#help-0
1 messages · Page 382 of 1
you do understand the sum sign correct?
it has a starting whole number value represented by a variable on the bottom (k = 1) and a value which the variable approaches in increments of 1 on the top (3)
for every step it plugs the value, starting at k = 1, into the equation and adds the answers together
You mean put in k³(k²-1)
here you would calculate k^3((k^2) - 1) for k = 1, k = 2, k = 3 and add those together
,rotate
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
State the definitions of arithmetic progressions and geometric progressions, and provide a couple of examples of each. Then, ask yourself if you took 3 elements in order from each of those progressions, is there a consistent, reasonable way to relate them? If so, is it an answer? If not, your answer is d.
There are ways to relate the means but not progressions
It seems you have your answer.
Is there a missing word? It say arithmetic mean of 4, and ... mean of 9?
number 47 doesn't involve the means.
Originally, we were. Instead of closing the channel and opening another one, they elected to ask a follow up for another item on the page.
Why do I feel like both (a) and (b) are valid solutions for 47?
@smoky condor Has your question been resolved?
The relationship between $p$, $q$, and $r$ is based on some initial value $s$ and some common ratio $t$. We could say that $p=st^n$, $r=st^{n+1}$, and $q=st^{n+2}$. Then, $pr = st^nst^{n+1} = s^2n^{2n+1}$ and $q^2 = s^2t^{2(n+2)}$. Since $pr\not=q^2$, I would rule out both a) and b) on the grounds that $a-b = b-c$.
Shenzao
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Can someone help me with the proof on why this is or isn't a vectorial subspace
Did you check the definition of subspace
@untold lake Has your question been resolved?
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I don’t really understand how X is a map (function) and a variable
roughly speaking a random variable is an assignment of a real number to each point in Ω
which is exactly what a function is
@lost dirge Has your question been resolved?
injective? with the natural numbers?
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is nulity of a matrix dimension of its kernel?
yes
nullity and kernel are identical, just different words for the same thing.
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✅
but how come be nunlity equal to dimKerA and kerA at the same time?
nullity is the dimension, nullspace is another name for kernel
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Hi
The solution seems not to be right
It should be this but idk how to reach this solution
I do not see any mistakes
I controlled everything. I just looked 15-20min on it
Take out a factor of e^(-2x)
What happens with 32
Well you can write (32=32\cd e^{-2x}e^{2x})
Lol my flights gonna take off good luck
There we go
Pure
Pure
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!15m
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
rise = change in y
run = change in x
slope = rise/run
Are you supposed to be doing it individually?
Like, without help from other people
Alright
Helpers are just people volunteering their time to help you. Be polite and patient.
damn bro is toxic
what made no sense about this?
the "rise" is how much you 'rise' vertically. it's how much you go up. It's the change in the y-value, from lowest to highest
the "run" is how much you 'run' horizontally. It's how much you go left to right. It's the change in the x-value
The slope of a line you can think of as the rise divided by the run. Rise/Run
change in y / change in x
!noans
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
it looks like the question is just asking y = mx+b, so being told rise/run was actually helpful. m = (y2-y1)/(x2-x1), where y2 and x2 are "later" x/y values, and y1/x1 are "earlier". In general the easiest way to do this is using the intercepts.
the +b of y=mx+b is just the y-int, which is just th value of y when x = 0
People have been helping you for over 15 minutes
you just expect to be handed the answer
that's not how it works
should’ve asked earlier than 8mins to the deadline…
you should not be so rude to people in the future especially people who are trying to help you. if u listened and tried to learn, you would've gotten this question right. Instead you were calling people idiots and laughing at them, which only ended up with you failing
Then why not solve it yourself?
we do not tolerate academic dishonesty
It wasn't that simple after all
You said it was test corrections, the moderator, was making sure you weren't cheating
<@&268886789983436800>
to help you learn
Then please read #❓how-to-get-help to understand how the server works
!noans is literally rules lol
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
It's called being entitled and rude
Yikes
you're doing very early year math, this is stuff you need to know if u ever want to do math. The purpose of this server is to help people understand so they can apply what they learn in tests. You're new to this server tho so maybe u missed it.
Found this
Yikes
What a great attitude to have
.close
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sarcasm isn't being rude, especially since you don't know anyone. It's one thing to do it with friends but it's weird with strangers
Nami did the bani
Unfortunately I don't even think they were trolling 😭
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Question: Each of the following graphs can be generated by stretching or compressing the graph of y=logx. Write an equation to correctly the describe the graph.
Answer: y=log(2x)
Why is this the case
The answer can't be log(2x)
The images show that the functions are zero at 1 and 2 respectively
While log(2x) is zero at x=1/2
for reference
They tried
they only considered transforming (10,1) but forgot about the (1,0) point lol
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?
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if $x_n$ converges then $\frac{x_n}{n}$ also converges
skischooldropout
so my initial thoughts are yes this should converge its just been a while since I have done proof based math and I am definitely struggling more than I think I should be on this problem. So I guess there would be two key cases. First where x_n grows faster than n at which point does it converge to a or when n grows faster than x_n/n at which point does it converge to 0
You may want to notice that $\frac{x_n}n = x_n\cdot \frac1n$
@pseudo ice
so this to me then wants me to say yes and my intial thoughts are to use this with the eplisons to try and make everything "equal"
so I think |x_n - a| > |x_n * 1/n - a|
Are you using $a = \lim_{n\to\infty} x_n$ right?
@pseudo ice
correct as an aside I would also have to consider $a = \lim_{n\to-\infty} x_n$?
skischooldropout
And what are you allowed to use? Can you e.g. use properties of convergent sequences or anything?
yep anything this is just self-study
Cool, you may want to think about properties of convergent sequences maybe 
Hopefully me writing it in this form should help you find something that might be useful!
I appreciate it!
You could use that too, but there should be a theorem somewhere that talks about you having convergent sequences and what you can do with them
ok ok Ill go back and look!
Yep, take a look through what you have, you should hopefully find something useful!
No problem
do let me know if you manage to cook something with those
(or not
)
@grand gulch Has your question been resolved?
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For limits of two variables
U can always prove it doesn’t exist via plugging in polar cords right
Like if there’s a trig function in it and no r then like it doesn’t exist bc the theta could change so the limit changes
@uneven rivet Has your question been resolved?
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let u=2+ln(x)
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could someone help me solve this?
i have to use the work energy theorem and this equation
@subtle blade Has your question been resolved?
@subtle blade Has your question been resolved?
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How do I factor x⁴-16? I've just started learning factoring perfect cubes and we weren't taught how to do anything above x³ yet💀. I don't want to use youtube since my teachers have a different method of teaching and that might screw me up, thanks.
you can treat x⁴ as (x²)²
do the ² twice
Do you know about difference of squares?
^^
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How do I do this?
Guys don't kick me out but I am a 5th grader who wants and desires to learn math. My hardest is pre-algebra and no one in my class knows how to do it. I am on winter break and am able for a few methods and practices to improve my algebra (not pre-algebra). Thank you.
You're not going to be kicked out. Open your own help channel though.
@vocal jewel Has your question been resolved?
@vocal jewel Has your question been resolved?
@vocal jewel Hi there, I think the missing statement is likely something about congruent triangles and the fact that you know SSS congruency
it's one of these
These are all X, Y, Z, but the original question you posted had ABCD
@vocal jewel Has your question been resolved?
when I click on the box that's what shows up
im assuming it's because it's a delta math
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what is 1+1
Please do not troll in help channels.
.close
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10c2 is for selecting any two x and y from set 3k but why didnt they do it 3 times as from the set of 3k+1 the difference is also multiple of 3 same thing for 3k +2
the square of a number of the form 3k+2 leaves 1 remainder when divided by 3
because (3k + 2)^2 = 9k^2 + 12k + 4 = 3(3k^2 + 4k + 1) + 1
so x^2 - y^2 will be divisible by 3 if:
both x and y are divisible by 3 or
both x and y are not divisible by 3
i might have jumped too much there, does it make sense?
its a bit confusing

3k+2 squared leaves a remainder so lets say its the x number
Then the y would also leave a remainder 1
what's y?
a 3k +1 form too?
like one number i chose is 3k_1 + 1 and other 3k_2 + 1
if x is of the form 3k + 1 and y is of the form 3m + 2, then yes, x^2 - y^2 will be divisible by 3
how is it being excluded 
Oh
there are 10c2 ways to pick x and y both divisible by 3, and 20c2 ways to pick x and y both not divisible by 3
it's included in the 20c2
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Can somebody please explain this passage?
@cinder breach Has your question been resolved?
(N+1)n!=n n!+n!
This is just distrubtion of the brackets
How do we come up with this?
Write the denominator in the same way as in the picture
What terms do you get extra?
Do i do the distribution of the brackets for the denominator as well?
Ok but why's that
How do you get there from k!(n+1-k)!?
Hint: smth like this
Yes?
You are writing it as if you have the solution already
and n+1-1-k turns into n-k
This is what the first fraction is right?
Yes
Ignore the top part for now
Only look at the denominator
<@&268886789983436800>
We have the first part already
K!(n+1-k)!=k!(n-k)!(n+1-k)
Now we want the second part
k!(n+1-k)!=.......=something*(k-1)!(n+1-k)!
Ignore the derivation
Right now
We are trying stuff out
To see if we can spot any pattern
We have no clue where alwe are going yet
So trying to write down the whole derivation is futile
we need to go to something with $k!(n-k)!$ and $(k-1)!(n+1-k)!$ in the denominator
Flappie
and they both need to come from $k!(n+1-k)!$
Flappie
we have already found how we got to the first one
$k!(n+1-k)!=k!(n+1-k)(n+1-k-1)!=k!(n-k)!*(n+1-k)$
Flappie
so now we want to go to the second one
$k!(n+1-k)!=??????=(k-1)!(n+1-k)!*\mathbf{stuff}$
Flappie
1 / (k-1)! ?
how do we go from $k!$ to $(k-1)!$?
Flappie
Divide by k
Flappie
so if we look here
stuff=k
right?
so we have
$\k!(n+1-k)!=k!(n-k)!*(n+1-k)\k!(n+1-k)!=(k-1)!(n+1-k)!*k$
Flappie
you see this part?
Yes
I don't understand
Flappie
n+1-k?
K
exactly
so only now we go back to our question
$\frac{(n+1)n!}{k!(n+1-k)!}=\frac{n*n!}{k!(n+1-k)!}+\frac{n!}{k!(n+1-k)!}$
Flappie
which fraction do you think becomes the k one and which the n+1-k one
(try stuff out)
We need to simplify n right?
I am
$\frac{n!}{k!(n+1-k)!}=\frac{n!}{k!(n-k)!(n+1-k)}$ and $\\frac{n\cdot n!}{k!(n+1-k)!}=\frac{n\cdot n!}{k(k-1)!(n+1-k)!}$
Flappie
$\frac{n!}{k!(n-k)!(n+1-k)}+\frac{n\cdot n!}{k(k-1)!(n+1-k)!}$
Flappie
okay well honestly
im not sure where this is going either
im just trying stuff out aswell
I am crying
${a \choose b}=\frac{a!}{b!(a-b)!}$
Flappie
aha
Btw thank you very much
And thanks for all your patience
And sorry if i am slow 😭
i want to find the solution aswell :)
i know i did it somewhere a few years ago
so its actually good practice for me aswell
Still that passage the professor wrote makes no sense
That where you split the fractions
Thanks very much
See ya
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goodbye
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i'm stuck on the inverse part here..
i know that the graph of inverse of f(x) is symmetric abt y=x..so the area on the y axis by f(x) will be same a the area on x axis by inverese..
<@&286206848099549185>
@nova barn Has your question been resolved?
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@alpine sable Has your question been resolved?
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yoo
@molten tusk Has your question been resolved?
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im pretty sure the right hand side should be in denominator
but anyways leme write the solution and explain, 1 min please
yes
$\frac{1}{(sec(x) - tan(x))^2}$ \
$\frac{1}{sec^2(x) + tan^x(x) - 2sec(x)tan(x)}$ \
$\frac{1}{sec^2(x) + sec^2(x) - 1 - 2sec(x)tan(x)}$ \
$\frac{1}{2sec^2(x) - 1 - 2sec(x)tan(x)}$ \
killersnake
this is what i get in end
idk if its related to the top

the original image u sent didnt include it lol
yea
which one you want to solve
use the result in b)
c is literally b but squared
so i juz square this?
the integrand is (1+sin x)/(1-sin x)
now sub sin(x)=t and it will be a rational function in t
what even is integrand-
if you prove (b) then its much easier than what i wrote
i proved b but no idea how to do c
just square
square secx+tanx?
oh
if you prooved (b), then just square both sides
but in exam, you will need to write steps to proove (b) before squaring
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Let T be the set of subtrees of a tree T. Prove that if the intersection of any two T1, T2 ∈ T is not empty, then the intersection of all (T in T) is also not empty.
@fallow wadi Has your question been resolved?
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Hello
I know how to do everything
But I dont understand the markscheme for B
I did a different way, but I cant understand this ^
Wait nvm I understand
they are calculating the area of y=x^2+1 from 0 to 2 and then simply the area of the triangle
the area under the parabola
Yeah I understood that ^
New question
How would you calculate the blue area
(4,10) is the coords of the corner
I would assume, you make a y = mx+c formula for the 4,10
And it would be y=x +6?
wait, why do you draw that tall rectangle?
Bc I want to find the area of it
aha
I would, make 2,5 a y=mx+c
So y= x + 3 ?
well, area of a triangle is area*width?
?
oh, you dont want from the line?
okay
If i wanted the area of the pink
I would start off with making a y = mx+c of that top blue line
So then
y= x+ 3 and x^2 +1
[x+3 -x^2 -1] dx from 0 -->2
Would that give me that pink area?
the verticle blue line would be x=2
oh
because a function requires you to have only one y value for each x
a parabola rotated to the right would not be a valid function
what are you going to use the vertical line for?
it was more of a question formyself
alright
to make sure I remember stuff hehe
:)
take your time
alright got it then
Im going to take a break now
Ty flappie

once again
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no problem
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If the curve of a continuous function on its domain has one point of inflection, then the greatest number of points at which the function curve intersects with any straight line is equal to.......
at least one or exactly one?
No exactly one
imagine any straight line
and a continuous curve
how would they intersect twice?
sketch it
It's only 1 point
In the question it literally says the curve has one inflection point
yes i am aware
How are those inflection points?
i just want to show you that for a curve to intersect a line twice, there must exist at least two points of inflection
Here is a sketch of a line that intersects twice with a curve with no inflection points
wait hold up
nvm i am wrong
but like
this is a purely visual question
the answer is 2 btw
Yup
$y'' = 0$ has 1 solution\
$y = 0$ has $n$ solutions\
solve for $n$
artemetra
3
The question really doesn't make sense for me
I don't even understand it
Oh hell yeah
I got it
oh i got it
oh
lol
now idk why i was thinking only 2
a lot of cubics satisfy this
Crazy
if you are done, write ".close"
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Apply gradient descent to MSE:
Come up with at least 3 training examples
Take at least 2 weights
Work out at least one step completely
Also, observe the effect on the cost
right picture is my solution, yet is seems to be wrong. This is the feedback i got^^ i dont understand what i did wrong
Hi! I had a question regarding the curves for this question. Why is the Area in the middle not considered??
ooooh i think i might understand, the 1.667 i calculated should be applied to the weights and then recalculate the MSE, till we reach 0 or as close as possible
wrong channel buddy
Ok
@pure depot would you mind deleting the messages
i dont fully understand the mse formula given by my school, when i google it looks so much different. Could anyone explain how the MSE formula i sent works the same
<@&286206848099549185>
sorry but what is mse 😶
Mean squared error
it's a way to calculate the error of an a.i models prediction
in order to tweak it's weights
oh
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<@&286206848099549185>
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does this logic make sense?
does it hold
@uncut escarp Has your question been resolved?
not really
<@&286206848099549185> could you check the logic, give some input and then close this, i gotta go
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is this working out correct?
Please don't occupy multiple help channels.
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I am about to take a college placer test that I failed earlier and I really need help studying arithmetic
I am struggling with the fractions and percentages
I barely failed last time and I fo ant take the test again in 40 minutes if anyone just has some quick advice I really need it
I am about to leave ANYTHING will help
I really need simple formulas for solving percentages and turning fractions into decimals and decimals into fractions (without a calculator.)
Its asking quesitons about computing in my head which I am not very good at
<@&286206848099549185>
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@forest hinge Has your question been resolved?
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Can you pls give some hints for these? f^3 means f(f(f(x)))
what does it mean for f^(3) to be surjective
for all y in A, there exists x in A such that f3(x) = y
and what is f^(3)(x)
f(f(f(x)))? sorry what do you mean?
yeah
that's the key
for all y in A, there exists an x in A, such that f^(3)(x) = y
for all x in A such that f^(3)(x) exists, there exists a z in A such that f^(2)(z)=...
and son on
ohhh okay i think its starting to make sense, let me process that a little first

by this, is this f(f(f(x))) = f(f(z)) what you meant?
sure
so i've written down what I assumed, but am i using the wrong idea? the definition for the 3 lines above were functions
your first line is already sus
for all x, there exists y1 such that f(x)=y1 ?
what if x is not in A?
what if x is an elephant?
and then moving to the second line
sure, for all x in A there exsists y1 such that f(x)=y1
but now the same problem
why must y1 be in A?
you have to start with what you are given about f^(3)(x) being surjective
and work backward from there
instead of forwards as you are
okay thanks, let me go back to your comments earlier to try and work backwards
is this more along the right line?
okay the first line is better
the second line doesn't make much sense
it should read more like
f(f(f(x))) is a specific output of f^(2)(x)
so for all f(f(f(x)) there is a value in the domain of f^(2)(x) that takes on it
it isn't clear to me how to state that neatly
but I don't think that's what you quite have in line 2
looks good at a brief glance
is this a bit more clear now? not full write-up, but does the idea make sense?
no problem
appreciate it lots
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@foggy pecan
i got d = 20
bru
@foggy pecan what did i do wrong
- i differentiated the equation and made them equal to 0
cuz i wanna find the stationry point which is the turning point
and then we also know that the the turning point is at 1, 3 at x
so idk what i did wrong
@foggy pecan can u see this?
i am here
a = -6, b = 9 and c = -2, you confirm them ?
yes
so
now use them in your given function cube polynomila
and finally
x = 3, and y = d
so 27 - 54 + 9 + -2 = d
how do i reduce my sily mistakes
i acc do this a lot recently
do u know any tips
you must write slower, and be precise, feel such precision, whenyouwrite soemthign try to veirfy each line you wrote
at beginnigns it makes process slower, but later, it wibe automatic
yw )
r u in uni?
yes i am
yes, that is my Baby, ) but virtual one :))
oh ooppsssss i thought it was real life
mb
anyways
smiles
yw)
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Jones is chasing a car 800 meters ahead of him. He is on a horse moving at 50 km/h. IfJones catches up to the car in 4 minutes, how fast was the car moving?
@faint monolith Has your question been resolved?
idk
how do u do it
can u show me
ok
Jones catches up in 4 minutes. How far did Jones travel
10/3 minutes
yeah
Good
Then we'll use it to derive a method to solve such qns
Let the speed of the car be x km/h
yes
How far did the car travel before it was caught up by Jones (not including the 800m at the beginning)
idk it. doesnt give any information about the car
Use x
oh
So?
We worked out the time taken for Jones to catch up
That's the same amount of time that the car moved
So let's first express 10/3 min in hours
1/18 huors
x/18
Oh shoot
I'm sorry
Earlier I thought u were correct but u were wrong
It's 10/3 km
wait im getting confused
can u write everything we've done up to here
like summary
ok
Earlier u said 10/3 mins right?
wait the time they travel is the same right?
Ya
so we just get the distance and spped of both a set them equal?
But I asked for distance
yeah
Not really
So it's actually 10/3 km
Get it?
yes
Ok
The car is ahead of him
Ye
We have the time
10/3 / 50 = 38/15 / x
yeah
thanks
i just needed help with the first part
my brain blanked out
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Wait
✅
I'll teach u an easier method
what is it?
Basically take distance over time straight away
0.8/(1/15)
12
Then that's the speed difference
So the car's speed is 50-12=38 km/h
But that's only for catchup type of qns
If its opposite direction
That's a different story
yeah
Okie?
opposite direction is adding the distances = the total distance
Yep
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how do i rearrange to solve for x
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guys how do you evaluate 29219+73924?
By the calculator
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Hi
I'm struggling to find out how to add a solution to a problem on AoPS (Art of Problem Solving)
can someone who knows tell me how
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@faint monolith Has your question been resolved?
@faint monolith Has your question been resolved?
what solution are you trying to add and where (aops wiki or aops contest collection)? well you could ask this on site support forum on aops anyway.
@faint monolith Has your question been resolved?
AMC 8 contest solutions
can you give the link to that problem?
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How does one solve it?
the first step is to write this in a less chicken scratch way
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Help me please
is this the whole problem as it was given to you?
perhaps any mention of x being an integer?
well I tried a bit and I'm out of ideas on how to solve "properly"
luckily it's quite easy to guess an integer solution
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Hey
Would the equation for A be
T-4g = 4x -g/4
Obviously assuming g is 9.8
Times
ohhhh
Like 4 times -g/4
Wouldn’t it be -g/4
Cos it’s descending
No it’s rising
Cos Q is descending
Or would it be 4g/4 @prime glacier
nah
it's positive
we take it as positive
because the net force is acting upwards
and that's where it's accelerating
if i'm wrong correct me
but i'm 100% sure it's +g and not -g
Yeah ur right



tyty