sure

#

is it possible for you to enlarge it?

tacit barn
#

Where do I even start in this?

tacit barn
#

The limit?

wicked sparrow
#

i cant really see the problem well

tacit barn
#

Oh hold on sure

#

Any idea?

wicked sparrow
#

oooh

#

thats a pretty hard problem

#

what grade are you? freshman?

tacit barn
#

im in the last year of high school

#

This is usually a problem youd encounter on the final exams, and it most likely is one of the final ones if not the final one

#

Its like the last 6/100 points

#

In my country the entrance exams to uni have like 4 problems, containing 4-5 sub-questions each of them(each problem is total 25 points) and this is like the D4 or D5

wicked sparrow
#

yeah im doing the problem now

#

gimme a few miniutes

#

*minutes

tacit barn
#

Thanks 🙏

wicked sparrow
#

been a while since ive done this

tacit barn
#

Just ping me because I'll close my phone to try it myself

tacit barn
wicked sparrow
#

ok

#

so

#

when you wrote [a, - inf)

#

did you mean ( -inf, a]?

#

@tacit barn

#

just to make sure

tacit barn
#

Where

wicked sparrow
#

at the top i think?

#

can you give some context for the problem so i have something to base it off of

tacit barn
#

At the domain and the range of f?

wicked sparrow
#

like a way of thinking

#

yeah

tacit barn
#

Well we have the function f(x) given to us with a domain of (0,+inf) and a range that ive found by the first derivative which is [1,+inf) (f has a total min value f(1)=1). Then we have the following information about x0 and that f is increasing on the mentioned interval (1,2) and that the tangent line is that of the above form. And it asks us then to prove that the limit above is -infinity

#

I tried my best translating the problem from greek to english man srry lol

#

My guess is that we play with the fact that f is increasing in the interval (1,2) not sure tho...

#

But we both agree the limit is a/0 but what a and what 0

tacit barn
lone heartBOT
#

@tacit barn Has your question been resolved?

wicked sparrow
#

hm

lone heartBOT
#

@tacit barn Has your question been resolved?

lone heartBOT
#
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#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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dusk umbra
#

Are components of an eigenvector orthogonal?

dusk umbra
#

Like for example, if you have an angle and a magnitude for a vector in 3d space

#

You can write the vectoe components as trig functions

#

Is this true for eigenvectors too?

flint pagoda
#

For symmetric matrices yes

#

Eigenvectors for distinct eigenvalues are always ortho

#

For example, in PCA, we have symmetric matrices for covariance so the representative eigenvectors we get as output are indeed orthogonal

dusk umbra
flint pagoda
#

Yes

#

Watch this

dusk umbra
#

ok gimme a min

#

.close

lone heartBOT
#
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lone heartBOT
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manic ruin
#

I could use some help with a statistics problem. I think I understand how to do the rest of this problem, but I straight up do not know how to get part a.

manic ruin
#

I'm trying to wrap my head around part a but I am having difficulty. I know there's 21 possibilities per stop and 4 stops total

#

I just don't know how to translate that into an actual answer. Unless my base assumption is wrong?

#

Part b is just 1/N x 1/N where N is the answer from a, right?

#

like, I feel like I'm almost there on my knowledge but something fundamental is not clicking. Any help is most appreciated.

balmy grail
#

So you’re right there’s 21 possible outcomes [0,20] for the first stop, but then you have to think about what happens on the second stop- if 1 persons gets off at stop 17, only [0,19] people can get off at stop 18

#

So if you had 1 person on the bus how many possible outcomes are there?

manic ruin
#

8?

#

I'm confused

#

or is it 2^4?

balmy grail
#

They have to get off eventually, so if we count the number of exits per stop you’ll see 4 possible outcomes: last stop: 0001, third: 0010, second: 0100, first:1000

#

So what happens if there’s a second person?

manic ruin
#

I have no idea. Does it double?

#

or square?

balmy grail
#

Try and reason your way through it, what choices can each person make?

#

They only get off once

manic ruin
#

off or not off at every stop

balmy grail
#

Or off at which stop?

manic ruin
#

so each individual person has 4 possibilities?

balmy grail
#

Yes

manic ruin
#

so it's 4^n where n is the total number of people?

balmy grail
#

Stops^number of people yes

#

So for 20?

manic ruin
#

Okay, that makes sense. I had it backwards on my paper. I was doing 20^4 and the answer felt wrong

#

4^20 = 1.1E12

balmy grail
#

In that case 1 person would have 1 possible outcome 1^4
11 billion looks about right though

manic ruin
#

Okay, cool. What about part b?

#

Is it 1/N x 1/N where N is 4^20?

#

Or do I have to figure out the total number of possibilities per individual stop?

#

So if no one gets off at stop 17, that's 1 out of the 21 total possibilities there

#

And if it happens again that is another 1/21 chance for the next stop?

#

so is it 1/21 x 1/21 or is it the first thing I said?

#

Oh, wait, maybe I'm misunderstanding the question. It's asking for the number of possibilities in the event that no one leaves in the first 2 stops, not the chances of it occuring.

balmy grail
#

Right, also I don’t think it’s either of those options

manic ruin
#

yeah, it isn't. Would it just be what we already did but for only 2 stops instead of 4?

balmy grail
#

That looks good to me

manic ruin
#

And then for c, if half the passangers leave in the first 2 stops, then all we have left are 10 passengers and 2 stops, so 2^10 possible outcomes?

balmy grail
#

That I’m not so sure about

manic ruin
#

oh, hm...then I'm not sure what it would be.

balmy grail
#

Is it exactly half or at least half?

manic ruin
#

exactly half

#

"the event that half of the passengers leave by stop 18"

#

Would it be double my original answer? Cuz either "half" could be in either place?

#

So 2^10 x 2 = 2048?

#

hello?

balmy grail
#

I’m not sure, I’m getting 48/128 for the case of n=4

manic ruin
#

wait, what?

#

for the probability of occurrence?

#

or for the total number of possibilities?

balmy grail
#

96 / 4^4 = 96/256

manic ruin
#

I have no idea what I am looking at...

#

I'm confused as to how the total number of possibilities could be less than 1

#

the questions is asking me to count how many different possibilities exist if half the people on the bus get off in the first 2 stops

#

So wouldn't that just be the number of ways exactly 10 people can get off in the first 2 stops + the total number of ways the other 10 could get off in the last 2 stops?

lone heartBOT
#

@manic ruin Has your question been resolved?

balmy grail
#

You have to imagine the fourth column because it wouldn’t fit

manic ruin
#

How did we get to 4?

#

or does it not matter as long as the ratio is 1/2?

balmy grail
#

Because I was using 2 as a simple case but then I was worried about that being too small / similar to other things

manic ruin
#

okay, so how do I apply that to my answer?

#

Do I multiply the total number of possibilities obtained in part a by 96/256?

balmy grail
#

No

manic ruin
#

I am very lost

balmy grail
#

On the case of n=2, 8 have exactly 1 person getting off at stop 17 or 18, which looks like 1/2 of the cases, but let’s check another case, eg n=4 for exactly 2 people getting off at stop 17 or 18, which when we go out and count them there are 96/256 = 3/8 ≠ 1/2. So we know this is more complicated than it looks

manic ruin
#

okay, so then how do I figure it out for 20 people where 10 get off at stops 17 and 18 without counting as that seems difficult?

#

without counting by hand that is. I must be missing a formula somewhere along this process

#

Is the total number of possibilities 20 C 10 x (something)?

#

cuz the first 2 stops eat 10 of the people but it doesn't matter which 10 so it's just a nCr thing?

#

is it just 20 C 10 x 2?

#

idk, I think I'm not understanding something more fundamental here maybe. I think I'm just gonna talk to my professor about it tomorrow during her office hours.

balmy grail
#

Yeah it looks like the pmf = 0.5 for the sum of 20 uniform variables from 1:4 but I don’t have a simple solution

manic ruin
#

okay, well I still appreciate all the help you gave me. Thank you. I have some other questions for my professor anyway so I think it'll work out with me going to her office hours tomorrow morning.

#

.close

lone heartBOT
#
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lone heartBOT
#
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lean river
#

help

lone heartBOT
keen pasture
gray isle
#

if you need help with a math question,
ask asap.
(before people lose interest and start skipping this channel when browsing)

lone heartBOT
#

@lean river Has your question been resolved?

lone heartBOT
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full apex
#

hey

lone heartBOT
lone heartBOT
full apex
#

i need help factorising this

#

someone please help

ebon sparrow
#

you can factor by grouping

full apex
#

i tried

ebon sparrow
#

!show

lone heartBOT
#

Show your work, and if possible, explain where you are stuck.

full apex
#

but i keep getting the wrong answer

#

one sec

#

this is the answer

#

what i did was

#

i grouped it

#

and i used binomial products to seperate -3xy^3 - 9y^4

ebon sparrow
#

I know what's the answer is like but I asked you to show your work

full apex
#

im doing that just give me time

#

actually ill show you my written working out instead of retyping it all

#

alr dnoe

#

done*

#

cant factorise further 😭

tardy stag
#

in this line, replace $(2x^2-3y^2)$ with $\rsq$ and try to factor it again

ocean sealBOT
#

hayley!

full apex
#

its a red box

tardy stag
#

you seem to be struggling with factoring it out

full apex
#

indeed

tardy stag
#

if you replace it with something abstract like a colored box (or another variable i guess) it can make it easier to see what you need to do

full apex
#

hm

#

lemme try

#

oh should i expand?

#

yoo

#

@tardy stag

tardy stag
#

why would you expand when you just factored Sobbingcrying

full apex
#

idk 😭

tardy stag
#

$(2x^2-3y^2)\blue{u} - xy\blue{u}$

ocean sealBOT
#

hayley!

jovial wind
#

that do be crazy

full apex
#

hush

#

lemme think

jovial wind
#

i need help

#

😭

full apex
#

no

#

uuuuh

#

i still dont get it

#

@tardy stag

jovial wind
tardy stag
#

basically

tardy stag
#

you're getting really confused with the subexpressions

full apex
#

yeah

tardy stag
#

you're trying to factor out (2x^2 + 3y^2) right

full apex
#

2am moment

tardy stag
#

so i replaced that with u

#

so that you can easily see what you need to do

jovial wind
#

💀

full apex
full apex
jovial wind
#

😭

#

she replaced that w u

#

hell nah

#

this aint math

tardy stag
jovial wind
full apex
#

oh shit

jovial wind
full apex
#

im so dumb

jovial wind
#

there is no U

full apex
#

gtfo here

jovial wind
#

this is my helpine now

full apex
#

i did this

#

@tardy stag

tardy stag
# full apex

that with parentheses around the (2x^2 + 3y^2) is correct

full apex
#

act like a normal human being for once

tardy stag
#

replace the d back

full apex
#

yeah

#

so substitute

full apex
#

lemme try solving it

#

jump

unkempt sundial
#

This channel is wild

full apex
#

ong

#

oh you want that?

#

😼

#

no

#

kys

summer dirge
#

easy now

full apex
#

ong

#

ing

summer dirge
#

no need to insult others or give them death threats

full apex
lone heartBOT
#

@full apex Has your question been resolved?

viral acorn
#

do u need help with this?

#

everything

#

sorry go on

#

so like

#

what exactly is the question

#

ong bro

#

wait

unkempt sundial
#

This is like the first ever successful channel hijacking

#

fr

viral acorn
#

all ive got

#

are you okat

#

ok bet

#

certainly

#

im going to kill you

#

that is ok

#

some people find it hot

north perch
viral acorn
#

all is said in a not meant fully manner

#

boobs yea

unkempt sundial
viral acorn
#

ive heard of that show

lone heartBOT
#
Channel closed

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north perch
#

not watched that shit

#

i am busy gambling in gacha games

unkempt sundial
#

Im a e-kitten

lone heartBOT
#
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twin compass
lone heartBOT
twin compass
#

Could somebody help me with this please?

split spire
#

try expanding

twin compass
split spire
#

yes

twin compass
#

From here I don't know what to do

split spire
#

use sin(a+b) and cos(a+b) formula

twin compass
#

Oh, you are rigth

#

Thank you

lone heartBOT
#

@twin compass Has your question been resolved?

#
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lone heartBOT
#
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scarlet drum
#

Let △ABC, M ∈ (AB),
AM/AB = 2/7
Knowing that MN ∥ BC, NP ∥ AB, P Q ∥ AC, QR ∥ BC,
RS ∥ AB, N, R ∈ (AC), P, S ∈ (BC), Q ∈ (AB).
a) Calculate AN/NC, CP/PB, BQ/AQ.
b) Show that AM = BQ.
c) Show that SM ∥ AC

scarlet drum
swift grail
#

Seems like a fun problem. What did you try / got already?

lone heartBOT
#

@scarlet drum Has your question been resolved?

scarlet drum
#

I get stuck a lot

swift grail
#

Did you get AN/NC?

scarlet drum
swift grail
#

AB/AM = AC/AN

#

You can get AN/NC from here

scarlet drum
swift grail
#

Not really

#

You should write AC as AN + NC

#

From there you get
AB/AM = 1 + NC/AN

#

7/2 - 1 = NC/AN

scarlet drum
#

Right.

#

So AN/NC is 2/5

#

CB/CP=CN/AN

#

Which is 5/2

#

Too

#

Right @swift grail

swift grail
#

Yes

scarlet drum
#

Alright, what about BQ/AQ

swift grail
#

You will get that once you get BP/PC as its equal

#

And BP/PC = AN/NC by similarity

scarlet drum
#

BP/PQ is also 5/2

#

So BQ/AQ is 5/2 too

swift grail
#

2/5

scarlet drum
#

Yeah, sorry

#

What about point b?

#

@swift grail

swift grail
#

I dont quite get it as AM is not BQ

#

Did you maybe mean AM/MB = 2/7

#

That would make way more sense

scarlet drum
lone heartBOT
#

@scarlet drum Has your question been resolved?

scarlet drum
#

<@&286206848099549185>

scarlet drum
#

We have to prove that BMS is simmilar to BAC

lone heartBOT
#

@scarlet drum Has your question been resolved?

lone heartBOT
#
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hot bison
#

does anyone know what this symbol means in calculus?

hot bison
#

the loopdy loop thing

#

its not a limit

#

and its in the limit section

#

.close

lone heartBOT
#
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lone heartBOT
#
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alpine sable
#

Hey, to prove that $\sqrt{2}$ is irrational, I need to proof by contradiction

ocean sealBOT
alpine sable
#

Setting sqrt(2) as p/q, etc.

#

Does this same proof apply to all irrational numbers?

#

For instance, sqrt(6), sqrt(15)...

ivory pivot
#

yes

woven harbor
#

it should

alpine sable
#

I tried with sqrt(2) and sqrt(5), seems to work

#

Why does the proof work though?

ivory pivot
#

in fact you can prove that $\sqrt n$ is rattional $\iff$ n is a perfect square

ocean sealBOT
alpine sable
#

Is there a way I can explain?

ivory pivot
alpine sable
#

The problem I'm trying to solve is:

Can you modify the proof that you used to show that √2 is irrational to show that √5 is irrational? What about √6? √15? √16? If you can do so, please explain how and why; if not, please explain why you are unable to do so

ivory pivot
#

sqrt 16=4

alpine sable
#

Is there a way I can put things simply? I'm not well versed in proofs, this is legit my first discrete math problem

#

I'm just trying to understand how the proof can possibly be generalized to all irrationnal numbers

limpid turret
alpine sable
#

I get it

alpine sable
limpid turret
#

Do you understand how the sqrt(2) irrationality proof works? If so, replace 2 with 5 and see if you get the same outcome? Why would you not get the same outcome for 16? What changes?

alpine sable
#

The question specifies that what it's asking is whether the proof to show that sqrt(2) is irrationnal works for other "rootable" numbers (/can be generalized)

alpine sable
#

No step in the proof that sqrt(n) is irrationnal is changed for all integers n

#

Nothing in the proof changes aside from the integer in the square root, same steps, same reasoning applies

ivory pivot
alpine sable
#

And for perfect squares like 16 (let's call them z), we don't reach a contradiction, but are rather able to prove the fact that sqrt(z) is indeed rational

alpine sable
#

The question that comes after is this one, so I guess it's a generalization that's expected after all

Formulate a conjecture of the following form: “Let N be a positive integer. Then √N is irrational if and only if N is... [Complete the conjecture].”

Describe how you came up with your conjecture. Did your work on the previous questions contribute to your formulation of it? What other approaches did you take? Please describe. Then try to prove your conjecture.

ivory pivot
#

you just don t reach a contradiction, but you can t even do all steps of the proof without n's primality

ivory pivot
alpine sable
#

And I'll come back later

ivory pivot
#

👍

alpine sable
#

Do you mind if I ping you if I encounter issues?

ivory pivot
#

sorry but here it s pretty late ...1 a m

alpine sable
#

All good, no worries

#

Thank you!

ivory pivot
#

but i think a lot of helpers can help you with that problem

alpine sable
#

Got you

#

Thank you

#

.close

lone heartBOT
#
Channel closed

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#
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kind pelican
#

Can someone explain how?

lone heartBOT
kind pelican
#

The second line I mean

main ruin
#

I say if you'd like since there are other ways to distribute as well, but that may be the easiest way to see it

kind pelican
#

I get that (I also solved it irl and keep getting that answer)

river badger
#

so what is the problem?

kind pelican
kind pelican
river badger
#

what doesn't make sense?

kind pelican
river badger
#

subtract 8 from both sides?

kind pelican
#

No the second line

main ruin
#

oh yeah that's interesting, it should distribute out to -9x^2

kind pelican
#

I thought I was going crazy fr

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☠️

main ruin
#

wondering if it could be a mistake?

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bc now I think I'm crazy

kind pelican
swift grail
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Probably is a mistake

river badger
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x^3 - 9x^2 + 27x -18

swift grail
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Any why would you expand it and not factor it?

river badger
#

is what I got

swift grail
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You litteraly have cubic on LHS and cubic on RHS

kind pelican
kind pelican
main ruin
swift grail
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You goona use the cubic formula?

alpine sable
#

Hey, just joined

kind pelican
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To get full credit

swift grail
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And what happens once you expand it?

kind pelican
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I lowkey don’t know how to do cubic formula anyway, but I know 2^3 is 8 so 🤷‍♂️

kind pelican
kind pelican
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If I’m not mistaken

swift grail
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No i mean what do you get when you write it like
[x^3 - 9x^2 + 27x - 35 = 0]

kind pelican
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And you add 3 to the other side so X = 5

ocean sealBOT
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casework

swift grail
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How will you solve that

kind pelican
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So imma just use synthetic division

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With guessing and checking

woven harbor
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yeah

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since it's a difference of cubes

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there should be one factor for sure

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and you can use quadratic formula after you divide

swift grail
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Or you can expand it then factor it again then solve it

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Theoretically you should get full credit

kind pelican
kind pelican
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That’s a certified W

lone heartBOT
#

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signal swift
lone heartBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
quartz rapids
# signal swift

Does the fact that 49 is the square of 7 help you to seeing where to go with this?

quartz rapids
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7^(2x) on the right but yeah

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So what can we do on both sides to bring those exponents down?

signal swift
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x-5=2x

quartz rapids
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Yeah exactly

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So whats x

signal swift
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-5

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thanks

quartz rapids
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Nw

signal swift
#

.close

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storm cove
#

I need help

lone heartBOT
storm cove
#

Geometry

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.close

lone heartBOT
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tired bone
lone heartBOT
tired bone
#

need help trying to set equal to 0?

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idk how to make common denominator?

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or however to find when it equalszero..

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#

@tired bone Has your question been resolved?

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@tired bone Has your question been resolved?

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high wolf
#

Could I go over this problem with someone?

high wolf
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or at least my solution to it

alpine sable
high wolf
alpine sable
#

you are simply assuming that [
P(k): ; 1^2+\dots + k^2 = \f{k(k+1)(2k+1)}6
]
holds

ocean sealBOT
alpine sable
#

you want to prove that the implication $\m Pk \Implies \m P{k+1}$ is legit

ocean sealBOT
high wolf
alpine sable
#

induction is akin to dominos in the sense that, if you can make sure that the first domino is falling down (basis case) and also can prove that the first domino can make the second domino fall (P(k) -> P(k+1)) then you can assure yourself all the dominos would fall eventually as well

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induction is NOT simply just substituting in k+1 into your proposition P(k) if that's what you mean. You are not using your inductive hypothesis

alpine sable
high wolf
mystic swallow
#

@high wolf if done do .close

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austere warren
lone heartBOT
austere warren
#

im confused as to why the shell method doesn't work here

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ignore the respect to y integral

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i also tried it as just a solid of revolution but doesn't work either

tardy stag
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something fundamentally changes at y=0

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needs to be two separate integrals

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this is also true at x=2 if youre going that way

austere warren
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im still confused

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isnt the formula (integral symbol) 2pi(x)(f(x))dx

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and in my case, i sbtract the outer integral from the inner integral

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the outer integral being y=9x-19

lone heartBOT
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@austere warren Has your question been resolved?

tardy stag
#

at the base

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like the base of the cup

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since the parabola only goes so low

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snow cobalt
#

ok

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is it an exam?

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then?

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then why do you have 7 minutes for revising-