help-0

[elfin dust]

If you understand what I'm saying right now I'm pretty sure you can carry it on from here

[crisp hill]

uh

absolutely not

im lost

😭

[elfin dust]

You get this?

[crisp hill]

i mean yeah a is the numebr he multiplies by so like if you multiply it 100 times then y should be different should it not?

[elfin dust]

well y remains unchanged so

[crisp hill]

oh

so that means that he just had to multiply it by 3

right?

or something

idk

😭

[crisp hill]

oh

....

haha... im so smarttt

fr...

[elfin dust]

You get it?

[crisp hill]

yeah

[elfin dust]

ok cool

[crisp hill]

gimme a sec to write that down tho

lol

u r like..

my savior i was dying

[elfin dust]

np lmao

type .close if ur done

[crisp hill]

alright

but theres some other stuff

[crisp hill]

im like on the last few problems which are usually the hardest so i always get stuck on these lol

ty anyways

.close :D

[lone heart]

Channel closed

Closed by @crisp hill

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[faint monolith]

The mean of a set of five different positive integers is 15. The median is 18. The maximum possible value of the largest of these five integers is

[faint monolith]

I used the numbers 1,1,18,19,x

but i got it wrong

because apparently you're suppose to use 1,2,18,19,x

why cant you have x2 1's though?

isnt that the smallest possibl

[fallen verge]

different

[faint monolith]

wdym

ohhh

nvm

.cloes

/close

.close

[lone heart]

Channel closed

Closed by @faint monolith

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn dew]

Math is too hard

[torn dew]

I'm leaving

[echo socket]

.close

[lone heart]

Channel closed

Closed by @echo socket

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable grotto]

how to know that (arctang(x))/x^2 is decreasing on (1;inf) ?

[vale wigeon]

why not just take its derivative?

or is that expressly forbidden?

[stable grotto]

yy

i just forgot that d/dx of arctang = 1/1+x^2 .

i thought it was something different

.close

[lone heart]

Channel closed

Closed by @stable grotto

Use .reopen if this was a mistake.

[vale wigeon]

missing parentheses but yes

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable grotto]

how to know that this diverges?

it says use integral test

[vale wigeon]

i'd do comparison: 1/ln(n) ≥ 1/n

integral test would require you to integrate 1/ln(x), which is hard

[alpine sable]

do you know what integral test is?

[stable grotto]

its not elementary integral

[buoyant saddle]

yea that’s not elementary

[stable grotto]

why is that

[buoyant saddle]

1/n diverges

[vale wigeon]

as in "why is that inequality true" or "why does this work" or "why did i choose this method"?

[stable grotto]

first

[vale wigeon]

0 < ln(n) ≤ n

well, ln(n) < n formally.

but strictness doesn't matter a lot here.

[stable grotto]

why ?

[stable grotto]

yes but how to know that witgout calculator

[alpine sable]

logarithmic functions grows slower than linear function

[vale wigeon]

i think this might be something you learn the first time you see the natural log function

it is a fairly useful property

but for FORMALISM: ln is a concave function and its tangent at x=1 is y = x-1. by its concavity it lies below its own tangent, thus ln(x) ≤ x-1 < x

of course, this formally leaves the following questions unanswered:

• why is ln(x) concave
• why is its tangent at x=1 the line y=x-1
• why is x-1 < x

[buoyant saddle]

well i mean the third one is a given lol

[alpine sable]

u can also show the integral test diverges

[stable grotto]

all these i know

how to calculate

[vale wigeon]

no, -1<0 isn't an axiom

you can't assume it to be known

if you're a hardcore formalist

[stable grotto]

y i like these type of explanations

[buoyant saddle]

i mean isn’t a definition

[stable grotto]

no i am now assuming but i know how to calculate them

[vale wigeon]

no

the definition of -1 is "the real number whose sum with 1 is 0"

[buoyant saddle]

y would u ever have to prove that one number is to the left of another number on the number line when it’s just an integer

we made the number line that way

-1 is to the left of zero

it’s less

[stable grotto]

ann being too extremist here

[vale wigeon]

i am being overly-formalist on purpose.

i would appreciate if you didn't call me specifically the word "extremist".

although i guess i kind of already am that, according to the laws of my home country.

[buoyant saddle]

no i get it it’s just strange why you wouldn’t just assume it to be a definition

[buoyant saddle]

unfortunate

[stable grotto]

i am very ok with this -1<0 . i do not need proof of it

tnx all

.close

[lone heart]

Channel closed

Closed by @stable grotto

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cinder sundial]

hello

[cinder sundial]

how to integrate a function with a shape of circle on the plane

.close

[lone heart]

Channel closed

Closed by @cinder sundial

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bright pier]

i need help with home work it’s in a photo

[lone heart]

@bright pier Has your question been resolved?

[bright pier]

.close

[lone heart]

Channel closed

Closed by @bright pier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting seal]

Can I get physics support here/

[drifting seal]

A string of length 3m is tied to the ceiling at points P and Q which are 2m apart. A smooth light pulley supported by the string is attached to a block of mass 6kg as shown. Find the tesion in the string.

[drifting seal]

photo ref

[lone heart]

@drifting seal Has your question been resolved?

Channel closed

Closed by @drifting seal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glossy lion]

can anyone help explain these steps?

[glossy lion]

I dont understand how the value of sin(x)cos(x) and sin(x)-cos(x) are obtained

[lone heart]

@glossy lion Has your question been resolved?

[glossy lion]

<@&286206848099549185>

[charred jewel]

sinx + cosx = k

square both sides

you'll get a 2sinxcosx there

and when you square it you also get sin squared plus cos squared

which is 1

then just find sinxcosx in terms of k

for sinx - cosx also same thing, let it be something say, A
so A = sinx - cosx

then square both sides again

after finding it in terms of k, square root it back

[lone heart]

@glossy lion Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic cape]

helo anyone knows add math intersection of lines and circles?

[abstract furnace]

[mystic cape]

oh hii

hold on lemme take a pic of the qs

Qs 4&5

[abstract furnace]

,rotate

[abstract furnace]

do you know calculus?

[lethal belfry]

you can either use calculus or substitute and solve , proving there is only one solution

[mystic cape]

im learning add math but idk if the methods are the same as calculus?

[abstract furnace]

anyway first of all start off with

completing the squares

we can do it without calculus ig

[mystic cape]

sub the line eq into the circle eq?

[lethal belfry]

yes

if you don't know calculus

[junior vigil]

Use the fact that a tangent line to a circle is perpendicular to a radial line

Line

[abstract furnace]

mhm

[junior vigil]

Circle

[mystic cape]

oke

[mystic cape]

oke

[mystic cape]

like this right?

[lethal belfry]

please occupy a new channel of your own

oops

they deletd their message

sorry

[mystic cape]

lol

[mystic cape]

wait but how do i sub

[lethal belfry]

express the circle purely in terms of x by using the relation between x and y from the line equation

and solve that

[mystic cape]

oh so its like simultaneous eq or?

[lethal belfry]

sort of , yes

[lone heart]

@mystic cape Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fading kestrel]

just want the final answer

[lofty creek]

!noans

[lone heart]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[lofty creek]

if you want answers go look them up

[fading kestrel]

i am not able to

i calculated 1

[alpine sable]

then solve it

[fading kestrel]

i want to check

[alpine sable]

strive to learn

[fading kestrel]

man cmon

i calculated

just wanna check

1 or nah

[gray isle]

,w integrate xe^x from 0 to 1

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ramonov

[gray isle]

use wolfram to check yourself next time

[fading kestrel]

what is wolfram

[gray isle]

powerful math tool

[lofty creek]

!nosols

[lone heart]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[fading kestrel]

omk

thenku

.close

[lone heart]

Channel closed

Closed by @fading kestrel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tough lintel]

Prove n^3 +5n is divisible by six

[tough lintel]

For n in N

I tried doing induction. But its not panning out right

I know the base case works

And it's dividable my six and 3

Can I, plug in 3k, 3k+1, 3k+2 In and see they're all divisible by 3, since those would be the remainder of things dividable by 3?

[alpine sable]

take 2 cases

when n is odd

and when n is even

when n is even it can be expressed as n = 2k

and when it is odd it can be expressed as n = 2k + 1.

that's a little hint for ya

[steep pendant]

i'm pretty sure this can still be solved with induction though, right ?

[tough lintel]

That top bits my attempt

[alpine sable]

not needed

it can be proved without induction

[steep pendant]

i think both methods are equally valid ways to do it, and i'm only saying because that's the way they originally attempted to solve it

[tough lintel]

Oh wow by an even number it's divisible by six

Same for odd

[steep pendant]

when you get to 3n^2+3n+6, you should try factoring out 3, then proving that the expression is equal to the product of one number that is divisible by 3, and one number that is divisible by 2

[tough lintel]

Then GCD is six right

[steep pendant]

yeah any number divisible by 2 and 3 must also be divisible by 6

[tough lintel]

Okay I'm glad I'm halfway there

Thanks for the help everyone

.close

[lone heart]

Channel closed

Closed by @tough lintel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim chasm]

Hi, wondering why the answe for part A is 80ms, we got 0.8s. Thanks!

[lone heart]

Show your work, and if possible, explain where you are stuck.

[frosty ginkgo]

how do i do grade 1 math

i am very autistic that is why i am asking how to do it

[lofty creek]

0.8s is incorrect

[slim chasm]

We used Suvat and got 0.8, very confused

[lofty creek]

$\text{speed} = \frac{\text{distance}}{\text{time}}$ right?

[ocean seal]

Flappie

[frosty ginkgo]

im autistic let me know how to do this bro

[lofty creek]

so here how to solve for time

[frosty ginkgo]

this sucks

i need helppp

algebra stuff

[lofty creek]

!help

[lone heart]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[slim chasm]

S = (u+v)/2 * t

[slim chasm]

Go away

[lofty creek]

what?

[slim chasm]

Go away

[slim chasm]

Suvat

Wait

[alpine sable]

what equation?

[gray isle]

<@&268886789983436800> in appropriate comments from Don and fled

[alpine sable]

Ur initial velocity is 20ms^-1, final velocity is 0 time is to be determined and displacement is 0.8m

[slim chasm]

<@&268886789983436800> ban these fools

[slim chasm]

Thus: equation 4

Shut up

[alpine sable]

yes, did u rearrange correctly?

[lofty creek]

why use this?

[gray isle]

how are you getting 0.8 from applying 4.

[lofty creek]

we know speed = distance/time

we have speed

and we have distance

so how to calculate time

[alpine sable]

the speed isnt constant???

[slim chasm]

Probably not ig

[alpine sable]

2s(v+u)=t

2s/(v+u)^^

thats what i meant

😭😭

[lofty creek]

<@&268886789983436800>

[slim chasm]

Wait

[alpine sable]

ignore that

i forgot the divide

[slim chasm]

No, we just hate you

I still got 0.08

[gray isle]

yes

[alpine sable]

u should get like 1.6/20

yeah 0.08

[gray isle]

0.08s is fine

[alpine sable]

is that not correct?

[gray isle]

0.08s = 80ms

[alpine sable]

whats the answer in the book

[slim chasm]

Why is the awsner 80ms?

[slim chasm]

80ms

[alpine sable]

ohh

[gray isle]

because they decided to express it in ms

[alpine sable]

1s = 1000ms

so 0.08s is 80ms

[gray isle]

the value you initially typed of 0.8s was incorrect

[slim chasm]

Oh ok cool Ty

[lone heart]

@slim chasm Has your question been resolved?

Channel closed

Closed by @slim chasm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mild token]

the answer is p=120, q=45
Please explain how you get the P

[hasty hill]

notice that rest starts after travelling for 20km

[mild token]

yes im dumb for not noticing that Thank you

[lone heart]

@mild token Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[formal ginkgo]

how it was simplified like this

[snow cobalt]

they factorized it

[alpine sable]

Factor (t³ - 3r - 2)

[formal ginkgo]

but nothing is clear to me

[raw stream]

*3t

[alpine sable]

Yes 3t, typo

[raw stream]

np

[raw stream]

its soo straightforward

[dire tiger]

Split -3t into -2t+(-t)

[dire tiger]

And just rerrange the terms and factor

[formal ginkgo]

but no t^3 not 2

[dire tiger]

No need to split them?

[dire tiger]

Do I send the solution

[formal ginkgo]

and then nothing

if it was t^2 then yes

[dire tiger]

Rerrange those term

Think of how you can rerrange them

So you can get a common factor

[raw stream]

@formal ginkgo

[dire tiger]

||take (t^3-t)-2(t+1)||

[dire tiger]

Only see this if you cannot find the solution

[formal ginkgo]

but noo

it will not help ...

look at (3)

[raw stream]

yes

you want range of t?

the intervals?

[dire tiger]

How

[raw stream]

you could plot them

[dire tiger]

I just did it by doing this

It will be t^3*(t+1)(an polynomial term)

You just have to factor out that polynomial term

||it will factor into (t+1)(t-2)||

[raw stream]

@formal ginkgo

[raw stream]

.

[lone heart]

@formal ginkgo Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[little spindle]

how to solve this using chain rule?

[slate vortex]

You want to see the "layer of functions" if that makes sense

[little spindle]

ya composite function.

should i take the function inside the sqrt as U?

im stuck in the middle

[slate vortex]

Uh I'm not sure what that means

But the way I see it is, the order of functions is

1. Cubed
2. Cotangent
3. Square root
4. 2-3sin(x)

[little spindle]

ok got it lemme try again

[alpine sable]

idk just use product rule

😁

[little spindle]

Im not good at calculus

[alpine sable]

js practice

[little spindle]

i ant solve it. Can u guys help me with the solution?

[alpine sable]

Have u covered the product rule yet?

@little spindle

[little spindle]

Yes

[alpine sable]

oh wait shit mb

i misread the question

ur gonna be using chain rule only

(2-3sinx)^1/2 is your u

and y=cot^3(u)

so find the derivative of both of them

and yeah

chain rule it

[little spindle]

Ok wait

[lone heart]

@little spindle Has your question been resolved?

[little spindle]

@alpine sable there are 3 composite function right ?

i can apply chain rule also in sqrt(2-3sinx))

got it

its a big fucking answer man

[lone heart]

@little spindle Has your question been resolved?

[lone heart]

Channel closed

Closed by @little spindle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jagged cobalt]

blimey

[alpine sable]

funny words

[jagged cobalt]

wish i could help, just beyond my current knowledge base as a second year uni student haha

i wish you luck though

[marsh rapids]

i'm afraid that puts your level in math as high in this server

the more mathematically knowledgeable people usually hang out in the advanced channels

[quiet vector]

i'm afraid that puts your level in math as "high" in this server

💀

[marsh rapids]

high level

yeah no

I don't think you'll find many people for that here, but maybe

[quiet vector]

yea; someone might still help u here in this channel

[next brook]

The help channels are mainly frequented by people who feel competent to help with high-school and early undergraduate homework.

[quiet vector]

💀

#get-advanced-access

go thru this

and look below

[marsh rapids]

this sounds like an internship project but weirdly phrased imo
This is hardly a math question

but who is a 3rd year Math/CS major to say

assuredly
but you showed none

idk
Just sounds complicated

meaning you may only get help from the people who can easily turn these words into the corresponding formulas

[stark crater]

If you want help from a math server, translate the physics you know into math

[worn fox]

Its just very niche and potentially inaccessible to anyone who doesn't already know exactly what you're doing. You might want to try stack exchange

[marsh rapids]

and as much as this server may seem big
There aren't actually that many people, that would be able to do this for you

[quiet vector]

server is for maths; not science

[next brook]

Anthracenequinone is a 24-atom molecule. It sounds like you're being asked to solve its electron structure numerically right from the Schrödinger equation, which sounds more like a thesis project than a test question...

[marsh rapids]

take the physics away, ask in the relevant advanced channel, in simpler steps, like help with some computations or some system/behavior, and you may already get much more help

[marsh rapids]

hence me mentioning internship

[next brook]

You might be able to get some methodological sparring in #modeling or #numerical-analysis, but not on the level of "here's how you solve this problem".

[marsh rapids]

listen to tropo not me
I'm definitely not the most knowledgeable here

[mellow grail]

Its a forum online. You will find people with a similar hanging out there, tho communication tends to be slower there

[tacit arch]

.

[worn fox]

If you know latex you can use @ocean seal

If you don't know latex then god help you

[ocean seal]

Claymore

LaTeX source sent via direct message.

[mellow grail]

Well actually the text cheatsheeet can help if he doesn't know latex

[mellow grail]

Okay nvm he seems to know what he's doing

[tacit arch]

.

[ocean seal]

Claymore

[tacit arch]

layed

[next brook]

I strongly suspect that to make your problem tractable, you'll need computational techniques developed specifically for in silico chemistry, so you'll need advice from active researchers in that or a related field (hopefully you have an advisor fitting that description!). Almost certainly there will exist specialized software you can at least use as a starting point, but mathematicians will not know about that.

[mellow grail]

Pretty sure the bigmans right

[alpine sable]

Don't mind my intrusion and personal comments, but I find it quite suspicious that you transitioned from addressing middle school/high school questions to claiming expertise in "PhD in quantum physics" after looking through your message history.

[alpine sable]

your LaTeX also seems more so a symbol salad rather than an articulated excerpt of what a PhD student would be writing as well

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal tapir]

need help understanding this:

[vocal tapir]

how it becomes this:

my textbook says that after taking out the last two equations, we get the second pic ^

original being:

L1 being equation 1

this is about vectors

[golden viper]

Don't you just add up the eqations?

[vocal tapir]

I mean yeah, but how did they get to L1+L2-L3+L4

[golden viper]

What is actually the question of the problem?

[vocal tapir]

<@&286206848099549185>

[naive valley]

is there more written than what you have pasted?

[vocal tapir]

just transformations

uhh

idk how to call it in English

[naive valley]

surely they're not concluding that based on the first screenshot

and while you can conclude it from the second, it would be hard to do so if you didn't already know the answer

[vocal tapir]

I understood exactly nothing

whatsoever

neither from the textbook

neither from the help I've received so far

you have this

question being linear dependence or no

ugu gaga

this

conclusion:

[naive valley]

well you can obviously check that L1 + L2 - L3 + L4 = 0 from this

[vocal tapir]

I agree

[naive valley]

but the question is, how would you have known that

[vocal tapir]

yes

[naive valley]

^ this doesn't show it

so what else was written?

[naive valley]

what's the last line of this chain of transformations

[vocal tapir]

It's equation 4 with 2*equation 1

with the aim of understanding if the equations are linearly dependent or not

(the 4 of them)

[naive valley]

from this step ^ did you try subtracting the last row from the one above it?

i'm surprised the book didn't do that explicitly

[vocal tapir]

yes

[naive valley]

what did you get?

[naive valley]

where did the 4th line go?

and you have to include the parts with the L1,L2,L3,L4

if you compute this:

minus this:

you should get L1 + L2 - L3 + L4

[vocal tapir]

I've received help from elsewhere

explanation:

I+II-III+IV=0

[naive valley]

that's obviously false

the first column of I + II - III + IV will be -1, not 0

[vocal tapir]

.close

[lone heart]

Channel closed

Closed by @vocal tapir

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Where did the 1 come from?

I just guessed the formula

well like

you notice how it goes like 3, 5, 7, ...?

I don’t remember how yes

OH

wait no I don’t get it

basically the thing is like

you can represent odd numbers by the formula 2n+1

and even numbers by 2n

assuming n is an integer

like 2(1) + 1 = 3
2(2) +1 = 5 and so on

[alpine sable]

mm maybe explain what you don't get?

So it’s 1 because it’s an odd number

yeah

Every time

exactly

But I remember like how I got taught a formula to learn this

It’s was like difference minus something idk

using Ur intuition rather than like some formula is fine as well

dw about it

Yeah but what if there’s harder questions like this

well idk what formula you are talking about

again DW about it until it comes your way or Ur teacher tells u about it or something

what class is this meant to be?

Lmao yeah ur right u just put the number in lol

[alpine sable]

It’s algebra

[azure needle]

its an arithmetic progression

[alpine sable]

What’s that

[azure needle]

a sequence of numbers with a common difference

where the common difference = currentterm - previousterm
or
nextterm - currentterm

[alpine sable]

Oh yeah I understand that

[azure needle]

the second term - first term = common difference
right?

[alpine sable]

Yeah

[azure needle]

also the third term - second term = common difference

[alpine sable]

Yes

But number next to the difference

[azure needle]

so the generalization is
nth term - n-1th term = common difference
nth term = n-1th + common difference

can I continue?

@alpine sable

[alpine sable]

Is that what u just explained or is this something new bc now I dont get it

[azure needle]

its a generalized form of what i explained
nth term (current term)
n-1th term(previous term)

[alpine sable]

Yeah ok

Continue

[azure needle]

now lets use letters to represent the terms
a is first term
n is nth term(or the number of the term eg 1st 2nd 3rd)
d is common difference
2nd term = a + d (but:2-1=1 and d= 1d)
2nd term = a + (2-1)d
3rd term = 2nd term + d
but second term = a + d
therefore: 3rd term = (a +d )+ d
3rd term = a + 2d (but:3-1=2)
3rd term = a + (3-1)d
so the generalization here is for any term n;
nth term = a + (n-1)d

@alpine sable

[alpine sable]

Yes I’m going though it I’m trying rlly hard to understand

[azure needle]

maybe try watching an eddie woo vid for more help though

[alpine sable]

I’ve never heard of him

[azure needle]

the letters are just generalization

[azure needle]

fr?

just type sequences and series on yt

[alpine sable]

I think I get it

Yeah

[azure needle]

it'll take a while for me to elaborate

[alpine sable]

Wow he’s like famous lmao never heard of him

Only use the chemistry tutor guy

[azure needle]

i also too

thats where i learnt stuff on polar coordinates

[alpine sable]

The thing is that I’m learning this in swedish so English terms become new to me

[azure needle]

nice

[azure needle]

oh

[alpine sable]

But ty have a good day

[azure needle]

should i translate

[alpine sable]

Lmao no it’s fine

.close

[lone heart]

Channel closed

Closed by @fair hull

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limpid shore]

Consider the following series $$\frac12+\frac13+\left(\frac12\right)^2+\left(\frac13\right)^2+\left(\frac12\right)^3+\left(\frac13\right)^3+\ldots$$ How can I determine whether or not it converges or diverges? Here the ratio test fails I guess, so maybe the root test?

[ocean seal]

Philip

[limpid turret]

Looks like it's two separate series.

[limpid shore]

I know, it's from Spivaks

but it's supposed to be a single series I assume

[lofty creek]

try writing it as a sum

[limpid shore]

well, then $a_{2n}=\left(\frac12\right)^{n+1}$ and $a_{2n+1}=\left(\frac13\right)^{n+1}$.

[ocean seal]

Philip

[limpid shore]

where n=0,1,2,3,...

does the root test apply here? or maybe the ratio test too?

[lofty creek]

why 2n?

just write it as an and bn

if one of them diverges then total diverges

if you can show that they both converge, then an+bn converges

[limpid shore]

but can I just rearrange the order of summation?

writing the series above as two separate series would require to rearrange the terms, no?

[lofty creek]

but its addition

youre allowed to do that

[limpid shore]

but it's infinite addition

[lofty creek]

i could do $\sum_{n=1}^{\infty} n^2 = 4^2+5^2+6^2+.... + 100^2+101^2 + 1^2 +2^2+3^2 + 102^2+103^2 +...$

[ocean seal]

Flappie

[tacit arch]

You can if all the terms are positive.

n^2>0 for all natural numbers n

[limpid shore]

ok

so is the ratio or root test overkill here?

[lofty creek]

no its not

[limpid shore]

if we simply rearaange, we get two geometric series, right?

[lofty creek]

because you still need to show that $\\sum_{n=1}^\infty \left(\frac12\right)^n + \sum_{n=1}^\infty \left(\frac13\right)^n$ converges

[ocean seal]

Flappie

[limpid shore]

ok

[lofty creek]

and to show that the sum of these sums converges, we need to show that each sum converges

and those you can check with ratio/root test

[limpid shore]

yeah 👍

[lone heart]

@limpid shore Has your question been resolved?

Channel closed

Closed by @limpid shore

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scarlet drum]

Through the middle M of the arc AC of the circumscribed circle of the triangle △ABC, a chord (MN) parallel to AB is drawn.

Show that the arcs BNC and MCN are congruent.

[scarlet drum]

Let me get the drawing rq

We have to prove that the angle formed by the blue is equal to the angle formed by the red

<@&286206848099549185>

[quick valley]

Which is which it's not clear

[scarlet drum]

Red and blue?

[quick valley]

Yes

[scarlet drum]

Here

Yellow angles are congruent

[quick valley]

Why not forget the black part bc its their intersection and just proof with the green ones

[scarlet drum]

Prove the triangles that form the green are congruent?

[quick valley]

I don't have an idea yet lol but im just saying if we can proof the green angles are equal we're done

[scarlet drum]

That may help

[quick valley]

So the yellow angels r equal?

What else do we have

[scarlet drum]

And right angles

And those middlepoints

[west girder]

This is not true

[scarlet drum]

Thats the question mate.

[west girder]

Are the yellow angles given to be congruent?

[scarlet drum]

It says that M is the middle of arch AC

So M is the bisector

Of AOC

OM i mean

[west girder]

Oh I misread I thought N was the middle of arc BC

[scarlet drum]

No worries.

It took me 20 mins to do the drawing

Very hard to understand

[west girder]

Let me take a look

[quick valley]

R these equal

The white

[scarlet drum]

Not sure.

[west girder]

It suffices to show NOM=BOC

the angles

And we can find those

<BOC=180-(<CBO+<BCO)

And

<MON=360-(<AOB+2<AOM)

You can rewrite all angles in terms of A,B, and C

[west girder]

This is because <BON=<AOM due to MN being parallel to AB

[scarlet drum]

Let me see.

[scarlet drum]

Dont really understand this part

I totally agree with the rest

To be exact, the 2*AOM part

[lone heart]

@scarlet drum Has your question been resolved?

[scarlet drum]

Im the only one doing geometry on Christmas day lol

[west girder]

Follows from this

[scarlet drum]

Thats amazing.

Thank you!

Alright. Now what next?

[west girder]

Try to rewrite all the angles I mentioned with A,B,C

[scarlet drum]

You mean in terms of A, B and C?

Or like rename them to A B and C

[west girder]

Yeah

[scarlet drum]

BOC is 180 - B - C

Let me think about MON...

Cant figure it out

BOC is equal to A right

I tried to use that information

Got stuck again.

[lone heart]

@scarlet drum Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh forge]

System of Equations
$e^x \cos y=0$ and $-e^x \sin y =0$

[ocean seal]

Professional Procrastinator

[marsh forge]

I know there is no real solution because cos and sin can’t be zero at the same time, but why doesn’t this work:

$e^x(\cos y -\sin y)=0$
\
Adding them
$e^x \neq 0, so \cos y= \sin y$

[ocean seal]

Professional Procrastinator

[wide tartan]

well, it’s just an example of a one-way implication that doesn’t go back the other way, once you know cos(y) = sin(y) , you can just check the values of y for which this is true and realize that none of these yield any solutions to the original equation

[marsh forge]

Ok

.close

[lone heart]

Channel closed

Closed by @marsh forge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vagrant agate]

how do i do b?

[gray isle]

deteremin the distance between the centre and P

(using the distance formula)

[lone heart]

@vagrant agate Has your question been resolved?

[vagrant agate]

oh so if it isnt the radius it isnt on the circle?

[gray isle]

yeh

[vale wigeon]

if you know the definition of a circle (NOT only the general form of its equation) then this should be clear as day

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[near hound]

@vagrant agate you can satisfied the co ordinate with the equation of circle, you can find the equation of circle by radius and centre.😀 and if this point satisfied then it is on point and if the not satisfied then it is not lies on the circle.
🪵 I know it is not according to question but you can also check it by this🪵

[lone heart]

@near hound Has your question been resolved?

Channel closed

Closed by @near hound

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

What would the contrapositive of this statement be?

"If Sup(A) and Inf(A) exist ∀A⊆N, then (N,≤) is complete"

[alpine sable]

Mainly confused on the "∀A⊆N" part; does it become "∃A !⊆ N"?

[limpid turret]

$\neg(\forall x(P(x)))=\exists x(\neg P(x))$

[ocean seal]

SWR

[alpine sable]

I'm trying to prove that (N,≤) is complete. So I stated that the contrapositive of the definition of completeness is "If (N,≤) is not complete, then ∃A ⊆ N s.t. Sup(A) or Inf(A) D.N.E." (which is easy to prove).

[limpid turret]

$A\subseteq N\leftrightarrow \forall x(x\in A \rightarrow x\in N)$

[ocean seal]

SWR

[sour verge]

Since you're negating the "or", wouldn't it become an "and" here?

[alpine sable]

Whoops, that was a typo.

[sour verge]

If so then I think your contrapositive is alright.

[limpid turret]

It is not

[limpid turret]

This is still incorrect

[sour verge]

Yeah but what they stated here is correct isn't it?

[limpid turret]

Ehhhh I guess it's correct? It's written weird

[alpine sable]

What do you mean?

[limpid turret]

Not used to that notation

For "not a subset"

$\nsubseteq$

[ocean seal]

SWR

[alpine sable]

^That is what I mean by !⊆

[limpid turret]

Yeah I figured that out

Then yeah it's correct

[alpine sable]

Can you explain why the subset does not get "negated" but the supremum and infimum do?

I would have guess that "Sup(A) and Inf(A) exist ∀A⊆N" becomes "Sup(A) and Inf(A) D.N.E. ∃A !⊆ N"

[strange meadow]

when all hell breaks loose start drawing truth tables 😭

[sour verge]

The statement is basically "if this holds for all such A, then N is complete". If you take the contrapositive, it means that "if N isn't complete, then it must not be that case that it holds for all A subset of N (i.e. it doesn't hold for some A)"

So A is still a subset of N regardless, because the original statement said nothing about sets that aren't subsets of N

[limpid turret]

$\forall (A\subseteq N)((N,\le)$ is complete$)$ is shorthand for $\forall A(A\subseteq N\to (N,\le)$ is complete$)$. Do you know how to negate logical implication?

[ocean seal]

SWR

[alpine sable]

OH

Hang on I suck at latex

$\exists A(A \subseteq N \wedge \neg((N,\le)$ is complete)$)$

[ocean seal]

gian

[alpine sable]

There we go

Okay so thats why A⊆N does not become A!⊆N

[limpid turret]

Exactly correct

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

Okay just to double check that I understand:

Let $A \subseteq \mathbb{N}$.

$p \coloneqq$ "Sup(A) and Inf(A) exist"

$q \coloneqq$ "$(\mathbb{N},\le)$ is complete."

I'm trying to show that $\forall A (p) \to q$ is true. I can instead show that the contrapositive is true, which is:

$\neg q \to \exists A (\neg p)$

[ocean seal]

gian

[alpine sable]

So like Azyrashacorki mentioned, A is a subset of N regardless, and what I'm trying to prove has nothing to do with A being a subset of N

[harsh swallow]

wouldn't it be p(A)?

[alpine sable]

What does p(A) mean?

I don't know formal logic very well

[harsh swallow]

$[\forall A p(A)] \Rightarrow q$

[ocean seal]

Katharine

[harsh swallow]

it should be the entire thing implies q

so if the statement in [] is true

that implies q

is what you're trying to prove

right?

[alpine sable]

Yes

I forgot to include the larger brackets

I don't know correct notation I'm learning as I go

[harsh swallow]

although maybe the (A) isn't even necessary

all the notation is for clarity

if your notation makes it clear

it's fine

most of the time standard notation is the clearest

and so you use that

such as the forall sign

and the there exists

and not

etc

any

anyway

$(\forall A, p) \Rightarrow q$

[ocean seal]

Katharine

[harsh swallow]

maybe not that

that looks confusing

lol

[alpine sable]

Lol

Anyways thanks that clears it up

[harsh swallow]

maybe this

$(\forall A | p) \Rightarrow q$

[ocean seal]

Katharine

[harsh swallow]

possibly

whatever yours is fine

😄

the contrapositive is much clearer

[lone heart]

@alpine sable Has your question been resolved?

Channel closed

Closed by @wary mauve

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Use the subspace test to deternine if the set of all functions f in $F(-\infty, \infty)$ where $f(0) = 1$ is a subspace of $F(-\infty, \infty)$

[ocean seal]

Derivative

[alpine sable]

so first we check if the set is non empty

and it is not empty so thats good

then we check axiom 1

$(f+g)(0) = f(0) + g(0) = 1+1 = 2$

[ocean seal]

Derivative

[alpine sable]

this should be equal to 1

so it fails

it fails because any f(0) = 1 so also (f+g)(0) must equal 1, but it does not

so it is not a subspace

is this good?

[unkempt mica]

yes

[alpine sable]

thanks!

another question i have

for All functions f in from neg infinity to pos infinity for which f(-x) = f(x)

how do i go about this

i was thinking of creating two functions f and g

and then doing f(x) - f(-x) = g(x) -g(-x)

where i get

f(x) + g(-x) = g(x) + f(-x)

since f(-x) = f(x) then

f(x) + g(x) = f(x) + g(x)

so it is closed under addition

[unkempt mica]

wouldnt you want to show that (f+g)(-x) = (f+g)(x) ?

[alpine sable]

ah i see

i also did that on my paper i did it both ways didnt know which one is valid

ig the latter is the right way

[unkempt mica]

im just not sure of what you are doing

[alpine sable]

so (f+g)(-x) = f(-x) + g(-x) = f(x) + g(x)

[unkempt mica]

yesd

[alpine sable]

closed under addition

[unkempt mica]

yes

[alpine sable]

now for axiom 6

(cf)x = cf(x) = cf(-x)

closed under scalar multiplication. therefore it is a subspace

[unkempt mica]

yes

[alpine sable]

one more question

show that f is a subscape of C[0,1] where f(0) = f(1)

so first, it is nonempty, obviously

next, let f and g be functions. then: (f+g)(0) = f(0) + g(0) = f(1) + g(1) = (f+g)(1). Closed under addition

next, for scalar multiplication (axiom 6): (kf)(0) = kf(0) = kf(1) = (kf)(0). Closed under scalar multiplication. Therefore it is a subspace

[unkempt mica]

seems good to me

[alpine sable]

ok thank you so much for your help

greatly appreciated

have a good one!

.close

[lone heart]

Channel closed

Closed by @quick dew

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade fox]

How would you work this out by rewriting this linear FODE?

considering that rate of change of price is p'(t)

[amber nymph]

p'(t) = 3*Excess of demand over supply

[jade fox]

The solution gives an example using a seperable FODE but I'm trying to work it out using the linear way

[amber nymph]

What's FODE

[jade fox]

first order differential equation

These are the steps I was given

[amber nymph]

Ohh

[amber nymph]

Integrating factor equations

Okay

Think how can you mathematically write excess of demand over supply

[jade fox]

Here’s what I have so far

[jade fox]

qD(p) - qS(p)

Substituted everything into the method given but something seems off

[amber nymph]

Use the fact that p(0)=p(0)

Weird, the initial condition should be p_0

[amber nymph]

Using this, eliminate C

[jade fox]

Let me try

[jade fox]

p(0) = p(0)?

[amber nymph]

, w y'(x) = 3*((10-2y)/3-2y+6)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ericsson6890

[amber nymph]

Yeah for some reason that's p(0)

p(0)=C+7/2
C=7/2-p(0)

$p(t) = [\dfrac{7}{2} - p(0)] e^{-8t}+\dfrac{7}{2}$

[ocean seal]

Ericsson

[amber nymph]

https://cdn.discordapp.com/emojis/711477832123154443.png?v=1&size=256&quality=lossless

I forgot how to use delimiters

[amber nymph]

Nvm, this should be what you will get

[jade fox]

I see

[jade fox]

Yeah it is more straightforward if I did it using the other way

[amber nymph]

Yup

Ohh wait my value of C is the other way around

It should be p(0)-7/2

[jade fox]

Thanks tho

was just trying to see if the other way works too

.close

[lone heart]

Channel closed

Closed by @jade fox

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thin sinew]

help

[thin sinew]

i need help with this

[vale wigeon]

image incoming?

[thin sinew]

yup

im so lost

[fallen verge]

Hi garlic

[thin sinew]

Hello garlic

[fallen verge]

First, how many petals does it have?

[thin sinew]

what u see is all i know

[fallen verge]

Its a cos(n*theta) function with an even n, do you remember how many petals you would have?

[thin sinew]

its 4 correct?

[fallen verge]

Yup

[lone heart]

@thin sinew Has your question been resolved?

Channel closed

Closed by @thin sinew

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gray isle]

!status

[lone heart]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[fading kestrel]

5

[gray isle]

show it

and state your issues with what they have

[vale wigeon]

^

[fading kestrel]

https://youtube.com/clip/Ugkx0lT4EDH6lMULKHa2zAEJ017lxQ60w_H0?feature=shared

why did he divide x^3/x+1 ?

and I cannot comprehend how he wrote it afterwards

this

[gray isle]

they divided / did long division since the degree of the numerator was greater than the denominator
looking at the result of division,
you'll have a polynomial and a rational function with a constant numerator which have established rules for easy integration

[vale wigeon]

do you know polynomial long division? @fading kestrel

[fading kestrel]

yeah

[vale wigeon]

that is what the guy did

[fading kestrel]

i understand we simplied for the ease of integration

but

i cant make out how we

reached here

[gray isle]

polynomial long division

[fading kestrel]

the first expression is the quotient

one sec

gimme a min

no i still dont get it

look

[fading kestrel]

i wanna how we reached here

just that

[gray isle]

can you do the long division for this

[vale wigeon]

quotient + (remainder)/(original denom)

it is kind of like converting an improper fraction into a mixed number

like 29/7 = 4 + 1/7

same kind of deal

[fading kestrel]

but ain't it written without the +

?

[gray isle]

that's what the notation represents

$4\frac17$ represents $4 + \frac 17$

[ocean seal]

ℝαμΩℕωⅤ

[gray isle]

but that mixed fraction notation isn't applicable when variables are invovled

(its also pretty crap by many peoples opinion)

[fading kestrel]

all my life nobody told me that

[fading kestrel]

so you mean i gotta write the + when i got variables?

[gray isle]

yes.

otherwise products are implied

[fading kestrel]

fuck

[fading kestrel]

you lost me

my doubt has been cleared

tis frustrating

[gray isle]

with numbers:
$$4\frac17 = 4 + \frac17$$
with variables or a mix of numbers and variables
$$a\frac bc = \frac {ab}{c}$$
$$a \frac 2d = \frac{2a}{d}$

[fading kestrel]

why did it dissapear

[ocean seal]

ℝαμΩℕωⅤ
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[fading kestrel]

what

you said + in variables

[gray isle]

yes. i said a + would be needed to represent a sum

[fading kestrel]

like this

[gray isle]

without the +, that's what writing stuff like that would represent

[fading kestrel]

hmm

i get it

[gray isle]

to make it clear, if you want to represent
$$a + \frac bc$$
you'd have to write stuff like
$$a + \frac bc$$
as $a \frac bc = \frac{ab}{c}$

[ocean seal]

ℝαμΩℕωⅤ

[fading kestrel]

man i thought that $a \frac bc$ was equal to $\frac{ca+b}{c}$

[ocean seal]

neo

[fading kestrel]

for example

17/3

sorry

for example

[gray isle]

$\frac{ac + b}{c}$ is what you'd get if you combined $a + \frac bc$ into a single fraction

[ocean seal]

ℝαμΩℕωⅤ

[fading kestrel]

okay

oh shitttt

i am having an aha moment

its so clear now

[gray isle]

it all comes down to when variables are present
$$a \frac bc = a \times \frac bc \redneq a + \frac bc$$

[fading kestrel]

fuck

[ocean seal]

ℝαμΩℕωⅤ

[fading kestrel]

wow

you are wow

thank you so so much

[gray isle]

the notation is crap btw, and if you intend multiplication, you should explicitly write the multiplication there anyway

[fading kestrel]

like a doubt from years ago got cleared today

thank you very much man @gray isle

and thanku @vale wigeon

.close

[lone heart]

Channel closed

Closed by @fading kestrel

Use .reopen if this was a mistake.