#help-0
1 messages · Page 376 of 1
Mr. Macro
present mary age minus present ann age = past mary age minus past ann age
does this make sense
idk
how does that give us the answer
sub 24 into x of this
u get 47.5 then
Anns current age is 16
Half of 18 is 9, but 24-18 is 6
Ann is currently the age at which Mary was twice her age.
Ann is twice the age difference.
Since Ann is currently let:2x yrs old, and Mary is x years older than Ann
So, Mary's 3x yrs old.
3x = 24 the age difference is 8 years.
2x= 2*8=16
Done!
18 doesnt make sense
\begin{tabular}{|c|c|c|}
\hline
& \textbf{Present} & \textbf{Past} \
\hline
\textbf{Mary} & 24 & x \
\hline
\textbf{Ann} & x & 12 \
\hline
\end{tabular}
࿈
Didn't I just give u that answer
Here.
yeah i see
hi yes you too read what i thought i read the first time
but the problem is
Mary is twice as old as Ann when Mary was old as Ann is now
not
Mary was twice as old as Ann when Mary was old as Ann is now
The tense was the real problem
so was it 16 or not
IV caught the problem red-handed
It is 16
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I'm somehow doing this wrong and I'm not sure. Can someone tell me.
I'm trying to find magnitude of the force on the 1nC charge
So what I did was first rotate this figure so the 1nC will be on the bottom right
Then i drew the forces, so for Force of 1 and -2, it will go to the right on the x axis because its attracted towards the positive
for force of 1 and 2, it will be repelled towards the southeast
So then i did my calculations, for force of 1 and -2, I got 1.8*10^-4 towards the right
for foce of 1 and 2, i got 1.8x10^-4 towards south east
Do components, 1.8x10^-4 x cos60 is 9x10^-5
1.8x10^-4 x sin60 is 1.56x10^-4
Since both the x components go to the right, i simply add them and get 2.7x10^-4
I do pythagorean theorem, so square the compoennts, and find the root, and I get 3.12x10^-4
but this is wrong apparently?
“..both x components go to the right”
no. not after rotating
also rotating the diagram makes the problem significantly harder than it needs to be 
really?
cuz I was taught that if i rotate it, then one of the forces will just be paralledl to the axis so i don't have to break it down to the components
i mean sometimes it’s useful but in this case you have some nice things going for you if you solve as is
specifically a lot of symmetry
just did a random paint drawing. is this a incorrect interpretation?
wait...
do i just have to find the y component and multiply it by 2 and that's the answer?
now write the direction of forces along the horizontal direction from the 2 other point charges
I mean for the horizontal direction, they both go towards the right?
ye but one of them has a neg charge
yeah but it goes from negative to positive
so it goes to the right for +1 and -2
and then +1 and +2, it repels so it goes bottom right, which is right and down component wise?
ok, that’s fine
but then what does it mean for the force exerted by the negative charge
is it pushing the charge the right or pulling it towards the left
isn't this scenario the negative is pushing?
you’re confusing concepts i think?
opposite charges attract, yes?
uh, hmm i might need to be more careful with my wording
this is only for forces acting on a positive charge which for this question is good enough
i'm so confused now. i was taught like, when I calculate the force, the coulomb's law disregards the signs cuz it's a absolute value. and you use the signs to find the direction after you find the force
ye, so if they have the same sign of charge the force is repelling, if they have opposite signs the force is attracting
so the +2nC charge does push the +1nC charge southeast
but the -2nC charge pulls the +1nC charge west due to having opposite charges
wait so forces go from positive to negative?
hmm?
no, you just have to find whether the force is attracting or repelling based on the signs of the 2 charges involved
wait but how do i find the direction if its attracting
it goes the exact opposite direction compared to if it were repelling
ohhhh nvm i see
let me try it out rq
still got it incorrect, hold on
So force of -2 and 1, is the red arrow, 2 and 1 is the orange arrow
They both have the same force, say F, because the net charge and distance is equal?
But red arrow is -F cuz it goes to the left
break orange into components, cos60F is Green, sin60F is Blue
the answer is sqrt((red + green)^2 + (blue)^2)
is this not right?
pong
it is now
but see the problem is that you add red and green but clearly they’re pointing in exact opposite directions
yeah but i made red into -F
ye so reflect that in your calculations
(im saying you were previously wrong because one of the forces you added together wasn’t made negative)
what you’re currently doing is correct, no more change needed
and no don’t do this
^ ok yeah that's what i thought, cuz I made F negative, and that'll just revert to my original problem
but the answer is still wrong unless i did some miscalculation?
so this is what i did
((9x10^9)(1x10^-9)(2x10^-9))/(0.01)^2
that's F, which is 1.8x10^-4
cos60 F is 9 x 10 ^-5
sin60 F is 1.56 x 10^-4
-1.8x10^-4 + 9 x 10 ^-5 = -9 x 10 ^-5
sqrt((9 x 10 ^-5)^2 + (1.56 x 10^-4)^2) = 1.27x10^-4
but the ocrrect answer apparently is just 1.8x10^-4???
sin 60 is just wrong
you forgot to divide by 2
divide by 2?
uhhh hold up
actually i get 1.8e-4 when i evaluate your sqrt
so idk what you were doing but i guess you typed the wrong thing into your calculator
like this is straight up 1.8*10^-4
bruh what
,w sqrt((9 * 10^(-5))^2+(1.56 * 10^(-4))^2)
ok
well
i guess i need to put parenthesis around everything, i think my calculator just squared the power of 10s
tysm
also as to why it’s just 1.8e-4
argue by symmetry that 2 of these 4 components cancel and the other 2 components are equal
so the vertical components cancel
but the bottom isn't horizontal x2 right?
its just half of horizontal x2?
those 2 aren’t the ones that cancel
The vertical forces are the ones that cancel
yeah so verticals cancel
but it should be reasonable to convince yourself that two equal forces acting in exact opposite directions cancel
how do u calculate the horizontal tho. cuz i thought it was just cos60 F * 2 but it snot
yeah i understand that
it is tho
did your calculator bork again
you mean -4?
🤦♂️
i've been calculating with the thought that the Force between the two was ^-8 not ^-4
ok i see
bruh
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can anyone explain why he had 45 and 50? why not just 50 as the S50E angle
45 just comes from parallel line transversal thing
I dont get it
why is there a transversal line in the first place
they're bearings
u initially didn't know what the pink angle was
u got the 50 from the question but the pink "?" was something you should've deduced fromg eometry
two yellow lines are parallel and purple line is the transversal
then from geometry, you can say the pink "?" is 45 as well
so a bearing isnt a point
but a straight line?
My concept is maybe fucked then because I thought a bearing was a point
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@rigid kayak Has your question been resolved?
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I need to calculate the charge on capacitor when t = 50microseconds after switched to flipped to b
.close
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Question 10
<@&286206848099549185>
,rccw
@austere fern Has your question been resolved?
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How do graph the period within 4.5π
@waxen turtle Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185>
@waxen turtle Has your question been resolved?
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@waxen turtle Has your question been resolved?
@waxen turtle Has your question been resolved?
I don’t understand your question
Do you need to draw the graph of this sine wave for [0, 4.5pi]?
uhh
Idk how to graph the period
Hello, don't graph a whole period. Maybe half of it, or one fourth of it, whatever is inside those limits
Remember what happens at pi/2 and pi and 2pi in sin(x)
Isk
Idk
Oh it like dipps
At π/2
So like
Idk
Should I make the dip
At
3.5π
yes, great 👍🏽
Ty
wait
there's a little mistake
One off I think
the minimum is not -7
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uhhh
7sin(π/2(x)+π/2)-3
Was I supposed to distribute B
Idk
Wait wat does is entered in radians mean
😭
Radians are a different version of degrees
Wait is the question what is radians
Never mind I can’t read
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7sin(π/2(x)+π/2)-3
That's right right fr
Idk if u are supposed to distribute the B part
Idk
There should be infinitely many solutions, so there should be a k inside the sin
But other than that, switch your -3 and -7
Y
Because what you wrote goes through +4 not -4
-3sin( (2k+1) * (pi/2)*x + (pi/2) ) -7 for all integers k
@waxen turtle Has your question been resolved?
Idk wat that first part is
Also I don't think that has a -3 amplitude fr
Plot it in Desmos if you don’t believe me
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@waxen turtle Has your question been resolved?
<@&286206848099549185>
You've done dozens of these.
On this one, I can't actually see what the question is.
That is the ahole question
Wjole
Whole
I mean - your question.
Are you again just wanting a check that you have it correct?
Idk what to do Abt the period
and also idk if I have it right so far I did everything except the period I think
@azure shuttle
<@&286206848099549185>
@waxen turtle Has your question been resolved?
<@&286206848099549185>
Do you understand how to disseminate information from a sinusoidal equation?
I think so
So given this equation, can you tell me the amplitude, periodicity, offset, and midline?
Amplitude is 4
Period is uhh
IDK
something under 2π
Idk what offset is
Midline is like
4
Ez
How would you put the prior equation into this form?
Take note of the expression x - H inside of the sine function.
Idk
You would factor out 3pi.
No, that's correct.
Take note of how I factored out 3pi. I multiplied the expression 3pi x - 2 by the whole fraction 3pi/3pi which is equivalent to 1.
In this form, 3pi is equal to 2pi/P.
$3\pi = \frac{2\pi}{P}$
Kookiemon
Does that make sense?
So what would the periodicity be of the equation I gave?
2/3
Meow
Put the expression inside of the sine function into the format I showed you by factoring out pi/2.
5sin(π/2(x-2))+3
Correct.
EZ
wat
P is the periodicity.
Oh
$\frac{\pi}{2} = \frac{2\pi}{P}$
Kookiemon
Correct.
Do you know how to graph your function now?
The period indicates the interval at which the sine function repeats.
So like
Idk
At 4???
Or likee
π/2
How far is that
How to graph
Is that like faster than normal
Or slower
Idk
It's usually easier to pick an obvious point to determine where it repeats. This can be either at the maximum value, the minimum value, or the center line.
Idk
Ok, from the periodicity, you know that the sine wave repeats after 4 units.
What is the simplest value of x that you can chose to find the first point for the purpose of making a graph?
That's a standard sine wave function, however you need to translate it using the equation given to you in the problem.
Ok, you have the periodicity correct.
EZ
Now adjust the amplitude.
Fr
Done
I'll do the +3 next fr cuz it's easy
then uhh
do I backwards 2
Like
Left
To the left
Move it
Shift

Horizontal
Shift
Left
2
Think about it. When does x - 2 = 0?
So which direction do you shift the graph from the origin
You shift the graph to the right 2 units from the origin.
Right
Wat ur thoughts 🙏
Looks good.
TYYYY
yw
Omg it only took like entire day fr ur liek the only one who could do it ff
De
Fr
🙂
Now try solving it again from scratch now that you have a solution.
You can refer back to it if you get stuck.
wahr
but that's ez fr
I didn't know Abt changing the formula thing fr
or
Equation
I meant
To match that
Might be easy now, but give it a day or two and see if you remember how to solve it. 😉
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How do I know when sin, cos and tan ratios
should be positive or negative?
@robust briar Has your question been resolved?
<@&286206848099549185>
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How do i figure out angles in standard position?
Angle A is 55 in standard position but idk how to figure out angle C in standard position
55 degree is already in standard position but how do i figure out 165 in standard position?
you have directions and distances
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alright so i was taking a practice test and i was given this equation
0.0625/5 - 0.125 x 3 + 0.099/0.011
now the asnwer i got was -2 (idk how i got there)
but it was wrong and it says the answer was -0.5
now ive redone it and i got 8.750 on my second attempt
What did you do?
but i dont see anyway it could equal 0.5
Can you show your work?
yeah one second
did you copy down the question correctly?
im decently sure i did, ive retaken this practice test a couple time now because a couple of the questions keep getting me
what is this? a division symbol?
it is
those dots are so faint it's hard to tell that it's not a minus
and also you really should be writing division as fractions ideally
you didn't set up the division for 0.0625/5 correctly
oh
also gonna suggest that you write 0.0625 as a fraction and don't bother with this long division
im still very rusty this grade 10 maths i have not done in like 4 years now
this is grade 10?
i cant use a calculator for this btw
you don't need a calculator here
yeah i have to take an exam to get into the navy and its on the grade 10 curriculum
for lord knows what reason
how do i make the 0.0625 into a fraction

?
do you know how to work with fractions, generally?
but do you guys get anywhere near -0.5?
i used to but havnt touched em in years
well you're gonna have to review those
but you would do $\frac{625}{10000} \cdot \frac{1}{5}$
Ann
it would be good to simplify the fraction 625/10000 beforehand as it is very simplifiable
ok and then that would be 625/50000?
oh my lord i see it
i think
this would explain why they gave the answer as -1/2 instead of -0.5
it is good practice to keep the answer as a fraction in general, unless there is a good reason not to.
that is something you should try to overcome
id make that 125/1000 x 3/1?
itd be nice if they just let me use a damn calculator for this exam
That kinda defeats the purpose of learning arithmetic
alright im taking a crack at it with the fractions and i'll lyk if it works
the exam is for the navy
they should teach me how to swim
not count
you say this as if you are not going to need to count anything while in the navy
imagine if somebody took the same stance towards, say, reading and writing
"the exam is for the navy, they should teach me how to swim, not read!"
(also wouldn't you be on a ship usually? so not that much swimming, or so one would think)
you are correct i agree with that
im just not a fan
also i dont know how well this went
i got up to 1/80 - 3/8 + 1089/10000000
i dont remember how to add and subtract fractions
i find common denominator right?
if im not mistaken
also that 10 mil dont look right but im rolling with it
that last one looks sus af
truly
the answer doesn't seem to be -1/2 at any rate
do you perhaps have a screenshot of the problem somewhere so we can rule out miscopying
yeah i ended up on like 610/80
1 second
oh im just blind
-1/2 was the answer for the question below
sorry
frying my brain trying to figure out whats wrong
sorry guys
... you sent us the wrong question
yeah im sorry i wrote down all the questions i got wrong and the answers with them
i got them jumbled
truly i apologise
how do i close channel
.close
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not sure if i did this correctly would anyone be able to take a look over my work
thanks 🙏🏼
@undone cove Has your question been resolved?
You have written two h's. Which one represents height here?
Sry not sure what you mean by that i think i started writing H as h
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No
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i claim
okay
so i need help with math credit that i needa turn in tmr or im screwed and half of it is that its 1am and im tired asf and another part i barely understand
help me just learn this
the range is the set of values the function can output when it gets inputs from the domain
what happens when you put the values in the domain into f(x) for problem 1
hello
yes, the values in the domain are 1 3 5
just insert the numbers given in the domain one by one in the function f(x)
f(x)?
wait whyd u put two 3's when its 1,3,5
what is f(x) when x=1
f(x) maps x to 9x-17
so it maps 3 to 9(3)-17
oh okay
see domain is all the possible x values of a function and range is all the possible y values of a function , so we are inserting domain x in a function f(x) to find the range
not rlly
yes
yup
alr so i dont rlly wanna do all that is there like
a different way to approach it
and get same answer
i mean
not really
but it takes like 2 seconds to just put the number into the formula
wdym
so after i put all the numbers in the (x) thing what am i solving for
For instance: f(x)=3x+1
f(x)=9x-17
so if we want to find f(3)
we put 3 into 9x-17
and get 9(3)-17
If you input f(5)= (3*5)+1
Like this is like a machine where you are inputting values of x one at a time
well you simplify, but yes that is what 3 maps to
oh
then you have to do it for all the other values in the domain
(in this case only 2)
so it really isnt that hard its just trying to make it look hard
sure
the range is the values you get when you put in the domain
okay im gonna try it jus correct me if i do sum wrong( ty for both of ur helps)
so
f(x)=9x-17
f(1)=9(1)-17
Range is the value you get after inputting whatever value of x in the f(x)
-8 gah
well i know that
alright so if i wanted to speed it up
a bit
i just take the number
multiply it by the number im puttin it next to
then add or subtract
whatever it is
and then write f(7)=20
or wtv
Og I thought you were unaware
you do whatever the definitino of the functino is
sometimes its a quadratic
ya idk what that means
and then you need to square it for example
What?
i used x as examples of a number
okay
cool
so
i know i can do the third one
but what would i write down in the "range______"
the line that says range
oh
all the numbers i gathered up?
Use curly brackets
-8,10 then blank?
use curly braces and commas
blank?
Did you actually understand the concept of functions diddybop?
Blank?
he didnt know f(5)
ima jus say thats right cus it seems like it
so he dubbed it "blank"
is functions what im doing>?
yes
ok wait, lets try something really quick
lets say that $f(x)=x^2+3x$
大野雄大
what is f(4)
oh i actually had chat gpt do those for me along time ago
like beginning of the month
anyways
what is all this
!nogpt
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
thats why i wanted to see if they were correct
frick
alr ya
theres about 38 more pages of this and i cant im going to sleep ty guys much respect to all of u helping people fr
Alright bye!
bye ty
and ty
.cclose
.c
,close
how to do it again
.close
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I have this exercise: A and B are sets. If P(A) = P(B) prove that A = B.
I have a solution but I don't know if it's correct. Can anyone have a look?
seems fine to me
If I wrote instead:
If x in A -> x in P(A)
Would it be wrong?
yes
yes it would
also if you can't type the set membership symbol it is better to replace it with "in"
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bro am i insane
or this doesnt even hold for n = 1
i guess it holds for n = 2, as rhs becomes 1/6?
but wouldnt n = 2 imply 1/6 + 1/24 + 1/60
alright yeah
with n=2, you'll only have the term 1/6
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the structure of your induction proof is wonky
you should delete the $3^{k + 1} + 7^{k + 1}$ after $a_{k + 1}$ as that's what you're aiming to prove, and should only be at the very end
south
otherwise that is correct
question 3 is correct
yeah question 1 is all good
yeah the other induction question 2 is also correct
Oh right
Tysm for the check
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The numbers 1 to 9 are arranged in a line (uniformly at random). What is the probability that the first number and last number are both at least 6?
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My answer is
Can someone verify this answer?
i put 4 and 3 at the beginning and the end cuz there's only 4 numbers that is atleast 6 i.e. (6,7,8,9)
was my reasoning correct?
let's see
4 options for what goes at the front, 3 for what goes at the back, and 7! for everything in between
yeah, this tracks.
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we have a dedicated he/him role fyi
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Please help, I got this integral TERRIBLY wrong and have no idea why.
massacre 🙂 i give you very simple formula:
$\sqrt{1-(5u)²} \neq 5\sqrt{1-u²}$
hayley
$\int_{}^{}\frac{f'\left( x \right)dx}{\sqrt{f\left( x \right)}}=2\sqrt{f\left( x \right)}+C$
oh nvm that's from the dx you're good
Joanna Angel

you may use it for the first part
the 5 is from dx
but is the method incorrect or the execution? do i use a different approach?
cos(arcsin(5x)) can be simplified to remove the trig, most commonly with the help of a triangle
how?
make a right triangle where the sin of a certain angle is 5x and find its cosine
And why does the calculator spit a completely different result?
what does the calculator say?
ok I fixed some numbers that were wrong it’s different now
I still have no idea how the calculator spit no trig functions in the second term
you will once you do what i said
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I'm not sure how to do this question, what I have so far is that no of X + no of Y + no of Z = 6800u + 3100s + 1400t
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I keep ending up with an extra 'n' on the right hand side of the solution, I am definitely doing something wrong with the arithmetic I just don't know what.
Well you did
$\sum_{i} y_i = n \bar{y}$
Bishop
Is the above true you know?
Thats what you put
in one of your steps
that is what you did is what im saying
Well i will assume its true
Just to clarify, you are saying it's not true? because it is.
y bar is the mean
and its equal to sum of Yi/n , so the sum if Yi = n*Y bar
I am new to stat. so I might be wrong tho. but that's how i understand it
$2 \bar{y}^2 n + \bar{y}^2n = \bar{y}^2 n( 2 + 1)$
Bishop
I gtg
@light ledge Has your question been resolved?
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Hey
I just want to see whether I did it correctly
Here’s what I did
<@&286206848099549185>
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f(x) = x + 1
g(x) = x^2
h(x) = f(1/g(x))
determine h'(1)
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I tried and I got the answer to be -2
but its supposed to be -4
so what i did was i did f'(x) * d(1/g(x))
= 1 * d(1/x^2)
= 1 * d(x^-2)
= 1 * -2x^-3
i think -2 is correct

Show the original question
f(x) = x + 1
g(x) = x^2
h(x) = f(1/g(x))
determine h'(1)
i havent altered it just translated
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Hi
I got
x=0
x=2
x=3
this was on the final so im just tryna confirm if i got it right
hopefully i did
HOLA
hi
Was I right?
celle la une martice augmenter
faux?
idk
it may help u
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multiply numerator and denominator by the conjugate of the denominator
could they use L'Hopital here btw?
ye
dont you think that would be simpler since both are made of sums?
yep
So i can use it right
you sure can idk if its simpler though haha.
okk
Hn thanks bro
👍 🥺
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Hello, can someone please help me work on this problem
Am I supposed to find a test statistic
hidingandseeking
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