wait for a sec..
#help-0
glossy lion
oh thanks
It's a multiple choice question btw so one of these is the answer. A.1 B.2 C.3 D.7/5 E.9/4
alpine sable
ohhh
wai
i got u
umm wai the options are more confusing though
theres an error in the options im sure
the answer is supposed to be 2 *root of 34
glossy lion
perhaps you made a mistake?
Cuz my teacher was able to solve it, but then he doesn't answer our questions
or maybe you could show me your steps?
glossy lion
<@&286206848099549185>
lone heartBOT
@glossy lion Has your question been resolved?
mental finch
@glossy lion How far have you come?
It helps drawing a figure
Try doing that as a start
uneven owl
xd?
fallen owl
lone heartBOT
@glossy lion Has your question been resolved?
mental finch
Well you can set up two eqs. do you see it? (Hint: use pythagoras thm)
glossy lion
One could be y^2+(x+5)^2=8^2
glossy lion
y^2+x^2=5^2
mental finch
Exactly!
mental finch
Now before you solve this. Observe that y here is not needed so you can subtract the two eqs. to get a very nice linear eq. in terms of x
Lmao
lone heartBOT
lone heartBOT
Available help channel!
blissful breach
Log27^x=2/3
lone heartBOT
Log27^x=2/3
blissful breach
I got that x = 9 thanks to my calculator
But how would I figure that out without my calculator
lone heartBOT
@blissful breach Has your question been resolved?
little mural
But how would I figure that out without my calculator
log is defined as follows: to what power should the base be raised in order to obtained the argument
ur argument is x
ur base is 27
ur power is 2/3
figure out the rest urself
lone heartBOT
@blissful breach Has your question been resolved?
worthy badger
hello
quaint cove
Is there no channel to voice chat
worthy badger
i dont think so
quaint cove
Damn
worthy badger
I dont understand why u cant just do 13C1 x 4C2 x 12C1 x 4C2 x 11C1 x 4C3
lone heartBOT
@worthy badger Has your question been resolved?
worthy badger
<@&286206848099549185>
alpine sable
shouldn't it be B
livid sage
choice A is correct
livid sage
I dont understand why u cant just do 13C1 x 4C2 x 12C1 x 4C2 x 11C1 x 4C3
i'm not sure how you obtained this product
do you mean 4C1 13C2 3C1 13C2 2C1 13C3?
worthy badger
i'm not sure how you obtained this product
do you mean 4C1 13C2 3C1 13C2 2C1 13...
no
the reasoning behind my decision is that at first u need to select a denomination for the 2 cards... hence 13C1
Then following that choice u need to select 2 cards out of the 4 available in the denomination that was just picked
hence 4C2
livid sage
ah i see i read "denomination" as "suit"
worthy badger
Do u see my thinking behind it?
livid sage
the reasoning behind my decision is that at first u need to select a denominatio...
yes that make sense but this results in overcounting
the reason is that you're choosing 2 cards from 2 different denominations
livid sage
the reason is that you're choosing 2 cards from 2 different denominations
this method of counting counts different orderings of these cards as different cases, when in reality they are the same
say you picked the denomination 3 with Diamonds and Clubs, then you picked the denomination 4 with Clubs and Hearts
this is the same as if you picked 4 with Clubs and Hearts, then 3 with Diamonds and Clubs
using choice B, we count these two choices of cards as different choices, but they end up in the same result
worthy badger
the reason is that you're choosing 2 cards from 2 different denominations
in what way then does it differ from this question where they use the strategy I employed (and in that case it worked)?
livid sage
in what way then does it differ from this question where they use the strategy I...
because you pick 4 cards, 3 cards, and 2 cards
the number of cards of each denomination are the same so you can use a product with a choice of 4, 3, and 2, and not result in overcounting
livid sage
the issue with this problem is that you have 2 cards, 2 cards, and 3 cards
you can't distinguish the groups of 2 cards from each other, therefore counting it the way you'd normally do it results in overcounting
worthy badger
the issue with this problem is that you have 2 cards, 2 cards, and 3 cards
why do they only choose 2 denominations instead of 3 then? in the first step
livid sage
because you can distinguish a group of 2 from a group of 3
there's only 2 groups of 2, so you pick 2 denominations (for the groups of 2) at the start, not all 3
worthy badger
bruhhh this stuff is confusing af
worthy badger
there's only 2 groups of 2, so you pick 2 denominations (for the groups of 2) at...
alr i see
livid sage
bruhhh this stuff is confusing af
ye combinatorics tends to do that to you unfortunately
livid sage
generally though when doing a problem like this i count it the way described in answer choice B, then i divide by some constant to remove the overcounting
in this case the constant would be 2! = 2
because there's 2! ways to order the 2 groups of 2 when you pick them, and these orderings were overcounted
livid sage
generally though when doing a problem like this i count it the way described in ...
if, say, i was picking 2 cards, 2 cards, 2 cards instead
i'd calculate 13C1 x 4C2 x 12C1 x 4C2 x 11C1 x 4C2 (which is the way you'd normally do it)
then i'd divide by 3!, or 6, since that's the number of ways to order the 3 groups of 2 cards
livid sage
(just noting this ^ since it's another way you can think about it*)
(the alternative posed in answer choice A is also correct)
worthy badger
(just noting this ^ since it's another way you can think about it*)
(the alterna...
so esentially I can think of it with the way I have been doing it and if the case arises where the number of cards in any of the listed group are the same, then I can complete the problem in the manner that I've been doing it, but I'd need to divide my end result by the number of groups present ( in this case 3) and include the ! sign?
livid sage
something like that yeah
worthy badger
like for instance if I had to choose 2 cards of one denominaiton, 2 cards of another denominaiton, 3 cards of another denominaiton, and 3 cards of another denominaiton.... then id do it my method where it would work out like 13C1 x 4C2 x 12C1 etc
and once I get my final answer I divide by 4!?
worthy badger
something like that yeah
thx for ur help btw
livid sage
and once I get my final answer I divide by 4!?
not 4!
you would divide by 2!, and then again by 2!
because you have 2 ways to order the 2 groups of 2, and another 2 ways to orger the 2 groups of 3
livid sage
thx for ur help btw
welcome 🙂
worthy badger
if, say, i was picking 2 cards, 2 cards, 2 cards instead
i'd calculate 13C1 x 4...
then how come for this one u dont do 2! and then 1!?
livid sage
ah that's a nice question
worthy badger
since there's 2 groups of 2 and one group of 3
livid sage
it's because 1! = 1, which is an implicit thing
technically yes you can think of it as dividing by 2! then dividing by 1!
but it's equivalent to only dividing by 2!
worthy badger
but it's equivalent to only dividing by 2!
wait how? 2!=2 and 3!=6?
2!= 2 and then 1!=1
which dont add up to 6
livid sage
wait how? 2!=2 and 3!=6?
i'm not sure if i understand the question
worthy badger
i'm not sure if i understand the question
You had mentioned that dividing 2! and then 1! is the same as 3!... but when looking at these values on the calculator I dont see how they are equal
livid sage
You had mentioned that dividing 2! and then 1! is the same as 3!... but when loo...
uh...
well they certainly are not equal
livid sage
then how come for this one u dont do 2! and then 1!?
oh i see what you're asking
livid sage
since there's 2 groups of 2 and one group of 3
there's 3 groups of 2
livid sage
whereas the other 2 asked for 2 cards
the extra example i gave you was 3 groups of 2
that's the case where you divide by 3!
worthy badger
that's the case where you divide by 3!
ohh i see
livid sage
yee
livid sage
😂 i'm struggling on my own tests lmaoo
worthy badger
well whatever u are struggling with is something well beyond my knowledge that's fs
livid sage
😭 it's linear algebra
livid sage
crying
livid sage
nahh atp i'm going on here to get exposure to what other people are doing
(although i mainly only answer questions that use concepts that are common in competitive math)
it's kinda fun helping ppl understand things and i genuinely think i've been able to improve myself by spending time in this server's help channels
worthy badger
hey man to each their own... i would never do math for fun 😂
but helping others and seeing all the various types of problems out there will make u better through time fs
lone heartBOT
@worthy badger Has your question been resolved?
broken briar
How do I find x y z and a
lone heartBOT
How do I find x y z and a
lone heartBOT
@broken briar Has your question been resolved?
broken briar
So what i decided is
60/a=4/X for a ratio
Giving me a is 15 larger than X
a+x=8
15a=x
15(x-8)=x
X=7.5
A=.5
(sqrt(60^2+7.5^2))+(sqrt(.5^2+4^2))=(y+z)
Tell me if I'm wrong
lone heartBOT
@broken briar Has your question been resolved?
hollow egret
lone heartBOT
hollow egret
Can you help me solve this
lone heartBOT
Can you help me solve this
hollow egret
without using L'Hopital's rule
tardy stag
closing this one as the other seems more active. please don't open multiple help channels at once
.close
jolly lichen
hello
tight locust
32 - 5 = ?
oak chasm
Well, she starts with 5 bracelets.
Each package adds 4 more.
So, how would you write that in algebra?
jolly lichen
oak chasm
Like if she had 1 package, that would be p = 1, so 5 - 4(1) = 1.
Oh, OK.
So, 5 + 4p is good.
What counts of bracelets would work?
You said 32, but there might be others.
jolly lichen
?
oak chasm
Like if she had 100 bracelets, that would also work.
That would be enough to give 32 people a bracelet, right?
jolly lichen
i think?
oak chasm
Well, think about the actual situation.
Let's say you want to give 32 people a bracelet.
jolly lichen
ye
oak chasm
If you have 100 bracelets, would that be enough to do that?
jolly lichen
yes
oak chasm
OK, so 32 works, but also 33, 34, 35, etc.
So, 5 + 4p has to be 32 or more.
Does that make sense?
oak chasm
Right.
jolly lichen
=>
oak chasm
5 + 4p >= 32.
jolly lichen
ok
just wanna make sure with a couple m,ore quesiton
cuz i have been stuck on two step ineqautlites for a long tim
oak chasm
OK.
jolly lichen
oak chasm
OK, so she needs 100 or more seashells, right?
jolly lichen
100=34+12d
oak chasm
Almost.
jolly lichen
100>=34+12d
oak chasm
You're getting there.
Can it be exactly 100 if she "wants to collect over 100 seashells"?
jolly lichen
wwhat?
oak chasm
Well, "over" means more than.
oak chasm
Right.
oak chasm
Equal means exactly the same.
Like 5 + 5 = 10 means that 5 + 5 is exactly the same number as 10.
jolly lichen
yes i know that
oak chasm
Does that make sense?
OK, so if she needs over 100, that means that she needs more than 100.
Exactly 100 won't work.
jolly lichen
so
oak chasm
Does that make sense?
alpine sable
she wants MORE than 100
alpine sable
just a 100 wont do
oak chasm
OK, so first you need to solve the inequality.
lone heartBOT
left isle
well what is (x+y)(x-y)
what does that equal
no. you FOIL it right?
that is the answer, but it wants you to show your work.
there are two terms that cancel each other
foil it out first
dont simplify it
yea!
lone heartBOT
sour dove
lone heartBOT
Available help channel!
untold hatch
Help
untold hatch
Its harf
cinder tundra
In the middle is a minus or a product?
Start factorizing the numerator of the first fraction
left isle
factor both numerators and cancel some terms in the fractions before you subtract them (assuming it's subtraction)
untold hatch
In the middle is a minus or a product?
Thanks for noticed, it was multiple
left isle
oh that makes it much easier
cinder tundra
Now you can just factor both numerators
And you will get it
Do you know how can u factor both numerators?
untold hatch
Indeed
lone heartBOT
Available help channel!
ruby elbow
I'm confused with step 4
lone heartBOT
✅
ruby elbow
I'm confused with step 4
<@&286206848099549185> ^
tulip bone
you have proved that they're congruent
right?
what do you think corresponding sides mean?
@ruby elbow
ruby elbow
hm
ruby elbow
you have proved that they're congruent
yes
ruby elbow
what do you think corresponding sides mean?
like
ruby elbow
what do you think corresponding sides mean?
if these two triangles are congruent
then
if we flip one onto another
that linear pair
should be corresponding angles
tulip bone
those are angles
alright lets say
we have a triangle ABC and DEF
Angle ABC =90 Degrees, and Angle DEF= 90 degrees
rest of the angles are 45 each
in that case
When u put them side by side
AB would be corresponding to DE
BC would correspond to EF
ruby elbow
what do you think corresponding sides mean?
oh i thought you said corresponding angles
tulip bone
and AC would correspond to DF
try putting those triangles on top of one another
whichever side perfectly fits the other, becomes its corresponding side
tulip bone
do you have a basic understanding now?
ruby elbow
im trying to draw what you said out
ruby elbow
wait
tulip bone
two equilateral triangles
ruby elbow
tho
tulip bone
THEY ARE
ruby elbow
ok
tulip bone
then they won't be congruent, they'll be similar triangles
congruent means every side and angle is equal
you cannot make sides bigger as it would then result in them not being congruent
ruby elbow
I'm confused with step 4
^
mortal magnet
I'm confused with step 4
triangles are congruent if they have equal sides and angles, but you dont need to prove that theyre all equal to find congruence
an example of this is "side-side-side congruence", where its enough to prove that the three sides are equal
this was shown in step 3 and is correct
now that both triangles are congruent, you can use that to say that ||angle ADC = angle DCE||, since theyre essentially the same angle in their respective triangles
this is called "CPCTC," short for "corresponding parts of congruent triangles are congruent
ruby elbow
triangles are congruent if they have equal sides and angles, but you dont need t...
?
there is no option
for angle ADC = angle DCE
lol
mortal magnet
did you read everything else around the spoiler you clicked
ruby elbow
yes
mortal magnet
bit telling that the only thing you talked about is the spoiler
mortal magnet
you know that the ending step is that "since the alternate interior angles are congruent, the lines are parallel"
so youll need to find two angles that are congruent and are alternate interior angles, knowing that the triangle's angles are congruent to the other triangle's
ruby elbow
hm
ruby elbow
so youll need to find two angles that are congruent and are alternate interior a...
don't alternate interiorangles need a transversal
is CD = DC the transversal
mortal magnet
what do they give you as answer choices
ruby elbow
?
mortal magnet
angle ECD and angle DCE are the same exact angle
ruby elbow
ok
ruby elbow
angle ECD and angle DCE are the same exact angle
ik
ruby elbow
angle ECD and angle DCE are the same exact angle
hey
can't
angle DCA congruent to
CDE work
mortal magnet
because that would prove that DE || CA instead
ruby elbow
how
mortal magnet
🤔
ruby elbow
i have no idea how any of this helps of solve how AB parallel to CE
mortal magnet
do you know what alternate interior angles are
ruby elbow
yes
mortal magnet
do you know that those alternate interior angles are between parallel lines and a transversal
ruby elbow
ye
mortal magnet
do you know that those dont involve any other kind of line
mortal magnet
🤔 the angles are only between those 3 lines - any other kind of line couldnt be included if it tried
so if you have an angle about EDC and DCA, then that would only be about lines ED, DC, and CA
mortal magnet
I literally said that
ruby elbow
ok
mortal magnet
do you want a solution so bad
mortal magnet
this is the second time you asked a question that would be answered if you read what I said
mortal magnet
I already screenshotted the correct answer
select it
ruby elbow
i am just confused with all this proofs and congruence stuff
mortal magnet
then once you get the question correct, click the button on the khan academy website that breaks down how the solution works
if you cant find it, screenshot the website and Ill point it out to you
ruby elbow
mortal magnet
those angles yes
mortal magnet
I already said that twice
ruby elbow
ok
i see
that
angle ADC and ECD
don't touch any other line
the angle ADC only is touching
mortal magnet
you didnt seriously consider ADC and ECD before this, I see
ruby elbow
you didnt seriously consider ADC and ECD before this, I see
no I just looked at all the possibly answers and instantly went here because I had no idea what they were talking about
mortal magnet
so you didnt try
once I point out these things you already know, you suddenly know
lone heartBOT
mortal magnet
np
lone heartBOT
Available help channel!
flat lion
lone heartBOT
surreal crystal
i think we use the mean value theorem
$$f'(c)=\frac{f(b)-f(a)}{b-a}, c\in[a,b]$$
ocean sealBOT
Cycadellic
surreal crystal
then, f'(c) is the mean rate of change
flat lion
thanks gimme a bit to calc my answers
@surreal crystal is part b just asking the limit as t approaches 1?
flat lion
I somehow messed up inputing the answers
but Im getting the same answer on b
is it when t is approaching 1 or 0?
@surreal crystal
ocean sealBOT
Cycadellic
flat lion
surreal crystal
its asking for the rate of change at that point
by the way
if we put this limit into the mean value theorem
$$f'(c)=\frac{f(b)-f(a)}{b-a}, c\in[a,b]$$
$$f'(c)=\lim_{h\rightarrow 0}\frac{f(b+h)-f(b)}{b+h-b}, c\in[b,b+h]={b}$$
$$f'(b)=\lim_{h\rightarrow 0}\frac{f(b+h)-f(b)}{b+h-b}$$
ocean sealBOT
Cycadellic
surreal crystal
its just asking for the derivative at that point
flat lion
I don't understand
surreal crystal
that was just a proof that its just asking for the derivative at that point
dont worry about it
what do the answers tend to
surreal crystal
we want what this approaches
10.3 seems close, and since its asking for an approximation, it may accept the answer
but its not strictly correct
surreal crystal
do you know how to find the derivative?
flat lion
haven't gotten to that part of calc 1
surreal crystal
if so, what is f'(1)?
it may be more obvious if you had ii and iii
but i think it simply wants 10.28
surreal crystal
yeah
last walrus
hi @flat lion are you around?
flat lion
yea
for bcd I think I figured it out
as it approaches from left to right, it has different values corresponding?
but they don't match up so that why's there isn't a limit for when x approaches 0
@last walrus
last walrus
use the open circles to talk about the limit (ignore the fact that f(2) = 1)
so limit as we approach from the left side is what do you think?
flat lion
2?
flat lion
0?
last walrus
correct
nicely done!
so the limit only cares about what the y-values are "tending towards" it never cares about what f(x) is at that particular x-value
Last one is as x approaches 4
last walrus
it would be DNE since the two one sided limits are different
last walrus
or does it also not exist?
yes
flat lion
Last one is as x approaches 4
as x approaches 4 it gets closer to 3?
but 3 is also defined as well no?
last walrus
yes, but we dont care if f(4) is defined, we jsut care about where the y-values are tending towards. in this case both sides are tending towards y=3, so thats the limit
ivory patio
lone heartBOT
ivory patio
this is impossible right?
lone heartBOT
@ivory patio Has your question been resolved?
shrewd prism
if there's only 1 value for x then yeah i think so
confused about the january feb being different
livid sage
i do not believe so
it might not seem true at first, but some choices of a and b actually lead to the same result
tardy stag
also why can't b be 26?
livid sage
ah yes also a good point
lone heartBOT
@regal ledge Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
grim remnant
Sparx
lone heartBOT
@grim remnant Has your question been resolved?
long belfry
Hey, could someone help me understand what determines whether triangles have 0, 1 or 2 solutions based on one angle and two sides?
limpid turret
Are you asking why angle-side-side is not a congruence theorem?
ocean whale
Are you referring to this?
Ignore that page number, because I pulled that from google
ocean whale
Where are you confused? The figures should help with it
Finding side a occurs after using law of sines/cosines
long belfry
Do any of the figures correspond to a number of solutions?
ocean whale
Yes, it corresponds to 2, 1, or no solutions
long belfry
Ok ty
ocean whale
As it describes below each figure
long belfry
but a is not <h in the last one?
oh wait
that was not a glitch
lol nvm
a is not >b tho in the second one?
ocean whale
If a >= b, it's only one solution
long belfry
doesnt seem like the figure reflects that?
ocean whale
You should know that "figures aren't to scale"
long belfry
but a is clearly not higher or equal to b in fig 2?
ocean whale
figures aren't to scale
limpid turret
I think Fig 2. meant to say a=h
long belfry
I think Fig 2. meant to say a=h
right in that case i understand
ocean whale
That could be it too, like I said I pulled it from google
limpid turret
That could be it too, like I said I pulled it from google
You should probably review your material before you say, with certainty, that it is true.
(A mistake I make often, myself)
long belfry
thank you
ocean whale
You should probably review your material before you say, with certainty, that it...
Idk I just work here
astral creek
hi, what does the little + or – exponent thingy mean here? is the 4 in b different from the 4 in c?
unique imp
Hi! Yes, this tries to tell you whether you approach 4 from the left or the right on the real number line. For example, with the minus sign you would approach 4 from numbers smaller than 4.
So coming from -inf and working your way through the numbers until you hit 4 and the reverse with the plus sign, you start from +inf (or where ever) and end up at 4 from the right side
unique imp
no problem!
tall garden
lone heartBOT
tall garden
how do you convert this into an integral
lone heartBOT
Available help channel!
vagrant basin
help
vagrant basin
imagine you have
uh
lol
imagine you have this:
these are all length 1 lines
now
i make a second length
these are all 2/3
ok no wait
let me fix the thinggy
the math isnt mathing
nvm
its correct
anyways
as you can see the lines sometimes overlay and sometimes not
lets segment it
here we have segments 1, 2, 3, 4, 5
how do i calculate, how many "partitions" are in a given index
example
first red line overlays with just 1 gray line
second red line however overlays with 2 gray lines
which gives the table
1:1
2:2
3:1
4:1
5:2
6:1
how can i mathmatically calculate this (My guess is that its something with % Modulo)
(fast pls if possible i gtg later)
it should btw work if the red is bigger than gray
example: 4/3
which results in any xth line being 2 partitions
smoky dagger
so you want to find the number of gray lines overlaying with a red line.. given its index (the red line's index)?
vagrant basin
so you want to find the number of gray lines overlaying with a red line.. given ...
yep
even better if you can find it with pixels, since thats my main issue :O
for example
pixel 1 has 1 partition
pixel 2 has 2 partitions
....
going with bigger red lines you might have for example 4 partitions ... how do i calculate this
vagrant basin
imagine you have this:
though this could be obtainable from here i guess
vagrant basin
i almost got the solution but i lost my pen
WHAAAT
lone heartBOT
@vagrant basin Has your question been resolved?
smoky dagger
wait wait
well
here's what i got
the red line i starts from (2/3) times i-1 to (2/3) times i
so the line positions are smth like this:
(0, 0.6)
(0.6, 1.3)
(1.3, 2)
(2, 2.6)
(2.6, 3.2)
a red line overlays with 2 lines if:
a normal line ends between the positions of the red line
or
an integer is between the positions (notice how i defined the positions of a red line as intervals)
here, let me illustrate it
lone heartBOT
@vagrant basin Has your question been resolved?
smoky dagger
The blue lines always end in integer positions, because each line is of an integer length unit.
line ends at 1, 2 ends at 2 and so on.
so if an integer lies between start and end position of a red line (exclusively), that means the red line overlays 2 blue lines. (because a blue line starts/ends between the positions of the red line)
I guess that's one way to put it.
I hope that makes sense.
fathom heron
The scale factor of two similar polygons is 1:3. The perimeter and area of the larger polygon are 78 in. and 144 in^2, respectively. Find the perimeter and area of the smaller polygon.
fathom heron
I am confused on how to solve the area
livid sage
I am confused on how to solve the area
if the perimeter scales by a factor of x, then the area scales by a factor of x^2
(you can also extend this to volume. if we scale a 3d shape with volume V by a scale factor of x, the new volume becomes V * x^3)
fathom heron
how would I set up my proportion?
would it be 1/3=144/1, although i don't thihk thats right
livid sage
what do you calculate for the perimeter of the smaller shape
fathom heron
i did 1/3=78/1
livid sage
what is that
fathom heron
a proportion i set up
livid sage
where is your variable
livid sage
how are you using that to solve for perimeter?
livid sage
which 1 there are 2
livid sage
thanks
alright so this would be incorrect because it treats the 78 perimeter shape as the smaller polygon instead of the larger polygon
for instance, if you solve for x here, you get x = 234
to fix this, we'd want to write our equation as 1/3 = x/78
does this make sense?
livid sage
cool
finding the area is a very similar process, but instead of using a factor of 3, we want to use a factor of 3 squared, which is 9
fathom heron
so you're squaring the scale factor?
livid sage
pretty much yes
fathom heron
alr and then?
livid sage
can you set up the equation to solve for the new area?
livid sage
two things
livid sage
first, you made the same mistake as the first time
second, the area of the larger polygon is 144 not 78
fathom heron
oh ok
livid sage
first, you made the same mistake as the first time
do you understand what your mistake is?
fathom heron
yes my second fraction was flipped the wrong way
livid sage
when you have an equation that compares two ratios, you want the individual parts of the fractions to match
fathom heron
so would it be 1/9=x/144?
livid sage
yep that's right
lone heartBOT
livid sage
welcome 🙂
fathom heron
.reopen
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stiff harness
Why is this problem DNE? I'm a bit confused with open circle graph limits.
naive valley
what was your reasoning for why it's 1
stiff harness
right
naive valley
but the limit as x->0 actually doesn't depend on the value of g(0)
only on values of g(x) for x near zero
stiff harness
i'm still a bit confused with that
naive valley
you have two cases to look at:
x < 0 (the behavior of the graph to the left of x=0)
and x > 0 (the behavior to the right of x=0)
stiff harness
I see
naive valley
the graph has to approach the same y value from both sides in order for that y value to be the limit
stiff harness
OHHH
naive valley
(or for the limit to exist at all)
stiff harness
that's where i was getting it wrong
so in order for it to be 1, (0,2) would have to be (0,1) basically?
like that line just connects to the closed dot
naive valley
the curve on the right side would have to approach (0,1)
just like the curve on the left does
the value at x=0 doesn't matter, but the behavior of the curves on both sides as they approach x=0 is what matters
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vernal kite
I’m learning to factor polynomials. My teacher mentioned “every positive number has a double negative”. In what case could I use this rule ?
Overall I’m very confused with this new topic and I’m constantly indecisive if I should put a negative in my answer or a positive lol
vernal kite
I don’t have a particular problem I’m struggling with but I just don’t know how to use this rule…
stoic cloud
I’m learning to factor polynomials. My teacher mentioned “every positive number ...
well -5-(-5) is -5+5 cuz of the double negative, so any equation u have -5-(x) in which x is a negative number
u should just change it
vernal kite
Okay thx
leaden charm
i need help
ith math
im in gr 9
i have an exam tmrw
and im like in need of help
can anyone help
leaden charm
how do i open a new channel
lone heartBOT
how do i open a new channel
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
stoic cloud
also just study whatever ur teacher gave u to study
leaden charm
also just study whatever ur teacher gave u to study
what he does is he gives us reveiw but the reveiw doesnt have anything thats on the test
lone heartBOT
what he does is he gives us reveiw but the reveiw doesnt have anything thats on ...
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
stoic cloud
what he does is he gives us reveiw but the reveiw doesnt have anything thats on ...
!occupied
lone heartBOT
what he does is he gives us reveiw but the reveiw doesnt have anything thats on ...
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
vernal kite
.close
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manic sundial
how does one solve these diffeqs? do i just guess and plug in?
manic sundial
is there a procedure for it?
lone heartBOT
is there a procedure for it?
manic sundial
i tried searching up how to solve "Homogenous diffeqs" but all of them are with given functions or something of the like.
lone heartBOT
@manic sundial Has your question been resolved?
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@manic sundial Has your question been resolved?
near harbor
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quick pike
Hello
quick pike
I need help too.
near harbor
This is the wrong chat
balmy grail
I need help too.
!occupied
lone heartBOT
I need help too.
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
balmy grail
Do you know how interior angles work?
near harbor
Not really
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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
balmy grail
You have a 4 sided shape so the angles you wrote in pen + the last angle sum to 180*(n-2) with n =4 sides
So the three you have + last interior angle = 180*(4-2)=360
near harbor
So C is 180?
near harbor
I added 75 + 95 + 105 which added up to 275
So then I thought it had to add up to 360
So I assumed C was 80
75 + 95 + 105 + 80 = 360
Wait nvm
85**
flat lion
how do I evaluate 3b?
lone heartBOT
how do I evaluate 3b?
flat lion
lone heartBOT
flat lion
sry claimed it first
flint pagoda
Have you learned lhopital rule?
tardy stag
you don't need l'hopital rule here at all and it's unclear how it would be useful
for a limit we only care about the value of f in the immediate neighborhood of 10 (in this case), not the value at 10
flat lion
so where do I start?
flint pagoda
Quotient rule?
tardy stag
so where do I start?
sketch the function
lone heartBOT
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languid bluff
so q = 8 + 5sqrt(3), 8 - 5sqrt(3) ? (checking my answer)
lone heartBOT
so q = 8 + 5sqrt(3), 8 - 5sqrt(3) ? (checking my answer)
@languid bluff Has your question been resolved?
languid bluff
.close
versed walrus
questions 2 and 4, i have the answer but need explanations. in AP statsitics
grizzled aspen
What does independent mean to you?
versed walrus
The occurence of one event doesn't affect the occurrence of the other event?
grizzled aspen
okay
so just take that information at face* value
and re-read the question aloud to yourself
grizzled aspen
okay
so
the chance that one runs doesnt affect the other
but they can BOTH run
does that help?
versed walrus
45%
grizzled aspen
okay
versed walrus
45-9
grizzled aspen
lets say that the chance that the day that she announces she is running is rainy is 20%
what is the chance that she runs, and it is raining?
grizzled aspen
that is how assessing multiple independent events works - you multiply the probability of each
e.g. chance of a coin being heads 3 times in a row = 1/2 * 1/2 * 1/2
now let me reword my example slightly
versed walrus
gotcha
grizzled aspen
so thats all your question is
what is the chance that ONLY hilary runs
and not this other guy
grizzled aspen
I would just picture it no differently to the example above
or to the multiple coin flips
what is the chance she runs?
versed walrus
ok
versed walrus
so 0.45*0.8?
grizzled aspen
yep
grizzled aspen
Well
same thing
multiple events repeated
take the product of their probabilities
what are the two ways that the event can occur? (In other words, describe the events that the question is wanting you to find the probability for)
versed walrus
tbh still confused w/ 4
versed walrus
probability that they pick either 2 girls or 2 boys
versed walrus
ok
grizzled aspen
what is the chance that the first selection is a girl (given the question says we are randomly selecting, not voting)
versed walrus
2/8
grizzled aspen
so what is the chance that those two events occur in a row?
versed walrus
then multiply?
grizzled aspen
are we asking if they are both going to occur
grizzled aspen
or are we asking if either one will occur?
grizzled aspen
right
versed walrus
its not asking for both
grizzled aspen
so
versed walrus
so addition, not multiply right
grizzled aspen
correct
assuming independent
you can add the separate probabilities
and
you can multiple probabilities
multiply for a series of events happening in a row/simultaneously
add for separate probabilities (when each of them are "successes" for your event)
if you like a visual understanding, think of a tree diagram
and we want to select all the paths that are Boy > Boy and Girl > Girl
because any of those are a success
but all of the paths that are Boy > Girl are a failure, and Girl > Boy
versed walrus
gotcha
thank you
i have a few more questions and am new here,
can i post them on this chat w u? or restart the process
grizzled aspen
just remember its a bit weird but "OR" generally means you are adding "AND" generally means you are multiplying (or in a Venn diagram, OR means you are doing everything in the circles you care about, and AND means you are only selecting things in the overlap)
Lot of students get confused that AND feels like it should be bigger or adding, and OR feels like it should be one or the other.
The idea is that AND is MORE restrictive - both things need to occur so we have a smaller selection
OR is less restrictive - either thing can happen for a success so there is a larger selection
grizzled aspen
can i post them on this chat w u? or restart the process
Normally I wouldn't mind, but I am about to go tutor someone so I have to go.
versed walrus
thanks. have a gday
grizzled aspen
no worries, just make sure u read over the above info and think about it (in venn and tree etc) ^^
lone heartBOT
@versed walrus Has your question been resolved?
versed walrus
yes
royal kiln
lone heartBOT
https://i.imgur.com/miXW5TO.png
royal kiln
is this a hard proof to come up with?
I had to do it but gave up after I tried to go with something inductive but hit a wall
rich quiver
is this a hard proof to come up with?
Like for first time ?
royal kiln
I mean yeah I've never proved exactly this before but for example I'd never think to put it into Ax^2 + 2Bx + C >= 0
to be honest even after I saw it I had to look for like 25 mins before I bought in
rich quiver
I think it depends on which level you are like for me we are not taught this inequality at 11th grade but i was just curious so looked up and this proof was so simple(i didn't thought that the proof will be this much easier to understand) but i am sure if was given to prove this i would not have done this in first time
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upbeat eagle
Hey
upbeat eagle
So im trying to calculate the value of ε
I did this by
rearaging it to make it look like a y=mx + c equation
and I got
1/n = ε /22 (1/I) - r/22
And to find ε , you plot in values of n and I, and ignore r
I got ε to be 66/41
My question is how do I find the values of r
Is doing lets say
Y= mx +c
y= mx -r
m (gradient being) ε/22 so (66/41)/22 = 3/41
Can you do
(lets say y = 0.3 when x = 5]
Can you do
A. 0.3=3/41 (5) - r/22 to find r
Is that wrong?
It looks wrong
Or would you have to have 2 y and 2 x values
B.
So lets say y=0.3 and x= 5 and y=0.9 when x=13.2
0.3=3/41 (5) - r/22
0.9 = 3/41 (13.2) - r/22
Or can you do,
1/n = ε/22 (1/I) - r/22
y = m x + c
So since 1/n is the y axis and 1/I is the x axis
y = ε/22 x - r/22
Thus
22y = εx - r
If you dont know what tf im on about and want to help, I can explain everything from scratch in like 2 min one after one
Im a bit confused on what the flip in doing haheuhauheuaeh
hasty creek
What does r and epsilon represent
upbeat eagle
What does r and epsilon represent
Internal resistance and ε emf