#help-0

1 messages · Page 382 of 1

haughty sun
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can you please show your work ?

uncut escarp
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you do understand the sum sign correct?

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it has a starting whole number value represented by a variable on the bottom (k = 1) and a value which the variable approaches in increments of 1 on the top (3)

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for every step it plugs the value, starting at k = 1, into the equation and adds the answers together

smoky condor
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You mean put in k³(k²-1)

uncut escarp
#

here you would calculate k^3((k^2) - 1) for k = 1, k = 2, k = 3 and add those together

smoky condor
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Thanks

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The 47th

warm copper
#

,rotate

ocean sealBOT
warm copper
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
smoky condor
#

1

warm copper
#

State the definitions of arithmetic progressions and geometric progressions, and provide a couple of examples of each. Then, ask yourself if you took 3 elements in order from each of those progressions, is there a consistent, reasonable way to relate them? If so, is it an answer? If not, your answer is d.

smoky condor
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There are ways to relate the means but not progressions

warm copper
#

It seems you have your answer.

last walrus
#

Is there a missing word? It say arithmetic mean of 4, and ... mean of 9?

warm copper
#

number 47 doesn't involve the means.

last walrus
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Oh I thought we were asked to look at 45

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my bad

warm copper
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Originally, we were. Instead of closing the channel and opening another one, they elected to ask a follow up for another item on the page.

last walrus
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Why do I feel like both (a) and (b) are valid solutions for 47?

lone heartBOT
#

@smoky condor Has your question been resolved?

warm copper
#

The relationship between $p$, $q$, and $r$ is based on some initial value $s$ and some common ratio $t$. We could say that $p=st^n$, $r=st^{n+1}$, and $q=st^{n+2}$. Then, $pr = st^nst^{n+1} = s^2n^{2n+1}$ and $q^2 = s^2t^{2(n+2)}$. Since $pr\not=q^2$, I would rule out both a) and b) on the grounds that $a-b = b-c$.

ocean sealBOT
#

Shenzao

lone heartBOT
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untold lake
#

Can someone help me with the proof on why this is or isn't a vectorial subspace

tacit arch
lone heartBOT
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@untold lake Has your question been resolved?

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lost dirge
lone heartBOT
lost dirge
#

I don’t really understand how X is a map (function) and a variable

vale wigeon
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roughly speaking a random variable is an assignment of a real number to each point in Ω

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which is exactly what a function is

lone heartBOT
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@lost dirge Has your question been resolved?

lost dirge
#

injective? with the natural numbers?

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prime seal
#

is nulity of a matrix dimension of its kernel?

alpine sable
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yes

hot bluff
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nullity and kernel are identical, just different words for the same thing.

prime seal
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ah alright thx

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prime seal
#

.reopen

lone heartBOT
#

prime seal
ocean hawk
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nullity is the dimension, nullspace is another name for kernel

prime seal
#

yes i understand now

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.close

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cosmic acorn
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Hi

lone heartBOT
cosmic acorn
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The solution seems not to be right

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It should be this but idk how to reach this solution

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I do not see any mistakes

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I controlled everything. I just looked 15-20min on it

tall topaz
#

Take out a factor of e^(-2x)

cosmic acorn
tall topaz
#

Well you can write (32=32\cd e^{-2x}e^{2x})

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Lol my flights gonna take off good luck

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There we go

ocean sealBOT
cosmic acorn
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I am not sure

tall topaz
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Use exponential laws

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Bye

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,,\expolaws

ocean sealBOT
cosmic acorn
#

bye ig

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.close

lone heartBOT
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limpid turret
#

!15m

lone heartBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

elfin fiber
#

rise = change in y
run = change in x
slope = rise/run

real gazelle
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Are you supposed to be doing it individually?

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Like, without help from other people

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Alright

tacit arch
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Don't be so entitled

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!volunteers

lone heartBOT
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Helpers are just people volunteering their time to help you. Be polite and patient.

edgy breach
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damn bro is toxic

vapid shuttle
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what made no sense about this?

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the "rise" is how much you 'rise' vertically. it's how much you go up. It's the change in the y-value, from lowest to highest

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the "run" is how much you 'run' horizontally. It's how much you go left to right. It's the change in the x-value

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The slope of a line you can think of as the rise divided by the run. Rise/Run

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change in y / change in x

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!noans

lone heartBOT
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The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

edgy breach
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it looks like the question is just asking y = mx+b, so being told rise/run was actually helpful. m = (y2-y1)/(x2-x1), where y2 and x2 are "later" x/y values, and y1/x1 are "earlier". In general the easiest way to do this is using the intercepts.

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the +b of y=mx+b is just the y-int, which is just th value of y when x = 0

vapid shuttle
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People have been helping you for over 15 minutes

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you just expect to be handed the answer

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that's not how it works

pseudo ice
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should’ve asked earlier than 8mins to the deadline…

edgy breach
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you should not be so rude to people in the future especially people who are trying to help you. if u listened and tried to learn, you would've gotten this question right. Instead you were calling people idiots and laughing at them, which only ended up with you failing

vapid shuttle
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Then why not solve it yourself?

hidden knoll
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we do not tolerate academic dishonesty

vapid shuttle
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without waiting 8 minutes until the deadline

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and then blaming others

tacit arch
vapid shuttle
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You said it was test corrections, the moderator, was making sure you weren't cheating

hidden knoll
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<@&268886789983436800>

edgy breach
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this is a pretty rude

vapid shuttle
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to help you learn

edgy breach
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learn

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xd

ocean whale
pseudo ice
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!noans is literally rules lol

lone heartBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

hidden knoll
vapid shuttle
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It's called being entitled and rude

tacit arch
edgy breach
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you're doing very early year math, this is stuff you need to know if u ever want to do math. The purpose of this server is to help people understand so they can apply what they learn in tests. You're new to this server tho so maybe u missed it.

ocean whale
tacit arch
vapid shuttle
#

What a great attitude to have

night geyser
#

.close

lone heartBOT
#
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edgy breach
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sarcasm isn't being rude, especially since you don't know anyone. It's one thing to do it with friends but it's weird with strangers

night geyser
#

no need to feed the troll folks

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just ping mods and move on

tacit arch
#

Nami did the bani

vapid shuttle
#

Unfortunately I don't even think they were trolling 😭

lone heartBOT
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trim wedge
lone heartBOT
trim wedge
#

Question: Each of the following graphs can be generated by stretching or compressing the graph of y=logx. Write an equation to correctly the describe the graph.

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Answer: y=log(2x)

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Why is this the case

chrome tiger
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The answer can't be log(2x)

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The images show that the functions are zero at 1 and 2 respectively

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While log(2x) is zero at x=1/2

hot bluff
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for reference

trim wedge
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really odd

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The book says it's y=log(2x)

pseudo ice
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They tried youTried they only considered transforming (10,1) but forgot about the (1,0) point lol

trim wedge
#

Books full of shit 😭

#

.close

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fading latch
#

?

lone heartBOT
#

@fading latch Has your question been resolved?

lone heartBOT
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grand gulch
#

if $x_n$ converges then $\frac{x_n}{n}$ also converges

ocean sealBOT
#

skischooldropout

grand gulch
#

so my initial thoughts are yes this should converge its just been a while since I have done proof based math and I am definitely struggling more than I think I should be on this problem. So I guess there would be two key cases. First where x_n grows faster than n at which point does it converge to a or when n grows faster than x_n/n at which point does it converge to 0

pseudo ice
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You may want to notice that $\frac{x_n}n = x_n\cdot \frac1n$

ocean sealBOT
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@pseudo ice

grand gulch
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so this to me then wants me to say yes and my intial thoughts are to use this with the eplisons to try and make everything "equal"

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so I think |x_n - a| > |x_n * 1/n - a|

pseudo ice
#

Are you using $a = \lim_{n\to\infty} x_n$ right?

ocean sealBOT
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@pseudo ice

grand gulch
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correct as an aside I would also have to consider $a = \lim_{n\to-\infty} x_n$?

ocean sealBOT
#

skischooldropout

pseudo ice
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And what are you allowed to use? Can you e.g. use properties of convergent sequences or anything?

grand gulch
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yep anything this is just self-study

pseudo ice
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Cool, you may want to think about properties of convergent sequences maybe cutethink

grand gulch
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ok thank you that gives me somewhere else to look!

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like considering boundness?

pseudo ice
grand gulch
#

I appreciate it!

pseudo ice
grand gulch
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ok ok Ill go back and look!

pseudo ice
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Yep, take a look through what you have, you should hopefully find something useful!

grand gulch
#

thank you so much! I appreciate the guidance

pseudo ice
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No problem catlove do let me know if you manage to cook something with those nyaHungry (or not bceBurntFoodWTF)

lone heartBOT
#

@grand gulch Has your question been resolved?

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uneven rivet
#

For limits of two variables
U can always prove it doesn’t exist via plugging in polar cords right
Like if there’s a trig function in it and no r then like it doesn’t exist bc the theta could change so the limit changes

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spiral pasture
lone heartBOT
spiral pasture
#

i dont get it

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uhhhh how to find the antiderivative of the thing

junior vigil
#

let u=2+ln(x)

spiral pasture
#

thgnak

#

s

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.close

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subtle blade
#

could someone help me solve this?

lone heartBOT
subtle blade
#

i have to use the work energy theorem and this equation

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#

@subtle blade Has your question been resolved?

lone heartBOT
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@subtle blade Has your question been resolved?

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tender oak
#

How do I factor x⁴-16? I've just started learning factoring perfect cubes and we weren't taught how to do anything above x³ yet💀. I don't want to use youtube since my teachers have a different method of teaching and that might screw me up, thanks.

hushed locust
#

you can treat x⁴ as (x²)²

glad echo
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do the ² twice

elfin fiber
#

Do you know about difference of squares?

glad echo
tender oak
#

Thank you guys, this has helped

#

.close

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vocal jewel
#

How do I do this?

lone heartBOT
visual citrus
#

Guys don't kick me out but I am a 5th grader who wants and desires to learn math. My hardest is pre-algebra and no one in my class knows how to do it. I am on winter break and am able for a few methods and practices to improve my algebra (not pre-algebra). Thank you.

elfin fiber
visual citrus
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Thank you but how??

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X+4=23. The value of X is 19.

lone heartBOT
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@vocal jewel Has your question been resolved?

lone heartBOT
#

@vocal jewel Has your question been resolved?

last walrus
#

@vocal jewel Hi there, I think the missing statement is likely something about congruent triangles and the fact that you know SSS congruency

last walrus
#

These are all X, Y, Z, but the original question you posted had ABCD

lone heartBOT
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@vocal jewel Has your question been resolved?

vocal jewel
#

when I click on the box that's what shows up

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im assuming it's because it's a delta math

last walrus
#

That's weird, what's delta math? 🙂

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junior vigil
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.test

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.okay this works

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. @alpine sable

north trout
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what is 1+1

lone heartBOT
junior vigil
north trout
#

oh

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sorry

junior vigil
#

.close

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novel sand
#

10c2 is for selecting any two x and y from set 3k but why didnt they do it 3 times as from the set of 3k+1 the difference is also multiple of 3 same thing for 3k +2

rose sigil
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the square of a number of the form 3k+2 leaves 1 remainder when divided by 3

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because (3k + 2)^2 = 9k^2 + 12k + 4 = 3(3k^2 + 4k + 1) + 1

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so x^2 - y^2 will be divisible by 3 if:
both x and y are divisible by 3 or
both x and y are not divisible by 3

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i might have jumped too much there, does it make sense?

novel sand
#

sadcat its a bit confusing

rose sigil
novel sand
#

3k+2 squared leaves a remainder so lets say its the x number

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Then the y would also leave a remainder 1

rose sigil
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what's y?

novel sand
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Wouldnt they cancel

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a 3k +1 form too

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just a different one

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wouldt the 1s cancel?

rose sigil
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a 3k +1 form too?

novel sand
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like one number i chose is 3k_1 + 1 and other 3k_2 + 1

rose sigil
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if x is of the form 3k + 1 and y is of the form 3m + 2, then yes, x^2 - y^2 will be divisible by 3

novel sand
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oh yea this is what im confused about

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why didnt they include this case

rose sigil
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how is it being excluded hmmge

novel sand
#

Oh

rose sigil
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there are 10c2 ways to pick x and y both divisible by 3, and 20c2 ways to pick x and y both not divisible by 3

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it's included in the 20c2

novel sand
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Ah damn

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its just hit

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Tysm

lone heartBOT
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cinder breach
lone heartBOT
cinder breach
#

Can somebody please explain this passage?

lone heartBOT
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@cinder breach Has your question been resolved?

lofty creek
#

(N+1)n!=n n!+n!

cinder breach
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I know that n! = n(n-1)!

lofty creek
cinder breach
#

Oh right

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Ok but still

cinder breach
lofty creek
#

Write the denominator in the same way as in the picture

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What terms do you get extra?

cinder breach
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Do i do the distribution of the brackets for the denominator as well?

lofty creek
#

Look at the image

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The first fraction

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Is k!(n-k)!

cinder breach
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Ok but why's that

lofty creek
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How do you get there from k!(n+1-k)!?

lofty creek
cinder breach
lofty creek
#

You are writing it as if you have the solution already

cinder breach
#

and n+1-1-k turns into n-k

lofty creek
#

You dont and nor do I

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Write it like scratch ppaprr

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Just try stuff

lofty creek
cinder breach
#

Yes

lofty creek
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Now, try to get to the second

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From the same starting point

cinder breach
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Sorry if i suck

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I feel like an idiot

lofty creek
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Ignore the top part for now

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Only look at the denominator

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<@&268886789983436800>

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We have the first part already

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K!(n+1-k)!=k!(n-k)!(n+1-k)

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Now we want the second part

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k!(n+1-k)!=.......=something*(k-1)!(n+1-k)!

cinder breach
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Ok got it

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Like this?

lofty creek
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Ignore the derivation

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Right now

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We are trying stuff out

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To see if we can spot any pattern

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We have no clue where alwe are going yet

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So trying to write down the whole derivation is futile

alpine sable
#

I can't read ur handwriting

cinder breach
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Okay

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Yes

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I mean

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I don't understand sorry

lofty creek
#

we need to go to something with $k!(n-k)!$ and $(k-1)!(n+1-k)!$ in the denominator

ocean sealBOT
#

Flappie

lofty creek
#

and they both need to come from $k!(n+1-k)!$

ocean sealBOT
#

Flappie

lofty creek
#

we have already found how we got to the first one

#

$k!(n+1-k)!=k!(n+1-k)(n+1-k-1)!=k!(n-k)!*(n+1-k)$

ocean sealBOT
#

Flappie

lofty creek
#

so now we want to go to the second one

#

$k!(n+1-k)!=??????=(k-1)!(n+1-k)!*\mathbf{stuff}$

ocean sealBOT
#

Flappie

lofty creek
#

what is the question mark

#

and what is the stuff

cinder breach
lofty creek
#

how do we go from $k!$ to $(k-1)!$?

ocean sealBOT
#

Flappie

cinder breach
#

Divide by k

lofty creek
#

yes

#

$k!=k*(k-1)!$

ocean sealBOT
#

Flappie

lofty creek
#

stuff=k

#

right?

#

so we have
$\k!(n+1-k)!=k!(n-k)!*(n+1-k)\k!(n+1-k)!=(k-1)!(n+1-k)!*k$

ocean sealBOT
#

Flappie

lofty creek
#

you see this part?

cinder breach
#

Yes

lofty creek
#

so here what are the extra terms

#

that arent in the denominator thats in the example

cinder breach
#

I don't understand

lofty creek
#

in the example

#

we have $k!(n-k)!$ and $(k-1)!(n+1-k)!$ in the denominators

ocean sealBOT
#

Flappie

lofty creek
#

what is the extra term that we have

cinder breach
#

n+1-k?

lofty creek
#

yes

#

and the second one?

cinder breach
#

K

lofty creek
#

exactly

#

so only now we go back to our question

#

$\frac{(n+1)n!}{k!(n+1-k)!}=\frac{n*n!}{k!(n+1-k)!}+\frac{n!}{k!(n+1-k)!}$

ocean sealBOT
#

Flappie

lofty creek
#

which fraction do you think becomes the k one and which the n+1-k one

#

(try stuff out)

cinder breach
lofty creek
#

just try stuff out

#

see what happens

#

its trial and error

cinder breach
#

I am

lofty creek
#

$\frac{n!}{k!(n+1-k)!}=\frac{n!}{k!(n-k)!(n+1-k)}$ and $\\frac{n\cdot n!}{k!(n+1-k)!}=\frac{n\cdot n!}{k(k-1)!(n+1-k)!}$

ocean sealBOT
#

Flappie

lofty creek
#

$\frac{n!}{k!(n-k)!(n+1-k)}+\frac{n\cdot n!}{k(k-1)!(n+1-k)!}$

ocean sealBOT
#

Flappie

lofty creek
#

okay well honestly

#

im not sure where this is going either

#

im just trying stuff out aswell

cinder breach
#

I am crying

lofty creek
#

what i realise now

#

is that it kinda looks like

#

binomial coefficients

cinder breach
#

Yes it's that

#

I have to prove this

lofty creek
#

${a \choose b}=\frac{a!}{b!(a-b)!}$

ocean sealBOT
#

Flappie

cinder breach
#

Prof wrote that passage

#

I have to prove this actually

lofty creek
#

aha

cinder breach
#

Btw thank you very much

#

And thanks for all your patience

#

And sorry if i am slow 😭

lofty creek
#

i want to find the solution aswell :)

#

i know i did it somewhere a few years ago

#

so its actually good practice for me aswell

cinder breach
lofty creek
#

okay well

#

there you have the derivation

#

i dont need to do anything anymore :)

cinder breach
#

Still that passage the professor wrote makes no sense

#

That where you split the fractions

cinder breach
#

See ya

#

.close

lone heartBOT
#
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lofty creek
#

goodbye

lone heartBOT
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nova barn
lone heartBOT
nova barn
#

i'm stuck on the inverse part here..

#

i know that the graph of inverse of f(x) is symmetric abt y=x..so the area on the y axis by f(x) will be same a the area on x axis by inverese..

#

<@&286206848099549185>

lone heartBOT
#

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#

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molten tusk
#

yoo

lone heartBOT
molten tusk
lone heartBOT
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hushed ether
lone heartBOT
oblique drift
#

im pretty sure the right hand side should be in denominator

#

but anyways leme write the solution and explain, 1 min please

hushed ether
#

ya i got that too but its wrong

#

it was -2secxtanx instead of +2secxtanx

oblique drift
#

yes

hushed ether
#

marking scheme

#

what do i even substitute

oblique drift
# hushed ether

$\frac{1}{(sec(x) - tan(x))^2}$ \
$\frac{1}{sec^2(x) + tan^x(x) - 2sec(x)tan(x)}$ \
$\frac{1}{sec^2(x) + sec^2(x) - 1 - 2sec(x)tan(x)}$ \
$\frac{1}{2sec^2(x) - 1 - 2sec(x)tan(x)}$ \

ocean sealBOT
#

killersnake

oblique drift
#

this is what i get in end

hushed ether
#

idk if its related to the top

oblique drift
#

oh

#

so its integration

#

and differentiation

hushed ether
oblique drift
#

the original image u sent didnt include it lol

hushed ether
#

yea

oblique drift
hushed ether
#

but i dont think theres relation to a and b tho

#

c

gray isle
#

use the result in b)

lofty creek
#

c is literally b but squared

hushed ether
#

so i juz square this?

crystal thistle
#

the integrand is (1+sin x)/(1-sin x)

#

now sub sin(x)=t and it will be a rational function in t

hushed ether
#

what even is integrand-

crystal thistle
#

the thing we are integrating

#

ahh nvm

hushed ether
#

am so confused what u typed

#

lmao

crystal thistle
#

if you prove (b) then its much easier than what i wrote

hushed ether
#

i proved b but no idea how to do c

crystal thistle
#

just square

hushed ether
#

square secx+tanx?

crystal thistle
#

sq both sides of b

#

yes

hushed ether
#

oh

oblique drift
#

if you prooved (b), then just square both sides

hushed ether
#

wtf

#

i am overthinking

oblique drift
#

but in exam, you will need to write steps to proove (b) before squaring

hushed ether
#

okok

#

thx

#

i kept simplifying until 1/cos^2 x bleakkekw

#

.close

lone heartBOT
#
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#
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fallow wadi
#

Let T be the set of subtrees of a tree T. Prove that if the intersection of any two T1, T2 ∈ T is not empty, then the intersection of all (T in T) is also not empty.

lone heartBOT
#

@fallow wadi Has your question been resolved?

somber crag
#

can someone help me for this

jagged cobalt
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upbeat eagle
#

Hello

lone heartBOT
upbeat eagle
#

I know how to do everything

#

But I dont understand the markscheme for B

#

I did a different way, but I cant understand this ^

#

Wait nvm I understand

lofty creek
#

they are calculating the area of y=x^2+1 from 0 to 2 and then simply the area of the triangle

upbeat eagle
#

Yeah

#

How would I be able to calculate this

lofty creek
#

the area under the parabola

upbeat eagle
lofty creek
#

they calculate

#

up until the point where they intersect

upbeat eagle
#

Yeah I understood that ^

#

New question

#

How would you calculate the blue area

#

(4,10) is the coords of the corner

#

I would assume, you make a y = mx+c formula for the 4,10

#

And it would be y=x +6?

lofty creek
#

(4,10)?

#

not (2,5)?

upbeat eagle
#

yeah ok lets make it (2,5)

#

Top right corner

lofty creek
#

wait, why do you draw that tall rectangle?

upbeat eagle
#

Bc I want to find the area of it

lofty creek
#

why?

#

arent you solving the blue area?

upbeat eagle
#

Yes but lets pretent this is a new question

#

To find the area of the rectangle

lofty creek
#

aha

upbeat eagle
#

I would, make 2,5 a y=mx+c
So y= x + 3 ?

lofty creek
#

well, area of a triangle is area*width?

upbeat eagle
#

?

lofty creek
#

oh, you dont want from the line?

upbeat eagle
#

Wait ill draw it

#

fully

lofty creek
#

okay

upbeat eagle
#

QUESTION

lofty creek
#

i see why you wanted 4,10 now

#

but continue

upbeat eagle
#

If i wanted the area of the pink

#

I would start off with making a y = mx+c of that top blue line

#

So then
y= x+ 3 and x^2 +1

[x+3 -x^2 -1] dx from 0 -->2

#

Would that give me that pink area?

lofty creek
#

wait that top line is x+3?

#

why not simply y=5?

upbeat eagle
#

Oh yeah it would be y =5

#

what would that verticle blue line be then?

lofty creek
#

the verticle blue line would be x=2

upbeat eagle
#

How would you put it in the form of y=mx+c?

#

If I may ask

lofty creek
#

its a vertical line

#

so you cant

upbeat eagle
#

oh

lofty creek
#

because a function requires you to have only one y value for each x

#

a parabola rotated to the right would not be a valid function

#

what are you going to use the vertical line for?

upbeat eagle
#

it was more of a question formyself

lofty creek
#

alright

upbeat eagle
#

to make sure I remember stuff hehe

lofty creek
#

:)

upbeat eagle
#

Going to write this again down haha

#

catKing tyty

lofty creek
#

take your time

upbeat eagle
#

alright got it then

#

Im going to take a break now

#

Ty flappie

#

once again

#

.close

lone heartBOT
#
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lofty creek
lone heartBOT
#
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fallow solar
#

If the curve of a continuous function on its domain has one point of inflection, then the greatest number of points at which the function curve intersects with any straight line is equal to.......

exotic canopy
#

at least one or exactly one?

fallow solar
#

No exactly one

exotic canopy
#

imagine any straight line

#

and a continuous curve

#

how would they intersect twice?

#

sketch it

fallow solar
exotic canopy
#

mhm

#

now mark approximately where the points of inflection are

fallow solar
#

It's only 1 point

exotic canopy
#

nope

#

don't confuse with stationary points

fallow solar
exotic canopy
#

yes that's one of them

#

what about on the left side of the curve

fallow solar
#

In the question it literally says the curve has one inflection point

exotic canopy
fallow solar
exotic canopy
#

i just want to show you that for a curve to intersect a line twice, there must exist at least two points of inflection

fallow solar
#

Here is a sketch of a line that intersects twice with a curve with no inflection points

exotic canopy
#

nvm i am wrong

#

but like

#

this is a purely visual question

#

the answer is 2 btw

fallow solar
#

I have the answer but I don't know why

exotic canopy
#

huh

#

is it more than 2?

fallow solar
#

Yup

exotic canopy
#

$y'' = 0$ has 1 solution\
$y = 0$ has $n$ solutions\
solve for $n$

ocean sealBOT
#

artemetra

exotic canopy
#

i really don't see how it can be more than 2

fallow solar
#

The question really doesn't make sense for me

#

I don't even understand it

#

Oh hell yeah

#

I got it

exotic canopy
#

oh i got it

#

oh

#

lol

#

now idk why i was thinking only 2

#

a lot of cubics satisfy this

fallow solar
#

Crazy

exotic canopy
#

if you are done, write ".close"

fallow solar
#

K

#

.close

lone heartBOT
#
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mild monolith
#

Apply gradient descent to MSE:
Come up with at least 3 training examples
Take at least 2 weights
Work out at least one step completely
Also, observe the effect on the cost

right picture is my solution, yet is seems to be wrong. This is the feedback i got^^ i dont understand what i did wrong

pure depot
#

Hi! I had a question regarding the curves for this question. Why is the Area in the middle not considered??

mild monolith
#

ooooh i think i might understand, the 1.667 i calculated should be applied to the weights and then recalculate the MSE, till we reach 0 or as close as possible

#

wrong channel buddy

pure depot
#

Ok

mild monolith
#

@pure depot would you mind deleting the messages

#

i dont fully understand the mse formula given by my school, when i google it looks so much different. Could anyone explain how the MSE formula i sent works the same

#

<@&286206848099549185>

crystal thistle
#

sorry but what is mse 😶

mild monolith
#

Mean squared error

#

it's a way to calculate the error of an a.i models prediction

#

in order to tweak it's weights

crystal thistle
#

oh

mild monolith
#

the weights are h0

#

with the stripe through the 0

lone heartBOT
#

@mild monolith Has your question been resolved?

mild monolith
#

<@&286206848099549185>

mild monolith
#

.close

lone heartBOT
#
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uncut escarp
#

does this logic make sense?

lone heartBOT
uncut escarp
#

does it hold

lone heartBOT
#

@uncut escarp Has your question been resolved?

uncut escarp
#

not really

#

<@&286206848099549185> could you check the logic, give some input and then close this, i gotta go

crystal thistle
#

its right

#

3(a2+b2+c2)>=(a+b+c)(a+b+c)>=3(a+b+c) => a2+b2+c2>=a+b+c

lone heartBOT
#

@uncut escarp Has your question been resolved?

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cursive cosmos
#

is this working out correct?

lone heartBOT
#

Please don't occupy multiple help channels.

cursive cosmos
#

.close

lone heartBOT
#
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lone heartBOT
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forest hinge
#

I am about to take a college placer test that I failed earlier and I really need help studying arithmetic

forest hinge
#

I am struggling with the fractions and percentages

#

I barely failed last time and I fo ant take the test again in 40 minutes if anyone just has some quick advice I really need it

#

I am about to leave ANYTHING will help

#

I really need simple formulas for solving percentages and turning fractions into decimals and decimals into fractions (without a calculator.)

#

Its asking quesitons about computing in my head which I am not very good at

#

<@&286206848099549185>

lone heartBOT
#

@forest hinge Has your question been resolved?

lone heartBOT
#

@forest hinge Has your question been resolved?

lone heartBOT
#

@forest hinge Has your question been resolved?

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plucky surge
lone heartBOT
plucky surge
#

Can you pls give some hints for these? f^3 means f(f(f(x)))

vapid shuttle
#

what does it mean for f^(3) to be surjective

plucky surge
vapid shuttle
#

and what is f^(3)(x)

plucky surge
#

f(f(f(x)))? sorry what do you mean?

vapid shuttle
#

f^(3)(x), is an output of f^(2)(x)

#

right

plucky surge
#

yeah

vapid shuttle
#

that's the key

#

for all y in A, there exists an x in A, such that f^(3)(x) = y

#

for all x in A such that f^(3)(x) exists, there exists a z in A such that f^(2)(z)=...

#

and son on

plucky surge
#

ohhh okay i think its starting to make sense, let me process that a little first

vapid shuttle
plucky surge
vapid shuttle
#

sure

plucky surge
#

so i've written down what I assumed, but am i using the wrong idea? the definition for the 3 lines above were functions

vapid shuttle
#

your first line is already sus

#

for all x, there exists y1 such that f(x)=y1 ?

#

what if x is not in A?

#

what if x is an elephant?

#

and then moving to the second line

#

sure, for all x in A there exsists y1 such that f(x)=y1

#

but now the same problem

#

why must y1 be in A?

#

you have to start with what you are given about f^(3)(x) being surjective

#

and work backward from there

#

instead of forwards as you are

plucky surge
#

okay thanks, let me go back to your comments earlier to try and work backwards

#

is this more along the right line?

vapid shuttle
#

okay the first line is better

#

the second line doesn't make much sense

#

it should read more like

#

f(f(f(x))) is a specific output of f^(2)(x)

#

so for all f(f(f(x)) there is a value in the domain of f^(2)(x) that takes on it

#

it isn't clear to me how to state that neatly

#

but I don't think that's what you quite have in line 2

plucky surge
#

i see i see, thanks for the tipcs

vapid shuttle
#

looks good at a brief glance

plucky surge
#

is this a bit more clear now? not full write-up, but does the idea make sense?

vapid shuttle
#

yes

#

better than I would've written it I think

plucky surge
#

aww

#

thanks so much for the help and endless patience man!

vapid shuttle
#

no problem

plucky surge
#

appreciate it lots

lone heartBOT
#

@plucky surge Has your question been resolved?

#
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alpine sable
lone heartBOT
alpine sable
#

@foggy pecan

#

i got d = 20

#

bru

#

@foggy pecan what did i do wrong

#
  1. i differentiated the equation and made them equal to 0
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cuz i wanna find the stationry point which is the turning point

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and then we also know that the the turning point is at 1, 3 at x

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so idk what i did wrong

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@foggy pecan can u see this?

foggy pecan
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i am here

alpine sable
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oh ncie

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can u see my working out?

foggy pecan
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a = -6, b = 9 and c = -2, you confirm them ?

alpine sable
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yh

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i used 1,2 to find them

foggy pecan
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yes

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so

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now use them in your given function cube polynomila

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and finally

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x = 3, and y = d

alpine sable
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so 27 - 54 + 9 + -2 = d

foggy pecan
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27 - 54 +27 - 2 = d

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you have 9x there

alpine sable
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OH HYHHHHHHH

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oh myyy

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i was there but i couldnt see that..

foggy pecan
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it's ok

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such things happen )

alpine sable
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i acc do this a lot recently

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do u know any tips

foggy pecan
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at beginnigns it makes process slower, but later, it wibe automatic

alpine sable
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oki doki

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thanks for the amazing tips

foggy pecan
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yw )

alpine sable
foggy pecan
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yes i am

alpine sable
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wow u r amazing

foggy pecan
alpine sable
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mb

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anyways

foggy pecan
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smiles

alpine sable
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thanks for helping me

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lol

foggy pecan
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yw)

alpine sable
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byeee

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.close

lone heartBOT
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lone heartBOT
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faint monolith
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Jones is chasing a car 800 meters ahead of him. He is on a horse moving at 50 km/h. IfJones catches up to the car in 4 minutes, how fast was the car moving?

eager sonnet
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Ok

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How much faster must Jones be to be able to catch up within four minutes

lone heartBOT
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@faint monolith Has your question been resolved?

faint monolith
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how do u do it

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can u show me

eager sonnet
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Ok

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I'm nit here to give u an answer

faint monolith
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yeah

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just show me

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like step by step

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pls

eager sonnet
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I'm here tobhelp u solve the qn

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So I'll guide u through and u do the workings OK?

faint monolith
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ok

eager sonnet
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Jones catches up in 4 minutes. How far did Jones travel

faint monolith
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10/3 minutes

eager sonnet
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Correct

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Have u learnt algebra?

faint monolith
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yeah

eager sonnet
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Good

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Then we'll use it to derive a method to solve such qns

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Let the speed of the car be x km/h

faint monolith
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yes

eager sonnet
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How far did the car travel before it was caught up by Jones (not including the 800m at the beginning)

faint monolith
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idk it. doesnt give any information about the car

eager sonnet
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Use x

faint monolith
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oh

eager sonnet
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So?

faint monolith
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is it 4x?

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?

eager sonnet
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We worked out the time taken for Jones to catch up

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That's the same amount of time that the car moved

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So let's first express 10/3 min in hours

faint monolith
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1/18 huors

eager sonnet
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Yes

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Thus the distance the car travelled is?

faint monolith
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x/18

eager sonnet
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km

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Yes

eager sonnet
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I'm sorry

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Earlier I thought u were correct but u were wrong

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It's 10/3 km

faint monolith
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wait im getting confused

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can u write everything we've done up to here

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like summary

eager sonnet
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But we were wrong from the start

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Like let's rework it

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I'm so sorry

faint monolith
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ok

eager sonnet
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Earlier u said 10/3 mins right?

faint monolith
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wait the time they travel is the same right?

eager sonnet
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Ya

faint monolith
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so we just get the distance and spped of both a set them equal?

eager sonnet
faint monolith
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yeah

eager sonnet
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So it's actually 10/3 km

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Get it?

faint monolith
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yes

eager sonnet
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Ok

faint monolith
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so is the car distance just 10/3 + 800

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i mean

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10/3 + 0.8

eager sonnet
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No

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Subtract

faint monolith
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huh

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oh yeah

eager sonnet
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The car is ahead of him

faint monolith
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38/15

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km

eager sonnet
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Ye

faint monolith
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so

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38

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x=38

eager sonnet
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Nah

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We have the distance travelled by the car

faint monolith
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its correct?

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i can see answer key

eager sonnet
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We have the time

eager sonnet
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Sorry

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I din know u were skipping ahead

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Yep

faint monolith
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10/3 / 50 = 38/15 / x

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yeah

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thanks

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i just needed help with the first part

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my brain blanked out

eager sonnet
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Ok

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Wiat

faint monolith
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.close

lone heartBOT
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eager sonnet
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Wait

faint monolith
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?

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.reopen

lone heartBOT
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eager sonnet
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I'll teach u an easier method

faint monolith
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what is it?

eager sonnet
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Basically take distance over time straight away

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0.8/(1/15)

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12

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Then that's the speed difference

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So the car's speed is 50-12=38 km/h

faint monolith
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ojh

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damn

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thanks

eager sonnet
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But that's only for catchup type of qns

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If its opposite direction

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That's a different story

faint monolith
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yeah

eager sonnet
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Okie?

faint monolith
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opposite direction is adding the distances = the total distance

eager sonnet
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Yep

faint monolith
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ok thanks

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.close

lone heartBOT
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eager sonnet
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No prob

lone heartBOT
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narrow geyser
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how do i rearrange to solve for x

lone heartBOT
keen mason
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(1.74-x)(5.3665) = 2x
9.33771 - 5.3665x = 2x

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9.33771 = 7.3665x

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9.33771/7.3665 = x

lone heartBOT
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@narrow geyser Has your question been resolved?

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keen mason
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what grade r u in

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yea idk why i asked that im not american

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how old r u

rugged spruce
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obviously

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not even remotely difficult

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the answer is of course, correct

night geyser
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.close

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woven grove
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guys how do you evaluate 29219+73924?

lone heartBOT
fallow solar
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By the calculator

lone heartBOT
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@woven grove Has your question been resolved?

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faint monolith
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Hi

lone heartBOT
faint monolith
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I'm struggling to find out how to add a solution to a problem on AoPS (Art of Problem Solving)

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can someone who knows tell me how

lone heartBOT
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@faint monolith Has your question been resolved?

lone heartBOT
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@faint monolith Has your question been resolved?

lone heartBOT
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@faint monolith Has your question been resolved?

crystal thistle
lone heartBOT
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@faint monolith Has your question been resolved?

crystal thistle
lone heartBOT
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@faint monolith Has your question been resolved?

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frosty oxide
lone heartBOT
frosty oxide
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How does one solve it?

vale wigeon
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the first step is to write this in a less chicken scratch way

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@frosty oxide Has your question been resolved?

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hoary ether
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Help me please

lone heartBOT
frigid mirage
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perhaps any mention of x being an integer?

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well I tried a bit and I'm out of ideas on how to solve "properly"
luckily it's quite easy to guess an integer solution

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@hoary ether Has your question been resolved?

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weak parcel
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Hey

lone heartBOT
weak parcel
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Is the diagram correct?

prime glacier
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yes it's correct

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wow do you not get whole numbers for this question

weak parcel
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T-4g = 4x -g/4

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Obviously assuming g is 9.8

prime glacier
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how did you get 4x - g/4

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what's x supposed to be

weak parcel
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Times

prime glacier
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ohhhh

weak parcel
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Like 4 times -g/4

prime glacier
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so 4g/4

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so g

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yeah alright that's what i got too

weak parcel
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Wouldn’t it be -g/4

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Cos it’s descending

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No it’s rising

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Cos Q is descending

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Or would it be 4g/4 @prime glacier

prime glacier
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nah

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it's positive

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we take it as positive

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because the net force is acting upwards

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and that's where it's accelerating

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if i'm wrong correct me

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but i'm 100% sure it's +g and not -g

weak parcel
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Yeah ur right