#help-0
1 messages · Page 370 of 1
,calc 3^6 -81*3-486
Result:
0
(this means (x-3) is a factor of the numerator)

Eh
(x-3) still equals 0
0/0 still doesn't make sense
?
x-3 is a factor of the numerator so factor out x-3
do horner scheme or whatever
in fact
,tex \polylongdiv{x^6 -81x-486}{x-3}
Pure
,tex \polyhornerscheme[x=3]{x^6 -81x-486}
Pure
Something like this???
And I can get rid of that (x-3)
where do i get help
thankss
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hi
ye
what is quartile 3 of 10,19,21,28,34,37,40,42,43,43,45,50,54,56,61,65,70,88
we struggling to know if quartile 3 is equal to 56 or 58.5
10,19,21,28,34,37,40,42, 43,43 ,45,50,54,56,61,65,70,88
Quartile 1 quartile 2 quartile 3
or
10,19,21,28,34,37,40,42,43 43 43,45,50,54,56,61,65,70,88
Quartile 1 quartile 2(median) quartile 3
we search online and results vary on each site
ox ajas
this is box and whisker plot
@neat totem Has your question been resolved?
<@&286206848099549185>
@neat totem Has your question been resolved?
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@neat totem Has your question been resolved?
help
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how do u make an equation out of this
One of the zeros at -2, y-axis is the axis of symmetry and the value of a is 2.
What's the standard form of a parabola you have?
What's a?
2
you can use any of the form?
standard
Vertex Form
roots of x
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(Sorry for the ping)
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I don't know what to do
@twin jewel Has your question been resolved?
where do the lines on the diagram intersect?
like, what's the x-value
and what's the y-value
7 is correct (wait, your x and y are switched)
but try again, 2 is not correct
you might need to click on the image to make it bigger
yes i just realised that too lol
ok
7 and -8
shit sorry for the typo
yes
so thats the anwser?
ok#
and as we found before, x = 1 and y = 7
it's the same as
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Help
the cuboid surface area is 6 rectangles
and circular sector is 60/360 * area of circle
but the cuboid is asking for surface area, not volume
you could just calculate the area of each side of the cuboid and add them up
shit
Is it cm² or cm³ for surface area
Surface area is squared (just like area is)
Oh thanks
Idk the area of the sector one tho
Idk how to do it
I havnt done that in ages
If it was a full circle could u find it
Probably
That is step 1 so start by finding that
Alr
Think that a full circle has radian 2π, and area of a full circle is πr^2, so what is the area of part a circle
You have to use the Google keyboard
Download it
Or latex if you know what that is
$\pi$
cali5nia
if ur on pc u can hold alt then press 2 2 7
2π•1/2•r^2 is area of a full circle
Where the angle is 2π radians
So how do u find a sector
I don't want to spoil it😭
Dw
How many degrees are in a circle
You can Google it if you really care to
360
But it makes sense if you think about it
you are given a slice with 60 degrees
How many slices do you need to form a full circle
I have but its giving me a weird symbol like a 0 with a line in the middle of it
Ohhhh so u do 360÷60
yeah
thats how many slices would form a full circle
you only have 1 slice though, when a full circle is 6. So the area is going to be 1/6 of if it was a full circle
When you have something that looks complex, see if you can relate it to a more simple shape (squares,triangles,circles) and find a relationship between them
Sorry for sneaking in , just wondering if any of you are free to help , thanks.
Is the answer 42.416 recurring
yeah but to be precise its not recurring if you use the true value of pi, it will be more random
So should I put it in terms of pie?
Yeah you usually put the exact value unless they ask otherwise. In this case that means putting in terms of pi
Ok thanks for all the help!
My calculator says in terms of pi it's 27/2 pi
Do I do 27÷2 or do I just leave it at 27/2 pi
both are fine. I believe most people would leave it in fraction form though so 27/2pi
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just plug stuff into the scenario
what goes where
oh wait im actually dyslexic LOL
wait no i still dont get it
You have h, all you need is to evalute y0 y1 y2 by inserting the values of points
looking at the example provided and i dont understand where they get 6 from
consider each point coordinates as (x,f(x)) it would help
How do you get one of these bots to help you? I did the tutorial it’s not working😭
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I've been struggling with #5 and idk how, please someone tell me what I'm doing wrong or misunderstanding
Here's my work and if you need anything else I'll be more than willing to give it
I thought I did everything I was supposed to am I missing smth or
the problem comes from P and P^-1 (more precisely, first column of P seems very dubious, 2nd seems ok)
you should read your lesson about how to find P again
idk your method but something here is wrong
you should get
0
1 instead to have a valid column
@sacred plume Has your question been resolved?
Ohhh okay i see, lemme look through my textbook again sorry
the columns of P have to be a basis of eigenvectors for the space
you first column (1, 0) is not an eigenvector for the eigenvalue -1 (2nd column is eigen for 1 so it's ok)
A*(1, 0)^t = (1, 6) not (-1, 0)
which is why your P doesn't work
but with (0, 1) instead it works bc A maps it to (0, -1)
the part I screenshot is where a problem occurs
Okay I got it now tysm T_T
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ok new question
can you have a commutator between a vector and a scalar?
well how should that look like
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hello 🥲 im sorry if its not exactly math related (more on physics) but im really desperate rn and maybe someone here understands how this works.. does anyone know how he got the latter equation from the first equation (conservation of momentum equation)? like how he manipulated it to be like that, thank you vm!!
KE is 1/2mv^2 and PE is mgy
is this part of a bigger problem?
yes it is
can u post that please ? :D
should i send the entire problem
thank you so much!!! sure sure
here is the problem
and the questions are: A. Write the equation for the conservation of momentum in the inelastic collision of the bullet and the woodblock
B. Suppose that a very massive bullet (where m>>M) is fired at the wooden block pendulum and still resulted to an inelastic collision. Determine the speed of the wooden block immediately after collision.
C. At what height y will the wood block pendulum rise after the collision? Express your answer in terms of the object masses and the velocity of the bullet.
D. Suppose that we fire a bullet with mass m=10g at a speed of Vb= 400 m/s into a wooden block with mass M=5.85kg and suspended by a taut string of length L= 75.0cm. By how much height y will the wood block rise? Express your answer in cm units
E. If we carry out the ballistic pendulum test described in D. On the surface of the moon where the acceleration due to gravity is 1.63m/s^2, how many times would the measured height differ from what is obtained on the surface of the earth?
i already have answers for A and B (though im not sure if theyre correct) and currently working on C
yeah so
this is combined mass
and initially we have maximum kinetic energy
and no potential
and we transfer all of that kinetic into potential
giving it new height y
that is where the reasoning behind this comes from I believe
so its just kinetic energy of both masses in the left hand side of the equation?
combined kinetic energy of the wooden block and bullet?
then on the right hand side its just potential? combined potential energy ?
combined mass yes , combined potential doesnt word right imo
the bullets kinetic energy is responsible for moving (m+M)
and yes it transitions all kinetic energy to potential
at a maximum y
but i kinda dont understand why it will be merged on the initial states since only the bullet is moving and the wooden block is stationary still the collission didnt happen yet
well it starts moving the instant they collide
aka when they combine
that is your initial moment
final is at the peak y
ohh wait the question is what height will be wood pendulum rise after collission i see
so the initial is the very moment they collide
and the final is the heighest it will go
highest*
Okok i seee
for question D, it has a given value of 75 cm for the length a taught string, where will i plug that value in?
do i need to use trigonometry for this
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I need help to understand and get better at doing these questions
but is coted off on the right
if every mile have expence of 2.25, and 20 per hour
in 1 day it haved 50 mile per hour and the gas and truck maintence is 147.50
first we make the 2.25 per mile and add 20 per hour
wich 2.25*5 is 10.25
yes
now we add the 0 we removed giving 102.50
then add 20 with become 122.50
20 is per hour and 2.25 is per mile,
do u know wt the equations would be
wait
need make a system to dertime number of hours droved and the mile the truck drived
but 1457.50 is only for that one day he drives 50$ per hour I thought
?
and dont u mean g instead of m
ended?
yeah
use .close
.close
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can u put variable after a metric unit
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
35cmx for example
What do you want this to mean
And what's x
a variable
no you can't
well you can but you shouldnt
you shouldn't have the cm be in your problems at all tbh
but if you do you need some indication of multiplication that's not concat
concat?
concatenation
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How exactly do I figure out what to use for the starting guesses?
do I use a positive and negative number?
like 2 random numbers such as -100 and 100
I also set it to 0 first so i'm using
x^8 - x - 3
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Optimization Problem
"A cylindrical tank with a given volume V is to be made without a lid. The material for the bottom costs five times as much per unit area as that for the sides. What should be the ratio of the height to the radius for minimum cost?"
How do I solve this optimization problem? I have formulated an equation for its total cost:
C = 2πrhx + 5πr^{2}x
Have you tried defining some variable a = h/r and somehow differentiating w.r.t it?
No i haven't tried that but am I right for getting the cost function???
I've tried deriving h from the volume of the cylinder:
V = πr^{2}h
h = V / πr^{2}
Then substituting h into the cost function
and arriving at:
C = 2Vx/r + 5πr^{2}x
<@&286206848099549185>
i found a b and d but i need help with finding c and e
<@&286206848099549185>
yes
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,rotate 270
Most common angles are multiples of 0, 30, 45, 60, 90
u can refer to the unit circle to get their values in radians
but i dont have the common angles
in this case u can substitute the angle in radians 2π / 9
into the trig functions like sin(x), cos(x), or tan(x)
just do sin(2pie/9)
yepp
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hello
hi
just replace dt with x
and try to make a graph
it comes out to be something like this
is there anyway to do it without just plugging in smaller and smaller numbers for dt?
yeah that is what we call getting a limit of a function right
you plug in closer and closer values to 0
and see how the function behaves
hmmm okay
but this is a standard limit right
so its better to remember it rather than deriving it from time to time
samjha bhai?
u can also do it algebraically with lopitals I tjink
yeah but i'm tryna use it prove that the derivitave of e^x=e^x
so to take the derivatave of the top function i would have to know that already
oh yeah okay
$\frac{e^{dt}-1}{dt} \\$ $x=e^{dt}-1 \\$ $\ln\left(x+1\right)=dt\\$ $lim_{x\to0}\frac{x}{\ln\left(x+1\right)}\\$ $lim_{x\to0}\frac{1}{\ln\left(\left(x+1\right)^{\frac{1}{x}}\right)} =\frac{1}{\ln\left(e\right)}=1$
Combustion
for that you need to know the first derivative rule for limits
@hasty creek yo how did you do that?
the steps are there lol
I have three methods:
1.pinch theorem:1/(1-x)>e^x>1+x
2.Lhopital:0/0
3.taylor expansion
the last step depends on $lim_{x\to0}\left(\left(x+1\right)^{\frac{1}{x}}\right)=e$
Combustion
how did you do the third step?
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how can i show this limit doesnt exist? lim x->0, y->0 of sin(xy)/(x^2+y^2)
as this type of limit is in the form of f(x)/g(x) where lim of g(x) tends to zero but not the same for f(x)
hence we can say that limit of the given function in totality does not exist for x,y tending to 0
,rotate
by calculating the limit from two directions,and the results not same,we can prove that
for example:from y=x and y=2x
and the results is
0.5 not equal with 0.4
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An equipment consists of nine components, each of which will independently fail with a probability of p. If the equipment is able to function properly when at least six of the components are operational, what is the probability that it is functioning properly?
is p = 0.5 and q = 0.5?
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hi my question is find arctan(tan(3))
is the answer 3 - pi?
3 > pi/2
so if we subtract pi it is between [-pi/2, pi/2]
,calc atan(tan(3))
Result:
-0.14159265358979
oh so it is 3-pi
is the 3 degrees?
the question doesnt specify
oh okay then 🙂
.close
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Hey gang, so we're doing some trig and I got this question correct except for tan, I'm not sure why you can turn "1 over radical 3" into "radical 3 over 3".
It is just equivalient fraction. Multiplication by sqrt(3). Basically it gives an idea of the value of 1/sqrt(3). E.g. take 1/sqrt(2). Multiply top/bottom by sqrt(2) => sqrt(2)/2. We know that sqrt(2) = 1.4 approx. Therefore we can say that 1/sqrt(2) = 0.7 approx
Ohhhhhh yeah because you can't have radicals on the bottom of a fraction, so you have to multiply the top and bottom by the radical to get rid of it.
I forgot lol. Thank you!
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How do I do this
Do you know the formula for linear approximation?
What have you got?
its 1-3/4(x-3)
but idk what to do from there
I cant find any resources on this either
Check the hint
(3.01)^2 is given as 9.06
So what happens if you normally plug 3.01 into the f(x) function?
oh shit
👀
you get sqrt(4.06)
Yup
Which means?
so I just plug 3.01 into x now in my linearized formula?
Alright
I think that's not correct
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which is the correct notation, $x = \varnothing$ or $x \in \varnothing$
FungusDesu
likewise, which is the correct notation, $x = \mathbb{R}$ or $x \in \mathbb{R}$
FungusDesu
an explanation would be helpful
What is x?
a variable
what about the empty set? it doesnt make any sense either to say something belongs to an empty set, since there isnt anything in there in the first place
Yeah are u trying to write solutions to an equation?
FungusDesu
what is S^R
Adam Chebil
It means the set of solutions in R is equal to empty set
Or simply write: no solutions in R
Adam Chebil
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well, you raise it to the nth power so, the value in the parenthesis is just a bit greater that 1, and since n is so large, it approaches e^a
don't think about this one as plugging in infinity, because you cant do that and the value is going to be just a bit greater than zero for large values of n, and when you add 1 to that and exponetiate n times you get e^a
shii.... thats when my knowledge ends lol
Well, there is a flaw in your argument.
The difference is in your expression, you are applying the limit both at the denominator n and the exponent n at once.
1^infinity is indeterminate
While, in the images, you are doing it separately.
So, you can not use association on it.
It is right that $\lim_{n\to\infty}{1^{n}}=1$
Anbit
But, as this user has stated 1^inf has no meaning. So, that argument does not work.
After applying the power rule, you are getting 1^inf right?
It is indeterminate.
You can use this rule when n is finite
not when n is infinite
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x + 1/4 (1/x) = 1?
Let the fraction be $x$, the reciprocal is $\frac{1}{x}$. One quarter of the reciprocal is $\frac{1}{4}\times\frac{1}{x}$. The sum must be one. So to determine the fraction, just solve for $x$ in $x+\left(\frac{1}{4}\times\frac{1}{x}\right)=1$.
SWR
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how do i do part c?
Looks like your net forces are gravity, and drag (going in opposite direction). So $F_{\text{net}}=mg-\alpha v$
SWR
Use Newton's second law to get $ma=mg-\alpha v$
SWR
Then you have the differential equation $\ddot{x}=g-\alpha \dot{x}$
SWR
Have fun with your differential equation.
Is that dog yours
Lol

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$\int e^{-|x|} ,dx$
Slowaq
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hi
hi
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Can you explain me the idea of branch cut in argz?
If i choose (0,2pi]
i can see that, value of argz little above positive real axis is close to 0
and below positive real axis is close to 2pi
<@&286206848099549185>
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didn't you ask this a while back and someone answered it too?
use chain rule
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Hi,
If i have a biased coin with 60 percent chance of head and 40 percent chance of tail and flipped 100 times, what would be the range of heads I would get?
...0-100?
you could get 0 heads or all 100 heads
on averge though
Youd "expect" to see 60 heads but that doesnt mean you necessarily have to get 60 heads when you flip 100 times
like you said i can get any no of heads but I want to know the range of average in which 60 percent of heads will get me.
Oh so maybe you mean to build a confidence interval?
ye thats it like i could get 40 heads or maybe 70 heads, and i want to know how to find that interval
ok give me a sec to think about it
Do you know about the binomial distribution?
Flipping a coin 100 times is a binomial distribution with $n=100$
and if treat flipping heads as a success, we have $p=0.6$ and $q=0.4$
Most of our possibilities should land "roughly" within two standard deviations of the expected value
So we could create an interval where we are most likely to see the number of heads this way
okay
The expected value of binomial is $np$ and the standard deviation is defined to be $\sqrt{npq}$.
so we should be able to use the formula $np \pm 2\times \sqrt{npq}$ and sub in numbers to get a reasonable upper and lower bound
I'm not sure if that makes sense to you or not 🙂
it does im just takimg some time
60 plus 2X 4.9
60 minus 2 X 4.9
is that correct?
yes
tysm i get it now
I get about $50$ as a lower bound and $70$ as an upper bound
and this should be valid "roughly" 98% of the time
so 2 sd is 98 percent?
Correct, I am loosely using the 2SD ~ 98% rule
okay got it👍
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Bruh
bruh
Idk how to do this shit don't ping me for it 😭
High school algebra with a bit of trig on the side
I can help but I gtg
bruhh
the why mesg
you can simplify the expression in the () using the sum to inf GP formula
what is the formula
if a, ar, ar^2, ar^3, ...... inf are in gp.
the sum of all those terms is a/(1-r)
in the (cos^2 + cos^4 + cos^6 + .... inf)
a is cos^2 and r is also cos^2
anything the uni teaches me
oh
gender studies?
bro, they do offer that course. 😂
i never would want to know wut they teach in that though
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Hi. Just wanna check that these equations are equal
only if v2=v and v1=0
should it be
Ek = 1/2m(v2-v1)^2 ?
i've never seen the second form
hmm
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did i do this correctly ?
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How is Fourier transform defined for a matrix in M_n(R) (n.n matrix)?
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What is the standard form of the polynomial p(x)= 4x^2+2?
idk, is it even a thing ?
do you have an example where ppl are talking about that or are you just wondering ?
just wondering
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hi guys i should check if this is a linear mapping
Please don't occupy multiple help channels.
is it?
oh ok
another question
generally
when i have a linear mapping
f(0) = 0
is this always true?
Yes, this it a requirement from linearity
has to be
What does linearity say about f(0+0)?
Yep
So we have that f(0)=f(0+0)=f(0)+f(0)
And so f(0)=f(0)+f(0)
Can you use this to determine what f(0) must be?
hm lemme check
for this to be true
f(0) = f(0) + 0
therefore f(0) = 0?
Yep 
noice
can i send you the scalar property too?
Hmm
i really thought from first view that this would be a linear mapping
but it isnt
does someone has an intuitive explanation
g(x+y) = 2(x+y) + 5 /= g(x) + g(y) = 2x + 5 + 2y +5 = 2x +2y + 10
you have to prove this:
$g\left( \alpha\cdot x+\beta\cdot y \right)=\alpha\cdot g\left( x \right)+\beta\cdot g\left( y \right)$
Joanna Angel
start from left side and reach right side
but it fails on the first condition
g(x+y) = 2(x+y) + 5
is not the same as
g(x) + g(y) = 2x + 5 + 2y +5 = 2x +2y + 10
therefore it cant be linear?
it's just that the "linear algebra" linear mapping has a stricter meaning than the usual way ppl use linear
yes
oh
you need y(0) = 0 in a "lin alg" linear mapping in particular
@sharp harness you have other questions or no?
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would $S: \mathbb{R} \rightarrow \mathbb{R}, S(x) = x^{2}$ be fine as it is surjective every value is mapped in the co-domain but it is not injective i.e $S(-2) = 4 \land S(2) = 4$
luke1
so the inverse would be
many to one
i mean
one to many
since the original function is many to one
This is not surjective
Yeah, codomain shouldn't be R
R+ ?
$\mathbb{R}_{\geq 0}$?
ye
not that R though
Jelle
yes
Or any set at least 2 elements into a set with one element
S: {1,2,3} $\rightarrow$ {1}
Gapi
S(x) = 1
oh i guess thats easier
Its simpler
but $\mathbb{R}_\geq 0$ is fine right
luke1
Yeah
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I have f(g(x)) = h(g(x)) for all x.
f,h are bijective functions from X to X.
g is a bijective function from Y to X
Can i say that f = h?
If $f : Y\to X$ and $h:Y\to X$ are two functions, you can say that $f=h$ when $f(y)=h(y)$ for all $y\in Y$.
SWR
So I just need to say that g is surjective?
seems like it, yup
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heu guys,i got stuck here while solving i just don't know ehat happens with x-pi/3->0
HI
do i move the -pi/3 so it would be x->pi/3 and then it would be 0/0 and do lhopitals rule?
Hello Sir
ill help
please
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Discrete math:
could someone tell me how one would solve this (with steps?)
the answer is n=3 with witnesses k=1 and C=4; but with the method i'm using i get n=4
my current method:
$3x^3 + (log x)^4 <= 3x^3 + x^4 <= 3x^4 + x^4 = 4x^4$
so n = 4 with witnesses k=1 and C = 4
Jody
right, should be noted that we're using log 2,
im not all too familiar with logarithm (my previous highschool never taught it) so there may be some simple logarithm inequality that will allow me to show that (logx^4) <= x^3; but i dont know nor do i know if its true or provable?
for x >= 1
log(x)^n is polylogarithmic, which is below linear
For any n > 1 (n = 1 makes it just logarithmic)
ah, so log(x)^n <= nx?
Nel
log(log(x)) grows more slowly than log(x), obviously
So there exists x_0 such that x > x_0 => log(x)^n < x
oh im following now
does that apply for a function f(x) as well?
log(f(x))^n < x for large enough x?
Of course not, just take f(x) = 2^x
log(f(x))^n < f(x) though, if f is increasing (I think that's a sufficient condition)
(for large enough x, again)
log(x^n) ?
yea
That's just nlog(x), so O(log(x))
i definitely have to go back and properly learn logarithm
but this makes sense
thanks a bunch
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How do I graph this?
I'm supposed to pick some x's and replace them with x
I'm not sure how to find which x's though
The x's I have currently are - 2.5 and -3.5
f(-3.5) = 2
How do I find what x's to pick other than -2.5 and -3.5
absolute value is just a V shaped graph. you know where the function = 0, so now you just need the slope, you make the V shape pointing at the 0 and use the slope to draw the rest.
@summer hemlock Has your question been resolved?
My teacher wants me to find the x's though
what x's? there are technically infinite x's to find.
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Could someone help me out with this?
If the bases are the same, you can just equate the exponents and solve for x from there
Lex1729
$$6x\log \left(7\right)=20\log \left(7\right)+4x\log \left(7\right)$$
Lex1729
$$x\left(6\log \left(7\right)-4\log \left(7\right)\right)=20\log \left(7\right)$$
Lex1729
alphaGengar
.
Why?
because you want to cancel the 7
so you have just the exponent stuff
recall that
log_x(x) = 1
so log_7(7) = 1
Yes
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Check your endpoints. That is, what is the function doing along the lines?
The first line is y = x - 4
mhm
so if I plug that into 11x-5y
then I get 6x+20
if I plug in -x-4 then I get 16x+20
if I just plug in 4 then I have 11x-20
but then what do I do with that? @placid zinc
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is the question correct?
cuz when k 1 or even 2, it’s not divisible by 19
@drifting seal Has your question been resolved?
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yup
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is that true
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Hi there, I am having a hard time wrapping my head around applying Richardson extrapolation in my homework assignment. I don't even know where to begin....
Okay well, maybe I do know where to start: I need to compute Q0, however I need a small n and a large N for that, and I'm not sure what they are in this case
I’ve gotten to this point
However, I'm not 100% sure that I even need it in sum form...
<@&286206848099549185>
Perchance 0 is an unlucky number....
Yeahs
Yeahs?
Wqcuzbi?
Uh ohhh
Uh ohhh
Well, at least I have someone to talk to
Wefechu
However, I imagine taking up a help channel is not ideal, so Ima close it
Good luck, random person
.close
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Bbh I am not sure if I will be in a relationship or not but if you can
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find cos(x) and tan(x) if csc(x) = -sqrt(6)/2 and cot(x) > 0
csc(x) isn't the same as 1/cos(x) though
how would i appraoch this problem
Can you recall what csc(x) is?
1/sin
Right, so you have sin(x) = -2/sqrt(6)
yes
Are you solving for x in [0, 2pi) or are you looking for the general solutions?
general
Just use (-1)^k arcsin(-2/sqrt(6)) + pik where k is an integer then
oh wait actually
what is the difference between general and solving for x
This was all the problem said
Oh wait would cos be sqrt2/sqrt6
Yes
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putridplanet
$-cos(x)+cos(-x)$
putridplanet
now what
Recall that cosine is an even function
wdym
cos(-x) = cos(x)
why
Changing the sign of the angle on the unit circle is equivalent to reflecting your point around the x-axis
That, however, does not change its x-coordinate
ok
Hence cos(-alpha) = cos(alpha) for all angles alpha (I named it alpha here not to confuse it with the x coordinate)
