the amount before the 9.2% percentage change??
#help-0
faint monolith
cyan drum
what is that representing
faint monolith
the total household water usage per day
cyan drum
did you already convert to a year
cyan drum
yeah then what you got is correct
unkempt compass
my answer isnt matching up with the answer key. can someone tell me where i went wrong?
lone heartBOT
my answer isnt matching up with the answer key. can someone tell me where i went...
@unkempt compass Has your question been resolved?
unkempt compass
<@&286206848099549185>
unkempt compass
tysm, before you go is that the only problem with it?
gray isle
stuff before that seems ok at a glance, update the rest and see what you get
unkempt compass
stuff before that seems ok at a glance, update the rest and see what you get
it matched up. ty again!
.close
tough dawn
I need help with these problems
lone heartBOT
I need help with these problems
viral oracle
a. 8 = 2^3
b. use property
c. ln both sides
d. use definition of logarithm
e. use property
f. use property
g. let e^x = t and then solve the quadratic
lone heartBOT
a. 8 = 2^3
b. use property
c. ln both sides
d. use definition of logarithm
e. us...
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
viral oracle
?
tough dawn
when you say use property, are you referring to logarithm properties?
north perch
i think yes
tough dawn
oh ok I'm not very familiar with those, still working on them
brazen iris
lone heartBOT
noble frost
AOB ≡ BOC
brazen iris
oh so thats it right
noble frost
yes
brazen iris
ohk thx
noble frost
sas
brazen iris
Do we need to use the y=mx+b formula?
lone heartBOT
Do we need to use the y=mx+b formula?
real glen
have you learnt pythagorus?
brazen iris
i have
real glen
use pythagorus with x2 - x1 and y2-y1
brazen iris
.close
lone heartBOT
brazen iris
thx
lone heartBOT
Available help channel!
real glen
np
real glen
.close
rocky kayak
lone heartBOT
north perch
do you have problem with step 5
rocky kayak
do you have problem with step 5
no matching them together
north perch
do u know all the properties that are mentioned in this image
rocky kayak
no not really i think step 5 is all angles on a straight line add to 180*
north perch
thats correct
do u know that alternate interior angles are equal
do u know what alternate interior angles are
north perch
?
rocky kayak
dw but no i do not know what alternate interior angles are i just know what interior angles are
north perch
u can search it up on the net
slow canopy
lone heartBOT
slow canopy
Can someone help me understand why x sub 0 becomes 0 here?
in the bit where it says x_i = x_0 + i * delta x
wouldn't x sub 0 mean the right endpoint of the first interval, and thus equal 2/n?
or does it mean the right endpoint of the 0th interval, and thus the left endpoint of the first?
I get that the interval in question is [0, 2], but if it was, say, [5, 10] would x_0 be 5?
worn fox
they're writing their intervals like [x_(i-1),x_i]
so the left point of the first interval is x_(1-1) = x_0 = 0
true dew
lone heartBOT
true dew
How can I prove that A is bounded
zealous lichen
it's not though
lone heartBOT
@true dew Has your question been resolved?
true dew
it's not though
According to the exercise it should be
true dew
It's a question from a test
zealous lichen
ok
true dew
Nor upper bounded?
true dew
Can't we suppose that n is odd and find its inf and sup
Then suppose that n is even and do the same thing
And take the common inf and sup from case one and two
high cargo
<@482092850197168129> Has your question been resolved?
@true dew make sure to answer this
zealous lichen
the subsequences are bounded but not A
true dew
But If the both cases are bounded , A should be too
zealous lichen
what no
if subsequent is not bounded then A is not bounded
you can't say if a subsequent is bounded then A is bounded
example: let a_n=(1,2,1,4,1,8,1,16,...)
the subsequence (1,1,1...) is bounded but not a_n
zealous lichen
no problem
lone heartBOT
@true dew Has your question been resolved?
native venture
lone heartBOT
lone heartBOT
@native venture Has your question been resolved?
native venture
<@&286206848099549185>
native venture
<@&286206848099549185>
lone heartBOT
@native venture Has your question been resolved?
native venture
<@&286206848099549185>
native venture
<@&286206848099549185>
lone heartBOT
@native venture Has your question been resolved?
native venture
<@&286206848099549185>
lone heartBOT
@native venture Has your question been resolved?
ancient saddle
Hello. All your steps look correct 🤔 . Remember that in the end you want to find sin(theta) = 1/3, so it would be better if you try finding sin(theta) in terms of r and h, rather than tan(theta)
spare fern
$$\frac{37}{3}m^3-8m=117$$
lone heartBOT
$$\frac{37}{3}m^3-8m=117$$
ocean sealBOT
Lex1729
spare fern
$$37m^3-24m=351$$
ocean sealBOT
Lex1729
spare fern
?
spare fern
you got a big one over
What do you mean?
empty moth
How may we be of help
^^
spare fern
I'm just curious what you were reffering to, did I type it wrong?
high cargo
What do you mean?
He doesn’t mean, he nice
high cargo
I'm just curious what you were reffering to, did I type it wrong?
No don’t worry about it lol, just post your question
spare fern
I'd like to know...
high cargo
I think he was referring to how those numbers are quite large for a polynomial equation
spare fern
Oh ok
I was just wondering If I am able to do this operation?
$$m\left(37m^2-24m\right)=351$$
high cargo
Yes you may do that
spare fern
$$m\left(37m^2-24\right)=351$$
ocean sealBOT
Lex1729
high cargo
$$m\left(37m^2-24m\right)=351$$
Yeah you corrected it I forgot to check the 24m before
spare fern
Oh, why is that?
high cargo
Because then one of the two factors must be 0
spare fern
Oh ok
high cargo
ab=0 means that a and/or b is 0
but ab=10 doesn’t mean that a and/or b is 10
Can m be any real number?
spare fern
**Lex1729**
After integration I get this
empty moth
$$(2x-m)^2=4x^2-4mx+m^2$$
wait shouldn't ie be negative
$(2x-m)^2 = 4x^2 - 4mx + m^2$
high cargo
Right
high cargo
It’s horrible that I’m uncertain of how to do this despite this literally being what I had to do in school over the last 2 months
$\frac{4}{3}x^3 - 2mx^2 + m^2x+C$
ocean sealBOT
FirstNameLastName
spare fern
$$\left[\frac{4}{3}x^3-2x^2m+m^2x+m^2x\right]\lim m->2m$$
ocean sealBOT
Lex1729
spare fern
I know it's incorrect notation (not sure how to type it) but the limits should be from m to 2m
high cargo
Where did that second m^2x come from
ocean sealBOT
Lex1729
high cargo
$$\left[\frac{4}{3}x^3-2x^2m+m^2x\right]^{2m}_m$$
ocean sealBOT
FirstNameLastName
high cargo
Let’s go with that notation
Plugging in 2m and m for x
We get only m^3 values
So the result should be a lot more simple than what you did earlier
Calculate that and post the result including calculation, I’ll have a look
spare fern
$$\left[\frac{32}{3}m^3-8m^2+2m^3\right]-\left[\frac{4}{3}m^3-2m^2+m^3\right]$$
ocean sealBOT
Lex1729
spare fern
This was after simplifying though
ocean sealBOT
FirstNameLastName
high cargo
You see why that is?
spare fern
$$\left[\frac{4}{3}\left(2m\right)^3-2\left(2m\right)^2m+m^2\left(2m\right)\right]-\left[\frac{4}{3}\left(m\right)^3-2\left(m\right)^2m+m^2\left(m\right)\right]$$
ocean sealBOT
Lex1729
spare fern
Oh I see now
$$\left[\frac{32}{3}m^3-8m^3+2m^3\right]-\left[\frac{4}{3}m^3-2m^3+m^3\right]$$
ocean sealBOT
Lex1729
spare fern
$$\left[\frac{14}{3}m^3\right]-\left[\frac{1}{3}m^3\right]=117$$
ocean sealBOT
Lex1729
spare fern
$$\frac{13}{3}m^3=117$$
ocean sealBOT
Lex1729
spare fern
$$13m^3=351$$
ocean sealBOT
Lex1729
spare fern
$$m^3=27$$
ocean sealBOT
Lex1729
high cargo
Seems so 🙂
spare fern
What about this?
$$\int _{-2}^2\left[9-x^2\right]-\left[kx^2-x^2\right]\cdot dx$$
$$\int _{-2}^2\left[9-x^2\right]-\left[kx^2-x^2\right]\cdot dx$$
ocean sealBOT
Lex1729
high cargo
I’m not sure you should just read off the intersections of the two functions, but if they’re correct then the approach should work
spare fern
Yeah I got the value of k to be 2.25
I've got one more question
I keep getting my answer to be 3, although this is incorrect
$$\int _{-1}^2-x^2+2+x\cdot dx$$
ocean sealBOT
Lex1729
spare fern
$$\left[\frac{1}{3}x^3-2x+\frac{1}{2}x^2\right]_{-1}^2$$
$$\left[\frac{1}{3}\left(2\right)^3-2\left(2\right)+\frac{1}{2}\left(2\right)^2\right]-\left[\frac{1}{3}\left(-1\right)^3-2\left(-1\right)+\frac{1}{2}\left(-1\right)^2\right]$$
$$\left[-\frac{1}{3}x^3-2x+\frac{1}{2}x^2\right]_{-1}^2$$
ocean sealBOT
Lex1729
spare fern
$$\left[\frac{1}{3}\left(2\right)^3-2\left(2\right)+\frac{1}{2}\left(2\right)^2\right]-\left[\frac{1}{3}\left(-1\right)^3-2\left(-1\right)+\frac{1}{2}\left(-1\right)^2\right]$$
$$\left[-\frac{1}{3}\left(2\right)^3-2\left(2\right)+\frac{1}{2}\left(2\right)^2\right]-\left[-\frac{1}{3}\left(-1\right)^3-2\left(-1\right)+\frac{1}{2}\left(-1\right)^2\right]$$
<@&286206848099549185>
After integrating I get this:
$$\left[-\frac{1}{3}x^3+2x+\frac{1}{2}x^2\right]_{-1}^2$$
ocean sealBOT
Lex1729
spare fern
$$\left[-\frac{1}{3}\left(2\right)^3+2\left(2\right)+\frac{1}{2}\left(2\right)^2\right]-\left[-\frac{1}{3}\left(-1\right)^3+2\left(-1\right)+\frac{1}{2}\left(-1\right)^2\right]$$
ocean sealBOT
Lex1729
lone heartBOT
@spare fern Has your question been resolved?
lone heartBOT
@spare fern Has your question been resolved?
fickle sandal
,w (-8/3+4+2)-(1/3-2+1/2)
ocean sealBOT
fickle sandal
you said you got 3?
trim laurel
Hello,
I am a young student, who is super into math and a time ago I thought of a question: "If you have a non-collinear number of 2D points, how can you calculate the number of triangles you can make?". I thought a lot about the question and I created a simple "algorithm" to calculate the number of triangles quickly and efficiently and I wanted to turn that into a equation. I didn't google any solutions to the problem, so that I can really make it by myself. And I came up with this. (i is the number of the points)
trim laurel
,, k = \sum_{n=1}^{i-2} [i - (n+1)] * n
ocean sealBOT
SuperPro
trim laurel
I don't think that it's the most efficient and shortest equation that I could've created, but I have 2 questions.
- I tried it a few times and it really worked, can someone confirm that that's a valid equation to that problem?
- Is there any simpler equation that solves this same problem?
Thanks in advance!
woven hedge
appreaciate your life story and it's really cool that you are into math
the answer is rather simple and one phrasal but it'd be boring
so i'll write more
the important thing about math is not knowing formulas and stuff, and rather is thinking procedurally and logically about your problems
that is, given certain knowledge, you can solve n sorts of questions
and the trickiest part about mathing imo is problem analysis, because sometimes u dont really know what to do
in this case, i'll try to solve your thing methodically, for education purposes, i guess
as you seem interested by the process
trim laurel
as you seem interested by the process
Yes I do!
woven hedge
If you have a non-collinear number of 2D points, how can you calculate the number of triangles you can make?
first of all, i'd imagine a grid of points
since you want to make triangles, you'll need at least 3 points
so u'll take it into consideration
mathematically (i don't know how to use latex without the computer licking my face sorry), you would write
p ∈ N | p > 2
p is the number of points
as you cant have half points, p is natural and p cant be lower than 3
now the deal is, as you increase the number of points, you start creating more intrinsic patterns with those points
forming more triangles
assuming that you are stuck here, you have a few options:
1 - do a few by hand and see if u find some pattern
2 - if it's too dificult, simplify your problem to a simpler one
you can try setting up a pattern to the grid, instead of randomly
as for example, the points follow the path of a circle, instead of being in a grid
woven hedge
as for example, the points follow the path of a circle, instead of being in a gr...
this is a famous problem in mathematics and it's used to proof the solution in a lot of schools
points around a circle that form a triangle in n ways
empty moth
p is the number of points
Lol
For my graph theory and combinatorics class
I have to use latex
For my hw
empty moth
but i use lyx
Huh
woven hedge
2 - if it's too dificult, simplify your problem to a simpler one
3 - you can simplify your problem, mathematically
woven hedge
It’s not that serious
i most definetly will
woven hedge
3 - you can simplify your problem, mathematically
this is more abstract but this is the way that the things are done, most of the time
when u really dont know what you are dealing
so in your case, you'd do
given a arbitrary set p of points
i have to find a formula that results in the combination of points that forms a triangle
so, the first steps would be
i dont want to write the formula so i'll explain first
u have three slots of points
xxxxx xxxxx xxxxx
this is the number of points you can use to form a triangle
lets suppose you have 10 points
so, for the first point
you could choose all of them
so 10 xxxx xxxx
in the second slot, you cant create a point with a point that u have already selected
so u have 9 to choose from
and so on
resulting in 10 - 9 - 8
or 10! / 7!
this does not work
if you test
woven hedge
but it does not work yet
but it works for a lot of cases
this method is called arrangement
in english
ig
this is used if and only if your set is subject to ordering
trim laurel
This is a kinda off-topic question, but what is your main language?
trim laurel
Yeah it is
woven hedge
thats life
someday hopefully i'll move to uk
and it'll get better
in brazil it's kinda hard to train
because no one here speaks it
lol
trim laurel
Lol
woven hedge
either way
if i type something wrong correct me pls
i'd greatly appreciate
it's not inconvenient at all
trim laurel
Ok
woven hedge
this is used **if and only if** your set is subject to ordering
^
this means: if the ordering of your set matters
example:
how many numbers with three different numerals can we make with the numerals 1,2,3,4,5,6,7,8,9
in this case, the order matters
because 123 is different than 213 and 321
etc
so we use the arrangement
idk
this thing that i explained
the formula is n arrange p = n!/(n-p)!
in this example we need 9 arrange 3
so 9!/(9-3)! = 9!/6! = 9 . 8 . 7
omg fucking discord
that equals to 504
in your question, however, ordering does not matter
so we have to adapt this same formula
because a triangle composed of the faces ABC, CAB, BCA etc
they are all the same
so we have to create an "exclusion" for these
you should note that for every triangle, in your case, are 6 duplicates
if you generalize, for every N faces in a polygon formed by 2D points, there will be N! duplicates
if you generalize EVEN more
for every combination of N subsets, there will be N! duplicates
so what you take from this is, when you find your problem, always search for generalizations
the final formula is called combination
or x choose n
idk
x choose n = x!/((x-n)!-n!)
so finally, the one phrase answer for your problem is:
combination -> if you have 10 points for example:
10 choose 3 = 10!/(7!*3!) = 120
with 10 points, you'd be able to make 120 triangles
but i hope you took something off of it
woven hedge
np
trim laurel
but i hope you took something off of it
I did!
woven hedge
i hope my english wasnt a big trouble for you lol
i'm really trying to get better
i want C1 in the english exam thing
but my writing is really bad
trim laurel
I have seen much worse
trim laurel
Your writing is pretty good actually
woven hedge
:D
trim laurel
i want C1 in the english exam thing
I hope that you'll get it someday!
woven hedge
me too lool
these literature texts are rlly hard for me
specially the poems and shit
and they add like 10 at the exam
but it's off topic
is your problem solved?
woven hedge
:)
trim laurel
.close
manic plank
How to solve $\arctan(\frac{1}{2}) + \arctan(\frac{1}{3})$ ?
ocean sealBOT
Determinator
zealous ingot
let x = arctan(1/2) + arctan(1/3)
then apply tan to both sides
and use tan double angle formula
manic plank
Hmmm
zealous ingot
indeed
manic plank
so should I treat arctans as some angles
let's say, theta
that would make it a hell lot of easier
lone heartBOT
zealous ingot
nw
woven hedge
you can use this identity as well
arctan(x) + arctan(y) = arctan((x+y)/(1-xy))
oh its closed
nvm
zealous ingot
thing is which that you would still have to find out arctan(5/6)
tall topaz
It becomes arctan(1)
manic plank
I did the calculations, applied tangent and everything went smoothly from that point
wide onyx
lone heartBOT
zealous ingot
differentiate, equate the derivative to 0
you can use the first or second derivative test to see the behaviour of the point
wide onyx
you can use the first or second derivative test to see the behaviour of the poin...
i dint get
the derivative thing
zealous ingot
do you know how to differentiate a polynomial?
wide onyx
wdym by differentiate
zealous ingot
-b/2a is the minimum x coordinate of a quadratic function
okay nw maybe watch a recap video on derivatives
and then this question will become much easier
lone heartBOT
@wide onyx Has your question been resolved?
shut arrow
why does sqrt(x^10) need to be negative?
lone heartBOT
why does sqrt(x^10) need to be negative?
lost flax
shut arrow
got here first sorry 😭
shut arrow
why does sqrt(x^10) need to be negative?
is it because we're evaluating the limit for negative infinity?
zealous ingot
its for negative values, so substitute -x for x. then, (-x)^5 = -1^5 (x)^5 = -x^5 = -sqrt(x^10)
waxen turtle
lone heartBOT
cursive badger
so to complete the square
you have 4x^2-36x
that's (2x+a)^2-b for some a and b
if we expand that out again we get 4x^2+4ax+a^2-b
(so the a^2 and b cancel each other out like normal)
we now know 4x^2+4ax=4x^2-36x
so, very simply, a= -9
(and a^2=81, = b, so that a^2-b = 0)
waxen turtle
what
waxen turtle
Fr
cursive badger
well yeah
like look
[x^2+8x-7=0]
[(x+4)^2-16-7=0]
[(x+4)^2=23]
[x=-4\pm\sqrt{23}]
ocean sealBOT
Astral
cursive badger
when completing the square, we only care about the x terms
the constant doesn't matter, it'll end up in the root or it won't, it's a later problem
so we have 4x^2-36x yes?
waxen turtle
yes
cursive badger
we know 2x*2x = 4x^2 (since we want the first part in the parentheses squared to become our x^2 term)
so we want to find (2x+A)^2 that matches with 4x^2-36x
to find that, we simply expand
(2x+A)^2 = 4x^2+4Ax+A^2
the A^2 is a constant and we don't care about it right now, we just want 4x^2+4Ax to match with 4x^2-36x
so what is A then?
waxen turtle
Uhhhh -9
cursive badger
yes
so if we want to convert 4x^2-36x into some perfect square
we have 4x^2-36x = (2x-9)^2 + B
what is B, so that when we expand it out, both sides are equal?
waxen turtle
-81
cursive badger
yes
waxen turtle
Ez
cursive badger
because when we expand it out, we get 4x^2-36x + 81 + B, so 81+B = 0 to make both sides equal
SO
we start with
[4x^2-36x+81]
complete the square
[(4x^2-36x)+81]
[((2x-9)^2-81)+81]
ocean sealBOT
Astral
waxen turtle
No
cursive badger
hint: undo the outermost parentheses
since it's just addition/subtraction, the order doesn't matter
in other words, you can reduce farther to
[(2x-9)^2-81+81]
ocean sealBOT
Astral
cursive badger
does that look reducible to you?
cursive badger
yup
-81 + 81 is the same thing as 81 + - 81 or 81 - 81
addition/subtraction, order does not matter
ah I see but your answer wants no coefficient on x
waxen turtle
Fr
cursive badger
so we have
[(2x-9)^2+0]
yes?
ocean sealBOT
Astral
cursive badger
do you understand how we got here?
cursive badger
that's fair lol
well, anyways
your question wants an answer in the form A(x+B)^2 + C
waxen turtle
Fr
cursive badger
obviously, as per above, C = 0
waxen turtle
Uhh do I just cut that stuff in half
cursive badger
now, do you know how we would rewrite (2x-9)^2 as A(x+B)^2?
cursive badger
yup
well, almost
the 2 has to pass through the ^2
[(2(x-\frac{9}{2}))^2=(2)^2(x-\frac{9}{2})^2]
ocean sealBOT
Astral
cursive badger
make sense?
cursive badger
why would it?
you agree, -9/2 times 2 is -9
if we "put the 2 back" the negative will stay negative
waxen turtle
Oh
cursive badger
we're just moving a two away, nothing with signs is changing
cursive badger
that looks right to me
wait no
remember? I said how the 2 has to pass through the ^2?
cursive badger
**Astral**
up here, it's a 2^2 on the front, not just 2
short notch
split spire
use the formula in which median and triangle side relate
short notch
Herons formula?
split spire
median divides the side of triangle in half
split spire
Herons formula?
yes
split spire
oh
lone heartBOT
But i had some difficulty during its calculation
Show your work, and if possible, explain where you are stuck.
lone heartBOT
@short notch Has your question been resolved?
north perch
could u show your calculation
lone heartBOT
lone heartBOT
Available help channel!
waxen turtle
lone heartBOT
waxen turtle
Should I set x^2 to a single variable
Uhh I got no real solution for that😭 😭
Did I mess up expanding
Oh wait
I didn't add the -4x^2 and -10x^2
waxen turtle
Uhh I got no real solution for that😭 😭
I messed this part up either way when making it 💀 💀
Anyways
I got no solutions again😔
Idk wat to do
<@&286206848099549185>
Yo wait
I messed up
AGAIN
Brb
north canopy
bruh
north canopy
show ur work too please
waxen turtle
ITS 7 AND 3 RIGHT
north canopy
3 works when plugging in
north canopy
7 doesnt
waxen turtle
I got 5 and 9
north canopy
both dont work
waxen turtle
Or did i
north canopy
show ur work
waxen turtle
show ur work
north canopy
thats not all steps
north canopy
show how u expanded
north canopy
this is hard to understand
north canopy
i cant read it, and its not even simplified
loud oracle
Hi
lone heartBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
north canopy
delete that
alpine sable
delete that
Done!
north canopy
Instead of just x^2
no u dont have to
waxen turtle
Then how get to answer fr
north canopy
well i would tell u but i have no idea what u did because u stopped midway and sent an img with 3 steps on it
i have no idea whats in ur brain dude
waxen turtle
well i would tell u but i have no idea what u did because u stopped midway and s...
WDYM
Which part is confusing
north canopy
this
north canopy
well then redo it and send it
waxen turtle
But I got like x^4-4x^2+45
north canopy
that sounds wrong
waxen turtle
😔
north canopy
ok then that looks right
waxen turtle
Then I turned x^2 into p
waxen turtle
Wat
waxen turtle
Fr
north canopy
u found p
waxen turtle
OH
north canopy
now plug those values into p=x^2
north canopy
and u get 4 answers
waxen turtle
√5
waxen turtle
So cool
north canopy
and u forced a sqrt
waxen turtle
Ty
waxen turtle
see thats all i needed, j a lil bit of ino
Plz ayudar
I think I messed up😭 😭
<@&286206848099549185>
Oh I see
I messed up
-b
On the quadratic formula
Brb
Fixed it
It's D right
alpine sable
It's D right
that's what she said
waxen turtle
RAAAA
alpine sable
lemme see
alpine sable
it's either 7 or 3
alpine sable
I got x = -2 ± √34 / -3
alpine sable
Should I try it fr
couldn't hurt
alpine sable
whatchu get
waxen turtle
Well D is the only one
That matches -12x and the other sude
Side
IT WAS CORRECT
YESSS
waxen turtle
whatchu get
Is this correct
@alpine sable
I don't trust myself
I don't know what's real
waxen turtle
<@&286206848099549185>
I don't think it's possible to get this wrong
But I'm so scared
This is the last question
alpine sable
I don't trust myself
Trust yourself
waxen turtle
lone heartBOT
waxen turtle
How do I find this without making a long table😭
craggy forge
Y=mx+b
Should be yea
Do u know how to get it in that form
This is solving linear system
waxen turtle
Oh
waxen turtle
At 85 seconds
They have the same
They will have 405 space left
So the answer is 405
Right
waxen turtle
Wat
waxen turtle
It wanted us to use dimensional analysis 💀
waxen turtle
.close
lone heartBOT
craggy forge
.close
Yea u can use that but the one I should is easier (I mixed up the 3 and 255, it should be 255/3)
lone heartBOT
Available help channel!
waxen turtle
lone heartBOT
waxen turtle
The answer is F right
F(3)=2-?(3)=1.25
I guess the slope is -.25
But its not given
I think it's F
slender gull
I guess the slope is -.25
That's right, yeah.
proper saddle
it says to post the querry on channel 0
waxen turtle
That's right, yeah.
Is the answer F
slender gull
You have to pick one of the available channels.
slender gull
Is the answer F
no.
waxen turtle
😔
slender gull
The initial point is y intercept, isn't it?
waxen turtle
Ohhhh
slender gull
(because x = 0)
craggy forge
Should be
slender gull
yeah
slender gull
Yes.
waxen turtle
lone heartBOT
alpine sable
flip
lone heartBOT
@waxen turtle Has your question been resolved?
lone heartBOT
@waxen turtle Has your question been resolved?
spare vessel
Guys Can you help me I really need help really bad so here the story we need to report this problem what this problem is still not tackle to us idk what my teacher thinking but here's the problem it's hard for me if you can just help me I appreciate it
Jane invests $5,000 annually in a simple annuity that earns interest at an unknown rate. After 10 years, the future value of the annuity is $80,000. Determine the annual interest rate. I know how to get the future value and present value but when it comes to rate I don't know how to get it. I tried searching everywhere YouTube, Google, I cant find any example if someone know how to do it please help🥺
royal bay
Present value * (1+interest rate)^time = future value
In this case we know that present value=5000, future value=80000 and time=10. Solve for the interest rate.
ashen copper
Guys Can you help me I really need help really bad so here the story we need to ...
since we know PV = 5000 and FV = 80000 and the amount of years t = 10 that means that we have a formula: 80000 = 5000 * (1 + r)^10
now we devide both sides by PV (5000 in this formula)
we get 16 = (1+r)^10
now we take the 10th root of both sides so we can isolate 1 + r
this becomes 16^1/10 = (1+r) -> 1.6 ≈ (1+r)
now since we want r and not 1+r we just subtract 1 from each side
this becomes r ≈ 0.6
so the annual intrest rate is approximately 0.6 or 60%
i hope i could help
spare vessel
Oh thank you so much🥺🥺🥺🥺🥺
ashen copper
o wait i just noticed something
spare vessel
it doesn't matter even not exact rates? right?
spare vessel
it doesn't matter even not exact rates? right?
nvm HAHAHA
spare vessel
o wait i just noticed something
what it is?
ashen copper
i said 16^1/10 = (1+r) ≈ 1.6 which was a mistake
since its not 16^1/10 = (1+r) ≈ 1.6 but 16^1/10 = (1+r) 1.6 ≈ (1+r)
16^1/10 = (1+r) and 1.6 ≈ (1+r) are approximately the same thing and x = y = v in this formula cant exist
dont worry, i corrected my mistake
so it wont be in the original explanation
spare vessel
now since we want r and not 1+r we just subtract 1 from each side
btw what do you mean here from each side? I don't get this part
How it become 0.6?
spare vessel
Ohhh
ashen copper
we need to subtract 1 from both sides
because r = 1.6 isnt correct
since there is still the 1 that we didnt subtract from the 1.6
thus the answer for r = wouldnt be correct
spare vessel
Tysm
ashen copper
np
spare vessel
I really appreciate it our teacher didn't teach it yet to us😭
ashen copper
lol
ashen copper
again
np
just take the time to actually get a hang of how to get to those values
and youre mostly done with the topic
spare vessel
just take the time to actually get a hang of how to get to those values
Yes I will so I can explain it when I do the reporting HAHAHA
ashen copper
😎
ashen copper
Last question does the results need to be $80,000?
since we calculated what the % of annual rates are
the result of putting those values should be around $80,000
ashen copper
were there any problems in doing so?
spare vessel
Yes it's the result is not 80,000
ashen copper
the result is?
spare vessel
yes
ashen copper
what is the result
the number that came out from the formula that you used
it would also be great if you would also show me the formula which you used
spare vessel
300,000
wait
HAHAHAH I'm confused😭😭 nvm it's ok I'm gonna figure this out HAHAHA
Ty
ashen copper
HAHAHAH I'm confused😭😭 nvm it's ok I'm gonna figure this out HAHAHA
im very sorry. the problem was from my side
as i have not correctly calculated the problem and got out an imperfect value
i have also left out some steps which made the equasion worse
spare vessel
im very sorry. the problem was from my side
It's ok it's not your fault I appreciate that you help me because I have no idea myself too 😄
ashen copper
It's ok it's not your fault I appreciate that you help me because I have no idea...
ok now after some trial and error i have the actual sollution.
5000*(1+0.319507911)^10
spare vessel
Ohh nice
spare vessel
wait
ashen copper
the annual interest rate (r) should be 31.95% which is the rounded variation of 31.9507911%
so the original version of r to get to 80000.00014 should be 0.319507911
spare vessel
Tysm😭
ashen copper
np 👍
spare vessel
ay wait how did you get it do you the solution HAHAHAHA
Did you. write it in paper?
spare vessel
5000*(1+0.319507911)^10
or it's just this